#help-42
1 messages · Page 16 of 1
yes true
surjectivity just means the preimage of the codomain is a subset of the domain
subset? not the domain itself?
does not necessarily have to be the domain
but every value in domain has to have an image right
read the definition of surjectivity carefully
subset also means the domain itself right
it can, yes
oh ok
what you said about surjective is correct. every element of the codomain is the image of an element in the domain.
This pre-image does not have to be the whole domain
i see
but wont that go against the defined domains
what i mean is, if the pre-images ≠ domain, that implies that some values in domain do not have an image in co-domain
which is wrong
Let f:A->B be a map between sets A and B. Let Y subset= B. Then the preimage of Y under f is denoted by f^(-1)(Y), and is the set of all elements of A that map to elements in Y under f. Thus f^(-1)(Y)={a in A|f(a) in Y}. (1) One is not to be mislead by the notation into thinking of the preimage as having to do with an inverse of f. The preim...
i havent gotten to inverse functions yet
it's not the inverse. it's reused notation. it means the pre-image here
wait this server is for all ages, right?
yes
k
13+ i believe
read #❓how-to-get-help
open your own channel. and upload an image of the question
oh ok
Basically,
If I have {1,2,3,4} -> {1,2,3} with f(x) = x for x=1,2,3 and f(4) = 1
Then the preimage of {1,2,3} can be {1,2,3}
it can also be {2,3,4}
i find the notations very confusing
yeah..... it's dumb
my brain has just stopped working ill break it down for my own sanity:
f(1) = 1
f(2) = 2
f(3) =3
f(4) = 1
oh i see what you mean
kind of
thats a onto function right, all of the co-domain values have a pre image in domain
still unclear on why the set of pre-images ≠ domain
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confused how to solve this?
for a function to be differentiable, what must it also be?
if a point exists..?
well yes, but it must also be continuous
implying that at x=0, the top expression and the bottom expression must be equal for it to be differentiable
and since it asks what makes it not differentiable, they must not be equal
i.e. breaking continuity breaks differentiability
oh because kind of like limits? left and right of 0 must be equal
sort of, though there are situations where the limit exists at a point but it is not differentiable at that same point
take for instance $\lim_{x\to 0}\abs{x}$
a disappointing son
that limit exists and is equal to 0, but |x| is not differentiable at x=0
the main takeaway being this
sounds like a good idea to me
well recall that you're trying to see if they're equal at the point x=0
so you should be plugging x=0 into both expressions
but the second one x > 0
right, but it gets infinitely close to the point x=0
therefore implying continuity if it is equal to the expression above it at that point
so its the right side 0+
that is one way of thinking of it
hm well i think more than 1 of them work
which is odd because the question doesn't seem phrased in a way to select multiple answers
oh
bc for a and b i said it is both diff bc both =0
then c i think both = 5?
then d for me i got -1 is not = to 0
okkk
i also um need help with this
i graphed c(t) and b(t)?
but am i supposed to do derivative of them?
and find max and min
<@&286206848099549185> :< sorryyy
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Which one is cubic formula equation? I'm so confused
A cubic equation is an equation that can be represented in the form a x 3 + b x 2 + c x + d = 0 ax^3+bx^2+cx+d=0 ax3+bx2+cx+d=0, where a, b, c, d a,b,c,d a,b,c,d are complex numbers and a is non-zero. By the fundamental theorem of algebra, a cubic equation always has 3 roots, some of which might be equal.
This is how you would know if it is one or not.
If you can't figure it out, come back.
Who even uses that 
Me 
Thank You
.
i never use that 💀
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f(x) is in blue on the left and g(x) is in red on the right, how would i go about finding the limit at x->1 for g(x)?
So we both struggling with Calc1000B huh.
@sudden patio Has your question been resolved?
<@&286206848099549185>
f(x) is in blue and g(x) is in red, what happens when adding limits where one doesn't exist or one is equal to infinity?
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what is the equilibrium quantity? apparently my answer is incorrect
here is what they told me to do, and i did exactly what they asked and still got that incorrect number
your answer for the equilibrium quantity is incorrect
hm. ok wait
the numbers do check out
oh but look at the rounding instructions for the quantity @gusty oak
cant lol
plus, didnt it say one answer was correct? thus format also good?
i could get rid of the .5 but i doubt it will work out
but id have to do to both
oh sht..
ur right
welp didnt work
took out the .5
.5 doesnt round up
on the contrary, you round up on five
i spent like an hour this set of problems
until question e
can we have someone else confirm
i have 1 try left
so rounding down didn't work...?
