help-39

[glacial sequoia]

we know that both the left hand derivatives and right hand derivatives exist

okay but then what's the difference between 2 and 3

[cosmic garnet]

idk

[cinder flower]

is f_+ the function defined by f_+(x) = max(f(x),0)

[dusk horizon]

f'_(x) is the left side derivative

[cosmic garnet]

like this?

[dusk horizon]

for f(x) = |x|, the f'_(0)=-1

you should try to think of counterexamples

which number?

how do you know that 1 is true?

[pearl pond]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight haven]

hi

[midnight haven]

how do i solve this??

<@&286206848099549185>

[limber glacier]

hae u drawn a picture

[pearl pond]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[midnight haven]

yeah

[limber glacier]

can u send it

[midnight haven]

i just used isoceles triangle didn't get much

isosceles*

[limber glacier]

hmm u cud probably use things like the sine law and stuff

[midnight haven]

no length given how can i use sine law

i mean

idk i don't think i can apply it here

[limber glacier]

u can probably find all the lengths in terms of some unknown and hopefully it cancels out in the end

coz u know three lengths are equal

[midnight haven]

hm

[agile vortex]

I am pretty sure CDA> = x

And also BAD> = x. Because angles are unknown.

I am pretty sure you can do sum of angles together and set equal to 360 degree

[agile vortex]

Let me know how it goes

[midnight haven]

Solved

I had to make a 60-60-60 triangle

[pearl pond]

@midnight haven Has your question been resolved?

Channel closed

Closed by @hard hill

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp smelt]

I have to prove each side is a subset of the other

[compact ridge]

so to prove equality X = Y
you want to show $X \subset Y$ and $Y \subset X$

[jolly parrot]

south's secret twin brother

[compact ridge]

right yeah beat me to it

so you want to prove any member of $P(A \cap B)$ is in $P(A)$ and in $P(B)$

[jolly parrot]

south's secret twin brother

[compact ridge]

your proof should start: let $X \in P(A \cap B)$

[sharp smelt]

Let $X \in P(A) \cap P(B) \implies X \in P(A) \land X \in P(B)$. let $x \in X \implies x \in A \land x \in B \implies x \in A \cap B \implies X \in P(A \cap B) \implies (P(A) \cap P(B)) \subseteq P(A\cap B)$

I'm writing it

[jolly parrot]

south's secret twin brother

[compact ridge]

yep nicely done so far

or just $X \subseteq A \wedge X \subseteq B$

[jolly parrot]

south's secret twin brother

A dense set

[sharp smelt]

Looks good?

[compact ridge]

yep looks good!

well the last X should be a small x, $x \in P(A \cap B)$

or wait

[sharp smelt]

Let $X \in P(A\cap B) . Let x \in X \implies x \in A \land x \in B. \implies X \in P(A) \land X \in P(B) \implies X \in P(A) \cap P(B) \implies P(A \cap B) \subseteq (P(A) \cap P(B))$

[jolly parrot]

A dense set

[compact ridge]

okay this looks good

[sharp smelt]

Let $X \in P(A) \cap P(B) \implies X \in P(A) \land X \in P(B)$.
\let $x \in X \implies x \in A \land x \in B \implies x \in A \cap B \implies X \in P(A \cap B) \implies (P(A) \cap P(B)) \subseteq P(A\cap B)$
\
\

Let $X \in P(A\cap B) . Let x \in X \implies x \in A \land x \in B.
\
\implies X \in P(A) \land X \in P(B) \implies X \in P(A) \cap P(B) \implies P(A \cap B) \subseteq (P(A) \cap P(B))$
\
$\therefore P(A \cap B) = P(A) \cap P(B)$

[compact ridge]

I think this way is easier to show lol

the other way ehhh I'm like only 95% sure

[sharp smelt]

worng emoji

oops

🤞

[jolly parrot]

A dense set

[sharp smelt]

.close

[pearl pond]

Channel closed

Closed by @sharp smelt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grave parcel]

Hi

[grave parcel]

Can someone explain domain and range please

[midnight haven]

no

[proud valve]

Domain is all the values you can put into your function

[grave parcel]

I get that

[proud valve]

Range are all the values that come out

[grave parcel]

???

[grave parcel]

Domain is x coordinate

Range is y coordinates

[proud valve]

Yeah

[grave parcel]

Correct??

