#help-39

1 messages · Page 155 of 1

sterile turtle
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how does it become r^n+1:1

dusty flame
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Check ur formula

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For geometric sum

sterile turtle
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oh

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minus

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makes sense lmao

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thanks again

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mint ridge
#

after finding g'(x) and plugging in the values into the power rule what do i do 😭

strange fox
mint ridge
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yes

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this is what i have

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im a bit iffy w the chain rule

strange fox
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ah wait

mint ridge
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oh my bad i shouldve put g(0)

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f’(0) f(0) although idk if thats g’(0) i just know its the derivative 😭😭😭

strange fox
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so

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are you trying to ask if thats the correct derivative

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or how to like

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solve

mint ridge
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how to solve

strange fox
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plug in 0s

mint ridge
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and the multiply,?

strange fox
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well yeah

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its asking you for the slope of k(x) at x=0

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aka the derivative of k(x) with respect to x when x is 0

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so just plug in and solve for the slope of the tanget line at x=0 of k'(x)

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am i misunderstanding the problem?

mint ridge
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like that??

strange fox
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well yeah im not sure what else the question could be asking

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just asking for the output of k'(0)

mint ridge
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yeahhhh thats why im confused

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ima js put that n pray lol

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thx ^^

strange fox
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does it seem too easy or something

mint ridge
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nono like i feel that wouldn’t be the answer but i could js be overthinking it

strange fox
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i mean it is the first question so its probably meant to be this easy

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and if its telling you specifically that you should find k'(0) there is a good chance it is just a number

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anyways goodluck

mint ridge
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thank you smsm

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ocean crater
#

I made an app that can

plush bramble
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Square both sides, then move the resulting square root to one side by itself and square again

versed ledge
#

Try assuming x+1 = y² , that might help

ocean crater
versed ledge
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<@&268886789983436800> ^^ is this allowed

ocean crater
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yes

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when u download just dm me 😁!

undone geyser
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Please do not advertise your stuff in here.

brazen current
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btw this has no solutions

indigo turtle
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Is it free?

brazen current
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if we still care about solving the problem

tight cairn
minor walrus
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sqrt(2-2) + sqrt(2+1)
sqrt(0) + sqrt(3) definitely is not 1

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same thing if you plug in 10

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ashen coral
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not quite sure where i went wrong here

pearl pondBOT
ashen coral
atomic oracle
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It's not clear whether a = AB or AC

ashen coral
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these r what the answers r supposed to be

atomic oracle
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,w calc (10/8) * Sin(64°)

atomic oracle
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Did you assume a as Ab?

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Or?

ashen coral
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wdym

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like which side?

atomic oracle
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Yea

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Like which side did you take a as

ashen coral
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would a not be opposide of A?

full jewel
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hello eveyone

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🥱

atomic oracle
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This triangle isn't possible

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Where a is the side opposite to a

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,w calc (8/10) * Sin(64°)

atomic oracle
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,w calc Sin^-1((8/10) * Sin(64°))

ashen coral
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so am i just allowed to switch up the sides like that?

atomic oracle
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Yup

ashen coral
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oh what

atomic oracle
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Unless they specify

ashen coral
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okay let me try this out then

atomic oracle
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,w calc Sin^-1((8/10) * Sin(64°)) *180/π

atomic oracle
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Which is approximately 46°

umbral stump
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is this correct?

ashen coral
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tysm

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atomic oracle
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glass remnant
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can someone explain number two to me

pearl pondBOT
glass remnant
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i dont understand how f(x) equals the sqrt of x

prime bramble
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if you let $g(x) = \ln(x)$, then $\sqrt{\ln(x)} = \sqrt{g(x)}$

jolly parrotBOT
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higher!

prime bramble
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now you need to write $\sqrt{g(x)}$ as $f(g(x))$

jolly parrotBOT
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higher!

prime bramble
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the only choice you have is $f(x) = \sqrt{x}$

jolly parrotBOT
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higher!

prime bramble
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functions of the form f(g(x))

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so we need to find what f(x) is, and this is how you can tell

glass remnant
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i think i get it nonow

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tysm

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prime bramble
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sharp smelt
pearl pondBOT
sharp smelt
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Axiom A5:

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Let there exist two distinct additive inverses, $a;b$ of $v$. So $a+v=0$ and $b+v=0$. So $a+v=b+v$. We know that $-v$ is one of the many ( If there are many) additive inverses. so $a+v-v = b+v-v$. From which we can conclude that $a=b$. Thus the additive inverse is unique!

jolly parrotBOT
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Veni, vidi, perii is not f(wai)

tropic saddle
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yes that works

sharp smelt
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Thanks

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sharp smelt
pearl pondBOT
sharp smelt
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Here's my proof

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Base case :- $a \cdot v_1= av_1$
Assuming this holds true up until $v_n$, we get $a(v_1+v_2 \dots + v_n) = av_1+av_2+av_3 \dots av_n$
Now we add $av_{n+1}$ to both sides, thus gettin $a(v_1+v_2 \dots +v_n)+av_{n+1} = av_1+av_2 + \dots +av_{n+1}$. Which is in turn equal to $a((v_1+v_2 \dots + v_n)+v_{n+1}) = a(v_1+v_2 + \dots + v_{n+1})$. Thus concluding our proof

jolly parrotBOT
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Veni, vidi, perii is not f(wai)

sharp smelt
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The second proof follows similarly. The base case is $(a_1)v =a_1v$. We then assume $(a_1+a_2 + \dots + a_n)v =a_1v+a_2v+ \dots +a_nv$. We now add $a_{n+1}v$ to both sides to obtain $(a_1 + a_2 + \dots +a_{n})v = a_1v+a_2v + \dots + a_nv+a_{n+1}v$. We now apply the distributive law of vector fields to obtain$(a_1+a_2 + \dots + a_{n+1})v= a_1v+a_2v + \dots +a_{n+1}v$

jolly parrotBOT
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Veni, vidi, perii is not f(wai)

sharp smelt
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<@&286206848099549185>

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midnight haven
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Could someone explain to me how/why the midnight formula / abc formula works? I feel like I’m missing some mathematical basics to understand it.

uneven smelt
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quadratic equation?

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they use completing the square

cosmic garnet
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ive never heard it referred to as "midnight formula"

tropic saddle
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"If I wake you at midnight you have to be able to say the formula"

jolly parrotBOT
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bacc the sigma😔🤞

rough forge
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You simply copy and paste the coefficients a,b and c and compute it.

rough forge
rough forge
pearl pondBOT
#

@midnight haven Has your question been resolved?

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quaint crag
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If 3(T-R)=10 which of the following correctly expresses T in terms of R?

cloud zephyr
quaint crag
timber tartan
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Is it D

quaint crag
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where to begin

timber tartan
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Consider the question 3(T-1)=10

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how would you solve this

cloud zephyr
quaint crag
timber tartan
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now can you go ahead and apply the same step to the question 3(T-R)=10

quaint crag
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im getting t = 10+3R/3

timber tartan
quaint crag
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i did earlier

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3t=10+3r

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but the t went to rhs and gets divided

tropic wolf
quaint crag
tropic wolf
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[(3t)/3] =[(10+3r)/3]

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[(t)]=[(10/3)+(3r/3)]

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(t)=(10/3)+(3)

quaint crag
tropic wolf
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you can seperately divide a number to each term if it is common in denominator

quaint crag
#

oh

tropic wolf
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got it?

quaint crag
#

yea ty

pearl pondBOT
#

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timber tartan
#

your lim resolves to -1/2 * (sinx + tanx)/x
=> -1/2 * (sinx/x + tanx/x)
=> -1/2 (1+1)

agile ridge
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ye just solved

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what about this one

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@timber tartan

timber tartan
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this is nothing but (a^t - a^-t)ln(a)/2t
=> a^2t -1)/2t * ln(a)

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=> ln a * ln a

agile ridge
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a^t-a^-t/2t=lna?

timber tartan
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yeah

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the a^t in the denom becomes one that's why i didnt write it

agile ridge
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wait why a^2t-1/2t=lna?

timber tartan
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lim x->0 a^x - 1/x = ln a

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here x = 2t

agile ridge
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thx

timber tartan
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d/dx x = 1

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d/dx a^x - 1 = a^x ln a

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lim x-> 0 a^x ln a / 1 = ln a

agile ridge
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aah i see iy now

