#help-42

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calm coralBOT
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normal gorge
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.reopen

calm coralBOT
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normal gorge
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plz guys help me

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this is question

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27 a

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<@&286206848099549185>

calm coralBOT
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@normal gorge Has your question been resolved?

normal gorge
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<@&286206848099549185> no help yet plz

normal gorge
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<@&286206848099549185>

sly coyote
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just draw a squiggly line

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it's the motion of the ocean that counts

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cos takes value x and spits out a y

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cos(0) = 1

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so start there

normal gorge
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glacial pecan
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idk how to do this

calm coralBOT
pure kayak
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didnt you draw a triangle?

glacial pecan
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ion think i did it right cuz my answers were not right

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is sec the opposite of sin

calm coralBOT
pure kayak
glacial pecan
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oh

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oops

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nvm i just did it wrong the first time

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got it

pure kayak
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nice

glacial pecan
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what does pi/3 + npi mean

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also how to turn tan into radian

valid vine
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this is because

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tan(pi/3), tan(pi/3 + pi), tan(pi/3 + 2pi), tan(pi/3 - pi) etc. are all equal in value

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(tan has a period of pi, its values repeat every pi)

glacial pecan
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oh

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and how do i turn tan sqrt 3 into radians

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am i supposed to just know dat cuz its common or what

valid vine
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You should know that tan x = sqrt(3) means x = 60 degrees or x = pi/3 (+ integer multiples of pi)

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but you can draw a right triangle with legs sqrt(3) and 1

calm coralBOT
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@glacial pecan Has your question been resolved?

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indigo gust
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How to find volume of this cylinder?

calm coralBOT
indigo gust
calm coralBOT
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Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

indigo gust
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This is the original problem

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@calm coral

dull wagon
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,rotate

potent lotusBOT
dull wagon
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use trig to get an expression for the altitude

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then apply formula for volume

indigo gust
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πR²lsinθ?

dull wagon
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yeh

indigo gust
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can we do it using integration?

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In 2nd figure volume = πr²l?

calm coralBOT
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@indigo gust Has your question been resolved?

vital plume
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wut

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I think It is an inclination angle, right?

calm coralBOT
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@indigo gust Has your question been resolved?

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pure breach
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$$\int_{}^{} \frac{dx}{a + dx}$$

calm coralBOT
potent lotusBOT
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ItzKraken

velvet osprey
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what's this supposed to mean

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is this some nonsensical notation à la $\int x^{\dd{x}}$

potent lotusBOT
pure breach
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No I was asking how do I find (i cant remember the right word) this integral

pure breach
leaden thunder
pure breach
leaden thunder
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It's not in any standard calculus book

velvet osprey
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$\int \frac{\dd{x}}{a + \dd{x}}$ doesnt make sense

potent lotusBOT
pure breach
velvet osprey
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indeed, it doesnt.

leaden thunder
velvet osprey
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i for one have no idea wtf it's supposed to mean.

leaden thunder
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a+dx means what?

pure breach
leaden thunder
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...

pure breach
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he wrote some weird notation, told us u wont get it, I got stubborn and did some more bull

velvet osprey
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garbage in garbage out?

pure breach
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lemme draw the diagram and what he wrote

pure breach
leaden thunder
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Just take a picture of your teacher's integral

pure breach
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he fudging told us verbally

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its gon take a few mins, can i ping you when am done?

leaden thunder
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Nah, doesn't sound promising

pure breach
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okay

calm coralBOT
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@pure breach Has your question been resolved?

calm coralBOT
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mellow kernel
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Let $V:=\mathcal{P}_3(\mathbb{R})$ and let $T \in \mathcal{L}(V)$ be the operator $f(x) \mapsto f(x-1)+f(x+1)$. Is $T$ triangularizable? If yes, is $T$ also diagonalizable? Justify your answers.

potent lotusBOT
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sadkid

mellow kernel
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I've shown it's triangularizable by putting it in it's matrix representation (it naturally appeared), but how to show it's diagonalizable?

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For reference I'm using Axler's text

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pure breach
calm coralBOT
pure breach
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so this is what my physics teacher wrote

pure breach
pure breach
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and by the F =... he meant u add for lots of tiny l (i.e. i think G times M times the limit as N goes to inifnity of a sum from i=1 to N of dx/l_i)

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$F = G \cdot M \cdot \lim_{N \to \infty} \sum_{i=0}^N \frac{dx}{L_i}$

potent lotusBOT
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ItzKraken

pure breach
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this should be it, I think

visual carbon
calm coralBOT
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pure breach
calm coralBOT
pure breach
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.close

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calm coralBOT
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feral spear
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Is it possible to obtain the power reduction formula for $\int\tan^{n}x{dx}$ using integration by parts?

potent lotusBOT
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R(icky)

calm coralBOT
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@feral spear Has your question been resolved?

