help-41

[tulip tapir]

if and when you have a doubt

we'll be more than happy to help you

[unreal kettle]

I HAVE DOUBT

[pallid canopy]

what are you willing to exchange for nitro

[tulip tapir]

but don't reserve channels

because other people need them too!

[coral wigeon]

math girl pee obviously

[dull pike]

Stop the spam maybe?

[tulip tapir]

do you currently have a specific math problem that you need help with?

[tulip tapir]

yeah agreed guys

[split sail]

what the hell

[tulip tapir]

we're giving off very mixed vibes to poor lex

[tulip tapir]

it's layla, don't question it

[tulip tapir]

@unreal kettle ?

[native stag]

If and when you do open a channel, you can ping me right away I won't mind.

[sick sandal]

The channel is closed. There's not really a need for regulation.

[native stag]

Whether or not I see it though...

[unreal kettle]

channel is close

[tulip tapir]

yes

@unreal kettle look

[coral wigeon]

wait is there something you want

[unreal kettle]

cannot speak at this time

[tulip tapir]

do you have a specific math problem that you need help with right now

[unreal kettle]

leave a message

[native stag]

pfft okay

[tulip tapir]

uh

okay...?

[unreal kettle]

help malara92

[pallid canopy]

[tulip tapir]

you mean

malaraj62?

[coral wigeon]

ren i think 5 times is enough

[unreal kettle]

yes

[native stag]

@unreal kettle .

[tulip tapir]

riemann
layla
PLEASE

stop with the spam

[coral wigeon]

you are spamming more than me lol

[unreal kettle]

spam i hate spam its too salty

[native stag]

he's tryna be nice

[tulip tapir]

are you certain it is a specific problem? if so, #help-12

[unreal kettle]

help malara62

[sick sandal]

The channel is closed

[tulip tapir]

you can have this discussion in #「helpers-lounge」 too yk

[tulip tapir]

and i am trying to explain how channels work to lex amidst their mixed signals

[native stag]

what channel is that lol it says no access for me

[sick sandal]

If Lex want to use it for help, she can reopen it or open a new.

[sick sandal]

#❓how-to-get-help

[tulip tapir]

*sighs*

[native stag]

do not rtfm her lmao

[sick sandal]

👍

[tulip tapir]

i think you mean malaraj62 but sure

[tulip tapir]

dk what that means but okay

ah okay

[native stag]

oh 'read the fucking manual'

[amber wasp]

Available help channel!

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[midnight harbor]

would this be graph a, one unit to the left

[split sail]

true

[past cedar]

What do you know about graph transforms on the x and y axis?

[midnight harbor]

/close

.close

[amber wasp]

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[past cedar]

Oh nvm you got it.

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[tough snow]

What should be in the parenthesis

[vernal swan]

what do u think

[smoky spade]

3

x + 3

[tough snow]

Thats why i asked for helt

Nope

[smoky spade]

you could use the guadratic formula

quadratic formula

[tough snow]

Idk what that is

[pallid canopy]

,rotate

[grizzled pagoda]

Couldn't find an attached image in the last 10 messages.

Sep 24, 2024, 5:35 PM

[smoky spade]

it's x + 3

[pallid canopy]

,tex .quadratic formula

[grizzled pagoda]

riemann

[tough snow]

Wouldnt it be this then

Hold on lemme send photo

That would be the answer if your answer was correct

[smoky spade]

No, one sec Imma work it out

[tough snow]

Ok

Cant i use delta

For this

[smoky spade]

wdym

[tough snow]

arent you supposed to multiply the two parenthesis together?

[smoky spade]

you should multiply the numbers individually using the rainbow method

https://www.bbc.co.uk/bitesize/guides/zcqmsrd/revision/4

[amber wasp]

@tough snow Has your question been resolved?

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[thick seal]

am i supposed to memorize this

[thick seal]

like i thought chem was more like math

this lecture seems like biology type of slides

[split sail]

bro thought chem was more like math 😭

[thick seal]

😭

[split sail]

well yea ur supposed to memorize this

[thick seal]

well they say 1 2 adnd 4 not so true

so da heck

[split sail]

wait until bro realizes about sub-atomic particles

[thick seal]

im cooked

[split sail]

fr

[thick seal]

i hoep that not on my exam thats on oct 1

😭

[split sail]

bruh u got like a whole week to remember those 4 points

[amber wasp]

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[tacit karma]

no idea where to start with this

[solar gust]

What is f(x+h) ?

[reef kraken]

They are asking you to find the first derivative using limits ig?

