#help-42

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quaint sphinx
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this

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do u know how to answer now

calm coralBOT
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jaunty helm
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Hey, I've been on this problem for hours and I'm just not coming onto the right answer

The angle of elevation from a point on the ground to the top of a pyramid is 38°20'. The angle of elevation from a point 160 feet farther back to the top of the pyramid is 25°40'. Find the height of the pyramid.

It's in the context of a trig class. There's a visual as well. I was wondering if someone could walk me through it?

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@jaunty helm Has your question been resolved?

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@jaunty helm Has your question been resolved?

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@jaunty helm Has your question been resolved?

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glad sinew
calm coralBOT
glad sinew
#

how to do?

hearty citrus
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Try defining it using division

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P(x) / (x-1) such that r =/= 0

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That may work?

honest quiver
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Alternatively you could possibly define it using polynomials of the form $[P(x) = (x-r_1)(x-r_2)…(x-r_n)]$

potent lotusBOT
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Hat MSC2020 82B10

calm coralBOT
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@glad sinew Has your question been resolved?

calm coralBOT
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@glad sinew Has your question been resolved?

honest quiver
# glad sinew

Like is this a more set theoretic question or algebra question? What level of algebraic rigor does it want, or is it more towards set theoretic rigor?

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If it’s set theory you could probably just take all polynomials in Pn with coefficients that satisfy the quadratic equation for x=1 and exclude them from Pn

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If it’s algebra you could say for instance all polynomials (x-r1)(x-r2)•••(x-rn) such that rn ≠ 0 and all complex roots are present in conjugate pairs

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But without context it’s hard to tell what the question is asking

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Especially since it appears to be part of a larger problem

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teal moss
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How do I find the domain and co domain in 2(d)?

teal moss
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is it just not the opposite of (c)?

proper ridge
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what ???????

calm coralBOT
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@teal moss Has your question been resolved?

teal moss
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the domain of (d) is the codomain of (c) and codomain of (c) is domain of (d)?

teal moss
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but when I tried graphing the inverse function, the domain seems to be different, it is not between 0 and sqrt(3/2)

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paper prawn
#

John got these scores in his 4 seatworks. On the first one he got 76% the second he got 80% the third he got 82% and for fourth he got 90%, the seatworks are 20% of his final mark. If he gets 80% on his final exam which weighs 50% what will be his final average?

paper prawn
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Solution and answrr

sick umbra
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answer is 5

paper prawn
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Oh ok how did u get?

calm coralBOT
# sick umbra answer is 5

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

sick umbra
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huh

paper prawn
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uh what

rough heath
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Not sure might be wrong but I think you first find average of the seat works then find it's 1/5th 20% then make the 80% of the final score 1/2(50%) and add them

paper prawn
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So i fijd the average of the seatworks

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Then add them with the final score

rough heath
paper prawn
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Alright

rough heath
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Also the final exam and the seatworks add up to 70% not 100% of the final average

paper prawn
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Ohh

rough heath
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Did I miss anything

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Where is the other 30 percent

calm coralBOT
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@paper prawn Has your question been resolved?

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full abyss
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x-2y+k=0 intersects circle x^2+y^2+2x-6y-30=0 at A and B, where AB = sqrt(80), what is k?

hardy maple
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draw a schematic circle

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then draw a triangle

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i think you got the idea

full abyss
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wait

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ok

hardy maple
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its more of a geometery question if you ask me

full abyss
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no for real dont get idea

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plus teacher advised us to use algebra

potent lotusBOT
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You must be a bot manager to use this command!

hardy maple
full abyss
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i tried

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subbing

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the straightline equation into circle equation

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then we have a quadratic equation in terms of y

hardy maple
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it would get hellish 🙂

full abyss
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its ok the first question of this was not tedious

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i hope so for thi squestion lol

hardy maple
full abyss
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but anyways im interested in the geometry method

full abyss
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nvm dont have phone with me

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basically since the distance between roots is sqrt(discriminant)/a

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i subbed the straight line equation into circle equation

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then find sqrt(D)/a

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but discriminant is negative

hardy maple
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yeh because that distance is in a 2D plane

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you are trying to find abs(x2 -x1)

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but in 2D plane its sqrt((x2-x1)^2 + (y2-y1)^2)

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you could only use that if and only if your line was y= k
or x= k

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you have R

calm coralBOT
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@full abyss Has your question been resolved?

full abyss
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ic so i cant use sqrtD/a in this case

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ok

calm coralBOT
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old pagoda
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I keep getting negative values when I apply the SA of revolution integral to a function

old pagoda
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This is the function if yall need reference

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pi * Integral from 5.94 to 3.336 of ((0.0821515 x^3 + 0.859522x^2 - 2.93095x + 7.55275)* (1+ (-0.2464545 x^2 +1.719044x-2.93095)^2)^1/2 dx
Yeah its a pain in the ass, I solved it using a GDC

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But I'm getting a negative value

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Am I supposed to just use a modulus sign or is there smthn more to it

calm coralBOT
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@old pagoda Has your question been resolved?

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@old pagoda Has your question been resolved?

