help-42

[teal coral]

if it doesn't, then you're okay to take them off

not sure why that has anything to do with derivatives

[noble cedar]

it would change the answer

multiplying the entire derivative output with x, or multiplying 6x with x

but now I see it's the entire output

so I need to keep the brackets

you would recommend doing this first before finding f'(x)?

[pure kayak]

it makes it relatively easier yeah

using the quotient rule is just unnecessary

[noble cedar]

this would use Chain Rule? or

[pure kayak]

just power rule

[noble cedar]

alright, let's see if I remember the steps

[pure kayak]

nonono

[pure kayak]

simplify this so each term is x to the power of something

[noble cedar]

OK

[pure kayak]

ie 4/x=4x^-1

[noble cedar]

took me a good minute to remember how to simplify this

just using exponents would have been easier?

[pure kayak]

yeah

[noble cedar]

hmmm

wish I could see that with symbolab

[pure kayak]

could just write 2x^1/2 *x^-1 or 2x^1/2 /x^1 then the simplification comes quite easily with exponent laws

[noble cedar]

true! I made -1 into -2/2 to get a common denominator

[pure kayak]

ah i see

[noble cedar]

i guess the radical was good to confirm, it looked weird haha

alright so now that i have it all like this..

it's not quite a polynomial, but it's much cleaner

[pure kayak]

yeah

[noble cedar]

so now I can use this same logic?

or wait, you said power rule

not product rule, right?

[pure kayak]

if im honest, i have no idea what this is supposed to be

[pure kayak]

yeah

[noble cedar]

product rule I think, but normally I only have two terms

this was a big mix up

[pure kayak]

product rule only works if its the product of 2 distinct things that could be defined as their own functions like x^2sin(x)

where f(x)=x^2 and g(x)=sin(x)

[noble cedar]

ohh I see. and if it's f(g(x)) it would need to use chain rule?

[pure kayak]

yeah

[noble cedar]

which is same thing as product rule twice, but time saver, afaik?

[pure kayak]

its not really the same

[noble cedar]

oh

i thought chain rule was just time saver

[pure kayak]

one is the product of 2 functions - the other is when a function is inside another function

[noble cedar]

it sounds like chain rule is a requirement for compositions

anyways, I will try power rule now

[pure kayak]

if you want to differentiate a composite function, yeah

[noble cedar]

would you leave f'(x) like that?

[pure kayak]

nothing wrong with leaving it like that

[noble cedar]

OK

so you are saying quotient rule not needed? can be done with just the product rule?

[pure kayak]

hmm, i would probably use the quotient rule here

theres not really any pre simplification you can do

unless you want to change the numerator into 0.5sin(2x)

[noble cedar]

OK

[noble cedar]

I think these brackets () are gonna be the death of me 💀

my answer is wrong I think

due to the brackets

(cosxsinx)

[pure kayak]

i think its alright

[noble cedar]

it should be (cosx)(sinx)

[pure kayak]

,w differentiate (cos(x)sin(x))/(1-tan(x))

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by AℤØ#4979

[pure kayak]

this is the same as what you have

[pure kayak]

as for this its just a bunch of expanding from the above

[noble cedar]

but WA looks different

hmmmm

I gotta study this hard for me to spot what's going on exactly

but basically, there is a big difference between (cosxsinx)(tanx) and (cos)(sinx)(tanx), right?

[pure kayak]

theres no difference

(2x3)x5=2x3x5

same logic

[noble cedar]

ohhhhh

I'm thinking distribution

keep forgetting

distribution requires + or - in between terms

[pure kayak]

yeah

[noble cedar]

is this called Associativity? or different

[teal coral]

actually no, the two things you've written mean the same thing

multiplication is done left-to-right

so (cosxsinx)(tanx) and (cos)(sinx)(tanx) both mean multiply the cos x and the sin x first

then multiply the tan x

but (cos x)(sin x)(tan x) = (cos x)(sin x tan x) would indeed be an application of associativity

[noble cedar]

interesting.. so it's a matter of preference to include the brackets, or even where to include the brackets

if no + or - involved

(cosxsinx)(tanx) = (cos)(sinx)(tanx)
(tanx)(cosxsinx) (cos)(sinx)(tanx)
[(tanx)(cosxsinx)] = (cos)(sinx)(tanx)

cossinxtanx = [(tanx)[(cosx)(sinx)]]

all of these equal exactly the same thing

no need to worry about distribution, as no distribution is happening here. just multiplication of 3 terms

however

can't remember what I was gonna say

[teal coral]

commutativity and associativity allow you to reorder things however you want

[noble cedar]

just taking the derivative, I wanna keep the brackets around the derived result. always a good habit, right?

there is no situation where that could lead to any trouble

[teal coral]

you should keep them unless you know they're not necessary and don't feel like keeping them

[noble cedar]

just to play it safe

[teal coral]

yes there is no situation where that leads to trouble

[noble cedar]

alright

thanks!

that's a big relief to know that

I will keep that in mind from now on

removing brackets will be my very last step, if at all

[noble cedar]

only with multiplication and addition

not with subtraction and division

[teal coral]

subtraction and division are neither commutative nor associative

[noble cedar]

multiplication is the same thing as addition, right? is division the same thing as subtraction?

that sounds weird to ask, but in the grand scheme of things

behind the scenes, so to speak

or is it only multiplication and addition that are similar like that?

subtraction and addition are more similar to one another than subtraction and division?

and division is more like multiplication?