They should specify what h is though

[keen topaz]

! status

[amber wasp]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[solar gust]

Yeah they forgot to put lim as h goes to 0

[inland pulsar]

h is a very small number

it is kinda understood

[inland pulsar]

yeah

@reef kraken ?

[reef kraken]

Not my question

[inland pulsar]

sorry

@tacit karma

[amber wasp]

@tacit karma Has your question been resolved?

[amber wasp]

Channel closed

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[calm pewter]

somone help me out

[split sail]

Is it reallight or rea light ?🤔

[split sail]

What have you tried ?

@calm pewter

[calm pewter]

realight lol

[calm pewter]

hmm

i was thinking to do

25x67.8

55x72.0

then minus

idk

[proud gull]

Yeah

The subtraction will give u the total marks by the 35 students

[calm pewter]

so am i goin the right way?

[proud gull]

Yes

[calm pewter]

kk thanks

[proud gull]

Assume mean mark for 35 students be x then solve it

[calm pewter]

@split sail ty for tryin to help thanks @proud gull

[calm pewter]

i think i got it

ty

[proud gull]

Okay

[calm pewter]

.close

[amber wasp]

Channel closed

Closed by @calm pewter

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[split sail]

I asked a question myself

Sorry I was answering other guys question

[amber wasp]

Available help channel!

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[swift bronze]

im stuck on this problem, can someone explain to me how to start it?

[swift bronze]

thats my work so far

[amber wasp]

@swift bronze Has your question been resolved?

[swift bronze]

<@&286206848099549185>

[amber wasp]

@swift bronze Has your question been resolved?

[swift bronze]

<@&286206848099549185>

[swift bronze]

PLEASEEEEEE SOMEONE HELP ME😭😭😭😭

ima migrate atp

.close

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Channel closed

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[amber wasp]

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[pallid canopy]

sir this is a math server

[final matrix]

I can't read what the image says

[pallid canopy]

#old-network for chem server

[final matrix]

what kind of help do you need exactly?

answer check?

[quartz hornet]

Yup

[final matrix]

looks right to me

you can always check online as well

[quartz hornet]

Never right

[final matrix]

for something this simple it will be right 99% of the time

especially if you know where to look

[quartz hornet]

Whhat about advanced

Like this

[final matrix]

dependent on the subject but I would definitely try and find reliable sources

[final matrix]

first one isn't right

and third one

[quartz hornet]

Why

[final matrix]

because aluminium ion is a 3+ charge

and Magnesium is a 2+ charge

[quartz hornet]

Ahhh so it would just be 1

Mg

And for the aluminum

[final matrix]

and then Al2O3

[quartz hornet]

Al0_3

[quartz hornet]

Why is the 2 still there

[mint wraith]

O is -2 and Al is +3

[quartz hornet]

But for Mg why would it be stripped

So this?

[mint wraith]

Yes

[quartz hornet]

Why did Mg lose it’s 2

But Al kept the 3

[final matrix]

it doesn't lose anything

[quartz hornet]

Since the BA charge is double

This should be correct?

[quick spoke]

yeah that's correct

then you can basically do something similar for the latter 2

[amber wasp]

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[thick seal]

not really getting this slide

so like

i look at the periodic table

and each time they go up ur multiplying by 2?

or if gOing down divide by 2?

[split sail]

$\frac{16}{2} = \frac{8 \times 2}{1 \times 2} = \frac{8}{1}$

[thick seal]

so thisoe masses

[grizzled pagoda]

icannotdoanymorecauchy

[thick seal]

oh

.close

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Remember:
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[noble girder]

can someone help me with my math homework? its due soon and i need it turned in because its late :c

[tawdry lintel]

What’s the topic

[noble girder]

algebra 2

[tawdry lintel]

Just post the questions here and explain what you’ve done

[noble girder]

i dont understand it

[tawdry lintel]

Which part are you struggling with

[noble girder]

everything, my teacher doesnt know how to teach and she just does the work without explaining it

[tawdry lintel]

Okay, let’s start by breaking down the domain. What is a domain?

[noble girder]

uhh

the values we can use in a function

[tawdry lintel]

Speaking specifically when looking at a graph

What does it mean to have an all inclusive domain (all real numbers) and a domain that is limited

(Expressed as an inequality that excludes values)

[noble girder]

i dont know

[tawdry lintel]

That’s fine, the domain refers to the x values

When looking at a graph, a domain that includes all real numbers (x ∈ ℝ) reaches from negative infinity to infinity

Could you guess then, what the range is?

[noble girder]

what dsoes that ∈ symnbol mean? i dont think we use those

[tawdry lintel]

Means belongs to

[noble girder]

y values?

