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#help-39
pearl pondBOT
pearl pondBOT
Available help channel!
swift whale
i need help finding a point on a line of best fit on a calculator
pearl pondBOT
i need help finding a point on a line of best fit on a calculator
@swift whale Has your question been resolved?
prime token
so you have a line of best fit in the form
y = a + bx
and a point with co ordinates (u,v)
sub x = u and y = v
swift whale
sorry i'm still confused, im using a ti-84 calculator and i have to find a point on an exponential model using a table. i plotted all the points and made a line of best fit and now i need to find a specific point on the line of best fit. i tried trace and calc -> value but got nothing
woeful stump
!original would be nice
pearl pondBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
pearl pondBOT
Available help channel!
midnight haven
pearl pondBOT
midnight haven
1/1/10
sorry bout the double bars lmao
soooo
ik u gotta multiply it with 10/1 but why
ping me guys
merry remnant
when dividing fractions, you flip and multiply
in this case, you have (1/1) / (1/10) so that becomes (1/1) * (10/1)
leaden wadi
merry remnant
^Also a nice way to see it
leaden wadi
You multiply by the whole fraction, which itself is equal to one and an allowable math operation, to eliminate the fraction in the denominator.
leaden wadi
Do you mean "why do we multiply it with just 10/1"?
leaden wadi
Multiplying a value by it's reciprocal, aka multiplicative inverse, results in the value of 1.
leaden wadi
The goal in the math operation you are performing is to eliminate the fraction in the denominator. You do that by multiplying the term by the whole fraction, (1/a)/(1/a).
velvet meadow
@midnight haven
midnight haven
<@456226577798135808>
YAY thank u
midnight haven
The goal in the math operation you are performing is to eliminate the fraction i...
trueee
pearl pondBOT
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modern island
hello, ii just need to confirm whether im getting this concept. is this pi over 3?
modern island
from my understanding
it gotta be in the 1st and 4th quad
and the only y/x that'll equal that would be 1/2 x 2/2 over root 3
idk if im getting this concept well
cosmic charm
hello, ii just need to confirm whether im getting this concept. is this pi over ...
tan(pi/3) = sqrt(3)
modern island
what
wooden merlin
$\frac{\sqrt3}{3}=\frac{1}{\sqrt3}$
jolly parrotBOT
Good
modern island
my friend and i are disagreeing over this answer, i have 2 pi over 3 whilst he has pi over 6
midnight haven
my friend and i are disagreeing over this answer, i have 2 pi over 3 whilst he h...
both of you are wrong
modern island
to specify he got - pi over 6
midnight haven
then yeah he is right
modern island
how did u come to that answer
pearl pondBOT
modern island
.reopen
pearl pondBOT
✅
modern island
evaluate the thing inside out
hey one last quesion
is this - root 3
i simplified arccos to 5 pi over 6
sudden pumice
its -1/root3
modern island
was my first step wrong?
sudden pumice
it was correct
viscid sierra
i simplified arccos to 5 pi over 6
that is correct
however tan(5pi6) is not equal to -sqrt(3)
modern island
ok i just tried another
2root 3 over 3
i simplified inverse sin of -1/2 to pi/3
viscid sierra
i simplified inverse sin of -1/2 to pi/3
sin(pi/3) is not equal to -1/2
viscid sierra
still no
modern island
well theres two x's that = -1/2, how do i know which to choose?
viscid sierra
arcsin(x) has principal range [-pi/2,pi/2]
viscid sierra
well theres two x's that = -1/2, how do i know which to choose?
which two?
viscid sierra
erm
modern island
nothing in 1st quad can be negative
so it must be 4th quad
and the only y there thats -1/2 is 11pi over 6
viscid sierra
😭🙏
arcsin(x) can must be greater than -pi/2 and less than pi/2 or equal
,w 11pi/6 > pi/2
jolly parrotBOT
modern island
i hate this chapter bro wtf
isnt the limits quad 1 and 4?
