#help-41

1 messages · Page 6 of 1

lusty turret
#

It just won't be easy

knotty reef
lusty turret
#

My prof from Uni doesn't know how to help sadly

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Did ask him once a year ago about it, but I was too occupied to keep up with Uni math to learn on my own

knotty reef
#

catscream dam u can try using yt and if ur stuck anywhere the server is always here for u

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catthumbsup and me too

lusty turret
#

Thank you for that

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Luckily as long as it's numbers I manage to do them with the correct tutorial

knotty reef
lusty turret
#

I probably will appear here once few days while I am studying

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Thank you again

amber waspBOT
#

@split sail Has your question been resolved?

amber waspBOT
#
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quartz crescent
#

is this solvable?

amber waspBOT
dull pike
#

Yes

quartz crescent
#

can you help?

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like i don't know where to start

amber waspBOT
#

@quartz crescent Has your question been resolved?

amber waspBOT
#

@quartz crescent Has your question been resolved?

quartz crescent
#

can any1 help?

mint wraith
quartz crescent
#

like from the corner to the intersection?

mint wraith
#

Yes

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You'll end up having some triangles with equal area

quartz crescent
#

ok what after that?

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how did you know they have equal areas?

mint wraith
#

Not all of them are equal

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Wait a min

quartz crescent
#

take your time

mint wraith
#

They have same bases and same height

quartz crescent
#

yes thanks a lot the answer is 28 thats what i got

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right?

mint wraith
#

Yes

quartz crescent
#

thanks again

#

.close

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rare hatch
amber waspBOT
rare hatch
#

let’s do this again

solar oyster
#

I thought the last guy did a good job lol 😨

rare hatch
#

what was bro even yappin about

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did not help one bit he just started spewing words that I didn’t even understand what was going on

solar oyster
tiny latch
#

can anyone help me figure out what I'm doing wrong

weak zinc
amber waspBOT
rare hatch
#

that’s literally all I’m asking

lusty pine
rare hatch
#

everything

#

I don’t understand the process

solar oyster
#

Sorry I forgot

solar oyster
amber waspBOT
#

@rare hatch Has your question been resolved?

rare hatch
#

So

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Why

solar oyster
#

Cause vertex form

rare hatch
#

Wow so helpful

solar oyster
#

my fault

amber waspBOT
#

@rare hatch Has your question been resolved?

rare hatch
#

.close

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long yoke
#

$\mathcal{(L}_s)^{-1} (\frac{s^2 + s +1}{s^2 + 4s +5})$

grizzled pagodaBOT
#

Triaxyz

long yoke
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I will explain my process but I got $\delta (t) -3e^{-2t}\cos(t) -4e^{-2t}\sin(t)$ which symbo says is wrong

grizzled pagodaBOT
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Triaxyz

long yoke
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convert $\frac{s^2 + s +1}{s^2 + 4s +5}$ into $\frac{s^2 + s +1+3s+4-3s-4}{(s+2)^2+1}$

grizzled pagodaBOT
#

Triaxyz

long yoke
#

which becomes $\frac{(s+2)^2+1}{(s+2)^2+1} - \frac{3s}{(s+2)^2+1} - \frac{4}{(s+2)^2+1}$

grizzled pagodaBOT
#

Triaxyz

cedar plaza
#

all s variables have to be replaced by s-a for you to use that

long yoke
#

wait it might

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yeah'

cedar plaza
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i.e. the second term

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what does symbo say

long yoke
#

so 3(s+2-2) which turns into +6 on that last term

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and 6-4 = 2 which is the coefficient that symbo says

#

alright I got it

#

thank you

#

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#
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glad schooner
#

I’m not sure if I plugged In the number correctly. Can someone please tell me if I have or not? And if I’m going in the right direction?

split sail
#

clicky with the linky?

vernal surge
#

^ porn

glad schooner
#

pls I just want help with my hw

split sail
#

<@&268886789983436800> 18+ (nsfw)
(sorry for ping)
(i turned off reply ping to that message)

abstract canopy
#

<@&268886789983436800>

glad schooner
#

I rewrote it bc I think the first time I wrote it wrong

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<@&286206848099549185>

amber waspBOT
#

@glad schooner Has your question been resolved?

glad schooner
#

<@&286206848099549185>

bronze basalt
glad schooner
#

What am I supposed to plug in for y then 💔

glad schooner
bronze basalt
#

you don't plug anything in for y

bronze basalt
glad schooner
bronze basalt
#

yep

#

exactly like that

glad schooner
#

Oh okay thank you!

amber waspBOT
#

@glad schooner Has your question been resolved?

