#help-39
1 messages · Page 292 of 1
fine, here's a different approach that's actually the same
determine all functions h that do not satisfy g R h
@stoic imp
how do I count
how many functions {...6} -> {...16} are there? ignore R
16 P 6
wait, no
what about 1,2,3,4,5,6 all map to 12? that's a function you didn't count
the outputs don't have to be unique
P is permutation
n P k is n!/(n-k)!
16^6
is that a different answer?
16 possibilities for the first out of 6 spots
16 possibilities for the second out of 6 spots
it's harder to follow if you're spontaneously changing arguments. is 16^6 different from 16 P 6?
yes
ok
now that I'm caught up, yes your new answer makes sense
the key is that you have 16 choices for each of the 6 entries
now count the number of those functions that are not related to g
it's harder to do the opposite, i.e. count the number of functions that are related to g
so, directly
6 x 16^5
no, but explain?
we just need them to share at least one element in their images
f R g iff im f intersects with im g
a R b iff im a n im b ≠ {}
my mistake for disliking the first version of that lol. I did ask for the number of functions not related to g, though
10 choices for first spot 10 choices second spot etc
the image of g is {15,14,13,12,11,10}
1,2,3,4,5,6,7,8,9,16
you see how every function h that is not related to g is precisely a function {1,2,3,4,5,6} -> {1,2,3,4,5,6,7,8,9,16}?
yes, so?
this was the intended answer to my first question, X = {1,...,9,16}
10^6?
it's not topology
only if you think so
you should try to enjoy finding multiple solutions to the same problem, it's good for you
if I thought it wasn't appropriate for a newbie, I wouldn't have mentioned it
a function h that is not related to g is precisely a function {1,...,6} -> {1,...,9,16}, and the latter space is easier to work with
amongst these functions, how many are related to f?
eh
the image of f is {2,4,6,8,10,12}
2,4,6,8
4^6
4 x 10^5
this overcounts
I need more hints
what class is this for?
what am I overcounting
it's first year gen eds
suppose 17 people run a race, including a guy named Kevin. how many top-five placements are there, featuring Kevin?
have you seen a counting problem like this before?
in case it's unclear, I want the number of top-5 placements in which Kevin is present
a,b,Kevin,c,d
( 17 P 1 ) x 16 x 15 x 14 x 13
17P1 is just 17, and you deleted that message last time
have you or have you not seen a question like this before?
<~> do you know this counting trick?
I guess i have, is just that counting is hard
no
counting is hard, genuinely
ok
so I actually alluded to this before, sometimes it's easier to count the opposite thing
every top-5 configuration falls into one of two sets: that which sees K, and that which does not
so to count all of the placements with K, we count every placement, then subtract the ones without K
that's (17 P 5) - (16 P 5)
nice
a similar idea applies to the question of how many functions are related to f
no, only because remember we want the total number of functions related to f that are not related to g
the image of g is {15,14,13,12,11,10}
every function that does this is obviously not related to g, so we restrict our search to functions {1,...,6} -> {1,...,9,16} that are related to f
how to use the complement principle
mmmm so you did know the trick after all
I am bad at counting
unless if you just came up with that name
it was taught in class but I'm bad
it really helps to see other examples of counting problems you've done in class or on other assignments, especially those you've actually solved yourself
help
you get better by doing it
I have a question
when do you normally ask for help on a math assignment?
how much time do you allow yourself to work things out on your own?
