#help-39

1 messages · Page 292 of 1

rare scaffold
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this isn't topology

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fine, here's a different approach that's actually the same

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determine all functions h that do not satisfy g R h

stoic imp
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how

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@rare scaffold

rare scaffold
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@stoic imp

stoic imp
rare scaffold
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how many functions {...6} -> {...16} are there? ignore R

stoic imp
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16 P 6

rare scaffold
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wait, no

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what about 1,2,3,4,5,6 all map to 12? that's a function you didn't count

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the outputs don't have to be unique

stoic imp
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P is permutation

rare scaffold
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n P k is n!/(n-k)!

stoic imp
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16^6

rare scaffold
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is that a different answer?

stoic imp
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16 possibilities for the first out of 6 spots

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16 possibilities for the second out of 6 spots

rare scaffold
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it's harder to follow if you're spontaneously changing arguments. is 16^6 different from 16 P 6?

rare scaffold
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ok

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now that I'm caught up, yes your new answer makes sense

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the key is that you have 16 choices for each of the 6 entries

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now count the number of those functions that are not related to g

rare scaffold
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it's harder to do the opposite, i.e. count the number of functions that are related to g

rare scaffold
stoic imp
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the image of g is {15,14,13,12,11,10}

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1,2,3,4,5,6,7,8,9,16

stoic imp
rare scaffold
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no, but explain?

stoic imp
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we just need them to share at least one element in their images

rare scaffold
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oh you're doing the opposite lol

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no, you don't want any overlap

stoic imp
rare scaffold
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I never mentioned f

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only g

stoic imp
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a R b iff im a n im b ≠ {}

rare scaffold
rare scaffold
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no, but explain?

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oh you've changed it

stoic imp
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the image of g is {15,14,13,12,11,10}

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1,2,3,4,5,6,7,8,9,16

rare scaffold
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you see how every function h that is not related to g is precisely a function {1,2,3,4,5,6} -> {1,2,3,4,5,6,7,8,9,16}?

stoic imp
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yes, so?

rare scaffold
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this was the intended answer to my first question, X = {1,...,9,16}

stoic imp
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10^6?

rare scaffold
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do you remember X? @stoic imp

stoic imp
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what

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you still talking about topology

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?

rare scaffold
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it's not topology

stoic imp
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is advanced

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I'm new to math

rare scaffold
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only if you think so

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you should try to enjoy finding multiple solutions to the same problem, it's good for you

stoic imp
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I am open to it

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I just said I am a newbie

rare scaffold
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if I thought it wasn't appropriate for a newbie, I wouldn't have mentioned it

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a function h that is not related to g is precisely a function {1,...,6} -> {1,...,9,16}, and the latter space is easier to work with

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amongst these functions, how many are related to f?

stoic imp
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the image of f is {2,4,6,8,10,12}

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2,4,6,8

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4^6

stoic imp
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@rare scaffold

rare scaffold
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@stoic imp

rare scaffold
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this overcounts

stoic imp
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I need more hints

rare scaffold
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what class is this for?

stoic imp
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what am I overcounting

stoic imp
rare scaffold
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suppose 17 people run a race, including a guy named Kevin. how many top-five placements are there, featuring Kevin?

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have you seen a counting problem like this before?

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in case it's unclear, I want the number of top-5 placements in which Kevin is present

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a,b,Kevin,c,d

stoic imp
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( 17 P 1 ) x 16 x 15 x 14 x 13

rare scaffold
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17P1 is just 17, and you deleted that message last time

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have you or have you not seen a question like this before?

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<~> do you know this counting trick?

stoic imp
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I guess i have, is just that counting is hard

rare scaffold
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counting is hard, genuinely

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ok

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so I actually alluded to this before, sometimes it's easier to count the opposite thing

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every top-5 configuration falls into one of two sets: that which sees K, and that which does not

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so to count all of the placements with K, we count every placement, then subtract the ones without K

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that's (17 P 5) - (16 P 5)

rare scaffold
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a similar idea applies to the question of how many functions are related to f

stoic imp
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16^6 - 10^6

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the image of f is {2,4,6,8,10,12}

rare scaffold
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no, only because remember we want the total number of functions related to f that are not related to g

stoic imp
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the image of g is {15,14,13,12,11,10}

rare scaffold
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every function that does this is obviously not related to g, so we restrict our search to functions {1,...,6} -> {1,...,9,16} that are related to f

stoic imp
rare scaffold
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mmmm so you did know the trick after all

stoic imp
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I am bad at counting

rare scaffold
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unless if you just came up with that name

stoic imp
rare scaffold
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it really helps to see other examples of counting problems you've done in class or on other assignments, especially those you've actually solved yourself

stoic imp
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help

rare scaffold
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I have a question

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when do you normally ask for help on a math assignment?

