#help-39
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anything larger and more encompassing than complex?
technically you have things like quarternions/octonions/sedenions
the rest of the cayley-dickson algebras
then things like split-complex/split-quaternions/etc
things after quaternions and split-complex are rarely used
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I need to know how can I show if a sequence is convergent or not I n-langugage , using induction , ratio test , or an+1-an test , I need to show that in a strict form
I have been stuck on these for the past day lol
i just need help with one or 2 diffferent problems , just to understand this process step by step
you have to spam this https://en.wikipedia.org/wiki/Monotone_convergence_theorem
In the mathematical field of real analysis, the monotone convergence theorem is any of a number of related theorems proving the good convergence behaviour of monotonic sequences, i.e. sequences that are non-increasing, or non-decreasing. In its simplest form, it says that a non-decreasing bounded-above sequence of real numbers
...
so that your problem often becomes bounding then studying the variations
for example for j, you should prove that 2 <= an <= 2.5, then show that an+1 >= an
so it converges
lol , yeah , but with the sqrts for example its kinda confusing , ex , its easy for a_n =1/n that it gets smaller but with ex , a_n= sqrt(2_an-1) it aint that easy (for me )hehe
for a) same idea, the first ones are easier than the last
an+1 = sqrt(3an)
if 1 <= an <= an+1 <= 3
1 <= sqrt(3) <= sqrt(3an) = an+1 <= sqrt(3an+1) = an+2 <= sqrt(3²) = 3
by induction, an is bounded and non decreasing
so it converges
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I have a crazy question with a lot of urgency. So basically I’ve been studying super hard for an entrance exam that you have to do in IB Sweden. It’s tomorrow so I’ve been grinding out mock entrance exams but this one doesn’t have an answer key. I was trying to get ChatGPT to make an answer key but it was dumber than me I’m basically asking if anyone smart could complete this mock test so I compare see what I got wrong and what the actual right answer is. Thank you so much.
we don't do your problem(s) for you sorry
No no no read the message I sent
It’s nothing like that
i doubt anyone will help will an entire paper. do u not have a markscheme?
Nah they gave a marksheme for the English not math
This is like an example test for what may be on the finale that decides if I get into gymnasium, skola
I will, im slightly bored
THANK YOU SO MUCH MAN 🙏🙏 somehow even I got all of those even though I’m not the best at math to be honest 😂
Don’t take this the wrong way but I am very happy you are bored 😂🙌
Ahhh I had I feeling I got the semi circle wrong but if you don’t mind me asking how it 9 5/8 I asked a few other people also and they agreed with 9/16 as well as ChatGPT but one other person also said 5/8
you can imagine cutting and pasting the shaded triangles
the blue line denotes the boundary of the shaded part
yep
OHHH THAT MAKES SO MUCH SENSE NOW THANK YOU
what was your answer to the semi-circle one?
did you count the bottom line too?
It was 12 cm tbh I don’t know how I got that
it should be pi/2 * 8 + 8 = 3/2 * 8 + 8 = 12 + 8 = 20
Yeah, 12 is just the curved part
you didnt count the bottom diameter
Ohhhh that would make sense thank you I was sure something looked off but I could figure out what
this one is sus though, x + y should be extremely close to 1
x and y seem to be the same distance from 0.5
meaning their average would be exactly 0.5
and their sum would then be exactly 1
Yeah this one made zero sense to me even in the slightest I was not taught it at all
the way I would approach is is just observing that x is slightly below 0.5 and y is slightly above 0.5
I thought it was d send it is like 0.5 of the line if that makes sense
meaning that their total should be around 0.5 + 0.5
yeah, that
wait
D?
