help-39

[latent quail]

Not an equation

[stoic imp]

,, |a|^2 -2|ab| + |b|^2 \leq |a^2 -2ab + b^2|

this?

[latent quail]

You can remove the absolute value on the right side actually

Since no matter what real numbers you square, the result remains positive

[stoic imp]

wdym

[latent quail]

wdym wdym?

[stoic imp]

remove the absolute value? is that legal?

mmm

i need more hints

[latent quail]

I literally gave you the entire solution…

[stoic imp]

does that mean its proven?

if I remove the abs in the right

[latent quail]

Do you understand why the right side remains the same when abs is being removed?

[jolly parrot]

calc_and_real_anal

[latent quail]

You have to understand this so we can proceed

[stoic imp]

I messed up the algebra

I made a typo in last inequality now its fixed

now what?

@scarlet raptor

I need more hints

b = -c

[latent quail]

You need to understand how it works

or else you’ll messed up again next time while encountering similar questions

[stoic imp]

,, |a|^2 -2|ab| + |b|^2 \leq |a^2 -2ab + b^2|

[jolly parrot]

calc_and_real_anal

[stoic imp]

how to proceed

do I check b<=0 and b>=0 for c = -b?

I need a bit more of hand holding

[eager sun]

What step u up to?

[latent quail]

You may start over from the beginning

[eager sun]

[latent quail]

He doesn’t seem understanding my method very well

[eager sun]

Ok

[latent quail]

And I have no idea how to proceed my tutoring 🥲

[eager sun]

Let me see the context

[latent quail]

Here

[eager sun]

@stoic imp u here?

Brother left

[stoic imp]

bro i’m here

but

I dont get it

[eager sun]

Sure

Nothing at all?

[stoic imp]

nothing

[eager sun]

Show me what you’ve done

[stoic imp]

,, |a|^2 -2|ab| + |b|^2 \leq |a^2 -2ab + b^2|

[jolly parrot]

calc_and_real_anal

[stoic imp]

I squared like the green one ordered me to do

[eager sun]

Left side

U can simplify

Also

[stoic imp]

||but for now we only care about right side of the inequality since right side is triangle inequality||

[eager sun]

Oh wait nvm

Ok

[stoic imp]

now we gotta pick cases

according to chipmunk person

[eager sun]

Yea

Not sure how else to put

Ok one second

[stoic imp]

if you can draw it out will be fine

[eager sun]

Brother

Have you squared both sides

@stoic imp if you square both sides then you can remove absolute value

Because square of any number is positive

[latent quail]

That’s what I said

[eager sun]

Yea

Need to get past basic understanding

[stoic imp]

ohhh

[eager sun]

Yes

Show working afterwards

[stoic imp]

,, |a|^2 -2|ab| + |b|^2 \leq a^2 -2ab + b^2

[eager sun]

Then we can proceed

[jolly parrot]

calc_and_real_anal

[stoic imp]

this?

[eager sun]

Yes

Ok awards

Afterwards

[stoic imp]

wdym

[eager sun]

I’m writing one sec

[stoic imp]

which awards?

[eager sun]

Do u understand this?

[stoic imp]

yes but I need a little bit of handholding for the implementation of that

[latent quail]

Have you tried on your own

[stoic imp]

yes

but lowkey arrived to nothing

i can draw if you guys explain to mortals

but preferable if you draw

@scarlet raptor

<@&286206848099549185>

,, |a|^2 -2|ab| + |b|^2 \leq a^2 -2ab + b^2

[jolly parrot]

calc_and_real_anal

[stoic imp]

for the left innequality, I think you can just consider the cases a>=0, b>=0, a>=0, b<=0 (with b=-c, c>0) and so on separately

the remaining cases can likely be obtained from these by setting a=-c and b=-d or something

mmm

wtf?

[latent quail]

I don’t think that would be a better idea compare to you trying and making attempts

[stoic imp]

guys can you help

@scarlet raptor

[pearl pond]

@stoic imp Has your question been resolved?

[pearl pond]

@stoic imp Has your question been resolved?

[stoic imp]

.close

[pearl pond]

Channel closed

Closed by @stoic imp

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jagged burrow]

lol what's the point of this ping

[jagged burrow]

.close

[pearl pond]

Channel closed

Closed by @jagged burrow

Use .reopen if this was a mistake.

