#help-39
1 messages · Page 141 of 1
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For a given ring $R$, construct the polynomial ring $R[x]$, where the elements are \textbf{formal} sums $\sum_{i=0}^na_nx^n$. Quadratics are elements in the polynomial ring. Given a map $R\to S$ of rings, the evaluation map $\operatorname{ev}_s:R[x]\to S$ is the map induced by $R\to S$ and $x\mapsto s\in S$
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I don't think you need to find zeros to plot the parabola. You can always evaluate for $y$ at given points $x$ and then plot those points.
uhhhh is that discreet math?
Element118
Yeah, the polynomial ring is a concept quite beyond this. In short, polynomial and polynomial functions are two different concepts.
o H
alright
thank you for explaining that.
Still, this describes my understanding of it, and I don't think that that is necessarily important to it.
The main question, again, was regarding how this was equivalent due to how they were graphing the parabola which is from the behavior of the quadratic of course.
My guess is that they are trying to graph $f(x)=ax^2+bx+c$.
Changing it to $f(x)=x^2+bx/a+c/a$ only scales the graph vertically.
Changing it to $f(x)=x^2+bx/a$ only shifts the graph vertically.
Element118
The other possibility is that they are trying to find roots
which they are trying to show the "complete the square method"
but getting rid of the c/a term so that it is easier to present the next step
https://www.youtube.com/watch?v=UTuxHsaH-gQ&list=PLybg94GvOJ9FoGQeUMFZ4SWZsr30jlUYK&index=37 (this explains what theyre doing)
1. Well, clearly, by subtracting c/a which logically is apart of the behavior of the problem and thus removing it would make the behavior when graphed different to the original quadratic they wanted to graph the behavior of
so this leaves me with two possibilities that they rather are removing it and it somehow isnt that important what the quadratics components are or that they somehow arent and its still somehoe equivalent to the original.
2. what is the difference between scaling and shifting vertically? Do you mean multiplication vs adding?
3. My very first question was the what values correlate to X or Y and which values get what.```
You remember this one, don't you? Opposite of b, plus or minus... what was it? Well instead of just telling you, why don't we derive the formula? As it turns out, it's like completing the square, but with variables. Will you just watch this already? I can't explain it without the pictures.
Watch the whole Mathematics playlist: http://bit.ly/Pro...
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
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The motivation of subtracting $\frac{c}{a}$ from both sides is to clean up the left-hand side to get $x^2+\frac{bx}{a}$. I think introducing graphs into this might complicate things. Doing the same reversible operation to both sides leaves you with an equivalent equation to the original.
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That seems to be implied by trying to plot it out on a graph.
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When solving $f(x)=0$, there's no $y$ to be concerned about. The point appears to be that doing a reversible operation preserves what $x$ satisfies the equation.
Element118
5 - 15 + 5 = -5 ---- 5 + 5 = 10
so is it not equal but because you can undo it it makes it equal?
and how does one go about undoing it?
In general "doing the same thing to both sides" preserves equality.
that does not appear to be the result.
if a = b, then f(a) = f(b). Being able to undo it, by adding back c/a to both sides, ensures that the final equation doesn't lose information the original equation had.
Say $a=b$ and we square it, we get $a^2=b^2$. But the solutions to this final equation are $a=\pm b$, which is different from the original equation. That's because squaring cannot be reversed.
Element118
so it is not equal?
only this half is?
and that part is perserved for the formula
and then c/a is added back after
?
Doing a reversible operation on an equation preserves the set of solutions. Doing an irreversible operation on an equation may increase the set of solutions.
