#help-42

1 messages · Page 16 of 1

viscid silo
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the function definition already requires the entire domain to have an image

hallow stirrup
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yes true

viscid silo
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surjectivity just means the preimage of the codomain is a subset of the domain

hallow stirrup
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subset? not the domain itself?

viscid silo
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does not necessarily have to be the domain

hallow stirrup
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but every value in domain has to have an image right

viscid silo
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read the definition of surjectivity carefully

hallow stirrup
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subset also means the domain itself right

carmine sorrel
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it can, yes

hallow stirrup
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oh ok

carmine sorrel
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what you said about surjective is correct. every element of the codomain is the image of an element in the domain.
This pre-image does not have to be the whole domain

hallow stirrup
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i see

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but wont that go against the defined domains

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what i mean is, if the pre-images ≠ domain, that implies that some values in domain do not have an image in co-domain

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which is wrong

carmine sorrel
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Let f:A->B be a map between sets A and B. Let Y subset= B. Then the preimage of Y under f is denoted by f^(-1)(Y), and is the set of all elements of A that map to elements in Y under f. Thus f^(-1)(Y)={a in A|f(a) in Y}. (1) One is not to be mislead by the notation into thinking of the preimage as having to do with an inverse of f. The preim...

hallow stirrup
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i havent gotten to inverse functions yet

carmine sorrel
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it's not the inverse. it's reused notation. it means the pre-image here

sick cloak
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wait this server is for all ages, right?

hallow stirrup
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yes

sick cloak
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k

carmine sorrel
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13+ i believe

carmine sorrel
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open your own channel. and upload an image of the question

carmine sorrel
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it can also be {2,3,4}

hallow stirrup
carmine sorrel
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yeah..... it's dumb

hallow stirrup
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oh i see what you mean

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kind of

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thats a onto function right, all of the co-domain values have a pre image in domain

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still unclear on why the set of pre-images ≠ domain

calm coralBOT
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@hallow stirrup Has your question been resolved?

calm coralBOT
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strange juniper
calm coralBOT
strange juniper
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confused how to solve this?

naive owl
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for a function to be differentiable, what must it also be?

strange juniper
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if a point exists..?

naive owl
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well yes, but it must also be continuous

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implying that at x=0, the top expression and the bottom expression must be equal for it to be differentiable

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and since it asks what makes it not differentiable, they must not be equal

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i.e. breaking continuity breaks differentiability

strange juniper
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oh because kind of like limits? left and right of 0 must be equal

naive owl
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sort of, though there are situations where the limit exists at a point but it is not differentiable at that same point

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take for instance $\lim_{x\to 0}\abs{x}$

potent lotusBOT
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a disappointing son

naive owl
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that limit exists and is equal to 0, but |x| is not differentiable at x=0

strange juniper
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i see

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so do i plug all the values in and see if they equal each other?

naive owl
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sounds like a good idea to me

strange juniper
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o

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okay

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could i set x for the first function to 0? and the second to 1?

naive owl
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well recall that you're trying to see if they're equal at the point x=0

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so you should be plugging x=0 into both expressions

strange juniper
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but the second one x > 0

naive owl
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right, but it gets infinitely close to the point x=0

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therefore implying continuity if it is equal to the expression above it at that point

strange juniper
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so its the right side 0+

naive owl
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that is one way of thinking of it

strange juniper
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okay

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so its d?

naive owl
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hm well i think more than 1 of them work

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which is odd because the question doesn't seem phrased in a way to select multiple answers

strange juniper
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oh

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bc for a and b i said it is both diff bc both =0

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then c i think both = 5?

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then d for me i got -1 is not = to 0

naive owl
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oh that's a pi

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i thought it said x+cx not x+cpi

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in that case yes i agree with you

strange juniper
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okkk

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i also um need help with this

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i graphed c(t) and b(t)?

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but am i supposed to do derivative of them?

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and find max and min

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<@&286206848099549185> :< sorryyy

calm coralBOT
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valid carbon
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Which one is cubic formula equation? I'm so confused

languid dragon
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A cubic equation is an equation that can be represented in the form a x 3 + b x 2 + c x + d = 0 ax^3+bx^2+cx+d=0 ax3+bx2+cx+d=0, where a, b, c, d a,b,c,d a,b,c,d are complex numbers and a is non-zero. By the fundamental theorem of algebra, a cubic equation always has 3 roots, some of which might be equal.

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This is how you would know if it is one or not.

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If you can't figure it out, come back.

steel karma
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Who even uses that hmmCat

languid dragon
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Me hmmCat

valid carbon
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Thank You

valid carbon
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.close

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sudden patio
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f(x) is in blue on the left and g(x) is in red on the right, how would i go about finding the limit at x->1 for g(x)?

leaden heron
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So we both struggling with Calc1000B huh.

sudden patio
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mhm

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yep

calm coralBOT
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@sudden patio Has your question been resolved?

sudden patio
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<@&286206848099549185>

sudden patio
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f(x) is in blue and g(x) is in red, what happens when adding limits where one doesn't exist or one is equal to infinity?

calm coralBOT
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@sudden patio Has your question been resolved?

calm coralBOT
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gusty oak
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what is the equilibrium quantity? apparently my answer is incorrect

gusty oak
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here is what they told me to do, and i did exactly what they asked and still got that incorrect number

velvet osprey
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your answer for the equilibrium quantity is incorrect

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hm. ok wait

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the numbers do check out

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oh but look at the rounding instructions for the quantity @gusty oak

gusty oak
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cant lol

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plus, didnt it say one answer was correct? thus format also good?

