help-39

[weak surge]

Am I missing one?

B should be included?

[tropic saddle]

why do you think that

[weak surge]

because i tried and it's wrong with C, D, E

.close

[pearl pond]

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[pearl pond]

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[pliant flare]

Hello, can someone tell me which channel would be the right one if i need a simple explanation of modulo in zero knowledge?

[hollow wadi]

dm me

I will help you

[midnight haven]

lol you can him here too

[pearl pond]

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[pearl pond]

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[bronze prism]

https://media.discordapp.net/attachments/903486478049488936/1223684892320202953/Screenshot_2024-03-30_at_10.56.47_PM.png?ex=661ac05d&is=66084b5d&hm=fd57b7060905f438c5f7c5478f11d4c088574d7ef292d0eb9eeb1ff84708c416&=&format=webp&quality=lossless&width=2160&height=276

[bronze prism]

<@&286206848099549185>

[tribal heart]

what

[bronze prism]

wha

[tribal heart]

u want help

?

[bronze prism]

.close

[pearl pond]

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[iron basin]

bruh

also wdym by doing it with triangles

[bronze prism]

its fine i got it

circles work

how would u calculate the area tho

j the middle arc part right

uMM

[iron basin]

im not sure of how to calculate are of segments without angle

but idk I'll see

[bronze prism]

oka

[iron basin]

i think this needs a calculator

[bronze prism]

yeah thats okay

we're allowed to use

[iron basin]

my idea for now

once we find theta its much easier to calculate area of one of the segments

[bronze prism]

what answer are u getting

@iron basin u can take the triangles horizontally

and then find the left angle and double it

and find area of segment

[pearl pond]

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[bronze prism]

.close

[eager coyote]

Is this assertation correct ?
" 'not(Q) => P' is equivalent to 'Q => not(P)' "

[fossil jewel]

No

[eager coyote]

How do you preove it ? any exemple ?

[fossil jewel]

If both q and p are true then the first is true and the second false

[pliant helm]

Is the move on the 4th line allowed

في حالة = in the case of

[gilded urchin]

this?

[pliant helm]

The problem was to solve the limit without lhopitals rule or taylor series

Cuz our curriculum is crap lol

But is such move allowed

[gilded urchin]

this is allowed

[eager coyote]

its not tho. We are assuming that Q and P are equations such as x>0

[pliant helm]

In math generally

Wait what happened

Did I post a question in an already in-use room?

Sry my internet tweakin

[eager coyote]

yes

nw

[pliant helm]

Oh well sorry for that

[eager coyote]

can you help me by any chance then

[pliant helm]

Imma try

What's the problem

[eager coyote]

its pinned

[fossil jewel]

Equations??

Can you send the original problem with full context

[eager coyote]

theres no original problem, it was a problem i stumbled upon by thinking

[eager coyote]

english not my first language so im not sure how to explain it

[fossil jewel]

Where did x come from

[pliant helm]

Yes

[fossil jewel]

No

You are wrong sorry

[pliant helm]

Why though

[fossil jewel]

Let me give an example maybe it will clear things up

“If it doesn’t snow tomorrow, the sun will rise”

True statement

However

“If it snows tomorrow, the sun will not rise”

False

[eager coyote]

ex : not ((x inferior or equal to 0) implies (x is superior to 0)) equivalent to( (x inferior or equals to 0 implies ) implies not(x superior to 0))

[fossil jewel]

Can you look up the definition of converse

[eager coyote]

it seams true but i cant be sure

[fossil jewel]

It is not true

You might be mistaking it for the contra positive

[eager coyote]

my english math language is crap so i may be making a mistake

[fossil jewel]

" 'not(Q) => P' is equivalent to 'not(P) => Q’ "

Does that make sense

[pliant helm]

I thought about it as a venn diagram where P U Q = the whole set, what's wrong about that, or am I very very dumb

[eager coyote]

for me it does

[fossil jewel]

This is true

[fossil jewel]

I just don’t think it’s helpful to think of it in Venn diagram form but you can

You should also consider the case when neither q nor p are true

Tho it doesn’t even matter for this problem

Because where it fails is when both q and p are true

[pliant helm]

Truuee

[fossil jewel]

not(falsee)

[pliant helm]

But when p and q are independent that previous statement is true

Right?

[spiral bear]

Hi, can any one help me, can i ask here?