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how much time do you allow yourself to work things out on your own?

stoic imp
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is hard to know if what I am doing is correct

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teacher never gives us solutions

rare scaffold
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I sympathize with this, especially for combinatorics, but that wasn't my question

stoic imp
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well I usually try my hardest and then I ask for help

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like everyone, correct?

rare scaffold
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ok, sure, just checking

stoic imp
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checking what

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sorry for not being a combinatorics pro

rare scaffold
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I thought you might tend to ask questions the moment you're uncertain about how to proceed, i.e. without trying random stuff first, that's all

rare scaffold
stoic imp
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it might seem easy to you, but sometimes things go south in the middle of the exercise

rare scaffold
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no I get it, and no it's not easy for nearly anyone when they first start

stoic imp
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using this compliment principle should be your last resource, in class teacher said it's useful when what you are trying to count is very hard

rare scaffold
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that's weird to say. counting complements can be really useful

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it shouldn't be treated as a last resort lol

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actually it's good because you immediately consider the complement and pick which one seems easier at the time

stoic imp
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she didn't said it should be the last resource, that's on me, but she did said the last sentence

rare scaffold
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yes

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so to recap

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every function h : {1,...,6} -> {1,...,16} that is related to f and not g is, first, a function that is not related to g

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so we can count amongst the collection of functions that are not related to g, how many are related to f

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since a function not related to g is just a function -> {1,...,9,16}, we want the number of functions {1,...,6} -> {1,...,9,16} that are related to f

rare scaffold
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do you see how you'd get to this point on your own?

pearl pondBOT
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@stoic imp Has your question been resolved?

rare scaffold
stoic imp
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the image of f is {2,4,6,8,10,12}

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2,4,6,8

stoic imp
rare scaffold
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not necessarily

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h(1) = 1, h(else) = 2

stoic imp
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one of the six outputs i mean

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@rare scaffold

rare scaffold
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@stoic imp

stoic imp
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4 x 10^5

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@rare scaffold

rare scaffold
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@stoic imp

stoic imp
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can I get some help

rare scaffold
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I'm literally still here

stoic imp
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help

rare scaffold
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I'm... literally still here

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thinking

stoic imp
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10^6 - 10 P 4

rare scaffold
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what is this

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are you changing your answer again?

stoic imp
rare scaffold
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well I was trying to think of a reason why it's wrong

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and I think it has something to do with your designation of a "first" input that's required to map to one of the four options

stoic imp
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how to correct it

rare scaffold
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explain your other answer

stoic imp
rare scaffold
stoic imp
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also, please ping me

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i dont see the messages otherwise

stoic imp
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@rare scaffold

rare scaffold
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@stoic imp second ping

stoic imp
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10 possibilities for each output

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since a function not related to g is just a function -> {1,...,9,16}, we want the number of functions {1,...,6} -> {1,...,9,16} that are related to f

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from 1 to 16 theres 10 numbers

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10 possibilities for each of the 1 to 6 inputs

rare scaffold
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what else?

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@stoic imp this is obviously not a complete argument

stoic imp
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then we subtract the ways that out of the 10 possible outputs we pick one of the 4

rare scaffold
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what is the quantity you're subtracting?

stoic imp
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10 p 4

rare scaffold
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what does it represent?

stoic imp
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2 4 6 8

rare scaffold
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these are the number of functions that do what, exactly?

stoic imp
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the image of f is {2,4,6,8,10,12}

stoic imp
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aka when they are related

rare scaffold
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that's not what you want

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if X is a finite set and A is a subset of X, we have |A| = |X| - |X-A|

stoic imp
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i want when they have empty intersecgion?

rare scaffold
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in this case, X is the collection of functions {...6} -> {...9, 16}, and A is the collection of functions that are essentially related to f

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characterize a function in X-A

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@stoic imp still here

stoic imp
rare scaffold
stoic imp
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"characterize f x a"

rare scaffold
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the whole point is that #{functions related to f} = #{all functions} - #{functions not related to f}

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@stoic imp do you really just lock your phone every time a message is sent to you or something lol

pearl pondBOT
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@stoic imp Has your question been resolved?

pearl pondBOT
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@stoic imp Has your question been resolved?

stoic imp
stoic imp
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I am back and reloaded

stoic imp
stoic imp
stoic imp
stoic imp
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.close

pearl pondBOT
#
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pearl pondBOT
#
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exotic gale
#

In base $b$, we have $r = 0.\overline{57}_b$ and $3r = 1.\overline{06}_b.$ What is the value of $r$ in base ten? Express your answer as a common fraction.

jolly parrotBOT
exotic gale
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i think we divde 3r by r or do we subtract 3r by r to get 2r and then do something with that?

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1.06 repeating over 3 equals 0.57 repeating

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base b

slender viper
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Multiple approaches here

  1. Write r in terms of b
  2. Trying to do arithmetic in base b (pretty much equivalent to approach 1, but possibly requires more experience to do properly)
exotic gale
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doesn't the question give that already?

slender viper
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Think of something like this, but try simplifying it

exotic gale
slender viper
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Also there's extra terms to deal with on account of r having a repeating base-b expansion

pearl pondBOT
#

@exotic gale Has your question been resolved?

pearl pondBOT
#
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#
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grand sun
#

AEDC is a square with side 17. AB=8, BC=15. Find FD/AG. Can someone give me a hint on this problem

glossy blade
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Gimme a min

ancient sapphire
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Use your trig functions

pearl pondBOT
# glossy blade Gimme a min

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

iron basin
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?????

glossy blade
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Wattahel?

grand sun
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is there a solution without trig

ancient sapphire
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I don't think so

glossy blade
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Similar triangles

grand sun
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i did it with similar triangles but the solution was too long

glossy blade
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Oh ok

grand sun
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in which triangles can we use trig

glossy blade
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Drop perpendiculars and apply

ancient sapphire
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If you know 1 side of a triangle and an angle you can use trig functions to figure out your missing pieces

grand sun
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i think if we draw a diagonal AD then we can try to prove that the 2 triangles that are formed are congruent

iron basin
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similar

grand sun
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yes, but i got answer 1 after manually calculating the side FD

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so they are congruent

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but we gotta prove it

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.close

pearl pondBOT
#
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pearl pondBOT
#
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crimson nebula
#

Can somebody explain the proof please

crimson nebula
#

Be precise

glass meadow
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I wouldn't say that's a proof, it's a definition

crimson nebula
#

I doubt too .
But ..

neon fossil
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It says that its assumed that xn doesn't converge to x and so we are basically just using the definition of convergence to prove the second sentence...?

hazy pilot
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what part doesn't make sense?

