help-42

[wintry glacier]

so how much should it decrease in 100 years

youll need to setup an equation

[crisp glen]

so

the original would be y=ae^-kt

[wintry glacier]

that seems overcomplicated

are you sure

[crisp glen]

-ky

?

[wintry glacier]

?

[crisp glen]

idk

[wintry glacier]

y=ae^-kt -ky?

[crisp glen]

wouldnt decay equation be y=ae^-kt?

[wintry glacier]

why e

[viscid silo]

the decay equation should be given to you

[viscid silo]

I think the radioactive decay equation has an e yeah

pretty standard

[wintry glacier]

huh

ive never seen that

[crisp glen]

im doing exponential growth and decay

[wintry glacier]

but yeah i guess any exponent can be rewritten to an e exponent

alright so a rephrasing of the question could be

what percentage should it decrease such that if it decreases that much 16 times, only half is left

x^16 = 0.5

[crisp glen]

wat

[calm coral]

@crisp glen Has your question been resolved?

[crisp glen]

<@&286206848099549185>

halp please

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[blissful wing]

I am a bit confused on what the question is asking me.

[blissful wing]

Do I make the matrix smaller by getting rid of the rows and column stated in the question and then find the determinant from there?

[calm coral]

@blissful wing Has your question been resolved?

[remote mural]

I think we need to use LaPlace here

[blissful wing]

i dont think i ever learned that lol

I am just confused on what (1,3) cofactor as I only used cofactor expansion across the row / column

[remote mural]

I guess you can use it the definition then

[calm coral]

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[thorny umbra]

okay, I'm just a little confused. how do I get the length of a slope if I know the angle of the slope and the Hight?

[cobalt estuary]

This seems like a trig question. Am I right in assuming that?

[thorny umbra]

umm, not really, I just need to know if there is a function that I can use. i haven't taken trig yet.

[cobalt estuary]

ah

[thorny umbra]

i just wanna know for a game i play.

[cobalt estuary]

I'm not sure if there is a distance formula that doesn't use x and y

ohh

[thorny umbra]

im making something in stormworks if you know what that is.

[cobalt estuary]

yeah I mean if you are using an angle and a side I think you would have to use a trig function

[thorny umbra]

okay, if you can explain it ill see if i can understand it.

there are trig functions i can use in there

[cobalt estuary]

ok

so imagine real quick

that you have a triangle

[thorny umbra]

yeah

[cobalt estuary]

you know the height of the triangle

assume it's right btw

that's your Y chord

[thorny umbra]

k gotcha

[cobalt estuary]

and your angle is the angle opposite of your highest point of the triangle

[thorny umbra]

okay

[cobalt estuary]

Kind of like this

your line A B is what you have

and you know the angle of A

[thorny umbra]

yeah

[cobalt estuary]

but you don't know the x coordinate at B

[thorny umbra]

i don't

[cobalt estuary]

what you do is sin (angle you have) = a /c

you have the angle and you have a

and that formula will solve for your distance c

[thorny umbra]

okay

[cobalt estuary]

does that make sense?

[thorny umbra]

kinda

i could just tell you what i need to know though, i already know the angle and height

the angle of the line is 45 degrees and the height is 600m

[cobalt estuary]

okay so I'll plug in sin(45) = 600/c

one sec

[thorny umbra]

ohhhh that's how that works, okay now I also understand how to use that equation.

i didn't know how that worked but if i just put those values in like that it can work with other paramaters as well?

parameters*

[cobalt estuary]

yes

so in that case it will be 848.528 meters

as long as you are using the same and angle as well as height

like you can't move the angle around or you have to use other trig formulas

[thorny umbra]

okay, thanks I think I understand this now.

yeah I assumed.

[cobalt estuary]

that was a bad explanation

it has to be angle A

not angle B

[thorny umbra]

ohhh, okay then, but i do understand what you mean.

anyways that's all I needed to know thanks!

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[rotund salmon]

am i on the right track?

or should i make the bases 9?

i mean 3

[trail glacier]

no it doesnt really matter

but 3 would be nicer

[rotund salmon]

right, less crazy numbers

[trail glacier]

yeah and you can actually evaluate them straight away

rather than keep writing the log

[rotund salmon]

?

[trail glacier]

yeah looks fine

[rotund salmon]

so now i have

2x = 2x + 35

[ancient thistle]

no you don't

[rotund salmon]

does that look right?

[ancient thistle]

no it doesn't

[rotund salmon]

what did i do wrong?