I sympathize with this, especially for combinatorics, but that wasn't my question
ok, sure, just checking
I thought you might tend to ask questions the moment you're uncertain about how to proceed, i.e. without trying random stuff first, that's all
you're not supposed to be lol
it might seem easy to you, but sometimes things go south in the middle of the exercise
no I get it, and no it's not easy for nearly anyone when they first start
using this compliment principle should be your last resource, in class teacher said it's useful when what you are trying to count is very hard
that's weird to say. counting complements can be really useful
it shouldn't be treated as a last resort lol
actually it's good because you immediately consider the complement and pick which one seems easier at the time
she didn't said it should be the last resource, that's on me, but she did said the last sentence
yes
so to recap
every function h : {1,...,6} -> {1,...,16} that is related to f and not g is, first, a function that is not related to g
so we can count amongst the collection of functions that are not related to g, how many are related to f
since a function not related to g is just a function -> {1,...,9,16}, we want the number of functions {1,...,6} -> {1,...,9,16} that are related to f
does this make intuitive sense?
do you see how you'd get to this point on your own?
@stoic imp Has your question been resolved?
how to count those
did you try it on your own first?
first output out of the six outputs must be either 2 4 6 8
@stoic imp
@stoic imp
I'm literally still here
help
10^6 - 10 P 4
well since you didnt confirmed it was correct I started self doubting myself

well I was trying to think of a reason why it's wrong
and I think it has something to do with your designation of a "first" input that's required to map to one of the four options
how to correct it
explain your other answer
which one
the only other one that came after your first
i tried using compliment princepol
@rare scaffold
you don't need to ping after a reply. replies ping.
explain how you used the complement principle
@stoic imp second ping
welll
10 possibilities for each output
since a function not related to g is just a function -> {1,...,9,16}, we want the number of functions {1,...,6} -> {1,...,9,16} that are related to f
from 1 to 16 theres 10 numbers
10 possibilities for each of the 1 to 6 inputs
then we subtract the ways that out of the 10 possible outputs we pick one of the 4
what is the quantity you're subtracting?
10 p 4
what does it represent?
2 4 6 8
these are the number of functions that do what, exactly?
the image of f is {2,4,6,8,10,12}
when the images have non empty intersections
aka when they are related
that's not what you want
if X is a finite set and A is a subset of X, we have |A| = |X| - |X-A|
i want when they have empty intersecgion?
in this case, X is the collection of functions {...6} -> {...9, 16}, and A is the collection of functions that are essentially related to f
characterize a function in X-A
@stoic imp still here
say what
don't just say "say what", tell me what you're confused about
what do you mean by
"characterize f x a"

a function in X-A, with X and A defined as above, is just a function that is not related to f
the whole point is that #{functions related to f} = #{all functions} - #{functions not related to f}
@stoic imp do you really just lock your phone every time a message is sent to you or something lol
@stoic imp Has your question been resolved?
@stoic imp Has your question been resolved?
why do you abstract everything with this notation, "X", "A"
i had to help my parents with something
I am back and reloaded
the idea is that you should try to help me because i am new to math, but you using this " a function in X-A" without defining X and A makes things a little bit confusing ngl, im new with that notation
yes, this is the what so called, complements principle of counting, how do I count the total number of functions ?
sorry, I had to help my parents with something, is just that this counting exercises are hard
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In base $b$, we have $r = 0.\overline{57}_b$ and $3r = 1.\overline{06}_b.$ What is the value of $r$ in base ten? Express your answer as a common fraction.
7
i think we divde 3r by r or do we subtract 3r by r to get 2r and then do something with that?
1.06 repeating over 3 equals 0.57 repeating
base b
Multiple approaches here
- Write r in terms of b
- Trying to do arithmetic in base b (pretty much equivalent to approach 1, but possibly requires more experience to do properly)
how would i write r in terms of b
doesn't the question give that already?
r = 5/b + 7/b^2 + ...
Think of something like this, but try simplifying it
like 5/b+7/b^2 is something with denom b^3?
erm... you could put it on a denominator b^3, but b^2 is enough
Also there's extra terms to deal with on account of r having a repeating base-b expansion
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AEDC is a square with side 17. AB=8, BC=15. Find FD/AG. Can someone give me a hint on this problem
Gimme a min
Use your trig functions
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
?????