[teal coral]

multiplication is not the same thing as addition

[noble cedar]

https://en.wikipedia.org/wiki/Multiplication_and_repeated_addition

[teal coral]

okay that doesn't mean that they're the same thing

[noble cedar]

is this like teaching kids mixed fractions?

bad habit

[teal coral]

obviously I know that multiplication can be done as repeated addition

[noble cedar]

that's what I mean by "behind the scenes"

not identical but similar

[teal coral]

still no

certainly there is a relationship

just as there is between subtraction and division

but these are not close to the same thing

[calm coral]

@noble cedar Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opal anchor]

can someone help me understand this

[opal anchor]

can someone help me understand this step by step

[calm coral]

@opal anchor Has your question been resolved?

[opal anchor]

.close

[calm coral]

Channel closed

Closed by @opal anchor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable python]

Here's the question and my solution. However, the answer sheet says it's 45/124 metres per second. Where have I gone wrong?

[viscid silo]

,w 45/124

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by DerpZ#9141

[stable python]

smh u thought I wouldn't have tried that

[viscid silo]

you probably made a mistake, try again then

[stable python]

I have been staring at this qn for like

1h30mins

And can't see any error 💀

Hm, if I were to use the answer and work it backwards

I'll get
9/31 × 1.25m/s, which implies that they somehow found dy/dx to be 9/31???

Hm....

[pure breach]

Have you tried dy/dt?

[stable python]

That is exactly what I expressed in my final answer

[pure breach]

Oh right sry

Shouldn't dy/DX be 40/9

[stable python]

f(x)=9x/40

Dy/dx = 9/40

And... even if dy/dx=40/9 it won't give us the answer in the solution sheet

... ima be honest I feel that the answer sheet is wrong

[bronze adder]

Why do you care about dy/dx at all

$$\frac{\dot{y}}{1.8} = \frac{\dot{x}}{8}$$
$$\dot{y} = \frac{1.8 \times 1.25}{8}$$

bruh

[potent lotus]

NEONPerseus

[bronze adder]

,calc 1.8*1.25/8

[potent lotus]

Result:

0.28125

[stable python]

Cuz it gives us the rate which the shadow changes without considering time. I was doing what u did too, but when I checked the answer and saw that it was wrong I expanded on the working to ensure that it was right

.... and Yr answer is the same as mine

9/32

Rlly seems like the answer sheet is wrong

[bronze adder]

I see

[stable python]

Ima slap this to my sch teacher and see what they say, tysm for yr time

.close

[calm coral]

Channel closed

Closed by @stable python

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strong wind]

I'm not sure what to use for my change of variables here

[strong wind]

The answer states that the correct change of variables is g(u, v, w)=(au, bv, cw) but I don't know how they acquired that

[low owl]

so it cancels out the a²,b²,c² in the equation

[strong wind]

oh my god

thank you

.close

[calm coral]

Channel closed

Closed by @strong wind

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight sedge]

find the Egien values of M, M =
[1 , 3 ,2]
[0, 2 ,0]
[0 ,-3, -1]

[midnight sedge]

[1-x , 3, 2]
[0, 2-x,0]
[0, -3, -1-x]
now i find the determinant of this

[arctic sparrow]

What is the solution to the equation 2.5(x+5) = 7.5x - 0.5

[midnight sedge]

???

[arctic sparrow]

oopsw

wrong one

sorry

[midnight sedge]

XD

[remote mural]

you can cofactor along the first column

[midnight sedge]

i've did that

i got

-x^3 +2x^2 +x - 2 as the determinent

can someone confirm?

[remote mural]

,w characteristic polynomial [[1,3,2],[0,2,0],[0,-3,-1]]

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Toby#2275

[remote mural]

yup, correct

[midnight sedge]

NOW heres the part im stuck on

finding these shitty vectors

,w factor -x^3 +2x^2 +x - 2

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ikraamampampam#3593

[midnight sedge]

x_1 = 1 , x_2 = 2 , x_3 = -1 (lets say)

so now i resub these into my matrix , yes?

[remote mural]

yea

[midnight sedge]

ok lets do x_1 first

[1 - 1 , 3 ,2] [0 , 3 ,2]
[0 , 2-1 , 0] = [0, 1, 0]
[0, -3 , -1-1] [0,-3,-2]

[0, 3, 2] [x]
[0, 1, 0] * [y] = 0 (is this part right)?
[0, -3,-2] [z]

[remote mural]

looks fine

try row reducing the matrix first

[midnight sedge]

uhm

wut

is row reduction

cant i just muitiply normally?

