#help-42

1 messages · Page 40 of 1

drifting seal
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does this make sense

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@fossil quest

fossil quest
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u think u can write it ?

drifting seal
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yea sure

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ignore the work above it

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@fossil quest

fossil quest
drifting seal
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because ur adding on the top

fossil quest
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Like I did here

drifting seal
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not multiplying

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think of dividing by 2 as multiplying by 1/2

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u have to distribute the 1/2 to each term

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not just the first

fossil quest
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Oh wait

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I see it

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Ohhhh I got it now

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Ty

drifting seal
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no problem

calm coralBOT
#

@fossil quest Has your question been resolved?

calm coralBOT
#
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cedar ether
#

A complex valued function, depending on a real variable and defined on $A$, is integrable if it's real and imaginary parts are integrable. Suppose we have $$\int_A |f|<\infty,$$are then the real and imaginary parts also integrable, i.e. finite?

potent lotusBOT
#

Philip

cedar ether
#

.close

calm coralBOT
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prime salmon
#

.

calm coralBOT
remote mural
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goddamn bro not these many questions at a time please no one's helping you with all these

sage cosmos
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It would have helped if you posted 1 question first and after we helped you, you move to other

prime salmon
remote mural
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so you dont know how to solve system of equations?

prime salmon
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lets start with this

sage cosmos
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Do you know how to write slope intercept form equations

prime salmon
sage cosmos
prime salmon
sage cosmos
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So do you know what's the slope and y intercept?

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If you know then the question is easy

prime salmon
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I justnknow the meaning

sage cosmos
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If you know the meaning you can solve it

prime salmon
sage cosmos
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tell me what's the y intercept

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since you know their meaning

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I only what to know the meaning

prime salmon
sage cosmos
prime salmon
sage cosmos
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Y intercept is the point where y axis cuts the graph

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So you can know what the b is by looking at the graph

prime salmon
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b=5

sage cosmos
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There are 2 lines so 2 bs

prime salmon
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but they only touch ones

sage cosmos
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Also 5 ain't the y intercept for both

prime salmon
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but its the the part when the two lines meet

sage cosmos
sage cosmos
prime salmon
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You mean 2 and 4?

sage cosmos
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Yes

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Y intercept will be the point on y axis where the line meets

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So now you know the b's, it's time to move on to m (slope)

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Can you tell, what is a slope?

prime salmon
sage cosmos
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Also it's "slope" spelling

prime salmon
remote mural
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slop is just cute

prime salmon
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but i forgot what slope in math means💀

prime salmon
sage cosmos
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Do you know what's tan theta is?

prime salmon
sage cosmos
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Trigonometric ratio

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Tangent

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Tangent of an angle, which I assumed theta here

prime salmon
sage cosmos
prime salmon
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@sage cosmos can we just go through answers becuse its kinda late for me

sage cosmos
prime salmon
remote mural
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i mean its the same thing as you said, tan value of the angle the line is making from positive x axis

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but he dont know what tan is

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so its kinda difficult

prime salmon
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in both ways i will learn

sage cosmos
remote mural
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i can just share a video with you so that you understand slope better

remote mural
prime salmon
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we can learn tomorrow

sage cosmos
prime salmon
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am

sage cosmos
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If we provide answer to someone because he is late or because of some sorrowful circumstances, then that will become excuse for anyone and discipline will be lacking in our cause to help people learn

remote mural
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right

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just watch any video bro it'll help

#
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these are some short lectures

sage cosmos
prime salmon
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but other lessons

sage cosmos
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It could be said unfortunate then

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Math was treated unfairly by you because you gave other lessons priority

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So now math is giving back karma

prime salmon
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math was my love

remote mural
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ok lets just not fight 😭

sage cosmos
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👍

prime salmon
remote mural
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instead of wasting time here

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go watch the vids

sage cosmos
remote mural
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HUH WHAT LMAO

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i did

sage cosmos
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Yes

remote mural
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yea lol

prime salmon
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anyways

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i gotta sleep and learn tomorrow

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Gn yall

remote mural
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gn

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!done

calm coralBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

#

@prime salmon Has your question been resolved?

