#help-39

1 messages · Page 148 of 1

cosmic charm
#

if you can clear the denominator of the fraction it'll be great right

buoyant garnet
#

One message removed from a suspended account.

#

One message removed from a suspended account.

#

One message removed from a suspended account.

cosmic charm
#

well if you want to cancel the b in a/b

#

you multiply by b

#

yeah?

buoyant garnet
#

One message removed from a suspended account.

cosmic charm
#

yep

buoyant garnet
#

One message removed from a suspended account.

heady finch
#

that's just a byproduct of fraction division

#

you should go look at it

buoyant garnet
#

One message removed from a suspended account.

cosmic charm
#

but since you multiply b on the top you need to multiply b on the bottom also

#

so (a/b) / c = a/(b*c)

#

if thats your question idk

buoyant garnet
#

One message removed from a suspended account.

#

One message removed from a suspended account.

#

One message removed from a suspended account.

cosmic charm
#

you said you dont understand it so i gave an explanation why that is

buoyant garnet
#

One message removed from a suspended account.

#

One message removed from a suspended account.

cosmic charm
#

uh huh yep

buoyant garnet
#

One message removed from a suspended account.

cosmic charm
#

1-1 is?

buoyant garnet
#

One message removed from a suspended account.

cosmic charm
#

and 0+h is?

buoyant garnet
#

One message removed from a suspended account.

#

One message removed from a suspended account.

cosmic charm
#

yep

buoyant garnet
#

One message removed from a suspended account.

cosmic charm
#

exactly

cosmic charm
#

h on the bottom

#

cancel em out

#

1/1+h

buoyant garnet
#

One message removed from a suspended account.

#

One message removed from a suspended account.

#

One message removed from a suspended account.

pearl pondBOT
#
Channel closed

Closed by @buoyant garnet

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

polar crypt
pearl pondBOT
polar crypt
#

What did i do wrong?

#

The 12 one

#

i got it now

#

sorry for bothering

#

close

#

,close

#

how do i close it

#

nvm

teal wyvern
#

.close

pearl pondBOT
#

@polar crypt Has your question been resolved?

#
Channel closed

Closed by @polar crypt

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gusty prism
pearl pondBOT
gusty prism
#

do i need to use some type of

#

length times width formula or something

#

like they give me the volume dimensions

#

22 times 3.8 ???? 😭

#

v=83.6cm^2

sinful nebula
#

nah

#

volume of cylinder is different

gusty prism
#

ah

sinful nebula
#

pi(r^2)h

#

h = length

#

r = radius

gusty prism
#

hm so

#

oh

#

ok

#

perfect then

#

and still use d=m/v?

#

and which ever is heavier will alarm the belll

sinful nebula
#

oh density *volume = mass

gusty prism
#

based on the mass for the can of sand

sinful nebula
gusty prism
#

ok prfct

#

thnx

sinful nebula
#

now it

#

no wait

gusty prism
#

o

sinful nebula
#

calculate the mass of those both first

gusty prism
#

like if sand is heavier than the gold then the thief prob triggered the alarm

#

ok

rose silo
#

Sand should not be lighter or heavier

sinful nebula
#

if mass of sand does not equal that of gold

rose silo
#

It should be same mass as gold to not set off the alarm

sinful nebula
#

then it should trigger the alarm

rose silo
#

Yes

gusty prism
#

ah

#

i see

#

i didnt read properly

rose silo
#

np

sinful nebula
#

yea I got a little confused too

rose silo
#

The dimensions are same but densities are different so the alarm will go off

gusty prism
#

what ever answer u get

#

from this formula

#

it must still be in cm right

sinful nebula
#

ye

gusty prism
#

ok

sinful nebula
#

bc radius and height are in cm

#

it would be in cm^3

#

clearly density of gold is greater than that of sand

#

for question b

gusty prism
#

yea

#

so becuz they arent the same

#

mass

#

sand isnt the same as the gold

sinful nebula
#

yes

gusty prism
#

and this is weight sensitive

#

ok prfct

#

.close

pearl pondBOT
#
Channel closed

Closed by @gusty prism

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight haven
#

What's difference between a function and a equation
A linear equation is there, by adding subtracting stuff on both sides I can get a function
But let's say I have a degree 2 equation
I can't write it as a dependent and independent variable
Like
y -mx = c
y = mx + c
It's a function right

But
x^2 + 2xy + y^2
I can't right it as y = bla bla
So this brings me back to question
What is function and what is equation

violet tundra
#

in simple terms, a function is something which maps an x value to only one y value

leaden wadi
#

An equation has an expression on either side of an equal sign.

#

A function explicitly designates a variable(s) to be a dependent variable.

#

f(x) explicitly designates x to be a dependent variable.

midnight haven
leaden wadi
#

In the latter case, you are explicitly solving for y with x being a dependent variable.

midnight haven
leaden wadi
#

Yes.

midnight haven
#

Cool

midnight haven
pearl pondBOT
#

@midnight haven Has your question been resolved?

midnight haven
#

@leaden wadi again sorry
x² - y² = 4
y = √(4+x²)
So again
I can write all equation in form of functions
Then what's the difference between them

leaden wadi
#

With a function, one of the variables is explicitly the dependent variable.