11pi over 6 is literally inbetween pi/2 and -p/2
this doesnt make sense to me
someone please uncook me the exam is today
modern island
YO FUCK YOU IM RIGHT
U HAD ME STRESSING OVER NOTHING BRO WTF
😭
Someone ban this man
jolly parrotBOT
modern island
,w sec(arcsin(-1/2))
jolly parrotBOT
viscid sierra
it's isn't trustworthy
modern island
alr so what did i do wrong
viscid sierra
you may need to see a video about range of arcsin(x)
modern island
ok heres my thought process
lmk when i make a mistake
-1/2 of sin-1
we gotta find a y soemwhere in the pi/2 to -pi/2 range
cuz sin = y
11pi/6 = (root3/2, -1/2)
-1/2 = y that fits the parameters
now where in there did i get it wrong
wait -pi/6 legit = 11pi/6
oh shit u gotta find the smaller one
ohhhhhhhhhhhhhhhh
alr im attempting another
@viscid sierra
root 3 / 2
,w sin(arccos(1/2))
jolly parrotBOT
modern island
im actually so goated its crazy
viscid sierra
genshin impact
jolly parrotBOT
viscid sierra
cot(pi) is undefined
viscid sierra
🦊🦊👉
jolly parrotBOT
jolly parrotBOT
modern island
Yeah it just called me the goat
viscid sierra
x is goat🔥🔥
modern island
alr i think i uncooked myself
viscid sierra
WE LIVE IN CITIES🐺
modern island
one more for the road
viscid sierra
rule no 1 of sigmahood: sleep by 9:30 PM🙏🤺
modern island
hell nah bruh i got 4 aps
viscid sierra
in order to stay sigma and have the sigma rise inside you, you must follow all the rules of sigmahood🐺🔥
jolly parrotBOT
jolly parrotBOT
viscid sierra
IS IT -PI/4
-pi/4 isn't in the principal range of arcsec(x)
viscid sierra
that must be 3pi/4
modern island
wait cosine
viscid sierra
,w 3pi/4
jolly parrotBOT
viscid sierra
dogathan🔥🔥
modern island
nevermind i was being a silly billy
1 more to make up
this one goes out for the sigmas
viscid sierra
🙇♂️🙏
viscid sierra
rule no 2 of sigmahood: have at least 16 uncles
luxy im about to traumatize you for the rest of your life
trail shoal
This the default wifi password when new router arrives
modern island
uncle shirmaz, uncle rooz, uncle dadash, uncle arash x2, uncle uncle hos, uncle pey, uncle amin, uncle shirvan, uncle tehrani, uncle shahnoos, uncle peyman, uncle kosnet, uncle koobi, and finally uncle eshget
RIP Uncle Dadash 🙏 🕊️
viscid sierra
This the default wifi password when new router arrives
real🗣🙏
viscid sierra
RIP Uncle Dadash 🙏 🕊️
Uncles Dadash may rest in peace for he made significant contributions to the rare fish market🐺
viscid sierra
you have disappointed the sigmas🐺
modern island
chaturbate nation im sorry 😢
to repay the sigmas
is it pi/6
,w arccos(root3/2)
jolly parrotBOT
viscid sierra
<@773731789113786399> ive repaid the sigmas and im out
you've been expelled from the sigmawarts
alright
goobye
pearl pondBOT
modern island
fellow radiohead enjoyer spotted
viscid sierra
i love the strokes
"500 days of summer" typa quote
pearl pondBOT
Available help channel!
light whale
List these 3 numbers in order, from smaller to larger: 2^40, 3^28 and 4^19
light whale
i worked out that 2^40 is larger than 4^19, because 4^19 is basically 2^38, but I can't figure out whether 3^28 is larger or smaller than the other two numbers
<@&286206848099549185>
Pls help <@&286206848099549185>
this is my homework and it is due soon
i had other classes before this so I didn't have time
worthy lance
Do you know how much is 2^10?
worthy lance
Do it is not hard
worthy lance
Ok so
worthy lance
Do you agree that 2^40=1024 * 1024 * 1024 * 1024
pearl pondBOT
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fathom oasis
By Krull's theorem, every element of a ring belongs to some maximal ideal. Which maximal ideal of the ring of integers does 1 belong to?
fathom oasis
From what I understand all the maximal ideals are precisely those generated by a prime number
and none of them should contain 1 right?
Oh nevermind I misremembered the result, only non-invertible elements are necessarily contained in a maximal ideal
.close
pearl pondBOT
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wide sentinel
pls help
wide sentinel
this question is bugging me so much
hasty osprey
!xy
pearl pondBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
compact veldt
u should just ask the question
wide sentinel
yes
i rather show it
its kinda long
can i video share it?
in like a call
its kinda about lims and inf
?
its for an important exam
well...
thin sigil
wide sentinel
i much rather show it
lets assume we are dealing with a f(x) like this
and on the left side we can see it converges to zero at minus infinity,
now consider a y=k where k is equal or lower than zero.
we are asked how many times will it cross f(x)
is it right to say it will cross f(x) once at the right side, but when k is equal to zero it will cross it 2 times
1 at the right side when f(x) crossed the x axies and once at minus infinity????????