feral spear
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<@&286206848099549185>

nocturne scaffold
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The power reduction formula for that could be obtained using integration by parts, where the integral is expressed in terms of a lower power of the tangent function and the natural logarithm of the cosine function. It's technically possible

feral spear
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there is a $\int\tan^n(x) \ln(\sec x) dx$ term which makes me think that I'll continue integrating forever

potent lotusBOT
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R(icky)

feral spear
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hey @nocturne scaffold I've watched some bprp and I've seen there is no need for natural logs

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he made this rearrangement

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instead of $ \tan^{n-1}x \times\tanx $

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he used $\tan^{n-2}x \times \tan^{2}x$

potent lotusBOT
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R(icky)

feral spear
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.close

calm coralBOT
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broken crow
calm coralBOT
broken crow
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Help.

remote mural
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!status

calm coralBOT
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
limpid coral
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have you played around with the hint bleakkekw

calm coralBOT
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@broken crow Has your question been resolved?

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fallow saffron
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question on einstein notation, we've been using it the first time, really...
does s_ij * s_ij mean what I think it means?
with there not being a s_12 * s_23 for example?

fallow saffron
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$s_{ij} , s_{ij} = \sum^i \sum^j s_{ij},s_{ij} =s_{11},s_{11} + s_{12},s_{12} + s_{13},s_{13} + s_{21},s_{21} +s_{22},s_{22} + s_{23},s_{23}+ s_{31},s_{31} +s_{32},s_{32} + s_{33},s_{33}$

potent lotusBOT
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Untitled7

torn gorge
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wooooww

fallow saffron
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well... <@&286206848099549185>

calm coralBOT
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@fallow saffron Has your question been resolved?

calm coralBOT
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@fallow saffron Has your question been resolved?

fallow saffron
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maybe again <@&286206848099549185>

leaden thunder
# fallow saffron question on **einstein notation**, we've been using it the first time, really......

In this video, I introduce Einstein notation (or Einstein Summation Convention), one of the most important topics in Tensor Calculus. Einstein notation is a way of expressing sums in short-form; repeated indices are used to denote the index that is summed over.

I describe the 4 major rules of Einstein notation, as well as the definitions of fre...

▶ Play video
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They explain your example around 5m

fallow saffron
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so yes?

calm coralBOT
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@fallow saffron Has your question been resolved?

fallow saffron
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i guess

calm coralBOT
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queen pendant
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any french person that could help with maths?

remote mural
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I need help

upper sparrow
calm coralBOT
stoic oyster
calm coralBOT
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@queen pendant Has your question been resolved?

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drifting vortex
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why does the b contain a modulus?

glass heart
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well given that you have a +- it doesnt really matter anyway

drifting vortex
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like whats the point

glass heart
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with your course I am asking myself that quite often

upper sparrow
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Because $\sqrt{b^2} = \abs{b}$, most likely

potent lotusBOT
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@upper sparrow

drifting vortex
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yh

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but i mean

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thats common knowledge

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idk why they wrote it anyway

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lol

glass heart
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well you still wanna write correct stuff

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the only reason you can leave it out is because the +-

drifting vortex
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ok ok

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thanks

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.close

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remote mural
calm coralBOT
remote mural
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how do i pull out a factor so that 27 turns into 1?

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i only need to know how to pull out a factor

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is it possible to pull out like this?

27(1+6/27x) ^ -1/3

upper sparrow
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(almost, but the -1/3 also needs to be applied to the 27)

remote mural
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😵‍💫

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so like 27^-1/3 ( 1+6/27x) ^ -1/3?

upper sparrow
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Yep like that SCgoodjob2

remote mural
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i dont understand it

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can u explain it with simpe numbers?

upper sparrow
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Well in this case note that you can factor $27 + 6x = 27(1 + \frac{6}{27}x)$, but then as you have $(27 + 6x)^{-1/3}$, you turn that into $\pqty{ 27(1 + \frac{6}{27}x) }^{-1/3}$

potent lotusBOT
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@upper sparrow

upper sparrow
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using rules of exponents that becomes $27^{-1/3}\pmqty{1 + \frac{6}{27}x}^{-1/3}$

potent lotusBOT
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@upper sparrow

remote mural
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oh

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that acc makes so much sense

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thanks mate

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what a great teacher

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👍

upper sparrow
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Awww, why thank you catlove

remote mural
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ok i will try it from now on

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bye

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.close

calm coralBOT
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remote mural
calm coralBOT
remote mural
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ok so i got b i

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but imm not sure about b ii

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for bi i got

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it was same as the mark scheme but im not sure about b ii

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hello??

