#help-39

1 messages · Page 41 of 1

reef quiver
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so you wouldn't be able to add the numerators together

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and combine into one fraction

dawn sierra
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Yeah because I'm multiplying by x+5

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Thank you, you are a lifesaver

reef quiver
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no problem!

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once your question has been answere

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you canclose the channel

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using .close

dawn sierra
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Okay

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.close

pearl pondBOT
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coarse dawn
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I did, you did it wrong

dawn sierra
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.close

coarse dawn
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Because $\frac{2}{5} + \frac{2}{6} \neq \frac{4}{11}$

jolly parrotBOT
#

dldh06

pearl pondBOT
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coarse dawn
#

,w (2/5) + (2/6) === (4/11)

pearl pondBOT
coarse dawn
#

False means not equal to

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,w (2/5) + (2/6) numerical value

coarse dawn
#

,w 4/11 numerical value

coarse dawn
#

@vapid horizon

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<@&268886789983436800> We got a troll here

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hollow pier
#

how to solve it?

pearl pondBOT
old geyser
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What have you tried

hollow pier
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i know it have to be solved like a non-homogenous

old geyser
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Yeah

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But first find y_h (the solution to the homogenous part)

hollow pier
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but i dont know what to do with de 14

old geyser
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so y" - 8y' + 7y = 0

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Start with finding the homogenous solution

hollow pier
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yeah thats easy

old geyser
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And then to find the nonhomogenous, let y = A. Then find y' and y", plug it in, and solve for A

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Since y = A is your particular solution

hollow pier
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the particular solution is 14?

old geyser
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No

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If y = A, plug in y, y' and y" into the nonhomogenous equation

hollow pier
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but y'=0 right?

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oh i see

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its 2

old geyser
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Yeah

hollow pier
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so the solution

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thannks

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help a lot

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stuck widget
#

would you guys give me the whole mark?

pearl pondBOT
stuck widget
#

so??

clear trench
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I would say the sign diagram is an equivalent merit to the 2x -6x^2 > 0

stuck widget
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what about final ans

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wispy loom
pearl pondBOT
wispy loom
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I dont know how to solve for x

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Do I just take the ln

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But the question told me to use the quadratic formula

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The other side is = 0

jolly parrotBOT
wispy loom
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I have no idea

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take the ln

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so x + 3(2x) + 3

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Take out a e

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Yeah

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Not really

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Because for (e^x)^2 I can just break them down and but then e^(2*x) is not the same as that

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Oh wait

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No it is

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And then take out e^x

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Is the answer there is no solution?

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jolly basin
pearl pondBOT
atomic ferry
#

use the shoe lace method

jolly basin
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This is what I did so far

jolly basin
jolly basin
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oh thanks

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just confused with the second step

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what did they do?

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wraith saddle
#

minor question, why is the standard form of a parabola y = 4ax^2

wraith saddle
#

like why do we not just include 4 in the constant a

midnight haven
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Just a convention. This makes the focus itself to be (0,a) and the other formulae simplify a bit.

wraith saddle
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makes sense thanks

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compact token
pearl pondBOT
compact token
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I have my doubt regarding the PDF of this Random variable

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I will explain

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compact token
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.reopen

pearl pondBOT
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compact token
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Can someone explain how it is c(t-X) in the PDF conditions?

karmic hound
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,rotate 90°

jolly parrotBOT
compact token
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Say we left at t' instead of t and according to the diagram you are like 5 minutes early then you would reach at 10:00

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so in the question you incur cs, and s is time here, how do you get s , which is the minutes that you are earlier to the class by subtracting X from t

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<@&286206848099549185>

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@compact token Has your question been resolved?

compact token
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past radish
#

Am I doing this right? Is it supposed to be written as a vector or as an equation?
Given: Integrate ((t)i+(3)j)dt

I took the integral of each individual piece and got
((t^2)/2)i+(9/2)j

Should I write it as
<(t^2)/2, 9/2> or is the first one good

jolly parrotBOT
pearl pondBOT
#

@past radish Has your question been resolved?

past radish
#

<@&286206848099549185>

pearl pondBOT
#

@past radish Has your question been resolved?

pearl pondBOT
#

@past radish Has your question been resolved?

nimble cave
#

also you didn't add +C FeelsBadMan

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tiny star
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please help

pearl pondBOT
tiny star
#

<@&286206848099549185>

pearl pondBOT
#

@tiny star Has your question been resolved?

dense goblet
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tame pawn
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p=irt solve for t

pearl pondBOT
dusty patio
#

,tex .alg manip

tame pawn
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i figured it out

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.close

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hushed egret
#

Hey

pearl pondBOT
hushed egret
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Status is 4

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I got an answer

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But I’m not sure

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If it’s correct

old geyser
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Remember what odd functions are

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f(-x) = -f(x)

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f(0) = -f(0) means nothing though

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Because that's also true for some even functions

old geyser
hushed egret
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That’s the

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True

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Yeah I’ll try that

hushed egret
old geyser
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Yeah

hushed egret
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As that’s the only one which satisfies the conditions

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Yup

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Thx

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wanton grotto
#

.reopen

minor mulch
#

Lucia is making a banner. The banner requires 12 yards of fabric and 3 yards of ribbon.

