#help-41

1 messages · Page 30 of 1

pure heron
#

Use complex

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Exponential

nova briar
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wdym?

pure heron
#

To verify your answer

wraith violet
#

What happened to cos a x cos b

indigo cairn
#

cos b

wraith violet
#

Not sure I understand

indigo cairn
#

huh?

wraith violet
#

So sin was being multiplied by cos then it turns into sin + cos

#

The last term disappears as well

amber waspBOT
#

@wraith violet Has your question been resolved?

amber waspBOT
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kindred plover
#

1- one to one
2- not
3- not
4- one to one
right?

split sail
#

yes

kindred plover
#

Thanks to all of you

#

.close

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frigid mountain
#

This is not making any sense

amber waspBOT
frigid mountain
#

Like why does it say "r-1" then it proceeds to write "r+1"

spiral scarab
frigid mountain
#

Combinations

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So nah

spiral scarab
#

wha grade you in rn

frigid mountain
#

This is 11th grade course

spiral scarab
#

👍

frigid mountain
#

Plz

frigid mountain
amber waspBOT
#

@frigid mountain Has your question been resolved?

frigid mountain
#

No 😭

amber waspBOT
#

@frigid mountain Has your question been resolved?

frigid mountain
#

Nope

#

.close

amber waspBOT
#
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frigid mountain
#

Help
Why does it say "r-1" but then it uses "r+1" in the equation

amber waspBOT
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honest orchid
#

need help

amber waspBOT
honest orchid
celest cove
#

what do you think

honest orchid
#

I have no idea

#

tbh

celest cove
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what do domain and range mean

honest orchid
#

x and y

quick ridge
celest cove
#

too vague

quick ridge
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why do all high school teachers do that

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every person in high school would always say domain is x and range is y

honest orchid
#

So whats the answer

celest cove
#

domain is our set of inputs, range is our set of outputs

#

that help?

honest orchid
#

x and y is better

celest cove
#

thats one specific case, for functions of the form y=f(x) where our range is the set of y values and domain is the set of x values
it is not a general concept of domain and range

honest orchid
quick ridge
#

in simple terms the domain is the set of input values which would commonly be denoted by x yes, but as this illustration shows a function is a mapping between two sets, the domain and the codomain, each element in the domain is mapped to an element in the codomain. the range is the set of values the function takes on, or in other words the set of values in the codomain that have a pre image (arrow pointing to them)

honest orchid
#

blud said in simple terms and gave a confusing paragraph😂

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nah thats acutally funny

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😂

quick ridge
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what was confusing?

honest orchid
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were getting off topic here

#

how do i solve this equation

quick ridge
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💀💀

honest orchid
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oh wait

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I think i solved it

quick ridge
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i cant be more clear than this

quick ridge
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do you need it in fortnite terms or something

honest orchid
#

is it

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Number 3

quick ridge
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yea it’s jelly’s channel

celest cove
#

no

honest orchid
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what

quick ridge
#

you linked jelly’s channel

honest orchid
#

accident

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meant to do # 3

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means number

#

blud

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What is this

#

nahh😂

quick ridge
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blud

honest orchid
#

font buggin

quick ridge
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buggin

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yo

honest orchid
#

so the answer not 3

quick ridge
#

are you in 6th grade

quick ridge
honest orchid
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has to be in 2

honest orchid
#

Bro the time running out

#

I needa do this question

celest cove
#

time?

quick ridge
#

ahh it’s a quiz

celest cove
#

oh dear oh dear oh dear

quick ridge
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you need help with the quiz man

#

we GOT YOU

honest orchid
#

Nah

celest cove
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open a book

honest orchid
#

I gotta sleep soon

quick ridge
honest orchid
#

so Im tryna do this assignment

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and i got stuck

quick ridge
#

yea and the time of the assignment is running out huh

honest orchid
#

nah

quick ridge
#

show the full screen blud

celest cove
#

times running out

honest orchid
#

yall crazy

quick ridge
#

nah come on shift

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show the full screen

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trust

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🤝🏻

honest orchid
#

yall people dont help

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only bring people down

quick ridge
#

you dismissed me

honest orchid
#

I asked for the answer not an explanation on domain and range

quick ridge
#

!nosols

amber waspBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

honest orchid
#

i know that already

celest cove
#

we gave you enough information to know what to do

quick ridge
#

we aren’t here to give you the answers

honest orchid
#

but it didnt tho

#

at least tell me how to solve

celest cove
#

we told you

honest orchid
#

lets do vc

celest cove
#

nah

quick ridge
honest orchid
#

its easier

celest cove
#

tick tock chap

quick ridge
celest cove
#

quit yapping and do your test

quick ridge
honest orchid
#

test?