Wattahel?
is there a solution without trig
I don't think so
Similar triangles
i did it with similar triangles but the solution was too long
Oh ok
in which triangles can we use trig
Drop perpendiculars and apply
If you know 1 side of a triangle and an angle you can use trig functions to figure out your missing pieces
i think if we draw a diagonal AD then we can try to prove that the 2 triangles that are formed are congruent
similar
yes, but i got answer 1 after manually calculating the side FD
so they are congruent
but we gotta prove it
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Can somebody explain the proof please
Be precise
I wouldn't say that's a proof, it's a definition
I doubt too .
But ..
It says that its assumed that xn doesn't converge to x and so we are basically just using the definition of convergence to prove the second sentence...?
A sequence (x_n) converges to x if, for all epsilon > 0, there exists a natural N such that for all n >= N, |x_n-x| < epsilon
That's the definition of "sequence X converges to x"
The negation is that there exists an epsilon > 0 such that for any natural N, there exists n >= N such that |x_n-x| >= epsilon
(if you've done a bit of logic it should be clear how that's the negation)
The second line ,
"That is , for each k.."
Does it mean , that for every natural number , we can't guarantee that this inequality holds.while It may hold for some natural numbers ...
Yes
Well, not quite, it's guaranteed it does not hold for at least one number
|x_n-x| >= epsilon is true for at least one n >= k
Ok thanks
Isn't it the same as my statement
No, your statement is like "we don't know"
The correct statement is "that sequence definitely does not converge (to x)"
"such that |xn-x| ≥ ε holds", yes
Okkhhayy
We say "for all k in N, there exists n >= k (such that) ..."
,, \forall k \in N (\exists n \geq k ...)
Nel
I dont know , for past few days , it takes me a lot of time , to figure out statments
I was stuck on this "proof" for 2 days
Trying to make sense and logical flow
Maybe find a course on first-order logic
It seems like , real Analysis is like a task for me now ,not the enjoyment of math
Whats that
Basically logic with quantifiers ("for all" and "there exists")
Do you have some recommendations
No, sorry, but there is #book-recommendations
The convergence statement written symbolically looks like this:
,, \forall \varepsilon > 0 \left(\exists N \in \mathbb{N} \left(\forall n \in \mathbb{N} \left(n \geq N \implies |x_n - x| < \varepsilon \right)\right)\right)
Ah yes the definition of converges
Nel
That's what first-order logic looks like, and it makes negating statements very easy without having to think about what every word means
Of course, words are still useful, nobody writes everything in logic symbols, but for precise semantics it can help
I found a course !
29 lectures , each 1.5 hour
Automata is there
Too
You don't need that much to better understand general mathematical statements
My primary aim is real Analysis
Only want to do what's relevant but in detail
Can you suggest which lectures should I watch
Just a few results from searching "introduction to first order logic":
https://builds.openlogicproject.org/content/first-order-logic/introduction/introduction.pdf
http://intrologic.stanford.edu/lectures/lecture_16.pdf
https://people.math.ethz.ch/~halorenz/4students/LogikML/Nutshell.pdf
Again I'm not the one to ask for recommendations but feel free to drop a message in #book-recommendations , even if you're looking for video content
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Let Γ denote a curve y = y(x) which is in the first quadrant and let the point (1, 0) lie on it. Let the tangent to Γ at a point P intersect the y-axis at YP. If PYP has length 1 for each point P on Γ, then which of the
following options is/are correct ?
i wrote the tangent as y=x(dy/dx) + Yp
and i dont know how to use that length = 1 condition
i thought ill take a point (x,y) on the curve and do x^2+(y-yp)^2 = 1
oh bruh
i can use y-yp = x(dy/dx) 😭
ok but then i get the condition
dy/dx = +- sqrt((1-x^2)/x^2)
how to choose between + or -
or can we take both?