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signal crater
#

Which statements are true or false?
A={0,2,{0,2},∅,{1}}
B={1,{0},{0,{0,2}}}

  1. {0,2} ∈ A ∩ B
  2. ∅ ⊆ B
  3. {0,1} ⊆ A ∪ B
  4. {1} ⊆ A
  5. 1 ∈ A
  6. {0,2} ⊆ A ∩ B
  7. 0 ∈ B
  8. {{0},{1}} ⊆ A ∪ B
  9. {0,{1}} ⊆ A
  10. |B| = 5
    1- True, {0,2} is an element of A intersect B as {0,2} appears in both sets.
    2- True, The null set is always a subset of a set.
    3- False, {0,1} is not a subset of A union B as neither set has {0,1}.
    4- True, {1} is a subset of A
    5.- True, 1 is an element of {1}
  11.  True, {0,2} is a subset of A intersect B as {0,2} appears in both sets
    
  12.  True, 0 is an element of {0}
    
  13.  False, {{0},{1}} is not a subset of A union B, but the individual {0} and {1} are each subsets of A union B.
    
  14.  False, {0,{1}} is not a subset of A
    
  15. False, the cardinality of B is 3
    

I’m not sure where I’m going wrong as the corrector only accepts if all the answers are right.

potent igloo
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1- True, {0,2} is an element of A intersect B as {0,2} appears in both sets.
Where are 0 or 2 in B?

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Oh derp nvm I read it wrong

frank gull
potent igloo
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3- False, {0,1} is not a subset of A union B as neither set has {0,1}.
Are you confusing this with ${0, 1}\in A\cup B$?

potent lotusBOT
signal crater
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oh i might be

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but does everything else make sense?

potent igloo
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5.- True, 1 is an element of {1}
Same question

signal crater
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A={0,2,{0,2},∅,{1}}

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im a bit confused as to why those two questions are different

potent igloo
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But where is 1? I see {1}, but not 1

signal crater
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oh

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1 is not there

potent igloo
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yeah

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Most of them are having this same problem

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I guide you to review all of your answers again with this in mind

signal crater
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do you mind explaining the difference between ⊆ and ∈?

potent igloo
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x⊆y means that every element that is an element of x is also an element of y

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Integers are a subset of all real numbers

calm coralBOT
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@signal crater Has your question been resolved?

calm coralBOT
#

@signal crater Has your question been resolved?

calm coralBOT
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pliant forum
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how am I wrong if the integration limits are only 4 to 5?

leaden thunder
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Only below it

pliant forum
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yes but the bounds are only between 4 and 5?

leaden thunder
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Yes

pliant forum
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4 to 5 should only represent under x-axis? 5 to 6 is above

leaden thunder
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But you're asked to calculate the area from 5 to 6 using the information about the area from 4 to 5

pliant forum
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no the 4 to 5 was setup by the website

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not me

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i had no choice

leaden thunder
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Yes I know

pliant forum
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oh I see what you are saying

leaden thunder
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int 4 to 6 = 2 * int 4 to 5

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The regions have equal area

pliant forum
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I see thank you

#

.close

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flint axle
calm coralBOT
flint axle
#

is it 9.2?

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<@&286206848099549185>

calm coralBOT
#

@flint axle Has your question been resolved?

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shadow tendon
#

Do you know what the average value is?

jolly sapphire
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no you picked the correct one

shadow tendon
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Yeah

jolly sapphire
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it does not need to be

shadow tendon
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To find average its not needed

jolly sapphire
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if its continuous it will reach the average value

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but if its not continuous it may or may not

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in this case it doesnt

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if you have 1 cookie and your friend has 0 cookie you have an average of 0.5 cookies together

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that makes sense

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but none of you has 0.5 cookie

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its pretty much the same here

calm coralBOT
#
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smoky crane
#

How do I determine the limit of this? And how do I know if it converges or not?

smoky crane
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Gut feeling tells me it converges somewhere between 0 and 1 but I am nit sure

low pasture
#

You can expand the fraction

calm coralBOT
#

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keen zodiac
calm coralBOT
keen zodiac
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Wolfram says the limit does not exist

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But even if so, how do i check it?

noble wasp
#

An engineer is not a fairy, so i would say that the limit does not exist

calm coralBOT
#

@keen zodiac Has your question been resolved?

sterile plover
#

you can look at the paths y=1 and x=0

keen zodiac
#

?

calm coralBOT
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warm grove
#

hello

calm coralBOT
warm grove
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i need help for this

torn gorge
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nice

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by the second equation you will get $y=x^{2/3}$

potent lotusBOT
warm grove
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yes

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first is y=lny^x/lnx ?

torn gorge
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since you can always extract the third root of a real number

torn gorge
warm grove
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ok

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so i replace y from x2/3

torn gorge
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by using what i got: $x^{2/3}\ln x=x\ln x^{2/3}=\frac{2}{3}x\ln x$

potent lotusBOT
torn gorge
#

we can simplify $\ln x$ when $x\neq 1$

potent lotusBOT
torn gorge
#

if x=1 then we get the trivial solution x=y=1

torn gorge
warm grove
#

how i do this

torn gorge
#

in the LHS you got $x^{\frac{2}{3}-1}$

potent lotusBOT
warm grove
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yes

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i need to multiply by sqrt3 x

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to the 2

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then i put all in ^3 ?