Ok

I get that

I just dont understand like how like for the first example how x is real

I dont get that

[proud valve]

Well

It's just which values are allowed

The parabola doesnt have endpoints

So for each x in the real numbers there is a given y value

[grave parcel]

So if x was 2 it would be real

Like how do i know if x is real if i was given a graph

[proud valve]

Oh

Real numbers are practically speaking all numbers

[glacial coral]

x belong to R set
So any R value can be out into the function to get a value (y)

[proud valve]

That arent complex

[grave parcel]

Yes i get that

But like how do i know if a graph is going to have x as any real solutions

[proud valve]

Typically you check if a function is defined within the whole interval

But

In the case of your drawing if there are arrows, that means it keeps going

If it has a dot it indicates an end point

[proud valve]

It most likely just assumes that x is a real number and omits it in the other examples

[grave parcel]

1 sec

[grave parcel]

I understand this the range would be (y: less than or equal to 4 y is real)

@proud valve

[proud valve]

No the range would be

[grave parcel]

Hmmm how??

[proud valve]

You said it yourself!

[grave parcel]

Oh wait ye

I got mixed up

But what would be the domain for that

[proud valve]

The domain for that one is just all x values

[grave parcel]

But i dont understand how x could be all values

[proud valve]

Its a parabola

E.g -x^2

Is there any x you can plug into it so that it doesnt make sense

An example of not making sense would be dividing something by 0

In other words is the function defined for all values of x?

[grave parcel]

So all x values in parabolas are all real x values??

[compact ridge]

yes

the domain of any quadratic function is all real numbers

[grave parcel]

Can the range of any quadratic be all real numbers?

Or is that impossible

[compact ridge]

no

cause of the turning point

[proud valve]

no your own example shows one that isnt

[compact ridge]

well one example doesn't show it for all quadratics

[proud valve]

true

[compact ridge]

in general

[grave parcel]

Huh

[compact ridge]

like proof by listing out 1000000 true examples is

not a proof

cause the 10000001st example could be false

[proud valve]

to be nitpicky it was a quesiton if any could be, then it's enough to show the existence of one!

but

i think you are mixing concepts gary

[grave parcel]

Wait guys one at a time im getting confused

[grave parcel]

Wdym by this

[compact ridge]

I meant to say that the logic for one quadratic happens to work for all quadratics

[proud valve]

Real numbers, are just a group of numbers

[proud valve]

This function never has a y value above 4

thus the range can't be all real numbers

[compact ridge]

yeah now replace 4, for any quadratic with the y-value of the vertex

and then if it's concave down (frowny face)

[compact ridge]

the range is all real y below the turning point

instead of above

[grave parcel]

Ok can we try some examples please

[compact ridge]

do you want to try the quadratics f and h first?

or do you just want to start from a?

[grave parcel]

I think from a

Would be best

[compact ridge]

okay so the line has an endpoint at x = -4 and y = -2

[proud valve]

What values can x take in a

domain is x values

range is y values

[grave parcel]

Oh shoot

Let me retry

Ohhhhh its just greater than or equal to -4

[compact ridge]

oh wait

[compact ridge]

yeah this is now correct

[grave parcel]

It aint

[compact ridge]

I thought you said range was -2

anyways

[grave parcel]

And the range is greater than or equal to -2???

[compact ridge]

you mean the range

[grave parcel]

OOPS

[compact ridge]

the range is y greater or equal to -2

[grave parcel]

Sorry there

So domain is x greater than or equal to -4

Range is y greater than or equal to -2

Correct ??

[compact ridge]

you are missing x and y when you say that

[grave parcel]

I know

[compact ridge]

ok now correct

[grave parcel]

But for most part ye

Ok for b

Let me write it down on a paper

So is this correct?

It’s loading

Ahh my internet

Ok here we go i have my data on

@compact ridge

@proud valve

[compact ridge]

you have your inequality signs the wrong way round

$-3 \le x \le 4$

[jolly parrot]

south's secret twin brother

[grave parcel]

Is it supposed to be this??

[compact ridge]

yeah

that's how you say between in maths (including the endpoints)

[grave parcel]

Oh I thought bc there way no arrows

[compact ridge]

think about it, if x is greater or equal to -3

AND it's less or equal to 4

the overlap is the region in between -3 and 4

[grave parcel]

Ohh ye i see

Ok lets do range

[compact ridge]

yeah so it's nearly the same

[compact ridge]

think about which order the 2 and -5 must go tho

[grave parcel]

Is this right?