quick ridge
#

question 9 (1 point)

honest orchid
#

lying ass

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i used photomath

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its number 3

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lying for what

celest cove
#

submit it then

quick ridge
#

it’s not number 3

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💀

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nah it is

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you’re right

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photomath is right

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our mistake man

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😂😂😂

honest orchid
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say on bro

quick ridge
#

we were just messing with you

quick ridge
#

😤😤

#

photomath knows best

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we don’t know shit

amber waspBOT
#

@honest orchid Has your question been resolved?

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hollow temple
amber waspBOT
hollow temple
#

How does 2sinxcosx become 1 + sinx

celest cove
#

it doesnt

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they factor out 2cos(x)

hollow temple
#

Aha

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Ty

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While I've still got the channel

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How do I do #6?

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I got 4x over 1-2y

cobalt vigil
amber waspBOT
#

@hollow temple Has your question been resolved?

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normal dove
#

what does it mean that happening of one event confirms non occurence of her in mutually exhaustive set of events?

amber waspBOT
#

@normal dove Has your question been resolved?

amber waspBOT
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@normal dove Has your question been resolved?

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patent slate
#

We know that the limit
(→1)^→inf is Euler's number

patent slate
#

Does the limit
(→inf)^→0 also has a value??

shadow stump
shadow stump
patent slate
#

Okay I know what you mean

#

Another question

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(1+x)^1/x is e where x tends to 0

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So does the limit
1/x ^ (1+x) where x tends to 0 has a value too

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Or 1/x^(x)

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I imagine it as a very big number raised to a very small number →0

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Can it tend to a new constant too?

shadow stump
#

something in the form 1/0 will tend to either +infinity or -infinity depending on the sign. something in the form 0^0 is also indeterminate

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if you want to find the limit of 1/x^x, you can use the fact that x = e^(ln x)

patent slate
#

Then.?

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Cloud where u gone 😦

#

@shadow stump

pallid canopy
#

Use their hint

#

Rewrite x^x with the base x = e^ln(x)

amber waspBOT
#

@patent slate Has your question been resolved?

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cloud niche
amber waspBOT
cloud niche
#

can someone please help me with question 1

shadow stump
#

so each elementary row operation corresponds to a particular elementary matrix

cloud niche
#

ok

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but what does it mean to factor the C matrix

shadow stump
#

so if you multiply C by a particular sequence of elementary matrices, you get the identity matrix (this is how you row reduced it)

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if we call those elementary matrices $E_1, E_2, \ldots E_k$ then we have [ E_k \cdots E_2 E_1 C = I ]

grizzled pagodaBOT
shadow stump
#

what does that tell us about the matrix $E_k \cdots E_2 E_1$?

grizzled pagodaBOT
cloud niche
#

uhmm

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tells us that C can be written as the product of the inverses of those elementary matrices??

shadow stump
#

we have (some matrix)*C = I

cloud niche
#

oh ok

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and the inverse of that

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and that inverse of that (some matrox) is basically the factor C of a product of elementary matricies?

shadow stump
#

yes

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the inverse of that matrix is C, and you can use the properties of inverses to distribute the inverse

cloud niche
#

so

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for work what do I show?

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do i have to show all the elementary operations?

shadow stump
#

well you still need to work out what E_1, E_2, (and their inverses!) are

cloud niche
#

but isnt that given?

cloud niche
shadow stump
#

you are given the row operations, but you still need to write out the elementary matrices corresponding to those row operations (and since you are inverting them, also write their inverses out)

cloud niche
#

ok i will do that right now

#

can you please check my work ill send it right now

amber waspBOT
#

@cloud niche Has your question been resolved?

cloud niche
#

would this be correct?

shadow stump
#

yes, you can confirm by multiplying them all out

amber waspBOT
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@cloud niche Has your question been resolved?

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cloud niche
amber waspBOT
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@cloud niche Has your question been resolved?

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carmine tusk
amber waspBOT
carmine tusk
#

I don’t get the answer at all?

stiff jetty
stiff jetty
amber waspBOT
# carmine tusk I don’t get the answer at all?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
#

@carmine tusk Has your question been resolved?