[stoic imp]

he sometimes help

why you ping me though? @jagged burrow

[jagged burrow]

i thought u randomly pinged a helper

[jagged burrow]

btw for your question, you can literally just read off the proof for reverse triangle inequality

and showing that |a - b| <= |a| + |b| follows directly from triangle inequality

|a + b| <= |a| +|b| -> have b map to -b and then you have |a - b| <= |a| + |-b| = (|a| + |b|)

[stoic imp]

,, |a|^2 - 2|ab| + |b|^2 \leq a^2 -2ab + b^2

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, - 2|ab| \leq a^2 - |a|^2 -2ab + b^2 - |b|^2

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, -2|ab| \leq -2ab

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, 2|ab| \geq 2ab

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[jagged burrow]

?????

are u proving the triangle inequality? Lol

[stoic imp]

nono, I just needed to show that the inequality holds , no proof needed

[jagged burrow]

this part just seems to help you find the conditions where the triangle inequality is stricly greater/ equality is attained

okay so like i said why can't you just

show this from reverse triangle inequality

which u can easily look up a proof for

and this bit is just triangle inequality with b mapped to -b

[stoic imp]

I can but I didnt knew the name nor what it meant, I was just asked this but didnt knew triangle inequality

nor reverse

[jagged burrow]

so you didn't know triangle inequality?

ngl u see an iteration of that in euclidean geometry but okay

if you consider degenerate triangles then you |a + b| <= |a| + |b|

[stoic imp]

degenerate?

TIL reverse triangle inequality tbh

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pearl pond]

@red hedge Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud salmon]

okay so this is the problem and my work so far

I am not sure what to do to find domain and range or the horizontal asymptote

I also sort of forgot what holes and lowest terms ares

,rotate

[pearl pond]

@cloud salmon Has your question been resolved?

[pearl pond]

@cloud salmon Has your question been resolved?

Channel closed

Closed by @cloud salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky nova]

guys

[plucky nova]

is √(( x-2 )^(-1)) = ∛(( x-2 )^(-3))

[steep niche]

what????

[plucky nova]

?

[steep niche]

what did you write, read again

left side specially

[plucky nova]

lemme give a photo, sorry i don't really write them on the keyboard so I'm not familiar with the format

[warm current]

,rccw

[steep niche]

why???

can you just write more steps and see what you wrote on both sides?

left side is 1/sqrt(x-2)

right side is 1/(x-2)

[plucky nova]

I remember we could do this

[warm current]

,rccw

[plucky nova]

so wouldn't it be like this?

,rccw

[plucky nova]

oh wait

i forgut something

is this correct tho?

[pearl pond]

@plucky nova Has your question been resolved?

[pearl pond]

@plucky nova Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight haven]

Someone help me

[midnight haven]

<@&286206848099549185>

[olive iris]

!status

[pearl pond]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[olive iris]

and please wait 15 min before pinning helpers

[midnight haven]

1

ok sry

@olive iris

.close

[pearl pond]

Channel closed

Closed by @low shard

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint drum]

hi

[flint drum]

im having a extremely hard time trying to fill this 2 way table in full

my exam is tomorrow and this is what i dont get

typical probably the most easiest thing

but i still dont understand it

this is what i have so far

[earnest delta]

You forgot to put in the 84 total coffees

[flint drum]

oh

so thats what that 84 was

about

i see

bro im so dumb

its midnight rn for me

holy

can u probably also help me with questions b c or d or nah?

[earnest delta]

Tbf that sentence is a bit ambiguous

But that’s the only thing it could mean

I’ll help

[flint drum]

yeah its because out teacher is slovak

i should be used to her broken english damn

[flint drum]

wait

but im filling it out rn

and it makes no sense

[earnest delta]

Why not?

[flint drum]

wait

where do i put the 84

just to be clear

[earnest delta]

Total coffees

[flint drum]

yeah

then it wouldnt make sense

becuase it doesnt add up

[earnest delta]

That means you made a wrong assumption on the other numbers

[flint drum]

i see

[earnest delta]

Start by completing the total row

[flint drum]

let me re check everything again

nah

im pretty sure

i got everything before hand correct

[earnest delta]

Yup, the 84 is correct too

[flint drum]

on

oh

its 256

bro im so dumb

give me a sec

let me complete this 2 way table

perfect

@earnest delta seems right?

[earnest delta]

Looks good to me

[flint drum]

ok

so b

150/290?

[earnest delta]

Yup

[flint drum]

bro

her english kinda sucks lowkey

cant lie

and to say that this is a exam

is beyond me

but its whatever lol

anyway c

[earnest delta]

Wait is this an exam?

[flint drum]

yup

like

the last year one

im studying it

for my next exam

so for c

not hot chocolate?

340/500?

[earnest delta]

For b, I think the problem actually asked for sunday, mb

[flint drum]

oh

106/210

my bad

didnt read it correctly

[earnest delta]

This is correct

[flint drum]

and

for d

[earnest delta]

This is correct too

[flint drum]

96/290?

