#help-41
1 messages · Page 7 of 1
Do you know the basic form of a parabola with shifted origin
is this equation wrong?
Mod only for the denominator ig
Once say the standard eqn of a parabola with shifted origin
Did you get first question atleast
thank you, that what i thought, because the tutorial showed this and i was very confused why so
ive only studied some and im having a really hard time with this one
https://lodev.org/cgtutor/raycasting.html#:~:text=sqrt(1 %2B (rayDirY * rayDirY) / (rayDirX * rayDirX))%20equals%20abs(sqrt(rayDirX%20*%20rayDirX%20%2B%20rayDirY%20*%20rayDirY)%20/%20rayDirX)
not yet
dont know
been watching tutorials on yt and still dont get it
dont judge me i suck at matu
math
Here the parabola is in the standard form x^2=-4ay
So these type of parabolas have their origin at 0,0
the first one has a vertex of 0,0
The parabolas which don’t have any extra numbers other than x,y (in addition) have vertex at (0,0)
thankyou so much
And now for the second question
Try to compare it to one of the eqn from the pic u sent
And find its vertex
ouhh okay i get it now
cuz of the formula
how did it become and -8?
i just need someone to explain it
can sum1 help
Because -4 times 2 is -8
thankyou but aside from that i need someone to explain me how this solvin works
step by step
It comes from the last equation here
The parabola goes to the left so it is the last one
Then you substitute each number
k = 2, h = 4 and p = |4-2| = 2
So you get (y-k)^2 = -4p(x-h) ---> (y-2)^2 = -4(2)(x-4)
what is negative plus negative?
positive plus positive?
negative minus positive
negative minus negative
what are the outcomes?
Negative plus negative is negative, positive plus positive is positive, negative minus positive is negative and negative minus negative depends
But how is that related to the question?
it is used when adding or subtracting the numbers
i get distracted by it and sometimes forget about the signs so yea
thankyou for helping
hi do you know anyone who can help me with chemistry?
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Calculate the angle theta between the force and the line AO
The solution is 57.7° But I don't know how to get that
I have calculated the unit vector to A, which is (1/3)i - (2/3)j + (2/3)k but I don't know how to continue with it
you can use the property of dot products [ \vb u \cdot \vb v = \norm{\vb u}\norm{\vb v} \cos \theta ] to calculate the angle between two vectors
cloud
so the unit vector here is u and the cartesian forces is v?
so do i have to do (-6i + 9j + 3k)(1/3i - 2/3j + 2/3k) = 11.22*cos(theta)?
but if i do that, how can i find theta since the left side will be cluttered with i, j and k?
<@&286206848099549185>
@stark sky Has your question been resolved?
<@&286206848099549185>
@stark sky Has your question been resolved?
To find the angle θ between two vectors, you first calculate their dot product, then use the formula involving the magnitudes of the vectors and the dot product to solve for θ.
@stark sky
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does any1 know how to prove this formulas?
you can do a u-substitution u = x/a, or a trig substitution x = a sin θ (or the appropriate trig function)
@unkempt imp Has your question been resolved?
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So what’s the answer you have already?
Right so since the difference between the x value of those two points (3) stays the same the difference between the two y values would have to be the same
So the difference between -1 and 3 is 4 so what’s the other y value that would have a difference of 4 from -1
would it be 5?
-5 specifically but yea!
What’s the difference between -1 and -5
Yea, which is why it’s -5
Because the difference between 5 and -1 is 6 which means the total distance between the two points if y=-5 wouldn’t be 5
If you draw it on a mini graph it makes a bit more sense
Ohh so you have to use the 1st answer ?
You can work it out in other ways but generally with a question like that the two answers are similar to each other in their differences from numbers
I would of worked it out graphically but it really depends on what feels best for you
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How would I solve this ?
,rccw
I don’t know how to calculate the surface area or volume of a funnel
My teacher never went over anything like that
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@sudden flare
@gentle galleon Has your question been resolved?
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Hello! Im having a bit of trouble with the folowing: find "b" s.t. y=x is tangent to y=log(base b)(x)
Well, you want both that $y = x$ meets $y = \log_b(x)$, and that at the point they meet, $y = \log_b(x)$ has the same gradient as $y = x$, right...?
