#help-41

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fresh ocean
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and that makes the curve QP a 60 degree arc of circle

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and similarly other 3 arcs too right?

split sail
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yes

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got it

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thank you very muc

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h

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.close

amber waspBOT
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elfin kayak
#

I need help w this using elimination method for non linear equations

elfin kayak
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I already have x but Idk how to solve for y

verbal siren
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Value of x substitue in 4x-y=-1 eqn you will get the value of y
simple

elfin kayak
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Oh I thought u substitute it to eq 1

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nvm

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ok lemme try

verbal siren
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You can do that way also but lengthy becasue of sloving many times x and x2 terms

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In eqn 2 less terms so easy

elfin kayak
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What do I do if my x looks like this tho?

verbal siren
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You will get 2 values

elfin kayak
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ye

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but what if there's still a square root there

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like this

verbal siren
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Slove them simple maths i guess

elfin kayak
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Idk how tho

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like 4(-1 + 2sqroot((13))/3) -y = -1

verbal siren
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If x vlaue is in square root then you will get y also in sqaure root terms only

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But if you want excat values then use the calcultors or any standard values for the near values

elfin kayak
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ok

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lemme try solving and can u check if I got it right?

rancid raven
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Then it's just multiplication division addition subtraction

elfin kayak
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even if it's decimal?

rancid raven
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Or if you want to keep it in √ form

rancid raven
elfin kayak
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aight

rancid raven
elfin kayak
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No

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not really

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I just need y

rancid raven
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Then keep it as root form but simplify a bit more

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As there is a -1

elfin kayak
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I dont get it im sorry

rancid raven
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Do you know this

elfin kayak
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no

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sorry

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πŸ₯²

rancid raven
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Its ok no need to say sorry πŸ˜…

elfin kayak
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oh okay

rancid raven
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Do you know fraction addition subtraction?

elfin kayak
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yeah

rancid raven
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So
a/b - 1 is also same

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Suppose question is
2/3 - 1

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How will you solve it?

elfin kayak
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I forgot how to solve fractions πŸ—Ώ

rancid raven
elfin kayak
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So you will make -1 into -1/1? then solve

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which I forgor how

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I mostly focus on other subjects im sorry

rancid raven
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Can be written as 
2/3 -1/1
Multiply 3 in numerator and denominator of 1/1
2/3 - 3/3
(2-3)/3
-1/3```
elfin kayak
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OHHH

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thank you

rancid raven
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Your solution is similar to this a/b - 1

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Solve it in similar way

elfin kayak
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I remember it being multiplied by numerator then divide it by idk

rancid raven
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Can be written as 
a/b -1/1
Multiply b in numerator and denominator of 1/1
a/b - b/b
(a-b)/b```
elfin kayak
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ty

rancid raven
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No problem

rancid raven
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At the end you need to multiply left and right with -1

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To get y = ....

elfin kayak
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ye

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Ik that part

rancid raven
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Cool

elfin kayak
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um now that it turned into 4+8sqroot((13)) - 3/ 3 what now do I still solve it... if so idk how

rancid raven
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4-3=1 so

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(1+8√13)/3

elfin kayak
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why only 4 is subtracted

rancid raven
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Because you can't subtract a perfect number from root

elfin kayak
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oki thnx

rancid raven
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8√13-3 ? It will only make sense once you convert √13 to decimal

elfin kayak
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oh

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if I somehow turn that into decimal what will happen to 8?

elfin kayak
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will I have to multiply 8 by the decimal

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oh

rancid raven
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8√13 = 8x√13

elfin kayak
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should I just turn it into decimal? since x and y is represented as points

rancid raven
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Sometimes it's written give answer to decimal place or something

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Sometimes just find x,y

elfin kayak
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well with how our teacher solved the other given there was still a square root..

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Ig I should leave it as is lol

rancid raven
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Yep

elfin kayak
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thank you!

rancid raven
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No problem

elfin kayak
#

ur a great teacher/helper have a nice day! (:

#

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languid whale
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Can someone check my work

amber waspBOT
languid whale
inland pulsar
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Hey

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Is there a relation given between V, y, x, z?

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If not I think you can assume them to be independent of V

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And just take them outside the integral

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@languid whale

languid whale
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wym V?

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I pressumed we can set up an integral using any of these bounds in any order

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Inner = dy
Middle = dx
Outter = dz

Thats the order in which I tried to solve it

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(((y^2(sin(3x+2z)))dy)dx)dz)

amber waspBOT
#

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wet depot
#

The value of 6+log 3 2 sqrt 1 3 sqrt 2 sqrt 4 - 1/(3sqrt(2)) sqrt 4- 1 3 sqrt 2 sqrt 4- 1 3 sqrt 2 ... ) is

wet depot
#

The value of 6+log 3 2 sqrt 1 3 sqrt 2 sqrt 4 - 1/(3sqrt(2)) sqrt 4- 1 3 sqrt 2 sqrt 4- 1 3 sqrt 2 ... ) is

amber waspBOT
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amber waspBOT
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@granite shard Has your question been resolved?