[earnest delta]

Yes

[flint drum]

alright nice thanks

also i have a question for you

how old do you think i am

based on this exam

im taking tomorrow?

im curious

[earnest delta]

I’m terrible at guessing age lol. Somewhere between 6 and 12th grade

[flint drum]

what age is that

sorry my school system is weird

[earnest delta]

Between 11 and 18 years old

[flint drum]

oh well im 16 lol

this is like low grade math tho

so its pretty easy

anyway

thanks for the help man

i really apreciate it

😄

.close

[pearl pond]

Channel closed

Closed by @flint drum

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sick bloom]

hi

[sick bloom]

caan someone help please

so

im an idiot

and dont know a lot about math

i have an interview

and im trying to speedrun the topics

can someone help me out

[kind rampart]

do you have a specific question

[sick bloom]

what are cyclic group

[warm current]

A group with a cycle

oh I'm thinking of graph. nvm

[sick bloom]

with some kinda example

[prisma escarp]

cyclic groups are groups that are generated by some element

[sick bloom]

for example

how is Z cyclic under addition

what is the generator

[prisma escarp]

Z is not cyclic but Z_n = {0,1,2,3... n-1} is

[sick bloom]

oh

how so

lets say

Z 5

is that cyclic

what would be the generator of Z _5

[prisma escarp]

1 is always a generator of any Z_n

[sick bloom]

im sorry

i dont get it

like

what i can tell

a generator is an element of the group such that g^n = every element

for different n

is that right

[prisma escarp]

A cyclic group is a group that is generated by a single element. That means that there exists an element 𝑔, say, such that every other element of the group can be written as a power of 𝑔. This element 𝑔 is the generator of the group

but there can be more generators

[sick bloom]

but how can every element be written as a power of 1

1^ anything is 1

[prisma escarp]

power of one in this case refers to addition

the operation is addition

[sick bloom]

ohhhh

oh

oh

ok

got it

thanks

can you help me with a bit more? its ok if you're busy

i wanna know what are permutation groups

[prisma escarp]

Do you know what are permutations?

[sick bloom]

i think so

[prisma escarp]

Ok so Sn is the group of all permutations {1,2,...n}

But i think a very good example to learn about it is S_3

write down all elements of S_3

[sick bloom]

123

213

321

etc

there would be 3!

but does the order of the elements of a group make a difference

isn't Z under addition not the same group as (Z*-1) under addition

as the order is reversed

sorry if im being dumb

[prisma escarp]

fk i wish i could help but idk abstract algebra that good sorry

im still learning myself too

[sick bloom]

aw

its ok

i'll try to look into it myself

i was just panicking so it was hard to

understand something on my own

ohhhh

[prisma escarp]

yeah it takes a lot of time

[sick bloom]

so S n is the group of permutations itself

not the permutation of the group

that makes sense

ok

[sick bloom]

xd

i dont have time

i have an interview

in less than 12 hours

and i have to speedrun

group theory to linear algebra to real analysis

and a lot more

thanks for helping

[prisma escarp]

oh shi dude

are you pure math?

student

[sick bloom]

im not a math student

I will be if i clear the interview

[prisma escarp]

okk haha i see so you are taking linear algebra and you have a slight introduction to group theory at the start fo the course right?

[sick bloom]

no

the interview is for admission into a masters in maths course

[prisma escarp]

huh okk but how much linear algebra you need to know?

like im sorry im just curious

[sick bloom]

 Linear Algebra: Finite dimensional vector spaces, linear independence of
vectors, basis, dimension, linear transformations, matrix representation,
range space, null space, rank-nullity theorem. Rank and inverse of a
matrix, determinant, solutions of systems of linear equations, consistency
conditions, eigenvalues and eigenvectors for matrices, Cayley-Hamilton
theorem.

that doesn't sound that daunting

maybe 45 mins

[prisma escarp]

omg

you know anything about all this or you going in with nothing

[sick bloom]

with group theory

ik nothing

20 mins ago

now i know lil

for linear algebra i studied most of these topics at some point but not properly at all

I have a bachelors in physics

[prisma escarp]

okk ik linear algebra so ill be up for 30mins more if u need anything

[sick bloom]

oki thanks

[prisma escarp]

with physics knowledge you can actually do it in an hour

[sick bloom]

I'll try, thanks again

[prisma escarp]

glgl

[pearl pond]

@sick bloom Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight haven]

linear pretty important for physics 🧍‍♂️

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic knoll]

prove that there exists 2 powers of 2 such that the difference between them is idivisible by 2017

[karmic knoll]

so im supposed to use the pigeon hole priciple

but i dont see how thats related

[prisma escarp]

two powers of two as in two integers a,b so that a^2 - b^2 is dividible by 2017?

[quiet tendon]

no, two integers a, b so that 2^a - 2^b is divisible by 2017

[karmic knoll]

yup

[earnest delta]

Consider 2^a and 2^b modulus 2017. Can you use the pigeon hole principle to say anything about whether two integers a and b must exist with the same remainder?

[karmic knoll]

cant think of anything

[earnest delta]

Well, how many possible remainders are there when dividing by 2017?

