help-42

[calm coral]

Show your work, and if possible, explain where you are stuck.

[vale pond]

just a min

is this right ?

i had an answer key but i lost it so yeah

[rustic osprey]

,w \sum^{n}_{k=1} (2k-1)^2

[vale pond]

also is there a better way to do this

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by civil_service_pigeon

[rustic osprey]

the final answer is right

[vale pond]

oh wait you can do that?

[rustic osprey]

but yeah the typical way is to use your summation formulas - idk of a better way than that

[vale pond]

tysm

[rustic osprey]

yeah you can do that in #bots

,w [your thing]

you can just type

,w sum of (2k-1)^2 from 1 to n

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by civil_service_pigeon

[rustic osprey]

if you don't know latex

[vale pond]

alr tysm for the help

I will close now

.close

[calm coral]

Channel closed

Closed by @vale pond

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rare sleet]

I need help with this question.

[rare sleet]

.close

[calm coral]

Channel closed

Closed by @rare sleet

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sleek wedge]

Need help on this

[grim latch]

By setting the price of adults to x and price of children to y

We get two equations

Solving them might help

[sleek wedge]

How do we solve them?

[grim latch]

Have you learned how to solve equations?

[sleek wedge]

Yeah but I just need a refresher

[grim latch]

Ok

In the first equation

We can simply divide both sides by 50

Therefore x+y=16

Still with me?

[sleek wedge]

Yup

[grim latch]

Now in second part, we sub in our values

Since x+y=16, 65x+65y=16*65

[sleek wedge]

Alr

[grim latch]

=1050

However, we have an extra 10 children here

And the price is now 1100

So we know 10 children must cost 50

And you can continue from here

[sleek wedge]

Ok thanks

.close

[calm coral]

Channel closed

Closed by @sleek wedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brazen jackal]

I tried finding the lambda value which I found -3 and 2
But after following YouTube tutorial I am completely lost 💀

[brazen jackal]

Nevermind

.close

[calm coral]

Channel closed

Closed by @brazen jackal

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic falcon]

Could anyone check my proof for this problem please?

[leaden thunder]

this sentence is sloppy

[graceful dust]

yea it's all wrong

[exotic falcon]

Really

I mean we can interchange the limit of the sum with the limit of the integral

because the series converges uniformly

Is it actually wrong?

[leaden thunder]

typo here

[exotic falcon]

ty, should be x(k+1) I think

kx+x

same thing

[exotic falcon]

How do you recommend I say this then?

[graceful dust]

i'm just doing some hilarious trolling i didn't even look at it

[exotic falcon]

We can interchange integral with the infinite sum because it converges uniformly?

[exotic falcon]

Normally I would've figured but riemann was also noting some things so I got legitimately worried

[leaden thunder]

i'm not convinced you've proven the new series with sin(x) multiplying converges uniformly

[exotic falcon]

if the original series converges uniformly

which was the assumption made

[exotic falcon]

then multiplying both sides by sin(x)

is surely equality

[solar spruce]

actually this isnt true

[leaden thunder]

justified by what

[exotic falcon]

sin(x) is not dependent on k

so we can interchange it in the limit

if sin(x) = lim k-> inf (thing) uniformly

(by assumption)

then sin(x) sin(x) = sin(x) lim k-> inf (thing) uniformly

and then we may bring the sin(x) inside the k limit

Is my justification

[leaden thunder]

yea try writing that up more carefully

[leaden thunder]

because this sentence isn't rigorous enough

[exotic falcon]

Okay I'll add a sentence there and at the beginning then

Thanks @leaden thunder

.close

[calm coral]

Channel closed

Closed by @exotic falcon

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[calm coral]

@remote mural Has your question been resolved?

[remote mural]

.close

[calm coral]

Channel closed

Closed by @sick ivy

Use .reopen if this was a mistake.

[remote mural]

.reopen

[calm coral]

✅

[remote mural]

<@&286206848099549185>

[modern peak]

!1c

[calm coral]

Please stick to your channel.

[modern peak]

!noclopen

[calm coral]

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

[modern peak]

SNIPED

[remote mural]

Ok

[modern peak]

this is the third time ;-;

[remote mural]

What should I do now lol

[modern peak]

wait

and resend your problem

wait until 12:26; if nobody responds, ping

[remote mural]

Here?

[modern peak]

yae

*yea

[undone marlin]

Which part did you need help with?

[remote mural]

All

[undone marlin]

For question a, do you know the definition of a conservative vector field?

