#help-39
1 messages · Page 265 of 1
still incorrect
oh
shi
uh im not too sure where ive gone wrong tbf
ok i went back and got radius, i got 110.11..
so i didnt do r^2 right
thats wat it was
great, now that's correct
okay, now rearrange for pi (small radius)^2
so i have 110.11 - 1/2 * pi *r^2 = pi(smallr)^2
what do i use for r on LHS?
4/sin32?
nope that gave me 20.6...
4/sin(36)
if you do everything right, you should get the bottom value as the radius of the smaller circle
kk ill try retype into calc
asdaluhdasd somethings going wrong
i have r^2 to be 46.31...
so 1/2 * pi * ans should equal area of OED
,w (4/sin(36 deg))^2
so now
so now you need to find the LHS
from 5 * 1/2 r^2 sin(72)
..
there's no pi for the triangles
ok cool so
now
,w sqrt((5 * 1/2 * (4/sin(36 deg))^2 * sin(72 deg)) - (1/2 * pi * (4/sin(36 deg)^2)/pi)
ok so thats not it
no
the pi in wrong place
110.11 - 1/2 * pi *r^2 first
,w sqrt(((5 * 1/2 * (4/sin(36 deg))^2 * sin(72 deg)) - (1/2 * pi * (4/sin(36 deg)^2))/pi)
yeah so you need to divide that entire thing by pi
wont i need to redo it to get the ans tho
ilke to use for next stage
it's easier if you calculate that first
,w (5 * 1/2 * (4/sin(36 deg))^2 * sin(72 deg) )- (1/2 * pi * (4/sin(36 deg))^2)
nope, you didn't subtract 1/2 pi r^2
okay now that's better
trial and error lol
,w sqrt(37.36566/pi)
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how would you go about calculating the chances of two populations being from the same distribution?
this isnt for homework, just something im curious about
@fathom plank Has your question been resolved?
Maybe ask that in the discussion channel since it isn't a specific problem?
can u explain what exactly do u mean?
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My solution for 2) is different from the official one. I tried it by writing:
((A->B) AND (B->C) AND not(A->C) | (A->B) AND (B->C) |= (A->C)
<=> (A->C) AND not(A->C)
And this is unsatisfiable and hence not a tautology.
is this a valid proof or is it informal to just rewrite (A->B) AND (B->C) to A->C ?
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lemme give this a lookover
i think it works but you need to spell out the logic behind $(A \rightarrow B) \land (B \rightarrow C) \therefore (A \rightarrow B)$
Mirror
in effect you're doing the same logical steps, but you need to spell out why the propositions are logically equivalent
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Need help with finding asymptotes
I need to find and sketch all asymptotes of this function
And i don't know how to start 🙁
Which one you want to do first, horizontal, vertical or slant
The horizontal
Ok how do you know the horizontal asymptote?
No :/
horizontal is y = a when lim x -> +inf f(x) = a
Symetricaly for -inf
Is there any horizontal asymptote here ?
if yes what are the equations of horizontal asymptote
I kinda don't know because we haven't even started learning about limits and asymptotes and my professor just put this on my seminar work
it doesn't have a horizontal asymtote.
it has a vertical, and a slanted
How did you find out that it doesn't have a horizontal?
Do polynomial long division, and you get the following where $Q$ and $R$ are respectively the quotient and remainder.
$$f(x) = \frac{A(x)}{B(x)} = Q(x) + \frac{R(x)}{B(x)}$$
As $x \rightarrow \infty$ we see $f(x)$ looks like $Q(x)$ because $R(x) / B(x)$ goes to zero.
Shuba
So Q describes the slanted asymtote, and B describes the vertical asymtote.
Hopefully I've not given too much away
I kinda don't understand sorry 😄
Or you can plot it and visually see the asymptote is slanted.
So a function can only have one type of asymptote?
It can only be horizontal, vertical or slanted?
The asymtotes can be veertical, horizontal, or slanted. And functions can have multiple asymtotes of different types
they can be either.
For example, your function has two asymtotes - one vertical, and one slanted
Ohh so this one doesn't have a horizontal but only vertical and slanted?
For example, have a look at this one. This function has a vertical and a horizontal asymtote.
This function has two vertical asymtotes, and one horizontal
Do you know what an asymtote means?