[pliant helm]

There are empty help chat rooms you can go to and submit your question

[spiral bear]

Thx

[pliant helm]

Make sure they're not occupied like my dumbass

[eager coyote]

i searched it up, i dont really understand where do you think i have made a mistake

[fossil jewel]

what you are saying is that P => Q is the same as ~P => ~Q

I’m using ~ for not

[eager coyote]

but that is falsw

[fossil jewel]

What I’m saying is that this is not the case

Yes

[eager coyote]

and im not saying that neither

[fossil jewel]

You are basically saying that, just swap P with ~R for example

Then we have ~R => Q is the same as ~~R => ~Q

Which is R => ~Q

[eager coyote]

i have already tried that but i only fall on the same problem but in reverse

[fossil jewel]

Wait do you get what I’m saying

[fossil jewel]

I’m saying that this is identical to the original statement you said, and that both this and the original statement are false

Or at least not always true

What IS true is that P => Q means that ~Q => ~P

But that is very different from P => Q implying that ~P => ~Q

[eager coyote]

i dont get how R=> ~Q is false

srry im so lost

[fossil jewel]

Does this make sense

[eager coyote]

yes

i get this but i dont get how is this related to my satetement

[fossil jewel]

Okay let me type the same thing but instead of P I will use ~R

What IS true is that ~R => Q means that ~Q => R
But that is very different from ~R => Q implying that R => ~Q

[eager coyote]

ahhhh ok

i get it

thanks a lot

.close

[pearl pond]

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[fossil jewel]

👍👍👍

[pearl pond]

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[atomic wigeon]

Hi! How are you doing? I'm stuck in this particular problem since yesterday.

[atomic wigeon]

I've been trying to do it, and in the process of trying, I've found that:

• |1/x - 1/xo| = |(xo - x)/(x.xo)|
• Since |ab| = |a||b|, then |(xo - x)/(x . xo)| = |xo-x|/|x . xo|
• So now |xo-x|/|x . xo| < Epsilon

And that's where i'm stuck

[pearl pond]

@atomic wigeon Has your question been resolved?

[atomic wigeon]

<@&286206848099549185>

[pearl pond]

@atomic wigeon Has your question been resolved?

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[narrow flame]

Can someone explain how to simplify the congruence down so there is just x on the left

Please 🙏

[pearl pond]

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[midnight haven]

is this not 0?

[verbal whale]

It is 0, indeed

[midnight haven]

apparently it is DNE

[verbal whale]

Yeah because for x → -3^- the sqrt doesn't exist

[midnight haven]

ah I see

[verbal whale]

But usually the textbooks for high schools (at least mine using in my country) neglect this detail

In this case your book is more correct, yep

[finite jolt]

well, it is 0 if you consider it in the complex plane

[midnight haven]

you think I'll be able to negotiate this with my teacher?

😂

[finite jolt]

id say so

[midnight haven]

mm okay so tell me the idea then

[bold ledge]

it's not well defined though because it branches right

[finite jolt]

wym

[bold ledge]

is this a complex limit or a real limit of a complex function

[finite jolt]

dont know what you mean by "real limit of a complex function"

[bold ledge]

nvm

[finite jolt]

but i do mean the standard definition of a complex limit (approaching from a neighbourhood of points)

oh wait did you mean if i was just considering lhs and rhs limit?

[finite jolt]

the idea is that square root is a continuous function over the complex plane

and by definition, lim x->a f(x) = a when f(x) is continuous over a neighbourhood near A

wait

is it continuous at 0?

[midnight haven]

is all it says

[finite jolt]

hm

which branch of the square root are we considering

the positive or negative branch

[midnight haven]

I assume it's

the natural square root

so positive

otherwise there would be a negative

[pearl pond]

@midnight haven Has your question been resolved?

[finite jolt]

ok

after some research

i found that you cant argue your way out of this one

[pearl pond]

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[quartz tangle]

Would anybody know what the issue is with my submission?

[unkempt yacht]

how did you arrive to this answer?

[quartz tangle]

partial fractions

A = -8/9

B = 8/9

[sharp vigil]

it does say "use absolute values when appropriate"

[quartz tangle]

OHHH

LOL

Must be that

lemme see

[unkempt yacht]

yeah you are missing abs for the logs

but be sure to double check your numbers too

[quartz tangle]

Good now?

[quartz tangle]

alr

thanks guys!

.close

[pearl pond]

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[scarlet surge]

is this correct

[scarlet surge]

is this correct

i think i should be C(3,2). (8!/2!)

can somebody help me

got stuck dude

[sharp halo]

Can you post normally rotated pic once again? It's bit uneasy to understand

[eternal reef]

,rotate

[eternal reef]

there you go

[sharp halo]

The word is ampetheatre right?

[eternal reef]

PI ig

[sharp halo]

Ohk lemme try

I feel this might be one way to get the answer...?

[pearl pond]

@scarlet surge Has your question been resolved?

[pearl pond]

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[vapid harness]

How can I solve the 10th qus

[light helm]

what 10th question? img starts from 11

[pearl pond]

@vapid harness Has your question been resolved?

[unborn abyss]

,rccw

[vapid harness]

Can anyone tell me how can I solve this

[pearl pond]

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[toxic cliff]

I'm confused why we can solve for S with respect to y

I thought when we're rotating about the x axis, the y in S = s • pi integral (y ...) was f(x)

Additionally, I'm unsure where the 128y comes from

[pearl pond]

@toxic cliff Has your question been resolved?