#

x - y = 0 would be an expression because neither variable is explicitly designated as the dependent variable.

#

x = y would be a function because y is the dependent variable.

#

It's mostly semantics.

midnight haven
#

Oh cool

pearl pondBOT
#

@midnight haven Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

charred sorrel
#

How can I work out 5^2 +5^2 - 2x5x5xCos(30) without a calculator? I know that Cos30 is √3/2 . But how can I get it to be 50-25√3 thanks.

edgy wren
#

What’s 5^2 ?

charred sorrel
#

25

frosty ravine
#

The number is irrational

#

You can approximate it

charred sorrel
#

Can I get it In the form r-s√3?

frosty ravine
#

Well you just multiply 2*5*5*sqrt{3}/2

#

And add 5^2 + 5^2 which is 50

charred sorrel
#

Thanks

#

.close

pearl pondBOT
#
Channel closed

Closed by @charred sorrel

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight haven
#

how to determine the

pearl pondBOT
midnight haven
#

minimum of x^x

#

it's not 1

#

How to get the value?

#

damn

#

derivative?

#

Suppose I don't have any knowledge about them

#

it's a very sus value

#

its

#

${\frac{1}{e}}$

jolly parrotBOT
#

icannotdoanymorecauchy

midnight haven
#

magic

chrome plank
#

let f(x) = x^x. if f(x) is always curving upwards, the minimum is where f'(x) is flat.

midnight haven
#

Is this always curving upwards?

chrome plank
midnight haven
#

Idk by inspection

chrome plank
#

nope

#

is x^2 always curving upwards?

midnight haven
#

Yes

chrome plank
#

is x^3 always curving upwards?

midnight haven
#

i think

chrome plank
#

nope

midnight haven
#

then what is it

chrome plank
#

what do I mean by "curving upwards"?

midnight haven
#

That it's value increases even for small x

#

but here it increases

#

always innit?

chrome plank
#

it's increasing yes, but it's not always curving upwards

midnight haven
#

curving is like convex and concave, no?

chrome plank
#

look at the left of the y axis, it's curving downwards there

chrome plank
chrome plank
#

what tools do you know in maths that could help?

midnight haven
#

idk

#

graphs

#

lol

chrome plank
#

without drawing anything XD

midnight haven
#

I can't think of any

chrome plank
#

well, how would you define "curving" mathematically?

midnight haven
#

calculus not allowed here ):

chrome plank
midnight haven
#

yea

chrome plank
midnight haven
#

oops

#

exactly brutha

chrome plank
#

that changes things

midnight haven
#

Then it is quite hard ig

#

extremely hard

#

$x^x = e^{x\ln x}$

jolly parrotBOT
#

icannotdoanymorecauchy

midnight haven
#

..

#

ok

#

I think there is a need to learn calculus asap

#

thanks guys

#

.close

pearl pondBOT
#
Channel closed

Closed by @hallow solar

Use .reopen if this was a mistake.

chrome plank
#

ye, go learn some calc XD

midnight haven
chrome plank
#

I suppose you could look at it, and propose the minimum is x. then, look a little to the left or right and show f(x+d) (for any d, positive or negative) is bigger than f(x).

#

you won't be able to calculate the minimum this way, but you can show some value iof x is indeed a minimum.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

high steppe
#

avg = total we counted/total variable?

pearl pondBOT
high steppe
#

for example 1+2+3+4+5
avg = 1+2+3+4+5/5

midnight haven
#

The average of 1, 2, 3, 4 and 5, is sum(1+2.....5)/(5), not of 1+2+3+4+5, because this simplifies to a single term.

#

tomorrow's my maths exam

midnight haven
#

the average of 1, 2, 3, 4 and 5 is (1+2+3+4+5)/5 = 3

high steppe
#

isnt that what i said?

midnight haven
midnight haven
high steppe
#

avg = 1+2+3+4+5/5

#

avg = 1+2+3+4+5/5

midnight haven
#

the sum is at the top and the number of terms is at the bottom

high steppe
#

wat

midnight haven
high steppe
#

avg = (1+2+3+4+5)/5
right?

midnight haven
#

yes

#

but use correct words

high steppe
#

wat words

midnight haven
high steppe
#

and?

midnight haven
#

wat

high steppe
#

so avg = (4+4+4+3+4+4+4+3)/8 right

midnight haven
#

yes good

high steppe
#

dude tell me the words

midnight haven
pearl pondBOT
#

@high steppe Has your question been resolved?

spark shuttle
#

hey do you have an advise for studying math?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shadow monolith
#

I'm trying to follow the following proof. How are they getting to it's false that Pr(e | A & ~T) is many times greater than Pr(e | T)?

pearl pondBOT
#

@shadow monolith Has your question been resolved?

pearl pondBOT
#

@shadow monolith Has your question been resolved?

pearl pondBOT
#

@shadow monolith Has your question been resolved?