@weak zinc
Yep, and you can find where log_b(x) does, right?
yes but that changes with b no?
Well, it will depend on b, sure, but that's fine 
Find the x coordinate in terms of b for the point where log_b(x) has gradient 1, then use the fact that at that point, you meet with y = x to find b's actual value
On that, what is the slope of $\log_b(x)$?
@weak zinc
1/xln(b)
Yep
and as above, if we find where that is 1...
b is fixed, though...
in the question it doesnt give a value for b, im supposed to find it so i dont have a number to evaluate it at
Which means you can find stuff in terms of b, it doesn't change like x can change: for a given value of b, the graph of log_b(x) is fixed
The whole aim is to try and find it given the information: only x changes here (similar to how e.g. log_2(x) doesn't have its graph change)
so should i evaluate it using b as some arbitrary constant?
Yes 
Got (e, e) as?
(x,y)
i averaged them after plugging in b
cuz it crossed at 2 points
tho now that i changed b it changed
Well, bear in mind that you're looking for b such that what you end up having, is this picture
There's an exact value for b
what method would u suggest to find it?
As per before: treat b like any other number, like 2, 5, e, 10, whatever
Given that b is a fixed number, for which value of x do you have that 1/(x * ln(b)) = 1?
for b=10 x=.43
Don't choose a specific value of b, remember we are, at the end of this, solving for b
And keep things exact
(but if b were 10, you would be right
)
hmm
Can you explain what you did to find that x?
i did ivt
...intermediate value theorem, to find x?
yes

...are you happy with the fact that $\frac1{x\ln(b)} = 1$ when $x = \frac1{\ln(b)}$, or...
@weak zinc
he did not figure that out
(ur bio says ping u when u dont respond)
💀
I've got some questions involving drawing for you 
whats the questions, do i know how to draw? not at all 😭
There've been a few where there's been a need to draw out a diagram to illustrate what was meant
me no like drawing either, to be fair 
Anyways, back to the actual question-
Are you at least happy that it's true?
my proff said he probably gonna put drawing on the exam 😭
yes
Cool cool, anyways, the idea from now, is that you also have that $x = \log_b(x)$ for the $x$ that we just found, that $x = \frac1{\ln(b)}$, because this is the point where $y = x$ meets $y = \log_b(x)$, being a tangent and all...
@weak zinc
Does that help a bit more with how to find b? 
GOSH DANG IT
what
gosh dang it why didnt we think of that 😂
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.reopen
I have assignment regarding the solve the equation in full formula and full explanation and the title is translations
@tepid verge
don't ping random people
I am sorry but I saw u were solving questions I am new and I need really help with this
what is the question asking?'
The upper pic
Our teacher needs to full explanation of that formula
It's translations
you tell me what it's asking
I ask you because it shows how well you understand the task at hand
The graph of y = √2x is translated by the vector (-5/3) Find the equation of the resulting graph.
Answer
y = √2x
y = √2(x+5) +3
y = √2x+10+3
Replace x by x +5, and add 3 to the resulting function.
in your own words
what does it mean to translate a graph / function by a vector (a,b) ?
It's an worked example it's already solved but our assignment is to solve it on a full formula with all explanation
It's translated by the vector
that doesn't answer the question because you've recycled the words 'translate' and 'vector'
I want to know what translated means in this context
and furthermore how to translate something by a 'vector'
Wait I will send u the lesson pics
no
I don't need you to show me your notes
you need to explain to another human being what your notes say
I am confused what do u want to say?
I'm telling you to explain what it means to translate a graph by a vector in your own words, as if you were teaching me
thanks for typing mommymorphism, that is a great name and a pleasure to read lol
When the x-coordinates on the two graphs are the same (x = x) the y-coordinates differ by 3 (y = y + 3)
This means that the two curves have exactly the same shape but that they are separated by 3 units in the positive y direction.
Hence, the graph of y = x ^ 2 - 2x + 4 is a translation of the graph of y = x ^ 2 - 2x + 1 by the vector(0/3)
intuitively, what does it mean to translate a graph?
