#help-39
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yeah the question doesn't specify
it's not very specific
I just dk because what if the pole is not even like what if it is 7
and it's maybe still right if you;re allowed to leave empty space
a(0) = 1
a(1) = 1
a(2) = 4
a(3) = 4
a(4) = 9+3+1
hm
so you have to fill it completely, because there's no option like that
so it's 3a(n−2)
Yeah i agree
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How To Solve This.
@molten carbon Has your question been resolved?
<@&286206848099549185>
Ok I'm here
@molten carbon Has your question been resolved?
How To Solve??
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HII! Can anyone explain me or have some good resources about problem decidability and turing machines. Also how do I prove that F(loop) <= F(M1, M2), where F(M1,M2) = True if and only if M1[111] = True or M2[111] = True
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i suppose youd have to differentiate this and say that the differntiated equation is larger than 0
but how would u get an inequality a out of it
h'(x) >= 0
if a is between some values h'(x) < 0
Positive so
h'(x) = 0 isnt increasing
What's the problem mate
9ax^2-2a+5>0
I'm here to cook maths
hod o we solve for a
Factor by a
ax^2 is always > 0
a>0 right
For the inequality to satisfy
a<0 isn't possible.
So
Use d≤0
We get
wtf is d
oh.
yep
so the detrminant has to be larger than 0
Right?
ohhh
Huh
like
Right
if u expand it and derive it
i think u get 9ax^2-2a+5
cause the expansion is 3ax^3-2ax+5x
its pinned i thunk
They saying to work out possible values of a such that h(x) is increasing as a is positive
Yep
So we take constant
Greater or equals zero
We get 0<x≤2.5
Here zero comes from 9ax²>0=> a>0
These are the possible values
@dire jewel any query?
uh
hm?
whats this from
We take constant greater or equals zero
What's the constant in the derived eq?
-2a+5≥0
a≥5/2
Which implies a≥2.5
i thought its
hmm?
-4 times the constant
times 9 a
cause i thought its the discriminant
has to b eless than 0
right
for 9ax^2-2a+5 to be always bigger than 0
Yep it has to be bigger
Okay take the discriminant
yep
wait what the actual
holup
@dire jewel Has your question been resolved?
ok im back sorry the internet went out
so solving rhe inequality gives us
0<a<2.5???
is that right
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all i got was that the dot product of PA and PB = 3a+b
well, the answer is depending on u, which is not given. Some data are missing.
@junior vapor Has your question been resolved?
u is the unit for the area, not a variable
then it is easy. As the area equals |3b-a|/2=10 and a^2+b^2=80. So you find a,b.
how did you get |3b-a|/2=10?
<@&286206848099549185>
do you know about cross product of vectors?
Ok, what formulas for the area of a triangle do you know?
1/2 bh 1/2 absinc
ok, do you know that dot product is a product of lengthes times cos ?
yes
so. if your unknown dot product is x then you can find this cos in terms of x.
then you find sin. And use this for the area 1/2 absinc
so do I let the dot product of PA and PB = x, which is meant to be |PA||PB|costheta?
yeah
do I need to find what x is as well?
That is exactly what they ask you to do in the problem 🙂
looks plausible
ohhh I see wat u mean now I just sub it into the area
ok I got it from here thank you
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
Use angle multiple formula to expand the 3x terms
$sin(3x) = 3cos^2(x)sin(x) - sin^3(x)$ \ $cos(3x) = cos^3(x) - 3cos(x)sin^2(x)$
LooseEthics
Then you get
$$cos^3(x) - 3cos(x)sin^2(x) - sin(x) = \sqrt{3}(cos(x) - 3cos^2(x)sin(x) + sin^3(x))$$
LooseEthics
are you trying to solve for x or trying to show this is true for all x?
If you're trying to solve for x, there's a much easier way
put the terms in 3x together, and the terms in x together
$\cos(3x) + \sqrt 3 sin(3x) = \sqrt 3 cos(x) + sin(x)$
rafilou is not not born in 2003
solve for x
That's better, forget what I wrote
why
$\frac{1}{2}$ and $\frac{\sqrt{3}}{2}$ are sin and cos of 30 degrees, respectively.
