help-39

[hollow cliff]

Want me to @ helpers?

[midnight haven]

sure if you want

[hollow cliff]

Alr

<@&286206848099549185>

This is a assignment worth 7% btw so I need the answer to be 100% right

[midnight haven]

there is a lot of inconsistency in this

[hollow cliff]

Wym

[midnight haven]

are the years are shifted

<@&286206848099549185> we need help with trig

[hollow cliff]

😭

[hollow cliff]

Lemme show u the graph

On desmos

[midnight haven]

did you make it?

[hollow cliff]

Yes

I got it from the website the teacher posted tho

This is the question btw: Part 2: Modelling Depreciation

Next, we will be modelling car prices using Desmos. You will do this part of the assignment on your own. This website shows the history of car prices for different makes and models of a car:

https://www.cargurus.com/research/price-trends

Choose a car make and model that you would like to analyze. Choose a car with the model year 2015.

You can edit the start and end date to see the price of the car over a given period of time.

Enter the price of your chosen car in June of each year. If you can’t find the cost in June of a given year, write down the cost on the day closest to June.

Name of car (make and model): BMW M5

[midnight haven]

can you check $37,793.29

[hollow cliff]

Where do u see that?

[midnight haven]

in 2030, its gonna be peak low

[hollow cliff]

.

[midnight haven]

well, a bit higher

[hollow cliff]

Unless the car gets more expensive you never know

[hollow cliff]

Where do u see it?

[midnight haven]

based on just observing the graph

its higher than 2020

$45,345

[hollow cliff]

What about it?

[midnight haven]

2030 is on the edge of the right side

[hollow cliff]

Yea?

[midnight haven]

yea

[hollow cliff]

Why does no one wanna help?

<@&286206848099549185>

[midnight haven]

they prob going to school

or sleeping in

or going to work

[hollow cliff]

Schools over for me

Winter break

[midnight haven]

sane

[hollow cliff]

Thank God

[midnight haven]

same

[hollow cliff]

W

[midnight haven]

nah its sad for me some homies leavin

[hollow cliff]

forever?

Damn

[midnight haven]

got discord

[hollow cliff]

?

[midnight haven]

at least we can vc thru discord

[hollow cliff]

Oh yea

[midnight haven]

you know the monty hall problem

[hollow cliff]

No

[midnight haven]

Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?

[hollow cliff]

Hmm

I'll stick to 1

[midnight haven]

nope

[hollow cliff]

Why lmao

[midnight haven]

lemme show diagram

[hollow cliff]

Alr

[midnight haven]

here

there is 2/3 chance with switching.

[hollow cliff]

Ahhh

I see

Interesting

[midnight haven]

how bout the birthday paradox

[hollow cliff]

Nope never heard of it lmao

[midnight haven]

how many people would it take in one room to get two people of same birthdate

[hollow cliff]

730?

Hundreds right?

Idk

[midnight haven]

45

56

sorry

[hollow cliff]

Huh

[midnight haven]

just 56

[hollow cliff]

What if they don't have the same birthday?

Why 56?

[midnight haven]

i have no friggin idea why, but theres this formula, (365/365)x(364/365)x(363/365) and repeat until no people left

[hollow cliff]

Oh

[flat plover]

What’s the q

[hollow cliff]

Here

Gotta scroll up a bit

[midnight haven]

wdym

og

oh

q question

[hollow cliff]

.

[midnight haven]

FINALLY BRO SOMEONE

[hollow cliff]

.

.

[hollow cliff]

Finally lmao

[flat plover]

So what is it

U build a ml model to predict car price?

[midnight haven]

yes

he needs the price for 2030

[flat plover]

What r expecting

Is linear regression enough

[midnight haven]

anything

i can hopefully convert

[flat plover]

Linear regression is best

For low data

I’m assuming it’s the case here

U can also try xgboost for low data

But u lose interprebility

[midnight haven]

I use xgboost, but i guess ill see you do regression

[flat plover]

Oh

[midnight haven]

im not that good.

[flat plover]

Just use xgboost

It’s good for most low sample size tasks

If u want to do better u need more data

Then u do neural net

[midnight haven]

oh im not talking about this problem

[flat plover]

Wut

[midnight haven]

we just need a money amount

[hollow cliff]

Wtf is zgboost

Let's stick to what I know pls

Cuz my teacher will be suspicious on me on how I found that

When I never heard of it

[flat plover]

Use linear regression then

Its simplest model

[hollow cliff]

What's that

I used the trigonometric

Look up

[midnight haven]

its a model

$37,793.29

can you check it

[hollow cliff]

Where'd u get 37k 💀

Here look

[midnight haven]

from graph

[hollow cliff]

So I had to make a graph and graph it on desmos

From the years 2015-2024

And how the prices changed over time

And got this

y=13793.8241sin(0.585195(x-1.28605))+51317.0035

Now I need to find the price of the car in 2030

Here's what chatgpt said: 👇

[jolly parrot]

anthony
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[hollow cliff]

@flat plover ☝️

[midnight haven]

I THINK I GOT IT

46,86346,86346,86346,86346,86346,86346,863

46,863

[hollow cliff]

This seems like a guess

Fuck this

Ima go to another channel

.close

[pearl pond]

Channel closed

Closed by @hollow cliff

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal coral]

Can you create a set of polar equations that represent different conic sections and other shapes, using the forms provided in the instructions? Your final product must include at least 8 polar equations, with a minimum of 4 different types, domain restrictions where appropriate, and a reference photo or description for inspiration. Additionally, you should upload the completed polar graphs to Desmos, ensuring you follow all formatting guidelines such as shading and dashed lines where applicable.