[remote mural]

sure

its just easier to get the matrix in row reduced echelon form first, than back substitution (especially since you already have the matrix)

but its fine either way

[midnight sedge]

ok (im going to do it normally)

0x + 3y +2z = 0
0x +y + 0z = 0
0x -3y-2z = 0

y = 0

z = 0

x = 0

??

so does that vector just not exist

[remote mural]

why would x=0?

[midnight sedge]

uhm

[remote mural]

x=1 also works

[midnight sedge]

wut

well couldnt you just give x any number then?

[remote mural]

yeah

[midnight sedge]

oh

[remote mural]

you should get a subspace of eigenvectors

[midnight sedge]

so how do i write that down as an eigen vector

do i just use 1

[remote mural]

choose a basis

[midnight sedge]

a basis?

[remote mural]

the nullspace of this matrix is span{(1,0,0)}

{(1,0,0)} is an example of a basis for the null space

[midnight sedge]

so once we choose a basis we just stick with it?

[remote mural]

yeah

[midnight sedge]

next vectors can be:
x_2 = 2 ,
[1]
[1]
[-1]

x_3 = -1,
[1]
[0]
[-1]

using that basis thingy majig

[remote mural]

,w eigenvectors [[1,3,2],[0,2,0],[0,-3,-1]]

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Toby#2275

[remote mural]

yup, all right

[midnight sedge]

thanks bro <3

i didnt know you could just assume stuff lmao

.close

[calm coral]

Channel closed

Closed by @midnight sedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite bane]

need help please

[swift marsh]

plug g(x) into f(x) whereever you see an x

and than put x as 5

so it would be (x+3)^2 , where x = 5

coz its asking for f(g(5))

[granite bane]

right

[rapid wasp]

it’s just written poorly

[granite bane]

yeah man my teacher really puts no effort into lessons aswell at this rate ill be doing foundation

[teal coral]

how is it written poorly

[remote mural]

I think they mean it isn’t clear that it is function composition

However that’s just notation - it doesn’t matter

[hollow furnace]

Bro dw my teacher just gives us a paper and leaves us to it 💀

[granite bane]

were getting 3s together

[rapid wasp]

lack of parenthesis

[teal coral]

well as long as fg is thought of as function composition

[rapid wasp]

it could be interpreted as you multiplying f*g(5) and getting 8x^2

[teal coral]

do the parentheses really matter

[granite bane]

bro i cant get past this man please help

the videos are really not helping bruh

[exotic falcon]

For a function f(x)

the notation f(1)

means to evaluate the function

at x=1

and it works the same if your function is instead g(x)

It looks like part 3 is meant to say g(f(3))

which means to evaluate g(x) at f(3)

which you can find by evaluating f(x) at 3

[calm coral]

@granite bane Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair pike]

Writing and Interpreting an Equation

[runic fjord]

what's ur problem/what do you need help with?

[fair pike]

I need help with like

A walkthrough

Please

[runic fjord]

About what exactly

what this graph is showing and means?

or how it was made?

or both

you didn't post a question, you posted a statement and a graph of a situation

[fair pike]

I need to make an equation in slope intercept form with this graph

And I need help

[runic fjord]

ohhh okay

sure we can do that

[fair pike]

Thank you

[runic fjord]

so the easiest part is the y-intercept

that's when x=0

so...

what's the value at x=0?

looks like... 150 to me

do you agree?

[fair pike]

Yes

[runic fjord]

okay so we got y = mx + 150 so far

for slope let's pick two points from the line

which two do u wanna pick

[fair pike]

Would this work?

[runic fjord]

yeah

I like using nice whole numbers tho

like (1, 120) and (2, 90)

[fair pike]

I can change it

[runic fjord]

since if u look here

it's a bit above a whole number and so it's a bit hard to be precise

we don't want that

[fair pike]

Alright

[runic fjord]

but anyways, with our two points, how would we find slope?

[fair pike]

Counting the amount of spaces down and across

?

Like rise over run

?

[runic fjord]

yep

so we got ... $\frac{120-90}{1-2}$

[potent lotus]

Juke | ping me if no response

[runic fjord]

which is 30/-1 which is just -30

so our final equation for the line is $y=-30x+150$

[fair pike]

Thanks!

[runic fjord]

np

[potent lotus]

Juke | ping me if no response

[fair pike]

That's all I need

[runic fjord]

lit

[calm coral]

@fair pike Has your question been resolved?

Channel closed

Closed by @fair pike

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[remote mural]

How do I do this

[naive owl]

what have you tried

[remote mural]

Honestly, I don't know where to start

[calm coral]

@remote mural Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted socket]

Any help is lovely appreciated !

[calm coral]

@muted socket Has your question been resolved?

[muted socket]

<@&286206848099549185>

[burnt phoenix]

How much sugar does Dana need for 1 gallon?

