help-41

[sharp dock]

2.297

[elder creek]

ye

[sharp dock]

Omg.

All that work

For that answer

💀

[elder creek]

heres an easier way

if you want

[sharp dock]

I hope this shi isn't on the quiz

[elder creek]

where u dont have to make into base 2

you just have to deal with fractions

[sharp dock]

I see

Thank u tho

I appreciate ur help

[elder creek]

np

good luck man

[sharp dock]

.close

[amber wasp]

Channel closed

Closed by @sharp dock

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic fox]

I am doing Sets, Functions and Logic: An Introduction to Abstract Mathematics by Keith Devlin. The question tells you to "simplify the following statements as much as you can". \newline
For ( (3 < 4) \wedge (3 < 6)) am I right to simplify it as (3 < (4 \wedge 6) )? \newline
Furthermore, how would one go about simplifying ((e < 4) \wedge (e^2 < 9))? I don't want to change the two statements by considering (e^2 < 16) or (e < 3) so

[grizzled pagoda]

usopper.

[storm moth]

i believe 3<4 should be evaluated to a truth value assuming < is inequality

[acoustic fox]

Yes < represents inequality here. What do you mean by 3<4 being evaluated to a truth value?

I think I get it. Can I just say 3<4?

Because it* implies that 3<6 and hence contains that fact as well

I figured everything out.

.close

[amber wasp]

Channel closed

Closed by @acoustic fox

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal fjord]

I am looking at the function f(x)=9x^(5/3) (x-2) over the closed interval -8 to 8. Would the point at x=-8 count as a global maximum or would there be no global maximum

[little dagger]

global maxima

A global maximum, also known as an absolute maximum, the largest overall value of a set, function, etc., over its entire range.

Source: wolfram

[little dagger]

x= -8 is its critical point right?

[vestal hatch]

No it's just the endpoint of the interval

[amber wasp]

@surreal fjord Has your question been resolved?

[little dagger]

yup still he will have to check at endpoints and critical points to reach at a conclusion abt global maxima

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night sundial]

why are they putting a constant behind the matrices

[indigo cloud]

you mean in front?

[night sundial]

mb yeah

[indigo cloud]

every entry is multiplied by the 1/2

its just way easier to write that way

instead of 1/2 or -1/2 in every entry

[night sundial]

oh so him putting a 1/2 in front of the 4x4 matrix has nothing to do with the matrix with cos and sin?

[indigo cloud]

well the 2x2 matrices are related

probably

somehow

I dont know the context

but the 1/2 is just how multiplying a number times a matrix works. and it makes the matrix easier to write

[night sundial]

its about orthononal matrices or smth and its length

they measure the length i guess?

and then 1/length

[night sundial]

oh yeah when its pi/4

[indigo cloud]

not quite the signs dont match up

[night sundial]

-pi/4

[indigo cloud]

in the top matrix the top left and bottom right entry have the same sign. in the bottom matrix they dont

orthogonal matrices makes sense at least

[night sundial]

he probably tried to correlate them

but it didnt work out

thanks for clearing things out

.close

[amber wasp]

Channel closed

Closed by @night sundial

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@hidden umbra Has your question been resolved?

[amber wasp]

@hidden umbra Has your question been resolved?

[unique rose]

That's the faintest box OAT

Wait also

Idk if u can just reciprocate the inequalities like that

Because if x squared - 2 was positive it's fine right

But if it's negative I don't think it is?

Or fractional

Maybe it is idk

Yh if a<b with the same signs then 1/a>1/b but if they oppose then 1/a<1/b

[hidden umbra]

well they would be the same signs cause x^2 - 2 < 0

they’re all negative so I assumed I can take the reciprocal and just flip the inequality without issue

[amber wasp]

@hidden umbra Has your question been resolved?

Channel closed

Closed by @hidden umbra

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty kernel]

hi can anyone help me find the zeros to my pre-calc & trig project?

[jaunty kernel]

we are supposed to make an image so I decided to make a tulip but I don't know how to find the zeros to the last two problems because I wrote them weirdly

[amber wasp]

@jaunty kernel Has your question been resolved?

[amber wasp]

@jaunty kernel Has your question been resolved?

[tight lagoon]

Are you required to show the solutions?

As in the equations for how you got the zeros? Otherwise you can find the the zeros just by looking at the graph

Otherwise you can just set the equations to zero and solve for your x-intercepts

[amber wasp]

@jaunty kernel Has your question been resolved?

[jaunty kernel]

yea we have to show our work to solve for the zeros

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[last rover]

what I have so far for part b

There's got be a cleverer way to find the line that cuts the area in half

that also should be "since our result is an odd function"

[amber wasp]

@last rover Has your question been resolved?

[amber wasp]

@last rover Has your question been resolved?

[amber wasp]

@last rover Has your question been resolved?

[winged trench]

@last rover I think I will do exactly what you did here, except using x=a and y=a^2-1

So you can get rid of all the square roots

Not really a cleverer way but at least you can get it solved

[last rover]

what do you mean

[winged trench]

Solve for x=a first

Instead of solving y=k

Since you know y=x^2-1 is symmetric about the y-axis, you get expressed the endpoints of the integral as x=a and x=-a

[last rover]

you mean putting in another variable?