[tawdry lintel]

Yes but in the same terms that I used

Or in your own words

$x\in \mathbb{R}$

[grizzled pagoda]

mari

[amber wasp]

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Remember:
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• Show your work, and if possible, explain where you are stuck.
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[hollow temple]

How does the second to last step turn into -1/2t^-3/2?

[rustic portal]

note that 1/t = t^(-1)

and 1/√t = t^(-1/2)

[hollow temple]

oh, so just keep the like terms and add the exponents?

[rustic portal]

sorry man, i had a typo

[hollow temple]

i got what you meant, dw

[rustic portal]

and yea, and add the exponents, you'll get the answer

[hollow temple]

cool, thanks!

[amber wasp]

@hollow temple Has your question been resolved?

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Channel closed

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[ocean dirge]

help me

[ocean dirge]

question b) the 2nd one

y no pple help 😞💔

[amber wasp]

@ocean dirge Has your question been resolved?

[ocean dirge]

💔

[dusk terrace]

b 2?

any thoughts?

do you know what cosec x is?

the cosec function in general

are you familiar with it

[ocean dirge]

no

i mean yes but i forgot all of it

where u goneeeee

😭😭

<@&286206848099549185>

[ashen ginkgo]

Hw

[desert rover]

mitch back off

[ashen ginkgo]

Hewwo...

[desert rover]

she’s mine

[ashen ginkgo]

NO

Stop it i got here first

[ocean dirge]

help pls

[desert rover]

are they two separate equations?

[ocean dirge]

bro i waited so long for some1 to help me

[desert rover]

i was reading question

[ocean dirge]

yes

[desert rover]

i got u aly dw

NO GET IUT

[ocean dirge]

😭😭

[desert rover]

is cosec a typo or is it cosecant?

like is that supposed to be cos * sec?

[ocean dirge]

its cosec

[ocean dirge]

idkkk

[desert rover]

if it’s cosec

then it’s js 1/sin

[ocean dirge]

this what i got so far from chtgpt

[desert rover]

well 1/sin(x)

well for 1

the top equation is simple since 1 = sin^2 + cos^2

[ocean dirge]

yeah top one is done

by other pple

[desert rover]

second equation get common denominator

[ocean dirge]

whats that

[desert rover]

common denominator for the fractions??

so that you can simplify them

[ocean dirge]

huh

[desert rover]

bc rn u can’t add/subtract them

bc they have diff denominators

[ocean dirge]

this correct?

[desert rover]

give me a sec

[ocean dirge]

okay

[proud gull]

This is right

Lemme know if u don't get it

[ocean dirge]

ouuuuuuuu

can u explainm?

[proud gull]

Okay first we need to simplify the above question into one single term

Which is sinx

And we know 1/cosecx = sinx

And cos^2x = 1-sin^2x

So now we have everything in sinx

Right ?

Got it ?

Just simplify the terms further and we will get a quadratic equation in terms of sinx

[ocean dirge]

yess

[proud gull]

Assume sinx as x and solve the quadratic equation

By factorial method

We will get two roots given above for the equation

[ocean dirge]

wait lemme copy the thing first

[proud gull]

Okay 👍

Btw let sinx =0 is a written error on the sheet what I meant was let sinx =x

To solve these kinda questions u need to have a strong base in trigno identities

Grind away

[ocean dirge]

doneee

explain again

[proud gull]

First thing we saw is there are different trigno terms in that equation right ?

Which will be difficult for us to solve

[ocean dirge]

how do u change the 1/12 cosec x

[proud gull]

Cosecx =1/sinx

It's an identity

[ocean dirge]

ohh

[proud gull]

Yeah

Wait

[ocean dirge]

okay

[proud gull]

Look at reciprocal identities

I suggest u practice all these identities and then solve the questions

U got it ?

[ocean dirge]

wait wait

lemme process

ohh okok

got it

continue w the explanation

[desert rover]

the only ones u rlly need are the squared and the reciprocal

bc the others are derived from those

[ocean dirge]

ohh

[desert rover]

when i say squared i mean pythagorean

[ocean dirge]

squared u mean half angle formula?

[ocean dirge]

huh

[proud gull]

No squared as in the power 2

[desert rover]

nono pythagorean

[ocean dirge]

ohhhhhhhh

[desert rover]

not the square root

[proud gull]

Yup

Did u understand the solution?

[ocean dirge]

kinda

[proud gull]

I could explain in VC if u don't mind

Or should I explain it here

[ocean dirge]

here cause im out rn

[proud gull]

Ok

[ocean dirge]

doing the discussion

[proud gull]

So the first step is to make the equation all same terms

Which is sinx ..we can make all the different trigno terms into sinx

U got this part ?

