#help-39

1 messages · Page 141 of 1

tranquil badger
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▬▬▬

slender viper
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  1. For a given ring $R$, construct the polynomial ring $R[x]$, where the elements are \textbf{formal} sums $\sum_{i=0}^na_nx^n$. Quadratics are elements in the polynomial ring. Given a map $R\to S$ of rings, the evaluation map $\operatorname{ev}_s:R[x]\to S$ is the map induced by $R\to S$ and $x\mapsto s\in S$

  2. I don't think you need to find zeros to plot the parabola. You can always evaluate for $y$ at given points $x$ and then plot those points.

tranquil badger
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uhhhh is that discreet math?

jolly parrotBOT
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Element118

tranquil badger
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calculus?

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which is this?

slender viper
tranquil badger
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o H

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alright

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thank you for explaining that.

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Still, this describes my understanding of it, and I don't think that that is necessarily important to it.

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The main question, again, was regarding how this was equivalent due to how they were graphing the parabola which is from the behavior of the quadratic of course.

slender viper
jolly parrotBOT
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Element118

slender viper
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The other possibility is that they are trying to find roots

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which they are trying to show the "complete the square method"

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but getting rid of the c/a term so that it is easier to present the next step

tranquil badger
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https://www.youtube.com/watch?v=UTuxHsaH-gQ&list=PLybg94GvOJ9FoGQeUMFZ4SWZsr30jlUYK&index=37 (this explains what theyre doing)

1. Well, clearly, by subtracting c/a which logically is apart of the behavior of the problem and thus removing it would make the behavior when graphed different to the original quadratic they wanted to graph the behavior of

so this leaves me with two possibilities that they rather are removing it and it somehow isnt that important what the quadratics components are or that they somehow arent and its still somehoe equivalent to the original.

2. what is the difference between scaling and shifting vertically? Do you mean multiplication vs adding?

3. My very first question was the what values correlate to X or Y and which values get what.```

You remember this one, don't you? Opposite of b, plus or minus... what was it? Well instead of just telling you, why don't we derive the formula? As it turns out, it's like completing the square, but with variables. Will you just watch this already? I can't explain it without the pictures.

Watch the whole Mathematics playlist: http://bit.ly/Pro...

▶ Play video
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slender viper
# tranquil badger https://www.youtube.com/watch?v=UTuxHsaH-gQ&list=PLybg94GvOJ9FoGQeUMFZ4SWZsr30jl...
  1. The motivation of subtracting $\frac{c}{a}$ from both sides is to clean up the left-hand side to get $x^2+\frac{bx}{a}$. I think introducing graphs into this might complicate things. Doing the same reversible operation to both sides leaves you with an equivalent equation to the original.

  2. That seems to be implied by trying to plot it out on a graph.

  3. When solving $f(x)=0$, there's no $y$ to be concerned about. The point appears to be that doing a reversible operation preserves what $x$ satisfies the equation.

jolly parrotBOT
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Element118

tranquil badger
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so is it not equal but because you can undo it it makes it equal?

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and how does one go about undoing it?

slender viper
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In general "doing the same thing to both sides" preserves equality.

tranquil badger
slender viper
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if a = b, then f(a) = f(b). Being able to undo it, by adding back c/a to both sides, ensures that the final equation doesn't lose information the original equation had.

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Say $a=b$ and we square it, we get $a^2=b^2$. But the solutions to this final equation are $a=\pm b$, which is different from the original equation. That's because squaring cannot be reversed.

jolly parrotBOT
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Element118

tranquil badger
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only this half is?

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and that part is perserved for the formula

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and then c/a is added back after

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?

slender viper
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Doing a reversible operation on an equation preserves the set of solutions. Doing an irreversible operation on an equation may increase the set of solutions.

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"Subtracting c/a" can be reversed by "adding c/a"

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"dividing by a" can be reversed by "multiplying by a" (assuming a is not 0)

tranquil badger
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Does that imply that I was correct?

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it is unequal until reversed? (removing c/a is unequal until reversed after operations are complete)

slender viper
tranquil badger
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im saying that by removing c/a which is a component of the problem and its behavior

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it isnt equal to the original equation until you reverse it and add c/a back

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but while its gone

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you gain access to certain forms

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allowing access to quadratic formula etc

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is this true?

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if not explain

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because throughout this entire time the idea of it being unequal hasnt been touched because you havent actually said anything on the matter (difference between fact stating and technical resolving)

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no matter how much you say something is or is not true or if something equates to something

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if my fundamental concept is off by even a little bit i will interpret the same information you gave differently

slender viper
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Firstly these two equations are equivalent

$x^2+\frac{bx}{a}+\frac{c}{a}=0$

$x^2+\frac{bx}{a}=-\frac{c}{a}$

We can get from the top to the bottom by subtracting $\frac{c}{a}$ from both sides and bottom to top by adding $\frac{c}{a}$ to both sides.

jolly parrotBOT
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Element118

slender viper
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equivalent, meaning

"(a, b, c, x) makes the top equation true if and only if this (a, b, c, x) makes the bottom equation true"

tranquil badger
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define top and bottem

slender viper
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top equation: $x^2+\frac{bx}{a}+\frac{c}{a}=0$

bottom equation: $x^2+\frac{bx}{a}=-\frac{c}{a}$

in this case

jolly parrotBOT
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Element118

slender viper
tranquil badger
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the last way i can interpret this

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is that

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they are unequal but also not

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in that the definition of equality was wrong

slender viper
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what do you mean by "equal"

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for this case

tranquil badger
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i always meant it in that the problems essential structure

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would be unchanged

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in that if you removed fundamental pieces of the problem

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it would have to be incorrect.

