upper crypt
"Check the position of those"
#help-39
pearl pondBOT
@austere pike Has your question been resolved?
exotic scaffold
how do they expect me to do this
pearl pondBOT
how do they expect me to do this
versed remnant
u are to find an expression not an answer
exotic scaffold
how do they expect me to do this
wait so the width is 5cm+5cm+?
because it doesnt give me the wide of the picture so do I substitute the ? to a pronumeral
regal herald
just keep in mind the frame is 5cm thick at all points and it should make sense
regal herald
but then it says 5 cm is the width
x is the width of the frame, yeah
it doesnt say 5cm is the width at all
exotic scaffold
ye ik what you mean
so the expression would be 2x*x for the total area of frame and picture
2xsquared
bc the area is length x width
regal herald
indeed
exotic scaffold
oh
I was overcomplicating it formyself
I thought I had to write a binomial proudct
bc thts what we learning
ok so how do I find the area of the painting only?
thts difficult for me
regal herald
just keep in mind the frame is 5cm thick at all points and it should make sense
just remember this
exotic scaffold
well, how could one express the width of only the picture?
x - 10
exotic scaffold
2x - 20
exotic scaffold
how do they expect me to do this
5 cm wide, length is twice the width
regal herald
the length of the frame is twice its width yeah
exotic scaffold
and theres 2 sides
regal herald
this has nothing to do with the 5
exotic scaffold
the width is 10
regal herald
the length of the frame is twice its width yeah
this is just where x and 2x come from
exotic scaffold
all together
regal herald
just keep in mind the frame is 5cm thick at all points and it should make sense
at all points.
even the sides
youre confusing the thickness of the frame to have anything to do with its width at all
the two statements arent related
the frame is 5cm thick, everywhere
its still just 2x-10
regal herald
oui
regal herald
just take your time, read the question carefully, and try not to overthink it too much
exotic scaffold
ye ty
so I have to write it in expanded form it would be
wiat
what would it be 😭
regal herald
cmon
exotic scaffold
bro im so dumb
regal herald
use foil
regal herald
nono
exotic scaffold
2xsquared - 30x + 100
regal herald
not quite
exotic scaffold
uhh
regal herald
check last term
exotic scaffold
check again
exotic scaffold
tyty
regal herald
now simplify
exotic scaffold
2xsquared - 30x + 100
?
regal herald
practice brings efficiency and proficiency
exotic scaffold
this is our 2nd last lesson for algebra by 7 more weeks ill forget everything
exotic scaffold
practice brings efficiency and proficiency
ty for ur help
regal herald
this is our 2nd last lesson for algebra by 7 more weeks ill forget everything
just dont slack off, review for a few hours a week, do a few questions
spread out its not that tedious
168 hours in a week, you could probably spare 3-5
anyway, good luck
pearl pondBOT
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sharp smelt
Let $f(x)= e^{\frac{x^2}{2}} + \int_0^x tf(t)dt$, then find the range of values in which $f(\sqrt2)$ lies
jolly parrotBOT
Why am. I here
sharp smelt
I started by differentiating both sides, and for convinience setting $f(x)=y$
jolly parrotBOT
Why am. I here
sharp smelt
$y'= xe^{\frac{x^2}{2}} + xy$
jolly parrotBOT
Why am. I here
sharp smelt
now this is a linear ODE
so I rearrange it to bring it to its standard form
$\frac{dy}{dx}-xy = xe^{\frac{x^2}{2}}$
jolly parrotBOT
Why am. I here
jolly parrotBOT
Why am. I here
sharp smelt
so the solution to the ODE is $d(ye^{\frac{-x^2}{2}})=xdx$
jolly parrotBOT
Why am. I here
cursive wraith
Homogeneous solution is Ce^(x²/2)
sharp smelt
or $ye^{\frac{-x^2}{2}}= \frac{x^2}{2}+C$
jolly parrotBOT
Why am. I here
sharp smelt
Homogeneous solution is Ce^(x²/2)
isn't it e^{-x^2/2}?
cursive wraith
Well no
sharp smelt
the IF I mean, sorry
sharp smelt
Integrating factor
cursive wraith
Ok
sharp smelt
how do I find C though?
