#help-39

1 messages · Page 162 of 1

vestal tapir
#

i think

dusk otter
#

yeah the question doesn't specify

#

it's not very specific

#

I just dk because what if the pole is not even like what if it is 7

vestal tapir
#

and it's maybe still right if you;re allowed to leave empty space

#

a(0) = 1
a(1) = 1
a(2) = 4
a(3) = 4

#

a(4) = 9+3+1

#

hm

#

so you have to fill it completely, because there's no option like that

#

so it's 3a(n−2)

dusk otter
#

Yeah i agree

pearl pondBOT
#

@dusk otter Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

molten carbon
pearl pondBOT
molten carbon
#

How To Solve This.

pearl pondBOT
#

@molten carbon Has your question been resolved?

molten carbon
#

<@&286206848099549185>

narrow turtle
#

Ok I'm here

pearl pondBOT
#

@molten carbon Has your question been resolved?

molten carbon
#

How To Solve??

pearl pondBOT
#

@molten carbon Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed by @molten carbon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hazy lotus
#

HII! Can anyone explain me or have some good resources about problem decidability and turing machines. Also how do I prove that F(loop) <= F(M1, M2), where F(M1,M2) = True if and only if M1[111] = True or M2[111] = True

pearl pondBOT
#

@hazy lotus Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dire jewel
pearl pondBOT
dire jewel
#

i suppose youd have to differentiate this and say that the differntiated equation is larger than 0

#

but how would u get an inequality a out of it

spare lark
#

h'(x) >= 0

north talon
#

if a is between some values h'(x) < 0

spare lark
#

Positive so

north talon
dire jewel
#

ok so

#

the derivative of h(x) is lke

spare lark
#

x³ isin't strictly increasing on R ?

#

It has a "hole increased" in x=0 ?

tame jungle
#

What's the problem mate

dire jewel
#

9ax^2-2a+5>0

tame jungle
#

I'm here to cook maths

dire jewel
#

hod o we solve for a

tame jungle
#

I see

#

It's simple

spare lark
#

Factor by a

north talon
tame jungle
#

a>0 right

#

For the inequality to satisfy

#

a<0 isn't possible.

#

So

#

Use d≤0

#

We get

dire jewel
#

wtf is d

tame jungle
#

Determinant

#

b²-4ac

dire jewel
#

oh.

tame jungle
#

yep

dire jewel
#

so the detrminant has to be larger than 0

worn bear
dire jewel
#

i mean

#

larger than 1

#

wait

tame jungle
#

Than zero

#

Since a>0

tame jungle
#

we get d≤0

dire jewel
#

ohhh

tame jungle
#

it's mathematical condition for QE.

#

We get

dire jewel
#

b is 0 right

#

cause theres no x term

tame jungle
dire jewel
#

like

tame jungle
#

Right

dire jewel
#

if u expand it and derive it

#

i think u get 9ax^2-2a+5

#

cause the expansion is 3ax^3-2ax+5x

tame jungle
#

I see I'm unclear of the question

#

What's the original question

dire jewel
#

its pinned i thunk

spare lark
#

They saying to work out possible values of a such that h(x) is increasing as a is positive

tame jungle
#

Yep

#

So we take constant

#

Greater or equals zero

#

We get 0<x≤2.5

#

Here zero comes from 9ax²>0=> a>0

#

These are the possible values

#

@dire jewel any query?

dire jewel
#

uh

tame jungle
dire jewel
tame jungle
#

We take constant greater or equals zero

#

What's the constant in the derived eq?

#

-2a+5≥0

#

a≥5/2

#

Which implies a≥2.5

dire jewel
#

i thought its

tame jungle
#

hmm?

dire jewel
#

-4 times the constant

#

times 9 a

#

cause i thought its the discriminant

#

has to b eless than 0

#

right

#

for 9ax^2-2a+5 to be always bigger than 0

tame jungle
#

Yep it has to be bigger

dire jewel
#

sooo

#

uh

tame jungle
#

Okay take the discriminant

dire jewel
#

-4 * 9a * -(2a+5)<0

#

oh ok so we get an inequality here

tame jungle
#

yep

dire jewel
#

72a^2-180a<0

#

a(72a-180)<0

#

wait now what

tame jungle
#

wait what the actual

dire jewel
#

holup

tame jungle
#

See

#

Discrimination is always less than zero

#

Like i said

#

@dire jewel you here?

pearl pondBOT
#

@dire jewel Has your question been resolved?

dire jewel
#

ok im back sorry the internet went out

#

so solving rhe inequality gives us

#

0<a<2.5???

#

is that right

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

junior vapor
#

all i got was that the dot product of PA and PB = 3a+b

ionic harness
pearl pondBOT
#

@junior vapor Has your question been resolved?

junior vapor
ionic harness
junior vapor
#

<@&286206848099549185>

ionic harness
junior vapor
#

nope

#

pretty sure that isn't taught in my high school

ionic harness
junior vapor
#

1/2 bh 1/2 absinc

ionic harness
junior vapor
#

yes

ionic harness
#

so. if your unknown dot product is x then you can find this cos in terms of x.