Lucia makes a third banner, still with the same ratio of fabric to ribbons. If the new banner requires 20 yards of fabric, how many yards of ribbon will it require?

minor mulch
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The part im stuck on is what times 12 is equal to 20.

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violet oyster
#

I need some help with derivatives. Would the derivative of e^-x be e^-x? Or would it change?

sick adder
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How familiar are you with the chain rule?

violet oyster
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Oh dang, not familiar, I wasn't sure if I'd need or not because my professor hasn't gone over it yet

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Is that the only way to solve for the derivative?

sick adder
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There might be some intuitive way but generally you'd use the chain rule to really show this one

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Is this a problem you have on a worksheet?

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Or just curiosity

violet oyster
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It's from my homework, trying to get ahead lol

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Is it the same for 8^x

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Chain rule ?

sick adder
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In a way yeah

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You modify it first and then use the chain rule

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If you want to get ahead, look into the chain rule first

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Which states $\frac{d}{dx} f(g(x)) = f'(g(x)) \times g'(x)$

jolly parrotBOT
#

M. Frost

sick adder
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For situations where you have compound functions, like e^-x where e^x=f(x) and -x=g(x)

violet oyster
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Ohh ok, i understand

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I'll keep this in mind so that way I can use it for when he goes over it later

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Thank you!

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have a good day

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sick adder
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cyan vortex
pearl pondBOT
cyan vortex
#

Im not sure why this answer is incorrect

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wait nevermind i thik i figured it out

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novel kestrel
#

Hi

pearl pondBOT
novel kestrel
#

One question, when multiplying monomials with different bases, do the exponents continue to add???

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for example

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Q°3 x P°4 = QP°7?

light helm
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no

native sparrow
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No, think of Q and P like the numbers 2 and 3, using your example 2^3x3^4=6^7

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However, if you do the math of that example, you find that they don’t equal each other

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For adding powers together, the base number has to be the same

novel kestrel
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is that the question for a job is If P is a polynomial of degree 4 and PQ is a polynomial of degree 7 then Q is a polynomial
grade 3

novel kestrel
novel kestrel
native sparrow
#

Yeah it would be false because it doesn’t follow the exponential product? Law

novel kestrel
#

Then it would be false because it does not comply with the law?

pearl pondBOT
#

@novel kestrel Has your question been resolved?

novel kestrel
#

jsaksaksaj

#

pense que nadie hablaba español

royal wolf
#

but nadie te entiende porque es un server ingles

novel kestrel
#

:v

royal wolf
#

en el shitpost habian mejores momos

novel kestrel
#

but no tienes foto de mujer y en cambio tienes una foto de anime but tu opinion no cuenta por eso

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covert ivy
pearl pondBOT
covert ivy
#

I get -inf for the answer so what should I put

warm dome
#

How did you get -inf?

split stream
covert ivy
#

how do I do this

warm dome
#

Do you know the graphs for these functions?

covert ivy
#

yes

warm dome
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Well, so you should find it easily, no?

covert ivy
#

what does it mean by upper bound and lower

warm dome
#

Oh ok

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A function has an upper bound where there exists a value such that the function is always lower than this value

covert ivy
#

ok

warm dome
#

And for lower bound, it's similarly that your function is always greater than some fixed finite value

covert ivy
#

can you show me an example

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im kinda confused

warm dome
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Do you know what's a minimum or a maximum?

covert ivy
#

yes

warm dome
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It's kind of a generalisation of these ideas

covert ivy
#

ok so I have the graphs how do I decide which one is right

jolly parrotBOT
#

Statufi

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Statufi

covert ivy
#

ok

jolly parrotBOT
#

Statufi

warm dome
#

Is it clearer? Could you now find which ones have an upper or a lower bound?

covert ivy
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I see that they either have just lower bond or both

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I dont see any with just upper

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d is lower

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c is both

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b is both

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a is both

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so what am I doing wrong

warm dome
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Maybe give me the upper/lower bound for each so we see the issue

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Or just some greater/lower value

covert ivy
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its lower bound when its negative y right

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and upper when positive y?

warm dome
#

I'm sorry I don't understand what you want to do...

covert ivy
#

im still confused what lower and upper bound is I think

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can you show me a graph of both

warm dome
#

Lower bound

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for the square function

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but no upper bound

covert ivy
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so what does a upper look like

warm dome
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Upper bound for this one

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But no lower

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One that has both:

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And one that has no lower or upper bound:

covert ivy
#

is d the answer

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thats what I think

warm dome
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It has an upper bound if "it cannot go to +infinity" anywhere

covert ivy
#

so its not that?

warm dome
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What would be the upper bound here?

covert ivy
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idk

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0

warm dome
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Yes

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Like some sort of a maximum but that it doesn't reach

covert ivy
#

ok

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so is this the answer

warm dome
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You said it

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0 is its upper bound

covert ivy
#

ok

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do you not remember the equstion

warm dome
#

yes

covert ivy
warm dome
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Does your function has a lower bound?

covert ivy
#

no

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its inf

warm dome
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-inf yes

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So that's the answer you wanted

covert ivy
#

ok

#

can you help me with another

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.close

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sweet radish
pearl pondBOT
sweet radish
#

What's the difference between option b and c

plush bramble
sweet radish
#

Ahhhhh

#

Righttt thank uuu

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visual lake
#

can someone explain division? i'm having a hard time understanding it

warm dome
#

Division? What kind of division?

visual lake
#

i can't imagine what would time/distance look like for example

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how do you divide time by distance? what does it mean? each division is completely an alien thing for me

warm dome
#

Ok aha that's ok

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Can I just know your level of schooling/studying?

visual lake
#

cs graduate

warm dome
#

ok

#

Is the notion of division a problem when we're talking about dividing quantities with different units (like time/distance)?

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Or is it in general?

visual lake
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like meters/seconds?

warm dome
#

Yeah

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For example if I say i do 2 meters/second, it means that in 1 second i do 2 meters, just a way of writing it in a math way

visual lake
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sometimes i think of division as repeated subtraction, sometimes as counting some unit with another unit. but i feel like i don't have a coherent concept of division

warm dome
#

I understand what you say

visual lake
#

and also yes, i have a hard time grasping dimensional analysis

warm dome
#

Actually to me the units like km/h, m/s etc that are unit created by a quotient, are just named like that for convenience in physics. But it represents a real math thing. For example, let's say that when you walk you do 10 meters in 2 seconds. Just imagine the 10 meters you walk on the ground. Let's say you walk uniformly (speaking about speed). Then, half of your 10 meters would be done in 1 second, like you're just cutting your 10 m walk in 2, right? So physicists just said "let's say you walked at a speed of 5m/s".

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I don't know if that answers even part of your question

warm dome
visual lake
#

hmm

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what about linear interpolation factor?

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x-x0/x1-x0

warm dome
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Actually I didn't cut distance by time in the example

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I'm not getting what you're trying to represent

visual lake
#

nevermind

#

sometimes division is used to single out some things

warm dome
#

ok

visual lake
#

when i think about multiplication i only think about something "times" something

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i can clearly visualise that but when thinking about division it feels like it has much more use

warm dome
#

To be honest I'm not sure I understand, sorry xD

visual lake
#

anyways, thank you for your help

#

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limber pumice
#

From the picture, if you turn the arrow head 2 3-4 turns counterclockwise, where will the arrow head point?

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thorny stream
pearl pondBOT
thorny stream
#

To start, Am i projecting QP onto QR?

midnight reef
#

Do you use any formula to calculate the distance from a point to a line?

pearl pondBOT
#

@thorny stream Has your question been resolved?

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thorny stream
#

given this shape, how can i represent lines AC and BC in terms of the radius?

thorny stream
#

would i use law of cosines, or is there a simpler way to do it?

blissful cloak
#

what's wrong with Pythagorean? :)

dense goblet
#

normal trig ratios is fine too

thorny stream
#

im not supposed to know that acb is a right angle

dense goblet
#

ok

thorny stream
#

so is law of cosines a good way to go about it or is there a simpler way?

#

cuz i can't use trig ratios since i dont kow that acb is a right angle

#

(at least pretend we don't know yet)

tulip forum
blissful cloak
thorny stream
#

how would i use trig ratios?

#

like law of cosines?

blissful cloak
#

In geometry, Thales's theorem states that if A, B, and C are distinct points on a circle where the line AC is a diameter, the angle ∠ ABC is a right angle. Thales's theorem is a special case of the inscribed angle theorem and is mentioned and proved as part of the 31st proposition in the third book of Euclid's Elements. It is generally attribute...

thorny stream
#

essentially im trying to prove the theorem

#

but without using angles because that's too easy

tulip forum
blissful cloak
thorny stream
#

but i dont know that it's a right angle yet

thorny stream
blissful cloak
#

no no say O=(0,0)

#

A=(-1,0)

#

and C=(1,0)

#

so it has radius 1, right?

#

then b is some point (sin(x),cos(x))

#

prove the product of the slope of AB and BC are -1 :)

#

and you've got your right angle!

tulip forum
thorny stream
#

but wouldn't i have to generalize the points?