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cloud niche
#

can someone check my work please

amber waspBOT
cloud niche
amber waspBOT
#

@cloud niche Has your question been resolved?

amber waspBOT
#

@cloud niche Has your question been resolved?

safe jackal
#

Looks good to me and to Wolfram

cloud niche
#

thanks

#

.close

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crisp stratus
#

Prove $a_n \to A \implies \sqrt{a_n} \to \sqrt{A}$

grizzled pagodaBOT
#

artemetra

crisp stratus
#

let $B = \lim_{n\to \infty} \sqrt{a_n}$\
$\implies A = \lim_{n\to\infty} a_n = (\lim_{n\to\infty} \sqrt{a_n}) (\lim_{n\to\infty} \sqrt{a_n}) = B^2$\
$\implies A = B^2$\
$\implies B = \sqrt{A}$

grizzled pagodaBOT
#

artemetra

crisp stratus
#

@stuck vapor sorry for the ping, it's the problem i was doing yesterday. my friend just showed me this proof -- is it any good or is there some flaw here?

#

i guess there is nothing that shows B actually exists - but is it necessary?

indigo cloud
#

you can only split up limits if the limits you get actually exist

amber waspBOT
#

@crisp stratus Has your question been resolved?

crisp stratus
crisp stratus
grizzled pagodaBOT
#

artemetra

stuck vapor
crisp stratus
#

right so the only problem is me saying ``let $B = \lim_{n\to\infty} \sqrt{a_n}$''

grizzled pagodaBOT
#

artemetra

indigo cloud
#

"only"

crisp stratus
#

well..

#

that's the mistake right

#

everything else follows fine it's just that i am making an assumption

indigo cloud
#

didnt you nearly have it last time? you only needed to bound sqrt(a_n)+sqrt(A). that should be doable

crisp stratus
#

i had it last time but Bezier said i needed to show that my formula for another epsilon was surjective

#

which i think is fine but i felt like there would be an easier/nicer way around this

indigo cloud
#

wdym surjective

#

you mean you wanted to choose bla = f(eps) or something?

#

it would probably be enough to have bla > or < f(eps)

crisp stratus
indigo cloud
#

ah well ok

#

like mentioned those are trivial enough

crisp stratus
#

okay thanks

crisp stratus
indigo cloud
#

I dont think there is something simpler than those simple steps

crisp stratus
#

okay

indigo cloud
#

no, it doesnt show existence

crisp stratus
#

understood

#

tysm 🙏🙏🙏

#

.close

amber waspBOT
#
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stuck vapor
crisp stratus
#

.reopen

amber waspBOT
#

crisp stratus
#

i'll write it nicely and send it

stuck vapor
#

Just a nice e-N proof

crisp stratus
#

do i need to involve N?

#

in any way

stuck vapor
#

You don't need to ask
Look at what you need to prove, figure it out

amber waspBOT
#

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fervent oasis
#

how can I solve this using "mod arithmetic"?

fervent oasis
#

the second one

#

is it 5? 3*5=1 (mod 7)

warped sage
#

since we're in mod 7, we want a number thats equivalent to -3

still pecan
#

Yes

fervent oasis
#

thanks

#

.close

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umbral epoch
#

need help

amber waspBOT
umbral epoch
#

anyone to come through?

amber waspBOT
#

@umbral epoch Has your question been resolved?

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cloud niche
#

can someone check my work

amber waspBOT
#

@cloud niche Has your question been resolved?

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split sail
amber waspBOT
split sail
#

Can some explain how to do q4

#

I know
AB
But CB and OC is confusing me

subtle viper
#

Notice BC = b

#

Meaning CB = -b

split sail
#

Yes

subtle viper
#

reversing start and end points of a line segment negates the vector

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And note that AB + BC = AC

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a + b = AC

split sail
#

Wait how is AB+BC=AC

subtle viper
#

If you go from A to B

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and then from B to C

#

That's the same as if you went from A to C

#

start and end points are the same

#

XY + YZ = XZ is a crucial property

split sail
#

Ok but why itd not minus since were trying to figure out CB

#

Oh wait ok so it -a+b?

subtle viper
#

CB = -b

#

since BC = b

#

and AC = a+b, because AC = AB + BC

split sail
#

Ok

#

Go on

subtle viper
#

sry am only partially available, if you're stuck on other vectors just write here

#

And other passengers will help voluntarily :]

split sail
#

Oo oki its oki thank u

#

Ill just keep this one for latr

#

Hv a good day

#

.close

amber waspBOT
#
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amber waspBOT
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bleak mason
amber waspBOT
bleak mason
#

How do I simplify this

#

Im so confused

#

-3^3 is -27

inland pulsar
#

yup

bleak mason
#

-2^4 is 16

inland pulsar
#

yup

split sail
#

-432

#

x^7

amber waspBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

inland pulsar
bleak mason
#

So it’s -27x^3 • 16x^4

split sail
bleak mason
#

Im stuck there I tried solving it and got -11x^7

#

It was wrong

#

Wait where

inland pulsar
inland pulsar
bleak mason
#

Ohhh so -27x times 16x

inland pulsar
#

yupp

bleak mason
#

That’s

#

-432x^2?