"Subtracting c/a" can be reversed by "adding c/a"
"dividing by a" can be reversed by "multiplying by a" (assuming a is not 0)
Does that imply that I was correct?
it is unequal until reversed? (removing c/a is unequal until reversed after operations are complete)
I'm not sure exactly how you are correct.
im saying that by removing c/a which is a component of the problem and its behavior
it isnt equal to the original equation until you reverse it and add c/a back
but while its gone
you gain access to certain forms
allowing access to quadratic formula etc
is this true?
if not explain
because throughout this entire time the idea of it being unequal hasnt been touched because you havent actually said anything on the matter (difference between fact stating and technical resolving)
no matter how much you say something is or is not true or if something equates to something
if my fundamental concept is off by even a little bit i will interpret the same information you gave differently
Firstly these two equations are equivalent
$x^2+\frac{bx}{a}+\frac{c}{a}=0$
$x^2+\frac{bx}{a}=-\frac{c}{a}$
We can get from the top to the bottom by subtracting $\frac{c}{a}$ from both sides and bottom to top by adding $\frac{c}{a}$ to both sides.
Element118
equivalent, meaning
"(a, b, c, x) makes the top equation true if and only if this (a, b, c, x) makes the bottom equation true"
define top and bottem
top equation: $x^2+\frac{bx}{a}+\frac{c}{a}=0$
bottom equation: $x^2+\frac{bx}{a}=-\frac{c}{a}$
in this case
Element118
there's a small caveat here, that we already assumed a is not 0.
so
the last way i can interpret this
is that
they are unequal but also not
in that the definition of equality was wrong
i always meant it in that the problems essential structure
would be unchanged
in that if you removed fundamental pieces of the problem
it would have to be incorrect.
because you lost the original data and behavior the zeroes described
but
what i get from that
is that
your idea of equal is completely different
in that
any formation of the same data even if subtracted to form a different result that isnt the zeroes
so long as it utilizes the same set of numbers
is still equal in the sense it is another expression of the same data
in that the subtraction to remove itself WAS the expression of that component
rather than that component not existing
hmm, it might be equivalent to my definition here
it doesn't fundamentally lose any piece of the problem because the set of solutions remain the same
that's what we care about when we are trying to solve for x
the "if and only if" is doing a lot of the lifting here
alright
i cannot continue
it is 3:09
am
ive been at this for hours and i cannot understand what you mean by alot of that.
also, no offense but, is english not your first language?
oh well
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This basically means that the cardinality of the set is non- finite , right
that's not all there is
I know
but that's the part I'm concerned about
It basically means A is an element of the set containing the elements of the powerset of P(\N)
being not finite is not sufficient to be an element of that set
{2, 4, 6, ...} is not contained in that set
I know
so it does not "basically mean that the cardinality of the set is non-finite"
that is not an equivalent description
As I said, that was the part that confused me
what are you confused by? you haven't specified
I was confused by $|\overline X|<\infty$
it means the cardinality of the complement of X is finite presumably
Veni, vidi, perii
Yes, that's what I wanted confirmed
thanks
.clsoe
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A travel company organizes a tour with a price of 500 $ per customer for 30 customers. Starting from the 31st customer, for each additional customer, the price of the tour decreases by 𝑎 $
(where a is a positive integer). The number of additional customers cannot exceed 15. It is known that if the number of additional customers ranges from 1 to 8, the total revenue increases as the number of customers increases. Find the maximum value of a. I need help with this problem
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Is 1/lnx considered continuous function?
It's obiviously not continuous when you have x<1 but do we call it non-continuous just because it's not between specific range
what do you need to have to say a function is not continuous
The function is continuous wherever is defined except at x=1
From (0,1) and (1, inf)
And is discontinuous at x=1 cause it is undefined
Because of division by 0
only x=1 ?
Where else?
is it not undefined ln(-5)
Here
When x<0 is not defined
Ln over reals is only defined when x>0
So you're saying it's because definition of domain of a logarithmic function ?
Check the function
Like it's not defined 0<x at the first pplace
,w plot lnx
yeah
Because 1/0 is undefined
so when we call a function continuous?
