#help-42

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dull wagon
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and do the expansion like you would any other expansion

dry shale
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5x^2+5xn+12x/n+12n/n

dull wagon
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and then identify the x terms, factor x out
k will be the coefficient

dry shale
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oh okay

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hmm i get it now

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why does it take rational values between -200 and 200

dull wagon
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for what I mentioned earlier

dry shale
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ohhh i get it

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why is |n|<=39

dull wagon
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and it should be easy to see that if non-zero integer |x| <= 12,
k would be relatively small

dull wagon
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because 0 < 12/x < 1 for values greater than 12

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you'd also want to ensure there aren't any issues for lower integers

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if there wasn't an restriction on values integers, there would be

calm coralBOT
#

@dry shale Has your question been resolved?

calm coralBOT
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frosty mica
#

Can someone please help me format this LaTex doc? I need to get a picture to right of the text.

frosty mica
#

.close

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lucid knot
calm coralBOT
lucid knot
#

how does my answer look?

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did I explain this right?

ionic moon
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is this ap stat?

calm coralBOT
#

@lucid knot Has your question been resolved?

lucid knot
lucid knot
ionic moon
# lucid knot

The mean is 8...Since the mean (7)
is 7 the mean or the median?

calm coralBOT
#

@lucid knot Has your question been resolved?

lucid knot
lucid knot
# ionic moon > The mean is 8...Since the mean (7) is 7 the mean or the median?

the data is skewed lower, 1 is the lower extreme and 20 is the higher extreme but most of the data points sit between 5 and 11. The mean is 8, since it is right between 11 and 5. The mean is close to the median, so the data is somewhat symmetrical. i had sort of a brain moment, this should be better, does my reasoning stand?

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long snow
#

hello

calm coralBOT
long snow
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can someone explain where this even came form pls

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i am sturglging to undeerstand

dull wagon
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power chain

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you have something of the form
$$\frac{k \cdot f'(u)}{(f(u))^n}$$

potent lotusBOT
#

ℝαμΩℕωⅤ

unique jackal
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,, \int \frac{u}{(u^2 + 1)^2} du = \int \frac{2u}{2(u^2 + 1)^2} du = \frac{1}{2} \int \frac{1}{t^2} dt = \frac{1}{2} \left[\frac{-1}{t} \right] dt = \frac{1}{2} [-t]^{-1} dt = \frac{-1}{2} [u^2 + 1]^-1

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oh, the last equality got cut off

potent lotusBOT
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higher!

long snow
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wait so its the integral of this one ?

unique jackal
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yeah

long snow
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okay but why is it -1/2

unique jackal
long snow
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where did we get the 2's from in the second step

unique jackal
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we multiplied the integrand by 1 = 2/2

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that's all

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we need the 2 in the numerator because dt = 2u

long snow
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and then we pull out a 1/2?

unique jackal
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yeah

long snow
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but how exactly does that even happen tho cuz isnt 2/2 = 1

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sorry

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im slow today

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LOL

unique jackal
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no worries haha

unique jackal
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we can multiply by 2/2 because it's just equal to 1

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but the 2 in the numerator combines with the u there to make dt

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while the 2 in the denominator comes out as 1/2

long snow
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omg.

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LOL

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AHHH

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cuz

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du = dt/2

unique jackal
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nono

long snow
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sorry

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dt/2u?

unique jackal
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dt/du = 2u

long snow
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oh

unique jackal
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so dt = 2u du

long snow
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OH RIGHT CVUZ

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OMG

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LMFAO

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and thenb comes 1/2

unique jackal
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yeah

long snow
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that is so annoying

unique jackal
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and (u^2 + 1)^2 is just t^2

long snow
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how has it become -1/t

unique jackal
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because 2u du is dt, the 1/2 comes out, and (u^2 + 1)^2 = t^2

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oh

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you changed the question

long snow
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like here wait

unique jackal
long snow
unique jackal
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this follows from the reverse power rule

long snow
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oh yeah

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cauise

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sorry i just get confused when i cannot do it step by step but i see it now

unique jackal
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no worries

long snow
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oh!

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and then they just plug in t later and pull out -1 from -t

unique jackal
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yeah

long snow
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becomes the final answer

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OKAYYYYY

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okay now it is time to tackle the ohter Half

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so i have this formula here

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my handwriting is bad but

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this formula somewhat applies but then again where did this come from

calm coralBOT
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@long snow Has your question been resolved?

long snow
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@unique jackal

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sorry for the ping but ur good at explaining

calm coralBOT
#

@long snow Has your question been resolved?

calm coralBOT
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hybrid dock
#

help

calm coralBOT
hybrid dock
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how do i solve lg 2 using lg 5 = 0.699 and lg 6 = 0.778

rancid root
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lg 5 is lg(10/2)

tame forge
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Bro tried to confuse us by giving log 6

hybrid dock
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i have to use both ☹️☹️☹️☹️

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its said in the question

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should i do lg 2 = lg(5*2) = lg(10/5)?

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my bad im new to lg so im sorry

tame forge
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no

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No problem.

tame forge
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2 is not equal to 5*2

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but 10/5

hybrid dock
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awh man im stuck

tame forge
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Is it told that you have to necessarily use log (6)?