And before I forget, here are the options I was given
$5<f(\sqrt2)<6
cursive wraith
Instead of integrating without bounds, integrate with bounds
So the thing is
y = e^(x²/2)(x²/2 + C)
And now find y(0)
sharp smelt
why y(0) specifically?
cursive wraith
why y(0) specifically?
Easier
sharp smelt
ah, that would just be 1, wouldn't it?
sharp smelt
y = e^(x²/2)(x²/2 + C)
I'm still not sure I understand why?
sharp smelt
The ODE is y'-xy=e^{x^2/2} right?
cursive wraith
y = e^(x²/2)(x²/2 + C)
cursive wraith
The ODE is y'-xy=e^{x^2/2} right?
This is correct with y'
sharp smelt
yeah, so isn't the integrating factor $e^{\frac{-x^2}{2}}$
jolly parrotBOT
Why am. I here
cursive wraith
Yes, you want f to verify the original equation
cursive wraith
I don’t think so
cursive wraith
Yes
sharp smelt
so $ye^{\frac{-x^2}{2}}= \frac{x^2}{2}+1$ or $f(\sqrt2})e^{\frac{-2}{2}}= \frac{2}{2}+1$
jolly parrotBOT
Why am. I here
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
sharp smelt
so $f(\sqrt2)=2e$
jolly parrotBOT
Why am. I here
cursive wraith
That's what i got
jolly parrotBOT
pearl pondBOT
pearl pondBOT
Available help channel!
cinder wedge
pearl pondBOT
midnight haven
-2a-a = -3a
pearl pondBOT
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fast torrent
This is more of a physics question but I still need help if possible. I need to determine the decay constant for my M&Ms and the half life for the M&Ms.
fast torrent
<@&286206848099549185>
mossy smelt
There are ten candidates for a job. The search committee will choose four of them, and rank the chosen four from strongest to weakest. How many different outcomes are possible?
mossy smelt
hello, what formula will I use if the problem is based on rankings? The lesson is about permutations
midnight haven
combination
or just pick 4 with permutation and divide by 4! because there is only 1 arrangement possible
midnight haven
would be 10P4 ÷ 4!
pearl pondBOT
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mossy smelt
Lisa has three vases of the same kind and two candle stands of the same kind. In how many ways can she arrange these items in a line?
midnight haven
P(n,r)=
(n−r)!
n!
Using the formula for permutations of distinct objects
n means the total number of items
its easy bro try
mossy smelt
so its distinct?
midnight haven
Yes, in this question, the items (vases and candle stands) are considered distinct because they are all individually identifiable, even though some of them are of the same kind
midnight haven
for more explanation
r=5 because Lisa wants to arrange all 5 items (3 vases and 2 candle stands) in a line. Each item is being included in the arrangement, so
r equals the total number of items.
there is 120 ways that lisa could arrange in line
bro i gtg if you want more assistance someone else will join
pearl pondBOT
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carmine breach
hii could anyone help with special triangless
pearl pondBOT
hii could anyone help with special triangless
gloomy scroll
did you make a sketch?
carmine breach
no...
gloomy scroll
It would help you :)
void yew
did you make a sketch?
why does it need a sketch
gloomy scroll
because visualising what the sine actually is, and how you can find the other relatonships is easier with a sketch
carmine breach
ohh um i havent learned graphing yet...
is there a way to use unit circle?
or the quadrants
void yew
because visualising what the sine actually is, and how you can find the other re...
dont u just use the identities here
its just 1st quadrant thing most probably
gloomy scroll
oh it doesn't need to be anything fancy. Just a right triangle with an angle called theta, then you should be able to place 3 and 4, and find the other measure
carmine breach
ohhhh
gloomy scroll
dont u just use the identities here
I'm assuming you could. I'm just showing the way I learned, which is by visualizing it.
void yew
I'm assuming you could. I'm just showing the way I learned, which is by visualiz...