Is it when there is only one undefined point or something like that
And at x<0 the function is also undefined because ln(neg) is undefined
We can say it is continuous in two (idk the word in english) parts
(0, 1)
And (1, inf)
And there is a discontinuity at x=1
does that mean there is no general referring like "f(x) is continuous but g(x) is not"
But the function is not continuous over the whole spectre
Not sure I get this question
Can u say with an example?
Is there no such a thing like calling a function discontinuous or continuous as a whole or general?
You can say f(x) = x is continuous
There is no undefined point in this function
But in 1/lnx you cant say that
Cause there are 1 point and 1 side undefined
So you're basically saying "to say if a function is continuous or not we need to include where we're talking about"
no?
Yes
You specify what are you talking about
That will make clear the context better
okay get it. So is it correct to say that 1/lnx is continuous at 1<x while It's not at 0 and x<0 ?
I see redundancy
okay
And is undefined for x<0
so do we say discontinuous only when there are undefined point or points in a continuous interval which is breaking it or something?
because I thought that we can still say it's discontinuous at x<0?
but you just said "undefined"
When a function is not defined at certain points like for x < 0, we do not consider those as points of discontinuity, the concept of discontinuity applies to points within the domain of the function where the function’s behavior breaks down.
ohh okay so my problem arose due to definitions I guess
Yes, definitions are the first thing to check
because I was thinking like when you try to go back from point 0, you are not allowed which must mean It's discontinuous
.cllose
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integer that is positive and odd?
how would i find part B
every number is divisible by 8?
yep
for (c) just take m to be some positive odd integer 2k+1, and show that the result is still divisable by p
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double angle identity
is a special case of the compound angle identity
which can be derived from clever construction of similar triangles
😮
damn they expect me to remember this while doing integrals
trig should've been a pre-requisite for calculus
if u need a easy way to derive it on the spot u can use the addition formula
yes but
in college not so much trig
economics college
so it very much in the dark
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Use Moivre's formula to express $cos4\theta$ and $sin4\theta$ by $sin\theta$ and $cos\theta$
Good
For $cos4\theta$, I got $2cos^2\theta-1$
Good
For $sin4\theta$, I got $$(1-sin^2\theta)(4cos\theta sin\theta +2sin^2\theta)+4cos\theta sin^3\theta$$
Good
Is there any way to keep factorize? Or is this enough?
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hi how do i go about solving these? any hint or a particular method
since this is calculus, us a CALCULATOR
hello can you help me in #help-36
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The bearing of point B from point C is $254^\circ$. The bearing of point A from point C is $344^\circ$ The bearing of point A from point B is $32^\circ$ If the distance from A to C is 780 miles, find the distance from A to B to the nearest meter.
snooze
I need some help visualizing and drawing this out
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I have been staring at this question for the longest time and I Dont really know how to even begin. this is about probability going from a point to a point.
$P(E_{1})=\frac{2}{5}$, $P(E_{2})=\frac{3}{4}$, $P(E_{3})=\frac{2}{3}$, $P(E_{3}\mid E_{2})=\frac{4}{5}$, $P(E_{1}\mid E_{2}\cap E_{3})=\frac{1}{2}$.
Totalani
First question asks what is the probability someone can go from A to B if he has to pass C ?
nevermind got the first question, very simple
Second question askes the prob from A to B
@dark sparrow Has your question been resolved?
Any help with this?
In how many steps?
Does not say, it just says the probability from A to B
I read that as directly, since last question was about passing C
Going from A to B passing C was 0.6
Why is it not just P(E1) then
I dont know, thats not what says in the asnwer, it says its 0.7 but im not sure how its getting it
did you read the first two sentences
yes
that's why it's not just P(E1)
the first 2 sentences doesnt matter. it says "in this particular day this and this are the probabilities.." and it gives you the probabilities for that day.