.5 is middle
i googled it and you dont round up or down
i took out the .5
got it incorrect
mymathlab program is so bad lmao
do i round up or down?
.5
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I need help with this i see youre supposed to factor it but the numbers are so weird and so is the equation compared to everything online
please @ me if someone is willing to help as I have discord alt tabbed and very forgetful
@proper shell Has your question been resolved?
let f(x) = 2/x - x - sqrt(x) ; the question become to show that f(x) = 0 has a root in the interval (2,3) you can know just do the steps of the IVT to prove that
@proper shell
Wouldn't it be f(x) = 2x - xsqrt(x) - 2 though
To make it so that 0 = to 2x - xsqrt(x) - 2
how did you get it like that ?
Just multiplying by x on the 2/x side to move it then minusing 2 so that 1 side was 0
Opposite operations pretty much
You'll have to multiply x by the sqrt(x) and 2 no?
I mean
X
Oh wait I think I got it
Hey thanks man
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ln e^2 no calculator
I wasn't in class and our teacher didn't give us enough information
I have no clue what ln is and my friend said it was just memorization
I wasn't there so I don't know what to memorize
do you know what e is?
hmm
yeah so you can do this using the definition of log, or with log properties
I know how to do log but for some reason I can't figure this out
you in fact do not need to know the value of e in order to calculate ln(e^2)
have you been introduced to logarithms in general?
by the few notes she gave us 🤩
sorry I'm a little frustrated with my teacher right now JKL;GFJ
I know how to evaluate without a calculator at least
that makes sense
Are you familiar with the properties of logarithms?
I don't think so
I mean stuff like log(a/b)=log(a)-log(b) or log(ab)=log(a)+log(b).
no I don't
Well, then you clearly lack the tools to solve this problem.
yeah, she didn't give us very much to work with
not really
wow, that's shitty of her.
she sent us a few videos and there's some stuff in a packet we got but hardly anything about ln and it's hard to understand anyways
somehow she's the math chair leader or something and she changed from our algebra book to this shitty book that she doesn't even have a teacher edition of
the answers are only the fully simplified version and there are only answers for the odd problems 🥰
she's so silly
ok I give up thank youu
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i have tried
but no one has helped
for the first one i get 0
but how do i work out sin theta
Subsitute sin(theta) with x, and find the solutions of this equation.
Observe that once we substitute sin theta with x we end up with the same expression given in part 1.
And -0.5 makes that expression zero, which means that it will make our new expression zero as well.
So for x=-0.5 our expression becomes zero and we know that x=sin(theta).
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how do I solve this? lg x = 4
def. of log
what does def meann?
Modus
okay thanks
Definition
if base isn't mentioned we usually treat it as 10
so A is 10?
I'd say so
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A brief description and guide on how to use me was sent to your DMs!
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omg the channel closed sorry. could i get a hint.
usually with problems like these it would be a good idea to list out at least 10 of the next terms
@karmic ridge Has your question been resolved?
from 11117?
like 11117, 11118, 11119,e tc
or actually
you dont need to
the sum of the numbers would be the change from the starting number to the ending number
wait why
think about it
if you compute the difference from 5 to 3 to 7, its the same as the difference from 5 to 7
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shall i ping a fellow of ours
Dio "Toby" Brando?
he is well versed in Newtonian Things
sir, do you want assistance from the best there is, in the name of Toby?
Sir
please answer
depends on the concavity of the graph
@remote mural
if it's linear (no concavity), you'll get the exact root after one iteration
if it's concave in the same direction that it's moving, you'll undershoot
This Desmos may help https://www.desmos.com/calculator/k5l90pmit6 Just replace the equation
if it's concave in the opposite direction, you'll overshoot
but as long as you started close, you'll overshoot but still be a lot closer
the way i know this is not that i had it memorized but just that i'm imagining the graphs in my head
and looking at the example you gave
feel free to draw out the others
it's possible for it to
touch the actual root at some step
even in a not linear case
just "infinitely unlikely" in the general case
Computers stop applying newtons method after the last 2 iterations are within a certain tiny amount of each other
In this case the tiny amount would be 0
So it gets the same root twice and then stops
Probably this one
Fine. I'll look past this.
it's my pleasure
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Can anyone explain why 0 isn't a vertical asymptote
so if the numerator wasnt that identity
then 0 would be a va?
say the numerator was 1
ahhhhh gotcha
yeah they're throwing some curve balls lol. thanks for the help!