LooseEthics
So
$$L = \frac{\cos(3x)}{2} + \frac{\sqrt 3 \sin(3x)}{2} = \cos(3x)\sin(30) + \cos(30)\sin(3x) = \sin(3x + 30) $$
LooseEthics
Similarly for the other side.
And then you compare the args.
Of course don't forget the periodicity.
thanks
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could someone help me on this question
i'm not sure where the factorisation comes from
tried expanding?
It's probably roots of unity
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hello need help
What is the minimum vertical distance between the parabolas y= x - x² and y=x² + 1
and if it was not the minimum how i would do
no
then just find distance between two vertex
no idea
idk too
do yk how to graph the two parabolas?
yeah
ok then i can use desmos
since vertically speaking
the red parabola is lower than the blue one
we need to find the y value of its vertex
then find its corresponding value using the blue parabola
the absolute value of their difference is the distance
mhmm
does that mean u didnt understand
i didnt not understand why we need to do the difference
its the distance formula
if u wanna calculate the distance between two points A and B on a graph such that A and B are parallel to the Y-axis
all u have to do is subtract their Y values only
cause they have the same X value
how they have same X value
its a rule
if u have the straight line AB parallel to the X axis
then the points A and B have the same x value
wait, by minimum distance
u mean the shortest distance between them vertically?
ys
idk
fr
the minimum distance between two points of a parabolas such that those two points when joined form a line parallel to the y -axis
“If I had an hour to solve a problem, I'd spend 55 minutes thinking about the problem and five minutes thinking about solutions.”
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Sorry for this horrible diagram but if you know that triangle ABC and DCB are congruent, can u say angle DBC and ACB are congruent because of CPCTC?
congruency of triangles = congruency of all angles
^
so if ABC and DCB are congruent because A corresponds to D, B corresponds to C and C corresponds to B
the angles correspond too
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Hello,
I'm trying to understand how Euler's equation of nth order can be reduced to a linear differential equation with constant coefficients, can someone help me figure this out? Ive done some work already: I used the substitution t = ln(x) and so far i've been working on identifying how that transforms the derivatives y^(n) although i cant seem to figure out a general pattern that works. I know the goal is to end up with a linear differential equation with constant coefficients perhaps simply of the form 1/x^k in the derivatives d^iy/dt^i, i dont know what to do with my 'extra' terms tho. I'll send a picture of the results of my work in a second.
@long valley Has your question been resolved?
Does my question make sense? Can i do anything to help it get answered?
<@&286206848099549185> I beg 🙏
yo
dm me
@long valley
$\ln{x} = \log_e{x}$
Daddy| |matr!x
Daddy| |matr!x
therefore, $\frac{dy}{dx} = e^x$
Daddy| |matr!x
I appreciate you trying to help but thats not what i was talking about. 😅
can you be more clear
Do u know what an Euler differential equation is?
<@&286206848099549185> pls hihi
You need to find the initial, or final derivative, and write it down. That's the only solution, or possibly one that goes around, which will be your way of the solution.
The term is a general question, sometimes you don't need to write down a final answer, or in your case it could be the opposite, like dxt over dly as a final answer, or something along this order of lines.
But the solution to your question is already derived by your final answer, which is your question, so it is hidden there. This, what I wrote down could be one of the solutions, but you need to think about it your way of things.
Hope I helped, let me know, or if you need anything else.
Just write it down here, and ping, if you have any more questions.
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Trig with vectors but im slightly confused
What confuses you?
So ive drawn out the triangle it forms
from origin to A and Origin to B with both values
lemme just draw it and show u
I think im not doing something right
Where is the x-axis in relation to these?
Recall AB=OB-OA
It looks confusing
Also, vectors are generally summed(and in consequence subtracted) according to the parallelogram rule
Never seen someone represent it as a triangle
my professor represents them using triangles ngl
when it comes to trigonemtry with vectors only
That's certainly peculiar then
so AB=(6i+2j)-(4i-j)
Essentially, yeah
How will i find the angle it makes with the x axis then
Once you've got the vector, it will indeed form a triangle
Gimme a sec, imma graph it rq
okay okay
Alright, this is the vector that goes from the origin to some point
(any vector can be considered a vector of this form)
The red line is the vector itself
And the blue dot is the point where the vector ends
What can you say about that triangle?
right angle triangle?