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$ log(6)$

hybrid dock
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in that case no

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i gotta choose my fault

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id choose lg 5 to find lg 2 right, but then what

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frick maybe i should use lg 6

tame forge
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2 = 10/5
log 2 = log (10/5)
log 2 = log 10 - log 5
log 2 = 1 - log 5

hybrid dock
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last one, is that correct?

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.close

calm coralBOT
#
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tame forge
#

yeah

calm coralBOT
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limber kernel
calm coralBOT
shell tiger
#

isnt it cosine?

limber kernel
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That's what I was thinking at first

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Number 11 got me confused

hybrid flint
calm coralBOT
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shell token
calm coralBOT
shell token
#

it says this is wrong but my thought process was that all the tension forces are the same since they go the same amount from the origin with the same angle

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so for the vertical components, T sin45 + T sin45 + T sin45 + T sin45 = 275*9.8

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but idk what's wrong

calm coralBOT
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@shell token Has your question been resolved?

shell token
#

<@&286206848099549185>

calm coralBOT
#

@shell token Has your question been resolved?

rapid cliff
#

so each rope has a component in the z axis, and a component in the xy plane. I'd start by finding the lengths of this triangle.

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@shell token assuming you're still around XD

shell token
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hmm okay

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yeah 😭

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still lost

rapid cliff
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you can use 1/4 the mass of the block, because there's 4 ropes carrying equal tension

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I'm saying you can model the each rope as two components, one pulling directly upwards, and the other pulling outwards from the center of the ceiling

shell token
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ohh

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so it's just the weight / 4?

rapid cliff
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so the tension in the vertical component is due to 1/4 of the weight. the actual tension in the rope is larger than that because it's not pulling directly up.

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make sense?

shell token
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yes

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wait so

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where are we going w this

rapid cliff
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We can calculate the tension in four hypothetical vertical ropes (it's just 1/4 the force requried to keep the mass still). And we can calculate a relation between the force in a vertical rope vs the force in the actual rope (using that cosine).

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I've made a mistake there, it should be 5 / cos(t)

shell token
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okay..

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sry I was on call with my friend

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he figured it out but in a completely diff way 😭

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and im just more lost

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but he did 0 = W - 4 (T1 * 5/sqrt(75)) and solved for T1 and it was surprisingly right

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all I know is 5/sqrt75 is the unit vector or something

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but I don't really get anything else

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but sorry @rapid cliff didn't mean to ignore what you said, ill be glad to hear how you would do it now, im just trying to understand both ways

shell token
#

45 deg?

calm coralBOT
#

@shell token Has your question been resolved?

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still grail
#

what does it mean for a point to be on the circle

glad parrot
still grail
still grail
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oh

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i see

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DF = PB sin B
DE = PC sin (A+B)

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how do i show this is equal

glad parrot
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Hum

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I feel like its not asking u to prove this equality

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But to prove the equivalent relation

still grail
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but wont showing the above show that

glad parrot
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Like assume equality is true, and show that implies the circle thing

still grail
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ohk

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right

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thx

glad parrot
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And

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Wait

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Do the same in reverse too

still grail
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k

glad parrot
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Assume the circle thing, and show that implies the equality

still grail
#

k

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but what result would lead to the point bieng on the apollonius cirlce

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oh

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done

#

.close

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noble cedar
calm coralBOT
drifting seal
#

dope

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ima lagrange kinda guy myself

noble cedar
#

I thought it's called Euler's Notation for the last column (blue)?

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And where is Partial Derivative Notation ∂f / ∂x

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I only see these two in my Math (Calc 2) university class

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I wish it was only LaGrange, but maybe it's not possible to teach all of Calc 2 using just this notation? Leibniz is mandatory?

surreal heron
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i dont think its mandatory

calm coralBOT
#

@noble cedar Has your question been resolved?

surreal heron
#

also apparently arbogast notation is more historically accurate

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echo mirage
calm coralBOT
#

Please don't occupy multiple help channels.

echo mirage
#

Fix bot sir

frank basalt
# echo mirage

so as we know that cot theta = 1/tan theta

find tan (-0.003) first and then find it's reciprocal
as the theta is very small ,tan theta is approximately equal to theta which means
tan (-0.003) = -0.003
now for cot (-0.003) as I said we have to do 1/-0.003 after which we get approx -333.33

echo mirage
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Im guessing itll be the same for

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cot(3raiden/2)

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find the tan of that then use its reciprocal

frank basalt
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yes

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tan(3radian/2) is undefined so will be the same for cot too

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I hope your doubts are resolved

echo mirage
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thanks so much

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how do you know its undefined?

frank basalt
echo mirage
#

How about this in solving it in this format

frank basalt
# echo mirage

it's complex, it could have been done more easily I think

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for ex that cos 225 can be written as cos ( 180 + 45 ) and then we can solve it using cos ( a + b ) = cos(A).cos(B) - sin(A).sin(B)

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If that graphical method is easier for you then you can go with it

echo mirage
#

my professor is weird bro

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she wanted it in that way i did it

frank basalt
echo mirage
#

You in America?

frank basalt
#

I am from India

echo mirage
#

i have 40 mins ot turn iin these two quizez bro im cooked

frank basalt
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I never thought someone would try to go for it graphically

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so things are diff there as I see

echo mirage
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Ngl I need help for this too bro

