sorry for the waiting lol
#help-39
midnight edge
uh
pearl pondBOT
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@midnight edge Has your question been resolved?
midnight edge
<@&286206848099549185> uh anyone?
vernal grove
my answers r correct?
Just making sure because im confused if its open brackets or close brackets. because my prof solved a similiar question in class and had the bound in open brackets.
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spice condor
Let N be the number of complex numbersa
z with the properties that |z| = 1 and z^6! − z^5!
is a real number. Find the remainder when N is divided by 1000.
spice condor
z=e^itheta?
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gritty tundra
yo guys how do i get banned?
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frail hawk
what is the question?
spice condor
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jolly parrotBOT
Incrypter
sharp smelt
sign analysis ?
acoustic path
there's something you should do before factoring out the x
acoustic path
sign analysis ?
yes you analyze the signs
make your own help channel (like #help-18)
subtract 12 from both sides
i'm assuming you know what "sign analysis" means since you're doing a problem that asks you to use it
oh ok
then continue and show me what u can get and i can tell/hint u what to do if needed
jagged burrow
\leq instead of <=
acoustic path
yes good
radiant terrace
Asking for help on quizzes and tests is against the rules
acoustic path
when the problem says "sign analysis" what it wants you to do is consider the signs of the factors
at different intervals of x
you consider the signs of the factors are different intervals of x
can you tell me which intervals you should consider for this problem? or does this not make sense so far
basically, what we want to make note of here is that the numerical values of (x + 3), (x + 2), and (x - 2) don't actually matter
our inequality only states that the product of these values must be less than (or equal to) 0
for this to be true, we need to have that the signs of these factors must be + + - or - - -
pretty much yes that's the idea
jolly parrotBOT
Incrypter
acoustic path
yep nice
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dusky turret
why is the 3Cxe^3x from the y'p not included in the final equation?
thin sigil
Can you show us the original equation?
pearl pondBOT
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night slate
pearl pondBOT
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rough python
Hello. There's a fundamental piece of knowledge I just feel weirdly uncertain about.
Invertible matrices.
"If A is a square matrix, then if A is invertible, every equation Ax = b has one and only one solution."
So to double-check my understanding, if A was a 2x2 invertible matrix, then if b was any 2x1 matrix, there will always be one and only one solution, for every b, correct? **As long as ** A is invertible? Or can it be possible that an invertible matrix will have none or multiple solutions?
rough python
It might be very basic, but my brain just can't seem to accept that it's true, but fundamentally it makes sense
I just need more time I assume
rough stream
You start with Ax = b
Left-multiply both sides by A^-1 to get the solution
x = A^(-1)b
That's if A^(-1) exists of course
knotty shoal
This is one of the questions on the AP Precalc practice exams, and I know the answer is D, I just don’t know how to get to it as I was never taught about this topic
woeful stump
(i don't know the exact terms but i see what's going on here so bear with me)
we can agree plot 2 is a better fit, right?
knotty shoal
honestly i got no clue
i was never taught anything about these plots before
but i know that residuals and stuff maps the difference of actual vs predicted graphs
woeful stump
yeah
and a residual of 0 means the prediction matches perfectly - there's 0 distance between them
woeful stump
mhm
young mural
You can see from the data and your annotations it's an exponential model. In its simplest form, regression is the straight line distance from a given point x,y to the equivalent point on the exponential graph, in this case
The regression which is most closely to its predicted has to be the exponential one in this case
Since you know the data follows an exponential pattern
knotty shoal
oh ok yeah that makes sense
so basically it cant be linear cause the outputs aren't linear and it cant be plot 1 cause it doesnt match perfectly
young mural
Yep, although technically you're not worried about it matching perfectly for this question
You want the one which is closest to perfect
It just happens that in this case it is perfect
knotty shoal
yeah
woeful stump
true, specifically they ask which is "more appropriate"
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wheat cape
What's the meaning of dimA?
pearl pondBOT
What's the meaning of dimA?
wheat cape
I know the rest only dim
pearl pondBOT
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fringe torrent
DRAKE?!
bitter lynx
fringe torrent
no idea
pearl pondBOT
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wary sigil
When does the equality Var(X⋅Y)=Var(X)⋅Var(Y) hold?
pearl pondBOT
When does the equality Var(X⋅Y)=Var(X)⋅Var(Y) hold?