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gusty stream
#

Hello guys, quick question:

How can I write
$\dots + \frac{-7}{2} + \frac{-5}{2} + \frac{-3}{2} + \frac{-1}{2} + \frac{1}{2} + \frac{3}{2} + \frac{5}{2} + \frac{7}{2} + \dots$ as a series?

grizzled pagodaBOT
#

Akkaman

split sail
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why do you want to write that as a series

gusty stream
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Because I need it to solve a problem. 😄

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I'm just unsure about how to write it as a series with the sigma symbol.

tropic wadi
split sail
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it is

pseudo crescent
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Well...

vernal surge
gusty stream
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Yeah it is, I am looking at the reciprocals of them, so $\frac{1}{\frac{-7}{2}}$ etc...

grizzled pagodaBOT
#

Akkaman

pseudo crescent
gusty stream
#

It has something to do with another problem.

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I really just need to know how to write it without the dots but rather with the sigma symbol. 🥲

pseudo crescent
tropic wadi
vernal surge
grizzled pagodaBOT
pseudo crescent
tropic wadi
wanton sentinel
pseudo crescent
#

I guess that since it's both directional, I can pick any order.
So 1/2 + 3/2 - 1/2 + 5/2 + 7/2 - 3/2 + 9/2 + 11/2 - 5/2....

#

whoops - that's not 0

vernal surge
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the cauchy principal value of it is 0, but just applying the basic definitions it will diverge

wanton sentinel
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Yeah, really this can evaluate to any rational number or -inf or +inf

pseudo crescent
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Can't it evaluate to any real number actually

wanton sentinel
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Well no not any rational

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integer or half

vernal surge
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well to answer the question though

gusty stream
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$\sum^\infty_{n=1} \frac{1}{(2n-1)^2}$ would be the series over the squared reciprocals of all positive odd numbers, right?

grizzled pagodaBOT
#

Akkaman

wanton sentinel
pseudo crescent
wanton sentinel
pseudo crescent
vernal surge
#

$\sum_{k=-\infty}^{\infty} \frac{2k+1}{2} = \sum_{k \in \mathbb{Z}} \frac{2k+1}{2}$ something like this, but it will really just diverge

grizzled pagodaBOT
pseudo crescent
#

its partial sums will oscillate

pseudo crescent
gusty stream
# vernal surge yes

If I multiply that by $\frac{1}{2}$, would I not just get the series over the squared reciprocals of $\frac{1}{2} + \frac{3}{2} + \frac{5}{2} + \dots$?

grizzled pagodaBOT
#

Akkaman

wanton sentinel
# pseudo crescent its partial sums will oscillate

pandahmm that's another interesting point, does it necessarily oscillate or can you find an order such that it doesn't? I guess since the terms are growing absolutely on either side, you actually can't find such an order, so yeah it can't even evaluate to a specific number

gusty stream
grizzled pagodaBOT
#

Akkaman

pseudo crescent
pseudo crescent
#

except instead of + you should use ,

gusty stream
#

Yeah sorry. 😄

pseudo crescent
#

and the series would be multiplied by 2 if im not mistaken

#

$2\sum_{n=1}^{\infty}\frac{1}{\left(2n-1\right)^{2}}=\sum_{n=1}^{\infty}\frac{2}{\left(2n-1\right)^{2}}$

grizzled pagodaBOT
#

MæthIsAlwaysRight

wanton sentinel
#

Anyway, like @pseudo crescent already said, you should just state the original problem instead

pseudo crescent
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what's the goal of multiplying it by 2 btw?

wanton sentinel
#

I must be blind

gusty stream
#

There should be a mathematical operation to go from $\frac{1}{2}, \frac{3}{2}, \frac{5}{2}, \dots$ to $1, 2, 3, \dots$, right?

grizzled pagodaBOT
#

Akkaman

wanton sentinel
#

Yes, +1/2

pseudo crescent
#

I think you are doing quite weird things here though

gusty stream
wanton sentinel
#

No

pseudo crescent
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no

gusty stream
pseudo crescent
#

there is a simple way to get value of this from that

gusty stream
pseudo crescent
#

are you trying to transform this to zeta function or sth?

gusty stream
wanton sentinel
# grizzled pagoda **Akkaman**

All pairs of consecutive terms in both sequences differ by 1. If you multiply one sequence by some number (apart from 1), that will change and it cannot give you the other sequence

pseudo crescent
vernal surge
#

I'm still confused, so you do not have proven zeta(2) yet, or do you? And now you want to prove the value for the odd squares?

gusty stream
#

I wanted to know how to get from $\frac{1}{2}, \frac{3}{2}, \frac{5}{2}, \frac{7}{2}, \dots$ to $1, 2, 3, 4, \dots$ by some mathemical operation.

grizzled pagodaBOT
#

Akkaman

pseudo crescent
#

add + 1/2 to each term

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isnt the real goal here getting from sum of 1/(2n-1)^2 to the sum of 1/n^2?

gusty stream
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No no.

vernal surge
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you can also multiply by 2, index shift and divide by 2

pseudo crescent
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multiply by 2, add 1, divide by 2

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just a warning: I don't think you can prove this thing "geometrically" by just playing around with numbers

gusty stream
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I think I made a mistake at some point.

wanton sentinel
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This feels so directionless

gusty stream
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I have to reevaluate my calculations I guess. 😂

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Thank you guys. 🙂

vernal surge
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also proving the value for zeta(2) is really not easy at all

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I know an elementary proof but it's a long journey

gusty stream
#

I have already done it algrebraicly and geometrically.

