help-41

[night stratus]

Hm, it doesn't seem right

[cobalt stump]

no you got it

[night stratus]

oh

hm

[cobalt stump]

13 dishes in total

[night stratus]

Oh right I see

I was multiplying for the total cost.

when I already had the answer geez. Thanks, I guess I was just solving for the total cost and forgot it was simply just how many sold each

Just have to pay attention and read the question

[cobalt stump]

lol that might help

[night stratus]

Yeah 😅

.close

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[tranquil pasture]

does anyone know a website for a dilation calculator that can calculate from a center thats not the origin,

like a dilation from (1, -2) with a scale factor of 1/2

[tranquil pasture]

or does anyone know how to dilate from a center thats not the origin

ik how to do it on a graph but is there a formula to do it w just the points

[austere pond]

https://www.desmos.com/calculator/elccqxyf4w

I found this desmos project you could use as a tool

[tranquil pasture]

thank you!

[austere pond]

np 👍

[tranquil pasture]

is this a correct formula of dilating from a point thats not the origin
example:
(1, -2) is the center of dilation
(-1, +2) is what it takes to get to (0,0)

original point + (-1, +2), then we multiply by the scale factor of 1/2, then we add the regular center of dilation which is (1,-2), then that is our answer

like: (-3,4) + (-1 , +2) = (-4,6) x 1/2 scale factor = (-2,3) + (1,-2) = (-1,1) , so the final point is (-1, 1)

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[pastel forge]

not sure why this is wrong? im in calc 3 and cant find where i went wrong

[pallid canopy]

How many digits are you supposed to round to

,calc 4409 * pi

[grizzled pagoda]

Result:

13851.282009677

[pallid canopy]

Try .282010

[pastel forge]

woops i got it now, i multiplied wrong

alsoo for this problem hold up

dont really get how i got that wrong?

[pallid canopy]

Where did the -2t come from

[pastel forge]

partial derivative of y with respect to s

and then the negative comes from the partial derivative of z with respect to y

[pallid canopy]

Maybe just plug in x and y in terms of s and t

[pastel forge]

omg yeah it worked thank you so much lol

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[slender blaze]

anyone have a good proof video for the sum of sine and cosines formulas?

[slender blaze]

i cant seem to find one

these

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[quartz hornet]

Question

[quartz hornet]

If I’m combining like terms

With -45+81i-33

Would it be 12+81i?

Or -12+81i

[south stag]

what's -45 - 33

[quartz hornet]

-78

[south stag]

-78 + 81i

[quartz hornet]

So this is correct?

[shadow stump]

that is not correct

[quartz hornet]

How did I get this wrong

[south stag]

show your work

[quartz hornet]

,rotate

[shadow stump]

,calc 6*-9

[grizzled pagoda]

Result:

-54

[quartz hornet]

So that was the only mistake

[shadow stump]

yes

[quartz hornet]

https://tenor.com/view/nick-eh-30-gif-9707254018493757955

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[livid patio]

plz bro ive been stuck on this for 30 minutes

[grizzled plume]

let pr=x

then since pre is similar to poc

then (x+115)/320 = x/255

and then cross multiply and solve

@livid patio

[livid patio]

x=451

YES

THANK YOU SO MUCH

[grizzled plume]

okay theres your answer

no problem

[livid patio]

.solved

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[old kernel]

Hi, I’m confused on how to find discontinuities

And continuities / cornercusp

[old kernel]

So if they are separated like at -2

[cunning jasper]

Continuities are continuous points, they lie INSIDE of the line or curve produced by one singular function
Corner/cusp are also continuous points but they lie BETWEEN the line or curve produced by TWO(or possibly more) functions

[cunning jasper]

then its a discontinuity yes

Anything that isn't a discontinuity = continuity

[old kernel]

How would I find corners then?

[cunning jasper]

Its in my definitions of continuities

[old kernel]

Im confused , what lies between two functions on the graph

Do they intersect ?

[cunning jasper]

you know how piecewise functions have specific domains for each function, for when the borders of these functions touch(not intersect), then it is a corner/cusp

[old kernel]

Is there an algerbrsic way to tell? Or can I only tell visually

[old kernel]

And In piecwise functions there is either equal too or not open or closed dot , does this effect the cusp/corners?