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the goal is to prove the statements are equivalent

glass meadow
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A sequence (x_n) converges to x if, for all epsilon > 0, there exists a natural N such that for all n >= N, |x_n-x| < epsilon

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That's the definition of "sequence X converges to x"

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The negation is that there exists an epsilon > 0 such that for any natural N, there exists n >= N such that |x_n-x| >= epsilon

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(if you've done a bit of logic it should be clear how that's the negation)

crimson nebula
# hazy pilot what part doesn't make sense?

The second line ,
"That is , for each k.."

Does it mean , that for every natural number , we can't guarantee that this inequality holds.while It may hold for some natural numbers ...

glass meadow
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Yes

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Well, not quite, it's guaranteed it does not hold for at least one number

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|x_n-x| >= epsilon is true for at least one n >= k

crimson nebula
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Ok thanks

crimson nebula
glass meadow
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No, your statement is like "we don't know"

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The correct statement is "that sequence definitely does not converge (to x)"

crimson nebula
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"for every natural number k , there's at least one n≥k , that holds |xn-x| ≥ ε

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?

glass meadow
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"such that |xn-x| ≥ ε holds", yes

crimson nebula
#

Okkhhayy

glass meadow
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We say "for all k in N, there exists n >= k (such that) ..."

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,, \forall k \in N (\exists n \geq k ...)

jolly parrotBOT
crimson nebula
#

I dont know , for past few days , it takes me a lot of time , to figure out statments

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I was stuck on this "proof" for 2 days

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Trying to make sense and logical flow

glass meadow
#

Maybe find a course on first-order logic

crimson nebula
#

It seems like , real Analysis is like a task for me now ,not the enjoyment of math

crimson nebula
glass meadow
#

Basically logic with quantifiers ("for all" and "there exists")

crimson nebula
#

Do you have some recommendations

glass meadow
crimson nebula
#

Ok thank you

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Maybe I will see on you tube

glass meadow
#

The convergence statement written symbolically looks like this:

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,, \forall \varepsilon > 0 \left(\exists N \in \mathbb{N} \left(\forall n \in \mathbb{N} \left(n \geq N \implies |x_n - x| < \varepsilon \right)\right)\right)

crimson nebula
#

Ah yes the definition of converges

jolly parrotBOT
glass meadow
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That's what first-order logic looks like, and it makes negating statements very easy without having to think about what every word means

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Of course, words are still useful, nobody writes everything in logic symbols, but for precise semantics it can help

crimson nebula
#

Automata is there

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Too

glass meadow
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You don't need that much to better understand general mathematical statements

crimson nebula
glass meadow
#

That seems very in depth

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But if it interests you, go for it

crimson nebula
#

My primary aim is real Analysis

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Only want to do what's relevant but in detail

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Can you suggest which lectures should I watch

glass meadow
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Again I'm not the one to ask for recommendations but feel free to drop a message in #book-recommendations , even if you're looking for video content

crimson nebula
#

Thank u

#

.close

pearl pondBOT
#
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pearl pondBOT
#
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eager jewel
#

Let Γ denote a curve y = y(x) which is in the first quadrant and let the point (1, 0) lie on it. Let the tangent to Γ at a point P intersect the y-axis at YP. If PYP has length 1 for each point P on Γ, then which of the
following options is/are correct ?

eager jewel
eager jewel
#

i wrote the tangent as y=x(dy/dx) + Yp

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and i dont know how to use that length = 1 condition

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i thought ill take a point (x,y) on the curve and do x^2+(y-yp)^2 = 1

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oh bruh

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i can use y-yp = x(dy/dx) 😭

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ok but then i get the condition

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dy/dx = +- sqrt((1-x^2)/x^2)

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how to choose between + or -

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or can we take both?

calm wing
#

Gamma is in the first quadrant

eager jewel
#

yeah

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so?

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cant slope of tangent still be +ve or -ve?

calm wing
#

well consider what happens as you approach (1,0)

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you can't approach it from below smoothly (gamma is in the first quadrant) so you have to approach it from above

feral olive
#

if the tangent line is always 1 you can use the distance formula for any point on the function and let that be true for all x

eager jewel
feral olive
#

you are able to find f'(x) using that

eager jewel
eager jewel
calm wing
eager jewel
#

oh shit

#

1 sec then

calm wing
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hmm

calm wing
#

so i assume we shouldn't consider points for x > 1

eager jewel
#

oh ok

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but still cant the slope take both values?

calm wing
#

well now that we are restricted to [0,1] basically, no, it can't

eager jewel
feral olive
#

use your formula for the tangent line and combine it with the distance formula

clear shore
#

why this problem looks kinda like the one in my book lmao

eager jewel
grave mirage
feral olive
#

i got one of the options

clear shore
eager jewel
feral olive
eager jewel
clear shore
#

Yeah same

eager jewel
#

B is wrong

clear shore
#

really?

feral olive
#

how though

eager jewel
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because of the slope sign bro

#

ive been tryna tell uthat from the past msgs..