[winged trench]

Yes

[last rover]

parameter rather

[winged trench]

Like $$\int ^a_a a^2-1-(x^2-1) ,dx$$

$$\int ^a_{-a} a^2-1-(x^2-1) dx$$

[grizzled pagoda]

Paradox/James

[winged trench]

After you let a^2-1=k

[last rover]

oh a substitution

[winged trench]

So you can solve it without worrying any square root

[last rover]

I still have to go back and figure out what k is

[winged trench]

Yea

[last rover]

did I make a mistake somewhere with this

because k is larger than 0

[last rover]

@winged trench could you look over my work real quick

oh I see now

I'm blind, made a simple mistake

thank you

.close

[amber wasp]

Channel closed

Closed by @last rover

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lusty pine]

there are 2 red shirt, 3 white shirt, 4 black shirt stacked on eachother, if the probability of the bottom shirt being red and the top shirt is black is $\frac{m}{n}$ where n is a positive integer and m is the smallest positive integer greater than 1 such that $$2024 \mid \prod^{m}_{i=1} a_i^2-i$$ where $a_1, a_2, \dots, a_i$ is some permutation of $1, 2, \dots, i$. Find n

[grizzled pagoda]

Skill_Issue

[lusty pine]

i tried to translate as best as i could, if anyone wants the original here

im pretty sure m/n=4/45

and after that im lost

[fresh ocean]

m/n is not a fraction in its reduced form

so you have to check if 2024 divides that product for m=4, 8, 12, ... till you find the smallest m

but ngl, that a_i is some permutation makes this weird

2024 = 2*2*2*11*23

so for 23 to be a part of the product, we need m=8 at least

so I guess n = 90?

[amber wasp]

@lusty pine Has your question been resolved?

[lusty pine]

yeah

[lusty pine]

how do you know if it can make it tho?

do you just like guess

[fresh ocean]

I am assuming that m/n = 4/45 you got is the correct value in its reduced form

[lusty pine]

yeah

[fresh ocean]

So from that, we need to have all the prime factors of 2024 in that product

[lusty pine]

if it makes it better, i think a better translation is "a_i is a permutation"

[lusty pine]

yeah

[fresh ocean]

So, the only way to obtain 11 or 23 is if m >= 8

23 = 25-2

11=16-5

[lusty pine]

oh ok makes sense

2×2×2 is just 8 and 9-1

i see

[fresh ocean]

yeah

[lusty pine]

alright thanks this made sense

.close

[amber wasp]

Channel closed

Closed by @lusty pine

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gleaming silo]

find the absolute extrema

[gleaming silo]

y = x^2-x-cosx
on [-1,3]

[gleaming silo]

f(-1) = 1.460
f(3) = 6.989
f'(x) = sinx+2x-1

i'm not sure where to go from there

[quick ridge]

set f’ = 0

[gleaming silo]

how do i even solve for

sinx+2x = 1

[quick estuary]

are you allowed to use graphing calcs?

[gleaming silo]

yes

[quick ridge]

are you not allowed a graph?

[quick estuary]

then use it

[gleaming silo]

so f' = 0

thats the root

of the derived graph

[gleaming silo]

the notes were vague on using one, so im unsure

[quick ridge]

you just use a graphing calculator

sinx + 2x = 1

[quick estuary]

that's the value of x that gives an extrema

[gleaming silo]

i meant the steps

[quick ridge]

you find the the x values

[quick estuary]

the solution of f'=0

[quick ridge]

then check f(those values)

compare it to endpoints

[gleaming silo]

(0.335,0)

[quick ridge]

,w sinx + 2x = 1

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by c.knief

[gleaming silo]

so my table would be
---|---
-1 | 1.46
0.335 | -1.167
3 | 6.989

so my absolute min = -1.167 for x = 0.335

and my absolute max is 6.989 for x = 3

[quick estuary]

uh

try plugging in 0.335 into f(x)

[gleaming silo]

oh hsoot

[quick estuary]

yep u got it

[gleaming silo]

ok ty

.close

[amber wasp]

Channel closed

Closed by @gleaming silo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean pike]

hey

[lean pike]

is anyone willing to help with physics?

im struggling with a

[amber wasp]

@lean pike Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solar kestrel]

guys

[solar kestrel]

how do i solve this using the normal method

1. ((x → y) →(z →¬x)) →(¬y→¬z).

so not with truth tables

but with changing around the form of the proposition

no matter what i do

it doesn't result in a tautology

[rough trail]

can you show your working? I might not be able to help personally, my knowledge is limited to the little I have read of a logic textbook. But it would help others help.

[solar kestrel]

sure man, let me take a picture

[amber wasp]

@solar kestrel Has your question been resolved?

[solar kestrel]

<@&286206848099549185>

[amber wasp]

@solar kestrel Has your question been resolved?

[solar kestrel]

whatever

.close

[amber wasp]

Channel closed

Closed by @solar kestrel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal rapids]

hiii anyone can check if my answers r right?