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tysm

pearl pondBOT
#
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agile ridge
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.reopen

pearl pondBOT
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timber tartan
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have you tried it on your own

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apply LH

agile ridge
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no it made things complicated

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aah nvm i got this

pearl pondBOT
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jade terrace
pearl pondBOT
jade terrace
#

can i cancel like this

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is this valid

sick adder
#

Yes

abstract owl
sick adder
#

$sin^{3}(x)$ is the same as $sin(x) * sin(x) * sin(x)$, so if you were to write them out like that, visualizing how they cancel is more clear

jolly parrotBOT
#

m. frost

dense reef
jade terrace
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ok hthanks

sick adder
#

It's a markup language called LaTeX that the bot @jolly parrot can render

dense reef
sick adder
#

$You type markup code between US dollar signs$ Here is an introductory guide to using it

jade terrace
#

.close

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red hedge
pearl pondBOT
red hedge
#

,rotate

jolly parrotBOT
red hedge
#

Need help with 13

oak quiver
#

Do you know the reminder theorem?

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@red hedge

red hedge
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Yeah

oak quiver
#

Use that lol

red hedge
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I tried and prob messed up somewhere I’ll try it again

oak quiver
#

Send your calculations then

red hedge
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Now I just solve for k such that f(-2) is twice f(2) right

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,rotate

jolly parrotBOT
oak quiver
#

Yeahh

red hedge
#

,rotate

jolly parrotBOT
red hedge
#

Imma plug it in and check my answer

oak quiver
#

Kk

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Bro wtf have you done

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You cancelled the 2 from 21?

red hedge
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Where

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No that’s 2k

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I just wrote the k weird

oak quiver
#

Lmao

upper drum
oak quiver
#

You Indian too? @red hedge

red hedge
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How’d you know 😭

upper drum
#

oh sh*t

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wrong chat

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i meant in that AP ques

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lmao

red hedge
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Was it my finger slightly showing in the picture that gave it away

oak quiver
upper drum
oak quiver
upper drum
oak quiver
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Ohh 11

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Wait this means we have all from 9-12

red hedge
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Got it

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Ty

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.close

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oak quiver
#

@red hedge f(-2) = 16 and f(2) = 6?

pearl pondBOT
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finite stump
pearl pondBOT
finite stump
#

help pls need to check my answers

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a) 1.75 or 7/4
b) 3.5 m/s
c) 1 m/s

oak quiver
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Show your steps too

finite stump
#

okay

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Oh No

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I just made huge mistake Brb

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a) 2 m/s
b) 4 m/s
c) 1 m/s

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new answers

oak quiver
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Why are your ans in m/s lmao

finite stump
#

its rate

oak quiver
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mol/L/sec imo

finite stump
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yes that

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but my answers are fine ?

oak quiver
#

Give me the corrected calculations lol

finite stump
#

a) 2 m/s

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b) 4m/s

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c) 1m/s

pearl pondBOT
#

@finite stump Has your question been resolved?

oak quiver
#

I think there are correct

finite stump
#

.close

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urban sun
#

what is the second question bruh

pearl pondBOT
urban sun
#

i don't understand it

oak quiver
#

Which?

urban sun
nimble osprey
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twin fox
pearl pondBOT
#

@twin fox Has your question been resolved?

twin fox
#

<@&286206848099549185>

pearl pondBOT
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@twin fox Has your question been resolved?

twin fox
#

<@&286206848099549185>

#

<@&286206848099549185>

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astral salmon
#

<@&286206848099549185>

pearl pondBOT
astral salmon
#

Where that 2 and 3 came from?

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Hello

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🖐️

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Where that 2 and 3 came from

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Yes

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Kinda

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Thanks man

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👍

pearl pondBOT
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analog shoal
#

hi guys sorry to be a pain but could someone check these answers for me please? i dont want to ask teacher in fear of being wrong for simple qs

analog shoal
plush bramble
#

,w simplify 5x + 3xy - x -xy

plush bramble
#

,w simplify x(1-y) - 8xy + 5(x+y)

plush bramble
#

,w simplify 4x^2 -4x+7y^2 - 3y + 2x^2 - y^2 +xy

analog shoal
#

Thats a usefull command! thanks for introducing it to me :)

plush bramble
#

yes wolfram alpha is a good website

analog shoal
#

for the last question

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which is a preferred way of presentation? 6X2 -4x +6Y2 -3y + xy or the one with brackets?