[remote mural]

No can u give me a rough idea...like I have to submit this in 15mins

Or I don't meet the attendance criteria

And gotta leave the course

[undone marlin]

If F is conservative, the following must be true:

[remote mural]

Pls

[potent lotus]

Αρχιμήδης

[remote mural]

Ok

[undone marlin]

Where f is the potential function.

[remote mural]

Ok

Phi?

[undone marlin]

To determine if this is true, you must take the partial derivative of P with respect to y, and the partial derivative of Q with respect to y of the following.

[potent lotus]

Αρχιμήδης

[remote mural]

What are p q

Ohh like expansion of F

[undone marlin]

P is the function in the i direction, and Q is the function in the j direction.

[remote mural]

Ok

Ok

Wait how do I evaluate potential function

[undone marlin]

Integration, either integrate P wrt x, or Q wrt y.

Assuming it is conservative, integrating P will give:

[potent lotus]

Αρχιμήδης

[undone marlin]

Then you have to fund your function h

[undone marlin]

And the reason we have a function of y is because we're working with partial derivatives.

[undone marlin]

I also forgot to mention, if it is conservative, the partial derivatives should equal.

[remote mural]

Nvm bro wrong question

Lol

Thanks

[undone marlin]

No worries

[remote mural]

.close

[calm coral]

Channel closed

Closed by @sick ivy

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading valve]

could anybody assist me please

[fading valve]

can’t work out p x q = <0 , 0 , r>

<@&286206848099549185>

[modern peak]

!15m

[calm coral]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[tawny idol]

whats ur rank

[fading valve]

what do y mean

in what

[tawny idol]

in val

[fading valve]

Like Iron 3 i think

[tawny idol]

NO WAYYY

[fading valve]

i went up a lot recently

[tawny idol]

thats insane

good job

[fading valve]

<@&286206848099549185>

<@&286206848099549185>

[modern peak]

!15m

[calm coral]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[modern peak]

please don't ping us several times in only a few minutes.

[fading valve]

yeah sorry i thought it was fine because i posted my q25 mins ago

[rough warren]

Isn't that yr college assignment

[fading valve]

no it’s not it’s like homework

u get weekly homework

<@&286206848099549185>

[calm coral]

@fading valve Has your question been resolved?

[fading valve]

<@&286206848099549185>

wait nvm worked it out

.close

[calm coral]

Channel closed

Closed by @fading valve

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heady thistle]

Would they expect me to have the solution for F aswell?

[heady thistle]

.close

[calm coral]

Channel closed

Closed by @heady thistle

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[remote mural]

for

[remote mural]

how do u derive those parameterisations for the unit vectors?

[tender coral]

You're talking about polar coordinates?

[remote mural]

yes

for $\vj r = A_r\vc*r$ i managed to recover a formula for $A_r$

[remote mural]

but i cant recover the above

,w cross product (cos(theta), sin(theta), 0) and (0,0,-1)

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by qylooo

[remote mural]

taking the cross product with -k does get me A_theta if i know the first

so thats fine

so i guess i just need to know how to find the first

[tender coral]

In Polar coordinates you make the transformation (r*cos theta, r*sin theta), the two unit vectors are the partial derivatives and then we norm them

[remote mural]

the two unit vectors are the partial derivatives

wait what

[tender coral]

If you take the partial derivative of this with respect to x you get u_r

If you take the partial derivative with respect to theta you get e_theta*r and you norm it to get rid of the r

[remote mural]

ok so just to be clear

we have [
\vj r(r, \phi) = r\6\cos\phi\vc*\imath + r\6\sin\phi\vc*\jmath
]
by definition of polar coordinates

[remote mural]

the partial derivatives will point at the direction of the unit vectors

so

[
\pdv[\vj r]r = \6\cos\phi\vc*\imath + \6\sin\phi\vc*\jmath \
\pdv[\vj r]\phi = -r\6\sin\phi\vc*\imath + r\6\cos\phi\vc*\jmath
]

[tender coral]

There's an r missing in the line below

[remote mural]

yeah thank you

so

taking the norm

first is just 1

so the unit vector is the same

the second will be r

assuming the positive case

divide by r and it gets u that

gee neat

okay thanks a lot!

.close

[calm coral]

Channel closed

Closed by @silent flower

Use .reopen if this was a mistake.