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I’m so stuck on this one it’s crazy

frank basalt
#

undefined

echo mirage
#

So this is undefined too then. Cause cos is = to 0 and for sec it’s
Sec A = 1/cos

frank basalt
frank basalt
echo mirage
#

Okay bet

echo mirage
# frank basalt

It’s hard using this compared to what I’ve learned in class but your way seems easier for sure

frank basalt
#

what grade are you in

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coz that table is like the foundation of whole trignometry

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the first thing to be taught and learnt

echo mirage
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Im a freshman in college

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I never learned it at all man

frank basalt
#

damn

echo mirage
#

American math is so stupid and all over the place

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I understand the numbers so well. But the concept i do not understand .

frank basalt
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well the way you are being taught even the simplest things in the most complex way

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it explains

echo mirage
#

bro thats what im saying

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my professor is doing the most dude. Its so annoying. Trig isnt suppose to be this difficult

frank basalt
#

you can remember that table, it will make things a lot easier

echo mirage
#

im just being told radians everynow and then and some numbers but not how everything comes together and when we use things

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Bet thanks bro ima rmb the table. Is it okay if I add you?

frank basalt
#

sure np

calm coralBOT
#

@echo mirage Has your question been resolved?

echo mirage
#

what if csc is at 240?

frank basalt
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cosec theta = 1/sin theta

echo mirage
#

so i make the 1=240?

frank basalt
#

sin (240) = sin ( 180 + 60 ) = sin 60

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sin 60 = √3/2

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so sin 240 is (- √3/2)

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doing again that reciprocal will yeild
cosec 240 = -2/√3

echo mirage
#

ohh because it resets cuases its 2 rads in a unit circle

frank basalt
#

yes

echo mirage
#

okay bet that makes sense

frank basalt
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it is an identity though

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which is used majorly in these type of ques

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based on the graphical method you use

frank basalt
echo mirage
#

Flex man ngl

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i think im cooked man

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My brain is fried and all i have left is 4 questions

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but i cant compute my brain anymore. my professor drop this quiz last minute it was 2 of them

frank basalt
#

well it is not smth you can just learn in few minutes and use it like pro

echo mirage
#

yeah true

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can you help me oout real fast and just pass me the answers 😭

frank basalt
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I will try

echo mirage
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thanks man

frank basalt
#

8 and 9 undefined

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10 is 0

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11 is -2√3/3

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12 undefined

echo mirage
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11 is written like this?

frank basalt
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no -2√3 whole is divided by 3

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bro I could be making errors

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give me some time

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not sure about the 8

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8 is -√2

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9 is 1/√3

echo mirage
frank basalt
#

8 is -√2
9 is 1/√3
10 is 0
11 is -2√3/3
12 undefined

calm coralBOT
#

@echo mirage Has your question been resolved?

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hollow sphinx
calm coralBOT
hollow sphinx
#

A bit stuck

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I tried to do byparts on the bottom left and then tried to continue it on the right page but doesn’t seem right

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And a u sub wouldnt really help so im kinda confused

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(The weird squiggly letter is supposed to be a “t”)

potent lotusBOT
elder pawn
#

if we just wanna know the "interval of validity" then theres a theorem out there that tells us what it is without finding an explicit solution

hollow sphinx
elder pawn
#

did you read the link? can you tell me how to apply it here?

hollow sphinx
#

yes, we have 5/(t^2-4) we look for something that makes the function = 0

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so we have +2 and -2

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and we're given y(-1) in the problem so we need an interval that contains -1, I think its -1<t<-2

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the ln(t^2) will always be defined since squaring a negative will give a positive

elder pawn
hollow sphinx
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ln(t^2) / (t^2 -4)

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which has the same discontinuity as the 5/(t^2-4)

elder pawn
#

theres another discontinuity you forgot

hollow sphinx
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ah its also undefined at 0/any t

elder pawn
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its not 0/0

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the bottom is continuous at t=0 but the top blows up

hollow sphinx
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yep

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so we have 0,-2,2

elder pawn
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now whats the "t0" in this problem?

hollow sphinx
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and the given initial value is y(-1) so we have to include -1 in the interval

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so -2<t<0 ?

elder pawn
#

ok yeah t0=-1 and the interval containing t0 is (-2,0)

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thats all! no need for explicit solution, isnt it neat?

hollow sphinx
#

yep thanks

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was trying to integrate a monstrosity that couldnt be integrated for the past hour

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at some point I gave up and knew it was a trick question lol

elder pawn
#

i didnt try it myself but i noticed you rewrote the IVP wrong

hollow sphinx
#

yeah I forgot to divide the ln(t^2)

elder pawn
#

not sure if itll get easier once you correct it

hollow sphinx
#

I think it would've still been pretty bad but not too sure

elder pawn
#

,w (t^2-4)y'+5y=ln(t^2)

elder pawn
#

for sure you need to use the theorem instead of trying an explicit sol 🙂

hollow sphinx
#

tysm

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.close

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#
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elder pawn
#

no prob!

calm coralBOT
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topaz sapphire
#

in solving inequalities, how do i know if the solution is all real numbers or no solution?

leaden thunder
#

Really depends on the equation

topaz sapphire
#

can u give an ex

desert torrent
# topaz sapphire can u give an ex

well if u know that the only possible solutions is all real or no solution, you can just plug any number into the inequalities and test if it is true