Not really
It means "which straight line does the function look like as x or y becomes very large"
It's like a form of visualization?
So take y = (x+1)/(x-2) for example. As x -> 2 we see the denominator goes to zero so the entire function becomes very large. That means there's an asymtote at x = 2.
Which means, "as we let y become very large, the function looks like x = 2"
But with your example, the numerator is a polynomial of a larger degree, so we can reveal another asymtote using long division.
So how would you depict that it has no horizontal asymptote?
I need to write it for my assignment and I don't really know how to
Take this function as another example. I would say "the function has a vertical asymtote at x=2 and a slanted asymtote at y=x-2"
We do long division to get $$\frac{x^2-3}{x+2} = (x-2) + \frac{1}{x+2}$$ Now when $x \rightarrow \infty$, we see the fraction go to zero which gives us the slanted asymtote $y = x - 2$ (the quotient), and when $x \rightarrow -2$ we see the entire function go to $\infty$ giving the vertical asymtote $x = -2$.
Shuba
Is that for this one?
That's for my example. I can't do your particular problem for you (rules of the server XD)
It's all about looking for when either x or y go very large
Oh right sorry
Let me know if you want more help on your example 🙂
I think it's fine like this thank you 🙂
I don't really understand how to do it but I'll try it somehow
This is a good polynomial long-division video.
https://www.youtube.com/watch?v=_FSXJmESFmQ
This video tutorial explains how to perform long division of polynomials with remainder and with missing terms.
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hi
this is a similar triangles thing
wow i am procrastinating a lot
anyways the big triangle is just height 24 and base w + l
small is the height of 6 with base just l
and you just gotta keep in mind they are similar
so what do you know about similar triangles now that you have the height and base of each the big and small triangle
4
i feel like you might be overcomplicating this
lets step back for a second
sure
w = the distance from the lamp to the woman (aka how far she has walked)
and l = the length of the shadow
l = length of shadow
our goal is to look for dl/dt
there will be 2 triangles
yes
1 larger one and a smaller one within that larger triangle
yes
meaning they are similar
the larger one will have a height of 24 and the base will be the total distance which is w + l
yes
the smaller triangle has a height of 6 and only has the length of the shadow which is l
yes
we know that the ratio between the height and the base of a right triangle for similar triangles is the same
yes
therefore we can setup the equation:
big height / big base = small height / small base
we know big height is 24
we know small height is 6
we know big base is w + l
24/w + l = 6/l
we know small is l
well it just becomes:
24 / (w + l) = 24 / 4l
so it simplifies a lot faster\
cause you got 24 on the top and bottom
so denominators must be equal
so w + l = 4l
then just isolate w
(4 * 6 ) / 18 = dl/dt
4/3
bruh what
what?
that was simple
yes
im confused what i did wrong originally
honestly im not sure what you were doing
the best process to these types of problems is to methodically go step by step
list out what is known
what is constant
and what is the goal
then use what you know to setup some sort of relationship/equation
and simplify and solve
usually when they give you something weird they want you to use a property of that thing
like with similar triangles in this case it is known that the ratio between the height and base for both are the same
well thats kind of missing the point
wdym
you just gotta use properties that are well known from different areas to apply to whatever the problem is seemingly asking
plus i dont think there is anything else with similar triangles
for ap calc
the most common ones are similar triangles exactly like how this one was, filling up or letting out liquid from a specific shape of a container, and pythag is used a lot
all of them use basic stuff usually like what is the equation for the volume of a sphere or something
and you just gotta use that to relate things, derive, and solve
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Brooo I’m sorry yall this has me drawing a blank
Idk how I’m supposed to know the dedicate graph without it showing
I meant derivative
Is that a test?
its not she explained this previously its a take home thing
allegedly
what is another way to say derivative
a synonym
when f’(x) = 0 what does that mean abt the graph of the function at point x
Idk does it mean it’s flat
I don’t know
I think another way to say derivative is rate of change
But don’t quote me
well you just asnwered yourself
rate of change is the same as slope and is the same as derivative
a slope of 0 just means flat ground as you said
so where does it look flat / unchanging
In the middle
correct
So at x=0?
correct
positive is above the line y = 0, increasing is going up aka derivative is positive
youre doing b right?
it is asking where f prime of x is positive
aka derivative of f(x)
what do you know about a positive derivative?