clear shore
#

istg it's B

eager jewel
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its NOT

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can we please move on

clear shore
#

Tho I don't know what you talk about

#

Since I didn't go that route

eager jewel
#

@calm wing whered u go 😭

feral olive
#

$f(x)-y_0=f'(x)x$

jolly parrotBOT
#

ImOakley

grave mirage
#

It's prolly D and whatever's the solution for D

eager jewel
feral olive
#

$1=\sqrt{(f(x)-y_0)^2+x^2}$

jolly parrotBOT
#

ImOakley

grave mirage
eager jewel
feral olive
#

$1=\sqrt{(f(x)-f(x)+f'(x)x)^2+x^2}$

jolly parrotBOT
#

ImOakley

grave mirage
feral olive
#

$1=\sqrt{(f'(x)x)^2+x^2}$

jolly parrotBOT
#

ImOakley

grave mirage
eager jewel
grave mirage
#

See y is either only decreasing

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Or only increasing

eager jewel
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uhh why

grave mirage
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Take the 1st case

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dy/dx = root(1-x^2)/x

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root is always positive

eager jewel
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yeah

grave mirage
#

x is always positive as it is in the first quadrant

feral olive
#

hang on

grave mirage
#

so dy/dx is always positive

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It can't be positive

feral olive
#

@eager jewel is this select more than 1 answer

grave mirage
feral olive
#

thats why b wasnt right

grave mirage
feral olive
#

because as apoorv said its either only increasing or only decreasing

grave mirage
#

Which is the negative sign

eager jewel
#

okay now i get it

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thanks a lot

grave mirage
#

Welcome

eager jewel
#

.close

pearl pondBOT
#
Channel closed

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Use .reopen if this was a mistake.

eager jewel
#

ty @feral olive and @calm wing

pearl pondBOT
#
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crimson nebula
#

Suppose I want to prove that this sequence is divergent.

Am i allowed to use such language .
"It can easily be seen that..."

plush bramble
#

sure if it follows from theorem 3.4.5

crimson nebula
#

.close

pearl pondBOT
#
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pearl pondBOT
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sharp smelt
pearl pondBOT
sharp smelt
#

Let $A$ be generated by $(a_1,a_2 \dots , a_n)$, each being distinct and no power of any $a_i$ is any power of $a_j$.
This is as if it were then the group would be generated by a subset of $(a_1,\dots,a_n)$
Then $A={a_1^{k_1} \dots a^{k_n} \mid k_i \in \mathbb{Z} , 1≤i≤n }$. Let $H≤A$. Then every element of $H$ must be of the form $a_i^{h_i} \dots a_k^{h_l}$. This being a representative element of $H$, $h_j$ are fixed . Suppose an element that's not of this form were in $H$, call it $t$. Then $a_1^{b_1} \dots a_{I}^{b_{i}} \dots a_{l}^{b_l} \dots a_n^{b_n}=t$.
We now multiply across by $a_i^{-h_i} \dots a_{l}^{-h_l}$.
Then $a_1^{b_1} \dots a_{i}^{-h_i+b_{i}} a_{l}^{-b_{l}+h_l} \dots a_{n}^{b_n} \in H$.
Then $a_1^{b_1} \dots a_n^{b_n} \in H$.
But this is a contradiction to our assumption that $H$ is of the form $a_i^{h_i} \dots a_l^{h_l}$ for some fixed $i$ to $l$. |

we're done.

I feel there's something wrong with this, but I can't quite put my finger on it.

jolly parrotBOT
sharp smelt
#

I see the error now

#

Is this salvagable though

#

<@&268886789983436800>

#

I did think of induction, and my book verifies that one way to prove this is indeed induction

brisk scarab
#

Does n-generated just mean "can be generated by a set of size n"

sharp smelt
#

1≤i≤n

sharp smelt
brisk scarab
#

how have you gotten existence of such a_i

#

like

#

even in Z if we have any two generators a and b (e.g. 2 and 3) then a*b is a "power" (where a*b is additive notation) of both

#

unless I'm being slow

sharp smelt
#

hmm?

#

I mean $a_j^{k}≠a_{i}^{l}$for any k,l

jolly parrotBOT
brisk scarab
#

yes, but in multiplicative notation (for the group Z with addition, which is confusing and alas nothing can be done about it) then $a_j^{a_i}=a_i^{a_j}$

jolly parrotBOT
#

Edward II

brisk scarab
#

in the usual notation for integers, both are equal to $a_i\times a_j$

jolly parrotBOT
#

Edward II

sharp smelt
#

then the group can be generated by 1 element , right

brisk scarab
#

yeah sure; are you also taking n minimal then

#

I suppose you can with no issues but then the n in your proof may not be the same n as in the question technically I suppose you can with no issues but then the n in your proof may not be the same n as in the question technically (i.e. where you're being asked to prove the generalisation of "a subgroup of the 2-generated group Z is also 2-generated", and your proof would say "well actually Z is 1-generated, so it's subgroups are 1-generated, which means they're 2-generated"

sharp smelt
#

lemme just verufy

#

right, so I was using a wrong definition 😭

brisk scarab
#

what you sent has nothing to do with being n-generated though

sharp smelt
#

oh , right I just need to show if $A$ has a generating set, then so does any of its subgroups

#

right

jolly parrotBOT
rustic gate
#

every group has a generating set

#

what does your book define n-generated to mean

sharp smelt
#

finite generating set of smaller size

#

I'm using this defn

rustic gate
#

? that's not a definition

#

what is the definition of n-generated in your book

sharp smelt
#

The problem with this defn is then {e} is not n-generated is it

rustic gate
#

what the blud

sharp smelt
#

?

