help-42

[coral osprey]

What is tan(pi/4)

Because like the answer is just behind that door

[coral osprey]

@sweet pier

[calm coral]

@sweet pier Has your question been resolved?

[sweet pier]

oh my god I completely forgot I had this question up

[sweet pier]

OH SHIT ITS 1 OK

LMFAO

I tried to put it in my calculator like 20 min ago and it was givin a weird decimal

gotta check the mode

but THANK YOU

[calm coral]

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[grand oak]

how do i figure out the number of injective functions here

[calm coral]

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[calm coral]

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[sweet totem]

How to prove that $2a(a^2 +3b^2)$ is not a perfect cube

[potent lotus]

Faq

[sweet totem]

a b are positive integers

[cloud topaz]

(a+b)^3 + (a-b)^3 = 2a^3 + 6ab^2

Then it’s trivial.

[sweet totem]

Oh

Wait how is it trivial?

[shell rune]

Fermats last theorem

[glass heart]

"trivial"

[cloud topaz]

[sweet totem]

I see

Thanks

.closoe

.cloes

[cloud topaz]

.close

[calm coral]

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[shell rune]

If a = b then it is perfect cube ig

[sweet totem]

I meant to say distinct

[calm coral]

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[mental merlin]

did you do addition and subtraction like this fopr whole bnumbers?

one sec

yes

[kind finch]

numbers without decimals

[mental merlin]

okay so show me on 52-17 pls

so we have a common ground

okay let me help you

you go from right to left

calculating 2 - 7

-5

yeah and -5 is smaller than 0 so it kinda fucks up our system

so add a 1 infront of the 2 so we get 12

to make up for it we add another below the next colluimn

[shell rune]

Or always subtract the smaller number from the bigger one
5 - 7 = -(7 - 5)

[mental merlin]

yes

perfect

we apply this to your issue now it function exactly the name but there is a comma in between

[calm coral]

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[shell rune]

-2.5

[calm coral]

✅

[mental merlin]

yeah on sec

is it -4.3 - 1.8?

[shell rune]

-4.3 + 1.8 is the original question?

[mental merlin]

write down exactly what you calculated

[shell rune]

Either it is and im correct or it isnt and we are both wrong

[mental merlin]

like the task

okay

but what is the operation usually it should be there (see photo)

basically it domes down to? are we adding or subtracting 1.8?

and is it really -4.3?

yes

[calm coral]

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[remote mural]

WHO WANTS TO DO SOME SYSTEMS OF EQUATIONS

[remote mural]

WOOT WOOT

Find a cubic function
$f(x) = ax^3 + bx^2 + cx + d$
that has a local maximum value of 3 at
x = −2
and a local minimum value of 0 at
x = 1.

[potent lotus]

MilkMan

[remote mural]

I messed up and created an infinite loop

[pulsar harbor]

how would I take the derivative of this

[remote mural]

ok first of all if you have a question make sure you choose a channel in the math help available channel

otherwise yeah you just use the product rule and then the chain rule
just go on derivative-calculator.net and itll show you the steps

[oblique mountain]

lol are we all using this channel now

[hidden elbow]

yes

[hidden elbow]

use product+chain rule

[oblique mountain]

👍 let me copy my problem here, one sec

jokes aside i hope you get some help milkman

good luck with the scary looking math

[calm coral]

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[remote mural]

dw i discovered wolfram alpha has a system of equations solver

[oblique mountain]

oh haha, nice

[calm coral]

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[final loom]

Help

[remote mural]

alr lemme see

so just graph them

[calm coral]

@final loom Has your question been resolved?

[final loom]

Give me a hint

[remote mural]

it says to use the calclator to graph it

did you do that?

[final loom]

No idk how

[remote mural]

graph the function with a calculator?

do you have a calculator

[final loom]

Yes I do

[remote mural]

do you know how to graph with it

[final loom]

No

[calm coral]

@final loom Has your question been resolved?

[remote mural]

do you know any other way to graph

[final loom]

No sorry

[remote mural]

desmos?

type the equation in https://desmos.com/calculator

[final loom]

Ok

Let’s switch questions

It’s

For question 3

The answer is It is continuous as both equations within the interval are continuous and it is continuous at the boundary (×=0) as both the limit from below and limit from above are the same.

?