worthy drift
#

What’s wrong with this question

plush bramble
pearl pondBOT
pearl pondBOT
#

@shadow monolith Has your question been resolved?

pearl pondBOT
#

@shadow monolith Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dusty heart
#

i need help with a complicated exercise using derivatives (theres also my attempt to solve it). What the exercise asks for is the minimal value of the function. Which would obviously imply using derivatives and, but i seem to be very far of from any of the multiple choice answers.

dusty heart
#

if you've got any question about my solution or what im trying to do id be more than glad to try and explain

pearl pondBOT
#

@dusty heart Has your question been resolved?

leaden wadi
#

I think you did a lot more work than you needed to do.

dusty heart
#

hmmm, wdum by that

#

i didnt even get an answer even after doing all of that mess

leaden wadi
#

Completing the Square was unnecessary.

#

You can just square both sides to eliminate the radical.

dusty heart
#

wdum completing the square?

leaden wadi
#

Hmm, some terminology lost in translation.

dusty heart
#

english is not my first language so thats why im asking

leaden wadi
#

The steop you did on the right-hand side.

dusty heart
#

oh

#

i just thought it may help somewhere along the line

leaden wadi
dusty heart
#

which i feel like it did kinda make my calculations easier

leaden wadi
#

Squaring both sides gets a better result that can then be simplified through polynomial division.

dusty heart
# leaden wadi

yup, thats what you would get by just raising them to the 2nd power

dusty heart
#

i mean, its an idea

leaden wadi
dusty heart
#

oh wow

#

i see what u mean now

#

this is so hype

#

did you find the values for x yet?

leaden wadi
#

Yes, and the end result does match up with one of the possible answers.

dusty heart
#

yup

#

same problem here

#

but these are some exercises for the entrance exam at a university so, it cant be that theyre wrong

#

it says its a)

#

so 14 sqrt 2

#

oh wait, did you plug the values u got for x in the function?

#

cuz thats what it asks for

leaden wadi
#

Yes

dusty heart
#

oh

leaden wadi
#

Solve for x and you will get two results. Only one of which gives a Real answer that lies inside of the interval you found earlier.

dusty heart
#

okay let me solve it too

#

ill see what i get

#

oh btw, random question, are u a helper that works for this discord server, or are you just a dude who likes math and decided to help

leaden wadi
#

I like to help others to help myself improve my own understanding of math.

#

And to learn about areas of mathematics that I do not know by observing some of the questions asked here.

dusty heart
#

thats really cool dude

#

we could jump on a call for this exercise btw if u want

leaden wadi
#

I'm good. You should be able to get the answer relatively easy now.

dusty heart
#

the final polynomial is 28x^2 + 700x + 343=0?

dusty heart
#

let me check again

#

wait, no way, the delta is 672, thats amazing

#

sorry, i meant sqrt delta

sinful solar
# leaden wadi

Would Componendo and Dividendo have been a bad idea at the start of the question ._.

dusty heart
#

whats that?

sinful solar
#

well,
if a/b = c/d , then
(a-b)/(a+b) = (c-d)/(c+d)

#

y'all prolly have a different name for it but yeah

dusty heart
#

i see what u mean

sinful solar
#

Would that just make it tedius or something as it'd get heavy in the denominator

dusty heart
#

so, u mean after we got rid of the square root?

#

or where are u suggesting that we should have done that

sinful solar
#

mbmb

dusty heart
#

yea no prob

leaden wadi
#

The final polynomial you got is divisible by 7 btw.

#

4x^2 + 100 +49 = 0

dusty heart
#

ah, i see, thx

#

i did it with a calculator anyway

sinful solar
# leaden wadi

Componendo Dividendo could be done in the 3rd step though here

dusty heart
#

alright so f(x) = sqrt 73 + 8*sqrt2?

#

this is what i got

#

but the thing is that theres obvi no choice like that

leaden wadi
#

What two values of x did you get?

dusty heart
#

nvm i solved it

#

finally

#

ill send you a pic

#

its really messy tho,

#

here ya go

#

i got more exercises that are hard btw

#

if yall interested

#

these entrance exam exercises are no joke

leaden wadi
#

Feel free to post more questions. Just make sure you start a new channel.

dusty heart
#

oh alr

#

how do i close this one

leaden wadi
#

Type .close

dusty heart
#

.close

pearl pondBOT
#
Channel closed

Closed by @dusty heart

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fringe yoke
#
  1. PQRS overlap OLMN. Area of PQRS = 30cm^2. Find the shaded region's perimeter.
  2. Triangle ABD is a right angled triangle, angle ABC = 90. Point D is between line AC.
    BD is perpendicular to AC. AD = 1 12/13, DC = 11 1/13, if the triangle's area is 30cm^2, find the length of AB.
pearl pondBOT
#

@fringe yoke Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gleaming musk
pearl pondBOT
gleaming musk
#

im not really sure where i went wrong

#

context is highschool math, hyperbolic trig is not a substitution technique i have learnt

#

my handwriting isn't the neatest, so please lmk if there is any part u are finding hard to read

#

i somehow got 0

#

(manifesting rishabh to appear 🙏 again)

rough forge
gleaming musk
#

i did this to myself

#

i cant even complain anymore

next dove
# gleaming musk

It might be some visibility error but I don't see any negative sign with du

gleaming musk
#

*sign

next dove
#

and cos(pi-x)?