[tidal rapids]

all vertical ellipses

[amber wasp]

@tidal rapids Has your question been resolved?

[tidal rapids]

anayone? 🥲

im super unsure if im doign it right

<@&286206848099549185> so sorry for the ping hope u understand

[empty reef]

Ai use ai

[jovial field]

!nogpt

[amber wasp]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[jovial field]

You know the basics ?

[tidal rapids]

yeah

[iron vector]

im so bored on the pc cus my dad wont bring my phone back

[amber wasp]

@tidal rapids Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solemn escarp]

a survey of a group of people has the following results:
10% of men think they are women
20% of women think they are men
50% of people think they are men
From the information given, what is the ratio of men to women?
3:5, 3:4, 4:3, 5:3

[solemn escarp]

this question is confusing to me

[split sail]

wait

[patent stratus]

actually men + men who think they are women - women who think they are men =50

[sinful sapphire]

the idea is that you think you're a man, if not woman, i guess
if x is men
0.9x + 0.2(1-x) = 0.5

[red knot]

apart from it being a question, what in the brainrot mental illness is this question with men thinking they are women and women thinking they are men

[solemn escarp]

i have no idea

[lyric sable]

they added transphobia to math 🔥 /j

[sinful sapphire]

yeah, solve that you get x, and one of the options fits

[solemn escarp]

howd you get this?

[sinful sapphire]

i didn't get anything, it's the data

it's what they said

[amber wasp]

@solemn escarp Has your question been resolved?

Channel closed

Closed by @solemn escarp

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night sundial]

i dont understand the part where they bring up nullspace into this

[amber wasp]

@night sundial Has your question been resolved?

[amber wasp]

@night sundial Has your question been resolved?

[amber wasp]

@night sundial Has your question been resolved?

[plain coral]

youre looking for a new vector $w$ where $u\cdot w=0$ and $v\cdot w=0$
\which is the same as $\begin{bmatrix}1&1&0&3\end{bmatrix}w=\begin{bmatrix}0\end{bmatrix}$ and $\begin{bmatrix}2&1&1&-1\end{bmatrix}w=\begin{bmatrix}0\end{bmatrix}$
\which is the same as $\begin{bmatrix}1&1&0&3\2&1&1&-1\end{bmatrix}w=\begin{bmatrix}0\0\end{bmatrix}$
\(carry out the multiplication, do it, notice its the same calculation)
\which is the same as that $w$ is in the nullspace of $\begin{bmatrix}1&1&0&3\2&1&1&-1\end{bmatrix}$

[grizzled pagoda]

mtt

[night sundial]

ohh thank you!

.close

[amber wasp]

Channel closed

Closed by @night sundial

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[amber wasp]

Show your work, and if possible, explain where you are stuck.

[patent dock]

.close

[amber wasp]

Channel closed

Closed by @patent dock

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unique snow]

Hi I need help

[unique snow]

Let f:[0;1]—->R be a defined and continuous safe numerical function [0;1] we assume that f(0)=f(1)= 0 and that for all x in [0;6/11]; f(x) = f(x+5/11)
Show that the equation f(x) = 0 admits at least 5 solutions on [0;1]

Can anyone help me solve it

[hearty inlet]

wdym by safe numerical function

[unique snow]

Neglect safe

Just a numerical function

[hearty inlet]

right

[unique snow]

My main language isn’t English so I’m a bit bad

[hearty inlet]

can you find any solutions to f(x) = 0

[unique snow]

We already have f(1) and f(0) that equal 0

So we need 3 more

[hearty inlet]

yep

[unique snow]

I think we’ll use intermediate value theorem

But idk how

[hearty inlet]

nah

use f(x) = f(x + 5/11) for all x in [0, 6/11]

[unique snow]

Sum Ai also suggested using the periodicity of the function

Yes

[hearty inlet]

x=0?

[unique snow]

By that f(0)=f(0+5/11)=0

[hearty inlet]

yes

[unique snow]

3 done 2 more

[hearty inlet]

x=6/11

f(6/11) = f(1) = 0

0, 5/11, 6/11, 1

[unique snow]

Indeed

The last one is the tricky one

[hearty inlet]

tbh i think there are 6 solutions

[unique snow]

If u prove that than u prove there is at least 5 solutions

[hearty inlet]

|| x=5/11 ||

|| x = 1/11 ||

you don't even need continuity

[unique snow]

That’s true

The teacher played w our minds

It seemed very diff

Thank you very much for ur help

. C l o s e

.close

[amber wasp]

Channel closed

Closed by @unique snow

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[leaden vale]

ok so its 2x5=10
10x8=80
80+10=90
90/10=9

? is that right?

hello?

[trim heath]

This is more a physics question

and as for the answer, you're right, its 90N

[leaden vale]

bet

[trim heath]

you might wanna do .close

[leaden vale]

some other guy told me to do 8x10

and 2x10

[trim heath]

they are wrong

[leaden vale]

ok

good to hear

.close

[amber wasp]

Channel closed

Closed by @leaden vale

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow valley]

hi! can i get help with my math question please!! 😄

[willow valley]

the second one (TOPE)

[weak zinc]

Well, do you know anything about diagonals of a parallelogram?

