#help-42

1 messages · Page 17 of 1

oblique current
#

that sounds way too general then

paper bolt
#

What do you mean

oblique current
#

its kind of like asking how to simplify a + b + c + d + e where a,b,c,d,e are just any numbers

leaden thunder
#

,calc 1/24

potent lotusBOT
#

Result:

0.041666666666667
leaden thunder
#

Computers seem to handle that fine?

paper bolt
paper bolt
#

Well let's say how would they handle

#

1 / 1000! ?

#

That's bad, I would assume

oblique current
#

,w 1/1000!

oblique current
leaden thunder
#

Your question just needs to be scoped better. Solving numerical approximation is different from simplifying fractions

paper bolt
#

Ideally

#

It would be best to represent it as a factorial

#

Which is later on going to be multiplied by certain other factorial and scale it back

leaden thunder
#

"best" for what purposes

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What problem are you solving

paper bolt
#

My friend and I are trying to make a certain algorithm work

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And essentially that thing is part of the algorithm

#

It's optimization to an already existing thing as far as I Know

#

and I would have to do the coding part

#

This is an example expression:

#

-1/8! + 1/2! * 1/6! + -1/4! * -1/4! + 1/2! * 1/2! * -1/4! + 1/6! * 1/2! + 1/2! * -1/4! * 1/2! + -1/4! * 1/2! * 1/2! + 1/2! * 1/2! * 1/2! * 1/2! = 277/8064

#

This 277/8064 will be later on multiplied by some factorial

#

Which will scale it back

oblique current
#

this is different to your original question, you didnt have products of factorials

paper bolt
#

Does that change anything significantly?

oblique current
#

probably not, but it could have

remote mural
#

what language? what algorithm? before we get too far down the xy rabbit hole

paper bolt
#

As for algorithm, I would have to keep that a secret for now :/

remote mural
#

use sympy if you care about the result (but not the speed)

paper bolt
#

Speed would also be important, that's kind of the point of optimization

remote mural
#

you cant have both if the problem that you've proposed is optimal ¯_(ツ)_/¯

paper bolt
#

XD

#

Thanks for the tip tho, I will take a look at it

#

But, can we anyhow simplify this mathematically

#

Mathway has successfully expressed this thing as that fraction up there

oblique current
#

sure, just add the fractions by hand

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thats what mathway will have done

paper bolt
#

What do you mean "by hand"

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Literally that way?

oblique current
#

like the usual way you add fractions

paper bolt
#

Are you really sure that will ... work optimally xD?

oblique current
#

you are asking whether you can simplify it mathematically

paper bolt
#

To phrase it mathematically, do you think that's simplified enough?

oblique current
#

how more would you simplify it than as one fraction?

paper bolt
#

But to get to that one fraction maybe you will have to calc 1000!

#

And that's not very great

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I am trying to evade that

oblique current
#

which brings me back to the original point of this being way too general. you can't hope for a general simplifcation that's going to work no matter what expression you give

#

simplifications that will avoid big calculations will be a result of cancelations because of the specific terms in an expression

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like how 24/6 = 4, but being able to do that simplification was completely dependent on the numbers being 24 and 6

paper bolt
#

Alright

#

We will end it at that then xd

#

Thank you for help

#

.close

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#
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exotic arch
#

Hi everyone, I hope you all are doing well today!
I am working on a creating some parametric gear drawings by means of code and for that need to use an involute curve.
Calculating the positions is no issue, but finding out where to start an stop is an issue.
To this end I have identified this formula to find out where a given angle would create a point on the involute curve:

involute_position = angle - atan(angle)

Now I am looking for doing the inverse to find out where I should start/stop.
The question would be:
Given the involute position (an angle) how would I find (or approximate) the input angle?

somber finch
#

,w x = y +arctan(y)

potent lotusBOT
somber finch
#

hm

#

'-'

exotic arch
#

Of course! Let me draw it up real quick

teal coral
#

are you just trying to solve equations that look like 3 = theta + atan(theta)?

exotic arch
#

I hope this illustrates the question:

exotic arch
teal coral
#

what's the difference between that and what I said

exotic arch
#

My mathematical vocabulary isn't too great, so it might be the same.

#

Ah, I'm looking for theta - atan(theta) instead of theta + atan(theta) I'm not sure if there's a difference?

teal coral
#

oh yeah my bad typoed that

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so you want to solve something that looks like c = theta - atan(theta)

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like do you just want numbers for practical purposes or are you looking for a proper analytical solution

somber finch
#

Do you have the tools to calculate theta - atan(theta) given theta? You could use derivative then to aproximate

exotic arch
#

It would be numbers for practical purposes

teal coral
#

practical purposes, you can probably just ask wolframalpha

#

,w solve 3 = theta - atan(theta)

potent lotusBOT
teal coral
#

if you need to write it in code, you can use some numerical optimization methods

exotic arch
#

Ah I see, so that would provide individual values

#

As 3 would be a dynamic value, I think the analytical solution is probably what I'm looking for then?

teal coral
#

are you writing code for it

exotic arch
#

Yes

teal coral
#

okay then you can use a numerical method

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in this case, there are a few ways to do it