[pearl pond]

@toxic cliff Has your question been resolved?

[pearl pond]

@toxic cliff Has your question been resolved?

[subtle shard]

shouldnt it be 2πx?

like 2π(5+4y²)

because if y = f(x), surface area of ​​rotation with respect to y: integrate 2πf(x)√(1+f`(x)²) x = a to b

here the function is 5+4y²

[toxic cliff]

Why is it with respect to y?

Isn't the radius f(x)? Aren't we computing the width with (5+4y^2)?

[subtle shard]

yes

so you will multiply with it

but

you multiplied it by y

itself

must be 5+4y²

do you understand it?

here we have a function x = f(y)

So we need to write f(y)

which is 5+4y²

[subtle shard]

instead of just "y"

but wait

it wants it to be rotated around the x axis

not y

why did we do it according to y?

[toxic cliff]

This was the key

Or was that a question for me

[subtle shard]

i dont know

it seemed wrong to me somehow

it's better if you ask someone else

i dont want to say anything sure

[pearl pond]

@toxic cliff Has your question been resolved?

[pearl pond]

@toxic cliff Has your question been resolved?

[pearl pond]

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[maiden rivet]

Find the moment of inertia $I_z=\int\int(x^2+y^2)\delta dA$ of the unit disk with density $\delta$ equal to the distance from the y-axis

[jolly parrot]

lena

[maiden rivet]

my prof used polar coordinates but i don't really understand how he did it :(

i used cartesian and got the wrong answer

oh wait nevermind i see what i did wrong woops </3

.close

[pearl pond]

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[mental verge]

Can someone tell me what are the other scenarios i got like nothing in mind

[pearl pond]

@mental verge Has your question been resolved?

[mental verge]

can someone also help me with this question as well? I dont want to interrupt two channels at once

I understood literally nothing from this question

Here’s my work though

<@&286206848099549185>

[pearl pond]

@mental verge Has your question been resolved?

[mental verge]

dude this is my channel

i havent closed the chat yet

<@&286206848099549185>

[pearl pond]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

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@mental verge Has your question been resolved?

[pearl pond]

@mental verge Has your question been resolved?

[pearl pond]

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[obtuse tendon]

hi

[pearl pond]

@midnight haven Has your question been resolved?

[pearl pond]

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[outer quarry]

hi could i get some help with binomial distribution? i don’t know what i’m doing wrong. i realised now it’s 50/20 and not 20/50, but i’m still getting really wrong and small answers when i put this into my calculator

[west sapphire]

should in fact be 50 choose 20, no?

not 50/20

[outer quarry]

choose?

sorry idk what that means 😭

[west sapphire]

$${50 \choose 20}$$

[jolly parrot]

Bungo

[west sapphire]

$$=\frac{50!}{20!30!}$$

[jolly parrot]

Bungo

[outer quarry]

i thought that was a messed up division symbol damn 😭

so how do i work with that? my math teacher just kinda threw the formula for binomial at us and didn’t really explain further

[west sapphire]

well it's a big number

but you're multiplying it by a small number

multiply them together and you get something reasonable

[outer quarry]

wait so is choose just a thing calculators have?

[west sapphire]

i assume some do

or you can use wolfram or whatever

[outer quarry]

i see

i’m just confused because i’m being expected to be able to do this on a test with only a basic scientific calculator

is that possible?

[west sapphire]

can you show the original question? maybe they're expecting you to make an approximation

[outer quarry]

yeah hold on

it’s part D

[pearl pond]

@outer quarry Has your question been resolved?

[pearl pond]

@outer quarry Has your question been resolved?

[pearl pond]

@outer quarry Has your question been resolved?

[outer quarry]

.close

[pearl pond]

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[pearl pond]

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[charred dome]

Idk how to plot the velocity of this graph…

[sharp tree]

How to plot velocity? The book plots it out for u

[charred dome]

I know this is wrong but idk how to get the first number

Like -5 and 5 are wrong

[sharp tree]

Oh

In term of function?

[charred dome]

Not plot I forgot what this is called my b

Yeah

[sharp tree]

The velocity change by t when 2 < t < 6 dude

v(t) should be a function of t

Not a constant

[charred dome]

i know that s what i am sdaying

i said it was wrong

idk how to do it

how do i figure out the function

[sharp tree]

Have u learnt abt function of line?

[charred dome]

yes but that was in beg of semester i just forgot

[sharp tree]

Here's a quick recap

Function of line look like this

y = ax

With coeff a called a slope of the function

[charred dome]

yes

[sharp tree]

a = 0; the function stay flat

a > 0; function goes up

[charred dome]

i am a bit tired so thats y i am having trouble

[sharp tree]

a < 0 function goes down

[charred dome]

yes i know that

[sharp tree]

a is defined as dy/dx

Thats all

[charred dome]

right now i am just trying to do the function parts

[sharp tree]

Do it then

a = dy/dx

[charred dome]

i forgot how lol

[sharp tree]

Find a

[charred dome]

that is the derivative

[sharp tree]

Nope

[charred dome]

a(t) = dv/dt

[sharp tree]

Not that...