(these are the pigeon holes)

[karmic knoll]

2016?

[earnest delta]

0 through 2017 = 2017 because we are working with integers

[karmic knoll]

oh 2017

[earnest delta]

Yup, and that only works since integer powers of 2 are integers

[karmic knoll]

yeah

[earnest delta]

Now, what are the pigeons?

[karmic knoll]

the number

[earnest delta]

Yup, how many integer powers of 2 are there?

[karmic knoll]

infinite?

[earnest delta]

Yes, infinite pigeons, finite holes

Therefore at least two powers of 2 must share remainder mod 2017

[karmic knoll]

but why?

[earnest delta]

The pigeon hole principle

[karmic knoll]

whats special about 2017?

[earnest delta]

If you tried to spread out the remainders among the possible remainders, you could only have 2017 pigeons without some going in the same hole

[karmic knoll]

we could say that about any number

[prisma escarp]

you can write 2^a = 2017 * k + r1 and 2^b = 2017 * l + r2

but since there are finite possible remainders (2017) and more than 2017 numbers there are atleast 2 numbers that have the same remainder r1=r2 = r

[karmic knoll]

oh

right

yeah

[earnest delta]

Does that tell you anything about their difference mod 2017?

[karmic knoll]

yeah its divisible

so thats true for any number then no?

[quiet tendon]

i believe this means that in general, you can always find two powers of 2 that are divisible by a finite number c. consider 2^n mod c, and consider 2^0, 2^1, 2^2, ..., 2^c mod c, then there's c + 1 terms here and only c possible remainders, so there are some a and b such that 2^a and 2^b are congruent mod c, but that means 2^a - 2^b = 0 mod c, so 2^a - 2^b is a multiple of c and therefore divisible by c

so not only can you know there exist such a and b, those a and b must be between 0 and c i think

[karmic knoll]

yeah makes sense

thanks

.close

[pearl pond]

Channel closed

Closed by @karmic knoll

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint musk]

When taking the derivative of $-4\cos(2\pix))^2$, do I also have to take the derivative of $2\pix$

[jolly parrot]

dingypine
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[flint musk]

aight

do i need to take the derivative of 2pix, when taking the derivative of this

cuz of chain rule

this was my thought process, but im not sure about the 2pi part

.close

[pearl pond]

Channel closed

Closed by @flint musk

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud salmon]

. close

[pearl pond]

@cloud salmon Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unique wadi]

Anybody know where I went wrong here?

Trying to find a number that is lower than every f(x) where x is bigger or equal to 1

[cosmic torrent]

Do (x+1)/x=1+1/x

And x>1
So 1/x<1

[unique wadi]

do you know why what i posted does not work?

trying to figure out where i went wrong so i dont repeat this

[cosmic torrent]

See let's say
X>2
So 1/x<1/2
You did the opposite you take > sign up and down

Your X+1>2 right
But 1/x<1

So you cannot right
(x+1)/x>2

You wrong because you take
1/x>1/2

[pearl pond]

@unique wadi Has your question been resolved?

[unique wadi]

hey sorry, thank you!

[pearl pond]

Channel closed

Closed by @unique wadi

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky glen]

Well, you know how to find cos(x) given x using the circle right

[latent quail]

cos45° = sqrt2/2

That’s where the solution is derived from

[quiet tendon]

maybe he's confused about radians vs degrees?

multiply the top and bottom by sqrt2

[pearl pond]

Channel closed

Closed by @frail forum

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant agate]

hi i got that

[vagrant agate]

which is false

not sure why

i rewrote it as cosx * cos x and used the DI method

DERIVATIVES: -sin x, - cos x
INTEGRATION: sin x, -cos x
-> sin x * cos x - integral of cos^2 x

[dusky glen]

That looks like you took the derivative, not the antiderivative

[vagrant agate]

huh

like this

1st derivative is multiplied with the 2nd integral
and then the 2nd row is multiplied with each other, getting cos^2 x

i subtract the former from the integral of the latter

add that integral to both sides

i get 2 * integral of cos^2 x dx = sin x * cos x

so i divide by 2

@dusky glen what's wrong

@hollow cobalt

<@&286206848099549185>

[near tendon]

The trick is to turn the cos^2(x) to cos(2x)

then it would be much easier

[vagrant agate]

i don't remember trigonometric identities

that's why i tried solvign it like this

could you please tell me where i made a mistake

[near tendon]

it's 1/2+cos(2x)/2

[vagrant agate]

okay

but what's wrong with my method

[near tendon]

You try to multiply e^x and divide e^x?

[vagrant agate]

No

[near tendon]

from here??

[vagrant agate]

This is an exmaple of this method on a different question

[vagrant agate]

this is how it's utilized in this quesiton

[vagrant agate]

.

