this seems a nice one really
are you doing sin or cos first?
#help-39
regal herald
gleaming nebula
sin first
regal herald
you have it maximal at x=0
so you would want sin(b(x-c))=1
so b(0-c)=pi/2 would be one since a>0 for example
sin(x)=1 whenever x=pi/2+2kpi
so b(0-c)=pi/2+2kpi
you can just choose different k for different equations
gleaming nebula
right and what does k represent in this case sorry where im from its usually the vertical translation or "d"
but because im dealing with this theyve changed k to d for whatever reason
Right now my equation for a > 0 is 12sin(x+2pi/5)
but a > 0 would also work for 12sin(x-2pi/5) + d
you know what I mean? because the graph could move left or right and both equations should make sense in relation to the origin, I just don't know if theres some sort of rule I forgot
gleaming nebula
i calculated "b" to be 1/4 because from peak to peak is 4 units, and the forumla for period is 2pi/|4| -> 1/4 but im gonna double check that
gleaming nebula
yeah I noticed that aswell, now I'm getting 4?
gleaming nebula
I used a different approach
because 2pi is 360 degrees
so I did it in degrees then switched back to radians afterward
regal herald
what is 2/4
it truly just comes down to this
regal herald
it doesnt
gleaming nebula
then what am I solving for in that case
becaseu I need to use the period to get my b term
regal herald
im simply asking you what is 2/4
gleaming nebula
1/2
regal herald
you have lost me there
gleaming nebula
im trying to use the formula given which was 2pi/|b|
regal herald
we just did
gleaming nebula
yes
regal herald
thats not the equation though actually
gleaming nebula
so is it sin(1/2)(x-c) now?
regal herald
2pi/P=b where P is the period
regal herald
...how
gleaming nebula
thats what was given
gleaming nebula
regardless, im still confused as to what value I include for my c term
regal herald
so we have b=pi/2
gleaming nebula
yeah
regal herald
sin(pi/2 [x-c]) is what were looking at
regal herald
so b(0-c)=pi/2+2kpi
we know sin=1 at x=0 here
so using the above
-pi/2 * c=pi/2+2kpi
c=-2/pi (pi/2+2kpi)=-[1+4k]
this is for sin(b(x-c)), if youre using sin(b(x+c)) then it would be c=1+4k
cosmic reef
@robust oar hai hru with work and all those stuffs its been a long time
pearl pondBOT
@gleaming nebula Has your question been resolved?
robust oar
<@362561562004946945> hai hru with work and all those stuffs its been a long tim...
why you would ping me here
pearl pondBOT
cosmic reef
why you would ping me here
well it was random
cosmic reef
why you would ping me here
remeber me?
pearl pondBOT
Available help channel!
robust oar
remeber me?
.ye
regal herald
yeah that works, that is k=0
pearl pondBOT
yeah that works, that is k=0
regal herald
.close
pearl pondBOT
pearl pondBOT
Available help channel!
pearl pondBOT
versed mica
it does not say to shade anywhere
it does not say to shade anywhere
label the points
(r, theta)
you can write this better
😟
but why
it does not say to shade anywhere
r = 2 and r = 1 + 2cos
polar curves
just like how youd label a point on the graph of a function in cartesian coordinates (x, y) you label the intersection points as (r, theta)
it does not say to shade anywhere
are you trolling?
💀
no like
literally don’t shade anywhere
no shading
versed mica
just like how youd label a point on the graph of a function in cartesian coordin...
do you get this?
you already have the points
you know both r and theta
for both
or 5pi/3 but those would be our thetas
i’m not asking anything
i’m telling you what they want you to do
you’ve done all the work
you just don’t understand their instructions
no because you shaded it
still wrong
they want it like
(r, theta)
(2, pi/3)
(2, 5pi/3)
labeled with a dot or something at those points
pearl pondBOT
@spring crystal Has your question been resolved?
hybrid trail
pearl pondBOT
mystic bison
its the whole thing
mystic bison
well you keep the x
but yea
x is x u dont replace it with 1
i think
maybe im just confused
im used to point slope
hybrid trail
well ur solving for b, no?