Oh ok
well then yeah
u dont even need a graph
just draw a triable
tiangle
and u should know the values of sin ratio
gloomy scroll
Exactly
carmine breach
okayyyyy
void yew
ie $sinx = Opposite/Hyphotenuse$
$cosx = Adjacent/Hypotenuse$
$tanx = Opposite/Adjacent$
jolly parrotBOT
❄ѕησωƒℓαкє❄
gloomy scroll
\frac{numerator}{denominator} is how you do fractions
void yew
oh mb
carmine breach
so it would be a triangle with
gloomy scroll
and text in LaTeX just looks like that so yeah. Happens. Not very intuitive
void yew
a right triangle
gloomy scroll
yes
void yew
wait a min
carmine breach
so i could use pythagoras to find the other angle
gloomy scroll
?
gloomy scroll
it doesn't have to be integers..
void yew
ok well yeha but in lower levels it was usually whole numbers
carmine breach
so im assuming
gloomy scroll
a pythagorean triplet is just any numbers a, b, c that satisfy a²+b²=c²
void yew
right
carmine breach
yaaaa its 10th grade math ahaha
void yew
but in this case we cant guarantee its a right triangle right?
or can we?
Im confused myself now lol
carmine breach
if we used identities it has to be right triangle right
gloomy scroll
since they tell you that the sine of some angle theta is 3/4, yes it's a right triangle
gloomy scroll
you can't use sin/cos/tan on non-right triangles
void yew
you can't use sin/cos/tan on non-right triangles
u can actually
gloomy scroll
so i can use that to solve
yeah, now you have all the pieces
void yew
carmine breach
ohhhhhh
gloomy scroll
no worries :)
carmine breach
thanks guysss
gloomy scroll
You're welcome
carmine breach
.close
pearl pondBOT
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Available help channel!
karmic gazelle
having a hard time grasping how factored cubes work. Mainly the A cubed plus B cubed formula, a3 + b3 = (a + b) (a2 - ab + b2). Equations 8x^3 + 27 & x^6 - y^6 are of question
karmic gazelle
i made an attempt already with c, but I’m not confident in my responses
<@&286206848099549185>
midnight haven
looks ok
karmic gazelle
looks ok
could you explain in better detail how to go through with the equation and why it happens?
midnight haven
you can change a^3 + b^3 to (a+b)^3 - 3ab(a+b)
and factor out (a+b)
to get the formula
autumn vector
Nah
autumn vector
@karmic gazelle there's a direct expansion
a³-b³=(a-b) (a²+ab+b²)
midnight haven
hes asking how its derived
not the formula
also thats wrong
should be (a-b)(a^2 + ab + b^2) instead
autumn vector
you can change a^3 + b^3 to (a+b)^3 - 3ab(a+b)
Then this is correct
pearl pondBOT
@karmic gazelle Has your question been resolved?
velvet meadow
,,\lim_{{x \to +\infty}} \frac{\sqrt{x^3 + 1} - x}{x+5}
pearl pondBOT
,,\lim_{{x \to +\infty}} \frac{\sqrt{x^3 + 1} - x}{x+5}
jolly parrotBOT
レナト (renato , ping if reply)
autumn trellis
!status
pearl pondBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
how do I start
autumn trellis
Have you heard of binomial approximation?
autumn vector
**レナト (renato , ping if reply)**
Maybe try using LHospital's rule
velvet meadow
how do I do that?
native gull
derivative of numerator and denominator seperately
then check if its still in the indeterminant form
or else apply it again
velvet meadow
,, \text{a moment please}
jolly parrotBOT
レナト (renato , ping if reply)
native gull
ah the x^3 in the root
velvet meadow
,align
\lim_{x \to +\infty} \frac{\sqrt{x^3 + 1} - x}{x+5} &= \lim_{x \to +\infty} \frac{\frac{d}{dx}(\sqrt{x^3 + 1} - x)}{\frac{d}{dx}(x+5)}
jolly parrotBOT
レナト (renato , ping if reply)
native gull
the x^2 was easier
alr
velvet meadow
,, \text{how to do that}
native gull
hold on
jolly parrotBOT
レナト (renato , ping if reply)
native gull
gotta use paper ig
native gull
,, \text{how to do that}
is the answer inifinity?
velvet meadow
,, \text{I dont have answer sheet}
jolly parrotBOT
レナト (renato , ping if reply)
native gull
**レナト (renato , ping if reply)**
should be infinity i suppose
velvet meadow
derivative of numerator and denominator seperately
,w d/dx( sqrt(x^3+1)-x)
jolly parrotBOT
velvet meadow
,,\lim_{{x \to +\infty}} \frac{\sqrt{x^3 + 1} - x}{x+5}
jolly parrotBOT
レナト (renato , ping if reply)
native gull
as you see x remains in the numerator
.