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whys everyone ignoring my question 😢

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.close

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proud kite
calm coralBOT
proud kite
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The 2nd method worked

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The first one not

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Why

leaden thunder
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Pain

proud kite
leaden thunder
leaden thunder
proud kite
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@leaden thunder

leaden thunder
proud kite
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Wdym

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I took z

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@leaden thunder ?

leaden thunder
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Can't understand when you're not specific

proud kite
leaden thunder
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Yea still don't know what you mean. You're not being detailed enough

proud kite
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X + 2x = x(1+2)

leaden thunder
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What about the line after that

leaden thunder
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The first line is equal to 18+6i, how did you conclude z=18+6i

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Be specific

proud kite
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The i did z+conjz

leaden thunder
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I can't understand what you're saying

proud kite
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X=0

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X=-1

leaden thunder
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Not when it's nonzero

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Also you don't have just x+1

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You have z + zbar

calm coralBOT
#

@proud kite Has your question been resolved?

calm coralBOT
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calm coralBOT
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rustic solstice
#

Calculate the result of
lim ( 1-cos(3x) / x^2 ); with x tending to 0

fallen whale
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do u have an idea of where to start

rustic solstice
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Ye, adding the value x tends to

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(forgot to type it)

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First of all trying to calculate it as I would do usually

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And it comes out as a indetermination form of type 0/0

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Then I have to find a workaround

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Which I don't know how to

fallen whale
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do u know a rule where if u get an indetermination form u can use said rule

rustic solstice
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The first that comes to mind in this case is 1-cos(x) / x^2 = 1/2

fallen whale
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(its called l'hopitals)

rustic solstice
remote mural
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And u will solve it

rustic solstice
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?

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The 3 is in the cos

remote mural
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1-co(3x)/3x^2 x3

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U will get 3/2

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Idk but I’m not sure

rustic solstice
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Result is supposed to be 9/2

remote mural
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My bad wait

fallen whale
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basically l'hopital is if u get indetermination form, then differentiate numerator and denominator and plug x=0 in that

remote mural
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Lemme write it so

remote mural
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cuz

rustic solstice
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No wait

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I wanna learn hopital rule

remote mural
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U should have everything root

remote mural
rustic solstice
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Ye

remote mural
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Cuz I’m in high school and teacher says that I can’t use it

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But it’s easy with hospital

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Lemme write it

fallen whale
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l'hopital is really easy u can learn it in primary school

rustic solstice
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Bro my teacher opened the book and spit random exercises numbers, as when I asked for help with another exercise he had to put glasses on to actually read (things that he doesnt while giving out exercises)

fallen whale
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but since u never learnt it im assuming whoever gave u that question wants u to do it another way

rustic solstice
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He never even mentioned it so I'll assume I can just use it

fallen whale
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u know differentiation?

rustic solstice
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No

remote mural
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So yeah he shouldn’t use the hospital rule

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See

fallen whale
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oh ok he defo doesnt expect u to use it then

rustic solstice
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Then how should I solve this

remote mural
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I solve it

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.rotate

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,rotate

potent lotusBOT
remote mural
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Do u understand

rustic solstice
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I think so

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Basically the expression is still the same

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As if I do the calculus normally at the second row I simplify the two 9 together

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And it turns out to be the original

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Then I use the rule I mentioned earlier and it works out

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Dam it was this easy?

remote mural
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depends on how old are u tho

rustic solstice
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17

remote mural
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Oh same

rustic solstice
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Probably my teacher's fault I suppose

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Can I ask for supervision with another exercise I had sort of the same problem with in this channel?

rustic solstice
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lim sqrt( 1-cos(x) ) / x ; with x = 0+

remote mural
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It’s 1/2 I supposed

rustic solstice
#

Ye

remote mural
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But lemme write it to make sure

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cuz it’s a usual limit

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Do u know how I solve it ?

rustic solstice
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I would divide the x by sqrt(1-cos(x)

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And multiply everything by the same

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So that the expression is unvaried

remote mural
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No

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X= sqrtx^2

rustic solstice
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What

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Ye I see it now

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Everything is hence under square root

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But what about the numerator ?

remote mural
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yeah my fault it will be 1/sqrt2

rustic solstice
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Im not understanding

remote mural
rustic solstice
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Ohhhhh

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Ye understood

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Didnt remember the rule

remote mural
#

Are u American ?

rustic solstice
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Italian

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y?

remote mural
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French

rustic solstice
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Hold up

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You asked me if I'm american cuz I'm dumb

remote mural
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I guess ur not familiar with limits

rustic solstice
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I can see Im not familiar with limits

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I just started studying them

remote mural
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Yeah if u need any help I’m here for it and if U need some challenging limit I can send them to u

rustic solstice
#

Like here rn or in dms?

remote mural
rustic solstice
#

Ill ask in a few days thru dms then to prepare for a test, right now I'm just making homeoworks days before the actual due date so I have less work later

rustic solstice
#

Thx a lot

#

.close

calm coralBOT
#
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vale mantle
#

can someone help me with this question?