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@old pagoda Has your question been resolved?

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kind forge
calm coralBOT
kind forge
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Need help understanding P{X = n}. The experiment ends after n flips, but I still don't get why we don't include the *p.

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I guess that would account for the (t,t,...,t,h)

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but the (t,t,...,t,t) would be (1-p)^n

upbeat venture
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"or a total of n flips are made"

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that's in the problem

flat laurel
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This is really the geometric distribution

kind forge
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Well sheldon ross doesn't do geom distribution until 4.8.1

upbeat venture
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what they did is this:

$(1-p)^n + (1-p)^{n-1}p = (1-p)^{n-1}(1-p+p)$

potent lotusBOT
upbeat venture
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they really should've shown more steps but they're adding the probability of each of those 2 possible events

kind forge
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oh wow, Thanks! So then I must ask, what resources did you use to learn probability?

upbeat venture
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I really don't remember lol, I think I started off by watching khan academy since they give an intuition instead of focusing on memorization. Harvard lectures are good too but much more high level

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I'm not much on books usually, but also practicing a lot helps

kind forge
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Ah, okay. I'll try khan academy too. Yeah I guess practicing on many problems is always gonna be the determining factor.

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have a good one.

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glad sinew
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I asked about this a while back, but for real matrices A, A is orthogonally diagonalizable iff A is symmetric

glad sinew
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but whats the theorem for complex matrices?

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and is this theorem correct?

calm coralBOT
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@glad sinew Has your question been resolved?

upper sparrow
glad sinew
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ok

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lololol ok what I’m gonna do is, literally nap for an hour and then come back

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I know my sleep schedule is actually a little (not a little) bit cray cray

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sooo yea

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I’ll stay in the channel tho I intend to get some work done

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@glad sinew Has your question been resolved?

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cloud flume
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Hi, it may seem like a stupid question but is this correct overall

remote mural
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the objective being?

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and no your derivatives are wrong if thats what u are asking

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v' is fine, u' is not

cloud flume
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Ik it isnt

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So ut is just

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cosx?

remote mural
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apply product rule

cloud flume
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but what i do with x

remote mural
remote mural
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,, (fg)' = f'g+fg'

potent lotusBOT
cloud flume
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AH

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okay

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so

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that is actually like multiple ah

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Ok i know rn

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Makes sense

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Thanks and sorry lol

remote mural
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no worries lmao

cloud flume
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I got stuck sometimes 😭

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unkempt kite
calm coralBOT
unkempt kite
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does my solution

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here

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make sense?

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used bayes thereom

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probability

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😔

pure zephyr
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Ye that looks correct

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Its just the application of the formula

calm coralBOT
#

@unkempt kite Has your question been resolved?

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remote mural
calm coralBOT
remote mural
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So I know that dy/dt = dx/dt * dy/dx

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dy/dx = -4xsin4x + cos4x

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The multiply by 3 and sub in x

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But I did not get the same answer

pure kayak
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what did you get

remote mural
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The answer was given in exact value

pure kayak
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try working with that

remote mural
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Is it dy/dx

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?

pure kayak
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no

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im saying its useful for you to evaluate dy/dt

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you have -12xsin(4x)+3cos(4x)

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and x=5pi/16

remote mural
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Waitttt

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So you're saying sin(4(5pi/16)) will be -1/sqrt(2) then?

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Nvm

pure kayak
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i am saying that

remote mural
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Yeah I got the same thing

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I couldn't get it alll they way down to the answer form but it didn't ask for it in exact form in the question

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So I got the equivalent to the answer

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Thanks

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glad sinew
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helloo

calm coralBOT
glad sinew
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Im having some trouble changing from f_x(x,y) to f(x,y)

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idk man its confusiing

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just this one question my brain is kinda fried cause im integrating, and then differentiating, and then differentiating with respect to some variable

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idk man

sinful pasture
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wdym changing

glad sinew
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q5

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not sure how they got f(x,y)=ye^xy + g(y)

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😭idkkk the other examples made sense my brain is just not working for this one??

sinful pasture
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the book integrated with respect to x

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so just the same way the derivative of derivative of a constant is 0

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the derivative of g(y) with respect to x is 0 since g(y) is a constant in terms of x

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suppose g(y) = y^2 + siny

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what is the partial derivative of g(y) with respect to x ?

glad sinew
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0

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cause y^2 and siny are constants

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differentiating with respect to x

sinful pasture
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ok now suppose f(x,y) = e^x + g(y)

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what is fx(x,y)?

glad sinew
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e^x

sinful pasture
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ok

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suppose now you started from fx = e^x

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then you know f = e^x + something that didnt depend on x

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aka

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f = e^x + g(y)

glad sinew
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ok

sinful pasture
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check by differentiating both sides by x

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h(y) is a constant with respect to x

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just like in single variable as c was the constant

glad sinew
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ah okok

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i see

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thank you

sinful pasture
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a constant with respect to x could be anything that doesn't depend on x

glad sinew
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ok

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thank you

sinful pasture
glad sinew
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im going to close channel

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.close

calm coralBOT
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native zealot
#

