yeah
#help-42
remote mural
lost ice
idk why it's not accepting
remote mural
idk why it's not accepting
no but like u put on -5 wnd 5 in there
remote mural
yeah i was gonna say hahaha
remote mural
i think just swotch the variables
lost ice
yee
calm coralBOT
remote mural
anytime
calm coralBOT
Available help channel!
grizzled ember
How do I go about solving this?
calm coralBOT
How do I go about solving this?
grizzled ember
I don't really understand the question so I don't know where to start. I thought that matrixes had either one, infinite, or no solutions and only know the conditions for those
crystal forge
I don't really understand the question so I don't know where to start. I thought...
well maybe by "has two different solutions" they don't mean "exactly two solutions"
if it has infinite many solutions i guess saying "it has two solutions" is technically true? 🤔
grizzled ember
what about the thing for "common solutions"
calm coralBOT
@grizzled ember Has your question been resolved?
calm coralBOT
grizzled ember
.reopen
grizzled ember
<@&286206848099549185>
calm coralBOT
<@&286206848099549185>
marsh summit
<@&286206848099549185>
do you have a question?
grizzled ember
Yes the question I sent before,
drifting seal
<@&286206848099549185>
!15min
calm coralBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
drifting seal
it has been more than 15 min
channel was closed
grizzled ember
ahh I see
grizzled ember
Yes the question I sent before,
what are the steps for this?
calm coralBOT
@grizzled ember Has your question been resolved?
karmic ridge
how would i do this problem?
calm coralBOT
how would i do this problem?
potent igloo
Find how many ways there are to tile an n x m rectangle, then use that to find the number of ways to tile an (n+1) x m rectabgle. That's my first guess. Not saying it's right or wrong, just an exploration choice
karmic ridge
i could try
calm coralBOT
@karmic ridge Has your question been resolved?
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ionic cipher
how do I do d)
calm coralBOT
how do I do d)
ionic cipher
OH
drifting seal
hint it’s the point where the vertex is
ionic cipher
2 + -2 / 2
drifting seal
parabolas r symmetrical about the vertex
ionic cipher
OHH
drifting seal
but u have it in vertex form already
drifting seal
u have it in the form y=a(x-h)^2+k
where h=-b/2a
or the x coordinate of the vertex
so the vertex is just at x=h
which is 2
for ur quadratic
ionic cipher
oh
ionic cipher
haha lol no worries
drifting seal
so to the left of 2 just pick any x<2 and right of 2 just any x>2 then evaluate the function at that point
drifting seal
haha lol no worries
i’m blind sorry
ionic cipher
i’m blind sorry
noooo ita okay lol
ionic cipher
so to the left of 2 just pick any x<2 and right of 2 just any x>2 then evaluate ...
any number?
drifting seal
yea
for simplicity u can do zero or one
then just plug it in
to the quadratic
u had
id do x=0
because u have a 1/2
ionic cipher
oh so I'd replace x?
ionic cipher
y = 1/2 (0-2)^2 -2?
ionic cipher
ohh ok!
ionic cipher
and then the answer goes to the y spot?
drifting seal
yes
and to the right let’s pick x=4
because we want to get an even number because of the 1/2
no one likes fractions
drifting seal
yes
also notice
it should be the same
because it’s equidistant from the vertex
as x=0 is
like
ionic cipher
yes
ionic cipher
oh right
drifting seal
since parabolas r symmetrical
however far to the right of the vertex u go
the y value there will be the same if u went the same distance to the left of the vertex
hence the term
axis of symmetry
drifting seal
yes
im not sure how accurate they want it
maybe just connect a few points
with the vertex
ionic cipher
yes
drifting seal
and 2,-2 for the vertex
ionic cipher
thank youuuu
calm coralBOT
calm coralBOT
Available help channel!
remote mural
when do you flip the signs
calm coralBOT
when do you flip the signs
remote mural
of an equality
calm coralBOT
of an equality
remote mural
$hello$
$$x^3+2x+8>5x^2$$
potent lotusBOT
mj
potent igloo
nope
If a>b, then a+c>b+c
Adding or subtracting to either side does not change inequality direction
remote mural
what does then?
potent igloo
If c is complex, then no ordering exists. It's just nonsense, @quiet forge
crystal forge
what does then?
multiplying or dividing by a negative number, not addition \ subtraction though
calm coralBOT
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placid kettle
“Given that $log_{2}(log_{32}x)=log_{32}(log_{2}x)$, find $(log_{2}x)^{4}$.”
potent lotusBOT
Ruby
keen stump
f
neat trail
calm coralBOT
@keen stump Has your question been resolved?
pastel jungle
do the beta parameter values change if the independent variable in a regression function is transformed ?
pastel jungle
for example for something like this
calm coralBOT
@pastel jungle Has your question been resolved?