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final wyvern
#

Hello, I'm currently studying the Mann Whitney U Test as I'm looking for non parametric testing in our research, question: how were they able to rank this? how did decimals appear out of nowhere?

final wyvern
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wait up, ill send the pics

mint nacelle
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say if you have 10, 20, 20, 30 and 10 is rank number 4

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30 is rank number 7

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so (4 + 7)/2 = 5.5

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both 20s have rank number 5.5

final wyvern
mint nacelle
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with the tied ranks you have 3, 4.5, 4.5, 6

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does that make sense?

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and then same thing, 6, 7, 8, 9 becomes 6, 7.5, 7.5, 9

final wyvern
final wyvern
mint nacelle
final wyvern
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1.5 + 1.5 = 3 units

mint nacelle
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yes!!

final wyvern
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another question:

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when do we know that theres either a separation or

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an even distributionm

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and lastly, is there a non-parametric test that can utilize big samples?

mint nacelle
mint nacelle
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a complete separation means that the highest value of dataset 1 is lower than the lowest value of dataset 2

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or vice versa

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and evenly distributed mean that you get patterns like ABABBABAB

instead of the complete separation AAAAABBBBB, if you rank them from lowest to highest, or highest to lowest works as well

mint nacelle
final wyvern
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i see

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so the data set here i assume is placebo and new drug

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does this mean equal distribution kasi its not complete separation

mint nacelle
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but it doesn't mean it's equally distributed or a complete separation

final wyvern
mint nacelle
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basically new drug = 6 is the only value that stands out

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also we do have placebo = 4 and new drug = 4 so it's not completely separated

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nevertheless most data will not be as separated as this

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it's like about 80 to 90% separated I'd say

final wyvern
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im sorry im asking a lot

mint nacelle
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then you would have [1, 2, 3, 4] and [4, 5, 6, 7, 12]

final wyvern
mint nacelle
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so the data would be basically separated

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there are the two 4s that overlap

final wyvern
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so like

mint nacelle
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but they are the same value

final wyvern
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stand out in the sense that they appear in both datasets

mint nacelle
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from making it be separate

final wyvern
#

is it like context based?

mint nacelle
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the thing you posted just took two extreme cases of what can happen with the data

final wyvern
mint nacelle
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I would rephrase it as, the more the data are separated, the closer U will be to 0

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and the more the data are mixed together, the closer U will be to the maximum possible value
something like (n1 * n2)/2 or whatever

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oh N(N + 1)/2 where N is the total number of observations

final wyvern
mint nacelle
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but 6 is an outlier in [1, 2, 3, 4, 6]

final wyvern
final wyvern
mint nacelle
#

it's the fact that 6 is an outlier in the new drug dataset
AND the fact that it would be in the middle of the placebo dataset

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so that means that 6 is a 'mixed' value

final wyvern
final wyvern
# final wyvern

does the table show that literallyβ€” the 6 is separated from 1-4

amber waspBOT
#

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fallow oriole
#

What are the points (-24, 12) after the transformation of
y = 3\sqrt{f(-x + 2) + 4} - 1?

fallow oriole
#

<@&286206848099549185>

mint nacelle
#

also only ping helpers after 15 mins

fallow oriole
#

My bad

fallow oriole
mint nacelle
#

no, like is the function f(x) given to you?

fallow oriole
#

No they just gave me the points of (-24,12) after I create a mapping rule I guess

mint nacelle
fallow oriole
#

Wym?

mint nacelle
#

doing something like this would be easier

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the problem with the square root is that it's not a neat transformation

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it will change the point differently depending on where in the coordinate plane it is

mint nacelle
# mint nacelle

whereas this transformation only moves everything in the x- and y- directions the same amount
only stretches everything in the x- and y-directions by the same amount

amber waspBOT
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keen pawn
amber waspBOT
quick spoke
keen pawn
#

Just a minute

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I have more pressing concerns to deal with atm, sorry

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.close

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lapis acorn
#

Hello

amber waspBOT
lapis acorn
#

I need some help on trig limits

night ember
lapis acorn
#

If vc is possible that would be super super appreciated

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12/13 on the first one

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My trig in general is not great at all

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And I really need help with trig limits because I have understand most of everything else

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Just trig identities and functions I don’t have a good understanding of
Even after watching multiple videos

amber waspBOT
#

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past ibex
#

I understand that the correct answer is 4/3 > x but why would my operations not work?

past ibex
#

wait give me a second

#

i may have done this correctly and not realized

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.close

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normal dove
#

cant find a solution online which i can understand

past wyvern
#

You want to simplify that sum term?

#

@normal dove

normal dove
#

i tried simplifying an everything to the best of my abilities but it only got uglier

amber waspBOT
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@normal dove Has your question been resolved?

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@normal dove Has your question been resolved?

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deep raven
#

Given $\varphi = xy + yz + zx$ and $\vec{F} = {x^2y, -y^2z, z^2x}$.
Determine at the point $(3,-1,2)$:
$\vec{F} \cdot \nabla\varphi$

grizzled pagodaBOT
deep raven
#

The answer is 5, but I don't know how to get to it

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Gradient phi is {y+z, x+z, y+x}

tulip tapir
#

are you sure about that? check the gradient again.

deep raven
#

ah

tulip tapir
#

after that, simply substitute the values of x, y, and z into F and grad(phi)

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then take the dot product

deep raven
#

really that simple yeah slight miscalc on the gradient lmao

#

th

#

x

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.close

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deep raven
#

.reopen

amber waspBOT
#

βœ…

deep raven
#

$\nabla\varphi \cdot \vec{F}$

grizzled pagodaBOT
deep raven
#

What if its like this now

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I'd assume just take the dot product too

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But the answer here is 10, not 5

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🧐

#

Nevermind, i didnt see phi is now on the left for the last one.