#

like that is just one particulat set of points

blissful cloak
#

that's all we care about

#

could do (-2,0) or (2,0)

#

result would still be the same

thorny stream
#

the result would be, but wouldn't i need to generalize the proof to fit all points?

blissful cloak
#

then do (-n,0) and (n,0) if it satisfies your conscious

thorny stream
#

ok thank you!

#

.close

pearl pondBOT
#
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blissful cloak
#

.reopen

pearl pondBOT
#

blissful cloak
#

@thorny stream I messed up the proof only works for n=1

thorny stream
#

no worries, i can just ask my teacher tomorrow

#

thank you though

blissful cloak
#

but it works nonetheless as a proof helper_laugh remember Thales's Theorem only cares about whether or not those two points are a diameter so you're all good

#

actually I see where that could cause confusion

#

do whatever works for you :)

blissful cloak
#

.close

pearl pondBOT
#
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golden willow
#

Question: How many numbers are there between 100 and 1000 such that at least one of their digits is seven?

golden willow
#

Still struggling to know if its right with counting

ashen rover
#

First off, do you agree this question is equivalent to asking you how many 3-digit numbers contain at least one 7 as one of their digits?

golden willow
limpid belfry
ashen rover
golden willow
#

Lol hes here

limpid belfry
#

that contain the number 7

limpid belfry
#

tweakin

ashen rover
golden willow
limpid belfry
#

because its asking how many of the numbers contain 7

ashen rover
#

@crisp niche, relax lemme help Nightmare

golden willow
#

Ur right mb

#

Ty

ashen rover
#

great so 900 numbers

limpid belfry
#

mf

golden willow
#

Ya

#

Robbie f off

ashen rover
#

now throw away the ones that do not contain the number 7

golden willow
#

No clue bro

#

I could count

ashen rover
#

First digit can be one of how many things?

#

second digit?

#

and third digit?

golden willow
#

9, 10, 10

ashen rover
golden willow
#

8, 9, 9

ashen rover
ashen rover
#

so 900-8(9)(9) should be the answer

#

,w 900-899

jolly parrotBOT
limpid belfry
#

no way

ashen rover
#

do u disagree?

golden willow
#

We agree

limpid belfry
#

i dont

ashen rover
golden willow
#

I counted manually and got the same thing. Sorry about robbie hes an instigator

#

Much appreciated

#

.close

pearl pondBOT
#
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ashen rover
#

U know the limit of x_n is 2, so the limit of (x_n)^2 is 4. 4+3=7

#

of course not sure what you're allowed to assume in your proof

#

oh right I skipped over that when I read the problem lol

#

so we're asked to show $(x_n)^2$ converges to $4$, then correct?

jolly parrotBOT
#

logician

ashen rover
#

we don't have to worry about the +3=7

jolly parrotBOT
#

ZedRedBed

ashen rover
#

well more precisely $\left|x_nx_n-4\right|<\epsilon$

jolly parrotBOT
#

logician

ashen rover
#

because if we show that then that means the limit of x_nx_n is 4

#

so +3=7

ashen rover
#

so you know $|x_n-2|<\epsilon$ and $\left|x_nx_n-4\right|=|x_n-2|\cdot|x_n+2|$

jolly parrotBOT
#

logician

ashen rover
#

you know that given any positive real epsilon, there is a natural number N for which |x_n|-2< epsilon for all n>=N. Can you find an N for which this is less than epsilon?

ashen rover
#

since $x_n$ converges to $2$, it can't converge to $-2$. So what if you assumed for the sake of contradiction, that there is some positive real epsilon, for which no matter what $N$ you choose $|x_n^2-4|\geq\epsilon_1$ for some $n\geq N$. For such epsilon we also know there is an $N_1$ for which $|x_n-2|<\epsilon$ for all $n\geq N_1$. For such $N_1$, we have $|x_n-2|<\epsilon_1\leq|x_n-2|\cdot|x_n-(-2)|$ for some $n\geq N_1$.

#

this is what I'm thinking so far....

jolly parrotBOT
#

logician

pearl pondBOT
#

@buoyant tinsel Has your question been resolved?

ashen rover
#

Here's another thought:

#

$|x_nx_n-4|=|x_n(x_n-2)+2(x_n-2)|\leq|x_n|\cdot|x_n-2|+2\cdot|x_n-2|$.

#

this looks potentially more promising @buoyant tinsel

jolly parrotBOT
#

logician

ashen rover
#

if this doesn't work out, try posting this question in the analysis channel.

