alr
#help-39
midnight haven
wild fable
$\frac{d}{dx}\left(\arctan\right)=\frac{1}{x^{2}+1}$
jolly parrotBOT
water beam
wild fable
have u seen this before?
midnight haven
u is x-3
jolly parrotBOT
water beam
wild fable
are you happy with this?
midnight haven
yeah
jolly parrotBOT
water beam
wild fable
now we have this
its starting to look like the derivative but we still have a 16 in the denominator
and we want a 1
any ideas of how we can get rid of it?
midnight haven
we want a 1?
midnight haven
u^2 + 4^2
wild fable
well thats technically not wrong but it doesnt help much
what we can do is
factor out something from the denominator
can you think of what we can factor out?
midnight haven
16
wild fable
when we do something like this we actually have to square root it
then factor it out
so really we take $\frac{1}{\sqrt{16}}$ out
jolly parrotBOT
water beam
wild fable
but do you see what happens to u^2 when we do this?
midnight haven
It becomes u^-2
wild fable
not quite
if we take out a factor of sqrt(16), then there must also be a sqrt(16) somewhere in u^2 right?
midnight haven
Not sure
jolly parrotBOT
water beam
wild fable
because if we took out a factor of 1/sqrt(16), there must also be a sqrt(16) inside of u to keep it the same
midnight haven
Right
wild fable
$\frac{7}{\sqrt{16}}\int_{ }^{ }\frac{1}{\left(\frac{u}{\sqrt{16}}\right)^{2}+1}du$
jolly parrotBOT
water beam
midnight haven
Yes
wild fable
do you see what to do here now
jolly parrotBOT
water beam
wild fable
which simplifies to 7/4 which is multiplied to the integral
midnight haven
makes sense
wild fable
$\frac{7}{\sqrt{16}}\int_{ }^{ }\frac{1}{\left(\frac{u}{\sqrt{16}}\right)^{2}+1}du=\frac{7}{4}\tan^{-1}\left(\frac{x-3}{4}\right)+C$
jolly parrotBOT
water beam
wild fable
yeah when you do more problems like these
you start to get a feel of what to do
just practice
wild fable
thank you so much
no problem
wild fable
type .close
pearl pondBOT
pearl pondBOT
Available help channel!
frosty badge
I need to find the area if a triangle that is inscribed in a circle with a radius of 2 and we know that the triangles two angles are pi/3 and pi/4
nocturne siren
Use law of sine
dusky scaffold
nocturne siren
Wym how?
If a triangle is inscribed in a circle, the said circle is called“circumcircle”
Denote the radius of circumcircle by R
We have
a/sinA = b/sinB = c/sinC = 2R
pearl pondBOT
@frosty badge Has your question been resolved?
midnight haven
I don't know how to do this
pearl pondBOT
I don't know how to do this
last summit
I would rewrite it
as tan(2x)*tan^(2)(2x)
then use the pythagorean identity on tan^(2)(2x) and split into two integrals
midnight haven
Oh
last summit
distribute the tan(2x) back through
and then split the integral
at the subtraction
midnight haven
Ok
change sec^2 (2x) to tan^2 (2x) + 1 ??
or
could I apply if I separate a sec from the sec and tan
i dont know
du could be sec^2 (2x)
.close
pearl pondBOT
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Available help channel!
midnight haven
pearl pondBOT
midnight haven
Anyone ?
nocturne siren
Use Vieta’s formula
If p(x)=ax^2+bx+c has roots n,m
then
n + m = -b/a
n * m = c/a
nocturne siren
Show your work
midnight haven
nocturne siren
If p(x)=ax^2+bx+c has roots n,m
then
n + m = -b/a
n * m = c/a
This is only for the general case
nocturne siren
In your question
p(x)= ax^2+abcx+bc
pearl pondBOT
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pure terrace
how is A,B,D true? I dont understand how this graph is continous nor fa = 0, or how it can be a jump discontinuity
vivid grove
how is A,B,D true? I dont understand how this graph is continous nor fa = 0, or ...