#

pi-u*

gleaming musk
#

where?

next dove
#

line just after u sub

#

it was cos(pi-u) so it will be -cosu right?

#

so a negative from this and a negative from du

gleaming musk
#

oh that is a pretty egreious

#

i just evaporated a negative sign

#

hold up let me redo this

next dove
#

kk

gleaming musk
#

@next dove i fixed silly error

#

last line is just by parts?

next dove
gleaming musk
next dove
round patio
# gleaming musk

A piece of advice,
You could have done the shift from x to -x to get another representation of I with same bounds

next dove
# gleaming musk

you assume this integral to be some I then after by parts you'll get I in some form
after that you can do some algebra to get I

round patio
#

That's much simpler

round patio
gleaming musk
#

oh right

#

that skips the 2 u subs i did

round patio
#

Then change the dummy variable to x again

round patio
gleaming musk
#

yeah the u subs were a bit silly in hindsight

#

good catch

round patio
#

If bounds look like -a to +a try this

#

This often works

gleaming musk
#

will keep that in mind

#

actually would that integral be nicer to crunch here?

#

since my u sub turns everything to integrating 0 to 2pi

#

your suggestion still keeps it from -pi to pi which might be nicer

round patio
gleaming musk
#

on?

round patio
#

2nd last line

#

On 3rd last line

gleaming musk
#

i split the integrla into 2 parts

#

and then use symmetry

#

like integrating f(x) = f(a-x)

#

squash the 2 together

round patio
#

It has e^(pi - u) + e^(u - pi)

round patio
#

I thought it was an algebraic mistake

#

my bad

gleaming musk
#

nw, i didnt write any justification either so thats a bit arbitrary to follow

#

wait idk how to do the last line by parts

#

my brain is cooked

#

T=T

#

actually nvm, let me try swapping

round patio
gleaming musk
#

pi/2?

round patio
#

e^-pi/2 is constant so we can pull it out

#

Yeah

#

Mb

#

Pi

gleaming musk
#

oh

#

yeah i did that

#

i think i just need to swap what i let my differentials equals to for by parts

round patio
#

Then the integral is cosu e^u

#

You can easily integrate e^u

gleaming musk
#

ended up getting -[e^pi - e^(-pi) ]/2

#

wolfram got decimal approximation rounded to it so i think its right

#

at least its correct to 4dp

#

thx for all the help here

#

🙏

#

.close

pearl pondBOT
#
Channel closed

Closed by @gleaming musk

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lucid valley
#

Im very mathematically challenged and im very stuck on understanding the system of disequalities of this type overall i can't wrap my head around what steps I'm supposed to take or what the rules are since it somtimes brakes already established rules for example "solve whatever is in (...) first" my math teacher said there are no formulas for it and im not sure what the rules are and how im supposed to solve it

rough forge
#

seems so

#

before we speak about a system, do you know how to approach one inequality, generally speaking?

lucid valley
#

the answer is supposed to involve some sort of system

#

i almost dont know anything

#

my mind sort of gets wiped when schools out ecpecially when it comes to math

rough forge
#

Let's start with something simple i guess

jolly parrotBOT
rough forge
#

can you describe what this means to you

#

or if you understand what this could mean

lucid valley
rough forge
#

yes

#

in fact this is always true

#

x^2 is a default parabola

lucid valley
rough forge
#

this

#

,w plot x^2

rough forge
#

you can see all y values are equal or greater than 0

#

it never goes below

lucid valley
#

so negative numbers don't exist in this case?

rough forge
#

negative outputs don't exist*

lucid valley
#

oh

rough forge
#

if you square a real number you always get a non-negative output

#

for example

#

(-2)(-2) = 4

lucid valley
#

coz - x - = +?

rough forge
#

yes

#

this was just an example so you get an intuition what an inequality means

#

you basically introduce more solutions

#

instead of asking x² = 0 (which the sol. is x = 0) you now also ask yourself when is x² > 0

#

which is true for all x unless x = 0

#

does this make sense?

lucid valley
rough forge
#

you ask why x² = 0 gives x = 0 as solution?

lucid valley
#

yea

rough forge
#

try any other number

#

to satisfy this equation

#

you will always get a false statement

rough forge
# jolly parrot

you can see also on the graph that x² becomes 0 is x is 0. For all the other values of x it's above the x-axis aka positive

lucid valley
#

oh

rough forge
#

does this make sense?

lucid valley
#

sorta

rough forge
#

well thats bad i guess

lucid valley
rough forge
#

say you have two functions

lucid valley
#

ye

rough forge
#

i suppose you kinda have an idea of what that is

lucid valley
#

maybe im not English and im currently in a country where i dont speak the language fluently so i might or i might not

rough forge
lucid valley
rough forge
#

polynomials
exponential functions
logarithms
trigonometric etc

#

rational functions

#

x, ln(x), e^x, sin(x), x/(x²-1) etc

#

such things

#

say we have two different functions

#

I call the one f(x) and the other g(x)