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But I wanted to modify the geometrical proof and now I am stuck. 😂

#

!close

#

.close

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sharp crater
#

how can this be proven in some other way

sharp crater
#

its unclear how one would reach this choice of q

indigo cloud
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one would reach this choice of q after hours of trying stuff

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its not that crazy. you want that p^2-2 in there quite naturally

sharp crater
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yes but that doesnt narrow down the choices for you so that you can reach this choice of q by trying some choices

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because there are still too many choices that involve p^2-2

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so there isnt a way to find these unless you gain more experience and gain this intuition naturally ?

indigo cloud
#

I mean thats how proofs generally go

sharp crater
#

thats right i understand your point

sharp crater
indigo cloud
#

its also not like this is the only choice of q that will work

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you would maybe start with q=p-(p^2-2), then square it and check what q^2-2 is. it doesnt work (presumably, otherwise they would have chosen that), so you maybe decide to use p-(p^2-2)/something. for that something you might decide it could be some multiple of p, so maybe kp. you try it out, maybe it works, maybe not. if it doesnt you might change it to kp+n

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and then you are there

amber waspBOT
#

@sharp crater Has your question been resolved?

sharp crater
#

i will try that

#

tysm

#

.close

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austere jungle
#

Hi, I've got a question I'm confused by... it's a really simple one but I have two different answers for it

A container will hold 106 ounces of grape juice. How many 6(5/8) ounce glasses of grape juice can be served from this container?

austere jungle
#

the picture shown is my working

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the answer in the textbook says it is 16 (glasses)

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but mathway says it is 11 (1/24)

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a 106-ounce container being served into glasses that are 6(5/8) ounce

tropic wadi
austere jungle
#

oh where it says 48/5

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D'oh!

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i just noticed as i was typing it out as well

tropic wadi
#

lol

austere jungle
#

53/5

limpid sun
tropic wadi
#

:magician:

austere jungle
#

i couldn't work it out but as soon as i asked it...

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some kind of quantum magic 🧙

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thanks guys

loud maple
#

what u guys doing?

tropic wadi
#

what does that supposed to mean/

loud maple
#

i came to this help-41/ap button saw u guys here what's up

loud maple
tropic wadi
loud maple
#

i'm just curios of what way you will use

tropic wadi
loud maple
#

(1 and 2/5) ^3

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??

tropic wadi
loud maple
#

yess

tropic wadi
#

{7/5}^3

loud maple
#

like the mixed fraction

austere jungle
#

it still works out to 11 though

austere jungle
loud maple
#

god that's 10

hoary musk
#

hi guys

night minnow
#

wassup

woven sparrow
hoary musk
#

im facing a problem when i try to solve through my calculator it keeps saying syntax error

amber waspBOT
austere jungle
loud maple
#

ap if you have let's say 121 where 2 is 1+1 it divides to 11

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wait

austere jungle
#

yes, 11^2 = 121

night minnow
loud maple
#

yeah for 13 it'd be 143

stoic locust
#

!status quo

amber waspBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
austere jungle
#
  1. i guess
loud maple
#

i'm trying to say 530 / 53 = 10 ap

stoic locust
#

wai

#

yes

#

53*10/10 = 53

austere jungle
woven sparrow
night minnow
#

I did the question idk if that’s what u wanted tho

austere jungle
#

i will check with mathway again as well

loud maple
austere jungle
# night minnow

16 is the answer that was given in the textbook, but i had the wrong answer (and working as well)

night minnow
austere jungle
#

that's good, at least the tetbook is right lol sully

stoic locust
#

are you a spammer jassbery?

night minnow
tropic wadi
night minnow
stoic locust
#

so the answer should be 2

austere jungle
#

d'oh!

night minnow
stoic locust
#

i hate when people don't care to calculate things

tropic wadi
loud maple
#

what how did i not see that good call 77

stoic locust
#

i mean 10

night minnow
#

@austere jungle so all good now :))?

austere jungle
#

i got it!