midnight haven
,,\lim_{{x \to +\infty}} \frac{\sqrt{x^3 + 1} - x}{x+5}
did you get the answer?
it should be infinity
native gull
yeah
velvet meadow
,align
\lim_{{x \to +\infty}} \frac{\sqrt{x^3 + 1} - x}{x+5} &= \lim_{{x \to +\infty}} \frac{\sqrt{x^3(1 + \frac{1}{x^3})} - x}{x+5} \
&= \lim_{{x \to +\infty}} \frac{x\sqrt{1 + \frac{1}{x^3}} - x}{x+5}
jolly parrotBOT
レナト (renato , ping if reply)
velvet meadow
why
native gull
can you explain why is it x?
velvet meadow
oh yeah
native gull
yup
midnight haven
it should be infinity
native gull
yes
midnight haven
also , renato , do you use nixOS?
velvet meadow
,align
\lim_{{x \to +\infty}} \frac{\sqrt{x^3 + 1} - x}{x+5} &= \lim_{{x \to +\infty}} \frac{\sqrt{x^3(1 + \frac{1}{x^3})} - x}{x+5} \
&= \lim_{{x \to +\infty}} \frac{x^{3/2}\sqrt{1 + \frac{1}{x^3}} - x}{x+5}
jolly parrotBOT
レナト (renato , ping if reply)
velvet meadow
also , renato , do you use nixOS?
im a package mantainer of one of the nixpkgs
for a c++ library
velvet meadow
long time no see omnipotent
spiral pivot
👋
your simplification is correct btw. And from there the answer to your question should be easy enough to see.
pearl pondBOT
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Available help channel!
magic bone
Where did I go wrong?
pearl pondBOT
@magic bone Has your question been resolved?
pearl pondBOT
@magic bone Has your question been resolved?
magic bone
tulip ore
Where did I go wrong?
gonna be honest with you, you need to use a graphing calculator instead of doing it like that
click the table option then put in the data, it will calculate an r for you or you can figure out how to calculate r using the table
magic bone
Noted
This is my first foray into the nightmare world of correlation coefficients and I wasn't taught the material, but I was given the homework, so I tried to get youtube to teach me (and it failed)
.close
pearl pondBOT
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minor rapids
pearl pondBOT
@minor rapids Has your question been resolved?
midnight haven
so
to prove that it is a median you prove that it is bisecting the other side
so therefore you have to prove that RM = RS
note that MNS ~ RTS
and the scaling factor is 2 because line MN is a perpendicular bisector which means that TN = NS so TS = 2TN
so then RS = 2MS so RM = MS
pearl pondBOT
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minor rapids
.close
pearl pondBOT
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restive bluff
pearl pondBOT
restive bluff
I am sturggling quite a lot with this question here
I have got this so far
but I don't see how the cancellation can occur
I'm pretty sure the first setup is right just which u to choose I don't know
glacial scroll
pearl pondBOT
pearl pondBOT
Available help channel!
sharp smelt
$\int \left(x^{3m}+x^{2m}+x^m\right)\left(2x^{2m}+3x^m+6\right)^{\frac{1}{m}}dx$
jolly parrotBOT
Why am. I here
sharp smelt
I'm guessing I start with logrithmatic differentiation for the u sub?
or would a trig sub be more appropriate ?
,w differentiate (2x^{2m} +3x^m +6)^(1/m) wrt x
jolly parrotBOT
sharp smelt
before I forget, m is a natural number
hmm, or would induction be a better idea here
Just a hint please
,w differentiate (2x^{2m} +3x^m +6)^(1/m) wrt x (edited)
jolly parrotBOT
glacial scroll
pearl pondBOT
pearl pondBOT
@glacial scroll Has your question been resolved?
pearl pondBOT
@glacial scroll Has your question been resolved?
glacial scroll
<@&286206848099549185>
glacial scroll
.close
pearl pondBOT
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covert dagger
i need help
pearl pondBOT
i need help
wooden merlin
Make the numerator fractions to one fraction.
