#help-41

1 messages · Page 7 of 1

sonic gazelle
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how do you solve this?

echo wharf
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Do you know the basic form of a parabola with shifted origin

dull salmon
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is this equation wrong?

sonic gazelle
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i have the standard equation formulas

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i have an exam tomorrow and im stuck

echo wharf
echo wharf
sonic gazelle
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here

echo wharf
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Did you get first question atleast

dull salmon
sonic gazelle
# sonic gazelle

ive only studied some and im having a really hard time with this one

echo wharf
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Did u get this one

sonic gazelle
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not yet

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dont know

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been watching tutorials on yt and still dont get it

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dont judge me i suck at matu

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math

echo wharf
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Here the parabola is in the standard form x^2=-4ay

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So these type of parabolas have their origin at 0,0

sonic gazelle
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the first one has a vertex of 0,0

echo wharf
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Yes

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Vertex mb

sonic gazelle
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how do u solve it

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the x2 = - 1/2y

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wait okay i get it now guys

echo wharf
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The parabolas which don’t have any extra numbers other than x,y (in addition) have vertex at (0,0)

sonic gazelle
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thankyou so much

echo wharf
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And now for the second question

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Try to compare it to one of the eqn from the pic u sent

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And find its vertex

sonic gazelle
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ouhh okay i get it now

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cuz of the formula

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how did it become and -8?

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i just need someone to explain it

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can sum1 help

elfin vale
sonic gazelle
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thankyou but aside from that i need someone to explain me how this solvin works

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step by step

elfin vale
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The parabola goes to the left so it is the last one

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Then you substitute each number

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k = 2, h = 4 and p = |4-2| = 2

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So you get (y-k)^2 = -4p(x-h) ---> (y-2)^2 = -4(2)(x-4)

sonic gazelle
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what is negative plus negative?

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positive plus positive?

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negative minus positive

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negative minus negative

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what are the outcomes?

elfin vale
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I don't understand

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What do you mean?

elfin vale
# sonic gazelle what are the outcomes?

Negative plus negative is negative, positive plus positive is positive, negative minus positive is negative and negative minus negative depends
But how is that related to the question?

sonic gazelle
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it is used when adding or subtracting the numbers

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i get distracted by it and sometimes forget about the signs so yea

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thankyou for helping

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hi do you know anyone who can help me with chemistry?

amber waspBOT
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@sonic gazelle Has your question been resolved?

amber waspBOT
#
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stark sky
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Calculate the angle theta between the force and the line AO

stark sky
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The solution is 57.7° But I don't know how to get that
I have calculated the unit vector to A, which is (1/3)i - (2/3)j + (2/3)k but I don't know how to continue with it

shadow stump
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you can use the property of dot products [ \vb u \cdot \vb v = \norm{\vb u}\norm{\vb v} \cos \theta ] to calculate the angle between two vectors

grizzled pagodaBOT
stark sky
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so do i have to do (-6i + 9j + 3k)(1/3i - 2/3j + 2/3k) = 11.22*cos(theta)?

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but if i do that, how can i find theta since the left side will be cluttered with i, j and k?

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<@&286206848099549185>

amber waspBOT
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@stark sky Has your question been resolved?

stark sky
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<@&286206848099549185>

amber waspBOT
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@stark sky Has your question been resolved?

noble peak
# stark sky <@&286206848099549185>

To find the angle θ between two vectors, you first calculate their dot product, then use the formula involving the magnitudes of the vectors and the dot product to solve for θ.

#

@stark sky

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unkempt imp
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does any1 know how to prove this formulas?

shadow stump
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you can do a u-substitution u = x/a, or a trig substitution x = a sin θ (or the appropriate trig function)

unkempt imp
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no U sub

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by using the unit circle

amber waspBOT
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@unkempt imp Has your question been resolved?

amber waspBOT
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@unkempt imp Has your question been resolved?

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vale smelt
amber waspBOT
vale smelt
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I need help on 2 I have 1 out of 2 answers

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I'm cooked

wet plinth
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So what’s the answer you have already?

vale smelt
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3

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that's one of them

wet plinth
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Right so since the difference between the x value of those two points (3) stays the same the difference between the two y values would have to be the same
So the difference between -1 and 3 is 4 so what’s the other y value that would have a difference of 4 from -1

vale smelt
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would it be 5?

wet plinth
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-5 specifically but yea!

vale smelt
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How's it a negative?

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can you help me understand😭

wet plinth
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What’s the difference between -1 and -5

vale smelt
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4

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?

wet plinth
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Yea, which is why it’s -5
Because the difference between 5 and -1 is 6 which means the total distance between the two points if y=-5 wouldn’t be 5

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If you draw it on a mini graph it makes a bit more sense

vale smelt
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Ohh so you have to use the 1st answer ?

wet plinth
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You can work it out in other ways but generally with a question like that the two answers are similar to each other in their differences from numbers

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I would of worked it out graphically but it really depends on what feels best for you

vale smelt
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okay thanks

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You saved me fr

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.close

amber waspBOT
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bright cloak
amber waspBOT
bright cloak
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How would I solve this ?

compact yarrow
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,rccw

grizzled pagodaBOT
bright cloak
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I don’t know how to calculate the surface area or volume of a funnel

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My teacher never went over anything like that

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<@&286206848099549185>

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.close

amber waspBOT
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amber waspBOT
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@gentle galleon Has your question been resolved?

gentle galleon
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@sudden flare

amber waspBOT
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@gentle galleon Has your question been resolved?

amber waspBOT
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@gentle galleon Has your question been resolved?