[tender coral]

You're welcome

The same trick works for cylinder and spherical coordinates, too

[remote mural]

yeah thats super helpful actually

[tender coral]

Yes, especially if you are studying physics with maths 😂

[remote mural]

yeah thats what imd oing LOL

[tender coral]

But tbf, this trick does only work for like spheres or circles. If you parametrized a parabola or sth the partial derivatives wouldn't be orthogonal

[remote mural]

oh right thats the catch

is there like anything that lets u derive them

more general and by definition maybe

[tender coral]

I mean you have to define one of those as a unit vector. Let's say you fix e_r as it is. Then you can construct e_theta as the unit vector orthogonal to e_r

But there would still be two possibilities

So even if you defined e_r you wouldn't even get a unique choice of e_theta

[remote mural]

i mean assuming we are following a right hand coordinate system

[remote mural]

then e_theta would just be this i guess?

[tender coral]

Then theta is unique

[remote mural]

but yeah alright

much appreciated!

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing coyote]

$\sqrt{9-8\cos\left(40\degree\right)}=a+b\sec\left(40\right)$

[potent lotus]

Why am. I here
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[blazing coyote]

$\sqrt{9-8\cos\left(40\degree\right)}=a+b\sec\left(40\degree\right)$

[potent lotus]

Why am. I here
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[blazing coyote]

it should be 40 deg

find |a+b| if a and b are both rational

I thought of squaring it first

not sure what to do from there

$9-8\cos\left(40\degree\right)=a^2+b^2\sec^2\left(40\degree\right)+2ab\sec\left(40\right)$

[potent lotus]

Why am. I here
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[blazing coyote]

I mean I could find 40deg

but it will be rather ugly IMO

[full niche]

u can compare both the sides

like u do for complex numbers

[blazing coyote]

why would that work here

both a and b are rational

unlike in complex numbers where one part is imaginary

[full niche]

Im not toally sure

but here

it might work

like a^2 = 9

and b^2 + 2ab = -8

[blazing coyote]

so a=+/-3

,w b^2+6b=-8

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[blazing coyote]

hmm

[full niche]

a^2 = 9 has two values as well

so b will have 4 values

[blazing coyote]

yeah, trying that now

there are options btw

1/2

3/2

2

3

[full niche]

what exactly u gotta find

a and b?

[blazing coyote]

|a+b|

[full niche]

check the combinations then

[blazing coyote]

hmm, if b=-3

[full niche]

u mean a

[blazing coyote]

then ,w b^2-6b=-8

[blazing coyote]

yeah, my bad

,w b^2-6b=-8

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[full niche]

,w b^2-6b=-8

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ___snowflake

[blazing coyote]

hmm, that gives |a+b|=1

which isn't any of the options

[full niche]

WAIT

Bro

[full niche]

I didnt notice

that its cos theta on one side

and sec theta on the other side

we cant compare them like that-

[blazing coyote]

so I have to evlavuvate cos(40)?

[full niche]

lemme try thinking of something else wiat

how about u let cos theta be a

[blazing coyote]

hmm, maybe I can factor out 9 from teh sq. root

[full niche]

I mean x

no no

let it be x

[blazing coyote]

ok

so then solve for x, I take it?

[full niche]

Yeah

that should most probably work

cos theta = x

sec theta = 1/x

that should give u a cubic polynomial

[blazing coyote]

cos(40)=x , where x is a constant, right?

hmm, so 9-8x=a^2+b^2x^2+2abx

that looks nasty TBH

[full niche]

just ask the thing

,w 8t^3 + (a^2 -9)t^2 + 2abt + b^2 = 0

[potent lotus]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by ___snowflake

[full niche]

.-.

how to put it

[blazing coyote]

,w 9-8x=a^2+b^2x^2+2abx

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[blazing coyote]

where did the cube come from

[full niche]

obv its gonna be a cubic

wait how did u not get a cube

sec theta gonna be 1/x broo

[blazing coyote]

ah

1/x

got it

[full niche]

yeahh

[blazing coyote]

,w 9-8x =(a+b/x)^2

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[full niche]

OH MY WTH

lemme try comparing wait

but I most probably think that should solve it

we just need to solve the thing

[blazing coyote]

I mean it would probably be easier to find cos(40)

cos(40)=cos(30+10)

cos(10)=cos(30/3)

,w cos(40deg)

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[blazing coyote]

,w cos(10deg)

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by physicsrocks

[full niche]

what sorta aproximation is that

[blazing coyote]

decimal

so now I have to solve

/sqrt{3}/2= 4cos^3(x)-3cos(x)

nah

that won't wokr

*work

[full niche]

the a part is 100% correct

a = 3 or -3

[blazing coyote]