[willow valley]

yeah, they bisect each other

[weak zinc]

Well then, can you cook with that?

[willow valley]

i have an exam tomorrow and its so late, im just brain dead rn 😭

[weak zinc]

Awwwww

You probably should get some rest real soon (and best of luck for the exam! )

[willow valley]

tysm!!! and yeah after doing some more problems i will :]!!

i got a = 6, and b = 4 would that be correct ?

[weak zinc]

there you go

[willow valley]

yipiee!

tysm! i'll close this channel thingie now

.close

[amber wasp]

Channel closed

Closed by @willow valley

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tacit badger]

was hoping someone could check my work, I am also confused on magnitude notation

[amber wasp]

Please don't occupy multiple help channels.

@tacit badger Has your question been resolved?

[tacit badger]

no

[trim heath]

note that i dont have much experience with vectors, but whatever ive seen so far is fine

[tacit badger]

can you just place magnitude signs wherever?

i dont get it

<@&286206848099549185>

[dark ore]

What do you mean by this?

Magnitude notation must be placed wherever there is a magnitude

[tacit badger]

how does magnitude come back in the end of my solution

[stoic ivy]

There are a few issues with your notation

You seem to drop the dot product in a few cases

[dark ore]

It shouldn't come back it should be throughout your proof

[stoic ivy]

You cannot square a vector but you can square a number, so after you do the “foil” you need to have ||v||^2

Ahh discord markup

||v||

That’s what I meant

You shouldn’t have forgotten it

Yeah what Jaxen said

[dark ore]

Your logic is correct tho

[tacit badger]

how do you get from v2 to llvll2

[stoic ivy]

You should be writing it more carefully

You never should have had v2

It’s incorrect

What you have is v.v

[tacit badger]

is that not v2?

[stoic ivy]

And that dot product can be written equivalently as ||v||^2

Remember the dot product is an operation between vectors that returns a scalar

So when you take the dot product of two vectors the output is not a vector but a scalar

You can’t “square” a vector but you can square the magnitude of a vector

And that is the same as taking the dot product of a vector with itself

[tacit badger]

so llvll = v2?

[stoic ivy]

No v^2 doesn’t really make sense

Don’t write it

Write v.v

It’s the vector v dot product with itself

But if you have the magnitude of v

||v||

Then you can square that

So v.v=||v||^2

Your logic in the problem is fine but your notation needs to be repaired

You can’t omit the dot product signs

And you shouldn’t write v^2

You should write v.v -v.w -w.v +w.w

[dark ore]

Also in your final solution you forgot to write the arrow over the w

[tacit badger]

so . Doesn't stand for multiplication?

[stoic ivy]

It stands for dot product

Also called scalar product

[dark ore]

In vector form it's dot product

[stoic ivy]

There are multiple ways defined to multiply vectors together

This is just one of them

That why the notation is important

[tacit badger]

i don't see exactly where I should change my proof

[stoic ivy]

Don’t you see where you wrote v^2

That needs to be either ||v||^2 or v.v

And anywhere that you put wv instead of w.v is not technically correct either

Also when you have |2v|^2

That’s wrong too since the 2 is inside the square

You don’t want 4|v|^2

I recommend rewriting it careful and heed what I have said

[tacit badger]

Ok ill do that thanks

[stoic ivy]

I’m happy to check it again after

Ping me

[glacial steppe]

am i allowed to ask physics questions on here?

[stoic ivy]

#❓how-to-get-help

You can

But in your own channel

[amber wasp]

@tacit badger Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thick seal]

PLS

[thick seal]

WHERE HE GOT

44 total number of squares

🤦‍♂️

i get the purple part

but he didnt explaiin the golden part

[cunning birch]

a) 44 is for bow 1

so triangle

[thick seal]

ya

do i like count the squares and multiply 2 each one

😦

he just said he was able to estimate 44 and wrote it

[cunning birch]

you can just find area of right triangle

[thick seal]

oh

[cunning birch]

base is 10 units

and height is like 8.8

10*8.8/2 = 44 units^2

1 unit^2 = 1 square

[thick seal]

wait

where is 10 and 8.8

from

the graph?

oh

yeah i see

so

350 divided by 40

8.8

0.50 divded bu 0.05

prfcgt ok i see

thnx a lot

[amber wasp]

@thick seal Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steel raptor]

hello,
i'm trying to find the range of f(x) = √4x-x^2
i already find the domain which is [0.4]
the method i'm trying to use to find the range is by integrating the f(x) formula which i change to √4-(x-2)^2
into the inequalities that i obtained from finding the domain 0 <= x <= 4.
but the equation doesn't make sense when i calculate the step that i marked with red "?" mark,
i have no clue how to solve this

[gloomy tide]

yeah you can't just square both sides of an inequality like that

[steel raptor]

i'm following the method that my teacher taught, but they just change the -1 from 2nd pic into 0, am I missing something?

