help-39

[pearl pond]

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[red hedge]

,rotate

[red hedge]

Need help 17 b

[slim verge]

Square both the sides

Make quadratic in sin or cos, whatever you want

@red hedge

[bronze coyote]

u can double angle both sides first

[red hedge]

Alright

[pearl pond]

@red hedge Has your question been resolved?

[pearl pond]

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[wheat otter]

prove that it is a 2d manifold

[pearl pond]

@wheat otter Has your question been resolved?

[pearl pond]

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[ember spear]

yeah

[midnight haven]

thx

.close

[pearl pond]

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[mighty pier]

m

[midnight haven]

ath

[pearl pond]

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[twilit gate]

How to find number of inversions of euler totient functions? for example phi(n) = 12 for 6 different numbers and how to prove it

[summer imp]

I doubt there is an actual good way to do this exactly, at least analytically.

There probably are bounds on the number of inverses for a given integer, or computational approaches, but finding a formula for it seems overly optimistic

[twilit gate]

how to do it for n = 20 then?

I was trying to find something more generalistic so i can explain it better in uni

but if it is impossible how would I find all inverses for n = 20?

I can put it into calculator but yeah it computes it using bounds i read about in pdf

but they are intended for computer computation and it would take too long to do by hand

[summer imp]

So you're asked to compute |{n : phi(n) = 20}| ?

[twilit gate]

yes

I could also just compute all answers if it is not that much harder

<@&286206848099549185>

[pearl pond]

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[twilit gate]

.close

[pearl pond]

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[pearl pond]

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[lilac mulch]

Calc 3, Green’s theorem.

I solved the problem correctly with two other methods. I want to figure out why attempt B isn’t matching.
The correct answer is -24pi.

[lilac mulch]

This is my attempt. I got A and C correct. Just want to know why B isn't right.

This is my formula sheet. The orange arrow indicates what I'm doing with part B.

This is the problem:

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[pearl pond]

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[nocturne grail]

https://cdn.discordapp.com/attachments/1218448674862923809/1314207862544662598/image.png?ex=6752eef3&is=67519d73&hm=fe924a26718387c21a06360f8ddbf6d308663bfe6e0b7979ef5b1af1cb23c4b6&

[nocturne grail]

idrk where to start

[pale frost]

hi

i can use tazculator !

[nocturne grail]

go on...?

[pale frost]

mmm

do you have the solution?

@nocturne grail

[nocturne grail]

how

am i gonna have the solution

[pale frost]

the final result

[nocturne grail]

if i needed help

no.

i dont.

but i want steps

explanation

[pale frost]

ok

@nocturne grail

can this diagram help?

[nocturne grail]

I dont want chatgpt

i want a human

[pale frost]

i didnt use chatgpt

i took it online

[nocturne grail]

taz, if you're not gonna solve it yourself. please dont waste your time trying to help me ❤️

[pale frost]

ok...

ill delete the pic

[dapper kraken]

can you use calculus here?

[nocturne grail]

well

yeah

what i thought of at first is to like

turn this into some coordinates stuff

then integrate/derive it, but i dont know how to integrate (other than the power rule <3) and i dont remember most of my derivation rules.

and idek if integration can work with such an area

like- int(of what function) gives us the area of that triangle xd

[dapper kraken]

maybe you can let the base of the folded triangle be like x then find the crease interms of it

[pearl pond]

@nocturne grail Has your question been resolved?

[dapper kraken]

ok i worked around it for abit and i think letting the red be x can get you an answer, but its verry messy and im sure is not intended

[pearl pond]

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[lilac mulch]

Ello. I still never got help.

[lilac mulch]

Here please ^

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

[lilac mulch]

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[lilac mulch]

<@&286206848099549185>

[pearl pond]

@lilac mulch Has your question been resolved?

[last moth]

Hey, I'll take a look rn

[last moth]

(reading through)

Can you explain your logic for how you're collapsing the 3D problem into 2D here? It doesn't make sense to me.

It seems like you're just ignoring anywhere the problem says z, and then I don't understand how you expect to get the right answer based on that

[pearl pond]

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[spare lark]

So x + 0.15x = 70

x(1.15) = 70

x = 70/1.15

[desert solar]

I think the account has been mutated

[spare lark]

Probably

[sacred crest]

.close

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[spring crystal]

This only be done with integration by part?

[steep saddle]

distribute the sqrtx?

[spring crystal]

X^(5/2)+x^(3/2)?

[steep saddle]

dont forget the coefficient

[spring crystal]

Wym

The dx?