[ocean dirge]

yes

[proud gull]

After making it all sinx we solve and what we get is a quadratic equation in sinx

U got this ?

[ocean dirge]

yeahh

and we just proceed the thing ?

[proud gull]

And u know how to find roots of a quadratic equation right ?

[proud gull]

Yup

[ocean dirge]

no

[proud gull]

U don't ?

[ocean dirge]

yeah

i dont

[proud gull]

Okay

Which grade ?

[ocean dirge]

uni

im js rlly bad at math

[proud gull]

Use this method

We will get the roots by this method

[ocean dirge]

y the plus thingy got a line under

[proud gull]

It's plus and minus

[ocean dirge]

ohhh

i saw that b4 and i thought its like another symbol

[proud gull]

Good luck for the next questions

[ocean dirge]

ohhh okok i kinda get it

how to do the quarter

wait no

the

quartile?

i think

[desert rover]

like in statistics??

[ocean dirge]

whats that

.close

[amber wasp]

Channel closed

Closed by @ocean dirge

Use .reopen if this was a mistake.

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil pasture]

A ladder is leaning against the side of a
building. The base of the ladder is 6 feet away
from the building and the top of the ladder
touches the building at a point 8 feet above the
ground. How long is the ladder?

[tranquil pasture]

would it be:

6/x = x/8 , so 48 = x^2, then find the square root of 48

[rancid raven]

Did you draw the picture?

[fluid prism]

no no

[tranquil pasture]

yes i did

[rancid raven]

Can you show us

[tranquil pasture]

oh then what?

[fluid prism]

this is a question that deals with right angled triangles

you know every side but the hypotenuse

theres a formula you can use to solve the hypotenuse

[tranquil pasture]

is this right?

[rancid raven]

Yes and No

[fluid prism]

what is A?

[rancid raven]

X is building height

[tranquil pasture]

oh wait mb i drew it wrong

i meant for x to replace 8

like switch that

[rancid raven]

Yeah

X is 8 that is building height

[tranquil pasture]

alrr

[rancid raven]

6 is base distance

Ladder length is A

It makes a right angle triangle

[tranquil pasture]

okay

how would i solve for a now

[rancid raven]

Do you know the relation between hypotenuse, base and perpendicular of right angle triangle?

[tranquil pasture]

yeah kind of

[rancid raven]

What's the formula?

[tranquil pasture]

hypotenuse = a ^2 + b^2?

[rancid raven]

Hypotenuse^2 =

[tranquil pasture]

ohh yeah

so

x = 8^2 + 6^2?

x^2 *

x =10?

so ladder is 10?

[rancid raven]

Yep

[tranquil pasture]

thx!]

[rancid raven]

No problem

[tranquil pasture]

.close

[amber wasp]

Channel closed

Closed by @tranquil pasture

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[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crisp stratus]

how was this series computed?

[crisp stratus]

it looks like there is a formula but i am struggling to look it up

i replaced the -2 in the denominator with -k and i get these formulas:

for k=4, the result is 5/3

[stiff jetty]

im not ognna lie

it looks like integration

[crisp stratus]

really?

[stiff jetty]

it is symmetrical about x = -1 i think

[crisp stratus]

hm

[stiff jetty]

actually

dont quote that

[crisp stratus]

lol

[stiff jetty]

its not symmetrical x=-1

[crisp stratus]

for k=5

[stiff jetty]

i mean the tan can only make me think of integration

since there is symmetry for the graph

i think u can integrate

[crisp stratus]

can you show me the function you are plotting?

[stiff jetty]

the sum u are trying to find

well just x instead of n

[crisp stratus]

ah i see

hmmmmmmmmmm

[stiff jetty]

because it is symmetrical

over estimation and underestimation can be dealt with

[crisp stratus]

context: trying to figure out how to deal with this sum which i split into even and odd n's

[crisp stratus]

this is the even part

[stiff jetty]

do u mean odd part?

