#help-41

1 messages · Page 48 of 1

coral wigeon
#

yep

sullen knoll
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Perms and combs is the death of me 😔🤚🤚

fierce edge
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it makes non-uniform stuffs uniform

coral wigeon
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i do like uniform

fierce edge
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i like uniform too happy

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Lol

coral wigeon
fierce edge
#

okay so

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(140-a, 140, 160, 160+a) -> (10-a, 10, 10, 10+a)

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10 and 10-a has the same deviation as 10 and 10 + a

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10^2 + (10 + a)^2 = 50^2 * 2

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(10 + a)^2 = 4900

|10 + a| = 70

shrewd elm
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and a > 0, so..

fierce edge
#

yep

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a = 80

shrewd elm
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wha

fierce edge
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i mean a = 60 LOL

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😭

shrewd elm
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math is hard

fierce edge
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😔 it is

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okay thanks

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i think i realize what i was doing "wrong"

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well not wrong but the time consuming thing

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it was expanding (10 + a)^2

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when i didn't have to

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bye

#

.close

amber waspBOT
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amber waspBOT
shrewd elm
#

not necessarily

modern marsh
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Why?

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I feel like that one is 1 and other is -1, i mean the det, but idk what happened in A+B

shrewd elm
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well a simple matrix with det 1 is the identity

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what's a simple matrix with det -1?

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hint: what can you do to a matrix to change the sign of the determinant?

modern marsh
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Inverse? I'm not sure

shrewd elm
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no, that will give you one over the original determinant

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how about exchanging two rows (or two columns)

modern marsh
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That'll change the signs? Damn I forgot so much

shrewd elm
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yep it will

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so what if you have the 2x2 identity matrix

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that's orthogonal with det = 1

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what do you have if you swap the two columns?

modern marsh
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Identity matrix with a minus sign?

shrewd elm
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no, literally just move column 1 to column 2 and vice versa

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what is the new matrix?

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wha

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you started with

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1 0
0 1
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exchange the columns

modern marsh
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0 1
1 0

shrewd elm
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yea

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let's call that B

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is it orthogonal?

modern marsh
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Yes

spark cobalt
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it can be much easier than that, take any nxn matrix where n is odd and mutliply it by -1 and now you have another orthogonal matrix with negative the determinant and their sum is zero which is clearly not invertable

shrewd elm
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and what is its determinant?

modern marsh
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-1

shrewd elm
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yep

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now if you add those two matrices, what do you get?

left tundra
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ah matrix

modern marsh
shrewd elm
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yep

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is that invertible?

modern marsh
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No

shrewd elm
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victory

modern marsh
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Tysm😂

left tundra
#

whats the basic rule you need for the multiplication of 2 mtrix

spark cobalt
shrewd elm
#

indeed!

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sandwiches for everyone

modern marsh
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Noooooo(running away

left tundra
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like the no. of rows of 1st matrix = no. of column of 2nd matrix?/

spark cobalt
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😂

amber waspBOT
#
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split sail
#

solve (1+tanx)/(1-tanx) = root3

amber waspBOT
split sail
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Please help

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🙂

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In radians

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PLEASE

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I did this

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1 + tanx = root3 - tanx root3

neat wind
fierce edge
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(1 + tan(x))/(1 - tan(x)) simplifes to tan(x + pi/4) which u could've said from the addition formula

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mqnic already has said this but u reacted with what so i thought ur still confused

split sail
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ancient sparrow
#

Anyway to integrate this?

amber waspBOT
ancient sparrow
#

<@&286206848099549185>

tepid widget
#

,rotate

grizzled pagodaBOT
ancient sparrow
#

😢

amber waspBOT
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keen pawn
amber waspBOT
#

Please don't occupy multiple help channels.

keen pawn
#

Closed the other one just now

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We first prove if $n \mid 3$ then $F_n$ is even

grizzled pagodaBOT
#

A dense set(Ping when reply)

keen pawn
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by induction

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wait

split sail
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what's the first fibonnaci number?

keen pawn
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1

split sail
split sail
keen pawn
#

ah

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if $3\mid n$ then $F_n$ is even

grizzled pagodaBOT
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A dense set(Ping when reply)

keen pawn
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so $3\mid 3$ and $F_3=2$ which is even
\
We now suppose that if $3 \mid i$ then $F_i$ is even $\forall i \leq n$
\
$F_{n+3} =F_{n+2}+F_{n+1} = F_{n}+F_{n-1} +F_{n+1} + F_{n} = F_n+F_n +F_{n-1} + F_n+F_{n-1}$
\
By inductive hypothesis $F_n$ is even and $F_{n-1}$ is odd, but $2F_{n-1}$ is even.
\
We this have $F_{n+3}$ is even , which proves the result as desired

grizzled pagodaBOT
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A dense set(Ping when reply)

cunning birch
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sure

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Though you didn't prove why F_(n-1) is odd

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so weird assuming that

cunning birch
amber waspBOT
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split sail
#

What's an example of a non-normal mathematical constant?

amber waspBOT
#

Please don't occupy multiple help channels.

sterile nymph
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@split sail any rational number

split sail
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That is irrational

sterile nymph
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You can construct one

split sail
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that have either a symbol for them or an algebraic representation

sterile nymph
#

That is a bit trickier

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Most irrational numbers (all but measure 0) have been proven to be normal. But the proof for any specific irrational number is incredibly difficult. It is widely believed that sqrt(2), pi, and e are normal, but it is not proven

split sail
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yes but what about non-normal

sterile nymph
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Very few numbers have been proven normal or not-normal that haven't been specifically constructed for this purpose.

split sail
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like which are tested to a million digits and found to be non-normal

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are there any?

sterile nymph
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You could easily just take sqrt(2) in its decimal expansion and turn all of the 9s into 8s and this number would not be normal in base 10

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It would probably still be normal in unrelated bases though

cunning birch
split sail
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isn't it like an infinite product?