[worthy lance]

What is your question? @royal coral

[royal coral]

i dont have a question i have this project that ive been working on for the whole week and i cant seem to make it work ive used ai but it just doesnt work at this point ive given up and im willing to pay $2 to do it for me on desmos

@worthy lance

[worthy lance]

We do not do projects here, we can answer specific math questions.

You do not have a specific math question.

[royal coral]

aww man

alright thank you

[worthy lance]

So this is not the place to ask

[warm current]

Did you want help figuring it out tho?

[royal coral]

sure

actually nvm i dont think you can help

i have to draw something on desmos using equations, 8 of them being polar equations

[warm current]

Polar in desmos does not seem too hard
https://www.desmos.com/calculator/ms3eghkkgz

[dapper kraken]

do you know desmos has a built in polar coordinate system?

[glacial sequoia]

I think that's what SWR was showing off

[pearl pond]

@royal coral Has your question been resolved?

[pearl pond]

Channel closed

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Available help channel!

Send your question here to claim the channel.

Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual garnet]

Can anyone tell me how to calculate a triangle if we only know one side

[dapper kraken]

you cant

[visual garnet]

I thought you use sqrt2?

[dapper kraken]

!original

[pearl pond]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[dapper kraken]

you need more info

[visual garnet]

In quadrilateral ABCD with an area of 48 cm², diagonal AC has a length of 8 cm and divides the quadrilateral into two triangles: ABC and ACD (see the diagram). The height of triangle ACD drawn from vertex D to line AC is 2 cm.

Calculate the height of triangle ABC drawn from vertex B to line AC. Show your calculations.

<@&286206848099549185>

[spiral pivot]

@visual garnet the area of the quadrilateral is the sum of the areas of the two triangles, correct?

Can you find the area of triangle ACD?

If so, what does that make the area of the triangle ABC?

Finally, now that you know the area of ABC, what is the height in question?

[visual garnet]

,calc 821/2

[jolly parrot]

Result:

8

[visual garnet]

8 cm

Is area of ADC

[spiral pivot]

8 cm^2

Mind your units 🙂

[visual garnet]

40 cm^2 is ABC

Do I have AB?

I need a to find height

[dapper kraken]

whats the formula for the area of a triangle

[visual garnet]

a * h * 1/2

I don’t have a

To find h

[spiral pivot]

You have AC

Let AC = a

[visual garnet]

This is base or “a” of a triangle.

[spiral pivot]

Any leg can be the base of a triangle

It doesn't need to be "the one on the bottom"

You already used this to calculate ACD, in fact

[visual garnet]

Oh

a * h * 1/2

h = a * 1/2

h = 8 cm * 1/2

h = 4 cm

And now

[spiral pivot]

Your arithmetic is off

[visual garnet]

8 cm * 4 cm * 1/2 = 12 cm^2

[spiral pivot]

It's Area = 1/2 * a * h

[visual garnet]

The height of ACD is 12 cm

[visual garnet]

Ooooh

Ooooh

40 cm = 1/2 * a * h

40 - 1/2 : a

,calc 40*0.5/8

[jolly parrot]

Result:

2.5

[visual garnet]

h = 2.5 cm

Ez

uh

what?

dawg…

[spiral pivot]

You did the math wrong

[visual garnet]

wdym

wrong

I moved

The things

To find height

[spiral pivot]

Be a little more careful, you made a mistake

[visual garnet]

wym

[spiral pivot]

Check your work specifically on moving the 1/2

[visual garnet]

When you move

You should change signs

[plush moss]

You careless dawg

[visual garnet]

So minus 1/2

[visual garnet]

💀💀

You took 2 mins to type one sentence (three words)

[plush moss]

Is basically what he's saying

I was tryna translate

[spiral pivot]

You subtract when things are being added to move across the equal

[visual garnet]

But it’s minus 1/2

[spiral pivot]

But this isn't being added

[visual garnet]

It is?

It’s +1/2

[spiral pivot]

It's being multiplied

[plush moss]

Here it's multiplied

[visual garnet]

where?

[plush moss]

1/2 * a *h

The * means multiplication

[visual garnet]

$40 cm = \frac {1}{2} * 8 cm * h$

[jolly parrot]

Ahsoka Tano

[visual garnet]

$40 cm - \frac {1}{2} : 8 cm = h$

[jolly parrot]

Ahsoka Tano

[plush moss]

Uh nah how about

[visual garnet]

But I change a

To division

[plush moss]

Dividing by 1/2 on both sides or in other words multiplying by 2 on both sides fr

[visual garnet]

There isn’t any sign before 1/2

,w 1/2*1/2

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ahs0ka.tano

[visual garnet]

,w 1/2/1/2

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ahs0ka.tano

[plush moss]

Bruh

[spiral pivot]

Use parentheses

,w (1/2)/(1/2)

[visual garnet]

Wdym divide both sides?

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by omnipotententity

[plush moss]

You do know how dividing by fractions works right

[visual garnet]

Let’s say

[spiral pivot]

Anything done to one side must be done to the other to maintain equality, unless it's multiplying by 1 or adding 0

[visual garnet]

$3x + 2x + 7 = 7x$

[jolly parrot]

Ahsoka Tano

[visual garnet]

I move 5x to the other side

It’s 2x = 7

[plush moss]

Yes

[visual garnet]

X = 3.5

[plush moss]

Yes

[visual garnet]

and I don’t use DIVISION to get rid off it @plush moss

Denzio…

[spiral pivot]

You did to get rid of the 2

[visual garnet]

I don’t do 5x : 5x and then 7x : 5x

Same with fraction

[plush moss]

And you do

You do 7 divided by 2

[dapper kraken]

$2x=7$
how do you find x?