calm coralBOT
vale mantle
#

this is the methods of question 4

#

you have to use the 2cos(theta) = e^itheta + e^-itheta

#

or smth like that

mortal orbit
#

Here's a nudge in the right direction : Show that $(e^{i\theta} + e^{-i\theta})^6 = ...$

potent lotusBOT
#

rafilou2003

vale mantle
potent lotusBOT
#

rego22o

mortal orbit
vale mantle
#

oh distraught

#

isn't that gonna be super long

#

surely theres a better way

mortal orbit
#

"super long" Idk there's like 7 terms so it's not that bad

mortal orbit
#

because you'll get twice as many calculations for just the same result

vale mantle
#

i'm just confused as to what they want us to use from question 4 then

mortal orbit
#

First of all (a) will be important

#

then, how did you find $(e^{i\theta} + e^{-i\theta})^3$ in the first place?

potent lotusBOT
#

rafilou2003

vale mantle
#

I didn't do that question but I assume you just expand and group like terms

mortal orbit
#

using newton's binomial formula

#

and you're gonna do the same here in 9)

#

Expand

vale mantle
#

alr

mortal orbit
#

and then group terms alike

vale mantle
#

this should be fun

#

actually it aint even that bad

#

@mortal orbit

mortal orbit
#

yep that's it

#

(don't forget thetas)

vale mantle
#

yeah whoops

mortal orbit
#

and now you can regroup terms alike

vale mantle
#

yeah I was able to figure it out from there

#

thanks for the help 👍🏿

#

.close

calm coralBOT
#
Channel closed

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steep marsh
#

hey

#

I need help with smth

calm coralBOT
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steep marsh
#

<@&286206848099549185>

calm coralBOT
steep marsh
#

<@&286206848099549185>

hasty fiber
#

You're supposed to ask your question and then ping helpers (only once, and only after 15 minutes)

#

!help

calm coralBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

steep marsh
#

Oh

#

so basically

#

I’m getting a keyboard with a height of 15cm

#

but I have a laptop which covers like 25cm of the desk

#

will that keyboard fit??

#

since this is taking an while please @ me when u want to respond

shadow tendon
steep marsh
#

wym

shadow tendon
#

Like how big is the desk

steep marsh
shadow tendon
#

Well 15+25=40 which is bigger than 38

#

So it will not be an ideal situation

steep marsh
#

hm

#

Thanks

#

.close

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#
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cold crow
#

help

calm coralBOT
#

Please don't occupy multiple help channels.

cold crow
#

pls is it 50 or 100

hasty fiber
#

Stick to your original channel

#

.close

calm coralBOT
#
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cold crow
#

.reopen

calm coralBOT
#

cold crow
#

help

oblique current
#

!noclopen

calm coralBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

cold crow
#

bro could have just told me if its 50 or 100

leaden thunder
calm coralBOT
# cold crow bro could have just told me if its 50 or 100

Please wait patiently, and do not interrupt other channels with your question. Helpers in this server are volunteers, and the server cannot guarantee that someone will be able to help you. By being impatient or begging, you will only turn potential helpers away.

In the meantime, please make sure your channel contains the original question, clearly describes what you have already tried, and states exactly what you are having trouble with. This increases your chances of getting a good response.

cold crow
#

just tell me if its 50 or 100 its not that hard please man

latent steeple
#

Maybe ask chatgpt

leaden thunder
calm coralBOT
#

@cold crow Has your question been resolved?

cold crow
#

u guys arent helping with anything

formal pumice
#

ping if you want explanation

leaden thunder
calm coralBOT
# formal pumice it is 100

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

cold crow
#

chat gpt said it was 50

#

@formal pumice

formal pumice
#

chat gpt doesn't know math

#

lol if the arc is 100 degrees, then the angle of the two points with vertex of the center is also 100

calm coralBOT
#

@cold crow Has your question been resolved?

calm coralBOT
#
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calm coralBOT
#
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chilly garnet
calm coralBOT
chilly garnet
#

How do I find the limit of this sequence

#

I tried using Lhopitals rule but I get stuck in a loop of e^x

#

Where have I messed up? Or what other techniques should I do?

upper sparrow
#

I would suggest working with that ln(1 + e^n), there's a way you can make it something a bit nicer to work withh...

chilly garnet
#

Is there a way to take out the n?

upper sparrow
#

Well, there's a way to get an n out of that, somehow catThumbsUp

chilly garnet
#

Hmm

#

Do I get any hints lol

upper sparrow
#

Maybe think of a way of factoring 1 + e^n, then log rules catThink

#

back to your l'opitals, you could also work with this to get something that's nicer too catThink

chilly garnet
#

Hmm

chilly garnet
#

But now I get an answer of 1 and it’s supposed to be 0

upper sparrow
chilly garnet
#

Wait

#

Ok I got it!