#

ok?

lucid valley
#

ok

rough forge
#

is there hope or did i lose you

lucid valley
rough forge
#

We can do the following

lucid valley
rough forge
#

We can ask ourselves if there is a common point among f(x) and g(x), an intersection for example

#

for example

#

,w plot x^2 and x

rough forge
#

you can see they have two intersections

#

so mathematically we would do the following

jolly parrotBOT
rough forge
#

We set them equal

#

we wanna find such x where y is the same in both functions

#

that's the idea of equations

#

any questions?

lucid valley
#

well why do people sometimes

#

move things around

#

like one number to the other side

rough forge
#

simply, to find x

#

let me give you an example

lucid valley
#

how would that moving work and in what cases

jolly parrotBOT
rough forge
#

Question

#

can you immediately tell me the solution for x

#

(i dont wanna hear the actual solution)

#

but my point being

#

we wanna simplify the equation

#

until we can get obviously and immediately tell what x is

#

here you would kinda have to think or even guess

lucid valley
#

uhmm

#

0+2?

rough forge
#

explain

#

wdym

lucid valley
#

well if 2x-2=0 if somthing beinf like subtracted gives u the answer you can just add jt up to see what your subtracting from?

rough forge
rough forge
#

So maybe you implied this

#

we could add 2 on both sides

jolly parrotBOT
rough forge
#

which gives us what

lucid valley
#

uhmm

#

a false thingy?

rough forge
#

what equation do you get after this

#

do the math

#

-2+2?

#

0+2?

lucid valley
#

0

#

2

rough forge
#

yes

jolly parrotBOT
rough forge
#

we basically "moved" 2 on the other side

#

hmm

#

how can we get rid of the 2 multiplied with x on the left?

lucid valley
#

isnt that impossible

rough forge
#

haha no

lucid valley
#

coz you gotta always do multiplication first?

rough forge
#

remember you can divide things on both sides

lucid valley
#

but what about the rule that says you gotta multiply 😭

rough forge
#

that's something different

#

PEMDAS

lucid valley
#

pemdas?

rough forge
#

this has nothing to do right now

#

PEMDAS stands for P- Parentheses, E- Exponents, M- Multiplication, D- Division, A- Addition, and S- Subtraction

#

this is what you mean

#

order of calculating numbers

#

forget this here for a second

lucid valley
#

i thought it was universal

rough forge
#

our goal is to isolate x

rough forge
jolly parrotBOT
rough forge
#

In order to get rid of the 2 multiplied with x

lucid valley
#

wait isnt 0 times anything 0

rough forge
#

we divide by the very same number

#

which looks like this

jolly parrotBOT
rough forge
#

We divide both sides by 2

#

so we get

jolly parrotBOT
rough forge
#

this is the solution to the equation

jolly parrotBOT
rough forge
#

you can see

#

isolating x is far better to get to the solution

lucid valley
#

oh

rough forge
#

instead we work our way there

#

and we do this by isolating x from everything else

lucid valley
#

so how do we separate the X?

rough forge
#

luckily these rules for equations are also applicable for inequalities, there is just one more thing with inequalities that you need to keep in mind

rough forge
#

we used arithmetic operations

lucid valley
#

what are those

rough forge
#

addition
subtraction
multiplication (except 0)
division (except 0)

#

there are a few more but we will stay with them for now

lucid valley
#

ok!

rough forge
#

so

lucid valley
#

ye

rough forge
#

before you touch inequalities

#

you have to get comfortable with equalties

#

with normal equations

#

the basic and hard ones

#

and i see that you are definitely not comfortable

#

that's an issue you have to accept for now

#

you should start from scratch

#

it's literally impossible to explain to you why inequalities and how you calculate with them

#

and then especially system of inequalities

#

that's too hardcore

#

that's just if you were level 1 this would be level 10

lucid valley
#

how do i get comfortable with equalitys

rough forge
#

practice

#

you master the very basic operations

#

addition
subtraction
multiplication (except 0)
division (except 0)

#

you can solve/isolate x fast without second guessing

#

that's something you have to do

#

you have to unlock this skill first

lucid valley
#

ok!

rough forge
#

so what you wanna do is this

lucid valley
#

ye?

rough forge
#

alternatively you can think of getting a tutor for yourself

#

otherwise self study

lucid valley
#

ty

rough forge
#

then the next level

#

system of equations

#

you get a good understanding of what a system is now

#

This algebra video tutorial explains how to solve systems of equations by elimination and how to solve systems of equations by substitution with 2 variables.

Systems of Linear Equations - 2 Variables: https://www.youtube.com/watch?v=oKqtgz2eo-Y

Systems of Equations - Fractions & Decimals:
https://www.youtube.com/watch?v=jlddJQ1qYDU

...