@wary sigil Has your question been resolved?
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timid viper
Does anybody know how to answer this?
pearl pondBOT
Does anybody know how to answer this?
steel canopy
Slope of f(x) is differential of f(x)
unkempt yacht
Does anybody know how to answer this?
are you familiar with the concept of derivative?
tepid ravine
Assuming I'm looking for this determinant, the notes do the following:
https://imgur.com/K45sGLU
Can someone explain why we cannot just do
R2: R2 - R3
R3 :R3 - R4
and so on?
tepid ravine
The diagonal is then lambda and lambda + 1 all the way through
I realized my mistake 🙏
the last row remains a mess
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stoic siren
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stoic siren
how do i calculate precentage
fossil jewel
Did you get a and b
clever pewter
how do i calculate precentage
S(after)/S(before) . 100
stoic siren
Did you get a and b
oh no i was talking about percentage increase of surface area
i think i know how to do 1.1r 😭
stoic siren
S(after)/S(before) . 100
ty
clever pewter
np
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vast holly
I got asked to plot atan2(y,x) on U. How do I do that?
pearl pondBOT
I got asked to plot atan2(y,x) on U. How do I do that?
vast holly
U is just a circle in 2d space
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vast holly
<@&286206848099549185>
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upbeat cosmos
upbeat cosmos
comment on sait quelle boule on
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hasty hamlet
how to prove that if x=-y=-z and x+y+z=3, then there is no solution
x,y,z are in R*
marble sonnet
So it not true then
(-3,3,3) Is a solution
hasty hamlet
oh I'm dumbass
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spare wyvern
Chris works in a supermarket. He earns €318.45 per month. On January 1st, he receives a salary increase. He now earns €349.25. By what percentage has his salary increased?
meager kettle
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muted nimbus
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muted nimbus
if we simplify the given condition we come to eqn that r^2 + s^2 = -rs
through which we can cocclude that either one of r or s is negative and (r/s)^3 is negative
but when further manipulate the condition we arrive at the answer which is positive
lemm post that too
what we have here is we have manipulated the eqn to form a quadratic (of r/s) then considering r/s as x and making another eqn x^2+x+1=0 and puuting it in the a^3-b^3 identity to find x^3 which is needed
any help will be appreciated thank you
autumn topaz
what video is that from?
muted nimbus
autumn topaz
I don't know if their solution is correct, but I can't see any mistake they make
muted nimbus
like did you get what i am trying to say why it shouls be -ve
???
i also had a doubt that when she arrives to the eqn x^2+x+1=0 we get two values of x and each one might have two different values of x^3
autumn topaz
it actually has no real solutions
muted nimbus
yes correct
muted nimbus
thanks man you tried!
autumn topaz
the way I approached it was to isolate 1 / s, then just multiply that expression by r
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quiet kernel
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quiet kernel
Can someone explain why you can’t use LH rule for #1 but you can for #2. Like I get that #1 is an asymptote now that I see the answer, but how should I know that
quiet kernel
Whats an indererminate form
last summit
quiet kernel
Ohhhh
Because it’s not 0/0
And then how do I know its infinity and not negative infinity
@last summit
last summit
<@779131727338930196>
x is approaching 2 from the left
cinder flower
https://byjus.com/maths/indeterminate-forms/#:~:text=The%20indeterminate%20form%...
lmao
cinder flower
nothing
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steady fractal
terbium (Tb) metal has an electron binding energy of 289.5 kJ mol-1. calculate the energy of electrons ejected (in kj mol-1) from a terbium surface by the above photons.
marble sonnet
And the above photons ?
marble sonnet
terbium (Tb) metal has an electron binding energy of 289.5 kJ mol-1. calculate t...