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well that way pi is too an infinite sum

cunning birch
sterile nymph
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sqrt(2) = 1.4142135623730950488...

We just find everywhere that is a 9 and turn it into an 8

sqrt(2) - α = 1.4142135623730850488...

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Where α is some real number that does this

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α is also abnormal in this case, consisting only of 1s and 0s in decimal

split sail
#

but that isn't algebraic?

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like 'a' isn't algebraic

modest sand
split sail
#

that has a representaion

sterile nymph
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You asked for a number, then an irrational number, now an algebraic number.

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It's possible one doesn't exist.

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I don't know

split sail
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wikipedia says so

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thanks guys

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amber waspBOT
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sterile nymph
#

@cunning birch thanks btw today I learned

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runic kraken
#

solving a problem that involves finding the vector angles, i got an angle of -79, does that go left wards or do i start from the bottom up?

runic kraken
#

talking about gamma

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balmy moss
#

hello i need help with my hw (im sending more screenshots)

balmy moss
#

the last 2 screenshots i would love help on it first

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it was the hardest

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<@&286206848099549185>

winter badge
#

please take a screenshot, no ones trying to read scew photos

balmy moss
#

Okikok

balmy moss
balmy moss
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harsh surge
amber waspBOT
harsh surge
#

Hello, I don't understand how to solve/proceed with this question

celest cove
#

you know y=F(2)-F(sqrt(x))
so you can use the chain rule there

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where F'(t)=f(t)=t^2+1

foggy kayak
#

first solve the definite integral and then differentiate the function you get afterwards

harsh surge
#

could you show me a solution please?

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I'll understand it better if I can see what's going on step by step

foggy kayak
#

we can't give direct solution

harsh surge
#

ah alrighty, do you have any sources I could study/practice?

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so it'll be something like 0-((sqrtx)^2+1) d/dx of sqrtx right?

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then proceed from there

foggy kayak
#

what

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integrate first

harsh surge
#

idk 😭

foggy kayak
#

first solve the definite integral

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use FTC

shadow stump
#

it's not necessary to find the definite integral to find its derivative

harsh surge
#

.close

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woeful dirge
#

what does this vertical line mean and x = 2

amber waspBOT
weak zinc
#

Evaluate dy/dx when x = 2

amber waspBOT
#

@woeful dirge Has your question been resolved?

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bleak mason
amber waspBOT
bleak mason
#

How…

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I tried

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Putting into calculator

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8^0,66

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INSTEAD OD REACTING MAYBE HELP ME

weak zinc
#

Put it in exactly, 8^{2/3}

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And do you know your rules of exponents?

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(if not, it would be a good time to learn them)

bleak mason
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Oh that was right

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It’s 4

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But

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It doesn’t feel right

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It feels to easy

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Is there a way to do this without calculator

cedar plaza
#

8=2^3

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you can use your exponent laws to simplify (2^3)^(2/3)

tepid meteor
#

This is like (8^1/3)^2

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cube root is 2, and its square is 4

severe lantern
#

$$a^{b/c} = \sqrt[c]{a^b}$$

grizzled pagodaBOT
#

spruce leaf

severe lantern
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$$a^{b/c} = \sqrt[c]{a}^b$$ is also true

grizzled pagodaBOT
#

spruce leaf

severe lantern
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where c is positive

bleak mason
#

Ohhhhh

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While this is open I might as well…

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I feel like all I can do rn is make -3a to -2a

tepid meteor
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youre right

bleak mason
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But so I can’t simplify it further

tepid meteor
#

i mean like unless the whole thing is equal to 0 thats all you can do

bleak mason
#

It was wrong

tepid meteor
#

is the equation equal to zero?

bleak mason
#

It’s not an equation

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It’s a

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Idk what it is in wbglihs

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But it’s not solvable

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You’re supposed to simplify it

tepid meteor
#

did you put -2a -7?

bleak mason
#

I put this

tepid meteor
#

brooo its 2a^2

bleak mason
tepid meteor
#

you need to simplify a^2

bleak mason
#

I can just combine them like that?

tepid meteor
#

yeeee

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because thgey are the same

bleak mason
#

Ohhhh

tepid meteor
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you can do the same thing even if its like a^1/2 + a^1/2

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itd be 2(a^1/2)

bleak mason
#

Ohhhhhhhhhhhh

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I’m so dumb

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I can swear someone told me I can’t do that

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Thanks though🩷

#

.close

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hearty sleet
#

i get how the 5sin/cos part works but how does the revolution in 4pi seconds part work

hearty sleet
#

great

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<@&268886789983436800> sorry for ping (?)

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help (?)

quiet cave
#

Barely missed

hearty sleet
#

lol thx

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<@&286206848099549185> hola a lil help pls lol

amber waspBOT
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@hearty sleet Has your question been resolved?

fresh gust
#

Where's the question?