Translating a graph means shifting the entire graph of a function or shape horizontally, vertically, or both, without changing its size, shape, or orientation. It’s like moving a picture up, down, left, or right on a page.
you're not being serious
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
That's my note that's what my teacher gave me as note
nevertheless, still not your words
ah rip ok I believe that
but yes it's your understanding he's trying to test, not your teachers
Yh cuz it's our new lesson and our teacher wants us ti explain it before she does
Ik but we haven't study the lesson yet
a verbatim excerpt of thoughts that aren't your own shared out of context helps no one
It's our assignment as presentation
so you're being asked to present the solution to this assignment?
Yes
My teacher chose 2 students a day to explain the new lesson and if we did she will give us points
They asked you to rephrase the question in your own words
Yh the book is cambridge
I need to solve the question in full formula with explanation
good assignment, and even more reason for you to show us your understanding
I need to present it in class so that other students can get it to its like being a teacher for a few min
Yh but I have problem solving it
first step to solve something is to understand what must be done in the first place
Ok
suppose I have a function f and a translation vector (a,b)
consider a point (x,y) on this function f; how do you translate it by this vector (a,b)?
Will it's our new lesson and we haven't study it
So I don't know
But if we have equations we can I do know that if the x is minus we got to the positive side of the the graph and if we x is plus we go to minus side of graph
And our teacher said we can help using the website desmos to draw the graph
The equation is solved already like I send the pic but I need the graph and the explanation
It's an worked example
what I want to do now is talk about translating points, rather than translating functions, because I think it'll help
you have a point (2,4) in space, no curve or function attached to it
I want to translate, or shift, this point by a translation vector (3,-1)
This was my friend presentation of today the same equation but different question
Yh?
Ok
let's talk about translating points
Ok
a point (2,4) is translated by a vector (3,-1). what do I mean by this?
rather, what should this mean?
means adding 3 to its x-coordinate and subtracting 1 from its y-coordinate maybe ?
exactly what I want it to mean
Ok
so after translating (2,4) by (3,-1), the corresponding point is now at (2+3, 4-1)
better expressed as (2+3, 4+(-1))
Is the my equation?
stop
Sorry
we're not there yet, we're on this ride
Oh ok
you can think of a translation vector as a general rule for where every point should be shifted
horizontally by how much, vertically by how much
generalizing now, a point (x,y) is translated by a vector (a,b)
where is this new point now?
Y (x + a, y + b) ??
exactly
you move the point x by a, and y by b
whether you shift the x-coordinate left or right (resp. the y-coordinate down or up) is encoded by whether a (resp. b) is positive or negative
that's why I decided to rephrase (2+3,4-1) as (2+3,4+(-1)) by the way
to recontextualize the shifting as just coordinate-wise addition, if that makes sense
Yh I do know that if x is minus it goes to the positive side in graph and it's it x positive it goes to the negative side
that's not what we're talking about
I hear you and know what you're talking about, but that's in the context of functions
Ok
that's saying the graph given by g(x) = f(x-a) is effectively the graph of f(x) in which each x-coordinate is shifted to the right by a
we'll being it back to functions here
to translate a function by a vector (a,b), we imagine that we're shifting every point (x,y) on the function by the same vector (a,b)
so for a given function f, each point (x,y) is transformed into the point (x+a, y+b)
but since (x,y) is on the function f, we of course know that y = f(x)
so this is the point (x, f(x)) translated to the point (x+a, f(x)+b)
does that make sense so far?
Yh ig
we want to collect this family of points (x+a, f(x)+b) to define a new function g, being the result of translating f by the vector (a,b)
so we can do this naive thing by defining g in such a way so that g(x+a) = f(x)+b; that's just correlating the x-coordinates with the y-coordinate
now if we want to determine g(x) for arbitrary x, we can write:
g(x) = g((x-a) + a) = f(x-a) + b
notice the substitution here; we add and subtract a to the parameter x inside of g in the first step, then identify that g((x-a)+a) is just a specification of g(z+a) with z=x-a to obtain the next step
this is why we see that, for example, g(x) = f(x-3) is the graph of f shifted to the right by 3, rather than to the left
does that all make sense?