u can't have x and b bc they're both variables I think
lemme submit and see if this is the answer
yeahb
mystic bison
i think you need to evaluate the y value at x = 1 too to find the point where its tangent
hybrid trail
hybrid trail
pearl pondBOT
hybrid trail
I converted to $-5x^4x^{1/2} + -2x^{-2}x^{1/2}$
regal herald
use {}
cobalt hinge
I converted to $-5x^4x^{1/2} + -2x^{-2}x^{1/2}$
$-5x^4x^{\frac12}+2x^{-2}x^{\frac12}$?
jolly parrotBOT
;(
hybrid trail
yeah that
cobalt hinge
Hmm. Last term isn’t correct.
regal herald
i think you also forgot to actually differentiate
old flower
looking for some fourier series help, im just super unsure if my calculation is correct
old flower
pearl pondBOT
@old flower Has your question been resolved?
pearl pondBOT
@old flower Has your question been resolved?
sacred fern
pearl pondBOT
sacred fern
hello
i think i need some help on this qustion
im up until a point where i keep overthinking it and that ive done it wrong
so someone could really just go over it with me and ill go from there
harsh gyro
if $P = (x,e^{-x^2})$ then what are the coordinats of $Q$?
jolly parrotBOT
flying_fly
sacred fern
opq would be isoceles right?
versed mica
opq would be isoceles right?
you didn't answer their question
sacred fern
Q=(2x,0)
cobalt hinge
Q=(2x,0)
Good.
So what is OQ? In addition, what is the height of the triangle? Finally, what is the area in terms of OQ and the height?
Then prove the max of the area is 1/sqrt(2e).
pearl pondBOT
@sacred fern Has your question been resolved?
sacred fern
So OQ=2x
and the height =x^-x^2?
pearl pondBOT
cobalt hinge
.reopen
pearl pondBOT
✅
sacred fern
.reopen
cobalt hinge
So OQ=2x
and the height =x^-x^2?
Rather, e^{-x^2}, but yes.
sacred fern
Ok
and then just differentiate right
Okay I think I understand now
I also have to set derivitives to zero right
pearl pondBOT
@sacred fern Has your question been resolved?
pearl pondBOT
@sacred fern Has your question been resolved?
pearl pondBOT
@sacred fern Has your question been resolved?
pearl pondBOT
@sacred fern Has your question been resolved?
fierce sky
I also have to set derivitives to zero right
yes
have you been stuck on that since 4 hours ago
hushed leaf
hi guys
regal herald
are these that {x-L/2} is x-L/2 if x>=L/2 and 0 otherwise?
hushed leaf
yup
regal herald
this is the first time seeing them but this is how im looking at it:
if x>=L/2, then its just (x-L/2) which integrates to (x-L/2)^2 1/2 (x-L/2)^2
if x<L/2 then it is zero, which will integrate to a constant
this constant term from that will be contained in C1 when you look at the expression for the cases of more or less than L/2
if you have some boundary conditions anyway
hushed leaf
how does integration p(x-L/2) get me p/2(x-L/2)^2?
regal herald
<@&268886789983436800>
hushed leaf
when i expand it out it does not integrate like that
regal herald
sorry i wrote something wrong in there
(x-L/2) integrates to 1/2 (x-L/2)^2
you can check that with a very quick chain rule
hushed leaf
(x-L/2) integrates to 1/2 (x-L/2)^2
you can check that with a very quick chain ...
theres chain rule for integration?!
regal herald
ive only looked at the wiki for these for a minute or so
but theres nothing to expand in {x-L/2}
jolly parrotBOT
hushed leaf
is this wrong?
regal herald
i dont think you can split them like that
i would just look at it as if you were integrating (x+b)^n
which is simply 1/(n+1) (x+b)^(n+1)
and here n=1 for the first integral
regal herald
P{x-L/2}=P(x-L/2) if x>=L/2
=0 if x<L/2
might be fine actually
though i dont see a big benefit here
regal herald
so we want to check if int{x-L/2}={ int(x-L/2) }?