.close
pearl pondBOT
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Available help channel!
sharp smelt
$2yy'=e^{\frac{\left(x^2+y^2\right)}{x}}+\frac{\left(x^2+y^2\right)}{x}-2x$
jolly parrotBOT
ƒ(Why am. I here)=I don't Know
sharp smelt
how would I even start this
I would guess this is a homogenrous DE
maybe I just differentiate the options
,w $2yy'=e^{\frac{\left(x^2+y^2\right)}{x}}+\frac{\left(x^2+y^2\right)}{x}-2x$
jolly parrotBOT
Requested by physicsrocks
jolly parrotBOT
jewels!
sharp smelt
what
west vault
You can rewrite the equation as $\dv{x}(y^2 + x^2) = \exp \left ( \frac{x^2 + y^2}{x} \right ) + \frac{x^2 + y^2}{x}$
jolly parrotBOT
jewels!
west vault
substitution should be clear now
rancid rune
so if $u=(x^2+y^2) =>\frac{du}{dx} = e^{\frac{u}{x}} +\frac{u}{x}$
jolly parrotBOT
Obotron
rancid rune
yeah another sub should work now
im still shocked how u noticed that
sharp smelt
thanks so much
rancid rune
$2yy' = \dv{x}(y^2)$ and $2x = \dv{x}(x^2)$
this i mean
sharp smelt
really hope this doesn't bite me when I start uni
thanks again
both of you
.close
gleaming girder
hi, I need help, I literally have no idea how to solve this
Write the equation of the ellipse which has the points A(3, 12/5) and B((5/3)sqrt(5), 2).
I tried inserting the points into the ellipse's equation but it didn't work, how do I even start???
pearl pondBOT
hi, I need help, I literally have no idea how to solve this
> Write the equation...
Show your work, and if possible, explain where you are stuck.
gleaming girder
ok so they're not called A and B actually but let me show you just the points bc the textbook is in croatian
I tried inserting them into the equation of the ellipse, and tried solving for a and b, but it didn't work
so I'd like if it someone showed me from scratch
<@&286206848099549185>
pearl pondBOT
@gleaming girder Has your question been resolved?
midnight haven
hi, I need help, I literally have no idea how to solve this
> Write the equation...
are u sure that's the whole ques?
gleaming girder
are u sure that's the whole ques?
yes
midnight haven
ohhk
tardy shell
pearl pondBOT
@gleaming girder Has your question been resolved?
pearl pondBOT
@gleaming girder Has your question been resolved?
pearl pondBOT
@gleaming girder Has your question been resolved?
pearl pondBOT
@gleaming girder Has your question been resolved?
strong helm
@gleaming girder
gleaming girder
<@785277458303811614>
omg thank you!
pearl pondBOT
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Available help channel!
brittle rain
What mistake am i making here?
pearl pondBOT
What mistake am i making here?
atomic ferry
theres no such rule
brittle rain
When solving the first line in the calculator the result is -0.56458
The second line solved in the calculator is -0.05693
atomic ferry
where u ln everything
dreamy ibex
a+b=c
ln(a+b)=lnc
u wrote lna + lnb = lnc
brittle rain
Okay, got it. I wrote that rule down aswell, i just didnt connect the dots
dreamy ibex
no problem!
pearl pondBOT
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Available help channel!
pulsar thorn
Need help with how to write the Binomial distribution notation onto google docs
for the n above the x part how would i write that in google docs? is there a format for it like a standard notation or would i just write (n x)?
atomic ferry
nCx
pearl pondBOT
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Available help channel!
regal sequoia
"6. Determine the circulation in two different ways
where ∂Ω is the counterclockwise stripe of Ω:
(a) partly directly, via parameterization of γ (b) by using Green's formula."
regal sequoia
i dont really understand the question or what i am supposed to do
can i use a formula here?
pearl pondBOT
@regal sequoia Has your question been resolved?
rough forge
I think you just need to apply now
Parameteization I think refers to the region Ω to use polar coordinates
regal sequoia
okay can i use polar coordinates like x= r cos theta?
r^2 cos^2 + 36r^2 sin^2 <= 36
rough forge
Wait
rough forge
r^2 cos^2 + 36r^2 sin^2 <= 36
not quiet
x^2+36y^2 <= 36 means you are integrating over an ellipse
rough forge
,,\dd x \dd y = a \cdot b \cdot r \cdot \dd r \dd \theta
jolly parrotBOT
𝔸dωn𝓲²s
rough forge
We can integrate over the ellipse region and then subtract the region with the line x+y-1
or not actually
so
Let's do it I guess
regal sequoia
do we need the bounds for r?