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i could get rid of the .5 but i doubt it will work out

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but id have to do to both

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oh sht..

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ur right

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welp didnt work

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took out the .5

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.5 doesnt round up

velvet osprey
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on the contrary, you round up on five

gusty oak
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i spent like an hour this set of problems

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until question e

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can we have someone else confirm

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i have 1 try left

velvet osprey
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so rounding down didn't work...?

gusty oak
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.5 is middle

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i googled it and you dont round up or down

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i took out the .5

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got it incorrect

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mymathlab program is so bad lmao

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do i round up or down?

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.5

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.close

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proper shell
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I need help with this i see youre supposed to factor it but the numbers are so weird and so is the equation compared to everything online

proper shell
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please @ me if someone is willing to help as I have discord alt tabbed and very forgetful

calm coralBOT
#

@proper shell Has your question been resolved?

obtuse pendant
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let f(x) = 2/x - x - sqrt(x) ; the question become to show that f(x) = 0 has a root in the interval (2,3) you can know just do the steps of the IVT to prove that

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@proper shell

proper shell
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To make it so that 0 = to 2x - xsqrt(x) - 2

obtuse pendant
proper shell
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Just multiplying by x on the 2/x side to move it then minusing 2 so that 1 side was 0

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Opposite operations pretty much

obtuse pendant
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if you multiply x on both sides you get 2 = x^2 - x*sqrt(x)

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not 2*x

proper shell
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You'll have to multiply x by the sqrt(x) and 2 no?

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I mean

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X

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Oh wait I think I got it

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Hey thanks man

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.close

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rotund birch
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ln e^2 no calculator

calm coralBOT
rotund birch
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I wasn't in class and our teacher didn't give us enough information

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I have no clue what ln is and my friend said it was just memorization

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I wasn't there so I don't know what to memorize

solemn plover
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do you know what e is?

rotund birch
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I know on a calculator

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I don't know how to use it without a calculator

solemn plover
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hmm

velvet osprey
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ln means natural log

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a.k.a. log with base e

solemn plover
rotund birch
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I know how to do log but for some reason I can't figure this out

velvet osprey
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you in fact do not need to know the value of e in order to calculate ln(e^2)

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have you been introduced to logarithms in general?

rotund birch
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by the few notes she gave us 🤩

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sorry I'm a little frustrated with my teacher right now JKL;GFJ

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I know how to evaluate without a calculator at least

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that makes sense

gleaming scarab
rotund birch
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I don't think so

gleaming scarab
rotund birch
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no I don't

gleaming scarab
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Well, then you clearly lack the tools to solve this problem.

rotund birch
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yeah, she didn't give us very much to work with

rotund birch
velvet osprey
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wow, that's shitty of her.

rotund birch
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she sent us a few videos and there's some stuff in a packet we got but hardly anything about ln and it's hard to understand anyways

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somehow she's the math chair leader or something and she changed from our algebra book to this shitty book that she doesn't even have a teacher edition of

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the answers are only the fully simplified version and there are only answers for the odd problems 🥰

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she's so silly

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ok I give up thank youu

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.close

calm coralBOT
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visual wigeon
calm coralBOT
visual wigeon
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i have tried

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but no one has helped

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for the first one i get 0

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but how do i work out sin theta

gleaming scarab
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Observe that once we substitute sin theta with x we end up with the same expression given in part 1.

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And -0.5 makes that expression zero, which means that it will make our new expression zero as well.

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So for x=-0.5 our expression becomes zero and we know that x=sin(theta).

calm coralBOT
#

@visual wigeon Has your question been resolved?

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crimson shadow
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how do I solve this? lg x = 4

calm coralBOT
mellow crater
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def. of log

crimson shadow
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what does def meann?

potent lotusBOT
crimson shadow
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okay thanks

pulsar knot
crimson shadow
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okay just quick question, what does the A represent then in lg x=4?

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is A the X?

mellow crater
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if base isn't mentioned we usually treat it as 10

crimson shadow
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so A is 10?

mellow crater
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I'd say so

crimson shadow
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okay 👍🏻

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yhea its correct if A is 10, thanks for help.