[trail glacier]

0 = 35

heheheha

[rotund salmon]

right, so

[ancient thistle]

nice

[trail glacier]

u did this

$2\log(x) = \log(2x)$

[potent lotus]

dog.

[ancient thistle]

[rotund salmon]

it should be log_3(x) = log_3(2x+35)/2

right?

[ancient thistle]

yes

[trail glacier]

yeee

[rotund salmon]

ok, so from here

x = 2x+25 / 2

[ancient thistle]

no

[rotund salmon]

right?

[ancient thistle]

no

[trail glacier]

what the hellll

[ancient thistle]

the /2 is outside the log

[rotund salmon]

ok lol ok

[ancient thistle]

you cannot remove the log immediately

[rotund salmon]

even though log_3(x) = log_3(x)

or am i on another planet

[trail glacier]

instead of thinking of evaluating

[rotund salmon]

yeah?

[ancient thistle]

are you saying that if sqrt(x) = sqrt(2x + 25)/2 then x = (2x +25)/2?

[trail glacier]

like setting the inside

equal

[rotund salmon]

nvm

[trail glacier]

think of it as raising 3 to the power of both sides

it will be easier to just multiply the 2

and then u can use log laws

just note x > 0

[rotund salmon]

so i have

2(x^3)

=

[trail glacier]

.

what happened

[rotund salmon]

ok hold on

[trail glacier]

just

[rotund salmon]

i have this

[trail glacier]

$2\log_3 (x) - \log_3 (2x+35)$

[potent lotus]

dog.

[rotund salmon]

ajam

thats the next step

[trail glacier]

yes now u can

move

the 2 into the log

and then equate

[rotund salmon]

what do you mean move the 2 into the log?

[trail glacier]

dont you know log laws

[rotund salmon]

the 2 becomes the expoent, right

?

[trail glacier]

ye

[rotund salmon]

onto x

[trail glacier]

just note that x > 0

if you are solving for real solutions

[rotund salmon]

so now log_3(x^2) - log_3(2x+35)

right?

[trail glacier]

ye

[rotund salmon]

so now i drop the logs?

because log(x) = log(x)/

?

[trail glacier]

yes

[trail glacier]

by reflexive property

[rotund salmon]

ookk, thats what i was after, just a bit early i guess

[trail glacier]

you mean log(x) = log(y) --> x = y

[rotund salmon]

yeah that

[mortal orbit]

what is 3^(log_3(...)) ?

you can use the fact that x = y => f(x) = f(y) using f the very nice function f(x) = 3^x

[rotund salmon]

@mortal orbit question

i currently have another problem...

[mortal orbit]

ask away

[rotund salmon]

and im here

[ancient thistle]

looks like exactly the same problem

just with different numbers

[mortal orbit]

base 5 and 25

[ancient thistle]

repeat previous calculation

[ancient thistle]

but with the new numbers

[rotund salmon]

@ancient thistle i need more practice

but the ending function that i factor is wierd

is it not x^2 - 3x +28?

thats unfactorable

right?

i know im doing something wrong

[mortal orbit]

in real polynomials, yes

[ancient thistle]

do not write - instead of =

[mortal orbit]

you wrote 4 x -7 = 28

[rotund salmon]

so i never move it over?

like a polynomial inequality?

make it = 0

so dont do that right?? lol

[mortal orbit]

the only thing you did is factor by x+4 and x-7, but unfactoring you get x^2 -3x -28

[ancient thistle]

no you have turned an equation into an expression

there is no = sign in the first 3 lines of your working

[rotund salmon]

exactly, that my mistake, right?

[ancient thistle]

no that is a separate mistake

[rotund salmon]

oh k

[mortal orbit]

the second mistake is this

you mixed up + and -...

[rotund salmon]

so the function that i ended up with should be

x^2 - 3x - 28?

[mortal orbit]

• 28

[rotund salmon]

right...

so when does 3x go negative?

[mortal orbit]

you have x^2 - 3x + 28 = 0 resulting from your equation

[rotund salmon]

yes

so thats right?

[mortal orbit]

this is correct starting from the original equation

or rather i should say this is "equivalent" to the original equation

[rotund salmon]

so i factor that and the positive is my answer...

correct?

[mortal orbit]

try to complete the square instead of factoring directly

[mortal orbit]

I'll do it for you because I have to go sleep soon :
(x+ 3/2)^2 - 9/4 + 28 = 0
So (x+ 3/2)^2 +103/4 = 0

[rotund salmon]

ok, so

[mortal orbit]

something non negative + something positive = 0

is that possible ?