[steep saddle]

5

[spring crystal]

.close

[pearl pond]

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[prime viper]

I have a question

[prime viper]

so here I had 38 nm x 10 ^ -9 m / 1 nm

my end result was wrong cuz i didnt read what they wanted as an answer

anyways how did 10 ^ -9 become 10 ^-8?

my book says rewrite the mantissa

It says you can have a number equal to 1 or greater but no less than 1 or greater than 10

I still don't understand

How did it go from 10 ^ -9 to 10 ^-8

[spare lark]

We know that 10^-9 * 10^1 = 10^-8

But 38 is 3.8 * 10

So make it appear

3.8 * 10 * 10^-9

3.8 *10^-8

[prime viper]

how did you come up with 10 ^ 1

what if i wanted to do 10^2

[spare lark]

Then 10^-9 * 10^2 = 10^-7

[prime viper]

yep

oh wait what

oh wait yep

[prime viper]

so could i use that as my answer

or am i missing something?

[spare lark]

Try to write 278*10^-7 as scientific writing

What is 278 in terms of 10^2

[prime viper]

in decimal?

[spare lark]

Sure

[spare lark]

No

I mean

[prime viper]

oh

[spare lark]

To be between 1 and 10

Do you agree that 278 = 2.78*10² and that 2.78 is between 1 and 10 ?

[prime viper]

no that would have t be a negative

10^-2

2.78 x 10^-2

or -1

[spare lark]

No

Cuz this is 0.278

[prime viper]

or 10 by itself

wait wait

[spare lark]

If negative power of 10 => comma step aside to the left

If positive then comma step aside to the right

[prime viper]

right

if its a negative, u go left

positive, right

[spare lark]

So

Try with
1356*10^-6

[prime viper]

does the decimal start at 1356.

[spare lark]

Yes

[prime viper]

ok

.001356

thats ur new number

[spare lark]

Its not scientific writing

[prime viper]

yeah its not

i dont understand 😔

was i supposed to do .001356 x 10^-6

[spare lark]

No

Let me remake from start

[prime viper]

ok

[spare lark]

We have a number

3457*10^-7

Ok

[prime viper]

mhm

[spare lark]

We write 3457 as a product of (a number between 1 and 10) and (a 10^smth)

So here

3457 = 3.457 * 10^3

Cuz if we make the .

To step aside 3 times to the right

We end up with 3457

And we have also thar 3.457 is between 1 and 10

So far so good ?

[prime viper]

ohh

3.457 is a number

on the scale of 1 and 10

brah

i understand it now

[spare lark]

Now

[prime viper]

ok go on

[spare lark]

You know that 3457 = 3.457 * 10³

[spare lark]

So you replace it in here

Which gives ?

[prime viper]

10^3?

[spare lark]

Write the whole replacing

[prime viper]

3.457 x 10^3?

whatt

[spare lark]

You have that 3457 * 10^-7

[prime viper]

yes

[spare lark]

So

Replace 3457 by the whole value we found and don't forget the *10^-7 at the end

[prime viper]

uhm we move the decimal to the left 3 times

[spare lark]

No

Do

[prime viper]

3.457 which is perfect on scale

oh

[spare lark]

This

[spare lark]

Yup

[prime viper]

can you give me a different example of how i can do that?

[spare lark]

Different method ?

[prime viper]

im a little confused or i dont understand

no not a different method

[spare lark]

Another example ok

[prime viper]

just give me an example with a different number

so i know what to do to solve the other problem

[spare lark]

0.023 * 10^-6

[prime viper]

oh thats below 1

[spare lark]

So what should you do ?

[prime viper]

2.3 is perfect

10^2 is good

2.3 x 10^2

but idk what to do after

[spare lark]

No

[spare lark]

This is 230

[prime viper]

so what am i trying to do?

am i trying to find something that equals 0.023?

[spare lark]

Yes

[prime viper]

ohh

uhm

[spare lark]

As a product of a number between 1 and 10 and also a 10^smth

[prime viper]

lemme see, maybe move the decimal to the right 1 more time lol

oh wait

oh naaur

0.023

[spare lark]

The only trouble here is the power in 10

Otherwise you was on right path

[prime viper]

but if i move it one more time, its gonna be 23 and larger than 10

thats not what we want

[spare lark]

You need 2.3*10^smth = 0.023

Always

[prime viper]

OHH

wait

10^-2

??

[spare lark]

Yup

[prime viper]

wait dont say nothing

[spare lark]

Nothing

What you gonna do huh ?

Kekw

[prime viper]

so when i wanted to get 10^-2, i had to change both the exponent and the number?

in order to equal what u provided as an example

[spare lark]

Wait

[prime viper]

bruh nooo, i had to hold in my thought or else id forget

i was like processing the info

[spare lark]

When you have found the "perfect number" as you said

[spare lark]

You solve smth like this

(Perfect_number)*10^smth = original number

[prime viper]

gotcha

[spare lark]

For smth

[prime viper]

can we try the OG question

[spare lark]

I let you do it and i look

You know everything to handle it now

[prime viper]

a

3457

3.457 x 10^-3???

ok dont say nothing

let me think

ohh

wait

no wait

it was 3.457 x 10^3

was it not?

u can say something

i said that before

[prime viper]

here

[spare lark]

I didnot said it was false

I said you forgot the 10^-7

That comes after

[prime viper]

what do u mean?