#

hard to know exactly what you can assume here aside from the definition of convergence...I've used the triangle inequality above^

pearl pondBOT
#
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oblique reef
#

every integer that takes the form: x^2 + 4x + 3 for some x is prime

oblique reef
#

this is true right?

toxic lichen
#

x^2 + 4x + 3 = (x+1)(x+3)

tired violet
#

you can also immediately discredit it since x=1 gives 8

#

definitely isnt prime for all

oblique reef
#

no i get that, but doesn’t it say

#

“for some x”

#

that means some x has to satisfy that the output is prime

toxic lichen
#

oh you wanna go formal

oblique reef
#

and it can yield a prime

oblique reef
toxic lichen
#

the statement says

forall y. ((exists x. y = x^2+4x+3) => y prime)

#

the "exists x" is inside not outside as you are now trying to pretend it is

upbeat field
#

lmfao

oblique reef
#

dangge

upbeat field
#

crazy

oblique reef
#

okay i see

oblique reef
toxic lichen
oblique reef
#

thanks ann

upbeat field
#

i know for a fact: (∃x ∈ Z)(x^2 + 4x + 3 ∈ P)

#

this is true

#

cuz x = 0

#

so one case exists

#

however

#

whats the point of saying "for some x in z"

#

like i dont get that wording

#

and i thoguht when it says every integer, it means like what x^2 + 4x + 3 = y, where y is the integer

#

"inferred integer"

#

for "every integer y in z"

cinder flower
#

there are non integer values of x that make x^2 + 4x + 3 an integer

#

the "for some x in Z" removes those from consideration

upbeat field
#

OHH

#

forgor that was a thing

#

it all makes sense now, thank you so much

#

.close

oblique reef
#

.close

pearl pondBOT
#
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pearl pondBOT
#
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fringe juniper
#

can anyone help me understand what i’m doing wrong

fringe juniper
#

nvm i got it

pearl pondBOT
#

@fringe juniper Has your question been resolved?

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fleet field
#

Hello

pearl pondBOT
fleet field
#

can someone solve this with all the steps on a paper so its clear pls

toxic lichen
fleet field
#

☹️

toxic lichen
warped violet
#

No point in things being solved for you

fleet field
#

okay then say how i have to solve this

midnight haven
#

!status

pearl pondBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
fleet field
#

1

#

beginning is hardest

midnight haven
#

I'd say the first thing you can do is make all the exponents positive

#

By this rule

#

$x^{-3} = \frac{1}{x^3}$

jolly parrotBOT
#

Wesley

fleet field
#

i do this with (2x+5)^-2/3

midnight haven
#

Yep

#

What do you notice about the denominator?

fleet field
#

i can miltiply thep

#

them

#

same base

#

what now?

#

@midnight haven

midnight haven
#

Numerator of exponent is a 4 right just confirming

fleet field
#

yes

#

sorry i have bad writing

midnight haven
#

Np

#

Do you see a common factor between the two terms in the numerator?

fleet field
#

3?

midnight haven
#

Not quite

fleet field
#

(2x+5)?

midnight haven
#

$3x^2(2x+5)^{\frac{1}{3}}-2x^3$

jolly parrotBOT
#

Wesley

midnight haven
#

Term 1 is on the left of the minus sign, and term 2 is on the right

fleet field
#

x^2?

midnight haven
#

Yes

#

You can factor that out, like doing the opposite of FOIL

fleet field
#

yes

#

any more steps?

midnight haven
#

I'm doing it now

#

We'll have to go back a step

#

Just un factor

fleet field
#

okay thnxx

midnight haven
#

Then you can separate the fractions

fleet field
#

results should ve thus

midnight haven
#

Here

#

Then just subtracting the fractions

fleet field
#

oh okay i see

#

let me test thus

midnight haven
#

Hmm

#

I got correct denominator but not numerator

fleet field
#

hmm

#

im not getting it eaither

midnight haven
#

I'm almost there

#

Dang

#

Alright I got it

#

Start here:

#

From beginning:

#

$3x^2(2x+5)^{1/3}-\frac{2}{3}x^3(2x+5)^{-2/3}$

jolly parrotBOT
#

Wesley

midnight haven
#

Becomes

#

$3x^2(2x+5)^{1/3}-\frac{2}{\cancel{3}}x^3 \frac{1}{3(2x+5)^{2/3}}$

jolly parrotBOT
#

Wesley

midnight haven
#

Cancels the three from 2/3 because it's in denominator

#

$3x^2(2x+5)^{1/3}- \frac{2x^3}{3(2x+5)^{2/3}}$

jolly parrotBOT
#

Wesley

midnight haven
#

Subtract the two

#

I've gotta run now but you can DM me if you get more stuck

fleet field
#

alrighht lemme try

midnight haven
#

But basically subtract those two fractions, which results in a 3-layer kind of fraction. Keep simplifying very top of layers, then you use this rule:

#

$\frac{\frac{a}{b}}{c} = \frac{a}{b}*\frac{1}{c}$

jolly parrotBOT
#

Wesley

midnight haven
#

To simplify it even further

fleet field
#

alright let me try

pearl pondBOT
#

@fleet field Has your question been resolved?

pearl pondBOT
#
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pearl pondBOT
#
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midnight haven
#

By looking only at the parametric equations,
How do i find the points the graph intersects

pearl pondBOT
#

@midnight haven Has your question been resolved?