[stiff geyser]

3/4 cup

[burnt phoenix]

Well then will she need more or less for 5 gallons?

[muted socket]

yh i was abt to write that.

More.

[burnt phoenix]

Very good!

Wht can you do to a number to increase it?

[muted socket]

add 2/4?

or idk

haven’t do this since a long time ago.

[burnt phoenix]

Well.. you have to multiply

[muted socket]

3/4x5

[burnt phoenix]

Well done!

What does that become?

[muted socket]

3 3/4

?.

[burnt phoenix]

Well.. that's the mixed form

[muted socket]

15/4 I meant

[burnt phoenix]

What would the improper form be?

[burnt phoenix]

Perfect!

Congratulations on solving the question 🎉

[muted socket]

and then 15/4 equals 3 3/4 ig

[burnt phoenix]

Indeed. 15/4 is an improper fraction and 3 3/4 is a mixed fraction

[muted socket]

yep.

[muted socket]

tyy!

[muted socket]

I’m trying to figure out if it’s addition or idk

any help

?

<@&286206848099549185>

[storm hatch]

26x148

26×148

@muted socket if there are 25 boxes of light bulb and each box have 148 light then
Total light will be 25×148

=3700

[muted socket]

yea

so then it would be multiplication ?

[muted socket]

?

[storm hatch]

26 times 148

[muted socket]

ty

[storm hatch]

In which standard you are in?

What's your age?@muted socket

[muted socket]

for wha

jus cuz this is easy ain’t no mean I’m young

[storm hatch]

It's a problem for a 10 year old

[muted socket]

who said I’m 10?

[storm hatch]

It's just a simple multiplication

[storm hatch]

The problem is for 10year old
And I am talking about max.
Here in India 5-6 year old can do these

[muted socket]

gawd damn y’all be mad annoying why y’all gotta ask me questions, this ain’t even mine 🤔.

[storm hatch]

Ok just leave it

Enjoy learning

[muted socket]

trust me ik how to multiply but I ion even do those stuff anymore .

It’s just a little question.

[storm hatch]

Are you okay telling your age and your country?

[muted socket]

I’m in 7th grade nd trust me we can’t control ages.🙅

ye

[storm hatch]

And which country?

[muted socket]

14

nd

[storm hatch]

Country buddy

[muted socket]

United States

[storm hatch]

Cool

[muted socket]

not rlly

how old are u?

[storm hatch]

17

[muted socket]

oh

so high school

[storm hatch]

Yes..
We call it 12th standard

[muted socket]

your are sophomore?

oh.

[storm hatch]

What's that?

[muted socket]

oh nvm but that’s how we call it here.

[storm hatch]

Ookkk

It is Last year of my school

[muted socket]

ohh

[mint crater]

Rip

I don't see how this relevant ngl

[calm coral]

@muted socket Has your question been resolved?

[coarse coral]

Yeah that's multiplication

[muted socket]

<@&286206848099549185>

[marsh moat]

Yes?

[muted socket]

Any help?

[white dove]

What about it

[muted socket]

It’s comparing decimals etc.

[white dove]

??

[marsh moat]

So for the 3/4 and 6/8 one, to simplify 6/8 you have to find one number that will divide both of them

Its 2

6/2=3 and 8/2=4

[muted socket]

that’s easy

[marsh moat]

So 6/8=3/4

[muted socket]

i don’t need that that’s easy.

I just need the other ones .

[marsh moat]

Yeah it is

[white dove]

So which part you didn’t specify

[marsh moat]

Okay

[white dove]

Just check if they’re equal

[muted socket]

They’re equal basically.

[white dove]

Find the sum or product

[muted socket]

6x4=24 8x3=24

equal

[white dove]

Is 500+2+8=502.8?

[marsh moat]

5.20=100+5.3=15, 100+15=115 and 5.23=115

First one is equal too

[white dove]

Wtf are u using period for multiplication

[muted socket]

yeah they’re only for decimals

[marsh moat]

Just simply do 500.8=4000 and add 10 to 500. Do they seem equal to you

[muted socket]

so (5x20)+ (5x3) = 5x23?

[marsh moat]

Its ≠

[marsh moat]

Yeah

[muted socket]

The second one is ≠?

[white dove]

Don’t just guess

Do the work

What is each side equal to

[muted socket]

I’m not guessing.

[white dove]

I don’t see any work

Looks like you’re guessing to me

[marsh moat]

For the third one 482/6 is about 80 something and (48/6)=8+(2/6)=1/3= 25/3 Do they seem equal to you

[white dove]

Don’t do the work for them wicked

[marsh moat]

Its ≠ too

[white dove]

That’s the whole point of the question

You have to just guide them

[marsh moat]

Oh............

Sorry

[muted socket]

yh but what’s the point helping if your not helping?

[muted socket]

ty tho

[white dove]

What

[muted socket]

why were you even here if you weren’t even helping?