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potent lotusBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

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karmic ridge
#

omg the channel closed sorry. could i get a hint.

fathom shuttle
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usually with problems like these it would be a good idea to list out at least 10 of the next terms

calm coralBOT
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@karmic ridge Has your question been resolved?

karmic ridge
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like 11117, 11118, 11119,e tc

fathom shuttle
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or actually

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you dont need to

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the sum of the numbers would be the change from the starting number to the ending number

karmic ridge
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wait why

fathom shuttle
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think about it

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if you compute the difference from 5 to 3 to 7, its the same as the difference from 5 to 7

karmic ridge
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ah right

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thanks

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.close

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calm coralBOT
lapis blaze
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shall i ping a fellow of ours

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Dio "Toby" Brando?

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he is well versed in Newtonian Things

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sir, do you want assistance from the best there is, in the name of Toby?

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Sir

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please answer

hollow totem
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depends on the concavity of the graph

lapis blaze
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@remote mural

hollow totem
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if it's linear (no concavity), you'll get the exact root after one iteration

lapis blaze
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his name is L

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do not disrespect him.

hollow totem
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if it's concave in the same direction that it's moving, you'll undershoot

pearl vigil
hollow totem
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if it's concave in the opposite direction, you'll overshoot

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but as long as you started close, you'll overshoot but still be a lot closer

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the way i know this is not that i had it memorized but just that i'm imagining the graphs in my head

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and looking at the example you gave

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feel free to draw out the others

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it's possible for it to

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touch the actual root at some step

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even in a not linear case

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just "infinitely unlikely" in the general case

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Computers stop applying newtons method after the last 2 iterations are within a certain tiny amount of each other

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In this case the tiny amount would be 0

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So it gets the same root twice and then stops

lapis blaze
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Newtit?

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How truly disrespectful.

lapis blaze
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Fine. I'll look past this.

hollow totem
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it's my pleasure

lapis blaze
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Your next line will be:

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How do you close?

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Ha!

hollow totem
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.close

calm coralBOT
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lapis blaze
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".close"

hollow totem
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like that

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🙇‍♂️

lapis blaze
#

its sir Moni

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stop disrespecting him

hollow totem
calm coralBOT
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cobalt scaffold
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Can anyone explain why 0 isn't a vertical asymptote

cobalt scaffold
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so if the numerator wasnt that identity

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then 0 would be a va?

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say the numerator was 1

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ahhhhh gotcha

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yeah they're throwing some curve balls lol. thanks for the help!

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spring garnet
#

Can someone help me with geometry homework? It covers perpendicular and angle bisectors. Here is the question that I am currently trying to work on.

spring garnet
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@rustic osprey

crystal forge
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think triangles, it's given in the problem based on the definition of perpendicular bisector that you have some congruent segments and angles

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if you prove that the two triangles are congruent it follows that their corresponding sides are congruent which is what you want to prove

spring garnet
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oh wait yeah

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so they are congruent due to SAS

crystal forge
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exactly

spring garnet
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do you mind helping with some other questions?

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@crystal forge

crystal forge
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sure, just post them here

spring garnet
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I'm not sure how to start with this one.

crystal forge
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equidistant just means same distance

spring garnet
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yeah

crystal forge
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honestly it's kinda fuzzy, i can't tell where the 2nd entrance even is, i only see one on the right side

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or i guess those two arrows are two different entrances? i was interpreting at some sort of large door

spring garnet
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ther are two different entrances\

crystal forge
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well, if you're at A are you closer to one of the entrances than the other?

spring garnet
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is it just as simple as i think it is

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B?

crystal forge
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yeah lol

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common sense goes a long way in math too : )

spring garnet
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lol

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well i have a different question then i guess

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im confused on what the theorem means

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like i dont understand what the 'sides of the angle' are

crystal forge
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that's uh, sloppy problem writing to say the least

spring garnet
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an angle bisector of an angle of a triangle divides the opposite side into two parts that are proportional to the other two sides of the triangle.

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still dont understand lol

crystal forge
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but what they mean is youve got this angle A opening up and kind of the "sides" of it : )

spring garnet
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would it be these two sides equal

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wait idk

crystal forge
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so they're talking about the angle A, like imagine you just had the red figure and the angle A

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and then you are drawing AD, bisecting that angle into two congruent angles (equal measures)

spring garnet
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yeah

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so angle BAD and angle DAC are congruent

crystal forge
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yep

spring garnet
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so would it just be aas

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cause of the shared side

crystal forge
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yes you can use that indeed

spring garnet
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and then the two angles

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so im not sure why we needed the theorem

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like i didnt use it

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or did i

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idk

crystal forge
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which theorem?

spring garnet
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angle bisector theorem

crystal forge
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well read the problem again, they're essentially asking you to prove the theorem

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not use it

spring garnet
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so how would i do that

crystal forge
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you just did lol

spring garnet
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oh alright

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ill send a picture of the completed proof and lmk

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also

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would angle b and c be congruent

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just cause it shows it

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it doesnt say it but it shows it

crystal forge
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basically proving that BD = DC is equivalent to proving the theorem because thats what the theorem says is that the point D is the same distance from the two sides

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so when you are talking about distance from a point to a line

spring garnet
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what

crystal forge
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or line segment

spring garnet
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okay

crystal forge
spring garnet
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so what do i do about angle b and c

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whats the reason for them being congruent?