#

.close

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sage chasm
#

im like mega confused on how to attempt this, i tried with schroder bernstein therom but idk if this makes sense

amber waspBOT
#

@sage chasm Has your question been resolved?

sage chasm
#

<@&286206848099549185>

coral wigeon
#

are you asking about how to do 2 or feedback on what you wrote for 1?

sage chasm
coral wigeon
#

if f’s codomain is Z+ x Z+, it should output a pair of positive integers

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not a pair consisting of a positive integer and another pair

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the second part of the proof looks good. g is injective

lime verge
#

is that discrete math?

sage chasm
sage chasm
coral wigeon
#

if y is a function that maps to the positive integers then yea sure

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the inputs to f would be x, a, and b

sage chasm
#

and then i assume i just do the exact same proof with more variables

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for part 2)

sage chasm
coral wigeon
#

if this was proved in lecture, the proof could be pretty similar probably

sage chasm
#

hmmm

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it was used as a lemma but we werent shown the full proof

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i could lowkey just google it and follow it no?

coral wigeon
#

oh actually i have an idea that uses that fact from lecture

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that facts implies there is an injective function y from Z+ x Z+ to Z+

coral wigeon
#

take two different triples (x_1, a_1, b_1) and (x_2, a_2, b_2) and show f(x_1, a_1, b_1) and f(x_2, a_2, b_2) are not equal

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using the injectivity of y

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does that make sense?

sage chasm
#

sort of ? the logic just isnt sitting with me idk

coral wigeon
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Z+ and Z+ x Z+ are both countable so there is a bijection between them

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which is also an injection

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call it y, mapping Z+ x Z+ to Z+

sage chasm
#

AH

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OKAY

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that why is my f(x, y(a, b)) ?

#

y*

coral wigeon
#

then you make a function f: Z+ x Z+ x Z+ to Z+ x Z+ defined by f(x,a,b) = (x, y(a,b)) and you want to show f is an injection

sage chasm
#

perfect

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i get it now

sage chasm
#

and my g is ok ?

coral wigeon
#

yep

sage chasm
#

perfect !!! thank u so much

coral wigeon
sage chasm
#

.close

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weak lagoon
amber waspBOT
weak lagoon
#

Can someone help for number 74

rocky vapor
weak lagoon
#

Wait so is it theta is arctan (800/s)?

#

And do I just find the derivative of that?

rocky vapor
#

tan?

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tan theta = perpendicular / base btw

weak lagoon
#

Oh shit oops arccos

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But then do I just find the derivative of that after??

rocky vapor
#

idk why h is marked (tho nothing is written about it in the question)

weak lagoon
rocky vapor
weak lagoon
#

Yeah

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So would it just be this???

rocky vapor
# weak lagoon

wait there is no t so this should be considered as a cconstant

weak lagoon
rocky vapor
#

lets think this again thonk

weak lagoon
rocky vapor
#

maybe we make 2 functions

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1 of tan and 1 of cos , and then chain rule

weak lagoon
#

okay so theta = arctan(h/800)

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but im still confused on how to differentiate w respect to t

rocky vapor
rocky vapor
#

we need to find in terms of ds/dt and s , so its chain rule

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something like
dtheta/dt = ds/dt * dtheta/ds

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so we find dtheta/ds and i thnk we should get our answer (do u have answer key ?:))

weak lagoon
rocky vapor
#

chain rules states
dtheta/dt = ds/dt * dtheta/ds
we leave ds/dt as it is , and calculate dtheta/ds

weak lagoon
#

can you do step by step (please)

rocky vapor
#

first find the function in terms of s (cos thingy)

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then seperate the theta , u get arccos (s/800)

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chain rule states
dtheta/dt = ds/dt * dtheta/ds

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we differentiate our function with respect to s , get dtheta/ds

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and the rest , we keep it as it is (and u should have a answer consisting of s and ds/dt , which is what they need)

weak lagoon
#

ohhh okay i kind of get it i think

#

but you dont know ds/dt tho

#

like i know you have to multiply it by what i found

#

but like how do you find it

rocky vapor
weak lagoon
#

but what is it or do i just leave it as ds/dt bc it says in terms of

rocky vapor
#

It's basically velocity

#

ur question is to find dtheta/dt "in terms of s and ds/dt" and we did it

amber waspBOT
#

@weak lagoon Has your question been resolved?

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uncut sand
#

Not sure where I’m going wrong here

amber waspBOT
vale marsh
#

,rccw

grizzled pagodaBOT
vale marsh
#

vertex is wrong. do it again
f(-1) = -(-1)Β² - 2(-1) - 5

#

not sure if the axis of symmetry should be x = -1 and not just -1 πŸ€”

#

do the range again

#

@uncut sand

uncut sand
#

Wait

uncut sand
#

With X=-2/2a

vale marsh
uncut sand
#

f(-1) = 26?

vale marsh
#

ok. so you already have x= -1. that is correct. now, susbtitute that to the equation to find y

-(-1)Β² - 2(-1) - 5
(-1)Β² = 1
2(-1)= -2
try it yourself

#

@uncut sand

uncut sand
#

ohhh yeah

#

that makes sense

amber waspBOT
#

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subtle wind
#

This one is quick theoretical question... How can I know if a function f(x) >= x?

subtle wind
#

Like if I have to graph the inverse of a function and the line y=x, how would I know if it's under the line y=x or above or if it touches?

