help-42

[azure bison]

this a 2 step thing

u know a few things

angle which tells us Vx Vy

a = -9.81

sorry misread that

u want to find u

u is inital speed

just a letter for it

give me sec ill do it now

that too

okay i figured it out

so what you do is

you know that

at the peak of the curve

Vf = zero

we r talking vertical components here

and because its a parabola

the max height is half the distance

so using the constant acceleration formula

0 = (usin35)^2 + 2x-9.81x(283/2)

which comes from

v^2 = u^2 +2as

@remote mural

thats times sorry

the 283/2

wait ive had brain death

ive mixed up dimension

let me draw

@remote mural

Hmmmm

What have u learnt to solve this

What r u learning In class

What class is it

That is physics

Basic kinematic

I don’t see any other way to get around it

But what i did is you’d go about it using the suvat

[calm coral]

@remote mural Has your question been resolved?

[calm coral]

@remote mural Has your question been resolved?

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@remote mural Has your question been resolved?

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[calm coral]

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[limber pilot]

hey im curious why this isnt cos(x), in khan academies explination video they just removed the integral, why is that not the case here?

[limber pilot]

and ik the chain rule/product rule which i think is somehow involved

nevermind i figured it out

.close

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[remote mural]

find the exact value of cot(105degrees)

[remote mural]

so i have tan(60 + 45) so far

and im planning to just reciprocate my answer once i find it

but im not sure what to do from my 2nd step

[sonic apex]

You can use the formula for tan(a + b)
If you can't recall it, you can use sin(a + b) / cos(a + b)

[remote mural]

idk formula

[sonic apex]

sin(a + b) = sina · cosb + cosa · sinb
cos(a + b) = cosa · cosb - sina · sinb

If these aren't familiar, I don't know what to recommend

[remote mural]

wait

oh

@sonic apex uhm what do i do with this

[sonic apex]

Now you can calculate it

You should be familiar with the sin and cos values of those angles

[remote mural]

yeah

[sonic apex]

Nice

[remote mural]

oof imma stop using whiteboard

.close

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[lethal rivet]

The diagonal of a rectangle is 15 cm, and the perimeter is 38 cm. What is the area?

[lethal rivet]

How would I do this?

@tough apex , you need to go to an open channel

I'm using this channel

Go to #help-33

[oak sand]

Imam Hussein

God bless u

[lethal rivet]

Thanks!

Where are you from @oak sand ?

[oak sand]

Karbala

From Iraq as well

[lethal rivet]

Mashallah

[oak sand]

And u?

[lethal rivet]

Baghdad

[oak sand]

God bless u🇮🇶

My father is from Baghdad

[lethal rivet]

Wa anta insha'allah

[oak sand]

But mother from Karbala

[lethal rivet]

Both my parents are from baghdad (born) but Originally from najaf

[oak sand]

Oh okay so u live in iraq currently

[lethal rivet]

Oh no

We live in Manchester, Uk now

[oak sand]

Oh okay

I live in Sweden

[lethal rivet]

Cool

Must be cold

Lol

[oak sand]

I’m born in Sweden, yeah

It’s

I’m freezing out here

[lethal rivet]

My name is also Youssef lol

[oak sand]

Is it cold in uk

Hahaha nooo r u serious

[lethal rivet]

Yeah but nothing like sweden

[oak sand]

But is ur name really Yousef

[lethal rivet]

Yes

[oak sand]

What a coincidence hahaha

Can u help me with this problem though

I should calculate the highest value of the function

[lethal rivet]

Haha I'm in ninth grade

[oak sand]

Oh okay

U are young

I’m 18

[lethal rivet]

Yeah I'm 13 lol

[oak sand]

I’m studying for engineering right now

So it’s a lot of math

[lethal rivet]

Mashallah

[lethal rivet]

Yeah , but your lucky not to be studying in Iraq 30 years ago when there was no calculators

Everything on paper

I couldn't even Imagine that

[oak sand]

True but In my university we aren’t allowed to use calculators though

[lethal rivet]

Really?

Damn

[oak sand]

Yeeeah

I know

[lethal rivet]

Must be hard

Tahchi arabi?

[oak sand]

Beli

[young pumice]

Same

My name's Ali btw

[young pumice]

I think you should find where the function's derivative is 0

[calm coral]

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[lethal rivet]

Masha'allah

Are you from Iraq @young pumice ?

[young pumice]

Sadly no im lebanese

[calm coral]

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[meager helm]

For the last 48 hours i was trying to solve this task

[calm coral]

@meager helm Has your question been resolved?