[cunning jasper]

kind of algebraic?, just check the values where the function changes in a piecewise one

[cunning jasper]

not really

[cunning jasper]

like check -2, 0, and 1 in this function to see if they're continuous, if they are then they're cusps

[old kernel]

So it’s x^2 at 1

It’s just 1,1

How do I tell if it’s a cusp based on that

.solved

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[keen pawn]

I'm trying to prove this

so $|x+2|<\delta$

[grizzled pagoda]

Veni, vidi, perii

[keen pawn]

this implies $|x-2|+4<\delta$

[grizzled pagoda]

Veni, vidi, perii

[keen pawn]

so $|x-2|<\delta-4$

[grizzled pagoda]

Veni, vidi, perii

[keen pawn]

so$|x+2||x-2|<\delta ( \delta -4)$

[grizzled pagoda]

Veni, vidi, perii

[keen pawn]

This feels awfully sus

[craggy sundial]

for an epsilon delta proof, you need to figure out what the value of delta is
usually as a function of epsilon

so that the |f(x) - L| < epsilon is true

[keen pawn]

I know

[keen pawn]

Let me try an easier problem first to see hwere I'm going wrong

wait

oops

$|x+2|(|x+2|+4)< \varepsilon$

[grizzled pagoda]

Veni, vidi, perii

[keen pawn]

so yeah $\delta = \frac{\varepsilon}{5}$

[grizzled pagoda]

Veni, vidi, perii

[craggy sundial]

mb, I thought you're confused on that from your previous times

[keen pawn]

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[reef niche]

Let ℕ denote the natural numbers {1, 2, 3, 4,…}.
Consider a function f(n) that satisfies f(1) = 1, f(2x) = f(n)
and f(2n + 1) = f(2n)+1 for all ∈ ℕ. Find a nice simple
algorithm for f(n). Your algorithm should be a single sentence long, at most.

[reef niche]

what they meant by an algorithm?

[timid vault]

Any way to get the value

[reef niche]

the function?

[timid vault]

to find f(n) for any n, yeah

[reef niche]

ok

ty

[indigo cloud]

do you mean f(2n)=f(n) ? instead of x?

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[reef niche]

yes

[tulip tapir]

so

[grizzled pagoda]

ren

[quick spoke]

hint: ||write n in binary||

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[reef niche]

yep

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[tender cipher]

Isn't x x 0 such that x is real, a vector space

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[fiery canopy]

can anyone help me with (a)(i)?

[fiery canopy]

cant seem to find a solution for it

[spiral zealot]

what did you try?

[fiery canopy]

i tried finding area of jkn

but i think it doesnt work

but i got the area for it

[spiral zealot]

you don't need any area for a)i)

[fiery canopy]

yh ik

i dont know what else to do

[spiral zealot]

cos rule

[fiery canopy]

whats the formula?

which is the formula

[spiral zealot]

look up cosine law/rule

[fiery canopy]

oh

ty

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[elder jay]

Let's say we had f(x) = -2sqrt[3(x-2) + 4]

[elder jay]

I'm a little confused on how to describe it

Because the mapping diagram would be

(x,y) → (x + 2, -2sqrt[3y] + 4)

So would It be reflected along the x-axis

Vertical stretched by a factor of 6

Horizontally translated 2 units right

Vertically translated 4 unit up

I'm mainly concerned about the first two

[elder jay]

I think it would be a reflection, but idk about the factor here

Ping me if you are helping!!

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@elder jay Has your question been resolved?

[elder jay]

Math 30-1 IB

No

X and y axis

Describe the transformations that occur

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[calm oak]

please help

[strange field]

increases ig

[calm oak]

I think the answer is decreases since, frequency varies inversely to length of air column, so less water, more air column, and thus less sound(pitch)

[strange field]

i said decreases too

wut

how

i swear i typed decreases

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[late peak]

increases i think

[frosty rain]

you must feel like the main character having ur own chat

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[cobalt kestrel]

how do i determine whether its odd or even

[quick ridge]

f(-x)

[cobalt kestrel]

how do i apply that here

[quick ridge]

dawg

check f(-x)

if it’s odd

then it will be -f(x)

if it’s even then it will be f(x)

where your f(x) is the function in the integral

@cobalt kestrel

odd or even

it’s been 4 minutes

we can talk about the integral properties after

is the integrand odd or even

[cobalt kestrel]

im watching a video on how to check if a function is odd or even...i havent done it in a whole year

gimme a few min 😭

[quick ridge]

bruh

[quick ridge]

^

[quick ridge]

^

[cobalt kestrel]

like i plug -x into all my x values?

[quick ridge]

^

[quick ridge]

yes

[cobalt kestrel]

oh so it depends on the exponent

[quick ridge]

sure yea

(-x)^2 is x^2

if that’s what you mean

[cobalt kestrel]

ye

ok its odd

so now i just integrate it like normal?

