Channel closed
Closed by @untold pebble
Use .reopen if this was a mistake.
#help-39
pearl pondBOT
pearl pondBOT
Available help channel!
junior vapor
hello i don't get how to graph the region of this. I'm just confused about what the actual graph looks like.
hard kite
take the reciprocal both sides and invert the inequallity and you get x < y
for positive (x,y)
no wait
junior vapor
i dont get why it has two lines
hard kite
x and y positive or x and y nevative
x < y
if x negative and y positive
no solution because 1/x is negative is 1/y is positive
if x positive and y negative
always true because 1/x is positive and 1/y is negative
,ask plot 1/x > 1/y
jolly parrotBOT
hard kite
yeah thats it
hard kite
i dont get why it has two lines
wym two lines?
junior vapor
like why it's made up of y=x and y=-x
junior vapor
x and y positive or x and y nevative
x < y
if x negative and y positive
no so...
is that to find the regions?
hard kite
yes
separating by quadrants of the plane
x and y positive is on the first quadrant, x negative and y positive is on the second quadrant, etc
junior vapor
oh ok that makes sense
i still dont get why drawing 1/x=1/y is the same as drawing y=+-x
like i thought u could just remove the reciprocal and draw x=y
hard kite
but it is..
hard kite
i still dont get why drawing 1/x=1/y is the same as drawing y=+-x
where have you seen that?
junior vapor
where have you seen that?
its the textbook answer
hard kite
,ask plot 1/x = 1/y
jolly parrotBOT
junior vapor
wait wat
hard kite
its just y = x
lethal vigil
for part c, the 3 permutations for would be these 5-digits: {2,...,6}, {3,...,7}, and {4,...8} right?
lethal vigil
.close
pearl pondBOT
cinder flower
for part c, the 3 permutations for would be these 5-digits: {2,...,6}, {3,...,7}...
no
if you want a hint ||if you pick 5 digits there is only one way to write them in increasing order||
pearl pondBOT
Available help channel!
quick star
how to count this?
pearl pondBOT
how to count this?
cinder flower
quick star
<a:waves:880516410948853840>
hi 
u get to watch me speedrunning geometry so i never have to come back to it again
cinder flower
if i gave you three positive integers, how could you determine if you can make a triangle out of them?
quick star
with the triangle inequality yeah
cinder flower
yea
quick star
a + b >= c
well without equality
yeah but what's an efficient way to count it?
do i list all 20 subsets?
cinder flower
probably not a good idea
cinder flower
a + b >= c
what about it?
quick star
it should be a + b > c
for triangles right
otherwise it's a straight line
when a + b = c
anyhow
cinder flower
to start what if we just count the triangle that use a side length 1
cinder flower
how many are there?
quick star
0
cinder flower
now scratch 1 off the list. how about triangles that use side length 2?
cinder flower
how did you find that there are 0 triangles with side length 1?
quick star
|a - b| < c < a + b
if c = 1 then the difference of the two other sides have to be less than 1
but that's only possible if we have duplicate side lengths
cinder flower
we have to use 2
cinder flower
😭
cinder flower
yep
we use 2 and the other two numbers can't differ by 2 or more
so that's all
now how about side length 3 (no 1 or 2 allowed)
quick star
don't we also have to consider the upper bound
quick star
now how about side length 3 (no 1 or 2 allowed)
3 cases probably
and for 4 1 case
for 5 we already counted
same with 6
cinder flower
yea sure you can just go through the last 4 cases and see if you want
cinder flower
no, just 4 left?
quick star
no, just 4 left?
i mean in total there's 7 right?
there was 3 fixing 2
3 for fixing 3
and i think 1 for fixing 4
cinder flower
for side length 3, you can choose 2 lengths from {4,5,6}. so 3 ways
then for 4, just 1 option (using 5 and 6)
and then you're done
quick star
so the whole idea was
fixing 1: then you have to choose from {2,3,4,5,6}
such that the difference is 0 between 2 terms
and so on
in other words, we only care about the lower bound?
and the upper bound somehow magically also works out
like in the traingle inequality you have:
|a - b| < c < a + b
we're only looking at |a - b| < c piece for making these selections which somehow works
cinder flower
yea, c is the smallest side
or like
say the sides are ordered a > b > c (so c is the one we fix in each case, the smallest one) . we need
- a + b > c
- a + c > b
- b + c > a
a > b > c gives 1 and 2 for free. if we insist a - b < c, then we also get 3
also note |a - b| = a - b
moreover, |a - b| < c is equivalent to b + c > a
(a,b,c) with a > b > c satisfies 3)
is equivalent to
it is possible to make a triangle with side length a, b, c
because
(a,b,c) satisfies 1) 2) and 3)
is equivalent to
it is possible to make a triangle with side length a, b, c
and a > b > c gives conditions 1) and 2)
now (a,b,c) with a > b > c satisfies 3) is equivalent to (a,b,c) with a > b > c satisfies c > |a - b|
ok this has to be so confusing but anyway my point is we just need to check the last two sides (labelled a and b with a > b) satisfy c > |a - b|
quick star
my head hurts
cinder flower
i'm sorry 😭 that was a lot
quick star
Wait 😭let me reread
cinder flower
ok this has to be so confusing but anyway my point is we just need to check the ...