Uhh
(aka positive slope, aka positive rate of change)
It goes upwards
correct
so the question is asking you exactly that
at which intervals is the function f(x) going upwards (aka derivative of f(x) is positive)
what about the distance between -3 and -2 makes you think that isnt a positive slope>?
Nuh uh im looking at it right now it’s literally open space
Here is proof
why only stop at x = -3 from -6 instead of going all the way to -2?
hello
Is it -6,-2 -2,2
sorry to bother but i kinda have a quick question
first half is correct
if its quick then ask it
what makes you think -2,0 has a positive slope?
okk.. can you guys graph sinusoidal functions
with degree not radians
bro
Cause it’s the whole line I think
i need steps
It goes up at the end
it doesnt have to be
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a function is just a bunch of points, an interval is just defining a starting and ending bounds
K so -6,-2 0,3
correct
there is a difference between positive and increasing
as i said positive is only saying that the function itself has to be above y=0
and increasing is saying that the DERIVATIVE of that function has to be above y=0
Idek
meaning this C is asking you where the derivative of f'(x) is positive
we already know that a positive f'(x) is saying that the slope is positive
a positive f''(x) (which is the 2nd derivative of f(x) aka the derivative of f'(x)) would just mean the slope's slope is positive
essentially that means the slope is increasing
so where in the graph do you see a slope that is increasing in value
B was looking for f'(x) to just be positive
C is looking for f'(x) to be INCREASING
B was looking for a slope greater than 0 across f(x)
C is looking for a slope's slope to be greater than 0 across f(x), essentially asking for a slope that gets greater and greater in magnitude in the positive direction
indeed
what makes you think that portion has the slope increasing in value along it
Is it -2,0
that is part of it
alright look at this
tell me which slope is higher in magnitude
B
correct
what the second derivative (f''(x)) is saying is we want that to be happening
where the slope increases
so lets look at this visually
-5,-3
take each one of these red lines as the derivative (slope) at a point
what intervals do you see consecutive patterns of A and B where A's slope is less than the slope of B
The left side has a steep slope
intervals, im asking for intervals in which the pattern occurs across
where the slope gets more and more steep
it is not asking if it is super steep or not, it is simply asking if the steepness is increasing
If it isn't straight its steeped
ah i just realized i shouldnt have used the word steep
Why not
youll get it
-6,-4 0,3?????????
incorrect
Bro how
what makes you think from A to B the slope isnt increasing?
Sorry to interrupt but one question, is this an issued textbook?
Cause it starts out steep and gets less steep
its a take home exam
No it’s from my math test
yes my bad, i shouldnt have used steep
the rule is whichever one is more positive*
aka increasing in value
That is not even a function..
these are both negative slopes
lets say at A its -9
and at B it is -8
B is more positive than A
Since it’s negative it’s different
yes which is why i shouldnt have said steep
well look at it this way:
at x = A, y = -9
at x = B, y = -8
the rate of change over A,B is -8 - (-9)
which is -8 + 9
which is 1
which is a positive number (over 0)
this is finding the rate of change of f'(x) (the slopes at points)
which is f''(x)
and since it is 1 (which is over 0) the slope increased
therefore f'(x) is increasing over that interval
this also applies to positive slopes
Why are you doing it like that and not immediately with the curve
because it is easier to explain that a line is more positive than another line then generalize it
than just saying oh yeah this is increasing
Is the answer -6,-4 -2,0 0,3
just -2,3
well technically since this is drawn and we dont know the function we cant actually be sure
It is the definition if the function curves (horns up) that f'(x) is (strictly )increasing
but i am assuming at x = 0 is the only instance of f'(x) being 0 near x=0
that doesnt explain the underlying concept
0 is very flat that’s why I think it’s weird
But I think I understand the increasing slope now
yeah no teachers do this a lot but usually unless it is super flat it doesnt mean just a flat line
cause they just draw a function since they dont want to come up with a piecewise (multiple functions smushed together into one)
Oh okay
Which question are you guys doing rn?
i can almost assure you that they meant x=0 to be a minimum though
I mean the dude that made this is a complete joker. It ain't even a function since rhe way he made it indicates 2 vertical points at -2
K bruh it’s not that deep my teacher just trying to help boost my grade I think he is a very good teacher
its a drawing? have you never seen this? lol
teachers do it all the time cause laziness and also to give better understanding to students without having them look at a weird piecewise
I ve seen this but its wrong drawing. Anyway tho
what makes you think f(x) at x=0 is not differentiable?