[quick ridge]

no you use the following property

$\int_{-a}^a f(x) dx = 0$

if f is odd

[grizzled pagoda]

knief

[cobalt kestrel]

thats it?

i dont have to do any work?

[quick ridge]

yup

and if f is even

$\int_{-a}^a f(x) dx = 2\int_0^a f(x) dx$

[grizzled pagoda]

knief

[cobalt kestrel]

how come thats the case tho

integration is just the area of a function on a certain interval

[quick ridge]

even functions are symmetrical about the y axis

[cobalt kestrel]

are we saying that the area doesnt exist on the interval [-a,a] when its odd?

[void steeple]

if f is even its graph looks the same on either side of the y-axis

[shadow stump]

remember that the area is given a sign, where area under the x-axis is negative

[quick ridge]

no

they cancel

because odd functions are symmetrical about the origin

[cobalt kestrel]

oh

[quick ridge]

the picture should make it clear to you

[cobalt kestrel]

hm so for even is it like [-a,a] but for odd its [-a,0),(0,a]?

[quick ridge]

what

[cobalt kestrel]

nvm im thinking about it the wrong way

[cobalt kestrel]

so this is saying that if we took the integral from [-a,a] we would end up with 0

the property is just a shortcut then?

[quick ridge]

yes

for odd functions

it isn’t true if it’s even or neither even nor odd

[cobalt kestrel]

i see

ty

.close

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[gray bone]

in stadistics
when they give a X amount of rows and columns
the rows and columns have a meaning like the rows and columns themself?

or I just have to focus on the numbers regardless of the columns or rows

[celest cove]

im not much of a statistics doer but this feels under-contextualised

would there not be information given about the data set

[storm moth]

thats just a random bunch of numbers

[shadow stump]

that's dependent on the context

[gray bone]

thank you!!

[gray bone]

A company's regional sales manager is considering several promotions to get grocery store shoppers to come more frequently. One idea is that the customer who spends at least $10 will receive a free bar of toilet soap for the first purchase made during the month. The second promotion is that the customer can choose any 371 gram box of cereal. To further examine the idea, the manager surveyed 50 customers with the following question:

like i already solved the problem

but i didnt touch the rows or columns as they were something in concret

but if those are just a bunch of random numbers

then aight

makes more sense to me

.exit

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.ready

.finish

ahm

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[shadow stump]

in this case the rows and columns don't mean anything, they're just a way of presenting the data

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[kindred raptor]

This may be physics but can anyone help me out with this problem?

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[kindred raptor]

<@&286206848099549185>

[split sail]

a) relative to point O

[kindred raptor]

can u explain how?

[split sail]

i forgorr

im bad at physics

[kindred raptor]

Don’t worry but I’m in 9th grade so my brain doesn’t understand

Oh nvm I get question a

Can u help with the rest and try to explain it?

[kindred raptor]

<@&286206848099549185>

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.close

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[earnest ridge]

i need help graphing equations for parallel lines on a graph

[earnest ridge]

heres my homework

[grizzled plume]

okay

i will help you with the equations

[earnest ridge]

ok

[grizzled plume]

you know how to do the graphing right

y = mx + c

[earnest ridge]

we had y = mx + b

for slope

it's either telling me to solve for point-slope form [y - y1 = m(x - x1)], or slope intercept [y = mx + b] i think

[grizzled plume]

alright

sorry for delay

for the first graph it passes through the points (1,3) and (2,1) so the gradient is (y2-y1)/(x2-x1) = -2

so y = -2x + b

then we can plug values into the equation: since (1,3) and (2,1) work, we can solve for b

try it out

[earnest ridge]

ok!

i got -3 for the slope

10 = b

so its y = -3x + 10?

?

and i got y - 3 = -3(x-1)

for point slope form

<@&286206848099549185>

<@&286206848099549185>

[distant quartz]

Pls do not spam this.

[distant quartz]

Which part?

The first part?

If yes then, I think you made a mistake, it should be -2

[earnest ridge]

Sorry for spamming. Ok

[distant quartz]

No prob, wait 15 mins

And what about the problem, did you check your work?

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[dreamy hatch]

I've reached s = 3800/sinθ and now stuck

[dreamy hatch]

s = 3800cscθ, (ds/dθ) = -3800cscθcotθ

plugging in 30 would give -3800(-2)(1.73205080757)

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[golden hamlet]

jump discontinuities count as removable discontinuities right?

[shadow stump]

no

[golden hamlet]

oh ok

thanks

.close

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[thick seal]

How is m2g positive?