Yeah
I'd say the question is wrong
I thought sense it was half of the line it’s self it could represent d
it could be either C or D
im 99% sure that if we actually measured it, the sum would be extremely close to 1
Not possible sense it’s the official 2017 exam of a major IB entrance test
like extremely close, 1mm close
Ahhh okayyy
I'd probably guess C though
because it's a bit closer to 1 than D
Yeah but I was thinking sense if you look the line keeps going after to and I can see that D is perfectly centered to the line if you forget about 0 and 2
So I think logically it would make more sense but I may be wrong
x + y is red + blue (drawn as red + light blue)
Does this help at all
Yeah that’s true, I just asked ChatGPT for a second opinion and it said D so idk
It may be wrong tho
this mark here is exactly 0.5
assuming x and y are the same distance from it, then x + y would be exactly 1
Yeah it’s weird that they would have a question that is so up for interpretation on a exam like this ngl
it's not up to interpretation, it would be a good question if only one of the letters was exactly at 1
Yeah that’s what I meant sorry
because x + y is almost exactly 1
Do you mind me asking how you did b because for the life of me I can’t get it
the best way is probably just guessing what x and y are approximately
x seems to be around 0.4
y seems to be around 0.6
y/x would then be 1.5
hmm its probably more like 0.55
,calc 0.55/0.45
Result:
1.2222222222222
yeah, definitely closer
Wait that’s the part I don’t get I feel very stupid for not getting it but how does it become 1.5
let's do different estimate
my first estimate was too bad
y = 0.55
x = 0.45
now y / x = 0.55 / 0.45
= 55 / 45
which is slightly larger than 1
Ohhh I get it now i seeee
or using this, you can ask yourself, how many times is y (the blue one) longer than x (red one)
and you can see that the ratio is definitely above one, since blue is larger
I see the other way seems easier tho ngl
jesus this is such a dumb question
and it's also only slightly larger than 1
the only dumb part about it is part a tbh
otherwise its quite a good question to check your understanding of the number line representation
Man I’m sorry math is not at all my strong suit I struggle a lot with and moving constantly has not allowed me to really study it well so I lack in math skills
do your answers for the exercise 11 match btw?
that's exactly what I was calling dumb
Ye, we can agree on that
I'm criticizing the question, not you
you're good
All except b and d
I think the question is just a very silly and poor question to ask
Ohhhh sorry my bad
no no it's alright lol
I definitely agree with you but ay that’s International baccalaureate for ya
wow, and I thought AP was a bad system
Yeah man tell me about it IB is the worst
And the weird thing is the English part of the test is super easy
I wouldn't classify this question as either "hard" or "easy"; just "stupid"
alright, lets check that
Fair enough but for me all math questions are hard 😂😂
sqrt(bc) - a = sqrt(3*12) - 6 = sqrt(36) - 6 = 6 - 6 = 0
e^2 - b^2 = (-4)^2 - 3^2 = (-4)*(-4) - 9 = 16 - 9 = 7
do you understand where you made the mistake or is sth unclear?
Tbh still unclear im confused how the answer is zero
Can you show how did you calculate it?
I got 36 for it but I have no idea where I calculated it my desk is a mess I’ve been doing math for 10 hours straight 😭
36 is just 3 * 12
thats the bc part
then you need to take the square root of that
since there is $\sqrt{bc}$ in the question
MathIsAlwaysRight
and square root of 36 is 6
and lastly, you need to subtract a
and a is 6
and 6 - 6 is 0
I’m about to ask probably the dumbest question ever
I’ve been doing advanced math for so long I forgot so many basics how do you find square root again? 😭
it's best to remember the square numbers
and if you are lost, you can just guess something
you could start by guessing e.g. 3
3^2 is then 9
too low, guess higher
so maybe try 7
7^2 is 49
too high, guess lower
maybe 5
5^2 is 25
guess higher
6^2 is 36, done
square root of 36 is 6
Wait but why are you multiplying _ by 2?
$\text{x^2 means} x^2$
Ohhhh I get it now this makes sense idk how I forgot that
MathIsAlwaysRight
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What the fuck latex
lmaooo
So the square root is just a number that is squared
yeah, square root is the opposite of squaring
if 5 squared is 25, then square root of 25 is 5
Okay now I get it thank you is there any way you could give me a similar question so I could see if I actually get it or I just think I get it
a = 16
b = 4
c = 14
find sqrt(ab) - c
mildly interesting property of square roots: since $x^{n+m}=x^nx^m$ and you can represent square roots like so: $\sqrt{a}=a^{\frac12}$, a natural consequence is that $\sqrt{ab}=\sqrt a \sqrt b$
00100000
it makes the problem marginally easier
I believe you've made a mistake in your calculations
I believe so 😂
c was 14
so it's sqrt(64) - 14
and you need to respect the order of operations
square root and squaring comes right after parenthesis
Oh you are completely right
so you should start by calculating sqrt(64) and only after that subtract 4
it's better style to use = between lines here
because those 3 dots often are used to mean "therefore"
Ohhh okayyy I think i get it now should I try the same question again or
and you're not really making any implications here, so
it looks better to go
$$2+2$$
$$=4$$
Oh okay will do
Yeah, i think you should try calculating sqrt(64)
00100000
because the way you did sqrt(60) is incorrect
with your style, it looks like "2+2, therefore 4"
which doesn't make sense since neither 2+2 nor 4 are "truth" statements (i.e. true or false)
MathIsAlwaysRight
a natural way to use the three dots is anywhere you need a therefore. for instance: a>0 and b>0, therefore a+b>0
(where I take a>0 and b>0 to be assumptions)
ok honestly what am i even waffling about
I appreciate it though I can’t lie
What do you mean by notation 😂😭
Oh wait what was I supposed to do?