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if there are more possible solutions it really depends on the problem

topaz sapphire
#

thank you

#

.close

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#
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remote mural
#

find min int c

calm coralBOT
remote mural
#

if a+b is an integer and 'c' is an integer

fringe reef
#

a and b are integers too right

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yeah they have to be

remote mural
#

yeah

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cuz ab is an integer

fringe reef
potent lotusBOT
#

artemetra

fringe reef
#

so $a^2 + b^2 < a^2 + 2ab + b^2$\
$2ab > 0$

potent lotusBOT
#

artemetra

fringe reef
#

okay this is not very useful haha

fringe reef
#

A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. Such a triple is commonly written (a, b, c), a well-known example is (3, 4, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any positive integer k. A triangle whose side lengths are a Pythagorean triple is a right triangle and call...

remote mural
#

yes

#

Ok so

#

this is the exact question

fringe reef
#

actually (15, 20, 25) works too

remote mural
#

Oo

#

I marked (6 * 4, 8 * 4, 10*4)

#

ac = 40

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😦

#

never mind

#

.thanks

#

.close

calm coralBOT
#
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fringe reef
remote mural
#

yez

calm coralBOT
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mellow yew
#

..

#

So I thought about it.

calm coralBOT
mellow yew
#

Is the reason why both of these are equal that

#

It's already equal to zero

#

Like because the equation Is already set equal to zero at the start it's considered the answer alr

#

Something you shouldn't be able to do if they weren't all variables unless you had the answer of what it solved out to

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?

#

Basically are those already the zeroes of the problem

drifting seal
#

multiplying both sides of the equation by a constant doesn’t affect the equation (obviously can’t multiply by zero but yea)

drifting seal
#

because either side of the equation is equal to other side consider the following equation: x=2

#

if i multiply both sides by 2

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i get 2x = 4

#

but notice x was just 2

#

so 2x = 2(2) which is still the same as the right side

mellow yew
#

There probably is some hidden goal or representation it has ppl don't explain causing all prior explanations to become annulled.

drifting seal
#

the goal of manipulating equations is to solve them

#

for the variable

mellow yew
#

Solve them how

#

What form do you want the answer in?

#

Zeroes(

#

?

drifting seal
#

in your case we are solving for x

#

when solving a quadratic for the zeros you’re solving for the values of x such that the function equals zero

mellow yew
#

One second I'm in an airport.

calm coralBOT
#

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forest saddle
#

How do I solve this integral? Everything I tried doesn’t really work

fiery crater
#

you need to sub back in u = x^2 + 1

#

cause the end points of the integral are defined in terms of x, you're integrating from x = -infinity to x = infinity

eager forge
#

You also need to split up the integral

fiery crater
#

yeah when you integrate to infinity you should split it up so that each end has a limit

forest saddle
#

when do I split vs don’t split and where do I split it at

eager forge
#

Split it up

#

Using any value c

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#

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knotty bridge
#

**For which value(s) of a does g(x) increase or decrease without bound as x approaches a or for which value(s) of a is g(x) not defined? (Select all that apply.) **

knotty bridge
#

I have no idea what the hell is it is asking. I'm reviewing my notes from class and the professor never talked about this

dry crystal
#

The question is just asking about the limits as x approaches a
Are you familiar with when limits exist or not

knotty bridge
#

Yes.

A limit exists if it is the same from both sides and not DNE

dry crystal
#

Oh nvm I see the question asks about g(x) not the limit of g(x)

knotty bridge
#

I think the entire function is g

#

Consider the following graph of the function g.

dry crystal
#

Didnt you just make a small mistake when entering your answer

knotty bridge
#

I literally am just guessing

dry crystal
#

You said for a=0?

knotty bridge
#

I have no idea what they want

dry crystal
#

Aaah

knotty bridge
#

The professor never gave us anything in class about increase/decrease without bound as (x) approaches (a)

swift laurel
#

that means it has a vertical asymptote there (because it means the limit approaching a is +/- infinity)

knotty bridge
#

So then just -1?

dry crystal
#

I think it is just x=-1, the entire picture isnt very clear but because it doesnt show an end I think theyre trying to say it goed infinitely further (down)

knotty bridge
#

I tried -1 already:

dry crystal
#

You forgot second part of the question now

knotty bridge
#

Oh

dry crystal
#

For which values of a is g(a) not defined

knotty bridge
#

So -1, -2, and 1?

dry crystal
#

Why 1?

knotty bridge
#

Oh you're right

#

1 is defined

dry crystal
#

Yes

knotty bridge
#

so just -1 and -2 then

dry crystal
#

I think so yes

knotty bridge
#

That worked

#

Now:

From the given graph of g, state the numbers at which g is discontinuous.

#

Would that be:

-2, -1, 0, 1?

dry crystal
#

I think that is correct again yes

knotty bridge
#

Got it, thank you

#

I'll probably be back later, going to close thread until I run into anymore issues

#

.close

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halcyon ore
#

this is for a part of my problem in physics

halcyon ore
#

how do u solve this to be honest sry

#

Like do i need the unit circle?