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,w

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,w simplify 4(x/(2xy)) +(6y/2y)-((x^2 y^2 /(xy))

#

not sure what i did wrong here

#

Are we not supposed to multiply 4 by the initial bracket?

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due to 2xy being inside another set we cant touch it?

twilit lion
#

It's 4 multiplied by (x/2xy)

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Multiplying means you only have to multiply the numerator

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which is x

analog shoal
#

thus we get 4x/2xy
canceling out gets us 2/y

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as we take 2x as a factor ?

twilit lion
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The (2xy) doesn't mean it's untouchable, it's there just to specify that 2xy is the entire denominator

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You have an x in the denominator and numerator so they cancel

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What's your concern exactly?

analog shoal
#

so i think i have done something wrong? idk

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sorry to be a pain

twilit lion
# jolly parrot

Huh? This isn't even the same equation as the one you sent

#

They're 2 completely different equations

twilit lion
analog shoal
#

oops, sorry deleted the picture from the bot when asking for more information before

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,w simplify 4(x/(2xy)) +(6y/2y)-((x^2 y^2 /(xy))

analog shoal
twilit lion
# analog shoal

You're really confusing me here, if we're just talking about the question you sent here, then we've already gone through it together just now

twilit lion
analog shoal
#

thanks for pointing out my mistake, i am less stressed now

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so sorry about the confusion

twilit lion
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dw

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At least it's sorted

analog shoal
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:)

#

.close

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dawn folio
pearl pondBOT
dawn folio
#

i don't know how to solve this

prime bramble
#

,rotate

jolly parrotBOT
prime bramble
#

try setting each quadratic to 0, and solving for x in each case

dawn folio
#

ok

prime bramble
#

one of them is going to have roots not equal to 6sqrt(2) and -6sqrt(2)

dawn folio
prime bramble
#

that would be once instance

#

though I recommend factoring instead of moving terms around

dawn folio
dawn folio
prime bramble
#

you can apply the quadratic formula though

#

that would suffice

pearl pondBOT
#

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dawn folio
pearl pondBOT
dawn folio
#

How do this

cosmic raptor
#

do you know how to find the absolute value of a complex number?

dawn folio
#

square root of a and b right?

#

then how

plush bramble
#

$|x+iy| = \sqrt{x^2 + y^2}$

jolly parrotBOT
#

riemann

plush bramble
#

for any real numbers x, y

dawn folio
#

so square root of 225 minus 64?

#

does the negative carry over or no

plush bramble
#

no

dawn folio
#

if not then its root 225 plus 64 right?

plush bramble
#

y^2 = (-8)^2

dawn folio
#

then its root what

#

so its square root of 225 + 64 right? which aes it 17

plush bramble
#

,calc sqrt(15^2 + (-8)^2)

jolly parrotBOT
#

Result:

17
plush bramble
#

yes

dawn folio
#

ty

#

.close

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#
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dawn folio
pearl pondBOT
dawn folio
#

How does this problem work

#

Because none of the answers has a negative root or i

woeful stump
#

are you sure? substitute i root 5 into the equations and see what you get

dawn folio
#

for x? @woeful stump

#

<@&286206848099549185>

twilit lion
#

How did you conclude that none of them have a negative root or i

#

If you just rearrange B, C and D for x^2 it should make sense

urban swift
#

it’s C

twilit lion
#

You aren't meant to just directly give the answer but a'ight

dawn folio
#

ik its c i dont how to get ther tho

urban swift
#

you just move the constant to the other side

twilit lion
#

x^2 = -5

#

It should make sense that a square can never be negative unless it's not real

dawn folio
#

oh so x =iroot5

twilit lion
#

Yes

dawn folio
#

so you just solve for x?

urban swift
#

yes

#

and there are two solutions always

dawn folio
#

ye plus or mines thank you @urban swift @twilit lion

twilit lion
#

np

dawn folio
#

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supple citrus
#

what am i doing wrong? im not getting the answer in the mark scheme

pearl pondBOT
#

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arctic carbon
pearl pondBOT
arctic carbon
#

not sure where to go

#

from here

feral sedge
#

<@&268886789983436800>

arctic carbon
#

lmfao

#

that blank i filled out is that just x?