The question does not make sense. Most likely the person created had no clue what they were doing
pure terrace
What about this one? is g differentialble because its the graph of g prime?
pure terrace
The question does not make sense. Most likely the person created had no clue wha...
if it had to be corrected, which would be the only right answer?, i was assuming e...
vivid grove
if it had to be corrected, which would be the only right answer?, i was assuming...
A, B, C, E are false, Only D is true
pure terrace
yep
can you clarify why that is? I was only under the impression that corners were indifferentaible
pure terrace
A, B, C, E are false, Only D is true
how come it is a jump when both dots are holes?
vivid grove
can you clarify why that is? I was only under the impression that corners were i...
sharp points are not differentiable when we are dealing with functions. So g' is not fully differetiable but g is.
vivid grove
how come it is a jump when both dots are holes?
I will need to take a look at a rigorous definition of jump continuity. I guess it will depend on how you want to define it.
pure terrace
I was also wondering for this question. What exactly is a tangent paralle tot a secant line
vivid grove
??What exactly is a tangent paralle tot a secant line
pure terrace
sorry i meant the sentence at the end of the question, stating if the tangent to the curve parallel to the secant line on that interval
I was thinking it looked something like this but i honeslty dont know what im doing
vivid grove
So do you want to know what tangent and secant are?
pure terrace
yes, isnt a tanget line that hits one point and a secant that hits 2 points?
like instantaous rate of change and average rate of cahnge
vivid grove
yes, isnt a tanget line that hits one point and a secant that hits 2 points?
A tangent touches a point on the graph. So we can say that line is a tangent to graph at x = XYZ
A secant cuts a graph. In others hits 2 point has you mentioned
pure terrace
then what does it mean by parrallel in that sentence
vivid grove
If two lines are parallel they have the same gradient. If they have same gradient they will never intersect with each other.
pure terrace
oh i think i confused parrallel and perpendiculart
pure terrace
I was also wondering for this question. What exactly is a tangent paralle tot a ...
then one last question regarding this question. If the lines never intersect how are they allowed to make the secant line = to the tangent to solve the equation
is it because they are like the same line with the same slope because they are parral and they are very close together?
vivid grove
We are not doing that make the secant line = to the tangent to solve the equation" What we are doing trying to do is make the gradients the same. If we do that they will be parallel
You might remember solving systems of linear equations
E.g., 2x + 1 = y, and 2x + 2 = y
If you tried solving the system above you will have a contadiction.
This means there is no x, y value where both equations hold, hence they don't intersect with each other
pure terrace
ok that makes more sense
vivid grove
If you are done remember .close
pure terrace
.close
pearl pondBOT
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hybrid haven
hybrid haven
i cant get this question right
i keep getting 1
at the red part
after i sub in pi
stoic path
There should be more info to find the value of c
Could you post the original question?
stoic path
You sure you got it?
hybrid haven
sorry
stoic path
Don't be
stoic path
Np
hybrid haven
.close
pearl pondBOT
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Available help channel!
strong glade
I saw a magic way to solve integral on a book, who named it "Chebyshev's Condition" but idk why it's true and how they get it
it says that the kind of indefinite integrals like ∫[(x^m)(a+bx^n)^p]dx can only be expressed by finite combinations of elementary functions when:
- p is integer
- (m+1)/n is integer, then use a+bx^n = z^s, s is the denominator of p
- (m+1)/n + p is integer, the use a*x^(-n)+b = z^s
it's rlly amazing, i had tested some integral and it's goddamn right, is there anyone who know this?
pearl pondBOT
I saw a magic way to solve integral on a book, who named it "Chebyshev's Conditi...