[meager helm]

eternal torture and misery

[calm coral]

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@modern night Has your question been resolved?

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[wary igloo]

We say the gradient is perpendicular to a surface

[wary igloo]

But that it also point to the steepest increase

Here for example

It's not perpendicular

Shouldn't it hug the surface if it points to the steepest increase?

Even in 2 dimensions

y=x

Gradient is 1

How is that perpendicular to the line

Oh wait

Does the gradient of a function only apply to the contour

For example, z=x-y

Contour are parallel lines y=x+C

Gradient is (1, - 1)

Which is perpendicular to the contour

But how's does it point to the steepest increase

[calm coral]

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.close

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[spare moon]

I need help with #50-52

[calm coral]

@spare moon Has your question been resolved?

[rustic osprey]

Did you do 45-49? What's the difference between those and 50-52?

[spare moon]

No I skipped those and decided to get help with the harder ones

[rustic osprey]

So do you know how to do them or not?

Cause they're all basically the same thing, just different numbers

or is it something specific with 50-52

[remote mural]

wow

i have a friend named ali that goes to my school and is from Lebanon.

[spare moon]

no

for the love of God, can someone help me understand how to solve these

[vernal coyote]

I don’t know this but I found a video that might help

https://m.youtube.com/watch?v=ogueoMJL9yc

[spare moon]

thank you so much !

[vernal coyote]

Your welcome

I can help find more videos if you tell me exact lesson name. If you need more help

[spare moon]

it's on refrence angle but I'm more confused on how to solve questions with decimals and the fractions with pi

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[remote mural]

hello

[remote mural]

<@&286206848099549185> i’m struggling with these 3 problems. If anyone could help that would be greatly appreciated

.close

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[old stream]

Can anyone tell me what i did wrong

I basically split x+5

So i can u sub it

And then used arctan on the second half

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[strange lichen]

i have no clue how im getting this answer today

[strange lichen]

i did this yesterday and i got it right

idk why im getting it wrong today as im trying it again

A' = P^-1 * A * P

P = B'

P^-1 = B'^-1

today, im getting the answer that i pointed to with a red arrow

i even tried the example in the textbook with the same method they used, and it worked out just fine, not sure where im going wrong with my problem...

.close

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[unique dust]

I am confused why | | N(x,y) | | = 2

[calm coral]

@unique dust Has your question been resolved?

[unique dust]

<@&286206848099549185>

<@&286206848099549185>

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@unique dust Has your question been resolved?

[leaden thunder]

show work?

[unique dust]

I got it

Its just the norm I thought it was

/close

/done

.close

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[midnight kelp]

.reopen

[midnight kelp]

Hey there i wasnt really sure how to do thus and how to get the area

i already created a ticket but it closed without an answer

<@&286206848099549185>

[unique dust]

Every side of the rhombus is equal to each other

If you divide the rhombus into 2 equilateral triangles you'll see each angle is 60°

[midnight kelp]

and how would i use that to calculate area?

[unique dust]

You know the length of the circle is 2

since radius 1

and you have the height of rhombus

use trig

[midnight kelp]

when i have all sides of the rhombus what do i do

[unique dust]

area is height times base

[midnight kelp]

ight ty

got the answer

thank you!

.close

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[calm coral]

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[empty shard]

Describe the region of space below the surface $z=4-\sqrt{x^2+y^2}$ and above the surface $z=2\sqrt{x^2+y^2}-5$ using cylindrical coordinates and find its volume

[potent lotus]

RockLEE

[empty shard]

So i think I found out that radius is upto 3

but im lost on how to setup integral right now

i got my integral as $\int _0^{2\pi }\int _0^3\int _0^{4-r}:rdzdrd\theta ::$

[potent lotus]

RockLEE

[empty shard]

but im not sure if this is correct.....

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[limpid skiff]

Help please

5x^2+10x^2+4x+x

15x^2+5x

Anyone got any idea?

[prisma mango]

It just wants an expression

[tawny niche]

yellow: 5x^2
green: 4x
pink: double yellow, so 2*(5x^2), so 10x^2
black: green minus 3, so (4x - 3)

[limpid skiff]

5x(3x+1)

[tawny niche]

do you see how I got all these?

[limpid skiff]

Yes

I think I made a mistake

@tawny niche did I

[tawny niche]

I think so

for black, you did 4x - 3x, not 4x - 3

small mistake

[tawny niche]

anyway what did you get from adding these together?

[calm coral]

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[eternal mason]

Hey

[eternal mason]

Need help

[potent lagoon]

with..?