It’s a flat line I think
So u can have a differential of a flat line
a point having a slope in the first place means it is differentiable
since being differentiable just means there is a slope there
-4 -2 3
correct
oh also can i see ur intervals real quick
But it says the function is not defined in -2
How am I supposed to know
it says the bounds are strictly greater than -6 and less than 6
so it needs to be a parenthesis instead of brackets
you need to do it in interval notation
yeah, its saying where is it not differentiable, at x=-2 its a jump discontinuity
Yes if -2 is at the domain. In the
Exercise it says it is not
yeah didnt read that part
-2 isnt in there then
since it isnt part of the function in the first place
See why the shape is bad
If it had the holes it would be clearer
[ and ] = including
( and ) = not including
u = union = or
yeah filled in circles and hollow circles would make it a lot better
well first of all x=-2 isnt part of the solution set for anything since it isnt part of the function f(x) in the first place
so you can put a parenthesis on where -2 pops up
In c
(-6, -4]U(-2,3)
however if you want to include the number in the solution then you use a bracket
How bout b
Do you understand why we put it like that in the first place?
well the function f(x) is only defined strictly greater than -6 and less than 6
which means -6 and 6 are not in the function in the first place
Yeah I understand it
so they cant be brackets
at x=3
we already determined just now that at that point it isnt differentiable
therefore we also put a parenthesis on that
and at -2 we know that x=-2 isnt in the function f(x) in the first place
so it is also a parenthesis
so currently what you have is correct it just needs a union
Oh okay
How can we be sure that -4 is a v.tangent?
Do yall. Understand E or no
Yall don’t need to overcomplicate it im sure it’s a simple thing like he’s not being tricky
i mean usually thats what that pattern means :p
It isn't
Since
E
Asks of f'(4)
Ah the v.tagnent is at -4
Mb
i mean yeah it could just be leading us towards DNE
oh well
yeah misreading negatives happens a lot to me too
its just basic rate of change
take a starting point and an ending point, its a straight line so you just use rise over run
aka y2-y1/x2-x1
Idek what the points r
well the obvious choice in this case would be (3,2) and (6,0) since those are the start and the end to the straight line from left to right
Oh shoot ur not wrong
The function isn't defined at 6
it can be inferred that it approaches 0
Imma just leave it at that I gotta get rolling on ts
just like how .9999999 repeating equals 1
-_-
im kidding
it doesnt really change anything though if we use it in the equation
plus its almost definitely the intended method
plus we're eyeballing both anyways
Yea but you need to mention that you're using it as a theoretical line
Anyway tho
F and G I have true and false do yall agree
acting like this is a masters thesis dawg
Yeay bad tbh but i mean..
Either you do it correctly or you dont
you got true for F?
Bro can u just stop not trying to be mean but it’s getting annoying bruh
Yeah
It’s true
what makes you think that
Bro nevermind
Cause f(4) is the biggest one
Right
Or am I wrong
I atleast know f(4) is bigger than f’(4)
well F is saying that f(4) is the smallest
Noooo f(4) is not the smallest
it is saying that f(4) < f''(4) < f'(4)
Which is saying f(4) is less than f''(4) is less than f'(4)
you are correct saying that f(4) is the largest
but the problem itself is saying otherwise
therefore it must be?
So it is false
correct
And g is true then
Cause putting 2 false in a row is ridiculous
It’s bigger than 0
correct
Does concave mean negative
concave is a state
you are either concave up, concave down, or straight
concave up makes a U shape
concave down makes an upsidedown U shape
however that isnt always the case
the formal definition is a function f(x) is concave up if its slope is increasing (meaning f''(x) is positive/f'(x) is increasing)
and a function f(x) is concave down if its slope is decreasing (meaning f''(x) is negative/f'(x) is decreasing)
and flat just means, well, straight line
sorry not flat\
Brooo I did not think it meant that
straight line*
Ok
anyways for g
it is saying that the f''(2) is less than 0
that statement is false
because as you just said, at x=2 f''(x) is greater than 0
so therefore it can not be less than 0
Yeah i get that
👍
False/false right?
