#help-39
1 messages · Page 148 of 1
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yep
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but since you multiply b on the top you need to multiply b on the bottom also
so (a/b) / c = a/(b*c)
if thats your question idk
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you said you dont understand it so i gave an explanation why that is
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uh huh yep
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1-1 is?
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and 0+h is?
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yep
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exactly
you have h on the top
h on the bottom
cancel em out
1/1+h
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What did i do wrong?
The 12 one
i got it now
sorry for bothering
close
,close
how do i close it
nvm
.close
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do i need to use some type of
length times width formula or something
like they give me the volume dimensions
22 times 3.8 ???? 😭
v=83.6cm^2
ah
hm so
oh
ok
perfect then
and still use d=m/v?
and which ever is heavier will alarm the belll
oh density *volume = mass
based on the mass for the can of sand
yes
o
calculate the mass of those both first
Sand should not be lighter or heavier
if mass of sand does not equal that of gold
It should be same mass as gold to not set off the alarm
then it should trigger the alarm
Yes
np
yea I got a little confused too
The dimensions are same but densities are different so the alarm will go off
like
what ever answer u get
from this formula
it must still be in cm right
ye
ok
bc radius and height are in cm
it would be in cm^3
clearly density of gold is greater than that of sand
for question b
yes
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What's difference between a function and a equation
A linear equation is there, by adding subtracting stuff on both sides I can get a function
But let's say I have a degree 2 equation
I can't write it as a dependent and independent variable
Like
y -mx = c
y = mx + c
It's a function right
But
x^2 + 2xy + y^2
I can't right it as y = bla bla
So this brings me back to question
What is function and what is equation
in simple terms, a function is something which maps an x value to only one y value
An equation has an expression on either side of an equal sign.
A function explicitly designates a variable(s) to be a dependent variable.
f(x) explicitly designates x to be a dependent variable.
Again
x + y = 5
y = -x+5
In both the case i get same graph and second one is function too
So here equation and function are same right
In the latter case, you are explicitly solving for y with x being a dependent variable.
Hmm makes sense
x - 3y = 5
x = 3y + 5
f(y) = 3y + 5
Is it also a function
Yes.
Cool
Thanks a lot man
@midnight haven Has your question been resolved?
@leaden wadi again sorry
x² - y² = 4
y = √(4+x²)
So again
I can write all equation in form of functions
Then what's the difference between them
With a function, one of the variables is explicitly the dependent variable.
x - y = 0 would be an expression because neither variable is explicitly designated as the dependent variable.
x = y would be a function because y is the dependent variable.
It's mostly semantics.
Oh cool
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How can I work out 5^2 +5^2 - 2x5x5xCos(30) without a calculator? I know that Cos30 is √3/2 . But how can I get it to be 50-25√3 thanks.
What’s 5^2 ?
25
Can I get it In the form r-s√3?
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how to determine the
minimum of x^x
it's not 1
How to get the value?
damn
derivative?
Suppose I don't have any knowledge about them
it's a very sus value
its
${\frac{1}{e}}$
icannotdoanymorecauchy
magic
let f(x) = x^x. if f(x) is always curving upwards, the minimum is where f'(x) is flat.
Is this always curving upwards?
(assume) I don't know. how would you find out?
Idk by inspection
Yes
is x^3 always curving upwards?
i think
then what is it
what do I mean by "curving upwards"?
it's increasing yes, but it's not always curving upwards
curving is like convex and concave, no?
look at the left of the y axis, it's curving downwards there
yep
I got it
what tools do you know in maths that could help?
without drawing anything XD
I can't think of any
well, how would you define "curving" mathematically?
calculus not allowed here ):
OOOOOOOOOH
yea

that changes things
icannotdoanymorecauchy
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ye, go learn some calc XD
no, that's not min, (1/e)^(1/e) is min value of x^x
I suppose you could look at it, and propose the minimum is x. then, look a little to the left or right and show f(x+d) (for any d, positive or negative) is bigger than f(x).
you won't be able to calculate the minimum this way, but you can show some value iof x is indeed a minimum.