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?

torn gorge
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seems correct (sorry i got an exam today so i might misread something because of tiredness) to me

warm grove
#

how i can verify

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if its correct ?

torn gorge
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now find the y value from the first equation we have used...then plug these values in the system

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and check if the equalities are verified

warm grove
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but the x is correct ,

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?

torn gorge
#

you have to find first the y value and then you can checl if your (x,y) are correct

warm grove
#

ok ty

calm coralBOT
#

@warm grove Has your question been resolved?

calm coralBOT
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frosty mica
#

Can someone check this rq?

calm coralBOT
remote mural
frosty mica
#

I figured as much. Always helps to have a second pair of eyes.

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Can you point them out to me?

remote mural
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PvQ means P or Q so there are two mistakes in that column

frosty mica
#

Ah, I looked at the wrong column

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is the entire last column true?

mortal orbit
#

no it should be all trues

frosty mica
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I thought that's what I just said

mortal orbit
#

there's a false in the last column

frosty mica
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I know.

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I already established that one was wrong

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I was asking if the entire last column was true.

mortal orbit
#

the row? the column?

frosty mica
#

Column

mortal orbit
#

yes its all trues

frosty mica
#

Ok.

#

That's what I thought

#

.close

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minor musk
#

i have an equation x^3/x^2-1 how do i calculate the vertical asymptote

minor musk
#

the domain is 1 and -1 so do i have to calculate it for both values?

humble ivy
#

You mean x^3/(x^2-1), right?

minor musk
#

x^3/x^2-1

humble ivy
#

Send a picture, because what you are saying now is this: $$\frac{x^3}{x^2} - 1$$

potent lotusBOT
humble ivy
#

You probably mean $$\frac{x^3}{x^2-1}$$

minor musk
#

the -1 is under the fraction

potent lotusBOT
minor musk
#

yeah

humble ivy
#

If you write this down in text, you need to use parentheses

minor musk
#

alright

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so how do i get va

humble ivy
#

You already found them, x = -1 and x = 1

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vertical asymptotes occur if the denominator is 0

minor musk
#

i know but that means there are 2?

humble ivy
#

Yes, it does

minor musk
#

alright so the graph is going to be restricted by a vertical line at 1 and -1?

humble ivy
#

Yeah, the function isn't defined at x = -1 and 1

minor musk
#

oki thx

#

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pulsar jolt
calm coralBOT
pulsar jolt
#

need

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7 8 9 questions

exotic iron
calm coralBOT
#

@pulsar jolt Has your question been resolved?

pulsar jolt
pulsar jolt
#

<@&286206848099549185>

pulsar jolt
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.close

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weary goblet
#

I'm having some like terms/distributive property troubles. I've gotten this problem wrong a few times and this website gives me 3 chances before generating a similar problem. I think I'm doing the distributive property incorrectly but I have no idea what I could possibly be doing wrong. For instance when I was given the task to simplify -3 (5n - 5) + 2n, I tried distributing the -3 to the terms in parenthesis (-3 × 5n=-15n and -3 × -5 = 15) and then adding 2n to the 15n to get 17n, but 17n - 15 was incorrect as was 17n + 15. I'm not very good at math so this might be super obvious to somebody but I'm completely lost. here's the problem I have right now

primal nebula
#

instead you did 15n - 15 + 2n which is why you got 17n - 15

weary goblet
#

that makes sense, I get my negatives and positives mixed up sometimes

primal nebula
#

let me know if you continue having trouble with this question

calm coralBOT
#

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white edge
#

I'm working on a homework assignment for my class, but I am stuck on a specific question. The question is to form a polynomial in standard form using the real zeros provided. Using the Factor Theorem and Conjugate Pairs Theorem, you get this: f(x) = (x+7)(x+i)(x-i)(x+8i)(x-8i). I'm struggling to correctly convert this function into standard form. Ignore the formula in the blue box, that was my latest incorrect answer.

white edge
#

DM me if you have questions. I'll post some screenshots for the theorems I mentioned if you need them.