8cos(40)=b/cos(40)

finding b still requires the value of b though

[full niche]

thats funny

finding b requiring a value of b

[blazing coyote]

wdym

nah, I;ll still get an uglu cubic

[full niche]

wiat a min

I found something realting

[full niche]

u see the cubic

we know that a = 9

I mean 3

for a being 3

t^2 = 0

so b = 0

[blazing coyote]

so |a+b|=3

[full niche]

Yessir

[blazing coyote]

my book says the answer is 2

wait, let me check the offical answer key(This is from a past exam)

[full niche]

ok then use cos3 theta

thats the final atttempt

3-1

isnt it

[blazing coyote]

3-1

where did the 1 come from?

[full niche]

we can

compare

I used that even in seq and series complex num trigo etc

I mentioned seq and series and trigo as well

[full niche]

y oyo

yo

cos(3theta) where theta = 40

use that

it solved it

[blazing coyote]

thought of that

but the cubic is ugly

very ugly

[full niche]

u want the justification?

[blazing coyote]

$\ -\frac{\sqrt{3}}{2}=4x^3-3x$

[full niche]

cos ( 120 ) = - sin 30

[potent lotus]

Why am. I here

[full niche]

do u agree

wait

what

[blazing coyote]

yeah, I know why, I'm just trying to figure out how to solve the cubuc

[full niche]

then use the formula

we know the value of sin 30

use the cos 3 theta

if u know that

[blazing coyote]

cos(3tehta)=4cos^3(theta)-3cos(theta)

[full niche]

so use it

4cos3*40 – 3cos 40 = -1/2

[blazing coyote]

yeah, the cubic isn't solvable

[full niche]

dont change it

[blazing coyote]

i mean Vitaes formula does exist

so I guess I use that?

[full niche]

Bro I already solved it

Im trying not to give direct answer

4cos340 – 3cos 40 = -1/2 compare with 8x^3 + x^2(a^2-9) + 2axb + b^2 = 0

[blazing coyote]

ah, ok, so $8x^3=4cos^3(40)$

[potent lotus]

Why am. I here

[blazing coyote]

wait, this gives b=0

which isn't correct

[full niche]

how did u do that-

[blazing coyote]

2axb=0

right?

also,I'm not really sure you can just compare the expressions like this

I'm not convinced

[full niche]

lemme send u a pic

compare these and tell me

what u getting

try once again

cos^2 term is zer in the other equation

so a^2 - 9 = 0

justifies?

[blazing coyote]

,rotate

[blazing coyote]

,rotate

rcw

,rcw

[full niche]

yeah

so u see it now

8cos^3 40 is same

[blazing coyote]

yeah, pretty much, snowflake suggested comparing both sides

[full niche]

b^2 is the only constant so b^2 = 1

[blazing coyote]

I;m thinking, just a him

that sort of makes sense

yes

so b=-1

[full niche]

b = +-1
a = +-3

[blazing coyote]

got it, thanks!

[full niche]

Man That was tuff

yeah now what do u mean

[full niche]

and what was that other formula u mentioned

this was my way of solving it

it took ridiculous amount of tries tho

I have no idea what that is

[blazing coyote]

that would require solving a bunch of simultaneous equations

[full niche]

is my method harder than that

?

then probably I might learn vietas as well

at first I thought it was cos x on both sides

It got me whole wrong

That was my fault

not reading the question properly

[blazing coyote]

vitaes is basically the relation between the roots and the coefficent of a polynomial

[full niche]

well yeha I know that

alpha + beta = -b/a

alpha*beta = c/a

[blazing coyote]

That can be extended for an nth degree polynomial

[full niche]

we learned it in qudratic

yeah but we learnt it first in quadratic

its all about the roots

[blazing coyote]

why do we discard b=1 though

[full niche]

theres only 1 term without cos theta in the whole equation

meaning only 1 constant term

and in the second equation as well theres only 1 constant term which is 1*

so b^2 = 1

[blazing coyote]

ah, ok

got it

thanks

[full niche]

Great

Np

[blazing coyote]

I'll close this now?

[full niche]

Yeah

[blazing coyote]

.close

[calm coral]

Channel closed

Closed by @blazing coyote

Use .reopen if this was a mistake.

[blazing coyote]

thanksa again!

[full niche]

Time to ask my question now

Im stuck hard lol

[blazing coyote]

got it, thanks!

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry copper]

Yoo

[wintry copper]

I need help

Determine the vertex and the direction of opening for cach quadrau
function. Then state the number of zeros.