hushed leaf
yeah i think we cant expand like that
regal herald
1/2 {x-L/2}^2 +Q for the left
for the right
{1/2 x^2 -L/2 x} = 1/2 {x^2 - Lx} = 1/2{(x-L/2)^2 - L/2} + W
now the brackets say we have 1/2((x-L/2)^2-L/2)+W if (x-L/2)^2>=L/2 and i think that has changed our conditions unless i did something
so no good
regal herald
np
dense iris
pearl pondBOT
dense iris
2c got me lost
already first 2 steps i got wrong
why are we binomial distributioning this thing
.close
wild fable
not sure how to start
pearl pondBOT
not sure how to start
compact ridge
not sure how to start
PQ cross PR
wild fable
did you find the plane yet
ill try that now
wild fable
PQ cross PR
$$
\vec{PQ} = \langle 2, 3, -4 \rangle
$$
$$
\vec{PR} = \langle 5, 4, -2 \rangle
$$
jolly parrotBOT
water beam
wild fable
ok and i take the cross product of that $$
\vec{PQ} \times \vec{PR} = \langle 10, -16, -7 \rangle
$$
jolly parrotBOT
water beam
wild fable
so i get this
wild fable
PQ cross PR
what do i do then?
frozen lantern
@wild fable what does the cross prod give you?
compact ridge
not sure how to start
it says you need a unit vector, so
and the first component must be positive, just saying
wild fable
<@722683408190406667> what does the cross prod give you?
like conceptually?
it gives me a vector orthogonal to PQ and PR
frozen lantern
mmm okay
frozen lantern
it is im just checking
iron basin
**water beam**
now you make it a unit vector
note that you could also have taken PR cross PQ
that would have given the negative of this vector
you decide which of the two to choose using the condition
of positive first component
wild fable
now you make it a unit vector
so using $\hat{v} = \frac{\vec{v}}{|\vec{v}|}$ i get $$
\hat{v} = \frac{1}{\sqrt{405}} \langle 10, -16, -7 \rangle$$
jolly parrotBOT
water beam
wild fable
is that right?
the first component is positive but it doesnt match any of my answers Lol
wait 305?
i got 405
something wen wrong
sharp smelt
wild fable
im looking at options
oh wait
they simplified the sqrt
so its -7/9sqrt5
ok got it
.close
pearl pondBOT
jovial kiln
oh my! thank you for your generous offer. how shall i redeem it?
pearl pondBOT
pearl pondBOT
Available help channel!
lime river
I was able to show that both sequences are monotone
But I'm stuck on how to show that the sequence xn is bounded
lime river
Did you get that yn is incresing or decresing?
Increasing
tired helm
Are you sure? Because i got that yn is decreasing
even if i'm wrong, since x1 <= y1, you'll get that y2 <= y1 so it's definitely not increasing
lime river
Are you sure? Because i got that yn is decreasing
even if i'm wrong, since x1 <...
Ahh yes mb
xn is increasing and yn is decreasing so yn is bounded
And since xn <= yn it must be that xn is bounded
I'm dum ig
Anyways thank you
tired helm
You don't know that xn <= yn, at least not yet
Oh wait
AG inequality
I got that xn <= yn and xn >=0, forall n
So yn >= 0 forall n
And i got yn <= y1, forall n
So you have bounds
pearl pondBOT
@lime river Has your question been resolved?
lime river
So you have bounds
Yup I got that too
lime river
You don't know that xn <= yn, at least not yet
Since xn <= yn we have
xn+1 = √xnyn > √xn² = xn
Thus xn+1 > xn
cerulean locust
If i have any equation like this or
Sinx+cosx=0
How can i solve and making sure i don’t divide by zero and not losing any answers
eager jewel
If i have any equation like this or
Sinx+cosx=0
How can i solve and making sur...
graphical approach
jolly parrotBOT
eager jewel
in this case 3 sin x = sin x / cos x
3 cos x = 1
cos x = 1/3
draw graph of cos x from 0 to 2pi and see how many times y = 1/3
or another method would be write the general solution
cerulean locust
in this case 3 sin x = sin x / cos x
3 cos x = 1
cos x = 1/3
But what if sinx =0
eager jewel
same thing?
cursive wraith
same thing?