[crisp stratus]

oh sorry

yes

odd

lol

[patent raptor]

,, s(x) = \sum_{n=2}^x \frac{3}{(2n-1)^2-2} - \frac{1}{(2n-2)^2+2} + 1

[stiff jetty]

im ngl

i tried integrating this

im getting logarithmic

T=T

im not getting tan anywhere wtf man

is that decomposition of original series or just even/odd

[patent raptor]

decomposition

might as well do an index shift

n=k+1

[stiff jetty]

how do you decompose alternating sequence tho

(-1)^n

[patent raptor]

,, s(x) = \sum_{k=1}^x \frac{3}{(2n+1)^2-2} - \frac{1}{2(n^2-1)} + 1

[patent raptor]

You consider the two terms as functions

[crisp stratus]

woah

[patent raptor]

I called the even term e(n) and odd o(n)

Then you have to figure that one term holds only for even numbers, the other for odd

an even number can be expressed as n = 2k

Then you figure which is the first even number and adjust it

forgot a plus 1

[grizzled pagoda]

bacc

bacc

[patent raptor]

,w partial fraction decomposition 1/(2(x^2+1))

the (2n+1)²-2 is tedious

,w partial fraction decomposition 1/((2n+1)²-2)

[patent raptor]

n=1 not k=1

oh i just realized i am dividing by 0

[neat wind]

https://cdn.discordapp.com/attachments/1089737939178750022/1288397638105825280/image.png?ex=66f5094e&is=66f3b7ce&hm=47c9a58c986bd056601ddd9622578900792acc9ef386236f057c7e019214e6b1&

[patent raptor]

wtf

[stiff jetty]

brother man spawned it

out of thin air

[patent raptor]

this was just for the first term?

[patent raptor]

2(n²+1)*

[grizzled pagoda]

Results provided by WolframAlpha

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Requested by adoniszgks

[patent raptor]

I see

,, s(x) = \frac{3}{8} \left ( 8 + \sqrt{2}\pi \tan ( \frac{\pi}{\sqrt{2}} ) \right ) + x -\sum_{n=1}^x \frac{1}{2(n^2+1)}

[grizzled pagoda]

bacc

[patent raptor]

even worse

[amber wasp]

@crisp stratus Has your question been resolved?

[patent raptor]

,w Sum[1/(2(n^2+1)),{n,1,x}]

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[patent raptor]

,w Sum[(n^2+1)/(n^2+2(-1)^n)-1,{n,2,x}]

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[amber wasp]

@crisp stratus Has your question been resolved?

[neat wind]

is this not good enough or

[crisp stratus]

oh shit i didn't see that

[crisp stratus]

thank you so much

[crisp stratus]

$\psi$ is digamma or lerch transcendent or something

[grizzled pagoda]

artemetra

[neat wind]

the function used in that img is digamma function

[crisp stratus]

i see

okay thank you

[neat wind]

btw this might not be best way to do problem idk. it's just what i thought was ok

[neat wind]

yvw 👍

[crisp stratus]

.close

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[barren marsh]

is the answer correct?

[crisp stratus]

yes

in fact, you don't have to know c to solve this

x^2 is even so h(2) = h(-2)

[barren marsh]

its not -10

[crisp stratus]

yes, it's +10

i didn't say it's -10

[barren marsh]

i tried it in. My claci

-2² = 4 x2 = 8

[crisp stratus]

but c is -2

[barren marsh]

ye and x is -2 too ryt?

[crisp stratus]

not 2

yes

-2 * (-2)^2 = -2 * 4 = -8

[barren marsh]

how -2² is 4 and not -4 idu😭

[crisp stratus]

because it's (-2)^2 not -(2^2)

[barren marsh]

how is that different

[crisp stratus]

one is (-2)*(-2), the other is -(2*2)

[barren marsh]

how do i know which is which

[crisp stratus]

-2^2 is ambiguous so context i guess

but here you have -2 as an argument

to the function

so $h(-2) = c\cdot (-2)^2 + 18$

[grizzled pagoda]

artemetra

[crisp stratus]

it's -2 that is being squared

not -(2*2) or something

[barren marsh]

ohhh tysm

.close

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[patent slate]

Well hello there!
Can someone explain to me what is the difference between y = y(x) and y = f(x) ,I know the latter , it means y can be expressed as a function of x
y= x^2 -Sin(x) + log x

[patent slate]

But I'm not sure about the former

[lethal oasis]

Formally speaking, the first one makes little sense

But if it means the same

[indigo cloud]

well y=y(x) also means that y can be expressed as a function of x

its often used like that if you dont want to introduce an extra letter

if you just want to compute with x and y but you also want to express that actually y depends on x

[patent slate]

Oo okay now
y^2-x^2 + cos(xy) +log y=0

Can this be written as y = y(x)

Or f(x) , I get it , both are same

Because I think y can never be expressed as a function of x

@indigo cloud @lethal oasis

[indigo cloud]

well y depends on x

if x changes then y also has to change for the equation to still be true

in that sense y is a function of x

you may not necessarily be able to actually write down how that function looks like

but thats different

functions and formulas are not the same thing

[patent slate]

Ah I see
I am an amateur and it was just my speculation that be can't actually write the function.