😭

[white dove]

ive been trying to help the entire time you just arent listening

[muted socket]

like yh they weren’t supposed to give me the answer but you didn’t help anyway so

[white dove]

do you know how to simplify 500+2+8

[muted socket]

yes

[white dove]

and what is it

..

it shouldnt take you this long

[muted socket]

.close

[calm coral]

Channel closed

Closed by @muted socket

Use .reopen if this was a mistake.

[white dove]

????

do you want to learn

or just get the answers

you have to be patient to learn

im taking you through the steps

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[remote mural]

Is this tree diagram correct?

[summer cypress]

err, the proabiilities within each tree should add up to 1

[remote mural]

Oh

Oh?

Confused

[summer cypress]

what are you confused about

0.7 + 1.1 = 1.8

this cant happen

since bus is 0.7, walking has to be 0.3

so that it adds up to 1

@remote mural also early and not early are the probabilities of choosing to be early/not early given that you are going by bus or walking

not the probability of going to the bus/walking early or not early

[remote mural]

Ooh

I see

[remote mural]

Oohh

I get it now

What about for b and c?

[summer cypress]

@remote mural have you done the probability tree correctly

[remote mural]

Yep yep

[summer cypress]

Let's see @remote mural

[summer cypress]

No

That's wrong

The early and not early part

Acc

No

That might be right

But it's confusing

What they mean by

Can you send the original question @remote mural

[remote mural]

Okie

[summer cypress]

Then yh, your tree is correct

[remote mural]

Oh okie

What do you do for b>

I think I have to like, multiply or divide it by some numbe

But Idk the number

Hi pls help

Sorry if I sound demanding, do I have to do something with 100?

I tried but nothing’s really.. um working out

close.

.close

[calm coral]

Channel closed

Closed by @unkempt shuttle

Use .reopen if this was a mistake.

[summer cypress]

.reopen

[calm coral]

✅

[summer cypress]

For b

Find the probability that she walks to school late

As in

Probability she walks to school late * probability she is not early given that she walked

[calm coral]

@remote mural Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady wasp]

Can I find the antiderivative of this function using substitution?

[swift marsh]

Aye you could

[steady wasp]

So U = x-1/3pi?

[swift marsh]

I would say

take the 1/2 into the sub too

[steady wasp]

Am I allowed to multiply what's within the parentheses by 1/2?

[swift marsh]

if thats the same as $\cos(0.5(x-\frac{1}{3}\pi))$

[potent lotus]

Mortta

[swift marsh]

Than yes

you can expand through by 1/2

[steady wasp]

So U will be that and du = 1/2dx => 2du = dx

[swift marsh]

Yep

[steady wasp]

So I'll have the integral of cos(U)2du = 2 times the integral of cos(U)

Oh yeah I end up with the correct answer!

Thanks for helping me

.close

[calm coral]

Channel closed

Closed by @steady wasp

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[umbral citrus]

1BE
2BDC
3ACE

[umbral citrus]

Is what I got for these

Correct me if I’m wrong on these please

[calm coral]

@umbral citrus Has your question been resolved?

[umbral citrus]

<@&286206848099549185>

[inner zealot]

Looks good to me.

[honest zephyr]

yes all are correct

[umbral citrus]

Thank you

.close

[calm coral]

Channel closed

Closed by @umbral citrus

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bronze adder]

Let $1, \alpha, \alpha^2 \cdots \alpha^{n - 1}$ be the roots of unity, and $\omega = \frac{-1 + i\sqrt{3}}{2}$ then what numerical values can $\prod_{r = 1}^{n - 1} \omega - \alpha^r$ take

[potent lotus]

NEONPerseus

[viscid silo]

roots of unity form a group

[bronze adder]

You told me

[viscid silo]

well yes

[bronze adder]

[viscid silo]

do some expanding ig

[bronze adder]

At n = 3

It's 0

Cube roots of unity

And that's all I marked on my sheet

[glass heart]

consider the polynomial $\prod_{r=1}^{n-1} (x-\alpha^r)$. can you write that more easily?

maybe by multiplying it by (x-1)

[potent lotus]

Denascite

[bronze adder]

Hmm

I'm not sure what you mean

If I can write that more easily

[glass heart]

(x-1)(x-a)(x-a^2)...(x-a^(n-1))

[bronze adder]

Yup

[glass heart]

those are all nth roots of unity

[bronze adder]

Yup

[glass heart]

so of what polynomial are they a root

[bronze adder]

$x^{n - 1} = 1$

[potent lotus]

NEONPerseus

[bronze adder]

I think?

[glass heart]

x^n-1

[bronze adder]

Oh no equals

[glass heart]

wait, nth roots or (n-1)th roots

[bronze adder]

The product only goes to n - 1

[glass heart]

yes but what are they

you didnt say

you only said roots of unity, not which roots

I assume nth roots?