#

Cause it’s x times x and I assume it will become ^2

#

Okay so what do I do now

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Is that the answer

inland pulsar
#

coeff is correct

#

x isnt

inland pulsar
#

-27 and 16 are right

bleak mason
#

Ohh

inland pulsar
#

x isnt

bleak mason
#

Why

inland pulsar
bleak mason
#

How

bleak mason
inland pulsar
#

you multiplied the coeff to get -432

#

now multiply the variables

bleak mason
#

Ohhh so -432^7

inland pulsar
#

forgot x lol

bleak mason
#

Woops

#

-432x^7

inland pulsar
#

yupp

bleak mason
#

Okay let me try

#

YAY IT WAS RIGHT

#

thank you

inland pulsar
#

legoo

bleak mason
#

I literally just started this chapter of math today so it’s all new to me

inland pulsar
#

ohh nice

#

you were one of the easier ones for me today

#

not in terms of ques

#

but how you understood

bleak mason
#

I can’t imagine doing anything harder than this I was so confused today in class about it

#

But then again collage boys are really a piece of work and scream like hoolagans so it was hard to hear or understand any

#

Anything

inland pulsar
#

this is college?

#

lmao

#

im in hs

bleak mason
#

Yess first year

#

That’s crazy how u know this in hs😭

inland pulsar
#

we learn these things pretty early

#

gtg

#

!done

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#

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bleak mason
#

Do u know this

#

I don’t understand

#

Idk if the translation is right

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#

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bleak mason
#

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tribal stone
#

do you know how they got the pathlength of 2.4%

shadow stump
#

looks like it comes from reading the graph on the right

tribal stone
#

hm really?

#

how would i read it?

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<@&286206848099549185>

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pallid canopy
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minor night
amber waspBOT
minor night
#

this is the answer for it

#

i dont think its right

#

because it says "for -5/4 < x < 1, f(x) < 0", i.e. y is negative, but y doesnt become negative until x > 1

#

they might have meant f'(x)

#

but am i wrong or are they?

shadow stump
#

i think they meant to say f'(x) rather than f(x) for conditions 2 and 3

#

that does make the solution incorrect for the problem as presented, though

sharp depot
#

the nthe answer is fine

amber waspBOT
#

@minor night Has your question been resolved?

minor night
#

yeah

#

i just marked it as if it was f'(x) and changed my response

#

.close

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abstract arch
#

Can someone help me with this question?

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cloud niche
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cloud niche
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thorn harness
#

whats the difference between this and taylor expansion

thorn harness
#

can i just use taylor expansion for this?

restive orchid
#

effectively, yeah, although I suppose it kind of depends on how you define the binomial expansion

#

for non integer exponents it ends up working out that it matches the binomial coefficients, although the strict definition in terms of factorials won't quite work for you

thorn harness
#

i forgor so i just used taylor

#

like i forgot how to use it

thorn harness
#

cuz if it works ill just keep using it

restive orchid
#

what I sorta vaguely described might not be the same thing you got

thorn harness
#

does taylor always match with binomial

#

when its rational exponents

restive orchid
#

what I'm picturing is $$\sqrt[3]{8+4x} = 2 (1+\frac{x}{2})^{1/3} = 2\sum_{n=0}^\infty \binom{1/3}{n} (\frac{x}{2})^n$$

grizzled pagodaBOT
#

Merosity

restive orchid
#

idk if that lines up with how you did it or not

thorn harness
#

i did both and it aligns

restive orchid
#

how do you evaluate 1/3 choose 2

thorn harness
#

💀

restive orchid
#

1/3 choose 2 should be the third term

#

well, part of it

thorn harness
#

wait

#

dont u just plug into the coefficient formula

restive orchid
#

what's the coefficient formula

thorn harness
#

idk how to type it out like that

restive orchid
#

are you talking about the taylor series or the binomial

thorn harness
#

binomial?