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given?

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even though it doesnt say

crystal forge
#

im trying to explain

#

...

spring garnet
#

okay

crystal forge
#

when you are talking about distance from a point to that segment

#

its basically the path you take from the point thats at a right angle to the segment

#

intuitively, that's the shortest path right?

spring garnet
#

yeah

crystal forge
#

like imagine you are in a field next to a road, and you want to take shortest walk to the road

#

youre going to end up walking into the road perpendicular to it right?

spring garnet
#

yeah

crystal forge
#

so since the whole thing you are trying to prove is that the DISTANCE from that point D to the two sides is equal

#

thats why BD and CD are drawn in such a way that they make a right angle to their two respective sides (see in the original figure?)

#

so yes of course those angles in the triangles are congruent as well since they are both right angles

spring garnet
#

so okay

crystal forge
#

so they couldve given you just this figure to begin with and told you ok we have an angle, an angle bisector and some point on that bisector

spring garnet
crystal forge
#

and asked you, prove that the distance between that point and the left red segment and red right segment is equal

#

but they were nice and already drew those segments at right angles for you...

#

but it would have been enough to just show you my figure because you wouldve thought to yourself "oh we are looking at the distance between this point and this segment, ill draw a new segment from the point to the red segment at a right angle"

spring garnet
#

is my proof right?

crystal forge
#

looks good

spring garnet
#

ALRIGHT

crystal forge
#

what does cpctc stand for anyway?

spring garnet
#

oops

#

caps lock

crystal forge
#

corresponding parts of congruent triangles are congruent?

spring garnet
#

yeah

#

its dumb

#

but my teacher adds the extra c

#

I have to go for an hour, but can you help me when I get back?

crystal forge
#

probably wont be around but just make a channel and someone will help you im sure

spring garnet
#

maybe\

#

probably not

#

nobody likes geometry here

calm coralBOT
#

@spring garnet Has your question been resolved?

calm coralBOT
#
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#
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gray knoll
calm coralBOT
gray knoll
#

need some help

muted marlin
#

!help

calm coralBOT
muted marlin
#

how far have you gotten?

#

or where do you have problems?

gray knoll
#

i got what x is

muted marlin
#

how did you do that?

gray knoll
#

5x=7x+1.5y

#

and then i went from there

muted marlin
#

nice

#

and how did you solve for y?

#

or is that the issue?

gray knoll
#

yeah thats the issue

muted marlin
#

ok when you say you solved for x do you mean you solved in terms of y or did you somehow get a number

#

what did you get for x

gray knoll
#

0.75y

muted marlin
#

nice

#

what are the angles of an equilateral?

gray knoll
#

60 each

muted marlin
#

nice

#

do you see how to continue?

gray knoll
#

not rlly

muted marlin
#

ok so the final equation comes from the angle

#

you know that the angle is just 60 degrees

#

you can plug in x and solve for y with the last equation

remote mural
#

It becomes a system of equations with two equations and two variables

gray knoll
#

ah alright

muted marlin
#

can you finish from here?

gray knoll
#

.close

calm coralBOT
#
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calm coralBOT
#
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icy otter
calm coralBOT
icy otter
#

How do you do number 93, 95 and 103

#

I’m so stumped with trig🥹

wanton wave
#

Do you know the pythagorean identities?

icy otter
#

kind of

#

idk how to use them tho

wanton wave
#

for 93, you're given sin(theta) and asked for cos(theta)

#

So do you see which one of those identities we want to use

icy otter
#

maybe sin + cos = 1

wanton wave
#

yeah

#

with the exponents though

icy otter
#

yay

#

oh yeah my key is broken lol

wanton wave
#

so plug in the value you have for sin(theta), and what do you get

icy otter
#

okkk!!

#

for the square do you multipy the whole fraction by itself or just the top and bottom to get 9/25

#

(3/5)2 + cos2 = 1

wanton wave
#

either way should be the same. 9/25 is good

icy otter
#

yay

#

whats next

wanton wave
#

You want cos(theta)

#

And you can solve that equation for cos(theta)

icy otter
#

ok ill tryy

#

i get cos2) = 16/25

wanton wave
#

awesome

#

which means cos(theta) = ?

icy otter
#

is 16/25

wanton wave
#

no, that's cos^2

icy otter
#

oh

#

square root

#

4/5

wanton wave
#

Right, but be careful

icy otter
#

YESSSSSSSSSSSSSSSSSSSS

wanton wave
#

It could be 4/5 or -4/5

icy otter
#

wait why

wanton wave
#

(4/5)^2 = 16/25. And (-4/5)^2 = 16/25

#

Whenever you apply a square root to both sides of an equation, you get a positive and negative solution

icy otter
#

ohhhhhhhhhhhhhh

wanton wave
#

But

#

You can figure out which one is right

#

since they told you which quadrant theta is in

icy otter
#

how

wanton wave
#

It says theta is in quadrant 2

#

Do you know what that means? like on the graph

icy otter
#

Yes itmeans they're in the 2nd box thing on graph

remote mural
#

Quadrant

icy otter
#

yess

remote mural
#

Different of the functions are in different quadrant

wanton wave
#

And is the cos positive or negative in that quadrant?