[calm coral]

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[red violet]

hello

[red violet]

If 3c +2 ≥ 7, what is the least possible value of 3c-2?
A) 1
B) 2
C) 3
D) 5

I understand how to solve for c in the equation 3c + 2 ≥ 7, but the second part of the question completely confused me

[hidden elbow]

-4 both sides

[red violet]

im confused why subtract 4

[hidden elbow]

so ull get 3c-2 on LHS

[remote mural]

I swear I thought it was asking for the least possible value of c in the original inequality and I was looking at the choices for a good minute being like

Wtf this isn't right

[hidden elbow]

YEAH SAME

[red violet]

I literally didn't understand the 3c-2 like how do I even put it with the first equation

[hidden elbow]

so u now have 3c+2

how do u change the +2 to -2

u subtract 4

[red violet]

oh

[hidden elbow]

cuz 3c+2-4 is 3c-2

[red violet]

OH

[hidden elbow]

and if u -4 on the left hand side

u have to -4 on the right side as well

so 7-4

[red violet]

OHHH

I GET IT NOW

[hidden elbow]

hence $3c-2\leq{3}$

[potent lotus]

Springsskateboard

[hidden elbow]

nice

[red violet]

damn

thanks

[hidden elbow]

npnp

[red violet]

.close

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[calm coral]

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[jolly anchor]

I was just introduced to log and whats the next step pls

[winter hazel]

um

at

$x^{-2} = 2$

$1/x^2 = 2$

$x^2 = 1/2$

then i think u can solve it from here

[jolly anchor]

can u write it clearly pls

[winter hazel]

um

ignore the $

lol

it wlda been clearer

with the bot

:c

[jolly anchor]

but its 2 to power 1/2

[winter hazel]

yea

just

ignore that last step of urs

or

from there u can take the reciprocal

[jolly anchor]

oh its the same thing anyways

[winter hazel]

both works

yes

[jolly anchor]

but can u teach me with what i showed pls

my teacher taught me with root and he wants that in the test

[winter hazel]

take the reciprocal

[jolly anchor]

Its the same methode for the previous one too?

oh i got it ty

.close

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[naive forge]

hello so i have a probleme it is suppose to be easy but i m bad at this lol so i have to solve this : |x+1|-|x-1|<|x+3|

[desert wren]

Consider cases: First see if this holds for x<-3, then for -3<=x<-1, then for -1<=x<1, then for x>=1

[naive forge]

THANKS

.close

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[young flower]

is an asymptote when you input a x value which gives you 2 y values? or does one have to diverge, for it to be considered an asymptote.

[royal salmon]

it's not neessarily 2 y values

like log for example

[coral osprey]

My definition is "a line which the curve essentially gets really close to, so that the distance essentially becomes close to but never 0"

[young flower]

hm mind showing a few examples

[rancid smelt]

The distance can get 0 as far as i know like sinx/x has horziontal asymptote y=0

[coral osprey]

I mean like

How do I explain it

It gets "squeezed" to that

Line

There are cases where it can intersect

[young flower]

so stuff like this

[coral osprey]

Yeah

I guess you can have "curved asymptotes" too, idk if that's what they're called but like

[young flower]

wdym theres no such thing as curved asymptotes

[young flower]

thats not an asymptote, an asymptote is a line which goes along the curve

basically

the one that you just showed

is like a vertical asymptote

if you kept extending it

it would become a line

an asymptote cant be curved in that logic

[coral osprey]

It's a line, yes

[young flower]

exactly

[coral osprey]

Note the quote marks

[young flower]

it cant be curved

[coral osprey]

I know they kinda have a name

They're not technically asympttoes

[young flower]

yes

i see your point

so talking about aymsptotes

i heard about something called a vertical tangent line

is that just asymptote?

[coral osprey]

I would say no because the function is defined at the vertical tangent line

[coral osprey]

Also I found they're called "curvilinear asymptotes"

So you can have nonlinear asymptotes

Like typically a vertical asymptote of a function means the function isn't defined at that asymptote

But a function can be defined at a vertical tangent line

[young flower]

no like

[coral osprey]

Functions are never defined at a vertical asymptote. Functions can be defined at a vertical tangent line

[young flower]

its a different type of thing

but yes

so this for example

wouldnt that be the aysmptote

[coral osprey]

That would, at x = 0

And y = 0

Vertical, horizontal respectively

[young flower]

wdym at y = 0

the function is 1/x^2

we are talking about x

oh mb yes

yes

i see

[coral osprey]

Asymptote :)))

[calm coral]

@young flower Has your question been resolved?

[young flower]

mind telling me the difference between the 2?