#

i did it

night minnow
#

Yay!!

austere jungle
#

horay : )

loud maple
austere jungle
#

yes, thank you all

loud maple
#

read that spammer word wrongly 1st time lol pheww

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i wonder why they'd call it that

austere jungle
#

yeah idk, i'm glad i clicked to show messages because i thought it might be a message from one of the bots at first

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hope you guys all have a great day btw, thanks again

stoic locust
#

bro thinks life is all sunshine and rainbows

maiden kernel
#

Close

austere jungle
#

sry

#

!close

#

.close

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#
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cursive wasp
#

Could I get help with this question please
I am not sure where to start

split sail
cursive wasp
split sail
cursive wasp
#

If I remember correctly it means that it is 2u + 5v where u = (1, 2) and v = (2, 3)

split sail
#

Not quite

#

[(2,5)]_B = [4 -1]^t means that 4u-1v = (2,5)

cursive wasp
#

Is [(2,5)]_B different from (2,5)_B?

split sail
#

I don't know what (2,5)_B means

cursive wasp
split sail
#

It's almost the same except [(2,5)]_B is vertical, I guess

cursive wasp
cursive wasp
split sail
cursive wasp
#

Ok I do nevermind

#

Thank you

#

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royal seal
#

Hello

amber waspBOT
royal seal
#

i’m a little confused on what i’m supposed to do for this problem

#

can anyone help me with it

#

and what does it mean by use any method

blazing cloak
#

g(x) is also a line

royal seal
#

what is g(x)?

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@median frost

#

@blazing cloak

blazing cloak
#

do you know how to find the equation of a line given two points?

#

I assume there's also a tool in the e-tool thing that allows you to form a line with two points

royal seal
#

we learned abt it in class today but i didn’t understand it

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don’t you like set them equal?

blazing cloak
#

???

royal seal
#

put me on to the tool 😂

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like how do i use it

royal seal
#

that’s what i’m really worried abt

blazing cloak
#

any two points define the line

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it doesn't matter which points you choose on g(x)

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you can also notice that there's a constant difference in the g(x) values and a constant difference in the x values. this also indicates its a line

royal seal
blazing cloak
#

yes

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you can use point-slope form

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y-(y1)=m(x-x1)

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where (x1,y1) is a point on the line

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and m is the slope

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you know how to find slope/gradient right

royal seal
#

i forgot 😅😅

#

i don’t remember anything from math 1 that’s why i’m so cooked

amber waspBOT
#

@royal seal Has your question been resolved?

amber waspBOT
#
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mystic hull
#

I don't get what it means by "increasing" and "decreasing"

pallid canopy
mystic hull
#

Could that be related to the first derivative test maybe

pallid canopy
#

equilibrium means dP/dt equals what value?

mystic hull
#

zero

#

If you do that you just get P=0 or P=230

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But if I remember those are called critical points of the function

pallid canopy
#

if dp/dt is zero at only those two points, then you can determine the sign around those points

mystic hull
#

This what I have so far

#

I meant p<0 my bad

pallid canopy
#

,w plot x(1-x/230)

pallid canopy
#

your sign looks wrong for p < 0

mystic hull
#

I made a typo so it should be p less than 0 means it's decreasing

pallid canopy
mystic hull
#

I don't know how I would phrase it, could I say for any p<0 the population is decreasing

pallid canopy
#

does p < 0 have physical meaning?

mystic hull
#

Most likely not

pallid canopy
#

do you understand why?

mystic hull
#

You can't have negative population

pallid canopy
#

right

pallid canopy
mystic hull
#

Yes

#

.close

amber waspBOT
#
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marble shoal
amber waspBOT
marble shoal
#

guys trying to solve this with L'H

#

i did someting wrong

#

but idk how

#

(e^1/x -1) derived

#

is chain rule right

#

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drowsy sedge
#

Hello! I understand you need to find the limit, right?

kindred trellis
drowsy sedge
#

Okey...

#

@marble shoal are you here?

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compact wagon
amber waspBOT
compact wagon
#

How to find left and right side limit

amber waspBOT
#

@compact wagon Has your question been resolved?

weak zinc
#

"Follow your finger from the left/right, what does it look like you're getting closer and closer to?"

compact wagon
#

i know thr right hand limit at x=0 but why does the left hand limit equal x=2 when there is ajump discontinuity

amber waspBOT
#

@compact wagon Has your question been resolved?

amber waspBOT
#

@compact wagon Has your question been resolved?

amber waspBOT
#

@compact wagon Has your question been resolved?

random epoch
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split sail
#

Is this correct?

amber waspBOT
tender knoll
#

,w sqrt(3x+12)=sqrt(x+8)

grizzled pagodaBOT
split sail
#

Nice

#

.close

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slate gale
amber waspBOT
slate gale
#

Guys, what should it be like? Is it number one or two?