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avg = total we counted/total variable?
for example 1+2+3+4+5
avg = 1+2+3+4+5/5
The average of 1, 2, 3, 4 and 5, is sum(1+2.....5)/(5), not of 1+2+3+4+5, because this simplifies to a single term.
tomorrow's my maths exam
i dont understand
the average of 1, 2, 3, 4 and 5 is (1+2+3+4+5)/5 = 3
isnt that what i said?
not total variables, total terms
..
the sum is at the top and the number of terms is at the bottom
wat
you forgot brackets
avg = (1+2+3+4+5)/5
right?
wat words
this is very ambiguous
wat
so avg = (4+4+4+3+4+4+4+3)/8 right
yes good
dude tell me the words
@high steppe Has your question been resolved?
hey do you have an advise for studying math?
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I'm trying to follow the following proof. How are they getting to it's false that Pr(e | A & ~T) is many times greater than Pr(e | T)?
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@shadow monolith Has your question been resolved?
What’s wrong with this question
!occupied
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i need help with a complicated exercise using derivatives (theres also my attempt to solve it). What the exercise asks for is the minimal value of the function. Which would obviously imply using derivatives and, but i seem to be very far of from any of the multiple choice answers.
if you've got any question about my solution or what im trying to do id be more than glad to try and explain
@dusty heart Has your question been resolved?
I think you did a lot more work than you needed to do.
.
Completing the Square was unnecessary.
You can just square both sides to eliminate the radical.
wdum completing the square?
Hmm, some terminology lost in translation.
english is not my first language so thats why im asking
which i feel like it did kinda make my calculations easier
Squaring both sides gets a better result that can then be simplified through polynomial division.
yup, thats what you would get by just raising them to the 2nd power
u wanna divide those polynomials together?
i mean, its an idea
Yes, and the end result does match up with one of the possible answers.
yup
same problem here
but these are some exercises for the entrance exam at a university so, it cant be that theyre wrong
it says its a)
so 14 sqrt 2
oh wait, did you plug the values u got for x in the function?
cuz thats what it asks for
Yes
oh
Solve for x and you will get two results. Only one of which gives a Real answer that lies inside of the interval you found earlier.
okay let me solve it too
ill see what i get
oh btw, random question, are u a helper that works for this discord server, or are you just a dude who likes math and decided to help
I like to help others to help myself improve my own understanding of math.
And to learn about areas of mathematics that I do not know by observing some of the questions asked here.
I'm good. You should be able to get the answer relatively easy now.
the final polynomial is 28x^2 + 700x + 343=0?
i feel like its nowhere close tho
let me check again
wait, no way, the delta is 672, thats amazing
sorry, i meant sqrt delta
Would Componendo and Dividendo have been a bad idea at the start of the question ._.
whats that?
well,
if a/b = c/d , then
(a-b)/(a+b) = (c-d)/(c+d)
y'all prolly have a different name for it but yeah
i see what u mean
Would that just make it tedius or something as it'd get heavy in the denominator
so, u mean after we got rid of the square root?
or where are u suggesting that we should have done that
yea no prob
Componendo Dividendo could be done in the 3rd step though here
alright so f(x) = sqrt 73 + 8*sqrt2?
this is what i got
but the thing is that theres obvi no choice like that
What two values of x did you get?
nvm i solved it
finally
ill send you a pic
its really messy tho,
here ya go
i got more exercises that are hard btw
if yall interested
these entrance exam exercises are no joke
Feel free to post more questions. Just make sure you start a new channel.
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- PQRS overlap OLMN. Area of PQRS = 30cm^2. Find the shaded region's perimeter.
- Triangle ABD is a right angled triangle, angle ABC = 90. Point D is between line AC.
BD is perpendicular to AC. AD = 1 12/13, DC = 11 1/13, if the triangle's area is 30cm^2, find the length of AB.
@fringe yoke Has your question been resolved?