[coral osprey]

wdym the two

one is vertical, the function can never be defined there

one is horizontal; sometimes functions can cross/intersect it. But in your case, it never does

[young flower]

no not that

i mean a vertical tangent line vs a vertical asymptote

[coral osprey]

functions are defined at a vertical tangent line, a vertical asymptote is a place of discontinuity

what the tangent line does is give the slope at an instantaneous moment. A vertical tangent essentially means the slope is a vertical line (or undefined)

you can think of it as falling down a cliff instead of running down a steep hill

[young flower]

isnt the vertical tangent line just the derivative

why does the asymptote look eactly like it

[calm coral]

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[calm coral]

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[cloud meteor]

If i am doing a probability

[cloud meteor]

is this correct?

or nay

ping me if you reply

<@&286206848099549185>

[calm coral]

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[low snow]

Hi I am trying to figure out this question I know the answer to "a" is 177 where you just substitute 3/2 to the function but how do you find the range?

[calm coral]

@low snow Has your question been resolved?

[low snow]

<@&286206848099549185>

[calm coral]

@low snow Has your question been resolved?

[thin urchin]

Since it’s a linear function, you know that f(-3) will be the min in your range and f(15) is max in your range. So you could just do f(15) - f(-3) to find the range.

If you think abt the graph of it, it would be a line going up and to the right so as x increases, f(x) increases

[low snow]

so my range cant be bigger than 15 or smaller than -3

[thin urchin]

Well it can’t be bigger than f(15) or smaller than f(-3)

f(15) and f(-3) is different than 15 and -3

[low snow]

so then how would I put that mathematically into my answer

f(15)>y. f(-3)<y?

[thin urchin]

You would write it as f(-3) < y < f(15)

But put the actual number for f(-3) and f(15)

How you write it kinda just depends on how your teacher wants it cuz there are different ways of writing it

[low snow]

so like -399 < y < 1905?

[thin urchin]

Yea

[low snow]

awesome thank you and the the second one you have to substitute and numerical solve right?

so 9.2?

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[low snow]

Thank you so much!

[calm coral]

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[glad trench]

why would sin be negative if 2pi/3 is located on the 2 quadrant?

[dull wagon]

show fullwork

[wanton wave]

pi/12 - 3pi/4 = -2pi/3

not 2pi/3

[glad trench]

ohhhhh

i get it

thanks

[wanton wave]

👍

[calm coral]

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[serene violet]

.

[calm coral]

@serene violet Has your question been resolved?

[serene violet]

can anyone help me how to start this?

I know that $D(I)=D(A\cdot A^{-1}) = D(A)\cdot A^{-1} + A\cdot D(A^{-1}) \rightarrow A\cdot D(A^{-1}) = -D(A)\cdot A^{-1} \rightarrow D(A^{-1}) = -A^{-1}\cdot D(A) \cdot A^{-1}$

[potent lotus]

b3s4d

[serene violet]

.close

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[wind yarrow]

Hi can I get some help with something

[wind yarrow]

Is set C a subset of set B?
When C = ø
B = { -4; -2,5; -0,(3); 0; 2; V11:}

Like okay o stands for an empty set but

[frank gull]

so C is the empty set?

[wind yarrow]

Yeah

But I don't get what an empty set it exactly

And how it correlates

[steep mountain]

Empty set is a subset of any set

Empty set is nothing

Truly nothing

[wind yarrow]

Right

[frank gull]

The empty set is just {}

[wind yarrow]

Then how can it be a subset then?

[oak ridge]

because u could just remove all elements

and get the empty set

its always possible to achieve

[wind yarrow]

Like if we take the example of fitting circles right

How would this work in an image

[steep mountain]

The empty set is the empty box which you place the other objects into

[oak ridge]

if u take the power of any set it would always contain the null set

[frank gull]

consider this as a counter argument. Can you find any elements of the empty set that are not in our main set?

[wind yarrow]

Also how would I need to answer it I assume its not by answering yes right? I need proof for it meaning a well forgot the word not a formula but the equation?

[wind yarrow]

No

I guess it makes sense then

Yeah

Haven't done maths in 2 years

qwq

So would I need to answer it with an equation?

[frank gull]

I would just say that the empty set is a subset of all sets so it's a subset of B

[wind yarrow]

Okay

Thank you for explaining it to me

Cleared it up haha

.close

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[jolly anchor]

How do i solve the 8th one pls

[hasty fiber]

,rotate ccw

[hasty fiber]

Notice that 8 is a quadratic

But with log(x) terms instead of x terms

[jolly anchor]

so do i have to x=y

and how do i find the domain

[calm coral]

@jolly anchor Has your question been resolved?

[jolly anchor]

nice help

.close

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[cobalt jasper]

how can I solve 2^x=x^10

[cobalt jasper]

im not supposed to solve it but im asked where they intersect when x is "very large" but i dont see them intersecting ever again

ive put both in desmos and ive zoomed out a lot and never see them intersect after their firsr positive intersection

[desert wren]

Or are you asked how many times they intersect?

Or how many solutions to that equation?