But can it actually be done?

By computer

[indigo cloud]

well if you for example put that equation into desmos then it will draw a graph for you

but it wont write down some expression

because the way it computes the graph is different

[patent slate]

Obvious
It secretly knows the function 👿

[indigo cloud]

wolfram alpha also cant seem to solve for y. and in general I would be surprised if you could actually write down an expression for y here

[patent slate]

Ohh so it actually plots graphs based on discontinuous points and then joins then ig ???

[indigo cloud]

pretty much

[patent slate]

Can you explain to me what is the difference between explicit and implicit function

I am just surprised , how can we not do that 🤯🤯🤯

[indigo cloud]

well something is written down explicitly if we have some expression like y=x^2+cos(x) or whatever

its implicit if its written like an equation like in your example

[patent slate]

I understand now
Still I wanna ask once more...
No computer can find that function??

[indigo cloud]

I doubt that there is an expression y=(something in terms of x) for the equation you wrote down

but its not like I can prove that

[patent slate]

Ahh I was curious is all
Thanks Denascite !!!

[indigo cloud]

that does not mean that you cant compute the corresponding y value if you are given some x value

for example if you have x=3 then you can just (numerically) solve the equation y^2-9+cos(3y)+log y=0 for y

[patent slate]

Yess I figured that one : )

Thank you for the clarification 🤠

.close

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[amber wasp]

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[pastel yarrow]

how to do b

[formal dome]

distance/time?

[pastel yarrow]

i did that and it was wrong😭😭 let me try again

[formal dome]

!show

[amber wasp]

Show your work, and if possible, explain where you are stuck.

[pastel yarrow]

ohhh i was dividing the distance by minutes and not hours🌚🌚

i think i need a nap

thanks tho😭

,close

.close

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[strange field]

do you know any kinematic equation that relates time, acceleration and displacement?

[grizzled pagoda]

faiyrose

[strange field]

yes

yep

[grizzled pagoda]

faiyrose

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[quasi epoch]

can anyone here explain how you get these answers with intervals? I dont really understand it

[inland pulsar]

if cos(x) = cos(y)

then either x = y

or x = y + pi

so we can write it generally as
x = y + k*pi

[grizzled pagoda]

Wumpus Man

[inland pulsar]

@quasi epoch

[quasi epoch]

uh

I get that

I honestly get everything up until the dutch text

but I dont understand how intervals work

[inland pulsar]

ohk

can you pls tell me what that thing written in dutch means

i only speak english

have you been taught that which func is +ve in which region

like sin is +ve between 0 to 180 then 360 to 540 ...

(degrees)

[quasi epoch]

on the interval [-π, π] are the answers:

[inland pulsar]

yeah

[quasi epoch]

idk what +ve means no

[inland pulsar]

positive

[quasi epoch]

oh uh

I have this picture

give me a sec

[inland pulsar]

i dont think these are sin or cos

[quasi epoch]

weve never been taught this specifically but if you mean with cosinus and sinus yeah I get that they act in waves

[inland pulsar]

yes

[quasi epoch]

these are f and g from the exercise

[inland pulsar]

oh

[quasi epoch]

the first one is f and the second is g

[inland pulsar]

so basically a sine / sin wave is like this

and it is above x axis from 0 to 180

se we can say in interval [0, 180] it is >= 0

[ -> includes
( -> does not include

in (0, 180) it is > 0

[quasi epoch]

yeah I get that

[inland pulsar]

can you pls ask your doubt again?

[quasi epoch]

well the original question of the exercise was to find where function f and g intersect

in the interval of [-π, π]

[inland pulsar]

okk i get it

so now you have x = 2/3 pi + k*2pi

[quasi epoch]

yes

[inland pulsar]

so now you will have to substitue a suitable value of k

[inland pulsar]

so that x is in

[quasi epoch]

what are the options for k?

[inland pulsar]

k is whole number

[quasi epoch]

so like 1, 2, 3 , 4 etc?

numbers without anything behind the comma?

[inland pulsar]

sorry

integer

[inland pulsar]

yeh no decimal

they can be negative too

[quasi epoch]

so here that would be -3, -2, -1, 0, 1, 2, 3

[inland pulsar]

-2, -1, 0 are also valid

yes

[quasi epoch]

and you just put those in for k

[inland pulsar]

yes

[quasi epoch]

and if its like 2π you just dont mention that right because thats the same as π?

idk if you understand that

[inland pulsar]

no

[quasi epoch]

because if you for example use the int 3

[inland pulsar]

this is wrong

it should be 2pi

[quasi epoch]

oh yeah thats not what I meant

[inland pulsar]

been a long time since i did this

[quasi epoch]

i mean if you receive x= 1 2/3π

you only mention 2/3π

[inland pulsar]

x = 12/3 pi?