Yup
And recall that in any right angles triangle you can apply the form of the trigonometric functions directly
Which values do you have in this triangle?
No, in the triangle I gave you
You've already got the vector AB
Yup
Not really
Look, im order to visualize this
Forget about the exercise for a moment
okay
And assume you've got a vector AB of the form(6,8)
What would the opposite and the adjacent be for the triangle it forms?
6 and 8
Yup, exactly
How would you get the angle it forms with the origin then?
tan
Yup
so then its
Well, arctan to be more precise
inverse function of tan
But that's all you need to do
would 6 be the adjacent?
Yes
,tex .unit circle
Steel
I gave ya a random vector
but it says its wrong
You need to do this for your vector AB
oh shit
im bugging
😭
sorry
2,3
are my values for AB
so then
this would be correct?
So your vector AB is (2,3)?
2?
Imagine the triangle
If you've got a triangle with the point (2,3) at the top
the angle is facing toward the x axis
And another one of its vertices at (0,0)
opposite would be 3
Yup
I think you can go on from here, the answer should be correct now
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!show
Show your work, and if possible, explain where you are stuck.
Ok according to product rule of counting
we should have3 options for the first integer
and 4 options for the 2nd
wait
wait no 3
but im confused as to what to fill in the blakns cause they kinda overlap
7 8 9 right
Yes, and how many options are there for the last digit?
like 4
Why 4?
it has to be odd so u can have 1 7 8 and 9 as the last digit
Which digits?
So when the first digit is 7, the last digits can be…
1 8 or 9
Why do you still think 8 is an odd number?
Go back here
1 7 9
(3 cases) and if first digit is 9, the last digits can be…
A total of (7 cases)
In the middle of each case you have 3 digits
In how many ways can you rearrange them?
we have choice of 3 for first digit
times choice of 2 for second digit
times.1 choice
so 6??
So we have
Case 1: 7 x y z 1 = 6 ways
You have 7 cases
What would be the total then?
ahh
so each first and last digit case
has 3 remaingi digits left
so like 6 subcases for each of the 7 cases
To rearrange in 6 different ways
Correcto
You are welcome
but i'm still cooked for product rule for counting cause idk how u would even think to approach it like that 😭
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How do I find the derivative of this function? I need it to find the critical points in order to determine where the function is increasing and decreasing.
|u|=$\sqrt{u^2}$
David
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how would u do 2a?
am i correct?
Yep
What do you think?
is it constant acceleration
yes
It's final
Initially the plane is at rest which makes the initially velocity 0
And the final velocity is measured the moment when the plane takes off which is when it has obtained enough ground speed of 150m/s
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Why is this the answer? Isn't -1 not in the domain of h, meaning it cannot be a critical point?
it's an open interval, -1 is not included
At -1, its not defined*, but for any value greater than -1, it is increasing
,w graph (x + 5)/(x + 1)
Hold on, the way I thought of it is -5 is a critical point. I set up a number line and determined an interval for which its increasing or decreasing
So like this pretty much
nvm i misread
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Hi, do you know how y was isolated here?
There's a sign error I think
that's what I thought but when I try to use my isolation I don't get the right answer
You divide both sides of the equation by 2 and then bring the x's on the other side
You'll need to factor x out of those terms
And then you're pretty much all set
Do you have a picture of your work?
i scribbled it all out sorry, i'll try your method out right now though
I'm getting:
8 = 1/4pix + y + 1/2
8- 1/4pix - 1/2x = y
x * (-1/4pi - 1/2) ?
yes
thanks i'll try it out
@halcyon karma Has your question been resolved?
I'm supposed to get a positive answer for x but I don't know where I'm messing up
i'll just skip over this since online resources tell me that our y answer is correct
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Require help with the (b) part of this question
I have thought of drawing a perpendicular on the y-axis
to form PM
now sin theta = OP/(AP)
sin beta = (PM)/(OP)
sin phi = (PM)/(AP)
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got the answer lol
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I'm kind of confused
Let's assume for the sake of contradiction that range(T)=null(T) is possible.