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terse prairie
no idea where to start.
terse prairie
no
indigo gust
Have u studied newton sum@terse prairie ?
terse prairie
the way i tried
indigo gust
Send ur work
terse prairie
yup
indigo gust
a_6 = 5a+3b
indigo gust
You high?
terse prairie
god damn
wait hold up
55a+33b = 4
5a + 3b = a_6
do i just divide
and simplify
indigo gust
Yep
indigo gust
No
indigo gust
Send
terse prairie
f(x)^2 = x-f(x)
but f(x)^2 is the inverse so its f(f(x))?
or -f(x)
nevermind
am dumb
its just f(x)^2 = x - f(x)
indigo gust
so its y²+y-x=0,where y should be +ve integer and we have to find largest 3 digit possible x
indigo gust
Why?
terse prairie
subtracting f(x)^2
indigo gust
See carefully
indigo gust
Δ should be perfect square for rational roots
terse prairie
what is that cryptic triangle meaning
indigo gust
what is that cryptic triangle meaning
Dsicriminant
terse prairie
oh
indigo gust
1+4x=k²
Now 100<=x<=999 find the range of k²
And since k is a integer k can be in b/w 20 and 63
You following?
terse prairie
9th rn
indigo gust
Oh nice which country?
indigo gust
11th
terse prairie
god damn
terse prairie
And since k is a integer k can be in b/w 20 and 63
is 63^2 the highest perfect root of 1+4x?
indigo gust
And since k is a integer k can be in b/w 20 and 63
Now x should be integer so (k²-1) should be divisible by 4
indigo gust
is 63^2 the highest perfect root of 1+4x?
No you need to check now
And since qstn is asking for largest so check from reverse
terse prairie
if k = 63 then (k^2 -1)/4 = 992
indigo gust
Like if you check for k=63 this works
indigo gust
Now 100<=x<=999 find the range of k²
.
indigo gust
No i find it
100×4<=(K²-1)<=999×4
Then approximate the square roots (if calc not allowed)
terse prairie
ohhhhhhhhhh ic ic
indigo gust
Are you prep for some kind of olympiad?
terse prairie
no
im just taking this course to get my credits and run
i probably should do olympiad though
.close
calm coralBOT
patent tundra
The answer is A. The principal square root returns the positive value only. If you want plus/minus square root you should type +/- sqrt(some_number)
principal square root is the square root that outputs a positive number.
In this case, you will have a function that returns multiple values. This will make it harder to perform calculations.
Everything will depend on the precise context. As result your question is not meaningful. If you were solving the equation x^2 = 2. Then you would use the +/- sqrt. However if you added the condition x>0. Then you will be force to use the positive sqrt or in other words the principal sqrt.
calm coralBOT
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dry hinge
how do you do something like this?
calm coralBOT
how do you do something like this?
dry hinge
i can do it, but i want to know if im doing it correctly
the answer is correct but there might be a better way to do it?
clear delta
how are you doing it?
hasty fiber
we can't answer that without knowing how you did it
dry hinge
how are you doing it?
i split it up into
(x+1)/(x+1) - 1/(x+1)
is this correct
then you get x-ln(x+1)?
is there another way to do it
clear delta
sure that seems good to me
dry hinge
sure that seems good to me
and thats how you would normally do it?
clear delta
yeah
dull wagon
that's probably how i'd do it
alternatives would involve stuff like u-sub of x+1
which is a lot more tedious
clear delta
alternatives would involve stuff like u-sub of x+1
which is a lot more tedious
and of questionable benefit
dry hinge
is that also how you would do something like that
clear delta
i had to expand and do the same thing
yeah that's how i'd do it. if that power were any higher i might try u = x+1 though
calm coralBOT
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Available help channel!
meager helm
calm coralBOT
meager helm
guys did i do any mistake hjere
cos the 0.9 is multiplicator which should make this y(GDP) bigger in theory
so im confused
correction
.close
empty oyster
a quick question
calm coralBOT
a quick question
empty oyster
What is y' × y' ?
tribal spire
where y' is ?
alpine stone
What is y' × y' ?