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because you lost the original data and behavior the zeroes described

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but

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what i get from that

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is that

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your idea of equal is completely different

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in that

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any formation of the same data even if subtracted to form a different result that isnt the zeroes

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so long as it utilizes the same set of numbers

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is still equal in the sense it is another expression of the same data

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in that the subtraction to remove itself WAS the expression of that component

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rather than that component not existing

slender viper
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it doesn't fundamentally lose any piece of the problem because the set of solutions remain the same

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that's what we care about when we are trying to solve for x

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the "if and only if" is doing a lot of the lifting here

tranquil badger
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alright

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i cannot continue

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it is 3:09

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am

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ive been at this for hours and i cannot understand what you mean by alot of that.

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also, no offense but, is english not your first language?

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oh well

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.close

pearl pondBOT
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pearl pondBOT
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sharp smelt
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This basically means that the cardinality of the set is non- finite , right

rustic gate
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that's not all there is

sharp smelt
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I know

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but that's the part I'm concerned about

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It basically means A is an element of the set containing the elements of the powerset of P(\N)

rustic gate
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being not finite is not sufficient to be an element of that set

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{2, 4, 6, ...} is not contained in that set

sharp smelt
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I know

rustic gate
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so it does not "basically mean that the cardinality of the set is non-finite"

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that is not an equivalent description

sharp smelt
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As I said, that was the part that confused me

rustic gate
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what are you confused by? you haven't specified

sharp smelt
rustic gate
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it means the cardinality of the complement of X is finite presumably

jolly parrotBOT
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Veni, vidi, perii

sharp smelt
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thanks

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.clsoe

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.close

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mild reef
#

A travel company organizes a tour with a price of 500 $ per customer for 30 customers. Starting from the 31st customer, for each additional customer, the price of the tour decreases by 𝑎 $
(where a is a positive integer). The number of additional customers cannot exceed 15. It is known that if the number of additional customers ranges from 1 to 8, the total revenue increases as the number of customers increases. Find the maximum value of a. I need help with this problem

pearl pondBOT
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low crystal
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Is 1/lnx considered continuous function?

pearl pondBOT
low crystal
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It's obiviously not continuous when you have x<1 but do we call it non-continuous just because it's not between specific range

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what do you need to have to say a function is not continuous

worthy lance
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The function is continuous wherever is defined except at x=1

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From (0,1) and (1, inf)

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And is discontinuous at x=1 cause it is undefined

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Because of division by 0

worthy lance
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Where else?

low crystal
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is it not undefined ln(-5)

worthy lance
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When x<0 is not defined

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Ln over reals is only defined when x>0

low crystal
worthy lance
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Check the function

low crystal
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Like it's not defined 0<x at the first pplace

worthy lance
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,w plot lnx

worthy lance
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Second one

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At x=1 there is a discontinuity

low crystal
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yeah

worthy lance
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Because 1/0 is undefined

low crystal
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so when we call a function continuous?

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Is it when there is only one undefined point or something like that

worthy lance
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And at x<0 the function is also undefined because ln(neg) is undefined

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We can say it is continuous in two (idk the word in english) parts

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(0, 1)

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And (1, inf)

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And there is a discontinuity at x=1

low crystal
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does that mean there is no general referring like "f(x) is continuous but g(x) is not"

worthy lance
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But the function is not continuous over the whole spectre

worthy lance
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Can u say with an example?

low crystal
worthy lance
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You can say f(x) = x is continuous

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There is no undefined point in this function

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But in 1/lnx you cant say that

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Cause there are 1 point and 1 side undefined

low crystal
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So you're basically saying "to say if a function is continuous or not we need to include where we're talking about"

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no?

worthy lance
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Yes

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You specify what are you talking about

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That will make clear the context better

low crystal
# worthy lance Yes

okay get it. So is it correct to say that 1/lnx is continuous at 1<x while It's not at 0 and x<0 ?

worthy lance
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I see redundancy

low crystal
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saying it's discontinuous at 1 might be wrong

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because its only one point

worthy lance
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You put the intervals

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(0, 1) U (1, inf)

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Has a discontinuity at x=1

low crystal
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okay

worthy lance
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And is undefined for x<0

low crystal
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because I thought that we can still say it's discontinuous at x<0?