and then it looks like you added a $^2$ to line 2 as well
$$=8-14$$
$$=-6$$
00100000
Oh so I basically put a square on a bunch of stuff that ain’t need it
because when you write $$8^2-14$$, it means $$8\cdot8-14$$
00100000
not quite; it turned it into an incorrect expression
which is worse
Ignore my horrendous handwriting btw
you were trying to say $$\sqrt{64}-14$$ $$=\sqrt{8^2}-14$$ I think
00100000
however, it came out as... something different
Yeah exactly 😂
Do you think you could give me another one to make sure this was not a fluke cuz I feel like I just got lucky or something idk
please note that while $\sqrt{a}^2=\sqrt{a^2}$ for non-negative $a$, you were trying to so $(\sqrt{a})^2=a^2$, which is definitely not generally true
00100000
Ahh so I got 16 correct and 17 but and 18 a and b but not c also I do not remember at all how I got 17 😭
$\frac{\sqrt{13+12}\cdot\left(2+\frac{6\sqrt{4}}{4}\right)}{5}$
MathIsAlwaysRight
oh gosh i committed the terrible latex sin of writing \sqrt{x}^2. i fixed it quickly, but forgive me latex gods
Huh that looks way more difficult for some reason oh god
Ima try it
But don’t have high hopes
lol
ok i need to go study for my own exam tomorrow. for your checking reference, the answer is ||5||
you better not have auto spoilers on
💀
doesnt matter lol, see if you get the same answer
But thanks so much for helping me good luck on you’re exam
True I’m going to try rn
sorry for spoiling lol, but in my humble defense, spoilers exist for a reason!!
😂😂you’re good dw
thank you! good luck to you as well
Appreciate it 🙌
wait bro u r straight up giving him all the answers
isn't this like uhhh, not the spirit of the server
I already did everything and this is a mock test
he already solved those Qs
Btw i got 82.5 💀💀 something def went wrong
oh I see
Six times two?
Yeah
Oops that would make more sense lemme adjust to that
$6\sqrt{4}=6\cdot\sqrt{4}=6\cdot2$
MathIsAlwaysRight
its almost correct
except you only did the top part
which indeed is 25
25 / 5 then simplifies to 5
I’m not gonna lie I completely got this wrong
Lets return back to this one, i think we havent checked it yet
Ohhh yeah you’re right
I got 840 kr somehow which is super embarrassing cuz that looks like the most simple question ever
for 12?
Yeah sorry kr means SEK
how did you do it?
we have tools for that
Oh damn that’s impressive
I see 😂
would you be able to calculate 15% of 900?
Is it 0.15 x 900?
yep, precisely
Sorry I think my brains fried so I just got that one wrong
btw one advice regarding the double-checking thing, I suppose that the exam has a time limit, so it might not always be worth it to waste your time double checking, maybe instead just put up marks on the calculations you performed and in case you'll have enough time, you can return to it and verify the calculations
Yeah I timed my self when doing it and finish with the alarm ringing 😭
Yeah, thats normal, we all get things wrong sometimes
It’s 90 mins no calculator
,calc 900 * 0.15
Result:
135
and then you'd subtract it
Yup thanks for pointing that out
Btw to multiple that I just do 900 x 15 and move over the decimal point right
yep
13 is correct, pretty impressive actually, I'd guess that most students would mess that one up
14 should then be 25 and 20
Yeah I’m not gonna lie I have to admit I waisted a good 10 mins of my time doing that 😭
Shit I got 20 and 20
I thought it was a trick question and both were 20
when we go to 4 blocks to 5 blocks, we are adding 1 block
and 1 block is 25% of 4 blocks
so we are adding 25% to the 4 blocks
Yuppp
I just came to a horrid conclusion I got all of 15 wrong wtf I am so done for
How did I do that
Those are so simple to
I have somehow forgotten the most basic solve for x
It's probably just silly mistakes
17 - 3x = 5
add 3x to both sides
17 = 5 + 3x
subtract 5
12 = 3x
divide by 3
4 = x
(2x-1) / 3 = 7
multiply by 3
2x-1 = 21
add 1
2x = 22
divide by 2
x = 11
3 - 2x = 1 + 2x
try this one
Wait is there anyway to make that bot write it out it’s so confusing looking at the discord text sorry 😭
$$\begin{align}
17 - 3x &= 5 \
17 &= 5 + 3x \
12 &= 3x \
4 &= x
\end{align}$$
MathIsAlwaysRight
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reaction for more information.