Gamma is in the first quadrant
well consider what happens as you approach (1,0)
you can't approach it from below smoothly (gamma is in the first quadrant) so you have to approach it from above
if the tangent line is always 1 you can use the distance formula for any point on the function and let that be true for all x
uh i dont understand what this means..one sec let me send a diagram of the situation im imagining
you are able to find f'(x) using that
👍 yes i got that thank u tho
these r the 2 scenarios im thinking of
huh? neither contains the point (1,0) tho
hmm
note that sqrt(1-x^2) is undefined for x > 1
so i assume we shouldn't consider points for x > 1
well now that we are restricted to [0,1] basically, no, it can't
use your formula for the tangent line and combine it with the distance formula
why this problem looks kinda like the one in my book lmao
already done bruh now im trying to figure out the sign of the slope
Slope is not defined for x>1 right?
you should already have the answer tho
i got one of the options
what did you get
ye just remove the parts for x>1
B
im not able to figure out the sign of the slope
Yeah same
B is wrong
really?
how though
istg it's B
@calm wing whered u go 😭
$f(x)-y_0=f'(x)x$
ImOakley
It's prolly D and whatever's the solution for D
what do u mean "prolly"?
$1=\sqrt{(f(x)-y_0)^2+x^2}$
ImOakley
Probably
no bro like based on what can u say that
$1=\sqrt{(f(x)-f(x)+f'(x)x)^2+x^2}$
ImOakley
I can see a decreasing function acting like that
$1=\sqrt{(f'(x)x)^2+x^2}$
ImOakley
Right got it
ok well i cant, and why is it a decreasing function?
uhh why
yeah
x is always positive as it is in the first quadrant
hang on
@eager jewel is this select more than 1 answer
Because x=1 corresponds to y=0
thats why b wasnt right
So it has to be the other option
because as apoorv said its either only increasing or only decreasing
Which is the negative sign
Welcome
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ty @feral olive and @calm wing
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Suppose I want to prove that this sequence is divergent.
Am i allowed to use such language .
"It can easily be seen that..."
sure if it follows from theorem 3.4.5
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Let $A$ be generated by $(a_1,a_2 \dots , a_n)$, each being distinct and no power of any $a_i$ is any power of $a_j$.
This is as if it were then the group would be generated by a subset of $(a_1,\dots,a_n)$
Then $A={a_1^{k_1} \dots a^{k_n} \mid k_i \in \mathbb{Z} , 1≤i≤n }$. Let $H≤A$. Then every element of $H$ must be of the form $a_i^{h_i} \dots a_k^{h_l}$. This being a representative element of $H$, $h_j$ are fixed . Suppose an element that's not of this form were in $H$, call it $t$. Then $a_1^{b_1} \dots a_{I}^{b_{i}} \dots a_{l}^{b_l} \dots a_n^{b_n}=t$.
We now multiply across by $a_i^{-h_i} \dots a_{l}^{-h_l}$.
Then $a_1^{b_1} \dots a_{i}^{-h_i+b_{i}} a_{l}^{-b_{l}+h_l} \dots a_{n}^{b_n} \in H$.
Then $a_1^{b_1} \dots a_n^{b_n} \in H$.
But this is a contradiction to our assumption that $H$ is of the form $a_i^{h_i} \dots a_l^{h_l}$ for some fixed $i$ to $l$. |
we're done.
I feel there's something wrong with this, but I can't quite put my finger on it.
wai
I see the error now
Is this salvagable though
<@&268886789983436800>
I did think of induction, and my book verifies that one way to prove this is indeed induction
Does n-generated just mean "can be generated by a set of size n"
1≤i≤n
But I was thinking of avoiding induction
how have you gotten existence of such a_i
like
even in Z if we have any two generators a and b (e.g. 2 and 3) then a*b is a "power" (where a*b is additive notation) of both
unless I'm being slow
wai
yes, but in multiplicative notation (for the group Z with addition, which is confusing and alas nothing can be done about it) then $a_j^{a_i}=a_i^{a_j}$
Edward II
in the usual notation for integers, both are equal to $a_i\times a_j$
Edward II
then the group can be generated by 1 element , right
yeah sure; are you also taking n minimal then
I suppose you can with no issues but then the n in your proof may not be the same n as in the question technically I suppose you can with no issues but then the n in your proof may not be the same n as in the question technically (i.e. where you're being asked to prove the generalisation of "a subgroup of the 2-generated group Z is also 2-generated", and your proof would say "well actually Z is 1-generated, so it's subgroups are 1-generated, which means they're 2-generated"
what you sent has nothing to do with being n-generated though
oh , right I just need to show if $A$ has a generating set, then so does any of its subgroups
right
wai
what the blud
?