restive orchid
#

I'm going to leave now

thorn harness
#

sorry

#

.close

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crystal cloak
#

How do we do this?

amber waspBOT
crystal cloak
#

I'm getting lim g(x) = 0 from sandwich

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#

@crystal cloak Has your question been resolved?

vestal hatch
#

In that case, solving for limits directly doesn't work because you get infinity*0, right

pale shell
#

You can probably do sandwhich on f(x)g(x)

vestal hatch
#

Maybe try finding lim f(x)/h(x), where h is a simple function that you think grows around the same speed as f as x→0

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visual wren
#

How many simplified fractions are there in 100

visual wren
#

pls help from this question

tulip tapir
#

what?

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#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

grizzled plume
#

@visual wren

visual wren
#

this $#@#

grizzled plume
#

bro is easy

#

look at wikipedia on euler totient

visual wren
#

i thought your saying is a joke

grizzled plume
#

seriously

tulip tapir
#

that question doesn't even make sense

grizzled plume
#

💀

visual wren
#

idk even know what does it mean

#

what next?

tulip tapir
#

no clue

visual wren
#

what is the connection from euler totient

tulip tapir
#

no idea what he meant

#

altho it's an interesting func

rancid raven
#

Although I have never studied this Euler totient

grizzled plume
rancid raven
#

I don't know about it , else I would have helped

grizzled plume
#

i told them to look at it

#

and then see if they could do it

#

!noans

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visual wren
#

!noans

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amber waspBOT
visual wren
#

.close

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tulip tapir
#

tf opencry

solar gust
#

Lmao

tulip tapir
#

hi yaku long time no see

solar gust
#

Hi ren howdy ?

tulip tapir
#

good, wbu

solar gust
#

Doing good, exam soon

tulip tapir
#

oh

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worn vault
#

I have the following pair of equations:
[ x_k\sin\theta + y_k\cos\theta = \sin(\phi_k - \phi_c)] and
[x_k\cos\theta - y_0\sin\theta = \cos(\phi_k - \phi_c)\sin(\lambda_k-\lambda_c)]

worn vault
#

I have two sets of points where $(x_k, y_k, \phi_k, \lambda_k)$ satisfy the equations

grizzled pagodaBOT
#

The د

worn vault
#

this leads to four equations

#

how can I solve for the constants $\theta, \phi_c$ and $\lambda_c$?

grizzled pagodaBOT
#

The د

#

The د

worn vault
#

.close

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#
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split sail
#

can someone explain what the lecturer means when he says this ?

What exactly does he imply when he says "weird sets"

prime cipher
#

Hi 🙂

#

This is linked to a quite advanced concept in measure theory

#

Basicaly

#

When you do probability you measure sets

#

Like on this example, a random point on a square

#

If the distribution is uniform, then to find the probability of the random point going to the left half, you just need to measure the left half and compare it with the measure of the square right

#

BUT

#

This word "measure" is just not easy to formulate

split sail
prime cipher
split sail
#

as in if its drawn on an axis, the unit length is defined as 1 unit and cant be broken down further?

split sail
#

nvm

prime cipher
#

So, like I said, there is a formal definiton to a measure

#

we say that a measure is just three things

split sail
#

go on

prime cipher
#

A set $\Omega$ of the thigs you want to measure For the square, you say just the points in the square

grizzled pagodaBOT
#

LucienF

split sail
#

wait so the word measure in measure theory quite literally stands for measuring things?

prime cipher
#

A set of subsets of $\Omega$ that that the sets you can measure

grizzled pagodaBOT
#

LucienF

prime cipher
#

And a map $\mu$ from this set of subsets to $\mathbb R$, that is your actual measure

grizzled pagodaBOT
#

LucienF

split sail
#

okay so

prime cipher
#

properly

split sail
#

i am dumb

#

actually

#

now that i think about it

prime cipher
#

Don't worry I were too and I'm a Phd student now ahahahah

split sail
#

i was never really told what a set is

#

like literally, mathematically

#

it was always a list or a bunch of like stuff

prime cipher
#

Axioms, not relevant here, just picture a bag of stuffsx

#

Anyway

split sail
#

all the best for your thesis or research

prime cipher
#

The problem lies in the second object, this set of meassurable sets

prime cipher
split sail
#

what is your field/branch of study btw? if you dont mind me asking

prime cipher
#

You cannot find a good map that will both fit the axioms of an actual measure; and be able to measure every sets you can possibly imagine