[eternal mason]

Went over in class

Forgot how to do it

💀

[potent lagoon]

.rotate

er what was the command

nvm

[eternal mason]

How do u do 15

Just need a refresher

[potent lagoon]

just write x=2t in terms of x

[eternal mason]

Wdym

[potent lagoon]

like

[fathom shuttle]

,rotate

[potent lotus]

Couldn't find an attached image in the last 10 messages.

Nov 15, 2022, 1:36 AM

[fathom shuttle]

Oop

[potent lagoon]

x = 1/4 t

[fathom shuttle]

,rotate

[potent lagoon]

in terms of x is like 4x = t

[fathom shuttle]

;)

[eternal mason]

Lol

Oh

[potent lagoon]

just get the t by itself

[eternal mason]

I did

[potent lagoon]

okay u get x/2 right

[eternal mason]

Ye

[potent lagoon]

replace the y = t - 1 with what you got

[eternal mason]

Y+1=t

[potent lagoon]

nono

you just got t = x/2

[eternal mason]

Mhm

[potent lagoon]

so now replace the t in y = t - 1

[eternal mason]

Oh

Y=x/4-1

[potent lagoon]

howd you get x/4

[eternal mason]

Sorry 2

[potent lagoon]

yup

good job

thats basically what u do

just get t by itself

then that other side of the equation you put into the other eq

[eternal mason]

What’s the next step

[potent lagoon]

no u just did it

if you got y = x/2 - 1

youre all godo to go

[eternal mason]

Nah there’s more

There no way it’s that simple

[potent lagoon]

uh its been a while since i did parametric equations

i might be forgetting something

[eternal mason]

Ye

Definitely there’s more to it

Is there someone else that can help?

Not trynna be rude

[potent lagoon]

yeah all good

when i saw parametric eq i already knew i might not be the best person

[calm coral]

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[eternal mason]

.close

[calm coral]

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[honest prawn]

The answer is that the product of the slopes are -1

The slopes are -3 and 1/3 respectively

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[honest prawn]

<@&286206848099549185>

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[dry glacier]

Help

[calm coral]

Please don't occupy multiple help channels.

[dry glacier]

I was just making sure this was correct?

[calm coral]

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[calm coral]

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[rugged oar]

This one is real easy but our teacher hasn’t taught it to us and this is a pre unit practice

[rugged oar]

Thanks but now I can’t see the other one lol

[coral osprey]

Geometric mean theorem

Yeah I closed it

[rugged oar]

Thanks

[coral osprey]

You can find the altitude if the triangle and then use Pythagorean theorem

[muted spoke]

It works because the triangles inside are similar to the big one

[rugged oar]

X 24

• = -
  8 x

X = 13.85

But how do I find side lengths?

[coral osprey]

Find the altitude first

And then use pythag

[rugged oar]

Oh right I’m stupid

Thanks for reminding me and finding that nice image

[muted spoke]

Since a+90+?=180

And b+90+?=180

[rugged oar]

Yea I see thank you 😊

[muted spoke]

K

Glad to help

[rugged oar]

.close

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[inland cipher]

(4+y)"2-3(5y+1)=1

[leaden thunder]

• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.

[inland cipher]

okay, so i do the equ and i end up with y"2-7y=-12,and i dont know how to go further

[leaden thunder]

what does y''2 mean

[inland cipher]

y squared

[leaden thunder]

and go futher with what?

what are you trying to solve for

[inland cipher]

one sec ill translate it

[inland cipher]

convert the equation to normal form and solve", not sure if the terms are correct but seems good

i need to tfind y1, and y2

[leaden thunder]

what's "normal form"

ay^2 + by + c = 0 ?

[inland cipher]

not a formula

or what does that mean

[leaden thunder]

answer this

[inland cipher]

Where do -3y and -4y come from

[leaden thunder]

do you mean y-3 and y-4?

[inland cipher]

No, like how has -7y become -3y-4y

[leaden thunder]

oh. -7 = -3 - 4

multiply both sides by y

[inland cipher]

So if the y was -9 instead

It would be -4-5

?

[leaden thunder]

depends on the problem

you want two numbers that sum to -7 and multiply to 12

(x+a)(x+b) = x^2 + (a+b)x + ab

in this case, a+b = -7 and ab = 12

[leaden thunder]

they worked backwards from this

[calm coral]

@inland cipher Has your question been resolved?