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hybrid mango
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Hello! Im having a bit of trouble with the folowing: find "b" s.t. y=x is tangent to y=log(base b)(x)

weak zinc
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Well, you want both that $y = x$ meets $y = \log_b(x)$, and that at the point they meet, $y = \log_b(x)$ has the same gradient as $y = x$, right...?

grizzled pagodaBOT
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@weak zinc

hybrid mango
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the same gradient?

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they both need a slope of 1 yea

weak zinc
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Yep, and you can find where log_b(x) does, right?

hybrid mango
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yes but that changes with b no?

weak zinc
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Well, it will depend on b, sure, but that's fine catokay

hybrid mango
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so do i set them equal

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how does finding b help?

weak zinc
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Find the x coordinate in terms of b for the point where log_b(x) has gradient 1, then use the fact that at that point, you meet with y = x to find b's actual value

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On that, what is the slope of $\log_b(x)$?

grizzled pagodaBOT
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@weak zinc

hybrid mango
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1/xln(b)

weak zinc
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Yep catokay and as above, if we find where that is 1...

hybrid mango
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that equals one anywhere tho

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since b changes

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and so does

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x

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im confused

weak zinc
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b is fixed, though...

hybrid mango
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in the question it doesnt give a value for b, im supposed to find it so i dont have a number to evaluate it at

weak zinc
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Which means you can find stuff in terms of b, it doesn't change like x can change: for a given value of b, the graph of log_b(x) is fixed

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The whole aim is to try and find it given the information: only x changes here (similar to how e.g. log_2(x) doesn't have its graph change)

hybrid mango
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so should i evaluate it using b as some arbitrary constant?

weak zinc
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Yes SCyes

hybrid mango
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ok

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so i plugged it in and averaged the x and y values

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and i got (e,e)

weak zinc
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Got (e, e) as?

hybrid mango
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(x,y)

weak zinc
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Hmmmm...

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Where and why did you average x and y values though?

hybrid mango
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i averaged them after plugging in b

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cuz it crossed at 2 points

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tho now that i changed b it changed

weak zinc
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Well, bear in mind that you're looking for b such that what you end up having, is this picture

hybrid mango
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yes

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manually trying points for b in desmos i got

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1.44444

weak zinc
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There's an exact value for b

hybrid mango
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what method would u suggest to find it?

weak zinc
weak zinc
hybrid mango
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for b=10 x=.43

weak zinc
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Don't choose a specific value of b, remember we are, at the end of this, solving for b

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And keep things exact

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(but if b were 10, you would be right catokay)

hybrid mango
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hmm

weak zinc
hybrid mango
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i did ivt

weak zinc
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...intermediate value theorem, to find x?

hybrid mango
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yes

weak zinc
hybrid mango
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it was fastest since i was using desmos

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slider

weak zinc
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...are you happy with the fact that $\frac1{x\ln(b)} = 1$ when $x = \frac1{\ln(b)}$, or...

grizzled pagodaBOT
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@weak zinc

hybrid mango
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..

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i did not figure that out

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...

unborn vapor
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(ur bio says ping u when u dont respond)

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💀

weak zinc
unborn vapor
weak zinc
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There've been a few where there's been a need to draw out a diagram to illustrate what was meant kek me no like drawing either, to be fair KL1NotLikeThis

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Anyways, back to the actual question-

weak zinc
unborn vapor
unborn vapor
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😂

hybrid mango
weak zinc
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Cool cool, anyways, the idea from now, is that you also have that $x = \log_b(x)$ for the $x$ that we just found, that $x = \frac1{\ln(b)}$, because this is the point where $y = x$ meets $y = \log_b(x)$, being a tangent and all...

grizzled pagodaBOT
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@weak zinc

weak zinc
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Does that help a bit more with how to find b? pikathink

unborn vapor
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x = log_b(x)?

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oh cuz y = x at that point...

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bruh

hybrid mango
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yes that helps

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thank youu

weak zinc
unborn vapor
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GOSH DANG IT

hybrid mango
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what

unborn vapor
amber waspBOT
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@hybrid mango Has your question been resolved?

amber waspBOT
#
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amber waspBOT
#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

split sail
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.reopen

amber waspBOT
split sail
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I have assignment regarding the solve the equation in full formula and full explanation and the title is translations

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@tepid verge

tepid verge
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don't ping random people

split sail
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I am sorry but I saw u were solving questions I am new and I need really help with this

tepid verge
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what is the question asking?'

split sail
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The upper pic
Our teacher needs to full explanation of that formula

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It's translations

tepid verge
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you tell me what it's asking

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I ask you because it shows how well you understand the task at hand

split sail
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The graph of y = √2x is translated by the vector (-5/3) Find the equation of the resulting graph.