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one way might be to rearrange the equation to theta = c + atan(theta)

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and then solving this amounts to finding a fixed point

exotic arch
#

I see, so I would swap out the function, and then iteratively find the closer value?

teal coral
#

well, hmm idk if that would work so well, since the derivative at the root is 1

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you could certainly use something like Newton's method

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there are plenty of root-finding algorithms

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at the worst, bisection would probably do the trick

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in particular, the equation you're solving is really well-behaved; it's monotone nondecreasing

exotic arch
#

That makes sense, I'll try that out!

teal coral
#

so even a simple binary search is guaranteed to converge

exotic arch
#

Thank you, I will try those methods out!

somber finch
#

Bisection can ensure decimal places

exotic arch
#

So if I understand correctly, there's no direct method for inverting this formula, and as such, using some root-finding method is necessary to approximate the values?

#

Thank you for your help @teal coral and @somber finch!

#

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sullen heart
calm coralBOT
sullen heart
#

Need help

frosty compass
#

whats the nature of ABCD ?

sullen heart
#

Parallelogram

calm coralBOT
#

@sullen heart Has your question been resolved?

frosty compass
#

is there a way to prove that AM is the bisector of BAC ?

sullen heart
#

Possible if AB:AC = 2:3

frosty compass
#

im looking for another but i cant seem to find one

sullen heart
#

Might be possible with constructing a line

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frosty compass
#

.reopen

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sullen heart
#

.

calm coralBOT
sullen heart
#

Need help

rotund olive
#

well I do have an idea

calm coralBOT
#

@sullen heart Has your question been resolved?

frosty compass
sullen heart
#

Yes please

rotund olive
#

nvm it didn't work blobcry

sullen heart
rotund olive
#

my idea ended up with a conclusion that 5=3qsrt2 KEK

sullen heart
#

???!!????!!? What does that mean

calm coralBOT
#

@sullen heart Has your question been resolved?

frosty compass
#

<@&286206848099549185>

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sudden nebula
#

I need a hint for how to handle the exponents here

sudden nebula
#

Could I multiply by something to make the math smoother?

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fair rapids
#

Good Evening!
Can someone help me to find the approach they used to get that result?
I know that the first fraction is 2 but what about the rest?

glass heart
#

show the original problem statement

#

but well, it does say quotientenkriterium there

remote mural
#

looks like ratio test

fair rapids
#

I am aware of the criteria, I just dont udnerstand how they transformed the first equation to the second

glass heart
#

well presumably plugged in a_k+1 and a_k

fair rapids
#

And from theory?

glass heart
fair rapids
#

Because 2^k+1 /2^k is 2

glass heart
#

well the factorials nearly cancel each other out

#

and just a few factors remain

fair rapids
#

So it says that we need to decide if the series converges

glass heart
#

(k+1)! = (k+1) * k!, the k! cancel and you are left with (k+1) in the numerator

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then squared

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and (2(k+1))! = (2k+2)! = (2k+2)(2k+1)*(2k)! and the (2k)! cancel

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and you are left with (2k+2)(2k+1) in the denominator

fair rapids
#

What is this (2k+2)! = (2k+2)(2k+1)*(2k)!

glass heart
#

well factorial

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(2k+2)! is the product of all numbers <= 2k+2

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(2k+2)(2k+1)(2k)(2k-1)(2k-2)....3*2*1

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but that second part is just (2k)!

fair rapids
#

Holy moly

#

Never though about it like this

glass heart
#

what did you think factorial was

fair rapids
#

I mean I get the concept for natural numbers

#

But not in such a way

#

Thats actually great help!

#

Appreciate it 👍

glass heart
#

youre welcome

fair rapids
#

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#
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modest otter
calm coralBOT
modest otter
#

I am confused and stuck since the first step

#

.closr

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remote pendant
#

If S is normally distributed with mean 1800 and variance 317.4

remote pendant
#

and L is also normally distributed with the same mean and variance

#

how can u work out the probability that S is atleast 25 units larger than L

#

textbook has the answer but no workings lol

#

<@&286206848099549185>

remote mural
#

Very carefully AA_Noted

remote pendant
calm coralBOT
#

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drowsy flume
#

Um hello can I please just have some help??

calm coralBOT
#

Please don't occupy multiple help channels.

drowsy flume
#

sorry

hasty fiber
#

stick to your first channel

#

.close

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eternal mason
#

log_10(1/sqrt1000)

calm coralBOT
eternal mason
#

how do u simplify this

remote mural
#

in a more simplified form

eternal mason
#

uhhh

#

idk

remote mural
#

well okay

eternal mason
#

ik its around 31

remote mural
#

1000 is just 100 times 10 right?

eternal mason
#

yea

remote mural
#

right so what is the square root of 100

eternal mason
#

10

remote mural
#

right

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so take that out of the square root

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what do you have now

eternal mason
#

10^3

remote mural
#

no

#

like

#

[
\s{1000} = \s{100 \cdot 10} = ?
]

eternal mason
#

10sqrt10?