[warped rampart]

they do intersect eventually, an exponential will always overtake a polynomial eventually

note that x isnt actually very large, just around 60

[cobalt jasper]

how were you able to know it was around 60 so quikcly

i kept zooming out and trying to go up and i couldnt find it ever going far out enough

is there a tool on desmos to be focused on exact points?

[warped rampart]

just by looking at it, you see that its at around $y=5\cdot10^{17}$ where they meet so you gotta go very very far out

[potent lotus]

Duh Hello

[cobalt jasper]

maybe im asking the wrong question but how did you know it was around 5*10^17

[warped rampart]

i did just zoom out

just like you, not sure how ud find it without just zooming. equation solvers seem to not consider the 2nd intersection between the functions so not sure how ud go about doing it any other way

maybe just checking several values. for example if you check 2^60 and 60^10 ull find that 2^60>60^10 and if you check 2^55 and 55^10 ull find that 55^10>2^55 and ull know its between there somewhere

[cobalt jasper]

yea my graphing calculator wouldnt give me an intersection beyond the first one at the beginning

i wish there was a more effiecient way

but thank you

.close

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[south vapor]

Let f be Riemann integrable. Show that the particular integral is a continuous function defined on [a,b] (delta-epsilon proof). Is F also uniform or Lipschitz continuous?

[south vapor]

I dont know how i should continue or simplify the term

*it should be an epsilon instead of delta on the right side of the blue thing

<@&286206848099549185>

[desert wren]

@south vapor Better to try #real-complex-analysis

[south vapor]

ok thanks 🙂

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[calm coral]

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[unborn breach]

I still am unable to make sense of the assignment

[unborn breach]

I need a method to solve this. I have been clued to use the multivariable chain rule. However, as I do not know my f as a function, and its f(j(x,y),k(x,y)) and not f(g(x),h(x)), I am confused.

[calm coral]

@unborn breach Has your question been resolved?

[unborn breach]

Please delete this, I still have an active question in this channel

<@&286206848099549185>

[calm coral]

@unborn breach Has your question been resolved?

[calm coral]

@unborn breach Has your question been resolved?

[remote mural]

you can still use chain rule here

[unborn breach]

I cannot figure out where to apply it. I can find the inner functions, but I do not know what the outer function is apart from f

[calm coral]

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[calm coral]

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[crisp glen]

i need help to do this

[calm coral]

@crisp glen Has your question been resolved?

[tall mason]

do you know how to find a maximum of a function?

[crisp glen]

yes

second diff

and test for <-

<0

[tall mason]

so i don't entirely understand what they're asking

because there is a local maximum

but there is also a infinite increase in profit with more spending

[crisp glen]

yk for this question

is it just asking for first diff

and find x

[hidden elbow]

find first deriv and then second deriv to prove max

[crisp glen]

and then just determine max

ok

the question is just confusing me

[hidden elbow]

#words

HAHAH yeye i get confused too sometimes

[tall mason]

here is the function at the local maximum

but when x goes up and up

it goes to infinity

[crisp glen]

whats the easiest way to find the factor of x^2-64x+960

[hidden elbow]

factors of 960

[crisp glen]

i got it

but i had to do a bunch of guessing tho

i found the answer for 19(b)

how would i find it for (a)

[tall mason]

you found the f(x)?

[crisp glen]

yes

[tall mason]

without finding the x?

[crisp glen]

x=24

[tall mason]

that is the answer for a

or x -> infinity

depending on whether they care about the infinite increase

[crisp glen]

the answer says its 24000$

[tall mason]

ah ok

it says in the question x is in thousands of dollars

so x = 24 means 24000$

[crisp glen]

oh

thanks

.close

[calm coral]

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[regal elk]

I'm writing equatiopns for parallel or perpendicular lines, but I'm having troubles.

[regal elk]

Line r has an equation of y=6/7x + 1. Line s which includes the point (7,-7) and is perpendicular to line r. What is the equation of line s?

[hidden elbow]

perpendicular means

[regal elk]

I wrote y=-7/6x+1 1/7
But I know this is wrong cause it doesn't pass through 7 -7

[hidden elbow]

ur gradient is alr wrong

wait nvm

I saw wrongly

ur grad of first line is 6/7

so yeah grad of perp line is -7/6

so ud have y=$-\frac{7}{6}x + c$

[potent lotus]

Springsskateboard

[hidden elbow]

now u know it passes thru (7,-7)

so plug in x=7 and y=-7

[regal elk]

What is C

[hidden elbow]

and solve for c

[regal elk]

c being y=-7/6x+ c
right

[hidden elbow]

yes

[regal elk]

ok

[hidden elbow]

now substitute

x=7 and y=-7

and solve for c

[regal elk]

How?