rustic gate
#

they probably don't mean for X to be a set then monkey

rustic gate
#

they probably mean a multiset

sharp smelt
#

I see, that just makes stuff so much worse

rustic gate
#

no it makes it better

sharp smelt
#

how so

#

allows induction with ease , yes

rustic gate
#

because now n-generation just means surjection Z^n -> A

sharp smelt
#

I dont' quite flllow

rustic gate
#

well if you have a generating set g1, ..., gn allowing duplicates, then you get a map Z^n -> A which takes (0, ..., 1, ... 0) -> gi

#

where the 1 is in the ith spot

#

the map is surjective because the set generates

sharp smelt
#

I see

#

that makes sense

#

Okay, I think I'll just come back to this tomorrow 🥀 , not clicking

pearl pondBOT
#

@sharp smelt Has your question been resolved?

pearl pondBOT
#
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cedar depot
pearl pondBOT
cedar depot
#

i found that f(1) f(2) make a series as 1 , 2 , 4 , 7 and so on

#

i tried to find f100 by this but its getting complicated and i wasnt able to find the summation of that series

steep saddle
#

looks familiar Aware

#

what if you subtract 1 from the series

#

is this series a well known sequence

#

well i mean that as in

#

it may have a formula already

cedar depot
#

formula for a random aah series would be wild

#

i think we will have to find it]

steep saddle
#

well

#

you would get 0 1 3 6 10 ... no?

viscid shale
#

If you consider how the function is constructed its pretty obvious what the series is

steep saddle
#

aside from the 0 it's the triangle numbers

steep saddle
cedar depot
midnight haven
viscid shale
#

Lets assume we want to know the value of f(5) without prior knowledge

cedar depot
#

oh.

steep saddle
#

A triangular number or triangle number counts objects arranged in an equilateral triangle. Triangular numbers are a type of figurate number, other examples being square numbers and cube numbers. The nth triangular number is the number of dots in the triangular arrangement with n dots on each side, and is equal to the sum of the n natural numbers...

cedar depot
viscid shale
#

⁨⁨```
f(5) = 5 + f(4)
>f(4) = 4 + f(3)
f(5) = 5 + 4 + f(3)
>f(3) = 3 + f(2)
f(5) = 5 + 4 + 3 + f(2)
>f(2) = 2 + f(1) = 2 + 1
f(5) = 5 + 4 + 3 + 2 + 1

#

mb, im used to the tex markdown, lmao

midnight haven
#

<@&268886789983436800>

viscid shale
#

<@&268886789983436800>

midnight haven
#

sniped

viscid shale
#

thanks

cedar depot
#

so i got it

viscid shale
#

If you want to know the value of f(X), then it will just be ⁨X + (X-1) + (X-2) ... 2 + 1

viscid shale
#

Which is a pretty well known series, as already has been stated

cedar depot
#

reals

cedar depot
#

its a bit hard to notice the patterns like this

#

can yall help me or give tips on the patterns

viscid shale
#

Some of them you can actually construct on your own

#

Others just come from practice/prior knowledge

steep saddle
cedar depot
#

i had the idea of writing x = f(x) - f(x-1)

#

and adding all of it

#

this gets the ans but there seem to be more ways to do this

viscid shale
#

That requires you to know f(x) and f(x-1), so you probably cant do much about it as is.

cedar depot
#

we can put x from 0 to 100

#

and we have a way to find f(-1) too by the relation thats how i got it like rn

#

does this not work?

viscid shale
#

Like, yes, you can do so, but that would take significantly more time

cedar depot
#

nono i mean

#

just add all the values

viscid shale
#

Precisely, if you want to add all the values from 0 to 100

#

You first have to compute them individually

cedar depot
#

f (x) - f(x-1) summation till 100 will cancel all the terms ecet f100 - f-1

viscid shale
#

You still dont know what f(100) is in that case

cedar depot
#

we have 1 + 2 + 3 ... 100

#

this is n(n+!)/2

#

and in rhs we will have f(100) - f(-1)

#

if we put x as 0 in the eq we get f(-1) is -1

#

sorry its 1 mb

viscid shale
#

ah, i see your idea

cedar depot
#

so 5050 +1

viscid shale
#

Yea, ig you can do that

cedar depot
#

nice

viscid shale
#

Really elaborated compared to just replacing a few values and noticing its 1+2+3...(n-1)+n, but it works

weary ferry
#

I can’t find the channel where I needed the help, as it put me in the discussion one after it closed the channel

pearl pondBOT
#

@cedar depot Has your question been resolved?

pearl pondBOT
#
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jovial harbor
pearl pondBOT
jovial harbor
#

How to do with substitution

#

Ignore the integration by parts part

mortal seal
#

u=sqrt(x-1)

steep saddle
mortal seal
#

Yeah probably works as well

jovial harbor
#

Yeah I was trying with u=x-1

#

then x=u+1

#

du=dx

#

so I get (u+1)(sqrt(u))

mortal seal
#

Yup

jovial harbor
#

hm

#

brb

#

oh this is easy

#

:3

mortal seal
#

!done

pearl pondBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

jovial harbor
#

nah

#

I got more

#

just grabbing more paper

#

can we do 8?