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but you just said "undefined"

worthy lance
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When a function is not defined at certain points like for x < 0, we do not consider those as points of discontinuity, the concept of discontinuity applies to points within the domain of the function where the function’s behavior breaks down.

low crystal
worthy lance
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Yes, definitions are the first thing to check

low crystal
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because I was thinking like when you try to go back from point 0, you are not allowed which must mean It's discontinuous

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.cllose

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.close

pearl pondBOT
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livid bolt
pearl pondBOT
livid bolt
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integer that is positive and odd?

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how would i find part B

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every number is divisible by 8?

livid osprey
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yep

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for (c) just take m to be some positive odd integer 2k+1, and show that the result is still divisable by p

livid bolt
#

.close

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hollow parcel
pearl pondBOT
hollow parcel
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guys i see in notes someone rewrite this as this

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howcome is this so?

light helm
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double angle identity
is a special case of the compound angle identity
which can be derived from clever construction of similar triangles

hollow parcel
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😮

hollow parcel
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damn they expect me to remember this while doing integrals

light helm
#

trig should've been a pre-requisite for calculus

livid osprey
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if u need a easy way to derive it on the spot u can use the addition formula

hollow parcel
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yes but

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in college not so much trig

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economics college

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so it very much in the dark

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wooden merlin
#

Use Moivre's formula to express $cos4\theta$ and $sin4\theta$ by $sin\theta$ and $cos\theta$

jolly parrotBOT
wooden merlin
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For $cos4\theta$, I got $2cos^2\theta-1$

jolly parrotBOT
wooden merlin
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For $sin4\theta$, I got $$(1-sin^2\theta)(4cos\theta sin\theta +2sin^2\theta)+4cos\theta sin^3\theta$$

jolly parrotBOT
wooden merlin
#

Is there any way to keep factorize? Or is this enough?

pearl pondBOT
#

@wooden merlin Has your question been resolved?

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deep bane
pearl pondBOT
deep bane
#

hi how do i go about solving these? any hint or a particular method

crisp ravine
desert nebula
pearl pondBOT
#

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arctic carbon
#

The bearing of point B from point C is $254^\circ$. The bearing of point A from point C is $344^\circ$ The bearing of point A from point B is $32^\circ$ If the distance from A to C is 780 miles, find the distance from A to B to the nearest meter.

jolly parrotBOT
#

snooze

arctic carbon
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I need some help visualizing and drawing this out

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dark sparrow
#

I have been staring at this question for the longest time and I Dont really know how to even begin. this is about probability going from a point to a point.

dark sparrow
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$P(E_{1})=\frac{2}{5}$, $P(E_{2})=\frac{3}{4}$, $P(E_{3})=\frac{2}{3}$, $P(E_{3}\mid E_{2})=\frac{4}{5}$, $P(E_{1}\mid E_{2}\cap E_{3})=\frac{1}{2}$.

jolly parrotBOT
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Totalani

dark sparrow
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First question asks what is the probability someone can go from A to B if he has to pass C ?

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nevermind got the first question, very simple

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Second question askes the prob from A to B

pearl pondBOT
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@dark sparrow Has your question been resolved?

dark sparrow
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Any help with this?

plush bramble
dark sparrow
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Does not say, it just says the probability from A to B

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I read that as directly, since last question was about passing C

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Going from A to B passing C was 0.6

plush bramble
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Why is it not just P(E1) then

dark sparrow
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I dont know, thats not what says in the asnwer, it says its 0.7 but im not sure how its getting it

plush bramble
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show the exact question

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screenshot or picture is best

dark sparrow
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Its in swedish tho

plush bramble
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did you read the first two sentences

dark sparrow
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yes

plush bramble
dark sparrow
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the first 2 sentences doesnt matter. it says "in this particular day this and this are the probabilities.." and it gives you the probabilities for that day.

plush bramble
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What does it say about A and B in the second sentence

dark sparrow
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It says you cant always travel between A and B during winter, but it does not say you cant travel between A and B during this particular day, its even giving you the probability no?

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lets assume you cant go directly from A to B then

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so you have to pass C

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That was already the question for a)

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I just want to know how it got to 0.7

plush bramble
dark sparrow
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No you asked why it wasnt just P(E1)

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and im saying it cant be because P(E1) is 2/5 but the answer is suppose to be 0.7

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any help with this?

dark sparrow
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.close

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violet wing
#

Let A be the set of real numbers R. Express the following proposition
with a simple sentence.
∀ x ∈ A ∃ y ∈ A [(x < y) ∧ (∀ z ∈ A (x < z) ⇒ (y ≤ z))]
Is this proposition TRUE ? If not, is there a set A for which it is TRUE ?
Justify your answer

violet wing
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so basically, x<y and z<=z

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so no, it is not true, BUT can I also say there is no set A for whicb it is true?

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because, for example, integers would be a set such as {1,2,3...}

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and so it cannot work because x > y if x = 3 and y = 1

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but i don't fully understand sets, so i'd like to know if i'm thinking on the right track

sharp vigil
#

you need to review the qualifiers:
"for all x in A, there exists y in A..."

violet wing
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for all x in A, there exists a y in A scuch that x< y AND for all z in A, if x< z, y <= z

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i'm just confsed by the set part

cinder flower
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this question has a super simple answer but i don't know how to allude to it without giving it away

violet wing
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is it like

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am i being dumb

cinder flower
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i'm not saying coming up with it is simple, just that the (or one) answer is simple

violet wing
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the sets of integers are ordered, right?