[near tendon]

ohhh got it.

this should be the correct DI

then you do udv = uv - vdu

u = cosx and dv = cosxdx

v = sinx and du = -sinxdx

[vagrant agate]

OHHHHHHHHHHHHHHHHHHHHHHHHHH

I OFRGOT ABOUT THE FIRST ROW

[near tendon]

lol

it's okay

[vagrant agate]

so cos x * sin x + sinx * cos x - integral of cos^2 x

[near tendon]

+1dx

[vagrant agate]

why + 1

where do you have +1

[near tendon]

cuz sin^2x+cos^2x=1

[vagrant agate]

where is

sin^2x+cos^2x=1
here

[near tendon]

vdu

[near tendon]

here

you have int{sin^2xdx}

[vagrant agate]

isn't that a different method...

i want to solve it like this

@near tendon

[near tendon]

Same method bro

[near tendon]

That’s exactly uv - vdu

[vagrant agate]

hwo is

first derivative * 2nd integral - integral of 2nd derivative * 2nd integral the same

[near tendon]

And you use this to get an equation wrt I

[vagrant agate]

DUDE

telll me where tf i made a mistake

this is the DI table

[near tendon]

Where I is the original integral

[vagrant agate]

per this

cos x (FIRST DERIVATIVE) * sin x (2ND INTEGRAL) + sinx (2ND DERIVATIVE) * cos x (3RD INTEGRAL) - integral of cos^2 x (3RD DERIVATIVE * 3RD INTEGRAL)

[vagrant agate]

this is the above method

now, where did I make a mistake

answer my question pls

[near tendon]

Yes can you simplify this out?

[vagrant agate]

that's just 2sinxcosx - integral of cos^2 x

per the above -> the answer is then sinxcosx + c

@shujija

@near tendon

<@&286206848099549185>

[vagrant agate]

.

[near tendon]

you should have first term as cosx*sinx

and second term as -int((-sinx)sinxdx

and pls be patient as everyone is here to help voluntarily

[vagrant agate]

wtf is int

[near tendon]

integral sign

[vagrant agate]

why is the 2nd term not -sinx (2ND DERIVATIVE) * -cos x (3RD INTEGRAL)

i literally took it from your table

@near tendon i have to go in a bit to an exam

and i don't understand why am i getting a wrong result

plesae be fast

we've been at it for an hour lol

[near tendon]

First diagonal is cosx*cosx

second diagonal is -sinxsinx

third -cosx(-cosx)

fourth sinx(-sin(x))

if you alternate the signs, you have +cosx*cosx --sinxsinx+-cosx(-cosx)-sinx(-sin(x))

If you use DI method, it gives you 2(cos^2x+sin^2x)

which does not help

DI is often applied to integrals where taking derivatives helps simplifying it significantly

[vagrant agate]

first diagonal is the black line
why would it be cosx * cos x...

[near tendon]

sry mb. should be cosxsinx, -sinxcosx, cosxsinx, -sinxcosx accordingly

[vagrant agate]

nah dude u r wrong again

you've wasted an hour of my time

[near tendon]

you need to alternate the sign.

+/-/+/-

[near tendon]

and I've pointed out at the very beginning what you should do to get the correct answer

[vagrant agate]

dude stop msging please

idk why you're helper

[pearl pond]

@vagrant agate Has your question been resolved?

Channel closed

Closed by @vagrant agate

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp smelt]

in a GP of positive terms , if any term is equal to the sum of the next two terms, find the common ratio

[sharp smelt]

so we have $ar^{n}=ar^{n+1}+ar^{n+2}$

[jolly parrot]

ƒ(Why am. I here)=I don't know

[sharp smelt]

or $1=r+r^2$

[jolly parrot]

ƒ(Why am. I here)=I don't know

[sharp smelt]

,w solve $1=r+r^2$

[jolly parrot]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by physicsrocks

[sharp smelt]

my book says the answer is $2sin(18\gamma)$

[jolly parrot]

ƒ(Why am. I here)=I don't know

[sharp smelt]

isn't it just $\gamma$

[jolly parrot]

ƒ(Why am. I here)=I don't know

[sharp smelt]

I'll TeX what the answer key says

wait a minute please

hmm

I think $\gamma$ is a typo here

.close

[jolly parrot]

ƒ(Why am. I here)=I don't know

[pearl pond]

Channel closed

Closed by @sharp smelt

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight haven]

oh

nvm

.close

[pearl pond]

Channel closed

Closed by @pseudo gulch

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hazy arrow]

does X change the reaction force

or affect

it

does weight = reaction force?

[pearl pond]

@hazy arrow Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight haven]

How do i calculate side B for example.

[pearl pond]

@midnight haven Has your question been resolved?