Answer

y = √2x

y = √2(x+5) +3

y = √2x+10+3

Replace x by x +5, and add 3 to the resulting function.

tepid verge
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in your own words

split sail
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Idk

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I don't get the formula that's y I mean the question

tepid verge
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what does it mean to translate a graph / function by a vector (a,b) ?

split sail
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It's an worked example it's already solved but our assignment is to solve it on a full formula with all explanation

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It's translated by the vector

tepid verge
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that doesn't answer the question because you've recycled the words 'translate' and 'vector'

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I want to know what translated means in this context

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and furthermore how to translate something by a 'vector'

split sail
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Wait I will send u the lesson pics

tepid verge
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no

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I don't need you to show me your notes

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you need to explain to another human being what your notes say

split sail
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I am confused what do u want to say?

tepid verge
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I'm telling you to explain what it means to translate a graph by a vector in your own words, as if you were teaching me

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thanks for typing mommymorphism, that is a great name and a pleasure to read lol

split sail
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When the x-coordinates on the two graphs are the same (x = x) the y-coordinates differ by 3 (y = y + 3)
This means that the two curves have exactly the same shape but that they are separated by 3 units in the positive y direction.

Hence, the graph of y = x ^ 2 - 2x + 4 is a translation of the graph of y = x ^ 2 - 2x + 1 by the vector(0/3)

tepid verge
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intuitively, what does it mean to translate a graph?

split sail
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Translating a graph means shifting the entire graph of a function or shape horizontally, vertically, or both, without changing its size, shape, or orientation. It’s like moving a picture up, down, left, or right on a page.

tepid verge
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you're not being serious

vestal hatch
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!nogpt

amber waspBOT
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Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

split sail
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That's my note that's what my teacher gave me as note

tepid verge
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nevertheless, still not your words

vestal hatch
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ah rip ok I believe that

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but yes it's your understanding he's trying to test, not your teachers

split sail
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Yh cuz it's our new lesson and our teacher wants us ti explain it before she does

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Ik but we haven't study the lesson yet

tepid verge
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a verbatim excerpt of thoughts that aren't your own shared out of context helps no one

split sail
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It's our assignment as presentation

tepid verge
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so you're being asked to present the solution to this assignment?

split sail
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Yes
My teacher chose 2 students a day to explain the new lesson and if we did she will give us points

rapid stag
split sail
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Yh the book is cambridge

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I need to solve the question in full formula with explanation

tepid verge
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good assignment, and even more reason for you to show us your understanding

split sail
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I need to present it in class so that other students can get it to its like being a teacher for a few min

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Yh but I have problem solving it

tepid verge
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first step to solve something is to understand what must be done in the first place

split sail
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Ok

tepid verge
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suppose I have a function f and a translation vector (a,b)

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consider a point (x,y) on this function f; how do you translate it by this vector (a,b)?

split sail
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Will it's our new lesson and we haven't study it
So I don't know
But if we have equations we can I do know that if the x is minus we got to the positive side of the the graph and if we x is plus we go to minus side of graph

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And our teacher said we can help using the website desmos to draw the graph

tepid verge
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where is the point (2, 4) in the plane?

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you may draw a picture

split sail
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The equation is solved already like I send the pic but I need the graph and the explanation
It's an worked example

tepid verge
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what I want to do now is talk about translating points, rather than translating functions, because I think it'll help

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you have a point (2,4) in space, no curve or function attached to it

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I want to translate, or shift, this point by a translation vector (3,-1)

split sail
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This was my friend presentation of today the same equation but different question

tepid verge
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what does that mean?

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hey

split sail
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Yh?

tepid verge
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join me on this ride

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I don't care about functions right now

split sail
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Ok

tepid verge
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let's talk about translating points

split sail
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Ok

tepid verge
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a point (2,4) is translated by a vector (3,-1). what do I mean by this?

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rather, what should this mean?

split sail
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means adding 3 to its x-coordinate and subtracting 1 from its y-coordinate maybe ?

tepid verge
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exactly what I want it to mean

split sail
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Ok

tepid verge
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so after translating (2,4) by (3,-1), the corresponding point is now at (2+3, 4-1)

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better expressed as (2+3, 4+(-1))

split sail
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Is the my equation?

tepid verge
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stop

split sail
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Sorry

tepid verge
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we're not there yet, we're on this ride

split sail
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Oh ok

tepid verge
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you can think of a translation vector as a general rule for where every point should be shifted

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horizontally by how much, vertically by how much

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generalizing now, a point (x,y) is translated by a vector (a,b)

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where is this new point now?

split sail
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Y (x + a, y + b) ??

tepid verge
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exactly

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you move the point x by a, and y by b

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whether you shift the x-coordinate left or right (resp. the y-coordinate down or up) is encoded by whether a (resp. b) is positive or negative

tepid verge
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to recontextualize the shifting as just coordinate-wise addition, if that makes sense

split sail
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Yh I do know that if x is minus it goes to the positive side in graph and it's it x positive it goes to the negative side

tepid verge
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that's not what we're talking about

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I hear you and know what you're talking about, but that's in the context of functions

split sail
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Ok

tepid verge
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that's saying the graph given by g(x) = f(x-a) is effectively the graph of f(x) in which each x-coordinate is shifted to the right by a

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we'll being it back to functions here

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to translate a function by a vector (a,b), we imagine that we're shifting every point (x,y) on the function by the same vector (a,b)

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so for a given function f, each point (x,y) is transformed into the point (x+a, y+b)

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but since (x,y) is on the function f, we of course know that y = f(x)

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so this is the point (x, f(x)) translated to the point (x+a, f(x)+b)

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does that make sense so far?

split sail
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Yh ig

tepid verge
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we want to collect this family of points (x+a, f(x)+b) to define a new function g, being the result of translating f by the vector (a,b)

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so we can do this naive thing by defining g in such a way so that g(x+a) = f(x)+b; that's just correlating the x-coordinates with the y-coordinate