[rotund salmon]

no

[mortal orbit]

so what's the answer ?

[rotund salmon]

7?

[mortal orbit]

we just showed that x^2 - 3x + 28 =0 implies impossible

so what are the solutions for x ?

[rotund salmon]

well, 7 was the correct answer when i submitted it to the homework

[mortal orbit]

OH I know why

you have log_5(x^2) = log_5(3x + 28)

So x^2 = 3x + 28

[rotund salmon]

yeah?

ok

so then

[mortal orbit]

So x^2 - 3x minus 28 = 0

[rotund salmon]

yeah

[mortal orbit]

and not + as you originally wrote

[rotund salmon]

then i factor for x+4 x-7

and the negative is 4 so its 7

[mortal orbit]

yes

[rotund salmon]

im sorry

[mortal orbit]

no problem

[rotund salmon]

this is all a bit confusung

.closre

.close

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[swift solstice]

I’m trying to do double conversions and this is the way that I’ve been taught but the answer is wrong in my quiz, wondering if you have an alternate solving method that will give me a different answer or do you see where I’m going wrong?

[swift solstice]

Sorry, should be 10^12pL

<@&286206848099549185>

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[arctic wraith]

how can I proof that 4k^2 + 4k is congruent to 0 (mod 8)? :c

[carmine sorrel]

factor it

[arctic wraith]

4(k^2+k) ?

[carmine sorrel]

keep going

[arctic wraith]

k(4k + 4)?

[carmine sorrel]

4k(k+1)

so you have it's a multiple of 4
You just need to show that k(k+1) is a multiple of 2.

[arctic wraith]

Mmm

k*k = 2k, so is multiple of 2?

[carmine sorrel]

k^2 is not 2k

think about it like this.
If k is even, what can you say about k(k+1)?
If k is odd, what can you say about k+1? and then k(k+1)?

[arctic wraith]

k = 2k, so 2k(2k + 1)

4k^2 + 2k = 2(k^2 + k), then is multiple of 2?

[carmine sorrel]

yep

[arctic wraith]

aaaa and the same when 2k + 1 (2k + 1 +1) = 2 ( 2k^2 + 3k + 1), multiple of 2

thank you so much <3

[carmine sorrel]

nice!

no problem

[arctic wraith]

.close

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[remote mural]

Please explain this derivative:

[calm coral]

@remote mural Has your question been resolved?

[remote mural]

<@&286206848099549185>

[remote mural]

<@&286206848099549185>

[remote mural]

<@&286206848099549185>

[remote mural]

<@&286206848099549185>

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@remote mural Has your question been resolved?

[remote mural]

<@&286206848099549185>

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@remote mural Has your question been resolved?

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[karmic surge]

A funny meme problem - I'm wondering if there is a solution to this that gets rid of the summation

[mighty bronze]

this has got to be

by far

the best "troll" post

i've seen

[karmic surge]

lmao I've been dared to "solve" this and they're saying I'm chickening out by using the zeta function

[mighty bronze]

nah they're just mad they lost

anything is fair game

[wanton wave]

Lmfao, that is the zeta function, what?

[karmic surge]

that makes it easy to solve!

[mighty bronze]

zeta function time to rewatch the 3blue1brown vid abt it again

to remind me why analytical continuation was a mistake

[graceful dust]

you're not going to find a nice form for that lol

[karmic surge]

I assume a lot of constants would start randomly popping up?

[winter hazel]

lol

[graceful dust]

I don't know if you can expect any familiar constants to pop up

[karmic surge]

welp I'll just leave it as is then lol

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[remote mural]

https://cdn.discordapp.com/attachments/905313633142210603/1030341941067534356/IMG_1620.png

[remote mural]

im stuck

im stuck on the part where i have to find the bounds of the integral

through the graph of x = 1/u,
as x->0, u-> inf

but im not sure about x-> inf

[karmic surge]

u -> 0 is right

meaning upper bound is 0 and lower bound is inf

[remote mural]

👍

[lapis rampart]

Isn’t this an improper integral

[remote mural]

to my knowledge, i assume yes

[lapis rampart]

Did your teacher say to substitute the infinity for a variable like t?