[jolly parrot]

Skissue ping4response

[visual garnet]

$\frac{1}{2}$

[jolly parrot]

Ahsoka Tano

[visual garnet]

BY DIVIDING

[plush moss]

Multiplication by 1/2 is the same as dividing by 2😭

[visual garnet]

I’m lost…

[dapper kraken]

by dividing by 2 yes? to get $\frac{2x}{2}=\frac{7}{2}\implies x=\frac{7}{2}$

[visual garnet]

I just don’t understand why is it not minus 1/2

[jolly parrot]

Skissue ping4response

[plush moss]

Its good

[visual garnet]

when you MOVE things, you only CHANGE signs…

I’ve always been taught that

[plush moss]

What grade are you in rn

[visual garnet]

don’t remember

[plush moss]

Huh

[spiral pivot]

Fr?

[visual garnet]

Idk mayb 8

[plush moss]

So like are you in the education system right now

[dapper kraken]

alright, $40=\frac{1}{2}\cdot 8\cdot h\implies 40=4\cdot h$, what do you do to find h?

[jolly parrot]

Skissue ping4response

[visual garnet]

40 - 4 = h

36 = h

H= 36 cm

[dapper kraken]

but here you divide by 2?

[visual garnet]

Sure…

But like

You change the signs…

I think yall don’t know how to explain to people

<@&286206848099549185> maybe someone else?

….

;-;

being ignored…

-_-

[plush moss]

We tried man

[tame spruce]

What is the question

[regal herald]

if i have a+x=b then i subtract a from both sides to be left with x=b-a, what you call 'moving' and getting a sign change

the same principle doesnt apply to multiplication, because the inverses are defined differently between addition and multiplication
if i have ax=b then i divide by a (multiply by 1/a) to get x=b/a

the first case is (-a)+a+x=(-a)+b
0+x=-a+b=b-a=x

the second is 1/a (ax) =1/a (b), x=b/a

explicitly

[plush moss]

Oh if you're under 13 we have a specific channel where we give more simplified explanations

[pearl pond]

@visual garnet Has your question been resolved?

[visual garnet]

Oh!

[visual garnet]

So?

The number was 1/2

+1/2 to be exact

If it was x * 1/2

I’d divide 1/2

[regal herald]

which is multiplying by 2, sure

i havent actually looked at the stuff prior to my message in any detail

[visual garnet]

This doesn’t make sense at all

[crystal wharf]

you dont subtract, but instead you multiply by 2 (ie dividing by 1/2) to remove 1/2 from the right side, since 1/2 is being multiplied, not added

[visual garnet]

I have this equation:

[jolly parrot]

Ahsoka Tano

[crystal wharf]

you can rewrite this as (8*h)/2

and then itd make much more sense to multiply by two

[visual garnet]

Ok then

[crystal wharf]

to get rid of the denominator

[visual garnet]

I use YOUR method

[crystal wharf]

yes

[visual garnet]

40 cm * 1/2 / 8 = h

,calc 40/8

[jolly parrot]

Result:

5

[visual garnet]

h = 5 ck

Cm

Answer

[crystal wharf]

remember to check your answer to see if you got it right

we know that the area is 40 cm, ans the area of the triangle is (b*h)/2 so does (5*8)/2 equal 40?

[visual garnet]

It’s apparently 10…

[crystal wharf]

fucking hell

damn markdown

ugyfhdufu wwww

[visual garnet]

lol

5*8 = 40

40*2 = 80 ck

80 cm

So no

Then how?

[crystal wharf]

its not times 1/2 its times 2

[visual garnet]

Niko

Why

[crystal wharf]

ping me instead of saying my name please

[visual garnet]

A * h * 1/2

….

[crystal wharf]

here!

(8 * h)/2 = 40

idk latex im so sorry lol

[crystal wharf]

but here we have a fraction on the left hand side

and to get rid of it, we should multiply by the denominator on both sides

ie here, multiplying by two on both sides

[visual garnet]

40 * 2

80

[crystal wharf]

yes

[visual garnet]

80 / 8

8

[crystal wharf]

then we have 8 * h = 80

[visual garnet]

10

[crystal wharf]

yes!

[visual garnet]

Yh

I know this

[crystal wharf]

do you understand now?

[visual garnet]

Yh

Ty

Good night

[crystal wharf]

gn!

dont forget to close this

[pearl pond]

@visual garnet Has your question been resolved?

[pearl pond]

Channel closed

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[pearl pond]

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[pearl pond]

@light canyon Has your question been resolved?

[warm current]

!status

[pearl pond]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson hemlock]

I need help with this topic named mathematical reasoning, it's totally a new topic for me, so can anyone tell me how to solve these ?

[crimson hemlock]

Can ping

[pearl pond]

@crimson hemlock Has your question been resolved?

[signal atlas]

Do you know when a statement If P then Q evaluates to true and false

[crimson hemlock]

Yeah I know a little bit about that

These are logical statements which evaluate to true and false only

[signal atlas]

Yeah but do you know when they are true and when they are false

[crimson hemlock]

Kind of I guess

[signal atlas]

Ok what is the truth value of "If P then Q" when P and Q are true

[crimson hemlock]

I don't get about what P then Q means here?