potent lotusBOT
remote mural
eternal mason
#

oh alr

#

then what

#

1/10sqrt10

remote mural
#

okay so

#

[
\log_{10}\parens{\f{1}{\s{1000}}} = \log_{10}\parens{\f{1}{10\s{10}}}
]

potent lotusBOT
remote mural
#

now,

eternal mason
#

mhm

remote mural
#

can you write sqrt(10) in exponential form

eternal mason
#

sure

#

10^1/2

remote mural
#

right

#

so

#

you have $10 \cdot 10^{\f12}$

potent lotusBOT
eternal mason
#

yep

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which is

remote mural
#

do you know anything in particular we can do with this?

eternal mason
#

10^1/2

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bases stay the same

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add the exponents

remote mural
#

yes

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so

#

add them up you get what

eternal mason
#

1 and 1/2

#

?

remote mural
#

yeah

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whats 1+ 1/2

eternal mason
#

3/2

remote mural
#

right

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so what do you have now

eternal mason
#

3sqrt10

remote mural
#

no

eternal mason
#

oh wait

remote mural
#

where did that come from

eternal mason
#

3/sqrt10

remote mural
#

no

#

again

#

where is the 3 coming from

eternal mason
#

1+1/2

remote mural
#

you said bases dont change at all

eternal mason
#

3/2

remote mural
#

we are only dealing with exponents

eternal mason
#

oh ok

#

so what do we have at the moment

remote mural
#

you have [
\log_{10}\parens{\f{1}{\s{1000}}} = \log_{10}\parens{\f{1}{10\s{10}}} = \log_{10}\parens{\f{1}{10^{\f32}}}
]

potent lotusBOT
eternal mason
#

yea

remote mural
#

i think it is best if you try to continue this on your own

eternal mason
#

why

#

??

#

@remote mural

remote mural
#

because i dont want to simply hand the answer to you

#

you wouldn't be learning anything in that process

#

why not try and attempt to continue it?

eternal mason
#

walk me through it

#

im understanding

#

or

#

what if i continue and u see if itts correct

remote mural
#

yeah sure

#

go ahead

eternal mason
#

ok

#

so

#

it would be

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1log_10(10^3/2)

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right?

remote mural
#

uh

#

where did the fraction disappear

eternal mason
#

oh wait

#

is it

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3/2log_10(1/10)

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according to the log rule

remote mural
#

okay sure

#

continue

eternal mason
#

then

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it would equall 3/2

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for the answer

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or am i wrong

remote mural
#

no

#

it would not be 3/2

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what is log_10(1/10)

eternal mason
#

1?

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right?

#

@remote mural

remote mural
#

no

eternal mason
#

how would u do it

#

@remote mural

remote mural
#

bring the 10 to the numerator

#

and please stop pinging me

eternal mason
#

ok

#

so 10^10?

remote mural
#

no like apply the exponent law of $\f{1}{a^n} = a^{-n}$

potent lotusBOT
eternal mason
#

ohh

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so it would be

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10^-3/2?

remote mural
#

yes

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idk why u brought back the 3/2

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but yes

eternal mason
#

so what?

#

just 10?

remote mural
#

yeah what u were already doing

eternal mason
#

yea

remote mural
#

so what do u have now

eternal mason
#

-1

remote mural
#

yes

#

apply the log rules

eternal mason
#

-3/2

#

right?

remote mural
#

yes

#

thats ur answer

eternal mason
#

ye

#

wasnt hard

#

now i got one more question

#

log_1/9(x)=-1/2

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i simplfied it to

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log_3^-2(x)=2^-1

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idk what to do after

#

@remote mural

#

last ping i promise

#

lol

#

anyone?

#

.close

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drifting vortex
calm coralBOT
drifting vortex
#

ive done part a

#

need some help on b plz

velvet osprey
#

$x_i \geq 0$

potent lotusBOT
velvet osprey
#

2+s-t >= 0, and -4+7s-19t >= 0, and so on...

drifting vortex
#

ok

drifting vortex
#

ight got them

#

what now?

velvet osprey
#

now graph them

#

that's what i would have done

#

it is not yet immediate just from looking at these ineqs that the five halfplanes they describe actually intersect in one single point

calm coralBOT
#

@drifting vortex Has your question been resolved?

drifting vortex
drifting vortex
#

with the credit of chartbit the goat

velvet osprey
#

seems like that works

#

i mean it would be nice to know what the value of t is too

drifting vortex
#

t = 0

#

💀

velvet osprey
#

oh, right. yeah.

drifting vortex
#

another Ann L

velvet osprey
#

🙄

drifting vortex
#

might have to change from rare Ann L to common Ann L

calm coralBOT
#

@drifting vortex Has your question been resolved?

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karmic ridge
#

could i get a hint?

calm coralBOT
karmic ridge
#

i dont even know where to start

tacit compass
#

maybe use a five digit variable abcde

#

and when you cross one out and add

#

you can create a system of equations

calm coralBOT
#

@karmic ridge Has your question been resolved?

karmic ridge
#

??