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Is it the trg one?

hearty sleet
#

ye

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i just wanna know how they get t/2

weak zinc
#

You know that for the "ordinary" trig functions sin(t) and cos(t), they repeat themselves every 2pi, but now you effectively want to repeat yourself every 4pi

hearty sleet
#

oh

fresh gust
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I was gonna say that

hearty sleet
#

wait

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im a dumbass

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LOL

fresh gust
#

💀

hearty sleet
#

forgot abt the 2pi period part

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thx hahaha

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potent sandal
#

Hey I am looking at some benchmarking results from running code on x number of CPU cores

potent sandal
#

Since the benchmark will only be slowed down by noise I am taking the minimum benchmark as my result

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However I would like to estimate some standard deviation

daring jetty
#

cap

potent sandal
#

Is a jackknife method appropriate here to estimate a standard deviation for the minimum?

steady snow
#

i dont think so

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coz like u use jackknife method to estimate the variance of a statistic by leaving out one observation at a time and recalculating the statistic right? so this would be effective for smooth and differentiable statistics (like the mean or regression coefficients), but the minimum is a non smooth statistic

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if u know what specific pattern the noise makes in ur benchmarking results u could model the noise explicitly using that

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OR even better u could use ALL the data points, not just the minimum, to fit a distribution model then use that model for estimating variability of minima and it can also give you both the minimum estimate and its standard deviation

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strong granite
#

am i on the right track here?

amber waspBOT
strong granite
#

any help would greatly be appreciated 😔

#

im confused about if im finding the mean

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and sample error of the mean correctly

#

<@&286206848099549185>

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@strong granite Has your question been resolved?

amber waspBOT
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@strong granite Has your question been resolved?

strong granite
#

😭

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@strong granite Has your question been resolved?

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chrome grotto
#

i need help with my math review but i don’t really understand this :( i have a 47 in math rn so im hoping somebody could please help me! much thanks

remote egret
#

for the last question

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the letters match up

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so L to X, M to Y, and N to Z

chrome grotto
#

really tysm im sorry to disturb u 🥹

remote egret
#

no don't be sorry

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so that means angle m matches with y

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and for ln its xz

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  1. SAS i think
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the lines on the sides CA and CB indicate they're congruent (fulfills S)

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angle shared with the 90 degree (fulfills A)

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and then CD nudged in the middle so its shared side too (fulfills last S)

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if you don't really know the postulates i recommend you learning them first through organic chem tutor

chrome grotto
#

ur explaning helped me understand a bit better tysm

remote egret
#

no problem

chrome grotto
#

i think i got it now, ill figure it out

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sorry for wasting your time!

#

tysmm

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clever gorge
#

Hi

amber waspBOT
clever gorge
#

I’ve tried 1b so many times but still have no idea how she got 0.25

#

I don’t understand the logic behind it

low adder
#

calculate the tension force when there is no friction

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use sum of forces is equal to 0 so that it is stationary as no acceleration

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then u should get that friction force is equal in magnitude opposite in direction

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to tension force

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divide that by the normal force

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and u get your minimum coefficient of friction

clever gorge
#

does it matter which object you do use the sum of forces on

low adder
#

well the only object that has friction is the desk one

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so it does matter

clever gorge
#

ye im still stumped i think imma just ask my teacher tmr morning

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ty for tonight

#

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split sail
#

What a +w

amber waspBOT
sterile nymph
#

Context?

amber waspBOT
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@split sail Has your question been resolved?

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topaz pond
#

<@&286206848099549185>

amber waspBOT
topaz pond
#

I am unable to solve the first question

#

Can someone help me solving the first question

#

The problem with this question is that
This has two independent variables
But problem comes with dependency

#

What to do

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<@&286206848099549185>

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normal dove
#

lemme know hints other than take log 😭

amber waspBOT
dull pike
#

You dont like easy way?

#

Ah no, i read wrong

normal dove
#

lol

dull pike
#

Are you sure the square root doesnt cover everything?

vernal surge
#

what does the inner factor converge to?

dull pike
#

@normal dove

normal dove
normal dove
#

its prolly riemann sum but cant convert to the format

dull pike
#

But inside u are getting a number <1, unless i am blind

normal dove
#

yeah would make sense

dull pike
#

And if u multiply over and over u get a smaller number

vernal surge
#

like, whats $\lim_{r \to \infty} \left(\sqrt{2} - 2^{\frac{1}{2^r-1}}\right)$

grizzled pagodaBOT
normal dove
#

sqrt 2 -1 i guess

dull pike
#

Y

normal dove
#

wait nvm

vernal surge
#

no thats correct

#

which is |sqrt(2)-1| < 1, so you know that there is some q < 1 and R, such that absolute value the inner term is always less than or equal to q for r > R

normal dove
#

erm

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solemn escarp
#

Let ABC be a triangle. Points M and N are on side BC such that BM = MN = NC. Extend AM to point P such that BP is parallel to AN. Extend AN to point Q such that CQ is parallel to AM. If the area of triangle MAN is 57, find the area of quadrilateral ABPQC

solemn escarp
#

this is a very menelaus-y looking question

#

oh wait

#

this is sick

#

every triangle is congruent

#

fire question

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ABPQC = 8MAN = 456

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harsh forge
#

how do i put this Sturm-Liouville form? Surely it is just $(y')' + \lambda y = 0$

grizzled pagodaBOT
#

lewis_f04

amber waspBOT
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@harsh forge Has your question been resolved?

harsh forge
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@hazy bluff

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@harsh forge Has your question been resolved?