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Summary: I am struggling to convert f(x) = (x+7)(x+i)(x-i)(x+8i)(x-8i) into standard form of a polynomial. All 'i's in the equation are imaginary numbers.

civic dirge
#

I suggest multiplying out the pairs, first

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Otherwise it's just tedious algebra

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,w (x+7)(x+i)(x-i)(x+8i)(x-8i) expanded form

calm coralBOT
#

@white edge Has your question been resolved?

white edge
#

good try tho, this question is a nightmare

marble escarp
#

How x+8i ?!

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root is 8 + i

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not 8i

white edge
#

dang it I typed incorrectly!!

marble escarp
#

Yeah

white edge
#

that one is on me

marble escarp
#

lol

white edge
#

gonna have to work on this later, but thx for the assist

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the problem automatically changes

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unfortunately >.<

marble escarp
#

Rip

white edge
#

we may have lost this battle, but we haven't lost the war!!

marble escarp
#

xD

white edge
#

going to close now

#

.close

calm coralBOT
#
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oak remnant
calm coralBOT
oak remnant
#

Wait so is the 42 degree angle and x add to 180?

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since they are interior angles??

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How do we find the angle BAD?

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I found that the third angle in the triangle BAC is 29 degrees

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Does that mean anything?

final raptor
#

x is 42°

oak remnant
#

how?

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Bro it's not 💀

final raptor
#

so you have the third angle of BAC which is 29

oak remnant
#

I got the problem wrong...

final raptor
#

huh

#

oops

#

wiat

oak remnant
#

naw x=29

final raptor
#

IM SORRY

oak remnant
#

thats fine...

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I'll just start again

final raptor
#

oh right because of the

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thingy

#

stufenwinkel

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in german

oak remnant
#

I hate geometry

final raptor
#

i get confused with geometry

oak remnant
#

same

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.close

calm coralBOT
#
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burnt ferry
calm coralBOT
burnt ferry
#

Im sorry WHAT??

#

How did they even get that (98/81)pi??

#

nvmm figured it out

#

.close

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remote mural
calm coralBOT
remote mural
#

How do I identify the change of rate?

idle marten
#

Do you know what the rate of change is?

#

like define it

remote mural
#

Slope

#

Of the line

#

What?

remote mural
#

I hope it would explain it

#

And then attempt

#

The question

remote mural
#

You must know your theory well before doing questions or it would just be a waste of time

idle marten
#

Rate of change is the of y over the change of X

remote mural
#

The videos don’t really help

idle marten
#

Do you agree?

remote mural
#

Yea

#

idk where to put the dot

idle marten
#

so when we look at the line we need to analyze how much y changes when x changes

#

So you need to pick 2 points to find that right

#

The best points are coordinates that are integers

remote mural
#

Nvm it won’t let me pick

#

The points

#

But I’ll listen

idle marten
#

listen to what?

remote mural
#

So like that basically

#

That’s an example

idle marten
#

Can you do that with the original line now

remote mural
#

It won’t let me put points

#

It’s just an answer

idle marten
#

Yes

#

The “points” are just a visual representation of the rate of change

remote mural
#

Mhmm

idle marten
#

Because it is 5 increase over 2 increase

idle marten
#

we want to pick ones that intersect the graph lines so we know the exact value

#

@remote mural I see a point on the y axis and another point in the 4th quadrant of the graph

remote mural
#

Which quadrant?

#

Top right?

idle marten
remote mural
#

Ok

idle marten
#

So point 1 is…

remote mural
#

-5? Idk man

#

I’m not good at math

idle marten
#

Uhhh

#

Srry I’m not the best at explaining

remote mural
#

Ur good

idle marten
#

Can you select a point on the graph that intersects the line

remote mural
#

I’m just not good at understanding

idle marten
#

A coordinate that the line goes through

#

Can you select the point that the line intersects on the y-axis?

#

It’s the big vertical black line

remote mural
#

Alr

#

2

idle marten
#

What is 2?

#

Do you know what a coordinate is btw

remote mural
#

Kinda

#

Well I know

#

Just don’t know how to explain

idle marten
#

Ok so the coordinate is (x,y) where x is the horizontal value and y is the vertical value

#

One point on the line is (0,4)

#

can you find that point on the graph

remote mural
#

Yea

#

The vertical line going up

idle marten
#

That’s called the y axis

#

Ok so we have our first point

remote mural
#

Yea that

idle marten
#

Can you select another coordinate that the line crosses

remote mural
#

Like on the y axis?

#

Or the x axis

idle marten
#

No not on the axis

#

It’s on the lien

#

a point on the line

remote mural
#

-1

#

.close

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#
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idle marten
#

the slope is -7

#

._. Rip

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remote mural
#

oh

#

never mind

#

.close

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dull rune
#

42

calm coralBOT
dull rune
#

life's meaning revealed

#

can you guy's help

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#

@dull rune Has your question been resolved?