I am worried for my future now
It's was all addition and subtraction
now it's x y f g z
Plus I am in high school too
hmm I thought you were an undergrad by the role you chose
I am in 11 class
undergraduates are college students by the way
who hadn't gotten their bachelors yet
I'm just saying your discord role suggests you're at the college level
How do u fit so much things in ur brain
Yh cuz I didn't saw the option of high-schooler one
that would be pre-university
I actually have stm
idk what stm is
Short term memory
ah
if it makes you feel better, I didn't just have a whole presentation memorized or anything
you just make it up as you go
thought that point translations, being more intuitive, would make function translations make more sense
Do u want me tell u something
I know zero things about math
That's y I hate it
Expect the basic
Plus we r studying online classes our school is online so it's makes it more harder to understand the lesson especially maths
a huge huge majority of math is about making overarching claims about systems, what can be said about every object of some kind in some world
⚰️
when we want to make a general claim about any object (like numbers or functions or whatever) and prove that our claim is true, we declare such objects arbitrarily and work with those
but we have to give them names. yet they're arbitrary, so we can't just say "pick a number -- like 3, I like 3"
you give them names so that you can refer to them easily, like x
because it's a single glyph and it looks good
f for function
whatever
Yh got it
especially in science, the exact representation of some data you're working with can be ugly numbers, either too large or require too much precision
which do you like looking at more, the number 173.1932809*pi*ln(3), or a single letter
I like the letter
yeah
so the point is that a function f translated by a vector (a,b) is a function g satisfying g(x) = f(x-a) + b
now refer to your original question
Finally
for whatever reason your translation vector is written like a column vector
but it changes nothing, it's just a representation
$\begin{pmatrix}a\b\end{pmatrix}\cong(a,b)$
Flip
I already saw it so there was no reason to delete it
sqrt just means square root, and it typesetted its response in latex
Yh idk the server was reporting something that's y
Then we just write it as sqrt ?
that was the bot complaining that it didn't compile correctly, but made a decent guess as to what it should look like
Ok
$\sqrt{2x}$
Flip
it's only written as sqrt in-line to make the compiler draw a radical
Ok
nobody writes sqrt as sqrt on paper
Yh that's y I asked it
How do I write it on paper?
$\sqrt{ }$
Flip
Ok
$\sqrt{\ \ \ \ \ }$
Flip
Got it
Flip
Ok
@tepid verge I will write the formula and then u check it if it's correct or not ok?
Is this correct ?
the vector $\begin{pmatrix}-5\3\end{pmatrix}$ is not awarded a horizontal bar. that makes it look like a fraction, which it isn't
Flip
the words are "shift" and "right" in the second line, i.e. they do not shed their t's
But in book it's written as fraction
it isn't
?
your wording stinks is what I'm saying
an answer to a question only "can be" something if the original question is poorly worded
and that your proposed answer is an answer to one possible interpretation of the supposedly-vague question
generally it's a bad habit to write "the final answer is _"
you want to address exactly what we've done here to avoid ambiguity
if we think of everything mathematical as a possible answer, you could really produce some absolute nonsense
like, '3' is an answer to some questions, but definitely not even a plausible answer to 'name a point on this graph'
Will I will solve u the whole formula along the explanation then send u in private then check it
no private messages, thanks
Ok sorry
your explanation should be a justification for why you know for sure that it's right
your reasoning is correct
I'm giving you feedback on your writing
because you'll be reading these notes and saying them out loud and it could sound awkward or unconvincing
Yh ik dw I will solve it later I do have time till Saturday
Thanks for ur help
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Sam places 2 straws forming angles p and q which are supplementary. Sam moves straw n such that value of q triples. How does value of p change?
you're given that the angles producing measurements p and q are supplementary
what does this mean?
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Trying to do Q26
so $x^3-0 < \varepsilon$
Veni, vidi, perii
so $-(\varepsilon)^{1/3}<x-0<(\varepsilon)^{1/3}$
so $|\delta|< \varepsilon^{1/3}$
what now
Do I select a value of delta?
ah yes
so okay, so take $\delta=1$
Veni, vidi, perii
$1<\varepsilon^{1/3}$
Veni, vidi, perii
so it seems to work?
p+q=180
Also why did the bot close the channel on its own
To not cause chaos ill switch to another channel kindly help me there
@keen pawn Has your question been resolved?