#

then you find sin. And use this for the area 1/2 absinc

junior vapor
junior vapor
#

do I need to find what x is as well?

ionic harness
#

That is exactly what they ask you to do in the problem 🙂

junior vapor
#

oh hold up

#

cus i got costheta=x/20 root 2

ionic harness
junior vapor
#

ohhh I see wat u mean now I just sub it into the area

#

ok I got it from here thank you

#

.close

pearl pondBOT
#
Channel closed

Closed by @junior vapor

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight flicker
pearl pondBOT
midnight flicker
#

/status

#

.status

#

!status

pearl pondBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
midnight flicker
#

1

wraith river
#

Use angle multiple formula to expand the 3x terms

#

$sin(3x) = 3cos^2(x)sin(x) - sin^3(x)$ \ $cos(3x) = cos^3(x) - 3cos(x)sin^2(x)$

jolly parrotBOT
#

LooseEthics

wraith river
#

Then you get
$$cos^3(x) - 3cos(x)sin^2(x) - sin(x) = \sqrt{3}(cos(x) - 3cos^2(x)sin(x) + sin^3(x))$$

jolly parrotBOT
#

LooseEthics

midnight flicker
#

yes

#

now what?

#

*sqrt(3) on the ( )?

cursive wraith
#

If you're trying to solve for x, there's a much easier way

#

put the terms in 3x together, and the terms in x together

#

$\cos(3x) + \sqrt 3 sin(3x) = \sqrt 3 cos(x) + sin(x)$

jolly parrotBOT
#

rafilou is not not born in 2003

cursive wraith
#

divide both sides by 2

#

and recognize angle sum formulas

wraith river
midnight flicker
wraith river
#

$\frac{1}{2}$ and $\frac{\sqrt{3}}{2}$ are sin and cos of 30 degrees, respectively.

jolly parrotBOT
#

LooseEthics

wraith river
#

So
$$L = \frac{\cos(3x)}{2} + \frac{\sqrt 3 \sin(3x)}{2} = \cos(3x)\sin(30) + \cos(30)\sin(3x) = \sin(3x + 30) $$

jolly parrotBOT
#

LooseEthics

wraith river
#

Similarly for the other side.

#

And then you compare the args.

#

Of course don't forget the periodicity.

midnight flicker
#

thanks

pearl pondBOT
#

@midnight flicker Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

random hinge
#

could someone help me on this question

pearl pondBOT
random hinge
#

i'm not sure where the factorisation comes from

pseudo oxide
#

tried expanding?

glacial sequoia
#

It's probably roots of unity

pearl pondBOT
#

@random hinge Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fresh silo
#

hello need help

pearl pondBOT
fresh silo
#

What is the minimum vertical distance between the parabolas y= x - x² and y=x² + 1

bronze coyote
#

find the vertex of each parabola

#

and then calculate the distanvce with pythagoras

fresh silo
#

yeah but its maybe not the minimum vertical distance no @bronze coyote

#

?

midnight haven
#

fr

#

well

fresh silo
#

and if it was not the minimum how i would do

bronze coyote
#

wdym minimum vertical distance

#

does it have to be a straight vertical line?

fresh silo
#

no

bronze coyote
#

then just find distance between two vertex

fresh silo
#

if its like this wait

#

how i would do like this

bronze coyote
#

no idea

fresh silo
#

idk too

green dew
#

do yk how to graph the two parabolas?

fresh silo
#

yeah

green dew
#

ok then i can use desmos

#

since vertically speaking

#

the red parabola is lower than the blue one

#

we need to find the y value of its vertex

#

then find its corresponding value using the blue parabola

#

the absolute value of their difference is the distance

fresh silo
#

mhmm

green dew
#

does that mean u didnt understand

fresh silo
#

i didnt not understand why we need to do the difference

green dew
#

its the distance formula

#

if u wanna calculate the distance between two points A and B on a graph such that A and B are parallel to the Y-axis

#

all u have to do is subtract their Y values only

#

cause they have the same X value

fresh silo
#

how they have same X value

green dew
#

its a rule

#

if u have the straight line AB parallel to the X axis

#

then the points A and B have the same x value

#

wait, by minimum distance

#

u mean the shortest distance between them vertically?

fresh silo
#

ys

green dew
#

wouldnt that be 0

#

they intersect

fresh silo
#

idk

midnight haven
green dew
#

i realized i gave u maximum vertical distance, thats why

#

yeah, @fresh silo its 0 bud

midnight haven
#

the minimum distance between two points of a parabolas such that those two points when joined form a line parallel to the y -axis

#

“If I had an hour to solve a problem, I'd spend 55 minutes thinking about the problem and five minutes thinking about solutions.”

pearl pondBOT
#

@fresh silo Has your question been resolved?

#
Channel closed

Closed by @fresh silo

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hidden void
#

Sorry for this horrible diagram but if you know that triangle ABC and DCB are congruent, can u say angle DBC and ACB are congruent because of CPCTC?

cursive wraith
#

congruency of triangles = congruency of all angles

crisp saddle
#

^

cursive wraith
#

so if ABC and DCB are congruent because A corresponds to D, B corresponds to C and C corresponds to B

#

the angles correspond too

hidden void
#

perfect ty

#

.close

pearl pondBOT
#
Channel closed

Closed by @hidden void

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long valley
#

Hello,

I'm trying to understand how Euler's equation of nth order can be reduced to a linear differential equation with constant coefficients, can someone help me figure this out? Ive done some work already: I used the substitution t = ln(x) and so far i've been working on identifying how that transforms the derivatives y^(n) although i cant seem to figure out a general pattern that works. I know the goal is to end up with a linear differential equation with constant coefficients perhaps simply of the form 1/x^k in the derivatives d^iy/dt^i, i dont know what to do with my 'extra' terms tho. I'll send a picture of the results of my work in a second.

long valley
pearl pondBOT
#

@long valley Has your question been resolved?

long valley
#

Does my question make sense? Can i do anything to help it get answered?