#

abcde+bcde=41751 for instance

#

how do i solve this

tacit compass
#

it looks liek that doesnt work

#

because e + e cannot end in a 1

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so try crossing out a different one

amber bolt
#

that's the answer then

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you can;t not cross e

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so you must cross e unles that doesn;t work either

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must be 1 or 0

#

only one equation

tacit compass
#

yep

#

abcde+abcd

#

use that

tacit compass
karmic ridge
tacit compass
#

is e is an odd number

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e + e will always end in an even number

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the only way you can end in an odd number is by adding an even and odd together

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1+1 = 2

#

3+3 = 6

#

5+5 = 10

amber bolt
#

e must be 6

#

and that lets you find d, and it keeps working

tacit compass
karmic ridge
karmic ridge
amber bolt
#

our equation is
11000a+1100b+110c+11d+e = 41751

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e must be such that 41751−e is divisible by 11

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i checked all options to find that e=6 makes it divisible by 11

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that was pretty dumb of me

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like the remainder of division bt 11 would give me 6 directly

#

at least it worked

#

now since 11000a+1100b+110c+11d = 41745 we can tell that d is 5, other letters don't even contribute to the last digit

amber bolt
#

it's a number that you have to subtract to make something divisble

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it only gives one number, smallest, so if it was appropriate e could also be 17 and 28 etc.

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but it's only 6 thaat can be a digit

karmic ridge
#

pardon...

karmic ridge
amber bolt
#

6+11

#

6+11+11

karmic ridge
#

ah ok

#

thanks for your help

karmic ridge
#

right?

amber bolt
#

right, they don't mess with the last digit

#

it's only defined by d

karmic ridge
#

but we still have to find the possible digits?

amber bolt
#

i don;t understand

#

yes

#

it just keeps working

karmic ridge
#

we have to find the possible values of a, b and c?

amber bolt
#

if d is 5, then 11000a+1100b+110c = 41690
and then c defines that 9

#

so c is 9

karmic ridge
#

right

#

so is there only 1 possible number?

amber bolt
#

yes

#

i checked

karmic ridge
amber bolt
#

how did you get that though

#

i don't know

karmic ridge
#

i subtracted 990 from 41690

#

@amber bolt since we said c=9

amber bolt
#

40700

karmic ridge
#

oh mb

#

THANKS

#

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wary condor
#

I need help understanding how to solve nested quantifiers

calm coralBOT
#

@wary condor Has your question been resolved?

calm coralBOT
#

@wary condor Has your question been resolved?

wary condor
#

<@&286206848099549185>

#

I don't have a frame of reference on how to solve this

#

so far I've only been given statements to negate

#

is it X is even --> x^2 + 1 is even?

#

idk if my train of thought is correct cause im struggling to find anything online that is similar to the questions im being asked.

But, for negating the statement do I negate everything

#

or just the 2nd stuff

#

so would it become
x ≥ −3 −→ x^2 < 9

#

and false

pulsar canyon
#

well for starters what do you do with the quantifier?

#

we have a ∀ right?

pulsar canyon
pulsar canyon
# wary condor <@&286206848099549185>

This one is phrased as an "if, then" if i'm understanding it correctly, so we flip the quantifier ("for all" gets replaced with "there exists an x" ∃). and then we say x is even AND x^2 + 1 is not odd (can just say even)

#

that's what i'm using to kinda refresh my brain on it

#

remember that push comes to shove use a truth table

calm coralBOT
#

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pulsar canyon
#

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frosty mica
calm coralBOT
frosty mica
#

This is the question I have an issue with.

#

This is what I have so far.

#

I understand I need to derive q to get i, but the software is saying my q is wrong.

#

The lecture on this section was very rushed in that it didn't explain any of the numbers, it just gave the initial top equation with values, then the next line was the q and i, without showing any of the steps in between.

calm coralBOT
#

@frosty mica Has your question been resolved?

upper sparrow
#

Hmmm, that integrating factor is looking a bit sus

teal coral
#

QC = V on a capacitor, is it not?

#

nvm I'm an idiot

#

Q = CV

#

but yeah your differential equation looks wrong, because q(0) = 0 is one of the boundary conditions

upper sparrow
#

Also seems like you implies that $\frac{1}{5\times 10^{-6}} = 5\times 10^{6}$ on that first line actually

potent lotusBOT
#

@upper sparrow

teal coral
#

should look something like q(t) = k(1-e^(-t/RC)) iirc

frosty mica
#

I'm not entirely sure, this entire section was not really explained whatsoever.

#

It's an online class so the teacher just assumes you know everything they don't explain, which I don't.

frosty mica
#

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frosty mica
#

This is what I'm stuck on

calm coralBOT
frosty mica
#

This is what I have tried

#

I'm just trying to wrap my head around all of the different variables/constants because the book is so egregiously awful at explaining it, that it doesn't seem to actually explain it, in my mind.