they probably don't mean for X to be a set then 
what 😭
they probably mean a multiset
I see, that just makes stuff so much worse
no it makes it better
because now n-generation just means surjection Z^n -> A
I dont' quite flllow
well if you have a generating set g1, ..., gn allowing duplicates, then you get a map Z^n -> A which takes (0, ..., 1, ... 0) -> gi
where the 1 is in the ith spot
the map is surjective because the set generates
I see
that makes sense
Okay, I think I'll just come back to this tomorrow 🥀 , not clicking
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i found that f(1) f(2) make a series as 1 , 2 , 4 , 7 and so on
i tried to find f100 by this but its getting complicated and i wasnt able to find the summation of that series
looks familiar 
what if you subtract 1 from the series
is this series a well known sequence
well i mean that as in
it may have a formula already
If you consider how the function is constructed its pretty obvious what the series is
aside from the 0 it's the triangle numbers
i didnt get what u mean
look up triangle numbers
triangle numbers? what
try writing f(x) + f(x+1) .. f(100)
Lets assume we want to know the value of f(5) without prior knowledge
A triangular number or triangle number counts objects arranged in an equilateral triangle. Triangular numbers are a type of figurate number, other examples being square numbers and cube numbers. The nth triangular number is the number of dots in the triangular arrangement with n dots on each side, and is equal to the sum of the n natural numbers...
thats wild. 1 step ans
```
f(5) = 5 + f(4)
>f(4) = 4 + f(3)
f(5) = 5 + 4 + f(3)
>f(3) = 3 + f(2)
f(5) = 5 + 4 + 3 + f(2)
>f(2) = 2 + f(1) = 2 + 1
f(5) = 5 + 4 + 3 + 2 + 1
mb, im used to the tex markdown, lmao
yeah basically that is the outcome
<@&268886789983436800>
<@&268886789983436800>
sniped
thanks
so i got it
If you want to know the value of f(X), then it will just be X + (X-1) + (X-2) ... 2 + 1
oh
Which is a pretty well known series, as already has been stated
reals
ohhh even this series is simple
its a bit hard to notice the patterns like this
can yall help me or give tips on the patterns
Some of them you can actually construct on your own
Others just come from practice/prior knowledge
Experience
like this one?
i had the idea of writing x = f(x) - f(x-1)
and adding all of it
this gets the ans but there seem to be more ways to do this
That requires you to know f(x) and f(x-1), so you probably cant do much about it as is.
i didnt rlly get what u mean
we can put x from 0 to 100
and we have a way to find f(-1) too by the relation thats how i got it like rn
does this not work?
Like, yes, you can do so, but that would take significantly more time
Precisely, if you want to add all the values from 0 to 100
You first have to compute them individually
f (x) - f(x-1) summation till 100 will cancel all the terms ecet f100 - f-1
You still dont know what f(100) is in that case
so in lhs
we have 1 + 2 + 3 ... 100
this is n(n+!)/2
and in rhs we will have f(100) - f(-1)
if we put x as 0 in the eq we get f(-1) is -1
sorry its 1 mb
ah, i see your idea
so 5050 +1
Yea, ig you can do that
nice
Really elaborated compared to just replacing a few values and noticing its 1+2+3...(n-1)+n, but it works
yea lol
tysm for the help
I can’t find the channel where I needed the help, as it put me in the discussion one after it closed the channel
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u=sqrt(x-1)
u = x - 1
Yeah probably works as well
Yup
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nah
I got more
just grabbing more paper
can we do 8?
