@clever thorn Has your question been resolved?
#help-42
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clever thorn
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remote mural
“Explain why the angles are congruent” why are do they both measure to the same measurements
clever thorn
so like a rectangle has 4 90* angles, because of this if you fold then you create 2 supplementary angles that are therefore congruent
idk
remote mural
I personally would say that’s a good response
But I’d personally say
“A rectangle has four 90 degree angles so therefore when you create two supplementary angles, it causes the angles to be congruent”
I hope you understand it now 🤔🤷♂️
calm coralBOT
@clever thorn Has your question been resolved?
clever thorn
But I’d personally say
“A rectangle has four 90 degree angles so therefore when ...
yes, thanks a lot
sorry for the late response
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devout wedge
Ive tried looking up examples and looking at info videos for help I just really dont understand this
severe scarab
angle 2 and angle 7 are congruent
so you can set them equal to each other
2x+33=4x-70
devout wedge
I know they have to equal to 180 together
but I dont know how to actually do the math
severe scarab
you mean the algebra?
devout wedge
yea
severe scarab
so you want to have all your variables (the x's) on one side
to do that I will subtract 33 from the left side of the equation
devout wedge
ok ima do this in microsoft paint real quick
severe scarab
actually adding 70 is much more easier
you add 70 to both sides
-70 on the right cancels out
devout wedge
so 103 right
severe scarab
correct
devout wedge
so 2x+103
severe scarab
yes
devout wedge
51.5
devout wedge
but if both sides have to add up to 180 would that make my awnser 128.5?
severe scarab
gimme one sec please
devout wedge
sounds good
severe scarab
hmm this is weird cause 51.5 is the right answer
devout wedge
can the answer even be a decimal
devout wedge
so that's the answer?
severe scarab
if i'm not mistaken then yes
devout wedge
alright apreciate it
severe scarab
yeah np
tacit linden
devout wedge
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remote mural
Is it possible to add the sin functions to make one sin function and then use that to find the period?
calm coralBOT
Is it possible to add the sin functions to make one sin function and then use th...
@remote mural Has your question been resolved?
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calm folio
I'm not sure about how to properly say this in english, but I'm trying to find the implicit derivative of something, and I'm wondering when finding the derivative of sin(x^2y) if thats cos(x^2y)(2x*y') or if you have to use the product rule to find the derivative of the core first
hollow totem
u do chain rule first since it's the outermost part
but after that you need product rule to get (x^2y)'
calm folio
but using the chain rule, dont I have to use the product rule? Or do I not because its 2 diffrent variables even though they are connected
hollow totem
since neither x^2 or y is constant
hollow totem
but using the chain rule, dont I have to use the product rule? Or do I not becau...
Yeah
calm folio
so then it would be cos(x^2y)(2xy+x^2y')?
hollow totem
yeah
calm folio
alright thanks
do you know if theres a tool to calculate a long implicit derivation? its so long that Im sure to have some stupid mistakes and would be nice to check if I got it right
I tried some but they gave some really long answers even though I know its supposed to be simpler
for refrence I want to find y''(0) of ln(1+2y)+sin(x^2y)=2
hollow totem
1 sec
not one in particular that I know of
You could graph the graph using desmos
and look at what you think the slope (y') is
and if it matches
calm folio
Im pretty sure I just have to find an expression for y'' that will contain x y and y' and then put in y(0), y'(0) and x=0 but yeah the problem is that its such a long solution for the y''
hollow totem
ah yeah that makes sense
there's probably some online calculator that can do it
if you haven't searched for one worth a try
calm folio
I wonder, can I put in values for y and y' as I go? or do I have to get the proper expression for y'' first
I tried a few but didnt really get it to work 😅 but I'll try a bit more
hollow totem
,w second derivative of y^2+xy+x^2 = 0
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calm folio
alright, thank you for helping 😄
calm folio
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weak grail
can you find both a and b in the pythagorean given only c?
calm coralBOT
can you find both a and b in the pythagorean given only c?
jaunty sigil
apply toa cah soh when appropriate
weak grail
no angle
impossible right?
unless maybe your given perfect square?
like in a 3,4,5
ok, only given 90 degrees, how would i do it
carmine sorrel
even then, there are lots of right triangles with hypotenuse length 5
carmine sorrel
without any other information (are they integers?), you'd at best, have a solution set of possible choices that would end up being part of a circle
carmine sorrel
then yes, you should be able to do this without any other information.... i think
weak grail
im thinking
if you are given a perfect square for c, then the a and b must also be perfect squares
??
carmine sorrel
if everything is an integer, the only solutions would be pythagorean triples.