wooden merlin
Make the left fraction have the same denominator as right fraction.
unkempt yacht
im surprised you made it to today without knowing how to take the sum of 2 fractions
unkempt yacht
like the second help channel said, you simplify the numerator first
covert dagger
like the second help channel said, you simplify the numerator first
it’s rlly late and it’s been a while since i’ve done these
no need to diss 😭😭😭 i’m struggling
unkempt yacht
multiply the first number with the denominator of the second number, and put that to the numerator
unkempt yacht
it’s rlly late and it’s been a while since i’ve done these
complaining wont help
its better to focus on the problem first
covert dagger
i am
i’ll lyk what i get
uhm stuck again
nvm got it
nvm i don’t got it
bro 😭
wooden merlin
,rotate
jolly parrotBOT
wooden merlin
Your denominator should be $\frac{9-x^2+x^2}{\sqrt{9-x^2}}$
jolly parrotBOT
Good
pearl pondBOT
covert dagger
i got it
wooden merlin
Alright.
covert dagger
.close
covert dagger
complaining wont help
forgot to say this, no one was complaining. like anyone in this server, people have questions and i said i don’t get it but got left on read so i left that server and came to ask this one. then dissing me saying “im surprised u got to today not knowing how to take the sum of 2 fractions.” not sure why you’re even in this server to help people but if you’re going to help, do it kindly otherwise i’ll report you. i left that server got away from you to ask a different server but ofc you had to come 💀
unkempt yacht
ok
covert dagger
it’s ok i know ur mad u didn’t get laid tonight
zinc parrot
bro 😭
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Available help channel!
vale turtle
pearl pondBOT
vale turtle
How to start this one?
pearl pondBOT
@vale turtle Has your question been resolved?
pearl pondBOT
sharp smelt
pearl pondBOT
sharp smelt
SO here I'm assuming one side of the triangle would be x=k where k is some arbitrary constant
so we have to maximise xy/2
so I write y in terms of x and then maximise the function, right?
hmm, so how do I find the distance between the vertices?
is it just 2x?
So do I maximise $\frac{1}{2}\left(-2x^2+54\right)\left(2x\right)$
jolly parrotBOT
Why am. I here
jolly shuttle
so two vertices are both on y=-2x^2+54, but they have opposite x?
sharp smelt
I think so , yes
jolly shuttle
**Why am. I here**
Then I think maximizing this is enough
pearl pondBOT
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pliant laurel
Hello. Can someone help me prove geometrically that the angle subtended by portion of a tangent to a parabola intersected by its directrix and the curve subtends a right angle at the focus
pliant laurel
I can prove this easily using slopes but I wonder how we do it geometrically
I only have this much so far
I somehow have to prove DF=ED for this to be complete
pearl pondBOT
@pliant laurel Has your question been resolved?
pliant laurel
<@&286206848099549185>
pearl pondBOT
@pliant laurel Has your question been resolved?
pearl pondBOT
@pliant laurel Has your question been resolved?
pearl pondBOT
@pliant laurel Has your question been resolved?
pliant laurel
<@&286206848099549185>
normal frigate
leave cos teta divided by 2 alone
then youll get this
square root of 3 divided by 2
this is from a 30 60 90 degree special triangle
hence teta is 60
pliant laurel
Can you help me with this if possible?
pearl pondBOT
@pliant laurel Has your question been resolved?
vivid pilot
why the frickity frack is this not right
pearl pondBOT
why the frickity frack is this not right
vivid pilot
i used the correct ratio
s / 8 = y / 20
s = 8y / 20 = 2y / 5
and the crossectional area would be that squared
but it doesnt like that
oh i got it
.close
pearl pondBOT
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visual cedar
what is this asking for
pearl pondBOT
what is this asking for
visual cedar
find the area of the region bysubtracting the area of a triangular region from the area of a larger region
y^2 = x+3
y=2x
west sapphire
!original
pearl pondBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
visual cedar
i mean
So I find the area in between curves
by subtracting the area of the triangle
how do I find that ^
then after that do i find the length with respect to x or y
.close
pearl pondBOT
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polar crest
pearl pondBOT
polar crest
<@&286206848099549185>
jolly shuttle
!15min
pearl pondBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
jolly shuttle
and what is exact question
pearl pondBOT
@polar crest Has your question been resolved?