#

becuz in the video he just got -75 without a second to think

empty quail
#

whats Rx?

halcyon ore
#

ax+bx

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ax was -50

leaden thunder
#

Show the original question

halcyon ore
#

and the bx was -bcos=-50cos60 i show whole pciture

empty quail
#

are you just looking for calculation of bx

halcyon ore
#

this part specific

#

]

#

thats the parts before

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yes Bx

#

I just want to know why rx=-75

#

becuz he did it in 1 second

empty quail
#

use a calculator

#

,w calc -50+(-50cos60)

halcyon ore
#

oh

#

thnxs so much

empty quail
#

yw

calm coralBOT
#

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orchid ridge
calm coralBOT
orchid ridge
#

idk how to do this at all

#

got these tho

#

idk what to do with em

calm coralBOT
#

@orchid ridge Has your question been resolved?

orchid ridge
#

<@&286206848099549185>

#

OH

#

.close

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hoary pulsar
#

Efficiency

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nimble portal
#

Could someone explain what the answer would be for this?

nimble portal
#

<@&286206848099549185>

leaden thunder
calm coralBOT
# nimble portal <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

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mossy wigeon
calm coralBOT
mossy wigeon
#

is it a mistake or is it me

#

r_x says 6 and then 8

teal drift
#

Yeah you're right

mossy wigeon
#

turns out 8 was the answer

#

so they mixed the answer and question

#

💀

silver sonnet
#

it is the answer

silver sonnet
#

hello syrex

mossy wigeon
#

hiii hru

mossy wigeon
silver sonnet
mossy wigeon
silver sonnet
#

anyhow you know how the answer came about right

#

do you need me to tell you how or you know it?

mossy wigeon
#

i forgot everything

#

in physics

calm coralBOT
#

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honest swallow
calm coralBOT
honest swallow
#

For twenty the answer is given as 10 but I'm getting 13

#

Can anyone tell me the way to get 121 in 10 steps?

#

Nvm got it

#

.close

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exotic cosmos
calm coralBOT
exotic cosmos
#

Can i have a hint for the "only if" part?

#

For the if part, i used the fact that the vertex angles are the same and also the legs are the same in an isosceles trapezoid and so the two triangles with the longest side as the diagonals are congruent

#

I think that's correct

#

Diagram:

calm coralBOT
#

@exotic cosmos Has your question been resolved?

calm coralBOT
#

@exotic cosmos Has your question been resolved?

calm coralBOT
#

@exotic cosmos Has your question been resolved?

jolly pilot
#

You can start the if and only if part by assuming that the diagonals are congruent AND the trapezoid is not isosceles

#

then, to prove the statement, you need to arrive at the conclusion that even if you assumed it was not isosceles, the rest of the conditions make you conclude that it has to be isosceles

calm coralBOT
#

@exotic cosmos Has your question been resolved?

exotic cosmos
#

i need help actually proving it

unkempt drift
# exotic cosmos Diagram:

ah using the hint, so triangles DBY and CAX are congruent by RHS (diagonals are the same length, and AX = BY by definition of a trapezoid)

so that must mean that DY = XC or that DX + XY = XY + YC or DX = YC

so then as AX = BY, by Pythagoras we have that DA = CB as desired

exotic cosmos
unkempt drift
#

why do you want a longer route

exotic cosmos
#

the book gives the same solution as you

#

but i didn't see that

unkempt drift
#

well, how did you approach the question otherwise then

#

I thought the hint was pretty nice as it seemed impossible otherwise

exotic cosmos
#

yeah 😭 but how would you know to drop a perpendicular

unkempt drift
#

the hint tells you

exotic cosmos
#

yeah but 😭 idk if there wasn't any hint i would've never considered doing that tbf

unkempt drift
#

if there are right triangles you have to drop a perpendicular

unkempt drift
exotic cosmos
#

mmmm okay, do you have any idea about the "little longer" route?

#

Maybe it's more natural but with more angle chasing or something

unkempt drift
#

I don't know, you could try opening a thread on AOPS

#

I considered angle ABD = angle CDB and so on

#

maybe that's what they are referring to

exotic cosmos
#

Thanks

unkempt drift
#

np

exotic cosmos
#

Not sure why they put this question with other regular questions

unkempt drift
#

it seemed pretty fun once you realise the hint helps

#

also there's actually more than one definition of an isosceles trapezoid

exotic cosmos
#

Most of the time i do it myself but the hint always guides you to the nicest way to the solution

#

This one was unapproachable ded

exotic cosmos
#

Can we show that thing is a square?

#

But okay that's almost similar to their solution maybe

#

okay nvm i'll just come back to this when i'm better

#

Now i'll live with the solution u and them provided

#

thanks

#

.close

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#
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mellow yew
#

Back

calm coralBOT
mellow yew
#

Had to get on the airplane last time.

#

pt1 ANSWER: Because everything including the input (x) is scaled down equally the functions result is still equal to zero even if the function has different outputs given different values.

mellow yew
mellow yew
# mellow yew
What is the nature of the equal sign and moving stuff past it such as -c/a? Clearly that would be unequal and very strange if it directly meant equal and Ive been given examples in which it appears as though it is indeed not the traditional equivalency sign because

5 + 10 = 15   15-10 = 5
vs
5 + (10 was subtracted/removed) = -10  resulting in -5 once 5 is added. (operation left incomplete and 10 was removed then subtracted)

1st example: the operations are performed normally, everything is equal in the end.

2nd example results in -5 because 10 was removed and then subtracted```
#

?

vagrant oak
#

what exactly is that example supposed to show

#

5 + 10 = 15 and 5 = 15 - 10

#

both are true

#

what's wrong

mellow yew
#

those are completely different operations

vagrant oak
# mellow yew they arent the same

They are statements. Not the same statements, but equivalent statement.
Equivalent means that that if one of them is true, then the other one is true as well.