@compact ridge

[compact ridge]

right order

you just forgot that it's not 5 but -5

[grave parcel]

AHHH

Let me retry

Wait so what’s the correct answer

@compact ridge

[compact ridge]

${y: -5 \le y \le 2 \ | \ y \in \mathbb R }$

[jolly parrot]

south's secret twin brother

[grave parcel]

Oh yeah i get that

Ok lets do question e bc its a circle

Is this correct for the domain??

[compact ridge]

yep!

[grave parcel]

It would be basically same as range on

[compact ridge]

yeah

[grave parcel]

How do u do i

[compact ridge]

just replace x with y

so you need to replace twice

[grave parcel]

Yee

[compact ridge]

${y: -3 \le y \le 3 \ | \ y \text{ is real} }$

[jolly parrot]

south's secret twin brother

[grave parcel]

Is that for i or e?

[compact ridge]

for e

for i the range is just all real y

[grave parcel]

Oh ok

And there is one more

This is a hyperbolae right?

@compact ridge

[compact ridge]

indeed

so yeah for this kind of rational function (ax+b)/(cx+d)

there is one value of x not in the domain

there is one value of y not in the range

all other real values of x, y are possible

[grave parcel]

Actually i prob dont need to learn hyperbolae i dont think we learning it yet

Can i get help on this though, please last thing for today 🙂

[grave parcel]

Ty tho for that

[stoic siren]

what are you stuck on

[compact ridge]

okay so find the vertex first

[stoic siren]

^

[grave parcel]

I’ve done this so far i dont know how to put the line of symmetry into it though. Is this even correct tho??

[compact ridge]

if you find the vertex and it's (h, k)

[stoic siren]

^^

and remember

normal turning point form is

[compact ridge]

then your equation will be y = (x - h)^2 + k

[grave parcel]

Idk tbh

[compact ridge]

if it's facing upwards

[stoic siren]

$y=a(x-h)^2+k$

[jolly parrot]

pixel

[compact ridge]

or -(x - h)^2 + k if it's facing downwards

here a must be 1 or -1

[stoic siren]

so if h is negative, then it becomes $y=a(x+h)^2+k$

[jolly parrot]

pixel

[grave parcel]

Yes so how do i find h

[compact ridge]

cause the q says it's equivalent to y = x^2

[stoic siren]

(h, k) = (x, y)

[compact ridge]

um

[stoic siren]

oh yeah

you have

[compact ridge]

yeah

[stoic siren]

but

only problem

[grave parcel]

Huhhh

[stoic siren]

@grave parcel h is x-axis, k is y-axis

[grave parcel]

So i done this all wrong???

[compact ridge]

just find the x-coordinates of the vertexes

wait no

[grave parcel]

What’s that

[compact ridge]

yeah you're just guessing for A and C

[grave parcel]

Ye i see

[stoic siren]

it isnt correct

[compact ridge]

a vertex is a turning point

[stoic siren]

he flipped them around

wait no

wait

💀

[compact ridge]

yeah that seems to be the issue

[stoic siren]

yeah he did

[grave parcel]

Ok lets start from scratch im confused

[stoic siren]

okay so knowing this, lets do graph A first

[stoic siren]

okay okay

so

$y=(x-h)^2+k$

[jolly parrot]

pixel

[stoic siren]

$(h, k) = (x, y)$

[jolly parrot]

pixel

[stoic siren]

does that much make sense?

[grave parcel]

Yes

[stoic siren]

okay

so

[grave parcel]

So how do i find x and y

[stoic siren]

do you know what a vertex is

[grave parcel]

The turning point??

[stoic siren]

it is the coordinate of the turning point

yes thats right

now

[grave parcel]

(4,2)

[stoic siren]

(h, k) are the coordinates of the turning point

exactly

[grave parcel]

So graph a turning point is (4,2)

[stoic siren]

now put it in $y=(x-h)^2 +k$

[jolly parrot]

pixel

[stoic siren]

remember $$(x, y) = (h, k) = (4, 2)$$

[grave parcel]

So y = (x-4)^2 + 2

[jolly parrot]

pixel

[stoic siren]

yessss

good job

now do the rest

[grave parcel]

Let’s do graph b

Since its concave down

[stoic siren]

alr

[grave parcel]

We put a negative at the front??

[stoic siren]

exactly

good job

now whats the coordinate of the turning point?

[compact ridge]

yes the negative is very very important

[stoic siren]

which is the same as (h, k)

[compact ridge]

it appears in circle equations too

[grave parcel]

And h and k is (0,9)???