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now if we want to determine g(x) for arbitrary x, we can write:
g(x) = g((x-a) + a) = f(x-a) + b

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notice the substitution here; we add and subtract a to the parameter x inside of g in the first step, then identify that g((x-a)+a) is just a specification of g(z+a) with z=x-a to obtain the next step

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this is why we see that, for example, g(x) = f(x-3) is the graph of f shifted to the right by 3, rather than to the left

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does that all make sense?

split sail
tepid verge
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woah

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why lol

split sail
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It's was all addition and subtraction
now it's x y f g z

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Plus I am in high school too

tepid verge
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hmm I thought you were an undergrad by the role you chose

split sail
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I am in 11 class

tepid verge
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undergraduates are college students by the way

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who hadn't gotten their bachelors yet

split sail
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Yh but I am still in class 11

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Of high school

tepid verge
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I'm just saying your discord role suggests you're at the college level

split sail
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How do u fit so much things in ur brain

split sail
tepid verge
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that would be pre-university

split sail
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I actually have stm

tepid verge
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idk what stm is

split sail
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Short term memory

tepid verge
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ah

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if it makes you feel better, I didn't just have a whole presentation memorized or anything

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you just make it up as you go

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thought that point translations, being more intuitive, would make function translations make more sense

split sail
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Do u want me tell u something
I know zero things about math
That's y I hate it
Expect the basic

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Plus we r studying online classes our school is online so it's makes it more harder to understand the lesson especially maths

tepid verge
tepid verge
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when we want to make a general claim about any object (like numbers or functions or whatever) and prove that our claim is true, we declare such objects arbitrarily and work with those

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but we have to give them names. yet they're arbitrary, so we can't just say "pick a number -- like 3, I like 3"

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you give them names so that you can refer to them easily, like x

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because it's a single glyph and it looks good

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f for function

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whatever

split sail
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Yh got it

tepid verge
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especially in science, the exact representation of some data you're working with can be ugly numbers, either too large or require too much precision

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which do you like looking at more, the number 173.1932809*pi*ln(3), or a single letter

#

I like the letter

split sail
#

I like none

#

Ok so can we continue back to the equation I did get it a bit

tepid verge
#

yeah

#

so the point is that a function f translated by a vector (a,b) is a function g satisfying g(x) = f(x-a) + b

#

now refer to your original question

split sail
#

Finally

tepid verge
#

for whatever reason your translation vector is written like a column vector

#

but it changes nothing, it's just a representation

#

$\begin{pmatrix}a\b\end{pmatrix}\cong(a,b)$

grizzled pagodaBOT
split sail
#

Its (-5 over 3)

#

@tepid verge ?

tepid verge
#

I already saw it so there was no reason to delete it

#

sqrt just means square root, and it typesetted its response in latex

split sail
split sail
tepid verge
#

that was the bot complaining that it didn't compile correctly, but made a decent guess as to what it should look like

split sail
#

Ok

tepid verge
#

$\sqrt{2x}$

grizzled pagodaBOT
tepid verge
#

it's only written as sqrt in-line to make the compiler draw a radical

split sail
#

Ok

tepid verge
#

nobody writes sqrt as sqrt on paper

split sail
#

Yh that's y I asked it

tepid verge
#

unless if they were talking about a program with a sqrt function

#

then maybe

split sail
#

How do I write it on paper?

tepid verge
#

$\sqrt{ }$

grizzled pagodaBOT
split sail
#

Ok

tepid verge
#

$\sqrt{\ \ \ \ \ }$

grizzled pagodaBOT
split sail
#

Got it

tepid verge
#

bar length matches contents

#

$\sqrt2x\neq\sqrt{2x}$

grizzled pagodaBOT
split sail
#

Ok

#

@tepid verge I will write the formula and then u check it if it's correct or not ok?

#

Is this correct ?

tepid verge
#

the vector $\begin{pmatrix}-5\3\end{pmatrix}$ is not awarded a horizontal bar. that makes it look like a fraction, which it isn't

grizzled pagodaBOT
tepid verge
#

the words are "shift" and "right" in the second line, i.e. they do not shed their t's

split sail
#

But in book it's written as fraction

tepid verge
#

it isn't

split sail
#

Oh sorry there isn't any line mb

#

So Is my formula correct ?

#

The one I solved

tepid verge
#

the final answer "can be" [blah] is wrong

#

it's "is"

split sail
#

?

tepid verge
#

your wording stinks is what I'm saying

#

an answer to a question only "can be" something if the original question is poorly worded

#

and that your proposed answer is an answer to one possible interpretation of the supposedly-vague question

#

generally it's a bad habit to write "the final answer is _"

#

you want to address exactly what we've done here to avoid ambiguity

#

if we think of everything mathematical as a possible answer, you could really produce some absolute nonsense

#

like, '3' is an answer to some questions, but definitely not even a plausible answer to 'name a point on this graph'

split sail
#

Will I will solve u the whole formula along the explanation then send u in private then check it

tepid verge
#

no private messages, thanks

split sail
#

Ok sorry

tepid verge
#

your explanation should be a justification for why you know for sure that it's right

#

your reasoning is correct

#

I'm giving you feedback on your writing

#

because you'll be reading these notes and saying them out loud and it could sound awkward or unconvincing

split sail
#

Yh ik dw I will solve it later I do have time till Saturday
Thanks for ur help

tepid verge
#

.close

amber waspBOT
#
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sharp stream
#

Sam places 2 straws forming angles p and q which are supplementary. Sam moves straw n such that value of q triples. How does value of p change?

tepid verge
#

you're given that the angles producing measurements p and q are supplementary

#

what does this mean?

amber waspBOT
#

@sharp stream Has your question been resolved?