rough forge
yes
regal sequoia
and theta is between 0 and pi/2 right?
rough forge
,,\iint_\Omega f : \dd x \dd y = \int_0^{1} \int_{1-y}^{\sqrt{36-36y^2}} (Q_x'-P_y') : \dd x \dd y
jolly parrotBOT
𝔸dωn𝓲²s
rough forge
brb
regal sequoia
.close
pearl pondBOT
pearl pondBOT
Available help channel!
heavy latch
How does this question take that step?
pearl pondBOT
How does this question take that step?
heavy latch
Shouldn't you muiltply first?
worthy lance
Multiply what
heavy latch
The k(2k-1) * (2k+1)
jagged burrow
,, k(2k-1) + 3(2k+1) = 2k^2 - k + 6k + 3 = 2k^2 +5k + 3
jolly parrotBOT
nyxie9151
worthy lance
If you realize you have a [] there
heavy latch
But he just added those [], they aren't even supposed to be there
worthy lance
No
He factored out the (2x+1)
In the previous step there is a (2x+1)^2
He has (2x+1)(k(2x-1)) + 3(2x+1)^2
You factor out 2x+1 and get
(2x+1)(k(k-1) + 3(k+1))
Now you expand inside the second bracket and get
In which part u are lost
heavy latch
Even if you factored out the (2k + 1) from the (#)^2 shouldn't you still have the other terms (2k+1)(k(2x-1)
worthy lance
Yes, let do this in an easy one
Imagine u have ax + bx^2
U factor as x(a+bx)
Agree?
heavy latch
Yes
heavy latch
Ah yeah I see
Okay but once you have those factors out. Then you'll have (2k+1) (k(k-1) + 3(k+1)) which then you'll just solve inside the () which will lead to 2k^2 + 5k + 3. Right?
heavy latch
Then you factor the 2k^2 +5k + 3
Whats the fastest to factor that?
By just splitting up the 5k?
worthy lance
That depends on what u are used to use
U are not gonna like the way i factor out that
heavy latch
Hahah, I hate the splitting method because if the numbers are larger it gets harder to split
heavy latch
Uhmm might have forgotten
worthy lance
No but dont worry about that, splitting 5x into 2x+3x is really easy
heavy latch
No but dont worry about that, splitting 5x into 2x+3x is really easy
That's true. Anyways thanks for your help!
I appreciate it
.close
pearl pondBOT
pearl pondBOT
Available help channel!
pearl pondBOT
just tell me the asnwer
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
pearl pondBOT
@midnight haven Has your question been resolved?
marble sigil
f is basically stretching out the prime factorization in the numerator by squaring it to give all even exponents, then fitting the denominator into the odd exponents
eternal void
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silk oyster
if you have a large disk and a skinny pole that have the same amount of mass and you spin them up to the same RPM (measured from where the shaft connects to the object) would they take the same amount of time to stop rotating when a break is applied?
pearl pondBOT
if you have a large disk and a skinny pole that have the same amount of mass and...
@silk oyster Has your question been resolved?
sterile tusk
so when the breaks are applied, they will exert the same amount of torque on both the disk and the rod
jolly parrotBOT
y0shi
sterile tusk
so really we just need to compare which has the greater moment of inertia
the one that would have the greater moment of inertia (the disk) would have smaller angular acceleration, and hence would take longer to completely stop as both have the same angular velocity
pearl pondBOT
@silk oyster Has your question been resolved?
pearl pondBOT
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golden scroll
im not sure on how to start this problem
pearl pondBOT
im not sure on how to start this problem
golden scroll
snow sail
im not sure on how to start this problem
what course?
pearl pondBOT
@golden scroll Has your question been resolved?
wintry marlin
Confused on how to approach this exactly
pearl pondBOT
Confused on how to approach this exactly
unkempt yacht
$\int_a^b+\int_b^c=\int_a^c$
jolly parrotBOT
visual oak
they add up so you can do 10-1-5
wintry marlin
Ohhh yeah I got the first one = 4
visual oak
and then for the other one just make it negative and do it
wintry marlin
Wait, make which one negative
visual oak
like flip the bounds and reverse the sign
pearl pondBOT
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hexed folio
are there multiple ways to show r^2 = 2sin(2theta) as an implicit equation?
pearl pondBOT
are there multiple ways to show r^2 = 2sin(2theta) as an implicit equation?