#

since y/x is tanx and thats x/1

feral sedge
#

isn't it tan^-1(x)

arctic carbon
#

yeah it is

#

can i just use a u substitution for now or something and come back to it later in the expression

feral sedge
#

I would give the cos(a+b) formula a try

arctic carbon
#

yeah i was gonna use that usig u substitution

#

i saw that angle sum difference identity

#

with pi/2 and u

feral sedge
#

Sure

#

I wasn't picturing using substitution for that but there's no difference

arctic carbon
#

yeah i got -sinu

#

from that when the cos on the left cancelled out

feral sedge
#

so sin(tan^-1(x))?

#

This is where the triangle will come in handy

arctic carbon
#

yeah i got

#

okay -x/sqrt(x^2+1)

#

so x = -x/sqrt(x^2+1)

#

and solving for x gives x^4 = 0

#

and fourth root of 0 is 0

#

so 0

pearl pondBOT
#

@arctic carbon Has your question been resolved?

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dawn folio
pearl pondBOT
dawn folio
#

i did it and got -4 +- sqrt2/3 i

#

i dont know how they got 6/3

solar juniper
#

what'd you do

dawn folio
#

-7 on both side

#

wait let me draw it realquick

solar juniper
#

hmm

#

This should be correct

dawn folio
#

is the key wrong then?

solar juniper
#

I assume so

#

I mean if you use online calculator

dawn folio
#

is i on the inside or outside of the sqrt

solar juniper
#

It can be outside

#

Because i = sqrt(-1)

#

so it doesn't matter

#

if you rewrite i to sqrt(-1)

#

you can plug it back into the other square root

#

and take it out too

dawn folio
#

oh ok ty

#

.close

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#
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dawn folio
#

how would you solve this

#

would you 25 and do x method

pastel raven
#

it's a 2-degree equation

dawn folio
#

?

pastel raven
#

in a single variable

#

so you can use

#

the quadratic formula

dawn folio
#

is there another way cause i dont know it by head

pastel raven
#

you can try factorisation

dawn folio
#

wdym

pastel raven
#

to put it in form like a(x-b)(x-c) = 0, for some a, b, c real

#

then x = b and x = c will be solutions

dawn folio
#

so -b/ac

pastel raven
#

what?

dawn folio
#

one sec

pastel raven
#

you need to learn how to use the formula

#

because it'll appear a lot to you

pearl pondBOT
#
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heavy hill
pearl pondBOT
heavy hill
#

hey guys im really confused on how to do part (iii)

#

i like dont even know where to start

cinder flower
#

if you have X as a vertex, how many ways can you choose two other vertices?

dawn folio
#

dawg they done closed my chanel

#

bruh

heavy hill
dawn folio
#

np

#

il get another its fine'

heavy hill
#

👍

heavy hill
#

ok so if you already have x

#

you have to pick one from both lines

#

so (n-1) x (n-1)

dusky basin
#

Yo

heavy hill
#

oHHH

dusky basin
#

I need help with logic

#

Can anyone who is available help me in the channel?

heavy hill
#

i think u need to use a new channel

dusky basin
#

I did no one is responding

cinder flower
#

too bad

heavy hill
#

💀

heavy hill
#

it makes sense now

dusky basin
heavy hill
#

.close

pearl pondBOT
#
Channel closed

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dusky basin
#

Dr p can you help me now then

heavy hill
#

uhh i can try

dusky basin
heavy hill
#

ummm

#

what is this

dusky basin
#

Logic

cinder flower
dusky basin
#

Proof tables

heavy hill
#

im gonna be honest

#

i cant help u

#

i dont even know what im looking at

dusky basin
#

Cooked

heavy hill
#

😭

pearl pondBOT
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buoyant garnet
#

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versed mica
buoyant garnet
#

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versed mica
#

what is the graphical technique from section 3.1

buoyant garnet
#

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versed mica
#

how precise does it have to be

#

getting the general shape is easy

#

approximating the slope is egregious

buoyant garnet
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versed mica
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like do we really need to scale the axes and have coordinates

buoyant garnet
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versed mica
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💀

buoyant garnet
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versed mica
#

for the derivative?