[thick seal]

shoudlnt it be negative?

is going down

[shadow stump]

because he defined down as the +y direction

[thick seal]

ohh

ok makes sense thnxs

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[thick seal]

waait

so if i

made the y go upwards

t would be positive

m2g would be negative?

[shadow stump]

yes

[thick seal]

or is that not a valid thing to do

oh

can i do that instead

Becuz i dont like the way this y is going down but somehow is still psotive

[shadow stump]

you can. he chose downwards as the positive direction because it would make the acceleration positive

[thick seal]

Ohhhh

Ok i get it

Thnx then

.close

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[split sail]

dawg what

the rest is correct

[quartz hornet]

How do i do that

[split sail]

Ca3P2

[quartz hornet]

That’s it?

[quartz hornet]

How tho

[split sail]

good

[quartz hornet]

Or is third one

In parenthesis

[split sail]

this one

there shouldnt be a hypothesis

[quartz hornet]

There all right?

[quartz hornet]

Which

[split sail]

bottom one

[quartz hornet]

The NaN

[split sail]

Na3N looks good

[strange field]

hypothesis?

[quartz hornet]

So which one

Isn’t correct

[split sail]

parenthesis

im

not fine

[strange field]

i dont see any parenthesis

[split sail]

.

this one

[strange field]

oh

the answer itself is wrong

[quartz hornet]

I’ve got that correct already

[strange field]

not the use of parenthesis

[quartz hornet]

I’m talking about the current one

[quartz hornet]

This

What’s wrong with this

[split sail]

nothing's wrong with this

[quartz hornet]

Ohhh u confused me

[split sail]

[quartz hornet]

How about this bad boy

[split sail]

uhh

${\text{Mg}^{2+}}$

[grizzled pagoda]

icannotdoanymorecauchy

[quartz hornet]

Why at the top

[split sail]

${\text{Al}^{3+}}$

[grizzled pagoda]

icannotdoanymorecauchy

[strange field]

they're saying magnesium ion is Mg2+

[strange field]

so why is your answer Mg2O

[quartz hornet]

Because the O is there

And there needs to be 2 MH

MG*

[formal dome]

You need to take into account how many electrons each atom "gives" to the oxygen. That's why you dont have MgO, NaO and AlO.
Mg ion gives 2, Na only gives one, and Al gives 3

you need to have as many metal ions and oxygens as needed for the compound to have total charge of 0

[quartz hornet]

So am i still doing +O

.close

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[zenith summit]

can someone tell me what they mean when they say describe the locus?

[amber wasp]

@zenith summit Has your question been resolved?

[amber wasp]

@zenith summit Has your question been resolved?

[haughty token]

Well, a locus is a set of all points satisfying a set of equations/conditions.

When asked to describe the locus, it could mean the shape formed by the set of points or just an important property of the locus to highlight.

Take question 3 for example, P(x, y) is equidistant to A and B. Such a locus must be the perpendicular bisector of line segment AB. Think about it and you'll see why

Try to give descriptions within the context of the question

[zenith summit]

it’s the perpendicular bisector bc PA = PB right

[haughty token]

not much an explanation but yes, it's that straightforward

[zenith summit]

so how would i describe it

P is the midpoint of AB

?

[haughty token]

The midpoint of AB does lie on the locus of P but it's not the midpoint

[zenith summit]

hold on im a bit confused

locus could be summarised as a set of points right

[haughty token]

Yes

[zenith summit]

but P is a singular point?

so how does it make sense to say the locus of P

[haughty token]

P may refer to a singular point but not necessarily the same point

P(x, y) for one particular pair of x and y is one point
but the locus of P is of P(x, y) for all pairs of x and y that satisfy the condition: PA = PB

[zenith summit]

oh so this is just saying that one particular P lies on the midpoint of AB but the rest doesn’t

[haughty token]

The question does imply that but it's not quite what it's asking.

You care about all the P that satisfy the PA=PB. That's what you want to find

If It wasn't clear before, all points on the perpendicular bisector of AB satisfy PA=PB

[zenith summit]

ah

i just said the locus of P is the perpendicular bisector of AB

is that fine

[haughty token]

yes

[zenith summit]

alr thanks

[haughty token]

no problem

[zenith summit]

.close

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[untold ravine]

What is "si"?

[weak zinc]

Probably “if” but not translated or something

[untold ravine]

Hmm ok

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[golden stratus]

For part b, wouldn't the set {1,{1,2}} need to be {{1}, {1,2}}?

[golden stratus]

since the set: {1} is not in {1, {1, 2}}, wouldn't it be false?