#

I understand that K is the limiting capacity, but r is just described as f(0), but I have no idea what f(t) represents.

teal coral
#

what do you mean by K and r

frosty mica
#

It's what's given in the book\

#

The book doesn't really explain anything clear enough for me to understand

#

K = carrying capacity, r is a constant where f(0) = r

#

f(P) =(r-rP/k)

teal coral
#

is that like the growth rate or something

#

and P is the population?

frosty mica
#

It would seem so, yes.

teal coral
#

it seems like rP/K is just a fudge factor to delete some offspring

frosty mica
#

I am assuming N and P are interchangeable here

#

For the purposes of the answer to the question

teal coral
#

not interchangeable, just different names for the same thing

frosty mica
#

Yeah

teal coral
#

the question doesn't talk about P

frosty mica
#

Yeah

#

I'm just extremely confused because this section is so poorly explained

#

I'm mainly confused on the N(0) = and the N(1) =

#

How do I tie those into the original equation to find r?

#

Or are those values for c?

teal coral
#

wait so are you confused where the form of the logistic equation comes from

#

or are you confused about how to actually solve the problem

frosty mica
#

Essentially, yes.

#

Both?

#

I don't really know where to find resources on this, since I haven't been in college in 5 years.

#

I am quite out of the loop.

teal coral
#

I dunno if it's that important for passing to know where the equation comes from

#

but as for actually solving the problem, you just need to know what the general form of the logistic equation looks like

frosty mica
#

I would assume that dN/dt = N(r-rN/K). Do I need to integrate that to get N(t)?

teal coral
#

and then find the constants like you would any other function

teal coral
#

you need to solve it to get N(t)

frosty mica
#

Is that not the logistic equation?

#

Oh

#

The book didn't say that at all

teal coral
#

you see that there's a derivative of N on the left side and the actual N on the right side

#

so you can't just integrate

#

solve it like you would any other initial value problem

frosty mica
#

Separate it for N on one side, t on other?

#

Would it have to be a Bernoulli equation since N is a denominator?

#

Oh never mind

#

I forgot you can integrate like that

frosty mica
#

Somethin more like that I think

frosty mica
calm coralBOT
#

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bitter plover
calm coralBOT
bitter plover
#

?

pseudo wedge
#

?

dry surge
#

?

pseudo wedge
#

they factored the denominator

bitter plover
#

how

pseudo wedge
#

well

#

$a = x^2 + 1, b = x, (a+b)(a-b) = (x^2+1)^2 - x^2$

potent lotusBOT
#

kheerii

bitter plover
#

thx

#

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calm coralBOT
astral mural
#

Huh

calm coralBOT
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mint cloud
#

how can u tell when certain letters are reffering to certain meanings

mint cloud
#

im starting to notice letters being used for multiple definitions

#

can you only tell based on the other letters around it?

exotic falcon
#

Normally you only know that a letter means anything if the problem tells you what it means

#

I could give you a question and say, "let x = the number of rubber ducks" or a different question and say, "let x = the number of cars"

#

and the only reason you know what "x" means is because I told you what it means for that specific question

#

Letters start to get used a lot for the same things and there will be patterns, so if sometimes you don't get an explicit explanation but you recognize what the letter probably means, it might be safe to guess.

mint cloud
#

hmmm ok thank you

#

so the letters that DO change are called variables correct?

#

and the ones that do not are Constants?

oblique current
#

"variable" and "constant" are not attributes assigned to letter, just to quantities themselves

#

i.e. there are not letters that are constants and letters that are variables

#

but in a specific setup, you can choose to represent variables and constants by whatever letters you choose

#

e.g. the speed of light in a vacuum is constant and we usually use the letter c for that

#

but that does not mean c is always representing a constant value

exotic falcon
#

yes and you can have an equation like this

potent lotusBOT
#

AustinU

exotic falcon
#

where a, b, and c are "constants" but x is a variable

#

although they are all letters

#

so it is entirely context-dependent, just like the definition of what the letters themselves signify

calm coralBOT
#

@mint cloud Has your question been resolved?

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whole swallow
calm coralBOT
whole swallow
#

the one with the truss

rotund olive
#

What's a truss

whole swallow
#

it's something that supports the roof

#

but in the image it's the one above. #2

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#

@whole swallow Has your question been resolved?

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whole swallow
#

.close

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#
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dense idol
#

is the null space of a matrix just the # of free variables?

exotic falcon
#

the dimension of the null space can be thought of as the # of free variables

#

I believe

dense idol
#

and then the col / row space dimensions are just the # of pivotal columns

#

which is also the rank

#

right?

runic fjord
#

... wait a sec

exotic falcon
#

Yes

runic fjord
#

that's not how I was taught it but that works fine, yea...

dense idol
#

thank god im not in medical school lmao

runic fjord
#

LOL wym

dense idol
#

i would probably explode with the amount of memorization i'd have to do

#

i hope i wont have to use this later

exotic falcon
#

linear algebra can be useful

calm coralBOT
#

@dense idol Has your question been resolved?