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wheat eagle
#

high-school math here, answer key is 2u=v, someone please tell me how to solve

wheat eagle
#

Idk how to even proceed

#

I may not be here to see when you answer since I have to sleep soon, so thanks in advance and please do ping !

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#

@wheat eagle Has your question been resolved?

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glossy pecan
#

Please may I get someone to explain to me how to work this out

wicked hull
#

b is the angle of W and Z I think so

glossy pecan
#

<@&286206848099549185>

pearl pondBOT
#

@glossy pecan Has your question been resolved?

glossy pecan
#

Please someone help I just wanna go sleep 🤣

pearl pondBOT
#

@glossy pecan Has your question been resolved?

pearl pondBOT
#
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dark prism
pearl pondBOT
warm junco
#

A 9 cm high pyramid has an equilateral triangle as its base, whose incircle has a radius of 2.5 cm. Find the surface area of the pyramid.#

pearl pondBOT
warm junco
#

Im sorry

remote roost
pearl pondBOT
# dark prism
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
dark prism
pearl pondBOT
#

@dark prism Has your question been resolved?

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#
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merry goblet
#

alr have the answer but need help with explaining

factor $4x+10+16x^2-100$

jolly parrotBOT
#

Minds&Moves

pearl pondBOT
#

Please don't occupy multiple help channels.

merry goblet
#

A= 4x+10+16x^2-100
=16x^2+4x-90
=2(8x^2+2x-45)
=2(4x(2x+5)-9(2x+5)
=2(2x+5)(4x-9)
what about this

coarse dawn
merry goblet
#

okay

#

m back!

merry goblet
#

hello?

#

its just basic math

#

<@&286206848099549185>

#

factor $4x+10+16x^2-100$

jolly parrotBOT
#

Minds&Moves

merry goblet
#

Even if i ping <@&286206848099549185> no body helps..

#

.close huh

pearl pondBOT
#
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sweet radish
#

I don't understand the solution really

pearl pondBOT
sweet radish
junior night
#

You're asked for the difference between the two in terms of volume

#

The volume of the first cylinder is 63pi
The volume of the second is 126pi, so d) 2v is your answer, when you divide 126 by 63.

sweet radish
#

Ahhhhh

#

There's two cylinderss 😭😭😭

junior night
#

Is that clear now?

sweet radish
#

Yes yes makes much more sense now

#

Thank uu

junior night
#

No problem

sweet radish
#

.close

pearl pondBOT
#
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pearl pondBOT
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copper ingot
#

What is the relationship between r and k

pearl pondBOT
copper ingot
#

Specifically what is k in terms of r

pearl pondBOT
#

@copper ingot Has your question been resolved?

copper ingot
#

<@&286206848099549185>

pearl pondBOT
#

@copper ingot Has your question been resolved?

pearl pondBOT
#

@copper ingot Has your question been resolved?

pearl pondBOT
#
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misty hamlet
pearl pondBOT
misty hamlet
#

i need help pls!~!

#

pls!!

sturdy lantern
#

How many days are spent on state/local taxes?

misty hamlet
#

36 days!

#

love ur pfp btw

sturdy lantern
#

hhh thanks :)

#

So 36 days out of how many?

misty hamlet
#

365

#

daus

sturdy lantern
#

36/365

misty hamlet
#

isnt that 131.4?

sturdy lantern
#

No

#

131.4 would be like 480 days

misty hamlet
#

oh..

#

i got 098

#

but it says i got it wrong

sturdy lantern
#

36/365 = 0.09863

#

So 9.86%

misty hamlet
#

ohhhhh

sturdy lantern
#

You get the percentage by multiplying the decimal by 100

misty hamlet
#

NOOOO I GOT IT WRONG

#

I DIDNT KNOW I WAS UPPOSED TO ROUND IT

#

AFROHJOIAOWFH

sturdy lantern
#

Oops sorry

#

Rounded to one decimal its 9.9%

misty hamlet
#

wait then how is this wrong?

sturdy lantern
#

Ah

#

It was 37 days

#

Not 36

misty hamlet
#

huh

#

what

sturdy lantern
#

Oh its a different question

#

My bad

misty hamlet
#

yeah

#

LOL

sturdy lantern
#

14/365

misty hamlet
#

which is 0.03835616438

sturdy lantern
#

Try 3.8%

misty hamlet
#

oh

#

YAYYYYY

#

IT WORKED

#

THANK YOUU

sturdy lantern
#

Nicee

misty hamlet
#

can i ask you one more?

sturdy lantern
#

Sure go ahead

misty hamlet
#

tyyyyy

sturdy lantern
#

Do you have an idea on how to approach this?

misty hamlet
#

i have no clue honestly

#

it has to do with 2016

#

but

#

yea..

sturdy lantern
#

Ok so we can see that the life expectancy is a lot higher in 2016 than during the stone age

misty hamlet
#

yes

sturdy lantern
#

Basically, we do the same thing as before

#

69/26

misty hamlet
#

oh!