@strong glade Has your question been resolved?
strong glade
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frail summit
pearl pondBOT
frail summit
what have you done?
why you gotta word it like I murdered someone bro
frail summit
wait
my teacher said that's the right answer, but I didn't divide it by 2, like the question asked
frail summit
also, does mC mean microcoulomb?
yes
frail summit
oh right
prime bramble
my teacher said that's the right answer, but I didn't divide it by 2, like the q...
right so
proportionality
frail summit
what
prime bramble
Fe = kq1q2/r^2
If the distance between the two is halved, then we can see that the denominator will be 1/4 the value it used to be
From there, you can deduce what the strength of Fe will be
alternatively, you can call the initial electric force strength Fe1 and halved distance one Fe2, which occur when the charges are separated by distances r1 and r2 respectively
where r2 = 0.5r1
if you divide Fe2 by Fe1, you can simplify and calculate what the relative strength between the two forces is
does this make sense?
prime bramble
the first explanation was easier to understand
then go with it
it doesn’t really matter how you choose to do it
as long as it makes sense
frail summit
why did I not have to divide my final answer by 2? I'm really having a hard time understanding it
prime bramble
Why do you have to divide by 2?
frail summit
because the question said so
prime bramble
where?
frail summit
"if the distance seperation was halved"
prime bramble
the question is asking what the strength of the force would be if the distance was halved after the fact
late moon
No the question asked to note what will happen to the force if the distance was halved.
You don't need to do much actually
prime bramble
the question is asking what the strength of the force would be if the distance w...
you can first calculate the electric force, then recalculate it with a distance that’s half the original amount, but it’s easier to just make the argument I did earlier
late moon
$F = \frac{kq_1q_2}{r^2}$
jolly parrotBOT
VulcanOne
late moon
Let's plug in R = r/2
frail summit
so 1/2r²?
frail summit
I don't understand sorry 😭
frail summit
Let's plug in R = r/2
but this bit made sense
late moon
$\frac{kq_1 q_2}{\left(\frac 12 r\right)^2}$
frail summit
$r/2 = \sqrt{\frac{kq_1q_2}{F_e}}$
frail summit
why do i have to square both sides? I just took out the square on the left side before I got that
late moon
Hm
frail summit
soo what now
late moon
$\frac{kq_1 q_2}{\frac 14 r^2}$
jolly parrotBOT
VulcanOne
late moon
No manipulate it such that you get a factor multiplied by the original Force
late moon
**VulcanOne**
This is the original force
frail summit
No manipulate it such that you get a factor multiplied by the original Force
that's the part that I dont understand
late moon
Hmm
Alright let's try the equation you posted
$\frac r2 = \sqrt{\frac{kq_1q_2}{F_e}}$
frail summit
**drutus**
this?
jolly parrotBOT
VulcanOne
frail summit
okay
late moon
Solve for Fe
frail summit
but why tho 😭 I thought we're looking for r
late moon
No we're looking for the effect of halving r
frail summit
oh okay
spice jay
**VulcanOne**
Sorry to interrupt, I'm actually curious. Why should we divide the r by 2?
late moon
Sorry to interrupt, I'm actually curious. Why should we divide the r by 2?
The question asked about the effect on the force if the r is divided by 2
spice jay
The question asked about the effect on the force if the r is divided by 2
Oh, i see. That's why
frail summit
$F_e=\frac{kq_1q_2}{\frac{r^2}{4}}$
late moon
Simplify now
jolly parrotBOT
drutus
frail summit
$F_e=\frac{4kq_1q_2}{r^2}$
late moon
Yepp
jolly parrotBOT
drutus
late moon
Notice now that there is 4 multiplied
frail summit
okay
frail summit
we multiplied the numerator by 4?
frail summit
so in the question, there are two answers?
late moon
You will replace $\frac{kq_1 q_2}{r^2}$ by $F$, making it multiplied by 4.
jolly parrotBOT
VulcanOne
late moon
So the result of halving the distance is making the force 4 times bigger
frail summit
ohh now I get it
late moon
Makes sense?
late moon
ohh now I get it
frail summit
So the result of halving the distance is making the force 4 times bigger
so the answer will be 127.28m and this?
frail summit
So the result of halving the distance is making the force 4 times bigger
and so basically the closer the 2 charges are, the stronger the force.
wait, I just discovered there's an answer key. It says here it's 127m and the electrostatic force will be doubled
but our answer states it is multiplied by 4
so is the module wrong then?
pearl pondBOT
@frail summit Has your question been resolved?
sick flame
what SI units are used in solving coulomb's law?
pearl pondBOT
what SI units are used in solving coulomb's law?
earnest stratus
What's the exact problem?
pearl pondBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
sick flame
What's the exact problem?
no specific problem, I'm just preparing for a quiz
earnest stratus
no specific problem, I'm just preparing for a quiz
But what you asked does not make any sense.
