#help-42

1 messages · Page 46 of 1

vague comet
#

a rhombus can be a
a) rectangle
b) parallelogram
c) square
d) triangle

im torn between options b and c. by definition of a rhombus, a rhombus is already a parallelogram by default. if you're asking about what a rhombus can be, then i think the correct option would be c, because rhombuses can be squares if all the angles are right angles.

amber bolt
#

if it can be square, it can be a) and b) as well

#

squares are rectangular and parallelogrammical

vague comet
#

hmm, true

red moat
#

the question seems obscure

vague comet
#

but then again i don't see why the option would be b because a rhombus is already a parallelogram by default

red moat
#

the question could have been better worded

vague comet
#

it was an mcq i got in my exam 😭

amber bolt
#

don;t try to solve it assuming one option is correct

#

there won;t be a satisfying solution

vague comet
#

alright

#

seeing that the question itself is vague and ambiguous, i'll just close the channel

#

.close

calm coralBOT
#
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red spear
#

need help solving this limit, can't use d'hopital

hollow perch
#

try factorising top

red spear
#

what now? I can write the expression in the paranthases as sin^2x but don't know if it helps

hollow perch
#

yeah

#

and then you have cosx(sinx/x)^2

#

remember $\lim_{x\to0}\frac{\sin x}x=1$?

potent lotusBOT
#

chlamydia

red spear
#

like that

#

.close

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#

@brave sluice Has your question been resolved?

calm coralBOT
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lost ice
calm coralBOT
lost ice
#

how do i find the message length? (it is not 4)

calm coralBOT
#

@lost ice Has your question been resolved?

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#

@lost ice Has your question been resolved?

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@lost ice Has your question been resolved?

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copper kiln
#

Heyy, I’m having trouble figuring out why this is not divergent.

copper kiln
#

But I thought I was supposed to use the limit notations… how do I know when I need the limit notation and when I don’t…

#

I thought we use a limit notation because there is a whole at x=25

upper sparrow
copper kiln
#

Well I thought that since we are taking a closest number from the left of 25, it would give us positive infinity, and then multiplied by -2 it would give us-infinity

upper sparrow
#

,calc 25 - 24.9999

potent lotusBOT
#

Result:

9.9999999999767e-5
past zinc
upper sparrow
#

Damn it calculator monke

copper kiln
upper sparrow
past zinc
past zinc
copper kiln
#

Yes, so if it’s in numerator, it would be just 0, yes? So that whole thing is just 0 and not infinity?

#

And if it was on a denominator, it would have been infinity?

copper kiln
#

Oh okay, because the professor didn’t clearly explain when stuff goes to zero or infinity

#

Thank you so much for the help!

past zinc
#

yvw

copper kiln
#

🫶🏻

calm coralBOT
#

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devout elm
#

calculate (3-4)+(6-7)+(9-10)+.......+(999-1000)

pure kayak
#

mhm mhm

#

just a bunch of -1s

devout elm
#

how many are there?

#

how do i count

broken adder
#

332, by my reckoning

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it goes up in 3s from 4 to 1000

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and since 333 instances of going up in three would be 999, i.e. 1 to 1000,

#

we know that we must have 332 instead

devout elm
#

so -332?

pure kayak
#

4 to 1000, steps of 3
4+3(n-1)
1000=4+3n-3, 999=3n n=333

#

333 terms i think

devout elm
#

what

pure kayak
#

im using arithmetic sequence equations

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with a sequence 4,7,10,... 1000 would be the 333rd term

broken adder
#

wouldn't we need a (0-1) to have 333 terms?

#

wait

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no

#

ur right

devout elm
#

so how do i countr it

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im confused

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whats the asnwer???

pure kayak
#

-333

#

do you know about arithmetic sequences?

devout elm
#

no

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isn't it 332?

pure kayak
#

not by my count

devout elm
#

ncm

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i forgot to incule the first 4

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cuz 332 terms after 4 is 1000

pure kayak
#

indeed

devout elm
#

thanks

#

.close

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devout elm
calm coralBOT
devout elm
#

help

calm coralBOT
celest stream
#

!status

calm coralBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
devout elm
#

1

celest stream
#

divide each term individuallly by root(a/b)

devout elm
#

what

remote mural
# devout elm what

$\frac{\sqrt{ab}}{\sqrt{\frac{a}{b}}}-\frac{\sqrt{\frac{a}{b}}}{\sqrt{\frac{a}{b}}}$

devout elm
#

so

potent lotusBOT
#

deltaG

remote mural
#

@devout elm this

#

do you see terms getting cancelled?

devout elm
#

like

#

ncm

#

idkk

remote mural
devout elm
#

so the right part becomes -1 right

remote mural
#

yes

devout elm
#

how do you solve left

remote mural
#

do you know that $\sqrt{ab}$ is just $\sqrt{a}\sqrt{b}$ and $\sqrt{\frac{a}{b}}$ is just $\frac{\sqrt{a}}{\sqrt{b}}$

potent lotusBOT
#

deltaG

devout elm
#

yep

#

multiply by root b?