You didn't give complete information
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midnight haven
If P(A) = 0.5, P(A u B) = 0.7 and P(B) = 0.4, the value of P(A n B) is?
midnight haven
I know the answer is 0.2
But not sure how they got that answer
Multiplying 0.5 by 0.4 does give 0.2, but I'm not sure why you would multiply it
wet osprey
Do you know about the inclusion exclusion principle
midnight haven
Not that I remember, no lol
wet osprey
If you draw a Venn diagram
And label the 2 circles A and B
The entire A (including the intersection with B) is 0.5
Similarly 0.4 for B and its intersect with A
And then the A ∪ B is 0.7
midnight haven
The entire A (including the intersection with B) is 0.5
How would the intersection be 0.5?
midnight haven
I'm confused as to why, I mean in venn diagrams the overlap is what both of the things have in common, right?
wet osprey
Yes
But if I ask what’s in A
You include the overlap
I didn’t say anything about B
I just said it needs to be in A
Now when I add A and B together do you see that we overcount the overlap?
We counted the overlap individual both in A and in B
midnight haven
I'm more confused 
wet osprey
😭
midnight haven
Why are we adding A and B
What do you mean overcount the overlap
What does the word overcount mean
wet osprey
Ok have a look at this
Yellow is P(A)
Red is P(B)
Green is P(A ∪ B)
Blue is P(A ∩ B)
Does this make sense?
midnight haven
I just looked in my notes that I totally forget. Hahaha. There's a formula for this! 
P(A u B) = P(A) + P(B) - P(A n B) which gives me the answer.
wet osprey
Well yeah, but where does that formula come from
midnight haven
The mathematicians 
wet osprey
If you look at this, you can see that yellow + red = green + blue
worthy edge
wet osprey
Because the middle part “got counted twice” when you do yellow + red
midnight haven
Data management
wet osprey
This is probability
midnight haven
The course name is Data Management, but this is probability yes
midnight haven
If you look at this, you can see that yellow + red = green + blue
But green covers everything, why does it need blue
midnight haven
Ohhhh
wet osprey
This is called the inclusion exclusion principle
You count everything separately, then take away the overlaps
midnight haven
Isn't taught in my course aha 
I think they just expect you to use the formula. Nonetheless, thank you for the help! 
.close
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brave badge
If there are two defined vectors in the 3D space namely v, u, and two arbitrary constants c, d, then it is possible to fill the whole 3D space with the linear combination of cv + du by selecting different values for c, d?
rancid rune
no
brave badge
Can you explain why
rancid rune
i cant
i just know that the dimension span of n vectors is at most n
it's not something ive ever questioned or needed to prove but ill try and find something
timid spindle
just take an example, can you reach (0,0,1) using linear combinations of (1,0,0) and (0,1,0)?
brave badge
just take an example, can you reach (0,0,1) using linear combinations of (1,0,0...
That makes a point
Thx
Oh wait
rancid rune
1 counterexample doesn't remove the possibility of a solution
brave badge
I mean, if you have a vector (1,1,0) and another (0,1,1), couldn't you make the whole 3d plane with that? like
brave badge
Take these planes. These are all the positions that these vectors could take (in their respective plane). So if you position one on top of the other, wont you fill the whole 3D plane?
brave badge
cannot be written as a linear combination of those 2
Oh that makes sense yeah
I think I'm being way too geometrical here
rancid rune
Take these planes. These are all the positions that these vectors could take (in...