#

Measure : (Set of things, sets of those things you want to measure, the map that measures the sets)

#

The measure you know on, well everything

#

Thats called the Lebesgue measure

split sail
#

i have never felt this dumb in my entire life

prime cipher
#

To have a proper meaning, it can only measure what we call Borelian sets

prime cipher
#

And you can create non borelian sets

#

So sets that you cannot actualy measure

split sail
#

but what is a borelian set...

prime cipher
#

Complicated

split sail
#

😭

#

i will just learn this later, if ever

prime cipher
#

Just a consequence of the axioms of a measure and this tribe, the set of measurable subsets

split sail
#

will stick to probability for kids

prime cipher
split sail
prime cipher
#

I'll finish by just giving you the link to an actual non measurable subsets

prime cipher
split sail
#

that will be intereseting

prime cipher
#

Ok I was wrong, there is actually a bigger set of measurable sets than just the Borelians but no one knows yet if this is every subsets of the real numbers.

#

ahahah

#

The name of this non-borelian set I mentionned you is the triadic set of Cantor

#

Its a wierd as fuck set that does not fit in this first definition i gave you

split sail
#

i am purely lost, your words are beyond me

#

this thing?

prime cipher
#

Aahahah dont worry, to sum up, a set can have a measure if it fits a precise definition, and some sets does not, so have no measure attached to it, thus no probability

split sail
#

is this even maths..

prime cipher
split sail
#

you dont define something, you dont get a probability for the subset of a function present in the "something"

prime cipher
#

I*ll look at the lecture

split sail
prime cipher
split sail
split sail
split sail
prime cipher
#

I'd say the level of the lecture is Year2 of college

split sail
#

electron probability stuff

prime cipher
#

end of year one

split sail
#

after grade 12?

prime cipher
#

yes

prime cipher
#

sorry

#

Im french ahaha

split sail
#

thansk fro your time

split sail
#

i will enjoy probability, i like combinatorics

#

even tho i do suck at it

prime cipher
#

Your welcome, take care, and don't worry, math is so big that no ones understand everything 🙂 You don't have to feel ashamed if you dont understand something

split sail
#

thank you

#

have a good day

#

.close

amber waspBOT
#
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prime cipher
#

you too bye

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split sail
amber waspBOT
split sail
#

CI = class interval

#

I am not interested in statistics.

inland pulsar
#

lol

#

you will get 2 eqns

#

from sigma(f_i) = N

#

and from mode

amber waspBOT
#

@split sail Has your question been resolved?

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split sail
amber waspBOT
split sail
#

Does it make sense to say $\lim_{x\to\infty}\frac{2(\infty)^3-(\infty)^2}{2-\infty-(\infty)^4}\to\frac{\infty}{\infty}$?

grizzled pagodaBOT
#

forMaths

split sail
#

Cuz otherwise I do not know how to deal with the numerator

#

your writing is weird

keen topaz
split sail
#

What do you mean?

split sail
tender cipher
#

A nice thing to do if u hate the infinities is to just express it in terms of 1/x instead of x

keen topaz
tender cipher
#

Because when x-> infinity, 1/x-> 0

keen topaz
split sail
keen topaz
split sail
#

oh, because that is the biggest power

keen topaz
split sail
#

i see what you meant now

#

okay, will try that and see how it goes

#

thanks people

tender cipher
#

There's a lot of ways to do this

#

Dividing by highest power is one, expressing in 1/x's is another, and also u can always do the repeated lopital here

split sail
#

i'd rather not repeat the L'Hopital

tender cipher
#

U better get used to it

split sail
#

😞

#

Also, could you elaborate more on the second method? Expressing in 1/x's

tender cipher
#

I have used lopital more times than Eminem says fuck

split sail
#

lol

#

well then im screwed

#

because L'Hopital is sooooooooooo boring

#

Actually, limits in general is boring

#

I miss ODEs and homogenous DEs.

tender cipher
tender cipher
#

With z-> 0

tender cipher
split sail
#

Because otherwise I am confused lol

tender cipher
#

It converts ur infinities into nice zeros

split sail
#

Ah

tender cipher
#

Basically if u have x-> inf then write it in terms of z=1/x-> 0

split sail
#

Aha, that makes sense

tender cipher
split sail
#

Gotcha. Will keep this method in mind

#

Yuh

#

Some of it

tender cipher
#

Wait r u doing this as a part of RA course?