(You may edit your message to recompile.)
Okay I’ll try rn
$$\begin{align}
\frac{2x-1}{3} &= 7 \
2x-1 &= 21 \
2x &= 22 \
x &= 11
\end{align}$$
MathIsAlwaysRight
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(You may edit your message to recompile.)
the general strategy for simple equations is
- get rid of fractions (by multiplying everything by the denominator(s))
- move everything with x to one side and everything without x to the other side (by adding / subtracting the terms)
- at this point you should have sth like 3x = 6, so you just divide by whatever is in front of x
Yep, thats it
Ahhh i see
now the last step is dividing by 4
Wait should I divide both by 2?
you could
you would get 1 = 2x
but you need x
not 2x
so you need to divide by 2 again
if you just straight up divide by whatever is in front of x, you will get there in one step
Wait is the answer a decimal?
in this case, it's 4
yep
Pre DP
yea same thing
Yea
i did IB in sweden lol
Oh fr
yea
That’s cool 😂 what school?
AYYYYY
Sorry for the finger not tryna dox
ISH 💪💪💪
That’s my third option though can’t lie
Yeah not cause it’s not good but because it’s hours away
I just put it down cuz why not
Anyway
oh wow
I’m getting a bit distracted
woops
oh wait
Any tips
rest
(says me who also has an exam tomorrow)
You’re probably right test is tmr at 12:45 I can study in the morning
art do you go any recommendations on what I could study tmr morning from you’re experience
my exam looked VERY different so i don't think i can help you much (i think it's because i didn't do IB before whatsoever)
but my advice is that you don't have to ace everything
Ahhh okay makes send do you know at all if bearings would be on it that’s just the one thing I’ve been wondering
You probably don’t know but yea 😭
It's important to know what you're good at tho, then you can efficiently manage your time during the exam
Okay well you guys are definitely right I should go to sleep
absolutely
Yeah the no calculator is gonna be a pain for tedious stuff only having 90mins
Well wish me luck for tmr ima study in the morning and hope for the best because this makes or breaks my future
Good night and good luck tomorrow!
hope it goes well! good luck!
Ohh btw I skipped 2 levels of myp so if I seem a bit dumb it’s cuz I got put hella up
Anyways
Good night yall
Thank you so much for the help
You don’t understand how much you saved me
👍👍
Np, good night :)
(you can close this with .close btw)
otherwise the bot would wake you up with ping
ill just close this, feel free to reopen it if needed
.close
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idk
Try to draw it
What is slope?
idk mAB =?
U need to draw that quadrilateral
i dunno how to draw a 1/7 to life in a quadrilateral form in a paper
No
I mean, just draw a quadrilateral ABCD
PQ = QR = RS = SP, right?
ye
Isnt is a square?
ye
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I don't know, where did you go wrong?
It looks right to me
You just haven't finished
Did you definitely copy down the equatinos correctly then?
No you didn't, you put a minus sign before the c in line 2
Hahaha
It happens sometimes
Happens to everyone dw
yeah just needa be careful
At least u used ur brain for a while
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,rotate
@manic cape Has your question been resolved?
try rephrasing the questions into equations
like for this one, try to make a "can of paint" into a variable like X
,rotate
there we go
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oop
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what
@thorny agate
first
motorcycle?
,
got it
with these sorts of story problems it's best to start by establishing your variables, the things you don't know the exact value for
Let x be the number of girls in the school
and let y be the number of boys
as we don't know how many of those are there either
the teacher never said y
hm
the question is only asking for girl tho
No, with ratios, you can only multiply the sides by the same number.
Owh
yes, but only using girls, theres no way to find the number
idk
Use boys, but not as variables
so lets start with x=number of girls and y=number of boys
there is a total number of 3460
I thought i could use that
im dumb
yes, you will use that
ok
you know that boys+girls=3460
yes
is there any other information that can be used to form an equation
Im a highschool student
its gonna turn out to be a system of equations, you can't just shove all of the info into one equation
my teacher used fraction idk and i think he devided
yeh
We can calculate % and use it
hm i think he did it in a different way than i'm thinking of doing it
but theyre both valid ways
Middle School method
girl is it possible for you to help people with math without insulting them
You've used the sentence "A school has 3460 students." to get x + y = 3460. What other information do they give?
are you asking me or the person who needs help? /gen
shes a girl
Oh, sorry.