[inland cipher]

just have to use x1,2 = -b"squareroot"b"2-4ac

[calm coral]

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[inland cipher]

:2a

actually very simple

[calm coral]

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[onyx quiver]

How come when he pl ug ged in x it became 5

also how do u add radicals like that

[gleaming hare]

Because of binomial expansion. In the brackets you have (5-root(7))×(5+root(7)). When you expand that probably using binomial expansion you get 5×5+5×root(7)-5×root(7) -7×7. Normally you can't add radicals so easily, but the positive 5root(7) and the negative 5root(7) cancel and the root(49) is just equal to 7.

Have you learned the FOIL method of binomial expansion?

[calm coral]

@onyx quiver Has your question been resolved?

[onyx quiver]

yes

[gleaming hare]

Alright. Is there any part that I didn't explain well? I'm not totally sure what level you are at so I may have explained it poorly.

[onyx quiver]

No I understand it now I didnt realize we had to do binomial expansion

[gleaming hare]

Yeah okay, cool.

[onyx quiver]

Thank you 😄

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[gleaming hare]

NP

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[normal field]

Helpppp ):

hellooooooooooooooooooo anyone

<@&286206848099549185>

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[onyx quiver]

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[remote mural]

if the sum of the angles is 108°, how about the angles inside? i got 108 by doing this formula 180°(5-2)/5

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[river coral]

Please help

[pulsar granite]

Let's number the pieces naturally starting from the bottom left as (1,1)

[pulsar granite]

What are the bounds of the (i,j)'th piece?

[river coral]

Idk

That's why I posted the question, I'm lost

[pulsar granite]

What are the bounds of the bottom left piece?

[calm coral]

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[near palm]

I am tying to find the length of a curve for a parametric function, i don’t know where to go from here and if I am on the right track or not

[carmine sorrel]

well... you plugged in dx wrong

(sqrt(2t+3))^2 = 2t+3

[near palm]

ohh, thank you

[near palm]

So would this be correct?

[carmine sorrel]

looks legit

[near palm]

ok thank you

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[fossil galleon]

This is like the third time Im asking this half way through the person helping me leaves 💀

<@&286206848099549185>

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[foggy latch]

is there a method to evaluate one side limits algebraically?: the only ways i know to do this are:

evaluate general limit and then conclude that side limits are equal to this
graphically
tabulating

[stuck kestrel]

depends what the question is

sometimes you can easily plug values in for whatever variable the unknown variable is approaching

[foggy latch]

that's tabulating, right?

but is there an algebraically way?

[stuck kestrel]

like for this you can easily plug in 1 for x

since you know x doesnt have any discontinuities in the question above

but you would need a different approach for this (graph below)

since theres a discontinuity at 0

see

[foggy latch]

🤔

then in that case u need to tabulate or do the graph ("same thing")

right?

[stuck kestrel]

sure

or you can use small values of 0

for example 0.000000001

1/0.0000001 is something large

and positive

as you keep increasing the numbers of 0 it gets larger and larger

[marsh agate]

Or you can actually look at the signs

Algebraically

[foggy latch]

oh, the sign analysis yeah

thanks to both of you

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[keen laurel]

There are 52 cards, i need to get 5 specific cards and i can grab 8 cards to get those 5 specific cards, what is the formula to this?

[keen laurel]

(The 5 specific cards can be in any order it does not matter)

(The formula is to the chances of getting those 5 specific cards)

<@&286206848099549185>

[stuck kestrel]

are you trying to find probability?

[keen laurel]

Yes

it can be 1 in ….. times or in % it doesn’t matter

[keen laurel]

the probability of getting these 5 specific cards

[stuck kestrel]

you can pick out 8 cards from the 52 cards

so on first try you have 52 possible options

on second try you have 51 possible options and so on

[keen laurel]

(52!-44!). ?

[stuck kestrel]

no you wouldnt subtract

you would divide

[keen laurel]

52! : 44!

:5?

[stuck kestrel]

those are the number of different sequences of cards possible

[keen laurel]

ohhh

but how do i do possible outcomes that match my requirements?

[stuck kestrel]

sorry i dont know 😦 😦 😦

[keen laurel]

could this be a possible formula?

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[errant vigil]

Is this valid ?

[glad grove]

nah

[errant vigil]

Why not ?

[glad grove]

if you put in any x other than 1 it's false

,w 2/(sqrt((2^6))

[potent lotus]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by keto11#8349

[glad grove]

,w sqrt((2^5))

[potent lotus]

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[errant vigil]

But I was using variables

Not numbers

So hypothetically it’s not wrong

And it stayed 1/

[glad grove]

yeah it's not wrong for the special case x=1

but that's the only time it's true

[errant vigil]

So for a comparison for a series

It technically wouldn’t be wrong

[glad grove]

[errant vigil]

Please say yes

I need to get 100% on my exam

[glad grove]

if it works for your theorem I guess

[errant vigil]

OOOO

YAYYY

[glad grove]

are you using the comparison test?