[bronze adder]

1, α, α^2... α^(n - 1) are the nth roots yeah

[glass heart]

good so they are roots of x^n-1

[glass heart]

so what is this product

[bronze adder]

x^(n - 1)

?

[glass heart]

no

[bronze adder]

[glass heart]

why are you using n-1 in the exponent

[bronze adder]

Because the last root is α^(n - 1)

I'm being foolish aren't I

If we're talking about n roots

Then the degree must be n

Alright so x^n

[glass heart]

so (x-1)(x-a)...(x-a^(n-1)) = x^n -1

[bronze adder]

Yeah

[glass heart]

now can you work with that

[bronze adder]

So Vieta's or something?

[glass heart]

what is the original question asking

[bronze adder]

The numerical values that the product can take

[glass heart]

its asking about (w-a)...(w-a^(n-1))

[bronze adder]

Yup

omega is a cube root of unity

[glass heart]

so what do you get if you plug w into this

[bronze adder]

w^n - 1

and we know w^2 + w + 1 = 0

[glass heart]

not so fast

dont forget that factor of x-1

you get (w-1)*what you want = w^n - 1

[bronze adder]

Oh right

We added that factor

Ooo

[glass heart]

so what you want = (w^n-1)/(w-1)

[bronze adder]

So it's just the summation formula for a geometric progression

I don't think that's a coincidence

[glass heart]

its not

roots of unity and geometric progression is never a coincidence

[bronze adder]

Yeah I remember our teacher saying something about it

So do I just put in a few numerical values of n

Since we know that w^4 = w

I don't have to check much

[glass heart]

because w is a cube root of unity it will just repeat

yes

[bronze adder]

Alright I'll do that

Thanks a lot man :)

[leaden thunder]

what a fun problem

[bronze adder]

You were of great help

Have fun reimann

.close

[calm coral]

Channel closed

Closed by @bronze adder

Use .reopen if this was a mistake.

[leaden thunder]

https://www.youtube.com/watch?v=gUPrnu3BEU8

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coarse sundial]

Determine f such that g(f(x)) = x for all x ∈ Dom(f), where g is given by

a) g(x) = (x+2)/(x+1)

[coarse sundial]

Is this even possible?

[leaden thunder]

yes. usual way of finding the inverse function

[vocal trout]

g should be the inverse of f

g is a rational fraction so it's injective and hence its invertible, so yes you just need to find the inverse

[coarse sundial]

Ok, I'll try to find it

[calm coral]

@coarse sundial Has your question been resolved?

[coarse sundial]

(-x + 2)/(x-1)

ok, I think I got it! Thank you two

.close

[calm coral]

Channel closed

Closed by @coarse sundial

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tepid snow]

For the first claim, where did they use minimality of d to deduce r=0

[carmine sorrel]

d is the smallest positive value that gives g^d in H
but they just showed g^r in H
and r < d

[pulsar granite]

g^r in H but d is the smallest positive integer such that g^d in H. Hence r is a positive integer and r >= d or r is not a positive integer.

0 <= r < d so r is not a positive integer and r = 0.

[calm coral]

@tepid snow Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[analog ferry]

hello

[analog ferry]

ive been googling a bit

and it says that the formula for a pascal (the unit ofmeasurement not the triangle) is 1 pa = 1 N/m^2, but other sources say that its 1 pa = 1n*m^-2. whcih is correct?

.close

[calm coral]

Channel closed

Closed by @analog ferry

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading talon]

is C right? D is confirmed incorrect

[white dove]

It doesn’t exist though

[marsh agate]

2-x² -> 2-

[fading talon]

that's weird

[marsh agate]

so it's f(2-) = 3

because 2-x² approaches from below

[fading talon]

i had to submit, and my teacher says that D is wrong.

[fading talon]

r u sure

[marsh agate]

yes

[coral osprey]

Yeah

It's the stupid thing about limits sometimes

[marsh agate]

it's not stupid

[fading talon]

okay

[coral osprey]

Well you must like limits. I hate limits

Every time I see "lim" I reach my limit

[marsh agate]

I enjoy topology

[fading talon]

thank you very much :D

[marsh agate]

so much so that at 18 I've already taken it 3 times

lol

[fading talon]

its 0 right?

@marsh agate

cuz its from the left side

[marsh agate]

yes

it's -2/3

[white dove]

shite i forgot

[marsh agate]

misread the slope

[fading talon]

ohh

[fading talon]

what about from the right side

cuz (b) was from the left side

[marsh agate]

of k' ?

[fading talon]

yes

[marsh agate]

DNE

or -inf

[fading talon]

is it dne cuz the semi circle isnt straight

[marsh agate]

k' is always defined

we're asking about the limit

but it goes to -inf there

[fading talon]

ohh

[marsh agate]

lol

what do you think

-3 ?

[fading talon]

let me show u my work

[marsh agate]

yeah -3

because it's just k(1) / cos(pi)

[fading talon]

okay ty

[marsh agate]

so no ?