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@harsh forge Has your question been resolved?

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gusty plaza
#

Hi this is my first time doing shell method so I’m sorry if I am doing it wrong but is this the correct way to set it up

covert onyx
patent raptor
#

ngl that was a smart move what you did

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but you should subtract it the other way

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(2-y) - y²

gusty plaza
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Thank

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gusty plaza
#

.reopen

amber waspBOT
#

gusty plaza
#

Did I set this up correct number 6

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(I just wanna make sure)

patent raptor
patent raptor
#

ok you did shell method

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should work yea if my head right

pallid canopy
patent raptor
#

,w 2pi * Integrate[y * y^(1/3), {y,0,8}] = pi * Integrate[8^2-(x^3)^2, {x,0,2}]

grizzled pagodaBOT
amber waspBOT
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@gusty plaza Has your question been resolved?

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gusty plaza
#

.reopen

amber waspBOT
#

patent raptor
gusty plaza
#

What’s the Antiderivayige of e^-x^2?

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Problem 12

patent raptor
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however you can use here a u-sub since you got that extra factor x

gusty plaza
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Ic

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Would I u sub the -x^2

patent raptor
gusty plaza
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I think I did something wrong cause I’m not cool or something idk

gusty plaza
#

Oh

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Bruh

patent raptor
#

but then

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i see you substituted again u = -x^2

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then you can keep the old bounds then

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then everythings fine anyway

#

and you are also cool

gusty plaza
#

Because my answer is negative

patent raptor
#

it seems so

gusty plaza
#

But that should be impossible right

#

Area can never be negative

patent raptor
#

but it isnt

gusty plaza
#

Oh

patent raptor
#

,w -pi * e^(-1^2) - (-pi * e^(0^2))

grizzled pagodaBOT
patent raptor
#

see, it's positive

#

everything is falling into place

#

like all things should

gusty plaza
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Yea that’s true

#

I only calculated upper bound for some reason

#

Which was dumb

#

Also is it raining there

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It’s raining here

patent raptor
#

snowing

gusty plaza
#

Whoa really

#

Can I see

patent raptor
#

yea, just open your eyes

gusty plaza
#

Ok

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Np

patent raptor
#

i feel so tired

gusty plaza
#

Go sleep

#

Why you up

#

.close

amber waspBOT
#
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pallid canopy
#

damn kicked you out adonis to make you sleep

gusty plaza
#

Yea but I’m gonna come back in like 6 min anyways

amber waspBOT
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eager karma
#

do i subtract or add -3? aaalso, its c, not b.

crude kite
#

If there is no sign, it's default adding

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Like for b, that 54, is positive 54

eager karma
#

right. everyone keeps saying that but i constantly forget lol

crude kite
#

Then make a note of it so you don't forget

#

If multiple people have told you the same thing

eager karma
#

yeup. tyyy

#

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eager karma
#

.reopen

amber waspBOT
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eager karma
#

i put a note

#

yay

#

byebye

#

.close

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ancient raft
#

Estimate the remainder of $f(x)=e^x$

amber waspBOT
grizzled pagodaBOT
ancient raft
#

Since $$T_n(e^x)=1+x+\frac{x^2}{2}+\dots+\frac{x^n}{n!}$$

grizzled pagodaBOT
tranquil shale
#

what is ur question? im sorry

vernal surge
#

you got a picture of taylors theorem?

ancient raft
#

I saw my mistake.

#

My bad, should've seen more precisely.

#

.close

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old drift
#

Can someone help me calculate the integral of Thomae's function on 0 to 1. I forgot the proof and how to make the partition. I know that the set where we're evaluating the integral on has measure zero and all of that but I want to use first level analysis techniques.

old drift
#

Recall Thomae's function is
$$f(x) = \begin{cases}
0 \qquad \text{ if } x \notin \mathbb{Q}\
\frac{1}{n} \qquad \text{ if } x = \frac{m}{n} \text{in lowest terms}
\end{cases}
$$

grizzled pagodaBOT
#

Bean Man

cunning birch
old drift
#

I kind of wanted a proof that created partitions so that the length of each interval is arbitrarily small and we get the |U(f, P) - L(f, P)| < epsilon so we get that its integrable in the first place and then that leads to it having integral equal to 0

cunning birch
old drift
#

.close

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quasi meadow
#

If you're given f(x,y) as your joint probability distribution function

quasi meadow
#

is finding E[X] for exmaple, a double integral of x and y of x * f(x,y)?

vast scaffold
#

No

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You need to find marginal

quasi meadow
#

ah

vast scaffold
#

To find that expected value

quasi meadow
#

uh

#

integral of x. *fx(x)?

vast scaffold
#

Ye

quasi meadow
#

hmm

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and to find fx(x)

#

we hold x constant, and integrate over all values of y

#

so we just integrate f(x,y) with respect to y?

vast scaffold
#

Ye

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So I guess you’re right lol

quasi meadow
#

hm

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im struggling with this integral than