Are you sure this is what you want to ask?
sick flame
yea
actually how do I convert this into scientific form
0.000300
is it 3x10^-4 or 3x10^-6
@earnest stratus
sick flame
Because 0.000300 = 0.0003
sorry, I meant 0.0003009
sick flame
so it is 10^-6?
earnest stratus
For?
sick flame
0.0003009
earnest stratus
Then it won't be 3 * 10^{-6}
sick flame
oh right, I get it now. I tried justifying my final answer on a problem but I just solved it wrong. thank you!
question. can all these SI units be paired with Coulomb?
like for ex, decaCoulomb (daC)?
I've only seen milli, micro and nano used for Coulomb
earnest stratus
all of these can be used with coloumb, what you've seen is also what we normally use.
For example, if you're talking about charge in a capacitor you'll have micro coloumbs. But thrn if you're talking about charge of something like an e, it'll be 10^{-19} ish so you'd use zepto (which I didn't know was the term)
pearl pondBOT
pearl pondBOT
Available help channel!
pearl pondBOT
jolly parrotBOT
Da Mucky Boi
merry python
shrewd schooner
pearl pondBOT
shrewd schooner
This requires shell method yes?
Oh no... I'm stuck.
$V=\pi \int_0^4 2\pi x (x-4)dx$
jolly parrotBOT
🌸 Katsune
shrewd schooner
This is shell method but with rotation of x=0, not x=6.
How does the x=6 modify this?
quiet whale
How does the x=6 modify this?
you're no longer revolving about the y axis, so you need to adjust the entire equation by a certain quantity
the way I like to think about it is:
what can I do to my equation to get it to revolve around the y (or x) axis?
in this case, we need to subtract six
so:
f(x) - 6 = x - 4
we can solve for f(x), giving us
f(x) = x - 2
quiet whale
your f(x) function
shrewd schooner
Where is the f(x) function here?
quiet whale
well, what is the shell method formula?
jolly parrotBOT
🌸 Katsune
shrewd schooner
But either the x or the x-4 is not correct
I think
What is the right configuration?
quiet whale
yeah it's your x-4 that isn't correct
you just have to modify it how I did up there
and then it should be right
quiet whale
because we subtracted six
when we transform a function like that, we're basically trying to set the axis of rotation back to one of the two axes
either x or y
in this case, y
shrewd schooner
Yo so it's x+2 not x-2
shrewd schooner
so:
`f(x) - 6 = x - 4`
This is f(x) = x+2
quiet whale
but that's basically the gist of how you deal with axes other than one of the regular ones
quiet whale
you have to put your transformation on the left of the equation
also i think you have an extra pi in there
quiet whale
Maybe someone can check correct me, but I think that's right
and if IIRC correctly, shell method is a bit different from other solids of revolution formulas cause you're integrating around the opposite axis than what you're rotating
in this problem, it doesn't really make much difference. But you could run into a problem where you need to isolate x or y for your equations and that could result in you integrating the wrong thing
shrewd schooner
I hate finding volume when the rotation is vertical
quiet whale
try and solve it now and see if it gives you the right answer
quiet whale
let's see your work
jolly parrotBOT
🌸 Katsune
quiet whale
alright well
you can either do integration by parts from here
or just distribute the terms
I'd distribute
shrewd schooner
$2\pi (\frac{x^3}{3}+x^2}) |^4_0$
jolly parrotBOT
🌸 Katsune
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
shrewd schooner
2pi(64/3 + 16)
quiet whale
hmm
shrewd schooner
224pi/3
quiet whale
show me the final set up for your integral before you integrated
I might know where the issue is
shrewd schooner
This isn't a hard integration at all
x(x+2)dx
x^2 + 2x dx
Thus
x^3 / 3 + x^2
Where is the problem ☠️
quiet whale
yeah it should be right
quiet whale
An online calc is telling me it's x^2 (x+2) dx
how did the online calc pull this out
shrewd schooner
Oh wait this is right okay
online calc made me think i should have entered x(x+2) for the function
this is correct for the function x+2
quiet whale
very nice
see bro, I should've just stayed lazy and assumed it was right in the first place 😤
quiet whale
yeah, it's just like the last problem
shrewd schooner
Okay, then what
jolly shuttle
then disc method
quiet whale
you can use shell for every problem
jolly shuttle
shell would be harder
quiet whale
but knowing when to use disk and washer makes your life easier
shrewd schooner
This is asking for a vertical rotation so why am I using disk when disk is for horizontal rotations
quiet whale
actually you can both of those methods for either rotation
jolly shuttle
method itself doesnt matter the rotation
quiet whale
it's just a matter of getting the equation and the integral set up correctly
shrewd schooner
Okay...