im confused by this
2 planes are described by 4 seperate vectors, since each plane is dimension 2 (meaning 2 vectors each)
rancid rune
it's kind of intuitive
brave badge
Yeahh
rancid rune
3 dimensions are 3 degrees of freedom
brave badge
I thought that with one vec you could make a plane, don't ask me why
rancid rune
xD
nah it's good that you are looking for intuition
most people just accept it and move on
questioning concepts makes your understanding better
brave badge
Yeah! Thanks for that :)
rancid rune
i hope someone else can provide a more intuitive answer tbh. i felt like i didnt explain much
brave badge
No no, I really get what you've said by your statement about creating planes
What I was imagining was that with only one vec, you could move in a whole plane, whereas you can only move around a "straight 3D line"
So then I thought that if one vec makes you able to move between a whole plane, then why not with two vecs
But that was a big missconcept xD
Thank you very much :)
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sand garden
These numbers would be too big so I think I'm doing wrong, where is my error?
pearl pondBOT
These numbers would be too big so I think I'm doing wrong, where is my error?
@sand garden Has your question been resolved?
sand garden
<@&286206848099549185>
lime jungle
<@&286206848099549185>
What is this exactly?
sand garden
So i need to find the value of x
lime jungle
Ok
sand garden
knowing that thw hole thing is supposed to give me 6000
thing is, that what im trying to do would give me numbers that would be too big
i think that the prcess im doing is correct but im messing up somwhere
the operation i posted is incomplete, because just putting e30*500 makes my calculator give up
lime jungle
the operation i posted is incomplete, because just putting e30*500 makes my calc...
e30*500 = 15000e
pearl pondBOT
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sand garden
.
mystic blaze
you could’ve done from e^30 = 400 / (500 - x) => 500 - x = 400 / e^30
then x = 500 - (400 / e^30)
mystic blaze
the thing is that 400 / e^30 is so incredibly small its almost zero so the value of x is closer to 500 then anything else
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midnight haven
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midnight haven
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quartz cosmos
you just need to apply length * breadth * height formula for volume
but convert the dimensions correctly
first
midnight haven
I don’t get it
quartz cosmos
its pi r^2 h for cylinder
r is radius that is 9 feet
and the question says it is 6 inches less than the total height of cylinder
that means 6inches =0.5 feet and hence height will be 4.5ft-0.5ft that is 4 ft
midnight haven
I don’t get the 6 inch part
waxen condor
@midnight haven what ?
midnight haven
This question
waxen condor
@quartz cosmos I am saying he is explaining something else
midnight haven
Can u explain?
quartz cosmos
I am saying that the container is filled upto a height of 4ft
as 6 inches are left from above..
quartz cosmos
6inches=0.5 feet
quartz cosmos
After that u have to subtract that height 0.5 ft from the actual height of cylinder
midnight haven
So 4.5-.5=4
quartz cosmos
yess
midnight haven
And after that what
midnight haven
Ohhhh now I get it
quartz cosmos
r=radius of cylinder
midnight haven
Thank you broski
quartz cosmos
Thank you broski
welcome
midnight haven
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wide oriole
is there any book to recommened me to read laplace transofmr and the frequency?
wide oriole
or source
autumn topaz
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golden scroll
im stuck on the next step do i divide or did i do something wrong before hand
golden scroll
its basically the first line
old marsh
ah ok
so heres the thing
to get from the first line to the second line, u differentiated both sides right?
golden scroll
yess
old marsh
but whats the derivative of "e+1" ?
golden scroll
e
old marsh
why?
old marsh
do u know what "e" is?
golden scroll
tbh no but i just know that e stays the same
midnight haven
therefore e = pi
jolly parrotBOT
old marsh
its a constant 2.718...
therefore, u have to differentiate it like you differentiate constants @golden scroll
golden scroll
so is it gonna be zero
old marsh
the reason you believe e stays the same is because ur referring to e^x, which does stay the same when differentiated, but this is just e
golden scroll
so e with exponents staya
and e itself is a constant
but e to the zero is one right
old marsh
so e with exponents staya
well u cant really generalize like this
old marsh
but e to the zero is one right
yes
for example
e^5 is a constant
e^-98 is a constant
even tho theres exponents
golden scroll
so if its variable
old marsh
yes basically, when we differentiate with respect to some variable "k", derivative of e^k = e^k
if we differentiate with respect to x, what is the derivative of e^pi @golden scroll ?