split sail
#

I have no idea what RA course is

tender cipher
#

How did u skip to ODEs before limits

split sail
#

lol well

#

i take a private tutor

#

the way it was introduced to us in school was limits first and then ODEs

#

but my private tutor made us do ODEs before limits

#

So things are reversed lol

tender cipher
#

Damn that's crazy

split sail
#

wait

#

but dividing by the greatest power isn't really L'Hopital's rule now, is it?

tender cipher
split sail
#

cuz uhh... heh, uhmm... the question is uhhh

#

demanding L'Hopital's 🥹

tender cipher
split sail
#

AAAAAAAAA IM GONNA DIE

#

ykw, i will just tell my private tutor that i couldnt solve it

tender cipher
#

Tbh simplifying the expression before using lopital should be valid

split sail
#

true

tender cipher
#

No child should suffer repeated lopitals

split sail
#

EXACTLY

#

this is like

#

cyclical integration

#

but worse

tender cipher
#

What's cyclical integration hmmcat

split sail
#

I'd rather find $\int,x\ln((x))^2$ then do L'Hopital's

grizzled pagodaBOT
#

forMaths

split sail
quick spoke
# split sail

weird question but u can just differentiate top and bottom like n times lol

split sail
#

When you integrate by parts but you end up getting the same thing

#

And then you go, "haha you cheeky bastard"

split sail
tender cipher
#

That's not integration then, that's just Sisyphus' punishment

split sail
#

LOL

#

welp, thanks for the help people

#

bye!!!

#

.close

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#
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keen pawn
#

I'm trying to prove that if $a,b\in \Z$, then $lcm(a,b)$ exists

grizzled pagodaBOT
#

Mr bean is not $\R \setminus \Q$

keen pawn
#

So I'm defining $lcm(a,b)=l$ to be that natural number that has the following properties

grizzled pagodaBOT
#

Mr bean is not $\R \setminus \Q$

keen pawn
#

$a \mid l \land b \mid l$

grizzled pagodaBOT
#

Mr bean is not $\R \setminus \Q$

keen pawn
#

and if $a \mid e \land b \mid e \implies e \mid l$

vast spade
grizzled pagodaBOT
#

Mr bean is not $\R \setminus \Q$

lethal steppe
#

Maybe you could use the fact that $\leq$ is a well-ordering on $\mathbb{N}$?

grizzled pagodaBOT
#

FirstNameLastName

keen pawn
#

Yeah, was planning

#

to

lethal steppe
#

What is your question then?

keen pawn
#

so $ab$ atleast is an element

grizzled pagodaBOT
#

Mr bean is not $\R \setminus \Q$

keen pawn
#

so it has a least element

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wanted it verified

lethal steppe
#

Yeah that seems like the right approach to me

#

The set of positive multiples is a nonempty subset of the natural numbers, therefore it has a least element

#

And verifying that it has |ab| as an element should be enough then

keen pawn
#

Thanks!

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earnest sinew
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earnest sinew
#

Consider C as a constant in the next qestions , we have the y is implictly defined as a function of t by the corresponding equations. In each exercise determine an Differencial equation where y is a solution

dapper phoenix
#

Yea Izzy is right

earnest sinew
#

my work

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its the exercice 2

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i differenciate both sides with respect to t

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and i think thats it

dapper phoenix
#

Yeah it might

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Good job!

earnest sinew
#

But in the last exercice

#

my english is not the best i am sorry btw

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i put the ODE in a solver

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and it gave me y = C1/(t^2 +4)

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and then i did a substituion of that expression in the original expression and i didnt get an equal thing from both sides

#

so that means i did something wrong right ?

#

The other ODE didnt have an "easy" solution the solution was written with non elementary fucntions so i couldnt test it

#

<@&286206848099549185>

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shadow swift
#

does anyone know how f(x) = $\frac{1}{h}\cdotln(1+sin2h)$ = $2\cdot\frac{sin2h}{2h}\cdot\frac{ln(1+sin2h)}{sin2h}$

grizzled pagodaBOT
#

Quantie
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

shadow swift
#

h = 1/x

#

its from the proposed solution

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$\lim_{x\to\infty} \left(\ln\left(1+\sin\left(\frac{2}{x}\right)\right)\right)^x$

grizzled pagodaBOT
#

Quantie

shadow swift
#

is the problem

ruby dome
#

Hi

shadow swift
#

yo

brisk nexus
#

Hi

shadow swift
#

alr i got it by small angle approximating, but its a much less elegant solution

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split sail
#

ok so

amber waspBOT
split sail
#

this is straightforward

#

f(x) = +-root(r^2-x^2)
Find the integral of f(x) from -r to r

#

it's pir^2

#

I mean

#

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split sail
#

its just a circle

#

f^2(x) + x^2 = r^2, and what you are trying to find is equivalent to finding the area of a circle of radius r