ah well I gtg
so Imma close
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Hi there, i am working on this question "The points (–2, 4, 5), (4, 5, –3), and (1, –1, 6) are three of four vertices of parallelogram ABCD. Explain why there are three possibilities for the location of the fourth vertex and find the three points. " I wrote that 3 possible points exist, as there could be a parallelogram in each plane
however, i am not sure if this is correct, as when i graph the points in each plane in desmos, the XZ plane does not look like a proper parallelogram
I am having similar trouble with a question giving the 3 points of a triangle and asking for it's shape
<@&286206848099549185>
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Heres an equation that repreents the amount of bacterias in function of the time past in minutes : N(t) = 10(2)^(t/40). Express by an equation the time in function of the amount of bacterias.
find the inverse function
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HEY EVERYONEEE!!!!!!
MY NAME IS HEAVEN
IM SO GLAD TO BE HERE
I HAVE A SERVER TOO!!!
Its for those who wanna make music but dont kno where to start
!redir
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Hey
fixed vector?
Let’s say I have an unknown which is point m and I wanna get rid of it in these vectors
can you show the context in which you saw that phrase?
Yes
Uh I don’t have a problem with me
But he mentioned it in class and my exam is soon
It’s like in 2 hours
So let’s say point M is any point
And I wanna remove it from
Let’s say I have
Vectors MB+MA+MC
I wanna remove m
To make it a fix vector
What do I do
@hazy escarp Has your question been resolved?
Okay I have another question about function
When I see a function and I solve it to find the image (y)
Let’s say I see the sign >< (alligator)
Do I solve it and take everything to the left making it 0 and solve it
Or do I just solve for x
And do I do a sign table or an interval
Or not and how do I know
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so first i take x = y = 1
from this we get a quadratic in f(1)
for which the values of f(1) i get as 3 and -2
now i put y = 1/x
so f(x).f(1/x) = f(1) +2(1/x + x +1)
but at this point im stuck
i tried doing x = 1/x
aight
oh what
i got it
but im getting 2 diff functions for the diff values of f(1)
yeah I think there is a way to reject one of them
I haven't figured it out tho
Gimme a min
they took both values and both of them are the ans
its an example problem, in ques they prolly say f(1) >0 or sum
for a single value
tysm for the help i got it
I guess?
u gor it in a single step tho-
dw , u helped me get the ans
lucky guess
so thank you
np
💀
advanced gambling right here
aight then
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so $p(x) \to p(x) + ((f(x))$ right
wai
the form is confusing me here
((f(x)) is a set, so all elements are of the form p(x)+((f(x))
Yeah
I suppose (f(x)) could absorb some part of p(x) but still
do you know what else was SILLY mistake??
Yeah this is going to act like reduction modulo f(x)
ah, lemme work a bit then
$(f(x))= { \sum a_ix^{nb_i} \mid a_i \in \Z, b_i \in \N }$
wai
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no worries
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.oh wait, here all I need to do is use the fact that it's a homomorphism , do I not
That's literally it
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well, it tells me that any polynomial in R[x] iis mapped to a polynomial of that forms
anyways class now
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went on chatgpt and it told me that the entire rombous does not fit within each sector (DAB and DCB)
Is this an igcse question?
I did this exact question 8 years ago haha
lol what a coincedence
You have to use the sector area formula: $Area = \frac{1}{2}r^2\theta$
Ajay
So $$Area_{sector} = \frac{1}{2}(4^2)\left(\frac{2\pi}{3}\right) = \frac{1}{2}(16)\left(\frac{2\pi}{3}\right) = \frac{16\pi}{3}$$ You got the correct are for the rhombus
Ajay
that's not a circle it's an ellipse right?