#

<@&286206848099549185> I beg 🙏

random flume
#

dm me

#

@long valley

#

$\ln{x} = \log_e{x}$

jolly parrotBOT
#

Daddy| |matr!x

random flume
#

@long valley

#

If $y=e^{x}$

jolly parrotBOT
#

Daddy| |matr!x

random flume
#

therefore, $\frac{dy}{dx} = e^x$

jolly parrotBOT
#

Daddy| |matr!x

random flume
#

now graph this

#

the linear function yu talking about

#

is the tanget to this curve

long valley
#

I appreciate you trying to help but thats not what i was talking about. 😅

random flume
#

can you be more clear

long valley
#

Do u know what an Euler differential equation is?

long valley
midnight haven
#

The term is a general question, sometimes you don't need to write down a final answer, or in your case it could be the opposite, like dxt over dly as a final answer, or something along this order of lines.

#

But the solution to your question is already derived by your final answer, which is your question, so it is hidden there. This, what I wrote down could be one of the solutions, but you need to think about it your way of things.

#

Hope I helped, let me know, or if you need anything else.

#

Just write it down here, and ping, if you have any more questions.

pearl pondBOT
#

@long valley Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lapis hatch
pearl pondBOT
lapis hatch
#

Trig with vectors but im slightly confused

west bluff
lapis hatch
#

So ive drawn out the triangle it forms

#

from origin to A and Origin to B with both values

#

lemme just draw it and show u

#

I think im not doing something right

pine jay
#

Where is the x-axis in relation to these?

west bluff
pine jay
#

It looks confusing

west bluff
#

Also, vectors are generally summed(and in consequence subtracted) according to the parallelogram rule

#

Never seen someone represent it as a triangle

lapis hatch
#

when it comes to trigonemtry with vectors only

west bluff
lapis hatch
west bluff
lapis hatch
#

How will i find the angle it makes with the x axis then

west bluff
#

Gimme a sec, imma graph it rq

lapis hatch
#

okay okay

west bluff
#

Alright, this is the vector that goes from the origin to some point

#

(any vector can be considered a vector of this form)

#

The red line is the vector itself

#

And the blue dot is the point where the vector ends

#

What can you say about that triangle?

lapis hatch
#

right angle triangle?

west bluff
#

And recall that in any right angles triangle you can apply the form of the trigonometric functions directly

#

Which values do you have in this triangle?

lapis hatch
#

OA and OB

#

so

#

4i-j

#

and

#

6i+2j

west bluff
#

You've already got the vector AB

lapis hatch
#

hm

#

so AB is the hypotenuese right?

#

of the triangle

west bluff
lapis hatch
#

OA is the opposite

#

and OB the adjacent

west bluff
#

Look, im order to visualize this

#

Forget about the exercise for a moment

lapis hatch
#

okay

west bluff
#

And assume you've got a vector AB of the form(6,8)

#

What would the opposite and the adjacent be for the triangle it forms?

lapis hatch
#

6 and 8

west bluff
#

How would you get the angle it forms with the origin then?

lapis hatch
#

tan

west bluff
lapis hatch
#

so then its

west bluff
#

Well, arctan to be more precise

lapis hatch
#

inverse function of tan

west bluff
#

But that's all you need to do

lapis hatch
#

would 6 be the adjacent?

west bluff
#

Yes

lapis hatch
#

so then 8/6

#

okay lemme try

broken fossil
#

,tex .unit circle

jolly parrotBOT
lapis hatch
#

the answers wrong

#

thats what i got

west bluff
lapis hatch
#

but it says its wrong

west bluff
#

You need to do this for your vector AB

lapis hatch
#

oh shit

#

im bugging

#

😭

#

sorry

#

2,3

#

are my values for AB

#

so then

#

this would be correct?

west bluff
lapis hatch
#

yea because AB=(6i+2j)-(4i-j)

#

2i+3j

west bluff
#

Alright, then what would be the opposite here?

#

Recall tan θ=opposite/adjacent

lapis hatch
#

2?

west bluff
lapis hatch
#

wait no

#

3 because

west bluff
#

If you've got a triangle with the point (2,3) at the top

lapis hatch
#

the angle is facing toward the x axis

west bluff
#

And another one of its vertices at (0,0)

lapis hatch
#

opposite would be 3

west bluff
#

I think you can go on from here, the answer should be correct now

lapis hatch
#

yes

#

i will try this answer now

#

thanks catthumbsup

#

.close

pearl pondBOT
#
Channel closed

Closed by @lapis hatch

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dire jewel
pearl pondBOT
worthy lance
#

!show

pearl pondBOT
#

Show your work, and if possible, explain where you are stuck.

dire jewel
#

Ok according to product rule of counting

#

we should have3 options for the first integer

#

and 4 options for the 2nd

#

wait

#

wait no 3

#

but im confused as to what to fill in the blakns cause they kinda overlap

worthy lance
#

You have three options for ghe first digit

#

Which are those options?

dire jewel
#

7 8 9 right

worthy lance
#

Yes, and how many options are there for the last digit?

dire jewel
#

like 4

worthy lance
#

Why 4?

dire jewel
#

it has to be odd so u can have 1 7 8 and 9 as the last digit

worthy lance
#

Which are those 4 digits?