We now choice $a$; $a \leqq 5$ linearly indepndetly vector in each set
A dense set
We thus have $2a=5$, but it's evident that this would mean the dimension of the subspace would be 2.5, which is absurd. Thus, we can only conclude that such a transfromation, where range(T)=null(T) isn't possible
A dense set
Is this fine?
<@&286206848099549185>
It isn't injective as it doesn't have the null mapping , $T : V \to {0}$
A dense set
oops
misread it
Let T(v), Q(v) be two non-injective functions from $V \to W$. We then have T(v)= T(u) for some $v,u$. We also have $Q(r) =Q(s) for some $r,s$
A dense set
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I basically want to show it isn't closed under addition
In other words, I want to show that the sum of two non-injective linear maps, can be injective
Let $w_1,\dots, w_m $ be a set of linearly dependent vector in $W$, let $v \in V$., where none of the vectors $v_i,w_i$ are zero
\
Consider the following linear maps $T(v) = \sum_{i=1}^{m} a_iw_i$; $Q(v) = -\sum_{i-=1}^{m-1} a_{i}w_i$.
\
It then follows that $T(v) + Q(v) = a_mw_m$
\
$a_mw_m$ is a linearly independent
\
It also follows that $Q(v)+T(v)$ is injective as $a_mw_m-a_lw_m =0 \implies w_m(a_m-a_l) \implies a_m +l$
\
Thus ${T \in \mathcal{L}(V,W) : T \text { is not injective }}$ is not a subspace of $\mathcal{L}(V,W)$
A dense set
How does this look?
@sharp smelt Has your question been resolved?
<@&286206848099549185>
what does this mean? The idea looks correct though (getting a dimension of 2.5)
We chose $a$ linearly indepndent vectors in$\R^5$
A dense set
dim(range(T))+ dim(null(T))
Probably should mention you used the fundamental theorem of linear maps or whatever its called in there
but yeah thats good
okie
How does this look?
It's still missing some detali I feel
I shoudl probably mention that such that removing $w_m$ doesn't make the set linearly indepndent
A dense set
I gtg for a bit but I think it would be easier to just find a counter example
That's what I've done
but thanks!
Let $w_1,\dots, w_m $ be a set of linearly dependent vector in $W$, let $v \in V$., where none of the vectors $v_i,w_i$ are zero. We chose $w_m$ such that removing it from the list , doesn't make the list linearly indepndent
\
Consider the following linear maps $T(v) = \sum_{i=1}^{m} a_iw_i$; $Q(v) = -\sum_{i-=1}^{m-1} a_{i}w_i$.
\
It then follows that $T(v) + Q(v) = a_mw_m$
\
$a_mw_m$ is a linearly independent
\
It also follows that $Q(v)+T(v)$ is injective as $a_mw_m-a_lw_m =0 \implies w_m(a_m-a_l) \implies a_m +l$
\
Thus ${T \in \mathcal{L}(V,W) : T \text { is not injective }}$ is not a subspace of $\mathcal{L}(V,W)$
A dense set
Let's assume to the contrary. that $T(v_1),\dots, T(v_n)$ isn't linearly independent.That would mean for some $a_i$ all, not equal to zero $\sum_{i=1}^{n} T_i(v_i)=0$. We thus have $T(\sum_{i=1}^{n} a_iv_i)=0$ where $\sum_{i=1}^{n} a_iv_i \neq 0$. However, T is injective, and the only vector mapping to $0$ in an injective function, is the zero vector itself, thus we;ve arrived at a contradiction, and the set ${T_iv_i}$ must be linearly indepndent
A dense set
@sharp smelt Has your question been resolved?
We know that $T: V \to W$. Thus every vector in the range of $T(v)$ has a pre-image in V. It thus follows that ${T ( \sum_{i=1}^{n} \alpha_{i}v_i})$ spans $range(T)$ . But $T(\sum_{i=1}^{n} \alpha_{i} v_{i}) = \sum_{i=1}^{n} \alpha_iT(v_i)$ by linearity. Thus $T(v_1),T(v_2) \dots , T(v_n)$ span $range (T)$
A dense set
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how to do this? i have found the area of the triangle first but not the trapezium. I was thinking we find the area of the triangle and trapezium and subtract them but we dont have h.