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keen pawn
#

Trying to do Q26

amber waspBOT
keen pawn
#

so $x^3-0 < \varepsilon$

grizzled pagodaBOT
#

Veni, vidi, perii

keen pawn
#

so $-(\varepsilon)^{1/3}<x-0<(\varepsilon)^{1/3}$

#

so $|\delta|< \varepsilon^{1/3}$

#

what now

#

Do I select a value of delta?

indigo cloud
#

what happened to your absolute values

#

but yes, select a delta that works

keen pawn
#

ah yes

grizzled pagodaBOT
#

Veni, vidi, perii

#

Veni, vidi, perii

keen pawn
#

so okay, so take $\delta=1$

grizzled pagodaBOT
#

Veni, vidi, perii

keen pawn
#

$1<\varepsilon^{1/3}$

grizzled pagodaBOT
#

Veni, vidi, perii

keen pawn
#

so it seems to work?

sharp stream
#

Also why did the bot close the channel on its own

#

To not cause chaos ill switch to another channel kindly help me there

amber waspBOT
#

@keen pawn Has your question been resolved?

#
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keen pawn
amber waspBOT
#

Please don't occupy multiple help channels.

keen pawn
#

oops

#

I would like to NOT use the hint

near stone
#

u already occupied

#

43

#

type .close

keen pawn
#

Closed that

near stone
#

oh ok

#

@status

#

!status

amber waspBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
keen pawn
#

I'm thinking

#

I'm on the floor rn, so kind of hard to write

#

waiting outside the classroom for my class to start

near stone
#

so what do you need help with

keen pawn
#

I think proving the contrapositive may be easier here

keen pawn
near stone
#

lol

keen pawn
#

Ofcourse that begs the question what's $\neg(A>B)$

grizzled pagodaBOT
#

Veni, vidi, perii

keen pawn
#

is it $B<A$

grizzled pagodaBOT
#

Veni, vidi, perii

near stone
#

i think yes

keen pawn
#

If $AB$ is invertible $\implies m \not > n$

#

is what I have to prove

near stone
#

i see

grizzled pagodaBOT
#

Veni, vidi, perii

keen pawn
#

If AB is invertible obviously m=n is possible

#

now m<n is a more interesting question

#

I think a single counter example will suffice?

#

Am I on the right track?

split sail
#

a single counter example is enough, as long as you don't fix A,B,m,n

keen pawn
#

wait what

#

a counter example requires me to fix A,B, m, n

#

right

split sail
#

The statement should read as, for all A,B such that A is m-by-n and B is n-by-m, if m > n, then AB is not invertible. So you have to prove for all A,B pair.

#

This question is actually easy, just shove m independent vectors in and see what comes out

keen pawn
#

n independent vectors

split sail
#

at most

keen pawn
#

Yes

#

Let me actually think about this a bit more

#

.close

amber waspBOT
#
Channel closed

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keen pawn
#

Sorry

amber waspBOT
#
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fringe spire
#

does pacals triangle only work with positive binomials like (a+b)^n and not (a-b)^n

elfin vale
grizzled pagodaBOT
fringe spire
#

ty

#

sm

#

.close

amber waspBOT
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wicked iron
#

hi i need help with this

amber waspBOT
wicked iron
#

one

foggy kayak
#

translate please

wicked iron
#

uhh yea sry forgot that part

#

it say decide every x for which is acceptable for ..... and then chose the correct answer

foggy kayak
#

so you need to find the interval of x

wicked iron
#

yes

#

i got -1-pi/3 < x < 1-pi/3

#

but i am not sure if that is correct or not

foggy kayak
#

seems fine to me

rugged edge
#

-(1-pi/3) or (-1-pi)/3

wicked iron
foggy kayak
foggy kayak
rugged edge
#

Im asking a clarification question

wicked iron
foggy kayak
#

3rd

rugged edge
#

No it isnt?

foggy kayak
#

wym

rugged edge
#

Its the second one

foggy kayak
#

how?

rugged edge
#

how is it the third one

foggy kayak
#

|3x+pi|<1

#

-1<3x+pi<1

#

-1-pi<3x<1-pi

#

(-1-pi)/3 < x < (1-pi)/3

#

?

wicked iron
#

i double checked now its the 3rd

foggy kayak
#

so it is solved

wicked iron
#

yes!

#

it say imagine if b>0. the number .... can be written such as ... , give the solution to a

#

i got the third on this also

wicked iron
foggy kayak
#

means?

wicked iron
foggy kayak
#

i mean the 1st one is solved, we're doing the 2nd one right?

wicked iron
#

yes

foggy kayak
#

so what does the 4th option says?

wicked iron
#

none of the solution given is correct

foggy kayak
#

ok so from the question, can you make an equation?

wicked iron
#

yes i did and in my final answer i got pi ln (4b)

foggy kayak
#

explain your steps

wicked iron
#

so first step was i took 4^bpi=e^a

#

and the next step is taking ln to both sides

#

and becuase we gonna solve a i got a= bpi*ln(4)

foggy kayak
#

wasn't it 4^(bpi)

wicked iron
#

yea

#

so did i do the correct way?

foggy kayak
#

so it will be 4^(b pi) = e^a instead

#

not 4b^pi

#

they are different

wicked iron
#

did not notice

#

on paper i had the correct way

foggy kayak
#

take natural log on both sides

wicked iron
#

yes i did that was the second step

foggy kayak
#

next what do you get

wicked iron
foggy kayak
#

and is there any option for this?

wicked iron
#

nope

foggy kayak
#

so the option will be?

wicked iron
#

none of them?

foggy kayak
#

yeah

#

d

wicked iron
#

but cant we simplify it?