Dude

[charred dome]

ok

dude

i am not evn on that patr

dude

[sharp tree]

BRUH DUDE

U've found a already

a = -5

[charred dome]

yes

[sharp tree]

.

[charred dome]

but what is the function

[sharp tree]

Just add t

[charred dome]

i can tell by judst looking at it

[sharp tree]

v(t) = -5t {2 < t < 6}

Thats all

Thats the function

😭

[charred dome]

wuh

hold up

i amtrying to figure out the thing i drew ok

[sharp tree]

this the answer

[charred dome]

the -5 is wrong and the 5 is worng

oh

i had that but erased it

[sharp tree]

-5 is correct though

The function goes down

[charred dome]

yea

[sharp tree]

So its negative

-5 is the slope

[charred dome]

but at 4 it is -5(4) that is -20

but it should be at 0 so it is messing me up

[sharp tree]

?

[charred dome]

look at the figure

at 4 sec vel = 0

[sharp tree]

OH im dumb

[charred dome]

yes

hah

[sharp tree]

Not v(t)

Lemme see

[charred dome]

see i told u i am not there yet

[sharp tree]

Oh nope

Im still right

[charred dome]

ok y

[sharp tree]

It should be

v(t) = -5(t-4)

@charred dome

[charred dome]

that is 20

[sharp tree]

U can shift the function

[charred dome]

ih

oh

u edited it

ok how did u get that

i need explanation

[sharp tree]

U shift it

[charred dome]

...

what

[sharp tree]

Imagine like this

-5 is the slope for the function

But we want at t = 4, the v(t) = 0

So just set (t-4)*slope

So at t = 4; its 0

And the slope stays the same

U can do the same with this

(t-8) * slope

[charred dome]

ok that is how you think of it but i need the real mathamatical way so i know what im doing cause not all the problems will be like tis

like show me the math

[sharp tree]

Its how its done my dude

[charred dome]

that doesnt ring a bell tbh

[sharp tree]

Function shifting?

Ur teacher doesnt teach it?

[charred dome]

we def did it a different way

ill have to check my notes

hold on

ok i found it

[sharp tree]

@charred dome

https://www.desmos.com/calculator/zhpjxnrewi

Take a look at this

[charred dome]

ok

[sharp tree]

see the a slider

[charred dome]

1 sec i wana see how he did it first so i dont get confused

[sharp tree]

Shift it around

[charred dome]

ok i get that that is a thing but we are not doing function shifting

and did not go over it

so ima have to pass big dawg

[sharp tree]

Take a pic of ur note?

[charred dome]

well this is determining the accel

[sharp tree]

I cant read it

😭

[charred dome]

how

[sharp tree]

Bruh

Your teacher method is the same of shifting

U just simplified it

[charred dome]

so simplify the one we're doing then

[sharp tree]

Instead of this, ur teacher just multiply all the term and get -5t + 20

Its the same thing but simplified

[charred dome]

?

can u show me the simplified version of the prob we areworking on then?

show the work

to get the function of 2<t<=6

im going to ask a helper cause idk what method you are doing., we need to do it like this sry

<@&286206848099549185>

[sharp tree]

HERE A STEP BY STEP TO SOLVE:

Step 1: Calculate the slope (u can do that already)

Step 2: We know a line function look like this y = ax + b

At point t=4; vt =0
so:
y = ax + b
we sub y = 0; a = -5 (slope);
0 = -5*4 + b

=> b = -20

ANSWER: v(t) = -5t - 20 { 2 < t < 6}

[pearl pond]

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[pearl pond]

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[broken estuary]

I tried method of undetermined coefficients and got y = e^t(c1cos(2t)+c2cos(2t))

[broken estuary]

but i cannot find the particular solution

[sterile tusk]

can you show your work?

[broken estuary]

yes one sec

[sterile tusk]

yeah so thats the homogeneous solution

what would be our guess for the particular solution?

[broken estuary]

i dont know since its e^t*cos(t)

if it was just e^t i would say et^t

[sterile tusk]

yeah so we would guess $Ate^tcos(2t)+Bte^tsin(2t)$

[jolly parrot]

y0shi

[sterile tusk]

because whenever we have sine, we have to have cosine

[broken estuary]

where are you getting the extra t in the general solution?

like the t next to the coefficients A and B

[sterile tusk]

since our general solutions are $C_{1}e^tcos(2t)+C_{2}e^tsin(2t)$

[jolly parrot]

y0shi

[sterile tusk]

we need to make sure we dont generate these solutions again

thats why we put an extra t

to avoid that

[broken estuary]

i see

ok, so to find Yc we would usually take the right side and go up to the nth derivative right?

and then subsitute that in

[sterile tusk]

yeah

[broken estuary]

but its e^t*cos(t)

[sterile tusk]

basically we just differentiate this

and plug it in to the differential equation

[broken estuary]

wait why that instead of the right side?