Merai, you've used the sentence "A school has 3460 students." to get x + y = 3460. What other information do they give?
Dude, dont invert my purpose, im not insulting
Because you're going to do it differently than I learned in middle school.
@limpid lily
Yes, that information.
OK, 31 what to 44 what?
31 are the boys and 44 are thi girls
yes
Does that make sense?
yes but how did he get 600
OK, now you can turn the ratios into normal fractions.
y/x = 31/44.
Then you can solve for either y or x.
What do you get for either one of them?
no only for girls
OK, then solve for x.
$\frac{x}{y} = \frac{44}{31}$
have patience, this person knows what theyre doing and you need to use boys to find girls, which is why its in the problem
SELVATOR
do i devide the 3460 with 44
It's y/x.
ok
so what now
do i add 31 + 44
Oh, I see.
it gave me 75
What did you get for x?
i just added them
Can you show your work?
ok
wait
i got 75 as the denominator
but his answer was 600
I still don't know how he got it
The percentage of girls is higher than that of boys
It couldn't
idk im confused
3460 ÷ 2 = 1730
idk
2029.72
Let's say 2030
Girls = 2030
Boys = 3460 - 2030 = 1430
Owh
Recheck the question
Asking about the difference between boys and girls
It is: girls - boys = 2030 - 1430 = 600
He asks you about the number of girls more than boys.
I added girls + boys = 44 + 31 = 75
how did you get 100
SELVATOR
That means, we have 46.13 group of 75
We multiply it by 44 (girls ratio)
We add a + b = T
And we dived Total ÷ T
And multiplying by a or b (depends on what u need)
so for the veronica question is it the same formula ?
or it depend on the question
No, we will use percentage%
how
$5 \to 10$
SELVATOR
$? \to 24$
SELVATOR
4x6
SELVATOR
Fast way to calculate it
1.2 over 100
$24 \times \frac{5}{10} = 24 \times \frac12 = \frac{24}{2} = 12L$
SELVATOR
That's math
Simple way to calcul it
you got 12 or 1.2
Calcul it again, and use () in ur phone calculator
U need to understand the idea
So u can use it by urself
If u have 5 : 10
Add 5 to 10
And devide (total × 5) ÷ (10+5)
so I just gather all the numbers up and multiply to square root
Or (total × 10) ÷(10+5)
why 10 and 5
Nope
lets say ur talking about it won't you use the same formula ?
70 devide by 30
I remember solving these problems in primary school.
23
But I forgot about it after I grew up
Im gr 10
SELVATOR
$?? \to 30$
SELVATOR
23
We multiply 30 by 70, and devide rhe result by 100
$\frac{30 \times 70}{100}$
SELVATOR
I divided 70 with 30 and then I got 2.3 and then 2.3 squared 100 it gave me 23
ur answer is 21 ?
No
We put amount in left
And percentage in right
To find ??
We multiply sideways, and devide them by the opposite sideway of ??
So we get ??
@manic cape
Try it
$\frac{36 \times 100}{50} = ??$
SELVATOR
@manic cape Has your question been resolved?
72
This
It is multiplication
ok
What's ur question
Ok it says Jill is selling cookie dough. Three tubs cost 22.50. How much will 8 tubs cost ?
does ur formula work for this ?
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✅
@orchid heath
4x4
ohh lol
I thought ur asking the typ of question that ask what two number multpyied by each other makes 8
?? this stand for x
right ?
x=unknown
Look here, multiply then divide
This box is about processes that have a connection
wait devide by what
By the rest number
We alr used 8 and 22.5
What is the rest number?

Put price in left boxs
And amount of pieces in right boxs
Just use informations from ur question
.
60
That's it
Did u see what had i done?
thats the answer ?
yes last time ur were putting 100 so thats what got me confused
100 is percentage
100%
This is for percentage-based operations.
oh
If we got goods and prices
We do this
8 cakes | 20$
3 cakes | x$
We multiply known corners, ( 3 × 20)
And divid them by last corner (8)
As like this:
$\frac{3 \times 20}{8} = x$
Try to see the similarities between them.