Given C, you can identify which triple.
carmine sorrel
if you are given a perfect square for c, then the a and b must also be perfect s...
nope
3^2 = 1^2 + (2root(2))^2
calm coralBOT
@weak grail Has your question been resolved?
weak grail
if i need an equation to figure out a and b, given c, what would i write
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quiet folio
rare tiger
Write 2 equations at t=0 and t=3 given the information you have in the question
After that we can find a and k
@quiet folio
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@quiet folio Has your question been resolved?
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pliant fern
Hi can someone help me to find my mistake here?
calm coralBOT
Hi can someone help me to find my mistake here?
pliant fern
Answer should be 13/3, but I’m keep getting. 11/3
pliant fern
g’(x) =1?
vernal plaza
you let g(x) = $\sqrt{2x+1}$
potent lotusBOT
duckiescute!
vernal plaza
so g’(x) = $\frac{1}{2}(2x+1)^{-\frac12}(2)$
potent lotusBOT
duckiescute!
vernal plaza
so you left with (2x+1)^(-1/2) for g’x
pliant fern
Where does last 2 came from?
pliant fern
So, first, different the y=u blah blah blah, the times with u ‘ at the end
*then times
pliant fern
Really appreciate for ur help
vernal plaza
no prob!
pliant fern
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pliant fern
Can someone help me to find my mistake here?
calm coralBOT
Can someone help me to find my mistake here?
pliant fern
Until the 4th line, I’m correct, but when I sub (3, 29/4) in, something wrong with my c value
Pls, I can’t use calculator here
winter hazel
,calc 2/3(9^(3/2))
potent lotusBOT
Result:
18
,calc 29-72+9+18
potent lotusBOT
Result:
-16
pliant fern
Okay
winter hazel
u shld get c=-4
calm coralBOT
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solar spruce
i have to show for a finite $S\subset\mathbb{Q}$, $\langle S\rangle$ is cyclic. i believe that $\langle\text{GCF}(S)\rangle = \langle S\rangle$. is my intuition correct, and is this that the right approach?
potent lotusBOT
maximo
velvet osprey
sure, so long as you define what GCF means for a finite subset of Q
ancient wren
maybe think of whether all your elements can be obtained from 1?
actually this prob devolves into the same argument as yours
calm coralBOT
@solar spruce Has your question been resolved?
solar spruce
hm maybe i can show it's isomorphic to some subgroup of Z
or just isomorphic to Z at that point
the isomorphism should be something like phi(a) = LCM(denominators of S) * a. i think im back to the same thing with LCMs now instead of GCFs
solar spruce
hm ok i have something going here i think
let $d:\mathbb{Q}\to\mathbb{Z},, d(\frac{p}{q})=|q|$, and $q\overset{def}=\prod_{s\in S}d(s)$. \
now let $\phi:S \to \mathbb{Z},,\phi(s)=qs$. $\phi$ is well defined since we multiply by at least the denominator of every $s\in S$.\
$\phi$ is a bijection, and $\phi(s_1 + s_2) = q(s_1 + s_2) = qs_1 + qs_2 = \phi(s_1) + \phi(s_2)$\
i guess all that's left to do is to show $\phi:\langle S\rangle\to c\mathbb{Z}$ is an isomorphism for some constant c, and we know $c\mathbb{Z}$ is itself cyclic
i think that makes sense, please let me know if it doesn't
potent lotusBOT
maximo
solar spruce
im so bad at using lcms gcds and stuff though. that last part definitely needs some playing around with those to find a suitable c
if it didn't show this is me trying to avoid using lcms and gcds at all costs lmao
calm coralBOT
@solar spruce Has your question been resolved?
solar spruce
ok so for this to work i need to somehow show $\psi:\langle S\rangle\to\mathbb{Z},,\psi(s)=qs$ is well defined.\
my idea is to let $s' = \frac{1}{q}$, $q$ as defined above. then clearly $\langle S\rangle\le \langle s'\rangle$ since every $s\in S$ is a multiple of $s'$.\
so finally, since $qs'=1,\psi(s) = qs=q(cs')\in\mathbb{Z},\forall s\in\langle S\rangle$\
thus $\psi$ is well defined, a bijection, preserves group operations, and so is an isomorphism
potent lotusBOT
maximo
solar spruce
god what a terrible proof
i don't even know if it works
aaaahhhhhh its not an isomoprhism to Z but to cZ for some c in N
solar spruce
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remote mural
I would like to ask how tanx derivative is sinx/cosx?