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dense cargo
calm coralBOT
dense cargo
#

I don't get why I'm getting part b wrong

#

It looks right when I eyeball it

#

I tried -1,2, didn't work either

#

.close

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dense cargo
#

Nvm I'm dumb

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slim cliff
#

i just wanna know how he got -8+a from |8-a|

potent igloo
#

If 8-a<0, then |8-a|=-(8-a)

calm coralBOT
#

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frozen dome
#

i can solve this but wondering if theres an algebraic way that doesnt involve guess and checking

frozen dome
#

its from a past paper for a timed test

crude moat
#

I will need one sec to check

frozen dome
#

i am able to solve it but it required longer than i wanted to take considering it is only 2 marks

#

i dont wanna need to guess and check

muted lotus
#

Rewrite 16 = 2^4 and 81 = 3^4

frozen dome
#

Btw the question is only talking about positive ints

frozen dome
muted lotus
#

Then you know that a and b must be powers of 2 and 3 respectively

frozen dome
#

Oh ive found one online that makes sense

#

Still just a really bad question especially with how they worded it

#

.close

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quaint sphinx
#

@muted lotus ?

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shadow leaf
#

I'm stuck

calm coralBOT
shadow leaf
#

I have no idea what the next step is

#

Solving for n

hexed grove
#

i think youll need the lambert w function for this

#

unless there is some clever trick here

shadow leaf
hexed grove
#

its defined $$W(xe^{x})=x$$

potent lotusBOT
#

Cycadellic

shadow leaf
#

What's the W

#

A constant?

hexed grove
#

the function is the W

leaden thunder
shadow leaf
#

Is there another way to solve it?

leaden thunder
#

! original

calm coralBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

shadow leaf
#

Given that R~B(n,0.8) and that P(R>n-1)<0.006 find the least possible value of n

leaden thunder
#

You can use inverse binomial distribution calculator

shadow leaf
#

How do I do that

#

I have calculator fx-570ex

calm coralBOT
#

@shadow leaf Has your question been resolved?

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hollow relic
calm coralBOT
hollow relic
#

How do I write this as a sum or difference of logarithims

#

Is this right?

#

Nvm that's wrong

#

restrictions: a isn't equal to 0, b isn't equal to 0

#

<@&286206848099549185>

lone radish
#

$\log{\frac{a^{3}\sqrt{ab}}{(ab)^{2}}}$

potent lotusBOT
#

Gowtham

lone radish
#

and

#

use $ \log{xy} = \log{x} + \log{y}$

#

$ \log{\dfrac{x}{y}} = \log{x} - \log{y} $

hollow relic
#

that didn't work

calm coralBOT
#

@hollow relic Has your question been resolved?

hollow relic
#

<@&286206848099549185>

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#

@hollow relic Has your question been resolved?

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normal wasp
#

I got 2 chords that come from the same point the big one is 12cm and the smaller one is 10cm. The distance betwwen the small ones midpoint to the big chord is 4cm need to find the radius of the circle

winter loom
#

Draw a figure if you haven't already. If you already have one, might as well post it.

normal wasp
#

@winter loom

#

<@&286206848099549185>

remote mural
# normal wasp

A perpendicular drawn from the centre of the circle bisects the chord

#

You can use Pythagoras theorem to find that

#

Let the centre be O
Let the chord be AB with midpoint M

Here you have to find OA

#

OA² = OM² + AM²

I hope you get it

normal wasp
#

wha would om be tho

#

2?

#

@remote mural

sacred valley
#

would be funny

remote mural
normal wasp
#

So the radius is sqrt41?

remote mural
#

Yeh

normal wasp
#

Thats wrong

remote mural
#

What the answer then

#

Wait

#

Is that 12

#

Diameter

normal wasp
#

12 why

#

Its ghe chords

remote mural
#

Radius = diameter/2

#

6

normal wasp
#

Both of them a chords

remote mural
#

Oh yeh yeh
My bad 💀

#

I thought that diameter

normal wasp
#

The correct answer is 6.25

remote mural
#

Sorry bud
I was thinking of something else
Sorry

#

I don't get the question

normal wasp
#

So you don’t know how to do it?

remote mural
#

I think i do

normal wasp
#

What don’t you get ask

remote mural
#

The diagram you have made is completely irrelevant

#

To what it should be

normal wasp
#

Yea mb then

#

How would the correct one look like

remote mural
#

I might be just wrong or something
Can't help i guess

#

It should be somewhat like this

#

MN is the distance between them

normal wasp
#

No

#

The chords come out of the same point

remote mural
#

sully yeh i am dumb idk

normal wasp
#

Thats ok maybe someone else can help

#

.close

calm coralBOT
#
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lusty kayak
#