@hexed folio Has your question been resolved?
rough stream
!xy
pearl pondBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
@hexed folio Has your question been resolved?
pearl pondBOT
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rich plinth
pearl pondBOT
steel canopy
substitution works
tall flint
t=1+x looks simpler to me
grizzled mesa
u/√u - 1/√u
tall flint
it will get complicated
not complicated at all
grizzled mesa
solve individually ig
rich plinth
u/√u - 1/√u
then integrate those?
grizzled mesa
yup
steel canopy
then integrate those?
oh yea tht works too
rich plinth
u/√u - 1/√u
how do i integrate u/sqrtu
grizzled mesa
u/√u = √u
grizzled mesa
u/√u = √u√u/√u
grizzled mesa
rationalize?
yea
rich plinth
o i forget
grizzled mesa
no worries
pearl pondBOT
@rich plinth Has your question been resolved?
dreamy ibex
I didn't quite get what you're tryna ask here
ohhh so what you're trying to say is
if you're given a collection sets, you want the collection to be such that their union does not exist?
well the union of any number of sets really just gives you all the elements of those sets such that each unique element shows up exactly once,ie no repetition of common values between them
say A= 1,2,3,4,5
B=2,6,7,8
AUB=1,2,3,4,5,6,7,8
notice how 2 didnt repeat
for the union of a collection of sets to not exist
each of those sets should be a null set
because then, the union of those sets would also be a null set
actually, that is still very much a valid set
it depends upon what you mean by the union of sets to not exist
say set A has all elements for which i^2= -10 (i is sqrt(-1))
and say set B has all elements for which i^3=100
now the union of these sets will not comply with each other, and neither do these sets exist in any practical mathematical sense
so, set A is a null set
set B is also a null set
and their union is also a null set
yup so it depends upon what you mean by the union of sets not existing
because a null set is very much a valid set, it is the set where the number of elements is 0, whatever the reason behind that may be
the reason can be have validity/invalidity/practicality/impracticality, but regardless the null set remains a comprehensible set
:D
pearl pondBOT
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hybrid haven
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pearl pondBOT
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primal fable
pearl pondBOT
pearl pondBOT
@primal fable Has your question been resolved?
primal fable
<@&286206848099549185>
dreamy ibex
are you familiar with the result of tan(A+B)?
primal fable
I know that exist, its just i dont know when to apply it
primal fable
are you familiar with the result of tan(A+B)?
Is the answer tan(2pi/3)?
dreamy ibex
I know that exist, its just i dont know when to apply it
sooo can you tell me how you would expand tan(A+B)?
primal fable
Why is it when I try to get an exact value of the expression it doesnt equal that
dreamy ibex
so the entire form can be reduced to tan(2pi/3)
primal fable
If the entire form can be reduced to that
dreamy ibex
and you can write tanx=sinx/cosx so there you have, your answer in the form tan, or sine and cosine
primal fable
If I were to find the tan of 2pi/3 and convert it to decimals why doesnt it equal the answer to the equation
dreamy ibex
u mean why does it not equal -sqrt3?
primal fable
Yeah
dreamy ibex
it is because they are irrational numbers
even if you try to approx them by converting into decimals
you'll always be off by a few
since they go infinitely long after the decimal points, calculators MUST need to approximate them to provide a 'GOOD ENOUGH' value
primal fable
Hmm
dreamy ibex
that's why when you substitute it back and convert it into decimals, you wouldn't get the same thing
if it were to converge to something like 1/2 or 1/3, then you would've been able to get your answers to match
primal fable
So if I were to get the exact value of the equation I should I just follow the simplified tan answer and represent the decimal version of that?
dreamy ibex
well u can represent in any way you would want to
it depends upon how you're supposed to represent it wherever you're supposed to submit an answer
but if you think about it, seeing the decimal representation of say, sqrt2, one wouldn't be entirely sure of what's it supposed to represent, however simply seeing a (sqrt2) would be enough to tell what you're talking about exactly
otherwise every representation is equally correct, but that's the thing about decimals and fractions when it comes to an irrational number, cuz neither can you write them as some a/b or in decimals with a meaningful pattern after the point
dreamy ibex
npp :D
dreamy ibex
mhmmm
primal fable
Alright
dreamy ibex
actually it would be better if you confine them to numbers but yeah
doesnt matter whichever is greater and/or smaller
primal fable
If the equation had negatives instead of positives would it still follow tan(a+b)
primal fable
actually it would be better if you confine them to numbers but yeah
Sorry another question
The message above it
Sorry
dreamy ibex
no problem, no problem
dreamy ibex
If the equation had negatives instead of positives would it still follow tan(a+b...
and no, it doesnt matter whatever the polarity may be, negatives positives are all fine
primal fable
Alright
primal fable
and no, it doesnt matter whatever the polarity may be, negatives positives are a...