#

Do you know what odd means?

#

define odd

dire jewel
#

oh wait im fucking stupid

#

its 3 digits

worthy lance
#

Which digits?

dire jewel
#

1 7 9

#

mb

worthy lance
#

So when the first digit is 7, the last digits can be…

dire jewel
#

1 8 or 9

worthy lance
#

Why do you still think 8 is an odd number?

worthy lance
dire jewel
#

wait

#

wait

#

i think im slightly autistic

#

its 1 7 9

dire jewel
#

Okokokok

#

if the first digit is 7

#

then the last digit can be 1 or 9

worthy lance
#

(2 cases)

#

If the first number is 8, the last digits can be…

dire jewel
#

1 7 9

worthy lance
#

(3 cases) and if first digit is 9, the last digits can be…

dire jewel
#

1 and 7

#

2 cases

worthy lance
#

A total of (7 cases)

#

In the middle of each case you have 3 digits

#

In how many ways can you rearrange them?

dire jewel
#

we have choice of 3 for first digit

#

times choice of 2 for second digit

#

times.1 choice

#

so 6??

worthy lance
#

So we have

#

Case 1: 7 x y z 1 = 6 ways

#

You have 7 cases

#

What would be the total then?

dire jewel
#

ahh

#

so each first and last digit case

#

has 3 remaingi digits left

#

so like 6 subcases for each of the 7 cases

worthy lance
#

To rearrange in 6 different ways

dire jewel
#

so its 7*6??

#

42??

worthy lance
#

Correcto

dire jewel
#

oh ok nice

#

thank u

worthy lance
#

You are welcome

dire jewel
#

but i'm still cooked for product rule for counting cause idk how u would even think to approach it like that 😭

worthy lance
#

!done

pearl pondBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

dire jewel
#

.close

pearl pondBOT
#
Channel closed

Closed by @dire jewel

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

round pollen
pearl pondBOT
round pollen
#

How do I find the derivative of this function? I need it to find the critical points in order to determine where the function is increasing and decreasing.

wet swallow
#

|u|=$\sqrt{u^2}$

jolly parrotBOT
round pollen
#

I got it

#

thanks for the help tho!

#

.close

pearl pondBOT
#
Channel closed

Closed by @round pollen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

queen ice
#

how would u do 2a?

pearl pondBOT
queen ice
#

am i correct?

midnight haven
queen ice
#

is final velocity 150 or initial?

#

@midnight haven

midnight haven
queen ice
#

probably final

#

cus 150 - 0

manic sparrow
queen ice
#

yes

midnight haven
# queen ice probably final

It's final
Initially the plane is at rest which makes the initially velocity 0
And the final velocity is measured the moment when the plane takes off which is when it has obtained enough ground speed of 150m/s

queen ice
#

ohhh right

#

yea that’s better

#

thanks

#

.close

pearl pondBOT
#
Channel closed

Closed by @queen ice

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

round pollen
#

Why is this the answer? Isn't -1 not in the domain of h, meaning it cannot be a critical point?

hard kite
#

it's an open interval, -1 is not included

#

At -1, its not defined*, but for any value greater than -1, it is increasing

#

,w graph (x + 5)/(x + 1)

round pollen
#

Hold on, the way I thought of it is -5 is a critical point. I set up a number line and determined an interval for which its increasing or decreasing

#

So like this pretty much

hard kite
#

nvm i misread

round pollen
#

.close

pearl pondBOT
#
Channel closed

Closed by @round pollen

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

halcyon karma
#

Hi, do you know how y was isolated here?

halcyon karma
summer imp
#

There's a sign error I think

halcyon karma
#

that's what I thought but when I try to use my isolation I don't get the right answer

summer imp
#

You divide both sides of the equation by 2 and then bring the x's on the other side

#

You'll need to factor x out of those terms

#

And then you're pretty much all set

#

Do you have a picture of your work?

halcyon karma
#

i scribbled it all out sorry, i'll try your method out right now though

#

I'm getting:
8 = 1/4pix + y + 1/2
8- 1/4pix - 1/2x = y

summer imp
#

That seems good

#

Then you can take an x out of - 1/4pix - 1/2x

halcyon karma
#

x * (-1/4pi - 1/2) ?

summer imp
#

yes

halcyon karma
#

thanks i'll try it out

pearl pondBOT
#

@halcyon karma Has your question been resolved?

halcyon karma
#

I'm supposed to get a positive answer for x but I don't know where I'm messing up

#

i'll just skip over this since online resources tell me that our y answer is correct

#

.close

pearl pondBOT
#
Channel closed

Closed by @halcyon karma

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight haven
#

Require help with the (b) part of this question

midnight haven
#

I have thought of drawing a perpendicular on the y-axis

#

to form PM

#

now sin theta = OP/(AP)

#

sin beta = (PM)/(OP)

#

sin phi = (PM)/(AP)

#

.close

pearl pondBOT
#
Channel closed

Closed by @maiden stag

Use .reopen if this was a mistake.

midnight haven
#

got the answer lol

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp smelt
pearl pondBOT
sharp smelt
#

I'm kind of confused

#

Let's assume for the sake of contradiction that range(T)=null(T) is possible.