#

so then b times roota / root a?

#

then they cancel

#

so 13-1?

remote mural
#

right

devout elm
#

12

#

tysm

remote mural
devout elm
#

i get it noow

remote mural
#

nicee

devout elm
#

thanks

#

.close

calm coralBOT
#
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open pine
calm coralBOT
open pine
#

Stuck in number 2. I'm trying to evaluate the limit

indigo gust
#

You made a calc mistake

#

In denominator

#

@open pine

open pine
#

Which one?

indigo gust
#

4-(4x-x²)

open pine
#

The denominator is zero still tho

#

@indigo gust

indigo gust
#

So limits dne

open pine
#

Ohh 😁 thank you!

#

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fallow nymph
#

I don’t know how to set this up

calm coralBOT
fallow nymph
#

I thought it was just asking for what x value in f’(x) you need to get 4, but that would be 6 which isn’t on here

hasty fiber
#

it's not quite that direct

#

have you been taught the derivative of the inverse function?

fallow nymph
#

I definitely was but I don’t quite remember it

#

I suppose there was a rule I forgot?

hasty fiber
#

i suppose so

#

well now's as good a time as any to bring it back

#

if h(x) = f^-1(x), what is h'(x)?

fallow nymph
#

uhh

#

I don’t remember how to do that, yeah

hasty fiber
#

alright then

hasty fiber
fallow nymph
#

Oh, so then I can use chain rule?

hasty fiber
#

that would be wise

fallow nymph
#

So

fallow nymph
#

It’s just like that?

hasty fiber
#

no

#

that's just the definition of inverse

#

if h(x) = f^-1(x), then f(h(x)) = x

fallow nymph
#

Ok

hasty fiber
#

the point is that second equation

f(h(x)) = x
is something which, if I said "differentiate both sides" is something you should be able to do

fallow nymph
#

Yeah

#

Ok

hasty fiber
#

differentiate both sides

fallow nymph
#

f’(h(x))(h’(x))=1

hasty fiber
#

hey look there's the h'(x) we were looking for

fallow nymph
#

ohh ok

hasty fiber
#

solve for it

fallow nymph
#

I singled out h’(x)

#

I’m plugging in x=4 now

fallow nymph
hasty fiber
#

sounds good to me

fallow nymph
#

ok thanks, I’ll try to remember that property of the inverse function for next time

#

.close

calm coralBOT
#
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maiden otter
#

How do I solve this? Ai told me to use L’hôpital’s rule but I haven’t learned it yet..

maiden otter
bright lagoon
maiden otter
#

But I got stuck while doing it

bright lagoon
#

factor the root first

#

or rather, factor out the GCF from the root

#

$\frac{2\sqrt{x+2} - 4}{\frac{1}{x+2} - \frac{1}{4}}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

now make the substitution

#

$w = \sqrt{x+2}$

potent lotusBOT
#

Melvin Eugene Punymier

maiden otter
#

hmm

bright lagoon
#

tell me what you notice

#

or rather, tell me what you think we should do after that.

#

*what you get after that

maiden otter
#

Not to sure, I’m still convinced that I have to do the conjugate

bright lagoon
#

you asked me for help and I have a solution for you, so bear with me

maiden otter
#

sorry

bright lagoon
#

can you use LaTeX?

maiden otter
#

What is that?

bright lagoon
#

^ that is LaTeX

#

the math.

maiden otter
#

ah

#

I could try but it would be my first time trying to do it

bright lagoon
#

nah, pick up from here, after the substitution:

#

$\frac{2w - 4}{\frac{1}{w^2} - \frac{1}{4}}$

potent lotusBOT
#

Melvin Eugene Punymier

maiden otter
#

um

#

How did you jump from that step to this one?

bright lagoon
bright lagoon
maiden otter
#

Right

#

Sorry you’ll have to be a bit patient with me because English isn’t my first language

bright lagoon
#

...and you are used to asking artificial intelligence for answers

maiden otter
#

…it gave me a method that I haven’t learned

bright lagoon
#

you don't need it to solve this.

#

we are trying to make indeterminant terms cancel

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..which they will

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what would you do next in this situation

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*could you

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to make this simpler

maiden otter
#

Put the fractions in the same denominator?

bright lagoon
#

yes.