Hi, can anyone help me with this question. I have to use multivariable calculus. I tried to use partial derivaties on S, but it didn't work. Any other ideas?

still marlin
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So basically the function ur tryna maximize is V(l, w, h) = lwh

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And the constraint is (lw + wh +hl) = S/2

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S is a constant

native zealot
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ok thanks

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so i treat S like a constant

still marlin
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yeah

native zealot
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we havent been told about lagrange multipliers though

still marlin
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hmm

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only other way I can think of is intuition hmmcat

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mainly that a cube would maximize the volume for a given surface area

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Cus symmetry shenanigans

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If it were a rectangle u could use single var calc hmmm

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Wait

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Maybe AM-GM?

native zealot
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I don't know what that is

still marlin
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Hell yeah

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Arithmetic Geometric Mean Inequality

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doesnt even require calc

native zealot
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.close

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hasty creek
#

Given the information $\sec(\theta)=\frac{-3}{2}$ find the exact value of the five remaining trigonometric functions

potent lotusBOT
hasty creek
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im pretty sure one of them is $cos(\theta)=\frac{-2}{3}$ but im not sure ohw to find the rest

potent lotusBOT
hasty creek
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also its probably importantt to mention pi < theta < 3pi/2

sly apex
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use pythagoras to find the value of sintheta

hasty creek
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yes thats what i was thinking

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but im not quite sure

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which quadrant this is in

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so idk which number is negative

sly apex
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do you know that sin^2(x)+cos^2(x)=1?

hasty creek
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yes

sly apex
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now find tantheta by pluggin sin/cos

hasty creek
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ohh i see okay thank u i got it from here i think

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brave snow
calm coralBOT
brave snow
#

watch should i do for question 9

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idk what to write

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and what sketches to use

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@brave snow Has your question been resolved?

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subtle kayak
#

hi

calm coralBOT
subtle kayak
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need help

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$\int_{-3}^{3}{\sqrt{9-x^2}}$

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wtf

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right

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EH?

potent lotusBOT
subtle kayak
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Finally

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What can I substitute for u here?

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I tried u = 9-x² but im still ending up with

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Dx = du/-2x

pearl dune
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It's a trigonometric substitution

subtle kayak
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Oh

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Wait huh

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Wdym

pearl dune
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Your integral is of the form $\sqrt{a^2-x^2}$

potent lotusBOT
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TayBee

pearl dune
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So you can make the substution $x=a \sin(\theta)$

potent lotusBOT
#

TayBee

subtle kayak
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Ooo

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Mhm

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Then?

pearl dune
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Same steps as standard integration by substitution, what do you get if you differentiate x=asin(theta)?

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You should end up with $dx = 3\cos(\theta)d\theta$

potent lotusBOT
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TayBee

pearl dune
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Substitute in and the rest is trig identities, so see how far you can get

subtle kayak
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ohhhh

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damn

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I didnt even know that existed

pearl dune
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Bit harsh of them to give you that integral if you haven't done trig substitutions yet lol

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More simplistically, if the coefficeint of x^2 is 1:

subtle kayak
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Oh interesting

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Thats my first time seeing that

pearl dune
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Well first time for everything XD Once you've made that subtitution in your question, your first target after some simplifying is to end up with:

subtle kayak
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mhm

subtle kayak
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a cos theta?

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wait

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would u use product rule

pearl dune
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$\int 9\cos^2(\theta)d\theta$

subtle kayak
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no u wouldn't

potent lotusBOT
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TayBee

pearl dune
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That's what you should aim for

subtle kayak
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ooh

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Mhm

pearl dune
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(I've removed the limits as one problem at a time lol

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So after you've substituted x=asin(theta) and substituted for dx, you have $\int \sqrt{9-[3\sin(\theta)]^2}\cdot 3\cos(\theta)d\theta$

potent lotusBOT
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TayBee

pearl dune
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Do a little expanding and that's $\int \sqrt{9-9\sin^2(\theta)} \cdot 3\cos(\theta)d\theta$

potent lotusBOT
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TayBee

pearl dune
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Now you can use your understanding of trig to simplify that square root

subtle kayak
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Ohhh

pearl dune
subtle kayak
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Wow thats tricky

#

Gotcha

#

Mhm

pearl dune
#

Let me know once you've got that far (or if you've got completely stuck) then we'll see what to do next haha

#

How goes it?

calm coralBOT
#

@subtle kayak Has your question been resolved?

subtle kayak
#

Thank u

#

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leaden sandal
calm coralBOT
leaden sandal
#

Hi, can anyone help me with this one? The answer should be 0.085

glacial nacelle
#

how did you get 0.064

calm coralBOT
#

@leaden sandal Has your question been resolved?

leaden sandal
#

That was my 1st attempt, I did 3C3*0.4^3

#

On my 2nd attempt, I did 10C30.4^30.6^7

amber bolt
#

what they mean is
70% of the phones are never submitted for repair, maybe they work forever or something
12% of the phones are replaced
18% are repaired

#

nothing happens with probability 0.4

leaden sandal
#

Wait, where did 12% and 18% come from?