[hidden elbow]

x is

7

right

[regal elk]

mhm

[hidden elbow]

y is -7

plug them in

replace x with 7

and y with -7

[regal elk]

how would I do that?

[hidden elbow]

$y=-\frac{7}{6}x + c$

[potent lotus]

Springsskateboard

[hidden elbow]

this is what we have now

[regal elk]

mhm

[hidden elbow]

now when we replace x with 7 and y with -7

we get

$-7=-\frac{7}{6}(7) + c$

[potent lotus]

Springsskateboard

[regal elk]

ok

• 49/6

wait

7/6

Oh I just realized 7/6 is 6th not 7th

ok

ty

.close

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[empty shard]

Hey i am trying to setup a triple integral equation. The question is this:
Use Geogebra to plot the planes $z=x+y$,$x=3$,$y=2$ and $z=0$ and let $D$ be the region inside these planes. Calculate $\int \int \int_{D}2xyz dV$

[potent lotus]

RockLEE

[empty shard]

it seems to look like this

but im not sure how to intepret any of this...

From top view, it looks like a triangle?

So does this mean the double integral part of it is going to be some kind of triangle

[calm coral]

@empty shard Has your question been resolved?

[empty shard]

<@&286206848099549185>

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@empty shard Has your question been resolved?

[calm coral]

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[tribal prairie]

$$ \sum_(n=1)^(\infty) \frac{n!}{n^n + 5^n}$$

[potent lotus]

Timanaku

[tribal prairie]

bottled that but you get the idea

need to show that this converges

tried the ratio test but couldnt seem to get it to work

[carmine sorrel]

Comparison test with n!/n^n

[tribal prairie]

I don't know that converges tho

like I know it does

[carmine sorrel]

then show it converges with the ratio test.

[tribal prairie]

so with ratio test on that

I would get (n/(n+1))^n

not sure where I would proceed

to show that that is less than some number thats < 1

[calm coral]

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[remote mural]

Do you know the outlier formula?

[calm coral]

@cyan oasis Has your question been resolved?

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[livid pilot]

does this make sense

[solar spruce]

how do those last 2 lines work

[remote mural]

yeah my man somehow removed all the x's

[livid pilot]

i thought that was like a rule?? im not sure wasnt it sth like 5x^2 = 10 cuz x^n = nx^(n-1)

[solar spruce]

no

that’s the power rule for derivatives

[livid pilot]

ooh yea right

so the third line from below is the solution?

[solar spruce]

no so

(a+b)^2 =/= a^2 + b^2

and also, (2x^2)^2 is not 2x^4

[remote mural]

let's retrace a bit back

are you trying to find the derivative or something?

[livid pilot]

yes :)

[livid pilot]

is this correct?

[remote mural]

okay doki so

usually i would advise against simplifying quotient rules because you know

[livid pilot]

can i simplify it further?

[remote mural]

no need to make your life harder on yourself

[livid pilot]

wait why

[remote mural]

it takes a while to do all the algebraic operations you did, that's all

[livid pilot]

oh okay

thanks

.close

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[remote mural]

also yeah it seems right so good job

[calm coral]

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[dusky fjord]

Hi! I have a fun problem. So I'm trying to make an algorithm that tells if you have won at club penguins card jitsu, this is the problem:

You have an X amount of victory tokens, which have two characteristics, color and type. Color can be blue red of green and type can be fire, water, or snow.

You win if you have at least three victory points of different colors which must either all be the same element or all different elements.

[dusky fjord]

For example, red fire, blue fire, green fire wins

I have converted the problem into a matrix and found out that if you have won then the matrix can be row reduced into the identity matrix

Is this true?

      Fire  Water  Snow
 Blue   1     1     0
 Red    2     0     0  
 Green  0     1     1

1  0  0
0  1  0
0  0  1

Here you win because you have
Red Fire
Water Blue
Snow Green

[calm coral]

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[calm coral]

@dusky fjord Has your question been resolved?

[calm coral]

@dusky fjord Has your question been resolved?

[calm coral]

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[junior frigate]

im having trouble solving these kinds of questions −5(4x+1)2

[dawn garnet]

why

[wind moth]

Hello

[junior frigate]

i think i understand how i should do them but my anwsers are absolutely different than the correct one

[wind moth]

Can you please rewrite this

[junior frigate]

in what way?

[hidden elbow]

are u sure that’s how it’s written

[wind moth]

yeah that is quite confusing

is it -5(4x + 1) * 2?

[junior frigate]

-5(5x+1)^2

[hidden elbow]

ah

[wind moth]

oh

[hidden elbow]

expand

-5(5x+1)(5x+1)

[junior frigate]

but i have trouble with working away the ()

[hidden elbow]

and use rainbow

🌈

[junior frigate]

Rainbow?