2x² - 3x = x² + 7x

[calm coral]

@wintry copper Has your question been resolved?

[wintry copper]

No

[calm coral]

@wintry copper Has your question been resolved?

[white hull]

use this formula for the vertex:

[white hull]

the number of zeros is equal to the highest power of x (im excluding complex zeros as an answer since i dont think you guys have done that yet)

[wintry copper]

Ok I will

Thanks

[calm coral]

@wintry copper Has your question been resolved?

[calm coral]

@wintry copper Has your question been resolved?

[calm coral]

Channel closed

Closed by @wintry copper

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan fox]

How do I figure this out

<@&286206848099549185>

[carmine temple]

What do you need?

[cyan fox]

The answer

[calm coral]

@cyan fox Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[abstract hatch]

can anyone help with this please

[calm coral]

@abstract hatch Has your question been resolved?

[abstract hatch]

??

please

[abstract hatch]

I did it but not sure if its correct

lemme share my solution

[calm coral]

@abstract hatch Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solar steeple]

Could someone explain how to do these problems properly/where I lost points?

[pallid halo]

second line seems wrong, how did you get +16u

[halcyon rock]

I'll go through one with you

3x here is not a constant

over here

I think you didn't show du = dx and stuff

also you can't just drop "du"

in the first line

the rest is just formatting issues

you should use the bar when possible

@solar steeple

[solar steeple]

so when do i add the bar

[halcyon rock]

when ur evaluating an integral across bounds given the anti derivative

[solar steeple]

so on every line?

[halcyon rock]

these bars

[solar steeple]

ik

but do i always add it at every step basically?

[halcyon rock]

only when you evaluate it

so here

[solar steeple]

o just there ok i see

[halcyon rock]

mhm overall not too bad

just remember can't pull out stuff that's not constant

[solar steeple]

so here

[halcyon rock]

and be careful with dropping du and stuff

right here

[solar steeple]

wdym

[halcyon rock]

where is "du" here @solar steeple

[solar steeple]

oh wait i just put it at the end

like that times du

but i didnt

[halcyon rock]

mhm

[solar steeple]

and i should put the bar on steps 4. and 5. here?

[halcyon rock]

you don't need the bars on indefinite integrals

[calm coral]

@solar steeple Has your question been resolved?

Channel closed

Closed by @solar steeple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solar bolt]

for part b, would a normal vector to the y-axis be <1,0,0>?

[solar bolt]

so could I use that to write the equation of the plane

[pallid halo]

orthogonal to the y axis means, use a vector pointing in the y direction as your normal vector

<1,0,0> doesn't point in the y direction

[calm coral]

@solar bolt Has your question been resolved?

[solar bolt]

but don't I have to find a vector that is perpendicular to the y-axis

oh

is it because the point (1,0) is the y-axis

[pallid halo]

no, the plane itself should be perpendicular to the y axis

so the plane's normal vector is parallel to the y axis

a bit confusing admittedly haha

(and not even necessarily true if you go to greater than 3 dimensions)

[solar bolt]

I'm kind of confused

oh wait

I think I get it now

its asking orthogonal to the y-axis but the normal is parallel to it

thats such a weirdly worded question

so would a vector be <0,1,0>?

well the normal vector for the plane be <0,1,0>?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thick mica]

I have a question for all of these problems do we check for absolute convergence first and if it’s divergent we check for conditional convergence?

[thick mica]

In another words if it’s not abs convergent we check for conditional convergence

If it’s abs convergent we are done

[mortal orbit]

yeah that's a way to do it

sometimes the problem will be easier, i.e the series can grossly diverge

[thick mica]

Thank you

.close

[calm coral]

Channel closed

Closed by @thick mica

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid knot]

i think its a am i right

[undone fog]

i would say yes, but B is also technically correct

[lucid knot]

oh no

it can only be one

[undone fog]

hm

because B is saying

(sqrt of 1 * x + sqrt of 49)^2

which is just (x+7)^2

but, since we have a coefficient of 1 at A, taking the square root of a is not needed

option A would be the best one

[lucid knot]

yeah i guess

thanks

i have a couple more

im unsure about

i think this one is a too

[undone fog]

is the function negative or positive?

[terse sigil]

I wouldn't say function, rather the "a" value in the vertex form: y = a(x-h)^2 +k

[undone fog]

yea true

[calm coral]

@lucid knot Has your question been resolved?

[lucid knot]

wait wdym

<@&286206848099549185>

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sinful helm]

This is a stats with calc.