remote mural
#

Quadrant 3

#

If cos is negative

#

I believe 4 if posos to e

#

Positive

icy otter
#

hmmmmmmm

wanton wave
# icy otter hmmmmmmm

remember the cos represents the x value of the angle. In quadrant 2, that is negative

icy otter
#

SO ITS -4/5

#

i see

wanton wave
#

Yep you got it 👍

calm coralBOT
#

@icy otter Has your question been resolved?

icy otter
#

THANK YOU SO MUCH

calm coralBOT
#
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calm coralBOT
#
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tulip sail
#

I need to verify are these are the answers for the principle solution for the sin theta = -1/2

tulip sail
naive owl
#

your answers in degrees are correct but you converted to radians incorrectly

#

though you showed the correct formula for converting

tulip sail
#

Ohh thank you. I didn't notice that. It should be 11π/6.

#

But I am confused with some of my notes and some online reference where it says principle solution for this as -pi/6.

naive owl
#

iirc the principal solution is any solution between 0 and 2pi

tulip sail
naive owl
#

so i'm not sure

tulip sail
#

Can you verify the above pic if can

calm coralBOT
#

@tulip sail Has your question been resolved?

calm coralBOT
#

@tulip sail Has your question been resolved?

pearl skiff
#

hello, the range of principle solution may differ in different situation.
I think the principal solution required in your context would be
(-pi/2,pi/2] for sine
[0,pi) for cosine
(-pi/2,pi/2] for tangent

pearl skiff
tulip sail
#

So is that the reason that solution is differ in the the printed image that I have sent.

#

I am stuck in here. There is no any context define in this note.

calm coralBOT
#

@tulip sail Has your question been resolved?

calm coralBOT
#
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crisp glen
calm coralBOT
crisp glen
#

how do i figure this

velvet osprey
#

carefully expand (α+β+γ)^4

#

use the known values of α^2+β^2+γ^2 and α^3+β^3+γ^3, as well as vieta's formulas, to your advantage

remote mural
#

use pascal's triangle

#

~~also hope you get better soon @velvet osprey ~~

crisp glen
remote mural
velvet osprey
#

something something multinomial coefficients

remote mural
#

just assume β+γ = u and expand (α+u)^4 normally

#

just make sure to also double expand on the u too after u undo the sub

crisp glen
#

quite the time it may take

remote mural
#

yeah

#

,w expand (a+b+c)^4

remote mural
#

might take a bit

crisp glen
#

is there a simplier way

#

how am i meant to do that in test conditions

calm coralBOT
#

@crisp glen Has your question been resolved?

calm coralBOT
#
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calm coralBOT
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desert bobcat
#

How exactly can I find an undetermined rate in regard to exponential growth and decay?

desert bobcat
#

.close

calm coralBOT
#
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calm coralBOT
upper sparrow
#

Assume that p(x) = ax^2 + bx + c, and assume that T(p) is mapped to the zero vector

#

Have you shown that at least? If so then you've answered your original question by showing the kernel just consists of the zero polynomial

upper sparrow
oblique current
#

well you shouldn't still have x's in those equations

calm coralBOT
#

@surreal tulip Has your question been resolved?

#
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blissful ermine
calm coralBOT
granite trout
blissful ermine
granite trout
#

Also, I assume you have studied parallelograms?

blissful ermine
#

yeah ?

granite trout
#

Great

#

What are the angles given to you?

blissful ermine
#

measues

#

measures

granite trout
#

Yes, I meant what are the values specifically?

blissful ermine
#

there is a right angle

granite trout
#

Correct

#

And?

blissful ermine
#

multiple accutes ?

granite trout
#

Only one of them is known

#

60 degrees

#

Can you use that to find any other angle?

blissful ermine
#

not so sure

#

yes though

#

most likley

granite trout
#

Yeah so go ahead, which one?

blissful ermine
#

I mean thw left bottom angle looks the same

granite trout
#

True

#

So it will be 60 degrees???

blissful ermine
#

yes

granite trout
#

Correct

blissful ermine
#

we have 45, 60, 60 degree angles so far

granite trout
#

Where did you get the 45 from?

blissful ermine
#

the right angle

granite trout
#

Can you send an image of your working?

blissful ermine
#

im doing this in my head

granite trout
blissful ermine
#

oh my bad

granite trout
#

Right

#

Now

#

You have the right angle

#

Correct?

blissful ermine
#

yeah

granite trout
#

There is a straight line going up if you can see

#

Can you use that in any way?

#

Extend it to make a familiar shape?

blissful ermine
#

if you extend it

#

it will eventaly form a triangle

granite trout
#

Exactly

#

Correct

#

Now

#

What kind of triangle???