Then simplifying it a little bit. The formula is tan a-b. If a was 5 and b was -8 . Would the equation become 5--8 then 5+8?
dreamy ibex
tan(a+b)= tanA+tanB/1-tanAtanB
put a=5 and b=-8
we get tan(-3) = tan(5)+tan(-8)/1-tan(5).tan(-8)
mighty light
how do i do this exactly on paper
pearl pondBOT
how do i do this exactly on paper
mighty light
like@what do i write there
golden hedge
You multiply each sides with (-1)
quick grail
what should i consider when substituting u and v when integrating by parts
quick grail
like which should i choose to be u
full agate
bro
LIATE
Usually works
90% times
In this order
Where
L logarithmic
I Inverse trigonometric
A Algebraical
T trigonometric
E exponential
pearl pondBOT
@quick grail Has your question been resolved?
quick grail
ill try thanks so much bro thanks
fast basalt
Okay so in this assignment you just have to integrate the function to get the answer. The question i have though is when i should use degrees and when i use radians
fleet delta
Use radians
fleet delta
No
fast basalt
The answer is 47 km^2
I get that with degrees but not with radians
Is the answer wrong then
?
midnight haven
uhmm no
but standard is radian like in most ques we use radian
instead of degree
midnight haven
Is the answer wrong then
idk if u calculated it right
light helm
show how you're getting that when working with degrees
pearl pondBOT
@fast basalt Has your question been resolved?
fast basalt
oh yeah whoops
pearl pondBOT
oh yeah whoops
fast basalt
minor mistake
viscid sierra
minor
fast basalt
.close
pearl prism
supple hill
frirst steps on how to solve the equation:
Define the variables. The variables in the equation are:
Alog TFP: The logarithm of total factor productivity
en(T): The natural logarithm of the time period
AT(i): The level of technology in sector i
N: The number of workers in the economy
α: The capital-labor ratio
Tg(i)t: The time spent working in sector i
JTg(i)t: The output of sector i
σ: The elasticity of substitution between capital and labor
Substitute the values of the parameters into the equation. The values of the parameters will need to be obtained from economic data or from assumptions.
Solve for the desired variable. The desired variable in the equation is Alog TFP. To solve for Alog TFP, you will need to use a technique such as substitution or elimination.
pearl pondBOT
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midnight haven
This isint really like help but is there any way to understand straight line graphs and all those other stuff (grade 8)
midnight haven
Got a exam on Sunday finna get cooked
sharp smelt
This isint really like help but is there any way to understand straight line gra...
watch khan academy
midnight haven
watch khan academy
I lowkey have for like the past few days it ain’t really helping much
It’s like i can’t understand it fully
sharp smelt
psot your doubts here
pearl pondBOT
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crimson apex
Which question?
midnight haven
48,49 52,53
crimson apex
48,49 52,53
Convert each eqn in slope intercept form
Then graph it
And the point where these two lines intersect will give u the solution
@midnight haven u got it?
$\frac{x}{a}+\frac{y}{b}= 1$
Where a is x intercept and b is y intercept
jolly parrotBOT
TᖇᗩᑎᔕᑭᗩᖇEᑎT ᔕᕼᗩᗪOᗯ
pearl pondBOT
@midnight haven Has your question been resolved?
midnight haven
$\frac{x}{a}+\frac{y}{b}= 1$
Where a is x intercept and b is y intercept
What this mean?
pearl pondBOT
What this mean?
crimson apex
What this mean?
Convert them into slope intercept form
For eg -3x + 4y = 12
Divide both sides by 12
And u will get x/-4 + y/3 = 1
midnight haven
I’m so cooked dawg I’m so lost
crimson apex
I’m so cooked dawg I’m so lost
See the eqn I sent u
There's a -4 below x so mark x = -4 on the graph similarly for y
@midnight haven u got it??
After u mark those two points make a straight line passing through the points
pearl pondBOT
@midnight haven Has your question been resolved?
midnight haven
how do i prove that the sum of an arithmetic sequence is (n(2a+(n-1)d)/2
pearl pondBOT
@midnight haven Has your question been resolved?
midnight haven
https://youtu.be/Uy_L8tnihDM
thankyou
pearl pondBOT
carmine root
Define the sequence {c_n} n in N given by
a) Show that {c_n, n in N} = {-1,0,1}.