pls help and lmk if i was on the right track
ur gonna have to use the other formula of finding the area of triangles which is
use sin area formula
A = 1/2 absin(α)
find the big one first
then whats the issue
and then use the big one minus the small one
how u find the orange cz i find the unshaded first
its a big triangle
and the unshaded one is a small triangle within the big triangle
yea
so find the area of the big triangle
OHHHHHH
and minus the unshaded area from it
1/2 ab sinc bigger one - 1/2 absinc smaller one
yea that makes sense lol i overcomplicated it
thanks alot
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😀
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"The method of differences solves the series that are not AP or GP series. This method finds a sequence in series by subtracting the values of the series term." => https://unacademy.com/content/jee/study-material/mathematics/the-method-of-differences/ ; I think that's what you're trying to figure out.
The method of differences solves the series that are not AP or GP series. This method finds a sequence in series by subtracting the values of the series term.
And it's casted onto the equation, or at least you're trying to do that, in the sum of cube formula.
hint: start with $n^3-(n-1)^3$
@valid kettle
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@sleek junco Has your question been resolved?
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Hi guys
use power of point to find OF, since OD and OE are radius of the circle, they are equal, use power of point again to find x
Yo dude
I tried that but somehow it is 7x4 = 2(2r -2) instead of 7x4 = 2(FO), explain why?
i was thinking of 7x4=2(2OF+2) bit the first one also works
oh wait
why is 2 getting added?
power of point is from edge to edge, not really sure what its called
like it intersects the circle
OF is just to the center
so 7x4 = 2x(OF)!
OOH
ok now I unerstand
so like 2(OF)!
I still have no idea where the extra +2 game from
Oh wait that is to make the other sie
yeah
Thanks bro and after OF is found we found radius an then do the same for x?
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"Projectiles, a,b, are shot up with the same angle and starting velocity from points A,B respectively. If A, B are l apart, find the delay of launching b such that a,b hit midair"
Same angle?
So the horizontal distance and maximum height will be same
What's their initial velocity
Okay
👍
you dont need to check for vertical as both uy and ay are the same
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I need help asap
well, for part A the total price is (price of mugs) + shipping, so if theres no mugs its just shipping
huh
Elaborate Please?
oh shi
WAIT OH
oh
mb
and Part B?
<@&286206848099549185>
ay where df the helpers at
just look at the definition of slope
@inland ingot Has your question been resolved?
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i need a trig function that connects the blue and red graph together including their derivative
if only i knew what the functions were
@stoic siren Has your question been resolved?
also this is gonna sound weird but the derivative of the trig function has to decrease
not increase
so it starts at blue function and ends at red function by decreasing
not increasing
w(x)=Acos(Bx+C)+D
w(8)=Acos(8B+C)+D=f(8)
w(8)=Acos(13.5B+C)+D=h(13.5)
w'(x)=-ABsin(Bx+C)
w'(8)=-ABsin(8x+C)=f'(8)
w'(13.5)=-ABsin(13.5x+C)=h'(8)
so this is the foundation, and also that
w''(x)=-AB^2cos(Bx+C)<0
w'(x)>0
you can probably do some fun stuff with all that but im too tired to
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can someone tell me what i did wrong here
Why do u think u’re wrong
nvm i figured it out
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How can I find an equivalent of a sequence u(n) where u(n+1) = 3/2.u(n) + o(1) ? I know it will be C.(3/2)^n but I can’t prove it
is O(1) supposed to be U(1)?
and should it be (3/2)U(n) or 3/(2.U(n))
o(1) is a sequence that has 0 as limit
And it is (3/2).u(n)
is it of the form -----> A(n+1) = rA(n) + C
In my exercise o(1) = ln(1+exp(u(n)))
It is not a constant so I don’t have direct formula
a base case must be given for this recursion
Just u(0) > 0
I don’t have to find explicit formula but just an equivalent
I can’t formalize the proof that u(n)~C.(3/2)^n
So it's this?