Well you can't forget the solutions of 3sin(x) = tan(x) that arise when sin(x)=0
eager jewel
Well you can't forget the solutions of 3sin(x) = tan(x) that arise when sin(x)=0
yes so make the graph for sin x = 0 as well
past perch
graphical method is def the best option here
cursive wraith
But what if sinx =0
Yes you have to split the cases between cos(x) = 1/3 and sin(x) = 0
toxic lichen
If i have any equation like this or
Sinx+cosx=0
How can i solve and making sur...
explicitly account for any division by a maybe-zero that you're about to do
cursive wraith
If "drawing a graph" helps then sure
toxic lichen
eg if you're thinking about dividing by cos(x) work out exactly what happens when cos(x)=0
cursive wraith
Here since it's an MCQ then finding the number of solutions by graphing is ok
toxic lichen
this way, even if you lose solutions, you will have taken them into account and can recover them that way
eager jewel
Here since it's an MCQ then finding the **number** of solutions by graphing is o...
how does it matter if its an mcq or not
oh "number"
👍
cobalt hinge
If i have any equation like this or
Sinx+cosx=0
How can i solve and making sur...
You should also note that in general, the amount of solutions for a standard interval (i.e., 0<=x<=2pi or 0<=x<=360 degrees) of cos(x)=a or sin(x)=a for aE(-1, 1) will always be 2.
If a=1, -1, it varies based on whether it is sine or cosine.
cerulean locust
Yes you have to split the cases between cos(x) = 1/3 and sin(x) = 0
I can make this in all equations right taking a case where what im dividing by is zero
cerulean locust
eg if you're thinking about dividing by cos(x) work out exactly what happens whe...
I make this in all equations right?
toxic lichen
...yes
cerulean locust
...yes
And if i substitute when sinx=0
And both sides aren’t equal so it’s not a real solution ?
toxic lichen
well, you've looked at what happens when sin(x) = 0. and your conclusion is that there's no solutions to be found there.
so yes now you can divide by sin(x).
cerulean locust
so yes now you can divide by sin(x).
And if it’s zero it take this solution and continue dividing by it so I didn’t lose anything right?
toxic lichen
...i am not sure what you mean.
maybe better if you just show your work and i tell you if it's good or not.
cerulean locust
...i am not sure what you mean.
I mean if i knew that the something i divide by maybe equal zero (sinx=0)
I take the solutions when sinx=0
and then i can divide the equation by sinx and there is no problem
pearl pondBOT
Available help channel!
molten latch
I finished a quiz and i wonder how is the answer to this "A".
I I arrived at The second image I sent so I thought it would be E (None of the above)
molten latch
Also as far as I know the derivative of tan is sec2 not sin2
Is this a mistake by the professor?
lime crest
No no, you were right, it's just that you didn't develop your expression good enough so you could identify your result with the answer
What if you multiply top and bottom by cos²(x+y) so that mess of a fraction looks better ?
See what that gives you
@molten latch
pearl pondBOT
@molten latch Has your question been resolved?
pulsar stump
why here i can sub x=sinh t ?
pearl pondBOT
why here i can sub x=sinh t ?
toxic lichen
try it and see what happens
you may need the identity $\cosh^2(t) - \sinh^2(t) = 1$
jolly parrotBOT
Ann
toxic lichen
also you always CAN sub that
pulsar stump
you may need the identity $\cosh^2(t) - \sinh^2(t) = 1$
already proved it
pulsar stump
try it and see what happens
i mean why is it legal?
toxic lichen
do you really mean legal or do you mean helpful
pulsar stump
legal
toxic lichen
sinh : R -> R is a bijective function. you can pretend you are substituting t := sinh^-1(x).
earnest girder
I need help
toxic lichen
I need help
!occupied
pearl pondBOT
I need help
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
pulsar stump
i know ever did, and know this is legal:
t=t(x)=sinh x
dt = (sinh x)` dx
pulsar stump
sinh : R -> R is a bijective function. you can pretend you are substituting t :=...