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im not really sure where i went wrong
context is highschool math, hyperbolic trig is not a substitution technique i have learnt
my handwriting isn't the neatest, so please lmk if there is any part u are finding hard to read
i somehow got 0
(manifesting rishabh to appear 🙏 again)
easiest high school exercises
honestly the educaiton system here lets you choose the level of math u want to do
i did this to myself
i cant even complain anymore
It might be some visibility error but I don't see any negative sign with du
i might havej ust flipped bounds without showing the negative isgn
*sign
where?
line just after u sub
it was cos(pi-u) so it will be -cosu right?
so a negative from this and a negative from du
oh that is a pretty egreious
i just evaporated a negative sign

hold up let me redo this
kk
yeah
dont u get stuck in a loop tho?
of course
A piece of advice,
You could have done the shift from x to -x to get another representation of I with same bounds
you assume this integral to be some I then after by parts you'll get I in some form
after that you can do some algebra to get I
That's much simpler
what do u mean by that
sub u = -x
Then change the dummy variable to x again
Yeah
will keep that in mind
actually would that integral be nicer to crunch here?
since my u sub turns everything to integrating 0 to 2pi
your suggestion still keeps it from -pi to pi which might be nicer
How'd you do the thing on
on?
i split the integrla into 2 parts
and then use symmetry
like integrating f(x) = f(a-x)
squash the 2 together
It has e^(pi - u) + e^(u - pi)
Ohh
I thought it was an algebraic mistake
my bad
nw, i didnt write any justification either so thats a bit arbitrary to follow
wait idk how to do the last line by parts
my brain is cooked
T=T
actually nvm, let me try swapping
e^u-pi/2 can be split in e^u * e^-pi/2
pi/2?
oh
yeah i did that
i think i just need to swap what i let my differentials equals to for by parts
Oh ok
ended up getting -[e^pi - e^(-pi) ]/2
wolfram got decimal approximation rounded to it so i think its right
at least its correct to 4dp
thx for all the help here
🙏
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Im very mathematically challenged and im very stuck on understanding the system of disequalities of this type overall i can't wrap my head around what steps I'm supposed to take or what the rules are since it somtimes brakes already established rules for example "solve whatever is in (...) first" my math teacher said there are no formulas for it and im not sure what the rules are and how im supposed to solve it
Are you referring to inequalities?
seems so
before we speak about a system, do you know how to approach one inequality, generally speaking?
the answer is supposed to involve some sort of system
i almost dont know anything
my mind sort of gets wiped when schools out ecpecially when it comes to math
nope
Let's start with something simple i guess
bacc
it means some sort of random number squared is more than zero
or equal
whats a parabola
so negative numbers don't exist in this case?
negative outputs don't exist*
oh
if you square a real number you always get a non-negative output
for example
(-2)(-2) = 4
coz - x - = +?
yes
this was just an example so you get an intuition what an inequality means
you basically introduce more solutions
instead of asking x² = 0 (which the sol. is x = 0) you now also ask yourself when is x² > 0
which is true for all x unless x = 0
does this make sense?
why js the solution of that 0
you ask why x² = 0 gives x = 0 as solution?
yea
try any other number
to satisfy this equation
you will always get a false statement
you can see also on the graph that x² becomes 0 is x is 0. For all the other values of x it's above the x-axis aka positive
oh
does this make sense?
sorta
well thats bad i guess
😭
say you have two functions
ye
i suppose you kinda have an idea of what that is
maybe im not English and im currently in a country where i dont speak the language fluently so i might or i might not
this is a function
oh then yes
polynomials
exponential functions
logarithms
trigonometric etc
rational functions
x, ln(x), e^x, sin(x), x/(x²-1) etc
such things
say we have two different functions
I call the one f(x) and the other g(x)
ok?
ok
is there hope or did i lose you
keep going we will see
We can do the following
i hope so😭
We can ask ourselves if there is a common point among f(x) and g(x), an intersection for example
for example
,w plot x^2 and x
bacc
We set them equal
we wanna find such x where y is the same in both functions
that's the idea of equations
any questions?
well why do people sometimes
move things around
like one number to the other side
how would that moving work and in what cases
bacc
Question
can you immediately tell me the solution for x
(i dont wanna hear the actual solution)
but my point being
we wanna simplify the equation
until we can get obviously and immediately tell what x is
here you would kinda have to think or even guess
well if 2x-2=0 if somthing beinf like subtracted gives u the answer you can just add jt up to see what your subtracting from?
To answer this:
You can always add,subtract things on both sides.
You can always multiply/divide things (except 0).