#

So how are you saying to factor the 1 + e^n

upper sparrow
#

Nice nice happyCat

upper sparrow
potent lotusBOT
#

@upper sparrow

upper sparrow
#

From there, working the limit out should be alright catThumbsUp

chilly garnet
#

That makes sense actually ok

upper sparrow
#

happyCat perfect SCgoodjob2

chilly garnet
#

Like this?

#

That doesn’t seem too much better than what I had before 😩

upper sparrow
#

Yep, then cause all of that is divided by n^2 SCCOZY

#

Of course ln(e) is 1

chilly garnet
#

Woaahhhhhhhh wait omg I forgot about that lol

#

Ok I am getting this! I have a test tomorrow and I have been studying allllll day and it’s clicking for me

upper sparrow
#

Awww best of luck for the test! Happy it's starting to set in CuteComfy

calm coralBOT
#

@chilly garnet Has your question been resolved?

#
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vapid nova
#

for intermediate value theorem, ik that for some value x = c to exist, f(a) < f(c) < f(b)
but can the order be switched around? f(a) > f(c) > f(b)

vapid nova
#

is this a valid?

wanton wave
#

if I'm understanding you right, yes

#

if f is continuous and u is some value between f(a) and f(b), then there exists some c between a and b such that f(c) = u

#

but it could be f(a) < u < f(b) or f(b) < u < f(a)

upper sparrow
#

[in fact, between a and b, f will attain a maximum value and a minimum value (which could be greater/less than f(a) and/or f(b)) and you can attain any value between that maximum and minimum]

vapid nova
#

so if i picked some arbitrary interval [a,b]
it doesnt matter if f(a) > f(b) or f(a) < f(b)
as long as f(a) != f(b) then there is some number f(c) that is in between f(a) and f(b)

wanton wave
#

yes, with c being between a and b

vapid nova
#

alright

#

thanks

#

.close

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#
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halcyon ore
calm coralBOT
halcyon ore
#

i stuck on this too long

#

Like its ln

#

ln^9=1-5x

#

idk

modest pebble
velvet osprey
#

did you maybe mean ln(9)?

halcyon ore
#

oh sry

#

yes

#

i show what i did but ik is very bad

#

i try to do both sides too

crystal forge
#

well you were on the right track with that step ln(9) = 1-5x, now finish solving for x

halcyon ore
#

Ok

#

i gotit wrong

crystal forge
#

what did you get, x = ?

halcyon ore
#

uh

#

ln(9)-1

-5

#

fraction answer

crystal forge
#

yeah

halcyon ore
#

oh

#

noway

crystal forge
#

$\frac{\ln 9 - 1}{-5} = \frac{1-\ln 9}{5}$

potent lotusBOT
velvet osprey
#

is how you would type that in plaintext

halcyon ore
#

oh k

#

thnxs

#

.close

calm coralBOT
#
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calm coralBOT
#
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solemn steeple
#

Any clue? All I was able to do was find the actual sequence but I have no clue how do I approach it further

formal tulip
#

Isn't that just an arithmetic progression

#

oh nvm it isn't

humble ivy
#

Did you find a closed form for a_n?

solemn steeple
solemn steeple
humble ivy
#

The the trick is to apply the recursive formula to the sum

calm coralBOT
#

@solemn steeple Has your question been resolved?

solemn steeple
humble ivy
#

What did you try?

#

For me it worked

solemn steeple
potent lotusBOT
solemn steeple
#

oh

#

oh okay that helps a bit

calm coralBOT
#

@solemn steeple Has your question been resolved?

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hollow sphinx
calm coralBOT
hollow sphinx
#

I saw a thing where if you have a polynomial you can ignore the rest of the terms and just look at the highest power

#

so 3x^2 and x^2 but that doesn't work here

merry python
#

that's only for limits at infinity

hollow sphinx
#

ah I see

#

got it thanks.

#

.close

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#
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terse marlin
#

Is this allowed in the integration for moment of inertia of a uniform density sphere?

still marlin
#

Yup

burnt phoenix
still marlin
#

It works in this instance tho

burnt phoenix
terse marlin
#

It works out, just wanted to make sure it’s valid, thank you

still marlin
#

Cus the bounds are independent

#

It's kind of like with a single integral u can take out the constants

burnt phoenix
terse marlin
#

Can I do this in general for simple shapes?

still marlin
#

Since the bounds don't depend on each other and when integrating u treat the other variables as constants

#

Hmmmm

#

There's a theorem I forget the exact conditions

#

But if the bounds aren't independent probably not

terse marlin
#

Do you remember the name of the theorem?

still marlin
#

nope I can Google it tho

#

OK it doesn't have a specific name but u can prove it by spamming fubini's theorem twice I think https://en.wikipedia.org/wiki/Fubini's_theorem#%3A~%3Atext%3DIn_mathematical_analysis%2C_Fubini's_theorem%2Cby_Guido_Fubini_in_1907.?wprov=sfla1

In mathematical analysis, Fubini's theorem is a result that gives conditions under which it is possible to compute a double integral by using an iterated integral, introduced by Guido Fubini in 1907. One may switch the order of integration if the double integral yields a finite answer when the integrand is replaced by its absolute value.