[grave parcel]

Yeee ty

[stoic siren]

yessss

thats correct

now put that in the turning point form equation

what do you get?

dont confuse yourself

[grave parcel]

Uhhh

[stoic siren]

its the same exact process

just give me an answer

[grave parcel]

Y= -(x)^2 + 9

[stoic siren]

yesss exactly but 0 is pretty much non existent

so what does that simplify down to?

[grave parcel]

Y= -(x)^2 + 9

This

[stoic siren]

my goat

youre doing well

[grave parcel]

lol

Ty

[stoic siren]

keep going

[grave parcel]

Now lemme try c

[stoic siren]

you got it

i wont reply till you get the answer

[grave parcel]

Y = (x+5)^2

@stoic siren

[stoic siren]

my king

bro took like 3 seconds

good stuff

thats it!

youre done

[grave parcel]

Ye so easy, i thought it was more complex

Tysm

Any chance u can help me with some logarithms??

[stoic siren]

absolutely no worries

yeah ofc

im here

just spam ping me i genuinely dont mind

[grave parcel]

@compact ridge Btw thank you for helping me out earlier

[compact ridge]

hey no worries

also thank pixel too!

[stoic siren]

$\text{Graph A: } y = (x-4)^2 +2 \
\text{Graph B: } y=-(x)^2+9 \
\text{Graph C: } y=(x+5)^2$

[jolly parrot]

pixel

[grave parcel]

Ok let me complete the page

[stoic siren]

lmk when ur stuck

[grave parcel]

And can u check my answers once im done??

[stoic siren]

ofc

can u ping me everytime u reply

[grave parcel]

@stoic siren

[stoic siren]

helo

[grave parcel]

Sorry image is loading

My internet is so slow today

[stoic siren]

allg

[grave parcel]

Ahhh its not gonna load its gonna take ages

Ill just type them manually

@stoic siren \

[stoic siren]

correct

[grave parcel]

I missed out on question c and question 7

[stoic siren]

this is correct

[grave parcel]

How do you do c??

[stoic siren]

ok so there are some log laws

that you need to know

so

[grave parcel]

Wait

Lemme try

[stoic siren]

okidoki

[grave parcel]

Logx(x) = 1???

Is it something like that

[stoic siren]

yes yes

$log_a(a) = 1$

[jolly parrot]

pixel

[grave parcel]

Yeeee

[stoic siren]

$log_a(1) = 0$

[jolly parrot]

pixel

[stoic siren]

any log that has (1) is always = 0

[grave parcel]

Ok I see

[stoic siren]

so apply those rules

[grave parcel]

What does that 2 in front of the log mean??

[stoic siren]

$2 \cdot log_9(9)$

[jolly parrot]

pixel

[stoic siren]

its just multiplying

[grave parcel]

Is the answer just 1?

Wait no

@stoic siren

[stoic siren]

hmm

close

[stoic siren]

have a look at this again

[grave parcel]

ohhh it’s just 2

[stoic siren]

yeeeee

[grave parcel]

Time being i attempted this its prob wrong tho

[stoic siren]

honestly

i have no idea what this one is telling you

but

it simplifies down to

$log(\frac{M^2P^5}{W})$

[grave parcel]

lol

I was close

Why there p^2??

[stoic siren]

oh sorry

p^5

[grave parcel]

So i was basically correct??

[stoic siren]

yeah

oh wait

also

@grave parcel

[grave parcel]

Ye

[jolly parrot]

pixel

[stoic siren]

its this

when you add two logs

they multiply

[grave parcel]

That’s what i got

OHHHH

So log(ab) = log a + log b?

@stoic siren

[stoic siren]

exactly

good job

[grave parcel]

Can you check this page

You dont need to check question 12 its dumb

[stoic siren]

okay one sec

[grave parcel]

Ty

[stoic siren]

be careful

with rounding

[grave parcel]

Ye idk how to round properly

But ye ty for letting me know

[stoic siren]

if its equal to or great than 5

u round up

so its 1862

what did u write here

[grave parcel]

2045

[grave parcel]

Ty

[stoic siren]

is that 286?