Hello

calm coralBOT
lusty kayak
#

I need to translate this but the question says u and v in the room and to solve $u=(2,-5,3)$ , $||v||=6$ and the $\theta$ between the two vectors is $\frac{1}{2}\pi$

potent lotusBOT
#

Totalani

lusty kayak
#

the formula says $u\cdot v=||u|| ||v|| \cos(\theta)$

potent lotusBOT
#

Totalani

lusty kayak
#

So i got it to $6\sqrt{ 38 }$ but im not getting the correct answer

potent lotusBOT
#

Totalani

past zinc
lusty kayak
#

ah fuck you are right

#

its 0

past zinc
#

ofc

lusty kayak
#

for some reason my brain thought just ignore it since its 0

#

but it all becomes 0

past zinc
#

it's ok )

lusty kayak
#

thank you !

#

.close

past zinc
#

yvw)

calm coralBOT
#
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tame shadow
#

how do i determine the sum of this series?

alpine stone
#

You can start by simplifying the denominator of each term

tame shadow
#

you mean like having 2/n(n+1)

#

?

halcyon ravine
#

Yes

tame shadow
#

what should I do afterwards? I'm having an exam soon with these types of exercises and i can't wrap my head around it no matter how hard i try

winter loom
#

The sum telescopes.

tame shadow
alpine stone
#

Use partial fraction decomposition on 1/(n(n+1))

tame shadow
alpine stone
#

Yeah, that

tame shadow
#

okk thanks

#

.close

calm coralBOT
#
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pliant niche
#

when i use this formula and my B value is negative

pliant niche
#

does this negative cancel out

pliant niche
crude moat
#

Yes

pliant niche
#

ty

#

.close

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#
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normal wasp
#

i have a triangle the sides are 10 17 and 21 in that triangle there is a rectangle inscribed in it the ractangles 1 side is on the triangles big side the ractangles perimeter is 24 need to find the ractangles side

normal wasp
#

<@&286206848099549185>

paper obsidian
#

It could be anything, no?

normal wasp
#

its not the whole big side of the triangle just some of it

#

no i need to solve i

#

t

paper obsidian
#

Probably. 24+24+12+12≠24

normal wasp
#

educated guess is no good

#

and the answer is not even a whole number

paper obsidian
normal wasp
#

yea

paper obsidian
#

Like about the triangle maybe?

normal wasp
#

bro what are you even talking about?

paper obsidian
#

Trolling prolly

normal wasp
#

fen idk theres no more info just that

#

ok

#

your right

#

i dont need your help thp

#

pls help someone else

paper obsidian
#

@remote mural chill.

paper obsidian
#

Long/short

normal wasp
#

all the sides

#

but if i find 1 ill find every other one

#

so i just 1 side would do

#

the answer is not a whole number ik that

paper obsidian
#

I just dont understand how come there is one answer

#

We can inscribe infinite rectangles into that triangle with a parameter of 24

#

So if we say that the side of the rectangle thats on the big side of the triangle is x

#

Then we get that the height of the rectangle is 12-x

#

So lets say the recatngle is ABC and x is on AB side which is 21

normal wasp
#

the ractangles side thats on the triangle is not the whole triangles side

paper obsidian
#

Obviously

#

We wouldnt be able to inscribe a rectangle if it was equal to that side

normal wasp
#

yea

paper obsidian
#

So the rest of AB that is not covered by x is 21-x

#

There are two unequal small segments sum of which us 21-x

#

Nah there is no way

#

I say there is not enough info to solve this

#

<@&286206848099549185> we got a situation here

normal wasp
#

idk thats all thats given

sterile plover
#

are you sure it's a rectangle not a square?

paper obsidian
#

It would make much more sense if it was a square tbh

sterile plover
#

hmmm but it would be just side is length 6 lol

paper obsidian
#

Basically, yeah

normal wasp
#

its a ractangle

#

ill tell the correct answers if that helps

paper obsidian
#

Go on

normal wasp
#

6 6/13 and 5 7/13

paper obsidian
#

You can close this channel, copy your message and make a new one to appear on the top of the help channels. People notice you easier, I tried it a few times.

normal wasp
#

wait

paper obsidian
#

Thats all I can help withhmmCat

normal wasp
#

can you help me with something else it simpler

paper obsidian
#

Sure

normal wasp
#

should be

#

ok so

#

a pyramids base is a parallelogram the sides of the parralelogram is 10 and 18 the area is 90 of the paraleloram the pyramids hight is 6 and it land at the toching point of the parallelograms diagnals i need the pyramids faces surfice area

#

so not the base just the faces

#

Looks something like this

#

Ignore the top bits just the pyramid

paper obsidian
#

Can you find the height of the base?