maybe i can rewrite this nicer
quick star
say the sides are ordered a > b > c (so c is the one we fix in each case, the sm...
how does a + c > b come for free from a > b > c
cinder flower
a + c > a
quick star
oh
cinder flower
so we have a + c > a > b
quick star
yeah true 
cinder flower
ok self contained nicer message:
we have three sides a,b,c with a > b > c. we want to check if a,b,c can make a triangle. this happens iff all three of these are satisfied:
- a + b > c
- a + c > b
- b + c > a
from a > b > c we get 1) and 2). now for 3), rewrite it as a - b < c. since a > b, we could write that as |a - b| < c if we wanted to but no need for that really if we've already labelled the sides. so condition 3) is equivalent to a - b < c
quick star
hmmmm okay i think i get the idea
oh
u rewrote it 😭
okay so if we let c be the smallest side
we only need to satisfy 3)
cuz the fact that we ordered it already satisfies a and b
quick star
are already satisfied cuz of the ordering
cinder flower
yes
quick star
mmmmmmkk okay okay
that’s another mind bending thing
at this point i would just write all 20 😭😭
cinder flower
loll
quick star
okay okay i get it, thanks 💅
cinder flower
weak plaza
is the way I did this question correct? I have to find the magnitude of the resultant force and I got 11.18 while the answer is 11.22. Is that too much of an error?
weak plaza
<@&286206848099549185>
then it's asking me to give the direction of the resultant as a bearing
midnight haven
<@&286206848099549185>
!15min
pearl pondBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
pearl pondBOT
@weak plaza Has your question been resolved?
weak plaza
can i ask what program are you using for writing ?
apple notes app
pearl pondBOT
apple notes app
weak plaza
i still need help btw
pearl pondBOT
@weak plaza Has your question been resolved?
pearl pondBOT
weak plaza
.reopen
pearl pondBOT
@weak plaza Has your question been resolved?
pearl pondBOT
pearl pondBOT
Available help channel!
wary vapor
I need help with simplifying this expression and finding its value at x = -3 and y = 5.
wary vapor
Sorry for bad English im not good at it
pearl pondBOT
@wary vapor Has your question been resolved?
waxen talon
!status
pearl pondBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
modern sluice
The length and the breath of a rectangular park are 75 m and 40 m respectively. Find the area of the park and the cost of planting grass in it at ₹20 per m²
pearl pondBOT
The length and the breath of a rectangular park are 75 m and 40 m respectively. ...
waxen talon
What have you tried so far?
modern sluice
What have you tried so far?
Idk
I'm jst a 7th grader
And i dont like maths at all
Can u help me how to use this
bold spoke
pseudo oxide
@modern sluice you said nobody was helping. have you even looked at what this guy has suggested?
modern sluice
<@1257689354290204836> you said nobody was helping. have you even *looked* at wh...
But i didn't understood
Idk
versed ledge
versed ledge
Idk
There is a rectangular park given in question
It's length and breadth are given
You need to find the area of the rectangular park
area of rectangular park = length × breadth
modern sluice
So it will be 75 × 40
versed ledge
Yes
modern sluice
Ig
versed ledge
That is part 1 of the question, find the area
versed ledge
modern sluice
It's done
modern sluice
3000m²
versed ledge
Now the 2nd part
modern sluice
Did you finish the 2nd part too?
What was the 2nd part
versed ledge
What was the 2nd part
Planting grass on 1 m² cost 20 rs
So planting grass on 3000m² will cost ???
modern sluice
I think it will be 3000 × 20
versed ledge
modern sluice
So the ans is 60000
versed ledge
Yup
modern sluice
Thank u so much
versed ledge
No problem
pearl pondBOT
Thank u so much
If you are done with this channel, please mark your problem as solved by typing .close
modern sluice
Find the area of a square , whose perimeter and area are in the ratio of 1:2
versed ledge
Find the area of a square , whose perimeter and area are in the ratio of 1:2
Hmm do you know the formula of area and perimeter of square?
Whose side is let's say x
modern sluice
Hmm do you know the formula of area and perimeter of square?