[hidden elbow]

perhaps u learnt it as FOIL

[junior frigate]

is that like the order of operation>

[remote mural]

Gigachad helping giga

What a story

[hidden elbow]

HOLY

I JUST REALISED

[remote mural]

When is mega joining in

[hidden elbow]

IM PART OF HISTORY NOW

[hidden elbow]

lemme be micro

like my..

👀

[remote mural]

[hidden elbow]

ÎQ

[remote mural]

Saved

[junior frigate]

if i try to calculate this on how i think it should be done i end up with -40x +10
the correct anwser according to the test is -80x^2 -40x -5
also maybe i should clarify the question is to work away all the () in the question

i just don't see how i end up with such a different anwser

[hidden elbow]

how did I get 40x

you*

[junior frigate]

the 40x was a typing error i have it as -40x

[hidden elbow]

still

same question

how did u get -40x

[junior frigate]

what tool is usefull for drawing mathmatical equasions

then ill draw out my thinking process

[hidden elbow]

drawing?

u can write it down and take a pic :)

[junior frigate]

sure

[wind moth]

I'm confused
Is it 4x+1 or 5x+1

[junior frigate]

its 4x+1

[winged eagle]

What's your calculation?

[junior frigate]

this is my calculation

[winged eagle]

your calculation is -5(4x+1)*2

[junior frigate]

no the question is -5(4x+1)^2

the awnser i came up with is -40x-10

[wind moth]

First multiply what's in parenthesis

Then get result and multiply that by -5

[junior frigate]

and the correct anwser is -80x^2 -40x -5

[winged eagle]

yes is correct

[junior frigate]

like (4x *4x + 1*1)

[wind moth]

No

(4x+1)(4x+1)

Do this and then multiply it all by -5

[winged eagle]

-5(4x+1)^2= -5(16*^2+8x+1)=-80x^2-40x-5

[wind moth]

yes what he said

[winged eagle]

yes

[wind moth]

Sum of squares to get -5(16x² + 8x + 1) then multiply to get -80x² -40x -5

[junior frigate]

where did the 8x in -5(16x^2+ 8x +1) come from?

[wind moth]

(x+y)² = x² +2xy +y², (4x+1)² = 16x² + 2*4x + 1² = 16x² +8x +1

[junior frigate]

im totally lost rn i tried a few exercies but i am everything but close ill try to find info online thanks for the help anyways

.close

[calm coral]

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[glacial turtle]

Hey

[glacial turtle]

I need help rearranging an equation

[latent steeple]

Provide your question

[glacial turtle]

Sorry for the delay

I need to plot Log U and either Re

but I do not know how t solve this

I tried

using log0.65

and ln

but the math was too complicated for me

is this possible to solve analytically?

I need to then plot this in MATLAB

[latent steeple]

,rccw

[potent lotus]

Couldn't find an attached image in the last 10 messages.

Nov 9, 2022, 10:17 PM

[glacial turtle]

Can you not see the image?

[latent steeple]

rccw

,rccw

[potent lotus]

Couldn't find an attached image in the last 10 messages.

Nov 9, 2022, 10:18 PM

[leaden thunder]

it's just easier if you rotated it

upload again and don't type messages so diesel can rotate it

[glacial turtle]

Sorry

Is this clear?

x/k and f are constants so we can call them delta . (i hope)

the issue is the power of minus 1

Re_h and Re_c are not the same and I'm trying to get U in terms of them so I can plot either Re_h and log U or Re_c and logU.

This equation is for the overall heat transfer coefficient of a plate heat exchanger if anyone's wondering

[latent steeple]

Let the whole thing inside the bracket be a, so:

U = 1/a
<=> aU = 1
<=> a = 1/U

If this helps

[glacial turtle]

hmm okay

ill give this a go

[calm coral]

@glacial turtle Has your question been resolved?

[calm coral]

@glacial turtle Has your question been resolved?

[calm coral]

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[mental wing]

<@&286206848099549185>

[winter hazel]

wow

!15min

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[winter hazel]

binchillin

[wind moth]

-b/6-50=-49,-b/6=1

get b from there

[mental wing]

That was the wrong one srry i meant to put this one, one sec

bru i just got abandon

<@&286206848099549185>

[marble crow]

Dude

[marble crow]

…

Read that

[mental wing]

Dude.

I waited 10 minuutes

this server sucks today bru

.close

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[old stream]

hello

[old stream]

does anyone know if this is an appropriate way of solving integration by parts

this is what the calculator got

but they used synthetic division first

but i'm not sure if the method using the tabular integration is wrong

wait

.close

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[neat grotto]

How can I solve this?