Looks like derivative of y multiplied by itself
What type of answer are you expecting?
tribal spire
if you know what y is
just derivate it
and then square the answer
if you want a rule or something for y' * y', i dont know any which exist
humble ivy
(x')^2
crisp fern
You find the derivative then square the result maybe
tribal spire
I think this is it
both are the same thing
regal bronze
Yeah its just (y')^2
tribal spire
multiply y' with y' is same as (y')^2
empty oyster
That was the answer i was looking for thx
regal bronze
y" is d²y/dx²
But (y')² is = (dy/dx)²
empty oyster
y" is d²y/dx²
But (y')² is = (dy/dx)²
Thx
My english isnt good
Well thanks for the help guys
tribal spire
close the channel if ur done
empty oyster
.close
calm coralBOT
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austere moth
Determine a and b so it can derivate
calm coralBOT
Determine a and b so it can derivate
austere moth
On this question, do i have to guess a and b or is there a methematical way to fighure out a and b?
I see that if x^2+ax + b becomes 2x + a
so if x = 1 then a has to be -2 but
what purpose does b have?
quaint sphinx
what purpose does b have?
function must be continuous
austere moth
It doesn't state that it has to be continous?
warm kelp
no polynomial functions are always continous
remote mural
continuity is necessary for a function to be differentiable
Differentiablity $\Implies$ continuity
potent lotusBOT
warm kelp
you can just put x=1 in the equation
both
and make them equal to get the values
these type of questions come with more conditions here there are two
when you have a face with that question remember to put in the limits of the same phase and make them equal
austere moth
I can't put x = 1?
warm kelp
here is only given for x=1
quaint sphinx
no polynomial functions are always continous
this is kind of irrelevant
warm kelp
I can't put x = 1?
you can
warm kelp
this is kind of irrelevant
depend if you dont try to mess up with the quadratic right?
quaint sphinx
the fact that they're polynomials doesn't mean anything here
warm kelp
it states x > 1
see it states that
quaint sphinx
continuity is necessary for a function to be differentiable
this is the main idea here
warm kelp
the fact that they're polynomials doesn't mean anything here
the fact that they are polynomials you dont have to look for continuity
they are already-
oblique current
You still have to look for continuity at x=1
upper sparrow
the fact that they are polynomials you dont have to look for continuity
Except the fact that while f is made up of polynomials piecewise, it’s not a polynomial itself
warm kelp
Except the fact that while f is made up of polynomials piecewise, it’s not a pol...
ik but looking at a question like this it is for sure we dont have to -
thats why i said if the function is not messed up you can just substitute and equate
austere moth
So how do i go about solving something like this?
put in a x which both functions allow?
warm kelp
yes if the limits of the functions are same ie here given for 1 the substitute and equate get the value and do the further required
if you get more conditions just remember you cant substitute in all
potent lotusBOT
Merineth
warm kelp
you have to see which has the same ending/starting interval
austere moth
So here a = 2 and b = 0?
upper sparrow
**Merineth**
Not quite, you have that by checking the left and right limits are the same that these are equal, but you can’t yet deduce what a and b are alone from that
For that, you want to use the differentiability requirement: the left and right derivatives at 1 also must be equal
austere moth
$2x + a \
1$
potent lotusBOT
Merineth
austere moth
if x 1
then a has to be -1?
and now i take that info back into the original equation?
or function or w/e it's called
💀
So be has to be 3
a = -1 and b = 3
How did you know that i can put in x = 1?
When it states that x can't be 1 in the second function?
warm kelp
were just using the limits basically as it says x cant be but but x can tend to 1 right?
oblique current
When it states that x can't be 1 in the second function?