[errant vigil]

LCT

[dull wagon]

you're violating exponent laws/ order of operations

[errant vigil]

But it was only for a variable

And it was a comparison

It wasn’t a real number

[glad grove]

this test?

[errant vigil]

Yes

[glad grove]

I don't really see how your q relates to this

are you taking the limit of x/ sqrt(x^6)?

[errant vigil]

No

[glad grove]

huh

[errant vigil]

Idk I got the answer

But my work may be janky

Who knows

[glad grove]

if it's algebra you can't do that

[errant vigil]

It’s not

[glad grove]

could you post the original Q?

[glad grove]

hold up

[errant vigil]

?

[glad grove]

damn bro

[errant vigil]

What

[glad grove]

I can't help on tests

[errant vigil]

No it’s not a test

I already took it lol

[glad grove]

oh

👌

can you write the original question

I can't get the context for your q from this

[errant vigil]

I will attempt to

But it’s all good

Hopefully I get partial credit

Thank you for your help anyways

I don’t wanna waste more of ur time

[glad grove]

aight

[errant vigil]

@glad grove I’m so mad

Like I made such a fucking stupid mistake

Or else I could have got a 100%

[calm coral]

@errant vigil Has your question been resolved?

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[leaden thunder]

Write $x = 8 - 2 / \sqrt{y}$ and solve for y

[potent lotus]

riemann

[fluid flame]

a technique for finding the inverse of the function y=f(x) is to invert the x and y's

and you can directly apply that here

so change all x's to y's and vice versa then solve for y

[leaden thunder]

https://tutorial.math.lamar.edu/classes/alg/inversefunctions.aspx

why

why are you struggling?

[leaden thunder]

start by subtracting 8 from both sides

how do you get rid of the - sign

right

do you know cross multiplication?

https://www.cuemath.com/numbers/cross-multiply/

yup

[leaden thunder]

2 = r and t = sqrt(y)

q = 1, so whatever you have on the left side is p

[leaden thunder]

do you have an equation in this form?

$\frac{p}{q} = \frac{t}{p}$

[potent lotus]

riemann

[leaden thunder]

explain what you have

just type in text here like

x - 8 = -2/sqrt(y)

what is that equal to and how did you get that?

[leaden thunder]

this is what you should be starting with

welp go get rest then

[calm coral]

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[topaz raft]

How do I do this with the “(0,1)” part

[topaz raft]

I know I’m supposed to put it into an equation

but what do I do with the 0,1

[golden raptor]

so it would be a circle with radius root(20) centered at (0, 1)

[topaz raft]

Ah

Do I put the 0,1 into an equation?

[golden raptor]

do you know equation for a circle

centered at (h, k)

[topaz raft]

Area? or you mean the other thing

[golden raptor]

yeah i mistyped

[topaz raft]

(x – h)2+ (y – k)2 = r2

Ye

That

[golden raptor]

yup so just plug in

[topaz raft]

so h is 0 right

[golden raptor]

yes

[topaz raft]

Kk

(x-0)^2 + (y-1)^2 = sqrt 20

ight thank you

[golden raptor]

not quite

= sqrt(20)^2

which is = 20

@topaz raft

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[carmine terrace]

hello, for this equivalence, do i just flip the integrals? is that the right way to do it?

[carmine terrace]

i would put c but i dont know

need advice

[indigo yoke]

c

[carmine terrace]

it literally just flips?

does this not have to do with type 1 / 2 regions?

like my limit changes

[fluid flame]

well you're still trying to bound the same function just in the other order

original you get x is bounded by x=0 and x=e^y

so if you want to bound y instead, what function of x is it bounded from above?

[carmine terrace]

x = 0 to x = e^y?

[ancient thistle]

this is your region of integration

[carmine terrace]

yes

[ancient thistle]

you want to rewrite the bounds with y dependent on x

[carmine terrace]

what do you mean?

we are integrating this part right?

[fluid flame]

this your region of integration where blue lines are restraints of x as functions of y and restraints of y as constants y=0 and y=1

now rewrite this region such that it's a restraint of y as functions of x and restraints of x as 2 constants

[carmine terrace]

0 < x < e, 0 < y < ln(x)?