i see, how can i prove bijection for sinh x?
toxic lichen
sinh is a strictly increasing and differentiable (thus continuous) function, and approaches ±∞ as x goes to ±∞ respectively.
well, that or you can straight up find its inverse
pulsar stump
sinh is a strictly increasing and differentiable (thus continuous) function, and...
we dont have a statement that says this => invertible
toxic lichen
which is some mix of logs and roots
pulsar stump
yes but idk how to go about it
toxic lichen
$\sinh(x) = \frac{e^x - e^{-x}}{2}$
jolly parrotBOT
Ann
toxic lichen
start with $\frac{e^y - e^{-y}}{2} = x$. solve for $y$. you will get a thing that has some logarithms and some roots in it.
jolly parrotBOT
Ann
toxic lichen
substituting z := e^y and making a quadratic equation will be helpful along the way.
pulsar stump
substituting z := e^y and making a quadratic equation will be helpful along the ...
ty, ill try that
pearl pondBOT
@pulsar stump Has your question been resolved?
neon jolt
hi
neon jolt
how to accurately make the er model sometimes I dont get the same solution
for the databases
for example like I did it include the possibility that play list may be empty cuz that does not make sense
but the sol shows that it may be empty
so how to figure that out from the wording of the question?
frozen lantern
....what?
lone smelt
what even
regal herald
a playlist can be empty, they typically are when you first create them after all
though i dont think i have a good grasp of what youre asking
pearl pondBOT
@neon jolt Has your question been resolved?
neon jolt
....**what?**
Basically what I am asking.. how to do the er model based on the description given
"a playlist may include many songs, and a song may be included by one playlist at most."
Solution shows that it may be zero or many
But I thought that logically a playlist may not be nothing it must contain at least 1 or many
neon jolt
a playlist can be empty, they typically are when you first create them after all...
But sometimes we say it's one or many
Like how a playlist be empty?
Isn't more logical that it be one or many?
regal herald
you have to create a playlist before you can add anything to it
otherwise theres nothing to be adding songs to
so it may be empty
neon jolt
otherwise theres nothing to be adding songs to
Can we say that words like "may be" , "at most " means a relationship that may be zero or more?
regal herald
'may include many songs' does imply there can be zero songs
'a song may be included by one playlist at most' just means the song can only be in a single playlist, or none at all
'may include' I would take to mean: can include, but doesnt have to
'at most' means the upper limit, so 'at most one' means 1 or less, [1 or 0 here]
neon jolt
'at most' means the upper limit, so 'at most one' means 1 or less, [1 or 0 here]
I see
Thank you very much
. close
.close
pearl pondBOT
pearl pondBOT
Available help channel!
fresh mesa
can i use this channel
pearl pondBOT
can i use this channel
fresh mesa
oop
robust kraken
yes
frozen lantern
can i use this channel
apparently yeah
fresh mesa
HI
okay
pls n ty
i get the first step, like the factors that multiply to 700 n shit
but like
idk what to do after
minor meteor
idk what to do after
U want help with the 9th question?
minor meteor
like everything
8th too?
minor meteor
Factor 700
minor meteor
yes but factor it in another way such that one of the factor is a perfect square
fresh mesa
what does perfect square mean
minor meteor
what r the factors?
fresh mesa
what r the factors?
100 x 7?
minor meteor
yupp
fresh mesa
ya
fresh mesa
yeah
minor meteor
I don't think it can be simplified further
fresh mesa
7 cant
minor meteor
So whats the answer for 8th
fresh mesa
but 100 can
minor meteor
Ya
minor meteor
bro theres more 😭
R u talking abt the 9th one?