Cn = [cos(√n)], n Є No
b) Determine the set of densification points for the sequence {n}ne No. [Of course, it must be proved that all the numbers listed are densification points and that none of the numbers not listed are].
carmine root
how do i do quesiton b
pearl pondBOT
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halcyon parrot
hello, a, b, c, and d are integers. how to prove that ad - bc divides a, b, c, and d simultaneously only if ad - bc = -1 or 1
visual yew
hello, a, b, c, and d are integers. how to prove that ad - bc divides a, b, c, a...
wdym simultaneously
as in divides adbc?
or divides a and b and c and d?
halcyon parrot
or divides a and b and c and d?
this
visual yew
ok
halcyon parrot
soooo
spark merlin
Same for all of them
visual yew
i mean ad-bc divides a
spark merlin
Yes
spark merlin
That’s what he write
halcyon parrot
a = (ad - bc)k1
b = (ad - bc)k2
c = (ad - bc)k3
d = (ad - bc)k4
visual yew
what how
spark merlin
Now try to make ad-bc
halcyon parrot
Now try to make ad-bc
to make it what?
spark merlin
To make it appear
halcyon parrot
ok
spark merlin
With the 4 equations
halcyon parrot
u mean i have to assemble the equations as one?
spark merlin
Exactly to recreate a new definition of ad-bc
visual yew
i don't get it
halcyon parrot
ok wait
visual yew
i was supposed to come here to teach but i am now learning
halcyon parrot
Exactly to recreate a new definition of ad-bc
i can multiply line 1 and line 4 and then line 2 and 3 and substract them that's what you mean?
spark merlin
i was supposed to come here to teach but i am now learning
Maths someday, you will teach. But first, learn, you have to
spark merlin
i can multiply line 1 and line 4 and then line 2 and 3 and substract them that's...
Yes exactly
halcyon parrot
ad = (ad - bc)²k1k4 and bc = (ad - bc)²k2k3
so ad - bc = (ad - bc)²k1k4 - (ad - bc)²k2k3
halcyon parrot
ad - bc = (k1k4 - k2k3)(ad - bc)² $\implies 1 = (k_1 \times k_4 - k_2 \times k_3)(ad - bc)$
jolly parrotBOT
abyssworld
spark merlin
Are you sure you can simplify?
halcyon parrot
to get rid of the square yes?
spark merlin
We can always simplify by a number like that ?
We don’t have to check something first ?
spark merlin
Is it tho ?
halcyon parrot
we assume it's not
spark merlin
Yes exactly, you need to specify that always
halcyon parrot
ok
visual yew
wait so
visual yew
what now?
visual yew
If you have the answer let abyssworld finish on his own
i don't
i'm wondering as well
spark merlin
Oh okay mb
halcyon parrot
so in the end, $\implies 1 = (k_1 \times k_4 - k_2 \times k_3)(ad - bc)$ means that ad - cd is 1 because an integer times an integer can only be 1 if they're both 1, isnt' it?
jolly parrotBOT
abyssworld
visual yew
i think i saw this question in some olympic exam
spark merlin
Almost yes
halcyon parrot
both 1 or -1
halcyon parrot
okk thank youuu 🙏
spark merlin
okk thank youuu 🙏
Nice work 👌
spark merlin
what's an integer?
It’s -1,1,2, etc..
visual yew
no 0.1?
spark merlin
But not 1/2, just whole number
halcyon parrot
.close
pearl pondBOT
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sudden pilot
could someone please help me with this
pearl pondBOT
could someone please help me with this
visual yew
what are you trying to understand?
sudden pilot
what are you trying to understand?
I don’t even know where to start
and i’ve watched videos and they’re so many different equations i’m just confused
sudden pilot
i just set the answer as incorrect so it shows the work done
i’ll just show you that
visual yew
oh i see
EGF is the length of the arc that is outside of the part given
In the solution they found the arc length of EF
So the arc length of EGF is everything the circumference of the circle minus the EF part outside of EGF
@sudden pilot
took me like 10 mins to understand this
I never knew how to count the length of the arc before lmao
uh?
pearl pondBOT
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pearl pondBOT
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tender cedar
for the sequence, find the limit points, for each of the limit points, find the subsequence...am I right in my approach..? Thanks for helping
marble gull
worldly glacier
pearl pondBOT
@tender cedar Has your question been resolved?
tender cedar
no
merry carbon
<@498630539197022228> Has your question been resolved?