But the whole function is defined at 1, you want to check its differentiable at 1 since that's the only problematic point, since they're polys the whole function is definitely differentiable at all other points
warm kelp
like not exactly 1 but 1.000000000000....... and somewhere 9
as the function is continous the values of x=1 ad tending to one will be same
therefore we can put in x=1 in the sec f(x)too
oblique current
https://www.desmos.com/calculator/nbwhy4yeqm
You might wanna play with this to see what's happening graphically, it's currently set to your initial guess a=2, b=0. And you can see that at x=1 the graph has a "kink" in it implying its not differentiable at that point
austere moth
Can i post a new question ehre or
should i open a new?
find g'(x) and simplify
-2/x is correct but now the other fraction
any ideas what i did wrong?
sterile plover
you did not multiply x^2 to it
sterile plover
i just looked at your work lmao. minor mistake
lunar meteor
cotx = cosx/sinx
lunar meteor
that's the first time i heard of that
now you know
oblique current
Yeah its equivalently 1/tan(x). Pretty much all named trig functions also have a name for 1/them since they're used often enough to warrant their own name
cot is short for contangent if that helps you remember. (But this is slightly confusing because cos is short for cosine and is not 1/sin)
lunar meteor
dull wagon
the "co" is short for complementary based on the complementary relations
upper sparrow
One comment is that before you do any differentiation, use log rules to turn what you have into $\ln(\sin(x)) - 2\ln(x)$, as that's easier to work with!
potent lotusBOT
@upper sparrow
dull wagon
avoids having to apply quotient rule, deal with skyscraper fractions, etc
where here you're just differentiating simpler logs with a smaller application of chain rule for one term
dull wagon
attempted what
dull wagon
log rules
you started with a log
what was recommended was the quotient to difference rule for logs
dull wagon
yes
austere moth
it even rhymes
upper sparrow
[also the power one, the $\ln(x^k) = k\ln(x)$ one too]
potent lotusBOT
@upper sparrow
gaunt violet
calm coralBOT
spark stratus
while I work though this, you can use https://desmos.com/calculator and type in each line to make sure that the limit hasnt moved/changed without notice with what youre working with
also from this zoom its not easy to tell some of your exponents
is it $\frac{\sqrt{2a^{3}x-x^{4}}-a\sqrt[3]{a^{2}x}}{a\sqrt[4]{ax^{3}}}$
potent lotusBOT
matt07734
gaunt violet
There should be a minus
Hang on
$\frac{\sqrt{2a^{3}x-x^{4}}-a\sqrt[3]{a^{2}x}}{a-\sqrt[4]{ax^{3}}}$
potent lotusBOT
Josh ♘
gaunt violet
It's It's @spark stratus
spark stratus
btw you should be aware that you can simplify the above to the below
spark stratus
found a typo
other than that missing - sign, the f'(x)/g'(x) you got and the the answer you got at the end would be correct
spark stratus
np
gaunt violet
Wait I don't think that helps?
It just makes my overall answer positive?
@spark stratus it should be 0, no?
spark stratus
its not 0, why would it be 0
I asked you to graph it, and when you graph it its not 0 at all
spark stratus
**matt07734**
you get 0 if you dont type the minus sign in the denominator
gaunt violet
spark stratus
the textbook sure does indeed say 0 instead of 16a/9 for that problem
not sure what the image is for
proper turret
calm coralBOT
fringe reef
!status
calm coralBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
i dont know what exactly to start with
if i take this face
the surface area i found out is 12cm^2
since you shouldnt take the entire surface area of one cube since only one side is taken into account
so i took surface area of one square
and there are 12 squares
so 12A
should i follow this step
or am i wrong
fringe reef
yeah that area is 12
but obv it's not hte whole thing
just consider every face as a rectangle
and calculate each respective area and add them up
proper turret
ok so my approahc is right
calm coralBOT
proper turret
.reopen
calm coralBOT
✅
proper turret
wait
proper turret
how i will i calculate the area of the face in the back and left?
which is out of our view
fringe reef
it's 3 by 4 centimeters
proper turret
what is 3/4?
fringe reef
what is 3/4?
proper turret
for face one SA is 12 cm^2
for face 2 SA is 17cm^2
for face 3 SA is 8cm^2
for face 4 SA is 4cm^2
for face 5 SA is 12cm^2
since the back side is 4 blocks tall
and 4 blocks wide
it should have SA=16cm^2
wait
isnt there a much better approach for this problem
first finish the top layer
fill it in
then find surface area
then since only the top layer is shaved off
subtract that surface area
is that right
spark stratus
I dont trust how youre shaving but thats the ideal way
you find the SA for the rectangular prism this would fit in
then pretend the 3D shape is hollow and push the squares inwards
the 3 squares on the left and the 3 squares on the right are removed
12 of the roof squares move down a cm
4 of the front squares move back by 3cm
if you can see this happen, then thats a more solid shortcut
spark stratus
it should have SA=16cm^2
as for what you were doing before, you were on the right track
all of the face SAs you calculated are correct
youre missing the left face and the bottom face
marsh schooner
the lenghts of the diagonals of a rhombus is 16 and 12 cm respectiviely . find its lenght of its sides ?