What does it say about A and B in the second sentence
It says you cant always travel between A and B during winter, but it does not say you cant travel between A and B during this particular day, its even giving you the probability no?
lets assume you cant go directly from A to B then
so you have to pass C
That was already the question for a)
I just want to know how it got to 0.7
yea but you said you didn't know why it's not P(E1)
No you asked why it wasnt just P(E1)
and im saying it cant be because P(E1) is 2/5 but the answer is suppose to be 0.7
any help with this?
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Let A be the set of real numbers R. Express the following proposition
with a simple sentence.
∀ x ∈ A ∃ y ∈ A [(x < y) ∧ (∀ z ∈ A (x < z) ⇒ (y ≤ z))]
Is this proposition TRUE ? If not, is there a set A for which it is TRUE ?
Justify your answer
so basically, x<y and z<=z
so no, it is not true, BUT can I also say there is no set A for whicb it is true?
because, for example, integers would be a set such as {1,2,3...}
and so it cannot work because x > y if x = 3 and y = 1
but i don't fully understand sets, so i'd like to know if i'm thinking on the right track
you need to review the qualifiers:
"for all x in A, there exists y in A..."
for all x in A, there exists a y in A scuch that x< y AND for all z in A, if x< z, y <= z
i'm just confsed by the set part
this question has a super simple answer but i don't know how to allude to it without giving it away
i'm not saying coming up with it is simple, just that the (or one) answer is simple
the sets of integers are ordered, right?
the issue is i haven't delved into sets at all so i don't understand if they're ordered
A is a subset of the real numbers
so it has an order inherited from there already
but sets are not manifestly ordered in general, no
but the requirements for this set is to be ordered
so does that mean no set exists as the sets aren't ordered?
the order used in the question is real number order
the elements of A are real numbers
remember that the statemeent says "for all x, there exists some y such that...". so given x = 3, can you choose a particular y that satisfies the statement?
if y>x then it satisfies it, so 4 would work
what about the second half of the statement?
which statement
the part about z. is it true that any z larger than x has to be at least as big as y?
yes, it's true
which number system is it true in?
the set of real numbers R (which is A)?
wait because it's just saying like
every number has a number greater than it, which has a number greater than it
but is infinity included in R?
consider z = 3.5 then
then it wouldn't work
WAITWAITWAIT
so like
as long as they're discrete intervals
like 1,2,3
beacuse x<z and y<=z and
so if x=1 and y=2
z has to be 2 or higher
so it couldn't be the real numbers?
any subset of R then?
not just any subset of R. think about the type of subset that comes up when we talk about "discrete" things
so let's take the integers, since the other two are subsets of that. does the statement work on the integers?
well in some cases. if youve got {-1,0,1} and x=-1 while y=0 it would work
but couldn't x=1 and y=-1, if either can represent any number of the set?
so the "for all" means that we have to make it work for every x in the set. but the "there exists" means that at least 1 y in the set satisfies the condition. so we don't get a choice of x, but given an x, we get to pick a y (if we can), to make it work
OH
I SEE WHAT YOU MEAN
so as long as a y exists that will be greater than x, it will work
yes, but we also need a guarantee that if z is larger than x, then it is at least as big as y. since we don't get to pick z, we need to make sure there can't be any numbers between x and y
and that's why it can't be a real number because it could be a fraction
i'm confused on z still
well let's say that x = 3, then we could choose y = 3.5. but then we still have the issue of z = 3.25, so it doesn't work
the problem we run into is that we can always find a z that is somewhere between x and y
do you mean when x = 3?
yes x = 3, sorry
what subset of real numbers doesn't have this issue? is there a type of number where we can pick two numbers and there aren't any numbers between them?
yes
with the integers we can have a "next integer" which we can't have on the real numbers
OH BECAUSE
x<y holds true in any sense
and if y<=z, z cannot be less then x, thus x<z
well the implication is the other way around. we want it to be true that 'if x < z, then y <= z'. in other words, any number bigger than x must be at least y, in other words, we can pick y which is the "next number after" x and there aren't any numbers between them
so for example
x=1, and z=2
if 1<z y<=z
so y is 2
okay
i get it
so it does work with integers because y comes directly after x, and no numbers are between them where z=>y
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why is sin the answer shown here and not 5/sqrt61 ?