amber bolt
#

that's what happens when you separate 30 into 4:6

leaden sandal
#

I still don’t get it

#

I’m not sure how to structure the answer if I use that

earnest sparrow
#

3/10 * 4/10 = 12/100

#

12% chance of being replaced

leaden sandal
#

Answer is 0.085

amber bolt
#

you did it right otherwise, on your second attempt

leaden sandal
#

8.5%

#

That’s what I was thinking

#

But this is the answer apparently, idk hoe

amber bolt
#

yes

leaden sandal
#

How^*

amber bolt
#

you just use the probability of the phone beng replaced

#

instead of 0.4 which corresponds to nothing

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#
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amber bolt
#

.reopen

calm coralBOT
#

leaden sandal
#

I plugged it in and it got it right

#

How was that derived? How’d you get to that?

amber bolt
#

i don't know how to explain it

#

"that's what happens when you separate 30 into 4:6"

#

this isn't magic, you don't have to derive anything, it's common sense and multiplying numbers

leaden sandal
#

The only reason I can think of on that is p(returned&replaced) = 0.3*0.4 = 0.12

amber bolt
#

if 7/90 of the cars in a town are white and 1/4 of white cars are trucks, then 7/360 of the cars are white trucks

#

we don't have a name for this

#

they teach it around 5th grade and they tell us to multiply the fractions and it's not called anything

calm coralBOT
#

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solar bolt
calm coralBOT
solar bolt
#

Is my answer correct?

#

for reversing the order of integration

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.close

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stark turret
#

Hi guys can someone tell me where it went wrong

timid oracle
#

the ratio of the sides is not exactly the ratio of the volumes

stark turret
#

How can I find the ratio to the volumes tho

timid oracle
#

try a simpler case: imagine a cube with side length s and a cube with side length s/2, what's the ratio of these volumes?

#

and the ratio would be the same for those pyramids, or any 3D shape

stark turret
#

1/8 ?

timid oracle
#

Yep

stark turret
#

Ohhhhh oki thank u so much !!!!

#

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timid oracle
#

*as long as the lengths are halved

#

forgot to add that detail

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rigid crystal
#

hello

calm coralBOT
rigid crystal
#

consider this example

#

what is the convention for ordering this polynomial

#

for example both -4ab and +6ac have the same degree, so how do I order them? and how do I order this entire polynomial

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desert falcon
#

find the remainder when 1⁰+ 2¹+3²+4³+...+1001¹⁰⁰⁰ is divided by 3

desert falcon
#

I see that they repeat after 1,2,0

#

What to do next?

amber bolt
#

they don't just repeat

#

it's better

#

nvm i misread

timid oracle
#

I would suggest splitting it into (1+4^3+7^6+…)+(2^1+5^4+8^7+…)+(3^2+6^5+9^8+…) before taking mod 3

desert falcon
#

Can you like guess the answer?

modern peak
#

wait so basically this is what you have

pallid halo
#

if the terms repeat as 1,2,0,1,2,0,1,2,0,...
then the partial sums will be 1,0,0,1,0,0,1,0,0,...

#

so work out where you are in that partial sum sequence

modern peak
#

$$(\sum_{n = 1}^{1001} n^{n-1}) \text{mod 3}$$

potent lotusBOT
modern peak
#

yes?

timid oracle
#

i don’t think they repeat as a cycle of 1,2,0

#

5^4 is 1 mod 3

calm coralBOT
#

@desert falcon Has your question been resolved?

winged basin
#

However, the numbers which leave remainders of the form 2^k

#

The remainders of this form will be in a gp

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calm coralBOT
calm coralBOT
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@stone steeple Has your question been resolved?

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rocky flower
#

Say you have that a_1b_1+a_2b_2=n where a_i and b_i are integers between 0 and 9. (How many/What are the) subsets of (a_1,a_2) exist such that we can choose certain b_i that produce all possible n within the bound of 0 and 9(a_1+a_2)? I was wondering about this, and sorry if this lacks mathematical clarity. I am never great at expressing myself

graceful dust
#

within the bound of 0 and 9(a_1+a_2)

#

what does that mean?

rocky flower
#

0<=n<=9(a_1+a_2)

#

so we pick certain b_i that can produce all the values of n within this range given the a_i we select

graceful dust
#

the b_i’s are confusing me still

#

let me write a possible interpretation of the problem and you tell me if it’s right

rocky flower
#

sure

graceful dust
#

fix a positive integer n. how many pairs (a_1,a_2) of integers are there with the following properties:

  1. 0 <= a_1, a_2 <= 9
  2. 0<=n<=9(a_1+a_2)
  3. there exist integers b_1, b_2 with 0 <= b_1, b_2 <= 9 and a_1b_1 + a_2b_2 = n
rocky flower
#

for example (2,1) works

graceful dust
#

produce all values of n?