[fading talon]

wait is it -3 or nah cuz thats my simplified work

3/-1 = -3

[marsh agate]

that falls in the category of "right result for the wrong reasons"

[marsh agate]

h(1) = 0

k(1) = 3

[calm coral]

@fading talon Has your question been resolved?

Channel closed

Closed by @fading talon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[signal dragon]

would i just do expand then collect?

[royal salmon]

you could do that but it's unncessarily long

because 4sqrt(5) -sqrt(5) can be simplified further

[calm coral]

@signal dragon Has your question been resolved?

Channel closed

Closed by @signal dragon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal bear]

In the process of making an arctan integration. I think I’ve technically already asked abt smth similar to this but I don’t get it…

To get the standard integration (1/(u^2 + 1)), id need to reduce the 9 to a 1 without modifying the u

[surreal bear]

The answer tells you to use x/3 as u but wouldn’t that just give what’s above?

[prisma mango]

x/3 for u sub?

[surreal bear]

Yes?

[mellow crater]

you forgot about 3 squared

I guess

if u = x/3 then 3u = x
x^2 = (3u)^2 = 9u^2

[surreal bear]

It doesn’t only apply to the x?

[mellow crater]

yes, to the x

but x is 3u

[surreal bear]

Like this is how I view it

Slightly off

3 should stay at 2nd row instead of vanishing into thin air

That’d make it 9 starting at row 3

[mellow crater]

still same mistake

[surreal bear]

I don’t get it :(

[mellow crater]

do you understand

that if x = 3u

then x^2 = (3u)^2 = 9u^2

?

[surreal bear]

Oh I didn’t see it as applied at the end

I thought it was still pending to be applied

Which didn’t make sense

Ic thanks

.close

[calm coral]

Channel closed

Closed by @surreal bear

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent steeple]

What have you tried

[pseudo wedge]

you can't just sub in 5

i'm not gonna send you the solution

remember how you calculate a normal integral

you subtract (antiderivative evaluated at upper limit) - (antiderivative evaluated at lower limit)

[calm coral]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent steeple]

The same procedure that you did earlier

[atomic cave]

it didnt work

[carmine sorrel]

what did you try?

[atomic cave]

the multiple is 4

so y= 4^x/

and i couldnt figure out the last number

[carmine sorrel]

what happens when x = 0?

[latent steeple]

Exponential function is generally y=ab^x. b is 4 here so plug in any point to find a

[atomic cave]

im not sure

[atomic cave]

y=(a)(4^x)?

[latent steeple]

Yeah,same thing

[atomic cave]

what do i put for a?

[latent steeple]

Find a

[atomic cave]

how-

[latent steeple]

Pick any x and y pair from the table given

[atomic cave]

so 0 and 3?

[latent steeple]

Yes, or (1,12) or (2,48) or (3,192). Any one gives same result

[atomic cave]

what am i testing for though

[latent steeple]

Finding a

To write the equation

[atomic cave]

yeah but how

[latent steeple]

y=ab^x.

Find a. You have all other variables

[atomic cave]

HOW DO I FIND A? 😭

.close

[calm coral]

Channel closed

Closed by @atomic cave

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upbeat shoal]

how would i solve this?

[reef nimbus]

is it $\sin{[(5x)^2]}$ or $[\sin{5x}]^2$?

[potent lotus]

cwatson

[upbeat shoal]

its -2 but idk how to get it

[reef nimbus]

ok it must be the latter. what's the lowest possible value of $(\sin{x})^2$?

[potent lotus]

cwatson

[upbeat shoal]

?

[neon shadow]

What is the range of sin function?

[upbeat shoal]

-1 to1?

[reef nimbus]

yes, so what is the range of $(\sin{x})^2$?

[potent lotus]

cwatson

[upbeat shoal]

1 to 1?

[reef nimbus]

no

sin(x) can be anything in between -1 and 1

so you can't just take the endpoints and square them

[upbeat shoal]

0 to 1?

[neon shadow]

Yes

[upbeat shoal]

so you do 3*0-2

[neon shadow]

That is the lowest value of sin(5x) too

[neon shadow]

Yes

Which is -2

[upbeat shoal]

ty

.close

[calm coral]

Channel closed

Closed by @upbeat shoal

Use .reopen if this was a mistake.

[neon shadow]

Thank cwatson too

Nvm too late

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[noble cedar]

am I allowed to do this? (where the light blue arrow is)

[fallen adder]

i don't think so

[noble cedar]

what should i do instead?

[fallen adder]

not that

[potent igloo]

Something else

[strange lichen]

Go back to the e^x = 1 + e^(2y)

Then isolate the e^(2y)

Then see if u can go from there

[noble cedar]

subtract 1?

tyty

[strange lichen]

Or u can be fancy and write it as

[potent lotus]

Stephen

[strange lichen]

What were u doing in the first few steps btw

[fallen adder]

wait so you were just solving for y

[noble cedar]

finding the inverse

oops i wrote that wrong

f^-1(x)

labeled as derivative accidentally

there we go

all good here or any issues with domain, range?