#

We now choice $a$; $a \leqq 5$ linearly indepndetly vector in each set

jolly parrotBOT
#

A dense set

sharp smelt
#

We thus have $2a=5$, but it's evident that this would mean the dimension of the subspace would be 2.5, which is absurd. Thus, we can only conclude that such a transfromation, where range(T)=null(T) isn't possible

jolly parrotBOT
#

A dense set

sharp smelt
#

Is this fine?

#

<@&286206848099549185>

#

It isn't injective as it doesn't have the null mapping , $T : V \to {0}$

jolly parrotBOT
#

A dense set

sharp smelt
#

oops

#

misread it

#

Let T(v), Q(v) be two non-injective functions from $V \to W$. We then have T(v)= T(u) for some $v,u$. We also have $Q(r) =Q(s) for some $r,s$

jolly parrotBOT
#

A dense set
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

sharp smelt
#

I basically want to show it isn't closed under addition

#

In other words, I want to show that the sum of two non-injective linear maps, can be injective

#

Let $w_1,\dots, w_m $ be a set of linearly dependent vector in $W$, let $v \in V$., where none of the vectors $v_i,w_i$ are zero
\
Consider the following linear maps $T(v) = \sum_{i=1}^{m} a_iw_i$; $Q(v) = -\sum_{i-=1}^{m-1} a_{i}w_i$.
\
It then follows that $T(v) + Q(v) = a_mw_m$
\
$a_mw_m$ is a linearly independent
\
It also follows that $Q(v)+T(v)$ is injective as $a_mw_m-a_lw_m =0 \implies w_m(a_m-a_l) \implies a_m +l$
\
Thus ${T \in \mathcal{L}(V,W) : T \text { is not injective }}$ is not a subspace of $\mathcal{L}(V,W)$

jolly parrotBOT
#

A dense set

sharp smelt
#

How does this look?

pearl pondBOT
#

@sharp smelt Has your question been resolved?

sharp smelt
#

<@&286206848099549185>

signal atlas
sharp smelt
#

We chose $a$ linearly indepndent vectors in$\R^5$

jolly parrotBOT
#

A dense set

signal atlas
#

Oh ok

#

And how do u get the equation 2a=5

sharp smelt
#

dim(range(T))+ dim(null(T))

signal atlas
#

Probably should mention you used the fundamental theorem of linear maps or whatever its called in there

#

but yeah thats good

sharp smelt
#

okie

sharp smelt
#

It's still missing some detali I feel

#

I shoudl probably mention that such that removing $w_m$ doesn't make the set linearly indepndent

jolly parrotBOT
#

A dense set

signal atlas
# sharp smelt

I gtg for a bit but I think it would be easier to just find a counter example

sharp smelt
#

That's what I've done

#

but thanks!

#

Let $w_1,\dots, w_m $ be a set of linearly dependent vector in $W$, let $v \in V$., where none of the vectors $v_i,w_i$ are zero. We chose $w_m$ such that removing it from the list , doesn't make the list linearly indepndent
\
Consider the following linear maps $T(v) = \sum_{i=1}^{m} a_iw_i$; $Q(v) = -\sum_{i-=1}^{m-1} a_{i}w_i$.
\
It then follows that $T(v) + Q(v) = a_mw_m$
\
$a_mw_m$ is a linearly independent
\
It also follows that $Q(v)+T(v)$ is injective as $a_mw_m-a_lw_m =0 \implies w_m(a_m-a_l) \implies a_m +l$
\
Thus ${T \in \mathcal{L}(V,W) : T \text { is not injective }}$ is not a subspace of $\mathcal{L}(V,W)$

jolly parrotBOT
#

A dense set

sharp smelt
#

Let's assume to the contrary. that $T(v_1),\dots, T(v_n)$ isn't linearly independent.That would mean for some $a_i$ all, not equal to zero $\sum_{i=1}^{n} T_i(v_i)=0$. We thus have $T(\sum_{i=1}^{n} a_iv_i)=0$ where $\sum_{i=1}^{n} a_iv_i \neq 0$. However, T is injective, and the only vector mapping to $0$ in an injective function, is the zero vector itself, thus we;ve arrived at a contradiction, and the set ${T_iv_i}$ must be linearly indepndent

jolly parrotBOT
#

A dense set

sharp smelt
pearl pondBOT
#

@sharp smelt Has your question been resolved?

sharp smelt
#

We know that $T: V \to W$. Thus every vector in the range of $T(v)$ has a pre-image in V. It thus follows that ${T ( \sum_{i=1}^{n} \alpha_{i}v_i})$ spans $range(T)$ . But $T(\sum_{i=1}^{n} \alpha_{i} v_{i}) = \sum_{i=1}^{n} \alpha_iT(v_i)$ by linearity. Thus $T(v_1),T(v_2) \dots , T(v_n)$ span $range (T)$

jolly parrotBOT
#

A dense set

sharp smelt
#

.close

pearl pondBOT
#
Channel closed

Closed by @sharp smelt

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

upbeat wigeon
#

how to do this? i have found the area of the triangle first but not the trapezium. I was thinking we find the area of the triangle and trapezium and subtract them but we dont have h.