polar crest
<@&286206848099549185> bro help me
jolly parrotBOT
EinPest
polar crest
Bro
I need help because I cant
It's not 1/m3-n3
Will u actually help me instead of telling me to do something
I've waited 20monutes + already
proceeds to not reply
<@&286206848099549185> s
seriously
<@&286206848099549185>
its been around 40 minutes for a singular question
plush bramble
its been around 40 minutes for a singular question
!volunteers
pearl pondBOT
its been around 40 minutes for a singular question
Helpers are just people volunteering their time to help you. Be polite and patient.
autumn trellis
They want positive indices, so how will you get rid of the -1 powers in the numerator?
polar crest
i dont knoww
autumn trellis
Multiply the numerator and denominator by mn
jolly parrotBOT
smidgin
polar crest
im doing it now
autumn trellis
Okay
polar crest
yes so u cancel out m-n
autumn trellis
Yes
autumn trellis
m-n
polar crest
okay
autumn trellis
How will you cancel out m+n if the numerator is n-m
polar crest
so its 1/mn*(m+n)
polar crest
-1/mn*(m+n)
autumn trellis
Yes
pearl pondBOT
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Available help channel!
devout heart
pearl pondBOT
midnight haven
did you try sketching the region
devout heart
did you try sketching the region
I got the picture on desmos
I just don't know how to start other than that
pearl pondBOT
@devout heart Has your question been resolved?
brazen reef
I got the picture on desmos
I just don't know how to start other than that
I think you should integrate with respect to y. If you had taken it according to x, you would have had to divide it into 2 parts because the boundaries did not remain the same like -2/3 to 1 and 1 to 64/9.
devout heart
I think you should integrate with respect to y. If you had taken it according to...
uhm I apologize but what does integrate with respect to y mean
midnight valley
u can try by finding point of intersection of red and blue, and green and blue, then put them into parts and find individual areas and then sub, may be sounds lengthy but kinda easy to do
devout heart
u can try by finding point of intersection of red and blue, and green and blue, ...
so i have to do 2 of each at a time?
midnight valley
so i have to do 2 of each at a time?
u can try, but ig finding areas individual will be much easier, by putting right limits
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Available help channel!
wanton orbit
help with this limit
pearl pondBOT
help with this limit
wanton orbit
i tried lhopital it didnt work
wanton orbit
i tried lhopital it didnt work
unless i didnt take the derivative correctly
hallow cedar
Do you just need to find the limit or show your steps?
wanton orbit
show the step also
wanton orbit
Do you just need to find the limit or show your steps?
hint? i wanna do it myself
hallow cedar
See I mean I would write it as (2)^(1/x) and go from there
And then note the property of limits when we have a continuous function
wanton orbit
And then note the property of limits when we have a continuous function
so you mean take the limit from right and left side?
like this?
vast berry
pearl pondBOT
vast berry
how do i do question 10?
nocturne siren
"B is 120m above the ground"
pearl pondBOT
@vast berry Has your question been resolved?
pearl pondBOT
pearl pondBOT
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candid flame
pearl pondBOT
pseudo oxide
okay one thing
you do realize you can just differentiate xy^2?
it's a partial derivative
so $\frac{d}{dx}xy^{2}=y^{2}=2y+2x^{2}y$
jolly parrotBOT
ren
regal herald
that isnt a partial derivative
void yew
It would be the u*v rule
regal herald
yeah, thatll give you a dy/dx term which can be proceeded from
void yew
2xy (dy/dx) + y^2 = 2y(1+x^2)
regal herald
just separation of variables i believe needed
pseudo oxide
that isnt a partial derivative
yea yea ik
regal herald
no nvm
void yew
I dont think its a homogenous equation
jolly parrotBOT
void yew
wth is that
regal herald
not really, it gives you y^2+2xy dy/dx = 2y+2x^2y which is different to what you said
void yew
not really, it gives you y^2+2xy dy/dx = 2y+2x^2y which is different to what you...
uh thats what I said
candid flame
i tink the question is wrong
native gull
native gull
i tink the question is wrong
its not
do you know how to solve linear differential equation?