#

where did u get the 26 from?/

sturdy lantern
#

26 is the life expectancy during the stone age

#

In the bar graph

misty hamlet
#

OHHH

#

and i got 2.65384615385

#

so

#

2.7?

sturdy lantern
#

Uhm

#

We want to turn it into a percentage first

misty hamlet
#

oh

#

my goodness

#

u right

sturdy lantern
#

If the life expectancy in 2016 is 2.7% of what it was in the stone age, it would imply that the life expectancy has gone significantly down

#

Which contradicts what we see in the graph

misty hamlet
#

yes

#

but

#

wouldnt it be

#

2.7% increase

#

not decrease

sturdy lantern
#

Almost. We are expecting it to increase, but by a lot more than 2.7%

#

Do you remember how we calculated the percentage in the previous problems?

misty hamlet
#

the pie chat?

#

chart?

sturdy lantern
#

Yes

misty hamlet
#

i guess?

sturdy lantern
#

After calculating the decimal value of the fraction

#

We multiplied by 100

#

We need to do the same here

misty hamlet
#

okay

#

so uh

#

265.38

#

is my percentage

#

is that rigght?

sturdy lantern
#

Yess

misty hamlet
#

should i round it as well?

sturdy lantern
#

265.4

#

Yeah

misty hamlet
#

ok

#

D:

#

i get 1 more attempt

#

what happened

sturdy lantern
#

Wait

#

It said to round to the nearest integer

#

So 265%

#

Wait

#

Let me read the question one more time just to be sure

misty hamlet
#

okay

sturdy lantern
#

The way they defined percentage increase

#

Is different from what we just did

#

I think its best to use the formula thats given in the picture

misty hamlet
#

okay

#

so it should still be 265 tho

#

right

#

i think..

sturdy lantern
#

No

#

The 2016 life expectancy is 265% of the stone age

misty hamlet
#

o

sturdy lantern
#

But amount of increase / original amount

misty hamlet
#

ok

sturdy lantern
#

Will give a different number

misty hamlet
#

what is the orginal amount?

sturdy lantern
#

That would be the life expectancy during the stone age

#

So 26

misty hamlet
#

oh!

#

265.38/26

#

right?

sturdy lantern
#

No

#

The amount of increase

#

I think is 69 - 26

misty hamlet
#

oh

sturdy lantern
#

Honestly, the question is poorly formulated. Since it can be interpreted in multiple ways

misty hamlet
#

true

sturdy lantern
#

Hopefully its not graded

#

But yeah (69-26)/26

#

=43/26

misty hamlet
#

it is LOL

#

ok let me tryt that

#

1.65

#

so that times 100 is

#

165.38

#

so 165 is the asnwer?

sturdy lantern
#

🤞🤞 hopefully

misty hamlet
#

I GOT IT RIGHT

#

YAYYYYYYYYY

sturdy lantern
#

LETS GOO

misty hamlet
#

THANK YOU

#

did u know girls like nerds

#

keep it up

#

<3

#

thank you :)

#

.close

pearl pondBOT
#
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pearl pondBOT
#
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cold temple
#

why is et/2 raised to the power of infinity zero ?

cold temple
pearl pondBOT
#

@cold temple Has your question been resolved?

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placid compass
#

can anyone help me get into the right direction? im missing a step i feel like. I know the 800x^4cos^3(4x^5) i can get from chain rule of cos^4(4x^5) * 10 but i dont know where to get the sin(4x^5) from

dense goblet
#

also from chain rule

placid compass
#

so im missing a step then

#

what step am i missing

plucky nebula
#

Think about how you would differentiate (1 + x^2)^2

#

You would first bring the power down

#

Then write the expression with the power decreased by one

#

And finally, by the chain rule, differentiate the inside of the function

placid compass
#

I thoguht by diffrentiating the inside of the function i would turn 4x^5 to 20x^4

plucky nebula
#

In your case, the inside of the function is cos(4x^5)

placid compass
#

ohhhhh

#

i would also diffrentiate cos

plucky nebula
#

Yeah it’s confusing

placid compass
#

to -sin

plucky nebula
#

Yeah

placid compass
#

so i would diffrenciate twice?

plucky nebula
#

No you wouldn’t

#

I’m kinda confused by what you mean by diff twice

placid compass
#

ohhhh i get it

#

alright i understand what you meant now

plucky nebula
#

Yeah it’s just like the other function i gave you

placid compass
#

yes

plucky nebula
#

Most diffs are like this

#

Glad that it helped

placid compass
#

thanks

#

have a good one

#

.close

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#
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cursive flare
#

could someone guide me

pearl pondBOT
wet osprey
#

What have you done

cursive flare
#

shown that d is a metric

#

devastation thats about it

#

wait nvm I skipped the intermediate thingy

#

.close

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midnight haven
#

Question: There are 14 boys standing around in a circle, of which one of them is Charlie. 10 girls walk up and join the circle at random to form a larger circle. Each girl must be between 2 boys. If the girls arrange such that all ways of forming a larger circle are equally likely, find the probability Charlie is still standing between two boys.