upbeat wigeon
#

pls help and lmk if i was on the right track

green dew
#

ur gonna have to use the other formula of finding the area of triangles which is

bronze coyote
#

use sin area formula

green dew
#

A = 1/2 absin(α)

upbeat wigeon
#

i used that

bronze coyote
#

find the big one first

green dew
#

then whats the issue

bronze coyote
#

and then use the big one minus the small one

upbeat wigeon
bronze coyote
#

its a big triangle

#

and the unshaded one is a small triangle within the big triangle

upbeat wigeon
#

yea

bronze coyote
#

so find the area of the big triangle

upbeat wigeon
#

OHHHHHH

bronze coyote
#

and minus the unshaded area from it

upbeat wigeon
#

i get it now

#

tysm

thick swallow
upbeat wigeon
#

thanks alot

#

.close

pearl pondBOT
#
Channel closed

Closed by @upbeat wigeon

Use .reopen if this was a mistake.

thick swallow
#

😀

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gilded dew
pearl pondBOT
gilded dew
#

Help with problem 1 please

#

What is method of difference?

midnight haven
# gilded dew What is method of difference?

"The method of differences solves the series that are not AP or GP series. This method finds a sequence in series by subtracting the values of the series term." => https://unacademy.com/content/jee/study-material/mathematics/the-method-of-differences/ ; I think that's what you're trying to figure out.

Unacademy

The method of differences solves the series that are not AP or GP series. This method finds a sequence in series by subtracting the values of the series term.

midnight haven
# gilded dew

And it's casted onto the equation, or at least you're trying to do that, in the sum of cube formula.

valid kettle
jolly parrotBOT
#

@valid kettle

gilded dew
#

Ok thx!!!

#

.close

pearl pondBOT
#
Channel closed

Closed by @gilded dew

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sleek junco
pearl pondBOT
sleek junco
#

what is Ay Bx By

#

and where is Ax

pearl pondBOT
#

@sleek junco Has your question been resolved?

sleek junco
#

.close

pearl pondBOT
#
Channel closed

Closed by @sleek junco

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sterile star
#

Hi guys

pearl pondBOT
sterile star
#

I am having a problem with this problem

#

How do I solve it?

dapper kraken
sterile star
#

I tried that but somehow it is 7x4 = 2(2r -2) instead of 7x4 = 2(FO), explain why?

dapper kraken
#

oh wait

sterile star
#

why is 2 getting added?

dapper kraken
#

power of point is from edge to edge, not really sure what its called

#

like it intersects the circle

#

OF is just to the center

sterile star
#

so 7x4 = 2x(OF)!

#

OOH

#

ok now I unerstand

#

so like 2(OF)!

#

I still have no idea where the extra +2 game from

#

Oh wait that is to make the other sie

dapper kraken
#

yeah

sterile star
#

Thanks bro and after OF is found we found radius an then do the same for x?

dapper kraken
#

yeah

#

lemme know what you get

sterile star
#

Oh Ok now I see it thanks mate I got it

#

.close

pearl pondBOT
#
Channel closed

Closed by @sterile star

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

north talon
#

"Projectiles, a,b, are shot up with the same angle and starting velocity from points A,B respectively. If A, B are l apart, find the delay of launching b such that a,b hit midair"

north talon
#

i wanna know if my sol. is correct

#

<@&286206848099549185>

chilly sand
#

So the horizontal distance and maximum height will be same

#

What's their initial velocity

north talon
#

the same

#

i let it be u

chilly sand
#

Okay

iron basin
#

you dont need to check for vertical as both uy and ay are the same

north talon
#

tysm

#

.close

pearl pondBOT
#
Channel closed

Closed by @north talon

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

inland ingot
#

I need help asap

pearl pondBOT
inland ingot
#

W if someone helps

#

🤑

north talon
inland ingot
#

Elaborate Please?

#

oh shi

#

WAIT OH

#

oh

#

mb

inland ingot
#

<@&286206848099549185>

#

ay where df the helpers at

north talon
#

just look at the definition of slope

pearl pondBOT
#

@inland ingot Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stoic siren
#

i need a trig function that connects the blue and red graph together including their derivative

regal herald
#

if only i knew what the functions were

pearl pondBOT
#

@stoic siren Has your question been resolved?

stoic siren
#

also this is gonna sound weird but the derivative of the trig function has to decrease