[sterile tusk]

well our guess for a particular solution is that

so we just have to find the coefficients thatll satisfy the differential equation

which means we need to differentiate it multiple times and then plug it in to solve for A and B

[broken estuary]

hmmm

im still very confused

[sterile tusk]

so when we use this method

we're guessing what our particular solution would be

[sterile tusk]

and in this case we guessed it to be this

but we still dont know what the coefficients are thatll make the equation true

which is why we differentiate this guess and try to plug it into the differential equation, in attempt to solve for A and B

[broken estuary]

i see

ok. can i ask another type of problem in the same help channel?

[sterile tusk]

is it related to this topic or no?

[broken estuary]

no

its variation of parameters

[sterile tusk]

oh yeah i know a bit of it but not too much

if you want others to help, maybe make a new channel to get more attention

[broken estuary]

ok

thanks!

[sterile tusk]

yw!

[pearl pond]

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[pearl pond]

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[crisp mango]

this is probably a stupid question

but how did they know the values of a3,a4, and a5

[regal herald]

just plug it into the formula

n=1 then a_3=2a_2-3a_1=22-15=7

etc

[crisp mango]

oh

alsoo ne more question

how is the mod 11 of -19, 3

isnt it like 8?

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[regal herald]

-22 is a multiple of 11, to -19 is a remainder of 3

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[regal herald]

so you want the sum of all terms to be a+z? or the sum of n terms to be a+z

so d=(z-a)/(n-1)
a=a

sum of x terms is x/2[2a+(x-1)d]

im sure you can go from there

common difference d

and i defined x

solve for x

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[weak surge]

i made this into Identity 4x4 using RREF

but how can i solve the second part?

[rough stream]

,w matrix row reduce {{-3,0,-2,-5,0},{0,2,1,-5,0},{3,-1,-2,25,0},{-2,3,1,-15,0}}

[jolly parrot]

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[weak surge]

😮

why would augmented change it?

[rough stream]

Wouldn't haha

Should hopefully be the same as yours

[weak surge]

so i solved incorrectly with RREF to get identity?

[rough stream]

Did you use the tool they're suggesting?

[weak surge]

no, i did by hand

,w matrix row reduce {{-3,0,-2,-5},{0,2,1,-5},{3,-1,-2,25},{-2,3,1,-15}}

[jolly parrot]

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[rough stream]

So indeed they are linearly dependent. Not only that, but the matrix also suggests how to fill in the blanks

[weak surge]

hmmm,

[weak surge]

the only one that is dependent would be the last column, correct?

[rough stream]

You can eliminate the last column, and doing so would give an independent set.

[weak surge]

since the last column is the only free variable without pivot in RREF

[rough stream]

But "dependent" isn't a property of a column

[weak surge]

oh

[rough stream]

They're all dependent on eachother, until that last column leaves

[weak surge]

is it tied to this somehow?

can easily be solved by looking at this?

i'm just imagining what numbers could work

but maybe there is a system to use

[rough stream]

So mine was augmented. That is, we're solving a system

It turns out the solutions to that system are exactly the blanks

If the blanks are w,x,y,z

Then we get:
w + 5z = 0
x = 0
y - 5z = 0

[weak surge]

w = -5z

[rough stream]

Whoops I messed up. See the edit.

[weak surge]

OK

y = -5z

not sure i'm following

like this?

[weak surge]

I think that's what you mean right

but w is not -5z

it's 5

and y is -5

dang thats wrong still

i'm confused

got it

tyvm

.close

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[ember beacon]

does number 9 equal to 5 also do this type of triangle have a name?

[pine iron]

a triangle with two equal sides is isosceles

[ember beacon]

ok

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[elfin ore]

how would i make the blue expression equal the red one?

[elfin ore]

what algebraic processes do i need to do

[last summit]

what algebraic processes do you know

[elfin ore]

or it already is equal, sorry

how do i manipulate it into the red form

[elfin ore]

not many

[last summit]

do you know about division

[elfin ore]

yeah but that just gives me a bunch of 1/y's and stuff

[last summit]

no

[elfin ore]

im bad with negative exponents

[last summit]

divide by the other thing

[last summit]

that would explain this doubt of yours

[spark parcel]

negative exponents are just fractions flipped

[last summit]

5=ye^x

divide not by y

but by e^x

[elfin ore]

bru

im stupid asl

[spark parcel]

if you got like

[elfin ore]

thanks

[last summit]

$a^{-1}=\frac{1}{a}$

[elfin ore]

🙏

[jolly parrot]

Austin

[last summit]

$\frac{1}{e^{x}}=e^{-x}$

[spark parcel]

^^^^^^^

[jolly parrot]

Austin

[last summit]

is how exponenets work my friend

[elfin ore]

gotcha

im very bad at those

thanks for the help

.close

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[last summit]

ABCD

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[limber escarp]

Hi, can anybody help me go over trig pls?