▶ Play video
#

If you watched, practiced and got the hang of this

#

then you can start with this

#

This algebra video tutorial provides a basic introduction into how to solve linear inequalities. It explains how to graph the solution using a number line and how to represent the answer in interval notation. It contains linear inequalities with fractions and explains how to solve compound inequalities. it contains many examples and practice ...

▶ Play video
#

then from there it starts to get a bit easier

#

cause solving inequalities is not that different from normal equations

#

I recommend taking your time to watch and understand these, in the order i sent. Then to try and apply the knowledge you gained

#

and during that you can always come here and ask questions

rough forge
rough forge
lucid valley
#

i littrally dont even know how to find the percentage of somthing 😭

lucid valley
rough forge
# lucid valley i littrally dont even know how to find the percentage of somthing 😭

This youtube video tutorial on percentages made easy explains how to calculate the percentage of a number mentally using your head without a calculator. This video contains plenty of shortcuts and tricks explaining how to find a percentage of a whole number. it goes over the basics and explains how to check your answer using your calculator. ...

▶ Play video
rough forge
#

just follow the order

lucid valley
#

ok

rough forge
#

make a todo list

#

of what you need to cover

#

so you get a basic understanding of things

#

if necesary write down notes

#

and most of all practice

#

until you develop an intuition for things

#

otherwise you will stay there where you are, and you dont want that

#

the most important thing for you is acceptance and to stay calm

#

there maybe tons of doubts you have right now

#

which i cannot cover all up

#

but it's important to start somewhere with something

#

concentrate now on this topic

#

then if you did that

#

do percentages

lucid valley
#

ok

rough forge
#

this guy i sent

#

he has everything you need

lucid valley
#

thank you

rough forge
#

just search and you will find

#

and if you struggle

#

you can ask here questions, always

#

i wish you good luck, and i hope we will see each other again

#

but when you are more ready

#

and more prepared

#

more equipped

lucid valley
pearl pondBOT
#

@lucid valley Has your question been resolved?

lucid valley
rough forge
pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

upbeat goblet
#

What does that even mean

#

Bro what

pearl pondBOT
placid zealot
#

so for a reflection

#

just imagine a line

#

if polygon a is reflected across that line to show polygon b, then it can be mapped only using reflections

#

something which uses something other than reflections would be scale factors, which would make a bigger or smaller

placid zealot
upbeat goblet
#

Oh

#

so in this case she could map it

placid zealot
#

👍

#

you can also think of it like a mirror

#

because mirrors reflect

upbeat goblet
#

ohh

#

TYSM im so backed up on assignments rn

placid zealot
#

np

upbeat goblet
#

What about this one

#

This one kinda confused me

#

Because I thought I got it right but I guess I got it wrong

pearl pondBOT
#

@upbeat goblet Has your question been resolved?

pearl pondBOT
#

@upbeat goblet Has your question been resolved?

upbeat goblet
hexed cobalt
# upbeat goblet

at the centre of a regular heaxagon we can see 6 equilateral triangle and taking about angles each angle should be 60 degrees

upbeat goblet
#

Oh

#

Tysm

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tropic estuary
#

let f be a function defined and continuous in R, prove that for every 2 real numbers a, b a real number d exists such that 3f(d) = 2f(a) + f(b)

plucky python
#

(the one u sent in last time)

plucky python
pearl pondBOT
#

@tropic estuary Has your question been resolved?

tropic estuary
#

and I did smth kinda

#

i worked with max and min

#

it's pretty scuffed

#

I don't even understand what I did

plucky python
#

ah ok

#

well basically we'll have to do cases which is a bit boring

#

but here's the general idea:

#

let's sps a<b and that f(a) < f(b)

#

then (2f(a) + f(b)) / 3 is somewhere between f(a) and f(b)

#

so we finish by IVT

tropic estuary
#

oh btw

tropic estuary
#

the other one was meant to be

#

7f(d)= 2f(a) + 2f(b) + 3 f(c)

plucky python
#

ah right

tropic estuary
#

it's not the same approach is it?

plucky python
tropic estuary
#

because we have 3 numbers here so we can't just say a<b and f(a)<f(b) ...

tropic estuary
plucky python
#

think intuitively - the average of a big number and small number is somewhere in-between

tropic estuary
#

yeeesss ?

#

but there we have 2f(a) not just f(a)

tropic estuary
#

.close

pearl pondBOT
#
Channel closed

Closed by @tropic estuary

Use .reopen if this was a mistake.

cloud wren
#

Can u help me with matrixes?

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

plain quarry
#

Can someone help me out with these problems? I just need a guide

storm osprey
#

wich one do you need help with ?

pearl pondBOT
# plain quarry Can someone help me out with these problems? I just need a guide
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
plain quarry
storm osprey
#

Alright

#

Do you understand the first one ?

plain quarry
#

Not really

#

The wording for all of them is just confusing

storm osprey
#

You need to find what axis you should use in order to have a 4th rectangle wich is a reflection of A''B''C''D''

plain quarry
#

Is it the Y axis?

storm osprey
#

What rectangle would you reflect with the y axis ?

plain quarry
#

I don’t know

storm osprey
#

what triangle is one the left side of your y axis ?

storm osprey
#

yes, but you want the reflection of A''B''C''D'' right

#

wich is below the x axis

plain quarry
#

Ohhhh

#

So therefore it’s the x axis?

storm osprey
#

yep

#

to the second one now

#

do you understand what you must find ?

plain quarry
#

Yeah I think I have to find where W”V”X”lies

storm osprey
#

yes

plain quarry
#

I believe W’V’X is already rotated right

#

So if it were to be rotated again would it be the first quadrant?