#

not increase

#

so it starts at blue function and ends at red function by decreasing

#

not increasing

regal herald
#

w(x)=Acos(Bx+C)+D

w(8)=Acos(8B+C)+D=f(8)
w(8)=Acos(13.5B+C)+D=h(13.5)

w'(x)=-ABsin(Bx+C)

w'(8)=-ABsin(8x+C)=f'(8)
w'(13.5)=-ABsin(13.5x+C)=h'(8)

so this is the foundation, and also that
w''(x)=-AB^2cos(Bx+C)<0
w'(x)>0

you can probably do some fun stuff with all that but im too tired to

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

river lodge
pearl pondBOT
river lodge
#

can someone tell me what i did wrong here

dusty flame
#

Why do u think u’re wrong

river lodge
#

nvm i figured it out

river lodge
#

.close

pearl pondBOT
#
Channel closed

Closed by @river lodge

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

light breach
#

How can I find an equivalent of a sequence u(n) where u(n+1) = 3/2.u(n) + o(1) ? I know it will be C.(3/2)^n but I can’t prove it

woeful crescent
#

and should it be (3/2)U(n) or 3/(2.U(n))

light breach
#

o(1) is a sequence that has 0 as limit
And it is (3/2).u(n)

woeful crescent
#

is it of the form -----> A(n+1) = rA(n) + C

light breach
#

In my exercise o(1) = ln(1+exp(u(n)))

#

It is not a constant so I don’t have direct formula

woeful crescent
#

a base case must be given for this recursion

light breach
#

Just u(0) > 0

#

I don’t have to find explicit formula but just an equivalent

#

I can’t formalize the proof that u(n)~C.(3/2)^n

woeful crescent
#

So it's this?

light breach
#

Yes

#

Sorry it’s exp(-u(n))

woeful crescent
#

if we take it to the power of e maybe itll simplify

#

We try to solve this recursion on k then take its log for a

#

this recursion looks hella tough tho

light breach
#

Yay it seems really horrible to solve

#

And i’m supposed to find k(n) ~ C^((3/2)^n)

#

I’ve tried to copy proof for geometrical recursion formula and then work on the other term but that don’t really help either

woeful crescent
#

is it a proving question? @light breach

light breach
#

I don’t understand what you mean

woeful crescent
#

whats the statement of the question

Find the expression for so and so
or
Prove that this recursion has the form so and so

light breach
#

Oh yeah of course it is « find an equivalent of u(n) such as… »

#

With only the recursion formula

#

By passing the equality under the ln it give something interesting

#

I just have to prove that the right term tend to 0

#

But I don’t think it is true 😭

woeful crescent
#

wait how did you get that n out of that ln. and how did you get that product can you show ur working

light breach
#

I’m using « télescopage » summation

#

I don’t know how to translate it

#

<@&286206848099549185>

plush bramble
#

,rccw

jolly parrotBOT
pearl pondBOT
#

@light breach Has your question been resolved?

#
Channel closed

Closed by @light breach

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sweet radish
#

What are mathematical ways to model this? And then make predictions using the model?

sweet radish
#

So far I have come up with:

  1. Sinosudial model
  2. Lagrange interpolation (but then I can't really use that to make predictions)
#

I need at least 3 solid models, what else could I do?

snow sail
#

this is all the data?

snow sail
#

which is basically sine

#

but who is counting

pearl pondBOT
#

@sweet radish Has your question been resolved?

sweet radish
sweet radish
snow sail
#

matlab has a command fft for it

#

but there are free libraries too

pearl pondBOT
#

@sweet radish Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight flicker
pearl pondBOT
midnight flicker
#

.status

#

!status

pearl pondBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
midnight flicker
#

1

versed mica
#

double angle identity

midnight flicker
#

i exactly dont know this method

#

can you explain me please

cursive wraith
#

just use the double angle identities in reverse

versed mica
#

$\sin(2x) = 2\sin(x)\cos(x)$

cursive wraith
#

to get sin(...) = cos(...) for example

jolly parrotBOT
versed mica
#

$\cos(2x) = 2\cos^2(x) - 1$

jolly parrotBOT
midnight flicker
#

ohh yes

#

didnt noticed that

#

thank you guys

wet swallow
midnight flicker
wet swallow
versed mica
#

$-\cos(2x) = \sin(2x)$

jolly parrotBOT
versed mica
#

no one said it was true for all x

wet swallow
versed mica
#

nope

midnight flicker
#

.close

pearl pondBOT
#
Channel closed

Closed by @midnight flicker

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pearl grove
#

does anyone know wtf im looking at? cause i dont

willow chasm
#

something is missing

pearl grove
#

oh

#

me when i dont read

#

thank you

#

.close

pearl pondBOT
#
Channel closed

Closed by @pearl grove

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dreamy shoal
#

I’m stuck on this since yesterday it’s the last problem on my hw please help;-;

dreamy shoal
#

I don’t understand it people tried to explain but I just don’t

#

No idea how to do or what to do

pearl pondBOT
#

@dreamy shoal Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

merry carbon
pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

upbeat wigeon
#

how do yk when u have to use cosine rule or sine rule

tall flint
#

you've hopefully heard the mnemonic "soh cah toa"? That's how

upbeat wigeon
#

tysm

#

ive been doing so much cosine/sine rule and non right angled trig i forgot how to do normal stuff opencry

#

.close

pearl pondBOT
#
Channel closed

Closed by @upbeat wigeon

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid cobalt
pearl pondBOT
orchid cobalt
#

i got the answer of 2 and -1

#

but i dont get why -1 is not a possible answer

midnight haven
#

plug it back in

orchid cobalt
#

OH ITS AN EXTRANEOUS ROOT?!

#

i totally forgot those existed.

#

tysm!!!