Yeah that’s what I put
which is correct
Bro try at took way to long I need to lock the f in
I believe in you man
It is false because we do not know if f'(x) is differentiable 👀
i mean
.-.
oh well
i guess we gotta burn the entire paper down and start over yall
:p
It is a good exercise for basics but very terribly written
i mean if you look at things that way
everything would need to have a citation all the way back to like god or wtv
kind of like wikipedia ngl
Yooo sorry to bother do yall know what concave down is
^
Is that like slope or something negative
concave down is where f''(x) is negative
Ohh I forgot i asked that
It's a frown
Bruhh I know what a upside down u look like im not that slow
Hating for what reason
Hoping it means strictly decreasing
I just wanted to show you accurately:(
So , this rule is like one of the most important.
When a derivable
Function is strictly increasing
The f'(x) is positive
And when strictly decreasing it is negative
That's like the first thing that must come to your mind when you hear increase/ decrease
So now to the exercise
It asks us when is f(x) is decreasing
So basically it asks when is f'(x)
Negative
So basically when the line is below x'x right?
So at which points is it below that?
( @strange fox check for mistakes)
Idk I think it’s just a and b cause they concave looking
Nononob
They round like a bowling ball
Concave has nothing to do with this
Wait first let me ask you
What are we looking at
Which function are we looking at rn
Like what's the name of it
Didn't you say A and B?
Yeah as the answer
Wait so did I get a and b wrong
Well yea
Oh
How much time do you have?
Idk it’s not due til tomorrow im just gonna stay up til i finish
This the last page w a graph tho so imma just cheat on the other shit
I can get in a call to explain better if you want in about 1:30 hours
Ok if u want
I mean man if you want me to just give you the answers i can but if you want to actually do it on your own i can explain it
I don’t care just don’t wanna waste ur time
I’m not very good with this shit
Stuff I meant my bad
I mean if you want to learn a thing or two i can explain it
D technically correct
E correct
F is incorrect
G is also incorrect
But man hey it's really good
So C
C is basically asking you when the rate of change ( f'(x) ) is at its highest right?
So when is it? ( Of the labeled points ofc)
Out of these points which one is the highest up
B
Isn’t a tangent line like always flat
Do you understand why tho B is correct?
Cause it’s highest up
Always straight* tangent just means against a curve
Like you know the red lines I drew before
Those are called tangent lines
Because the lines are tangential to the curve, aka the slope at the points on the function
Also I’m back wassup
Hello
^
yo bro
Well yeah that’s a tangent line against point C
i just lifted for an hour, cooked and ate food and we still on
no way
dedication
respect
Yea. Remember tho that this is a graph of f'(x) not f(x)
It is just the line representing the slope at a point thats what a tangent line is
It has to be tangent in accordance with something else
Brother its 5 40 am here
^
Yeah so technically this is representing the f’’ at that point, but it’s still technically a tangent line
Yea i joined in to help hope i don't mind
K bro be respectful he is just trying to help out u don’t have to point it out
I’m coding, doing a project, and helping with math all at once
My tri-tasking is on another level
I got alt tab on LOCK rn
I don’t think he was trying to be hurtful but I appreciate the backup
He being nosy bruh like mid ur beeswax it’s a free country on bro
I amma let you in on a secret
The f'(x) shows basically the tangent of the angle of f(x)
And what tangent do 0 degree angles have? ( Straight lines)
Is it 0 or dne I forget
Both technically since he said straight lines
DNE is vertical and 0 is flat so horizontal
0 since the angle of functions is [0,90)
By definition ^
I mean
(-90,90) technically
Also angles don’t exist in this context it’s just the slope steepness he’s just using angles as an example
Well yea the slope
I just realised that slope and angle in my language is the same word
For wat
Yep
F
Ok
Bro what the hell is that question
Asking for x values when they labeled points using the alphabet and the x values aren’t even lined up
Am I reading it wrong this doesn’t seem possible on paper and eyeball
What do u mean?
Yea its very badly written
There are lines
Well now for g
How is g not right like huh
Rip
Well then its all correct:D
I’m a genie
Yes, please tell the genius that wrote these exams to go back to high school, some of it inexcusable for a teacher
Tbf my teacher is fresh out of college
It shows
He is only a few years older then us
Oh well if you have anything more send it if not close this ticket :d
Impressive
This was fun cruembeler
Yur
This the last question besides inverses and I fuckng hate those so I’m calling it quits
Ooh
Inverses aren’t that bad
As if i know latex 
thecrumbeler2
I just use a generator
Correct
Last 2
Oh boy
Oh you use this
Have you learned power rule yet?