Disk method then ig
How am I supposed to do f(x) when x=y-y^3, it's with respect to y
jolly shuttle
so you integrate with dy
shrewd schooner
$V=\pi \int_{-1}^0 f(y)^2 dy$
jolly shuttle
same method but 90 degree rotated
jolly parrotBOT
🌸 Katsune
jolly shuttle
why -1~0?
shrewd schooner
Because you said to shift the entire graph left one
jolly shuttle
that's for x axis
jolly shuttle
x=y-y^3 is original right?
shrewd schooner
Yes
jolly shuttle
I mean you transformed left by 1
shrewd schooner
Shift graph left by one = transform left by 1
jolly shuttle
then x-1=y-y^3
shrewd schooner
And the limits of integration?
jolly shuttle
https://cdn.discordapp.com/attachments/908078029778083872/1206645608434241676/19...
the interval is for rotation axis
jolly shuttle
same as this
jolly shuttle
you integrated from a to b on x axis, where x axis is the one you rotate around
shrewd schooner
Yes, I think so.
jolly shuttle
For your question it's for y. So 0 to 1 on y axis, where y axis is the one you rotate around
shrewd schooner
I don't understand. Please show me how it should look like.
I will understand way better from replication. I don't understand theory discussion that well.
jolly shuttle
$\int_{0}^{1}{\pi f^2(y)dy}$
jolly parrotBOT
Dri111
shrewd schooner
Okay so thte limits of integration do NOT change, but the f(y) does change?
jolly shuttle
yes
shrewd schooner
$V=\pi \int_{0}^1 f(y)^2 dy$
jolly parrotBOT
🌸 Katsune
shrewd schooner
Where f(y) = x=y-y^3 -1
jolly shuttle
yes
jolly parrotBOT
🌸 Katsune
jolly shuttle
As you're aware of interval I think it is right
shrewd schooner
Why did the limits of integration not change?
It should have been -1 to 0 since the graph was shifted left.
jolly shuttle
because we didnt transformed the graph in y axis
jolly shuttle
we moved left, not up or down
shrewd schooner
Wtf. So the limits of integration are just looking at the y not the x?
jolly shuttle
if you are rotating it for y axis yes
if that is hard to take
then just think the interval after moving the graph
like this
shrewd schooner
I got | -17pi/21 |
jolly shuttle
,w integrate pi*(x-x^3-1)^2 from 0 to 1
jolly parrotBOT
jolly shuttle
idk how you calculated the integral
but it looks like that's actually not the right answer
jolly parrotBOT
🌸 Katsune
shrewd schooner
$\int_0^1(y^2-y^6-1)dy$
jolly parrotBOT
🌸 Katsune
shrewd schooner
Is it supposed to be all positives
Don't be so coy, you can tell me the polarity is wrong
Oh crap
I just realize this is a trinomial squared
I put in the calculator and it's right lmao
121pi/210
jolly shuttle
I think that's the right answer
shrewd schooner
.close ty btw :3
warped ether
Hey there, I got a physics test in a week and theres this question I don't understand exactly how to solve:
"A steel pipe must support 10 kN in a building structure. The inner diameter of the pipe must be 20 mm (due to the installation of electrical wires). Dimension pipes for a permissible stress of 60 N/mm^2"
So I started with defining diameter x and diameter y
dx = 20 + dy
(3.14*(dx)^2)/4 = dy
I'm wondering whether this is wrong? It seems logical to me because we want 20 + something we need to decide and to get the thing we want we put it through a geometric formula
warped ether
btw when I try solving it I don't get the correct answer but it's very close
pearl pondBOT
@warped ether Has your question been resolved?