[spare lark]

Here

The value you have found was right and i didnot doubt about

[prime viper]

what do u do with the 10^-7?

it isnt relevant to 3457 = 3.457 x 10^3

[spare lark]

3457 * 10^-7
(3.457*10^3) * 10^-7

[spare lark]

Ofc it is

[prime viper]

oh

[spare lark]

And just apply exponents rule to this

To 10^

[prime viper]

what is the expo rule?

[spare lark]

a^b * a^c = a^(b+c)

[prime viper]

so 10^-7 x 10^3 = 10^-4?

[spare lark]

Sure

Whats final ans ?

[prime viper]

3.457 x 10^-4?

[spare lark]

Great

[prime viper]

thats the answer????

whaaaaaaaaaat

[spare lark]

Yup

[prime viper]

bruh no way

i thought it was the one with 10^3

[spare lark]

This one was just the value of the original number

But we transformed it

[spare lark]

And since we replace in the expression here

[prime viper]

how do we know when to transform it?

[spare lark]

When its less than 1 or greater than 10

To make it "perfect number" as you said

[prime viper]

oh the number? 3457?

[spare lark]

Yes

[prime viper]

ohh

thank you

I will write this down

[spare lark]

You're welcome

Practice some and it will be a sandwich soon

[prime viper]

raaaaaarr sammitch

sounds tasty rn, all this math talk made me hungry

💅

[spare lark]

Guten appetit

[prime viper]

Thank you Yaku 🫶

I appreciate your patience in helping me

[spare lark]

If you don't have questions left and everythings clear to you then its perfect

[prime viper]

yes I will attempt some on my own and then if i dont understand it, ill probably come back here

i think I understand it clearly

[spare lark]

Wunderbar

[prime viper]

🫶

Thank you Yaku

I hope you have a nice day :DDDD

[spare lark]

You too

[prime viper]

Imma close this channel

[spare lark]

Aight

[prime viper]

Bye bye :>

[spare lark]

Ciao

[prime viper]

.close

[pearl pond]

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[pearl pond]

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[tepid dust]

if all columns vectors are linearly independent does this necessitate that all row vectors are linearly independent for a square matrix? How about for a non square?

[edgy stone]

!status

[pearl pond]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[rugged jolt]

yes. the dimension of the row space is the same as the dimension of the column space

[nimble osprey]

rank row=rank columns ...but if you have 2 columns of lin. ind. vectors (of dim 4) then the rows cannot be lin. ind. as they will be 4 vectors in a 2 dimensional vector space

[pearl pond]

@tepid dust Has your question been resolved?

[pearl pond]

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[tiny jay]

hi how come when i do it not by symmetry it gives me something else

[tiny jay]

in the end i mean 8*pi^2/3

not 32pi etc that was my prev answer

[raven plank]

Isnt the integration of sec²x, tanx

you put tan²x in yours

[tiny jay]

oh

omg thank u

😭

[raven plank]

Ok

[tiny jay]

.close

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[pearl pond]

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[torpid garnet]

how do i do this qestion 1

[torpid garnet]

,rotate

[latent quail]

What have you tried so far?

[torpid garnet]

maybe

bd/bc

15/21

2/7

ratio

idk

[latent quail]

Pretty close, but there is a slight mistake

[torpid garnet]

ok

[latent quail]

Do you know how to find the area of the parallelogram?

[torpid garnet]

uh isnt bh

[latent quail]

How about the area of the triangle?

[torpid garnet]

bh/2

[latent quail]

So have you found the mistake yet?

[torpid garnet]

i forget to divde by 2

i think

[latent quail]

Correct

[torpid garnet]

so what would it be

15/21 over 2

@latent quail

hello

sir

hello

@latent quail

@latent quail@latent quail

@latent quail

.close

[pearl pond]

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[unkempt yacht]

testing 2

[unkempt yacht]

.close

[pearl pond]

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[pearl pond]

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[pearl pond]

@granite isle Has your question been resolved?

[granite isle]

ratio test

[plush bramble]

Yea that should work

[granite isle]

1/5 is correct?

[versed mica]

yes

[pearl pond]

@granite isle Has your question been resolved?

[pearl pond]

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[pearl pond]

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[ebon ivy]

hey a question asks me to sketch 2x^3+3x-7 with all key features

[ebon ivy]

but i have no idea how to find the x-intercept

i've tried rational root theorem but to no avail

[dusk horizon]

I've accidentally assigned questions like that.