#

You have the area and the side (choose any)

#

If you dont know how to do it, tell me so I explain. Phone's battery is dying, we gotta be quick

normal wasp
#

9

#

right

paper obsidian
normal wasp
#

ok whats next lets do it fast

paper obsidian
#

And the other height would be?

#

Use the other side

normal wasp
#

90/18

paper obsidian
#

Yeah, thats 5

normal wasp
#

oh yea now what

paper obsidian
#

Can you draw these heights on your paper so that they cross the touching point of the diagonals?

#

And show it here

normal wasp
#

the hight are for the parallelogram yes?

paper obsidian
#

Yep

normal wasp
#

how do i draw it so it touches the diagnals point

paper obsidian
#

Like this

normal wasp
#

oh yea

#

now what

paper obsidian
#

Yeah so can you connect the top of your pyramide to the points where these heights meet the sides of the parallelogram?

normal wasp
#

yea

#

ok so h is 6

#

do i do pyth

#

now

#

6^2+9^2?

paper obsidian
#

No

#

Pyth is only for right triangles

normal wasp
#

then whats next

paper obsidian
#

When you connect the top you should get this

normal wasp
#

yes

paper obsidian
#

To do pyth you need to fing length between red and blue dots

normal wasp
#

4.5?

paper obsidian
#

Yeah

#

From there you find the yellow to blue side and the area of that triangle

#

You do the same on the other side (dont forget to split in half the height)

normal wasp
#

wait

paper obsidian
#

Yeah?

normal wasp
#

sqrt56.25

#

got that

paper obsidian
#

Correct

normal wasp
#

sqrt42.25

#

the second one

#

now what

paper obsidian
#

Yep

#

Thats the height of those triangles

#

You need to calculate their areas

normal wasp
#

6*4.5 no?

paper obsidian
#

No no

#

You need the area of the right triangle

paper obsidian
#

The base is given

normal wasp
#

so base is 10

paper obsidian
#

Yep

normal wasp
#

h is that

#

is that enough gor the area?

paper obsidian
#

Yes

#

The area of the triangle is base times height divided by two

normal wasp
#

10*sqrt5625/2

paper obsidian
#

Yeah

#

So its 5 times sqrt 56.25

normal wasp
#

75/2

#

oh 5

#

i did 10 wait

paper obsidian
normal wasp
#

thats 10 tho

paper obsidian
normal wasp
#

oh yea

#

now what

paper obsidian
#

We have 10 times 1/2 times height

#

So have one triangle

#

3 more to go

normal wasp
#

one is the same as that right

paper obsidian
#

Yes

#

The opposite one

#

So we get 75/2 times two which is 75

normal wasp
#

so we got 75 as 2 area

paper obsidian
#

Area of those triangles, yes

normal wasp
#

yea

paper obsidian
#

Now do the same for the other two

#

And then add the area of the base and you get the full area

normal wasp
#

ok i did it 117/2

#

so its 117

paper obsidian
#

Yes

normal wasp
#

and the surfice area is 192

#

i love you ong

paper obsidian
#

No no

normal wasp
#

thanks a lot

paper obsidian
#

Wait

paper obsidian
normal wasp
#

i dont need the base

#

the problem says no base

paper obsidian
#

Oh k

normal wasp
#

just the faces

paper obsidian
#

Glad to help

normal wasp
#

thanks a lot

paper obsidian
#

Good luck :>

normal wasp
#

u2

#

.close

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sturdy acorn
#

How do I know whether to use power reduction formula as opposed to pythagorean identities? (Sin^2 = 1 - cos^2)

exotic falcon
#

what are you trying to solve?

#

Typically, if this is for integrals, you use the power reduction formula if there is a sin^(2) or a cos^(2) left by themselves with no other sine or cosine terms involved in the integrand.