I'm just asking if I set this question up correctly

[calm coral]

@sinful helm Has your question been resolved?

[sinful helm]

.close

[calm coral]

Channel closed

Closed by @sinful helm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic ridge]

how would i do this? im not sure where to start

[calm coral]

@karmic ridge Has your question been resolved?

[quaint sphinx]

is this a problem from a set that's attached to a topic or smth

there exists a fairly easy way to prove this so i'm assuming just use that topic as a reference idea (if it exists)

if not, then my honest recommendation is to just try what you know (imo there's not much to be said here without giving away the approach)

hint that's not really a hint but more like friendly advice: ||you don't want to do anything with trig or excessive pythag calculations; the solution is clean and accessible||

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[smoky fulcrum]

can you help me solve this(i have no idea where to start)

[grim blade]

You can use the fact that the ratio of the bases is the ratio of the areas, if the heights are equal

[smoky fulcrum]

i am sorry but i am in grade 10 i dont know what that means

[kind kraken]

Do you see the relationship here

[smoky fulcrum]

yes ?

[kind kraken]

Do you see the relationship here

[smoky fulcrum]

oh i think i get it

thank you for your help

.close

[calm coral]

Channel closed

Closed by @smoky fulcrum

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[calm coral]

@remote mural Has your question been resolved?

[calm coral]

@remote mural Has your question been resolved?

[calm coral]

@remote mural Has your question been resolved?

[leaden thunder]

!ss

[calm coral]

Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.

[calm coral]

@remote mural Has your question been resolved?

[royal basalt]

, rcw

[calm coral]

@remote mural Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[static berry]

So, I got stuck on this and it's been a little task that me and some others have been tasked with. I have no entire clue where to start and I got 1 more day to somehow complete it.

9^14^22^18^13^28^33^27^30^19^36^38^20^12^16^27^49^13^27^30^14^38^10^19^14^35^45^20^12^23^20^19^17^36^46^14^10^18^14^22^18^17^40^15^18^27^48^10^14^26^39^10^14^38^10^19^16^37^35^27^40^18^14^22^16^25^20^19^36^38^20^13^36^37^30^18^17^39^34^36^24^10^18^16^30^17^46^35^38^33^20^18^14^44^17^40^12^28^30^19^13^20^13^16^30^18^26^23^37^47^38^12^16^23^10^18^14^23^20^12^36^47^15^33^29^24^38^19^30^16^33^30^18^14^44^17^40^18^12^17^45^20^12^16^23^10^19^36^38^27^30^15^34^36^14^38^17^40^19^14^38^14^44^16^20^18^14^44^17^40^15^24^36^23^10^16^33^30^17^44^38^32^18^14^36^46^17^40^13^32^17^33^29^13^25^45^2

[remote mural]

nah

[static berry]

Yeah, I'm confused as hell.

I wish it was a joke..

[storm stirrup]

is that all you were given?

no further instructions?

[static berry]

Nope.

All I was given was.

"Hint: Exponents"

I'm either guessing it's just work it out one by one then power it by the next number or do that but backwards then power 9 by that number.

[leaden thunder]

you're getting trolled

now you're spreading your troll

[static berry]

How?

It's a genuine thing I got asked to do.

[leaden thunder]

#help-17 message

[static berry]

Oh she did one?

My bad..

.close

[calm coral]

Channel closed

Closed by @static berry

Use .reopen if this was a mistake.

[storm stirrup]

lmao

[timid blade]

You could go on using python and waste computing power but it's just a troll

[static berry]

So there's like no way to work it out?

[timid blade]

Its too much computation for a human

[static berry]

I tried python, it gave me 2 answers.

A long one and "1".

Cheers tho!

[karmic sonnet]

1....

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[supple vector]

Anyone who can help

[calm coral]

@supple vector Has your question been resolved?

[supple vector]

No, IT will never be resolved

[calm coral]

@supple vector Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[green night]

shoot this is unclear sec

if (x-3.5)^ = 0 then the + or - shouldn't change after the root right?

here is the og here is the og problem

I factored f(x) and then i'm supposed to determine if it's + or - inbetween each of the roots, but it should be - + - + + and geogebra gives a negative numbers for f(x) when x is between 2 and 3.5

f(x)=2 x^(5)-5 x^(4)-31 x^(3)+92 x^(2)+4 x-112 and here is f(x) directly copied and pasted from geogebra

[calm coral]

@green night Has your question been resolved?