#

i thought we were fixing n and counting the pairs (a_1,a_2)

rocky flower
#

i want to find all (a_1,a_2) pairs such that there exist b_i's which are integers between 0-9 that produce all values of n between 0 and 9(a_1+a_2)

#

so i want to fix (a_1, a_2) and see if it produces all values of n within the range by selecting b_i each time

graceful dust
#

oh ok i might get it now

rocky flower
#

oh ok

graceful dust
#

let me try again

rocky flower
#

sorry .-.

graceful dust
#

lol dw

rocky flower
graceful dust
#

which pairs of integers (a_1,a_2) with 0 <= a_1, a_2 <= 9 have the following property?
for all integers n with 0<=n<=9(a_1+a_2), there exist integers b_1, b_2 with 0 <= b_1, b_2 <= 9 and a_1b_1 + a_2b_2 = n

graceful dust
rocky flower
#

thank you

graceful dust
#

ok so for the problem…

#

if a_1 and a_2 are both even and greater than 0, they don’t have the property

#

see why?

rocky flower
#

yes i see why

#

because they only produce even numbers

graceful dust
#

yep

#

(0,1) and (1,0) have the property but if one of them is 0 and the other is greater than 1 then they don’t right?

#

(0,0) has it

graceful dust
#

ok anything with 0 taken care of

graceful dust
#

still lots left

rocky flower
#

yeah

graceful dust
#

well actually if a_1 and a_2 aren’t small it shouldn’t be possible to get small n’s right?

rocky flower
#

i was thinking that if a_1 divides a_2 or the other way round, it wouldnt work as well, right?

graceful dust
#

yea if they are both 2 or greater you can’t get n = 1

graceful dust
rocky flower
graceful dust
#

that covers a lot then

#

what’s left?

#

one of a_1,a_2 are 1 and the other is at least 1?

#

i think we got everything else

rocky flower
#

yes, i think so

graceful dust
#

(1,1) has the property me thinks

#

any pair with a 1 has it prolly

rocky flower
#

hmmm, could we check

graceful dust
#

kinda like that other problem

rocky flower
#

yeah

graceful dust
#

say a_1 = 1 and a_2 is whatever. we can get 0, a_2, 2*a_2, 3*a_2, …, 9*a_2 by setting b_1 = 0 and ranging b_2 over 0 through 9

#

and we can fill in the gaps with 1*b_1

rocky flower
#

yes this should make sense

graceful dust
#

so i think my answer is:
(a_1,a_2) has the property if and only if [[a_1 = 1 or a_2 = 1] or [a_1 = a_2 = 0]]

rocky flower
#

yes, that should be the answer i think too

#

i also have a similar question

#

which pairs of integers (a_1,a_2,a_3) with 0 <= a_1, a_2,a_3 <= 9 have the following property?
for all integers n with 0<=n<=9(a_1+a_2+a_3), there exist integers b_1, b_2 with 0 <= b_1, b_2, b_3 <= 9 and a_1b_1 + a_2b_2 +a_3b_3 = n

graceful dust
rocky flower
#

omg, so sorry .-.

graceful dust
#

lol

#

so if i’m understanding you’ve been wanting to generalize your problem from earlier this whole time KEK

rocky flower
graceful dust
#

having a 1 might be the key thing no matter how many terms

rocky flower
#

i thought that by doing smaller cases, it would be easy to generalise through intuition

graceful dust
#

yea that’s good

rocky flower
graceful dust
#

you need a 1 to get the = n condition when n = 1

#

and if you have a 1, you can “fill in the gaps”

graceful dust
#

and i thiiiiiink it generalizes

rocky flower
rocky flower
rocky flower
graceful dust
#

should be able to, you can build up to 9(a_2 + a_3 + … + a_k) by increasing the b_i’s one by one and and the gaps will be no bigger than 9

#

with a_1 = 1 ig i should say

rocky flower
#

hmmm, thats interesting

#

now finally could we count the number of pairs that do exist

graceful dust
#

so if there are k terms, we want the number of k-tuples (a_1, a_2, …, a_k) that have at least one 1

rocky flower
graceful dust
#

plus an extra one for all 0s case

rocky flower
#

ok

graceful dust
#

0s basically just make it so that there are fewer terms

#

might be best to assume all coordinates are nonzero

#

so that we actually have k terms

#

yea i think it’s better this way and doesn’t change any results found earlier

rocky flower
#

ok

graceful dust
#

b_i’s can be 0 but make the a_i’s nonzero

graceful dust
#

first coordinate has 9 options (1 through 9), second has 9 etc

rocky flower
#

yes

graceful dust
#

there are 8^k that have no 1s right

#

so 9^k - 8^k that have at least one 1

rocky flower
#

wait, is it fine if you could list all the tuples that work for k=2

#

im still a bit confused

graceful dust
#

(1,1), (1,2), …, (1,9)
(2,1), (3,1), …, (9,1)

#

top list has 9, bottom has 8

rocky flower
#

how about (0,0)?

graceful dust
#

i’m gonna say we should ignore it

#

that’s like having 0 terms

rocky flower
#

yeah

graceful dust
#

and (0,1) is like having only 1 term

rocky flower
#

hmmm true

graceful dust
#

it just depends what you wanna count really

#

up to you

rocky flower
#

i dont mind including the (0,0), (0,1) and (1,0)