because u can’t have a radical at the bottom
this is new to me
so u find the hypotenuse using pythagorean theorem
ah i see, its 5/sqrt61 but multiplied by sqrt61 so the square root is moved up top
right?
yup
thank you goat 🙏
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any <@&286206848099549185>
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My working so far is that there is 7C3 ways to incorrecty guess the other 7 songs, and 3C0 ways to incorrectly guess the 3 band songs, and 10C3 ways to choose 3 songs from the 10, so my answer is 7C3*3C0/10C3 = 7/24. is this right?
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this makes no sense
oh ok
so like they know all songs, but not the order, one of 10! guesses
yeah 7c3/10c3 makes sense
no not right
they have to guess the exact song, this only "allows" them to guess the band
you gotta do inclusion exclusion
guess first song right: 9!
guess first two songs right: 8!
guess all songs right: 7!
3(9!) − 3(8!) + 7!
@onyx moat Has your question been resolved?
Wait so what would the probability work out to
,calc 1 - (3(9!) - 3(8!) + 7!)/10!
Result:
0.73194444444444
Result:
0.73194444444444
Could u elaborate a little bit on the inclusion exclusion
I understand them individually but not all together
Oh nvm I just saw the 1 - lol
I think I get it now
yeah we find union of outcomes where something was guessed right
I see
Is this just a counting problem? or can we apply a probability distribution somewhere bc that’s kind of the theme of worksheet
i don't know
well
maybe the idea is you just always have 1/10 chance, instead of choosing a permutation
then it's just binomial
a differetn answer, but it maybe makes sense too
no they said "only once"
so it's clearly about permutation
I was thinking maybe hypergeometric fit in somehow but I’m not sure
it would make sense if it was about identifying the band, so the same thing you said first
so it's possible, just wrong wording
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Is the rate of convergance for a taylor series always the highest polinomial you use?
Basing it from this:
Ok here is a better question, why is the remainter therum located where it is:
should it not be + error, why is it being multiplied into the last portion?
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Need help with calculus
Be more specific, or just ask directly the exercise/doubt on the theory
I want to ask about
The integration with numbers formula
Oh wait
Wth am I doing
Sry sry
.close
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Hi guys I am having trouble on what type of angle this is: co interior, corresponding, alternate
@eveyone
<@&286206848099549185>
@mental aspen with what angle
Like identifying what angle it is
yes, but the names "cointerior, corresponding ..." refer to pairs of angles
Ok thank you.
i think the alternate they are like a Z outside and inside and corresponding like double L
i use that to identify
ok thanks for the tip
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what if i put root 4 and did the same process
what part do you not get
i dont get how showing that it has common factors shows that its irrational
you assumed that p and q has no common factors
but in the end you end up with p and q having a common factor of 2
p^2 = 2q^2
how does this show that p is divisible by 2
p² is an even number since its 2 times some integer
5^2 = 25
and if p² is even, then p has to be even
what
OH
p^2 = 2q^2
oh
if you want to prove this on your own go ahead, extremely simple to do
i remember seeing a proof of this but i forgot
nooo 😭
my test is tmr
and its on complex numbers proof of contradiction and induction
im cooked
hi water beam
do u wanna see what i got for my chem test
6/26
..
hey i got this before though..
im doing a titration 🫨
cap
dw you'll do fine
u cant do as bad as me
i cant believe
i finished unit 1 and 2 of specialist and i havent dropped it 😭
im so proud of my self 😭
NO
😭
if i finish it early
in year 12 i can just cruise through
yes i am
ima finish specialist and methods early
and have sm time to study for others
are u good at english
well i just searched for this online and its pretty similar
i can do mid in it
i cant do like
very well in it
bc i have never finished a book in my life 😭
only the in class ones where the teachers read it to u
can i see it..
just in case its in my test..