#

ah well I gtg

#

so Imma close

#

.close

pearl pondBOT
#
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pearl pondBOT
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random flower
#

Hi there, i am working on this question "The points (–2, 4, 5), (4, 5, –3), and (1, –1, 6) are three of four vertices of parallelogram ABCD. Explain why there are three possibilities for the location of the fourth vertex and find the three points. " I wrote that 3 possible points exist, as there could be a parallelogram in each plane

random flower
#

however, i am not sure if this is correct, as when i graph the points in each plane in desmos, the XZ plane does not look like a proper parallelogram

#

I am having similar trouble with a question giving the 3 points of a triangle and asking for it's shape

#

<@&286206848099549185>

pearl pondBOT
#

@random flower Has your question been resolved?

random flower
#

.close

pearl pondBOT
#
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pearl pondBOT
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pine jacinth
#

Heres an equation that repreents the amount of bacterias in function of the time past in minutes : N(t) = 10(2)^(t/40). Express by an equation the time in function of the amount of bacterias.

heavy onyx
#

find the inverse function

pine jacinth
#

ahh ok ty

#

.close

pearl pondBOT
#
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bleak sonnet
#

HEY EVERYONEEE!!!!!!

#

MY NAME IS HEAVEN

#

IM SO GLAD TO BE HERE

#

I HAVE A SERVER TOO!!!

#

Its for those who wanna make music but dont kno where to start

heavy onyx
pearl pondBOT
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hazy escarp
#

Hey

pearl pondBOT
hazy escarp
#

Can someone explain what a fixed vector is to me rq

#

Like how it works

cinder flower
#

fixed vector?

hazy escarp
#

Let’s say I have an unknown which is point m and I wanna get rid of it in these vectors

sharp vigil
#

can you show the context in which you saw that phrase?

hazy escarp
#

Yes

hazy escarp
#

But he mentioned it in class and my exam is soon

#

It’s like in 2 hours

#

So let’s say point M is any point

#

And I wanna remove it from

#

Let’s say I have

#

Vectors MB+MA+MC

#

I wanna remove m

#

To make it a fix vector

#

What do I do

pearl pondBOT
#

@hazy escarp Has your question been resolved?

hazy escarp
#

Okay I have another question about function

#

When I see a function and I solve it to find the image (y)

#

Let’s say I see the sign >< (alligator)

#

Do I solve it and take everything to the left making it 0 and solve it

#

Or do I just solve for x

#

And do I do a sign table or an interval

#

Or not and how do I know

#

.close

pearl pondBOT
#
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pearl pondBOT
#
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cedar depot
pearl pondBOT
cedar depot
#

i tried taking y = 1.y

#

y = 1/x

#

i found the value of f(1) = 3

clear shore
#

what you did

#

exactly

cedar depot
#

so first i take x = y = 1

#

from this we get a quadratic in f(1)

#

for which the values of f(1) i get as 3 and -2

#

now i put y = 1/x

#

so f(x).f(1/x) = f(1) +2(1/x + x +1)

#

but at this point im stuck

#

i tried doing x = 1/x

clear shore
#

then why did you reject -2

#

try x=x and y=1

cedar depot
#

that was a silly mistake

#

it said from r +

#

so ithought i wont give -ve mn

#

mb

cedar depot
#

oh what

#

i got it

#

but im getting 2 diff functions for the diff values of f(1)

clear shore
#

yeah I think there is a way to reject one of them

#

I haven't figured it out tho

#

Gimme a min

cedar depot
#

they took both values and both of them are the ans

#

its an example problem, in ques they prolly say f(1) >0 or sum

#

for a single value

#

tysm for the help i got it

clear shore
#

I guess?

cedar depot
#

can u like gimme a few tips

#

to know what to put

clear shore
#

I'm deadass stupid at function equation so I don't have any tips 😭

#

sorry

cedar depot
#

u gor it in a single step tho-

cedar depot
clear shore
#

lucky guess

cedar depot
#

so thank you

clear shore
#

np

cedar depot
#

advanced gambling right here

#

aight then

#

,close

#

.close

pearl pondBOT
#
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pearl pondBOT
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sharp smelt
pearl pondBOT
sharp smelt
#

so $p(x) \to p(x) + ((f(x))$ right

jolly parrotBOT
feral sedge
#

Yeah

#

~~\mapsto but yeah ~~

sharp smelt
#

((f(x)) is a set, so all elements are of the form p(x)+((f(x))

feral sedge
#

Yeah

sharp smelt
#

I suppose (f(x)) could absorb some part of p(x) but still

desert wagon
feral sedge
#

Yeah this is going to act like reduction modulo f(x)

sharp smelt
#

ah, lemme work a bit then

sharp smelt
jolly parrotBOT
sharp smelt
#

I have a class now, have to go :(

#

sorry

#

lost track of time

#

.close

pearl pondBOT
#
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feral sedge
#

no worries

pearl pondBOT
#
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sharp smelt
#

That's literally it

pearl pondBOT
sharp smelt
#

.close

pearl pondBOT
#
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tropic saddle
#

that what is a homomorphism

#

and how does that give you the answer

sharp smelt
#

anyways class now

tropic saddle
#

sure. and?

#

the degree condition is the interesting part

pearl pondBOT
#
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sterile crypt
#

went on chatgpt and it told me that the entire rombous does not fit within each sector (DAB and DCB)

solar ember
#

Is this an igcse question?

sterile crypt
#

school resource question

#

not sure

#

im in a 1st year a level

solar ember
#

I did this exact question 8 years ago haha

sterile crypt
#

lol what a coincedence

solar ember
#

You have to use the sector area formula: $Area = \frac{1}{2}r^2\theta$

jolly parrotBOT
solar ember
#

So $$Area_{sector} = \frac{1}{2}(4^2)\left(\frac{2\pi}{3}\right) = \frac{1}{2}(16)\left(\frac{2\pi}{3}\right) = \frac{16\pi}{3}$$ You got the correct are for the rhombus

jolly parrotBOT
unborn abyss
#

that's not a circle it's an ellipse right?