dull wagon
how many properties of rhombuses do you know
marsh schooner
2 or 3
dull wagon
can you state the ones you know
marsh schooner
diagonals bisect at 90 degree
dull wagon
diagonals bisect at 90 degree
that's the most relevant one here
apply that
amber bolt
yeah that's all you need
amber bolt
bisect means equal halves
dull wagon
represent that on a diagram if you haven't drawn one already
and you should see that you have right triangles
marsh schooner
yes
dull wagon
of which you know the length of the legs
marsh schooner
?
dull wagon
?
dull wagon
show the diagram you drew
marsh schooner
.close
calm coralBOT
calm coralBOT
Available help channel!
fast dune
so, asking for a bit advanced help, obviously programming but a lot about math, we have n words, in this case, 21, from 0 to 20. for helping, ive added relative pos, as well as the id, [name][id][relative]. the only info i have is the selectedId, everytime i click, the selectedId will be set to id and scroll to a proper position, (in my case, ive set it to 2). however the modulo is a problem, i don't know how to set it up so that it searches for the "shortest" path. (basically instead of scrolling 21th by 20 items, would be easier to scroll to just -1.) i suppose i will have to use some kind of previousId and it's relative distance from selectedId but yeh, out of ideas.
calm coralBOT
so, asking for a bit advanced help, obviously programming but a lot about math, ...
@fast dune Has your question been resolved?
fast dune
ok, i hate to ping people but since it's in the instructions, <@&286206848099549185>, do you mind helping me out? Thank you so much.
if you need my code or anything, i have no problems sharing it. i just wanted to simplify the problem as much as i could
chadjippity didn't really help in this case..
sacred valley
so you have a list and everytime you click on an element you want to scroll to that element
sacred valley
chadjippity didn't really help in this case..
Also it’s called chatgpt
fast dune
chadjippity xd
fast dune
so you have a list and everytime you click on an element you want to scroll to t...
yes, exactly that
sacred valley
what are you using to make this
fast dune
the list is repeating btw
fast dune
what are you using to make this
well, svelte and js
sacred valley
so when you get to the end, it starts from the beginning
fast dune
yes, that's just easy modulo
sacred valley
well, svelte and js
i dont really know anything about svelte though
fast dune
i dont really know anything about svelte though
don't worry, it's like react, but more plasing syntax, simply said i didn't even have to mention it, it's javascript.
sacred valley
your problem is that it doesn’t display the correct relative indexes?
fast dune
oh well, it displays the indexes, that it will do after that, but for example in situation
19 <-
20
0 ->
1
2
instead of getting there by -2, it does +19.
sacred valley
oh thats the problem
fast dune
(id * height * -1) + mod((id - selectedId) * height, itemCount * height)
this is the code i came up with to calculate the position of each item.
to simplify the thing, i can remove the height:
(id * -1) + mod(id - selectedId, itemCount)
also the mod is upgraded % modullo. in js, it acts differently with negative numbers.
if i do
-13 % 5 it returned -3
on stack ive found a method that gives me the expected output, that is,
2
const mod = (n, m) => {
return ((n % m) + m) % m;
};
that's about all i can add to that.
sacred valley
n and m represent what in this case?
fast dune
well it does the classic modullo that everyone is used to from any lang except js, in js, the % is the reminder.
fast dune
do i ping another helper?
upper nova
So... from what I understanded you have ringed-list scroll and you want to get shortest scroll path if you click it?
calm coralBOT
@fast dune Has your question been resolved?
fast dune
So... from what I understanded you have ringed-list scroll and you want to get s...
exactly
upper nova
And you want a fuction that, if you have 0~20 and if you want to move from 0 to 20, will return -1?