Channel closed

Closed by @lofty trench

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stoic imp]

,, \int_{0}^{\infty} \ln^2(x)\sin(x^2) dx

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[inland ivy]

that looks terrible

[eager sun]

[stoic imp]

@scarlet raptor

[inland ivy]

!original

[pearl pond]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[stoic imp]

can we use ibp?

or change of variable?

[inland ivy]

you'll have to use some very complex integration techniques and results for this

which is why I asked for the original problem

[sharp smelt]

@stoic imp

!original

[pearl pond]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

@stoic imp Has your question been resolved?

[stoic imp]

,w integrate ln^2(x)sin(x^2)

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

the problem is the sin(x^2)

because if we differentiate ln^2(x) that is possible

well, $\frac{d}{dx}\left[ln^{2}(x)\right] = \frac{2\ln(x)}{x}$

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

but integrating sin(x^2) is hard

,w integrate sin(x^2)

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[inland ivy]

substitute $u=\sqrt{x}$ and use the identity $$\int_0^{\infty}x^{p-1}\sin(x)dx=\Gamma(p)\sin\left(\frac{\pi p}{2}\right)$$

[jolly parrot]

kheerii

[inland ivy]

differentiate both sides twice wrt p and substitute a suitable value

that looks tedious

[stoic imp]

u = sqrt(x)

du = (1/2)x^(-1/2) dx

dx = 2x^(1/2) du

,, \int_{0}^{\infty} \ln^2(x)\sin(x^2) dx

,, \int_{0}^{\infty} (2\sqrt{x})\ln^2(u^2)\sin(u^4) du

[inland ivy]

wrong

sorry I meant u=x^2

[stoic imp]

u = x^2

du = 2x dx

dx =(1/2x)du

,, \int_{0}^{\infty} \frac{1}{2x}\ln^2(\sqrt{u})\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[inland ivy]

,, \frac1{8} \int_{0}^{\infty} \frac{\ln^2(u)\sin(u)}{\sqrt{u}} du

[jolly parrot]

kheerii

[stoic imp]

ln^2(u) is sus should be ln^2(x) no?

u = x^2

sqrt(u) = x

mmm so confusing give me a moment

also denominator has sqrt(u) which is interesting

,, \int_{0}^{\infty} \frac{1}{2\sqrt{u}}\ln^2(\sqrt{u})\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

ahh you use log property for the sqrt

,, \int_{0}^{\infty} \frac{1}{4\sqrt{u}}\ln^2(u)\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \int_{0}^{\infty} \ln^2(x)\sin(x^2) dx

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

u = x^2

du = 2x dx

,, 2\int_{0}^{\infty} \sqrt{u}\ln^2(\sqrt{u})\sin(u) du

x = sqrt(u)

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \ln^2(\sqrt{u}) = \left(\frac{1}{2}\ln(u)\right)^2

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

okay

that was the step I was missing

,, 2\int_{0}^{\infty} \sqrt{u}\left(\frac{1}{2}\ln(u)\right)^2\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{1}{8}\int_{0}^{\infty} \sqrt{u}\left(\ln^2(u)\right)\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

omg

,, \int_{0}^{\infty} \ln^2(x)\sin(x^2) dx

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

u = x^2

du = 2x dx

dx = 1/(2x) du

okay

,, \int_{0}^{\infty} \ln^2(\sqrt{u})\sin(u) \frac{1}{2x} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{1}{2}\int_{0}^{\infty} \ln^2(\sqrt{u})\sin(u) \frac{1}{x} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

x = sqrt(u)

,, \frac{1}{2}\int_{0}^{\infty} \frac{\ln^2(\sqrt{u})\sin(u)}{\sqrt{u}} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{1}{2}\int_{0}^{\infty} \frac{\left(\frac{1}{2}\ln(u)\right)^2\sin(u)}{\sqrt{u}} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{1}{2}\int_{0}^{\infty} \frac{\left(\frac{1}{4}\ln^2(u)\right)\sin(u)}{\sqrt{u}} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{1}{8}\int_{0}^{\infty} \frac{\ln^2(u)\sin(u)}{\sqrt{u}} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

we need another change of variable most likely

partial fractions is not possible

or ibp

[pearl pond]

@stoic imp Has your question been resolved?

[random cypress]

let me try to help

im gonna try something

btw was this a homework or something?

ok i solved it

@stoic imp

let me write down the solution

lmao took 3 minutes

do you know feynman tecnique?

the solution might take me a bit to write down

give me some time

i solved it in my head first

the solution is a mess though

do you have the value of the answer?