#

I’m confused on how we’re supposed to connect the chords

#

Bcs i’m getting a gradient of 0 for the chord CB in the 2nd drawing

mint nacelle
mint nacelle
#

so that means the perpendicular bisector will be a vertical line

#

since its slope is undefined

#

actually notice that you have a right angle at B, due to the coordinates

#

so the centre is just the midpoint of CA

#

remember your circle theorems from IG

slate gale
slate gale
# mint nacelle number 2

How do i know if no 2 is the correct one in case CB and BA are not perpendicular to each other?

mint nacelle
#

you just need 2 out of the 3 perpendicular bisectors, so drawing 1 isn't wrong

#

it's just messier to work out

slate gale
#

Okk i’ll try to do it first

woeful temple
#

Just finished my As level on this yr may June got 73 on my p1 I'm pretty sure this has a formula

slate gale
woeful temple
slate gale
woeful temple
#

Just replace x and y and u will get 3 unknowns and 3 equations

mint nacelle
#

yes so radius is|| sqrt((7 - 4)^2 + (9 - 5)^2)||

woeful temple
#

Yes

#

Oh

split sail
# woeful temple

sorry for interrupting but i think x and y are supposed to stay as x and y and others to be substituted by number values so as to be an equation?

slate gale
mint nacelle
#

h, k, r are constants which depend on the circle

If we know h, k, r we can sub those in and get the equation of the circle

split sail
#

ah k

split sail
woeful temple
slate gale
mint nacelle
#

CA is the diameter

slate gale
#

Ohhhh okok

#

That makes more sense

#

Thank youuu

mint nacelle
#

.close

amber waspBOT
#
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errant vortex
#

can someone explain venn diagram union and intersection im really confused

zenith summit
#

Intersection means and

#

so for example, if we take a union b

#

we're saying a or b

#

in a venn diagram, it would be both the circles including the middle/overlapping section

#

however, if we say a intersection b

#

we're saying a and b

#

so you would only take the middle/overlapping section of the venn diagram

errant vortex
#

so does a or b mean both

#

and a and b means like

#

whatever is the same

#

because i get confused

zenith summit
#

A or B or both

errant vortex
#

okay thank you i get so confused

zenith summit
#

ight allgs

errant vortex
#

.close

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soft comet
amber waspBOT
soft comet
#

what can i even do here

split sail
soft comet
#

this is the original

split sail
#

i feel like it is translated cause the english isnt really that well

#

oh

soft comet
#

thing is aabb is a 4 digit perfect square where a and b are its digits

#

so we need to find the number

split sail
#

hm

soft comet
#

calculators arent allowed btw

split sail
#

oops

#

i was about to

soft comet
#

yea ik 😭

rancid raven
#

What does this mean

soft comet
#

ignore the GIF part , its the greatest integer function

soft comet
tropic wadi
#

some significant calculation*

soft comet
#

whats the method?

tropic wadi
#

you can pair the a and b things together

soft comet
#

oh i see

tropic wadi
#

so 1100a+11b
then you factor out a 11

#

so 11(100a+b)

soft comet
#

hmmm

#

so it must be a multiple of 11^2?

tropic wadi
soft comet
#

like the whole number

tropic wadi
#

a multiple of 11 and also a square number

soft comet
#

yea

tropic wadi
#

so like 100a+b=11k^2

#

like this

#

so that both 11 makes 11^2

#

but there could be a more efficient method

soft comet
#

maybe

#

most of the questions on this test had a lot of trial and error involved tho so this may be correct

tropic wadi
#

at least with this method you don't have to check all the numbers

soft comet
#

yea

#

ty

#

.close

amber waspBOT
#
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sharp depot
#

In how many ways can 4 boys including John and Matthew, and 4 girls, including Sally, be arranges in a line if:

sharp depot
#

(ii) Girls and bous alternate and John and Sally stay together

amber waspBOT
#

@sharp depot Has your question been resolved?

sharp depot
#

<@&286206848099549185>

abstract seal
#

is 252 the answer?

sharp depot
#

uh im not sure

#

it doenstsay

amber waspBOT
#

@sharp depot Has your question been resolved?

sharp depot
#

<@&286206848099549185>

violet raven
#

for this

#

first we will make 8 spaces

#

and then we will make a block of john and sally

#

This is the first hint

#

@sharp depot

sharp depot
#

sure

#

then iget confused on how to rearrange the other around the block

#

while ensuring girl abnd boys alternate

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#

@sharp depot Has your question been resolved?

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midnight harbor
amber waspBOT
midnight harbor
#

HOw is 81% not right? I'm sick of this problem, please help

pallid canopy
#

,calc (2 * 81 ^ 2 + 50) / (81 * (100 - 81))

grizzled pagodaBOT
#

Result:

8.5588044184535
pallid canopy
#

yea that's not 30

midnight harbor
#

i did 2x^2 + 50/x(100-x) = 30

pallid canopy
#

that's not how calculators work

#

a/bc means a / b * c

#

use helpparens

pallid canopy
midnight harbor
#

idk formula u use

#

,calc (2 * 94 ^ 2 + 50) / (94 * (100 - 94))

grizzled pagodaBOT
#

Result:

31.421985815603
midnight harbor
#

,calc (2 * 93 ^ 2 + 50) / (93 * (100 - 93))

grizzled pagodaBOT
#

Result:

26.648233486943
midnight harbor
#

,calc (2 * 93.9 ^ 2 + 50) / (93.9 * (100 - 93.9))

grizzled pagodaBOT
#

Result:

30.874177272648
midnight harbor
#

,calc (2 * 93.8 ^ 2 + 50) / (93.8 * (100 - 93.8))

grizzled pagodaBOT
#

Result:

30.344040167824
midnight harbor
#

,calc (2 * 93.79 ^ 2 + 50) / (93.79 * (100 - 93.79))

grizzled pagodaBOT
#

Result:

30.291965519296
midnight harbor
#

,calc (2 * 93.78 ^ 2 + 50) / (93.78 * (100 - 93.78))

grizzled pagodaBOT
#

Result:

30.240058315316
midnight harbor
#

,calc (2 * 93.779 ^ 2 + 50) / (93.779 * (100 - 93.779))

grizzled pagodaBOT
#

Result:

30.23487677328
midnight harbor
#

,calc (2 * 93.65 ^ 2 + 50) / (93.65 * (100 - 93.65))

grizzled pagodaBOT
#

Result:

29.580142177903
midnight harbor
#

,calc (2 * 93.68 ^ 2 + 50) / (93.68 * (100 - 93.68))

grizzled pagodaBOT
#

Result:

29.730020862835
midnight harbor
#

,calc (2 * 93.69 ^ 2 + 50) / (93.69 * (100 - 93.69))

grizzled pagodaBOT
#

Result:

29.780297129201
midnight harbor
#

,calc (2 * 93.71 ^ 2 + 50) / (93.71 * (100 - 93.71))

grizzled pagodaBOT
#

Result:

29.88132925056
midnight harbor
#

,calc (2 * 93.73 ^ 2 + 50) / (93.73 * (100 - 93.73))

grizzled pagodaBOT
#

Result:

29.98300592271
midnight harbor
#

,calc (2 * 93.74 ^ 2 + 50) / (93.74 * (100 - 93.74))

grizzled pagodaBOT
#

Result:

30.034087895893
midnight harbor
#

,calc (2 * 94 ^ 2 + 50) / (94 * (100 - 94))

grizzled pagodaBOT
#

Result:

31.421985815603
midnight harbor
#

@pallid canopy so if im rounding its 94%\

#

,calc (2 * 93 ^ 2 + 50) / (93 * (100 - 93))

grizzled pagodaBOT
#

Result:

26.648233486943
midnight harbor
#

,calc (2 * 93.5 ^ 2 + 50) / (93.5 * (100 - 93.5))

grizzled pagodaBOT
#

Result:

28.851501439737
midnight harbor
#

yeah has to be 94

#

.close

amber waspBOT
#
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left spire
#

not sure how to approach both questions

amber waspBOT
mortal dust
#

According to google itself you should use:

Cauchy-Schwarz Inequality

AM-GM Inequality

lusty pine
#

for 7 am-gm should work i think

left spire
#

hmm i think im missing something

#

i got (a+1/a)^2 + (b+1/b)^2 >= 8

#

did i apply AM-GM incorrectly?

shell osprey
#

how did you get >= 8

left spire
#

(a+1/a) / 2 >= 1 => (a+1/a)^2 >= 4

#

did something similar for b and added the 2

shell osprey
#

oh nvm i misunderstood

lusty pine
left spire
#

hmm

lusty pine
#

am i stupid or does the inequality not hold

restive harness
lusty pine
amber waspBOT
#

@left spire Has your question been resolved?

amber waspBOT
#

@left spire Has your question been resolved?

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lilac sky
#

hi

amber waspBOT
lilac sky
#

so in my class we are getting groups of 4 that we will be using for some time and i want to calculate the probability of getting paired with a certain person

#

A for ease of use

#

The groups will have 4 people and there's 26 people in total

#

That's 6 groups with a remainder of 2

#

So 7 groups where 2 of them will have 3 rather than 4

#

Now I could just go 1/7=14.29%

#

but

#

now that the groups arent equally sized, that introduces a whole other can of worms that i dont know how to deal with

#

that's what i need help with

mortal dust
#

its around 16%

#

just cause of the smaller groups, itll be a little bit over 1/7

lusty pine
lilac sky
mortal dust
#

itll just be around 16% im like 90% sure

lilac sky
#

Yes it will obv be a bit less

#

But I want to know how

mortal dust
#

oh wait 2 groups of 3

#

in that case itll be more like 10-11%

#

i assuming there would be 1 group of 2 but that sounds kinda dumb now that i think about it

lusty pine
#

say you are A and the certain person is B
label the groups to be groups are
a,b,c,d,e,f,g where f and g are the 3 groups
try finding the P(A in a)×P(B in a)×ammount of groups of 4+P(A in f)×P(B in f)×ammount of groups of 3

#

im pretty sure

#

wait nk

#

there

#

we multiply by ammount of 4 so we take into consideration goinf into a,b,c,d,e

#

so here, P(A in a) is 4/26, ill let you do the rest

lilac sky
#

Hm

#

P(A in a) = 4/26

#

P(B in a) = 4/26

#

So 5(4/26)(4/26)

#

=80/676

#

=20/169

#

P(A in f)=3/26

#

P(B in f)=3/26

#

So 2(3/26)(3/26)

#

=18/676

#

=9/338

#

So 20/169+9/338

#

180/57122

#

=0.03%

#

Oh wait

#

I multiplied

#

=14.5%

#

Is that right?