#

Please ping me if you guys know how to do this without having to do complicated mathematical induction πŸ₯² tyy

subtle wind
# pallid canopy depends on the function

what would be the best way of determining if a usual function like a quadratic or exponential and reverse exponential crosses the line y=x without having to substitute x?

#

.close

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sterile cipher
#

Help how do I do this

amber waspBOT
celest cove
#

,rccw

grizzled pagodaBOT
celest cove
#

are you asking how to graph them

amber waspBOT
#

@sterile cipher Has your question been resolved?

sterile cipher
#

Yes

#

And how I even know what to graph like how do I use these equations to be able to graph

#

Something

#

@celest cove

celest cove
#

first get them into y=f(x) form
then do the usual, find any roots, any asymptotes, y intercept

#

once you have those put it together and draw the graph

amber waspBOT
#

@sterile cipher Has your question been resolved?

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sinful sky
#

Consider the propositional formula
F=((B∨C)β†’((A∨¬B)∧C))∨(A∧¬C)
Give a formula G that is equivalent to F, but in which each atomic formula A, B, and C
appears at most once. Prove that F ≑ G by providing a sequence of equivalence transformations with at most 12 steps.
Expectation. Your proof should be in the form of a sequence of steps, where each step
consists of applying the definition of β†’ (that is F β†’ G ≑ Β¬F ∨ G), the following rules: F ∧ Β¬F ≑ βŠ₯, F ∧ βŠ₯ ≑ βŠ₯, F ∨ βŠ₯ ≑ F, F ∨ Β¬F ≑ ⊀, F ∧ ⊀ ≑ F, and F ∨ ⊀ ≑ ⊀. For this exercise, Each step of your proof should apply a single rule once and state which rule was applied.

I am afraid if I did the step 4 wrong ¬B∧¬B. is it correct?

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fluid pecan
#

i need help with part (i)

amber waspBOT
pallid canopy
#

how many ways are there to choose 2 distinct integers from {0, 1, ..., 9} ?

#

similarly for b

fluid pecan
#

9c2*5c2?

sick sandal
fluid pecan
#

the answer is 675 btw, im not getting there

sick sandal
fluid pecan
#

ok got it

#

.close

amber waspBOT
#
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shrewd tartan
#

I need help with c), i got part a but don’t know how to use that to show the equation in c

shrewd tartan
#

this is all i got

formal yacht
shrewd tartan
#

f(a+t) + f(a)

formal yacht
#

Is there a reason you used a+t and not the intended at?

shrewd tartan
#

it should look like this?

formal yacht
#

Yeah, or atleast from what i can tell the problem wants it as

#

Do you see how?

#

We can sort of compare to the other def.

shrewd tartan
#

yea I see now

formal yacht
#

Alright neat

shrewd tartan
#

for c do i just multiply on the right ?

formal yacht
#

For c) i think it might be suitable if you just do that yea

shrewd tartan
#

kk i’m gonna try that out

#

can i combine the t’s any more?

formal yacht
#

It's not quite clear to me where e.g. t^(2n-1) came out of?

shrewd tartan
#

i was trying to do tβ€’t^n-1

formal yacht
#

I see, so t^1 times t^(n-1)

#

do you recall how to rewrite this as?

shrewd tartan
#

oh it would just be t^(n-1) right ?

formal yacht
#

Almost, think of it like this, if we have the same base (t in this case), then we just add the exponents

#

exponent laws or whatever theyre called

shrewd tartan
#

t^(n) ?

formal yacht
#

yup!

shrewd tartan
#

kk thanks !

formal yacht
#

ur welcome, see if that changes your calculation

shrewd tartan
#

this is updated

#

can i combine the t exponents ?

formal yacht
#

Is the last line an equality with the above?

shrewd tartan
#

the first two lines should be the same

#

and the last line is once I cancelled out terms

formal yacht
#

Notice that you also have terms like t^(n-2) over from your first line

#

so that should be cancelled too

#

and in fact every other such terms

#

apart from t^n and -1

shrewd tartan
#

should i not have t^3 ?

formal yacht
#

Like would you agree that e.g. $t\cdot(t^{n-1}+t^{n-2}+\cdots+t^2+t+1)=t^n+t^{n-1}+\cdots+t^3+t^2+t$?

grizzled pagodaBOT
shrewd tartan
#

yes i agree

#

what about the -1 ?

formal yacht
#

and that $-1\cdot (t^{n-1}+t^{n-2}+\cdots+t^2+t+1)=-t^{n-1}-t^{n-2}-\cdots-t^2-t-1$ ?

grizzled pagodaBOT
shrewd tartan
#

yes

formal yacht
#

so notice that when we combine these two

shrewd tartan
#

i got left with the terms t^n + t^3 - t^n-2 -1

formal yacht
formal yacht
formal yacht
#

Or let me maybe make it less ambiguous with sum notation, are you comfortable with that?