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the issue is i haven't delved into sets at all so i don't understand if they're ordered

cinder flower
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A is a subset of the real numbers

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so it has an order inherited from there already

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but sets are not manifestly ordered in general, no

violet wing
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but the requirements for this set is to be ordered

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so does that mean no set exists as the sets aren't ordered?

cinder flower
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the order used in the question is real number order

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the elements of A are real numbers

violet wing
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i'm very confused

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is there a way you can explain it differently?

sharp vigil
violet wing
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if y>x then it satisfies it, so 4 would work

sharp vigil
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what about the second half of the statement?

violet wing
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which statement

sharp vigil
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the part about z. is it true that any z larger than x has to be at least as big as y?

violet wing
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yes, it's true

sharp vigil
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which number system is it true in?

violet wing
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the set of real numbers R (which is A)?

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wait because it's just saying like

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every number has a number greater than it, which has a number greater than it

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but is infinity included in R?

sharp vigil
violet wing
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then it wouldn't work

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WAITWAITWAIT

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so like

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as long as they're discrete intervals

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like 1,2,3

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beacuse x<z and y<=z and

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so if x=1 and y=2

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z has to be 2 or higher

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so it couldn't be the real numbers?

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any subset of R then?

sharp vigil
violet wing
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just like integers, whole numbers, and natural numbers

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i don't know much about sets

sharp vigil
violet wing
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well in some cases. if youve got {-1,0,1} and x=-1 while y=0 it would work

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but couldn't x=1 and y=-1, if either can represent any number of the set?

sharp vigil
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so the "for all" means that we have to make it work for every x in the set. but the "there exists" means that at least 1 y in the set satisfies the condition. so we don't get a choice of x, but given an x, we get to pick a y (if we can), to make it work

violet wing
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OH

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I SEE WHAT YOU MEAN

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so as long as a y exists that will be greater than x, it will work

sharp vigil
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yes, but we also need a guarantee that if z is larger than x, then it is at least as big as y. since we don't get to pick z, we need to make sure there can't be any numbers between x and y

violet wing
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and that's why it can't be a real number because it could be a fraction

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i'm confused on z still

sharp vigil
#

well let's say that x = 3, then we could choose y = 3.5. but then we still have the issue of z = 3.25, so it doesn't work

#

the problem we run into is that we can always find a z that is somewhere between x and y

violet wing
#

do you mean when x = 3?

sharp vigil
#

yes x = 3, sorry

sharp vigil
violet wing
#

doesn't it work with integers since there isn't any "gaps"?

#

wait

#

no

#

wait

#

yeah

sharp vigil
#

with the integers we can have a "next integer" which we can't have on the real numbers

violet wing
#

OH BECAUSE

#

x<y holds true in any sense

#

and if y<=z, z cannot be less then x, thus x<z

sharp vigil
#

well the implication is the other way around. we want it to be true that 'if x < z, then y <= z'. in other words, any number bigger than x must be at least y, in other words, we can pick y which is the "next number after" x and there aren't any numbers between them

violet wing
#

so for example

#

x=1, and z=2

#

if 1<z y<=z

#

so y is 2

#

okay

#

i get it

#

so it does work with integers because y comes directly after x, and no numbers are between them where z=>y

pearl pondBOT
#

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hasty galleon
#

why is sin the answer shown here and not 5/sqrt61 ?

barren quarry
#

because u can’t have a radical at the bottom

hasty galleon
#

this is new to me

barren quarry
#

so u find the hypotenuse using pythagorean theorem

hasty galleon
#

ah i see, its 5/sqrt61 but multiplied by sqrt61 so the square root is moved up top

#

right?

barren quarry
#

yup

hasty galleon
#

thank you goat 🙏

barren quarry
#

and when u multiply the bottom the square root goes away

#

yurr

pearl pondBOT
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#

@velvet wolf Has your question been resolved?

pearl pondBOT
#

@velvet wolf Has your question been resolved?

velvet wolf
#

any <@&286206848099549185>

pearl pondBOT
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@velvet wolf Has your question been resolved?

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onyx moat
pearl pondBOT
onyx moat
#

My working so far is that there is 7C3 ways to incorrecty guess the other 7 songs, and 3C0 ways to incorrectly guess the 3 band songs, and 10C3 ways to choose 3 songs from the 10, so my answer is 7C3*3C0/10C3 = 7/24. is this right?

pearl pondBOT
#

@onyx moat Has your question been resolved?

onyx moat
#

<@&286206848099549185>

vestal tapir
#

this makes no sense

#

oh ok

#

so like they know all songs, but not the order, one of 10! guesses

#

yeah 7c3/10c3 makes sense

#

no not right

#

they have to guess the exact song, this only "allows" them to guess the band

#

you gotta do inclusion exclusion

#

guess first song right: 9!
guess first two songs right: 8!
guess all songs right: 7!
3(9!) − 3(8!) + 7!