Area = side × side
= s2
Perimeter = 4 × side
versed ledge
Area = side × side
= s2
Perimeter = 4 × side
Correct
modern sluice
😥
versed ledge
One S will be cancelled from numerator and denominator, so you will be left with
4/S = 1/2
Now do cross multiplication
4×2=S×1
S=8```I have not paid enough attention at school during the classes
And after 2 weeks my exams are gonna held
versed ledge
```4S/S²= 1/2
One S will be cancelled from numerator and denominator, so you wil...
@modern sluice understand this
modern sluice
<@1257689354290204836> understand this
Let me try
versed ledge
Same as you
modern sluice
Same as you
India.?
versed ledge
Hindi atta he na
Haa , let's not use this channel for chat. These channel are for specific problems and doubts
versed ledge
.close
pearl pondBOT
wraith river
@opaque raven A needs 1 piece of carpet, 4m long running vertically, you trim the width to 3.4m and throw the strip away.
B needs 2 pieces, first 3.4m long running horizontally, second 0.4m long running vertically, the second trimmed like the one in A. 3.8m in total.
So B is cheaper, but it might look ugly since the thread of the two pieces is perpendicular.
The 3.4m piece only covers the floor below the dotted line. You need a piece to cover the top also.
Where did you get 4.2? The bottom piece is 3.6x3.4
Yes. And the carpet is 3.6 wide.
That's what happens in A. You need to trim it to fit, so you throw some of it away.
Yeah, the bottom part of B is 3.4x3.6. This leaves you with an uncarpeted bit that's 3.4x0.4. So you carpet that the same way you do A, except instead of having to trim a segment that's 4m long, it's now just 40cm.
That's how much wider the carpet is than the room.
20x40cm is your waste here, as opposed to 20x400 in A.
pearl pondBOT
pearl pondBOT
Available help channel!
worthy grail
Does my work look good?
pearl pondBOT
Does my work look good?
worthy grail
I used symbolab to check and x=3 is right but my method was different
summer imp
It’s good
pearl pondBOT
pearl pondBOT
Available help channel!
mild stirrup
pearl pondBOT
warm current
!status
pearl pondBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2
midnight haven
solutions?
warm current
what does it mean by zeroes
Value(s) of x that satisfy k(x)=0.
mild stirrup
it’s on the right
pearl pondBOT
@mild stirrup Has your question been resolved?
mild stirrup
.close
pearl pondBOT
pearl pondBOT
Available help channel!
unborn scaffold
In importance sampling if I sample from another density (say it's similar but not the same) why does it converge to the same expected value?
pearl pondBOT
In importance sampling if I sample from another density (say it's similar but no...
@unborn scaffold Has your question been resolved?
pearl pondBOT
@unborn scaffold Has your question been resolved?
pearl pondBOT
@unborn scaffold Has your question been resolved?
plush bramble
In importance sampling if I sample from another density (say it's similar but no...
do you have an actual example of two densities
unborn scaffold
do you have an actual example of two densities
Actually, I found what was bothering me. but the question isnt answered
So here: https://math.arizona.edu/~tgk/mc/book_chap6.pdf
I understand 6.1 6.2, 6.3, 6.4.
I understand how this converges because the q(x)s cancel
But then here: https://computergraphics.stackexchange.com/questions/4979/what-is-importance-sampling
They use 1/n sum of f(x)/pdf which I don't understand how is equivalent or how it converges. I came to this from a raytracing perspective so that's why Im confused
plush bramble
is this estimate your question?
unborn scaffold
yes
but aren't we calculating the expected value of f?
so \int f(x) x dx
I guess
\int f(x) p(x) dx assuming x is sampled from p
unborn scaffold
Actually, I found what was bothering me. but the question isnt answered
So here...
I just noticed that here we seem to try to compute an integral
while the first link calculates the expected value
this might just be why the forms are different
but I dont see it yet
plush bramble
Actually, I found what was bothering me. but the question isnt answered
So here...
just read the examples in chap6 and see if you have a more precise question
unborn scaffold
on 6.16 I don't get how p(x) disappears.
I get
$$(fx) \frac{p(x)}{q(x)} = e^{-x}(1-\alpha) p(x)$$
jolly parrotBOT
Cedric
plush bramble
don't think p(x) = 1
you can either just trust the example and solve for p(x) in their answer
or find it using inversion formula/method
https://www.stats.ox.ac.uk/~rdavies/teaching/PartASSP/2020/lectures_latest/simulation_lecture2.pdf
oh nevermind you're right it is
unborn scaffold
yes
words
unborn scaffold
This I understand, but I don't get how this problem is the same as the
1/N sum f(x)/pdf(x) from the raytracing question
is q(x)/p(x) is the PDF here?
so you don't know p but come up with a pdf such that q(x)/p(x) = pdf(x)
unborn scaffold
ch 3 and ch6
I guess they don't explain that well which is why I looked online. They are consistent with this in notation: https://computergraphics.stackexchange.com/questions/4979/what-is-importance-sampling
But only the stats course stuff makes sense to me, I don't see how what they are doing is equivalent
unless we're assuming that p(x)=1 is always true or something
pearl pondBOT
@unborn scaffold Has your question been resolved?