#

even if it is extraneous

graceful dust
#

alright

#

i’ll revise then

rocky flower
#

so for k=2 it would be 20 possible tuples i think

graceful dust
#

(0,0)
(1,0), (1,1), (1,2), …, (1,9)
(0,1), (2,1), (3,1), …, (9,1)

#

agreed

#

1+10+9

graceful dust
#

the + 1 being the all 0 tuple

#

agrees with our answer for k = 2

rocky flower
#

wait, could u list the number of tuples for k=3

graceful dust
#

,calc 10^3 - 9^3 + 1

potent lotusBOT
#

Result:

272
graceful dust
rocky flower
#

sorry, could u tell me the condition again

#

i just need to check with you

graceful dust
#

what condition?

rocky flower
#

was it that all a_i=0 or one of a_i=1 and the others could be anything

graceful dust
#

a tuple has the property iff at least one coordinate is 1, or they are all 0

#

so yes

rocky flower
#

oh my bad, sorry .-.

graceful dust
#

they get hard to list nicely because you can have various amounts of 1s

rocky flower
#

yeah, i should have known

graceful dust
#

for k = 3 they take the forms
0 0 0
1 _ _
_ 1 _
_ _ 1
1 1 _
_ 1 1
1 _ 1
1 1 1
with the empty slots being not 1

#

darn

rocky flower
#

for k=3, i was thinking of (0,0,0), then the number of (1,blank,blank) tuples which in total is 3*100+1 minus the number of repeats

graceful dust
rocky flower
graceful dust
#

no problemo

#

i’m amazed your problem had a clean answer

rocky flower
#

yes, im amazed by it too

rocky flower
graceful dust
#

yep!

graceful dust
rocky flower
#

oh ok i think i get it now

rocky flower
#

your formula should be correct

graceful dust
#

just gets a little messy with all the ways to have 1s with larger k

rocky flower
#

thank you so much for your help!

graceful dust
rocky flower
#

.close

calm coralBOT
#
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calm coralBOT
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wary sun
#

how do i do this

calm coralBOT
tiny monolith
#

1,2,3,3
1,1,2,3

jagged latch
#

what have you tried

calm coralBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

tiny monolith
#

that should be the main columns

jagged latch
#

mb

#

ideleted it

wary sun
#

then put them in

#

and idk how that is helping

jagged latch
#

ig we could do it using basic combinatorics

tiny monolith
wary sun
tiny monolith
#

one would be horizontal and the other vertical

wary sun
#

oooo

tiny monolith
#

move the column to the left

wary sun
#

ohk

tiny monolith
#

you should have a 4 by 4 table to put in stuff

wary sun
#

mhm

#

so now I multiply?

tiny monolith
#

no, add them

wary sun
#

ohk

jagged latch
#

basically try adding each of the numbers from the corressponding columns

wary sun
#

like this?

jagged latch
#

yep

#

now count the number of sums which are more than 3

wary sun
#

alrr

tiny monolith
#

you want to see what proportion of those are 4 or more

jagged latch
#

now do 11/16

#

thats ur answer

wary sun
#

oooo

jagged latch
#

since 16 is the total number of sums

wary sun
#

thanks bros

jagged latch
#

and 11 is the total number of sums more than 3

wary sun
#

yeah

tiny monolith
wary sun
#

thank you both!

jagged latch
#

!done

calm coralBOT
#

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tiny monolith
calm coralBOT
#

@wary sun Has your question been resolved?

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brittle crow
#

how do i find the domain and range of a circle

brittle crow
empty quail
#

do you see that 9 is a perfect square root

#

hint: the domain and range for any circle is always becomes the same

#

in x^2+y^2=9, as x^2 and y^2 both are positive and hence cannot take values beyond 9

#

so what do you think the domain and range will be for this function

brittle crow
#

[-3, 3]

#

for both domain and range

#

🙏

empty quail
#

correct

calm coralBOT
#

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brittle crow
calm coralBOT
brittle crow
#

how do i solve this

#

wait no sorry

#

how do i find the domain and range

#

ive tried already and got it wrong (i got solution)

#

my answer was

#

domain: $(-\infty, 0]$

potent lotusBOT
brittle crow
#

range: $[2, \infty)$

potent lotusBOT
brittle crow
#

but thats wrong

#

so how do i do it

#

uh

#

youre in my channel lol

fleet raptor
#

Domain should be x less than or equal to 2

#

Range is 0 to infinity

raw dirge
#

try using derivatives to find range

raw dirge
calm coralBOT
fleet raptor
#

Domain is all the values x can take on: ask yourself what x values result in a math error? what x values work

#

Range is all the values y can take on

#

The square root sign is important here, what restrictions does that cause?

raw dirge
#

yes

calm coralBOT
#

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autumn pollen
#

Hello

calm coralBOT
autumn pollen
#

I am confused as too why you can use the upper bound when proving that a function is an little of another function

#

this is what i am in particular talking about

#

here they are showing that the limit of the upper bound approaches 0

#

and that somehow shows that the original must also be 0

#

?