#

more ?

foggy kayak
#

simplifying won't do anything

wicked iron
#

but the third one seems also correct

foggy kayak
#

atleast you won't get the other options

wicked iron
#

becuase everything is * each other

foggy kayak
#

yup

wicked iron
#

a= bpiln(4)

#

so why isnt the third one correct?

foggy kayak
#

in 3rd option. a= pi*ln(4b)

#

and they are not same

#

so the answer will be d

wicked iron
#

uhhh yea true

#

none of them is correct

#

thx for the help bro

#

.close

amber waspBOT
#
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amber waspBOT
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river whale
#

Does the function f(x) = 3x^3 + 4x^2 + 5x + 2 have no maxima nor minima?

river whale
#

At least that's what I got

static shoal
olive surge
#

Are you talking about absolute or local max/min? all functions have a max/min

#

I guess my precalc(?) teacher might have tought me differently, does your teacher/professor consider infinity as a max/min, other wise the function doesn't seem to have a "hill" or "trough" so, yes there is no maxima nor minima, to those standards

amber waspBOT
#

@river whale Has your question been resolved?

river whale
#

So

#

The function should be

#

Only increasing

#

And never decreasing

#

Meaning no local maximas or minimas exist

#

Im asking for confirmation of that

river whale
#

Thanks

#

.close

amber waspBOT
#
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static shoal
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static shoal
amber waspBOT
#

@static shoal Has your question been resolved?

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unique rose
#

Prove that for any Polynomial P with integer coefficients and any n atural number k, there exists such a natural n, that P(1) + P(2) + ... + P(n) is divisible by k

unique rose
#

I assume this'll use the Integer Root Theorem of Bezout

#

where p(a) - p(b) is divisible by a-b

#

however i don't see hwo to manipulate those statements to get + Polynomials instead

amber waspBOT
#

@unique rose Has your question been resolved?

unique rose
#

<@&286206848099549185>

unique rose
#

.close

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#
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exotic olive
amber waspBOT
exotic olive
#

am i right with A

trim cliff
#

to spot your mistake, think about the value f(x) would have at the very values just before it switches to another equation

#

like -1 or 2

clever dock
#

An easier way to solve that would be to plug in the values for x and get y coordinate using that
And then compare

trim cliff
#

yeah comparing the different y values for the x's in the graphs is easier

clever dock
#

It should be c

#

In the second equation when you put x=1
You get y = -1/2

exotic olive
#

oh wait really??

exotic olive
clever dock
#

Ohh

amber waspBOT
#

@exotic olive Has your question been resolved?

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hot nacelle
#

how do I do this

amber waspBOT
mortal dust
#

to isolate a variable you need to know what operations are currently being done on the side the variable is on and in what order they are in

#

this will be in the opposite order of:
Parenthesis, Exponents, Multiplication and Division, Addition and Subtraction

#

looking at the side of v we have: sqrt(5+vt)

#

only operation currently is what?

amber waspBOT
#

@hot nacelle Has your question been resolved?

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#
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hasty rock
amber waspBOT
hasty rock
#

i isloated for x

#

and got 13

young needle
#

How'd you get 13? can you show the steps

hasty rock
#

i took the sqaure root of 3

#

and then added 4

#

5.73

#

not 13 mb

young needle
#

Why square root?

hasty rock
#

to get rd of the

#

rid of the absoulte

young needle
#

The question is asking for which interval does |x-4|<3. The answer is not a particular number but rather a collection of points, and in this case an interval

#

When you take a square root, what you have is $\sqrt{|x-4|}<\sqrt{3}$, this doesn't solve anything

grizzled pagodaBOT
#

Van21sT

hasty rock
#

oh

#

what am i even doing in the questio

young needle
#

Do you know what (a,b) represents?

hasty rock
#

cords that exist

#

on the graph

young needle
#

Not really. (a,b) is an interval in this case. It means the collection of points x such that a<x<b.

hasty rock
#

okay

#

what do you have to do

young needle
#

Well you could do process of elimination. For each option pick a point in the interval and see if it satisfies the inequality. In the case where 0 is in the interval what can you conclude?

hasty rock
#

i plug in the x cord?

young needle
#

Ye

hasty rock
#

got the answer thanks

#

what about this one

young needle
#

What's the formula for a slope?