I mean, you might be able to use modulo function, but I think one if statement would be enough to do what you need
calm coralBOT
@fast dune Has your question been resolved?
swift pumice
i have a question in terms of quadratic equation
calm coralBOT
i have a question in terms of quadratic equation
swift pumice
So the question goes : a quadratic equation has roots 2 and 4 and the parable top is (3,2)
This is the correct answer
But somehow i only get to f(x)=-2(x-2) (x-4)
how do i get to the last bit?
slate field
you can multiply it out using FOIL (or whatever your favorite method is for multiplying binomials is)
slate field
so like $(x-2) (x-4) = x^2 - 2x - 4x + 8 = x^2 - 6x + 8$
potent lotusBOT
smay
slate field
there are resources that can help you with practice problems for multiplying two binomials
let me find one rq
https://tutorial.math.lamar.edu/extras/algebratrigreview/MultPoly.aspx the first problem here is something like you might see in your class, and it has solutions for all of these problems
swift pumice
lemme quick calculate what you did above. 😄
slate field
oh yeah, let me know if there's anything you need me to elaborate on
slate field
well we can multiply our stuff in any order
so i did the hard part first
and then we can multiply the result by -2
after
slate field
well that is after we combine like terms, notice that after we multiply out the binomials, we have two "x" terms
so we have -2 x
swift pumice
aah
slate field
and -4x
slate field
once we have $x^2 - 6x + 8$, we will multiply all of the numbers by -2 yeah
potent lotusBOT
smay
swift pumice
aaah
It all makes sense now!
Thank god i searched for this channel
So
😄
So how would it look on paper
like this
-2(x^2-6x+8)
?
slate field
yeah
slate field
first one - remember that parentheses are grouping, so when you have your polynomial at the end, you just "group the whole thing together"
slate field
-2(x^2-6x+8)
this one says "multiply -2 by the entire polynomial that I got when I FOILed" which is what we want 👍
slate field
-2(x^2)(-6x)(+8)
this one says "multiply all the terms together" which will just get you something unrelated
swift pumice
ah so the incorrect one would basically tell us something like -2*whatever number we get, then that number times -2 so it gets even bigger/lower
correct?
swift pumice
At least i understand what you mean by the correct version to do the polynomial
slate field
like when you have (thing)(another thing) it means multiply these things together, so when you have the polynomial "x^2 - 6x + 8", then you want to put that (the whole polynomial) in parentheses, because we want to multiply that thing with -2
swift pumice
Yeah but you still take every number for itself and then multiply correct
Since -2*x^2 obviously is -2x^2
slate field
yes, here is the way that you would write the thing that you're trying to say
swift pumice
Sorry, my "math" english is at its early stages. Feels weird being a noob at something in english for a first time in many many years
😛
slate field
$-2(x^2 - 6x + 8) = (-2)(x^2) - (-2)(6x) + (-2)(8)$ - this is an example of the "distributive property" if you have heard of it
potent lotusBOT
smay
slate field
the -2 "distributes" over the terms (blocks) of the polynomial
where by "block" of a polynomial i mean x^2, 6x, and 8
swift pumice
Yeah it makes sense
slate field
-2(x^2)(-6x)(+8)
okay great, do you see how it's different from this?
swift pumice
Very much yeah
slate field
okay great!
swift pumice
Its just nice to understand the difference
Even though that you know one is correct and one isn't
Awesome Smay, you have a good way of elaborating
slate field
:3 ty
swift pumice
I will keep on with my homework here, but i guess i can just give u a heads up if u feel like helping again. I know this math isnt at a very hard level, but its been 10 years since i last studied any math, and now at the age of 29, i need it to start Computer Science here in September
So im trying my best 😛
slate field
feel free to ping me in a help channel if you like
graceful dust
:3
calm coralBOT
what is this problem called
calm coralBOT
clever ruin
Indices
floral violet
indices?
leaden thunder
so i would search how to simplify indices?
,tex .exp rules
potent lotusBOT
dr. matlab plot
floral violet
,tex \.exp rules
how would i describe this particular problem?
leaden thunder
how would i describe this particular problem?
It's in the title
leaden thunder
**dr. matlab plot**
Here
floral violet
exponent rule property?
calm coralBOT
@floral violet Has your question been resolved?
tepid snow
For this question, can’t I just say for any set A in sigma algebra C, we can just consider the set D to be (empty set, omega, A, A^c) which is contained in sigma algebra C, hence Lucy is correct
glass heart
calm coralBOT
@tepid snow Has your question been resolved?
main musk
Would someone be willing to take a look at the following math paper I wrote and give me feedback on it.
main musk
ping me if please if you have something to say 😊
exotic falcon
ping me if please if you have something to say 😊
Not much to say about the paper except maybe you want to blur your name and other personal details
main musk
yup, realized after sending
main musk
Not much to say about the paper except maybe you want to blur your name and othe...