pearl pondBOT
@unborn scaffold Has your question been resolved?
crimson bobcat
hi
crimson bobcat
hi everyone
The grocery store earns 30% of the sale price for each box of biscuits sold. During the Thadingyut Festival, the store decides to take 20% off the sale price for one day. By what percentage must the number of boxes sold increase to earn the same amount of money as the previous day?
can anyone help me solve
this
this is a very ez question but
it seems that my answer
did not match the answer
is there anyone who can help me clear the
misunderstanding
jolly parrotBOT
Alex
solemn rock
e: earnings/box originally
e' is earnings/box after 20% discount
p: price originally
n: original number of boxes sold per day
n': number of boxes to sell during festival
we want to find (n'/n-n) * 100%
e = 3/10 * p
e' = 1/10 * p
en=e'n'
hence:
n'/n=e/e'=3
answer is 200%
solemn rock
chatgpt can't do numbers...
crimson bobcat
i see
solemn rock
bruh
solemn rock
chatgpt can give you good reasoning but its calculation is very bad
solemn rock
its not reliable
pearl pondBOT
jolly parrotBOT
Alex
Alex
\begin{aligned}
e^{x} &\geq 1+x \quad \forall x\ge0 \\
x &\geq \ln(1+x) \quad \forall x\ge0
\end{aligned}
\sum_{i=1}^{n}x_{i} &\geq \sum_{i=1}^{n}ln(x_{i}+1) \\
\sum_{i=1}^{n}x_{i} &= \sum_{i=1}^{n}(\frac{a_{i}}{A}-1)=(\sum_{i=1}^{n}\frac{a_{i}}{A})-n=n-n=0, \\
\sum_{i=1}^{n}ln(x_{i}+1) &= \sum_{i=1}^{n}ln(\frac{a_{i}}{A}-1+1) \\
&= \sum_{i=1}^{n}ln(\frac{a_{i}}{A})=ln(\frac{a_{1}a_{2}...a_{n}}{A^{n}})
0 &\geq \ln(\frac{a_{1}a_{2}...a_{n}}{A^{n}}) \\
1 &= e^{0} \geq \frac{a_{1}a_{2}...a_{n}}{A^{n}} \\
A &\geq \sqrt[n]{(a_{1}a_{2}...a_{n})}=G
```Compilation error:```! Package amsmath Error: \begin{aligned} allowed only in math mode.
See the amsmath package documentation for explanation.
Type H <return> for immediate help.
...
l.49 \begin{aligned}
You're in trouble here. Try typing <return> to proceed.
If that doesn't work, type X <return> to quit.```
pearl pondBOT
Available help channel!
chilly terrace
pearl pondBOT
lethal palm
everything seems correct to me
pearl pondBOT
@chilly terrace Has your question been resolved?
pearl pondBOT
pearl pondBOT
Available help channel!
sand coyote
pearl pondBOT
sand coyote
Can I do this using row echelon
Where I make 0 appear everywhere in the ‘’rectangle triangle’’ bottom left
compact ridge
Where I make 0 appear everywhere in the ‘’rectangle triangle’’ bottom left
yes you can make it upper triangular, or lower triangular, or whatever
start by eliminating the 9 in the second row, so 5r2 - 9r4 -> r2 for example
then you want to work with the new top 2 rows, to eliminate the 2 and then the -1
then eliminate the -4
now it's lower triangular, so you can easily change the order of the rows to make it upper triangular if you want to
pearl pondBOT
@sand coyote Has your question been resolved?
pearl pondBOT
pearl pondBOT
Available help channel!
short orchid
Hi guys, how to solve this equation? Im stuck here
pearl pondBOT
Hi guys, how to solve this equation? Im stuck here
frozen lantern
uh what step
versed remnant
45 and 60 degrees are special kinda angles , u should know thier sin/cos values tbh
frozen lantern
that's also fair
valid kettle
the algebra looks right
versed remnant
and then i think it turns into a tan ? send cos to rhs and then divde that
short orchid
45 and 60 degrees are special kinda angles , u should know thier sin/cos values ...
Ohhh ure right
valid kettle
$\sin45^\circ=\frac{\sqrt{2}}{2}=\cos45^\circ$, $\sin60^\circ=\frac{\sqrt{3}}{2}$ and $\cos60^\circ=\frac{1}{2}$
jolly parrotBOT
@valid kettle
short orchid
oh that's your working?