#

(a,b) in this case means that point x=a and y=b

hasty rock
#

y=mx +b

young needle
#

That's the equation for a line

#

The equation for a slope is the equation for m

hasty rock
#

oh yh

#

m= (y-b)/x

young needle
#

That's not the general formula tho. It works if one of the point lies along the x-axis y-axis

#

But in this case it's not

hasty rock
#

ok

amber waspBOT
#

@hasty rock Has your question been resolved?

amber waspBOT
#
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amber waspBOT
#
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silk crescent
#

So basically I have this question, and the answer is shown here:

silk crescent
#

but I need to know why its not that part in red?

patent raptor
#

between 3pi/4 and 7pi/4

silk crescent
#

Oh so it goes from the positive x axis counterclockwise?

patent raptor
#

yes

silk crescent
#

ok thanks

patent raptor
#

counterclockwise always

silk crescent
#

alr

#

thanks

#

.close

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#
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split sail
#

can someone help me with this proof

amber waspBOT
olive pelican
#

what part of it are you confused on

#

@split sail

split sail
#

I’m just not exactly sure how to get to proving that ad bisects bac bc ik i can do BA is congruent to CA because of definition of isosceles and then after there i’m just not fully sure how i should go about it

olive pelican
#

ok so first

#

you write bd equals dc

#

cuz ad bisects bc

#

then ab = ac

#

so then you do sss

#

to get

#

abd is congruent to acd

#

and then cpctc

#

bad is congruent to cad

#

then since Since BAD = CAD AD bisects BAC

split sail
#

oh okay that makes sense

#

thank you

#

i was just a little confused on how to get to that

olive pelican
#

oh ight

#

just do alot of questions and you'll get the hang of it

split sail
#

alright thank you

#

.close

amber waspBOT
#
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bronze ore
#

can someone help me with this? i’m struggling with how im supposed to plug in the limit and get the answer.

mellow hornet
#

you don't plug anything in

#

you're just analyzing the graph

bronze ore
#

how do i do that? i’m so confused in this class my professor never showed us

mellow hornet
#

do you know what the lim notation means

bronze ore
#

yea x as it approaches a certain point

#

but never actually reaching that point

mellow hornet
#

at x=1 what is the function approaching

#

you might have to estimate a little

bronze ore
#

so what does the x=1 signify

mellow hornet
bronze ore
#

ohh

#

so that would be like 3.3

#

but in my calc book the answer shows as 2

mellow hornet
#

you sure that isn't for b or c

bronze ore
#

a=2, b=1, c=4

mellow hornet
#

nah that's wrong 😭

bronze ore
#

😭

#

this making me even more confused

mellow hornet
#

for x=3 it approaches y=2 from both sides

#

so b and c should be 2

bronze ore
#

that makes sense

#

book threw me off so hard

#

preciate it

#

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merry adder
#

Im stuck on the first image with the arrow and question mark
I dont understand how the integral is equal to that

merry adder
#

Thismy work

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merry adder
#

How is it equal to that

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merry adder
#

Noone has answered anything

merry adder
#

How do i close this

pallid canopy
merry adder
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.close

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hearty finch
#

i dont know what i need to do
i dont understand what n, r and t means
can you please show me how to start this question

hearty finch
compact yarrow
#

n, r, t are values you need to find

#

if you perform algebra to simplify the given expression, it'll ultimately end up in that form

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hearty finch
#

it says my anser is wrong

#

i got n=5, r=5, t=1

#

only r is right

compact yarrow
#

!show

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#

Show your work, and if possible, explain where you are stuck.

hearty finch
compact yarrow
#

what's going on with your denominator here?

hearty finch
#

ummmm idk

compact yarrow
#

that's concerning

hearty finch
#

how do i solve 5b^-1/6 cat_happycry

flat hollow
hearty finch
# hearty finch

im trying to find this but i dont know what to do with the ^-1/6

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tender schooner
#

Is the red panda population increasing or decreasing how would I know

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slate gale
#

hi guys this is about compound angle formula. i don’t understand why that angle (yellow mark) is A. the person on yt mentioned something related to that 90 degree-A (circled in green). but i don’t understand why it became A

soft comet
#

take triangle PRB

#

there R is 90

#

and the sum of all angles of a traingle is 180 ( i think this is the compound angle formula)

slate gale
#

if it’s like that, why is the angle highlighted yellow not (90-B)/2?

#

(i’m not sure if it’s divided by 2 or not)

keen topaz
#

Wha-

soft comet
soft comet
keen topaz
#

Sum of angles in a triangle is a different formula

soft comet
keen topaz
#

@slate gale

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iron heath
#

I am trying to do part c.

amber waspBOT
iron heath
#

I'm thinking that you can pair each number with its counter part up until 4 and 46.

#

Like (5, 0)/(0, 5) would work but (-1, 4)/(4,-1) would not since -1 isn't in the range.

#

So if I ignore the mirrored pair and start the sequence, it would be something like (0, 5), (1, 6), (2, 7) ... (45, 50). Does this mean there is 46x2 possible pairs?

full marsh
#

its unordered so u dont multiply by 2

#

unordered means (0,5) and (5,0) are considered same

iron heath
#

Gotcha.

#

So 46?

#

Or am I missing something

full marsh
#

yes

iron heath
#

Cheers.

cedar plaza
#

oh wait unordered

iron heath
#

If it was ordered, would I multiply by two?

cedar plaza
#

yes

iron heath
#

Heard.