And u will understand
SELVATOR
ok thx
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How would i. make a formal proof for this? ik its convergent because for large n, an^2 < an. And since an is convergent, an^2 must also be convergent
part d?
can’t you do term-by-term comparison?
so a_n convergent implies a_n < 1 for sufficiently large n
see where you can go from there
recall that this holds since a_n convergent implies lim a_n = 0
@slow nebula do you understand what i mean
well if you did a_n^2/a_n youd get 0 and if you did the other way youd get infinity so no
this is the idea
then use comparison
then i can use the comparison test?
yep
is there like a formal def for it
like intuitively i understand
yeah
like in a proof can i just say its convergent bc of the inequality?
suppose a_n >= 0. then if |b_n| <= a_n for large n and a_n converges then b_n converges
yea same thing
okok thanks
knief
just state that since lim a_n = 0, there exists N such that a_n < 1 for all n > N
then this result follows immediately
ok that makes sense
okay thanks a lot
you’re welcome sir
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Is using the MVT the right idea?
I'm not sure if i actually proved anything though
but my idea was that x_0 is arbitrary
because a, b are arbitrary
but i feel like im jumping at a conclusion and theres some step im skipping
I dont think this is sufficient
Your question asks if you can prove this for all x_0 in R
so, if I provide you with a number x_0, can you come up with the pair (a,b) that satisfy this?
Oh scratch that, on second thought you can infact assume a random a less than x_0 and find a b that satisfies this condition
Yea, but for a given random x_0, you can still show that it works out
MVT generates an x0 given a and b, not vice versa
finding a and b such that the MVT value is x_0 is more than just MVT
it takes nontrivial amount of work to show its existence
if it even exists at all
We already know that such an x_0 exists 
you're not asking about the existence of x_0, it is given
hmm
the question is the existence of a and b
my idea was like
given any a, b you will find some x_0
now the question becomes can u find every x_0
ah
MVT makes no statement about what x_0 is
my idea was that wouldn't matter becaue eventually every (a, b) pair would eventualyl. generate every x_0
iirc the proof involves just using the definition of the derivative at x = x0
hm maybe i should just do that then
how do you know that? while i don't deny this is true, the MVT doesn't say this
yeah it doesnt
if it is true at all, it takes non trivial amount of work to prove it
so i did jump at a conclusion
it sounds true though i wonder if its possible to prove it
I think it is true that you can generate a and b for which that is true (from an x0) if f is monotonically increasing
but you'd have to prove that
and that's icky
yeah
I think contradiction would be your best bet there
your reccomendation is just use definition of the derivative for this problem specifically right
yeah
we're discussing a different problem, not this one
this
yeah
right that one
oh
i think arctan(x) is a counterexample at 0
ah that's true. it's probably possible to prove if f is also concave up for all R, that's what I was imagining when i thought it was true lol
or at least has a second derivative that never changes sign 🤔
oh thank you!
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Im not really sure how to figure out b and c,, i received help from my teacher on a and help from a classmate about b (0.00495) but I dont really understand how you appoach the question
have you done part a already?
mhm! its k(52) k(51) k(50) k(49) in that order
52k, 51k, 50k, 49k
are the probabilities in the table
now
what do you know about probability distribution tables?
something that is always true of the probabilities in a correctly formed distribution table?
that adding everything together should always equal 1!!
yes indeed
that's how you find k
from exactly this condition that you just stated
so like k = 1/202?
okayy i think i understand b now and hoq they got that answer!!
yes
do you know how to find out c? :?
i had an idea but i talked to another classmate and im not really sure whats the correct way
i tried 0.00495(100-97) = 0.01485, and 0.00495(100-49) = 0.2525 and then added to get 0.2673
but they only did 0.00495(100-48) = 0.2574, and 0.00495(100-49) = 0.2525 and got 0.5098-0.5099
well that way would make sense because theres already a chance for the probability to be 49 twice
but im not sure if that means i should square 49 or instead use them to divide
because my other idea
was to go like 49/202 -> 0.2426*0.00495 = 0.0012
but that feels like too low of a probability to me
and also when i tried to do 1/49 i got like it to like the power of negative four so i dont think thats super accurate either lol
okay wait i think i understand it now
because of the 1/202 i think maybe it would make more sense to add 48/202 and 49/202 together to make 103/202
because thats just like ummm i forgot what it was called but we learned this im pretty sure
okay so 103/202 would be .5099 whichh would be just a simplified way of getting the same rounded result