#

$$\int _0^{\infty }\frac{1}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dy$$

grizzled pagodaBOT
vast scaffold
#

,w $$\int _0^{\infty }\frac{1}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dy$$

quasi meadow
#

yeah idk what that is

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💀

#

maybe i did it wrong

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btw thats f(x,y)

vast scaffold
#

What’s bound on X

quasi meadow
#

0 to infinity

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both x and y are bounded 0 to inf

vast scaffold
#

,w $$\int _0^{\infty }\int _0^{\infty }\frac{1}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dy xd$$

vast scaffold
#

,w $$\int _0^{\infty }\int _0^{\infty }\frac{1}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dy dx$$

quasi meadow
#

hmm

vast scaffold
#

Checks out

quasi meadow
#

okay so i was supposed to do a double integral

vast scaffold
#

No

quasi meadow
#

oh

#

hm

vast scaffold
#

I was checking to see if it’s 1

quasi meadow
#

whats the easiest way to approach this

#

ah

vast scaffold
#

Maybe use a transform

#

That makes it look more like normal pdf

quasi meadow
#

💀

#

im so tempted to write

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"solved with an integral calcualtor"

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for this hw assignment

#

ughhh

quasi meadow
vast scaffold
#

,w $$\int _0^{\infty }\int _0^{\infty }\frac{x}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dy xd$$

vast scaffold
#

,w $$\int _0^{\infty }\int _0^{\infty }\frac{x}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dy dx$$

vast scaffold
#

Maybe let u =x/y

quasi meadow
#

hmm

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thats what i started off with actually

#

then i got tired of doing this questino and was thinking theres no way he asks such an annoying calc problem on a probability hw assignment

vast scaffold
#

Integrate with respect to X first

quasi meadow
#

alr

vast scaffold
#

Then it’s an exponential dist with parameter 1/y

quasi meadow
#

ah

#

distribution

vast scaffold
#

Do you see it

quasi meadow
#

ill give it a shot first

amber waspBOT
#

@quasi meadow Has your question been resolved?

quasi meadow
#

,w $$\int _0^{\infty }\int _0^{\infty }\frac{y}{y}\cdot :e^{-\left(y+\frac{x}{y}\right)}dx dy$$

grizzled pagodaBOT
amber waspBOT
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clear finch
#

I had to use desmos to find the answer, but I dont understand it

clear finch
#

the period is pi/3 i believe

marble sparrow
#

I might be crazy but I don’t believe that’s correct

clear finch
#

i thought so too

#

im so confused where that 4 comes from

marble sparrow
#

That’s a good realization

clear finch
#

desmos says so tho...

marble sparrow
#

Oops I forgot about that

#

One second I’m gonna work it out on a whiteboard and I’ll send a pic 😓

clear finch
#

kay

marble sparrow
#

I see now

#

Let me know if I didn’t write something clear enough or didn’t show a step

clear finch
#

o....

#

i c

#

i am supposed to use power reduction rule...

marble sparrow
#

Yes

clear finch
#

thanks for the help

marble sparrow
#

No problem

clear finch
#

lmao, I always forget that rule

marble sparrow
#

Yeah it can be annoying/hard to see

clear finch
#

anyway, have a great day!

#

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mystic solstice
#

Hello! I need help with this question, I'm doing yr10 maths and it's for my end of yr exam. I don't understand what the 'least squares regression line' means and therefore the rest of the question. I have the answers but I don't know how my teacher got to that

mystic solstice
#

Sorry?

ionic zodiac
#

r u nsw?

mystic solstice
#

wdym by nsw

ionic zodiac
#

ok nvm then

mystic solstice
#

😭

#

oh new south wales?

red island
#

Don’t worry too much about what the “least squares regression line” is, just substitute the data into the equations given in the question.

mystic solstice
#

ohhhh got it, thank you

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grim isle
#

how do i set the domain for s and t

amber waspBOT
grim isle
#

the video juz states since z=3sin(s) , so set s as that domain

#

is there a trick or smtg

amber waspBOT
#

@grim isle Has your question been resolved?

grim isle
#

<@&286206848099549185>

amber waspBOT
#

@grim isle Has your question been resolved?

grim isle
#

How do I determine the domain of a parameter

#

<@&286206848099549185>

amber waspBOT
#

@grim isle Has your question been resolved?

grim isle
#

.close

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tough mica
amber waspBOT
tough mica
#

,, \textbf{ finding interval of convergence} \ \sum_{n = 1}^{\infty} \frac{(x-3)^n}{n^2 \cdot 2^n}

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

I want to try root test out but I am scared of justifying the $\sqrt[n]{n^2}$ haha

grizzled pagodaBOT
#

Renato Chavez

wispy ermine
#

if you want to find the limit of n^(n/2) you can write it as e^(something)

tough mica
#

lets do root test then if we know the limit of n^(n/2)

#

,, a_n = \frac{(x-3)^n}{n^2 \cdot 2^n} \ \textbf{ applying root test} \ \lim_{n \to \infty} |\sqrt[n]{a_n}| < 1 \ \lim_{n \to \infty} \left|\sqrt{\frac{(x-3)^n}{n^2 \cdot 2^n}}\right| < 1 \ \lim_{n \to \infty} \frac{|x-3|}{|\sqrt[n]{n^2}| \cdot 2} < 1

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

,, \sqrt[n]{n^2} = n^{2/n} \ L = n^{2/n} \ \ln(L) = \ln\left(n^{2/n}\right) \ e^{\ln(L)} = e^{2/n \cdot \ln(n)} \ L = e^{2/n \cdot \ln(n)}