[stoic siren]

correct

[grave parcel]

256

[stoic siren]

okok correct

correct just dont forget base 5 in log

[grave parcel]

Oh yeee

Idk how to graph this (ignore the old markings) this is the last question

@stoic siren

[stoic siren]

whats the turning point

[grave parcel]

Oh i also have 1 more question

[grave parcel]

-7

Wait no

[stoic siren]

remmeber turning point is a coordinate

[grave parcel]

(-2,-7)

[stoic siren]

yesyes

whats y intercept

[grave parcel]

(0,-3)

[stoic siren]

whats x intercept

[grave parcel]

It’s giving me lots of decimal answers

[stoic siren]

well yeah

those are ur intercepts

[grave parcel]

One was like 0.6 something something the other was like -4something something

[stoic siren]

yep

thats correct

[grave parcel]

So do I plot that??

[stoic siren]

yeah yeah

and u connect everything

[grave parcel]

It’s messy but ill fix it up

@stoic siren i this correct?

[stoic siren]

yep

good job

[grave parcel]

WAIT I MESSED UP THE LINE OF SYMMETRY

NO ITS WRONG

I THINK

[stoic siren]

looks right to me

-2

[grave parcel]

No i think this is correct

@stoic siren is this correct or was the one before correct?

[stoic siren]

it looks the same

😭

[grave parcel]

Trust they aint

WAIT IM CONFUSEDDD

@stoic siren 😭

[stoic siren]

😭 bro theyre both at -2

[grave parcel]

Are they

Prob not to scale

Prob a rough sketch

This is very last question

[stoic siren]

ur close

[grave parcel]

Ahhhhhh\

[stoic siren]

$y=a(x-h)^2+k$

[jolly parrot]

pixel

[stoic siren]

whats turning point?

[grave parcel]

(6,1)

[stoic siren]

mmmmmm

focus on ur symbol

[stoic siren]

🔥

[grave parcel]

Why a - tho

[stoic siren]

because

turning point is (6, 1)

not (-6, 1)

[grave parcel]

I thought if it was convace down it turns negative

[stoic siren]

this turns negative

[grave parcel]

OH WAIT NVMMM

I see

I see

lol

[stoic siren]

ya

[grave parcel]

@stoic siren Tysm for all the help tonight, i appreciate it so much i have a large test coming up soon (lots of content I’ve only covered abit today lol) enjoy your day/night 🙂

[stoic siren]

no worries

take care

[grave parcel]

You too

.close

[pearl pond]

Channel closed

Closed by @grave parcel

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upbeat surge]

hey i need help

[upbeat surge]

I don’t understand part (c)

am I even doing this correctly? I’m hella confused

<@&286206848099549185>

anyone with Calculus knowledge pls?

[pearl pond]

@upbeat surge Has your question been resolved?

[upbeat surge]

Not yet brudda

[quiet flower]

yes?

[upbeat surge]

Am I doing this question correctly?

[quiet flower]

wait lemme read sasuke

[upbeat surge]

okay😁

[quiet flower]

the questions last part isnt visible

[upbeat surge]

I’ll send part (c) again, wait a second

[upbeat surge]

Oh you meant after $10?

[quiet flower]

yes

quick bro we dont have time

[upbeat surge]

do you see it now?

[quiet flower]

yes yes

sorry bro i am unable to do this one

wait until someone else helps you

[upbeat surge]

Thanks Naruto

anyways .close

.close

[pearl pond]

Channel closed

Closed by @upbeat surge

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silent mango]

heyy

[silent mango]

i understand most of this but density= mass/volume

so that means u need the volume whch for a cuboid would be length x base x height

so I don't understand why in the working out they have done mass/height /base squared

ty

<@&286206848099549185>

[acoustic belfry]

length * base = base squared

[silent mango]

how?

[acoustic belfry]

look at the diagram

d*d

[silent mango]

so the volume can be found by just doing height over base ^2

ohhh because their the only ones given?

[acoustic belfry]

yes

[silent mango]

okay ty sm

😊

.close

[pearl pond]

Channel closed

Closed by @silent mango

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[covert relic]

Actually I kinda have a physics problem but I have asked my friends. But they were unable to solve it.

Can I post it here. If it's not allowed I will close the channel.

[midnight haven]

whats the physics problem

im guessing you’re in high school, and i am too

also taking physics

so maybe i could help

[covert relic]

I am having trouble with this @midnight haven

[midnight haven]

nvm

im not that smart

[covert relic]

It's OK! Me too!🥲

[midnight haven]

i got a link for you though

its a physics group

like this is mathematics

[covert relic]

I also saw u on phy group

[midnight haven]

other one is physics

ph

oh

[covert relic]

I have that

[midnight haven]

i just looked it up and joined lol

[covert relic]

Oh

😅

[midnight haven]

ohh

i see your question there

i hope someone could help you!