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Closed that
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
I'm thinking
I'm on the floor rn, so kind of hard to write
waiting outside the classroom for my class to start
so what do you need help with
I think proving the contrapositive may be easier here
I'm just using this as my notebook
lol
Ofcourse that begs the question what's $\neg(A>B)$
Veni, vidi, perii
is it $B<A$
Veni, vidi, perii
i think yes
i see
Veni, vidi, perii
If AB is invertible obviously m=n is possible
now m<n is a more interesting question
I think a single counter example will suffice?
Am I on the right track?
a single counter example is enough, as long as you don't fix A,B,m,n
The statement should read as, for all A,B such that A is m-by-n and B is n-by-m, if m > n, then AB is not invertible. So you have to prove for all A,B pair.
This question is actually easy, just shove m independent vectors in and see what comes out
n independent vectors
at most
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does pacals triangle only work with positive binomials like (a+b)^n and not (a-b)^n
It also works if you rewrite $(a-b)^n$ as $(a+(-b))^n$
d
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hi i need help with this
translate please
uhh yea sry forgot that part
it say decide every x for which is acceptable for ..... and then chose the correct answer
so you need to find the interval of x
seems fine to me
-(1-pi/3) or (-1-pi)/3
so its correct?
you messed up in signs
yes
but is it the second one or the third one?
3rd
No it isnt?
wym
Its the second one
how?
how is it the third one
i double checked now its the 3rd
so it is solved
yes!
it say imagine if b>0. the number .... can be written such as ... , give the solution to a
i got the third on this also
do i think right?
means?
i write it below it
i mean the 1st one is solved, we're doing the 2nd one right?
yes
so what does the 4th option says?
none of the solution given is correct
ok so from the question, can you make an equation?
yes i did and in my final answer i got pi ln (4b)
explain your steps
so first step was i took 4^bpi=e^a
and the next step is taking ln to both sides
and becuase we gonna solve a i got a= bpi*ln(4)
wasn't it 4^(bpi)
i typed it wrong here lol
did not notice
on paper i had the correct way
take natural log on both sides
yes i did that was the second step
next what do you get
and then i got this
and is there any option for this?
nope
so the option will be?
none of them?
simplifying won't do anything
but the third one seems also correct
atleast you won't get the other options
becuase everything is * each other
yup
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Does the function f(x) = 3x^3 + 4x^2 + 5x + 2 have no maxima nor minima?
At least that's what I got
I'm getting imaginary roots bruh
Are you talking about absolute or local max/min? all functions have a max/min
I guess my precalc(?) teacher might have tought me differently, does your teacher/professor consider infinity as a max/min, other wise the function doesn't seem to have a "hill" or "trough" so, yes there is no maxima nor minima, to those standards
@river whale Has your question been resolved?
Yeah
So
The function should be
Only increasing
And never decreasing
Meaning no local maximas or minimas exist
Im asking for confirmation of that
Local
Ah so no local maxima or minima essentially
Thanks
.close
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Bro
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It's increasing so no maxima Or minima?
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Prove that for any Polynomial P with integer coefficients and any n atural number k, there exists such a natural n, that P(1) + P(2) + ... + P(n) is divisible by k
I assume this'll use the Integer Root Theorem of Bezout
where p(a) - p(b) is divisible by a-b
however i don't see hwo to manipulate those statements to get + Polynomials instead
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nope
to spot your mistake, think about the value f(x) would have at the very values just before it switches to another equation
like -1 or 2
An easier way to solve that would be to plug in the values for x and get y coordinate using that
And then compare
yeah comparing the different y values for the x's in the graphs is easier
im leaning towards D
i think its D
oh wait really??
oh my god dude i messed up with the numbers
Ohh
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how do I do this
isolate v
to isolate a variable you need to know what operations are currently being done on the side the variable is on and in what order they are in
this will be in the opposite order of:
Parenthesis, Exponents, Multiplication and Division, Addition and Subtraction
looking at the side of v we have: sqrt(5+vt)
only operation currently is what?
@hot nacelle Has your question been resolved?
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How'd you get 13? can you show the steps
Why square root?