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

,, \textbf{ auxiliary calculation 1: } \ \lim_{n \to \infty} \frac{2 \ln(n)}{n} \overset{\text{L'Hôpital}}{=}
\lim_{n \to \infty} \frac{2/n}{1} = \lim_{n \to \infty} \frac{2}{n} = 0

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

,, a_n = \frac{(x-3)^n}{n^2 \cdot 2^n} \ \textbf{ applying root test} \ \lim_{n \to \infty} |\sqrt[n]{a_n}| < 1 \ \lim_{n \to \infty} \left|\sqrt{\frac{(x-3)^n}{n^2 \cdot 2^n}}\right| < 1 \ \lim_{n \to \infty} \frac{|x-3|}{|\sqrt[n]{n^2}| \cdot 2} < 1 \ |x-3| < 2 \implies -2 < x - 3 < 2 \ 1 < x < 5 \implies x \in (1,5)

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

i have to verify if its open or closed interval

#

like 1 and 5

wispy ermine
#

you can just plug in the values and check if the resulting series converges

tough mica
#

problem is this makes the limit be equal to one and root test says thats inconclusive

#

we need to try another way

wispy ermine
#

ah not quite what I mean

I mean you have the series

$\sum \frac{(x-3)^n}{(2^{n}n^2)}$

plug the values of x into that

tough mica
#

,, \sum_{n = 1}^{\infty} \frac{(-2)^n}{n^2 \cdot 2^n}

grizzled pagodaBOT
#

Renato Chavez

#

LayneTheAndroid

tough mica
#

is an alternating series

wispy ermine
#

it is an alternating series; even better it's a well known alternating series

#

(i'm assuming you've seen the series $\sum \frac{1}{n^2}$ in your course by now)

grizzled pagodaBOT
#

LayneTheAndroid

tough mica
#

p test

#

its a p series

#

,, a_n = \frac{(-1)^n \cdot 2^n}{2^n \cdot n^2} = \frac{(-1)^n}{n^2} \ a_{n+1} = \frac{(-1) \cdot (-1)^n}{(n+1)^2}

wispy ermine
grizzled pagodaBOT
#

Renato Chavez

tough mica
amber waspBOT
#

@tough mica Has your question been resolved?

wispy ermine
# tough mica

does this not answer the question? you could also do something a bit simplier and use the fact you can bound the alternating series above by the non-alternating one (which is a p series, as you say, and p>1)

tough mica
#

,av @wispy ermine

grizzled pagodaBOT
#
l.a.y.n.e's Avatar

Click here to view the image.

wispy ermine
#

???

tough mica
#

I was just confused for a sec, I need more practice with this alternating series

wispy ermine
#

fair enough

tough mica
#

ty

#

,, \sum_{n = 1}^{\infty} \frac{(5-3)^n}{n^2 \cdot 2^n} = \sum_{n =1}^{\infty} \frac{1}{n^2}

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

p series p > 1 ==> convergent

#

so its closed interval

#

x in [1,5]

tough mica
#

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tough mica
amber waspBOT
humble ferry
#

hables ingles?

tough mica
#

ye

humble ferry
#

ok great

#

so we know we have an inflection point at x=1

tough mica
#

how to find the range and the k

humble ferry
#

and we know that inflection points occur when f”(x)=0

tough mica
#

no

#

an inglection point occurs when f'(x) = 0

#

maybe it was a typo

humble ferry
#

no, that’s critical point

#

inflection point is when you go from concave up to concave down

tough mica
#

,w define inflection point

grizzled pagodaBOT
tough mica
#

I see

#

f''(x) = 0

#

sry

#

f''(1) = 0

#

,, f(x) = kx^2 - \ln(x) \ f'(x) = 2kx - x^{-1} \ f''(x) = 2k + x^{-2}

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

,, f''(1) = 2k + \frac{1}{1^2} = 2k + 1

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

0 = 2k + 1 ==> 2k = -1 ==> k = -1/2

#

,, f(x) = -\frac{1}{2} x^2 - \ln(x)

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

f(1) = (-1/2) - 0 = -1/2

#

,, f(x) = -\frac{1}{2}x^2 - \ln(x)

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

x > 0

#

Dom(f) = (0, +infty)

#

,, \lim_{x \to 0^+} -\frac{1}{2} x^2 - \ln(x)

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

I am trying to find the vertical asymptote

humble ferry
#

should be at x=0

#

and i believe that the range should be from -inf to +inf

tough mica
#

,w lim x to 0 of ln(x)

grizzled pagodaBOT
tough mica
#

I dont get it

#

like the limit of f(x) when x is approaching 0 is infinity

#

and the limit of f(x) when x is approaching infinity is negative infinity

#

food for thought

amber waspBOT
#

@tough mica Has your question been resolved?

hard ermine
#

What's the problem?

amber waspBOT
#

@tough mica Has your question been resolved?

tough mica
#

,, f(x) = -\frac{1}{2}x^2 - \ln(x)

grizzled pagodaBOT
#

Renato Chavez

tough mica
#

the range of this function

hard ermine
#

Do you know how a regular log function graph looks like?

tough mica
#

ye

hard ermine
#

But there's a negative sign in front of it

#

So it will look like?