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Can someone help me with geometry homework? It covers perpendicular and angle bisectors. Here is the question that I am currently trying to work on.
think triangles, it's given in the problem based on the definition of perpendicular bisector that you have some congruent segments and angles
if you prove that the two triangles are congruent it follows that their corresponding sides are congruent which is what you want to prove
the perdendicular bisect or shows congruent segments?
oh wait yeah
so they are congruent due to SAS
exactly
sure, just post them here
equidistant just means same distance
yeah
honestly it's kinda fuzzy, i can't tell where the 2nd entrance even is, i only see one on the right side
or i guess those two arrows are two different entrances? i was interpreting at some sort of large door
well, if you're at A are you closer to one of the entrances than the other?
lol
well i have a different question then i guess
im confused on what the theorem means
like i dont understand what the 'sides of the angle' are
that's uh, sloppy problem writing to say the least
an angle bisector of an angle of a triangle divides the opposite side into two parts that are proportional to the other two sides of the triangle.
still dont understand lol
but what they mean is youve got this angle A opening up and kind of the "sides" of it : )
so they're talking about the angle A, like imagine you just had the red figure and the angle A
and then you are drawing AD, bisecting that angle into two congruent angles (equal measures)
yep
yes you can use that indeed
and then the two angles
so im not sure why we needed the theorem
like i didnt use it
or did i
idk
which theorem?
angle bisector theorem
well read the problem again, they're essentially asking you to prove the theorem
not use it
so how would i do that
you just did lol
oh alright
ill send a picture of the completed proof and lmk
also
would angle b and c be congruent
just cause it shows it
it doesnt say it but it shows it
basically proving that BD = DC is equivalent to proving the theorem because thats what the theorem says is that the point D is the same distance from the two sides
so when you are talking about distance from a point to a line
what
or line segment
okay
so what do i do about angle b and c
whats the reason for them being congruent?
given?
even though it doesnt say
okay
when you are talking about distance from a point to that segment
its basically the path you take from the point thats at a right angle to the segment
intuitively, that's the shortest path right?
yeah
like imagine you are in a field next to a road, and you want to take shortest walk to the road
youre going to end up walking into the road perpendicular to it right?
yeah
so since the whole thing you are trying to prove is that the DISTANCE from that point D to the two sides is equal
thats why BD and CD are drawn in such a way that they make a right angle to their two respective sides (see in the original figure?)
so yes of course those angles in the triangles are congruent as well since they are both right angles
so okay
so they couldve given you just this figure to begin with and told you ok we have an angle, an angle bisector and some point on that bisector
and asked you, prove that the distance between that point and the left red segment and red right segment is equal
but they were nice and already drew those segments at right angles for you...
but it would have been enough to just show you my figure because you wouldve thought to yourself "oh we are looking at the distance between this point and this segment, ill draw a new segment from the point to the red segment at a right angle"
is my proof right?
looks good
ALRIGHT
what does cpctc stand for anyway?
corresponding parts of congruent triangles are congruent?
yeah
its dumb
but my teacher adds the extra c
I have to go for an hour, but can you help me when I get back?
probably wont be around but just make a channel and someone will help you im sure
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need some help
!help
Please read #❓how-to-get-help
i got what x is
how did you do that?
yeah thats the issue
ok when you say you solved for x do you mean you solved in terms of y or did you somehow get a number
what did you get for x
0.75y
60 each
not rlly
ok so the final equation comes from the angle
you know that the angle is just 60 degrees
you can plug in x and solve for y with the last equation
It becomes a system of equations with two equations and two variables
ah alright
can you finish from here?