Yeah that’s why I knew the answer to the other one before I did the limit definition
Noice
These should be easy then
Just remember that sqrt is the same as exponent to the 1/2
I’m assuming you also know quotient and product rule
Yes
Alright ur set then
I think yeah
Well also chain rule
But I’m assuming you probably understand that if you know product and quotient
Crazy
I did this a long time ago do u think I did it right I don’t even remember
Is it 2/3
ye
Ok I see
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Hello I need help explain how to do math equation in chapter 3.5 and 3.6 in intergrated math 1 textbook. Here is a pdf of it. I do not understand how they work and need understanding of how to solve them. You can choose the questions.
@misty trout Has your question been resolved?
what exactly do u not understand
How to write the equation out
3.5 a y-intercept is a point on a function that touches the y-axis. to identify the y-intercept for a linear function, set x = 0
an x-intercept is a point on a function that touches the x-axis, to identify the x-intercept for a linear function, set y = 0
3.6 a transformation is a change in computation in comparison to its parent function. this could be multiplying by a constant, adding a number, etc etc
for whatever is inside f(x) is the variable. for instance, in f(x) = 3x-2, this is what we get when we plug in x. if we plug in x+3 instead, we get f(x+3) = 3(x+3)-2 = 3x + 9 - 2 = 3x+7
step 1?
in 3.5
mhm from my math teacher say we start with original line
which is something
and than find the new line
do yk the slope intercept form?
foggy but yes
y=mx+b
yes I remember tha
what r m and b here?
and x is the amount
so if y=2x+b
for every time it goes right by 1
goes up by 2
true
its a graph of a straight line
so it doesn't really have a start or end
a line can be stretched infinitely
If you've understood this form , can we discuss the ques?
Okay so we need the x intercept (a,0)
okay....
Wait you're also supposed to graph it
yes
But might take long
And I do not wish to waste your time
really? u use a diffrent method to solve the equation?
So first we rewrite the equation in this form
mhm ic
which question do u want to use
No, to plot the graph. Just find two soln ,plot them,join them
First one
ques. 18?
Which one do u want to start with
whatever you think works best to help me learn how to this
Oh to learn
Oh I forgot to say
Thxs so much for teaching me, I'm gonna have a test tmr and I'm stressing out. You teaching me means a lot to me. So thank you so much. Now back to math
question 18 says
y = 2x+4
Good so, can u compare the general form and this eqn to find m and b?
So first we need find slope and y-intercept right....
Acc to the method in the pic ,yes
In y=mx+b m is slope and the y is y-intercept
so 2 is slope
but doesn't say y intercept?
y = 2x+4
No b is y intercept
Thats an eqn in x and y , hence they are can take different values
Yessss
So our b is (0,4)
Yes
2/1 =m
Every time it goes up 2 goes right 1 I believe or other way around😅
2rise, 1run yes
Eh not really
You just need this but yeah all others are valid
Now you've got 2 points ,join em you've got a line
Now we've got our graph
ok...
About x intercept(a,0)
We can see y=0
We can solve for a ,by substituting in eqn
why the dots...
oh nothing just idk u already got our graph
I was making it
Here I have it
Oh i thought u already graphed it😅
no no
I was planing to gragh on paper
but than saw desmos
..
Yh do tht
YH?
Yeah
well
our math teacher doesn't like us use computers
and say it's not the games, its technology
cause when we don't have it
we must relay on paper
I js wanted u to confirm it using desmos yk
👍
So..did u get the graph?
Ehh again it starts nowhere, 4 is js the y intercept
Yesh
yes
it starts no where
just y-intercept
GCSE Maths revision tutorial video.
For the full list of videos and more revision resources visit www.mathsgenie.co.uk.
Is that all, did we did it🥺 👍
whats this for?
Yep
Ima save the vid
This is js another method
I kinda need to go 🫠
Heh not when you have exams going on:')
Hello everyone I have been taught chapter 3.5 from this wondeful person
however I did not be able
to learn chap 3.6