[fluid flame]

close, actually it needs max{0, ln(x)}<y<1 which looks disgusting

pretty confident your lecturer made a mistake giving this question, i wonder if they intended for the original integral to be

$\int_{0}^{1} \int_{1}^{e^y}f(x,y)dxdy$

[potent lotus]

IV

[fluid flame]

also this should be your new restraints which i think is important to your understanding

[carmine terrace]

thank you so much

[carmine terrace]

so if the lecturer were to use this integral, the answer option would be d right?

[ancient thistle]

yes

[carmine terrace]

thank you, i will clarify with him the question when i see him again

thanks all!

🙂

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[ruby eagle]

how did my teacher get 32x^3ydy in the second step

[calm coral]

@ruby eagle Has your question been resolved?

[ruby eagle]

<@&286206848099549185>

[toxic tartan]

@ruby eagle

$4(4x^3(2y)dy)$

[potent lotus]

moonside

[leaden thunder]

they made a mistake

[toxic tartan]

$= 32x^3ydy$

[potent lotus]

moonside

[leaden thunder]

the 4x^3 should just be x^3

[toxic tartan]

ah

yes

[leaden thunder]

since they factored the 4 out

[toxic tartan]

they did

fire them

[remote mural]

Damn riemann, if I had to look at an implicit differentiation-product-quotient rule combo wombo attempt it would take me 5 minutes to find the original question

[ruby eagle]

ohhhh

[ruby eagle]

wait does that mean the whole thing is wrong

[leaden thunder]

yes

[ruby eagle]

oh

ok

thanks

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[silent adder]

oh lawd

i assume things simplify

based on the number choices

[cloud topaz]

What do you notice about 1212 2020 405 403

[sweet totem]

[velvet osprey]

some symmetry bullshit ought to be in order

[cloud topaz]

||king's property||

[sweet totem]

Oh 2020-(405+403) = 1212

I got 1

Is that correct?

[silent adder]

<@&268886789983436800>

[cloud topaz]

(405-403)/2

=1

[sweet totem]

Okay thanks everyone

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[cerulean swift]

i dont understand the question and possibly how to do this

[shy terrace]

Do you know how to rewrite the 4th root as a fraction?

[cerulean swift]

uhhh im not sure 😄

[shy terrace]

It's okay

So, let's say we want to find the square root of 4

We could write it as 4^(1/2)

[cerulean swift]

oh

i see

[cerulean swift]

like root 4 =?

[shy terrace]

Well, if we write 2 squared, it would be 2^(2), yeah?

[cerulean swift]

ye

[shy terrace]

That's the same as 2^(2/1), yeah?

[cerulean swift]

ye like the fraction?

[shy terrace]

Yep

So the numerator is how many times the number multiplies by itself. The denominator is finding what root number multiplies to get the base

[cerulean swift]

i see

so what is the question asking me Xd?

[shy terrace]

Well, let's finish the explanation, there's more to learn

[cerulean swift]

ok

[shy terrace]

So let's take 4^(1/2)

That's asking what number times itself equals 4, yeah?

[cerulean swift]

2?

[shy terrace]

Yeah, 2 times 2

So if I were to write 27^(1/3), what would you get?

[cerulean swift]

9?

[shy terrace]

What is that asking?

[cerulean swift]

cube

[shy terrace]

Not quite, but you're close

[cerulean swift]

square cube?

cube root?

[shy terrace]

It's asking what number times itself, as in X times X times X, equals 27

There's three X's

This, 27^(1/3)

[cerulean swift]

isee

[cerulean swift]

wut the name called

[shy terrace]

Not sure what you mean

[cerulean swift]

like is root ^3 thing called?

[shy terrace]

3rd root

Also called cubed root

[cerulean swift]

cool so i got it right 😄

so i work ut 4 of them

[shy terrace]

There's more

When you have a number in the denominator, it means the number's exponent is negative

[cerulean swift]

what does exponent mean im basic

[shy terrace]

If I write x^(2), the 2 is the exponent

[cerulean swift]

i see

[shy terrace]

Brb, tutoring in person, might be a bit, sorry

[cerulean swift]

np

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[swift marsh]

https://gyazo.com/357d7239d342f83e570f1f6cca2f5431

[swift marsh]

i dont understand how the question wants me to format it in that way

with r and lambda

[remote mural]

its like y=mx+c, y is r and x is lambda (your variables), and m is b (slope), c is a (intercept)

write out each vector equations with lambda = 0 r=x0, and with 1

[calm coral]

@swift marsh Has your question been resolved?