[stoic imp]

everyone is saying that I use feynmann with t paramter but I cannot figure it out by myself, I still dont understand feynmann trick

[random cypress]

well let me show you the solution first

it's quite tricky to spot if you're not used to it

[random cypress]

this is correct right? cause im also using this

[stoic imp]

kheeri said to use x^2 and that using u = sqrt(x) was a mistake

[random cypress]

i started from this btw

it's easy from there

[stoic imp]

I still cannot understand the gamma function

[stoic imp]

well this uses u = x^2

[random cypress]

you're opening pandora's box, but i will help you

[random cypress]

ye

[stoic imp]

I was just mathing the algebra behind what kheeri said

[random cypress]

let me write it down 😭

ye it's a good step from kheri

good lord it's a mess

give me some time to evaluate everything

where the hell did you find this integral

[stoic imp]

found it on the internet, saw it uses one application of feynmanns trick and maybe ramanujan master theorem. Since I wanted to learn about this topic I wanted to try the integral

[random cypress]

oh so it did use feynman tecnique

good i spotted it

im getting good at it slowly

[stoic imp]

there is no race, just ping me with anything you got and I will appreciate it

[random cypress]

im almost there

do you know what the result is

@stoic imp

[stoic imp]

aprox 0.0242

[random cypress]

bro my result so long wolfram isnt giving me a value

one sec

oh it didnt see gamma as euler mascheroni

i got it

i was like why is it wrong

i had forgot to divide by 8 at the end

@stoic imp

and if you want me to derive the double derivative and the first derivative of the gamma function at 1/2 i can do that aswell

i just used the results

as i had them noted down

(i forgot to divide by 8 at the end, do like it's there)

this was fun, the thinking process maybe a bit too easy but some fun calculations

[stoic imp]

the third line is feynmann trick?

(d^2 I)(d x^2)

[random cypress]

it's an alpha

when i close the loop on the left it's an alpha

my x doesnt look like that if you notice

[stoic imp]

right, its alpha^2 not x^2

[random cypress]

did you get it?

[stoic imp]

I am still reading, what does d^2 mean? second derivative?

[random cypress]

ye that's the notation for second derivative

if you are familiar with derivatives you should know the derivative of n^x with respect to x is n^x*ln(n)

which is what im doing here

doing the double derivative gives me the ln^2 i need

so i then evaluate the integral i made purposefully and once i find a better way to write it i take the second derivative of that, which i know will be equal to the integral i want to evaluate

which here was where i used that identity by kheri

very useful one

which basically solves the integral

is it clear

[stoic imp]

a moment

[random cypress]

tell

when alpha is -1/2 you get that term to be the sqrtx on the bottom

[stoic imp]

how did u^alpha ln^2(u)(sin(u) happened

[random cypress]

are you asking about the ln^2

as i said, i took the second derivative of the other integral

with respect to alpha

this might be where you get stuck with feynman tecnique

you need to get used to this process

and this was NOT an integral to start with

bro died while trying to understand it

[stoic imp]

Im still on it

but feynmann trick is new to me give me a moment

[pearl pond]

@stoic imp Has your question been resolved?

[stoic imp]

,, I = \frac{1}{8} \int_{0}^{\infty} \frac{\ln^2(u) - \sin(u)}{\sqrt{u}} du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, I_1 = \int_{0}^{\infty} u^{\alpha} \sin(u)du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{-1}{8} \frac{d^2 I_1}{d\alpha^2} = \frac{1}{8} \int_{0}^{\infty} u^{\alpha} \ln^2(u) \sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

partial derivative with respect to alpha

,, \frac{d}{d\alpha} I_1 = \frac{d}{d\alpha}\int_{0}^{\alpha} u^{\alpha} \sin(u)du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{d}{d\alpha} I_1 = \int_{0}^{\alpha}\frac{d}{d\alpha} u^{\alpha} \sin(u)du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

okay

,w d/dy[x^y sin(x)]

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{d}{d\alpha} I_1 = \int_{0}^{\alpha} u^{\alpha} \ln(u)\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \frac{d^2}{d^2\alpha} I_1 = \frac{d}{d\alpha}\int_{0}^{\alpha} u^{\alpha} \ln(u)\sin(u) du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,w d/dy[x^y ln(x)sin(x)]

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

okay

,, \frac{d^2}{d^2\alpha} I_1 = u^{\alpha}\ln^2(u)\sin(u)

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

I did understand the feynmann trick but I still cannot understand the gamma function

what is this x^p + 1 shenanigans

that is gamma function I believe

mmm

a moment

[stoic imp]

that is the feymann technique, taking the partial derivative with respect to alpha

but the partial derivative of the integrand

not of the integral

well

let me understand what gamma function means

this $\Gamma(\alpha + 1) = \Pi(\alpha)$ I think btw

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

,, \Gamma(\alpha + 1) = \int_{0}^{\infty} t^{\alpha} e^{-t} dt

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

okay

,, I_1 = \int_{0}^{\infty} u^{\alpha} \sin(u)du

[jolly parrot]

938c2cc0dcc05f2b68c4287040cfcf71

[stoic imp]

yeah this is the hard step

I mean

[stoic imp]

another change of variable

r = sin(u)

dr = cos(u) du

du = dr/(cos(u))

e^r = e^(sin(u))

e^-r = e^(-(sin(u)))

[pearl pond]

@stoic imp Has your question been resolved?