old marsh
no
old marsh
good
so now
if we differentiate with respect to pi, what is the derivative of e^pi ?
golden scroll
0
old marsh
pi not being a constant
golden scroll
oh wait e to the pi
old marsh
how about derivative of e^y, with respect to y
golden scroll
e to the y
jolly parrotBOT
old marsh
when we differentiate both sides what do we get
golden scroll
old marsh
ok, u still have 1 error
golden scroll
do i add dy/dx on to the e to the y
jolly parrotBOT
old marsh
we actually have to do product rule here
golden scroll
ohhh rightt
old marsh
so lmk what u get when doing that
old marsh
do i add dy/dx on to the e to the y
and this
golden scroll
subtract usually if its addition ubt its multiplying so divide butthat also means that ima divide the inside too to other side
old marsh
whats the answer
golden scroll
do i add them
old marsh
wdym by add
jolly parrotBOT
golden scroll
old marsh
no
get all terms without a dy/dx to one side and all terms with a dy/dx to the other side
that middle e^x e^y doesnt have a dy/dx attached to it
so u have to get it over
golden scroll
so subtract the e to the x and e to the y
old marsh
show me
jolly parrotBOT
old marsh
and then u can subtract
the e^x e^y from both sides
and then u get
$\frac {dy}{dx} (e^{x+y} + 2y) = - (1 + e^{x+y})$
jolly parrotBOT
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hollow saffron
Can someone explain why the following questions are wrong. The correct answer is in pink. #2 I had put what i thought the answers were for each option. #6 why is statement 1 true? #21 why is it C and not E? Can it never be option E? #18 I dont know where i went wrong
pearl pondBOT
Can someone explain why the following questions are wrong. The correct answer is...
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hollow saffron
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hollow saffron
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hollow pike
what does vertical position mean?
pearl pondBOT
what does vertical position mean?
thin sigil
Basically how high up it is
hollow pike
Basically how high up it is
so first one is 30 feet?
and the last is 270 feet?
but thats degrees
thin sigil
yeah that's degrees, you gotta convert the rotation of the windmill to the height of the point
hollow pike
yeah that's degrees, you gotta convert the rotation of the windmill to the heigh...
how?
making an equation?
thin sigil
yeah
thin sigil
Looks good to me
hollow pike
Looks good to me
even the f(theta)? shouldnt it be P(thetha)?
thin sigil
don't expect pretty numbers when dealing with sin
hollow pike
don't expect pretty numbers when dealing with sin
r u sure tho? i got 10sin(60)+20
,calc 10sin(60)+20
jolly parrotBOT
Result:
16.951893788978
yeah but is your calculator adjusted for degrees
hollow pike
i got 20+5sqrt root 3
hollow pike
yeah but is your calculator adjusted for degrees
well when i do sin(90) i get 1
so pretty sure
it is
thin sigil
,calc 10sin(pi/3)+20
jolly parrotBOT
Result:
28.660254037844
The following error occured while calculating:
Error: Syntax error in part "°)+20" (char 9)
thin sigil
,calc 10sin(60deg)+20
jolly parrotBOT
Result:
28.660254037844
see
hollow pike
@thin sigil i got this
thin sigil
Looks good
hollow pike
Looks good
but the 28.7 looks weird
thin sigil
yes
sin is weird
but it's correct
don't expect nice numbers in life
you'll be in for a lot of disappointment
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normal swan
someone help me out with the answers im stupid
pearl pondBOT
someone help me out with the answers im stupid
grave parcel
someone help me out with the answers im stupid
Honestly
I’m not really a maths expert, I’m a high school student
So I may be incorrect
@normal swan
If you need help still ping me I think I know it
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normal swan
If you need help still ping me I think I know it
@grave parcel
my bad i didnt see the notification till now
but yes
i need help
flint wyvern
pearl pondBOT
austere tinsel
Yeah that looks right to me
autumn topaz
weird question but yea
austere tinsel
I thought so too, is this for a CS course?