fresh mesa
no 8
minor meteor
i just told u how to do it
fresh mesa
oh
minor meteor
Such that one of the factors is a perfect square
fresh mesa
ill try
fresh mesa
gurl use brian
WHY DO U THINK IM HERE
minor meteor
BRAIN*
minor meteor
WHY DO U THINK IM HERE
im sry
fresh mesa
bro im actually
so bad at math
i had this test due like last week
but i skipped so i wouldnt have to take it
minor meteor
bruh
minor meteor
U want me to solve ur test
fresh mesa
ima try
minor meteor
💀
minor meteor
who?
fresh mesa
my teacher
fresh mesa
yes u r
minor meteor
.close
fresh mesa
mf
minor meteor
you'll get banned
fresh mesa
??
minor meteor
no slurs
fresh mesa
thats not a slur
minor meteor
Ok
simple jasper
Is the smaller text below the question the answer you put?
simple jasper
Yeah, AI isn't always the greatest for math
First, I'm going to say this, consider constants (actual numbers) separately from the variables
fresh mesa
okok
simple jasper
hmm
graceful yacht
Do you mean coefficients when you mention constants?
fresh mesa
😭
fresh mesa
kk
simple jasper
and looking at x^21, what could that be rewritten as?
simple jasper
yep!
simple jasper
and what about the y part?
fresh mesa
simple jasper
Only considering numbers smaller than 16, what is the closest number that is divisble by 3?
fresh mesa
15!!!
simple jasper
yes and divide by 3?
fresh mesa
5!!!!
simple jasper
That remainder, the numerator is the remaining variable (x or y (or any other letter/symbol that isn't defined)) left in the cbroot (or other root)
So, try writing out the simplified form
<@&268886789983436800>
fresh mesa
oh hn
simple jasper
Thank you mods
fresh mesa
hmm
simple jasper
(the math you have written down here (5^3 * 3) is correct)
fresh mesa
yay
fresh mesa
So, try writing out the simplified form
IDK
simple jasper
So, try writing out the simplified form
Let me reword this question to be more discord typing friendly
fresh mesa
😿
simple jasper
What is going to go outside the cube root?
fresh mesa
HELP
simple jasper
What about the x component
fresh mesa
ok
fresh mesa
What about the x component
so 7?
simple jasper
Write it as y^(?)
fresh mesa
y^5
fresh mesa
whats the cube root again
simple jasper
$\sqrt[3]{x}$
jolly parrotBOT
dragonbreath
simple jasper
We've moved the 5^3 outside of the cuberoot as 5 (because 3 * 1/3 = 1)
fresh mesa
hold on ima eat and come back
simple jasper
simple jasper
Probably yeah, ping me
simple jasper
Saying this as a reminder and so it doesn't time out: x root also equals a power of 1/x
pearl pondBOT
@fresh mesa Has your question been resolved?
simple jasper
Lol
fresh mesa
😿
simple jasper
<@829442771714310145> Has your question been resolved?
Quick hit x on this
fresh mesa
kk
jolly parrotBOT
dragonbreath
simple jasper
The like
[Number] root?
fresh mesa
yess
simple jasper
What is the number that is going to go inside the root?
simple jasper
Yes
fresh mesa
sorry im backreading
simple jasper
You're good
fresh mesa
3
simple jasper
Yes
fresh mesa
YUPP
simple jasper
Do you think there will be any x remaining inside the cube root?
fresh mesa
no
simple jasper
How many?
fresh mesa
Only considering numbers smaller than 16, what is the closest number that is div...
this
right
fresh mesa
squareroot 3 y
fresh mesa
🎉
jolly parrotBOT
dragonbreath
simple jasper
Yep!
fresh mesa
OMG
WTF
i put it in its right
ilysm omg
u made it super simple for me
i think i get it now
look its marked right
wait im gonna try doing some by myself now but can i keep this open just in case
tysm omg
simple jasper
Yippee
pearl pondBOT
@fresh mesa Has your question been resolved?
simple jasper
@fresh mesa Do you still have questions?
fresh mesa
<@829442771714310145> Do you still have questions?
i havent started another problem, ill do no 8 rn and ill lyk if i do
fresh mesa
(16 - 15)/3
so is it like this again?
simple jasper
yes
simple jasper
5 isnt divisble by 5
I think you mean 5 isn't divisible by 2?
simple jasper
yes
fresh mesa
Go ahead and try to put together the outside of the square root
10x^2y^6
simple jasper
yes, and the inside?
fresh mesa
yes, and the inside?