[swift marsh]

this

you see

how can it be like y=mx + c

when its on a 3d plane

[calm coral]

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[pulsar plover]

hi guys can anyone give me a helping hand on how to compute this

[pulsar plover]

im not gettin 0.2

[leaden thunder]

show your work

[leaden thunder]

the formatting of the problem is confusing

it's telling you $\beta = 1$

[potent lotus]

riemann

[leaden thunder]

so you just plug in $t=3$ into your CDF

[potent lotus]

riemann

[leaden thunder]

but you want exceeds design value

so it's 1-F

[pulsar plover]

what would the 1 represent

[leaden thunder]

it's just the complement event that you want. if you roll a dice and you have its CDF and you want the probability that it exceeds 4, you calculate 1 - F(4)

F(4) = P(X <= 4) = probability dice roll is less than or equal to 4

so probability dice roll exceeds 4 is P(X > 4) = 1 - P(X <= 4) = 1 - F(4)

[pulsar plover]

ohh ok that makes a lot more sense now

I really appreciate your help man

[leaden thunder]

.close

[calm coral]

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[tranquil salmon]

can i solve these using fourier transform?

[leaden thunder]

probably overkill, but sure

[tranquil salmon]

if i apply it to both sides

what to do with that 0

transform of 0 ?

[calm coral]

@tranquil salmon Has your question been resolved?

[tranquil salmon]

its zero

.close

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[stray zealot]

I need help with finding the point-slope form and slope-intercept form

[calm coral]

@stray zealot Has your question been resolved?

[stray zealot]

<@&286206848099549185>

[calm coral]

@stray zealot Has your question been resolved?

[calm coral]

@stray zealot Has your question been resolved?

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[stray zealot]

.reopen

[calm coral]

✅

[golden raptor]

ok whats the form of point slope

[stray zealot]

idk

[golden raptor]

ok whats the form of slope intercept

[stray zealot]

idk either, sorry

[golden raptor]

ok so do you know

y-y1 = m(x - x1)

[stray zealot]

nope

I was confused on how to find slope intercept form and intercept point slope form

[golden raptor]

urm maybe just khan academy them

[calm coral]

@stray zealot Has your question been resolved?

[calm coral]

@stray zealot Has your question been resolved?

[calm coral]

@stray zealot Has your question been resolved?

[calm coral]

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[cloud topaz]

What have you tried?

[sweet totem]

Parts but it gives me a weird expression

[digital holly]

Does it?

The first term would evaluate to zero

[cloud topaz]

,tex \int ^{1}_{0}x^{m}\left( 1-x^{n}\right) =\left[ \dfrac{x^{m+1}\left( 1-x\right) ^{n}}{m+1}\right] {0}^{1}+\dfrac{n}{m+1}\int ^{1}{0}x^{m+1}\left( 1-x\right) ^{n-1}

[potent lotus]

Pure
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[cloud topaz]

which implies $$I(m,n) = \frac{n}{m+1} I(m+1,n-1)$$

[potent lotus]

Pure

[cloud topaz]

can you go from here

[sweet totem]

I’m not sure

Can you tell me the next step

[rancid smelt]

This is beta(m+1,n+1)

[cloud topaz]

Take the product $$\prod_{i=1}^n \frac{I(m+n-i,i)}{I(m+n+1-i,i-1)}$$

[potent lotus]

Pure

[sweet totem]

How will this help? Seems random

[rancid smelt]

Do you know wallis theorem?

[sweet totem]

Nope

[digital holly]

The terms will get cancelled in that product

[sweet totem]

I’m not sure how that works

Nvm

[digital holly]

Its similar to of m/m-1 * m-1/m-2 * m-2/m-3

[sweet totem]

I think i got it kinda

Maybe not

[ancient thistle]

[cloud topaz]

🗿

[graceful dust]

☠️

[sweet totem]

I got that I(m,n)/I(m+n,0) = m!n!/(m+n)!

[leaden thunder]

Do you know what these numbers are

[sweet totem]

I think I got it

[leaden thunder]

Maybe when you did your first combinatorics / probability problem

[graceful dust]

i think they have something to do with B(m+1,n+1)

[cloud topaz]

||with I(m+n,0) = 1/(m+n+1) we have I(m,n) = (m!n!)/(m+n+1)!||

[sweet totem]

Yes I got this

[sweet totem]

Wdym?

[leaden thunder]

Are you off by a +1

[sweet totem]

No i got the same thing

For I(m,n)

[digital holly]

Does this integral have combinatorical interpretation?