[ebon ivy]

wait so is it not possible to find x intercepts?

[dusk horizon]

You can use Cardano's formula if you like.

[ebon ivy]

that isnt in our study design

[dusk horizon]

Yeah, it's not really solvable for grade 12

[ebon ivy]

rip

allr thx

.close

[pearl pond]

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[blazing birch]

Can someone help with this?

[blazing birch]

<@&286206848099549185>

[warm current]

!15m

[pearl pond]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[blazing birch]

sorry

[pearl pond]

@blazing birch Has your question been resolved?

[blazing birch]

<@&286206848099549185>

bruh

are there actually tutors on here ive been waiting for 25 minutes

[mystic bison]

there are

but

only if they want to help u

solve the problem ur doing

its not like they are obligated to

whats your question

specifically

[latent fjord]

can you explain what the vertical line test is?

[blazing birch]

its desmos.com

[latent fjord]

and if it fails, what does it mean?

[mystic bison]

that is NOT desmos

that is a worksheet

[blazing birch]

I was testing this i didnt think anyone was actually up this late

[latent fjord]

the graphs are from desmos

[mystic bison]

ah

[blazing birch]

No it actually is desmos lmao

[mystic bison]

shoot time zones exist everywhere

[blazing birch]

i click the link and it brings me to desmos

[mystic bison]

its 3am for me!

[blazing birch]

thats cool

[latent fjord]

did you learn what the vertical line test is?

[blazing birch]

i get to have a british man helping me

[mystic bison]

whose british

[blazing birch]

I do not know

[blazing birch]

idk time zones exist everywhere

[mystic bison]

true

[latent fjord]

ok, so the vertical line test is that you draw a vertical line (straight) and see how many times it passes the graph

[mint wave]

part of the problem could be in an earlier post you posted pages and pages of stuff, admitted to not taking notes, and then asked for someone to help you go through all of your pages

[blazing birch]

mmmm okay

[latent fjord]

if the vertical line only passes through the graph once and only once, then y is a function of x

[blazing birch]

bruh but then no one actually ended up helping me

[mystic bison]

yikes

[mint wave]

yes because ppl are here for specific questions not to teach material

[latent fjord]

however if there is any place where the vertical line will cross the graph more than once, y is not a function of x

[latent fjord]

true

[blazing birch]

define a specific question

[blazing birch]

Do i graph the given in b.?

[latent fjord]

yes so try to use the vertical line test on b

there are two outcomes, the line only passes through the curve once, or more than once

which case is it?

[blazing birch]

How do I type the vertical line test in b?

Also It has to be from only 0 Y correct?

[latent fjord]

you can draw it with a pencil

[latent fjord]

it can be a vertical line at any place left to right

[blazing birch]

for -5 it doesnt go through anything but for 5 it goes through the line twice

[blazing birch]

Is it two time?

[latent fjord]

yes

so based on what i said before

does that mean y is a function of x or no?

[blazing birch]

no because one input must have one output?

[latent fjord]

exactly

do the same process with the next one

and see how it goes

[blazing birch]

it's not a function for the second one either

because it crosses through two lines

[latent fjord]

yay! done!

[blazing birch]

Btw do I need to solve this?

He did this stuff and I don't know what this is for

[latent fjord]

thats just proving what you did with the vertical line but with numbers

what you did by drawing the vertical line is the same thing

[blazing birch]

oh okay

[latent fjord]

you chose a value for x and see if it has multiple y values or not

thats what the vertical line test does

[blazing birch]

Do you know how I can do this?

[latent fjord]

put x+2 instead of x

and simplify

[blazing birch]

what do you mean?

[latent fjord]

so in the previous problem you see how you put t instead of x

now do the same thing but you need to put the whole thing (x-2) instead of x

[blazing birch]

Okay

is it like this?

[hot badge]

Hello guys, how are you? If my English is bad, it's because I speak Spanish, so I apologize.

alright, the problem is that I have an exam at 9Am. of math to get through the semester, and I don't understand one thing, I'm not good at math at all so it's probably simple for you but not for me.

the problem says:

Determine the area under the curve and construct the graph of:

f(x)=x in [1,3]

[dusk horizon]

!occupied

[pearl pond]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[blazing birch]

guys i found a tutorial nevermind

.close'

[mental dune]

bruh

[blazing birch]

.close

[pearl pond]

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[hot badge]

Hello guys, how are you? If my English is bad, it's because I speak Spanish, so I apologize.

alright, the problem is that I have an exam at 9Am. of math to get through the semester, and I don't understand one thing, I'm not good at math at all so it's probably simple for you but not for me.

the problem says:

Determine the area under the curve and construct the graph of:

f(x)=x in [1,3]

[gray lantern]

what seems to be the trouble in this case? finding the area?