Yess
frozen lantern
for $\cos$ it's $\cos(45^\circ)=\frac{1}{\sqrt2}, \cos(60^\circ) = \frac12$
jolly parrotBOT
Percy
short orchid
<@951897314333700186>
Okk i’ll try writing the values
Guys info: i’m stuck! 
i don't know what to do next guys
can anyone pls give me clue
valid kettle
Take the sinx * ... to the other side
And then divide both sides by cosx
You should get tanx = ...
rapid timber
can anyone pls give me clue
I think you can either convert sin(x+60) to cos(x+k)
or cos(x+45)=sin(x+k)
short orchid
Take the sinx * ... to the other side
And then divide both sides by cosx
You sh...
ohhh
short orchid
I think you can either convert sin(x+60) to cos(x+k)
is it by dividing sin by cos?
valid kettle
more like $\sin(90^\circ-x)=\cos x$
jolly parrotBOT
@valid kettle
valid kettle
or that
short orchid
<@951897314333700186>
wait what rule is this
rapid timber
i believe it is quite trivial if you draw it out
short orchid
uhmm
ohhh okay
i'll try the other method
i haven't learnt that
Guys why is it kinda weird
wait maybe i can try compound angle again?
btww thank youuu guys
short orchid
i believe it is quite trivial if you draw it out
thank youuuu
short orchid
more like $\sin(90^\circ-x)=\cos x$
thank youuuu
short orchid
for $\cos$ it's $\cos(45^\circ)=\frac{1}{\sqrt2}, \cos(60^\circ) = \frac12$
thank youuu
short orchid
and then i think it turns into a tan ? send cos to rhs and then divde that
thank youuu
versed remnant
thank youuu
those bracket things
send them to left hand side
they are not the angle , they are multiplying with sinx and cos x
and then u can arc tan both sides
versed remnant
||sin/cos = tanx||
versed remnant
!done
pearl pondBOT
If you are done with this channel, please mark your problem as solved by typing .close
pearl pondBOT
pearl pondBOT
Available help channel!
pearl pondBOT
why is this wrong
spiral pivot
hi
pallid oriole
why is this wrong
spiral pivot
so the original question is integral of cos x / (cos x - sin x) dx?
pallid oriole
yes
this seems to be the right answer, but obv my answer has a difference
i suspect the step where i multiplied -
spiral pivot
your answer is equivalent
civic drum
it’s the same
spiral pivot
don't forget the + C as well
civic drum
lol
pallid oriole
.close
pearl pondBOT
pearl pondBOT
Available help channel!
silent bramble
pearl pondBOT
silent bramble
question asks to find points where func is not analytic
but del(u)/del(x) != del(v)/del(y)
apparently the ans was just 2-3i
which makes sense cause you cant have denom 0
whatt
silent bramble
i have in my notes
silent bramble
ohhhhh
silent bramble
dwdw
pearl pondBOT
@silent bramble Has your question been resolved?
silent bramble
also this one it’s also cauchy riemann does not hold
but ans says analytic except z=0
cursive wraith
also this one it’s also cauchy riemann does not hold
did you really check if those are equal or not?
because something tells me you didn't simplify enough
silent bramble
do you just replace + with -
i think sooo
oh wait wait imma send a photo
I have to express in cartesian form
plush bramble
yea just simplify your fractions and check your work with a calculator
silent bramble
ye
im so cooked
I think I know what im doing
but i calculate it very slow
we have to express in polar form
for theta=arctan(-1/sqrt(3)), how do you know which quadrant it falls under?
how do you know if its in between -pi/2 and pi/2
w/out a calculator
for this one its more self-explanatory actually
but what about other values
plush bramble
you can figure out the quadrant using the angle
it's a special angle on the unit circle
silent bramble
would you change sqrt(3)-i into polar first?
plush bramble
it really doesn't matter
plush bramble
both give the same answer and it's just whatever you're more comfortable doing
plush bramble
i-pi/3 is i minus pi/3, not i * (-pi/3)
silent bramble
oh oops yea
what if you want to leave it in arctan form
is it right to say 2arctan(-1/sqrt(3))
if the angle is not special
should be
the questions Im doing doesnt have solutions
so Im doubting everything I do
plush bramble
why would you leave it in arctan form
oh if it weren't a special angle i see
i guess?
silent bramble
for example, here, I can only leave it like this, but knowing the angle is important cause arctan(x) has to be within -pi/2 and pi/2
actually, on my notes it says -pi/2 and pi/2 is principle branch of sqr root
so if z is not under a square root, we can disregard the requirement of having arctan(x) to be within this range?
silent bramble
i get 1-(sqrt(3)/2)
plush bramble
,calc 1-(sqrt(3)/2)
jolly parrotBOT
Result:
0.13397459621556
,calc (sqrt(3)-1)/(1+sqrt(3))
jolly parrotBOT
Result:
0.26794919243112
2-sqrt(3)
pearl pondBOT
@silent bramble Has your question been resolved?