tough mica
#

no idea what I am doing

hard ermine
#

This is correct

tough mica
#

xdd good

#

so wat

amber waspBOT
#

@tough mica Has your question been resolved?

untold shoal
#

Was thinking if you rewrite x as e^a, so you will have
ln(e^a) = a.
lim [e^a->0] ln(e^a)
lim [e^a -> 0] a

#

tbh am kinda stuck here on how to write a non empirical proof that e^a -> 0 implies a -> -inf

amber waspBOT
#

@tough mica Has your question been resolved?

bitter ibex
# tough mica the range of this function

just the range?
the only "restriction" here is ln x
that means x must be > 0
because for ln x, x>0 (for negative numbers and 0 the function doesnt have value), you can see that by checking ln(x) graph in desmos or somewhere else
x^2 can be any real number so its ignored
so the range is from 0 to infinity

amber waspBOT
#

@tough mica Has your question been resolved?

untold shoal
#

,w define range

untold shoal
#

,w define domain

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fossil shell
amber waspBOT
fossil shell
#

I don't rlly understand what they are tryna do here

#

They did d^2y/dx^2=0

#

And that value of x has the minimum graident? I don't understand wby

hollow wolf
grizzled pagodaBOT
#

derivada.schwarziana

hollow wolf
#

so you just do second derivative test on z(x)

fossil shell
hollow wolf
#

well, the second derivative test says that

  • any extreme value (i.e. maximum or minimum) of a function must occur on a critical point, so we find points such that z'(x)=0
  • if x is a critical point and z''(x)>0, then z has a minimum at x
fossil shell
#

So this 1.5 is the point of inflexion on curve right

hollow wolf
#

what I called "critical point" above but point of inflexion is another term for that

fossil shell
hollow wolf
#

then z(x) would be a maximum

fossil shell
#

Oh

#

So bascially if we didint use z=graident function and y``(x) =0 if has to either be the maximum or minimum graident

hollow wolf
#

well since y'(x)=z(x), y''(x) would be z'(x)

#

you'd still need one derivative more

fossil shell
#

Oh

hollow wolf
#

the point is, what they're doing here is calc 1 optimization but for the derivative (= gradient) of y(x)

fossil shell
hollow wolf
#

yes

#

it's a point of inflection for z(x) since we're actually finding a minimum of z(x)

fossil shell
#

Oh

fossil shell
hollow wolf
#

point of inflection means a point where the derivative is zero

#

so a point where z'(x)=0

#

then you check the sign of z''(x)

#

(your book does it the other way around for some reason)

fossil shell
#

Oh

fossil shell
hollow wolf
#

it's what you check to apply the second derivative test

#

so if z'(x)=0, then z has a local minimum at x if z''(x)>0 and a local maximum if z''(x)<0

fossil shell
#

Ohhh

#

Ahhh I understand now

hollow wolf
#

in a sense it represents the "concavity" of the function if it's at a point of inflection/critical point

#

but yeah that's all there's to it

fossil shell
#

Hmm okay

hollow wolf
#

you want the minimum gradient of y(x), so you use calculus to find a minimum of z(x)=y'(x)

fossil shell
fossil shell
#

Ohhh I see thanks

#

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grim isle
#

why are the 2 1ohm parallel

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grim isle
#

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fallen chasm
amber waspBOT
inner prawn
#

why is 1 false?

#

also why 2 true

fallen chasm
#

The way I answered it was by finding stuff that are true about graph f’(x). Which ik is wrong cuz it’s asking about graph f(x)

I’m not sure how to visualize the graph of f(x) from that f’(x) graph

inner prawn
#

yea, you answered as if the graph was the f(x)

#

but it's not

#

if f'(x) < 0 in an interval (a, b) then f(x) is decreasing

distant herald
inner prawn
#

and inflection points are where f''(x) = 0

#

these are the definitions

#

use them

distant herald
#

f increases when f' > 0, decreases when f' < 0. and f has an inflection point where f'' changes signs, which is where f' changes from increasing to decreasing

distant herald
inner prawn
#

f''(x) <0 for x< a and f''(x) > 0, for x > a, and vice-versa

#

for some a, f''(a) = 0

#

but it doesn't matter here

#

or do

#

nah

fallen chasm
distant herald
#

sorry if that was hard to read, inflection points are where f'' changes signs

#

there's two primes there

#

so f'' changes signs when it changes from negative to positive, or from positive to negative

#

but since f'' is the derivative of f', this means that an inflection point only occurs where the first derivative f' changes from increasing to decreasing, or from decreasing to increasing

#

and you have the graph of f'

fallen chasm
#

So if f” changes signs, it doesn’t mean f’ changed signs too?

#

How do I figure out where f’ changed signs then cuz i need to find inflection of f(x) for the question

distant herald
#

you don't care where f' changes signs

#

let me clarify

#

you want inflection of f

#

this is where f'' changes signs

#

which is where f' changes from increasing to decreasing, or from decreasing to increasing

#

you don't care where f' changes signs

#

a function can change from increasing to decreasing and still not change signs

fallen chasm
#

OHH

fallen chasm
hollow cape
#

i don't see any points of inflection

fallen chasm
#

Isn’t an inflection when the graph goes from increasing to decreasing ?