solar ember
#

No, it is circular

sterile crypt
#

my question was

#

is the rombous a part of the sector

#

and if so we should do sector - rombous

#

am i correct

#

and if not why

solar ember
#

yes, to get the segment area

sterile crypt
#

okay

#

intersting

#

gpt was lying to me ig

#

ty

#

i was full tweaking for 4 hrs abt this

solar ember
#

lol

#

don't use AI

sterile crypt
#

not even the mathgpt one

#

like the ones developed for math

solar ember
#

Can you solve it on your own now?

sterile crypt
#

yes

#

thanks

#

.close

pearl pondBOT
#
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coral pecan
#

I do not understand vectors and need help solving this

dire tapir
coral pecan
#

-4a+3b+2a+b

coral pecan
#

But when they ask a mid point

#

Like where 2 lines intersect

dire tapir
coral pecan
#

OM would be some portion of OA

#

So OM is x of OA

dire tapir
#

Close, it's a half of OA because M is the midpoint so it means OM and MA are equal distance

dire tapir
#

yeah

coral pecan
#

How could I miss that 🤦‍♀️

#

🥲

dire tapir
coral pecan
#

So ratio is 1:1 ya ?

dire tapir
#

basically

coral pecan
#

hm

#

You there @dire tapir

dire tapir
#

yeah

#

I was waiting for you to message

#

lol

coral pecan
#

Ok so

coral pecan
dire tapir
coral pecan
#

Ok next

#

To find

#

Wait

#

The line OA will be 2a?

dire tapir
#

yeah

coral pecan
#

AN=-2a+b

#

Is this correct ?

dire tapir
#

yes

coral pecan
#

What does vector terms mean 🥲

dire tapir
coral pecan
#

a and b in terms of vector

karmic flower
#

use section formula for vectors?

dire tapir
dire tapir
coral pecan
coral pecan
dire tapir
dire tapir
coral pecan
#

What's the formula

karmic flower
dire tapir
# coral pecan Oh

I just wanna go through it rather than using the formula, so you understand it

karmic flower
#

The one used in coordinate geometry

dire tapir
coral pecan
karmic flower
#

its applicable here as well as in complex numbers

dire tapir
karmic flower
coral pecan
#

Yes I never learnt this formula

#

I think it's better if I go step by step or I'll probably make some mistakes

dire tapir
#

It'll help you understand what's going on if you do step by step

#

but using the formula can be useful for saving time

coral pecan
#

I don't even understand the formula 🥲

#

Guys sorry I'm really frustrating to teach maths to

dire tapir
#

nah

#

There have been worse helpees who were rude, stubborn, etc

coral pecan
#

But i don't think sector formula vector is in gcse

dire tapir
#

no it isn't

#

maybe your teacher might tell it, idk

#

mine didn't

karmic flower
#

do you need help with 2nd part of the problem?

coral pecan
coral pecan
dire tapir
coral pecan
#

Yes that's what I'm also saying

#

So would they like reduce marks if I use section vector formula ?

dire tapir
#

anyways i'll let @karmic flower take over, i have to go

dire tapir
coral pecan
#

@karmic flower your still here right ?

karmic flower
#

Yes im thinking of how would I solve it without using the above result

#

ts is tuff without it. im gonna try again after a while. Sorry man. im not getting it rn

pearl pondBOT
#

@coral pecan Has your question been resolved?

karmic flower
#

using the above result

#

still this was the method I originally had in mind

coral pecan
karmic flower
# coral pecan Using the formula ?

Yeah. I expressed P two times assuming lambda and nu as ratios in which the lines are divided. then compared both equation and coefficient of a and b. It gave two equations. Solving them I got value of lambda and nu. Plug them into P to find its position vector wrt O. Now you can find the required ratio

pearl pondBOT
#

@coral pecan Has your question been resolved?

coral pecan
karmic flower
pearl pondBOT
#

@coral pecan Has your question been resolved?

pearl pondBOT
#
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#
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ebon basin
#

help how to integrate tanxsinxdx?

pearl pondBOT
toxic lichen
#

$\int \tan(x) \sin(x) \dd{x}$

jolly parrotBOT
toxic lichen
#

this?

ebon basin
#

yes

toxic lichen
#

ok, progress so far?

ebon basin
#

i managed to recall the chain rule. i dont know how to use it tho

toxic lichen
#

the chain rule?

#

...what do you mean

ebon basin
#

idk the thing where you go d/dy*dy/dx

#

atleast that what i think that is

toxic lichen
#

that's for differentiation...

ebon basin
#

or was i supposed to make it into sin2x/cosx

toxic lichen
#

kinda useless for this integration question

ebon basin
#

sin^2x/cosx

toxic lichen
#

sin2x
do you mean sin^2(x) or do you mean sin(2x)?

#

anyway

#

writing the stuff inside the integral as sin^2(x)/cos(x) and then (1 - cos^2(x))/cos(x) is the way to go imo

ebon basin
hybrid ivy
#

you can probably split that fraction you got into two fractions

toxic lichen
#

you'll need to either know or rederive the integral of sec(x) dx

ebon basin
#

oh then i can split it into two integrals sum

#

how do i integrate sec x

#

isnt it tan x

west sail
#

do you have access to a common integral table?

ebon basin
#

no i dont have one

#

wait lemme look it up

karmic flower
#

Convert into sin and cos function. then cosx=t

rustic atlas
#

Alternatively subbing u=sint works

ebon basin
#

havent learnt u sub still

#

but i can just integrate in terms of cosx=t?