[humble hearth]

what kind of trig?

[limber escarp]

Basic

[humble hearth]

SOH CAH TOA?

[limber escarp]

Yes

[humble hearth]

you do sine and cosine rule?

[limber escarp]

Yes i know them

[humble hearth]

trig functions?

[limber escarp]

This

[humble hearth]

so this?

[limber escarp]

Yes

The one with the triangles

[humble hearth]

how old r u so i can get an idea of what stuff you’re doing

and is this for a test perchance? then i can give you some resources

[limber escarp]

Year 10 mocks

[limber escarp]

15

[humble hearth]

australian?

[limber escarp]

UK

[humble hearth]

okay

what do you need help with?

getting the questions, or what’s up?

is there’s something you’re stuck on

[humble hearth]

Okay so let’s see what we need to find AC

AC = AD + CD right?

@limber escarp

[limber escarp]

a its alright

I understood

.close

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[midnight haven]

hi, so i was wondering in what ways is it better to go for unis known for their research when going for bachelors, if i want to pursue research in the future.

[midnight haven]

i'm mostly talking about ISI and CMI here? whats the advantage in getting a bachelor from there specifically?

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[midnight haven]

.reopen

[pearl pond]

✅

[midnight haven]

^

[compact ridge]

This question isn't on-topic for the help channels

[spiral sierra]

might get a better response if you ask this in #advanced-lounge

[midnight haven]

what is the appropriate place for this question

[harsh maple]

nice maths

[compact ridge]

Also this is very Indian specific

You can still try asking in #discussion

[midnight haven]

oh its saying no access

[compact ridge]

Yeah you need the undergrad role

[spiral sierra]

id:customize you need the advanced access role. also as south said, this question is Indian specific so not many people are familiar with the terms/colleges you are mentioning.

[midnight haven]

they are discussing something atm, so i better not interrupt there rn

[midnight haven]

im asking for the general scenario, but i thought i'd mention that in case there was anything specific worth mentioning in regards to those two unis

i asked in the advanced lounge, thank you, i'll close this here now

.close

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[snow flare]

hey! the question is what the bearing from point O from B

.close

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[elder pawn]

i tried 1/6

[harsh maple]

thats for the first step only

when you roll the 6

the probability doesnt reset for the secodn step

[elder pawn]

is it 2/3

[harsh maple]

no

[elder pawn]

what do i do

[harsh maple]

ok think about this image

you first flip a coi nthen you role a dice

the amount of outcomes is the amount of first step outcomes times the second step

so tis the same for your dice question

[elder pawn]

that doesnt make sense to me

[harsh maple]

there are 6*6 possibilities

for your question

ok

whatever

its 1/36

i know im nto supposed to do that

[elder pawn]

im just confused of it

oh wait

6*6 is 36

[mint notch]

yes

[elder pawn]

.close

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[sly hornet]

Hi can someone please help me with this?

[sly hornet]

I'm not really sure how to make word-problems and how to solve them, would appreciate the help.Thanks😅

[pearl pond]

@sly hornet Has your question been resolved?

[sly hornet]

<@&286206848099549185>

[cyan flume]

I have never done any exercises like that, but I'd draw 2 circles with a radius of 1km (entire (Durchmesser, I'm German but basically it's 2 times the radius) 2 km).
You then have the range of your 2 towers. If the towers don't cover all municipalities, but they cross into each other, you could look for a way, where f.ex. the two ranges don't cross into each other and just touch each other.
This way you could cover a bigger area f.ex.
You could write smth like resident is in (coordinates, ex quadrant (3|1) and has no cell phone service.
Solution: The cell tower locations could be spread more efficiently to cover a bigger percentage of the map (of Minglanilla).

But after your scheme given, you'd have to come up with an introduction, have to draw the circles with r= 1km and their middle point into it. For calculations you could use the Thales theorem and calculate, if the resident is within the range of the cell towers

And how or he's away from them

And then you could say something like, if the cell towers would cover more area of the municipalities, the resident would have cell servises

[sly hornet]

ohh okay but is it possible to use the distance formula in this?

[cyan flume]

Yeah sure. It's way easier

Completely forgot about that one💀

Sry

[sly hornet]

Alright I'll try it then:)

oh no worries😅

[cyan flume]

🙂

In which grade are u?

[sly hornet]

10th

is what I'm doing right?lol

[cyan flume]

Do you know the scale of the map?