[gloomy tide]

well if we think about this

give me a number between -1 and 1

any number

[steel raptor]

0

[gloomy tide]

ok well that's a pretty boring number but it does work

0^2 = 0 which is in that range

but if we looked at like 0.69

0.69^2 = 0.48

but let's look at negative numbers

(-0.73)^2 = 0.53

also positive

so if you start with a number that's between -1 and 1, then you square it, you'll end up with a number that's between 0 and 1

[amber wasp]

@steel raptor Has your question been resolved?

[steel raptor]

so based on -2 <= x-2 <= 2,
i have to make an assumption that (x-2)^2 is more than 0 and less than 4?, and continue from there?

[gloomy tide]

ye

[steel raptor]

thanks, it's finally align with the graph

[amber wasp]

@steel raptor Has your question been resolved?

Channel closed

Closed by @steel raptor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid fox]

someone can verify this pls

[gloomy tide]

[amber wasp]

@rancid fox Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[minor night]

im pretty sure the answers for part b are wrong

a) says its 9, which i got

but b says its 19 which i dont think is right. its either 9 for signed area (what its asking for) or 21 for total area

can someone double check for me to make sure i'm not going crazy

[amber wasp]

@minor night Has your question been resolved?

[minor night]

<@&286206848099549185>

[quick ridge]

i agree

it’s 9

the integral considers negative area

it didn’t ask for the "area"

[minor night]

ok thanks

.close

[amber wasp]

Channel closed

Closed by @minor night

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real plinth]

how do i do this im genuinely confused

[glad pulsar]

hi

[glad pulsar]

Can u tell what indeterminate form is this

[real plinth]

i have not learned that

[glad pulsar]

oh

[real plinth]

my teacher gave us a hint, here it is:

[glad pulsar]

what happens if u put x=8?

in the function

[real plinth]

if u put 8 it is undefined

[glad pulsar]

yes

do yk l hospital

?

[real plinth]

nope

[glad pulsar]

Well then you have to hse factorisation

use

[real plinth]

i dont understand how they get the 1/3 x at the top

[glad pulsar]

do yk differentiation basics

[real plinth]

yes this is wat we have been using

[real plinth]

explian more plz

[glad pulsar]

they just applied a^3-b^3

Formula

[real plinth]

ohhhhhhh

yes i see that now

[glad pulsar]

which is (a-b) (a^2+b^2+ab)

sorry

if x is a^3

[real plinth]

so x has exponent of 1/3 cayse when cubed it is x again?

[glad pulsar]

then a is x^1/3

[glad pulsar]

correct

[real plinth]

alr thanks

[glad pulsar]

no worries

[amber wasp]

@real plinth Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe mist]

Yo can l get some help

[amber wasp]

Please don't occupy multiple help channels.

[severe mist]

Can l get help

I found the semi circle but not the smaller circle

Forget the numbers the radius of the semi circle is 1 though

I just need to find the radius of the small circle

Hello?

[limpid sun]

what is gauss student ?

[severe mist]

It’s problems my teacher gave me

Hello?

[limpid sun]

interesting

[amber wasp]

@severe mist Has your question been resolved?

[severe mist]

Yes very

[limpid sun]

how did you find the radius of the semicircle '

?

[limpid sun]

maybe I am wrong but the angle in the small circle looks like a right angle ...so if it is the case we can conclude

what about

[severe mist]

Yeh ur definitely on to something

[limpid sun]

we can use pythagora theorem on the righ triangle

[severe mist]

But the line into the small circle isn’t 4

It’s 4+y?

[severe mist]

How do you know the base of that triangle is 4-y?

[limpid sun]

the red line below is 4- the dotted line

[severe mist]

But y is the radius of the small circler

Wait what’s ur equation for y?

[limpid sun]

y is the black line

[limpid sun]

I wrote it in the right angle below in the pic

[severe mist]

Can you just do (4+x) squared - (4-x) squared

[severe mist]

Damn you a thinker

[limpid sun]

actually your method for the first part helped me a lot

[severe mist]

Yeh but you solved it

What did you get as ur answer with the algebra?

[limpid sun]

wait

so x is nearly half of the radius of the semi circle

[severe mist]

Yes

Oh my gosh

[limpid sun]

vey interesting problem though

[severe mist]

My friend just sent me a video

You won’t believe this

[limpid sun]

let's see..an easier method xD?

[severe mist]

https://www.youtube.com/watch?v=qlmHzAX-FwY

The exact answer to the problem

Wowwwwww

[limpid sun]

LET ME SEE

[severe mist]

That’s crazy

[limpid sun]

ok that is impressive ... however I did some mistake somewhere as my answer is not a rational number ...but eventually the equations used are the same

[severe mist]

Yeh thanks for your time and effort appreciate your help

[limpid sun]

thanks! I hope you the best with this contest math problems!

[amber wasp]

@severe mist Has your question been resolved?