calm coralBOT
I would like to ask how tanx derivative is sinx/cosx?
fleet peak
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ohNoiAmHere
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hollow hamlet
i dont understand how to simplify this can you explain as well
dim ibex
Well to start
You can see that 6*5^k and 5^k share common factors so they can be simplified
and then there also the -6 ... +5
dim ibex
yeah, but see that 6*5^k-5^k can be simplified
you can take 5^k out as a factor
to get 5^k (6-1)
hollow hamlet
where does the -1 come from sorry
so it would come out 5^k(6-1)
5^k*5
w exponential rule
5^k+1
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flint mist
I dont understand what it means by reflect on y = -1
calm coralBOT
I dont understand what it means by reflect on y = -1
manic mist
I dont understand what it means by reflect on y = -1
its like reflecting it across the y axis
but this time, instead of y axis, its the line y=1
limber delta
you're creating a new password for your sachool email, your passsword must be 8 letters long. You can use uppercase letter, lowercase letter, or numbers as part of your password. Because you're not very savvy about password security, you decide to include the 4 didgit of your birth year and your 4 favourite alphabets, to be arranged in any order. How many different passwords are possible that dont start with a 0 or end with a 0
limber delta
my birth year is 2005 and 4 favourite alphabets are H R W S
useful for the question
fierce mulch
So you can only use the letters h,r,w,s and numbers 2,0,0, 5 and use each once ?
fierce mulch
How many options are there for character 0
limber delta
Character 1
it can be 7 things
fierce mulch
Yep
fierce mulch
but that 6 can be in any place
Idk what you mean by this
limber delta
combinations adn permutations?
we are supposed to use that
are you there?
<@&286206848099549185>
fierce mulch
I was just having a think I don’t think I can help you W this cause the way I’d go about it is different sorry
limber delta
its okay no worries
manic mist
you're creating a new password for your sachool email, your passsword must be 8 ...
I think I would solve it by first ignoring the condition for start/end with 0. So just count how many ways to arrange the 8 letters and digits. Then, you subtract how many ways there are if 0 is the first digit, and then if 0 is the last digit.
limber delta
hello again! @manic mist
so to arange 8 letters and digits you could do 8C1 x 7C1 x 6C1 x 5C1 x 4C1...
manic mist
so to arange 8 letters and digits you could do 8C1 x 7C1 x 6C1 x 5C1 x 4C1...
Yes, or just permutations of 8
Cause xC1 is just x
manic mist
Idrk you can ask someone else if they write permutations like that, but yes, just 8 x 7 x 6… x 1
manic mist
Ok I gtg, hopefully you can solve the rest. Sorry 🙁
manic mist
Nvm I just realized how inefficient my way was
Find someone else, if not, I’ll be back in a few hours and can explain
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restive mason
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thick pond
What have you tried?
sly python
Idk if this is how I'm supposed to ask for help but yeah I would like some lol
teal coral
Idk if this is how I'm supposed to ask for help but yeah I would like some lol
I guess you could use Newton's method to approximate it?
since you're given the possible answer choices, the real thing here is just to plug them in
calm coralBOT
@sly python Has your question been resolved?
sly python
since you're given the possible answer choices, the real thing here is just to p...
it is a study guide for a test that is not multiple choice so I need to know how to do it, ya know? But I appreceate the suggestion!
teal coral
you could use the cubic formula, but that's clearly not what they want
your best bet is probably Newton's method, which just locally linearizes the function
sly python
your best bet is probably Newton's method, which just locally linearizes the fun...
I'm unsure what that is but will Google and get back to you, thank you for the assistance
Thanks!
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gaunt vortex
How would I answer a question like Mr Manku is preparing an acidic solution for his science class. He mixes a 25% acid solution and a 15% acid solution to get 100 mL of 19% acid solution. How much did he mix from each solution?
carmine sorrel
system of equations
gaunt vortex
What would the equations look like
velvet osprey
the variables are the amounts of each available solution going into the mix, and the equations describe the total volume of the mixture and the volume of acid therein
gaunt vortex
Adam invested $10000 into two accounts: one earning 8% interest and one earning 12% interest.