pearl pondBOT
#

@onyx moat Has your question been resolved?

onyx moat
#

Wait so what would the probability work out to

vestal tapir
#

,calc 1 - (3(9!) - 3(8!) + 7!)/10!

jolly parrotBOT
#

Result:

0.73194444444444
vestal tapir
#

527/720

#

,calc 1 - (3(1/10) - 3(1/10)(1/9) + (1/10)(1/9)(1/8))

jolly parrotBOT
#

Result:

0.73194444444444
onyx moat
#

Could u elaborate a little bit on the inclusion exclusion

#

I understand them individually but not all together

#

Oh nvm I just saw the 1 - lol

#

I think I get it now

vestal tapir
#

yeah we find union of outcomes where something was guessed right

onyx moat
#

I see

#

Is this just a counting problem? or can we apply a probability distribution somewhere bc that’s kind of the theme of worksheet

vestal tapir
#

i don't know

#

well

#

maybe the idea is you just always have 1/10 chance, instead of choosing a permutation

#

then it's just binomial

#

a differetn answer, but it maybe makes sense too

#

no they said "only once"

#

so it's clearly about permutation

onyx moat
#

I was thinking maybe hypergeometric fit in somehow but I’m not sure

vestal tapir
#

it would make sense if it was about identifying the band, so the same thing you said first

#

so it's possible, just wrong wording

onyx moat
#

Thanks for the help

#

.close

pearl pondBOT
#
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outer hare
#

Is the rate of convergance for a taylor series always the highest polinomial you use?

outer hare
#

Basing it from this:

#

Ok here is a better question, why is the remainter therum located where it is:

#

should it not be + error, why is it being multiplied into the last portion?

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#

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upbeat ocean
#

Need help with calculus

pearl pondBOT
verbal whale
#

Be more specific, or just ask directly the exercise/doubt on the theory

upbeat ocean
#

I want to ask about

#

The integration with numbers formula

#

Oh wait

#

Wth am I doing

#

Sry sry

#

.close

pearl pondBOT
#
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mental aspen
#

Hi guys I am having trouble on what type of angle this is: co interior, corresponding, alternate

#

@eveyone

#

<@&286206848099549185>

midnight haven
#

@mental aspen with what angle

mental aspen
#

Like identifying what angle it is

midnight haven
#

X is corresponding to 105

#

Y is alternate to 65

verbal whale
midnight haven
#

oh

#

ok

mental aspen
#

Ok thank you.

midnight haven
#

i use that to identify

mental aspen
#

ok thanks for the tip

pearl pondBOT
#
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livid bolt
#

how does doing this prove that its irrational

pearl pondBOT
livid bolt
#

what if i put root 4 and did the same process

cosmic charm
livid bolt
cosmic charm
#

but in the end you end up with p and q having a common factor of 2

livid bolt
#

how does this show that p is divisible by 2

cosmic charm
#

p² is an even number since its 2 times some integer

cosmic charm
#

and if p² is even, then p has to be even

livid bolt
#

OH

#

p^2 = 2q^2

#

oh

cosmic charm
livid bolt
#

what if it was another number

#

like sqrt(8)

#

no sqrt(3)

cosmic charm
livid bolt
#

nooo 😭

#

my test is tmr

#

and its on complex numbers proof of contradiction and induction

#

im cooked

livid bolt
#

do u wanna see what i got for my chem test

wild fable
#

hi

#

um

#

ok

livid bolt
wild fable
#

6/26

livid bolt
#

..

wild fable
#

u got a 6/26

#

thaats very impressive

livid bolt
#

hey i got this before though..

wild fable
#

btw

#

hsc in 33 days

livid bolt
#

hsc is too easy

livid bolt
#

im doing a titration 🫨

livid bolt
#

cap

#

dw you'll do fine

#

u cant do as bad as me

#

i cant believe

#

i finished unit 1 and 2 of specialist and i havent dropped it 😭

#

im so proud of my self 😭

wild fable
#

drop it!!!!!!!

#

go do normal maths stop doing accelerated!!

livid bolt
#

😭

#

if i finish it early

#

in year 12 i can just cruise through

wild fable
#

ur not gonna cruise thru

#

ur not gonna be a nonchalant dread head

livid bolt
#

yes i am

#

ima finish specialist and methods early

#

and have sm time to study for others

wild fable
#

are u good at english

livid bolt
#

im ok at it

#

im on like a 65 average

wild fable
#

people who are good at math arent very good at english

#

its like a common pattern

cosmic charm
livid bolt
#

i can do mid in it

#

i cant do like

#

very well in it

#

bc i have never finished a book in my life 😭

#

only the in class ones where the teachers read it to u

livid bolt
#

just in case its in my test..

pearl pondBOT
#

@livid bolt Has your question been resolved?

pearl pondBOT
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stoic imp
pearl pondBOT
midnight haven
#

multiply and divide by (6x)square

#

then cx-1/x2 and lnx+1 expansion

#

put limits

warped rapids
stoic imp
#

(6x) square is 36x^2

midnight haven
#

like whats lim cosx-1 whole /x2

#

its 1/2

#

use that logig

pearl pondBOT
#

@stoic imp Has your question been resolved?