shrewd tartan
#

yes i think i got it now

#

does this make sense

formal yacht
#

hm im not sure, thats not clear to me atleast

#

is it okay if i try and explain it via sum notation?

shrewd tartan
#

sure

formal yacht
#

So basically we have that $t\sum_{k=0}^{n-1} t^k = \sum_{k=1}^n t^k$ right?

grizzled pagodaBOT
shrewd tartan
#

maybe sum notation isn’t the best idea

formal yacht
#

Hm okay thats fine

formal yacht
#

its just not terribly clear to me is all

shrewd tartan
#

i don’t get how we cancel out the t^3

formal yacht
shrewd tartan
#

i don’t see where it would be

formal yacht
#

im only limiting myelf from writing out all the terms, the dots here is meant to capture the notion that the terms continue like so

#

i.e if n = 1000

#

then it would be pretty hard to write this all out

#

unless we used sum notation

#

so the dots here (if thats the confusing bit) is meant to capture a pattern

#

i.e 1 + 2 + ... + n

#

implicitly assumes a pattern

#

that say 3 is a term in this sum

#

or 4

#

etc

shrewd tartan
#

yes, i agree, i don’t know how to show that on paper

#

i can’t cross it off physically

formal yacht
# grizzled pagoda **Aslan**

right, and thats okay. We can argue differently. Because would u agree that -t^3 has to be in this subtraction?

shrewd tartan
#

yes

formal yacht
#

neat! so conversely

#

notice how -t^n can not be in this substraction

shrewd tartan
#

yup, and -1 right ?

formal yacht
#

-1 is right at the bottom

shrewd tartan
#

or that can’t be in the t

#

yea

formal yacht
#

yeah so exacatly -1 cant be in the sum

#

of +t's

shrewd tartan
#

yes

formal yacht
#

So we have a bunch of powers of t, one being a sum of them which does not contain -1

#

while the other the substraction does not cointain t^n

#

combining these they should all cancel apart from t^n and -1

#

so we get t^n - 1

shrewd tartan
#

would this be enough writing?

formal yacht
#

Yeah, but i think the parts before are still a bit fuzzy

#

like starting from the first line

#

where is the parenthesis at the end?

shrewd tartan
#

?

formal yacht
#

What's going on here?

#

A bit unclear

shrewd tartan
#

oh i forgot the parenthesis

#

sorry

formal yacht
#

No worries

#

the following lines also make it a bit confusing, im not sure where it ends or start even though you have an equality, or stuff seems missing

shrewd tartan
#

should i write the next two lines on one line?

formal yacht
#

Yes if possible

shrewd tartan
#

kk

#

close

formal yacht
amber waspBOT
#

@shrewd tartan Has your question been resolved?

shrewd tartan
#

yes

amber waspBOT
#
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heavy python
amber waspBOT
heavy python
#

why is delta(y) equal to r(1-cos(theta))

#

the curved part is circular

vestal hatch
#

Because y is rcos(theta)

#

and y+Ξ”y is r

heavy python
vestal hatch
#

Because it's a radius

heavy python
#

oh ye right

#

thats it, thanks

#

.close

amber waspBOT
#
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warm eagle
#

if we being real i have tried this over and over and cant get it

warm eagle
#

pls help man i suck at networks

#

i find https://csacademy.com/app/graph_editor/ is a good place to make these graphs quickly but im still just getting stuck with these questions

#

<@&286206848099549185>

amber waspBOT
#

@warm eagle Has your question been resolved?

amber waspBOT
#

@warm eagle Has your question been resolved?

warm eagle
#

.close

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humble panther
#

guys i want to check, are these equal???

amber waspBOT
#

Please don't occupy multiple help channels.

humble panther
shell osprey
#

the solutions? no?

austere pond
obtuse bolt
#

Making 6x^2+x-1=0

#

Factor the equation

#

(3x-1)(2x+1) = 0

#

We have 2 solution x = 1/3 and -1/2

#

Cos theta = 1/3

#

And cos theta = -1/2

humble panther
#

but yo can rearange one to equal the other

#

you can rearange the second one to equal the first one

#

@obtuse bolt

obtuse bolt
#

Huh??

#

What you mean

humble panther
#

you can use tanx = sinx/cosx

obtuse bolt
#

Yeah

humble panther
#

but they aren't equal

obtuse bolt
#

Yeah that's right then

humble panther
#

but when i sub a number in, lets say 3 i get different answers

obtuse bolt
#

What do you want to find here

#

I mean where is the original equation

#

And what do you want to find

humble panther
#

i want to find why aren't they equal when i sub it in

obtuse bolt
#

Which equation and which equation

obtuse bolt
#

Is that what u mean

#

And

humble panther
#

both of em

obtuse bolt
#

6 cos^2 + cos -1 = 0

#

Let's say that theta is equal to 45

humble panther
#

the two ones at the satar

#

start

obtuse bolt
#

In first equation

obtuse bolt
#

Here

#

Sin^2 +cos^2 = 1

#

Phytagoras theorem

#

That mean sin^2 = 1 - cos^2

#

Hope that help

humble panther
#

i know they are equal

#

its just when i sub in 3, they don't equal

pallid canopy
#

Are you using a calculator or something else

humble panther
#

just liek replace the theata with 3

#

in a calculator

obtuse bolt
#

Yeah Riemann will take care

pallid canopy
#

Type what you mean here. There's a calculator

#

,calc sin(30 deg)

grizzled pagodaBOT
#

Result:

0.5
pallid canopy
humble panther
#

,calc 6cos^2(3) + cos(3) -1

grizzled pagodaBOT
#

The following error occured while calculating:
Error: Unexpected type of argument in function pow (expected: number or Complex or BigNumber or bigint or Fraction or Unit or Array or Matrix or string or boolean, actual: function, index: 0)

#

The following error occured while calculating:
Error: Unexpected type of argument in function pow (expected: number or Complex or BigNumber or bigint or Fraction or Unit or Array or Matrix or string or boolean, actual: function, index: 0)

humble panther
#

,calc 6(cos(3 deg))^2+cos(3deg)-1

grizzled pagodaBOT
#

Result:

5.9821952208594
humble panther
#

there we go

#

,calc 5cos(3deg) -sin(3deg)tan(3deg) +1

grizzled pagodaBOT
#

Result:

5.9904048625295
humble panther
#

see they're different

#

but they're the same thing just rearanged

#

the funny thing is when i don't square

#

,calc 6(cos(3deg) + cos(3deg) -1

grizzled pagodaBOT
#

The following error occured while calculating:
Error: Parenthesis ) expected (char 27)

humble panther
#

,calc 6(cos(3deg) )+ cos(3deg) -1

grizzled pagodaBOT
#

Result:

5.990406743282
humble panther
#

when i don't square they're the same

#

yall got any idea why this is

#

@pallid canopy

pallid canopy
#

Did you try showing they're the same to start

#

You proved it isn't

pallid canopy
pallid canopy
humble panther
#

but they are the same

pallid canopy
#

According to what

humble panther
#

the answers

#

heres the question

#

here's the answers

#

@pallid canopy

pallid canopy
#

,w plot 5 cos(x) - sin(x)tan(x) +1 -(6cos^2(x) +cos(x)-1)

pallid canopy
#

Yea that's not zero

humble panther
#

wdym

pallid canopy
#

But that's because they have specific theta values it has to satisfy

humble panther
#

oh, so they're not the same thing

pallid canopy
#

3 degrees doesn't satisfy this equation

humble panther
#

uh ok

amber waspBOT
#

@humble panther Has your question been resolved?

#
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minor igloo
#

someone help, struggling with this, 8th grade

dull pike
#

What have you tried so far?

minor igloo
#

distributing a and d to get rid of the parentheses

idle light
#

πŸ‘

dull pike
#

Ok

minor igloo
#

then i tried to divide but it just went down hill from there

idle light
#

do you have a paper with your work on it

minor igloo
#

yeah

dull pike
#

Show a picture of you specific status

idle light
#

^

minor igloo
#

give me a second

#

there

dull pike
#

After distributing, isolate x related terms in on side and the others in the other side

minor igloo
#

but then wouldn't x cancel itself out?

dull pike
#

No, because they don’t have the same coefficient

#

They will be subtracted but not canceled

minor igloo
#

ok

#

i shall be back

#

where do i go from here

rancid raven
minor igloo
#

Meaning?

rancid raven
#

ab+ac, factor out a it will become
a(b+c)

#

Like this you need to factor out x

minor igloo
#

oh

#

so then would that lead to ac-de=x(d-ab)

rancid raven
#

Yep

#

Now divide both side by coefficient of x

#

That is (d-ab)

minor igloo
#

thank you

#

how do close the help things

rancid raven
#

Do .close

minor igloo
#

.close

amber waspBOT
#
Channel closed

Closed by @minor igloo

Use .reopen if this was a mistake.

minor igloo
#

.reopen

amber waspBOT
#

βœ…

minor igloo
#

it didn't work

idle light
#

wym

#

give picture

minor igloo
#

look at previous chats

idle light
#

I mean give picture of your solution

#

current solution

minor igloo
#

this is wrong

idle light
#

yes that is wrong

#

it's close but it's wrong

minor igloo
#

then what

#

please

#

i am losing my mind

#

I have been on the same problem for 45 minutes

#

Hello?

idle light
#

can you provide a picture of your solution on paper please

#

I want to see your work

spark dragon
minor igloo
idle light
#

multiply the top and bottom of the expression by -1

#

so -1(ac-de)/-1(d-ab)

#

trust

minor igloo
#

yeah just realized that, sorry, have a good one

idle light
#

and distribute the -1

#

lol

minor igloo
#

.close

amber waspBOT
#
Channel closed

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amber waspBOT
#
Available help channel!