[remote mural]

someone in my math group chat posted this challenge question, so there were no teachers

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.close

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[wind quarry]

Can someone please explain this

[wind quarry]

I thought when y = 0 is that not a HORIZONTAl asymptote

[tribal ember]

horizontal asymptotes can be at any y.

in this case its at y = 0

[wind quarry]

How do u graph y = 1/0

The bottom can’t be 0

[tribal ember]

its saying that the roots of the denominator will be where vertical asymptotes are, since then 1/f(x) approaches +-inf

[wind quarry]

Oh yeah so x int of f(x) are thé same as VA 1/f(x)

Or the NPV / VA of 1/f(x) are thé roots of f(x)

That’s what it’s saying?

[tribal ember]

npv?

[wind quarry]

Non permissible value

I get it thanks

.close

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[vernal coyote]

I am confuse

[wintry glacier]

you didnt round up first of all

not sure what theyre asking though

[vernal coyote]

I did round

Says round to the hundredth

I original got 1.178

[wintry glacier]

oh thought they meant round 1.decimals to 1

[vernal coyote]

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[violet glacier]

Given BA = BC and <DAB = < DCB Prove ABCD is a kite

[violet glacier]

How do I prove this? Becuase I need to prove BD and AC perpendicular I think

[velvet osprey]

what are F, E and G?

[violet glacier]

Confused with another question

Fixed

[velvet osprey]

triangle ABC is isosceles by definition, and triangle ACD is easy to prove isosceles too

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[violet glacier]

.close

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[proven dune]

Yes please! I answered 4 but it was wrong, isn’t 4 bigger than 3?

[hasty wraith]

Rewrite the ine bro

Not find the value

[proven dune]

How do I rewrite it what

[hasty wraith]

y > 3

[proven dune]

How do I rewrite that

[winter loom]

They just told you how

[proven dune]

I’m confused

Because it wants the answer next to y

Basically saying “y is what?”

[tacit helm]

So the symbol > Means that the symbol on the left is greater than or more than (bigger than) the symbol (or number) on the right

[proven dune]

Correct

[tacit helm]

< means the symbol on the left is "less than" the symbol/number on the right

[proven dune]

Oh

So it would be 2

[tacit helm]

so if you rewrite the expression with y on the left

[proven dune]

That means 3 is less than y

[tacit helm]

If 3 is less than y,
This also means that:
y is more than 3

the statements are equivelent but written in a different way so to speak

[proven dune]

Ohhh

[tacit helm]

like the guy said, rewritten they just want you to put
y >3

[proven dune]

So it would be 3 since it’s equivalent

[tacit helm]

im out

[proven dune]

I’m confused asf

Coz I can’t input the > on the thing

WAIT I JUST DID

OMG

That? @tacit helm

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[old geode]

Is this wrong

[visual nimbus]

no

[velvet osprey]

does not appear to be wrong as of yet; did you receive indication from somewhere that this is wrong?

[visual nimbus]

-19pi/12 = 5pi/12 +2kpi maybe

[old geode]

yeah im not sure

.close

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[glass meadow]

f(x)=2-(cuberoot(x+1))
Find values for which f(x)=|f(x)|

[glass meadow]

x=-1 ?

Got it

.close

[calm coral]

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[calm coral]

@dreamy spire Has your question been resolved?

[calm coral]

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@junior ruin Has your question been resolved?

[sleek plover]

Let me have a look buddy

If I were you I would integrate both sides between -2 and 2

Then you would get an equation in terms of $\underset{-2}{\overset{2}{\displaystyle\int}}f$

[potent lotus]

black_couscous

ved?

[calm coral]

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[sinful crater]

How do i figure out when sin(t) = arcsin(t)

[sinful crater]

Tried drawing the graphs but that just shows me there is indeed intersections

.close

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[rotund birch]

is there a way to put 3x-2y=40 into a calculator with the value of y as -50/13? I know how to use sto-> but I don't know how to put in 3x-2y=40 into a calculator

[rotund birch]

I have a TI-84 plus CE

[gentle anvil]

why don't you do 3x-2(-50/13)=40

[rotund birch]

I don't know how to put in an = without making it solve it

I know how to put in a quadratic equation but this is just a two variable equation

[gentle anvil]

i don't understand the context whatsoever

[rotund birch]

I figured it out

I pressed math --> C:Numeric Solver --> put in 3x-2(-50/13) in the top box, press enter, then put 40 in the bottom box, press enter, then press graph to solve

then at the end of the answer press math --> frac --> enter

then it's 140/13

:D

[calm coral]

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[pliant snow]

Stuck an yone able to help?

[civic garnet]

commutatie is when the order doesn't matter

[pliant snow]

ok

[civic garnet]

eg: a + b = b + a

or $a * b = b * a$

[potent lotus]

Doug Judy

[civic garnet]

so select the ones that look like these

[pliant snow]

would 2+( 6 +9) = 9+ (2+6) use commulative lawls then?