No, it is circular
i understand how the area of the sector equation works
my question was
is the rombous a part of the sector
and if so we should do sector - rombous
am i correct
and if not why
yes, to get the segment area
okay
intersting
gpt was lying to me ig
ty
i was full tweaking for 4 hrs abt this
Can you solve it on your own now?
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I do not understand vectors and need help solving this
for 36(a) think of what path you can take to get from A to C, there's two paths but one of them isn't useful
-4a+3b+2a+b
No I understood this part I feel
But when they ask a mid point
Like where 2 lines intersect
Ah okay. Say for an example, in question 11 we know M is the mid point of OA. It also shows you know OM is a. What would be the ratio be for OM:MA?
Close, it's a half of OA because M is the midpoint so it means OM and MA are equal distance
Ohh midpoint
yeah
don't worry, my dumbass missed these type of stuff during gcse 😭
So ratio is 1:1 ya ?
basically
Ok so
Is this correct for OM AND MA
yes
yeah
yes
What does vector terms mean 🥲
wdym?
use section formula for vectors?
it just means what the vector equals to using the variable a and b
like you did here
Then the answer would just be this or
What's section formula for vectors 😭😭
it's similiar to what we are doing, but putted in a formula
for (a), yeah
Oh
What's the formula
wait that's the name right
I just wanna go through it rather than using the formula, so you understand it
The one used in coordinate geometry
yeah
I don't even think I learnt the formula but yes makes sense
its applicable here as well as in complex numbers
as an example
yeah ts
Yes I never learnt this formula
I think it's better if I go step by step or I'll probably make some mistakes
It'll help you understand what's going on if you do step by step
but using the formula can be useful for saving time
I don't even understand the formula 🥲
Guys sorry I'm really frustrating to teach maths to
But i don't think sector formula vector is in gcse
do you need help with 2nd part of the problem?
Are you saying it's there or that it isn't there ?
Yes ig
it isn't there
Yes that's what I'm also saying
So would they like reduce marks if I use section vector formula ?
anyways i'll let @karmic flower take over, i have to go
no, as long as you show your working and get it right
Ok take care
hmm
@karmic flower your still here right ?
Yes im thinking of how would I solve it without using the above result
ts is tuff without it. im gonna try again after a while. Sorry man. im not getting it rn
@coral pecan Has your question been resolved?
It's fine I get it
Using the formula ?
Yeah. I expressed P two times assuming lambda and nu as ratios in which the lines are divided. then compared both equation and coefficient of a and b. It gave two equations. Solving them I got value of lambda and nu. Plug them into P to find its position vector wrt O. Now you can find the required ratio
@coral pecan Has your question been resolved?
Gng I haven't learned lambda and annol and nu🥲🥲🥲
eh. lambda and nu are just variables I assumed to be the ratios in which sides are divided. you could take them x and y if you're comfortable with that.
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help how to integrate tanxsinxdx?
$\int \tan(x) \sin(x) \dd{x}$
Ann
this?
yes
ok, progress so far?
i managed to recall the chain rule. i dont know how to use it tho
that's for differentiation...
or was i supposed to make it into sin2x/cosx
kinda useless for this integration question
sin^2x/cosx
sin2x
do you mean sin^2(x) or do you mean sin(2x)?
anyway
writing the stuff inside the integral as sin^2(x)/cos(x) and then (1 - cos^2(x))/cos(x) is the way to go imo
oh damn
you can probably split that fraction you got into two fractions
you'll need to either know or rederive the integral of sec(x) dx
oh then i can split it into two integrals sum
how do i integrate sec x
isnt it tan x
do you have access to a common integral table?