Fubini...

#

There's a section for rhe product of 2 integrals case

#

So then ud use it a 2nd time for 3 integrals

#

2nd*

terse marlin
#

It looks like it makes sense, thank you headpatme

#

.close

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#
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calm coralBOT
#

Please don't occupy multiple help channels.

oblique current
#

.close

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hollow sphinx
calm coralBOT
hollow sphinx
#

tried plugging in 0 and equating them but I get sin0/0 = -2

#

so idk what to do

upper sparrow
#

Well you don’t exactly “plug in” 0 - hold on a moment glassescat

#

Is that supposed to be a trick question, or did they write that wrong(?)

upper sparrow
wanton bobcat
#

virus

wanton bobcat
#

do you know u sub?

upper sparrow
#

So can you be continuous at 0?

wraith sand
#

Hi

#

Can

hollow sphinx
#

No.

#

?

wraith sand
#

Some one help me

upper sparrow
hollow sphinx
wraith sand
#

Can someone help me?

wanton bobcat
#

look i think the question is badly worded and we mus assume that sin(0)/0=1

hollow sphinx
#

this is the solution but I'm so confused

wraith sand
#

In math

hollow sphinx
#

why are they deciding by ax then multiplying by a

wraith sand
hollow sphinx
#

Is this guy serious lol

wanton bobcat
calm coralBOT
# wraith sand

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

upper sparrow
#

[
f(x) =
\begin{cases}
\frac{\sin(ax)}{x} & x < 0 \
x^2 + x - 2 & x\geq 0
\end{cases}
]

potent lotusBOT
#

@upper sparrow

wanton bobcat
#

yep^

upper sparrow
wanton bobcat
#

virus does this change anything?

upper sparrow
#

At which point, working out the limit from both sides and all (shall leave this to you @wanton bobcat catLove)

hollow sphinx
#

even then I'd just think to plug in 0 and equate them to each other thats what I saw in a vid

wanton bobcat
#

you dont plug in

#

you do the limits

hollow sphinx
#

but I'm not actually sure how to check for differentiabilty and continuity

wanton bobcat
#

to check for continuity at a point you do the limit from the left at said point and from the right

wanton bobcat
#

what would the limit from the left be? and from the right?

hollow sphinx
#

do you use lohpitals on the top one?

wanton bobcat
hollow sphinx
#

so acos(ax) / x

wanton bobcat
#

/x?

hollow sphinx
#

1**

wanton bobcat
#

so the limit from the left is

hollow sphinx
#

0 from both the right and left?

wanton bobcat
#

you have just calculated it

#

from the left

#

with lhopital

hollow sphinx
#

oh wait is

#

its 1?

wanton bobcat
#

virus

#

you found and expression using lhopital cor the left limit

#

what is that expression

#

dont skip steps

hollow sphinx
wanton bobcat
#

what does that yield in your case

hollow sphinx
#

a?

wanton bobcat
#

the whole expression virus

hollow sphinx
#

acos(ax)/1 if you plug 0 into that you get a

wanton bobcat
#

perfect

#

that is the limit from the left

#

to prove continuity the limit from the left must be the same as the limit from the right at said point

#

so lets do the limit from the right

hollow sphinx
#

Also a?

wanton bobcat
#

limx—>0+ x^2+x-2

hollow sphinx
#

oh I thought u meant for the same function

#

-2

wanton bobcat
#

when going from the left however you coming from -0.000000001 which applies to the top and from right from 0.0000001 which applies to the bottom

wanton bobcat
#

what do we have?

hollow sphinx
#

a=-2

#

makes sense now thanks

wanton bobcat
#

🤞🏽

hollow sphinx
#

and for differentiability do I differentiate the top and bottom and equate to each other?

#

@wanton bobcat

#

sry for ping

wanton bobcat
#

i am not 100% sure bc i never actually used diferentiability but im pretty sure it means if the gunction is continuous and its derivstive exists for all points

calm coralBOT
#

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pulsar bear
#

did I do this polynomial division right?

pulsar bear
glad plover
#

the answer is right

pulsar bear
#

Thank you

#

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#
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pulsar bear
#

.reopen

calm coralBOT
#

pulsar bear
#

Thx chart

calm coralBOT
#

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remote mural
#

how do you undo an inverse

calm coralBOT
remote mural
#

say f^-1

#

what would you do to undo

#

inverse again?

potent igloo
#

depends on f thonk

remote mural
#

welp that's my answer

#

thanks

#

.close

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muted vale
#

f'(x) = -1-2sin(x)

calm coralBOT
muted vale
#

I need to find local min/max

#

So I took second derivative

#

f''(x) = -2cos(x)

#

So for this, would it just be cos(x) = 0/-2, or in other words cos(x) = 0?