pearl pondBOT
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robust cape
I need help finding the axis of symmetry in this graph
pearl pondBOT
I need help finding the axis of symmetry in this graph
wicked mortar
Honestly, with this, I would just eyeball it
robust cape
lol, it says the answer is x = 1 but I don't see how that's close to being correct
robust cape
I don't understand it fully yet. I was led to believe the axis of symmetry is the point where the y axis crosses the vertex
fluid root
no
the axis of the symmetry would be whatever the x value of the vertex is
your vertex is somewhere around (1, 16)
robust cape
so do I choose a value anywhere from 1 to -16?
fluid root
yes
robust cape
so why is it 1 and no other value
wicked mortar
It's called an axis of symmetry because the parabola is symmetric over that line
Across what line does it look symmetric?
fluid root
thats where the vertex is
robust cape
"across what line does it look symmetric" to me, the X line.
I started this module about 30 minutes ago which is why this is confusing
fluid root
In a parabola, the axis of symmetry is essentially just the line that goes through the coordinate x of the vertex
It means that, if we were to draw a vertical line through the vertex, the 2 sides of the parabola would be symmetric
you can kinda see that with your eyes tbh
robust cape
the red line I drew is where 1 is on the graph. That's where I'm supposed to be looking?
wicked mortar
You're looking at the vertical line through that point
robust cape
then that is 1 on the y axis
wicked mortar
the red line I drew is where 1 is on the graph. That's where I'm supposed to be ...
The line through it
Not a point
robust cape
OH
my god
ok
that makes sense
so it's the line that goes through the highest/lowest point in the parabola right
fluid root
you're welcome
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stray spruce
Could I get a step by step explanation with answer
pearl pondBOT
Could I get a step by step explanation with answer
@stray spruce Has your question been resolved?
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visual canyon
pearl pondBOT
visual canyon
how did i do explaining?
ive included q2 because im iffy about my notation
would i be better off just pasting symbols instead?
Sn
oh
pasting doesnt work
well would I be better off just typing it normally?
pearl pondBOT
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plucky wing
how do i do any of these
pearl pondBOT
how do i do any of these
celest hatch
@plucky wing do you have your unit circle with u
plucky wing
wdym
plucky wing
celest hatch
hmm
i dont think thats the right one
one second
okay so we have this
do you know what cot is equal to?
plucky wing
sin/cos i think
celest hatch
yes the second one
if you simplify it you get cos/sin
so now we have cot = cos/sin
what a is asking is what angle (in radians im assuming) on the unit circle does cos/sin = root 3
cosine is the x value, sin is the y value
plucky wing
wait wdym by simplifying gives us cos/sin
plucky wing
ok
celest hatch
okay so we know that cos = x and sin = y now
so basically its x/y = root 3
where on the unit circle does it give us that answer?
plucky wing
maybe im just not looking hard enough but idk
celest hatch
do you see the coordinates on the circle
if you put x over y and then simplify it, where do you get root 3
(look at pi/6)
so pi/6 and 4pi/3 is your answer
but idk if ur teacher wants 2 answers
plucky wing
i dont think so
plucky wing
the way my teacher told us to do stuff like this was with these special triangles or something like that
do yk what i mean by special triangles or is that just a thing from my teacher
celest hatch
ohh ik what u mean
LOWK its been shch a long time since ive done special right triangles rhat i just do it this way
because its easier for me
plucky wing
this stuff
plucky wing
how do i get the answer using those triangles tho
or do i have to use the unit circle
plucky wing
how do i know which angle i use tho
cuz obv since its root 3 its gonna be on the second triangle but theres 2 angles
do i find sin and cos of 30 or 60
celest hatch
hmm
you could try both ways and see id you end up getting the samw answer
ik its a lot of work
plucky wing
yea but wouldnt the angle i need to use be different for different questions
celest hatch
yes but im saying that you could try using cos/sin of 30 vs cos/sin of 60 and see if u get the same answer
because idk if it matters
celest hatch
oh doing it from 60 wouldnt work anyways cause u dont get root 3
i think you have to guess and check the angle
plucky wing
yea i was gonna say wouldnt it have to be 30
celest hatch
ye
plucky wing
how do i do any of these
how do i do the other 2 questions
celest hatch
i have to sleep but follow the method from 1
csc is equal to
1/sin
find sin
multiply by root 3
what angle = 2
plucky wing
30
celest hatch
3 find cosine, multiply by 3, add 1 find rhe angle that equals 0
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low lake
What happens in the very last step when they let x-> infinity? Im confused how they ended up on 0
plush oriole
A pro tip
Normally for these questions
Look at the highest powers
In both the numerator and the denomenator
As x approaches infinity the dominant terms would be the ones of highest power
Which is x^2 in both the numerator and denomenator
low lake
what do you mean by dominant terms?