[signal atlas]

Where are you learning this from

Anyway it basically means is it possible to derive Q from P

P and Q are logical statements that evaluate to true or false

[pearl pond]

@crimson hemlock Has your question been resolved?

[pearl pond]

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• Show your work, and if possible, explain where you are stuck.
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[inland vale]

i need someone to help me with these triangle proofs asap
i need to get this is to pass this semester and its due tomorrow at 8am

[inland vale]

these are literally the last 3 questions i need to do

i really need to pass

[vocal lark]

use CPCTC

"Congruent Parts of Congruent Triangles are Congruent"

[inland vale]

yes i know that

[vocal lark]

so you need a congruency theorem to apply here

[inland vale]

well i need to add a statement first

[vocal lark]

notice that both triangles share an edge. what doe that mean?

[inland vale]

they congruent

[vocal lark]

yes

so AC = CA

[inland vale]

wait

what about ac=ac

using reflexive property as a reason

okay okay

next statement

[vocal lark]

reflexive property is the reason

but when you compare the sides

they have opposite chirality

[inland vale]

so if i do AC = CA what would the reason be

[vocal lark]

that is, when you transform one to perfectly overlap the other, you'll notice that C for one trianlge overlays A on the other, and vice-versa

[vocal lark]

"reflexive property"

[inland vale]

okay

next statement

[vocal lark]

how can you show that <BCA ~= <DAC?

it's one of the first transversal theorems you learned

[inland vale]

hmm

[vocal lark]

those angles are "opposite-interior"

and "opposite-interior angles" are...

[inland vale]

congruent!!

right

[vocal lark]

https://www.dummies.com/article/academics-the-arts/math/geometry/definitions-and-theorems-of-parallel-lines-187739/

with those statements, you can say that triangle ABC ~= triangle ADC by AAS congruency

[inland vale]

boom

[vocal lark]

finally, AB ~= DC by CPCTC

[inland vale]

?

[vocal lark]

you're not keeping up

[inland vale]

sorry im confused

[vocal lark]

☝️

[inland vale]

oh i didnt see that

sorry

[vocal lark]

because you're not keeping up

[inland vale]

still wrong

[vocal lark]

show me what you put

[vocal lark]

what happened to your relexive property from earlier for AC and CA?

[inland vale]

honestly idk

ill add it back rq

okay

thank you 1 down

2 to go

so

i tried this one earlier

and i had like almost all the angles congruent and it didnt let me say the triangles were

[vocal lark]

which one

[inland vale]

im stuck here

[vocal lark]

let me get some paper

[inland vale]

okay

[vocal lark]

ok

we have enough info now

to show that triangle AEB is isosceles

or more specifically for use case, isoangular (same thing)

[inland vale]

so what would the statement be

[vocal lark]

definition of isosceles triangle

statement 1

any triangle with two equal sides or two equal angles is isosceles/equilangular

[inland vale]

okay

[vocal lark]

you got it?

[inland vale]

done that

[vocal lark]

now we want to show that <DAE = <CBE

we already know that <DAB = <CBA

and since now we know the middle triangle is isosceles, we know that <EAB = <EBA.

so that last line is your next statement

[inland vale]

uhh wait so

like tyhat??

[vocal lark]

no, I made a correction, and you're still not following what I am saying

you didn't read the next three lines

[inland vale]

i dont understand what your trying to say

[inland vale]

which line

what line

[vocal lark]

which lines do you not understand

[vocal lark]

☝️

[inland vale]

its too late for me

mybrain isnt braining

[vocal lark]

oh well

[inland vale]

can you just like give me the answers

please

[vocal lark]

no way.

[inland vale]

i need to sleep

PLEASE!!

its two questions

[vocal lark]

you need to sleep more than you need to pass sophomore math?

[inland vale]

yes

i need sleep so my brain brains

its too late

for brain

so brain no brain

ive been doing this since 7pm 😭

i beg you

[vocal lark]

you haven't been doing this since 7pm

[inland vale]

i swear

[vocal lark]

you've been doing this since what

January?

no

[inland vale]

no no

like

[vocal lark]

September

[inland vale]

this assignment

[vocal lark]

right but this is a class I've taught

as a substitute, granted

but here's what I remember about that experience

[vocal lark]

arriving two hours early every day

staying two hours late every day

and seeing almost nobody asking for help before or after school

but plenty of students with spotty attendence asking for favors at the end of the semester

[inland vale]

well i didnt have u as a teacher

[vocal lark]

ask for an explanation and you shall recieve

ask for answers, you will be denied

[inland vale]

idk how to do ts

and ur teachings are not making sense

[vocal lark]

then you can ask for help from somebody else

I'm sorry this format doesn't work so well for you

it's very verbose, not very visual or interactive

It's not my favorite either

certainly not for geometry

[inland vale]

for reals

even ai cant do these proofs properly

[vocal lark]

I hope you notice

that I was basically spoonfeeding you what to write

and you still got frustrated

[inland vale]

yes i noticed

this hard

spoon feed me more please

[vocal lark]

it's not the easiest transition

well here's a fact

this is a pretty famous geometry homework problem

the figure anyway

odds are good somebody worked this out on Youtube

if you want to follow along with their solution

[inland vale]

orrr

you could just like

tell me the answers

to two problems

out of the other 100 i been doing since 7pm.

[harsh idol]

if u never figure out ur self, you will never develop the intuition to know what to do

you dont build that skill

(coming from experience) (Discrete maths)

thats all about proofs

[vocal lark]

by the way man, teachers don't like failing kids

they'll take your homework past due if they know you did it and tried. If the stupid software will let you finish it

they'll just be glad you did it

because it justifies their subject

"oh damn, this kid DID THE MATH?"