#

I mean equilateral or isosceles or scalene or right angled?

blissful ermine
#

id have to say obtuse

granite trout
#

Something like that?

granite trout
blissful ermine
#

wait no it might be scalene

#

I dont have a camera

granite trout
#

Ah okay

#

Alright

blissful ermine
#

im on a 70$ monitor

granite trout
#

Will the line, when you extend it, be perpendicular to the base of the parallelogram?

blissful ermine
#

yes

granite trout
#

Means one angle will be?

blissful ermine
#

scalein

granite trout
#

Well, those definitions are wrt sides

#

One angle will be 90 degrees, right?

#

You are correct on scalene btw

blissful ermine
#

yes

granite trout
#

We need angles though

granite trout
#

Now, how many angles of the triangle do you know?

blissful ermine
#

scalen obtuse, acute, right

granite trout
#

And I would suggest drawing now for the part after this one, grab any piece of paper near you

granite trout
blissful ermine
#

yeah, the right one

granite trout
#

Correct

#

The third angle

#

Will it be in terms of x?

blissful ermine
#

I have no idea

granite trout
#

What should it be? Can you use 2x and 3x to find the third angle?

blissful ermine
#

yeah

granite trout
#

You extended the straight line to make a right angled triangle

#

Now I STRONGLY suggest you draw

blissful ermine
#

yes

granite trout
#

Can you see any connection between 2x and 3x?

blissful ermine
#

yeah

granite trout
#

Know what vertically opposite angles are?

blissful ermine
#

ive heard of it

granite trout
#

Okay, I will try to explain it here in brief

#

Draw 2 intersecting lines wherever you are writing

#

And then see that 4 angles are formed

#

And each angle is equal to the one opposite to it

#

So 2 pairs of equal angles are formed

#

That is a vertically opposite angle

blissful ermine
#

i understand now

granite trout
#

Yes

blissful ermine
#

the line caused both of the angles

granite trout
#

Correct

#

Now, if you have drawn everything so far

blissful ermine
#

so then 2x and 3x would have to qual the same

granite trout
#

No, actually

blissful ermine
#

oh

granite trout
#

If you have drawn it all

#

You will see that via vertically opposite angles

#

You can write it as 2x + x

#

And the angle x lies inside the triangle

#

That means, the angles of the triangle are 90 degrees, 60 degrees, and x

#

I think you know how to find x?

blissful ermine
#

subtract ?

granite trout
#

Do you know what the angles of a triangle sum to?

blissful ermine
#

150

granite trout
#

The sum of all angles of a triangle is 180 degrees

#

That means 90 + 60 + x = 180

#

You can solve this equation I guess

#

You will find x

blissful ermine
#

yay

granite trout
#

And I suggest doing the problem once again all on your own

blissful ermine
#

thank you for your help

granite trout
#

Geometry gets easier when you draw it

blissful ermine
#

I did not understand how to break it down

granite trout
blissful ermine
#

yeah

granite trout
blissful ermine
#

yes

granite trout
#

Good

remote mural
#

I’m also doing something similar but it deals with trigonometry. Can I ask the question?

granite trout
#

Now, just try to remember all you know about parallelograms and triangles

#

And analyze it

blissful ermine
#

alright. Thanks for the help

granite trout
#

Or in short, ask in a help channel that is not occupied @remote mural

granite trout
blissful ermine
#

alright, ill try to get better

#

.close

calm coralBOT
#
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granite trout
#

Good luck and happy studying ✍️

blissful ermine
calm coralBOT
#
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rugged stirrup
#

2x - 3y - 10 = 0;
X^2 + xy + y^2 + 2x + y - 6 = 0

Please I need workings for these simultaneous equations

quick glade
#

Express x in terms of y

rugged stirrup
#

i know, but im finding it difficult to arrive at the answer...

#

let me show you my workings

#

Somethibg must have been wrong somewhere but I can't figure it out

quick glade
#

I think you should multiply it by 9 to get rid of the factor, not by 3

rugged stirrup
#

Oh I see

calm coralBOT
#

@rugged stirrup Has your question been resolved?

rugged stirrup
#

the answers are x = 2 or 172/19 and y = -2 or 58/19

#

But the answer I got is different

vast stirrup
#

lemme read what happened here

rugged stirrup
#

Please read

vast stirrup
#

Ok imma try to work it myself and see

rugged stirrup
#

Thank you!!

vast stirrup
vast stirrup
rugged stirrup
#

lmao I actually used it for Whatsapp, now it says im playing a game😂

vast stirrup
rugged stirrup
vast stirrup
#

Alright

#

so what u do is

#

Multiply by 3

#

everything

#

Ok idk how to use the bot

#

U get this

#

Expand and u get this

#

then just use the quadratic formula

#

and u get the x vlaues

#

values

rugged stirrup
#

Yea i got it to this place after @quick glade made a correction. Both our answers are the same but it doesn't tally with the one in the textbook. It wasn't worked tho', just the answer. Is it possible the textbook answer is wrong??