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waxen sequoia
how do i solve this?
pearl pondBOT
how do i solve this?
edgy stone
how do i solve this?
what have you tried
waxen sequoia
what have you tried
i know that i can use the inclusion-exclusion principle and when the question is asking for "at least" its usually subtracting?
waxen sequoia
so its c) but im not sure with the values being used
waxen sequoia
so what would you be subtracting
thats what im trying to figure out. How do i come up with 2^n - 2^n/2
edgy stone
ok
so 2^n is the number of subsets of S
you want the number of subsets of S with at least one even number
so what would the opposite of that be
waxen sequoia
so 2^n is the number of subsets of S
what does 2 represent?
edgy stone
so
if you have a set with n elements
then for each of the elements
they can either be in a given subset, or not
so 2 possibilities
waxen sequoia
ahh
edgy stone
so there are 2^n possible subsets of a set with n elements
waxen sequoia
and the subset has to be even values?
waxen sequoia
right
edgy stone
here's a hint
waxen sequoia
so what would the opposite of that be
no even values
edgy stone
the number of subsets with at least one even value
right
what's another way to say that a subset has no even values
waxen sequoia
in terms of?
edgy stone
?
ok fill in the blank
if none of the elements of a subset are even
then all of the elements of a subset are: ___
waxen sequoia
odd
edgy stone
right
so then you can say
the number of subsets with at least one even value
is equal to: the number of subsets (2^n)
minus the number of subsets with all odd values
so you should try to find that
waxen sequoia
hmm
if you have n elements in a set and you divdide them by 2 you should get odd numbers
ok i got it. thanks
.close
pearl pondBOT
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frosty badge
Medians of the triagnle are 3cm 4cm and 5cm i need to find the area
pearl pondBOT
Medians of the triagnle are 3cm 4cm and 5cm i need to find the area
@frosty badge Has your question been resolved?
pearl pondBOT
Medians of the triagnle are 3cm 4cm and 5cm i need to find the area
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
the medians of a triangle split it into six smaller triangles, if you draw it
it turns out that all of those triangles have the same area
you can try to prove that
draw a diagram to start and then mess around with it
midnight haven
frosty badge
The median split the side in 2 equal parts right
And medians split each other 2:1
That effects all the triangles right
?
@edgy stone
midnight haven
You can easily find it using this
(The question there was what is the ratio of the are of triangle formed by the 3 medians to the area of the triangle ABC)
pearl pondBOT
@frosty badge Has your question been resolved?
pearl pondBOT
@frosty badge Has your question been resolved?
torpid cosmos
pearl pondBOT
torpid cosmos
The original equation is at the top
we have to simplify it
but im confused on whats the common denominator for the bottom two.... (because theyre opposites soooo)
hollow rose
but im confused on whats the common denominator for the bottom two.... (because ...
you can cancel out the (a + 3)
you’ll just be left with -2
torpid cosmos
but u cant cancel out when adding and substracting rational expressions
and either way thats wrong because I know the answer
hollow rose
Oh wait my bad
torpid cosmos
this is the answer for the question
granite wyvern
you can cancel out the (a + 3)
but when you factor 3-2a you get -2(a-3)
hollow rose
I read it as multiplication lol
neat harbor
are you sure about that first step
hollow rose
I’m doing this on paper gimme a second lol
torpid cosmos
are you sure about that first step
well shouldnt the variable come first?