IDK
wai
7xy
because 7 was 1 7, then we were off by one for both the x and y
simple jasper
yes
simple jasper
Is question 6 still incorrect?
fresh mesa
Is question 6 still incorrect?
yes
dw ab that tho
this is for another problem
how do i get the first number again
like before x and y
i promiseee this is like the laast one
i almsot have it down!
simple jasper
Consider dealing with the 2^5 like you would x^5
fresh mesa
Consider dealing with the 2^5 like you would x^5
wait
i mean like the 448
i forgot what to do. w it
simple jasper
I mean you've broken it down
fresh mesa
yes
simple jasper
448
8 * 56
4 * (2) * 8 * (7)
(2) * (2) * (2) * 4 * (2) * (7)
(2) * (2) * (2) * (2) * (2) * (2) * (7)
It's not 2^5 though
simple jasper
Look at the 2 can you move it outside the cube root?
simple jasper
Consider dealing with the 2^5 like you would x^5
This but since it is 2^6, treat it like x^6
fresh mesa
kk
fresh mesa
i took a quick nap
fresh mesa
This but since it is 2^6, treat it like x^6
wdym
like do i do that thing where i count how many times it goes inside
the 3
restive hornet
it takes a whole village to help me
You're fine
restive hornet
Do you know how fractional exponents work
fresh mesa
no
can u help me w like the 448
what do i do w it
i already factored it or whatever
its 2^6 x 7
restive hornet
i already factored it or whatever
did you do the prime factorization
fresh mesa
but i forgot what to do w those numbers
restive hornet
its 2^6 x 7
Oh alr
You want to find a number thats a perfect cube that you can factor
Perfect cubes will have an exponent which is a multiple of 3
Example 3, 6, 9, 12 and so on
Do you see a 6 as any exponents?
fresh mesa
i dont know
restive hornet
i dont know
Alr
simple jasper
How would you deal with $\sqrt[3]{x^6}$
jolly parrotBOT
dragonbreath
restive hornet
Do you know the exponent rule where a^(b times c) is equal to (a^b)^c
restive hornet
How would you deal with $\sqrt[3]{x^6}$
She needs help with the 448 part
restive hornet
Do you know the exponent rule where a^(b times c) is equal to (a^b)^c
@fresh mesa
fresh mesa
no idk what that is
simple jasper
They've already broken it down to 2^6 * 7
restive hornet
no idk what that is
Hmm
Here
a is 2
and xy=6
How do we break it apart so we get 3?
@fresh mesa \
fresh mesa
**dragonbreath**
isnt it 3
fresh mesa
How do we break it apart so we get 3?
divide by 2
restive hornet
divide by 2
Yeah
2^(2)(3)
We can rewrite this as (2^2)^3
2^2=4
So we can rewrite 2^6 as 4^3
This should help
vale hill
dawg what
fresh mesa
fresh mesa
😭
fresh mesa
finish this problem for me
or help
vale hill
ok did you break down 448
fresh mesa
yes
vale hill
what is it
fresh mesa
2^6 x 7
fresh mesa
OH
vale hill
then it is the 3rd root right
so you get 4
and a 7 is still under the root
4 * x^3 * y^7 * cuberoot(7)
yw
pearl pondBOT
@fresh mesa Has your question been resolved?
pearl pondBOT
@fresh mesa Has your question been resolved?
lone kite
@fresh mesa still need help?
pearl pondBOT
@fresh mesa Has your question been resolved?
twilit prairie
tf
fair path
**dragonbreath**
x^6x1/3
x^2
fresh mesa
What's the problem?
okay so the 448
is
2^5 x 7
but idk what to do next
like i do but i cant understand it
lone kite
Hold on.
I'll write it down because writing here will make it a mess.
@fresh mesa have you tried extracting the cuberoot by parts?