These are the very basic rules for solving equations/inequalities
The goal is to isolate x
So maybe you implied this
we could add 2 on both sides
bacc
which gives us what
yes
bacc
we basically "moved" 2 on the other side
hmm
how can we get rid of the 2 multiplied with x on the left?
isnt that impossible
haha no
coz you gotta always do multiplication first?
remember you can divide things on both sides
but what about the rule that says you gotta multiply 😭
oh
pemdas?
this has nothing to do right now
PEMDAS stands for P- Parentheses, E- Exponents, M- Multiplication, D- Division, A- Addition, and S- Subtraction
this is what you mean
order of calculating numbers
forget this here for a second
i thought it was universal
our goal is to isolate x
it is but it has nothing to do right now with our matter
bacc
In order to get rid of the 2 multiplied with x
wait isnt 0 times anything 0
bacc
bacc
this is the solution to the equation
bacc
oh
then staring at this and asking what it could be
instead we work our way there
and we do this by isolating x from everything else
so how do we separate the X?
luckily these rules for equations are also applicable for inequalities, there is just one more thing with inequalities that you need to keep in mind
what are those
.
addition
subtraction
multiplication (except 0)
division (except 0)
there are a few more but we will stay with them for now
ok!
so
ye
before you touch inequalities
you have to get comfortable with equalties
with normal equations
the basic and hard ones
and i see that you are definitely not comfortable
that's an issue you have to accept for now
you should start from scratch
it's literally impossible to explain to you why inequalities and how you calculate with them
and then especially system of inequalities
that's too hardcore
that's just if you were level 1 this would be level 10
how do i get comfortable with equalitys
practice
you master the very basic operations
addition
subtraction
multiplication (except 0)
division (except 0)
you can solve/isolate x fast without second guessing
that's something you have to do
you have to unlock this skill first
ok!
so what you wanna do is this
ye?
alternatively you can think of getting a tutor for yourself
otherwise self study
This pre-algebra video tutorial explains the process of solving two step equations with fractions and variables on both sides. It also explains how to solve 2-step equations with parentheses and decimals. This video contains plenty of examples and practice problems.
Algebra 2 - Basic Introduction:
https://www.youtu...
ty
then the next level
system of equations
you get a good understanding of what a system is now
This algebra video tutorial explains how to solve systems of equations by elimination and how to solve systems of equations by substitution with 2 variables.
Systems of Linear Equations - 2 Variables: https://www.youtube.com/watch?v=oKqtgz2eo-Y
Systems of Equations - Fractions & Decimals:
https://www.youtube.com/watch?v=jlddJQ1qYDU
...
If you watched, practiced and got the hang of this
then you can start with this
This algebra video tutorial provides a basic introduction into how to solve linear inequalities. It explains how to graph the solution using a number line and how to represent the answer in interval notation. It contains linear inequalities with fractions and explains how to solve compound inequalities. it contains many examples and practice ...
then from there it starts to get a bit easier
cause solving inequalities is not that different from normal equations
I recommend taking your time to watch and understand these, in the order i sent. Then to try and apply the knowledge you gained
and during that you can always come here and ask questions
but this, this is too overkill right now
especially if this is your level
i littrally dont even know how to find the percentage of somthing 😭
what do i start with then :(.
This youtube video tutorial on percentages made easy explains how to calculate the percentage of a number mentally using your head without a calculator. This video contains plenty of shortcuts and tricks explaining how to find a percentage of a whole number. it goes over the basics and explains how to check your answer using your calculator. ...
I explained how and which
just follow the order
ok
make a todo list
of what you need to cover
so you get a basic understanding of things
if necesary write down notes
and most of all practice
until you develop an intuition for things
otherwise you will stay there where you are, and you dont want that
the most important thing for you is acceptance and to stay calm
there maybe tons of doubts you have right now
which i cannot cover all up
but it's important to start somewhere with something
concentrate now on this topic
then if you did that
do percentages
ok
thank you
just search and you will find
and if you struggle
you can ask here questions, always
i wish you good luck, and i hope we will see each other again
but when you are more ready
and more prepared
more equipped
ok thank you very much again!