#

So 3pi/2 and 1pi/2?

#

then test those in the f(x) function

#

oh wait thats for concavity

#

My bad not local min / max

#

I've got the min/max done

calm coralBOT
#

@muted vale Has your question been resolved?

calm coralBOT
#

@muted vale Has your question been resolved?

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#
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fluid musk
#

I understand that this requires the fundamental theorem of calc, and that -15 = g(9), and f(9)=g'(9), but I have no idea what my first step should be in solving this

strange lichen
#

Do a u-sub

#

@fluid musk

fluid musk
#

oh!!

#

i'll give it a try rn

#

i'm still lost...

#

i'm here ^^

#

it should be h'(u)=f(u), oops

zenith ginkgo
#

you don't need the fundamental theorem of calculus for that one

#

As stephen suggested, you should let u = 3t and do an u-substitution

fluid musk
#

but then what about the different bounds?

astral mural
#

Why not just use FTC?

strange lichen
#

u = 3t
du = 3 dt
1/3 du = dt

fluid musk
#

oh... i don't think i learned that yet...

#

i think i'm supposed to use FTC

strange lichen
fluid musk
#

is there a way to do it using FTC? sorry,,,

zenith ginkgo
#

No

fluid musk
#

😨

#

would I also use a u-sub for the second question?

zenith ginkgo
#

yes!

fluid musk
#

okay, thanks sm for the help! i'm glad i wan't j going crazy that FTC wasn't working

#

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misty hound
calm coralBOT
thorny stump
#

!status

calm coralBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
misty hound
#

1

thorny stump
#

I guess it's assumed that the cost of the fence is proportional to its length

misty hound
#

yeah

thorny stump
#

You have a rectangle, can you pick two letters for its side lengths?

misty hound
#

x and y

thorny stump
#

Can you give me the total length of fence in terms of x and y?

misty hound
#

I don't know that. It's part of what I'm trying to figure out

thorny stump
#

Isn't that how it would look like?

misty hound
#

yeah. Perimeter would be 3y+2x

thorny stump
#

Well that's the total length of fence

misty hound
#

oh I thought you meant the total length in numbers

thorny stump
#

I said "in terms of x and y"

misty hound
#

oh fck. Dunno how i missed that

thorny stump
#

Anyway, can you now give me the area in terms of x and y?

misty hound
#

x*y

thorny stump
#

RIght, and that equals 1.5 million, right?

misty hound
#

yeah

thorny stump
#

With square feet as a unit but that's unimportant

#

Actually let's just make the unit "million square feet", so that x*y = 1.5

#

You want to minimize 3y+2x

#

Can you simplify this to keep only one variable?

misty hound
#

x*y=1.5 so x=1.5/y. Then it's 3y + 2(1.5/y)

thorny stump
#

Ok, can you simplify?

misty hound
#

3y+3/y

thorny stump
#

Right

#

Do you know about derivatives?

misty hound
#

yeah

thorny stump
#

Can you find this one?

misty hound
#

3-3/y^2

thorny stump
#

Yes

#

Where does that equal zero?

misty hound
#

y=3

thorny stump
#

No

misty hound
#

wait no

#

y=1

#

mb

thorny stump
#

Yes, though that's not the only root

misty hound
#

-1

thorny stump
#

Yes

#

Now since y is a distance, we know it's positive, so we can ignore this one

#

But now we know y=1

#

So what is x?

misty hound
#

1.5

thorny stump
#

Yes, and now the total length of fence?

misty hound
#

6 cause 1.5x2 + 1x3

thorny stump
#

Yes

#

,w minimize 3y+2x with x*y = 1.5, x>0, y>0

thorny stump
#

Huh weird, it's imprecise

#

,w minimize 3y+2x with x*y = 3/2, x>0, y>0

misty hound
#

probably a coding bug. Am computer science major so I run into this occasionally

thorny stump
#

Ok that's better

misty hound
#

so would the final answer be 1000ft by 1500ft cause it's 1.5 million

thorny stump
#

Yes

#

If the unit of area is "million square feet" then the unit of length is "thousand feet"

misty hound
#

alright, thanks for your help

#

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icy flame
#

Not sure how Im suppose to solve this

calm coralBOT
keen pike
#

what question are you stuck on?

icy flame
#

3

keen pike
#

the triangles are both congruent

#

which means if you have an angle on one triangle you can find it on the other

icy flame
#

Ohhhh

#

Meaning Y would equal 124

keen pike
#

yup

icy flame
#

Since Y is congruent to N

#

Tysm

keen pike
#

np

icy flame
#

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frosty marsh
#

Can someone help me solve this

calm coralBOT
calm coralBOT
#

@frosty marsh Has your question been resolved?

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#

@frosty marsh Has your question been resolved?