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oh brother

buoyant garnet
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versed mica
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well for the max you can look at the middle section

buoyant garnet
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versed mica
#

where it has a point of inflection

buoyant garnet
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versed mica
#

you aren’t familiar?

#

changing concavity

#

f’’ changes sign

buoyant garnet
#

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versed mica
#

think of it like critical point for f’

buoyant garnet
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versed mica
#

what

buoyant garnet
#

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versed mica
#

no it more so looks like a straight line

buoyant garnet
#

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versed mica
#

no

#

not a horizontal tangent

#

just look where it changes concavity

buoyant garnet
#

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versed mica
#

it changes from concave up to concave down

buoyant garnet
#

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versed mica
#

if you have the solution what’s confusing you

buoyant garnet
#

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versed mica
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cant you learn from looking at the solution

buoyant garnet
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versed mica
#

you just desperately wanted to talk to me

buoyant garnet
#

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versed mica
#

i get it

buoyant garnet
#

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versed mica
#

well it should be obvious that it starts ~0 and ends ~ 0

buoyant garnet
#

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buoyant garnet
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versed mica
#

hopefully you can tell it’s suymmetrical

#

just by looking at it before and after the point of inflection

buoyant garnet
#

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versed mica
#

yea about the point of inflection

buoyant garnet
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buoyant garnet
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versed mica
buoyant garnet
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versed mica
#

need i say more about the shape?

buoyant garnet
#

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buoyant garnet
versed mica
#

let’s look at the slope near point of inflection

#

it’s approximately linear

#

so we can just good old slope formula

buoyant garnet
#

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versed mica
#

you can use 20->25 or 25->30

#

(20,100)

buoyant garnet
#

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versed mica
#

you can

#

(30,250)

#

ish

buoyant garnet
#

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versed mica
#

little more

buoyant garnet
#

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versed mica
#

the coordinates

buoyant garnet
#

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versed mica
#

yuh

buoyant garnet
#

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versed mica
#

what did you get

#

(20,100) and (30,250)

buoyant garnet
#

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buoyant garnet
#

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versed mica
#

keep it simple

buoyant garnet
#

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versed mica
#

15

buoyant garnet
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buoyant garnet
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versed mica
#

8/5

#

brother what

buoyant garnet
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versed mica
#

160/10

#

is 16

#

🤔

buoyant garnet
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versed mica
#

no idea where 1.6 came from

buoyant garnet
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versed mica
#

so either works

versed mica
#

👍🏻

buoyant garnet
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versed mica
#

yea

buoyant garnet
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versed mica
#

yes way

buoyant garnet
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versed mica
#

you’re saying something i guess

#

🤷🏼‍♂️

buoyant garnet
#

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versed mica
#

bring bullying back

#

💯💯

#

🙏🏻🙏🏻

buoyant garnet
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pearl pondBOT
#
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buoyant garnet
#

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buoyant garnet
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versed mica
#

Q’(t)

#

Q’(10)

#

yooo

#

the goat

#

🐐 🐐🐐

finite jolt
#

whom

versed mica
#

@finite jolt

#

my guy

buoyant garnet
#

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versed mica
#

nah

#

hired

finite jolt
#

ah thanks ;)

versed mica
finite jolt
#

Yeah ive been trying to come back to mathcord and help more

finite jolt
obtuse plaza
versed mica
#

you need the green my man

buoyant garnet
#

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finite jolt
#

green grind starts today

obtuse plaza
#

yes

finite jolt
#

wrt time

buoyant garnet
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no need for the ^1