The question is asking for which interval does |x-4|<3. The answer is not a particular number but rather a collection of points, and in this case an interval
When you take a square root, what you have is $\sqrt{|x-4|}<\sqrt{3}$, this doesn't solve anything
Van21sT
Do you know what (a,b) represents?
Not really. (a,b) is an interval in this case. It means the collection of points x such that a<x<b.
Well you could do process of elimination. For each option pick a point in the interval and see if it satisfies the inequality. In the case where 0 is in the interval what can you conclude?
i plug in the x cord?
Ye
y=mx +b
That's not the general formula tho. It works if one of the point lies along the x-axis y-axis
But in this case it's not
ok
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So basically I have this question, and the answer is shown here:
but I need to know why its not that part in red?
because your theta is bounded
between 3pi/4 and 7pi/4
Oh so it goes from the positive x axis counterclockwise?
yes
ok thanks
counterclockwise always
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can someone help me with this proof
I’m just not exactly sure how to get to proving that ad bisects bac bc ik i can do BA is congruent to CA because of definition of isosceles and then after there i’m just not fully sure how i should go about it
ok so first
you write bd equals dc
cuz ad bisects bc
then ab = ac
so then you do sss
to get
abd is congruent to acd
and then cpctc
bad is congruent to cad
then since Since BAD = CAD AD bisects BAC
oh okay that makes sense
thank you
i was just a little confused on how to get to that
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can someone help me with this? i’m struggling with how im supposed to plug in the limit and get the answer.
how do i do that? i’m so confused in this class my professor never showed us
do you know what the lim notation means
whether it reaches the point or not doesn't really matter
at x=1 what is the function approaching
you might have to estimate a little
could you explain? because there isn’t a point at x=1
so what does the x=1 signify
yes there is
you sure that isn't for b or c
a=2, b=1, c=4
nah that's wrong 😭
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Im stuck on the first image with the arrow and question mark
I dont understand how the integral is equal to that
Thismy work
@merry adder Has your question been resolved?
How is it equal to that
@merry adder Has your question been resolved?
Noone has answered anything
How do i close this
Do .close
.close
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i dont know what i need to do
i dont understand what n, r and t means
can you please show me how to start this question
n, r, t are values you need to find
if you perform algebra to simplify the given expression, it'll ultimately end up in that form
@hearty finch Has your question been resolved?
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Show your work, and if possible, explain where you are stuck.
what's going on with your denominator here?
ummmm idk
that's concerning
how do i solve 5b^-1/6 
youre trying to find b? or just simplify??
im trying to find this but i dont know what to do with the ^-1/6
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Is the red panda population increasing or decreasing how would I know
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hi guys this is about compound angle formula. i don’t understand why that angle (yellow mark) is A. the person on yt mentioned something related to that 90 degree-A (circled in green). but i don’t understand why it became A
take triangle PRB
there R is 90
and the sum of all angles of a traingle is 180 ( i think this is the compound angle formula)
if it’s like that, why is the angle highlighted yellow not (90-B)/2?
(i’m not sure if it’s divided by 2 or not)
Wha-
its not divided by 2 lol
I don't think so
and it is btw just that we have taken the opposite ( B = 90-A)
Sum of angles in a triangle is a different formula
idk what its called but over here its called the angle sum property
Do you know how he got the two circled angles
@slate gale
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I am trying to do part c.
I'm thinking that you can pair each number with its counter part up until 4 and 46.
Like (5, 0)/(0, 5) would work but (-1, 4)/(4,-1) would not since -1 isn't in the range.
So if I ignore the mirrored pair and start the sequence, it would be something like (0, 5), (1, 6), (2, 7) ... (45, 50). Does this mean there is 46x2 possible pairs?
its unordered so u dont multiply by 2
unordered means (0,5) and (5,0) are considered same
yes
yes
Cheers.
oh wait unordered
If it was ordered, would I multiply by two?
yes
yes
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hi omg sorry for the late reply
hii sorry for the late reply, yes i know
i think i get it noww
thank you so much for ur help
thank you so much for your help!