#

i tried showing that this works with the epsilon definition of the little o definition

#

but so far, it doesn't make much sense

#

any help would be great

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@autumn pollen Has your question been resolved?

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void frost
void frost
#

.close

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zealous slate
calm coralBOT
zealous slate
#

help

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.close

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native zealot
#

$$ Why is w_1= (2 1), I get why mu = 1/5, but when i input it in the equation, it doesn't give me these scalars $

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potent lotusBOT
#

snow
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

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regal rain
#

"A series $\sum_{}^{} a_n$ converges if its sequence ${a_n}$ converges. "

Why is this the case? Taking $a_n = 2 - (1/n^2)$ as example, doesn't this sequence converge because its terms approach 2 as n approaches infinity? But the series are definitely divergent right?

potent lotusBOT
#

seinng

marsh agate
#

it's moreso
series converges only if sequence converges to 0

regal rain
marsh agate
#

not iff

dull wagon
#

if the sequence doesn't converge to 0, the series doesn't converge

regal rain
#

oh oops, not the other way around

marsh agate
#

for convergence of the series, the sequence must go to 0
But it is not a sufficient condition

regal rain
#

alrightt thank you!! that answers my question

#

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celest flower
calm coralBOT
celest flower
#

how can i calculate the height

calm coralBOT
#

@celest flower Has your question been resolved?

calm coralBOT
#

@celest flower Has your question been resolved?

calm coralBOT
#

@celest flower Has your question been resolved?

calm coralBOT
#

@celest flower Has your question been resolved?

potent smelt
#

@celest flower your image is different from the question. I'm going to answer the question rather than the image.

#

Also there does not seem to actually be a sought value.

#

Please clarify

celest flower
#

what

#

the guy on the floor is 175 tall

potent smelt
#

Yes

#

And we have two angles, so we can make two right triangles

#

But if we want to know, for instance, how high up the balcony is, we would need to also know how far away Romeo is from the wall

celest flower
#

yes alpha is 33,7degree and beta is 46,8 degree

potent smelt
#

Well, hmmm

#

So actually thinking about it you might be able to figure it out

#

So your first triangle is the 33.7 degree one.

celest flower
potent smelt
#

Let the base of the triangle be b

#

This base is shared between both triangles

#

Let the height of the shorter triangle be h.

#

This means the height of the higher triangle is h + 1.2

celest flower
#

yes

potent smelt
#

So we have

tan 33.7 = h/b
tan 46.8 = (h+1.2)/b

celest flower
#

yes

potent smelt
#

You can solve these two equations simultaneously for h and b

#

And your answer is h + 1.75, the height of the bottom of the balcony, plus the offset from Romeo's eyes

celest flower
#

you mean equaation system

potent smelt
#

Yes

celest flower
#

ok i'll try it brb

#

$tan(33,7) = h/b \ b = \frac{h}{tan(33,7)} \ tan(46,8) = \frac{h + 1,2}{\frac{h}{tan(33,79)}}$

#

like this?

potent lotusBOT
celest flower
#

@potent smelt

potent smelt
#

Ok, you should be able to solve that for h.

celest flower
potent lotusBOT
celest flower
#

but sadly this is false

#

oh wait

#

the man

#

i come to 3,78m the solution book says 3,760m

celest flower
potent smelt
#

This is close enough, the errors are in the second decimal place and likely due to rounding

celest flower
#

alr thanks buddy

calm coralBOT
#

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languid vine
calm coralBOT
languid vine
#

please help with 2😭

#

something with legrange error??

#

<@&286206848099549185>

#

😔

calm coralBOT
#

@languid vine Has your question been resolved?

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@languid vine Has your question been resolved?

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@languid vine Has your question been resolved?

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safe moss
#

Can someone please explain me descartes' Rules of Signs and Upper and Lower bounds theorem

safe moss
#

I dont understand anything from these theorems theyre so complicated

#

like a simple explanation and an error works fine

#

Explanations of the book

#

ik this is like the 3rd time im aaking someone to describe some theorems but i just cant do them and i need to do them im sorry

wide jewel
# safe moss

Variations in signs, which means if the sign is different than the previous one

#

The number of variations is equals to the number of positive zeroes

#

And for negative zeroes its same but with p(-x)

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#

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tall kindle
#

is this answer wrong

calm coralBOT
tall kindle
#

I got the same exact answer except that the exponent is 2 in denomentrator

patent tundra
#

!show

calm coralBOT
#

Show your work, and if possible, explain where you are stuck.