#

but sure

buoyant garnet
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#

and -1

#

you need the -1

#

for chain rule

finite jolt
#

Isnt there supposed to be a negation

buoyant garnet
#

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finite jolt
#

yeah

buoyant garnet
#

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versed mica
#

brother

buoyant garnet
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finite jolt
versed mica
#

yep

finite jolt
#

in this case g(x) is 30-t or whatever

versed mica
#

from -t

buoyant garnet
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versed mica
#

brother i know you know the chain rule

#

we’ve done problems that involve it

buoyant garnet
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#

😭

finite jolt
#

no

versed mica
#

for instance

#

the derivative of sin(2x) = 2cos(2x)

buoyant garnet
#

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versed mica
#

derivative of e^(x^2) is 2xe^(x^2)

buoyant garnet
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versed mica
#

that’s power rule

buoyant garnet
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buoyant garnet
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versed mica
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🤔

buoyant garnet
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finite jolt
#

Okay then

#

You should probably learn it

buoyant garnet
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versed mica
#

yo kenzo we have

buoyant garnet
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finite jolt
#

what is f(x) in this case

buoyant garnet
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versed mica
#

if you don’t want to use chain rule then distribute

#

and only use power rule

buoyant garnet
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finite jolt
#

yes but chain rule is arguably the most important differentiating rule

#

and youll need it eventually

#

if not today in 2 weeks

versed mica
#

this isn’t the place to learn it though

buoyant garnet
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@buoyant garnet

buoyant garnet
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finite jolt
#

ah alr

versed mica
#

did you read the damn book

finite jolt
#

Then expand it

versed mica
#

by mcmullen

buoyant garnet
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finite jolt
buoyant garnet
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versed mica
buoyant garnet
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finite jolt
versed mica
versed mica
#

we can’t promote this though

#

i’ll dm you

buoyant garnet
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finite jolt
#

Alright uh

#

expand 30-t

#

swuared

#

Then its just a simple power rule

buoyant garnet
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versed mica
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f(x) is really x^2

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then g(x) is 30-x

buoyant garnet
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finite jolt
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Great

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Differentiate

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And go from there

buoyant garnet
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finite jolt
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Yes

buoyant garnet
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finite jolt
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Wait a minute

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Where the hell did the 200 go

buoyant garnet
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finite jolt
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its being multiplied

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not added

buoyant garnet
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finite jolt
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Is derivative of 2x the same as x

buoyant garnet
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finite jolt
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Exactly

buoyant garnet
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finite jolt
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..what

versed mica
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brother

buoyant garnet
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versed mica
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d/dx cf(x) = cf’(x)

buoyant garnet
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versed mica
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constant multiple

buoyant garnet
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versed mica
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dawg we’ve been doing problems that involve this for weeks

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are you ok

buoyant garnet
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versed mica
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give your brother back the controller

finite jolt
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okay look studying while sleep deprived is not

buoyant garnet
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finite jolt
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How do you know product rule and not

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constant multiple

buoyant garnet
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finite jolt
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You can derive constant multiple from product rule

buoyant garnet
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finite jolt
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anyway

buoyant garnet
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finite jolt
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Yes

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Plug in 10

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and the torture will be over

buoyant garnet
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finite jolt
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sure

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sounds right

buoyant garnet
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finite jolt
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whats the right one

buoyant garnet
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finite jolt
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oh wait

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The question might be kind of cheeky

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wait nvm

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Also the answer cannot be a positive number

buoyant garnet
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finite jolt
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The fuck is photomath

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the math is saying -8000

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tsrust math

buoyant garnet
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finite jolt
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fuck it put it in wolframalpha

buoyant garnet
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finite jolt
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,w derivative of 200(30-t)^2 at t=10

jolly parrotBOT
finite jolt
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see

buoyant garnet
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finite jolt
buoyant garnet
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finite jolt
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It says on there

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show steps

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what does it say there

buoyant garnet
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finite jolt
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Hi

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anyway

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We got part 1

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Part 2 now

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Its pretty simple

buoyant garnet
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pearl pondBOT
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Channel closed

Closed by @buoyant garnet

Use .reopen if this was a mistake.

pearl pondBOT
#
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ruby wadi
#

My main question is about v-w. When graphing, do you graph the resulting matrix or rather just v connecting v?

ruby wadi
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to me, this is what I see.

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What I am unsure about is whether v-w would just be [-7, 9] or rather what I described earlier. Because the vector would be totally different.

gleaming musk
# ruby wadi

u would join vector v and w, with the arrow pointing towards the tip of vector v

ruby wadi