[quasi epoch]

ok for example if I use the interger 3 I get 3x 2π +2/3π

[inland pulsar]

yes

[quasi epoch]

so 6 2/3π

[inland pulsar]

yes or 20/3 pi

[quasi epoch]

but its not listed because 2/3π and 6 2/3π have like the same y?

I dont know the exact reason

but you dont mention the one with the 6 in front like they do in here

even tho its inside of the interval

[inland pulsar]

x should be in -pi to pi

[quasi epoch]

alright thanks

.close

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[inland pulsar]

wlcm

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[silver orbit]

Hey There can someone guide me this problem?

I just did h = √(3)x /2 so far

Am i at the right track ?

[fresh ocean]

tbh you dont need that

Do you know where the centre of that circle is located?

[silver orbit]

Yea, just middle position in circle

[fresh ocean]

how about wrt the triangle. Where inside the triangle is it located?

exact place is what you need

[silver orbit]

wut ?

[inland pulsar]

you can use centroid divides median in 2:1

[fresh ocean]

^

[silver orbit]

whats this

[fresh ocean]

...

[inland pulsar]

which class?

[fresh ocean]

Are you attempting problems from beyond your class?

[silver orbit]

nope im here to solve the radius

[inland pulsar]

do you know what a circumcircle is?

[fresh ocean]

What grade are you in? And which grade is the problem from?

[silver orbit]

just a triangle inside the circle

[silver orbit]

im 18 dk which grade form asian

[inland pulsar]

i guess 10th grade

this qques is 10th grad for asians

[mint wraith]

Do you know the sine rule

[mint wraith]

^

[silver orbit]

yep

[mint wraith]

a/sin(A) = 2r

[silver orbit]

yes

solve it

2h/3

thanks

[mint wraith]

No problem

[amber wasp]

@silver orbit Has your question been resolved?

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[late plover]

What is the probability of getting 8 heads or tails in a row out of 100 coin flips

[covert onyx]

Do you mean exactly 8 or at least 8

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[amber wasp]

Please don't occupy multiple help channels.

[thick seal]

like for this

oops

closed the other sry

Do our d= 1.11

but we dont know m or v?

or is 226 the mass but need to go from ml to g?

isnt that incompatible conversion

[soft comet]

226 is the volume

In ml

[thick seal]

oh

[soft comet]

Btw you have to convert the units first

[thick seal]

ohhh

ok

so ml to L is best

and for b ill do 4.2 kg to g

illl try both brb

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[raw oyster]

Given a triangle ABC with area 360 and perimeter 90 such that it’s incircle in centered at I. Point D is drawn on the triangle’s circumcircle such that AD passes through I and intersects BC at E. Find DE If CD=10

[amber wasp]

@raw oyster Has your question been resolved?

[raw oyster]

<@&286206848099549185>

[zenith chasm]

@raw oyster whats the ques

[raw oyster]

Here

[proud gull]

Area bro

[raw oyster]

I’m also secondary

[zenith chasm]

I just found DI=BD=CD=10

Have you made any proggress??

[raw oyster]

Oh?

I did

[zenith chasm]

Show me plz

[proud gull]

How did u get the value of BC

[zenith chasm]

Have you found the value of AC and AB??

[raw oyster]

Yeah

[proud gull]

How

[zenith chasm]

By similarityM

?*

[raw oyster]

Herons

The answer is an integer

So I’m assuming all sides are integers too lol

[proud gull]

3 variables and one equation u can't find the value

[zenith chasm]

Oh i see

[raw oyster]

But still

[raw oyster]

Can you explain

[zenith chasm]

But we should proceed systematically

[raw oyster]

Yeah

But I was out of time

[zenith chasm]

If you use the property of cyclic quard then you will find angle DCE=DBE=CAE=BAD

As AI is the angle bisectro

Bisector*

So BD=DC

and BIE= A/2 + B/2

So BD=DI

[raw oyster]

wait can you explain the DBE part

[zenith chasm]

As BAD and BDC substance same arc

So they are equal

Same goes for DCE= DAC

[raw oyster]

Oh

Yeah

[zenith chasm]

as BAD=DAC so they all are equal

And form an isosceles triangke

Triangle*

[raw oyster]

And this part?

[zenith chasm]

Do you know how to find the value of external angle?