After one year, the 12% investment has earned $480 more than the 8% investment. How much was invested into each account?
gaunt vortex
How would I do this too
velvet osprey
you have two unknowns here
the amounts invested into each account
make a variable for each & convert the problem statement into equations
gaunt vortex
Can you show me how to do that?
velvet osprey
let x be the amount invested at 8% interest and let y be the amount invested at 12% interest, both in dollars
the total amount of money we invested into our two accounts is $10,000 therefore x + y = 10000
this is the variable declaration and one of the two equations
do you understand what has been written thus far?
gaunt vortex
Yes
velvet osprey
do you understand how to write down the other equation?
gaunt vortex
I don’t know what to do after the first part…
velvet osprey
the second sentence of the problem talks about interest
can you give an expression for the interest earned by the 8% account?
also please don't attempt to jump the gun and do more than what i ask you to!
velvet osprey
can you give an **expression** for the interest earned by the 8% account?
...okay so that's a no to this
have you worked with the concept of interest before?
or perhaps percentages more generally?
gaunt vortex
Yes
velvet osprey
yes to both?
gaunt vortex
Percentages
velvet osprey
okay so if you meant "percentages but not interest" then why not say "I have worked with percentages in general but not with interest"?
anyway, ok
when we say that an account earns 8% interest, we mean that the amount of money in the account increases by 8% every year. that is, the amount by which it increases is equal to 8% of what you put into it.
there is a difference between simple interest and compound interest (namely whether the percentage is calculated from the current total or the initial deposit), but for our purposes it does not matter as the duration is only one year.
do you understand this?
gaunt vortex
Yes
velvet osprey
okay
then let's come back to the question i asked prior
can you give an expression for the interest earned by the 8% account?
gaunt vortex
No
velvet osprey
the interest earned by the 8% account is 8% of the amount invested into the account.
what letter did i use for the amount invested into the 8% account?
gaunt vortex
X
gaunt vortex
.8x
velvet osprey
no
gaunt vortex
.08
velvet osprey
first off, never write decimals without the leading zero
so it's 0.08, not .08
and 0.8, not .8
gaunt vortex
Yeah mb
velvet osprey
that, unless you want to deliberately set yourself up for losing that decimal point
anyway, let's try this again
what is 8% of the amount invested into this account?
gaunt vortex
0.08x
gaunt vortex
0.12y
velvet osprey
great
and now
the 12% investment earned $480 more interest than the 8% investment.
can you write this down as an equation?
gaunt vortex
0.08x+0.12y=480?
velvet osprey
no,
that would be "The two investments earned a total of $480 in interest"
which is not what is happening in your problem
gaunt vortex
So how would I write it down
velvet osprey
The interest earned by the 12% account is $480 greater than the interest earned by the 8% account.
gaunt vortex
Yeah but how would I write down the equation
velvet osprey
can you write down "A is 480 greater than B" as an equation?
with the letters A and B obviously
gaunt vortex
No
velvet osprey
A = B+480 no bueno?
gaunt vortex
0.12y=0.08x+480
velvet osprey
great
now you have a system of two equations
x + y = 10000
0.12y = 0.08x + 480
are you able to solve this system of equations for x and y?
gaunt vortex
I need to solve it by elimination
So would I move x to the other side
0.12–0.08=480
And then solve
Or no
velvet osprey
0.12–0.08=480
where'd this come from?
also, no, there are no instructions in the problem to use a specific solution method. you do not "need to" solve this system by elimination.
gaunt vortex
So how would I solve it
velvet osprey
well you could do it by elimination if you really wanted to
gaunt vortex
I learned substituting and eliminating
velvet osprey
substitution can work here too
i would suggest first multiplying both sides of the equation 0.12y = 0.08x + 480 by 25 to get rid of the fractions
i just think you should try something on your own instead of getting me to handhold you through the easy part of the problem
gaunt vortex
I’ve never done a substitution or elimination problem with an equation that has y and x on different sides
velvet osprey
well you can do some algebra to that equation such that the x and y don't appear on different sides anymore if you want
but for the purposes of substitution i don't think that will be super necessary
you do you though
gaunt vortex
Oh wait, x=10,000-y
And then I do the rest
Right
Nvm that wouldn’t work I think
velvet osprey
why do you think it wouldn't work?