[calm coral]

Please don't occupy multiple help channels.

[neat grotto]

<@&286206848099549185>

[prisma mango]

!15m

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

@neat grotto Has your question been resolved?

[neat grotto]

<@&286206848099549185>

[calm coral]

@neat grotto Has your question been resolved?

[calm coral]

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[lethal shadow]

I know there is relative extrema at x=-2 , 0 , 5, and 6 (because it is undefined) and inflection points at x=1, 2 , 3.5 but where is the 4th inflection point because the choices only give one inf point, two inf points and four inf points, I could only find 3

[calm coral]

Please don't occupy multiple help channels.

[lethal shadow]

.close

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[calm coral]

@whole quail Has your question been resolved?

[whole quail]

<@&286206848099549185>

[jagged sorrel]

alr so you wanna name the triangle first

(srr for the writting)

you can easily see, AB = AC => ABC = ACB (Isosceles triangle)

and then you can also see that ABD = 5x ; ACD = 3x

then you will have DBC = 3x ; DCB = 5x

after that, you will notice 12x + 5x + 3x = 180 degree

=> 20x=180

<=> x = 9

any question ? :DD ?

[whole quail]

Why DCB=5x?

[jagged sorrel]

because ABC = ACB

but ABD = 5x and ACD = 3x

=> DCB = 5x and DBC = 3x

[whole quail]

.close

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[potent lotus]

Yousuf

[jagged sorrel]

the domain of function f(x) here is all real number

alright, the domain of function its like a thing they make to crop out all "x"s that make the function wrong (or some kind, you get the idea)

a small example, if $f(x) = 1/x$

[potent lotus]

Akwjnfwua

[jagged sorrel]

then the domain of function f(x) here is all real number except for x = 0

or if $f(x) = sqrt{x}$

[potent lotus]

Akwjnfwua

[jagged sorrel]

:LL.....

f(x) = sqrt/(x)

then x must be all positive real numbers

hmm, i'll explain to you in an easier way

f(x) = "whatever who cares" have the domain of function all x = real number

if f(x) contains : square roots or some thing like 1/x or 1/x+(whatever)

then you need to take some value of "x" that make the function become nonsense

like anything inside a square root must be positive

or the denominator must be different from 0

you use that and then crop out some value of x

understand ?

[calm coral]

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[remote mural]

Hi there

[remote mural]

Needed help with the second part of this question

I used comparison for the first part and got the right answer

I did the same thing in the second part

However my answer is incorrect

[clear sapphire]

okay so the main point is to write $6-4\sqrt{2}$ as a square

[potent lotus]

Deol

[clear sapphire]

what did you get for a?

[remote mural]

Lemme check

Just a moment

a=4

b=2

OR

a=2

b=4

Are these two system of equations correct?

@clear sapphire you there mate?

[clear sapphire]

the first set of solutions

a=4 and b=2

[remote mural]

Yuppado

[clear sapphire]

sorry

okay so

next question

[remote mural]

What are you getting as the answer?

[clear sapphire]

plug in $\sqrt{a}-\sqrt{b}$ into the $\sqrt{6-4\sqrt{2}}$

[potent lotus]

Deol

[clear sapphire]

for the second one

[clear sapphire]

^^

this

[remote mural]

Nah mate

Don’t think they are related

[clear sapphire]

bro

spot the $\sqrt{6-4\sqrt{2}}$ in the second question

[potent lotus]

Deol

[remote mural]

Oh ok

Gotcha

[clear sapphire]

do you see it?

[remote mural]

Yup

[clear sapphire]

so, plug in $2-\sqrt{2}$

[potent lotus]

Deol

[clear sapphire]

in place of that

and sorry if i am a bit slow

and ping me when you reply

i will be back in a few minutes

[remote mural]

No worries mate

Appreciate the help

[clear sapphire]

,rotate

[clear sapphire]

ye looks like that

why were you getting incorrect answer

[remote mural]

Not sure

But can’t thank you enough for the help

[clear sapphire]

is it correct now?

[remote mural]

Yup

[clear sapphire]

okay great:)

have a good day

[remote mural]

Have a nice day

[clear sapphire]

it was really nice talking to you

[remote mural]

Lol same time

[remote mural]

Same

[clear sapphire]

lmao

[remote mural]

The pleasure was all mine

.close

[calm coral]

Channel closed

Closed by @nimble terrace

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[clear sapphire]

i was faster though lmao 💪

[remote mural]

https://tenor.com/view/respect-salute-military-gif-25703362

[calm coral]

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[toxic blaze]

Hi I'm not sure why im getting an incorrect answer for this question

[toxic blaze]

here's my solution: is there something im missing??