#

although i think you gotta assume r > 0 as a restriction

#

ok

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slate gale
#

Guys. If sin x/cos x = tan x,
Does that mean sin^2x/cos^2x = tan^2x?

pallid canopy
#

Yes

slate gale
#

Ohhhh i see

slate gale
#

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leaden carbon
#

I have two questions for this.

  1. Where is the -1/2 exponent coming from?

  2. When do we “stop” with the chain rule? My expectation is that since we need to take the derivative of the stuff inside the root, we’d end up with more terms.

Meaning, why does (t-3)^2 not become 2(t-3) * t? Shouldn’t we have to apply the chain rule again?

Perhaps I missed it.

pallid canopy
#

√a = a^(1/2)

#

And power rule for derivatives

#

What else would there be for the derivative past chain rule?

#

They did multiply by the derivative of the "inside" function

leaden carbon
#

I agree with that, but I’m not sure why it’s negative.

And maybe I’m just misunderstanding the inner function, then.

I cannot see why we do not multiply by an additional t.

They have the 2*60^2(t-3) that I expect. But taking the derivative of that requires us to also take the derivative of t-3, no?

#

Because it in itself is a function.

craggy sundial
leaden carbon
#

Oh Jesus, I confused a rule. My bad lol

#

Thank you.

craggy sundial
#

yea it's just 1 so they omitted it

leaden carbon
#

Thank you again!

#

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craggy sundial
leaden carbon
#

I did not, but figured I’d look harder at it now that I wasn’t confused about the 1

#

Could you explain it?

#

.reopen

amber waspBOT
#

craggy sundial
#

yea, so how do we do the power rule on x^a?

leaden carbon
#

Ahhhh, the 1/2-1 is where it’s coming from, right?

craggy sundial
#

yup, mhm

leaden carbon
#

Well, that settles both of them, then lol. Thanks again.

craggy sundial
#

no problem

leaden carbon
#

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junior vale
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junior vale
#

its will be 2m?

solemn escarp
#

no

spare belfry
#

no, why?

solemn escarp
#

factorize m

junior vale
#

ohhh

#

thank you

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calm pewter
amber waspBOT
inland pulsar
#

!status

amber waspBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
calm pewter
#

1

inland pulsar
#

if you have 10 chocolates

#

and want to give it to 2 children

#

how many choco per child?

calm pewter
#

5

inland pulsar
#

correct

#

what about 3 children?

calm pewter
#

3.3333333333333333

inland pulsar
#

good

#

because 0.333... isnt possible

#

we round to 3

#

do the same here

calm pewter
#

kk

inland pulsar
#

16m wood

#

70cm fence

#

how many fence?

calm pewter
#

16 dvive by 70?

#

wait we convert

#

or no

inland pulsar
#

what does convert mean?

calm pewter
#

turn 1 unit to another

inland pulsar
#

yup correct

#

do that

#

then divide

calm pewter
#

16000 devide 17?

inland pulsar
#

nope

calm pewter
#

wait

#

sry

inland pulsar
#

np

calm pewter
#

1600 by 17

inland pulsar
#

yes

#

now calculate it

#

and round it off

calm pewter
#

94.12

inland pulsar
#

,w 1600/17

#

yes good

inland pulsar
calm pewter
#

94?

#

but wait wouldnt it be 95 bc we need more of it

#

hello

inland pulsar
inland pulsar
#

and you wanna give to 3 children

#

you give each 3 or 4?

calm pewter
#

3 but i gotta give some guy bits of other guys chocolate or smth

inland pulsar
#

thus 94

#

not 95

calm pewter
#

ok

#

94

#

whts next

inland pulsar
#

thats the ans imo

calm pewter
#

say no

inland pulsar
calm pewter
#

bc is 17

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upper bound

inland pulsar
#

?

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bc?

calm pewter
inland pulsar
#

yeah me too

calm pewter
#

u had to do 1600/65

inland pulsar
#

why 25?

calm pewter
#

sry

inland pulsar
#

why 65?

#

i think 70

calm pewter
#

no

#

is corrct to the nearest 10cm

#

so

#

to find the largest number possible