#

Or no wait

#

Is it for concave up and concave down?

hollow cape
#

inflection is when a graph goes from concave up to concave down or vice versa

fallen chasm
#

okok yea got it

distant herald
fallen chasm
# fallen chasm

Andd is it true that at interval (Neg inf, 0) and (2,0) in the f’(x) graph, f(x) is increasing?

hollow cape
#

oh i didn't realize that

distant herald
hollow cape
#

sorry for being misleading

distant herald
#

f has inflection at 1, and yes f is increasing on (-inf,0) U (2, inf)

fallen chasm
distant herald
#

we're always talking about f. for f, inflection happens whenever it changes from concave up to down, or from concave down to up. this is equivalent to f' changing from increasing to decreasing or from decreasing to increasing. this is equivalent to f'' changing from positive to negative, or from negative to positive

#

all of these tell you the same thing about f

#

but these are three different ways to find inflection depending on what information you're given

fallen chasm
#

OHHHH

#

I seee

#

I get it now, there’s different ways to get the inflection depending if you have graph of f, f’ or f’’

fallen chasm
hollow cape
#

yep!

fallen chasm
#

Awesomee tysmm guyss !!

hollow cape
#

once again sorry for the little bit of misleading i thought that was a graph of f not f'

fallen chasm
#

nah dww abt it

#

it actually helped me realize finding inflections would be different depending on graph type lol

#

So you’re gooodd

distant herald
#

always make sure you're clear about what you're fidning the ifnormation for and what you're given

hollow cape
#

Yes learn from my mistakes

fallen chasm
#

Loll will doo

distant herald
#

if you were asked to find inflection points of f', you'd have to be looking for where f' changes concavity, where f'' changes increasing/decreasing, or where f''' changes signs

#

so the derivatives and info you look for are all relative to what the problem asks

fallen chasm
#

Oh finding inflection of f’ is a thing? Is finding inflection at f’’ a thing too?

hollow cape
#

You can find inflection points of any polynomial so yes

#

Not only polynomials but all graphs of functions if I’m thinking about it correctly

#

Just think of it as its own problem

fallen chasm
#

ooo okok, I’ll wait till I learn it in class so I won’t confuse myself. But that’s good to knoww

#

Ty againn

#

.close

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#
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runic kraken
#

trying to find the nth derivative of sin(3x), i found (-1)^(n/2) *sin(x+n(pi/2)) but my book says just sin(x+n(pi/2))

runic kraken
#

like it does not mention the change in sign

spiral zealot
#

both seem wrong

edgy sky
#

yeah what happened to the 3 that should be in front?

patent raptor
spiral zealot
#

and what's with the x + n(pi/2)

runic kraken
#

yeah my bad forgot the 3

#

n is element of N_0

proven vapor
runic kraken
#

so its never negative

spiral zealot
#

oh right

proven vapor
runic kraken
#

ah

proven vapor
#

why do you need that (-1)^(n/2) part anyway?

edgy sky
#

first one should be 3^n sin(3x+n pi/2) if Im not mistaken?

patent raptor
runic kraken
#

is that becasue sin is a odd function?

patent raptor
#

sin(x+pi/2+pi) you are basically shifting it half a period which resembles negative sine

edgy sky
#

sin(x+pi) = -sin x

runic kraken
#

ah yeah okay

#

so it changes sign when n is odd ?

#

no

patent raptor
#

sin(3x+pi/2) = cos(3x)
sin(3x+pi) = -sin(3x)
sin(3x+pi+pi/2) = -sin(3x+pi/2) = -cos(3x)
sin(3x+pi+pi) = sin(3x)

#

now you would need the right factor in front

#

so 3^n and done

#

and again (-1)^(n/2) how did you come up with that

#

the division by 2

#

for n = 1 you get (-1)^(1/2) = i

runic kraken
#

yeah idk

#

i was trying many things

#

like -1 ^ 2n-1

#

didnt' work

#

2n+1

#

none of these worked

#

then i asked the forbidden machine

patent raptor
#

I also wouldn't know how to express ++--++ that it changes sign after two derivatives

runic kraken
#

yeah i think it doesn't exist

#

like a sequence that changes sign every second value

patent raptor
#

unless you explicitly define it but the point is to find one unique closed form

runic kraken
#

yeah

#

okok i see it now

#

i drew it on a graph and it became a bit more clear

patent raptor
#

my number 1 advocate is drawing stuff when doing math catking

runic kraken
#

eeh its kinda clear

#

wait when you add pi/2 or pi or any

#

you go back?

#

like you translate the graph to the left?

#

yeah you do

#

now it makes sense

patent raptor
runic kraken
#

okok i see it now

#

thank you very much for your help

#

have a good day

#

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earnest sinew
#

I need help in the statistic software R

amber waspBOT
earnest sinew
#

I have a tsibble table with Microsoft Closure stock prices, and i want to fit Arima models to it

#

but i cant , cause since i am working with stock prices i dont have data at weekends and Holidays

#

so R can t interpret my data

#

But just for the Arima Models

#

i can make the plots

#

autocorrelation functions

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#

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@earnest sinew Has your question been resolved?

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@earnest sinew Has your question been resolved?

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@earnest sinew Has your question been resolved?

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vague raptor
#

Need help with learning series in calculus

vague raptor
#

I need to be able to show that a sequence is bounded or unbounded and to calculate the limit of said sequence. I have to recognize geometric series, show whether p series converge or diverge using integral tests, and recognize when a series is positive, alternating, or neither

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