[calm coral]

@toxic blaze Has your question been resolved?

[calm coral]

@toxic blaze Has your question been resolved?

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[atomic blaze]

this is the answer to the question but

i have no idea what they did

i understand that the limit as x approaches 1 of f(x) is f(1)

because its continuous at 1

but what did they do after that???

[calm coral]

@atomic blaze Has your question been resolved?

[atomic blaze]

<@&286206848099549185>

pls

i have a test tmr :')

[topaz path]

Gonna be honest I have no clue how the answer they have is correct

It seems to me that f(1) would have to be 10 otherwise we wouldn't have a defined limit which we do

Wait what is that 2 before f(x)

[atomic blaze]

i believe its 2 times f(x)

[topaz path]

Is that 2.f(x)

Oh

[atomic blaze]

yea they formatted it a bit weird

[topaz path]

Then it would have to be 5

[atomic blaze]

thats one of the possible answers apparently

but i also have no idea how they got to it

[topaz path]

Because you are already assuming that the limit exists you can just do the limit on both sides and then solve for f(x)

And then plug in x

Also idk how they could get 2 diff answers

I gtg

[atomic blaze]

bet

thanks for the help

.close

[calm coral]

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[warm wren]

set f'(x)=0 and salve the quadratic

[queen axle]

Ok would I use the b formula or just find the roots?

Because 4 places are needed

[warm wren]

I assume the roots won't be nice number

s

since it says 4 place of accuracy

so yo uneed quadratic formula

[queen axle]

Ok thank you sm 💕

[calm coral]

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[vocal tide]

Hey does anyone have any knowledge on analysing significant difference of means?

[calm coral]

@vocal tide Has your question been resolved?

[calm coral]

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[remote mural]

calculate how large an area the sheep can graze on. the sheep sits with a rope in one corner of the house. the rope is 2 meters long

[calm coral]

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[calm coral]

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[remote mural]

How do I know who will be 'u' and 'dv'

[pure kayak]

x is algebraic so u is x

[remote mural]

e^x is exponential?

and what about x^e?

[pure kayak]

x^e is still algebraic, e is just a number

e^x is exponential yes

[remote mural]

so that's it?

[calm coral]

@remote mural Has your question been resolved?

[foggy plume]

I think you mixed up your v and dv

[calm coral]

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[hollow bloom]

i just need help on how to work these out

[calm coral]

Please don't occupy multiple help channels.

[hollow bloom]

@glass heart can u help plssssssssss been waiting over an hour man

[glass heart]

channel is open for 4 minutes

don't ping other people to help you

[hollow bloom]

bruh ive had my other one open for ages what do u mean

[calm coral]

@hollow bloom Has your question been resolved?

[calm coral]

@hollow bloom Has your question been resolved?

[calm coral]

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[calm coral]

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[silent roost]

is this legal?

[elfin dragon]

no

[silent roost]

I'm not done typing holmes

$\int sin(x)e^{2x}-2\int sin(x)e^{2x}$

[elfin dragon]

no

[potent lotus]

Dr. Leonard McCoy

[silent roost]

ok go away pls ty

[elfin dragon]

no

[silent roost]

I'm gonna block a mf

[elfin dragon]

no

[silent roost]

$\int sin(x)e^{2x}-2\int sin(x)e^{2x} = -\int sin(x)e^{2x}$

[potent lotus]

Dr. Leonard McCoy

[elfin dragon]

that seems right no cap

[silent roost]

are you just yankin my chain

[elfin dragon]

no

[silent roost]

mr. "no"

[elfin dragon]

idrk integrals yet but why wouldnt it

you could call the intergral "u"

and it makes sense

[silent roost]

it seems valid, but I just wanted to check

[elfin dragon]

ok if theres some technical reason regarding integrals i wouldnt know

[silent roost]

k, I'm gonna wait for a second opinion then

[marsh agate]

Then just leave and let people who actually know answer it

[elfin dragon]

im probbaly right

theres no way its not

[silent roost]

waiting for a second opinion

[marsh agate]

It was ibp on sin(x) e^x right ?

[silent roost]

e^2x, but yes

[marsh agate]

Then there would be a cos somewhere

[silent roost]

right, I didn't type out the whole thing

[marsh agate]

No matter whether you integrate or differentiate sin

[silent roost]

just wanted to make sure that one piece was correct

I think it is

[marsh agate]

That just holds with integrals like with anything else

[elfin dragon]

is there any case in math where u-2u fails to equal -u

i think not

[elfin dragon]

w 😤

[marsh agate]

Don't think so

[calm coral]

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[calm coral]

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[azure bison]

@remote mural okay so