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Do you know the pythagorean identities?
for 93, you're given sin(theta) and asked for cos(theta)
So do you see which one of those identities we want to use
maybe sin + cos = 1
so plug in the value you have for sin(theta), and what do you get
okkk!!
for the square do you multipy the whole fraction by itself or just the top and bottom to get 9/25
(3/5)2 + cos2 = 1
either way should be the same. 9/25 is good
is 16/25
no, that's cos^2
Right, but be careful
YESSSSSSSSSSSSSSSSSSSS
It could be 4/5 or -4/5
wait why
(4/5)^2 = 16/25. And (-4/5)^2 = 16/25
Whenever you apply a square root to both sides of an equation, you get a positive and negative solution
ohhhhhhhhhhhhhh
But
You can figure out which one is right
since they told you which quadrant theta is in
how
Yes itmeans they're in the 2nd box thing on graph
Quadrant
yess
Different of the functions are in different quadrant
And is the cos positive or negative in that quadrant?
hmmmmmmm
remember the cos represents the x value of the angle. In quadrant 2, that is negative
Yep you got it 👍
@icy otter Has your question been resolved?
THANK YOU SO MUCH
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I need to verify are these are the answers for the principle solution for the sin theta = -1/2
your answers in degrees are correct but you converted to radians incorrectly
though you showed the correct formula for converting
Ohh thank you. I didn't notice that. It should be 11π/6.
But I am confused with some of my notes and some online reference where it says principle solution for this as -pi/6.
iirc the principal solution is any solution between 0 and 2pi
so i'm not sure
Can you verify the above pic if can
@tulip sail Has your question been resolved?
@tulip sail Has your question been resolved?
hello, the range of principle solution may differ in different situation.
I think the principal solution required in your context would be
(-pi/2,pi/2] for sine
[0,pi) for cosine
(-pi/2,pi/2] for tangent
would this help?
So is that the reason that solution is differ in the the printed image that I have sent.
I am stuck in here. There is no any context define in this note.
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how do i figure this
carefully expand (α+β+γ)^4
use the known values of α^2+β^2+γ^2 and α^3+β^3+γ^3, as well as vieta's formulas, to your advantage
that sure is going to take a bit
use pascal's triangle
~~also hope you get better soon @velvet osprey ~~
i have no idea how to expand that
pascal's triangle is an option, for sure
something something multinomial coefficients
just assume β+γ = u and expand (α+u)^4 normally
just make sure to also double expand on the u too after u undo the sub
quite the time it may take
might take a bit
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How exactly can I find an undetermined rate in regard to exponential growth and decay?
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Assume that p(x) = ax^2 + bx + c, and assume that T(p) is mapped to the zero vector
Have you shown that at least? If so then you've answered your original question by showing the kernel just consists of the zero polynomial
If not, then try and see what T(p) looks like, then equate that to [0, 0, 0]
well you shouldn't still have x's in those equations
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What have you tried?
im not sure what to do. I have not treid anything
What do you think you should try?
Also, I assume you have studied parallelograms?
yeah ?
Yes, I meant what are the values specifically?
there is a right angle
multiple accutes ?
There are 3 acute angles
Only one of them is known
60 degrees
Can you use that to find any other angle?
Yeah so go ahead, which one?
I mean thw left bottom angle looks the same
yes
Correct
we have 45, 60, 60 degree angles so far
Where did you get the 45 from?
the right angle
Can you send an image of your working?
im doing this in my head
A right angle is 90 degrees?
oh my bad
yeah
There is a straight line going up if you can see
Can you use that in any way?
Extend it to make a familiar shape?
Exactly
Correct
Now
What kind of triangle???
I mean equilateral or isosceles or scalene or right angled?
id have to say obtuse
Something like that?
Can you draw what you are thinking on paper and send an image?
im on a 70$ monitor
Will the line, when you extend it, be perpendicular to the base of the parallelogram?
yes
Means one angle will be?
scalein
Well, those definitions are wrt sides
One angle will be 90 degrees, right?
You are correct on scalene btw
yes
We need angles though
scalen obtuse, acute, right
And I would suggest drawing now for the part after this one, grab any piece of paper near you
Okay, one angle you figured is 60 degrees, the other 90 degrees, right?
yeah, the right one
I have no idea
What should it be? Can you use 2x and 3x to find the third angle?
yeah
You extended the straight line to make a right angled triangle
Now I STRONGLY suggest you draw
yes
Can you see any connection between 2x and 3x?
yeah
Know what vertically opposite angles are?
ive heard of it
Okay, I will try to explain it here in brief
Draw 2 intersecting lines wherever you are writing
And then see that 4 angles are formed
And each angle is equal to the one opposite to it
So 2 pairs of equal angles are formed
That is a vertically opposite angle
i understand now
Yes
the line caused both of the angles
so then 2x and 3x would have to qual the same
No, actually
oh
If you have drawn it all
You will see that via vertically opposite angles
You can write it as 2x + x
And the angle x lies inside the triangle
That means, the angles of the triangle are 90 degrees, 60 degrees, and x
I think you know how to find x?
subtract ?