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crimson cliff
calm coralBOT
crimson cliff
#

how did we get this?

calm coralBOT
#

@crimson cliff Has your question been resolved?

winter loom
#

Chain rule really.

potent lotusBOT
#

! What the hell am I doing here?

winter loom
#

That's also required.

#

After this, chain rule, yeah.

calm coralBOT
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sweet totem
#

How do I prove limit as x approaches 3 of x/(x-2) = 3?

sweet totem
#

I tried checking f(x) - 3 and it’s 2|x-3|/|x-2|

#

Which is less than 2delta/|x-2| but idk how to go from here

#

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sweet totem
#

.reopen

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#

cloud topaz
#

Choose delta to be a minimum of some number and the thing

sweet totem
#

Wdym

cloud topaz
#

$$\delta=\frac{1}{2} \implies -\frac{1}{2} < x-3 < \frac{1}{2} \ \implies \frac{1}{2} < x-2 < \frac{3}{2}$$

#

Blah

potent lotusBOT
#

$Pure$

sweet totem
#

Don’t get it why can we say delta is 1/2

cloud topaz
#

Because delta can be any number we’re just choosing it to work and I’m not saying delta is definitely 1/2

#

But we can use the fact that delta is 1/2 to bound 1/|x-2|

#

Then if you solve for delta that makes the expression less than epsilon you can just say choose delta to be the minimum of 1/2 and that value

ancient thistle
#

pure helping faq

#

its dejavu

cloud topaz
#

Where’s faq

#

Oh wait

#

He’s far

ancient thistle
#

lol

cloud topaz
#

Lmao

#

I didn’t realise that

#

@sweet totem

ancient thistle
calm coralBOT
#

@sweet totem Has your question been resolved?

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stuck raptor
#

What formula do i use to find angle A?

calm coralBOT
winter loom
#

Sine, cosine, either would work.

#

You should get a good understanding of when to use what.
This is your second time for the same problem. Not belittling you, just saying.
Observe when you use cosine formula and when the sine formula.

calm coralBOT
#

@stuck raptor Has your question been resolved?

stuck raptor
#

im sorry, im still trying to understand, but i got it with cosine for now, still trying to get the sine rule to work

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dense cedar
#

Hello again, I wanted to ask a question on how do you simplify this expression

dull geyser
#

Combine the two fractions

fringe reef
#

again, denominators are the same

#

just add the numerators

#

unlike the last time though, you are not done after doing that

dense cedar
fringe reef
#

what do you have so far

dense cedar
#

wait

fringe reef
dense cedar
#

9x-6

3x-2

fringe reef
#

yes

#

can you cancel something?

dense cedar
#

Dont think so

fringe reef
#

well

#

you can

#

can you factor something out of the numerator?

#

what's the common factor of 9 and 6

dense cedar
#

3

fringe reef
#

yes

#

that means you can factor out 3

dense cedar
#

OH SO LIKE

#

3x-2

3x-2

fringe reef
#

almost

#

$\frac{3(3x-2)}{3x-2}$

potent lotusBOT
#

artemetra

fringe reef
#

but yeah

dense cedar
#

Why is there a 3 again on the other side

#

Left side

fringe reef
#

because we just factored it out

dense cedar
#

Oh mk

#

So the answer would be 3?

fringe reef
#

yes

dense cedar
#

Ty ty ty

fringe reef
#

np

dense cedar
#

.close

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desert storm
#

hi i solved for this and got these answers but it says one of them is wrong, don't know which one

calm coralBOT
#

Please don't occupy multiple help channels.

desert storm
#

.close

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astral mural
#

Hello

calm coralBOT
astral mural
#

I differentiated twice using LH

#

and got

#

$\frac{-\frac{2}{9}\left(27x\right)^{-\frac{4}{3}}}{\frac{5}{9}\left(27x\right)^{-\frac{1}{3}}}$

potent lotusBOT
#

LE SSERAFIM

astral mural
#

What do I do after?

cloud topaz
#

Simplify power of x

astral mural
cloud topaz
#

Exponent rule

#

a^n/a^m = ?

astral mural
#

a^(n-m)

#

What happens to the coeff?

cloud topaz
#

Just simplify the power of x

#

And see what happens

astral mural
#

Ohh I see

#

-2/135x

#

Thank youu

#

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#
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cloud topaz
#

Np

calm coralBOT
#
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rapid axle
calm coralBOT
rapid axle
#

This question is greens theorem, i understand everything just not how to get the bounds for X,Y

#

for the double integral

#

This is what i have so far

#

i have the integrand

#

just am not sure how to get the bounds for the question

whole hinge
#

(Moderator ping answered)

leaden thunder
rapid axle
#

oh wait

#

jesus christ

#

0 <= x <= 1, x^2 <= y <=sqrt(x)

#

@leaden thunder appreciate it

#

how do i close channel?

grand dragon
#

.close

rapid axle
#

.close

#

ty

calm coralBOT
#
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waxen talon
#

Help