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void steeple
#

just want to check my work. if anyone could confirm that those are right thatd be great.

a) should be $C = \frac{1}{\zeta_4} \$
b) using $E[g(x)] = \sum_{n=1}^{\infty} g(x_n)p_x(x_n)$, got $E[X^2] = \frac{\zeta_2}{\zeta_4}$

grizzled pagodaBOT
amber waspBOT
#

@void steeple Has your question been resolved?

void steeple
#

<@&286206848099549185>

formal yacht
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#

@void steeple Has your question been resolved?

amber waspBOT
#
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rotund dawn
#

Hello, I have a problem with a decomposition into single element (I don't know if this is the right term in English)

here is the equation:
$S(p) = \frac{E}{p(1 + 3RCp + (RCp)^2)}$

I find a decomposition in:

$S(p)= \frac{A}{p}+ \frac{B}{p-p_1}+ \frac{D}{p-p_2}$

$p_1$ et $p_2$ root of the polynomial $(1 + 3RCp + (RCp)^2)$

I have:
$\frac{E}{p(1 + 3RCp + (RCp)^2)}=\frac{A}{p}+ \frac{B}{(p-p_1)(RC)^2}+ \frac{D}{(p-p_2)(RC)^2}=\frac{E}{p(p-p_1)(p-p_2)(RC)^2}$

My question is does i place correctly $(RC)^2$ (thedominante coeficient) in the equation ?

grizzled pagodaBOT
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Silicium

rotund dawn
#

I'm pretty sure i'm wrong

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jaunty shale
# rotund dawn I'm pretty sure i'm wrong

do like this $\S(p)=\frac{E}{p(1+3RCp+(RCp)^2)}=\frac{E}{p \cdot (RC)^2 \cdot (p-p_1) \cdot (p-p_2)} \ \ (RC)^2 , S(p) = \frac{E}{p , (p-p_1) , (p-p_2)} = \frac{A}{p} + \frac{B}{p-p_1} + \frac{D}{p-p_2}$

grizzled pagodaBOT
jaunty shale
#

so basically, the (RC)Β² doesnt show up only under B and D

#

it shows up under A as well

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tough mica
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tough mica
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Let $B = {(4, 1, 2), (0, 1, 0), (-3, -1, -1)}$ be a basis of $\mathbb{R}^3$.

Find all vectors of $\mathbb{R}^3$ such that their coordinates in the canonical basis are double their coordinates in the basis $B$.

grizzled pagodaBOT
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938c2cc0dcc05f2b68c4287040cfcf71

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rotund dawn
# jaunty shale it shows up under **A** as well

I feel really stupid but if I want to find the factors by multiplying by the denominator how do I do it,

For A it's give me
$\frac{E}{(RC)^2}=\frac{A}{(RC)^2}$
For B, what would that give me then, I think that:

$\frac{E}{p_1(p_1-p_2)(RC)^2}=\frac{B}{(RC)^2}$ ? I know it's incorrect but I can't understand why I've been stuck on this for too long, I can't think anymore ;

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Silicium

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keen pawn
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keen pawn
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Trying to prove this via contradiction

mint nacelle
#

hint: show that the square of an integer can never be 2 mod 4

keen pawn
#

what does 2 mod 4 mean

#

I only know $a \equiv b (mod(n))$

grizzled pagodaBOT
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Veni, vidi, perii is not f(wai)

keen pawn
#

I start by assuming $\exists a,b \in \Z$, such that $a^2-4b-2 \neq 0$

grizzled pagodaBOT
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Veni, vidi, perii is not f(wai)

rotund oak
#

I think you’re assuming the wrong thing

half rover
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keen pawn
indigo cloud
#

what does a^2 = 2 mod 4 mean

keen pawn
#

$4 \mid (a^2-2)$

grizzled pagodaBOT
#

Veni, vidi, perii is not f(wai)

indigo cloud
#

which means?

keen pawn
#

$a^2-2=4b$

grizzled pagodaBOT
#

Veni, vidi, perii is not f(wai)

indigo cloud
#

see the connection now?

keen pawn
#

yes

#

We wish to proceed via a proof by contradiction, so we start off by assuming $ 4|(a^2-2)$. Case 1: We assume $a$ is even, and is thus of the form $2n$. We thus have $4n^2-2$. Which isn't a multiple of $4$. We now assume $a$ is odd, and thus of the form $2n+1$. We thus have $4 |((2n+1)^2-2$. So we have $ 4n^2+4n-1$, which isn't a multiple of 4 either. We thus conclude that $4 \nmid (a^2-2)$. QED

grizzled pagodaBOT
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Veni, vidi, perii is not f(wai)

olive quiver
keen pawn
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!occupied

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keen pawn
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<@&286206848099549185>

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solemn escarp
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"Let O be the center of a semicircle which is tangent to circle A and B where RS is tangent to A,B,O and PQ is tangent to circle A,B as in the image. If A,B have radii of 25 and 49 respectively, then find the radius of O"

solemn escarp
#

what ive wrote is basically all ive done

#

im not good at geometry😭

#

<@&286206848099549185>

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@solemn escarp Has your question been resolved?

solemn escarp
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<@&286206848099549185>

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anyone?

solemn hazel
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yeap

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what do you want?

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split sail
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Help

amber waspBOT
rancid raven
#

Is this test/exam live ?

split sail
#

It’s not a test

#

It’s my friends problem

#

I am stuck on it also

rancid raven
#

Well
in bigger cylinder the circumference will be length of rectangle
In smaller cylinder circumference will be breadth of the rectangle

split sail
#

Yes I got that

rancid raven
#

Heights will be vice versa

spiral zealot
split sail
#

Yh

spiral zealot
#

there also seems to be tangible prizes involved

rancid raven
spiral zealot
#

at risk of other potential participants around, probably best not to discuss it here.