#

$\frac{2w-4}{\frac{4 - w^2}{4w^2}}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

now what

maiden otter
#

Idk how to explain it, but bring the (4-w^2) with the (2w-4)

bright lagoon
maiden otter
#

yeah

#

How a/b/c = AxB/c

bright lagoon
#

$\frac{(2w-4)4w^2}{4-w^2}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

what else

maiden otter
#

Distribute

bright lagoon
maiden otter
#

Oh wait

#

the denominator

bright lagoon
#

what about it

maiden otter
#

put it in like 2 parentheses

#

idk the name

bright lagoon
#

what is this called

#

"Difference of ___"

#

s

#

q

#

u

#

a

#

r

#

e

#

s

maiden otter
#

Difference of two squares

bright lagoon
#

too slow

maiden otter
#

In French it’s called différence de deux carrées

bright lagoon
#

$\frac{4w^2(2w - 4)}{(2-w)(2+w)}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
maiden otter
#

yup

bright lagoon
#

what now

maiden otter
#

now I guess take out the common factor in the (2w - 4)

#

Which is 2

bright lagoon
#

cool

#

$\frac{8w^2 (w-2)}{(2-w)(2+w)}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

now what

maiden otter
#

I was thinking of taking out the negative sign in the (w - 2)

bright lagoon
#

ok

#

$\frac{-8w^2 \cancel{(2-w)}}{\cancel{(2-w)}(2+w)}$

potent lotusBOT
#

Melvin Eugene Punymier

maiden otter
#

Yup

bright lagoon
#

now what

maiden otter
#

replace

#

By 2

bright lagoon
#

(this is true, but why)

maiden otter
bright lagoon
#

but we have w here

#

so how are you sure

maiden otter
#

And there’s practically nothing else to do besides replacing

bright lagoon
#

what was the substitution again?

maiden otter
bright lagoon
#

$\lim_{x \to 2} \left(w = \sqrt{x+2}\right) = \sqrt{2+2} = 2$

#

hmm..I can't do limits anymore

maiden otter
#

I get what you mean

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

ok anyway

#

what does that get us

#

$\lim_{w \to 2} \frac{-8w^2}{2+w} = ?$

potent lotusBOT
#

Melvin Eugene Punymier

maiden otter
#

-8

#

!

bright lagoon
#

cool

maiden otter
#

Alright now there is just one thing that I don’t understand in all of this

#

And it’s the whole substitution part

bright lagoon
#

hmmm

#

I'm getting something else though hang on

maiden otter
#

All good take your time

bright lagoon
#

hmm...I wonder where I went awry

#

check out this graph

#

(one sec)

#

oh, no

#

I'm right

#

Wolfram Alpha is WRONG 😳

#

~neat!~

maiden otter
#

Gasp

bright lagoon
#

anyway, here's the graph

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Wolfram thought there is an asymptote at x=2

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but there isn't

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(or maybe I goofed typing it)

maiden otter
#

It looks right

bright lagoon
#

yeah so

#

apparently

#

if you ask Wolfram Alpha DIRECTLY what the answer is to a limit in "indeterminant form" (which is what your expression is),
it may or may not get it wrong as its precision gets buggy near the limit

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however, if you just ask Wolfram Alpha to GRAPH the expression, then it will draw it correctly

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(usually)

#

Desmos worked out fine because I just asked it to graph.

maiden otter
#

yeah

bright lagoon
#

Do you remember what "indeterminant form" is?

maiden otter
#

Yeah

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I think?

bright lagoon
#

ok good

#

tell me

maiden otter
#

For example, -inf / -inf is an indeterminant form

bright lagoon
#

good

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also...?

maiden otter
#

Uh

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0 / 0?

bright lagoon
#

(our situation here--yes!)

maiden otter
#

Right

bright lagoon
#

that is also the condition where "L'Hospital's Rule" will work.

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...but you haven't learned that yet.

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good job, @maiden otter

maiden otter
#

Im still confused on the substitution part though. How does the square root disappear all of a sudden?

bright lagoon
#

we "substituted" it

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you see, when we see square roots in these nasty expressions, it's ~n i c e~ if we can find another version of the same expression in the root, but without the root

#

if we see that, then we can call the rooted version some variable, like w, and the version WITHOUT the root, w^2

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that is,

#

$\sqrt{x+2} = w \text{ and } x+2 = w^2$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

it just makes things cleaner and (usually...in math homework) enables something to more obviously cancel after we finish factoring

maiden otter
#

Right

#

but I don’t know in our situation I still seem confused

maiden otter
maiden otter
bright lagoon
#

I just SUBSTITUTED exactly like I wrote here ^

bright lagoon
potent lotusBOT
#

Melvin Eugene Punymier

#

Melvin Eugene Punymier

bright lagoon
#

don't you see that

potent lotusBOT
#

Melvin Eugene Punymier

maiden otter
#

Now I’m even more confused 😭

#

For some reason I can’t remember substituting

bright lagoon
#

you REALLY don't understand that

#

$t = (\sqrt{t})^2$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

?

maiden otter
#

Well yes that becomes t

bright lagoon
#

(I mean, technically, you get the absolute value, but it's ok in this situation)

maiden otter
#

Uhhhhh

#

Sorry but how did the 1/ x + 2 become 1/ x^2 ?

bright lagoon
#

I don't have that

maiden otter
maiden otter
bright lagoon
#

although, you know...