[sly hornet]

honestly no, I actually don't really get the concept of what to place sorry

[cyan flume]

Ok, so on the bottom right of the map are some numbers. I can't read them, bc it's a bit pixeld.
Is there a location, or kilometer scale or any numbers like that?

[sly hornet]

oh yeah

[cyan flume]

You need to place 2 circles with the range of 2km(range 2km = radius 1km)

[sly hornet]

it says Scale: 1 unit to 500 meters

[cyan flume]

And you need the scale to determine how big your circles are on the map

[cyan flume]

Is there a line ? Like 1 line 500 or smth

[sly hornet]

no I don't think so?

[cyan flume]

Ok, so 4 units would be 2000m/2 km

Then you have to pick a point on the line of the quadrants. This point is where the cell tower stands. Then you go two times to the right from that point. Back to the middle point and do it for the left, down and up

[sly hornet]

Is the units the one on the side?

[sly hornet]

ohh

[cyan flume]

Bc of the scale that is 500 per unit.
1 unit= 500meters
4 units = 2000 meters /2km (range)
2 units = 1000 meters /1km (radius)

Did that help?

[sly hornet]

Yeah, I'm understanding it now

is that the same for the other circle btw?

like does it apply also? if I put the other cell tower to the right

[pearl pond]

@sly hornet Has your question been resolved?

[sly hornet]

If these were my 3 word-problems where would be the appropriate location to draw the two circles/cell site towers?

Scenarios:

A resident located 1.5 km away from Cell Site Tower 1 experiences excellent internet connectivity. How far is the resident from the edge of the coverage area of Tower 1?
Beyond Coverage Area Scenario:

A resident situated 2.5 km from Cell Site Tower 2 complains of poor internet connection. How far is the resident located beyond the coverage area of Tower 2?
Mixed Coverage Scenario:

A family resides at a point equidistant from both Cell Site Tower 1 and Tower 2. If the distance to Tower 1 is 1.8 km and to Tower 2 is 2.2 km, in whose coverage area do they fall, and how is their connectivity affected?

<@&286206848099549185>

[cyan flume]

I'd say logically in the most populated areas

Just for the realism

In a way you can cover as much area as possible ig

[sly hornet]

so like a bit in the middle?

Can you please demonstrate an example of where you'd draw them?:)

[sly hornet]

@cyan flume I'd also like to know if my word problems can be accurate to where I'll put the two towers so I can see if it's easy to solve🥲 (sorry for the bother)

[cyan flume]

The picture is pixeled 😭just do it in areas where many shops and streets are ig

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[midnight haven]

How do factor 26 no clue where to start

[pseudo oxide]

which one now

that's just a difference of squares

[midnight haven]

How

[pseudo oxide]

9a^2 - 12ab + 4b^2 is a square--use (a-b)^2

and ofc, 9 is a square

[midnight haven]

Ohh let me try

[midnight haven]

Thanks I solved it

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[pseudo oxide]

alr

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[shut linden]

How does the cdf differentiate into the marginal here?

[pearl pond]

@shut linden Has your question been resolved?

[pearl pond]

@shut linden Has your question been resolved?

[fluid axle]

you mean differentiate, as in an actual derivative ?

"to derive the marginal density", they're talking about the process they're using to find the marginal, not a derivative

so just continue to read

they found the CDF

and right after the picture you posted, they're certainly gonna do something with it to get the marginal
they're not finished yet

@shut linden

[shut linden]

They don’t do anything, it says that the the derivative of the cdf equals the marginal

[shut linden]

But when I try differentiating it I get something completely different?

[pearl pond]

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[dense plover]

can someone help me with this please

[dense plover]

i got the area

but is it supposed the be obvious that the volume of one half the the same as the other half?

[steep saddle]

yeah

[dense plover]

fairs

also

when i tried to find the volume using cosec equation

[steep saddle]

are you asking for a proof of why those equations are symmetrical about x=pi/4

[dense plover]

for someone reason it giving me infinity

[dense plover]

yea i think

acutally yea i am

[steep saddle]

show work?

[dense plover]

This is it sorry it’s a bit messy

Let me re write it rq

[steep saddle]

just move the one on the right pi/2 units to the left
csc (x + pi/2) - sin (x + pi/2)

and then flip it over y axis

csc (-x - pi/2) - sin(-x - pi/2)

and i think that should be equivalent to the first

[dense plover]

Hopefully this a bit better

when i put in pi/2

into the cot

its undefined

which makes no sense since it shouldnt be if its the same as the other

unlesss i did something wrong

[steep saddle]

😭 bro why do ppl write x like that

[dense plover]

my teacher sorry about that

he drilled it into me

😭

[steep saddle]

lol at least make the halves touch each other

looks like ) (

[dense plover]

yea my handwriting isnt the best

i can explain the parts that are messy

[steep saddle]

it should be 5/2 no?

not 3/2

[dense plover]

nah since i did -2 + 0.5

unless its supposed to be -0.5?