[cunning birch]

no

If you ever have a doubt, write out the elements of each set

Set on the left has element 1

set on the right has elements 1 and {1,2}

so all elements on the left are also on the right

[cunning birch]

this is never the correct justification

it's not the set itself that should be in the other

it's the elements of said set

[golden stratus]

but {1} is not an element of the other set

[cunning birch]

again, for A to be a subset of B, the elements of A need to be in B

not A itself

we're not writing $A\in B$

[grizzled pagoda]

rafilou2003

[cunning birch]

we're writing $A\subseteq B$

[grizzled pagoda]

rafilou2003

[cunning birch]

meaning "all that A contains, B contains as well"

what A contains is inside the brackets

[golden stratus]

1 would be a subset of {1, {1, 2}} and {1} would be a subset of {1, {1, 2}}?

[cunning birch]

1 is not even a set

{1} is a subset of {1, {1, 2}}

[golden stratus]

ah I see

[cunning birch]

because when you look at what {1} contains

it contains 1

and fortunately

[tulip tapir]

1 is an element

[cunning birch]

{1, {1, 2}} also contains that

[robust isle]

1 is an element of {1, {1, 2}}, written with ∈

[tulip tapir]

{1} is the set containing 1

[cunning birch]

\{

bad tex

[tulip tapir]

sh

OMFG

[golden stratus]

I get it now

thanks for the help

.close

[grizzled pagoda]

ren

[amber wasp]

Channel closed

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[patent raptor]

😂

[tulip tapir]

*sighs*

i give up

[cunning birch]

ren didn't have time to finish xdd

:(

[patent raptor]

I thought this was snows wtf

[amber wasp]

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[keen pawn]

pretty easy , je sais la

so $\delta = 3 \varepsilon$

[grizzled pagoda]

Veni, vidi, perii

[keen pawn]

so $|x-2|<3\varepsilon$

so $\frac{2}{1 - 6 \varepsilon}>1/x$

[grizzled pagoda]

Veni, vidi, perii

Veni, vidi, perii

[ancient raft]

Start with defining $$|x-a|<\delta$$ and $$|f(x)-f(a)|<\epsilon$$

[grizzled pagoda]

Good

[coral wigeon]

this is hard to follow

[keen pawn]

I think I'll just send all my steps

form $\delta = 3\varepsilon$

[grizzled pagoda]

Veni, vidi, perii

[coral wigeon]

i kinda suggest spreading it over fewer messages

[keen pawn]

$-\varepsilon <x-2<3\varespilon$
\
\implies $2 - \varepsilon<x< 2 + \varepsilon$
\
$\frac{1}{2} - \varepsilon}> \frac{1}{x} > \frac{1}{2+ \varespilon}$
\

so $|x-a|< 3\varespsilon$
\
$\implies$
\
$\frac{|x-2|}{2}< \frac{3\varepsilon}{a}$
\
$\implies$
\
$\frac{|x-2|}{2|x|}< \frac{3 \varepsilon}{2 (2 - \varepsilon)}$

oops

the a should be 2

[grizzled pagoda]

Veni, vidi, perii
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[keen pawn]

now how do I show this is less than $\varepsilon$

[grizzled pagoda]

Veni, vidi, perii

[ancient raft]

Start with this format.

Should be 0<|x-a|<delta.

[amber wasp]

@keen pawn Has your question been resolved?

[patent raptor]

why are you starting off with epsilon?

[keen pawn]

I found that erlier

[amber wasp]

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[meager gale]

this is the answer for part c

i disagree tho, shouldnt it be -1/45 rad/s?

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[earnest ridge]

can anyone help me with finding the domain and range of a function on a graph?

[patent raptor]

just post it

[earnest ridge]

i have a test tomorrow and i just need help finding it but let me see if i can send an old homework question

[patent raptor]

good luck

[earnest ridge]

thank you

[patent raptor]

ok good what you tried

[earnest ridge]

for number one, it isn't a function, its continuous and the domain is all real numbers i think?

[patent raptor]

it isn't a function?

[earnest ridge]

wait sorry i did the vertical line test wrong, it IS a function

[patent raptor]

yes

[earnest ridge]

how would i find the range of it?

[patent raptor]

it's continuous

so you really need to figure if it's bounded

for example

is there a minimum/maximum

[earnest ridge]

sorry i dont understand

[patent raptor]

range means what y values are possible

For example is y=0 possible?

[earnest ridge]

ohh

[patent raptor]

yes it is

[earnest ridge]

how do you know if its possible?

[patent raptor]

look at you curve and at the y-axis

if you would go along the curve from left to right

say you walk on it

then the lowest value you can get to is -3

then you go up again

and that for

infinity

no upper barrier

[earnest ridge]

ohhh

[patent raptor]

but lower

does this make sense somehow?