#

$\frac{2\sqrt{x+2} - 4}{\frac{1}{x+2} - \frac{1}{4}}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

we should technically have

#

nah it's good

#

so again, we said that

#

$w = \sqrt{x+2}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

the other expression, x+2, is just the square of this. So x+2 = w^2.

#

$\frac{2w - 4}{\frac{1}{w^2} - \frac{1}{4}}$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

do you see?

maiden otter
#

I don’t really want you to try to re-explain it again and again

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I’ll take in note what we’ve done and try to understand

bright lagoon
#

you already know how to substitute letters for numbers.

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now we are just substituting letter expressions for single letters (w)

maiden otter
#

The w is just x right?

bright lagoon
#

because it is easier to write

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no!

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the w is sqrt(x+2)

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instead of writing sqrt(x+2), we wrote w.

maiden otter
#

oh it makes it just simpler?

bright lagoon
#

that's it.

bright lagoon
maiden otter
#

OHHHHH

#

no wonder

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I was so confused

bright lagoon
#

you can do all this (technically) without substituting

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but I've been doing this for years

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and I wouldn't have noticed right away

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unless I made the subsitution first

maiden otter
#

Yeah I get it now

bright lagoon
#

good luck interpretting a square root expression as a difference of squares!

maiden otter
#

But I don’t think my teacher would let me do it

bright lagoon
#

you just forgot

maiden otter
#

I have a really strict teacher

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But I’ll ask her tmr if it’ll be okay with her

bright lagoon
#

$\text{factor: } f(x) = x + 2\sqrt{x} + 4$

potent lotusBOT
#

Melvin Eugene Punymier

bright lagoon
#

you did this

#

y = sqrt(x)

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so then

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y^2 = x

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and then

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f(y) = y^2 + 2y + 4

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...which is a "perfect square trinomial"

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f(y) = (y + 2)^2

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...and so f(x) = (sqrt(x) + 2)^2

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...but it was easier to see that with the substitution 🙃

maiden otter
#

Yeah

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That’s fair

bright lagoon
#

ok, that all?

maiden otter
#

I think so!

bright lagoon
#

ok, goodnight

maiden otter
#

goodnight : )

#

thank you so much

bright lagoon
#

no problem

#

.close

calm coralBOT
#
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fluid yew
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Let A be an ordered integral domain. Prove that $a^2+b^2+c^2 \geq ab+bc+ac$. This is possibly trivial, but I got to $2a^2+2b^2+2c^2 \geq 2ab+2bc+2ac$. Am I allowed to multiply by 1/2 here, and if so, why? How do I know the LHS/RHS is still in A if I multiply by 1/2?

potent lotusBOT
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Fuzzy_Alpaca

fluid yew
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<@&286206848099549185>

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barren nymph
#

what is the logic behind this? btw it's asking to solve the inequality

pure kayak
#

you can expand it to look a bit easier
-1<(x-1)/(x+1)<1

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barren nymph
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nvm I got it, sorry

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cosmic hill
#

Can someone explain how this step came?

calm coralBOT
cosmic hill
#

Instead of writing sin2a how is there cos2a(t)

#

And also the C1

leaden thunder
#

cos(2a) is a constant with respect to t

#

C1 is just a dummy name for a constant

cosmic hill
cosmic hill
#

What does that mean?

leaden thunder
#

C is a constant wrt t

cosmic hill
#

Can you please explain

#

Instead of C1 can we write C

leaden thunder
cosmic hill
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Okayy

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Thanks

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vale mantle
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can someone please help me with question b?

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<@&286206848099549185>

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rose depot
#

Layla has a coin that has a 60% chance of showing heads each time it is flipped. She is going to flip the coin 5 times. LetX represent the number of head she gets.

What is the probability that she gets more than 3 heads?

round tusk
#

binomial probability formula:

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use this formula

#

for n = 4 and 5

rose depot
#

Thank you :)

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prime ingot
#

I need some help with Surface Area of revolutions. Having a tough time figuring out what to pick as my radius.

prime ingot
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/close

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calm coralBOT
prime ingot
#

r in this case we needed to pick a radius

#

I did some reading and it turned out r=x which makes a lot of the practice questions I have give weird solutions. So ill talk to my prof for help

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spark adder
#

Guys the function inside is odd right? therefore the integral is 0?

torn gorge
#

do you know odd function's definition ?

spark adder
#

f(-x) = -f(x)

torn gorge
#

does this function satisfies that property ?

spark adder
#

well yes?
(-x^3 - 3sin4x) cosx^3

torn gorge
#

hence your function is odd

spark adder
#

ok thanks

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maiden solstice
#

i want to find the gradient of this

calm coralBOT
maiden solstice
#

can some1 tell me why this is the solution?