[hot badge]

Yeah

[gray lantern]

is this for calculus or lower?

[hot badge]

Wait

[mystic bison]

those are integral bounds

[gray lantern]

have you learned fundamental theorem?

[mystic bison]

This problem is either

you know how to integrate or you dont

I suggest you watch a video on what integrating is if you dont know

[gray lantern]

tbf rereading that question makes it seem a lot like calc

[mystic bison]

it is calc

wut

[mint wave]

i mean it just makes a triangle

[mystic bison]

your integrating x

for the bound 3 to 1

[mint wave]

plus a rectangle

[mint wave]

you can do it without calc

[gray lantern]

well i mean my alg physics class would use that wording

[hot badge]

I asked a friend for help about this problem because he knows a little more and he sent me this. This is the only problem on the exam that is strange.

[mystic bison]

oh well if its just a triangle and rectangle like you said thant I guess so

but thats kinda counter intuitive

[gray lantern]

i mean it's just area under the basic line

[mint wave]

yeah i mean integrating is easier but if this isn't a calc class you can still do it

[gray lantern]

yeah

[mystic bison]

whats this work for

on the right

[gray lantern]

this one uses the shape

(triangle + rectangle)

[hot badge]

Guys

As the other friend said, I will watch a video on that topic even if it lasts 3 hours, thank you very much anyway

[mystic bison]

you

probably shouldnt watch the video

¿Cómo se llama la clase de matemáticas en la que estás?

[mint wave]

the video is going to make things more complicated

[mystic bison]

yea theres no shot this is calc

if it was they would have just integregrated already

[hot badge]

Antes era álgebra, ahora cambiaron a matemáticas 3, un nombre más simple

[mystic bison]

Si miras el video que tomé podrás resolverlo pero lo más probable es que no recibas crédito porque no aprendes eso en álgebra.

[mint wave]

so you managed to draw the graph of f(x)=x right?

oop ill let you handle it since you know spanish lol

[mystic bison]

you can help

[mint wave]

oop haha

[mystic bison]

lol

[hot badge]

Veamos, en teoría el problema de la imagen ya contestado está terminado, lo que yo quiero es saber el procedimiento para aplicarlo en los posibles problemas similares que vengan en el examen, para eso estoy aquí JAJA, para ver si ustedes pueden ayudarme a sacar ese procedimiento

[mint wave]

are you able to speak in english at all? i can translate to spanish if needed but it's easier for me in english

[hot badge]

Yeah, i go for the PC

Wait please

Guys ?

[mint wave]

you said to wait

so i was waiting

[hot badge]

They didn't say so I thought they weren't there.

[mint wave]

oh

are you ready now?

[hot badge]

Yep

[mint wave]

so can you draw the graph of f(x)=x for me?

[hot badge]

Isn't it the one that is already answered? or one from scratch you mean

[mint wave]

from scratch

[hot badge]

alright

ready

[mint wave]

can you show me the graph you drew?

[hot badge]

but it's blank without answering, it's still going

[mint wave]

can you draw it on a piece of paper?

[mystic bison]

maybe you should translate to spanish xD

[mystic bison]

he did do what hes told

[mint wave]

perfecto, ese es el plano coordenado. ¿Ahora puedes dibujar f(x)=x en él?

[hot badge]

The translator's translation is strange, it is not understood very well, sorry haha

[mint wave]

what does the graph of f(x)=x look like?

[hot badge]

Like that or am I very lost?

[mint wave]

i'm trying to figure out how to word this. do you know how to graph a function?

[hot badge]

I didn't go to that class lol, I was in Tucson

[mint wave]

were you at the class where they taught you how to graph a function?

[hot badge]

for just that is what it takes help

Look bro, I'm very lost regarding that specific topic for not being in that class at that moment, maybe you're wasting your time with me, maybe there are people who need more help since it's probably not clear to me xD

[mint wave]

i think i found a video on how to graph the function in spanish

https://www.youtube.com/watch?v=j-CzY9Iz7tU

could you maybe watch this video and then graph the function, and then maybe I can help with the second part?

[hot badge]

https://www.youtube.com/watch?v=edE5Y1kOgFw

this guy is good

[mint wave]

perfect

[hot badge]

is it the same?

[mint wave]

that is exactly what we want

yes

just instead of graphing y=2x-1, we want to graph y=x

[hot badge]

yes

[mint wave]

so can you follow the same steps in the video but instead of doing y=2x-1 do y=x?

[hot badge]

That's simpler, I'll do it.

like this ?

[mint wave]

exactly good job!

now can you plot a few more points for me (such as when x=2, x=3, x=4)

[hot badge]

yep

No ?

Xd

[mint wave]

yay! exactly!!

so we just constructed the graph

now it asks us to focus on the interval [1, 3]. Do you know what that means?