plush oriole
x^2 grows a lot faster than x, do you agree?
low lake
yes
plush oriole
Right, so the terms with x^2 is the dominant term
plush oriole
Since they are growing so slow compared to x^2
midnight haven
yea
low lake
So i just disregard the 2 other terms in the numerator and demonator right?
plush oriole
It gives us the answer of 3/5 immediately
midnight haven
So i just disregard the 2 other terms in the numerator and demonator right?
yea
plush oriole
So, consider the limit as x approaches infinity of 3x^2/5x^2
midnight haven
So i just disregard the 2 other terms in the numerator and demonator right?
for limits
plush oriole
Which just gives us 3/5
low lake
Ohhh i see
low lake
yes
low lake
yes
plush oriole
Consider 1/100. What is this?
midnight haven
We are trying to find why limit as x approaches infinity of 1/x is 0
from the positive side
right?
plush oriole
It would be 0.01
midnight haven
from negative is -inf
plush oriole
Then as x gets larger and larger
Consider 1/100000000000
It would be so so close to 0
Do you agree?
low lake
Yes
plush oriole
So basically it approaches 0, which is the definition of a limit.
low lake
oooohhhhh i see
low lake
that makes a lot more sense thank you
plush oriole
np.
The same goes for 1/x^2...
Which also goes to 0
Same logic
You now understand this one right?
@low lake
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delicate jasper
pls help with this
pearl pondBOT
pls help with this
opal yoke
hiii
topaz mica
pls help with this
are you familiar with the geometric distribution?
delicate jasper
are you familiar with the geometric distribution?
yeah i do just fogot a lil bit
opal yoke
nvm bye
topaz mica
i recommend watching a video on it to refresh your memory
is this high school statistics?
delicate jasper
i recommend watching a video on it to refresh your memory
i mean i can get it just forgot the formula
but how is this related to gd
topaz mica
geometric distribution is for the amount of trials until a success correct?
for example flipping a coin until you get a heads
delicate jasper
geometric distribution is for the amount of trials until a success correct?
yes yes i got it confused geometric progression
how do i solve this
topaz mica
dyk the formula for the expected value of a geometric distribution
and the formula for the variance
you just plug in values for those
versed mica
expected value is just the mean
delicate jasper
yeah so 1/p?
topaz mica
and rather than p = 4/5 as the probability of a success we are looking at p = 1/5 as the probability of success
yes
delicate jasper
so expected is 5?
topaz mica
should be
versed mica
and do you know the formula for standard deviation
delicate jasper
and vairance is (1-1/5 )/(1/5)^2
delicate jasper
and do you know the formula for standard deviation
yes but idk how to show in discord
topaz mica
i want to know why 1/5 is taken as p
because we are looking for the first time they fail the free throw
versed mica
yea the "success" would actually be them failing
topaz mica
thus meaning the probability of "success" (p) is the first time we miss the free trow
topaz mica
👍
delicate jasper
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round cloak
how can i show that all the functions from R to N have cardinality of beth 2 ?
pearl pondBOT
how can i show that all the functions from R to N have cardinality of beth 2 ?
@round cloak Has your question been resolved?