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<@&286206848099549185>

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remote mural
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<@&286206848099549185>

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upper drum
#

Hello please help me establish the order of convergence of the sequence obtained from the bisection method

upper drum
#

In the text we have only established that this condition is necessary but not sufficient for linear convergence

#

How do we conclude that p_n converges linearly?

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proven junco
#

I need help with 12 b)

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remote mural
calm coralBOT
marsh valley
#

Have you tried anything?

remote mural
#

Wdym

#

I'm not sure how to do this kind of problem at all I'm failing my math class 😭😭

marsh valley
#

Consider the triangle you obtain by drawing a horizontal line where the slanted part starts.

#

Try and find the sidelengths with the information given to you.

remote mural
#

The side lengths are given to me right

marsh valley
remote mural
#

I'm so confused

marsh valley
#

Have you tried drawing the triangle I'm talking about?

remote mural
#

No

#

I'm too confused

#

😭😭

marsh valley
#

You should draw it.

remote mural
#

My school blocked addons

#

I don't ahev any drawing website thingies

limpid flame
#

use paper lol

#

do you know how to find these lengths?

#

start with that

remote mural
#

So the bottom length would be 5

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And the left side length would be 4

limpid flame
#

yep

#

then you can use the pythagorean formula

#

to find that slanted length

remote mural
#

A^2 + b^2 = c^2

#

25 + 16 =

#

41

limpid flame
#

yes sqrt(41) tho

#

since c^2 = a^2 + b^2, c = sqrt(a^2 + b^2)

remote mural
#

6.4?

calm coralBOT
#

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@remote mural Has your question been resolved?

leaden thunder
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onyx quiver
#

sorry but why was he allowed to turn x^3 - 64 to x - 4 ?

dull wagon
#

they didn't

onyx quiver
#

your allowed to cube root it ???

#

ohh

#

now i see

dull wagon
#

x^3 -64 didn't change into x-4

#

they factorised x^3 - 64 to (x-4)(x^2 +4x+16)

onyx quiver
#

ohh ok

dull wagon
#

difference of two cubes identity

onyx quiver
#

ty

#

il close now

#

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devout elm
calm coralBOT
devout elm
#

can someone explain how

quaint sphinx
# devout elm

first

draw segment between two points of intersection of the shapes

this might help you see what to do

empty quail
#

!15m

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#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

devout elm
#

oh

devout elm
#

nvm

#

found out

#

.close

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half raven
calm coralBOT
half raven
#

not sure how to start

calm coralBOT
viscid ice
#

start with a substitution of u=1/x

half raven
#

okay

half raven
viscid ice
#

spot on

half raven
#

okay

#

what's the integral of that

#

i forget

dull wagon
#

a few notation errors

half raven
#

wat

dull wagon
#

missing dx in the original integral
and missing () around the -x^2 when converting to du

half raven
#

i see

#

my bad

viscid ice
dull wagon
#

don't forget the + c

viscid ice
#

but otherwise yes correct

half raven
#

tysm

#

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half raven
#

how do i get the integral of something to the x power

half raven
#

$7^{x}$

#

like dat

potent lotusBOT
blazing coyote
#

$\int a^x = \frac{a^x}{ln(a)}$

potent lotusBOT
#

Why am. I here

blazing coyote
#

I encourage you to ponder why

half raven
#

is it sort of like the chain rule

#

idk

#

i jus don't understand

blazing coyote
#

What? Why it's $\frac{a^x}{ln(a)}$

potent lotusBOT
#

Why am. I here

half raven
#

i see but like i just can't visualize where it comes from

blazing coyote
#

what are you unable to understand? I'm unable to understand what you can't understand?

half raven
#

Idk

#

LOL

#

i will jst leave it at that

#

thank you for helping me

upper sparrow
potent lotusBOT
#

@upper sparrow

upper sparrow
#

Are you happy with integrating something like $\int e^{kx} \dd x$?

potent lotusBOT
#

@upper sparrow

calm coralBOT
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glacial pecan
#

does this seem right and if it does do i combine 2x^4 and x^4

glacial pecan
#

the equation

glacial pecan
#

so itd be 3x^4?

kindred estuary
#

Yes

glacial pecan
#

thanks

#

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feral totem
calm coralBOT
feral totem
#

ah

little brook
#

For the first inequality $x-1 \leq 2-2x$, we add $2x$ to both sides to get $x + 2x - 1 \leq 2$, which simplifies to $3x - 1 \leq 2$. Then we add 1 to both sides to get $3x \leq 3$. Finally, we divide both sides by 3 to get $x \leq 1$.