[inland vale]

today last day of the semester and day b4 winter break

i dont think

they would

take it late

[vocal lark]

yeah, so catch them early and ask if they can help you

it's two problems

[inland vale]

🐒

idk how to do this so im gonna fail

[vocal lark]

the line I told you to write

[harsh idol]

just look up a video that teaches u that lesson specifically again

[vocal lark]

was the penultimate line

you only need one line afterwards

[burnt thicket]

Hey man, I’m a student right now too so I get it: dealing with work is hard but asking for answers is only beneficial in the short run. You will literally learn it far more effectively by trying it on your own

[harsh idol]

exactly

[inland vale]

hey "man" ive been trying it on my own for almost 7 hours now

[harsh idol]

yeah i spent 2 days on 1 question once its ok

[burnt thicket]

Then your task isn’t to work on this problem; it’s to work on something easier

[inland vale]

thx for letting me know

[burnt thicket]

Take a break for a while and come back to it

[vocal lark]

I finished it.

[inland vale]

thats dumb logic this is a assignment thats due in 6 and a half hours

[vocal lark]

:/

[burnt thicket]

Well clearly asking for answers isn’t working right? So it appears your only option is to actually learn the content

Trust me. This is the fastest way

[vocal lark]

I offered to finish the problem with you and I even offered in DM to video record the paper I worked out step-by-step (if you don't get motion sickness) so I don't know what more anybody can do for you here if that's not enough

[harsh idol]

video record paper is crazy

[vocal lark]

I already did it and it's only 6 lines

[inland vale]

please reply to when you offereed to dm a video of u recording the paper or wtv

[vocal lark]

lol

it's a DM

direct message

can we upload vids here?

oh, maybe

[inland vale]

i didnt see it because it went in my message request

i dont get like notis for that or wtv

[inland vale]

and you can

if its like not to big of a file

unless the servers boosted

so i guess im alone now

BRO FINALLY

and i still have one more

great

[burnt thicket]

That was a fast 7 hours

[inland vale]

what

[vocal lark]

nice job

[inland vale]

yeah im lost again

like bro

i get one statement then idk

[vocal lark]

do you remember your bisection theorems?

I sure don't

I remember that one angle bisection theorem is the converse of the other

https://www.cuemath.com/geometry/angle-bisector-theorem/

[burnt thicket]

This isn’t necessary for the problem

[quick star]

AC bisects BD because triangle CEB is congruent to AED

[vocal lark]

yeah I'm regretting posting that

we can't say much about the angles at the start

[inland vale]

wait reallt?

like no duh bro

holy

[quick star]

yes...?

[inland vale]

its a proof

i cant just say that

[quick star]

but that's literally a "proof" 😭

u show that those two traingles are congruent

[inland vale]

i need these useless statements and reasons thatim never gonna use in life

[quick star]

by AAS or anything like that

[burnt thicket]

Sometimes it’s easier to work backwards

Now you have an easier statement to work towards

[quick star]

i don't know what statements you have available to choose

[vocal lark]

oh yeah

[quick star]

u never showed us

but my thing is a proof

[vocal lark]

use your transversal theorems again

opposite-interio...vertical angle...

[quick star]

^

alternate interior angles

[inland vale]

i skipped the question and made a new one

to hard

[quick star]

whatttt

[vocal lark]

that one was a gimme

ugh

disgusted

*spit*

>;|

[quick star]

draw the triangles separately

[vocal lark]

(╯°□°)╯︵ ┻━┻

[inland vale]

i dont want to

[quick star]

.....

[vocal lark]

woop, this is the moment I check out

[inland vale]

i can imagine it

[quick star]

u clearly can't or you'd solve the problem

[inland vale]

no, i can imagine triangles

i cant imagine the answers though

[burnt thicket]

Maybe we should let him work on it a while and once he has a specific question we can answer from there?

[dapper kraken]

remember properties of an icoseles triangle

[quick star]

yeah i don't think he really needs help lol

[inland vale]

i need answers

[burnt thicket]

you need patience

[quick star]

i gave u the answer for the last problem but you couldn't even parse it to solve your exercise

it helps you to actually learn the topic

bc you're going to have to do more of these in school

it doesn't matter if it's useful to you irl or not, does it?

unless you plan on dropping out of school then okay yeah there's no reason to learn this maybe

[inland vale]

dude im so confused

whats next dawg

[dapper kraken]

is this a test?

[inland vale]

no

assigment

bruh im finna get 3 hours of sleep

[dapper kraken]

look, im fine you making silly messages about me but please do not disturb in other peoples help channels. thank you @pearl yew

[quick star]

[marsh moss]

You know what's given, right?

[inland vale]

yes

[burnt thicket]

Okay so you’re trying to prove that the diagonal cuts directly through the middle right?

[dapper kraken]

is 3,4,5 your typing or directly from the question?

[inland vale]

from 2-5 is all mine

[burnt thicket]

And you almost have a triangle congruence on the two sides there

[inland vale]

only 1 was given to me

[burnt thicket]

How can you prove those triangles are congruent?

[inland vale]

i dont know bro

[burnt thicket]

Well think on it for a while

[inland vale]

theres 4 triangles dawg

which ones are u talking abt

[burnt thicket]

Left and right mb

(Honestly either pair works but stick to that)

[inland vale]

be = ed?

like idk

[burnt thicket]

That’s what you’re trying to get to right

[inland vale]

no im trying to get to ac bisects bd

[burnt thicket]

To do that, you’d probably need establish congruency between some of the triangles

[burnt thicket]

But wouldn’t be = ed imply that?