#

.close

amber waspBOT
#
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errant vortex
#

can someone explain the difference between or, and because i'm confused in probability when it says or n and what does it want me to do

errant vortex
#

hm so i'm confused

#

so idk how to tell the difference and how to always get the right answer

graceful coral
#

or = either or both sides are true
and = both sides are true

#

false or false = false
false or true = true
true or true = true

false and false = false
false and true = false
true and true = true

errant vortex
#

ohhh okay

little dagger
#

or just understand it with simple english

you have to eat fries or burger

you have to eat fries and bruger

errant vortex
#

ohhh so or limits you to one category

graceful coral
errant vortex
#

okay i think i get it

#

thank you

graceful coral
errant vortex
graceful coral
#

false xor false = false
false xor true = true
true xor true = false

errant vortex
#

huh

#

i haven't learnt that

#

😭

stoic locust
#

[;

graceful coral
#

or means that either side is true (including both being true), xor means that exactly one side is true

errant vortex
#

okay thanks

#

can i close this now

#

.close

amber waspBOT
#
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woven sundial
#

did 1, need help with 2

amber waspBOT
bleak shoal
woven sundial
#

The answer says 2/3a

#

I just have no idea how to get to it

#

PQ is a straight line

#

So it should be PQ= a+2a/2

#

that would be 3a/2

bleak shoal
bleak shoal
woven sundial
#

I mean

#

you can prove that some triangles are similar? maybe

bleak shoal
woven sundial
#

same thing

bleak shoal
#

but do you know some parallel lines ->equal ratio properties?

woven sundial
bleak shoal
woven sundial
bleak shoal
woven sundial
#

Yes

bleak shoal
#

then AD:AB=DE:BC=AE:AC

woven sundial
#

Yeah

#

wait thats what you meant?

bleak shoal
woven sundial
#

Oh

#

Ok lets see

bleak shoal
woven sundial
#

AMD is a triangle

#

lets do it there

bleak shoal
#

👍

woven sundial
#

MP/PA= MQ/QD= AN/ND

#

i think thats what it should be

bleak shoal
woven sundial
bleak shoal
#

notice BM is parallel to AN

woven sundial
#

Right

#

Lets see

#

AN/BM=AP/PM=NP/BP

#

Its the same

#

Exept AN is a

#

and BM is 0.5a

#

Lets see

#

If it helps

bleak shoal
#

wait one sec

#

why AN/ND?

#

did you mean PQ/AD?

woven sundial
#

I forgot this variation

bleak shoal
woven sundial
#

Ok hold on ill write it down rq

bleak shoal
woven sundial
#

i wrote it down but theres only ad that we know

bleak shoal
#

we see that PQ/AD=MP/AM

woven sundial
#

We dont have AP or AM

bleak shoal
woven sundial
#

Oh shit

bleak shoal
#

and AN/BM have a known value: 0.5a/0.25a=2

woven sundial
#

AN is a

#

BM is 0.5a

#

isnt it

bleak shoal
#

but yeah the ratio is stilll 2

woven sundial
#

Oh right

bleak shoal
#

AN/BM=2

woven sundial
#

Yeah

bleak shoal
#

maybe you can try to transform one to the other?

#

hint: write everything as multiples of PM

woven sundial
#

Ok ok

woven sundial
#

i tried

bleak shoal
bleak shoal
woven sundial
woven sundial
#

wdym by that

bleak shoal
#

since AP/PM=2 we have AP is 2PM

woven sundial
#

Arent AP=PM

bleak shoal
#

if AP=PM then AP/PM=1

woven sundial
# bleak shoal 🤔 why is that so?

I had an explanation to 1at was that DM and AM meet at the midpoint M and CN and BN meet as midpoint N and because they intersect, I think it would form a straight line that’s parallels to the base AD

woven sundial
bleak shoal
woven sundial
bleak shoal
#

well how does that give you AP=PM?

#

🤔

woven sundial
#

And Q too

#

because does it just turn into a straight line without them being midpoints

bleak shoal
#

PQ being paralle to AD doesn't tell us a lot

woven sundial
#

yeah

#

But is my explanation correct?