For the second inequality $3x+5>2$, we subtract 5 from both sides to get $3x > -3$. Then we divide both sides by 3 to get $x > -1$.

we are looking for the values of $x$ that satisfy both $x \leq 1$ and $x > -1$. This is the interval $(-1, 1]$.

potent lotusBOT
#

Flamey

little brook
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tepid glacier
#

How do i solve coordinate/ordered pair composition of function

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trail ingot
#

lolll what is that asking

plush spoke
#

Idk

broken anvil
#

Is that the whole question??

plush spoke
#

Yea

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jade wyvern
#

how to calculate the minimum,maximum and zeros for the function : 2cos(x/4 -π/3) -1

jade wyvern
#

because when i calculate the second zero it says it is 8kπ but i have 8π+8kπ. HELP

leaden thunder
#

Then find the k+1 that is the second zero

jade wyvern
#

no cuz i ran it through photomath and it says the 8π is zero because the closest positive coterminal angle is zero?

jade wyvern
leaden thunder
#

Like ab+ac = a(b+c)

jade wyvern
#

yes but the equation is x=8π+8k so that does nothing

jade wyvern
leaden thunder
jade wyvern
# leaden thunder

yes the answer is x=8kπ but i have x=8π +8kπ. When i put in the origrinal function into photomath it transforms x=8π +8kπ into x=8k because apperently the closest coterminal angle is zero

jade wyvern
leaden thunder
leaden thunder
#

You can check photo math after you find your k

jade wyvern
#

the x-es are zeros the k is there only to signify the fact that the function repeats

#

<@&286206848099549185>

leaden thunder
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cobalt cave
#

what i am doing wrong here?

calm coralBOT
upbeat venture
#

take z = 5 + 5i for example

cobalt cave
#

it means k x sqrt(2) ?

upbeat venture
#

I mean sure, but k could be any real number, so that's not very helpful

cobalt cave
#

ok i understand your point

#

how would you solve this question

upbeat venture
#

Arg(a+bi) = arctan(b/a)

cobalt cave
#

ah for real

#

i always forget some stuff

cobalt cave
#

isn't it jsn't it just tan?

#

isn't arg supposed to mean tilt angle of z?

upbeat venture
#

Arg(z) represents the angle z makes with the real axis. from trig, you know tan(Arg(z)) = b/a, if z = a+bi

cobalt cave
#

<@&286206848099549185>

#

ok i got it

cobalt cave
#

.close

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silent oar
#

Use the shell method to find the volume of the solid generated by revolving the shaded region about the​ y-axis.

silent oar
#

$\int_0^32\pi{xf(x)}:dx = 2\pi\int_0^3\frac{18x^2}{\sqrt{x^3+9}}:dx$

potent lotusBOT
silent oar
#

is this correct?

#

i got my final answer as 72pi but its wrong apparently...?

leaden thunder
#

,w 18 * int 0 to 3 of x^2/(x^3+9)^(1/2)

leaden thunder
#

You should be taking 3 - curve as your shell

#

Solve for x in the equation for y

silent oar
#

heh..? ok i will give it another shot thank you

#

.close

calm coralBOT
#
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calm coralBOT
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worn light
#

.close

remote mural
#

this is false right

calm coralBOT
remote mural
#

or am i just stupid

#

because if you let m = n + 1, this clearly isnt true lol

#

but im convinced i just read this wrong

#

and am being stupid

torn gorge
#

n=0?

remote mural
#

yeah

#

0 in N

#

in my class

#

ohhh

#

hahaha

#

hmm

#

i see

torn gorge
#

every number divide 0=0 times what ever

torn gorge
remote mural
#

ok

#

this is so stupid

#

i just have to prove this is true when n = 0

torn gorge
#

i m going to eat something

#

bye

frank gull
frank gull
#

bugt since y'all do then yeah it's totally valid

remote mural
#

but like why tf would they ask this

#

thats so stupid

#

i dont have to show that it only holds for 0 and not any other n right

frank gull
#

part of getting an education in math is also reading comprehension

#

edge cases, etc

remote mural
#

yeah my reading comprehension is

#

horrible

torn gorge
remote mural
#

any advice...

#

ive been trying to practice a lot

#

to overcome my reading comprehension struggles

frank gull
frank gull
#

Make sure that you have all of the availalble data

remote mural
#

btw

#

do u have a good text book rec

#

the supplemetal materials they gave us are not enough i dont think

frank gull
#

what always tripped me up was forgetting some small detail like "a natural number n that is prime". The key to the proof was that it was prime, but I forgot that fact

#

which class is this for?

remote mural
#

it would lowkey dox me

frank gull
#

I'm not a big DM person from here if that's alright. Keep work and pleasure separate, ya know?