[steep saddle]

💀 ur right mb

[dense plover]

dw

[pearl pond]

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[stable moon]

2nd part of the question

I've made a different approach, is it correct?

[mellow idol]

I think it should be -5 here?

[stable moon]

?

Oki

[mellow idol]

Yeah ur solution is correct

[stable moon]

Yay

Thanks

[mellow idol]

I would suggest that u take each of the functions to be smaller than 0 also ( caus negative x negative is positive ) so it's a rigorous proof

[stable moon]

Ms had different approach so I thought it was wrong

[mellow idol]

Nah it's correct

[stable moon]

Can you please elaborate

[mellow idol]

Well, here you've evaluated y-1>0 and 4y+5>0

[stable moon]

No

These are critical values

Y > 1 and y is less than -1.25

Square of negative numbers is not possible

And square root of numbers greater than 1 are always greater than 1

[mellow idol]

I'm not talking about squaring anything tho

[stable moon]

And range of cos x is less than 1

Oh

I still don't get what you mean 😭

[mellow idol]

NVM ur right I misread the last step 😭

[stable moon]

💀

[mellow idol]

The striked out inequality

[stable moon]

Ok

[mellow idol]

Is what I misread

[stable moon]

Thanks bro

Are you in university?

[pearl pond]

@stable moon Has your question been resolved?

[pearl pond]

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[hard wraith]

was wondergin why this wouldnt work

[hard wraith]

this is the correct solution

[regal herald]

where did your first line even come from

[hard wraith]

Just took A^2 from both sides

[regal herald]

no you didnt

because I disappeared

[hard wraith]

i see

[barren edge]

what a pun

[hard wraith]

revised solution

is this method correct

[regal herald]

sure, it works, you didnt really do anything different to what they did though, its exactly the same in content

[hard wraith]

i see, i just forgot the I.

thanks

close

$closer

$close

.close

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[orchid pecan]

4. (Op A PAU June 2015)
   Consider the function f(x) = ln(x 1) defined on the interval [2, e + 1]. Determine the equation of the line tangent to the curve y = ln(x-1)
   parallel to the line passing through the points P(2, 0) and Q(e + 1, 1).

[orchid pecan]

please

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[pure anchor]

What's the answer here

[sharp vigil]

try drawing a diagram of the situation

[pure anchor]

Hm

I guess we can make it A+B = - C

Is this valid

That's trig angle 0

Then the opposite of it would be -C

Which is 180°

@sharp vigil am i on the right track

Idk

Nvm

[sharp vigil]

yes, that's correct

[pure anchor]

Are those correct

If the speed of an object is uniformly changing, then there must be an acceleration, so it can't be in equilibrium, right?

I don't know which one is which

[pearl pond]

@pure anchor Has your question been resolved?

[pearl pond]

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[clear flint]

we went over the standard answers in class but we didnt go over how to find nonstandard amounts on a normal distribution table, how would i find the answer

[sharp vigil]

you either need a table of values or a calculator

[clear flint]

i have a calculator

[sharp vigil]

what kind of calculator?

[clear flint]

ti 30x

[sharp vigil]

does your calculator have any labels on it that say "stat"?

[clear flint]

yes

[sharp vigil]

if you access the menu labelled "stat", there should be an option "normal cdf"

[clear flint]

it only says 1-var and 2-var

[sharp vigil]

if your calculator doesn't have that, then you can use a lookup table

[clear flint]

is there one online i could use?

[sharp vigil]

you can use desmos

you will still want to learn how to use a lookuptable, since you may need it on an exam, though

[clear flint]

alright

[sharp vigil]

on desmos the command is normaldist(mean, standard deviation).cdf(lower bound, upper bound)

which gives the proportion of data points we expect to be in between the lower and upper bounds

[clear flint]

ok, i put that in

[sharp vigil]

what did you put in, and what did you get out?

[clear flint]

170,5 and 150,190
got 0.999936657516

not sure i did it right

[sharp vigil]

you got the mean and standard deviation correct

what we want to do is find how many will be taller than 166 cm

so what would a reasonable lower bound be?

[clear flint]

150cm

[sharp vigil]

where did you get 150 cm from?

[clear flint]

reducing by the var to the furthest point on the curve

[sharp vigil]

what we are interested is the proportion of people with heights between the lower bound we set, and the upper bound we set

[clear flint]

so it would be 166?

[sharp vigil]

that would be a reasonable lower bound

is there any upper limit on the height?

[clear flint]

no

[sharp vigil]

so a reasonable upper limit would be infinity

which you can enter in desmos as infty

[clear flint]

ok

got 0.788144601417

[sharp vigil]

so that is the proportion of people you expect to be above 166 cm

how many people does that correspond to?

[clear flint]

47

[sharp vigil]

yes

[clear flint]

i appreciate the help