#

5 + 10 = 15 is true and so is 5 = 15 - 10. Both are true.

#

They aren't the same, yes. But is that a problem? Should all statements be same?

mellow yew
#

you probably really dont try to understand why confused people are confused nor try to resolve from that

#

not that you arent helping by doing this

#

i do have another question to ask you

mellow yew
# mellow yew you probably really dont try to understand why confused people are confused nor ...

if im being honest for the longest time i already was absolutely infuriated by this because from my perspective it always looks like everyone explains everything in the most complex possible terms and lays out some advanced gigantic block of random thesis and numbers every time someone asks a basic question thinking theyd somehow understand when they couldnt even understand the first step

#

not that you did it this time

#

im speaking in general that this happens so often

#

and what i cant tell is if its actually their fault or not

#

because every single time ive ever solved a problem it always ends up summing up to the most simple and basic two sentence explanation possible

#

leading me to see them as almost horrible people when it comes to explaining things

#

what i want to know is

#

do you think thats actually the case do they just not care or is it just perspective and they really are doing their best?

vagrant oak
#

you are doubting something that most people take as granted

mellow yew
#

people seem to care so much about whats right they forget entirely about the person theyre actually trying to explain to and that if that person is confused or has even 1 piece missing all information is null because their context itself would be faulted meaning the same information would have a different meaning.

vagrant oak
#

and if you want an in-depth understanding of that, it probably will be explained complexly

pseudo wedge
mellow yew
mellow yew
pseudo wedge
pseudo wedge
#

if you're trolling then good job you got your two seconds of fame

mellow yew
pseudo wedge
#

otherwise frame your question properly and stop pretending like you're better than everyone else

mellow yew
#

i always desire to achieve that perfection whenever i fail in life.

unkempt drift
#

<@&268886789983436800> this discussion is turning unproductive and toxic

mellow yew
#

i am not better than you

#

i am a flawed person trying to be the best i can because i cant live with my inability.

mellow yew
#

i was just asking a question i always wanted to know the answer to.

#

kheeri misinterpreted it as me thinking i was superior when it was the opposite though its both simutaneously sometimes its a complex topic really.

pseudo wedge
slate field
#

can we keep the conversation on topic

#

please

mellow yew
#

we are i was asking 2 different questions and that one question ive been wondering for like 5 months it makes it painfully hard to pay attention at times not knowing the answer because i always think about it.

mellow yew
#

they a r e different yes

#

they dont have to be equal either

pseudo wedge
#

what don't have to be equal

mellow yew
#

the question was meant to see IF they were equal because the context they were given in if it wasnt equal it would cause problems

#

because thats in context of quadratics where you have to find the zeroes

#

and if it isnt equal then you dont get the answer

#
1. quadratics require you to solve for the zeroes so if one value changed you wouldnt have a question equivalent to the zeroes```
#

this is why i care so much about if it was or wasnt equal

pseudo wedge
#

Let's address the 5+10=15 vs 15-10=5 thing first

#

why exactly do u think these statements are not equivalent

mellow yew
#

also kheeri stop thinking people are trolling because im not sure if you realise that but you yourself are actually trolling by assuming someone is trolling and disregarding their points and labeling them that when they have a real question

mellow yew
tribal jetty
#

if you have a quadratic equal to 0 and do the exact same operations on both sides (lets just assume for now that this is just adding/subtracting/multiplying/dividing by non zero constants, since stuff like squaring can be weird) then whatever x values (or roots) solved the initial equation, the same ones will solve the equation made after doing some operations

mellow yew
#

5+10 = 15 vs 5 + = -10

mellow yew
mellow yew
mellow yew
#

10 IS -10 in this context

#

thats why it appears nonsensical

#

how can 10 be -10 C/A = -C/A thats a completely different result

#

sorry if i miswrote it earlier

pseudo wedge
mellow yew
#

well sorry

tribal jetty
mellow yew
#

but thats what they just did

pseudo wedge
#

no

#

it is not

mellow yew
#

wait

#

oh so 0/a and -c/a were separate?

#

to be fair my eyes arent exactly good but wow

#

i really do have problems huh....

tribal jetty
mellow yew
#

i wasnt lying when i said i might have dyscalculia LOL

tribal jetty
#

the x values that solve both equations are equivalent

mellow yew
#

no they did

#

wow my eyes

#

are terrible

#

so let me get this straight

mellow yew
#

im stupid

#

this is a mess!!

#

but not really my fault its a simple error

mellow yew
# mellow yew

ok so 0/a became -c/a and c/a became negative and past the equal sign

mellow yew
pseudo wedge
#

$$\begin{aligned}
ax^2+bx+c&=0\
\implies \frac{ax^2+bx+c}{a}&=\frac{0}{a}\ (\text{assuming }a\ne 0)\
\implies \frac{ax^2}{a}+\frac{bx}{a}+\frac{c}{a}&=0\
\implies x^2 +\frac{b}{a}x&=-\frac{c}{a}\end{aligned}$$

potent lotusBOT
#

kheerii

pseudo wedge
#

does this help clear up things

mellow yew
#

how?