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glacial elk
#

if you have an operator that acts on f(x), what is the significance of a '^' above an x in its definition (like in the example below)

glacial elk
#

ive seen operators where if the goal was O(f(x) = x * alpha * f(x) they would write the x without the hat on top

#

so i'm confused as to why i'm seeing x hats in operators and if they mean something specific

calm coralBOT
#

@glacial elk Has your question been resolved?

calm coralBOT
#

@glacial elk Has your question been resolved?

calm coralBOT
#

@glacial elk Has your question been resolved?

solar spruce
#

do you have more context?

glacial elk
#

i'm trying to understand notation so that i can do a question for a piece of coursework

#

(which is testing linearity of operators)

#

i dont really think i understand the topic enough to phrase it in a way that makes more sense

#

i guess since i'm unsure of how vague the term 'operator' even really is

#

this is for example the hamiltonian operator [using the same field/definition of 'operator' i am studying and attempting to understand]

#

but i'm referring to any operator O that has notation 'x^' within it

stark sable
#

hey

#

that’s acutely really simple

#

so you see

#

use chat gpt👍

calm coralBOT
#

@glacial elk Has your question been resolved?

calm coralBOT
#

@glacial elk Has your question been resolved?

warped rampart
# glacial elk but i'm referring to any operator O that has notation 'x^' within it

operators in quantum mechanics are just given a hat on top to show that they are operators. in the example of the position operator $\hat{x}$ we just have that this operator just happens to be the position, $x$, so $\hat{x}=x$. a different operator like momentum is not just defined as the "momentum" (whatever that would be in quantum mechanics since velocity is not well defined) but as $$\hat{p}=-i\hbar\pdv{x}$$ or more generally $$\hat{p}=-i\hbar\nabla$$

potent lotusBOT
#

Duh Hello

warped rampart
#

so in this case $\hat{O}$ is just multiplying some function $f(x)$ by $\hat{x}\cdot\alpha$ (from the left). since $\hat{x}=x$ then this operator is just regular multiplication. so this O operator is just scaling a function by a factor $x\alpha$

potent lotusBOT
#

Duh Hello

warped rampart
#

to test for a linear operator you just need to check if this holds where $\alpha, \beta$ are scalars, $A$ is the operator and $x,y$ are the functions, vectors or tensors etc.

potent lotusBOT
#

Duh Hello

calm coralBOT
#

@glacial elk Has your question been resolved?

rigid kettle
rigid kettle
warped rampart
potent lotusBOT
#

Duh Hello

warped rampart
#

unless they just threw in the qm hamiltonian for no reason

glacial elk
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fresh mountain
calm coralBOT
fresh mountain
#

I have 29 and 30

#

<@&286206848099549185>

#

..

#

ok then?

#

I'll wait

mossy anchor
#

What do you want help with?

fresh mountain
mossy anchor
#

Which part? Where are you stuck? What have you tried?

fresh mountain
#

I'm trying to find the points of the triangle on 29

#

e

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#

@fresh mountain Has your question been resolved?

fresh mountain
#

...

#

ok?

#

.close

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turbid osprey
#

anyone knows how I get from left to right?

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#

@turbid osprey Has your question been resolved?

leaden thunder
turbid osprey
leaden thunder
turbid osprey
#

oh wait did he just multiplied it?

#

so he made it row echelon form and multiplied it by that [x1, x2] at first step right?

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sleek prawn
#

Hello, I’m practicing some logic questions in preparation for a competition in March. One of these questions is the following:

sleek prawn
#

You can see in the figure the sides of the rhombus divided into four equal parts and, inscribed inside the rhombus, the dark rectangle. What is the ratio (expressed as a decimal number) between the area of ​​the rectangle and that of the rhombus?

low owl
#

well i'd start trying to compute the small side of the rectangle

#

considering the soze of the rhombus is one

#

each equal parti is 1/4

#

using pythagoras

#

that rectangle's small side is 1/sqrt(8)

leaden thunder
#

Does the answer not depend on the angle?

#

If not, just treat it like a square

low owl
#

hm

sleek prawn
#

I’m trying to set up an equation starting from the triangles next to the rectangls

low owl
#

you'r correct

sleek prawn
#

The answer must be a numerical value

#

I’ll do what I can think of and let y’all know

low owl
#

we now for sure that the triangle is isoscele

sleek prawn
#

Yeah

low owl
#

oh wait

#

imagine

#

deleting that rectangle

#

from the total area

#

is it possible to compute the new area ?

sleek prawn
#

Calling x every fourth part of the side of the rhombus, and α the vertex angle of the small triangle next to the rectangle, the total area of the rhombus is as follows:

#

indeed, I precisely calculated the total WHITE area

#

I think I got the result!

#

I checked and it’s correct, thank you guys!

#

The other question I need help with is this:

Number 2020 admits 12 divisors. If you write them in ascending order, the seventh is a prime number. What other year of the twenty-first century will in the future admit twelve divisors with the same property (if they are ordered in ascending order, the seventh is a prime number)? Can you name at least two?

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#

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#
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oblique ferry
#

ChatGPT seems to have called out an issue with this equation's units not actually equal to m^3/s. I am confused because it seems to actually be right. There is a left over 1/2 of this portion of the equation, so that means it has to be higher than m^3?

oblique ferry
teal coral
#

nah the units do seem to be

#

chatgpt says that sqrt(9.8m/s^2) has units of m/s, but it has units of sqrt(m)/s

oblique ferry
teal coral
#

sqrt(m/s^2) is just the rules for fractions

teal coral
oblique ferry
#

This makes sense now thank you guys for your help I guess chatGPT can’t help with everything

#

.close

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sick blade
calm coralBOT
sick blade
#

could someone please look through my solution to verifty it? no answers were posted for this set ):

#

nvm can just use chatgpt!