[civic garnet]

i'd say yes

but that's a difficult one

because bidmas says you do the bracket first right, so that one is interpreted as 2 + 15 = 9 + 8

[pliant snow]

ok

[civic garnet]

it's like they're purposely trying to catch you out, but either way it's not that deep as long as you know that the commutative property just means the order in which the numbers are added or multiplied doesn't matter

[pliant snow]

are you able to tell me the answers as im still confused ahah

[civic garnet]

1 is commutative, 2 is distributive, 3 (i'd say) is commutative, 4 is commutative, 5 is distributive, 6 (i'd say) is commutative

[remote mural]

last one is associative

third too

[pliant snow]

what does that mean

[civic garnet]

ahhhhhhh yes i forgot about that one

[pliant snow]

so is 6 distributive and 3distributive

[civic garnet]

associative mean $a + (b+c) = a + (b+c)$

[potent lotus]

Doug Judy

[civic garnet]

commutative means $a + b + c = c + b + a = a + c + b =$ any other combination (without the brackets)

[potent lotus]

Doug Judy

[remote mural]

Just select those that looks like that

[civic garnet]

^

[pliant snow]

got it thanks

[calm coral]

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[remote mural]

is the answer to this 8; -6

[calm coral]

Please don't occupy multiple help channels.

@remote mural Has your question been resolved?

[remote mural]

If you're not sure you can check with the formula of distance between 2 points

if the distance between A and (0,0) is the same as the distance between (0,0) and B it's good (origin is the midpoint and you have the segment AB)

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[dense knot]

Is this free to claim?

[graceful dust]

yep, it's yours now

so actually I guess it's not free to claim anymore, but it's your channel

[dense knot]

Oh, is it free?

[graceful dust]

yep

[dense knot]

Okay sorry lol, as you can tell I get confused easily

[graceful dust]

loll sorry I was just messing around

[dense knot]

Its okay, I just need math help lmao

It’s due in like a two hours and I got a 22/100 score on my Econ homework 😭 and I have two more tires to fix it

Anyways, this is the math I’m confused with

I literally have no idea how to solve it even when I look back at my notes which are the same ones as my professor

[jaunty sigil]

Qn 1: equilibrium is reached at the output level where L^s = L^d . Using the given info we can form an equation as such :

10L^s + 40 = -20L^d +100

find equilibrium quantity of labor

[winter hazel]

oh my is that not subscript? its super

[jaunty sigil]

Qn 2: equilibrium wage (w^x) = 10(2) + 40

Qn 4: required L^s at minimum wage at 70$ is
L^s = 0.1(70) - 4

Qn 5: required L^d at minimum wage at 70$ is
L^d = 5-0.05(70)

[calm coral]

@dense knot Has your question been resolved?

[dense knot]

Everything is great, I just needed to Calculate it into a number. I also need this graph help though

[calm coral]

@dense knot Has your question been resolved?

[calm coral]

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[remote mural]

completely forgot how to do this, i know distance formula & such but i dont know what to do from there

[remote mural]

YZ is 7.1 (rounded

[winter hazel]

idt we need yz

we just find wx

same way u found yz

but swap the numbers

[remote mural]

would wx not just be 2?

[winter hazel]

er

i think not

[remote mural]

😭

[winter hazel]

its like

uve to use

euclidean dist formula

pyrawr?

[remote mural]

OHH

Ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

[winter hazel]

yes

[calm coral]

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[dusk basin]

hi, could someone help me with this question?

[dusk basin]

im given r = 12 and h = 4

[leaden thunder]

are you supposed to use a given formula or derive it using integration?

[dusk basin]

integration sorry haha

using slices

[leaden thunder]

do you know how to set up the integral?

or even know the function to set up the integral?

[dusk basin]

yeah I'm struggling to find the function

[leaden thunder]

i'm not 100% sure since usually you're given more information about the radius of the whole sphere

do you have anymore information?

[dusk basin]

no

I also didn't realize that this is what a spherical cap is 🤦‍♂️ thought I was looking at half of an elipsoid

[leaden thunder]

here, it looks like a=r and you're not given unknowns theta or R

unless that cap is just a hemisphere

which then it's stupid to call it a spherical cap

[dusk basin]

it can't be because the height and radius aren't the same

[leaden thunder]

oh yea that too

[remote mural]

doesnt the second formula work?