plush bramble
,calc (1+i) / (sqrt(3) + i)
jolly parrotBOT
Result:
0.68301270189222 + 0.18301270189222i
,calc e^(i * (atan(2 - sqrt(3)))) / sqrt(2)
jolly parrotBOT
Result:
0.68301270189222 + 0.18301270189222i
looks right
pearl pondBOT
@silent bramble Has your question been resolved?
silent bramble
i have more questions and I wanna ask smth related to this
but i’m so tired im gonna sleep
quick nap
pearl pondBOT
@silent bramble Has your question been resolved?
plush bramble
but i’m so tired im gonna sleep
can you stop occupying channels when you're just gonna leave
just close and reopen
silent bramble
.close
pearl pondBOT
pearl pondBOT
Available help channel!
rich jolt
how did the teacher assume the point n ignore the typo as r where it says (1+lambda)i-(2+2lambda)j+(2lambda-1)k
pearl pondBOT
how did the teacher assume the point n ignore the typo as r where it says (1+lam...
@rich jolt Has your question been resolved?
pearl pondBOT
@rich jolt Has your question been resolved?
lavish portal
can someone check this work 🤩
pearl pondBOT
can someone check this work 🤩
bitter lynx
can someone check this work 🤩
you should get -1/8cot(2x) + C
versed remnant
1/4?
versed remnant
you should get -1/8cot(2x) + C
the answer should be -2cot2x +c :c
versed remnant
did you use symbolab for that
i mean , divide and multiply by 4/4
bitter lynx
the answer should be -2cot2x +c :c
int of csc^2(2x) is -1/2cot(2x)
versed remnant
1/4 stays in the intergral , 4 goes out
bitter lynx
times 1/4
versed remnant
im saying $$\int \frac{4}{4} \cdot \frac{dx}{cos^2x sin^2x} = 4\int \frac{1}{4}\cdot \frac{dx}{cos^2x sin^2x}$$
jolly parrotBOT
JustToPro
versed remnant
yeah , thats correct
versed remnant
why tho?
versed remnant
nah i dont think i can think of any xd
pearl pondBOT
hybrid palm
oh thats clean
pearl pondBOT
Available help channel!
lavish portal
why is my dtheta so messed up
pearl pondBOT
why is my dtheta so messed up
lavish portal
OMG I KNOW WHY SORRY
it's e^2x/25
wait now i have another issue
can anyone check my work for this
versed remnant
can anyone check my work for this
why is the sqrt {1-sin^2} in numerator?
shouldnt that be in the denominator?
nvm
yeah i think its correct , just simplify further
lavish portal
yeah i think its correct , just simplify further
i took the derivative wrong
🤩
.close
pearl pondBOT
pearl pondBOT
Available help channel!
ashen forum
Im having trouble with bringing an argument in its principal range [-pi, pi], the argument which im trying to bring in the range is arg(z) = 2pi - 30, i don't really have any clue
vocal lark
Im having trouble with bringing an argument in its principal range [-pi, pi], th...
2pi - 30 radians?
ashen forum
2pi - 30 *radians?*
yes, although it wasn't specified i do believe to be radians
vocal lark
yes, although it wasn't specified i do believe to be radians
I think you just need to add 4 multiples of 2pi?
I lost count
~ 1.41 radians
~ 40.56 degrees
ashen forum
we aren't allowed to use any computational tools in the exam for these kind of problems, so im wondering if there is another way?
vocal lark
we aren't allowed to use any computational tools in the exam for these kind of p...
you can just estimate how big 2pi - 30 is using the approximation pi = 3.14?
ashen forum
you can just estimate how big 2pi - 30 is using the approximation pi = 3.14?
okay, i'll do that thank you
vocal lark
once you know how many multiples of 2pi you actually need, just add it and simplify
so if it is 4 multiples, then you would do (2pi - 30) + 8pi = 10pi - 30
and that is it, actually
now, I'm assuming that your problem statement is accurate
that this is all they're asking you to do
pearl pondBOT
pearl pondBOT
Available help channel!
worn goblet
derivative of [x^3 + y^3]/[x^3-y^3]
pearl pondBOT
derivative of [x^3 + y^3]/[x^3-y^3]
worn goblet
with respect to which variable do you need to derive?
x
desert solar
Ok
Then treat y as a constant (example 1) and take the derivative
Using differentiation rules for functions of one variable
Since y is constant
edgy wren
derivative of [x^3 + y^3]/[x^3-y^3]
just take the derivative normally but every time you derive y write dy/dx next to it
worn goblet
just take the derivative normally but every time you derive y write dy/dx next t...
ik
i just cant get to the ansewer
edgy wren
i just cant get to the ansewer
any work you can show ?
worn goblet
any work you can show ?
worn goblet
any work you can show ?