Channel closed

Closed by @severe mist

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hexed horizon]

i have found that the roots are + or - (4-4i) but then after this my working divulges from the answer (ik my working above this is right)

[hexed horizon]

solving for z

<@&286206848099549185>

[inland pulsar]

!status

[amber wasp]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[inland pulsar]

@hexed horizon

[hexed horizon]

don’t know how to use what I have done to finalise the answer

2

[inland pulsar]

Share your working?

[hexed horizon]

solved

.close

[amber wasp]

Channel closed

Closed by @hexed horizon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short oxide]

how do i know whether this series converges pointwise or not?
$\sum_{n=1}^{\infty} sin(\frac{n\pi}{2}) sin(nx)$

[grizzled pagoda]

laby_yl

[amber wasp]

@short oxide Has your question been resolved?

[crisp stratus]

$\sin(\frac{n\pi}{2}) = \begin{cases}0 \text{ if } n \text{ is even} \ 1 \text{ if } n\equiv 1 \text{ (mod 4)} \ -1 \text{ if } n\equiv 3 \text{ (mod 4)} \end{cases}$

[grizzled pagoda]

artemetra

[crisp stratus]

does this help?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short oxide]

Not really

[harsh olive]

the series will loop between being sin(nx) + 0 - sin(nx)

[amber wasp]

@short oxide Has your question been resolved?

[short oxide]

But the n’s are different?

[harsh olive]

oh yeah i see what you mean now

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[leaden vale]

A ball is thrown vertically upwards from the ground at a velocity of 12.5 m/s. Approximately, how long does it take to reach the ground again?

[leaden vale]

Assume gravity is 10

[patent stratus]

physics problem

[leaden vale]

yes

[split sail]

what hav eyou tried

[leaden vale]

i just thought u do 12.5-10

ngl

[split sail]

why ?

[leaden vale]

no clue i read it up

everyone says different answers

[split sail]

alr

[split sail]

the motion can be split into 2 parts

first when the ball is going up

and second when going down

[leaden vale]

so thats 12.5

m/s

[leaden vale]

usually 9.81 but in this case 10

[split sail]

duce you just mixed accelration and velocity

[leaden vale]

wdym

[split sail]

nvm

[leaden vale]

oh

[split sail]

familiar with the equations of motion ?

[leaden vale]

nope

fyi this is refreshing on some stuff for an upcoming aptitude test

[split sail]

here you go

[leaden vale]

so havent done it in ages

[leaden vale]

v is final velocity right

u is initial

[split sail]

yeah

[leaden vale]

and at???

acceleration?

[split sail]

a is accelration

t is time

[leaden vale]

t?

right

[split sail]

and s is displacement

[leaden vale]

soooo

my inital velocity is 0

[split sail]

no

[leaden vale]

my inital velocity is 12.5>

?

[split sail]

yes

[leaden vale]

yeah mb

so the accelration is 10?

nah

[split sail]

close

its -10

[leaden vale]

bruhhhhhhhhhhhh

[split sail]

do you understand why ?

[leaden vale]

cus its going down to the ground

not up

🤷‍♂️

[split sail]

cause its going up and not down

[leaden vale]

yeah wrong way around

mb mb

so i do

12.5 + -10xtime

but i dont know time

[split sail]

chill

any idea what v would be as soon as it reaches the maximum height ?

[leaden vale]

0

god

im stupid

[split sail]

yes!

[split sail]

yes!Q

lol

[leaden vale]

ok

so

[split sail]

now find a equation which has v u a and t only

[leaden vale]

0 = 12.5 + -10 x time

what the sigma

[split sail]

correct

thats give time as ?

[leaden vale]

wait so i do it backwards right?

0 divide 12.5?

or just do 12.5 + -10?

which is like

[split sail]

[leaden vale]

i forgot how to solve

equations

[split sail]

idk how to explain algebra so will write it down

so we have 0 = 12.5 + -10 x time

[leaden vale]

yes

[split sail]

-12.5 = -10 x time

mods

[leaden vale]

go to #help-6

oh bruh

join a mental health discord

[split sail]

<@&268886789983436800>

12.5 / 10= time

time = 1.25

get it ?

[leaden vale]

kinda

but isnt it 2.5

cus u have to double it

[split sail]

why ?

[leaden vale]

cus when it reaches top and stops

[split sail]

oh

[leaden vale]

and then when it hits floor and stops

[split sail]

we are still not done yet

[leaden vale]

oh fuck

[split sail]

we just found out the time taken for the fall to reach its maximum height

now we have to findout how long it takes to reach the ground

same method

but you can double it to get the total time

[leaden vale]

Ahhhh

Okay

[leaden vale]

Wait where did u get -12.5 from

[split sail]

i took 12.5 and placed it on the left

[leaden vale]

Oh

So it became a minus

Gotcha

Thanks man

.close

[amber wasp]

Channel closed

Closed by @leaden vale

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deep zealot]

ABC is right triangle
BT is height from B to hypotenuse AC. T is on AC
Two equilateral triangles BTX and BTY are constructed such that
X is on same half plane as A relative to BT
Y is in same half plane as C relative to BT
P is intersection of AY and CX

I am suposed to prove PA* PC=PB* CA=PC* AB

Im trying menelaus theorem to prove using the transversals AY and CX. Do you guys think it work?