Do you know what the angles of a triangle sum to?
150
The sum of all angles of a triangle is 180 degrees
That means 90 + 60 + x = 180
You can solve this equation I guess
You will find x
yay
And I suggest doing the problem once again all on your own
thank you for your help
Geometry gets easier when you draw it
I did not understand how to break it down
You're welcome but do not forget to redo it on your own
yeah
Did you draw it?
yes
Good
I’m also doing something similar but it deals with trigonometry. Can I ask the question?
Now, just try to remember all you know about parallelograms and triangles
And analyze it
Hey Vegan, check out #❓how-to-get-help
alright. Thanks for the help
Or in short, ask in a help channel that is not occupied @remote mural
You're welcome, a little more effort and you will be able to do it on your own 👍
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That is the spirit
Good luck and happy studying ✍️

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2x - 3y - 10 = 0;
X^2 + xy + y^2 + 2x + y - 6 = 0
Please I need workings for these simultaneous equations
Express x in terms of y
i know, but im finding it difficult to arrive at the answer...
let me show you my workings
Somethibg must have been wrong somewhere but I can't figure it out
I think you should multiply it by 9 to get rid of the factor, not by 3
Oh I see
@rugged stirrup Has your question been resolved?
the answers are x = 2 or 172/19 and y = -2 or 58/19
But the answer I got is different
lemme read what happened here
Please read
Ok imma try to work it myself and see
Thank you!!
I got x=2 and 8/19
Get out of bluestacks and get ur ass back here
lmao I actually used it for Whatsapp, now it says im playing a game😂
Whatsapp aint got lobbies what
Alright
so what u do is
Multiply by 3
everything
Ok idk how to use the bot
U get this
Expand and u get this
then just use the quadratic formula
and u get the x vlaues
values
Yea i got it to this place after @quick glade made a correction. Both our answers are the same but it doesn't tally with the one in the textbook. It wasn't worked tho', just the answer. Is it possible the textbook answer is wrong??
@vast stirrup
Whats the answer in the text book
this?
Yes
Hmmm, that's actually a problem if it's wrong, I gotta change textbook
@vast stirrup But is there a way to proof our answers
Cause its like plugging those answers in the equation doesn't do much in proving anything?
Both might actually results to 0 which is weird to me, but its maths yk
I mean its just simple math
Aiit, thanks for the help, really 'preciate
Ok u can go play now
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Yeah
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Hello i have a probability question
4 players play with a 32 card deck. We draw out 3 cards for each player. What’s the probability that each player gets an ace
Is it this or am i tripping ?
Why do you have y in the expression????
thats a 9 or a 4
Woops no y haha
Cmon bro 😂
and after you do al that thats the number of possibilites that each player gets an ace
Wait what ?
and the total possibilites are just distributing everyone 3 cards
I don’t get it ?
huh?
The cards are distributed at random
You can’t do this tho
That defies the problem they’re asking ?
like when u roll 2 dies
whats the probability the sum is 2?
the total possibility is 6*6
Sum of ?
and the number of ways it give 2 is just forcibly rolling two 1's
sum of the dies
so your counting the number of ways each player gets an ace is the same as the counting if you give them the aces
so i give them the aces and count
also you have to account for have many ways you can give the acse

anyways the answer is $$(hello)$$
(number of ways to distribute the aceless card set to each player 2 cards) * (number of ways to give the players the aces) / (number of ways to distribute each player 3 cards)
Jester
I think i agree
How do you calculate the fist part of the product tho ? ( left side )
28C2 * 26C2 * 24C2 ?
@remote mural
yeah sure
i was personally thinking 28C6 * 6! / (2!)^3
but they maybe the same
Where did you get that from haha ?
just choose 6 cards to distribute
line them up
but every 2 card is counted 2! times in 1 hand
yeah i checked its the same
same with the total numebr
Nice
Oh wait there are 4 players tho
So 28C2 * 26C2 * 24C2 * 22C2
How do you count the aces tho ?