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@round cloak Has your question been resolved?
untold pebble
help please
pearl pondBOT
help please
untold pebble
im pretty sure i have to use the formula n+k-1 choose n but i dont know how
vestal tapir
yes
you have to put 18 balls into 5 bins, assuming that's what they mean, that the blanks can't be last or first
you just literally take 10 blanks to put them between the letters first
only 8 blanks remain for you to decide on
n and k are 8 and 5 and you use the formula
oh and there's a catch that you need to permute the symbols too
untold pebble
you have to put 18 balls into 5 bins, assuming that's what they mean, that the b...
so in the stars and bars method
the 18 blanks would be the bars and the 6 symbols would be the stars?
untold pebble
ok so 5 symbols
untold pebble
im getting all wrong 😦
vestal tapir
if we decided that we have 4 bars, then k−1 = 4
untold pebble
because k−1 is the number of bars
isnt it k-2
vestal tapir
no
untold pebble
6 symbols turn into 4
vestal tapir
the formula doesn't know that we turned 6 symbols into 4
if there was no restrictions on that
untold pebble
oh okay
vestal tapir
7 is options you have
untold pebble
i would have said 24 choose 5
vestal tapir
6 bars represent 7 options
top is when blanks can be outside
7 rectangles can contain blanks
we remove 2 bars and 2 rectangles
k−1 would be 6
k−1 is now 4
vestal tapir
it would be right but there's no formula for this
if there was a formula, you could do this
untold pebble
okay
vestal tapir
well it shows that we have 5 options for the blanks, so that's exactly how to do it
untold pebble
yes
vestal tapir
we use n+k-1 choose n
where k is 5
k−1 = 4 bars
i mean, that's it, you solved that part
now n was 18, and we set it to 8 instead
for each of 5 BLANKS two blanks are used up
pearl pondBOT
@untold pebble Has your question been resolved?
untold pebble
for each of 5 BLANKS two blanks are used up
thanks for helping but i am too stupid to get it
thanks anyway
.close
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Available help channel!
wheat siren
What's wrong with this? The answer is 1+sqrt(6) but I'm not getting close to that when I find my mod zp
pearl pondBOT
What's wrong with this? The answer is 1+sqrt(6) but I'm not getting close to tha...
@wheat siren Has your question been resolved?
pearl jewel
Do you have the full original question?
pearl pondBOT
@wheat siren Has your question been resolved?
balmy scaffold
did i do this correctly
pearl pondBOT
did i do this correctly
balmy scaffold
and where can i check my results
balmy scaffold
what is the question?
just to look for the area between the 2 functions within their intersections
balmy scaffold
does it also say what the area is?
balmy scaffold
why not -1 to 3 directly?
steel canopy
cuz one side is below x axis and other is above
steel canopy
cuz one side is below x axis and other is above
and below x, integral gives negatice value
so u are basically subtracting
balmy scaffold
i thought htat is why we use | |
violet tundra
i thought htat is why we use | |
you can use | | if you are using a calculator
by hand you shouldn’t
also note that some calculators cannot give an exact answer if you use | |
fallen drift
The first question is good, and the second question is wrong with the subtraction of two functions，fx-gx it should be -x²+2x+3
balmy scaffold
The first question is good, and the second question is wrong with the subtractio...
oh i messed up the +3 there
but is the rest of calculating it that way correct?
balmy scaffold
I came up with ten and two thirds
how
fallen drift
how
I think you miscalculated the last step
You used the absolute value sign, the plus or minus in it doesn't matter, but there's something wrong with the number
fallen drift
yes
grave parcel
Hi
grave parcel
Can I get help for question 9 and 10 thanks
I’m not to sure on how to do compass bearing trig
midnight haven
They way they represent the question is quite funny
grave parcel
They way they represent the question is quite funny
I know lol
Our teacher is trying to give us applied questions
cloud zephyr
I’m not to sure on how to do compass bearing trig
do you know how to find the angle given the true bearing of 125°?