[earnest ridge]

yes

[patent raptor]

yea

so what would be the range

[earnest ridge]

so the range is y > -3 but the inequatlity sign has an underline

[patent raptor]

nice

good job

[earnest ridge]

ty

let me try the second

[patent raptor]

the second one you can count

[earnest ridge]

its discrete

[patent raptor]

yep

[earnest ridge]

(1,1) (3,2) (3,6,) (4,4) (5,6) (6,1) (6,4) ?

[patent raptor]

your points

i would have written it separately

[earnest ridge]

so the domain is : {1, 2, 3, 4, 5, 6}

[patent raptor]

yes exactl

y

mind reader

[earnest ridge]

hahaa

[patent raptor]

is x=2 really in the domain?

[earnest ridge]

ohh i see what i did wrong

its x=3

[patent raptor]

yea

[earnest ridge]

(1,1) (3,2) (3,6,) (4,4) (5,6) (6,1) (6,4)

the new domain is: {1, 3, 4,5, 6}

the range is: {1, 2, 4, 5, 6}

sorry messed up the range

[patent raptor]

3 and 5?

[earnest ridge]

the range is: {1,2,4,6}

[patent raptor]

yes

is it a function?

[earnest ridge]

no, bc the x repeats

[patent raptor]

you are so cool

yes

[earnest ridge]

yayy

ok number 3

its linear

[patent raptor]

[earnest ridge]

its continous

lol

[patent raptor]

yea you will rock this exam tomorrow

[earnest ridge]

ty lol

[earnest ridge]

uhh how do i find the domain and range of number 3 im stuck

[patent raptor]

you always assume the domain are all real numbers, except when you divide by x or take the square root of something

if you divide by x then it must not cause division by 0

and x in square root always non-negative

but here as you said it's a linear function

it has the form y=mx+c

so we dont have to worry about anything of what i just mentioned

we can put in anything

[earnest ridge]

ok

[patent raptor]

the arrows especially suggest that it goes on forever

keep your eyes on that

[earnest ridge]

so are they both all real numbers?

[patent raptor]

yes

for the range

[earnest ridge]

yayyyyyyyyyyyyyyyy

[patent raptor]

if you were to walk on that linear line

you would never stop

[earnest ridge]

ok let me send problems 4-6

[patent raptor]

no matter if you go down or up

[patent raptor]

[patent raptor]

ok let's see how good you really are

this was just a small warm up

[earnest ridge]

haha

hmm 4. is continous and is a function

[patent raptor]

ok good

are you giving up already?

[earnest ridge]

trying not to lol

and the domain is x > 3?

with an underline bc its a closed circle

[patent raptor]

YAY

range?

also you can say x>=3

to mean what you say

[earnest ridge]

uhh idk what to do for the range here

[patent raptor]

walk on the curve

at what height do you start

[earnest ridge]

0

[patent raptor]

yes

y = 0

[earnest ridge]

ohh

[patent raptor]

now if you go along

where does it seem to go

[earnest ridge]

erm

idk but is it y>=0?

[patent raptor]

do you go up?

[earnest ridge]

no

[patent raptor]

into the positive realm?

[patent raptor]

so

where are you heading

[earnest ridge]

down

[patent raptor]

yes

and that forever

as the arrow suggests

so you start from y=0

and you lose height

you enter the negative realm

[earnest ridge]

yes

[patent raptor]

so what is it

[earnest ridge]

all real numbers?

[patent raptor]

again

can you go up?

[earnest ridge]

no

[patent raptor]

your highest range value is 0

from there you only go down

[earnest ridge]

oh is it y>=0

[patent raptor]

i hope it's a typo

[earnest ridge]

yea it is lol the inequality sign goes the other way around

[patent raptor]

change it

[earnest ridge]

y<=0

[patent raptor]

😂

you just want not to get rid of the positive

are you so positive

[earnest ridge]

lol

[patent raptor]

CORRECT

[earnest ridge]

YAYAYYAAYAYAYAYAYAYAYYAYAYAYAYAYAYAYAYAYAYAYAYYAYAAYAYAYA

[patent raptor]

you can only attain values within 0 and -inf

really try to scan what y-values are being attained

[patent raptor]

if you walk from y=0 and then you continuously walk down then you can conclude I capture every y-value that's lower or equal to 0

[earnest ridge]

ok

[patent raptor]

ok i see you still a bit unsure

[earnest ridge]

a little

[patent raptor]

count

[earnest ridge]

huh

[patent raptor]

you count from y=0

now you go down

y=-1

y=-2

y=-3

y=-...