#

and otherwise you do a u-substitution, and then use the pythagorean identity

sturdy acorn
#

I was just going through some example problems, but I’m not Referring to a specific problem. Since sin^2 can either become (1-cos2x)/2 OR/also 1-cos^2

#

So sin^2 equals both of them?

exotic falcon
#

yes

#

(1**+**cos(2x))/2 = 1 - cos^(2)(x)

sturdy acorn
#

So if doing u sub, then use pythagorean identity

exotic falcon
#

but it should be a +

sturdy acorn
#

And if just by itself, use reduction?

exotic falcon
#

Yeah

#

if a u-sub is possible

#

it's probably nicer to do

#

but if there's nothing to be the du

#

then use reduction

sturdy acorn
#

Ok i see

sturdy acorn
exotic falcon
#

yes

#

my mistake

#

not a +

sturdy acorn
#

Ok i see

sturdy acorn
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hardy canopy
#

I need help with the five disk covering problem: https://mathworld.wolfram.com/FiveDisksProblem.html. For five symmetrical disks placed, how is it that the radius is equal to 1/phi? I understand its something to do with the pentagon but I have no concrete idea why.

hardy canopy
#

<@&286206848099549185>

exotic falcon
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hardy canopy
#

cool

#

<@&286206848099549185>

exotic falcon
hardy canopy
#

its been more than 15 minutes

#

I thought it was once per 15 mins

exotic falcon
#

It is only once total

hardy canopy
#

alright

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@hardy canopy Has your question been resolved?

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@hardy canopy Has your question been resolved?

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@hardy canopy Has your question been resolved?

hardy canopy
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.close

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neon jetty
#

Pls help

calm coralBOT
empty tartan
#

consider this: the total number of arrangements will be 5x4. Then, we can consider the first ball. The first ball cannot be 1, otherwise it cannot sum to 7. So 4 possible balls at first. The second ball has 3 options.

empty tartan
#

because we have 5 options at first right

#

then since we used that first ball, there are 4 left to choose the second ball from

neon jetty
#

so there will be 3 left to choose

#

?

neon jetty
wanton wave
#

I think it's simpler to think of this in terms of combinations (non-ordered)

#

How many combinations of two balls exist? How many of them have a sum of 7?

wanton wave
#

Okay, and how many possible combinations exist total?

wanton wave
#

No, I mean how many combinations of two balls exist total?

wanton wave
#

Do you know nCr?

neon jetty
wanton wave
#

yes

neon jetty
wanton wave
#

This is exactly the kind of thing it's for

wanton wave
#

You have five balls. How many combinations of two are possible?

neon jetty
#

so 5C2?

wanton wave
#

No, there are only five balls

#

yeah

#

5C2 is the total number of pairs

neon jetty
wanton wave
#

yep, and like you said, 2 of them have a sum of 7

wanton wave
#

so

#

10 pairs are possible

#

2 of them have the property you want

#

So what is the probability that you get a pair with the property you want?

neon jetty
#

10 x 2?

#

or 2/10?

wanton wave
#

2/10, yeah

#

2 out of 10 pairs

neon jetty
wanton wave
#

yep

neon jetty
#

so combination is used when order doesn't matter

#

how does that apply to this question

#

🗿

wanton wave
#

well because you don't care the order in which you draw the two balls

#

3 then 4 or 4 then 3

#

either way it adds to 7

neon jetty
#

but how do I know it quickly I should use combination

#

I get stuck on these types of question

wanton wave
#

Like, whenever you're choosing a group from a larger set

neon jetty
#

alright I look through it

#

.close

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timid minnow
#

hello

calm coralBOT
timid minnow
#

I need help on this

#

This is the question

#

The paper is my work

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@timid minnow Has your question been resolved?

timid minnow
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.close

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junior frigate
#

for the function y = slope*x+b

calm coralBOT
junior frigate
#

y = 1/6
slope = -1/18
x = 3

#

when i calculate it i get

1/6 = -1/18 * 3 + b
1/6 = -3/18 + b
1/6 = -1/6 + b
0 = b
#

hower b should be 1/3

#

where did i go wrong?

storm stirrup
#

1/6 + 1/6 is not 0

junior frigate
#

oh wait

#

damn i see

#

well that explains it thanks for the quick help

#

.close

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charred fable
#

Anyone help pls🙏

muted lotus
#

No

steep trout
#

48

charred fable
#

thanks. I was desperate for ur help

steep trout
#

Is this your electronic homework

charred fable
#

Yes

#

For sure

calm coralBOT
#

@charred fable Has your question been resolved?

charred fable
#

<@&286206848099549185>

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lost ice
#

so for cartesian bounds c: i have tried -sqrt(5^2-y^2) -> sqrt(5^2-y^2) , and -5 -> 5

lost ice
#

both are wrong.

remote mural
#

i dont think you can have a numerical value for c and d

#

they gotta be in terms of the next variable

#

so like

#

,, c = -\s{5^2-x^2} \tss{and}d = \s{5^2-x^2}

potent lotusBOT
lost ice
#

this is what i thought it was !