#

how about you react? lol

#

Intro to adv math

#

number theory

remote mural
#

thats fair

frank gull
#

discrete math

remote mural
#

no

remote mural
#

not discrete math, the one before it

frank gull
#

oh I don't think I had a class before discrete math for that topic, lol

#

for me that was calculus 2 but they're separate fields

remote mural
#

i need a good textbook

#

with practice problems

frank gull
#

I recall our course used The Book of Proof by Richard Hammack

#

it provides solutions for odd problems and each chapter has a large sample of practice problems

remote mural
#

so you would say it is good

frank gull
#

yeah I enjoyed it personally

remote mural
#

im not going to lie, i really hate this math, but i really am trying to change my mindset

#

but it is hard

frank gull
#

that's fair. I say this as someone who loves math, not everyone feels that way. But that's also because our education system kinds of fails us because the way we teach it is not very efficient

#

I really enjoyed some more "off the beaten path" math courses like abstract algebra

#

and that came after proofs

remote mural
#

yeah its true, but my major is math adjacent

#

and proofs are important, even if i dont want to admit it

frank gull
#

I'm guessing CS?

remote mural
#

yes

frank gull
#

100% Proofs are what make math math. It's why it's so strong. Without proofs, we can't truly prove any statement, even if it seems obvious

#

I was a CS major too

#

currently a software engineer

remote mural
#

but like, my brain doesnt work to use proofs

remote mural
#

well i want to do ||compiler development||

#

but yeah

frank gull
#

OOOOH

#

hold on I think I remember seeing a book that specifically caters to that

remote mural
#

crafting interpreters?

#

the dragon book

frank gull
#

||compiler construction||

frank gull
#

it's seriously awesome

remote mural
#

and its the only thing holding me back

#

from doing what i like

#

which is why i hate this class

frank gull
#

I guess DM the specific course

#

I'm still not clear on what this particular course subject is lol

remote mural
#

wait r u american by any chance

remote mural
#

sounds accurate

frank gull
#

ok yeah that textbook I recommended should help a ton then

#

it's a gentle approach of proofs and holds your hand through the first concepts.

remote mural
#

i should really practice every day

#

im not even kidding i have nightmares about this class

#

my calc 3d class is 10x easier for me

frank gull
#

Yeah for sure. If you can manage it, what I used to do was like 10 theorems a day for the chapters of studying concepts, I would try to re-write them on my own, then do like 5-10 practice problems

#

takes in total like an hour a day if you can spare that

remote mural
#

one thing i want to avoid is like, memorizing proofs

frank gull
#

it's practically impossible to do, imo. Unless you have an eidetic memory, you'll trip up small details.

#

proofs is like learning a new language

#

you have to also understand the structure of your proof, make sure that your claims have validity (this is where things like axioms or previous proofs come into play)

#

however, I will say (and I really hate to admit this) but depending on which CS branch you go, you may or may not need that much math

#

the most math I use in my job is for figuring out subnets in networks

#

I like math so I do it on my own, but yeah I use very little of my math degree in the day to day job

#

your primary focus should be on bit masking, manipulation, inversions, etc. This is all math related, but you learn more about that in an actual compiler/OS course than in any related math topics.

Most people who get CS degrees and don't like math just survive the math part until they're done with it, much like I did with government courses

#

I hated them, I made a C and moved on with my life

remote mural
#

for me

#

but

#

i dont know

#

its not a good excuse to not learn it well, it used to be, ive changed my mind

remote mural
remote mural
remote mural
#

even despite the practice

frank gull
#

practice makes perfect 🙂

#

fwiw I failed most of my math courses in HS, then years later I started back at algebra 1 and got my math degree

#

compared to other helpers here I'm absolutely trash at math

#

but I still managed. Persistence and practice trump natural abillity

#

if directly comparing the two

#

(tortise and the hare, etc)

remote mural
#

its really unmotivating

#

i feel like im the bottom of my class

calm coralBOT
#

@remote mural Has your question been resolved?

#
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forest walrus
#

T_A and T_B are linear transformations, with standard matrices respectively A and B [as shown in image].
Find standardmatrix C for the composite transformation T_A ∘ T_B.

forest walrus
#

I don't know where to start from here. I'm going through these chapters before we go through this in class. Could someone teach me some fundamentals here? What does "T_A ∘ T_B" mean basically?

#

Wait... is this supposed to be a dot product? ∘ is a weird symbol.

glass heart
#

composition

#

first apply T_B then apply T_A

forest walrus
#

lmao I got the correct answer by just multiplying both matrices

#

Was it the right approach? x)

forest walrus
glass heart
#

yes the point is that composition of linear maps is the same thing as multiplying their corresponding matrices

forest walrus
#

thank u 😄

#

.close

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#
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west merlin
#

hey can you verify my explanation as I'm trying to understand the intuition of how to use 'unless' in logic.

q unless not p means that when not p is the case then not q which is the same as p then q

(q unless not p) = (not p then not q) = p then q

west merlin
#

im trying to come up with my own blurb to remind me of the intuition why q unless not p = p then q

clear delta
#

q unless not p
q if p
if p then q

west merlin
#

i see the advantage of this one to for the symmetry is mine correct too tho?