ok well thanks for taking a look
.close
calm coralBOT
calm coralBOT
Available help channel!
obsidian ingot
Help
calm coralBOT
@obsidian ingot Has your question been resolved?
calm coralBOT
leaden thunder
If the question asks for it then yes
dull wagon
its possible for a function to have both
calm coralBOT
dull wagon
wait i was mistaken
frank gull
.reopen 🙂
calm coralBOT
✅
dull wagon
depends on the type of function you have
graceful dust
yes
calm coralBOT
calm coralBOT
Available help channel!
valid bane
I need help with this, If this is for an undirected adjacency matrix I think we can derive the matrix equation with A = D - EE^T where D would be a Degree matrix https://en.wikipedia.org/wiki/Degree_matrix. But the problem is A is directed, how can I derive the adjacency matrix A from the incidence matrix E?
valid bane
this is how to get A and E from the graph if it helps
i try to get to this:
what other operation should I do to turn the bottom matrix into A, the bottom matrix is symmetric while A is not
<@&286206848099549185> 😦 anyone?
valid bane
yes it is
valid bane
digusting yes, the first chapter btw
runic ether
Maybe you can look through your sources again
valid bane
appreciate that!
runic ether
No problem
valid bane
the other questions are manageable but we are forced to deal with graph theory all of a sudden I'm so lost, all resources I have looked into are for undirected version of the graph
calm coralBOT
@valid bane Has your question been resolved?
calm coralBOT
@valid bane Has your question been resolved?
calm coralBOT
@valid bane Has your question been resolved?
calm coralBOT
@valid bane Has your question been resolved?
modern peak
@valid bane DM helpers, sorry i can't help you :( no idea how matrices work
valid bane
<@292937308804612096> DM helpers, sorry i can't help you :( no idea how matrices...
aww, that's totally alright! I appreciate your trying to help tho! thanks kind guy!
modern peak
np
i'm sorry i really can't make sense of this :(
maybe ask WA if you can input the matrices??
valid bane
definitely not your fault or just you tho, I was pretty confident with this assignment until this question came out of nowhere and tore me apart
calm coralBOT
@valid bane Has your question been resolved?
umbral wraith
How to do this?
calm coralBOT
How to do this?
umbral wraith
Ping me w/ a reply please
<@&286206848099549185>
I think that the diagram migth be wrong, I'm not so sure
untold drum
are you searching the length x or the angle?
umbral wraith
The quesetion says the bearing of the ship from its initial position
the bearing, does that make sense?
@untold drum
untold drum
thats - in my humble opinion - typically the marked angle:
umbral wraith
mind if i clarify, wdym by the "marked angle"?
Oh wiat so the marked angle should be x?
untold drum
have you looked at my sketch?
umbral wraith
oh yeah
how do you know which is the marked angle tho
its always the starting point one tho, right ?
dull wagon
that isn't quite the angle they want
but you will need to use that in your calculations
dull wagon
recall that the bearing is mearsured clockwise from north
umbral wraith
tan( 16/5 ) = x , correct?
umbral wraith
tanx = (16/5?)
dull wagon
yes
dull wagon
from
tan(x) = 16/5
use inverse tan
umbral wraith
tan^-1 = 16/5 ?
dull wagon
yeh.
umbral wraith
are you sure its arctan I thought its degrees
umbral wraith
you can convert that to degrees manually
But I don't know how to do that ?
umbral wraith
hm
I'm a bit confused
can you do this step for me? I didnt learn it in school and dont think its necc yet, as i'm only 14
or tell me how
dull wagon
have you done any sort of unit conversions , dimension analysis before?
umbral wraith
no
dull wagon
e.g convert
23.2m to cm
umbral wraith
We are just learning trig + bearings, we dont know that much in trig
umbral wraith
e.g convert
23.2m to cm
well stuff like that iknow
dull wagon
that's what i meant by
have you done any sort of unit conversions , dimension analysis before?
umbral wraith
yes but i dont know what dimension analysis is
dull wagon
unit convertsion type questions
umbral wraith
Like I know how to do conversions of like cm metres km and stuff yeah
I laernt that before
dull wagon
same idea applies here
the underlying principle is multiplication by 1
100cm = 1m → 100cm/(1m) = 1m/(100cm) = 1
to convert from cm to m, you multiply by 1m/(100cm)
to convert to m to cm you'd multiply by 100cm/(1m)
dull wagon
here
pi (radians) = 180°
and apply the same idea
umbral wraith
I see
umbral wraith
I dont hve my calculator with me, is it called arctan?