#

.close

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old falcon
#

can you define dividend?

#

what piece of the problem are we looking for

#

thats where id start

#

,w dividend

potent lotusBOT
old falcon
#

so i wonder

#

if $\frac{\text{dividend}}{\text{divisor}} = \text{quotient}$

potent lotusBOT
#

jan Niku

old falcon
#

and we're given quotient and divisor

#

what can we do

#

the remainder contains the divisor

#

think of how you write them

#

are you sure it was simplified?

#

its not simplified

#

try it yourself

#

youll get your answer

#

no

#

think about what the quotient and the divisor are here

#

we know the structure of the remainder gives us the divisor

#

which part is the quotient

#

and the remainder

#

okay

#

now if dividend/divisor = quotient

#

give me a formula for dividend

#

yup

#

so we know quotient, its that whole thing plus remainder

#

and divisor is x-3

#

its $(x-3)\qty( 2x^2 + 7x + 21 + \frac{67}{x-3})$

potent lotusBOT
#

jan Niku

old falcon
#

does that help?

#

well $A(C+D) = AC + AD$

potent lotusBOT
#

jan Niku

old falcon
#

this is the distributive property

#

so we can do some distributinvg

old falcon
#

haha

#

well it just cancels the fraction right

#

$(x-3)\frac{67}{x-3} = 67$

potent lotusBOT
#

jan Niku

old falcon
#

is this what youre asking

#

yup

#

so we have 3 pieces

potent lotusBOT
#

jan Niku

#

jan Niku

#

jan Niku

old falcon
#

youre asking how we have a +4

#

since we know we have a +67 floating around from the remainder

#

that means were hunting for a -63

#

can you see where we might pick this up?

#

where do we have just a number times just a number, with no x's

#

yup

#

so getting +4 makes sense

#

np

calm coralBOT
#
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winged forge
#

Hello, so I'm in 9th grade and I was just revewing my teacher's correction of a test that didn't count until I saw that she multiplied the numerator and denominator by four on the red circled part.

I'd like to know why she mutiplied it by four.

winged forge
#

I'm pretty sure she explained why during class but I forgot what she said 💀

prisma mango
winged forge
winged forge
prisma mango
#

Yes

winged forge
#

Alright thank you very much

#

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hearty silo
#

How do i do solve b?

calm coralBOT
hearty silo
#

do i do 2pi = tpi/6?

#

How do i do this?

#

@warped rampart

muted marlin
#

its where the function starts repeating

hearty silo
#

so from here to here?

warped rampart
#

note that you cannot include the point where it has repeated

hearty silo
#

i feel like it should be [0,12)

#

yeah right?

warped rampart
#

yeah

hearty silo
#

but why is it including it

#

in the question [0, r]

warped rampart
#

no idea, seems weird

hearty silo
#

in that case wouldnt it be 6

#

when we reach the first bottom tide

#

cuz we only want one y value associated to one x

#

so if we go back up to the 2nd high tide we use the same y-values

#

where these lines are

#

@warped rampart

muted marlin
#

yeah

#

we want the domain to be such that d(x) is 1-1

warped rampart
hearty silo
#

all good

#

last question how do you do this

#

.close

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#
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junior stag
#

so i have a quadratic formula worksheet here and i know how to do it most but i have to break down the 60, i broke it down into 10 and 6, then 3 and 2 (for the 6) then 5 and 2 for the 10, but i forgot how what to do next

junior stag
exotic bone
#

you are trying to simplify the square root right?

exotic bone
junior stag
exotic bone
#

yeah, in the radical

#

check that again

junior stag
exotic bone
#

square root*

junior stag
#

6 squared it’s 36

exotic bone
#

yep

junior stag
#

this is the formula

exotic bone
#

yah, you did the formula right, but the math is wrong

junior stag
#

a is 1, b is 6, c is -7

exotic bone
#

you have this equation right? $\frac{-6\pm\sqrt{36-4\left(1\right)\left(-7\right)}}{2}$

potent lotusBOT
#

Judgemental Snail

junior stag
#

yeah

exotic bone
#

we can first multiply 1 and -7

#

getting this

#

$\frac{-6\pm\sqrt{36-4\left(-7\right)}}{2}$

potent lotusBOT
#

Judgemental Snail

junior stag
#

oh i didn’t know that

exotic bone
#

ah ok, redo it then i can check your answer

junior stag
#

thanks

exotic bone
#

np 🙂

junior stag
#

@exotic bone so i broke 64 down

exotic bone
#

you dont need to do that

#

64 is a perfect square

#

meaning you can evaluate the square root and get a whole number

junior stag
#

ohhh i see

exotic bone
#

what number would you get if you do so?

junior stag
#

1 right?