Convert into sin and cos function. then cosx=t
Alternatively subbing u=sint works
you know the result for integrating √a^2-x^2 dx. That's be useful later on
$\int \frac{\dd{x}}{\cos(x)} = \ln\absv{\sec(x) + \tan(x)} + C$
Ann
so the answer is just whatever this is - sinx?
int sec**^2**(x) = tan(x) is what you were thinking of earlier
how can i derive like sec x and csc x on the go?
i dont think writing it as (sinx)^-1 and derivation wont work
or should i just memorize
if you don't have access to u-sub then you don't have access to any method to rederive those integrals im afraid
dont be afraid im here
but ok i got it!
...lol?
thank you for your help
memorise?
yea
maybe
but memorization is just for the weak
i derive it because im too lazy to bother otherwise
thank you once again for help👍
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Proof for int secx dx
op doesnt have access to substitution
that's sad:( is there any other way then
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Ohh
What is lambda and nu
lambda and nu are just greek letters
they can be variable names like any other letter
here is a picture of the Greek alphabet that I can find for OP.
it's even shorter than the english alphabet
are my eyes deceiving me or are there two forms for lowercase sigma?
oh word-final position sigma, okay. interesting.
@coral pecan Has your question been resolved?
What would learn these be useful for
a lot of variables in math are expressed in Greek letters.
for example, angles are usually expressed with theta.
the two roots of a quadratic are usually expressed as alpha and beta.
the change in a variable is usually expressed as delta.
and the summation notation is essentially just a really big sigma.
Upsilon is new
oh and in statistics there's a kind of distribution called the chi-squared distribution, which is exactly the chi in the Greek alphabet.
in general, in STEM (so science, tech, math, engineering) people use Greek letters a lot, for better or worse. might as well get the ball rolling.
they are symbols that mathematicians use all over the place
knowing them makes formulas seem less alien
@coral pecan Has your question been resolved?
you should indeed refer to your syllabus, but most math and science syllabi use Greek letters to various degrees.
some more, some less.
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Ok Ty GUys
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Sorry das es deitsch ist aber wie macht man die schar bei der 3
Can you translate?
Yeah
Investigate the common position of the plane E and the family of lines gt as a function of t:
For which t is the line gt parallel to the plane E? Does it lie on the plane E?
For which t does the line g intersect the plane E orthogonally? Also state the point of intersection. (6 points)
The coreect answers on tze notes but i dont get how you find out waht to do
@vernal minnow Has your question been resolved?
@vernal minnow Has your question been resolved?
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Is this right i dont have answers
righto
Is the working fine
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Renato
since these are surjective functions from {1,…,8} to {1,…,8} they must be bijections, which correspond to permutations of {1,…,8}
i think that will be easier to work with than thinking about functions
who is talking about injectivity
nobody
by bijection you mean an isomorphism, aka injective + surjective?
a surjective function from {1,…,8} to {1,…,8} must be a bijection. because every one of the 8 elements in the codomain must be mapped to. since there are only 8 elements to send into the codomain, each must be sent to a different one
yes
though those usually are not called isomorphisms
the word "isomorphism" is reserved for shit like groups or rings or whatever
bijections are isomorphisms in the category of sets 
no
we can send 1 to 8 to 1
what
can you write down a surjective function for me
from {1,…,8} to {1,…,8}
or even just from {1,…,4} to {1,…,4}
i promise you it will be injective
f(1)=1
f(2)=1
f(3) = 1
f(4) =1
that's not surjective
this function fails to hit 2 as an output
why is that a dealbreaker
do you know what surjective means?
your function's image is just {1} and fails to be {1,2,3,4}
so in a subjection the cardinality of the image needs to be equal or greater than the cardinality of the domain

hello blanket
no
then why are you telling me “no you’re wrong” when i say things about surjective functions
lmao
well I thought i knew, i just noticed i didnt
okay
anyway, you notice how 1 is the only value gets mapped to here?
there is no x with f(x) = 2 for example
nothing maps to 2 or 3 or 4
surjective means that everything in the codomain gets mapped to by something
f(1)=1
f(2)= 4
f(3) = 3
f(4) = 2
is an example
ok