[amber wasp]

@deep zealot Has your question been resolved?

[amber wasp]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim belfry]

Hi

[dim belfry]

If i want to differentiate this

[molten shale]

quotient rule

[dim belfry]

Do i use this on the top and them the bottom?

This one?

[naive pivot]

Yep

[molten shale]

yes

[inland pulsar]

first quotient then sum

[dim belfry]

Is this correct to plug in the rule?

Can somebody answer me

[true jackal]

Yes, all correct

Don't doubt too much of yourself 😉

[dim belfry]

So it would be something like this

After this what do i do

.close

[amber wasp]

Channel closed

Closed by @dim belfry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich comet]

why in one question are we multiplying for the combination of the already fixed alphabet and in one we arent?

[rich comet]

Here in the first question mark scheme they multiplied for the combinations of the already fixed numbers too like for AD_ _ its

2C1 x 2C1 x 5C2

But in another question
In the markscheme they only wrote rhe combinations for the empty spaces
like
E M M _ is 5C1 only for the empty space

So im confused. Why are they doing one thing in one question and something else in another

i have the exam tomorrow so help would be really appreciated 😞

<@&286206848099549185>

[unreal thunder]

yeah im also rly confused what the first markscheme is doing

but the question asks for a probability

did they get the right answer

[inland pulsar]

btw 47/50 nice

i guess in probability, you should take all the cases

so you arrange them too

but in the second one they asked for "different selections"

so you dont arrange

@rich comet

[rich comet]

ahhh i see now

makes sense

[rich comet]

thank u : -D

[inland pulsar]

[rich comet]

.close

[amber wasp]

Channel closed

Closed by @rich comet

Use .reopen if this was a mistake.

[unreal thunder]

wait i dont see how 2c1 x 2c1 arranges tho

[rich comet]

.reopen

[amber wasp]

✅

[unreal thunder]

can u show the rest of the working out

[inland pulsar]

yeah not arranges

but i guess the 2 A's are diff for prob

im not very sure tho

[rich comet]

its just 40+10 (obtained by the method 1 as they showed) and then divide by 9C4

[unreal thunder]

ah so they counted duplicates in both steps ok

[rich comet]

wait i didnt get it can u explain

[inland pulsar]

i think they are counting

AD___
and again
AD___

cos 2 A's

[unreal thunder]

yeah

[rich comet]

ohhhhhh bc of probability right

?

[unreal thunder]

yeah

if they asked out of unique combinations, then itd probably be diffferent

[rich comet]

got it :- D was racking my brain over this couldnt get it but now i do

thank u

both

.close

[amber wasp]

Channel closed

Closed by @rich comet

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weak abyss]

"A person runs at the edge of a 100m radius circle at 8m/s, and a friend stands 200m away from the circles center. When the distance between the two friends is equal to 200, at what speed is the distance between them changing?"

[weak abyss]

Im stuck at the part where I need to apply the given speed

or dx/dt (diff x in respect to time)

my friend is at the point (0,200)

[elder harbor]

Can’t u draw like a triangle

[weak abyss]

and im at (+- 25 Sqrt(15),25)

[weak abyss]

how so?

[vestal hatch]

Can you write distance in terms of x and y?

[vestal hatch]

,rotate

[weak abyss]

and I got stuck here

[weak abyss]

so the sine gives us the point when r=1, and if we multiply by 100 its the same if r=100?

[elder harbor]

shouldnt this be

[elder harbor]

yes

[weak abyss]

should it be? I wasnt sure

[grizzled pagoda]

k

[elder harbor]

According to distance formula

[weak abyss]

but then it should be just x, and not x^2, since my point is just x

[elder harbor]

wdym

[weak abyss]

the distance formula is just drawing a triangle right

for the x axis, I draw a triangle between the point x and then the result on the y axis

[elder harbor]

but the position for the man u've given is

x^2 + y^2 = 100^2

[weak abyss]

I see

well then, I understand why we use sine and cos on this

but I dont know how to follow that'd me give a differential theta

is differential theta = 8? or can I use that speed to know its value?

[elder harbor]

howeverrr

by chain rule

[grizzled pagoda]

k

[elder harbor]

@weak abyss

also

this might be a little confusing but

${r\omega = v}$ where ${\omega = \frac{\dd \theta}{\dd t}}$

[grizzled pagoda]

k

[weak abyss]

I got sin= 1/(8^1/2)

[elder harbor]

i distributed wrong btw

[weak abyss]

and then cos= (7/8)^1/2

[weak abyss]

no worries

[elder harbor]

for?

[weak abyss]

for this

[elder harbor]

u are fidning sin and cos for when?

[weak abyss]

when distance = 200

[elder harbor]

i got cosx = 1/4

[elder harbor]

i distributed this wrong

but u get the idea

[weak abyss]

did it again, youre right

@elder harbor

so I replace sin and cos with my values and will get

[elder harbor]

i suggest u expand 100sin^2theta

u can factor 100 out of the square root

[weak abyss]

when I get something along, dD/dt = x*dtheta

[elder harbor]

before staking derivative

[weak abyss]

what can i do with that result?