exotic bone
#

no

junior stag
#

or 8

exotic bone
#

^

#

8

#

because 8^2=64

junior stag
#

yeah but don’t you simplify that to 8/8 and then 1/1?

exotic bone
#

taking a square root is asking yourself, what number, times itself results in the number in the root

#

so in this case, what number, times itself results in 64

junior stag
#

8 times itself

exotic bone
#

yep, so the square root of 64 would be 8

#

does that make sense?

junior stag
#

yeah i know square roots but i forgot what to do next

exotic bone
#

well we can replace sqrt(64) with 8 because sqrt(64)=8

#

$\frac{-6\pm\sqrt{64}}{2}\to\frac{-6\pm8}{2}$

potent lotusBOT
#

Judgemental Snail

junior stag
#

this this

exotic bone
#

yep

junior stag
#

and then just one last question

exotic bone
#

whats the question?

junior stag
#

for this do i do -12 on both sides to make the other side equal to 0

exotic bone
junior stag
#

that way i can label A B and C and use it for the quadratic formula

junior stag
exotic bone
#

k

junior stag
#

but for the last one yes

#

thank you

exotic bone
junior stag
#

and to get approximate answers how do i do it on a ti84

#

the teacher taught us on a ti83 how to get what x is approx. but doing the same doesn’t work on my ti84

#

she showed me i have to do it differently but i’m not sure how

exotic bone
#

solve it first using the quadratic formula

#

then plug what you got into the TI84

junior stag
#

i tried that with another one but it said non real answers

exotic bone
#

for which one?

junior stag
#

ohhh it’s because i didn’t do the formula right

#

i see

exotic bone
#

k

calm coralBOT
#

@junior stag Has your question been resolved?

#
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#
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muted marlin
#

$\int_0^1 f(x) x^n dx = 0$ Prove that $f(x) = 0$ on [0,1]

potent lotusBOT
#

please request a new nickname

muted marlin
#

and n is some positive integer

calm coralBOT
#

@muted marlin Has your question been resolved?

calm coralBOT
#

@muted marlin Has your question been resolved?

pallid halo
#

it's easy to find counterexamples if it's only true for one n

muted marlin
#

yeah for all n

pallid halo
#

proof by contradiction seems viable, suppose f(x) > 0 at some point

#

find a polynomial which has no roots in [x-epsilon, x+epsilon]

#

and hence has the same sign throughout [x-epsilon, x+epsilon]

muted marlin
#

but wouldnt you lose generality if you suppose f is some polynomial

#

would it help if i mentioned that we're learning sequences of functions

muted marlin
#

ok so looks like i have to learn a theorem before i can try this problem

#

.close

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#
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fierce cradle
#

Can someone help me with the circled question

fierce cradle
#

Using this formula:

marsh agate
#

Just compute it I think

#

According to my mental math, y is chosen for integral to give a nice perfect square to remove the square root

fierce cradle
#

And then I’d evaluate from there?

marsh agate
#

Yes

fierce cradle
marsh agate
#

Yes

#

How else could you possibly try to rewrite this

fierce cradle
marsh agate
#

You're not telling me you're trying to find the length of a curve through integration yet need to be hand-held to expand a square

fierce cradle
#

Well alrighty.

#

Thanks for your time.

#

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thorn stag
#

I think I have created a "new" type of best fit plot for an asymptotic data set (think something like a box office graph), and I want to know how to improve it. I found an approximate slope at each point by taking the average slope of the two surrounding points, then entered this data into an exponential best fit calculator. Then, I wrote a function that took an integral of this best fit exponential curve, which gave me a best fit line for the data set. What are the flaws with this approach?

thorn stag
#

data set

#

function

#

.close

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fierce mulch
calm coralBOT
fierce mulch
#

Hi I'm trying to compute this integral, I need to do it by substitution to "show it"

#

I attempted first to sub u=x-5, and then from there u=3 sinh t

#

But I don't believe the answer should have logs, as I believe the integral of sech would have, it should come out as arctan I belive, anyway, any help would be amazing! Thanks

leaden thunder
#

the anti-derivative of this is just something with arctan(u)

fierce mulch
#

Ik by recognition it’s 1/3 arctan (u/3) but I have to show it by substitution I believe

leaden thunder
#

then do u = tan(t)

fierce mulch
#

I forgot about the tan^2 + 1 formula

#

Thanks for your help

#

.close

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#
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noble cedar
calm coralBOT
noble cedar
#

do I need brackets on this part that I circled after taking the derivative?

leaden thunder
#

yes

noble cedar
#

ty

leaden thunder
#

but also you're doing this the long way

#

write f(x) as a sum of terms and distribute the derivative to each term and you'll only need to use power rule

teal coral
#

pwer

noble cedar
#

Oh OK

pure kayak
#

you can split the fraction into 3 separate terms

leaden thunder
#

d/dx (4/x) =?

noble cedar
teal coral
#

the quotient rule is very specific about what needs to be done

#

i.e. it requires (vu' - uv')/v^2

#

if taking off the brackets changes the meaning of what you have with the brackets

#

then clearly that's not acceptable