stoic imp
#

.close

pearl pondBOT
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rose sentinel
#

33 don’t know how to start, I’m thinking something with conjugates and u sub but I can’t get it to work

slim moss
#

what did you use as the u sub

frozen lantern
#

I'm sure there's an identity somewhere.... 👀

#

so yes what did you try for the sub

rose sentinel
#

Neither seemed to work and no other one seemed relevant

frozen lantern
#

oh no

#

yeah it won't

#

it's a trig sub

#

think of all the trig identities which look similar

rose sentinel
#

Not meant to be

frozen lantern
#

....well it's a trig sub so

#

maybe your instructor goofed.

rose sentinel
#

Well it very well might but but there must be a non trig sub method

#

It’s not my instructor it’s a book

#

Trig sub is another 30 pages from here

frozen lantern
#

Ah

#

hm

compact ridge
frozen lantern
#

lemme see if i can think of non trig stuff

worthy lance
#

You can use u sub = the whole thing

compact ridge
slim moss
#

thats what i was thinking of ngl

frozen lantern
compact ridge
#

not really

rotund creek
#

i like that method

worthy lance
compact ridge
#

oh they mean u = 1 - x^2 lol

worthy lance
#

There is no one single way of doing things

rose sentinel
#

Uhmm

frozen lantern
rose sentinel
#

I’m lost

frozen lantern
#

i just dont see it ig

frozen lantern
worthy lance
frozen lantern
compact ridge
#

if you sub u = the whole thing you have to do a partial fraction decomposition

rose sentinel
#

I don’t know that stuff

frozen lantern
#

i honestly think the cleanest is the trig sub here lmao

worthy lance
#

Well, what do you know?

frozen lantern
#

if you know trig i'd recommend trying it just for the lols anyway

frozen lantern
rose sentinel
#

uhm like everything integration by parts and earlier

#

Wait what’s du/dx then I can’t do it rn I’m walking to clsss

#

When you say whole thing you mean everything within the radical or radical included?

worthy lance
#

Yes

#

You can also so without the radical

rose sentinel
#

The latter?

worthy lance
#

It doesnt matter

rose sentinel
#

What’s du/dx then

worthy lance
#

Just whatever u can do

#

In which case

rose sentinel
#

Either

worthy lance
#

Well you are the one who has to work out on that

rose sentinel
#

I’m typing on my phone on a sidewalk 😭

worthy lance
#

Do not try this exercise if you are not in a chair and table

rose sentinel
#

Is it (1)(1-y)+(1+y)(-1)

1-y-1-y
-2y

#

Then what

worthy lance
#

What is that?

rose sentinel
#

du/dx?

#

thin

#

I think

#

Wait I see how to do it

#

Conjugate and then just make two fractions

#

Right?

rotund creek
#

yes

rose sentinel
#

Wrote with finger on monitor 😎

#

Okay I got it right thanks

#

.close

pearl pondBOT
#
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pearl pondBOT
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grand idol
#

how do i do this proof

pearl pondBOT
simple elbow
#

Find the values of the constant c for which the line y= x+c is a tangent to the curve y = 3x + 2/x

frozen lantern
#

What lmao

simple elbow
#

uhhh how do I solve this

frozen lantern
#

first you get a separate channel

simple elbow
#

?

#

I dont get it

pearl pondBOT
latent quail
simple elbow
#

感谢啦

simple elbow
#

还有我的繁体挺差的 xs

grand idol
#

then c=-x

simple elbow
latent quail
simple elbow
simple elbow
#

Sorry my bad gang im too stupid to understand

grand idol
#

hmm

simple elbow
#

Heehee

grand idol
#

wait

#

mb

#

i gave the wrong ans

simple elbow
#

Oh

#

The answer is 4,-4

#

But idk how to get

grand idol
#

yuh

#

so

#

do uk derivatives

simple elbow
#

UK derivatives?

#

Uh

grand idol
#

you know derivatives?

simple elbow
#

🤷🤷

grand idol
#

like dy/dx and shi

simple elbow
#

Nah we don't write that lol

grand idol
#

oh

simple elbow
#

But feel free to explain

#

I'm listening/ reading

grand idol
#

hmm then idk how to teach ya this

#

do you know calculus

#

ig not

simple elbow
#

Nah

#

Just in 10th grade rip

grand idol
#

ohh

simple elbow
#

B squared -4ac =0

grand idol
#

ok

#

so

simple elbow
#

3x + 2/x=0

grand idol
#

we know that for a line to be tangent to a curve the y value shud be equal

#

so equate em

simple elbow
#

Yes

grand idol
#

so x+c=3x+2/x

simple elbow
#

yeah

#

3x - x + 2/3

#

2/x mb

#

=c

grand idol
#

that gives $x^2+(c-3)x-2=0$

simple elbow
#

huh wait let me digest rq

grand idol
jolly parrotBOT
simple elbow
#

oh

grand idol
#

get it?