#

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slate gale
slate gale
#

i think i get it noww

slate gale
slate gale
keen topaz
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limpid totem
#

In how many ways can the numbers 1 through 5 be entered once each into the five boxes below so that all the given inequalities are true?

tulip tapir
#

a < b
c < b
c < d
e < d

amber waspBOT
limpid totem
#

2, I thought it would be 6, since

1 3 2 5 4
1 5 2 3 4
2 3 1 5 4
2 5 1 3 4
3 5 1 4 2
3 5 2 4 1

are the permuations I found

#

but that is incorrect

fresh ocean
# tulip tapir a < b c < b c < d e < d

according to this, you can write the numbers as a,c,e < b,d OR a,c < b < e,d OR a highly specific case c,e < a,d < b. Now you can figure from here on, which numbers may be placed at which locations and permute them accordingly

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split sail
#

1 4 2 5 3 is definitely missing

limpid totem
#

Hmm

#

yeah i'm more stuck then

split sail
#

maybe a sudoku-like approach may work. 5 needs to be in second or fourth place. Then 4 needs to be next to the 5 but at the edge (first or last place), or in the fourth or second place where the 5 isn't.

#

And then take it from there

#

When 4 is at the edge place next to the 5, then the position of 3 is fixed.

#

Got it? Does this help?

limpid totem
#

sort of.. let me try again (still can't get it)

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#

@limpid totem Has your question been resolved?

unreal dome
#

Why is A(x) = √(x^4 ) = I x² I and why not -x² because (-x²)(-x²)=x^4

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#

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plush marten
#

the principle square root always returns a positive number

sinful sapphire
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hasty lotus
#

couldnt it be 4 or 8 seconds since both of them have the same area under the curve

#

just at 4 seconds it was moving right then at 8 seconds it was moving left

#

but the velocity is the same even if you are moving different direrctions?

shy hazel
#

You are thinking of speed. Velocity has direction.

hasty lotus
#

so since its a negetive, the direciton and speed will be opposite so its slower?

#

idk

prisma onyx
#

That is important

hasty lotus
#

oh wait

#

at 8 seconds the velocity would be negetive because its going left

#

4 seconds its positive going right

#

so 4 is when it has the highest velo?

shy hazel
#

Yes but to be pedantic negative doesn’t mean going left and positive doesnt mean going right. It means going towards vs against a reference direction.

hasty lotus
#

ah

#

ty

#

.close

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shy hazel
#

np

#

Oh also at 8 seconds the speed is 0 because the area is 0

hasty lotus
#

and at 4 seconds it would be furthest away from the starting position, right?

shy hazel
#

Yeah

#

Actually maybe not

#

It could still be traveling away from the starting point, just at a lower speed

hasty lotus
#

even if its below the 0 it could still be traveling away from the starting point?

shy hazel
#

If acceleration is below 0 yes.

#

If you are driving a car and let go of the gas pedal you are accelerating negatively but still going forward

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fathom pawn
#

Hi! How do I go about solving this?

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fathom pawn
#

<@&286206848099549185>

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#

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mild kindle
#

Let A and B be two open, non-empty subsets of R with A =/= B. Is there always an open subset of A \ B?

cunning birch
#

well apart from empty set depends on A and B

#

if A is a subset of B...

mild kindle
#

In this I reckon it would be true, but I don't understand how to prove the assertion

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cunning birch
#

Imagine A = (0,2) and B = (0,1)U(1,2).

mild kindle
#

True

#

Okay

#

I'm asking about Y when I should be asking about X

#

How would I show that an open subset of R uniquely determines the set of rational balls contained in it (i.e. open balls with rational center)? If this is even true that is

cunning birch
#

where does this question come from?

#

you know that if a rational number q is in a open subset A, then any ball (so interval) B(q,r) with r < d(q,R\A) is contained in it

#

in fact this works for any real number x instead of just any rational number q

mild kindle
#

Yeah

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keen pawn
#

what does this even mean

amber waspBOT
cunning birch
#

V is infinite dimensional if and only if you can find an infinite sequence v1,... such that (v1,...,vm) is linearly independent

#

no matter which m is picked last

indigo cloud
#

from the other perspective, you know that if V is finite dimensional, then at some point you run out of linearly independent vectors to take. at some point v1,...,vm have to be linearly dependent

shrewd elm
#

"no matter how many linearly independent vectors you have, you can always find one more"

indigo cloud
#

for infinite dim spaces that doesnt happen

keen pawn
#

I see

#

okay

#

Let me think

#

Now that I think of it, we haven't done dimension yet, i'll come back to this in a bit

#

thanks

#

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marble shoal
#

Guys can someone just check this for 5 seconds and say if NOGPT‼️is doing it correctly?

marble shoal
#

sorry i didnt translate

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fair nest
#

A fish has 17 cards labelled 1 to 17
It shuffles it
It notices that in the shuffled deck if it can charge the position of one card the cards are in ascending order
Find the number of possible arrangement of cards that the fish could have had

fair nest
#

my approach is that pick any one card and there are 16 ways that it can be in the wrong position

#

so a total of 17*16 ways

#

but apparently thats wrong.

coral wigeon
#

what if you think about the problem in reverse

#

put all the cards in order

#

now just move one card

#

do you see how, if you started with that, you could move that one card to make them in order?

fair nest
#

yes

#

but isnt the logic same here? each card has 16 other positions i can move to

coral wigeon
#

let’s do a simpler example

#

with say 3 cards

fair nest
#

ohh i am overcounting

#

there would be repeated permutations

fair nest
coral wigeon
#

starting with 1 2 3:
we will count 2 1 3 twice

#

once when we move the 2 around, again when we move the 1

fair nest
#

is this similar to circular permutations?

coral wigeon
#

i don’t think so

coral wigeon
#

and subtract off the overcounting

coral wigeon
fair nest
#

yeah

#

i dont get it 😭