#

Ill use both if mine is correct to help me remember

#

in particular this:

q unless not p means that when not p is the case then not q which is the same as p then q

clear delta
#

"unless not" would annoy me in most writing

unique jackal
#

yeah i prefer the "q unless not p" means that "if not p is true, then not q is true"

#

but i dont like unless not anyways

west merlin
#

i hate it its so confusing

#

But thank you so much for both your help

unique jackal
west merlin
#

i thought so too but id just get mad if i didnt get it lmao

#

you have no idea how happy this has made me lmao

#

ive been thinking about it all day

calm coralBOT
#

@west merlin Has your question been resolved?

#
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calm coralBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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glad sinew
#

Ok, so I wasn't there when ta explained the question.. I'll share the notes but I have no idea what Im looking at

glad sinew
#

I'll try deciphering the notes and figure it out

#

Im already stuck on the first statement

#

why (x-eps, x+eps) intersect A

#

oh man its so over

upbeat venture
#

this guy's handwriting sucks

upper sparrow
upper sparrow
upper sparrow
glad sinew
#

From my understanding, if you have an interval there's always an x in between the two bounds. So rationals and irrationals are both dense in the reals

#

but yea I dont really understand the solution

#

I'll try writing everything out and I can send what I wrote

upper sparrow
#

Also what do the curly brackets {} represent? Like closest integer or?

glad sinew
glad sinew
#

set notation?

#

maybe

upper sparrow
#

Would seem strange, it appears as if they're treating them as numbers e.g. here

#

If e.g. it were the floor/ceiling, it would explain this part here (if they were the same, the difference between them would be strictly less than 1, which would force m = n) wait nope

glad sinew
upper sparrow
#

Actually no I think it might be the fractional part of the relvant number

#

That would explain them being in [0, 1)

glad sinew
#

I dont understand this proof at all

#

I dont understand the solution

#

oh my friend replied

#

its floor

#

the decimal part only

upper sparrow
upper sparrow
potent lotusBOT
#

@upper sparrow

upper sparrow
glad sinew
#

what do you mean you get irrational equal to rational. Also, m doesnt have to equal to n? cause you can have floor m= 3.63 and floor n= 3.32 for example and the floor of m and n are equal

#

if fractional parts are equal, you can still have 6.63 and 4.63 for example

upper sparrow
#

You assumed $\alpha$ was irrational, but $m \neq n$ gives that $\alpha = \frac{\floor{\alpha m} - \floor{\alpha n}}{m - n}$, a ratio of integers with a nonzero denominator

potent lotusBOT
#

@upper sparrow

upper sparrow
#

And of course 3.63 and 3.32 are rational: the point was more that if you had an irrational number, you can't have two integer multiples of it having the same floor or fractional part

glad sinew
#

Im sorry Im very confused. So alpha is an irrational, multiplying by n an integer and m a natural number, and two integer multiples cant have the same floor??

#

or fracional part??

#

what why

#

Im so lost here

upper sparrow
#

both

upper sparrow
potent lotusBOT
#

@upper sparrow

upper sparrow
#

But as alpha is irrational, it's not zero, so we can divide by it safely and find an integer strictly between 0 and 1, or -1 and 0, not possible

upper sparrow
# potent lotus <@788085606483361802>

As for the fractional parts not being able to be the same, note that for any number $a$ you can write it as $a = \floor{a} + { a }$ and so as per here...

potent lotusBOT
#

@upper sparrow

upper sparrow
#

Actually wait, ignore the floor part for now, reasoned it wrong

#

The fractional part still holds tho

glad sinew
#

yup, fractional part makes sense, its floor + its decimal part, makes up alpha

#

but fractional part is {a}

#

why not have the same

upper sparrow
#

As before, noting that ${ a } = a - \floor{a}$ for any number $a$, then ${\alpha m } = {\alpha n }$ means that
[
\alpha m - \floor{\alpha m} = \alpha n - \floor{\alpha n}
]
and so
[
\alpha m - \alpha n = \floor{\alpha m} - \floor{\alpha n}
]
factorise $\alpha m - \alpha n = \alpha (m - n)$, and if you had $m\neq n$, you get
[
\alpha = \frac{\floor{\alpha m} - \floor{\alpha n}}{m - n}
]
Now, $m, n, \floor{\alpha m}$ and $\floor{\alpha n}$ are all integers, and $m - n \neq 0$, and $\alpha$ was assumed irrational, i.e. not a fraction of integers with nonzero denominator...

potent lotusBOT
#

@upper sparrow

upper sparrow
#

[also as a note I was wrong about the "floors not being equal", e.g. alpha = sqrt{2}/4 is such that there are different integer multiples with the same floor, dummy moment brainTiny]

calm coralBOT
#

@glad sinew Has your question been resolved?

upper sparrow
#

oop mistyped lol

upper sparrow
glad sinew
#

alpha would be 0?

upper sparrow
potent lotusBOT
#

@upper sparrow