Channel closed

Closed by @stoic imp

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pearl pond]

@chrome flame Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual hazel]

152

[waxen condor]

All ?

[empty lotus]

this series tests?

[visual hazel]

152

[visual hazel]

Nah
Practice problems

[empty lotus]

ahh

[visual hazel]

This is the answer
Idek where to start
Can't simply the inside term into some telescopic series due to that 4^n

Any help is appreciated

[waxen condor]

n²4^n
= (n² + 3n +2)4^n - (3n+2)4^n
= (n² + 3n +2)4^n - (3n+6)4^n + 4×4^n
= (n² + 3n +2)4^n - (3n+6)4^n + 4^(n+1)×[(n+2)-(n+1)]

Does this helps ? [IDK abt this]

[pearl pond]

@visual hazel Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp smelt]

the number of ways in which 4 boys can be seated around a table in 4 chairs of different colours is?

[sharp smelt]

so I have to permute both simultaneously

[waxen condor]

Boys can be arranged in (4-1)! But chairs again ...

[sharp smelt]

3!*3!

right

[waxen condor]

No

Thers will be common cases no ?

[sharp smelt]

on yeah

*oh yeha

*yeah

[waxen condor]

Hey

If we consider

Let a boy sit on a fixed chair

Then others arranged in 3! Ways coz all chairs diff

And this particular boy sitting on a chair of fixed color

[sharp smelt]

oh right

so $4 \cdot 3!$

[jolly parrot]

ƒ(Why am. I here)=I don't know

[waxen condor]

yeahh i think

[sharp smelt]

so 4!

cool

thanks

[waxen condor]

Is it in answer ?

[sharp smelt]

yes

[waxen condor]

Welcome !

[sharp smelt]

.close

[pearl pond]

Channel closed

Closed by @sharp smelt

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brisk anchor]

Calculate √11111111-2222

[brisk anchor]

without a calculator, showing all the steps

[eager sun]

[waxen condor]

Both inside root ?

[brisk anchor]

yes

[golden bramble]

Any common factors that can help?

[brisk anchor]

?

I think 1111?

[waxen condor]

You want approx right ?

[brisk anchor]

I think exact

the question doesn't specify

[waxen condor]

,calc sqrt(11111111-2222)

[golden bramble]

You can find the exact value yeah

[jolly parrot]

Result:

3333

[waxen condor]

exact

[golden bramble]

well you’re not supposed to donate the answer

[brisk anchor]

how though

without a calculator

[golden bramble]

.

[waxen condor]

Yeah exact easily

[golden bramble]

Try thinking of factors that both 11111111 and 2222 have

[waxen condor]

First factor comes 1111 so take it out

Then subtract

Then think again

[brisk anchor]

Take out?

[waxen condor]

1111(a-b)

This kind of form

[waxen condor]

Keep it inside root

[brisk anchor]

oh

ok

[waxen condor]

I was just checking bro (sry)

[pearl pond]

@brisk anchor Has your question been resolved?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime token]

How does one approach this question?

[west sapphire]

you can rephrase it in terms of a matrix equation

[sharp vigil]

we want to find out if there are scalars $k_i$ that solve the equation [ k_1 \vb v_1 + k_2 \vb v_2 + k_3 \vb v_3 + k_4 \vb v_4 = \vb b ] note that by setting components equal we get a system of linear equations, which as bungo mentioned can be formulated as a single matrix equation

[jolly parrot]

cloud

[prime token]

Variables v1234

Four variables, four equations

How about for the span of u?

Why is it an empty set?

[glass meadow]

The span of {u1,u2,u3,u4} is not the empty set, the set of
conditions is.

[prime token]

oh oops

There are no restrictions on a,b,c,d

[glass meadow]

Correct

[pearl pond]

@prime token Has your question been resolved?

[prime token]

.close

[pearl pond]

Channel closed

Closed by @prime token

Use .reopen if this was a mistake.

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tardy stream]

hi

[pearl pond]

@tardy stream Has your question been resolved?

[hot thunder]

So is (c) asking for this angle here?

[pearl pond]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[hot thunder]

Oh wow, really? Just after I respond xd

[tardy stream]

.reopen

[pearl pond]

✅

[tardy stream]

yea

[pearl pond]

@tardy stream Has your question been resolved?

[tardy stream]

.close

[pearl pond]

Channel closed

Closed by @tardy stream

Use .reopen if this was a mistake.

[hot thunder]

@tardy stream Did you figure it out?

[tardy stream]

yeah

thanks

[pearl pond]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pearl pond]

@carmine solar Has your question been resolved?

[pearl pond]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.