[ancient thistle]

B(m+1,n+1) certainly does

[sweet totem]

Another question while you’re discussing

[cloud topaz]

f(0)=0 by setting m=n=0

[leaden thunder]

More statistics than combinatorial || https://en.m.wikipedia.org/wiki/Beta_distribution ||

[sweet totem]

Yes I got that

[ancient thistle]

https://en.wikipedia.org/wiki/Beta_function

is a bit more relevant

[cloud topaz]

Setting m=0 and n=s then f(s) = s

[ancient thistle]

f(n) = 0 is crying over here

[cloud topaz]

no more like f(n) st f(n) = s with s being an element of blah

f(m+s) = f(m) + s

ah if we have U subset N0 with a being the least positive integers then we can claim that the multiples of a span the whole set U

do you see why: let u,v in U with u>v and consider u-v

[calm coral]

@sweet totem Has your question been resolved?

[cloud topaz]

Then surely there are infinitely many such f: f(n) = (g(r)+t)a with n=ta+r and define g:{+integers less than a} to N0 with g(0)=r

ie g(r) = f(n)/a

[sweet totem]

I don’t understand

[ancient thistle]

just gon look like a step function or something

f(n) = 0 is a solution

and if f(n) isnt identically 0

you have something in the image of f that is nonzero

call that s

then you can inductively deduce that f(ks) = ks or something

[sweet totem]

Okay

[ancient thistle]

and then the rest of the inputs which arent multiples of s could either also map to themselves

or some multiple of s or something

[sweet totem]

I understood that the gaps between each image is greater than or equal to a from here

[sweet totem]

But don’t understand this conclusion

[cloud topaz]

with n in the form ta + r where r is the remainder we have f(n) = f(r + ta) = f(r) +at = g(r)a + at = a(g(r)+t)

[calm coral]

@sweet totem Has your question been resolved?

[calm coral]

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[calm coral]

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[calm coral]

Please don't occupy multiple help channels.

[coral osprey]

You already have a channel

[remote mural]

Oh I though last one didn't work

[coral osprey]

With the same question

[remote mural]

Sorry

My bad

Can you help me

No one literally

[formal burrow]

this one is tough bro

[remote mural]

Tough question are the best aren't they

Why run from tough questions

[cloud topaz]

Is it ever prime? this is equal to (p+3)(p+5)(p+7)

[formal burrow]

i wrote a python program and there is none in the range of 0 to 100_000 so u are lucky

[remote mural]

I will wolfram this question if nobody can help

[cloud topaz]

.

[formal burrow]

# Python program to display all the prime numbers within an interval

lower = 0
upper = 100000

primes = []
for num in range(lower, upper + 1):
   # all prime numbers are greater than 1
   if num > 1:
       for i in range(2, num):
           if (num % i) == 0:
               break
       else:
           primes.append(num)
           print(num)

print(primes)

# integers which result a prime will be stored in nums
nums = []
for i in range(100000):
    if i ** 3 + 15 * (i ** 2) + 71 * i + 105 in primes:
        nums.append(i)

print(nums)

haha

[remote mural]

Can you show your work

[cloud topaz]

what work

[remote mural]

How did you do it

[cloud topaz]

factor the cubic

?

[remote mural]

Oh

[formal burrow]

https://www.youtube.com/watch?v=vUNgcN6MbjA

[remote mural]

So the final answer is (p+3)(p+5)(p+7)

[formal burrow]

well it doesnt awnser the question rly cuz it doesnt ask u to factor the function, u must also explain why there is no prime number

[remote mural]

Do you know how to do that

[formal burrow]

no sorry

[cloud topaz]

Do you know what prime numbers are

[remote mural]

I don't

🤓

Enough

[formal burrow]

Numbers that are divisible only by 1 and by themselves 😤 except 1

[cloud topaz]

What?

[remote mural]

.close

[calm coral]

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[calm coral]

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[wise kestrel]

How do I work out % in reverse? So for instance if I had, 200 - 15% = 170 but I don't know that first number. All I know is the answer and the % taken away from the original number to get the answer. how do I work out what % of 170 I have to add to 170 to get the original number. Hope this makes sense.

[lusty spruce]

When you calculate it in a "forward" way, you subtract the percentage from 1 (getting 0.85 in this example) and multiply the first number by that, right? Then, to reverse it, you simply need to divide the result by that number. For example, x - 20% = 80. Then x = 80/0.8 = 100.

[wise kestrel]

2 secs sorry, just trying to wrap my head around it

[solid ore]

So if you know that 15% has been taken away and you are left with 170, then 85% is equal to 170, just divide both sides by the remaining percentage (85), and then multiply by 100 to find the original 100%

[wise kestrel]

think I get it, just need to try a few examples to drill it in, thanks a lot guys

[calm coral]

@wise kestrel Has your question been resolved?