React with ❌ to the bot @tender cedar
!nopdf also please
pearl pondBOT
Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.
tender cedar
for the sequence, find the limit points, for each of the limit points, find the subsequence...am I right in my approach..? Thanks for helping
rancid rose
I'm really struggling in trig, not sure how to even begin to solve
plush oriole
Try using sinx and cosx to simplify the fractions up
plush oriole
Yes
plush oriole
It’s tedious hahaha
grim fractal
Here's a better idea factor out the tan(x) from the first expression
And then change CSC and sec to sin and cos
rancid rose
Oh so I replace the tanx with a 1 over each one
Is this correct?
I probably should've shown my work better on getting tan^2x from the sinx/cosx • sinx/cosx
grim fractal
Not quite I think
rancid rose
Dangit
I'm lost on this one
Can you tell me where I made an error?
<@&286206848099549185>
pearl pondBOT
@rancid rose Has your question been resolved?
pearl pondBOT
@rancid rose Has your question been resolved?
rancid rose
<@&286206848099549185>
strong depot
It seems like you’re almost correct
For the first parenthesis, I see you got “tanx”
You took that result, multiplied it by the second parenthesis, and you obtained “tan^2 (x)”
Compare this to what you wrote as your final answer
rancid rose
Would the correct answer be tan^3x-sec^2x then?
rancid rose
It seems like you’re almost correct
.
pearl pondBOT
@rancid rose Has your question been resolved?
pearl pondBOT
@rancid rose Has your question been resolved?
midnight haven
I think the answer is -1
you have simplified the first parenthesis correct which is tanx
now the second one which is 1+tanx/1+cotx you can write tanx as sinx/cosx and cotx as cosx/sinx and by simplification you get tanx
so the final result is tan^2x
which is now tan^2 x - sec^2 x = -1
pearl pondBOT
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vestal tapir
pearl pondBOT
vestal tapir
is this wrong or what?
there's 8000 from below and there's 1000 from the gravity, why not 70 m/s²?
fossil herald
The contact force includes gravity I think
But anyways use Newton’s 2nd law
F = ma
pearl pondBOT
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Available help channel!
near otter
Can someone help me, I can see that dil f>= sup_x dil_x f but i'm having a bit of issue proving the other direction. Also what key metric makes it so that it works on R but not on S^1 while inheriting the R^2 metric
pearl pondBOT
Can someone help me, I can see that dil f>= sup_x dil_x f but i'm having a bit o...
@near otter Has your question been resolved?
pearl pondBOT
near otter
.reopen
near otter
.reopen
pearl pondBOT
✅
near otter
<@&286206848099549185>
pearl pondBOT
@near otter Has your question been resolved?
pearl pondBOT
@near otter Has your question been resolved?
pearl pondBOT
@near otter Has your question been resolved?
pearl pondBOT
@near otter Has your question been resolved?
near otter
?
near otter
u right
fluid root
Can someone help me, I can see that dil f>= sup_x dil_x f but i'm having a bit o...
Aak in math stack
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midnight haven
Find the domain of $\log_{\left[x+\frac{1}{x}\right]}|x^2-x-6|+^{16-x}\text{C}{2x-1}+^{20-3x}\text{P}{2x-5}$
jolly parrotBOT
yajat
midnight haven
my answer is $x={3,4,5}$ but the answer key says its $x={4,5}$
jolly parrotBOT
yajat
fair bramble
no your function is not defined for x=3
you cannot have a 0 inside the log function
substituting 3 into x^2-x-6 gives 0
fair bramble
no worries
midnight haven
.close
pearl pondBOT
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midnight edge
I'm studying the extremes of the following function and I'm required to use elevation curves: $f:A\to\mathbb R;|;f(x,y)=2x^2+y^2,A:={(x,y)\in\mathbb R^2;|;x^2+y^2\ge4,|x|\le4,|y|\le4}$
jolly parrotBOT
Leo, ze FluffBøt
midnight edge
I mapped out A on the xy plane (a square with side 8 centered at the origin with a circular hole of radius 2 in the middle) and noticed that in A we have no critical points
So the extreme points must lay on $\partial A$
jolly parrotBOT
Leo, ze FluffBøt
midnight edge
I found the general elevation curve: for $c>0,{x^2\over{c\over2}}+{y^2\over c}=1$
jolly parrotBOT
Leo, ze FluffBøt
pearl pondBOT
@midnight edge Has your question been resolved?
vivid grove
I found the general elevation curve: for $c>0,{x^2\over{c\over2}}+{y^2\over c}=1...
So what are you trying to do. I wouldn't use elevation curves to find extremums