#

Or something I think 😭

storm osprey
#

it is rotating in the direction of the arrow

plain quarry
#

Oh so the fourth quadrant

storm osprey
#

yes

plain quarry
#

Man I knew that 💀

#

Thank you

storm osprey
#

do you get the third one ?

plain quarry
#

Hmmm

#

I believe I do but I forgot the steps to find it

storm osprey
#

if you say that P->P' is a rotation of 90 and P'->P'' is one of 45

#

try to find P->P''

plain quarry
storm osprey
#

how did you get to that result ?

plain quarry
#

Errr actually

#

Is it 135?

storm osprey
#

it is

plain quarry
#

Awesome sauce

storm osprey
#

do you understand the last one ?

plain quarry
#

Hell nah 💀

pearl pondBOT
#

@plain quarry Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

weary dragon
#

Can someone check if this is right

pearl pondBOT
acoustic path
#

is correct

pearl pondBOT
#

@weary dragon Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

eager flax
#

could someone help me to find out the anwser for that indetermination without l'hopital?

acoustic path
eager flax
#

I called a=sqrt[4]{2x} and b=1
so I find out after some conclusions 0/4, do you found out that?

#

I do that, is it right? @acoustic path ?

naive orbit
#

,rotate

jolly parrotBOT
eager flax
#

@acoustic path ?

pearl pondBOT
#

@eager flax Has your question been resolved?

pearl pondBOT
#

@eager flax Has your question been resolved?

#
Channel closed

Closed by @eager flax

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

half goblet
#

Yo someone wanna help me figure out how youd get 5d and 15c

half goblet
#

Just some functions

light helm
#

did you do all the other parts?

half goblet
#

For 15?

#

For 5 I did

#

For 15 think my teacher said not to worry bout a and b

light helm
#

did you do 5c?

half goblet
#

Yessir

#

Oh wait

#

Yo 15c i)

#

And 5c

#

Are the exact same arent they.

light helm
#

exact same question, no
but the same idea applies when doing it

half goblet
#

Alr

light helm
#

they're pretty much all evaluating/simplifying

pearl pondBOT
#

@half goblet Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

craggy rivet
#

A group of physics students builds a catapult. They place it on the roof of a school, 18.0 m above the ground and launch a ball toward the east at 24.5 m/s [24° above horizontal]. When the ball hits the ground, how far away from the school will it be?
I am looking for t so I can do vc=dx/t
but none of the equations in the book let me find t

edgy wren
#

first get the vector components

craggy rivet
#

but idk how I get time from that?

pearl pondBOT
#

@craggy rivet Has your question been resolved?

uneven bear
#

The general approach to such problems is to start with the equation of motion

#

$$F=m\ddot{z}$$

jolly parrotBOT
uneven bear
#

Then figure out what forces are involved

craggy rivet
#

I never got such an equation in my text book

uneven bear
#

In this case we only got gravity

#

Never seen F=m*a?!

craggy rivet
#

what does it mean?

#

maybe ive seen the equivalent

uneven bear
#

$\ddot{z}$ is the z component of the acceleration vector

jolly parrotBOT
uneven bear
#

m is the mass of the object and F is the total force that is acting on it

craggy rivet
#

yeah never see that before, this is confusing me

uneven bear
#

Have you seen this before at least?

#

$$z=\frac{1}{2}at^2+v_0t+z_0$$

jolly parrotBOT
uneven bear
#

Still who the heck would introduce such problems without teaching Newton's equation of motion first :/

craggy rivet
#

can i take pictures of the equations I have access to?

uneven bear
#

Just a distance. Probably the textbook has x or d or whatever

uneven bear
uneven bear
#

There it is 😄

#

Mine is just more general with the initial position/distance included

#

$$d=\frac{1}{2}at^2+v_0t+d_0$$

jolly parrotBOT
uneven bear
#

So again, we are just looking at the vertical component

#

$d_0$ is the initial height, $v_0$ is the z component of the initial velocity and $a$ will be $-g$ from gravity

jolly parrotBOT
uneven bear
#

And we want the time it takes for d to become 0, so you have to solve this quadratic equation to get t.

craggy rivet
uneven bear
#

One solution is negative, so not physical meaningful

craggy rivet
#

im falling asleep a bit, how do you know that, and which solution?

uneven bear
#

midnight formula is your friend

craggy rivet
#

idk wehat that is

#

I gotta go to sleep man, ill probably ask in the morning

obtuse plaza
#

You should see examples of that question the concept behind it on yt or smth

#

As you don't know anything about the laws of motion

craggy rivet
#

Those get introduced later

uneven bear
#

I agree with FlexO though. You can't really appreciate the solutions to these problems without understanding the laws of motion, so have a look already and it might give you an edge 😉

pearl pondBOT
#

@craggy rivet Has your question been resolved?

pearl pondBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

pearl pondBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

north talon
#

There is a math test with 30 questions, where 3 students and 1 teacher is doing it. If each of the students can do atleast 3 questions, and the teacher can do no more than 15, how many ways can the 4 people complete the test?

north talon
#

ive never seen these types of questions before

cinder flower
#

can do atleast 3 questions
does that mean must do at least 3?