[winter loom]

All good.

[noble cedar]

.close

[calm coral]

Channel closed

Closed by @noble cedar

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[regal remnant]

can someone please explain how to find the period

[regal remnant]

i dont understand what this means

[fallen adder]

do you know what a period is?

[regal remnant]

the amount of time it takes to complete one cycle?

[fallen adder]

do you know how to find b?

[regal remnant]

not sure

[regal remnant]

no cycle is completed between 0 & 2pi ?

[calm coral]

@regal remnant Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tepid willow]

If 3√a * 3√b = 3√a*b
What would happen if the second one (3√b) wouldn’t be in ^3?

Ex:

3√a * √b

[potent igloo]

$3\sqrt{a}\times3\sqrt{b}\ne3\sqrt{ab}$

[potent lotus]

SWR

[tepid willow]

My teacher literally said it…

[potent igloo]

There's a difference between $3\sqrt{a}$ and $\sqrt[3]{a}$

[potent lotus]

SWR

[potent igloo]

$3\sqrt{a}$ is "three times square root of a". $\sqrt[3]{a}$ is "cube root of a"

[potent lotus]

SWR

[tepid willow]

I don’t understand

[potent igloo]

which part do you want to me clarify?

[tepid willow]

3 * a
and then
a * a * a

Is this like this?

[potent igloo]

3 * a is just 3a

a * a * a is a³

3a is adding a three times

a³ is multiplying a three times

[tepid willow]

Disabling 4sqrt3 equals to

sqrt4^2*3?

[potent igloo]

?

disabling?

What are you trying to do exactly?

[tepid willow]

You don’t know Math?

<@&286206848099549185>

[real epoch]

😂

wtf is this

[tepid willow]

Go away

[real epoch]

What it's saying is that if you have 2 or more radicals being multiplied, the v looking thing being multiplied.
They combine into 1 square root.

root a multiplied by root b combine into 1 root

[tepid willow]

Anyways why does the red circle equal go blue circle? <@&286206848099549185>

[real epoch]

under that 1 root multiplication still happens

[tepid willow]

This is so complicated!

[untold drum]

the red circel does not equal the blue circle, you have something before the red circle.

[tepid willow]

Why yellow * red = blue???

[untold drum]

you have the third root from 4 multiplied with the third root from 4^2 which is the third root of 4^3. and the third root of 4^3 is 4.

[tepid willow]

This is correct? @untold drum

[untold drum]

$2\cdot\sqrt{6}=\sqrt{24}$

[potent lotus]

ThM

[untold drum]

$4\cdot\sqrt[3]{2}=\sqrt[3]{128}$

[potent lotus]

ThM

[tepid willow]

Im so pro

What’s this called in English?

@untold drum

[untold drum]

what do you mean?

[calm coral]

@tepid willow Has your question been resolved?

[tepid willow]

Doing these? @untold drum

[untold drum]

math? calculation?

or writting in latex?

[tepid willow]

OMG 🤦🏻‍♂️

[calm coral]

@tepid willow Has your question been resolved?

[white dove]

theres not really a term for it

its just algebra

[tepid willow]

It’s not algebra.

[white dove]

looks like alg to me

[tepid willow]

[white dove]

wat

[real epoch]

@tepid willowresend

quesitons

more clearly

[calm coral]

@tepid willow Has your question been resolved?

[calm coral]

@tepid willow Has your question been resolved?

[untold drum]

this.

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet osprey]

!status

[calm coral]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[gleaming lark]

1

I think I put it all in x and y values right

[velvet osprey]

"put it all in x and y values" is bad wording.

you have here an optimization problem, and more specifically a linear programming problem.

[gleaming lark]

so its a objective expression with constraints right

f(x,y) = 60(4)y + 175(8)x is my objective expression

60y + 175x ≤ 27000
y + 5x ≤ 575 are my constraints

for space and weight

[velvet osprey]

f(x,y) = 60(4)y + 175(8)x is my objective expression
this is incorrect

the objective function is the sales revenue from the food and water you bring

[gleaming lark]

but that is the one changing right?

[velvet osprey]

weight has nothing to do with that

oh wait

my bad

the prices are given per pound

not per container

okay your objective function is correct sorry

[gleaming lark]

the maximum revenue is $31,200 I think?

[velvet osprey]

ok so you have those constraints as well as x, y ≥ 0.

[velvet osprey]

nobody says "objective expression" by the way

[gleaming lark]

selling 80 units of food and 240 of water?

does that sound right?

[velvet osprey]

dunno

how'd you arrive at that

divine apparition?

[gleaming lark]

I wish

I solved it as a linear equation

wait plugging back in the values

it looks like I might be wrong?

because the weight does not add up to 27000 pounds

[velvet osprey]

"it"?

[gleaming lark]

the objective equation

or whatever it is supposed to be called

[velvet osprey]

do you have your work on paper