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quick mesa
amber waspBOT
quick mesa
#

can someone hgepl me

#

i need to find the degree

#

i asked chat gpt and it did 82 - 25

#

not -82 - (-25)

#

im confused

keen topaz
quick mesa
#

yeah

#

i reasleid its term b - a

#

not a -b

#

so im good now

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vital quiver
amber waspBOT
vital quiver
#

why is the end result 7 bits, not 8?

#

i understand the leftmost bit is the sign bit, but the discard is a bit confusing

#

i guess when using signed-magnitude arithmetic, we only add 7 bits, and keep track if any leftmost bit is a 1 to be negative

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gilded pine
amber waspBOT
gilded pine
#

;rotate

#

.rotate

#

,rotate

grizzled pagodaBOT
gilded pine
#

,rotate

grizzled pagodaBOT
gilded pine
#

i am stuck

#

L'hospital would be very interesting to apply and I doubt it is going to work

split sail
#

uh

#

so u have

#

on the top ln(n+1)?

#

and bottm ln(n+1) + ln(n+1/n)^n?

gilded pine
#

Yep

#

It's not the entire ln at the power of n just what is inside of the ln

split sail
#

ik

gilded pine
#

Any ideas?

alpine flower
#

((n+1)/n)^n = (1+1/n)^n

#

@gilded pine

gilded pine
alpine flower
#

standard limits

gilded pine
#

Oh fuck yds

#

Thx

#

Have a good one thx

#

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normal dove
#

ap,gp,or hp

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@normal dove Has your question been resolved?

strange field
normal dove
#

tried to use known properties

#

for eg if its a hp then a-b/b-c = a/c

alpine flower
#

yea

#

a-b/b-c = a/a

normal dove
alpine flower
#

you can say 1/x-1/y = 1/y - 1/z

normal dove
#

but what abt square root

#

the book assumes some kinda constant after making that ugly aahh form

#

and does some plain ugly math

alpine flower
#

what can you write the first term as

alpine flower
normal dove
#

yeah ik

#

thats a proprety of hp

strange field
#

$\frac{\sqrt{yz}}{\sqrt{y}+\sqrt{z}} = \frac{1}{\frac{1}{\sqrt{y}} + \frac{1}{\sqrt{z}}}$

grizzled pagodaBOT
#

Astar777

normal dove
#

yeah i had similar ideas

#

but had no idea how to proceed

strange field
#

do the same for all, let them a, b and c

#

then (a-b)/(b-c)

normal dove
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ohh

#

got it

amber waspBOT
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hollow quartz
#

So I did a work but I'm not sure about it.
The translation is:
We consider a and b two real numbers different from zero such as aΒ²+bΒ²=6ab
1/ Prove that a and b have the same sign
2/ Determine the value of a+b/a-b

grizzled pagodaBOT
hollow quartz
#

Here's my work

hollow quartz
#

Tnx and part 2 ?

mint nacelle
#

yep that also is correct! good job on the casework

#

I think you should write $a - b = \pm 2\sqrt{ab}$ though

grizzled pagodaBOT
#

higher's secret twin brother

mint nacelle
#

or you don't actually need that part

hollow quartz
#

Ok thank you so much ! I think the redaction can be a little be better that's why I was worried about the content

hollow quartz
mint nacelle
#

yeah you can just skip straight to if a > b after you obtain (a + b)^2 / (a - b)^2 = 2

#

no worries!

hollow quartz
#

Thanks for going through it even though its not in English! Thanks a lot !

mint nacelle
#

no worries it helps that I can read French but not speak it

hollow quartz
#

That's a relief thank you so much again !

#

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split sail
#

Hi, how does one "describe Aut(C5) and Aut(C7)"?

quick spoke
#

(hint: for each automorphism, think about what 1 maps onto)

split sail
#

does that describe though?

#

My friend wrote a paragraph as her answer she told me

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@split sail Has your question been resolved?

quick spoke
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there's a very 'simple' group that's isomorphic to Aut(C_5) in this case

#

(using simple and normal in the normal english way lol)

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heady moss
#

quick thing

amber waspBOT
heady moss
#

how do get an absolute value of a vector?

#

|a| if a= <3,4,4>

celest cove
#

with pythagoras
sqrt(3^2+4^2+4^2)

heady moss
#

thank u man

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appreciate it

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surreal hedge
#

i know the answer, but im not sure of the equation i'd have to set up

wanton sentinel
#

A two-digit number is just 10a+b where 1 <= a <= 9 and 0 <= b <= 9

surreal hedge
#

okay

#

uhh

#

😭

#

how would i write out the equation tho

#

like ik id have to subtract 54 at some point

wanton sentinel
#

Well, reversing its digits gives you 10b+a instead

surreal hedge
#

right

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but where would i subtract 54

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.close

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mint patio
#

why not?

amber waspBOT
pallid canopy
#

$\int dx = x + C$

wanton sentinel
#

You forgot the 3?

grizzled pagodaBOT
#

riemann

mint patio
#

oh its 3x

#

sorry its my first ever integral

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mint patio
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.reopen

amber waspBOT
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βœ…

mint patio
#

second ever integral