thats what the tecaher told us idk
neat harbor
in the first fraction, how are you just adding that bracket
neat harbor
you cant?
granite wyvern
factor 3-2a into -(2a-3)
neat harbor
2a - 3 is not the same as 2(a - 3) as far as im aware
hollow rose
you can factor out the negatives
granite wyvern
bring - to top
torpid cosmos
omg
granite wyvern
yes
granite wyvern
-5/2a-3 is the same as 5/3-2a
neat harbor
yeah that’s what I wrote
granite wyvern
because if you bring the negative down : -(2a-3) = -2a +3 which is 3 - 2a
pearl pondBOT
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hollow rose
I just wanna see if im on the right track, since a= -2/3, there will be a vertical stretch factor of 2/3 and a vertical reflection?
hollow rose
And is my writing correct? Was I supposed to factor out the -2?
pearl pondBOT
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hollow rose
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hollow rose
Okay scrap the stuff above, can someone double check if everything on here is correct? I just gotta graph the g(x) which is gonna be a alot
tall wave
Okay scrap the stuff above, can someone double check if everything on here is co...
yes
shouldn’t be hard to graph u just move it over and make it smaller
hollow rose
there’s no horizontal reflection correct?
hollow rose
So there’s both a vertical and horizontal reflection?
tall wave
yes
pearl pondBOT
bronze harbor
I'm blind... where is I in the equations?
hollow rose
no im plotting the point
the lighting is terrible lol i’ll send a better one hold up
bronze harbor
No, I can see the whole thing
I'm just trying to find the reference point in the equation that you're trying to graph
hollow rose
im trying to graph the new function. the og is the the points labeled I, II, III and IV
hollow rose
lol
hollow rose
I was looking for a variable, lol
yeah im just wondering if I plotted I’ (I prime) correctly
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tacit edge
robust quail
i need help
pearl pondBOT
i need help
snow sail
did u see example 3
snow sail
you just write it as a product of two factors
snow sail
hmm? things?
pearl pondBOT
midnight haven
can you show your work
pearl pondBOT
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midnight haven
so in 34 , you have two rectangles , and those expressions are their areas
you have to determine sides
one side is common between the two
so you have to take the common factor as the vertical length of both rectangles
and then determine horizontal lengths accordingly
midnight haven
haan to woh hogi na , woh seedhi waali side hogii
which is common in both
midnight haven
divide 💀
robust quail
so its
robust quail
5ab(2ab^2+3b+4a)
robust quail
alg
robust quail
bro
midnight haven
kya hua
robust quail
its 2 years ahead of my level
midnight haven
fir kyu gand mra rha
midnight haven
5ab(2ab^2+3b+4a)
itna to kaafi hain na
midnight haven
she/her 💀
midnight haven
nahi be , 5ab is one side and the remaining is the other side
tumhe side ki length nikalni hain
area ka formula hota hain lb
so ek l hain aur dusra b
robust quail
a
midnight haven
close kardo if youre done
robust quail
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lone pier
pearl pondBOT
lone pier
Sorry for the vertical
lone pier
When factoring this, I’m turning it into a somewhat simple trinomial form, but I am having trouble knowing where how am I supposed to find my multiplication/addition combo for what b(-3) and c(1), I tried using a chat to explain and it instead used did a combo for 2x and -3x
One sec my dum brain trying to figure out how what u said works so I can try it rq
final hound
2x^2 - 2x - x +1
2x(x - 1) - 1(x- 1)
(2x-1)(x-1)
midnight haven
,rccw
jolly parrotBOT
versed mica
U CAN DO THAT?
yes
lone pier
2x^2 - 2x - x +1
2x(x - 1) - 1(x- 1)
(2x-1)(x-1)
Where did start this from in my current progression?
final hound
Where did start this from in my current progression?
im just solving hte bionomial
versed mica
Where did start this from in my current progression?