[hot badge]

i don't have idea bro JAJAJA

but show me

[mint wave]

it just means we look at the function between x=1 and x=3

[hot badge]

yes

[mint wave]

so we want to find the area under the graph from x=1 to x=3

[hot badge]

mjm

So the table that my friend sent me is wrong? I see negative numbers there.

[mint wave]

your friend just did it slightly differently

[mint wave]

so I took the graph that you just drew, and I divided the area under the curve from x=1 to x=3 into 2 regions

1 of them is atriangle, and one of them is a rectangle

[hot badge]

yes

[mint wave]

from there you calculate the area of the triangle and the area of the rectangle and add them together

[hot badge]

alright

[mint wave]

hmmmm i get different numbers

what is the base of the triangle?

[hot badge]

3 no ?

[mint wave]

not quite. are you looking at the picture i drew?

[hot badge]

How much did you do it with as a base? 2?

[mint wave]

2, yes!

and the height is also 2!

[hot badge]

I thought about it but I counted the 3 numbers below, yes I thought about the 2 but I saw that it covered the 3 and I put it like that, sorry brother

[mint wave]

no worries, we're almost done!

so given that the base of the triangle is 2 and its height is 2, what is the area of the triangle?

[hot badge]

the area is 2 then

[mint wave]

correct!

now let's move on to the rectangle

what is the base and height of the rectangle?

[hot badge]

2 and 2

like triangle

y guess

[mint wave]

the height is actually only 1

note that it only goes up 1 unit

[hot badge]

Cierto, me deja guiar por que esta muy separado el 1 con el centro, jaja es correcto, es 1 hay bastante separación

fck

True, let me guide you because 1 is very separated from the center, haha ​​that's correct, it's 1, there's quite a bit of separation

now yes in english

a= 2

A=2

[mint wave]

yay! now add the areas of the rectangle and the triangle together!

[hot badge]

4

[mint wave]

yes, that is the answer!

[hot badge]

wow

bro

It is very different to work with someone who knows how to teach like you hahaha.

Can I ask for something?

[mint wave]

happy to help 🙂

depends, what is it?

[hot badge]

It's not bad at all hahaha. just so that it sticks in my mind a little more than if you could give me an exercise to answer it on my own.

[mint wave]

ok, sure how about

Determine the area under the curve and construct the graph of:

f(x)=2x+1 in [1,4]

i changed the function and the interval

[hot badge]

[mint wave]

i do have to go to bed now but good luck with your exam!

[hot badge]

thakns bro

good night

How do I close this HAHA

a comand ?

[rapid wagon]

Yes by typing .close

[hot badge]

.close

[pearl pond]

Channel closed

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• Show your work, and if possible, explain where you are stuck.
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[proud yew]

hi guys

[proud yew]

why is ln(absolute value xsquared-1) equal to ln(1-xsquared)

[worthy lance]

Do you know the definition of absolute value?

[proud yew]

when x is bigger than 0 we keep it

if not we multiply by minus

ig

but like

why didnt we keep it as xsquared-1

[worthy lance]

Not x

[proud yew]

it depends on the interval ?

[worthy lance]

What is inside absolute value

[proud yew]

x squared -1

[worthy lance]

In this case we have $x^2-1$

[jolly parrot]

Samuel

[proud yew]

yea

[worthy lance]

If $x^2-1>0$ it will be $x^2-1$

[jolly parrot]

Samuel

[worthy lance]

But if $x^2-1<0$ it will be $-(x^2-1)$

[jolly parrot]

Samuel

[modest hearth]

And if $x^2-1<0$ it will be $1-x^2$

[jolly parrot]

ungu-bungu

[proud yew]

ah

[worthy lance]

Which js that

[proud yew]

but how would i know if it is bigger or less than 0 ?

[worthy lance]

You do not know, that is the point

You cover both situations

So it will be always positive

[proud yew]

oh

okay

[modest hearth]

X² is always positive

[worthy lance]

No but he is talking about the whole thing

[modest hearth]

I see

[proud yew]

alright thanks you two

appreciate it

.close

[pearl pond]

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[pearl pond]

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[livid hound]

What did I do wrong?

Find circumference and area of trapeze.

[pearl pond]

@livid hound Has your question been resolved?

[light helm]

,rotate

[light helm]

,rotate

[light helm]

your work for the perimeter is unclear

which part is the work for the length of the slanted edges?

[livid hound]

The area is 156,25 cm^2?