Hint: doing cuberoot is essentially raising the power by 1/3.
fresh mesa
how do i do that
lone kite
how do i do that
Try doing it and show my your work.
What do you think?
It's okay to get it wrong, I just need to know what you get wrong.
fresh mesa
kk
lone kite
@fresh mesa please ping me when you're done.
lone kite
What you go wrong here is forgetting that it's a cuberoot.
You should find a factor of 448 that is a perfect cube.
56 is not one of them.
fresh mesa
64
lone kite
64
Correct.
You're implying that 64 is a factor of 448.
What do you multiply 64 with to get 448?
@fresh mesa
lone kite
Perfect.
Also, isa.
I have an advice.
I use this technique when dealing with exponents.
fresh mesa
what is itt
lone kite
Cuberoot is essentially division in exponents.
Meaning divide by 3.
It might be intuitive when you write it that way.
lone kite
@fresh mesa anything else I should know?
If not, you can close this one.
.close
I'll be leaving now, so I hope that I answered your question.
open rivet
!noping
pearl pondBOT
Please do not ping individual helpers unprompted.
open rivet
dont ping me cuh
compact ridge
<@&268886789983436800> mass spam ping of mods
unborn abyss
yes mmhmm and you immediately pang the server owner despite the fact that they're not online
iron basin
can you explain what you tried
open rivet
why would you ping the owner of a 250k member server 💀
iron basin
the perimeter?
in feet?
you should get something very close to 400
like 399.5
by 42 units
can you show all the lengths you added up
maybe then we can figure out
why did you leave a portion of it
like just 21.5 instead of another 63
while you considered pairs of other lengths
unborn abyss
oh my god dude
unborn abyss
don't ping me - or any other mods - again, or you'll be muted
iron basin
at the left you took the top 21.5 feet and left the bottom
this
you didn't include the dotted line and did an error in calculating a missing side
come on
unborn abyss
alright
iron basin
ragebait used to be believable
unborn abyss
you've been given enough information
it's time for you to read and understand it
they even drew out a nice drawing for you
for the work you turned in? i'd probably give you 1 or 2 at most because it's so incredibly messy
yes
frozen lantern
likely spammer huh
iron basin
maybe
unborn abyss
i have a masters in math and computer science and taught cryptography at a university level
unborn abyss
find a pencil
iron basin
the perimeter
unborn abyss
no
anyway i think unless you are willing to put in the effort to redo this problem and figure out the correct answer then this channel has run its course
midnight haven
Is this the problem?
unborn abyss
nope
midnight haven
You have messed page but wait let me read the question
open rivet
i have a masters in math and computer science and taught cryptography at a unive...
crypto 🤑
open rivet
if i was your teacher, i would give you 0
give you a 0 for the exam aswell
and make you redo the year
yes, you
unborn abyss
if this is your homework you should get another piece of paper and write out the solution without crossing stuff out, then staple that to the homework paper
midnight haven
Oh
open rivet
yes
midnight haven
iron basin
bruh
pearl pondBOT
midnight haven
The next dimension of the bottom lawn would be 20f
iron basin
it WAS ragebait then
unborn abyss
thank you to blurple and valeheart for the effort
open rivet
you're an alt account of a banned user
it took you this long to realise? 🙂
midnight haven
you're an alt account of a banned user
💀
unborn abyss
i appreciate it even if they didn't
unborn abyss
it took you this long to realise? 🙂
i'd never really seen this person before
spiral pivot
it WAS ragebait then
I DMed you a while back to tell you this 💀
pearl pondBOT
Available help channel!
small ingot
small ingot
how come they compare the series to 1/rootn ?
why wont direct comparison like this work?
hazy pilot
sqrt(n)/n is not equal to 1/n^(3/2)
small ingot
sqrt(n)/n is not equal to 1/n^(3/2)
ohhh its 1/n^1/2
so it diverges by p series
okay thank u
pearl pondBOT
Available help channel!
fresh mesa
yooo
fresh mesa
.close
pearl pondBOT
toxic lichen
...
frozen lantern
the what
plain finch
pearl pondBOT
pearl pondBOT
Available help channel!