@lucid valley Has your question been resolved?
i mean if i manage to understand later on maybe😭
you will if you put in the work
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so for a reflection
just imagine a line
if polygon a is reflected across that line to show polygon b, then it can be mapped only using reflections
something which uses something other than reflections would be scale factors, which would make a bigger or smaller
in this case something like y=x
np
What about this one
This one kinda confused me
Because I thought I got it right but I guess I got it wrong
@upbeat goblet Has your question been resolved?
@upbeat goblet Has your question been resolved?
at the centre of a regular heaxagon we can see 6 equilateral triangle and taking about angles each angle should be 60 degrees
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let f be a function defined and continuous in R, prove that for every 2 real numbers a, b a real number d exists such that 3f(d) = 2f(a) + f(b)
was this what the question was meant to be lol
(the one u sent in last time)
anyway haven't thought about it fully but hint: ||IVT||
@tropic estuary Has your question been resolved?
ik that
and I did smth kinda
i worked with max and min
it's pretty scuffed
I don't even understand what I did
ah ok
well basically we'll have to do cases which is a bit boring
but here's the general idea:
let's sps a<b and that f(a) < f(b)
then (2f(a) + f(b)) / 3 is somewhere between f(a) and f(b)
so we finish by IVT
oh btw
it's a different one
the other one was meant to be
7f(d)= 2f(a) + 2f(b) + 3 f(c)
ah right
it's not the same approach is it?
i'll have to think abt it but i think the same approach should work?
because we have 3 numbers here so we can't just say a<b and f(a)<f(b) ...
also how do we conclude taht (2f(a)+f(b))/3 is between f(a) and f(b) just from the condition that f(a) < f(b)
bigger than f(a), less than f(b)
think intuitively - the average of a big number and small number is somewhere in-between
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Can someone help me out with these problems? I just need a guide
wich one do you need help with ?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
All four, in terms of the choices the bot has given me im in the middle of one and two
You need to find what axis you should use in order to have a 4th rectangle wich is a reflection of A''B''C''D''
Ohhh I see now
Is it the Y axis?
What rectangle would you reflect with the y axis ?
I don’t know
what triangle is one the left side of your y axis ?
A B C?
Yeah I think I have to find where W”V”X”lies
yes
I believe W’V’X is already rotated right
So if it were to be rotated again would it be the first quadrant?
Or something I think 😭
it is rotating in the direction of the arrow
Oh so the fourth quadrant
yes
do you get the third one ?
if you say that P->P' is a rotation of 90 and P'->P'' is one of 45
try to find P->P''
Would it be something like 180 degrees or 270 degrees?
how did you get to that result ?
Because if to get P->P’ is 45 degrees then P->P” must be 180?
Errr actually
Is it 135?
it is
Awesome sauce
do you understand the last one ?
Hell nah 💀
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Can someone check if this is right
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could someone help me to find out the anwser for that indetermination without l'hopital?
consider the domains of those root functions
I called a=sqrt[4]{2x} and b=1
so I find out after some conclusions 0/4, do you found out that?
I do that, is it right? @acoustic path ?
,rotate
@acoustic path ?
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Yo someone wanna help me figure out how youd get 5d and 15c
did you do all the other parts?
did you do 5c?
exact same question, no
but the same idea applies when doing it
Alr
they're pretty much all evaluating/simplifying
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A group of physics students builds a catapult. They place it on the roof of a school, 18.0 m above the ground and launch a ball toward the east at 24.5 m/s [24° above horizontal]. When the ball hits the ground, how far away from the school will it be?
I am looking for t so I can do vc=dx/t
but none of the equations in the book let me find t
first get the vector components
I got them
but idk how I get time from that?
@craggy rivet Has your question been resolved?
Let's say x is the horizontal axis and z the vertical. To get the time, you only need to figure out how long it takes for z to reach 0.
The general approach to such problems is to start with the equation of motion
$$F=m\ddot{z}$$
Kex
Then figure out what forces are involved
I never got such an equation in my text book
$\ddot{z}$ is the z component of the acceleration vector
Kex
m is the mass of the object and F is the total force that is acting on it
yeah never see that before, this is confusing me
Kex
Still who the heck would introduce such problems without teaching Newton's equation of motion first :/
What does z mean?
can i take pictures of the equations I have access to?