it really sounds as if what's stopping you is less lack of algebraic fluency and more extreme hesitation
gaunt vortex
Wait I did something wrong
Ight now I know what to do I think
Ight I did it
And got x=3600 and y=6400
Thanks a lot for the help
.close
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remote mural
need help with statement
alpine stone
Just post the question
remote mural
Determine the truth table of the logical value of the formula H:F1 <->F2 if F1:L(pvq) and F2:Lp(conjunction)Lq
i just dont understand how do u set up the table
with these
alpine stone
Just like you'd set up the table for any other logical value with given formula, just run though cases when p and q are both true and when one of them is true and the other is false and when both of them are false
remote mural
Just like you'd set up the table for any other logical value with given formula,...
this is my problem
i dont understand how do u get these
alpine stone
Since the formula is F1 <-> F2, start with determining the values of F1 and F2 in each of the cases
remote mural
its harder for me to explain it to u
cause from different country
but i just dont get it like why is p true and why is q false
..
etc
alpine stone
We aren't saying that p is true and q is false
We are just considering all of the possible cases
T, T
T, F
F, T
F, F
alpine stone
Yes
alpine stone
pvq means "p or q", if you're having trouble with determining its value then use the table of it
TvT = T
TvF = T
FvT = T
FvF = F
remote mural
okay
im starting
to get it
i need to ask
what about second collum
how do u get that?
alpine stone
Btw how is L defined?
calm coralBOT
@remote mural Has your question been resolved?
alpine stone
Ah
So to determine F2, which is the same as Lp ∧ Lq
You first have to invert the values of p and q and then take their conjunction
Negation of T is F and negation of F is T
alpine stone
Ah
Well sometimes you may see t and f first and then f and t I think
But it doesn't really matter
alpine stone
You are free to write tt tf ft and ff, yes
remote mural
it seems like that
cause there are
different
question where
in second collum or third
t is f
and otherwise
and its confusing to me
on how to get the other collum
remote mural
okay
that is clear
now
what about third collum
sorry for asking
i need to know this cause its kind hard
third collum how are p = f and q = t
calm coralBOT
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modern kayak
please help
calm coralBOT
please help
sturdy stratus
again?
modern kayak
yea im very confused
sturdy stratus
First, write what you have:
Julian: 10%
Anne: 10%
Richard: 10%
George: 7/25
Timmy: 1/10
Abi: 16
sturdy stratus
Then you convert George and Timmy into percent.
modern kayak
Timmy - 1
George - ?
sturdy stratus
George: 7/25 = 28%
Timmy: 1/10 = 10%
modern kayak
ah alr
sturdy stratus
1/10 = 10% because 1 = 100%
modern kayak
oh yea that makes senes
sturdy stratus
Now, you add everyone except for Abi.
modern kayak
ty
sturdy stratus
That means that Abi got the remaining 32%
modern kayak
bet ty again ❤️
sturdy stratus
So how many percent is one points if Abi's 16 points are 32%?
modern kayak
So how many percent is one points if Abi's 16 points are 32%?
2
modern kayak
100
sturdy stratus
No
modern kayak
68 + 32
sturdy stratus
Okay
sturdy stratus
np
modern kayak
.close
twin apex
can x<5/3 and x>13/3 be written as XE(13/3,5/3)
calm coralBOT
can x<5/3 and x>13/3 be written as XE(13/3,5/3)
twin apex
just double checkin
visual nimbus
but 13/3 is greater than 5/3, so your notation makes no sense
but the spirit is there
twin apex
thats what im double checkin
hmmm
yeah duh
shoulda just solved 13/3 and 5/3, was just confused xD so the correct form is
XE(5/3,13/3)
visual nimbus
yea but that means x>5/3 and x<13/3
twin apex
oh shoot, then how would I write x<5/3 and x>13/3 in XE(x,y) format?
hmmm lemme think one sec sorry
twin apex
Well the original problem is to solve the inquality for I 3z - 9 I > 4
and i got "z < 5/3 or z > 13/3"
twin apex
???
how do YOU solve an inequality?
cause the textbook agrees with "z < 5/3 or z > 13/3" but i was just trying to write it in interval notation
visual nimbus
oh, I see the problem
You have z < 5/3 (the first solution) or z> 13/3 (the second solution)
You will have two intervals
visual nimbus
(-oo, 5/3) U (13/3 , +oo)
twin apex
ooooh ok got confused again thinkin 13/3 was the smaller value
it's the fractions that are gettin me mixed up on where i need to be placin em on the number line, but i should type 13/3 into my calc and see 4.33, 5/3 see 1.66, so 13/3 is to the right of 5/3 on the number line
and cause z needs to be smaller than 5/3, or bigger than 13/3, i get why it needs to be (-inf, 5/3)U(13/3,inf) 🙂
thanks!