#

@vast stirrup

vast stirrup
#

Whats the answer in the text book

rugged stirrup
vast stirrup
#

I mean it could be wrong

#

I don't think we're wrong so

rugged stirrup
#

Hmmm, that's actually a problem if it's wrong, I gotta change textbook

#

@vast stirrup But is there a way to proof our answers

#

Cause its like plugging those answers in the equation doesn't do much in proving anything?

#

Both might actually results to 0 which is weird to me, but its maths yk

vast stirrup
rugged stirrup
#

Aiit, thanks for the help, really 'preciate

vast stirrup
rugged stirrup
#

lol

#

Discord be doing too much

#

.close

calm coralBOT
#
Channel closed

Closed by @rugged stirrup

Use .reopen if this was a mistake.

vast stirrup
#

Yeah

calm coralBOT
#
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fervent matrix
#

Hello i have a probability question

calm coralBOT
fervent matrix
#

4 players play with a 32 card deck. We draw out 3 cards for each player. What’s the probability that each player gets an ace

#

Is it this or am i tripping ?

remote mural
#

take out the aces

#

distribute 2 cards to everryone

#

give the aces to the players

hollow furnace
#

Why do you have y in the expression????

remote mural
#

thats a 9 or a 4

fervent matrix
#

Woops no y haha

fervent matrix
remote mural
#

and after you do al that thats the number of possibilites that each player gets an ace

fervent matrix
#

Wait what ?

remote mural
#

and the total possibilites are just distributing everyone 3 cards

fervent matrix
remote mural
#

huh?

fervent matrix
#

The cards are distributed at random

remote mural
#

yes

#

"total" is the number of every such random distribution

fervent matrix
#

Can you go through your reasoning again ?

#

I’m not sure i understand

fervent matrix
remote mural
#

yeah u can

#

because you are counting the number of ways the players get the aces

fervent matrix
#

That defies the problem they’re asking ?

remote mural
#

like when u roll 2 dies

#

whats the probability the sum is 2?

#

the total possibility is 6*6

fervent matrix
remote mural
#

and the number of ways it give 2 is just forcibly rolling two 1's

remote mural
fervent matrix
#

Sure

#

But why does that apply here ?

remote mural
#

so your counting the number of ways each player gets an ace is the same as the counting if you give them the aces

#

so i give them the aces and count

#

also you have to account for have many ways you can give the acse

fervent matrix
remote mural
#

anyways the answer is $$(hello)$$
(number of ways to distribute the aceless card set to each player 2 cards) * (number of ways to give the players the aces) / (number of ways to distribute each player 3 cards)

potent lotusBOT
#

Jester

fervent matrix
#

I think i agree

#

How do you calculate the fist part of the product tho ? ( left side )

#

28C2 * 26C2 * 24C2 ?

#

@remote mural

remote mural
#

yeah sure

remote mural
#

but they maybe the same

fervent matrix
#

Where did you get that from haha ?

remote mural
#

just choose 6 cards to distribute

#

line them up

#

but every 2 card is counted 2! times in 1 hand

#

yeah i checked its the same

#

same with the total numebr

fervent matrix
#

Nice

#

Oh wait there are 4 players tho

#

So 28C2 * 26C2 * 24C2 * 22C2

#

How do you count the aces tho ?

#

4! ?

#

Yeah has to be

#

Right ? @remote mural

#

.close

calm coralBOT
#
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calm coralBOT
#
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fiery tide
calm coralBOT
fiery tide
#

i got the answer but i typed it into my calc manually

#

and it took forever

#

is there a quick way of doing this?

leaden thunder
#

Use demoivre's formula

fiery tide
#

or do i have to use calculator

fierce mulch
#

Complex numbers

fiery tide
#

.close

calm coralBOT
#
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remote mural
#

(\sqrt(306))/(x)=(15)/(20)

calm coralBOT
remote mural
#

How would I simplify this equation

#

that looks weird

#

let me fix that

#

square root of 306/x = 15/20

#

[{\f{\s{306}}{x}} = \f{15}{20}] is this it

#

√ 306/x = 3/4

#

No the square root is only over the 306

potent lotusBOT
remote mural
#

yeah

#

that's it

#

multiply both sides by x first

#

so square root of 306 = 15x/20

#

√ 306 = 15x/20

#

which is simplified to √ 306 = 3x/4

#

Oh so looking at the answer key that's how I was supposed to do it

#

which would be 4√306 / 3 = x

#

Gotcha

#

I asked mathway to see what it got it and it gave me some weird bs

#

alright

#

.close

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cunning ravine
#

does anyone know what the difference between a "y on x" line of best fit and a "x on y" one?

hasty fiber
#

The role of dependent and independent variable is switched

cunning ravine
#

but the line of best fit changes? I don't understand that part

hasty fiber
#

The equation does, yes

cunning ravine
#

in this question they already pre-defined the x and y

#

how?