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Both requires different cognitive faculties
(6x) square is 36x^2
noooo
like whats lim cosx-1 whole /x2
its 1/2
use that logig
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33 don’t know how to start, I’m thinking something with conjugates and u sub but I can’t get it to work
what did you use as the u sub
Well I tried y-1 and y+1
Neither seemed to work and no other one seemed relevant
oh no
yeah it won't
it's a trig sub
think of all the trig identities which look similar
I can’t do trig sub yet it’s prior to that
Not meant to be
Well it very well might but but there must be a non trig sub method
It’s not my instructor it’s a book
Trig sub is another 30 pages from here
lemme see if i can think of non trig stuff
You can use u sub = the whole thing
I found this by searching on approach0.xyz
okay but that's even worse 😭
not really
i like that method
It can be dine like this too
oh they mean u = 1 - x^2 lol
There is no one single way of doing things
Uhmm
through that sub?
I’m lost
i just dont see it ig
sub the whole function as u and you should be good
Yes but i don recomment
hmm lmaoo
if you sub u = the whole thing you have to do a partial fraction decomposition
I don’t know that stuff
i honestly think the cleanest is the trig sub here lmao
Well, what do you know?
if you know trig i'd recommend trying it just for the lols anyway
indeed lmao :')
uhm like everything integration by parts and earlier
Wait what’s du/dx then I can’t do it rn I’m walking to clsss
When you say whole thing you mean everything within the radical or radical included?
The latter?
It doesnt matter
What’s du/dx then
Either
Well you are the one who has to work out on that
I’m typing on my phone on a sidewalk 😭
Do not try this exercise if you are not in a chair and table
What is that?
du/dx?
thin
I think
Wait I see how to do it
Conjugate and then just make two fractions
Right?
yes
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Find the values of the constant c for which the line y= x+c is a tangent to the curve y = 3x + 2/x
What lmao
uhhh how do I solve this
first you get a separate channel
!occupied
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開一個你的頻道
感谢啦
b^-4ac=0 of y=3x+2/x
还有我的繁体挺差的 xs
then c=-x
oh
好吧,我可以转成简体
thank
hmm
Heehee
you know derivatives?
🤷🤷
like dy/dx and shi
Nah we don't write that lol
oh
ohh
B squared -4ac =0
3x + 2/x=0
we know that for a line to be tangent to a curve the y value shud be equal
so equate em
Yes
so x+c=3x+2/x
that gives $x^2+(c-3)x-2=0$
huh wait let me digest rq
what
zen
oh
get it?
why c-3
to get rid the fraction?
zen
it gives this
yea
alr
zen
i got the answer tysm
its actually so simple lollll
my dumbass just dont get it but i got it now tysm
lol its aight
tysm
also what does The line y = 2x + k is a tangent to the curve x^2 + 2xy + 20
mean
exactly
it only touches the curve in a single point
ooh i got the answers already and also
theres a b) for it
its uh for each of these values of k, find the coordinates of the point of contact of the tangent with the curve
k = 10 or =10
10 or -10
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I mean I know it's true because i did a weird repeated integration by parts method to get a form of the integral of the bell curve (too lazy to explain it, it was a pain in the ass 😭 )
but is there like.. a way it telescopes?