.close
earnest pendant
ahem
earnest pendant
its up top
hidden elbow
all?
earnest pendant
yah 1 , -4 and9
earnest pendant
a=1 b = -4 and c=9 ?
earnest pendant
.
hidden elbow
you know
what that means
I not asking u for it
I just asking u
if yk
what it means
earnest pendant
yeh
hidden elbow
nice
earnest pendant
right
?
hidden elbow
perfect
see you got this
alr so
now
x coordinate
of vertex
is 2
so u know
x is 2
how to find y coordinate
of vertex?
take a guess
earnest pendant
ye
hidden elbow
alr
earnest pendant
,w x^2-4x+9 when x=2
earnest pendant
oh my bad
potent lotusBOT
hidden elbow
nice
earnest pendant
y = 5 :3
earnest pendant
ye
hidden elbow
nice nice
you got this
so next part
let’s go
hm
alr so
x intercept
what does
it mean
hidden elbow
amazing
so
ok let me make it clear
so
usually
are u used to
the eqn
being like
y=
something
earnest pendant
yeh
earnest pendant
so to find y
hidden elbow
u know y=0
earnest pendant
,w y=x^2-4x+9 when x=0
potent lotusBOT
earnest pendant
tis 9
earnest pendant
y intercept
potent lotusBOT
earnest pendant
scari numbers 😦
hidden elbow
ye so imaginary
that means
eh
no y-intercept
wtf
why ur qn like that
Lmao
nah can’t be
oh wait
nvm
ye
that means no x intercept
earnest pendant
am confuzed
hidden elbow
so basically
earnest pendant
there no intercept right ?
hidden elbow
that i
earnest pendant
because
hidden elbow
u see the i
earnest pendant
it goes downnn
earnest pendant
oh
earnest pendant
OH
hidden elbow
yeye
earnest pendant
ok ok that makes more sense
hidden elbow
ayeeee
nice
so ye
no x int
u can use discriminant
to show that
b^2 -4ac
<0
earnest pendant
but the min or mac
hidden elbow
the next part
earnest pendant
max*
earnest pendant
wud be 5 right ?
earnest pendant
but
earnest pendant
2 is smoller than 5
hidden elbow
this is a happy face
earnest pendant
hm
earnest pendant
it applies to 5 ?
hidden elbow
it’s where u draw the y line
earnest pendant
so it only applies to y
earnest pendant
if its likke -5 id be max right ?
earnest pendant
yes
earnest pendant
the way it goes up and downs
earnest pendant
: (
hidden elbow
the left
that’s a maximum
cuz
sad face
has a highest point
it has no
lowest point
earnest pendant
so its the highest point
hidden elbow
cuz it goes down never ending
earnest pendant
hapi face is min sad is max
earnest pendant
oh the next one is range...
hidden elbow
domain refers to
yes exsctly
X
so range
applies to values
that y
can take
so we found out
that y
ONLY
goes down to
5
earnest pendant
ye
hidden elbow
that’s the minimum
then rmb for sad face
it goes down never ending
for happy face
it goes up
never ending
to infinity
earnest pendant
thats tru
hidden elbow
nah
usually
smallest to biggest
also
what brackets
will u use
that’s impt
earnest pendant
[)
earnest pendant
the regiular paranthesis for the 5 because its not infity right ?
earnest pendant
ye
earnest pendant
yah...
earnest pendant
THE INFITY is the ) and 5 is [
earnest pendant
so [5,insert inf symbol)
hidden elbow
[ means inclusive of that number
yeye
so just know that
if ure dealing
with inf or -inf
it will never
be []
for the inf
earnest pendant
oh ok
earnest pendant
bye bye thank u so much
earnest pendant
nah
hidden elbow
glad to help
earnest pendant
bai baiii
potent lotusBOT
earnest pendant
,w -4x^2-8x-5 when x=0
potent lotusBOT
earnest pendant
,w y=-4x^2-8x-5 when y=0
potent lotusBOT
calm coralBOT
@earnest pendant Has your question been resolved?
crisp glen
i dont get the wording
calm coralBOT
i dont get the wording
crisp glen
wintry glacier
well the halftime is 1600 years