#

we aren't changing the variables on the axis right?

hasty fiber
#

Because one is x plotted against y, the other is y plotted against x

#

Yes we are, that's exactly what we're doing

cunning ravine
#

oh ok

#

but

#

aren't line of best fits always expressed in terms of x and y

#

oh so you just write the equation one in
y = mx+c
the other in
x = my+c
form?

hasty fiber
#

It matches the usual references to x and y, but they're just letters

cunning ravine
#

wait what do you mean

#

say for y=2x

#

that would be "y on x" right

#

since you are measuring rise over run

hasty fiber
#

I'll admit I've never seen "y on x" verbatim so I don't know which direction that is

#

Ideally it'd be defined earlier

cunning ravine
#

yeah I'm also super confused, can't seem to find anything online either

hasty fiber
#

If you do both then it shouldn't matter

#

But I would get it cleared up

cunning ravine
#

alright, thanks a lot!

calm coralBOT
#
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gilded drum
calm coralBOT
gilded drum
#

please can someone guide me through this question

#

do i do the (area x d) x centre of mass of each shape then add it up and divide by the total (area x d) to get the centre of mass for the wholle thing ?

#

<@&286206848099549185>

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#

@gilded drum Has your question been resolved?

gilded drum
#

<@&286206848099549185>

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#

@gilded drum Has your question been resolved?

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#

@gilded drum Has your question been resolved?

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#

@gilded drum Has your question been resolved?

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thorny whale
#

did i do this correctly?

calm coralBOT
vagrant oak
calm coralBOT
#

@thorny whale Has your question been resolved?

thorny whale
#

thanks for the help

#

.close

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tender current
#

,w 10 * 8 * 13 * 13

calm coralBOT
potent lotusBOT
tender current
#

What am I doing wrong here?

#

I assumed this was a fundamental counting principle problem, but the book says the answer is 6240

low pumice
#

look closely at the two desserts

#

there will be times where the same meal happens twice

velvet osprey
#

are you sure that (a) choosing the same dessert is allowed, and (b) the order in which you choose desserts matters

tender current
edgy raven
#

^
right now you say that {dessert1, dessert2} is different from {dessert2, dessert1}

#

though in reality you may choose which dessert gets served first and which gets served second, here I think you have to count out the order

tender current
#

I'm sorry I don't understand what you mean by count out the order?

edgy raven
#

pretend that there is no order

calm coralBOT
#

@tender current Has your question been resolved?

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calm coralBOT
#
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fierce cradle
#

Would I. E able to graph each scenario?

fierce cradle
#

With the information given?

edgy raven
#

yes, they expect a general graph with both curves

fierce cradle
# edgy raven yes, they expect a general graph with both curves

I’d like to know whether I’m understanding the price right. For the 1st one, I know there would be a shift in the demand curve and it would be to the right because greater demand always shifts the curve rightwards…but my supply curve would shift leftwards and would be lower then my demand curve?

#

Anyone?

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#

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remote mural
#

$8b^4+24b^3-2b^2-6b$

calm coralBOT
potent lotusBOT
#

AllUtility

remote mural
#

should i group or just factor out 2

sterile seal
#

Factor out 2b first

remote mural
#

$4b^3+12b^2-b-3$

potent lotusBOT
#

AllUtility

sterile seal
#

Yea now the factoring is pretty clear

remote mural
sterile seal
#

What

velvet osprey
#

it doesnt just vanish into thin air

remote mural
#

idc

#

its gone

sterile seal
#

forgor 💀

velvet osprey
remote mural
#

$2b(4b^2-b)(b+3)$

potent lotusBOT
#

AllUtility

remote mural
#

is dis rite

velvet osprey
#

looks suspicious.

remote mural
#

$2b(2b-1)(2b+1)(b+3)$

amber basin
potent lotusBOT
#

AllUtility

amber basin
#

great

remote mural
#

.close

calm coralBOT
#
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#
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shell granite
#

Hello, I am back after not recieving feedback. I think my handwriting wass probably too difficult.

shell granite
#

This is the original question - and here are my notes

#

I am getting the incorrect answer, and I am hoping to find out what I am doing wrong.

#

@heady karma

#

.close

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remote mural
calm coralBOT
visual nimbus
#

B commutes with any 2x2 matrix A if AB - BA = 0

remote mural
#

The solution says: a = d, b = c = 0

visual nimbus
#

then great

remote mural
#

I'm not following

leaden thunder
remote mural
#

Am I on the right track here?

glass heart
#

and now choose specific values of w,x,y,z

remote mural
glass heart
#

preferably easy values

#

lots of zeros and ones

calm coralBOT
#

@remote mural Has your question been resolved?

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#
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paper bolt
#

I have expression a_1 + a_2 + a_3 + a_4 ... a_n, where each element is of form a_x = 1/(2k)! if k is odd, and -1/(2k!) if k is even

paper bolt
#

I would like to somehow simplify this expression since it can't be easily evaluated by computers

#

1/4! is already too little

#

Not to mention greater factorials

oblique current
#

$\sum_{k=1}^n (-1)^{k+1}\frac{1}{(2k)!}$

potent lotusBOT
paper bolt
#

Not really that

#

It's not from k to n

#

That k is just any natural number

#

They can repeat etc etc

#

For example

#

1/8! + 1/2! * 1/6!

#

etc etc