#

@tall kindle Has your question been resolved?

quaint sphinx
quaint sphinx
patent tundra
#

yes but it can be useful to see their work to do that

quaint sphinx
#

i mean not rly

#

if u can do the problem urself it's a simple yes/no question

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sonic raft
#

Guys, i need help to understand this math topic, it called progressions (this is the teory)

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sonic raft
#

nope

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blissful garnet
#

How can i find sin and cos of alpha

calm coralBOT
blissful garnet
#

Alpha is the opposite angle of 6 meters btw

jagged latch
#

!original

calm coralBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

blissful garnet
#

Its in portuguese

#

Ill translate

#

In an ABC triangle, which AC is 8m, BC is 6m, opposite angle of 8m is alpha, opposite angle of 6m is beta, and beta equals 60°, find senalpha and cosalpha

surreal patio
#

in ur diagram, opposite angle of 8m is beta

blissful garnet
#

Hmmm

#

Sorry

#

Let me fix the triangle then

surreal patio
#

never heard the term sen before

potent lotusBOT
#

JustToPro

blissful garnet
#

Sen is sin

surreal patio
#

ah ok

blissful garnet
#

In portuguese its seno so it turns into sen

surreal patio
#

so ig we first need to find alpha , what do u think we can do to find alpha?

blissful garnet
#

Law of sines

#

a/sena= b/senb=c/senc= 2R

surreal patio
#

yes

#

use that to find alpha and then u can find sinalpha and cos alpha easily

blissful garnet
#

Or did i multiply in a cross the wrong way

surreal patio
#

seems good

blissful garnet
#

Then sen is 4.sqrt3/6

surreal patio
#

yes

blissful garnet
#

Oh so i simplify by 2

#

2.sqrt3/3

#

How do i find sin and cos now

surreal patio
#

well u already have sin alpha

#

sen alpha = 2 sqrt3 / 3 , u found that out

blissful garnet
#

Yes but usually i do it by seeing like sin is 60 degress cos is 30 degrees

#

But with this i dont know the angle

surreal patio
#

u only need to find sin alpha

blissful garnet
#

Sin30=cos60

surreal patio
#

not the angle

#

if they wanted to find angle then they would have said to find alpha

blissful garnet
#

Cosalpha

surreal patio
#

u can find cos 2 ways

  1. taking sin inverse to get alpha then then finding cos alpha
  2. sin^2alpha + cos^2 alpha = 1
    OR cosalpha = sqrt{1 - sin^2 alpha)
blissful garnet
#

We actually learned the second way

#

Sinx squared + cosx squared= 1

#

But i actually didnt think about it

surreal patio
#

both ways give same answer

blissful garnet
#

Yeah i just didnt remember how to apply it

#

Would 2.sqrt3/3 squared be 12/9?

surreal patio
#

yes

#

u can simplify that a bit btw

blissful garnet
#

4/3

#

So 4/3. cosalpha squared=1

#

But it is already over 1

#

4/3

#

So how do i do i do it

surreal patio
#

4/3 + cosalpha squared=1

#

cosalpha squared=1 - 4/3

#

cos alpha can be negative

blissful garnet
#

Oh

surreal patio
#

this means that the angle lies in quadrant number 2 (if u learnt about those)

blissful garnet
#

But wait

#

How does cos alpha squared turn into negative 1/3

#

We dont even know imaginary numbers rn

surreal patio
#

wait

blissful garnet
#

I think the triangle was right

#

The other one

surreal patio
#

,w arcsin ((2 sqrt3) / 3)

blissful garnet
#

If we used the other triangle

#

Cos alpha would be 0.592014313

#

I think its the right answer

surreal patio
#

the other triangle isnt correct tho

blissful garnet
#

It is i think

surreal patio
#

not according to the question

blissful garnet
#

A opposite b c

#

What is wrong about it (not trying to be mean i just didnt see something wrong)

surreal patio
#

beta is opposite to 6m

blissful garnet
#

The -- Abovee the letters is a line

#

The ^ on the letter means opposite of the side

#

So alpha is in opposite angle of side a

surreal patio
#

u translated it wrong

blissful garnet
#

Oh truee

#

Im sorry

surreal patio
blissful garnet
#

Ok

#

But i got it now

surreal patio
#

what u said was opposite angle of 6m is beta

blissful garnet
#

Yes

surreal patio
#

btw i gtg

#

!done

calm coralBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

blissful garnet
#

With the correct triangle the answer is cosalpha= 0.592014313

#

.close

calm coralBOT
#
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surreal patio
blissful garnet
#

Thanks

#

.close

calm coralBOT
#
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timid leaf
calm coralBOT
timid leaf
#

I dont know where to go next.

#

But this is the final answer

surreal patio
#

both are same

#

they just factored out and simplied it further

timid leaf
#

Oh so they factored out the 2? And e^sin2x?

surreal patio
# timid leaf

here u can factor out 2 , e^(sin2x) and ln(cos2x) from the numerator which cancels with 1 of the ln(cos2x) in denominator

timid leaf
#

Huhu i see idk how id see the solution without the final answer hehe

#

Thank you!

surreal patio
calm coralBOT
#

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remote mural
calm coralBOT
remote mural
#

Can someone explain why both 2^n become only one there

spice phoenix
#

you factored the 2^n out

#

2^n (16-2)

remote mural
#

So It is 2^n(14•2)

spice phoenix
#

no

#

for example
AB + AC
you can rewrite this as
A(B + C)

remote mural
#

Can I rewrite that as 14 •2(n+n)?

spice phoenix
#

no

remote mural
#

Do you know a good factoring video I can check?

spice phoenix
#

idk about a good video man maybe ask someone else here or consult your teacher

remote mural