if we take it to the power of e maybe itll simplify
We try to solve this recursion on k then take its log for a
this recursion looks hella tough tho
Yay it seems really horrible to solve
And i’m supposed to find k(n) ~ C^((3/2)^n)
I’ve tried to copy proof for geometrical recursion formula and then work on the other term but that don’t really help either
is it a proving question? @light breach
I don’t understand what you mean
whats the statement of the question
Find the expression for so and so
or
Prove that this recursion has the form so and so
Oh yeah of course it is « find an equivalent of u(n) such as… »
With only the recursion formula
By passing the equality under the ln it give something interesting
I just have to prove that the right term tend to 0
But I don’t think it is true 😭
wait how did you get that n out of that ln. and how did you get that product can you show ur working
I’m using « télescopage » summation
I don’t know how to translate it
<@&286206848099549185>
,rccw
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What are mathematical ways to model this? And then make predictions using the model?
So far I have come up with:
- Sinosudial model
- Lagrange interpolation (but then I can't really use that to make predictions)
I need at least 3 solid models, what else could I do?
this is all the data?
how about a fourier
which is basically sine
but who is counting
@sweet radish Has your question been resolved?
I am using two year data
Do you know about a good tutorial for that :/
look at any tutorial on fft
matlab has a command fft for it
but there are free libraries too
@sweet radish Has your question been resolved?
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
double angle identity
just use the double angle identities in reverse
$\sin(2x) = 2\sin(x)\cos(x)$
to get sin(...) = cos(...) for example
knief
$\cos(2x) = 2\cos^2(x) - 1$
knief

Not too sure LHS=RHS
$-\cos(2x) = \sin(2x)$
knief
you’re solving for the values of x that make it true
no one said it was true for all x
Oh ok I thought it was one of those: prove the identity questions
nope
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does anyone know wtf im looking at? cause i dont
something is missing
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I’m stuck on this since yesterday it’s the last problem on my hw please help;-;
I don’t understand it people tried to explain but I just don’t
No idea how to do or what to do
@dreamy shoal Has your question been resolved?
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.[Do you know what a point of inflection is? Note they allow you to compute the slope of the graph by moving the slider]
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how do yk when u have to use cosine rule or sine rule
you've hopefully heard the mnemonic "soh cah toa"? That's how
im actually restarded
tysm
ive been doing so much cosine/sine rule and non right angled trig i forgot how to do normal stuff 
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plug it back in
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what have you tried?
ok lemme snap a photo!!
(2x)² ?
OH MB 4x^2
yup
bacc (unhelpful)
I would divide by 4 here
I like avoiding big computations
okok!!
bacc (unhelpful)
Now it's stinky normal quadratic equation
how did you get that
uhh
bacc (unhelpful)
you have -4x on the right hand side instead of +4x
yup
tysssm!!
nuit
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how do i determine the equation of this graph
ik x ints r on the top and va's are on bottom
but how do i account for the oblique asympotote
whats the function?
that’s what you have to figure out
thats what we need to find
ah well
@regal herald can i see what u wrote
@river lodge Has your question been resolved?
are all 3 lines the same graph
or just one
same graph
@river lodge Has your question been resolved?
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im confused about part b because i got701/729 but its nothingg close to 3√9
Show your work
well for a =i just expanded the equatio which gave me
1-(1/3)x -(1/9)x^2
then i just did x=1/9 into the expanded equatin
simplufued, and.i got 701/729
How did you get this expansion
through the binomial formula?
I see
yea
,calc 701/729
Result:
0.96159122085048
,calc 9^(1/3)
Result:
2.0800838230519
Oh
1-1/9 = 8/9
So you're supposed to do something with the 8
Factor it out of the cube root yea
what do you mean by that?
@haughty hamlet Has your question been resolved?
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7(III) I don't understand where I'm messing up in my differenatation
lol
this one amath ah
Yea
look like the textbook
Sg?
jc
Damn
Oh
leave it out its a constant
But I don't rlly understand from that part where I factor out 1/6 what rule am I supposed to use if I use product rule it's troublesome
use quotient rule
Can I just use the quotient rule for the partial fractions and ignore the constant?
no
Oh?
Ohhh ok
Oh so when I differentiate I can js differentiate one part only and ignore the others?
ya if its a constant
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wdym by the left
2, 3, 4?
what do you think about 2?
what even is the difference between 2 and 3
what's the subscript notation mean
I see
- for a bit left and + for a bit right
like 0+ and 0-