Also the L is just supposed to be a standin for the limit as the variable goes to infinity
(desmos doesn't have limit notation.. i think)
$lim_{L \to \infty} \sum_{n=0}^{L} \frac{(2n+1)x^{2n} - x^{2n+2}}{\prod_{k=0}^{n} (2k+1)} = 1$
Serphic
there we go okay
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help
youre almost done, just remove absolute value sign, and solve both equations as normal
yes
x
@finite pagoda
can u help me solve
@thin bane
@plush bramble
<@&286206848099549185>
@real tiger
don't ping me out of no where
and in general
bro i need help
!noping
Please do not ping individual helpers unprompted.
wait a min
is that $| 3 - \frac{1}{3}x| - \frac{7}{4} = \frac{1}{2}$?
dragonbreath
I found the solution can I send my work here
ok
2 minutes pls
In your second line where you have the two functions equal to 9/4 and -9/4, drop the absolute values and solve accordingly
For example $|x - 3| = 4$ is equivalent to $x - 3 = 4$ and $x - 3 = -4$
dragonbreath
thanks
you're welcome hope you'll understand
I'm getting 9/4 and 63/4 as solutions
You might have made a mistake somewhere
Is it 9/4 or 3/4?
63/4 was right
i dont know how they teach this to you
Yours is correct, the 9 looks like 3 for me so i got confused
haha its ok
Lol I have skill issues
you multiply the numerator in the first fraction times the denominator in the second fraction, then you write that number down. Then you multiply the numerator of the second fraction times the number in the denominator of your first fraction, and you write that number down. So this way you'll remove denominator
it happens 😛
Very relatable lmao
do both negatives cancel out and that’s y they are positive
yess
thx
you're welcome
Close if you don't have any doubts
No need
why not
Are you gonna check your answer by doing that ?
yes
Ok then you do
How do you guys write neatly on a whiteboard?
Ohh
I tried writing with a mouse but no one was able to understand
Skill issue btw
yeah it takes too long and letters or numbers are always edgy
i cant even read what i wrote after some time
@chilly sand
Yes
it says only negative 1 works but
when i plug -1 in it doesn’t = to the other side
that means they’re both wrong
-1 is the only solution
how
i input it to the equation after and it’s not equal to thebotherbside
the other side
@chilly sand
Wait let me explain
You see abs (b+5) is always positive
Take the case as -(b-3) =b+5
You'll ultimately get the answer for this one upon solving this
@latent crescent
Idk whether it's correct , ask her
B<-5, b<3 can this be possible?
I don't want to confuse you
You should take either both as positive or one positive and other as negative
but which one do i know to take as negative
Your wish
if i do it this way it doesn’t work
if u plug -1 in it doesn’t work
You apply the answer to the question...
Not with that
to find the solution
It's 2am here
all good
You got the answer?
Yes abs -4 is 4
4=4, hence your solution is indeed correct
4
Anything you put inside the modulus function the output will always be positive
Hasn't your school taught that?
interesting
i didn’t know that
thx
so if i get |-5-5/6|
the answer is
5+5/6
Yess
Good night
good afternoon for me
If you have any doubts dm me
Lol
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im not sure if this is right i kind of inferred that deltaY is greater than dy
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bro
am i tripping
Is Pa pascal
yeah
looks right
WHY IS THAT RIGHT
,w si unit pressure
,w si unit pascal
did you not understand the steps shown?
dimensions can indeed seem odd
nah its just pissing me off that im just now realizing this
ill survive, whatever
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ohm = kg m^2 s^−3 A^−2
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I don’t understand how to solve this rational equation
Do I simplify 2x-6 to x-3
2x - 6 = 2(x - 3)
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They hate me because i'm the flash
what is Ws and Wt?
partial derivative of W with respect to s and partial derivative of W with respect to t
Do you know the chain rule?
bacc
O i see
F(u(1,0),v(1,0)) = F(5,3)
Thank u
no problem
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How do i solve this with 2 variables?
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don't understand how I am supposed to take y = -1/8x - 3/8 and turn into this form Ax+By=C
Step 1: Ax+By=C has both x and y terms on the same side. So, how can you manipulate y = -1/8 x - 3/8 to get x and y on the same side?
add -1/8x + both sides ?
yeah, lets try that
1/8x + y = -3/8 ?
yeah, it's almost there though.