In this question radians is 1.267
Right?
dull wagon
no
dull wagon
100cm = 1m → 100cm/(1m) = 1m/(100cm) = 1
similarly
pi (radians) = 180°
→ 1 = ?
dull wagon
that's what i'm trying to get you to do
replicate what i did with the conversions between cm and m
follow what i did here
100cm = 1m → 100cm/(1m) = 1m/(100cm) = 1
umbral wraith
> 100cm = 1m → 100cm/(1m) = 1m/(100cm) = 1
I see
hm
I'm quite confused
I dont have much time.
dull wagon
100cm = 1m
i divided both sides by 1m, to get "1" on one side of the equation
which gives 100cm/(1m) = 1
similarly dividing both sides by 100cm will give
1m/(100cm) = 1
umbral wraith
ok
dull wagon
do the same for
pi (radians) = 180°
umbral wraith
> 100cm = 1m → 100cm/(1m) = 1m/(100cm) = 1
similarly
pi (radians) = 180°
→ 1 = ...
so I divide both sides by "180"?
dull wagon
that'll give you one of the conversion factors
dividing both sides by pi will give you the other
which one you should use depends on the units in the numerator and denominator
units of the numerator is the one you want
units of the denominator is the one you want to cancel
umbral wraith
pi * 1.26791 = 180
pi * (1.26791 * 180) = 1
umbral wraith
ok
dull wagon
what do you get when you divide both sides of that by 180°
umbral wraith
pi/180
dull wagon
where's the other side of the equation
umbral wraith
pi/180 = 1 ?
umbral wraith
180 = 1/pi
umbral wraith
man I am just really w orried i hve lots of things on my mind and this agassignment is due tmrw and i have to sleep :/
I dont know
I have 3 questions for this hw left
dull wagon
what's pi/pi
umbral wraith
1
dull wagon
180° divided by pi is 180°/pi
and can be left as is
umbral wraith
ok
dull wagon
dividing both sides by pi would result in
1 = 180°/pi
$$\frac{1m}{100cm} = \frac{100cm}{1m} = 1$$
$$\frac{\pi}{180\deg} = \frac{180\deg}{\pi} = 1$$
potent lotusBOT
ℝαμΩℕωⅤ
umbral wraith
yes i see'
dull wagon
to convert from radians to degrees you'd multiply your value by 180°/pi
and from degrees to radians you'd use pi/180°
dull wagon
to convert that to degrees yes.
dull wagon
that's the angle x in degrees
which won't be your final answer
umbral wraith
o
dull wagon
recall that the bearing is mearsured clockwise from north
dull wagon
which part of
recall that the bearing is mearsured clockwise from north
do you have an issue with
umbral wraith
which part of
> recall that the bearing is mearsured clockwise from north
do you...
what abt tht?
dull wagon
wdym
umbral wraith
I dont understand 72.645 is x but how to get the bearing from that ?
dull wagon
i'm asking you for the specific issue you're having with what i said
which part(s) of that definition of bearing don't you understand
umbral wraith
If x is 72.645 how do I find the bearing ?'
" Find the bearing of the ship from its initial position. " I dont understnad how to do that
dull wagon
start from the line north of the initial position
draw an arc, going in the clockwise direction until you reach line between the initial and final position of the boat
umbral wraith
I dont have time to do that? Can you say answer and tommorow I can go through it, please?
dull wagon
it literally takes 1 second
dull wagon
if you follow the instruction
do you know what north means
do you know what clockwise means
untold drum
Its very late here and its due soonand I have to go
you used more time to discuss it instead of simple drawing it.
dull wagon
wait, i typoed, fixed now
do you see the line connecting the initial and final position of the boat
dull wagon
yes.
now put that all together and
start from the line north of the initial position
draw an arc, going in the clockwise direction until you reach line between the initial and final position of the boat
umbral wraith
dull wagon
yes
dull wagon
that's literally what you calculated earlier
umbral wraith
yeah i get it
dull wagon
from arctan(16/5) and converting the radians result to degrees
umbral wraith
72.65 is 2DP, right ?
dull wagon
yes
dull wagon
did you even read what i said?
that angle will be the bearing
referring to the red angle/arc i told you to draw
umbral wraith
yeah
dull wagon
and i already said that angle wasn't the one they wanted