[leaden thunder]

Oh yes you're right

[dusk basin]

I need to use a slice of the cap though, I can't just use the volume formula

[leaden thunder]

you just assume a radius R > r, then your function is

$\sqrt{R^2 - x^2}$

[potent lotus]

riemann

[leaden thunder]

then you calculate the integral from 0 to r

https://www.cuemath.com/measurement/volume-of-a-section-of-a-sphere/

I guess the occurrence of the variable R will disappear

[dusk basin]

how do you do just step one?

[leaden thunder]

this is basically it

[dusk basin]

what is x in that equation?

[leaden thunder]

a variable in this range

[calm coral]

@dusk basin Has your question been resolved?

[dusk basin]

.clse

.close

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[mental rock]

Idk how photomath got 4-4X-X^2

[hidden elbow]

aye aye

wassup

eh

it just

squared

both sides

to remove the square root

[mental rock]

Yeha but how did they add another 4

Its confusing

[hidden elbow]

wdym

add another 4

$(x+2)^2 = (x+2)(x+2) = x^2 + 4x+4$

[potent lotus]

Springsskateboard

[hidden elbow]

it is not

x^2 + 4 btw

[mental rock]

Uhhhhhhh

[hidden elbow]

https://youtu.be/63oU-AIzTcE

here

watch from

3:48 onwards

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[stone goblet]

Inequality

[stone goblet]

U can flip that image using textit

I don't know how to

Pls ping when replying

[amber wedge]

,rotate

[wintry glacier]

prove with peano axioms?

[stone goblet]

Wut

Were supposed to do with basic thingies

The first theorems you learn in inequalities

[wintry glacier]

what were you given as theorems then

[stone goblet]

If a < b b < c

Blah blah blah blah

The very first therems you learn

The common sense one

[cloud topaz]

$a<b \implies a+c<b+c$ and $c<d \implies b+c<b+d$

[potent lotus]

Pure

[cloud topaz]

This probably works

[stone goblet]

Explain

How did u substitute in that c for d

[cloud topaz]

I didn’t substitute anything

[stone goblet]

D for c

In the end

After stating c was less than d

[cloud topaz]

c<d add b to both sides

[stone goblet]

Oh

Thats

Incorrect

A + c < d + b

[cloud topaz]

Yeah $a+c<b+c$ and $b+c<b+d \implies a+c<b+d$

[potent lotus]

Pure

[stone goblet]

Ah got it

Thank u

And

For proving

If a > b
-a < -b

@cloud topaz

[calm coral]

@stone goblet Has your question been resolved?

[stone goblet]

Anyone else?

Use another channel

[cloud topaz]

$a>b \implies a-a-b>b-a-b \implies -b>-a \implies -a<-b$

Probably enough

[potent lotus]

Pure

[calm coral]

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[stone goblet]

Thank you so so much

[calm coral]

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[amber wedge]

does a parallelogram have equal diagonals?

[amber wedge]

.close

[calm coral]

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[urban yoke]

What is the difference between integers x and y?

[sick plover]

Wdym?

[glass heart]

x-y

[calm coral]

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[dawn roost]

The asnwer is negative infinity I odnt understand why I keep getting either 1 or undefined

[sick plover]

Explain your answer

[dawn roost]

So since they said they want the limit of cscx as x approaches 0-

I tried writing 1/sinx instead of cscx isnce it's the same thing I i still kept getting 1/0 which is undefined

[sick plover]

You can't plug in x = 0

You need to see what happens to the function when you get close to 0 from the right

Which you can do graphically

Or numerically

But the problem says graphically

[dawn roost]

How can I do it this way?

Becuase I can't graph this later on in exams and the teacher wants us to solve it

[sick plover]

Well, plug in values

What's csc(0.1)?

csc(0.01)?

csc(0.001)?

[dawn roost]

Something in the five hundreds if I'm not mistaken

[dawn roost]

But yeah it gets larger here

[sick plover]

So what's happening as we get really close to 0 from the right?

SHIT

It's supposed to be left

lim x->0^-

[dawn roost]

Basically the same asnwer but with minus

[sick plover]

Then it would be csc(-0.1), csc(-0.01), csc(-0.001)

[dawn roost]

So as we approach zero from the left it goes to negative infinity

[sick plover]

Yes

[dawn roost]

I got it thank you so much for the help

[calm coral]

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[calm coral]

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[sage socket]

I am studing vectors and matrices

[sage socket]

and i have a question

about transformation of vectors

the matrix at the top represents to transformed values of i and j

but these arent scaled

as i has points 1,0 and j has points 0,1

then he goes on to find the transformed coordinates of vector 5 7

by multiplying it by the new i and j values

essentialy scaling the coordinate points

but how can he scale them

https://www.3blue1brown.com/lessons/linear-transformations 6:53 of this video

.close

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[jolly mason]

please help.