[raw oyster]

yea

[zenith chasm]

Yeah BIE Is the external angle of BIA

triangle BIA

[raw oyster]

hm wait

I is the center of the incircle

Not both the incircle and the circumcircle

[zenith chasm]

yeah

AI is the angle bisector of BAC

And BI is the angle bisector of ABC

[raw oyster]

Ok

But it doesn’t for an isos triangle

[zenith chasm]

No no i mean BDC is isosceles

[raw oyster]

How so?

[zenith chasm]

As CBD=DCB

By that cyclic property

[raw oyster]

Ok

Proceed

On why it’s an isos triangle

[zenith chasm]

As it has two equal sides

[raw oyster]

Where

CE and BE?

So DEC=DEB=90?

[zenith chasm]

BD And DC are equal

[zenith chasm]

No they are not 90

[raw oyster]

Oh yeah right

[raw oyster]

How tho

[zenith chasm]

As DBC=DCB

its a property of Isosceles triangke

Triangle

[raw oyster]

Oooh right

Ok proceed

[zenith chasm]

Ok

But after the similarity i cannot proceed further

[proud gull]

Is the ans 4

[zenith chasm]

How

The answer should be integer

[proud gull]

The ans is 4

@raw oyster

[zenith chasm]

How did you find thattt

[proud gull]

It is an equilateral triangle

[raw oyster]

How

How

[proud gull]

Wait

Is the ans right tho ?

[raw oyster]

Idk

[proud gull]

Not given ???

[raw oyster]

Not given

It was originally from a competition I competed a few days ago

So the comp ended and I wanna revisit this question

[proud gull]

Ok

Sending the solution

2 mins

[raw oyster]

Cool

[raw oyster]

Hey so how’s the solution going?

Not rushing take your time

[proud gull]

Yup 2 mins more

Done

My bad the ans is 8 .. previously I did some error on my calculation

Lemme know if u got it

[zenith chasm]

I couldnt see your answer

Can you send it again?

[proud gull]

The angle bisector is for A .. writting error

For the congruency of first two triangle I did some error in the naming but it shouldn't matter

@raw oyster u got it ?

[raw oyster]

hmm

You said AB=BC=AC=30

[proud gull]

Yes

[raw oyster]

But then the areas don’t match

The area is 360

(1/2)(30)(30)(sin60) is not 360

[proud gull]

Hmm

I guess im wrong then

Truee

[zenith chasm]

BC is not tangent at point E

As ABC Is not isosceles

[proud gull]

It is

[zenith chasm]

How?

[proud gull]

It is said that incircle at I hence making it a tangent

[zenith chasm]

You need to show the proof of your claim

[proud gull]

Given in the question

[zenith chasm]

Noo

[proud gull]

Incircle at I

[zenith chasm]

If AI intersect BC at E then AEB Is not 90

[quick spoke]

^

[proud gull]

Basic property of an incircle

[quick spoke]

literally not

[zenith chasm]

A,I,Ma is not collinear

[proud gull]

Righttt

My bad

Fuck!!!!

I didn't see that

[quick spoke]

i have somewhat retired from olympiad geo lol so i kinda don't really wanna do any more geo

but i will give some potential pointers

[quick spoke]

this is quite a common configuration, we have BD = DI = CD

which also means that D lies on the perp. bisector of BC

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[split sail]

Isn't it like the radius of an incenter is 1:3 of the the triangle sides?

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[split sail]

what is ln(x)/(log(x))

[sterile nymph]

What base is log?

Do you know the log rules?

[split sail]

10

!occupied

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[sterile nymph]

https://www.chilimath.com/wp-content/uploads/2020/04/the-change-of-base-formula.gif

[keen topaz]

Change of base

For the top only

Okay that should be enough hints

[split sail]

,w 1/(log(e))

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[split sail]

reallly?

[regal glacier]

No

[split sail]

lol

[sterile nymph]

log(e) is interpreted by wa as being log_e(e)

[regal glacier]

,w 1/(log_10(e))

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[split sail]

oh ok thanks

.close

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[cobalt mica]

I need to calculate this for the derivability of the function, the result should be 0. I did l'hopital and I got to here but I don't know what to do from there on

[cobalt mica]

I'm not sure whether it matters or not, but I'm approaching x from the right

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[stoic ivy]

Oh man this one is pretty involved I think this is a special case of Holders inequality

And the statement above is called young’s inequality for products

I recommend that you observe that the integrands are all real numbers so they satisfy the young inequality

So what you can conclude is that x(t)y(t) <= x(t)^p/p + y(t)^q/q