simple elbow
#

why c-3

grand idol
#

i cross multiplied

#

and took x as the common term

simple elbow
#

to get rid the fraction?

grand idol
#

oh wait

#

$2x^2-cx+2=0$

jolly parrotBOT
grand idol
#

it gives this

grand idol
simple elbow
#

alr

grand idol
#

then compare with ax^2+bx+c=0

#

then do $b^2-4ac=0$

#

you will get 2 values for c

jolly parrotBOT
simple elbow
#

i got the answer tysm

#

its actually so simple lollll

#

my dumbass just dont get it but i got it now tysm

grand idol
#

lol its aight

simple elbow
#

tysm

#

also what does The line y = 2x + k is a tangent to the curve x^2 + 2xy + 20

#

mean

#

exactly

grand idol
simple elbow
#

ooh i got the answers already and also

#

theres a b) for it

#

its uh for each of these values of k, find the coordinates of the point of contact of the tangent with the curve

#

k = 10 or =10

#

10 or -10

pearl pondBOT
#

@grand idol Has your question been resolved?

pearl pondBOT
#

@grand idol Has your question been resolved?

pearl pondBOT
#

@grand idol Has your question been resolved?

pearl pondBOT
#
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cedar perch
#

I mean I know it's true because i did a weird repeated integration by parts method to get a form of the integral of the bell curve (too lazy to explain it, it was a pain in the ass 😭 )

#

but is there like.. a way it telescopes?

#

Also the L is just supposed to be a standin for the limit as the variable goes to infinity

#

(desmos doesn't have limit notation.. i think)

#

$lim_{L \to \infty} \sum_{n=0}^{L} \frac{(2n+1)x^{2n} - x^{2n+2}}{\prod_{k=0}^{n} (2k+1)} = 1$

jolly parrotBOT
#

Serphic

cedar perch
#

there we go okay

pearl pondBOT
#
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cedar perch
#

uhhh

#

i forgot about that

#

mb

pearl pondBOT
#
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latent crescent
#

help

pearl pondBOT
#

Please don't occupy multiple help channels.

latent crescent
#

how is this

#

how do i solve

#

il so lost

#

im

#

@thin bane

thin bane
#

what are you trying to find

#

x?

finite pagoda
#

youre almost done, just remove absolute value sign, and solve both equations as normal

latent crescent
#

x

#

@finite pagoda

#

can u help me solve

#

@thin bane

#

@plush bramble

#

<@&286206848099549185>

#

@real tiger

plush bramble
#

and in general

latent crescent
#

bro i need help

plush bramble
#

!noping

pearl pondBOT
#

Please do not ping individual helpers unprompted.

finite pagoda
simple jasper
#

is that $| 3 - \frac{1}{3}x| - \frac{7}{4} = \frac{1}{2}$?

jolly parrotBOT
#

dragonbreath

latent crescent
#

yes

#

@simple jasper

chilly sand
latent crescent
#

ok

chilly sand
#

2 minutes pls

simple jasper
# latent crescent

In your second line where you have the two functions equal to 9/4 and -9/4, drop the absolute values and solve accordingly

finite pagoda
#

do the same with other equation

simple jasper
#

For example $|x - 3| = 4$ is equivalent to $x - 3 = 4$ and $x - 3 = -4$

jolly parrotBOT
#

dragonbreath

latent crescent
finite pagoda
#

you're welcome hope you'll understand

chilly sand
#

I'm getting 9/4 and 63/4 as solutions

latent crescent
#

i don’t get this

chilly sand
finite pagoda
#

where exactly?

#

i forgot to write - in second equation

chilly sand
#

Is it 9/4 or 3/4?

latent crescent
finite pagoda
finite pagoda
chilly sand
chilly sand
finite pagoda
#

you multiply the numerator in the first fraction times the denominator in the second fraction, then you write that number down. Then you multiply the numerator of the second fraction times the number in the denominator of your first fraction, and you write that number down. So this way you'll remove denominator

finite pagoda
chilly sand
latent crescent
finite pagoda
#

yess

latent crescent
#

thx

finite pagoda
#

you're welcome

chilly sand
#

Close if you don't have any doubts

latent crescent
#

now do i plug the numbers in for x to see if they work

#

or no

latent crescent
#

why not

chilly sand
latent crescent
#

yes

chilly sand
#

Ok then you do

chilly sand
finite pagoda
#

i use samsung tablet

#

its hard to write with mouse

chilly sand
chilly sand
finite pagoda
#

yeah it takes too long and letters or numbers are always edgy

#

i cant even read what i wrote after some time

chilly sand
#

Lol

latent crescent
#

@chilly sand

chilly sand
latent crescent
#

it says only negative 1 works but

#

when i plug -1 in it doesn’t = to the other side

#

that means they’re both wrong

chilly sand
#

Wait let me try

latent crescent
#

whoops

#

sorry

chilly sand
latent crescent
#

how

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i input it to the equation after and it’s not equal to thebotherbside

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the other side

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@chilly sand

chilly sand
#

Wait let me explain

#

You see abs (b+5) is always positive

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Take the case as -(b-3) =b+5