[calm coral]

@jolly mason Has your question been resolved?

[calm coral]

@jolly mason Has your question been resolved?

[calm coral]

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[unique kindle]

can someone help me with basic geometry

[teal coral]

okay do you understand the diagram

[unique kindle]

yes

linear pairs?

[teal coral]

what do you mean by that?

like do you just understand the notation on the diagram?

[unique kindle]

yes

[teal coral]

do you understand what you're given?

[unique kindle]

the intersect part no

[teal coral]

do you know what intersect means?

[unique kindle]

yeah

[teal coral]

so if I say that two roads intersect at a town, do you know what I mean by that?

[unique kindle]

yes

[teal coral]

do you know what ABD with the arrow above it means?

[unique kindle]

ray

[teal coral]

and I'm guessing you know what a ray is

so that sentence is basically saying that the two rays meet at point A

just like how I might say two roads intersect at a town

[unique kindle]

yes

thats not telling me anything

[teal coral]

your givens are drawn in the diagram to the right

you're given something else too

[unique kindle]

my question is what do i do next after the givens

[teal coral]

obviously that's the question

but you need to understand the givens to come up with an answer

[unique kindle]

okk

[teal coral]

problem solving is about understanding what you have and what you need to get to

[unique kindle]

i got you

[teal coral]

so do you understand the diagram and your givens?

[unique kindle]

yes

[teal coral]

now do you understand what you have to prove?

[unique kindle]

yes

[teal coral]

state it in your own words

for example, I might say that you're given that the two angles at the bottom of the triangle are the same size

state what you have to prove in your own words

[unique kindle]

how angle dbc equals to angle ecb

[teal coral]

angle dbc and ecb are the obtuse angles under the triangle, yeah?

[unique kindle]

yeah

[teal coral]

why, in your words, do you think they should be equal?

[unique kindle]

i do but idk why

[teal coral]

imagine you break the triangle apart at point A

and break the red line in half too

do you see how you can get the thing on the right

[unique kindle]

linear pairs

[teal coral]

what does that even mean

math isn't about applying big words to things

most of it is just steps of common sense logic, though sometimes you have to be careful

[unique kindle]

linear pairs basically mean they share the same line

[calm coral]

@unique kindle Has your question been resolved?

[calm coral]

@unique kindle Has your question been resolved?

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[hollow pine]

is this d

[tawny sinew]

Eliminate statements as you go
1 is clearly not right
2 is definitely right
That only leaves you with d

[hollow pine]

ye thats what i did

[tawny sinew]

So yea d is correct

[hollow pine]

bet

[calm coral]

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[remote mural]

Help

[remote mural]

Anyone teach me 😭

<@&286206848099549185>

.close

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[honest arch]

Can someone explain the reasoning between questions ii and iii

[calm coral]

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[honest arch]

Can someone explain the reasoning behind question 3iii? Why do I multiply?

[honest arch]

As for this one, why do i multiple by (2x2)

[somber cedar]

Dang good question

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[remote mural]

does n = 55? n-13
---- = 3.5
12

[remote mural]

(just wanted to make sure

[karmic wigeon]

cant understand ur question

[remote mural]

hold on

its like the little fraction division sign thing

the line that divides things

you know

hold on

[karmic wigeon]

write it somewhere and take a screenshot or smth

[remote mural]

(n-13)/12 = 3.5?

[karmic wigeon]

oh yea

[karmic wigeon]

ur correct

just substitute n = 55

and see

it works

[remote mural]

kk thx

[remote mural]

ye

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[jolly mason]

about boxplots. has to be a integer

[jolly mason]

I dont know how that will help me understand

ahh i see thanks

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[lusty kayak]

Hello

[lusty kayak]

The question states that X is evenly dividable with both 6 and 9, what other evenly number below must it also be divided with.

From what I can tell it works for both 18 and 72, but the asnwer it stats is 18, why?

[humble ivy]

well, since it is divisible by 9 it has 2 factors 3 and since it is divisible by 6 it also has 1 factor 2

divisible by 6 also means one factor 3, but that could be one shared with 9

so its factors are at least 2, 3 and 3

[lusty kayak]

I still dont get it 😦

[humble ivy]

why did you think 72?