[green night]

hmm

ok I'll give it a shot

I don't have the premium to give it photos haha

wait maybe I can

.close

[calm coral]

Channel closed

Closed by @green night

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silk horizon]

hi

[silk horizon]

i need help

[waxen narwhal]

so

how old ru

[silk horizon]

can someone tell me how to solve this

[silk horizon]

wh

why

[waxen narwhal]

i wanna know

like

doesnt really matter

but i wanna know how to explain

[silk horizon]

14

[waxen narwhal]

this is school math?

[silk horizon]

im stuggling bro my head is going crazy

[silk horizon]

ye

s

[waxen narwhal]

brother just relax

and think for each info that the exercise gave u

lemme help you

so when we have km/h we cant multiply it with minutes

[silk horizon]

right

[waxen narwhal]

so 35 minutes = 7/12 hours

first thing you do at this kind of problems

so what can u do with that info

[silk horizon]

idk

im going crazy

[waxen narwhal]

xD

[silk horizon]

im on 40th question

[waxen narwhal]

oh wait

how many u got to do?

[silk horizon]

6

can you give me the answers for em pls i spent 3 hours on this

promise

[waxen narwhal]

uhm

bro

im 14 too

[silk horizon]

oh

[waxen narwhal]

and if u spent 3 hours on this u would do it

dont lie please 🙂

lemme do it

[silk horizon]

ok

[waxen narwhal]

tag me so when i reopen discord i can find u easily

[silk horizon]

ok

when do you want me to tag you

[waxen narwhal]

now

or nvm

wait

[silk horizon]

ok

[waxen narwhal]

doing it

[undone fog]

So we know that Sanjit drove at 54 km/h from York to Leeds. Now, it took him 35 minutes to drive 42 km from Leeds to Skipton.

[silk horizon]

right

[undone fog]

So

remember that speed is equal to distance over time?

[silk horizon]

yes

[undone fog]

so, your given kilometers per hour

[silk horizon]

yes

[waxen narwhal]

imma wait if u understand by Azar

[undone fog]

so, what do you need to divide in order to get kilometers per hour (hint, its in the units)

[silk horizon]

ummm

by 100

idk

its hard topic for me

[undone fog]

kilometers per hour so it has to be the distance he traveled 35 kilometers divided by what?

remember, our D is 35 kilometers

[waxen narwhal]

35 minutes is it?

[silk horizon]

he traveled 45 km

so you have to do 45km divided by the time right?

[waxen narwhal]

imma just do it

[undone fog]

We already know the speed between York to Leeds, its 54 km/h

[silk horizon]

may you please tell me the answer pls

[undone fog]

we need the speed from leeds to skipton

sorry, i made a mistake, he traveled 42 kilometers from leeds to skipton

so 42/time it took to go to skipton

[silk horizon]

ok

[undone fog]

which is 35 minutes

but, its asking for km per hour

we have minutes

[silk horizon]

so you make it in to an hour

[undone fog]

yes, convert it into a hour

[silk horizon]

0.35?

hour

is that right

[undone fog]

that if a hour is a 100 minutes

[silk horizon]

no wait its not

[undone fog]

but its not

[waxen narwhal]

umz draw a road and write all info

it will be easier for u

[undone fog]

he almost got it

[silk horizon]

is it 0.58

hours

cause you do 35 divided by 60

[undone fog]

good*

[silk horizon]

since there is 60 in 1 hour

thx

[undone fog]

now

you have all the information to get the speed from leeds to skipton

[silk horizon]

so do i add the 2 distances

or no

[undone fog]

you can do that

[waxen narwhal]

total distance/total time

[silk horizon]

i got 150

when i divided

[hoary silo]

This is my solution

[undone fog]

150? boy he must've gotten a few tickets

[waxen narwhal]

better to use things like 45/54

not numbers

i solved it

[silk horizon]

what is it arsi

[waxen narwhal]

well tbh its kinda strange number

lemme check my answer again

[undone fog]

i got the same

[silk horizon]

so wait whats the answer

[hoary silo]

my answer was 61,7km/h

[silk horizon]

let me see if its correct

not right for some reason

[waxen narwhal]

bruh

lemme solve from start

just gimme 7 mins

[hoary silo]

Why, what should be the solution?