[covert relic]

I have posted it in the forum! Waiting for someone to ans!

<@&286206848099549185>

[languid gazelle]

whats up

[pearl pond]

@covert relic Has your question been resolved?

Channel closed

Closed by @covert relic

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[smoky flare]

This isn't really a difficult question, I just need help understanding what they're asking. What is "true north?".

[smoky flare]

For some reason I can't understand the question lol.

[timber stirrup]

there are two direction false(according to compass) and the true one

so the question is asking the angle between the false west and true north(maybe)

[pearl pond]

@smoky flare Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brittle grove]

Given triangle ABC. Construct a circle (J) passing through A and having B as point of tangency, a circle (K) passing through B and having C as point of tangency. (J) intersects (K) at P . Prove that (PCA) has A as point of tangency.

[pearl pond]

@brittle grove Has your question been resolved?

Channel closed

Closed by @brittle grove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vale moss]

somebody help me w/ this circuit

[sharp vigil]

do you know how inductor series/parallel combinations work in general?

[vale moss]

yea

but i dont know how to simplify it

[sharp vigil]

so we know that two elements are in parallel, if they share the same start and end nodes

and in series, if they share one node and there is nothing else connected to the node between them

[vale moss]

yep

[sharp vigil]

also remember that you can change the shape of the circuit into whatever you want as long as the connections stay the same

[limber glacier]

u probably need to redraw this so u can see how they are actually connecte

[vale moss]

that is what i confused

[limber glacier]

the points at the top and bottom

just draw a line from top to bottom

remove the wire that goes to the left like a C

imagine pinching those points together

[vale moss]

should i do the same thing with the wire that goes to right?

[limber glacier]

which wire do u mean?

will u be able to send a labeled diagram so we can talk abt it easily

[vale moss]

Sure

i dont understand isnt it just (4+2)||(3+5)

[limber glacier]

draw point b to the right

and u dont need that big loop that appears to the left

also draw point a to the left

[limber glacier]

yes thats better

[vale moss]

but i still stuck here

[limber glacier]

now u dont need that big loop thing

theres a point between 2 and 3 right

and another point between 4 and 5

[vale moss]

yes

[limber glacier]

those two points are connected

u dont need to go all around to connect them

just bring those two points together

remove that long wire, and imagine pinching those points together and connect them together

[vale moss]

ok

[limber glacier]

yes

now make it shorter lol

it doesnt really need to be a line. just imagine the wire getting shorter and shorter until it reduces to a point

hopefully thatll help u see

[vale moss]

i think my dumped brain will never get it

[limber glacier]

wait let me draw it

u cud make the inductors horizontal

[limber glacier]

there u go

how are 2 and 4 now conneted

[vale moss]

||

[limber glacier]

yes. replace them with a single resistor having that value

[vale moss]

ohhhhhhhhhh

u r my savior

thank you sooooooooooo much

[pearl pond]

@vale moss Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hearty roost]

What’s an example of a series for which the ratio test is inconclusive because the limit doesn’t exist but still converges?

[cinder flower]

https://en.m.wikipedia.org/wiki/Ratio_test

examples of various things here

(the specific one you want included)

oh uh

i just decided to read your message as “limit is 1” for some reason

maybe you can modify something like $\sum_{n=1}^\infty \frac{(-1)^n}{n}$

[jolly parrot]

generating function courtesan

[cinder flower]

multiply every third term by 1/2 or whatever

still converges but that will mix the ratios of consecutive terms up

ok maybe it’s simpler to use $\sum_{n=1}^\infty \frac{1}{n^2}$ because that one with the modification more obviously converges

[jolly parrot]

generating function courtesan

[cinder flower]

so define $(a_n)$ by $a_n = \frac{1}{2n^2}$ if $n$ is a multiple of 3 and $a_n = \frac{1}{n^2}$ otherwise

[jolly parrot]

generating function courtesan

[cinder flower]

and then $\sum_{n=1}^\infty a_n$ is an example

[jolly parrot]

generating function courtesan

[cinder flower]

actually rather than multiples of 3 we could just do evens. that’s a little simpler

[pearl pond]

@hearty roost Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail oxide]

Say you have an object displaced vector A, and then after it is displaced vector B.Can someone explain why adding these vectors is the same as the object displacing (C) from its intital to its final point? (A + B = C)

[midnight haven]

think of A & B as two separate "instructions" for a specific "movement" (displacement)

combining the two together results in the total movement (displacement)

yes?