#

didnt you just rewrite the problem?

tribal jetty
#

i thought that was your question

mellow yew
#

alright

#

.close

calm coralBOT
#
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calm coralBOT
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narrow spear
#

in my lesson I have if (Un) and (Vn) 2 sequences of constant sign from a certain rank and monotone then if Un ~ Vn we have the series of Un and the serie of Vn of the same nature . Can we remove the monotone hypothesis if not do you have a counter example

narrow spear
#

got it

#

.close

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#
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shrewd helm
#

hey

calm coralBOT
shrewd helm
#

anybody understands how we came up to this conclusion?

#

this regards complex numbers where we're trying to find the solutions of this equation
U^2 = Z where Z is a complex number

suppose Z = a + bi and U = x + yi

eternal shard
potent lotusBOT
eternal shard
#

Same if you solve for x^2 instead and plug that in

shrewd helm
#

thanks

#

i get it now

eternal shard
#

good goku

calm coralBOT
#
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hazy trout
#

Hello.

calm coralBOT
hazy trout
#

Quick question, am I allowed to do this in this specific case?

#

$\int_{0}^{1} \sum_{n=1}^{\infty} \frac{(-1)^{2n} \cdot n^{-1+n} \cdot x^{-1+n} \cdot (\ln x)^{-1+n}}{n!} , dx$

potent lotusBOT
hazy trout
#

$\sum_{n=1}^{\infty} \int_{0}^{1} \frac{(-1)^{2n} \cdot n^{-1+n} \cdot x^{-1+n} \cdot (\ln x)^{-1+n}}{n!} , dx$

potent lotusBOT
hazy trout
#

I am assuming I can, just wanted to double check to make sure.

leaden thunder
#

(nx log(x))^n / n! convergence looks sus

graceful dust
#

i wouldn't "assume" you can

hazy trout
#

That was my only worry

graceful dust
#

like it's not immediately obvious you can

leaden thunder
#

do you have the original problem statement

hazy trout
#

This works comes from here

#

$\int_{0}^{1} \left(x^x\right)^{\left(x^x\right)^{\left(x^x\right)^{\cdots}}} , dx$

potent lotusBOT
fleet verge
calm coralBOT
#

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silk shuttle
calm coralBOT
silk shuttle
#

Hey, I have no idea where to start on this question

#

Please help

wraith robin
#

do you know how to plot linear and quadratic equations?

silk shuttle
#

No

#

Well I probably do

#

But I don’t remember how to

#

Once you explain it may come back to me

#

@wraith robin

wheat wyvern
#

What do you get when x = 1

wraith robin
#

okay maybe go on khan academy and learn how to plot an equation first, they have good resources

silk shuttle
wraith robin
silk shuttle
wraith robin
#

that is plotting the line x = 1, not the value of the function at x=1, which i believe was the question being asked

silk shuttle
#

Oh

silk shuttle
#

What does that 10 represent ?

wraith robin
#

best bet is to go through khan academy algebra 1, itll actually teach how to read these equations, what they mean, and how to visualise them

silk shuttle
#

Okay, would it be okay if I ping you once I’ve gone through that?

wraith robin
#

yeah j go through the resources on that website and you will be able to answer the q urself easily

wheat wyvern
calm coralBOT
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lavish glen
#

How do I know what the inside and outside functions are for chain rule and I’m a little lost on what to do in general

balmy cape
lavish glen
#

So the inner function would just be -ax?

balmy cape
#

yeah you're right

lavish glen
#

I was confused because it was an exponent and I wasn’t rlly sure how that worked

balmy cape
#

you turn it into f(u) = ae^u and u = -ax and continue from there.

lavish glen
#

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minor scroll
#

Why is the angle between u and w 120degrees while the angle between u and v is 60degrees?

minor scroll
#

for # 11

hollow totem
#

Because you have to rotate u 120 degrees to turn it into w

minor scroll
hollow totem
#

No

winter elbow
#

and don't forget vectors can be shifted

hollow totem
#

A vector doesn't have a start point and an end point

#

It just has a direction and a distance

minor scroll
#

but still, in order to make sure the two vectors start from the same point, wouldn't we have to rotate the vector 180 degrees?

hollow totem
#

No

#

You would move it

#

If you rotate it it's no longer the same vector

#

If you move it, it is

#

Because vectors don't actually have start and end points

#

But they have directions

minor scroll
hollow totem
#

Is

#

Yes*

minor scroll
#

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hollow totem
#

Np

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manic timber
#

Why was 0^0 evaluated as 1 here?

calm coralBOT
leaden thunder
#

But one reason could be because the limit of x^x as x goes to zero from the right is 1

manic timber
#

ight thanks

#

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burnt gazelle
#

Shown is the graph of a function f(x). Sketch the graph of f′(x) by estimating the derivative
at a number of points in the interval: estimate the derivative at regular intervals from one
end of the interval to the other, and also at “special” points, as when the derivative is zero.
Make sure you indicate any places where the derivative does not exist.

burnt gazelle
calm coralBOT
#

@burnt gazelle Has your question been resolved?

burnt gazelle
#

<@&286206848099549185>

remote mural
#

this?

burnt gazelle
#

What>

#

I mean yes

remote mural
#

yeah

burnt gazelle
#

What>

#

Is the same graph

#

It does not make sense

#

<@&286206848099549185>

fickle coral
#

wow, this question is really really cool. I however dont know how to answer it. so like derrivatives are like guessdimation based on how far you wanna get into it all. so like at -0.8, the function is 0.8. and like at -0.6 the number is 1.2. at -0.4 the number is 1.3 and so on. these might be special points. I dont know if any of what I said was helpful. I dont know too much of how this stuff works.

burnt gazelle
#

I do not know either lol

#

<@&286206848099549185>

calm coralBOT
#

@burnt gazelle Has your question been resolved?