[light helm]

area is fine

[jolly parrot]

Beata Szydło

Beata Szydło

[light helm]

where's
5^2 + 12.5^2 coming from

[livid hound]

The hypotenuse is 13,46 cm

[light helm]

can you show what right triangle you're using

also try not to use the same variable to represent different things, its confusing

[livid hound]

The triangle is

5^2 cm * 12,5^2 cm = c^2

[light helm]

can you draw/show where that triangle is in the trapezium

[livid hound]

,w 15+10+2(13.46)

[jolly parrot]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by beataszydlo

[light helm]

the value of the hyp is incorrect because you're not using the correct values

[livid hound]

The base of the triangle is 5 cm

And the bright 12,5 cm

[light helm]

the base of the triangle isn't 5cm

[livid hound]

It is…

15 cm is the side’s length .

It’s a in trapeze

[light helm]

of the whole side

where's 5cm coming from?

[livid hound]

15 cm - 10 cm

oh wait this isn’t rectangle

[light helm]

red + green would be 5cm
your base (red) isn't 5cm

[livid hound]

It’s 2,5 cm then?

[light helm]

assuming you have an isosceles trap, yes

[livid hound]

,w sqrt(2,5^2 + 12,5^2)

,w sqrt2,5^2 + 12,5^2

[light helm]

use . for decimal points

[livid hound]

,w sqrt(2.5^2 + 12.5^2)

[jolly parrot]

Results provided by WolframAlpha

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[livid hound]

,w 15cm+10cm+2cm (12.7475cm)

[jolly parrot]

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Upgrade to WolframAlpha Pro!

Requested by beataszydlo

[livid hound]

What-

@light helm

[light helm]

you put an extra cm after the 2

two lengths of (12.7475cm)
would be 2(12.7475cm)

[livid hound]

,w 15cm+10cm+2(12.7475cm)

[jolly parrot]

Results provided by WolframAlpha

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Requested by beataszydlo

[livid hound]

Ok it’s

$50,5 cm$

[jolly parrot]

Beata Szydło

[pearl pond]

@livid hound Has your question been resolved?

[pearl pond]

@livid hound Has your question been resolved?

[pearl pond]

@livid hound Has your question been resolved?

[pearl pond]

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[plush bramble]

,calc 1526 * exp(0.08 * 10)

[jolly parrot]

Result:

3396.1754568795

[plush bramble]

yes

[pearl pond]

@midnight haven Has your question been resolved?

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[vague sinew]

I have to identify the non-permissible values for the variables. I'm stuck on this one as I'm not sure what to do. I got m ≠ √3 but the answer key says m ≠ -3, 3. Where could I have gone wrong?

[plush bramble]

answer key is wrong

[vague sinew]

Did I get the right answer?

[plush bramble]

,w solve m^2 - 3 = 0

[jolly parrot]

Results provided by WolframAlpha

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Requested by rie.mann

[plush bramble]

yes

[vague sinew]

Thanks.

.close

[pearl pond]

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[tulip marsh]

Looks very much so

[plush bramble]

,w expand (x-3)(x-(-4+4i))(x-(-4-4i))

[edgy wren]

without the (x+4)

[plush bramble]

pain i can't read

[tulip marsh]

-4x+4i, -4x-4i

[jolly parrot]

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Requested by rie.mann

[tulip marsh]

😄

Yep, we have it now...

no no you were correct

[edgy wren]

3 is correct

[tulip marsh]

I was telling to the other user that plugged it in (initially wrongly) in wolfram alpha, to check

[midnight haven]

ah

Thank god

thank you guys to

.close

[pearl pond]

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[midnight haven]

Should I use ± or +

[pearl pond]

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[tulip marsh]

on your initial post, your teacher said to use $\pm$. So I think yea, use it

[jolly parrot]

Wild123

[tulip marsh]

Rip.

.close

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[warm sonnet]

how can you find the area of the isosceles trapezoid with the given info?
(BD is the diagonal)

[mint wave]

If I’m thinking about it correctly you could use law of cosines to determine the bottom left angle and then get the rest of the angles from there. Could then probably use law of cosines to get the remaining side lengths

[warm sonnet]

something like this I guess?

ok yea I think it is the correct way

I found that cosa = 8/17 but idk how that helps

ok yea I solved it

thanks for your help 👍

I wouldn't have noticed that for a while 🤣

.close

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[heavy timber]

The base of this vector subspace is {(3,0),(−1,−1)}?

[merry carbon]

"subspace"

[heavy timber]

Sorry

[merry carbon]

(the word is fine, I'm questioning whether the set you're considering is a subspace to begin with...)

[heavy timber]

Oh, yes yes, I have already confirmed it, that is why I did not ask about it, it is a subspace.

[merry carbon]

Fairs if you've verified it, seems a little bit sus but then again I might be tired suspace of R^2 under the "usual" addition/scalar multiplication right?

[heavy timber]

Yep, that's right

[sharp vigil]

just replace alpha with some other scalar that "absorbs" the 2

[heavy timber]

1: 0 e W
2: W1+W2
3: \gamma * W

[heavy timber]

So, is this okay?