#

.close

pearl pondBOT
#
Channel closed

Closed by @orchid cobalt

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid cobalt
pearl pondBOT
orchid cobalt
#

-sigh- i dont even know how to start this.

#

radicals are the death of me

rough forge
orchid cobalt
#

ok lemme snap a photo!!

orchid cobalt
#

im kind of lost!!

rough forge
#

(2x+2)² try again

orchid cobalt
#

OH

#

I FORGOT BINOMIALS ARE DIFFERENT

#

2x^2 + 8x + 4 = 16(7 - x)

#

?

rough forge
#

(2x)² ?

orchid cobalt
#

OH MB 4x^2

rough forge
#

yup

jolly parrotBOT
#

bacc (unhelpful)

orchid cobalt
#

wait im lost again

rough forge
#

I like avoiding big computations

orchid cobalt
#

okok!!

jolly parrotBOT
#

bacc (unhelpful)

rough forge
#

Now it's stinky normal quadratic equation

orchid cobalt
#

ok so now i got x^2 - 2x - 27

#

how do i factor from here ;-;

rough forge
#

how did you get that

orchid cobalt
#

uhh

jolly parrotBOT
#

bacc (unhelpful)

heady finch
#

you have -4x on the right hand side instead of +4x

orchid cobalt
#

OH

#

is it 6x

#

mb chat!

#

(x - 3)(x + 9)

#

?

rough forge
#

yup

orchid cobalt
#

YAY!

#

ok and 9 would be extraneous?

rough forge
#

yea

#

-9*

orchid cobalt
#

tysssm!!

rough forge
#

nuit

orchid cobalt
#

.close

pearl pondBOT
#
Channel closed

Closed by @orchid cobalt

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

river lodge
pearl pondBOT
river lodge
#

how do i determine the equation of this graph
ik x ints r on the top and va's are on bottom
but how do i account for the oblique asympotote

hasty citrus
#

whats the function?

cosmic raptor
#

that’s what you have to figure out

river lodge
hasty citrus
#

ah well

river lodge
#

@regal herald can i see what u wrote

pearl pondBOT
#

@river lodge Has your question been resolved?

river lodge
#

<@&286206848099549185>

#

anyone?

fathom mauve
#

or just one

river lodge
pearl pondBOT
#

@river lodge Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

haughty hamlet
#

im confused about part b because i got701/729 but its nothingg close to 3√9

haughty hamlet
#

well for a =i just expanded the equatio which gave me
1-(1/3)x -(1/9)x^2

#

then i just did x=1/9 into the expanded equatin

#

simplufued, and.i got 701/729

plush bramble
haughty hamlet
#

through the binomial formula?

plush bramble
#

Show the binomial formula you used

#

And how you got -1/9 coefficient

haughty hamlet
plush bramble
#

I see

haughty hamlet
#

yea

plush bramble
#

,calc 701/729

jolly parrotBOT
#

Result:

0.96159122085048
plush bramble
#

,calc 9^(1/3)

jolly parrotBOT
#

Result:

2.0800838230519
plush bramble
#

Oh

#

1-1/9 = 8/9

#

So you're supposed to do something with the 8

#

Factor it out of the cube root yea

haughty hamlet
#

what do you mean by that?

plush bramble
#

The rational approximation you're being asked for is 9^(1/3)

#

(1-1/9) is not 9

haughty hamlet
#

ah

#

so the expanded equation is

#

2/9^(1/3)

pearl pondBOT
#

@haughty hamlet Has your question been resolved?

#
Channel closed

Closed by @haughty hamlet

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

astral pebble
pearl pondBOT
astral pebble
#

7(III) I don't understand where I'm messing up in my differenatation

atomic ferry
#

lol

astral pebble
atomic ferry
#

this one amath ah

astral pebble
astral pebble
atomic ferry
#

look like the textbook

astral pebble
#

Sg?

atomic ferry
#

ya

#

hahah

astral pebble
#

Lmao

#

O lvl dis yr?

atomic ferry
#

jc

astral pebble
#

Damn

atomic ferry
#

don't bring the 1/6 in

#

very confusing

astral pebble
#

Oh

atomic ferry
#

leave it out its a constant

astral pebble
#

But I don't rlly understand from that part where I factor out 1/6 what rule am I supposed to use if I use product rule it's troublesome

atomic ferry
#

use quotient rule

astral pebble
#

Can I just use the quotient rule for the partial fractions and ignore the constant?

atomic ferry
#

ya

#

can

astral pebble
#

Oh

#

So a(b+c) I use quotient rule by themselves but den a wld dissapear

atomic ferry
#

no

astral pebble
#

Oh?

atomic ferry
#

diff b+c)

#

then times a at the end

astral pebble
#

Ohhh ok

#

Oh so when I differentiate I can js differentiate one part only and ignore the others?

atomic ferry
#

ya if its a constant

astral pebble
#

Ahh ok

#

Ohhh

#

Got the ans liao

#

Tyty

#

.close

pearl pondBOT
#
Channel closed

Closed by @astral pebble

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pearl pondBOT
glacial sequoia
#

wdym by the left

#

2, 3, 4?

#

what do you think about 2?

#

what even is the difference between 2 and 3

#

what's the subscript notation mean

#

I see

cosmic garnet
#

like 0+ and 0-