integrating factor
candid flame
where
native gull
candid flame
theres no dy
native gull
divide the whole equation by 2xy
candid flame
but u still wong get dy
candid flame
here there is no dy
regal herald
the dy/dx is right there
pearl pondBOT
@candid flame Has your question been resolved?
pearl pondBOT
pearl pondBOT
Available help channel!
midnight haven
I’m having trouble solving things like these, it’s the fractions that throw me off….
midnight haven
If someone could teach me how to multiply when there are fractions present
uneven smelt
solve?
midnight haven
midnight haven
I’m being asked to evaluate the expression and find its domain…
I looked the answr key and it says this
That’s y I’m so confuse with what I have
worthy lance
What don't you understand exactly about the solution?
midnight haven
This is my solution
Why is it different from there’s..
Or am I not done..?
What do I do next??
worthy lance
Your writing makes no sense to me. Could you explain what you did?
pearl pondBOT
@midnight haven Has your question been resolved?
midnight haven
Your writing makes no sense to me. Could you explain what you did?
Multipled both brackets by (x+2) in order to get rid of the fraction… on the right side 2 is remaining… on the left side I need to expand… so I expand directly below it…. (X+2)(2x-1) expanded is (2x^2+3x-2)… then I need to multiply that by 2… after doing that I get 4x^2 +6x -4
pearl pondBOT
@midnight haven Has your question been resolved?
midnight haven
Multipled both brackets by (x+2) in order to get rid of the fraction… on the rig...
@worthy lance
i can help
Please!
so (x/y)(a/b) is just (xa)/(yb)
Thank you
np
if you need more explanation i can provide
midnight haven
Multipled both brackets by (x+2) in order to get rid of the fraction… on the rig...
Did what I did not make sense
that is a way to do it
midnight haven
What do I do after this tho… I don’t understand how they got the answr below
midnight haven
I’m being asked to evaluate the expression and find its domain…
I looked the an...
.
wait i don’t understand your steps in the thread can you show your current work?
One sec
Gimme a min to write it out clearly
i can read your current handwriting from the above images
This is the question, I’m stuck on c
This is my work, bottom is where I’ve gotten to
@midnight haven
where did the 2 come from
Which one
on the 2nd to last line
ok
it appears you have evaluated it
hasty roost
Since you're not working in an equation, you cant multiply it by (X+2)
midnight haven
Since you're not working in an equation, you cant multiply it by (X+2)
Wym
ohh right
hasty roost
You cant just multiply the problem by (x+2) because you dont have a = sign
midnight haven
Oh
so what you have to do is instead move the (2x - 1) to the top of the fraction
hasty roost
yeah
midnight haven
so (x/y)(a/b) is just (xa)/(yb)
So should I try it like this?
yes
you can visualize it as (2x - 1)/1 multiplied by 2/(x + 2)
Should I use distributive property on that part?
yes
They didn’t
In the answr key
ALSO, whenever I have a final answr with an x in the denominator… I must write a restriction on the domain right??
midnight haven
They didn’t
i mean i would distribute it but since it’s not the answer idk
hasty roost
It probably doesnt matter, especially if thats your answer key
midnight haven
yeah
How do you do division with polynomials ?
You just multiply by the reciprocal right?
it’s really hard i think
one time i spent 6 hours trying to implement it in python and failed
midnight haven
You just multiply by the reciprocal right?
Wait what I thought you just multiply by the reciprocal
yes but how do you multiply something by 1/(x + 2)
there is an algorithm but it dosen’t involve reciprocals in that way i think
Do you do your domain restriction on the most simplified denominator or the original denominator (if one)?
wdym the original problem’s denominator or the simplified form’s one?