#

it doesn't read like that but why would it be there if it really just meant 'can' eeveethink

north talon
#

oh in the original question (i translated it) they used can so i dont really know

cinder flower
#

ok probably must do at least 3 then

north talon
#

alright

cinder flower
#

hm well i have a way of doing it but i don't think you'll like it

north talon
#

what is it?

cursive wraith
#

I was thinking about stars and bars but the >= 0 version

cinder flower
#

the constraints are kinda annoying for a stars and bars approach

north talon
cursive wraith
cursive wraith
cinder flower
#

i think i have the answer

#

(i will not say yet)

cursive wraith
#

but do you know how many ways can we choose x1,...,xk such that x1+...+xk = n

#

(x1,...,xk are non negative integers)

cinder flower
#

wait does complete the test mean just assign a number of questions to each person

north talon
#

no😭

cinder flower
#

or does which questions each person does matter

cursive wraith
#

oh yeah this is important

cinder flower
north talon
#

i think this was like comp math from a month ago but ive found nobody doing it online

cinder flower
cursive wraith
cinder flower
#

LOL yea i agree

#

you could just assign the 3 students 3 questions each, and then take cases on assigning the teacher 0 through 15 questions

#

then you just need to compute like compute 16 binomial coefficients

#

by stars and bars

north talon
#

they have to do a total of 30 questions

cursive wraith
cinder flower
#

ohhhhh

cursive wraith
#

the number of ways to choose $x_1,...,x_k$ non-negative integers such that $x_1+...+x_k = n$

jolly parrotBOT
#

rafilou2003

cursive wraith
#

is $\binom{n+k-1}{k-1}$

jolly parrotBOT
#

rafilou2003

north talon
#

oh

cursive wraith
#

had you seen this before?

north talon
#

no sorry

cursive wraith
#

no worries

#

the visual proof that I use for this

#

you imagine that you have n stars to distribute between k bags

#

those bags are in a line, and there's bars between them to separate them

#

so after placing the stars, from left to right you will have a total of "n+k-1 objects"

#

the objects regrouping the stars and the bars

#

(n stars, k-1 bars)

north talon
#

ohh

cursive wraith
#

and to choose how many stars goes in each bag

#

all you have to do is choose where in that sequence you place the bars

north talon
#

makes sense

cursive wraith
#

so now to apply the formula

#

you can write for example s_1, s_2, s_3 and t the number of questions each person takes

#

so then you would be solving $s_1 + s_2 + s_3 + t = 30$

jolly parrotBOT
#

rafilou2003

cursive wraith
#

problem being, those can't be any non-negative integers

#

because each student must take at least 3 questions

north talon
#

yeah?

cursive wraith
#

so, instead of looking at the number of question each student takes

#

we're gonna look at the number of questions each student takes, minus 3

#

call these numbers x1,x2,x3

north talon
#

oh dang i was about to ask if that would work😭

cursive wraith
#

and we get $x_1 + x_2 + x_3 + t = 21$

jolly parrotBOT
#

rafilou2003

cursive wraith
#

so, if there were no restrictions on t, how many choices do we have?

north talon
#

24?

cursive wraith
#

uuuhhh

#

this is where you're supposed to apply the formula

north talon
#

oh

cursive wraith
north talon
#

4

cursive wraith
#

and how many stars do we have to place in total?

cursive wraith
north talon
#

oh nice

cursive wraith
#

what's even nicer

#

is that this is 2024

north talon
#

crazy

cursive wraith
#

ok so

#

unfortunately

#

there's not that many choices

#

because we overcounted the outcomes where the teacher had too many questions

#

for which values of t does that happen?

north talon
#

16 to 30

cursive wraith
#

but it does start at 16

north talon
#

oh

#

to 21 maybe?

cursive wraith
cursive wraith
#

what does matter is that we gotta get rid of the outcomes where t >= 16

north talon
#

would we subtract 16 then?

cursive wraith
#

we subtract 16 to what?

north talon
#

from t

cursive wraith
#

yesss

#

so it becomes a new variable

#

x_4

north talon
#

hooray

cursive wraith
#

and now, we wanna know the amount of ways

#

such that...?

north talon
#

x_1 + x_2 + x_3 + x_4 <= 5? im not sure

cursive wraith
#

almost

cursive wraith
#

so if you subtract 16 from both sides

#

not sure there's an "inferior or equal to"

north talon
#

o

cursive wraith
#

$x_1 + x_2 + x_3 + x_4 = 5$

jolly parrotBOT
#

rafilou2003

cursive wraith
#

alright