[elder harbor]

wdym by x*dtheta

[weak abyss]

my equation is dtheta times the result of everything else

[elder harbor]

its not dtheta

its ${\frac{\dd \theta}{\dd t}}$

right?

[weak abyss]

right

[grizzled pagoda]

k

[elder harbor]

now

[elder harbor]

use this

it's from physics 1

but u can prove it in math

[grizzled pagoda]

k

[weak abyss]

hmm that would work, but I think you should be able to use only calculus I to solve this

maybe I can say

theta = arcsin(1/4)?

[elder harbor]

its proof is calculus

for movement along circle

[elder harbor]

shouldn't it be arccosx?

[weak abyss]

I got sin= 1/4 and cos= sqrt(15)/4

friend was at (0,200)

[elder harbor]

oh

that makes sense

[elder harbor]

u can just substitute that in

[weak abyss]

alright I got to go now but I think I got all I need to solve it

thanks !

[elder harbor]

👍

good luck

[weak abyss]

.close

[amber wasp]

Channel closed

Closed by @weak abyss

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raven sage]

I dont know where to start even

[mint nacelle]

do you recall the definition of a pmf?

the sum of all probabilities must be 1

[raven sage]

yeah

function has to be greater than or equal to zero

[mint nacelle]

that's another rule yes

[raven sage]

I dont understand what the zero means tho

does it mean that the function is equal to zero as well

[mint nacelle]

yeah, when x is not equal to 1, 2, 3, .... 10

[raven sage]

oh ok I see

so do I just equal the summation to 1?

[mint nacelle]

yeah

[raven sage]

ok ok I see

what I'm confused about also is what binomial identity do I know to use

[mint nacelle]

what binomial identity are you talking about

you don't need that for the questions you sent

you just need the sum of 1^2 + 2^2 + ... + n^2

[raven sage]

from what I remember, I think the prof used n=(n(n+1))/2

[mint nacelle]

sum of n is that yeah, for the first question

[raven sage]

oh is that for part 2

[raven sage]

yeah so Im confused what binomial identity do I know to use

[mint nacelle]

yes

[mint nacelle]

those are not called binomial identities

[raven sage]

oh

[mint nacelle]

well if you do question 2, you get $\sum_{x = 1}^n cx^2 = 1$

or that $\sum_{x = 1}^n x^2 = \frac{1}{c}$

[grizzled pagoda]

south's secret twin brother

[raven sage]

oh wait ur right cuz there would have to be factorials 😭

[mint nacelle]

no, there are no factorials either

[raven sage]

no I meant for it to be binomial identity it would have to right

[mint nacelle]

what are you even talking about....

[raven sage]

😭 nvm

[raven sage]

oh what u just solved for x^2

that's it

?

its that simple

[mint nacelle]

no, we have the sum of x^2

https://www.youtube.com/watch?v=XJkIaw2e1Pw

sounds like you need some help working with summations

[raven sage]

yeah prob

thanks a lot

[mint nacelle]

so that means $\frac{n(n + 1)(2n + 1)}{6} = \frac{1}{c}$ if you use the formula

[grizzled pagoda]

south's secret twin brother

[mint nacelle]

yeah, c is expressed in terms of n for question 2

[raven sage]

oh I see

is this question similar too

is a probability function referring to pmf?

[mint nacelle]

yeah

[raven sage]

ohh ok

[mint nacelle]

yeah okay so now you need some summation identities

hmmmm

[raven sage]

wouldnt this be just e^2

[mint nacelle]

how btw?

[raven sage]

summation of 2^x / x!

[mint nacelle]

like how did you get that

[raven sage]

one sec let me write it down

[mint nacelle]

it is indeed e^2 actually, I checked on Wolfram Alpha

[raven sage]

oh ok thank god

how do u use wolfram alpha btw it makes no sense to me

[mint nacelle]

ahhhh

I should have thought of that

https://math.stackexchange.com/questions/578111/calculus-computation-of-sum-frac2ii?noredirect=1

yeah lol it's just $\sum \frac{x^n}{n!}$ when $a = 2$, so that's the Maclaurin series of $e^x$ of course

[grizzled pagoda]

south's secret twin brother

[mint nacelle]

,w sum 2^n / n! from n = 0 to infinity

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by sooouth.

[raven sage]

in the end its just gonna be k=1/e^2 then

[mint nacelle]

yep

[raven sage]

ok thanks a lot for ur help

.close

[amber wasp]

Channel closed

Closed by @raven sage

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne swan]

sooooo how do i even start with a question like this

[elder harbor]

Taylor?

[mint nacelle]

oh lmaooooo

[elder harbor]

How do I pull 2n out tho

[mint nacelle]

you need to sub in $n = u + 1$

[elder harbor]

Yeah

[grizzled pagoda]

south's secret twin brother

[elder harbor]

But how do I pull 2n 😭

[mint nacelle]

so that gives you (-1)^(u + 2) = (-1)^u

[mint nacelle]

ahhhh right

try differentiating the summation

I mean integrating