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#

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burnt gazelle
#

Approximate a root of f = x^4 + x^3 − 5x + 1 to one decimal place.

dull wagon
#

what are you allowed to use

#

and what have you tried

burnt gazelle
#

First of all, this is from a book and I already know on of the answers(which is .2), but I want to get to that answer by myself, I tried to use Newton Raphson, but there are too many decimals and in the test I can not use a calculator

#

Our teacher said that we have to do it by guessing

#

Sure, for example I chose [0, 1]

#

But ho do you get to that .2\

#

Did I explain myself?

glass heart
#

well you can round along the way

burnt gazelle
#

May you explain?\

#

Wdym?

remote mural
#

nothing

burnt gazelle
#

So did I have to guess my way to the .2?

#

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gleaming panther
#

the question is to prove/ disprove the statement above in the rectangle,
but when I saw this disproof i got confused.
why does polar coordinates not work here?
(the limit in polar =0 but the original limit does Not exist)

can anyone please help me with this or tell me when do polar coordinates work and when not?

calm coralBOT
#

@gleaming panther Has your question been resolved?

gleaming panther
#

<@&286206848099549185>

calm coralBOT
#

@gleaming panther Has your question been resolved?

quaint adder
#

I think that phi is not fixed here, this is why

#

The assumption is only for phi fixed

gleaming panther
#

like why even though it =0 the original limit is not 0 and does not exist

quaint adder
#

You are not considering the same paths

#

Having the angle fixed means that you are doing limit on straight lines

#

Here, you don't

#

You just consider other functions in a sens

#

f°gamma, where gamma is either a straight line or gamma(t) = (t, k cbrt(t) )

gleaming panther
#

but like I mean why does polar work on this function but does not for the func' from before?

#

like what is special about that func' that polar doesnt work

#

or is it like because the limit is not F(r) * G(theta) and G(theta) is bounded?

quaint adder
#

Or it touches with that

gleaming panther
#

i got confused cuz my lecturer did not go deeply into this whole polar thing

#

tysm

#

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remote mural
#

∆ABC has vertices A(3,4), B(−5,2), and C(1, −4). Determine an equation for
a) the median from C to AB

remote mural
#

I need to make a midpoint then make a slope out of the median right?]

#

its just my answers dont match to the questions answers

errant lotus
#

Oh give me a second

remote mural
#

how did u get it

errant lotus
#

So median is a linear function

#

And has to have a form $y = ax+b$ for any point $(x,y)$ on it

potent lotusBOT
errant lotus
#

Meaning that you can get two equations to find a and b as: $3 = -a+b$ and $-4 = a + b$ which you can pretty easily solve

potent lotusBOT
remote mural
#

i will be real

#

so

#

im too tired

#

I dont understand anything

remote mural
#

so I need to ask you to like

#

say it simpler

#

midpoint bro

#

ok

#

(-2,3)

#

tru?

errant lotus
#

The midpoint should be (-1,3)

remote mural
#

ah

#

yes

#

one sec

errant lotus
#

Maybe that's why your solution is wrong

remote mural
#

A and B midpoint no?

errant lotus
#

Yeah

remote mural
#

I did C and A

errant lotus
#

Ah

#

Yeah ok that would do it

remote mural
#

no I did A and B

#

not C and A

#

cuz 2+4 = 6 / 2

#

thats y

errant lotus
#

Yeah

remote mural
#

oh

#

shi

#

forgot to divide x

errant lotus
#

Ahh

remote mural
#

alr ppreciate it

#

.close

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#
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sudden sluice
#

Am I crazy or does this problem not make sense? how can it be aroudn the y-axis when deriving in terms of x? furthermore, if it was a typo and it's around the x-axis, then why is this not the integrand?

fiery crater
sudden sluice
#

nono

#

it should be the arc surface area formula

fiery crater
#

oh the surface, didn't catch that

#

still, shouldn't you be able to find the surface area with a method analogous to the shell method ?

sudden sluice
#

Mayhaps, but this is the formula used in this chapter for which the homework was assigned:
S = ∫[a,b] 2πf(x)√(1 + (f'(x))^2) dx

#

on second thought no it's impossible using shell method

fiery crater
#

i dont see why it would be

sudden sluice
#

considering cylinders forming around the axis with a crossection similar to that rectangle drawn, I think no

#

idk how to explain why I don't think so but that's definitely not what it wants

fiery crater
#

why cylinders ? you're not finding volume

sudden sluice
#

but that's shell method

#

shell method is volume :?

fiery crater
#

ya

sudden sluice
#

okay this is a tangent lmao

fiery crater
#

i mean the integral is just going to be finding the surface area of a section of a cone

sudden sluice
#

$$S = 2\pi \int_{a}^{b} f(x) \sqrt{1+(f'(x))^2} , dx $$

potent lotusBOT
#

Dominick

sudden sluice
#

For example, this problem:

fiery crater
#

i understand what youre saying

#

you cant solve this problem that way though, unless you're right and it somehow is a typo

sudden sluice
#

mm sadcat

#

then my bad, thank you