[pearl pond]

@heavy timber Has your question been resolved?

[heavy timber]

I trust you! You can answer! Anything you need to know, don't hesitate to ask :)

[pearl pond]

@heavy timber Has your question been resolved?

[livid hound]

Please close. @heavy timber

[pearl pond]

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[eternal parcel]

What exactly is an algebraic integer? And how is it related to "integral in" (integral element)?

[pearl pond]

@eternal parcel Has your question been resolved?

[warm current]

Mind providing context?

[tropic saddle]

https://math.stackexchange.com/questions/70088/why-do-we-use-this-definition-of-algebraic-integer

you can read here a bit about why this definition makes sense

[eternal parcel]

Ring homomorphisms

[pearl pond]

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[flint wyvern]

am i right with A here?

[trail citrus]

can u explain how u found that answer

[severe quarry]

,w x^2 + y^2 = 5 and 3x + y = 5

[jolly parrot]

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[severe quarry]

Yeah, WA agrees

[flint wyvern]

thank you so much!!

.close

[pearl pond]

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[pearl pond]

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[flint wyvern]

am i right with D here?

[flint wyvern]

am i right with this

[dense jasper]

,w inverse of 4^(x+3)-2

[jolly parrot]

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[flint wyvern]

thank you so much

[pearl pond]

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[ocean temple]

How is y=0 a horizontal asymptote for this graph, when there is a blatant line contradicting an asymptotes untampered path?

[versed mica]

you mean how it intersects in the middle?

[ocean temple]

Yes

[versed mica]

look at lim x -> inf

[ocean temple]

Yes

but arent asymptotes uninterrupted?

[versed mica]

not always

[ocean temple]

how can u kno when they are/arent

[versed mica]

we care about lim x-> inf here, it’s about the limiting behavior

[ocean temple]

is it also lim inf ->-x

[versed mica]

yes

but

[ocean temple]

what if lim inf->x wasnt how it was

[versed mica]

x ->

[ocean temple]

what if it was at 1

or -1

[versed mica]

not inf ->

[ocean temple]

and lim->-x stayed the same

[ocean temple]

right yeye my bad dawg

[versed mica]

you mean if you decided to shift everything over one unit?

[ocean temple]

not everything

what if on the + side the y= was +1

and it was kept the same on the - side

would y=0 still be an asymptote

like does it need both sides to be on y=0 for it to be an asymptote

or can it be one side of the graph

and still count

[versed mica]

no

[ocean temple]

so asymptotes are just the stated limits?

would there be a limit placed on an asymptote if it stopped at a certain point, like at x=0

or would it still be stated ast y=0?

[versed mica]

well they aren’t equivalent to the limits but yes that’s how we find the horizontal asymptotes

[versed mica]

wdym

[ocean temple]

like how we jjust talked about

let me draw it for easier understanding

[versed mica]

i think whats confusing you is that you arent aware of what we really mean by horizontal asymptote

you were probably taught that its some horizontal line the function never crosses

[ocean temple]

still horizontal asymptote?

[versed mica]

but that just isnt true

[ocean temple]

still y=0?

[versed mica]

so you mean if you got rid of that right part and shifted it up?

[ocean temple]

yes

[versed mica]

yea

[worthy lance]

Well, assuming that yes

[ocean temple]

so asymptotes are

just the limits of the whole graph

no matter what intereferes

as long as it stops at some point on a y= or a x=

and goes along that line

[versed mica]

asymptotes couldnt care less about what happens for finite values of x

[ocean temple]

that's an asymptote?

[ocean temple]

lol

[ocean temple]

? + written above

[pearl pond]

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[lone mural]

@midnight haven

[midnight haven]

hi so actually I used irem/iquo functions within maple and got that problem fixed

[lone mural]

oh okay sick

[midnight haven]

thx for your time tho!

[lone mural]

glad u got that resolved! sorry about the. incredible hassle

[lone mural]

no worries :) sorry about how that went 😭

[pearl pond]

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[prime bramble]

stupid question. we can always identify a set X with X x {p}, right?

[prime bramble]

p is some random element of any set, it shouldn't matter

[cursive wraith]

well f: X -> X x {p}, f(x) = (x,p) and g:X x {p} -> X, g(x,y) = x certainly say so

[prime bramble]

mhm, okay

so if I have a map X x {p} to X

I can just identify X x {p} with X

so a projection map becomes the identity?

[cursive wraith]

you mean the map g

?

[prime bramble]

sure thing

[cursive wraith]

I mean

not every map X x {p} to X becomes the identity map when you naturally switch X x {p} into X

[prime bramble]

of course, but I'm concerned primarily with the projection rn

[cursive wraith]

I mean

f and g give isomorphisms

g is the "identity?" map

that naturally links X x {p} to X

[prime bramble]

hm