Just a distance. Probably the textbook has x or d or whatever
Sure, would help to get an idea what your background is
I live in Canada
@uneven bear
There it is 😄
Mine is just more general with the initial position/distance included
$$d=\frac{1}{2}at^2+v_0t+d_0$$
Kex
So again, we are just looking at the vertical component
$d_0$ is the initial height, $v_0$ is the z component of the initial velocity and $a$ will be $-g$ from gravity
Kex
And we want the time it takes for d to become 0, so you have to solve this quadratic equation to get t.
how do I get t though because there are 2
One solution is negative, so not physical meaningful
im falling asleep a bit, how do you know that, and which solution?
midnight formula is your friend
You should see examples of that question the concept behind it on yt or smth
As you don't know anything about the laws of motion
Those get introduced later
I agree with FlexO though. You can't really appreciate the solutions to these problems without understanding the laws of motion, so have a look already and it might give you an edge 😉
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There is a math test with 30 questions, where 3 students and 1 teacher is doing it. If each of the students can do atleast 3 questions, and the teacher can do no more than 15, how many ways can the 4 people complete the test?
ive never seen these types of questions before
can do atleast 3 questions
does that mean must do at least 3?
it doesn't read like that but why would it be there if it really just meant 'can' 
oh in the original question (i translated it) they used can so i dont really know
ok probably must do at least 3 then
alright
hm well i have a way of doing it but i don't think you'll like it
what is it?
I was thinking about stars and bars but the >= 0 version
the constraints are kinda annoying for a stars and bars approach
ive never heard of that what is it
we can get rid of teacher condition and then subtract amount of ways where teacher > 15
so you might not know by name
generating functions
i think i have the answer
(i will not say yet)
but do you know how many ways can we choose x1,...,xk such that x1+...+xk = n
(x1,...,xk are non negative integers)
wait does complete the test mean just assign a number of questions to each person
no😭
or does which questions each person does matter
oh yeah this is important
this seems kinda hard
it wasnt specified
i think this was like comp math from a month ago but ive found nobody doing it online

let us be in this configuration xdd
LOL yea i agree
you could just assign the 3 students 3 questions each, and then take cases on assigning the teacher 0 through 15 questions
then you just need to compute like compute 16 binomial coefficients
by stars and bars
they have to do a total of 30 questions
I only needed to compute 2 but
ohhhhh
yea that's so much better
alright so here's to you, formula that might be helpful
the number of ways to choose $x_1,...,x_k$ non-negative integers such that $x_1+...+x_k = n$
rafilou2003
is $\binom{n+k-1}{k-1}$
rafilou2003
oh
had you seen this before?
no sorry
no worries
the visual proof that I use for this
you imagine that you have n stars to distribute between k bags
those bags are in a line, and there's bars between them to separate them
so after placing the stars, from left to right you will have a total of "n+k-1 objects"
the objects regrouping the stars and the bars
(n stars, k-1 bars)
ohh
and to choose how many stars goes in each bag
all you have to do is choose where in that sequence you place the bars
makes sense
thus this value
so now to apply the formula
you can write for example s_1, s_2, s_3 and t the number of questions each person takes
so then you would be solving $s_1 + s_2 + s_3 + t = 30$
rafilou2003
problem being, those can't be any non-negative integers
because each student must take at least 3 questions
yeah?
so, instead of looking at the number of question each student takes
we're gonna look at the number of questions each student takes, minus 3
call these numbers x1,x2,x3
oh dang i was about to ask if that would work😭
and we get $x_1 + x_2 + x_3 + t = 21$
rafilou2003
so, if there were no restrictions on t, how many choices do we have?
24?
oh
how many bags do we have?
4
and how many stars do we have to place in total?
24C3?
yeah that's it!
oh nice
crazy
ok so
unfortunately
there's not that many choices
because we overcounted the outcomes where the teacher had too many questions
for which values of t does that happen?
16 to 30
if everyone here is non negative, the max value of t would be
yes
what does matter is that we gotta get rid of the outcomes where t >= 16
would we subtract 16 then?
we subtract 16 to what?
from t
hooray
x_1 + x_2 + x_3 + x_4 <= 5? im not sure
almost
this is always gonna be true
so if you subtract 16 from both sides
not sure there's an "inferior or equal to"
o
$x_1 + x_2 + x_3 + x_4 = 5$
rafilou2003
alright