4! ?
Yeah has to be
Right ? @remote mural
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i got the answer but i typed it into my calc manually
and it took forever
is there a quick way of doing this?
Use demoivre's formula
or do i have to use calculator
Complex numbers
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(\sqrt(306))/(x)=(15)/(20)
How would I simplify this equation
that looks weird
let me fix that
square root of 306/x = 15/20
[{\f{\s{306}}{x}} = \f{15}{20}] is this it
√ 306/x = 3/4
No the square root is only over the 306
yeah
that's it
multiply both sides by x first
so square root of 306 = 15x/20
√ 306 = 15x/20
which is simplified to √ 306 = 3x/4
Oh so looking at the answer key that's how I was supposed to do it
which would be 4√306 / 3 = x
Gotcha
I asked mathway to see what it got it and it gave me some weird bs
alright
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does anyone know what the difference between a "y on x" line of best fit and a "x on y" one?
The role of dependent and independent variable is switched
but the line of best fit changes? I don't understand that part
The equation does, yes
in this question they already pre-defined the x and y
how?
we aren't changing the variables on the axis right?
Because one is x plotted against y, the other is y plotted against x
Yes we are, that's exactly what we're doing
oh ok
but
aren't line of best fits always expressed in terms of x and y
oh so you just write the equation one in
y = mx+c
the other in
x = my+c
form?
It matches the usual references to x and y, but they're just letters
wait what do you mean
say for y=2x
that would be "y on x" right
since you are measuring rise over run
I'll admit I've never seen "y on x" verbatim so I don't know which direction that is
Ideally it'd be defined earlier
yeah I'm also super confused, can't seem to find anything online either
alright, thanks a lot!
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please can someone guide me through this question
do i do the (area x d) x centre of mass of each shape then add it up and divide by the total (area x d) to get the centre of mass for the wholle thing ?
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<@&286206848099549185>
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@gilded drum Has your question been resolved?
@gilded drum Has your question been resolved?
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did i do this correctly?
idk what's blank 1 and blank 2, but h and depth are correct
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,w 10 * 8 * 13 * 13
What am I doing wrong here?
I assumed this was a fundamental counting principle problem, but the book says the answer is 6240
look closely at the two desserts
there will be times where the same meal happens twice
are you sure that (a) choosing the same dessert is allowed, and (b) the order in which you choose desserts matters
No I'm not sure of either of those things
^
right now you say that {dessert1, dessert2} is different from {dessert2, dessert1}
though in reality you may choose which dessert gets served first and which gets served second, here I think you have to count out the order
I'm sorry I don't understand what you mean by count out the order?
pretend that there is no order
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Would I. E able to graph each scenario?
With the information given?
yes, they expect a general graph with both curves
I’d like to know whether I’m understanding the price right. For the 1st one, I know there would be a shift in the demand curve and it would be to the right because greater demand always shifts the curve rightwards…but my supply curve would shift leftwards and would be lower then my demand curve?
Anyone?
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$8b^4+24b^3-2b^2-6b$
AllUtility
should i group or just factor out 2
Factor out 2b first
$4b^3+12b^2-b-3$
AllUtility
Yea now the factoring is pretty clear
lol
What
you forgor the 2b you factored out 💀
it doesnt just vanish into thin air
forgor 💀

AllUtility
is dis rite
looks suspicious.
$2b(2b-1)(2b+1)(b+3)$
I think you mean $2b(4b^2-1)(b+3)$
great
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Hello, I am back after not recieving feedback. I think my handwriting wass probably too difficult.
This is the original question - and here are my notes
I am getting the incorrect answer, and I am hoping to find out what I am doing wrong.
@heady karma
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B commutes with any 2x2 matrix A if AB - BA = 0
The solution says: a = d, b = c = 0
then great
I'm not following
Prove that using herels hint
Am I on the right track here?
and now choose specific values of w,x,y,z
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I have expression a_1 + a_2 + a_3 + a_4 ... a_n, where each element is of form a_x = 1/(2k)! if k is odd, and -1/(2k!) if k is even
I would like to somehow simplify this expression since it can't be easily evaluated by computers
1/4! is already too little
Not to mention greater factorials
$\sum_{k=1}^n (-1)^{k+1}\frac{1}{(2k)!}$
ΣAC