That’s what bisecting means

[inland vale]

okay but im proving bisecting not congruence

[burnt thicket]

Mhm, you’re trying to prove those sides are equal (be and ed)

And the easiest way of doing that is to show the triangles are congruent first

Then since the triangles are congruent, the corresponding sides (which are be and ed) should also be congruent

[inland vale]

bro i dont know what statement to put

ive been looking at ts for 30 mins]

[burnt thicket]

You gotta take things one step at a time

You’re rushing yourself

[inland vale]

bro im actually bouta just accept to fail

[burnt thicket]

I mean if that’s your decision go for it

But we both know it would be extremely tragic to lose at the last stretch

This is the fastest way and the sooner you accept that, the faster the end will arrive

[inland vale]

dawg i dont know how to do this

how do i show the triangles are congruent

[burnt thicket]

Can you list the triangle congruence theorems?

[inland vale]

no

i forgot them

[burnt thicket]

Then I can’t help ya bud

[inland vale]

blah blah blah

theres somehting called google

[burnt thicket]

Okay

Use it

Why make me do it

[inland vale]

Side-Side-Side (SSS), Side-Angle-Side (SAS), Angle-Side-Angle (ASA), and Angle-Angle-Side (AAS)

[burnt thicket]

You’re the one learning here

[burnt thicket]

Mhm, now which of those could you actually use for these specific triangles?

[inland vale]

asa

[burnt thicket]

Yup

So now you need to get that other angle right?

[inland vale]

yes

i dont know the reason to choose

[burnt thicket]

Read all of em, one of them looks pretty obvious to me

[inland vale]

i tried every reason it list

none work

[burnt thicket]

Well obviously one does since the angles are equal

[inland vale]

dude

[burnt thicket]

Read them carefully

[inland vale]

i tried all the reason

s

like i clicked them

pressed try

and none worked

[burnt thicket]

Okay then try opposite angles of parallelogram

Did that work?

[inland vale]

do i need to use

abe

ade

[burnt thicket]

Yeah I guess so

[burnt thicket]

Wait which angles are you trying to prove are the same?

[inland vale]

B and D

[burnt thicket]

Well that’s not abe and ade

[inland vale]

what is it then

[burnt thicket]

Oh you mean the small ones

[inland vale]

eba

eda

[burnt thicket]

Okay okay sorry you can keep the angles

When you had the other ones I thought you meant the opposite angles of the parallelogram

[inland vale]

so

i tried every reason

again

[burnt thicket]

Okay so those angles are on opposite parallel lines right?

[inland vale]

yes

im actually about to jump

i came to this server for answers 1 hour and a half ago

for 2 questions

[burnt thicket]

Then leave and figure it out

It’s probably faster than you typing and discord and complaining anyways

[inland vale]

no i need nano jumpers help

[burnt thicket]

No you don’t. Don’t wait for me. You can figure it out

If you really need a hint: ||it’s because of another triangle congruence||

[inland vale]

im just gonna fail

goodnight

[tulip ore]

bruh really

[surreal relic]

Is the question solved @inland vale ?

[inland vale]

no

im giving up and going to sleep

goodnight

[prime bramble]

well, the channel is going to be closed if you’ll be gone

are you fine with that?

[surreal relic]

.close

[pearl pond]

Channel closed

Closed by @surreal relic

Use .reopen if this was a mistake.

[inland vale]

yes

goodbye

[prime bramble]

have a good night

[inland vale]

its morning

i have practice in 2 hours

might as well just not sleep

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland vale]

this server sucks!!

[surreal relic]

Lmao

Convenient message got pinned

[prime bramble]

well, I think the server is generally quite good tbr

[spare lark]

We don't do aftersell services

[prime bramble]

but this is also not a help channel question so uhh

[wild fable]

Hi higher! Bye higher!

[surreal relic]

.close

[pearl pond]

Channel closed

Closed by @surreal relic

Use .reopen if this was a mistake.

[dapper kraken]

peak

[prime bramble]

https://tenor.com/view/anime-love-smiling-menhera-hearts-gif-12479110

[dapper kraken]

.forceclose (sorry test)

[spare lark]

.disapear

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pearl pond]

Please don't occupy multiple help channels.

[midnight haven]

!occupied

[pearl pond]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[pure rapids]

Do to discussy fr

[cerulean thunder]

yes sir

[pure rapids]

ig new channel also works

[pearl pond]

@midnight haven Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ivory musk]

I got this question on my test. I chose A and it is correct, but now as I look at it, I am not sure I understand why it is correct. I differentiated it and at that point it was 0, but isn't the same true about E, for example?

[ivory musk]

This is what I get for E

[sharp smelt]

You don't know if $f'(0)$ is defined or undefined

[ivory musk]

yeah

it could be undefined

[jolly parrot]

ƒ( wai ina teacup)= I don't know

[ivory musk]

But for E it is defined, right?

regardless of f prime, I get a 0 when x = x_0

[inland ivy]

that's still considered a critical point

[sharp smelt]

What if $0$ is a point where the function tends to infty

[jolly parrot]

ƒ( wai ina teacup)= I don't know

[sharp smelt]

oh right

my bad

[inland ivy]

I think you're right, I don't see why E isn't correct

are you sure the question didn't have multiple correct options

[ivory musk]

No(

tbh I didn't even look at E when I was doing the test lol, I just chose A when I calculated its derivative
but now I am super confused

[inland ivy]

I think @sharp smelt is right, there can be a problem where f diverges at x=0

A is the only one we can be sure about

[ivory musk]

Can we bring an example of such a function?