[pearl pond]

@frail oxide Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rose sentinel]

Where did I mess up?

[rose sentinel]

It’s a system of differential equations and I solved the first one and subbed it in

The second one (y) apparnetly has no y_0 in the answer so somehow it needs to cancel when plugging in y(0) but I don’t see how it would

I literally have the right answer if the y knot was gone so I’m confused

<@&286206848099549185>

.close

[pearl pond]

Channel closed

Closed by @rose sentinel

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gusty prism]

question

like

[gusty prism]

ik i should know this but i forgot

like if 3L/4 and L/2 got canceled out

in the green color

Would that make L/2 1/2? Or just 2

[sharp vigil]

they divided both sides by L

L/2 = L(1/2)

[gusty prism]

i just dont get

how it got to t2=2mg/3 lol

like he added the mg to the rgiht?

and divided whats with the t2?

if someone can show pls

i feel like the steps were skipped

LIke ill show how i did it

i boxed it

i an so confused

,r=fkip

,flip

[plush bramble]

,rotate

[gusty prism]

like how did it get to that

like 3/4 just disappear ;/

[pearl pond]

@gusty prism Has your question been resolved?

[gusty prism]

OH

Multiply 4/3 top buttom

omg

bottom

.close

[pearl pond]

Channel closed

Closed by @gusty prism

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silent mango]

hey

[silent mango]

how do i find the lcm of a number using the line method

(lowest common multiple)

[green dew]

u mean prime factorisation?

(prime factor decomposition)

[silent mango]

yeah e.g find the lcm of 70 and 56 but using the horizontal line method

the one where u keep dividing

[green dew]

ok so whats the prime factors of each one of them?

70 and 56

using the line

[silent mango]

give me one sec to work it out

[green dew]

sure

[silent mango]

so for 70 i got 2,5,7

and for 56 i got 2^2, 7, 2

so 2 and 7 are common

[green dew]

yes

yk how in gcd, u take the common ones with the lower power?

[silent mango]

gcd?

[green dew]

greatest common divisor

[silent mango]

yes i think so

[green dew]

if not, its okay

[silent mango]

can u explain it plz 🙂

[green dew]

56 = 2³ × 7
70 = 2 × 5 × 7

[green dew]

after lcm

[silent mango]

okayy

[green dew]

focus on the numbers without caring about their exponents/powers

which numbers are common?

[silent mango]

2+7

[green dew]

2 and 7 yes

but in 56, theres 2³ and in 70 theres 2

when dealing with lcm, always take the number with the higher exponent

which is?

[silent mango]

the 2 in 56

[green dew]

u mean 2³

?

[silent mango]

yes sorry

[green dew]

btw im sorry its 2³ not 2², fault

[silent mango]

dw i got it

[green dew]

alr

for the 7, its 7¹ for both

so no problem

now to determine the lcm

u take 2³ and 7, multiply them with the remaining uncommon numbers

[silent mango]

multiply them?

yea

[green dew]

what would be the expression like?

[silent mango]

so

[green dew]

js seeing if u understood well

[silent mango]

2^3 X 7 X 5

[green dew]

bravo

and calculate it

thats LCM(56, 70) for u

[silent mango]

280!

tysm

i have my maths paper 2 ppe tomo morning so now i'm hoping this comes uppp

[green dew]

wait hold

i wanna give u an example

[silent mango]

okay

[green dew]

and see if u can try it by urself

since theres an exam upcoming for ya

[silent mango]

sounds good

[green dew]

alr

determine LCM(378, 330)

[silent mango]

okay gimme a min to work it out

[green dew]

u dont have to calculate it btw

js give me the overall expression

calculating is when ur calculator joins in the work

[silent mango]

sorry i alr did😬

[green dew]

alr then hand it over

[silent mango]

i got 20790

[green dew]

its alright

[silent mango]

which seems very wrong

[green dew]

youd think so

but LCMs tend to be huge

[silent mango]

i did 3^3 X 2 X 7 X 11 X 5

[green dew]

and ur correct

i js verified it

see

[silent mango]

yeah im starting to notice lol

[silent mango]

wow no way

[green dew]

yes way

[silent mango]

while ur here

tysm

but is there anyway u know how to do functions aswell

[green dew]

i mean sure

[silent mango]

its on my last min list😬

[green dew]

thats kinda

[silent mango]

do u want me to find an example

[green dew]

nvm

[green dew]

sure

[silent mango]

thanks alot

[green dew]

so the purpose of functions

is to assign a new value

for their variable

in this case, the variable is x

[silent mango]

okay

[green dew]

now to find f(x - 2)

and ur given f(x)

f(x) is the value of x

while f(x-2) is the value of x - 2

so its just substitution

replace x with x - 2

[silent mango]

so x-2=x^2 -1

[green dew]

no

so look

u have x in the expression f(x)

u want f(x - 2)