#

its just that P and Q arent midpoints

bleak shoal
#

you want to put PQ parallel to AD into ratio equalities

#

what would imply PQ being parallel to AD?

woven sundial
#

Oh wait

#

that gives us that

#

MQ/QD is 2

bleak shoal
bleak shoal
#

and this indeed proves AD parallel to PQ rigorously

woven sundial
#

Yes

#

We can use MQ/QD is another thales

bleak shoal
# woven sundial Yes

i think your argument for why AP=PM is maybe just getting a lil bit carried away by some wrong intuition

woven sundial
bleak shoal
#

you build intuition through those proofs and example

woven sundial
#

while thats not the case

#

But is PQ really a straight line

bleak shoal
woven sundial
#

I just stated how it could be a staright line

bleak shoal
#

i don't understand what you mean by straight line here

#

u can't have a wiggly line connecting PQ by definition

woven sundial
#

I dont really know the meaning in english

#

but ill find it rq

#

Google translate says it means "Means section"

#

do you know what that is?

bleak shoal
woven sundial
#

midsegment

#

Right

#

I remembered

woven sundial
bleak shoal
woven sundial
bleak shoal
#

PQ is a midsegment of AMD iff P and Q are midpoints

woven sundial
#

Exactly

#

Thats why i was confused when AP/PM was 2

#

that means i also proved 1 incorrectly

#

💀

bleak shoal
#

but you are "extending" this to the intersection of two triangles

#

which doesn't quite work

woven sundial
#

I dont know how to prove that PQ is parallel to AD

bleak shoal
#

this is sort of a scenario where you really have to ask yourself whether the "intuition" you have is correct

bleak shoal
#

with proof

woven sundial
bleak shoal
#

this would imply PQ parallel to AD as you suggested

woven sundial
#

Wait what how

#

Hold on

#

so

bleak shoal
#

ok lemme state it formally

woven sundial
bleak shoal
woven sundial
#

We can try to do thales

#

or similarity

bleak shoal
#

^try and see why

woven sundial
#

and not 1/2

bleak shoal
#

MQ/QD is MC/ND

woven sundial
#

Yes

bleak shoal
#

0.5a/a

woven sundial
#

Right

#

Yes

#

Ok so

#

MP/AP isnt 1/2 tho or am i mistaken

#

Nvm im mistaken

bleak shoal
woven sundial
#

it is 1/2

bleak shoal
#

so they are equal!

woven sundial
#

Yes

#

which proves

#

that PQ parallel to AD

#

Well that makes much more sense now

bleak shoal
#

just to make sure, you know why the equal ratio implies parallel right?

woven sundial
#

1/2 is much easier to work with

bleak shoal
#

ok good!

woven sundial
#

ill use the 1/2

bleak shoal
#

so you see the ratio isn't really 1, but 1/2

woven sundial
bleak shoal
#

which sort of proves that your intuition originally was wrong

bleak shoal
#

its correct

woven sundial
#

Ok ill try to put it in other ratios

bleak shoal
#

we said AP/PM=2

woven sundial
#

see if i can get somethin

bleak shoal
#

but PM/AP=1/2 is still correct

woven sundial
#

yes

bleak shoal
#

(they are not equal but you can do something to the fractions)

woven sundial
#

AM=2PM

#

Or am i dumb

#

MD=2MQ

bleak shoal
woven sundial
#

Right

bleak shoal
woven sundial
#

MQ=2QD

bleak shoal
#

how many PM is AM?

woven sundial
#

I think

#

Or no im wrong

#

it should be

bleak shoal
woven sundial
#

MP is x AP is 2x

bleak shoal
#

hint: AM=AP+PM

woven sundial
#

Holy shit

#

that means'

#

AM=3pm

#

3PM

bleak shoal
#

YES!

woven sundial
#

PQ=3AD?????

woven sundial
#

No wait

woven sundial
bleak shoal
woven sundial
#

Wait hold on let me go back rq

#

Oh its correct

bleak shoal
#

and you are done!

woven sundial
#

it says 2/3 in answers

bleak shoal
#

AD is 2a isnt it?

woven sundial
#

It is

bleak shoal
#

so...

#

what is PQ?

bleak shoal
#

you forgot the a

woven sundial
bleak shoal
#

and AD is 2a

woven sundial
#

PQ/AD is 1/3

#

AD is 2a

#

PQ/2a=1/3

bleak shoal
woven sundial
#

Thats crazy

#

thank you so much

#

I have more problems that idk how to do but woudve helped me for a hour so i wont bother you

bleak shoal
#

no worries you got that PQ is 2a/3 right?

woven sundial
#

Thank you alot

bleak shoal
#

no worries

woven sundial
#

I got 5 more problems

#

Thank you again ill close this channel now

#

.close

amber waspBOT
#
Channel closed

Closed by @woven sundial

Use .reopen if this was a mistake.

#
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high berry
amber waspBOT
high berry
#

idk how to being

#

summation of F_x and summation of F_y = 0?

#

can someone solve it and send me the answer, i know its not allowed, but i just need to see the working of one question, so i can attempt the rest on my own

amber waspBOT
#

@high berry Has your question been resolved?

#
Channel closed

Closed by @high berry

Use .reopen if this was a mistake.

amber waspBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sonic gazelle
#

hi

amber waspBOT
sonic gazelle
#

can someonehelp me

hard monolith
#

Ok.