I'll understand it better

[inland ivy]

something like f(x) = 1/x(x+1)

x_0 = -1/2 is a critical point

but f((x-x_0)^2) won't

[ivory musk]

yup

can you please explain once again why we are entirely sure in A? for these cases

wait no this is incorrect

it should be +

but still, not a critical point

[ivory musk]

.close

[pearl pond]

Channel closed

Closed by @ivory musk

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[golden bolt]

p

[golden bolt]

Find the shaded area

at first i thought about using integers for the base which all adds up to 12

i assumed the two small triangles are equal and is a, and the left triangle is b, and the biggest is c

2a + b + c = 12

And tried multiple combinations

tried a = 2, b = 3, c = 5.

And got 30

a = 1, b = 3, c = 7

And got 30 as well

but apparently my friend told me it’s 36

Just by seeing the question i also assumed it’s 30

[pearl pond]

@golden bolt Has your question been resolved?

[golden bolt]

Nvm i got it

[pearl pond]

Channel closed

Closed by @golden bolt

Use .reopen if this was a mistake.

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Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom coral]

Hello, I have question about a proof of polynomial remained theorem.
In the wiki page for it ( https://en.wikipedia.org/wiki/Polynomial_remainder_theorem#Using_Euclidean_division ), the proof declares g(x) as the divisor, then defines it as g(x) = x - r without excluding x = r from the domain (due to it being divisor and anything divided by 0 is undefined). Later on, we use g(r) to find the remainder. Is this proof incorrect or am I missing something?

[tropic saddle]

x-r is a polynomial of degree 1, x is a symbol and not a number

polynomial division is initially just symbolically

later you can substitute x=r into the result you get

[fathom coral]

If I substitute x = r, then the divisor is r - r = 0

f(g) divided by (x - r) is only defined when x is not r

[sweet snow]

Polynomial division is not the same as number division. You treat the x as a symbol, not a number

[rustic gate]

also note that no "division" takes place, it is merely an equation f(x) = Q(x)g(x) + R(x) which holds true regardless of if you can divide by g

[orchid path]

if (x - r) divides f(x) we can write f(x) = (x - r)g(x). sub x = r we have that f(r) = 0
conversely suppose f(r) =0 then thanks to the division algorithm we have f(x) = q(x)(x-r) + r(x)
sub x = r gives f(r) = r(x) = 0. since there is no remainder (x -r) divides f(x) as desired

[fathom coral]

I understand the proof, this little details of g(x) being divisor represented as x - r without excluding x = r was what bugged me

But from the other answers I think I kind of started getting it by treating polynomial division differently from number division

[orchid path]

why can't x =r?

[fathom coral]

Because x - r is divisor, and if x = r then x - r = 0, and we can't have division by 0 as it is undefined

[rustic gate]

do you see division happening?

[fathom coral]

But as Blake said, there is no division taking place, it's defined as multiplication

[rustic gate]

absolutely no division

being a divisor does not mean do division

4 is a divisor of 8 because 4*2 = 8

not because 8/4 = 2

[fathom coral]

That makes sense

Thank you for helping me understand, I appreciate it

[tropic saddle]

the process of polynomial division is really just a smart way to make sure that the polynomial Q(x)(x-r) + R actually ends up being f(x)

and note that even for numbers, we can actually use the division algorithm to "divide" by 0

the result will just be that the remainder is your original number

aka n = k*0 + n

so even for numbers, we arent actually really dividing, we are more like trying to work backwards from the product

which is kind off the same thing but kind of not quite

[fathom coral]

!done

[pearl pond]

If you are done with this channel, please mark your problem as solved by typing .close

[fathom coral]

.close

[pearl pond]

Channel closed

Closed by @fathom coral

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom coral]

Hello, it's me again.
My question is maybe a continuation of literally the previous question in this thread, but I went in a rabbit hole for definitions of certain operations.
The euclidean division proof of polynomial remainder theorem is described in https://en.wikipedia.org/wiki/Polynomial_remainder_theorem.

It goes to a form f(x) = Q(x)(x-r) + R.
In euclidean division formula a = bq + r, what is corresponding to the 'b' is actually (x-r), but we have constraint that b must be different than 0.
Then we go on and place 'b' as zero in our proof.

If we follow the same logic, we can prove anything.
Assume f(x) divided by (x-a) gives a remainder of 3.

f(x) = Q(x)(x-a) + 3 , then
f(a) = Q(a)(a-a) + 3 ,
f(a) = Q(a)*0 + 3 = 3 , then f(a) would always be equal to 3.

But we can use the same logic for any other remainder, which leads to contradictions.

[fathom coral]

Now this theorem has another proof which might be correct, but my point is that in Euclidean division proof, we are performing banned operations (that a = bq + r such that b is not 0). From that I conclude that is is not an actual rigorous proof of the theorem (even though another rigorous proof could exist)

So am I right that this 'proof' is not rigorous, or it is rigorous and I am missing something from the definition of operations (as described in the wiki articles)?