[silk horizon]

idk

when i typed the answer in it didnt say correct

[undone fog]

you can get the speed by averaging the speed from york to leeds and the speed from leeds to skipton

[hoary silo]

where do you have to enter the answer, maybe it is a decimal place

[silk horizon]

i wrote 67.8

i mean

61.7

[waxen narwhal]

yooo

im nearly done

im 99% im accurate

cuz numbers arent weird

[silk horizon]

ok

whats the answer pls

[waxen narwhal]

uh

48,78504672897196 try it

lol

or just 49

idk why thats the answer

maybe thats it or im wrong

@silk horizon

[silk horizon]

wrong

[hoary silo]

try 61,41km/h it´s an more precisely sulution, than before

[waxen narwhal]

bruh

why

[silk horizon]

i wrote 48.8

[waxen narwhal]

nah

ur on sparx?

or no

[silk horizon]

yay

correcto

can we please do 2 more

[waxen narwhal]

bruh

[waxen narwhal]

why the heck mine is wrong

[silk horizon]

bruh i need help

unkown can you show us the way you worked it out

[silk horizon]

also @hoary silo can you try working this out

[waxen narwhal]

send me the answer

im confused

[silk horizon]

just send in here

help

please

[waxen narwhal]

eh imma go do my own homework

i got around 200 exercises to do with geometry

[hoary silo]

there is the sulution, but with inaccuracies

[waxen narwhal]

hard ones 🙂

[silk horizon]

uknown

can you work this out

[waxen narwhal]

huh

[silk horizon]

someone helppppppppppp

[hoary silo]

sorry, I don't have any more time

[silk horizon]

oh

[calm coral]

@silk horizon Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime forge]

prove that 1 + 1 is 2

[green night]

lol

following

[prime forge]

prove it

[green night]

i don't think it's possible, I think it's just taken for granted

[prime forge]

so

1 + 1 could be 3?

[green night]

no because it isn't

1 has an assigned value that when you add 1 and 1 together you get 2 idk man

but I'm curious what people who know more will say

[prime forge]

ill keep it open

for more answers

[glacial nacelle]

Principia Mathematica

is a book

where two people took around 1000 pages to prove 1+1=2

[green night]

hahahaha lol

[glacial nacelle]

based on euclids postulates

[prime forge]

got it

[green night]

aint that some shit

[glacial nacelle]

pretty sure thats abstract algebra

not that great at college math tho

[prime forge]

thanks for the answer

🙂

.close

[calm coral]

Channel closed

Closed by @prime forge

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[calm coral]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[harsh night]

$a - \frac{a^{\frac{1}{3}}{\frac{1}{3}\cdot a^{\frac{-2}{3}}}}$
so i set a = -2, and my ti nspire calculator spit out 4 - 1.700893e^-13 *i. what does this mean

[potent lotus]

Aurora
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[harsh night]

bruh

[glad grove]

whats the q

[harsh night]

too lazy to debug latex

[harsh night]

use newton's method to estimate the roots of the cube root of x, with an initial estimation of 1

which brings the question wtf

why the -1.700 e^-13 i

[leaden thunder]

Probably rounding error

[harsh night]

from the calculator?

i mean it is a cas

[leaden thunder]

Calculators round yes

All calculators round

[harsh night]

how did the rounding error produce i tho

[leaden thunder]

Google how your calculator model works

This is a math server not a calculator software server

[harsh night]

cuz i only see a third root which doesnt cause i

[calm coral]

@harsh night Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[calm coral]

Please don't occupy multiple help channels.

[honest holly]

uhh

How is this wrong

nvm

[unkempt drift]

Good on you for realising

[unkempt drift]

Btw please close your channel by typing:

.close

[honest holly]

.close

[calm coral]

Channel closed

Closed by @honest holly

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[remote mural]

;rotate

,rotate

[remote mural]

Doubles every four hours how can I convert that so the equation can commence?

I think o have to use geometric sequence or series

[golden frost]

divide the power by 4

[remote mural]

Divide n by four?

[golden frost]

I don't quite follow your work

but yeah i think n/4

why did you put n-1 tho?

[remote mural]

It’s the formula

For geomtric

For geometric sequence

I think that’s what I’m supposed to use

It’s $an=a1(r)^n-1$

[potent lotus]

micock

[remote mural]

n-1 is the exponent but yeah

[golden frost]

oh

I would just write an equation in the form of y=Ax^n

[remote mural]

Our unit formulas didn’t have that

I think we are supposed to utilize the geometric and arithmetic sequence formulas

[golden frost]

so y = (3,000,000) * 2^(n/4) where n is in hours

[young zephyr]

is it because its in a series like:an = a11(r)^((n-1)/4)

[remote mural]

Or series formulas if it’s asking for the sum

[remote mural]

Idk if it’s in a series or sequence