[lusty kayak]

Its possible im reading the question wrong, but when you divide 72 with 6 and 9 you get even numbe

[humble ivy]

well, 36 is divisible by 9 and 6, right?

[lusty kayak]

yea

[humble ivy]

but it isn't divisible by 72, because 36 / 72 = 1/2 and 1/2 is not an integer

[lusty kayak]

ah right

you checked by multiplying 18 with 2

well

thats one way to do it

[humble ivy]

yeah, I chose 36, because it wasn't an answer, so it wouldn't be confusing

not per se multiplying by 2

54 would've worked as well

or 90

[lusty kayak]

Soryr I have been studying all day, my brain doesnt want to understand it

lol

[humble ivy]

just look at the numbers 9 and 6 and check which new factors they introduce

[lusty kayak]

a 2

3*

wait

6 is 26 and 9 can be 33

[humble ivy]

9 introduces 2 factors 3, and 6 introduces 2 and 3, but we already know there were 2 factors 3, so only the 2 is new

use spaces in between *

[lusty kayak]

oh my bad

I think i need a break

[humble ivy]

it's fine

[lusty kayak]

Thanks for the help tho, I appreciate it, I will revisit this once I have a rest 😄

have a good evening

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[kindred thistle]

In how many ways can a committee with nine members form a subcommittee with at least one person on it?

[main adder]

What?

@calm coral

[desert wren]

@kindred thistle What do u think/

[kindred thistle]

511

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[pure bronze]

How to do this question?

John can finish a job alone in H hours, while Peter can finish it alone in (H+3) hours. If they work together, they can finish the job in 2 hours. Find the value of H.

[loud obsidian]

So you can do it like this

John can finish the job in $h$ hours $ \implies $ Work done by him in one hour = $\frac {1}{h} $

[potent lotus]

n11

[loud obsidian]

Similarly, work done by him in 2 hours will be $\frac{2}{h}$

[potent lotus]

n11

[loud obsidian]

We can do the same for Peter — work done by him in 2 hours will be $\frac{2}{h+3}$

[potent lotus]

n11

[loud obsidian]

Now both of these works make up $1$ work done

[potent lotus]

n11

[pure bronze]

oh right average in one hour 🤦‍♂️ i forgot

[loud obsidian]

Sum of these will be 1, and we get a quadratic equation

[pure bronze]

wait so do i just add $\frac{2}{h+3}$ and $\frac{2}{h}$ and the sum is 1?

[potent lotus]

mars_gorilla

[loud obsidian]

I believe yes

h+2*

$2h+2h+4=h^2+3h$

[potent lotus]

n11

[loud obsidian]

oops... 2h* lol

[pure bronze]

oh ok thx i'll try it

[last atlas]

And also, you'll very likely get one negative root. So you need the aditional constraint that h > 0.

[loud obsidian]

right!

[pure bronze]

i got it yas

[loud obsidian]

no wait h+3 is correct
sorry lol I got confised

confused*

[pure bronze]

thx guys 😄

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[lyric magnet]

Could someone explain this to me please?

What’s the value for f(4) is -4

There’s some wacky rules they’re pulling to deal with this, Symbolab shows the same thing, but I do not understand at all what is happening here

This is calculus

Eh

Oh, I think I figured it out, it’s e derivative law and then chain rule on the exponent of e

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[kindred thistle]

A bowl of ‘fun-sized’ treats contains 4 boxes of Smarties, 7 Mars bars and 6 Twix bars. How many different ways are there to make a snack of these treats if a person has to have

At least one treat?
At least 3 Mars bars and exactly 2 boxes of Smarties?

[kindred thistle]

is this for me

.close

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[sage socket]

To double check

In this triangle

If given angle b

It is impossible to find out the area

[wintry glacier]

impossible indeed

[sage socket]

Thanks

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[ancient thistle]

you sure you aren't given more than that and you're just making assumptions?

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[tender current]

Confused about number 54

[tender current]

Why does it have a degree symbol if it’s in radians?

Is radian degrees a real unit?

[amber bolt]

no, it's gotta be a typo

ignore the °

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[maiden zenith]

since I have forgotten much of the linear algebra i learnt

<@&286206848099549185>

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@maiden zenith Has your question been resolved?

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[remote mural]

s

[remote mural]

Am I doing this correctly?

<@&286206848099549185>

[latent steeple]

!15min

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[remote mural]

oh

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@remote mural Has your question been resolved?

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@remote mural Has your question been resolved?

[remote mural]

<@&286206848099549185>

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[faint lion]

My channel closed without an answer and someone typed in it before i got there

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