[grim fractal]

I think that when you take the division algorithm for polynomials, the constraint that b is not 0 just means that $g(x) \neq 0$

[jolly parrot]

Ari

[grim fractal]

In this case, we use $g(x) = x-r$, which, yes, has a zero at $x=r$, but this doesn't go against the division algorithm

[jolly parrot]

Ari

[grim fractal]

basically, the divisor just can't be the 0 function. It's allowed to have zeroes, and the division algorithm still holds when evaluated at the function's zeroes

[fathom coral]

so if g(x) must be different than 0, then x - r must be different than 0

so x must be different than r, but we plug in r as an input to g

g(x) = x - r , g(x) != 0 , x - r != 0 => x != r => r is not in the domain of the function

[grim fractal]

g(r) = 0 doesn't mean that g(x) = 0

The divison algorithm just says g(x) can't be the zero function

It doesn't say that g(x) can't have any zeroes

[fathom coral]

I am not saying that g(r) = 0, I am saying that g(r) is undefined

because it is used as the 'b' in a = bq + r ( b != 0 )

[grim fractal]

You're misunderstanding the polynomial divison algorithm

when it says g(x) is nonzero, it just means g(x) isn't the zero function

g(x) = x-r in this case

g(x) is allowed to equal zero at certain values of x

[fathom coral]

but if g(x) is allowed to equal zero, then it doesn't follow the formula for euclidean division anymore, as it is only defined when g(x) is not 0

And what do you mean exactly by "the zero function"? I am not sure I understand what is the zero function and that might be the reason I don't fully understand you. Is it just 0 or is it something more special?

And I have learned just today the formula of polynomial division algorithm, so it's highly likely I don't fully understand it

[grim fractal]

The zero function is g(x) = 0, where every value in the domain gets mapped to 0

so g(x) = x-r is not the zero function

[grim fractal]

Euclidean division is only used when you're looking at the entire function, not specific values.
So g(x) here is not the zero function, so we can use the division algorithm to get
f(x) = (x-r)q(x) + r(x)

Then, we can plug in values of x. Euclidean division doesn't matter more after we've gotten to this point

[fathom coral]

But as far as I can see in the wiki article, the proof depends on euclidean division, which is defined as a = bq + r

now I get that we could plug in any x in f(x), except that I don't get why we can plug in the value 'r'

because even if g(x) is not the zero function, there are values of 'x' that produce 0 as output of the g function

and if g(x) = b in the formula, and b != 0, then g(x) must also be different than 0

so this leads me to conclusion that the domain of g function must exclude the inputs that output 0

[grim fractal]

Euclidean division isn't exactly the same for polynomials as it is for integers

This is extra fancy terminology but the ring of integers are the ring of polynomials with integer coefficients are different euclidean domains and so euclidean division doesn't work the exact same

In general, for euclidean division, you just need the divisor to be nonzero in that ring

In polynomials, the zero is just g(x) = 0. Any other polynomial allows euclidean division

and it doesn't matter if that polynomial happens to have some zeroes. The division algorithm stil works

[plucky python]

i'm kinda confused, you've proved the remainder theorem which is true?

if f(x) leaves remainder 3 when divided by (x-a), then f(a) = 3

[plucky python]

not sure what you mean by any other remainder?

[grim fractal]

They're confused that the divison algorithm for integers says that
a = bq +r requires b to be nonzero
And at x=r, g(x)=x-r is 0, so they think the divison algorithm does not apply for x=r

[plucky python]

oh right ic makes sense

[fathom coral]

Ari, I am a bit lost with the ring terminology

you said that euclidean division is not exactly the same for polynomials as it is for integers

So I am using the description from wiki https://en.wikipedia.org/wiki/Polynomial_greatest_common_divisor#Euclidean_division

which still states that b != 0

[plucky python]

there's a slightly confusing bit of terminology when we say f(x) = 0

here what 0 means is not that there is some integer x that makes f(x) = 0

it means that f(x) is not identically 0

think of it like this - there's many different number systems out theer

i.e. the integers etc.

the integers is the number system that you're most familiar with, but there are other such number systems too

one such number system is R[X], the set of polynomials with real coefficients

when we think about R[X], we're not thinking about them as functions or anything of the sort, we are interpreting this number system as just stuff of the form a_n X^n + ... + a_0

now the "0" for this number system would be 0 and "1" would be 1

(0 polynomial not a polynomial equalling 0)

every nice enough number system has its own division algorithm

where just like how with integers, i can divide a by b to get a=qb+r

that holds for every nice number system

(the formal name for this is a Euclidean domain - it's not too hard to prove that R[X] is a euclidean domain but take it as a fact for now)

so it means that in our fancy number system of R[X], that means i can divide one expression by another to get a remainder

so i.e. a(X) = p(X)b(X) + r(X)

[fathom coral]

I think I am following

Is there more to it, or?

@grim fractal I re-read everything you said, and from what I understand is that if I look at the wiki article for euclidean division, it means that if 'b' is the function g(x), then g(x) must not be the zero function, but it can be a function who has zero outputs. I guess that this will start making sense when (or if) I get to rings, but for now I should accept that g(x) is any function that has at least one output different than 0?

[grim fractal]

Yes, pretty much

I think this all makes more sense when you learn about rings, but for now, the division algorithm for polynomials applies as long as g(x) isn't the zero function

[fathom coral]

Got it, I will take your word and hope to fully understand this one day

Thank you all for giving me different perspectives to think about this 🙂

[grim fractal]

[fathom coral]

.close

[pearl pond]

Channel closed

Closed by @fathom coral

Use .reopen if this was a mistake.

[pearl pond]

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[stoic imp]

In the diagram below, lines $k$ and $\ell$ are parallel. Find the measure of angle $x$ in degrees.

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[brave sluice]

one of those lines is just a distraction

actually i'm not sure you even need k

<@&268886789983436800>

[stoic imp]

[stoic imp]

?

Can someone help me