I wrote out a sequence of BGBG... and saw that there were 3 boys who were inbetween 2 other boys so I did 3/14 but don't think this is the right answer and a reason could be is I did not consider all possible combinations or permutations but am not sure how to apply it here.

midnight haven
#

<@&286206848099549185>

vestal tapir
#

it's easy to count

#

with a calculator of course

#

the girls randomly fill 10 out of 14 spots

#

and the condition is that 2 spots next to charlie don't get filled

midnight haven
#

If I do 14 choose 10 to find the number of combinations of girls and boys standing then how can I factor in that grls have to stand inbetween 2 boys

vestal tapir
#

the first girl can stand in 14 spots, the next can stand in 13

#

like it's a fake condition sorta

#

you don't have to track it in a sophisticated way, it just gets used up

midnight haven
#

sorry I don't think I understand

vestal tapir
#

i'm saying 24 choose 10 would do what you said

#

we're not doing 24 choose 10

midnight haven
#

ah ok

vestal tapir
#

we're choosing empty spots between boys to get filled

#

and they don't behave weirdly

midnight haven
#

ahhh okok yeah I understand your previous point

vestal tapir
#

they just behave like they are getting filled

midnight haven
#

So I think there will always be 3 spots where a boy is standing between two other boys

vestal tapir
#

i don't think that makes sense

#

like, i don;t know if it's right, if it's right, it's useless

#

think of boys as lampposts or something

#

they are static

#

there's 14 lampposts, one of them is red, and there's space for one girl between 2 lamp posts. what's the probability there's no girl next to a red one

midnight haven
#

If there are 10 girls with 14 lampposst each one would have to not stand in the two spots next to the red lampost so would it be 1/12! ?

vestal tapir
#

If there are 10 girls with 14 lampposst each one would have to not stand in the two spots next to the red lampost
yes, that's how i see it

#

no clue why it should be 1/12!

#

it would be like (12/14)(11/13)...

#

like 10 misses in a row

midnight haven
#

Yeah sorry I made mistake and thought it was one girl with 12 spaces they could fill

vestal tapir
#

if we reserve 2 spots, there would be 12c10 combinations, and 14c10 in total

midnight haven
#

Ahh okok

#

Yes seeing the 12C10/14C10 makes sense

vestal tapir
#

,calc (3/5)(4/6)(5/7)(6/8)(7/9)(8/10)(9/11)(10/12)(11/13)(12/14)

jolly parrotBOT
#

Result:

0.065934065934066
midnight haven
#

ahh okok

#

Thank you so much I think I get it now

#

.close

pearl pondBOT
#
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devout surge
#

Hi, I just need some math double-checked

old geyser
#

Send it

devout surge
#

Ok, so we got f(x, y) = x - y

#

I need to calculate the partial derivative wrt x and y

#

I get 0 for both, is this correct?

foggy mason
#

no lol

devout surge
#

i didnt think so

#

heres my logic

#

df/dx = x - 1

#

treat y as a constant, which is 1

old geyser
#

That's not correct

devout surge
#

x^1 = 1x^0 = 1

#

1 - 1 = 0

old geyser
#

Partial f/partial x is not x -1

#

It's just like doing a regular ass derivative but any other variable is treated like a constant

#

So partial x of xy + x + y is y + 1

devout surge
old geyser
devout surge
#

but wouldnt you get x1 + x + 1

#

.close

pearl pondBOT
#
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old geyser
#

Partial x means to take the derivative wrt only x

#

,w partial x of (xy + x + 1)

jolly parrotBOT
pearl pondBOT
#
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midnight haven
#

How do i find the area inside this parabola

midnight haven
#

Is it this?

pearl pondBOT
#

@midnight haven Has your question been resolved?

pearl pondBOT
#

@midnight haven Has your question been resolved?

pearl pondBOT
#

@midnight haven Has your question been resolved?

nimble cave
# midnight haven Is it this?

if f is the function f(x) = (1/4p)x^2, then f doesn't have an inverse. but the preimage of h contains exactly 2 elements (unlesls h = 0); you can just pick the positive one

#

otherwise seems good

#

you can write it out more explicitly than f^{-1}(h) though

pearl pondBOT
#

@midnight haven Has your question been resolved?

midnight haven
#

ty

pearl pondBOT
#
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opal forge
pearl pondBOT
opal forge
#

How to check what this will form?

#

,rotate

jolly parrotBOT