its cancerious
edgy wren
Process for right picture looks right but for the left pic where did the denominator go ?
worn goblet
Process for right picture looks right but for the left pic where did the denomin...
the maths teacher said that after sin^-1 a becomes 0 send denominator to there so it multiplies with 0 can becomes zero
edgy wren
Ok lemme do it rq
worn goblet
Ok lemme do it rq
done?
worn goblet
ngl the algebra was too much but yea
and the answer is
edgy wren
||y/x||
edgy wren
I think what you did wrong here is something of moving the variables
worn goblet
I think what you did wrong here is something of moving the variables
can u show ur work i dont understand until i see how to get the answer
edgy wren
Ok I know where you messed up
it was x^3 y^2 (in the denominator)
worn goblet
Ok I know where you messed up
it was x^3 y^2 (in the denominator)
so y/x is correct???
worn goblet
writing dy/dx as y' btw
ik
wolfram kept the denominator as it is whole sqwuared
and got the 6smthsmth/(x=y)^2
x-y
edgy wren
Process differs
edgy wren
and got the 6smthsmth/(x=y)^2
looks like partial differentiation
worn goblet
looks like partial differentiation
idk what that means
edgy wren
Is this work correct
Forgetting chain rule
worn goblet
Forgetting chain rule
in where
edgy wren
Is this work correct
Or to exact messing it up at the line in the middle
d/dx(e^[x+y])=e^(x+y)*d/dx(x+y)
=e^(x+y)[y'+1] same goes for left
worn goblet
Or to exact messing it up at the line in the middle
so d/dx of (x+y_ = ( 1 + dy/dx)
which i then multipled to e^x+y
edgy wren
Yea same goes for the sine
Derivative of the function (while keeping the inside) * derivative of the inside
worn goblet
Yea same goes for the sine
Derivative of the function (while keeping the inside...
so i got ( 1-y`)
and multipled it
worn goblet
Yea same goes for the sine
Derivative of the function (while keeping the inside...
btw for all x^n+y^n/x^n-y^n answer all always be y/x right?
if rhs of that = o
edgy wren
btw for all x^n+y^n/x^n-y^n answer all always be y/x right?
Yea
heady finch
for question 5b
pearl pondBOT
for question 5b
midnight haven
represent what as a double integral?
midnight haven
oh sorry lol just saw that
I think a better way is possible
if you write it in terms of the constants
as your final answer
@heady finch
is this meant to be your final answer?
cause I would definitely not want to leave it as double integrals at the end
heady finch
is this meant to be your final answer?
no just as an intermediate working step
heady finch
I'm wondering whether it's considered equivalent to the solution in this case
alright thanks
midnight haven
bet to put brackets tho
heady finch
gotcha
midnight haven
$$\int \left \int (-2x) dx \right dx$$
pearl pondBOT
jolly parrotBOT
Edmund Cloudsley
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
pearl pondBOT
Available help channel!
midnight haven
i cant do part b
pearl pondBOT
i cant do part b
midnight haven
<@&286206848099549185>
ivory lichen
you have the equation, they're asking u to find y(8)
u have to substitute x = 8 into your equation
pearl pondBOT
pearl pondBOT
Available help channel!
jovial dock
please can someone answer this without calculation
pearl pondBOT
please can someone answer this without calculation
edgy wren
Bro just plug r as 13 and solve it with a calculator
jovial dock
wait waht?
edgy wren
please can someone answer this without calculation
It even says it
r is the radius
neon ermine
They gave u the formula
edgy wren
r=radius=13
pearl pondBOT
jovial dock
.reopen
pearl pondBOT
✅
jovial dock
edgy wren
reverse the process
4/3(πr^3)=5100π
and solve for r
edgy wren
?
Volume of sphere=4/3(πr^3)
Volume of sphere=5100π
Volume of sphere=volume of sphere
4/3(πr^3)=5100π solve for r
jovial dock
Volume of sphere=4/3(πr^3)
Volume of sphere=5100π
Volume of sphere=volume of sph...
how am i supposed to put this in a calculator?!
the equal sign in a calculator only gives u answers?
edgy wren
how am i supposed to put this in a calculator?!
You know how to solve for a variable ?
jovial dock
You know how to solve for a variable ?
no?
edgy wren
what does that have to do with thee question?!