Let’s say original question is (x+1)/x^2-1
I factor denom and cancel x+1 up top with x+1 on bottom
yeah then you have (x-1)/1
My final answer is 1/x-1
yeah then use that to make domain restrictions
So do I write domain restriction on just the simplified denom… or the original denom as well
So just x cannot equal 1 or x cannot equal +-1
the simplified one i think
because the problem says that you have to evaluate it therefore the “original one” isn’t in the problem
if you are done use “.close”
Uhhh
I think I do restriction on both the simplified and original
midnight haven
if you think so do that
pearl pondBOT
@midnight haven Has your question been resolved?
midnight haven
make a new channel
lapis lava
How?
midnight haven
put it in one of the available math help channels above
also read #❓how-to-get-help
lapis lava
Ok I found it thx
midnight haven
wtf
indigo pewter
hmmmmmmm
last summit
.close
light helm
we have a 👻
last summit
tropic saddle
austin why did you break a channel
indigo pewter
we have a 👻
i think this channel's a rebel
last summit
austin why did you break a channel
it was broken before I got here
plush bramble
bot borken
pearl pondBOT
bot borken
last summit
lmao
midnight haven
oh look its back
plush bramble
oh fascinating
last summit
bot borken
!status
plush bramble
can you guys get out of my channel, thanks
midnight haven
riemann you use the bot so much it only responds to u lol ok i’m out
tropic saddle
it was broken before I got here
of course
vital estuary
@plush bramble stuck again?
cinder flower
can you guys get out of my channel, thanks
no
plush bramble
<@261933205387477002> stuck again?
no, i've increased my fiber in my diet
light helm
.closet
vital estuary
show work
plush bramble
alright i'll be back in the morning that's when i go poopsies
wet osprey
!xy
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
plush bramble
.close
pearl pondBOT
midnight haven
.close
frank patio
.close
cinder flower
@plush bramble nice channel you have here
west sapphire
be a shame if something happened to it
pearl pondBOT
Available help channel!
civic totem
I'm not allowed to use hopital's rule for this question. I tried just multiplying by the conjugate, but I'm stuck. How do I actually find what k is?
light helm
since the denom → 0
it is essential that the numerator would also → 0 for a limit to exist
civic totem
Sorry, but could you explain why exactly the denominator approaches 0?
light helm
what does x-k appraoch as x→k
civic totem
oh
lol sorry i'm stupid
so since they both approach 0
k would have to be 4, right?
ty
.close
pearl pondBOT
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Available help channel!
wild fable
I’m not sure how to go about this integral, I thought of doing partial fractions but idk how that would work with trig terms
sharp smelt
try $sin(\theta)=u$
jolly parrotBOT
Why am. I here
wild fable
On the non factored integral right
sharp smelt
yup
wild fable
Oh then I get 1/(1 - u^2)
I’m guessing this will be some inverse trig thing
Oops 4 not 1 my bad
I can’t see what this will be tho
not quite sure what to do with this
Ohh
do I partial fractions this
But does partial fractions still work even after a u-sub??
sharp smelt
yes, it does
pearl pondBOT
pearl pondBOT
Available help channel!
fossil fog
I need help solving C
pearl pondBOT
I need help solving C
rough iron
if we say a function has local extrema, we don't also say at that point its also a HIP right?
runic quail
if we say a function has local extrema, we don't also say at that point its also...
what do you mean by HIP?
rough iron
horizontal inflection point
runic quail
yes if a point is a local extremum, that means it cannot be an inflection point because it is in the middle of its convexity/concavity
pearl pondBOT
pearl pondBOT
Available help channel!
fierce prism
How do I solve this?
pearl pondBOT
How do I solve this?
fierce prism
It’s probably just something I’ve forgotten
sharp smelt
y=3sin(x) or 3cos(x) should help
light helm
or you could consider what this integral represents geomeetrically
fierce prism
Yeah that’s where it came from actually. I’ll show the original question
Question 16
tropic saddle
draw how the area looks like
fierce prism
Is this right?
I guess I could just do
A = pi x r^2
= 9pi
Divided by 4 is 9pi/4
So no integration required??
unborn abyss
yep
pearl pondBOT
pearl pondBOT
Available help channel!
ancient bolt
pearl pondBOT
tall flint
what's "coding method"?
pearl pondBOT
@ancient bolt Has your question been resolved?
pearl pondBOT
pearl pondBOT
Available help channel!
granite loom
How do I find the zeros for this?
pearl pondBOT
How do I find the zeros for this?
pearl pondBOT
@granite loom Has your question been resolved?
frail summit
pearl pondBOT
frail summit
our teacher gave us an assignment that we haven't discussed before
we only did coulombs law, I don't know how to start with that x axis thing
regal herald
do you know the formula for electric field strength