karmic flower
#

you know the result for integrating √a^2-x^2 dx. That's be useful later on

toxic lichen
#

$\int \frac{\dd{x}}{\cos(x)} = \ln\absv{\sec(x) + \tan(x)} + C$

jolly parrotBOT
ebon basin
toxic lichen
#

int sec**^2**(x) = tan(x) is what you were thinking of earlier

ebon basin
#

i dont think writing it as (sinx)^-1 and derivation wont work

#

or should i just memorize

toxic lichen
#

if you don't have access to u-sub then you don't have access to any method to rederive those integrals im afraid

ebon basin
#

but ok i got it!

west sail
#

...lol?

ebon basin
#

thank you for your help

karmic flower
ebon basin
#

yea

karmic flower
#

maybe

ebon basin
#

but memorization is just for the weak

#

i derive it because im too lazy to bother otherwise

#

thank you once again for help👍

#

.close

pearl pondBOT
#
Channel closed

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karmic flower
#

Proof for int secx dx

toxic lichen
#

op doesnt have access to substitution

karmic flower
#

that's sad:( is there any other way then

pearl pondBOT
#
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pearl pondBOT
coral pecan
#

What is lambda and nu

sharp vigil
#

lambda and nu are just greek letters

#

they can be variable names like any other letter

toxic lichen
#

btw general tip for math, learn the greek alphabet

glacial bluff
#

here is a picture of the Greek alphabet that I can find for OP.

toxic lichen
#

it's even shorter than the english alphabet

west sail
#

are my eyes deceiving me or are there two forms for lowercase sigma?

#

oh word-final position sigma, okay. interesting.

pearl pondBOT
#

@coral pecan Has your question been resolved?

coral pecan
#

What would learn these be useful for

west sail
#

a lot of variables in math are expressed in Greek letters.

#

for example, angles are usually expressed with theta.

#

the two roots of a quadratic are usually expressed as alpha and beta.

#

the change in a variable is usually expressed as delta.

#

and the summation notation is essentially just a really big sigma.

midnight haven
#

Upsilon is new

west sail
#

oh and in statistics there's a kind of distribution called the chi-squared distribution, which is exactly the chi in the Greek alphabet.

#

in general, in STEM (so science, tech, math, engineering) people use Greek letters a lot, for better or worse. might as well get the ball rolling.

toxic lichen
#

knowing them makes formulas seem less alien

coral pecan
#

Hmm makes sense

#

Is it useful in gcses / igcses

midnight haven
#

Ig

pearl pondBOT
#

@coral pecan Has your question been resolved?

west sail
#

you should indeed refer to your syllabus, but most math and science syllabi use Greek letters to various degrees.

#

some more, some less.

pearl pondBOT
#
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coral pecan
pearl pondBOT
#
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vernal minnow
#

Sorry das es deitsch ist aber wie macht man die schar bei der 3

glossy blade
#

Can you translate?

vernal minnow
#

Yeah

#

Investigate the common position of the plane E and the family of lines gt as a function of t:

For which t is the line gt parallel to the plane E? Does it lie on the plane E?

For which t does the line g intersect the plane E orthogonally? Also state the point of intersection. (6 points)

#

The coreect answers on tze notes but i dont get how you find out waht to do

pearl pondBOT
#

@vernal minnow Has your question been resolved?

pearl pondBOT
#

@vernal minnow Has your question been resolved?

#
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pearl pondBOT
#
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green meteor
#

Is this right i dont have answers

pearl pondBOT
iron basin
green meteor
#

Is the working fine

iron basin
#

yeah checked

#

assuming question is to find sin(A+B)

green meteor
#

Thanks

#

.close

pearl pondBOT
#
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pearl pondBOT
#
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stoic imp
pearl pondBOT
jolly parrotBOT
#

Renato

cinder flower
#

since these are surjective functions from {1,…,8} to {1,…,8} they must be bijections, which correspond to permutations of {1,…,8}

#

i think that will be easier to work with than thinking about functions

cinder flower
#

nobody

stoic imp
#

by bijection you mean an isomorphism, aka injective + surjective?

cinder flower
#

a surjective function from {1,…,8} to {1,…,8} must be a bijection. because every one of the 8 elements in the codomain must be mapped to. since there are only 8 elements to send into the codomain, each must be sent to a different one

toxic lichen
#

though those usually are not called isomorphisms

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the word "isomorphism" is reserved for shit like groups or rings or whatever

cinder flower
#

bijections are isomorphisms in the category of sets kuromi_evil

cinder flower
#

what

stoic imp
#

well along as the two conditions are met

#

srry

cinder flower
#

can you write down a surjective function for me

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from {1,…,8} to {1,…,8}

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or even just from {1,…,4} to {1,…,4}

#

i promise you it will be injective

stoic imp
cinder flower
#

no

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this is not surjective

toxic lichen
#

that's not surjective

toxic lichen
stoic imp
cinder flower
#

do you know what surjective means?

toxic lichen
#

your function's image is just {1} and fails to be {1,2,3,4}

stoic imp
#

so in a subjection the cardinality of the image needs to be equal or greater than the cardinality of the domain

modern talon
cinder flower
#

hello blanket

stoic imp
cinder flower
# stoic imp no

then why are you telling me “no you’re wrong” when i say things about surjective functions

#

lmao

stoic imp
#

well I thought i knew, i just noticed i didnt

cinder flower
#

okay

cinder flower
#

there is no x with f(x) = 2 for example

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nothing maps to 2 or 3 or 4

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surjective means that everything in the codomain gets mapped to by something

#

f(1)=1
f(2)= 4
f(3) = 3
f(4) = 2

is an example

stoic imp
#

ok