rewriting the trinomial
final hound
not disturbing the 2x outside
lone pier
Simple trinomial form would be like #x^2 + #x + # though right? I don’t understand what it turns into when you rewrote it sorry
final hound
yes
so when you equate the equation to 0
you can divide both sides by 2x
and you get a solution
there is a binomial remaining
when you solve the binomial you get the other 2 solutions
lone pier
One sec just processing, might be reading too into it in just trying to make sense of it rq
Is this what you said? Sorry just trying to relate this rq
lone pier
Ok cool
Ok thanks, i know it makes sense, but for some reason i can’t understand how 2x (2x^2 - 3x +1) turns into 2x [(2x^2 -2x -x +1)] but I’ll probably be fine, thanks for your help
final hound
in such binomials
its easy to factorize by using a technique called middle term splitting
im guessing you are not familiar with it
lone pier
Not really
lone pier
Alright
I’ll try to compare then and see the formula for middle term splitting
Thanks! (Post close, I just figured it out by just going backwards throughout your example, I feel kinda dumb but at least I know it now, rlly appreciate the help tho)
.close
pearl pondBOT
final hound
Thanks! (Post close, I just figured it out by just going backwards throughout y...
least i can do :)
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hybrid axle
find the number of seating arrangements in which eight people can sit around two identical circular tables (seating four on each table) if two particular people want to sit next to each other on a table, a second couple wish to sit at different tables and a third coiple wish to sit at the same table (but not necessarily together)
pearl pondBOT
find the number of seating arrangements in which eight people can sit around two...
@hybrid axle Has your question been resolved?
final hound
do you need the answer? or the working?
final hound
absolutely no idea
pearl pondBOT
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little cypress
pearl pondBOT
cinder brook
im just interesed in how to solve it normally (im not very good at combinatorics)
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tacit edge
hi how can i help
little cypress
how to do this same question for n people and r colors
.
pearl pondBOT
little cypress
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little cypress
ignored twice oof
native gull
ah yes jee advanced
native gull
generalising idk howto do
hold on
no two person sitting adjacent
so all colors
must be used
ummm
little cypress
so all colors
i dont think so
little cypress
i dont have a doubt in this q
little cypress
how to do this same question for n people and r colors
.
native gull
oh
m
b
i think you cant generalise
number cases matter
here 2 2 1 was the only case
little cypress
i think you cant generalise
💀 skill issue then
im thinking the same thing
there is probably some way tho
will probably be some really bad function in GIF and all
pearl pondBOT
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little cypress
no
sharp smelt
$\int_{10}^{19} \frac{cos(x)dx}{1+x^8}$, find the range of this area
jolly parrotBOT
Why am. I here
sharp smelt
.ie is it less than $10^{-7}$
jolly parrotBOT
Why am. I here
sharp smelt
more, or something else
how would I even start
as this is neither increasing nor decreasing monotonically
I was thinking I could estimate the positive area in one cycle
and then multiply it by an appropriate factor
,w 10/3.14
jolly parrotBOT
jolly parrotBOT
sharp smelt
So That's just below 1 cycle
this would thus be between 4 times the value of the function at 10
and 4 times that and 19
am I right?
,w value of cos(x)/(1+x^8) at x=10
jolly parrotBOT
sharp smelt
,w cos(10)/(1+(10)^8)
jolly parrotBOT
sharp smelt
,w 4(cos(10rad)/(1+10^8)
jolly parrotBOT
sharp smelt
,w (19rad)/(1+19^8)
jolly parrotBOT
jolly parrotBOT
Requested by physicsrocks
sharp smelt
,w what's the area under sin(x) from 0 to 3π
jolly parrotBOT
sharp smelt
,w what's the area under cos(x)/(1+x^8) from 10 to 19
jolly parrotBOT
sharp smelt
huh, could someone verify this for me?
is my logic correct?
<@&286206848099549185>
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austere pike
Yo
austere pike
I have this problem
and i need to check the position of those
i already figured that they aer parallell like if i multiply the direction vektors they are 0
but now i need to do a point sample
but how?
upper crypt
What you've said makes no sense