[silent mango]

mhm

[green dew]

replace the x in f(x) by x - 2

[silent mango]

so f(x-2)

[green dew]

which is what ur trying to find, yes

[silent mango]

okay sorry maths is not my forte

as u can see lol

[green dew]

let me make it simpler to u

forget the exercice

say we have f(x) = 2 + x³

that means:

[silent mango]

yes

[green dew]

f(2) = 2 + __2__³

[silent mango]

ohhhhhhh

[green dew]

f(46) = 2 + __46__³

[silent mango]

okayy i see

wtv f(x) is is what the x in the equation next door represents

[green dew]

f(k + 3)= 2 + __(k + 3)__³

[silent mango]

got it

[green dew]

its whatever x becomes (as a new value) using the function f

[green dew]

for example this function

any value x we put, it turns it into a cube

and adds 2 to it

hence f(x) = 2 + x³

so it changed x into 2 + x³

[silent mango]

yeahh i understand that bit now

[green dew]

now can u answer it?

[silent mango]

ig i'll give it ago

gimme 2 mins

soooo f(x-2) = (x-2)^2 -1
which can be expanded to (x-2)(x-2)-1
that gives x^2-2x-2x+4-1 i think
which then simplifies to x^2 -4x +3

therefore f(x-2) equals to x^2 -4x+3 ??

hoping rn thats right cos it took foreverr

[green dew]

yep

it is right

[silent mango]

omd

ur rlly good at explaining ur sefo not in highschool

[green dew]

i js started highschool

[silent mango]

TYSM rlly appreciate it thats 2 topics ticked of

[silent mango]

no wayy thats insane and i'm meana b top set😭

[green dew]

uh

whatever that meant

thanks

[silent mango]

classes organised in sets for us dw mb

.close

[pearl pond]

Channel closed

Closed by @silent mango

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland ingot]

help with this please?!?!

[vocal lark]

!status

[pearl pond]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[inland ingot]

1

🤑

[vocal lark]

You didn't even post the directions you were given

[inland ingot]

I did

[inland ingot]

It's literally here bro

[vocal lark]

All I see is an equation and an empty field

[inland ingot]

bro

[vocal lark]

Does the application want you to rewrite it in slope-intercept form?

[inland ingot]

Yeah

[inland ingot]

bro it shows it right here

[heady finch]

so your question is with regards to how the worked examples make sense?

[vocal lark]

Oh I see, at the very bottom in light orange. You just cut off the problem

[inland ingot]

no

that was showing like

the steps

if the helper didn't know how to approach it

or like what to do

[inland ingot]

ye

[heady finch]

well what question specifically do you nee help for

[inland ingot]

here

[vocal lark]

I'm right here working in this already dude

[heady finch]

ah yep

[willow chasm]

what is your first guess of what to do?

[vocal lark]

Lol

Go for it guys

[inland ingot]

convert it

[willow chasm]

how?

[inland ingot]

into slope intercept form

🥶

[willow chasm]

what's the first thing you think of doing?

[inland ingot]

I don't know

[willow chasm]

well the y has to be on its own to be slope-intercept form

how would get y to be the only thing on the left side of the equation?

[inland ingot]

subtract

3x from both sides

[willow chasm]

yes

what would you end up with after doing that

[inland ingot]

5y = 15 - 3x

?

[willow chasm]

yes

now how would you get 5 off of the y?

[inland ingot]

uh

divide

[willow chasm]

yes

what would you get

[inland ingot]

uhh

y = 3 - 3/5 x

?

[willow chasm]

yes but swap 3 and -(3/5)x

[inland ingot]

to what

wait

OH

y = - (3/5)x + 3?

[willow chasm]

+3

[inland ingot]

oh

mb

now what

[willow chasm]

its done

you did it

👏 👏 👏

[inland ingot]

ohh

[inland ingot]

thank you for helping me