seems to go endlessly negative

along with your finger maybe

[earnest ridge]

ohhh

[patent raptor]

the range is nothing more than all attainable y-values

[earnest ridge]

yes

[patent raptor]

let's move one and see

[earnest ridge]

five is it continous, it is a function, and the domain and range are both all real numbers

[patent raptor]

💀

let's move on to 6

[earnest ridge]

(1,2) (2,1) (3,2) (4,3) (5,4) (6,7)

the domain: {1,2,3,4,5,6}

the range: {1,2,3,4,7}

discrete

and it is a function

[patent raptor]

[earnest ridge]

YAYY

[patent raptor]

damn

well done

[patent raptor]

☠️

[earnest ridge]

erm

[patent raptor]

ok 7.

[earnest ridge]

continous

not a function

[patent raptor]

think about it again

[earnest ridge]

doesn't it pass through the y-axis twice

[patent raptor]

does it fail the vertical line test

[patent raptor]

where

I see only (0,0)

passes once

[earnest ridge]

ohh

its a function

[patent raptor]

yes

[earnest ridge]

erm how do i find the domain and range for this

well i atleast know that the domain is all real numbers

yippeee

how do i find the range

[patent raptor]

walk on it

[earnest ridge]

1/4

[patent raptor]

yo

[patent raptor]

yes and where is your lowest

[earnest ridge]

also 1/4

[patent raptor]

almost

negative

[earnest ridge]

ohh right because its going down

[patent raptor]

yesss

so what is the range

where you being in between

[earnest ridge]

-1/4 <= y <= 1/4

[patent raptor]

hell yeah

[earnest ridge]

YIPPEEEEEEEEEE

[patent raptor]

you're oscillating between this range

going up and down

does this make sense

[earnest ridge]

yeah i understand

[earnest ridge]

not a function, continous

[patent raptor]

yes

[earnest ridge]

domain is all real numbers

[patent raptor]

[earnest ridge]

wait the range is all real numbers

[patent raptor]

yes

[earnest ridge]

x>=0

[patent raptor]

🥹

[earnest ridge]

lol

[patent raptor]

yes

[earnest ridge]

YAYYYYYYYYY

[patent raptor]

the problem with this not being all real numbers is because it is not a function

[earnest ridge]

ohhh

so if it is not a function then the domain cant be all real numbers

[patent raptor]

at least it's not always the case

[earnest ridge]

ok

[patent raptor]

because if you take a closer

look

that's x = y^2

which if we solve for y gives us two functions

y = sqrt(x) or y = -sqrt(x)

and if you remember in square roots x must be non-negative, hence x>=0

my advice is still to recheck everything by looking at the graph again

like ok you assumed all real number, but then check again if that's actually the case for example, x=-1, is this defined or not etc

[earnest ridge]

ohhh

ok ill do that 👍

[patent raptor]

functions can become really quick complicated

[earnest ridge]

yep

[patent raptor]

so it's rather btter to treat each case unique

for example

,w plot sqrt(x-2)

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[patent raptor]

what would be the domain for this

[earnest ridge]

uhh

[patent raptor]

is x = 1 allowed?

[earnest ridge]

yes?

[patent raptor]

sqrt(1-2) = sqrt(-1)

oppsie

negative number

[frigid wigeon]

Domain is all x values that provide an real output (the blue line)

[patent raptor]

do you see

you have to make sure that x-2 >= 0

never negative

and if you solve this inequality you get essentially the domain

x >= 2

[earnest ridge]

ohh

igtg to school but thanks for helping!

[patent raptor]

oh

[frigid wigeon]

Technically greater than or equal to, but I don't know the unicode for the charcter off the top of my head

[patent raptor]

good luck for tomorrow then

[earnest ridge]

ty

byee

[frigid wigeon]

👋

[amber wasp]

@earnest ridge Has your question been resolved?

[amber wasp]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[silver orbit]

Someone pls teach me this question

[hollow plaza]

you know what logs means?

[silver orbit]

yea?

[hollow plaza]

you need to use the log's sequences where is says:
log(abc....) = log(a) + log(b) +....

[silver orbit]

i got log(1/200)

is that correct?

[wintry merlin]

yea should be

cuz all the other numbers cancel out

[silver orbit]

so i get -2.3 as the integer i should write as -2 or -3 ?

[wintry merlin]

log1/200 is -2.3

-2.3 is between -2 and -3

which is smaller among -2 and -3?

[silver orbit]

-3

[wintry merlin]

thats n

cuz n + 1 is -2

and -2.3 lies between -2 and -3

[silver orbit]

got it thanks

[amber wasp]

@silver orbit Has your question been resolved?