It’s the same process just different numbers
pearl pondBOT
@jovial dock Has your question been resolved?
random flume
what's the problem
random flume
jus equate the two equations
random flume
can u just giive me the answer
against the rules
jovial dock
bro nobody is answering the question
pearl pondBOT
@jovial dock Has your question been resolved?
jolly parrotBOT
denzio321
jovial dock
Basically:
$\frac{4}{3}\pi r^3=5100\pi$
Basically:
$\frac{4}{3}\pi r^3=5100\pi$
jolly parrotBOT
JakeTSS
Basically:
$\frac{4}{3}\pi r^3=5100\pi$
jovial dock
so i need to write Basically:
$\frac{4}{3}\pi r^3=5100\pi$?
jolly parrotBOT
JakeTSS
plush moss
Oh you just want the answer flat
jovial dock
yea.
plush moss
Uh
jovial dock
its online hw
pearl pondBOT
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
jovial dock
its too much holiday stuff
plush moss
There's this thingy
plush moss
Then just do it
jovial dock
i am just too tired
plush moss
Take a break
jovial dock
gauthmath is fake
plush moss
Should be able to solve simple equations like these
$\frac{4}{3} r^3=5100$
We can cancel out the pi on both sides
That makes it a bit simpler
jolly parrotBOT
denzio321
plush moss
Then divide by 4/3 on both sides
Then cube root both sides
I am also too tired to use my calculator rn
Mb
If your teacher hasn't taught you this you might want to kill them🔥
jovial dock
If your teacher hasn't taught you this you might want to kill them🔥
they didnt
jovial dock
Then cube root both sides
also im sorry but u didnt help me
but i will thank you for the gauthmath idea
since its working lol
thanks for that
❤️
.close
pearl pondBOT
plush moss
they didnt
Rip
plush moss
Your math teacher doing you dirty
pearl pondBOT
Available help channel!
willow delta
can someone help compute this, where C=830e-12 and t=5e-3 and Q=123e-6 and L=3.30
willow delta
online calculator cant do it properly for some reason
pearl pondBOT
@willow delta Has your question been resolved?
stuck wasp
Ok so heres a problem
pearl pondBOT
Ok so heres a problem
stuck wasp
I'm prepping for COMC and AMC 10 and I'm working on combanitorics and probability (weak spots)
so uhh
I got 16!/4^8
but the right answer is 16!/2^8
can someone explain
elfin tinsel
Because the total no of ways to put the sock and shoe for a single leg is 2
Then there are 8 legs
So 2 to the power 8 is number of sample space
Why did you use 4 power 8
stuck wasp
Why did you use 4 power 8
Cuz if
Lets say we arrange the socks from a1 to a8
and the shoes from b1 to b8
in a total of 16! combinations for both of those
and we want the sock to be first
it could be aa, ab, ba, bb
so uhh
divide by 4 each pair of assumed ab?
confusion
<@&286206848099549185>
sorry for the ping
elfin tinsel
Sorry
stuck wasp
sorry sorry
elfin tinsel
Well let me expl
For a single leg
There are two ways to arrange
The 16 factorial is for the order in which accessories are weared on the legs
stuck wasp
For a single leg
There are two ways to arrange
erm like ab and ba?
elfin tinsel
Yes
stuck wasp
The 16 factorial is for the order in which accessories are weared on the legs
but thats uhh combining a and b though?
elfin tinsel
No
stuck wasp
feeling insanely stupid
elfin tinsel
It is for the order of legs
stuck wasp
er er er
elfin tinsel
Say first you are wearing on leg 1 then leg 2 … or the leg 1, leg 3 ….
Did you get it
elfin tinsel
It is not even about the shoes and shocks
It is about the order in which legs are chosen
elfin tinsel
Sorry i am confused
stuck wasp
nvm nvm im tweaking
stuck wasp
Sorry i am confused
so can you pls help another pls 🥺
answer is this:
I mean I get the first part
i mean term
the first is basically total amounts of possible combinations
minus equivalent
but what about the second term?
elfin tinsel
Let me try
elfin tinsel
@stuck wasp
I understood the concept
Do you still need help??
We are rotating the board in 4 rotation viz 0,90,180,270
There is theorem called Burnside Lemma
In 0 degree
Total no of ways is 49 Combination 2 which is
1176
In 90 and 270 degree , the number of inequivalent is 0
elfin tinsel
In the rotation of 180 degrees the board is equivalent if the two colours are in symmetrical position
elfin tinsel
It is 24
stuck wasp
o
elfin tinsel
Then add all these
stuck wasp
which would give?
stuck wasp
oh
elfin tinsel
Okay hope it helps
elfin tinsel
Byeee
pearl pondBOT
pearl pondBOT
Available help channel!
quick star
pearl pondBOT
quick star
so 2 <= possible guesses <= 10
where possible guesses is an integer
that's 9 integers to choose from
i'm guessing we have to assume that jane is a logical person? Lol
and jane would choose a number > 5
so she can choose either 6,7,9, or 10
static helm
so 2 <= possible guesses <= 10
if john is being logically, the least amount of beads he could have is 3 and then the other lady would have 5
quick star
so is the answer 4/9?
dusky scaffold
so she can choose either 6,7,9, or 10
this would be 1/4 tho right?