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You'll ultimately get the answer for this one upon solving this

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@latent crescent

latent crescent
#

ok

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am i not supposed to make it like this

chilly sand
#

Idk whether it's correct , ask her

latent crescent
#

b-3=-(b+5)

#

it’s supposed to be like that

#

i thought

chilly sand
#

B+5 can never be negative

latent crescent
#

why

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since when can i pick a side to do it on

chilly sand
#

B<-5, b<3 can this be possible?

latent crescent
#

idk

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how should i know

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im confused

chilly sand
#

I don't want to confuse you

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You should take either both as positive or one positive and other as negative

latent crescent
#

but which one do i know to take as negative

chilly sand
latent crescent
#

if u plug -1 in it doesn’t work

chilly sand
#

Yo |-1-3|=4

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|-1+5|=4

chilly sand
#

Not with that

latent crescent
#

-1-5

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cause the negative -(b+5)

#

so it would be

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1-5

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-4

chilly sand
#

Bro what was the question?

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@latent crescent

latent crescent
#

to find the solution

chilly sand
#

I'm leaving now

latent crescent
#

ok

chilly sand
#

It's 2am here

latent crescent
#

all good

chilly sand
#

You got the answer?

chilly sand
latent crescent
#

wdym abs-4 is 4

#

what’s that mean

chilly sand
#

4=4, hence your solution is indeed correct

chilly sand
#

Modulus

latent crescent
#

so -4 is correct ?

#

how is -4=4

chilly sand
#

Yo bro what's |-4|?

#

@latent crescent

latent crescent
#

idk

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what is it

chilly sand
#

4

latent crescent
#

how

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elaborate

chilly sand
#

Anything you put inside the modulus function the output will always be positive

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Hasn't your school taught that?

latent crescent
#

interesting

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i didn’t know that

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thx

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so if i get |-5-5/6|

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the answer is

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5+5/6

chilly sand
latent crescent
#

bet

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thanks

#

goodnight

chilly sand
latent crescent
#

good afternoon for me

chilly sand
#

If you have any doubts dm me

chilly sand
pearl pondBOT
#

@latent crescent Has your question been resolved?

pearl pondBOT
#
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copper pagoda
pearl pondBOT
copper pagoda
#

im not sure if this is right i kind of inferred that deltaY is greater than dy

pearl pondBOT
#

@copper pagoda Has your question been resolved?

copper pagoda
#

.close

pearl pondBOT
#
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pearl pondBOT
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abstract rune
#

bro

pearl pondBOT
abstract rune
#

am i tripping

plush bramble
#

Is Pa pascal

abstract rune
#

yeah

plush bramble
#

looks right

abstract rune
#

WHY IS THAT RIGHT

plush bramble
#

,w si unit pressure

plush bramble
#

,w si unit pascal

plush bramble
woeful stump
abstract rune
#

ill survive, whatever

#

.close

pearl pondBOT
#
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woeful stump
#

ohm = kg m^2 s^−3 A^−2

pearl pondBOT
#
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ripe prairie
#

I don’t understand how to solve this rational equation

ripe prairie
rough forge
#

cross multiply both sides

#

and define the domain

ripe prairie
#

Do I simplify 2x-6 to x-3

verbal whale
#

2x - 6 = 2(x - 3)

ripe prairie
#

OH

#

ok I think I got it

#

Ty

#

.close

pearl pondBOT
#
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pearl pondBOT
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misty gorge
pearl pondBOT
misty gorge
#

:'(

#

i dont know where to start

#

<@&286206848099549185>

#

help ! ! !

midnight haven
#

Why do they take so long

#

To respond

misty gorge
#

They hate me because i'm the flash

midnight haven
#

Fr

#

You guys know kumon

misty gorge
#

🤢

#

steve jobs

fluid sequoia
#

what is Ws and Wt?

misty gorge
#

partial derivative of W with respect to s and partial derivative of W with respect to t

fluid sequoia
#

lost as well...

#

I guess we will both learn something.

jolly parrotBOT
misty gorge
#

Ohh duh

#

Wait

#

How do i find Fu and Fv though

#

because they're evaluated at (5,3)

rough forge
#

F is a function of u and v...

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u and v at (1,0)

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give 5,3 respectively

misty gorge
#

O i see

rough forge
#

F(u(1,0),v(1,0)) = F(5,3)

misty gorge
#

Thank u

rough forge
#

no problem

misty gorge
#

.close

pearl pondBOT
#
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zinc flower
#

How do i solve this with 2 variables?

pearl pondBOT
zinc flower
#

nvm figured it out

#

.close

pearl pondBOT
#
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pearl pondBOT
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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midnight haven
#

don't understand how I am supposed to take y = -1/8x - 3/8 and turn into this form Ax+By=C

chrome plank
midnight haven
#

add -1/8x + both sides ?

chrome plank
#

yeah, lets try that

midnight haven
#

1/8x + y = -3/8 ?

chrome plank
#

yep

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Does that fit Ax + By = C?

midnight haven
#

no

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I don't think there can be fractions the teacher said

chrome plank
#

yeah, it's almost there though.