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[normal dove]

when is differentiating a parameter under the integral valid

[normal dove]

the formal stuff is way too verbose

[sterile nymph]

When the functions involved are sufficiently well behaved.

[normal dove]

well behaved as in?

[sterile nymph]

The formal stuff

[normal dove]

its actually on the edge of the syllabus of my course

so i am not trying to get too deep into it but have a general idea

thanks for the help smartass

.close

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[sterile nymph]

@normal dove not trying to be a smartass

Willing to discuss it with you and answer questions

But like, specific ones

[neat wind]

my brother your grievance was that “the formal stuff is way too verbose”; hence, you got an answer that was neither formal nor verbose

[quick spoke]

i mean you can't really give an answer to exactly when you can differentiate under the integral sign without the formal stuff

[sterile nymph]

Be nice

[quick spoke]

this is probably the best short answer you could get

if ur an engineer or physicist, the answer will be always

for all practical purposes, all ur functions will be 'nice'

if u study analysis, then you'd care about when differentiating under the integral sign is valid

[vast spade]

i can confirm that most of the time this is the case

[amber wasp]

Available help channel!

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[tacit karma]

Ive attempted this question around 6 times or so, using interval notation and commas between each answer for both lines and it keeps marking it as incorrect, maybe im misinterpreting what theyre asking?

[quick spoke]

what were u submitting?

[hard monolith]

So, what was your answers for the...
(A) Domain
(B) Range

[quick spoke]

it is entirely possible that it's a website issue but we should check if ur answer is right first

[tacit karma]

it regenerates every time you get it wrong, but for example for that one i would have written
Domain: [-4, 4), [5, Inf)
Range: [-8, 1], [4, 4]

and i can check it but likely its going to come up as incorrect for both

[quick spoke]

well the domain would be [-4, 4) U [5, inf)

since the whole thing is the function

[quick spoke]

then similarly the range would be [-8, 1] U {4}

[tacit karma]

o

ill try that

The range was correct but not the domain

[quick spoke]

oh it's -6 lol

[tacit karma]

oops

[tacit karma]

that should get me the right answer then, thank you!

[amber wasp]

@tacit karma Has your question been resolved?

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[stone wigeon]

please don't tell me how to solve this just give me the first step as thats where I'm confused

[pallid canopy]

X ~ N(mu, sigma), then P(X > 180) = 0.2. find another equation with the 5% and 170cm height

[stone wigeon]

yeah I wrote out that and the P(X < 170) = 0.05 but I have just been staring at those two for ages

[sterile nymph]

Two equations and two unknowns

[stone wigeon]

ooo interesting thanks

got it!

thanks!

.close

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[amber wasp]

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Remember:
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unreal kettle]

hi i want this channel

[split sail]

for?

[tulip tapir]

uhm

this

you don't just claim channels

unless you actually have a doubt

[unreal kettle]

i mean for the maintime i need help

[tulip tapir]

so

[unreal kettle]

one sec

[tulip tapir]

occupy one when you have a doubt-

you can't just reserve a channel

[unreal kettle]

its for my homework

[tulip tapir]

that doesn't justify it...

[pallid canopy]

other people have actual questions

[unreal kettle]

im so confuse

[tulip tapir]

look

if you have a question rn

send it

and you get to keep the channel

[cold sparrow]

You don't need to reserve in advance

Just post your questions

[tulip tapir]

otherwise, please close it

[native stag]

if you have a question just paste it or else .close it

[tulip tapir]

so that others can use this channel

[unreal kettle]

close/

[tulip tapir]

.close

[native stag]

there's always plenty of channels lol.

[amber wasp]

Channel closed

Closed by @tulip tapir

Use .reopen if this was a mistake.

[sick sandal]

I'll sell it to you for $5

[pallid canopy]

[coral wigeon]

i’ll sell it to you for nitro

[unreal kettle]

it was for the 5 mins cause i was trying to find the problem

[native stag]

I'll sell you help for $5

/j

[unreal kettle]

ILL GIVE U NITRO

[tulip tapir]

okay first off

we are not here to help others in exchange for nitro

[native stag]

ren everyone's joking chill

[unreal kettle]

JUST BE MY TUTOR PLEASE\

[tulip tapir]

it doesn't seem like lex is

[native stag]

Ah.

[tulip tapir]

ik the rest of you are lmfao

[native stag]

Well we're joking.

[coral wigeon]

speak for yourself

[unreal kettle]

I AM

[tulip tapir]

sh

[tulip tapir]

lex chill

[unreal kettle]

ahhaa oop