You are welcome
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In how many ways can the numbers 1 through 5 be entered once each into the five boxes below so that all the given inequalities are true?
a < b
c < b
c < d
e < d
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2, I thought it would be 6, since
1 3 2 5 4
1 5 2 3 4
2 3 1 5 4
2 5 1 3 4
3 5 1 4 2
3 5 2 4 1
are the permuations I found
but that is incorrect
according to this, you can write the numbers as a,c,e < b,d OR a,c < b < e,d OR a highly specific case c,e < a,d < b. Now you can figure from here on, which numbers may be placed at which locations and permute them accordingly
@limpid totem Has your question been resolved?
@limpid totem Has your question been resolved?
1 4 2 5 3 is definitely missing
maybe a sudoku-like approach may work. 5 needs to be in second or fourth place. Then 4 needs to be next to the 5 but at the edge (first or last place), or in the fourth or second place where the 5 isn't.
And then take it from there
When 4 is at the edge place next to the 5, then the position of 3 is fixed.
Got it? Does this help?
sort of.. let me try again (still can't get it)
@limpid totem Has your question been resolved?
Why is A(x) = √(x^4 ) = I x² I and why not -x² because (-x²)(-x²)=x^4
@limpid totem Has your question been resolved?
the principle square root always returns a positive number
@limpid totem Has your question been resolved?
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couldnt it be 4 or 8 seconds since both of them have the same area under the curve
just at 4 seconds it was moving right then at 8 seconds it was moving left
but the velocity is the same even if you are moving different direrctions?
You are thinking of speed. Velocity has direction.
so since its a negetive, the direciton and speed will be opposite so its slower?
idk
even if you are moving different directions
That is important
oh wait
at 8 seconds the velocity would be negetive because its going left
4 seconds its positive going right
so 4 is when it has the highest velo?
Yes but to be pedantic negative doesn’t mean going left and positive doesnt mean going right. It means going towards vs against a reference direction.
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and at 4 seconds it would be furthest away from the starting position, right?
Yeah
Actually maybe not
It could still be traveling away from the starting point, just at a lower speed
even if its below the 0 it could still be traveling away from the starting point?
If acceleration is below 0 yes.
If you are driving a car and let go of the gas pedal you are accelerating negatively but still going forward
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Hi! How do I go about solving this?
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Let A and B be two open, non-empty subsets of R with A =/= B. Is there always an open subset of A \ B?
Okay yeah true, uhhh add that A is not a subset of B
In this I reckon it would be true, but I don't understand how to prove the assertion
@mild kindle Has your question been resolved?
Imagine A = (0,2) and B = (0,1)U(1,2).
True
Okay
I'm asking about Y when I should be asking about X
How would I show that an open subset of R uniquely determines the set of rational balls contained in it (i.e. open balls with rational center)? If this is even true that is
where does this question come from?
you know that if a rational number q is in a open subset A, then any ball (so interval) B(q,r) with r < d(q,R\A) is contained in it
in fact this works for any real number x instead of just any rational number q
Yeah
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what does this even mean
V is infinite dimensional if and only if you can find an infinite sequence v1,... such that (v1,...,vm) is linearly independent
no matter which m is picked last
from the other perspective, you know that if V is finite dimensional, then at some point you run out of linearly independent vectors to take. at some point v1,...,vm have to be linearly dependent
"no matter how many linearly independent vectors you have, you can always find one more"
for infinite dim spaces that doesnt happen
I see
okay
Let me think
Now that I think of it, we haven't done dimension yet, i'll come back to this in a bit
thanks
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Guys can someone just check this for 5 seconds and say if NOGPT‼️is doing it correctly?
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A fish has 17 cards labelled 1 to 17
It shuffles it
It notices that in the shuffled deck if it can charge the position of one card the cards are in ascending order
Find the number of possible arrangement of cards that the fish could have had
my approach is that pick any one card and there are 16 ways that it can be in the wrong position
so a total of 17*16 ways
but apparently thats wrong.
what if you think about the problem in reverse
put all the cards in order
now just move one card
do you see how, if you started with that, you could move that one card to make them in order?
hmm
yes
starting with 1 2 3:
we will count 2 1 3 twice
once when we move the 2 around, again when we move the 1
is this similar to circular permutations?
i don’t think so
one thing you can try to do is figure out which arrangements you overcount with this process, and how many times you count them
and subtract off the overcounting
you might notice that e.g. 3 1 2 only gets counted once
