Looks like there is some piece of the question 5 missing in the picture
#help-39
sturdy lantern
cant see the entire description of the set A
Q6 looks good to me
Q7 would be nice to see the theorem that is being proven
nevertheless, Caleb computed the complement of B wrong
river sun
Looks like there is some piece of the question 5 missing in the picture
wdym
its there
river sun
nevertheless, Caleb computed the complement of B wrong
7 is correct right
sturdy lantern
not sure about the examples
do induction proofs count as examples?
also, is it multiple choice? because Caleb definitely computed the complement of B wrong
sturdy lantern
Q5 says $A={(n,m) | n,m \in \mathbb{N}, 0 \leq 2m(n+1 -\$ Where is the rest of the set?
river sun
wait so q5 is wrong
jolly parrotBOT
OOKK
sturdy lantern
cant see the whole set
sturdy lantern
now that i think about it
Q7 is probably right too
even though Caleb did computational errors
it doesnt matter
river sun
sturdy lantern
because the example doesnt prove the theorem
river sun
here
sturdy lantern
q5 looks good to me
river sun
can i check more of my answers with u
sturdy lantern
sure
river sun
river sun
whaaat
river sun
oh im correct?
sturdy lantern
yeah
sturdy lantern
both good
river sun
oh
main crane
Help please. This is my first time doing this kind of math.
pearl pondBOT
Help please. This is my first time doing this kind of math.
sweet junco
Help please. This is my first time doing this kind of math.
do you know how to find the slope of a line?
main crane
My teacher told me it's y=mx+b or something like that but I didn't understand him that much
sweet junco
My teacher told me it's y=mx+b or something like that but I didn't understand hi...
the slope, or m = (y2-y1)/(x2-x1)
main crane
wait nvm, he said something like rise over run
sweet junco
Where (x1, y1) and (x2, y2) are points in the line
sweet junco
wait nvm, he said something like rise over run
Yeah, climb up steps
sweet junco
the slope, or m = (y2-y1)/(x2-x1)
use this to get m, then when you get m
use the values of x, y, and m to get b
sweet junco
use the values of x, y, and m to get b
Any point can work
main crane
Some of the instruction on a example says to "Choose any two points. Find the rise and the run.
"
But idk how
sweet junco
Some of the instruction on a example says to "Choose any two points. Find the ri...
Yeah
rise and run is like
for how much it moves to the right, how much does it move upwards or downwards
In this case, when the line is moving to the right, it's moving down
main crane
What if I choose point (1,5)
sweet junco
What if I choose point (1,5)
that's not a point on the line
or in the line
I'm not sure how prepositions work in this scenario
main crane
(2,2)?
main crane
How do find the point on the line
main crane
So is it:
Slope= Rise/Run= -4/6 = -2/6
x intercept: 1
y=mx+b
y=-2/6 X-1
@sweet junco ?
sweet junco
<@910426153217581057> ?
no?
main crane
š
sweet junco
So is it:
Slope= Rise/Run= -4/6 = -2/6
x intercept: 1
y=mx+b
y=-2/6 X-1
uh
Uhhh
Well, there's a really good video tutorial on youtube on how to do this
dusty plank
does anyone know how to solve this
pearl pondBOT
does anyone know how to solve this
dusty plank
A business firm is owned by five partners, P1, P2, P3, P4, and P5. When making
group decisions, each partner has one vote and the majority rules, except that P1 has
veto power and therefore must vote yes for the motion to pass.
Find the Banzhaf power distribution of the weighted voting system.
midnight haven
P1 has all the power
dusty plank
i understand that but i am confused on how you write the weighted voting system
can you walk me through a step by step process
midnight haven
[3: 1, 1, 1, 1, 1] but $P_1$ must vote yes for the motion to pass
jolly parrotBOT
Replaced by new brandon H
midnight haven
The easy way to solve would be
Creating a power set from ${P_1,P_2,P_3,P_4,P_5}$ ( list all the subsets )
Remove the sets that don't include $P_1$
Count the times that each player is critical
Then divide by the number of subsets
dusty plank
okay how would that look like? I think i know what you are talking about but im not really sure
how would the banzaf power look like? becuase I think i did something wrong
pearl pondBOT
@dusty plank Has your question been resolved?
dusty plank
no
pearl pondBOT
@dusty plank Has your question been resolved?
finite rover
I'm not sure how to deal with this, if I subtitute, it becomes undefined. I can't manipulate it as well, but somehow the answer is -infinity
finite rover
Could you explain the steps you would take to solve this
opal moss
when you square something itās always non-negative
continue the reasoning from there
finite rover
So since both sides are approaching a negative number and since the denom will always be positive, then the value will always be negative
how would I know if it's infinity without graphing it?
gusty prism
gusty prism
I have question
so y-x and x-y turn to -1?
If thats even right where would i put the negative 1
vital estuary
-1 can technically go anywhere
frosty bolt
You are correct
pearl pondBOT
pearl pondBOT
Available help channel!
thorn plume
so
molten hornet
so to be clear they are asking for the arc length right
toxic lichen
this is excessive btw.
thorn plume
is it actualy 152?
toxic lichen
a central angle subtends an arc of the same degree measure as itself
you don't need any inscribed angle here
thorn plume
but
dont i have to multiply by radius?
when i have like
an angle and a arc length
i mean like
im definitely mixing stuff up
i just dont know what
molten hornet
well apparently they are not asking for arc length
thorn plume
if they were, i would need a radius right
cuz i thought they were asking for arc length
thats y i was so confused
since there isnt a radius ;-;
molten hornet
right so this question is more obvious than i thought, i guess it is just a definition check for arc measure
thorn plume
whats the diff between arc measure and length
molten hornet
didnāt you packet tell you or something
molten hornet
go read the packet again, i am not going to spoon feed you everything
thorn plume
go read the packet again, i am not going to spoon feed you everything
i dont have access to it
im just confused with what an arc measure is
vs arc length
thats all
wats the point of opening a help channel only to be told to read a packet i dont have
.close
heady oak
pearl pondBOT
heady oak
How do I write this in set notation
sweet bone
what have you tried so far?
heady oak
Like rn I'm guessing x belongs to real number such that -5<x<-1,xā -1,-1<x<8
Is that correct
pearl pondBOT
@heady oak Has your question been resolved?
pearl pondBOT
@heady oak Has your question been resolved?
halcyon grove
how to simplify square roots- eg simplify square root of 48?
pearl pondBOT
Available help channel!
onyx night
How do I inverse this function.. or is it already D?(note: I donāt have the answer key :( )
pearl pondBOT
How do I inverse this function.. or is it already D?(note: I donāt have the answ...
verbal whale
In general, it (like in this exercise) can be very hard to find the inverse of a function. Hence, here I would simply look for which x gives you -5 as output
In other words, solve f(x) = -5. This equation is also very difficult to solve, but there is a solution that should jump out at you
Hint: look at the coefficients 15 and -20 and try to think how they are related to -5
pearl pondBOT
@onyx night Has your question been resolved?
onyx night
Hint: look at the coefficients 15 and -20 and try to think how they are related ...
Sorry for the wait, I didnāt really understand the relation part
Oh
I see
Okay got it
Nice man thanks!
pearl pondBOT
pearl pondBOT
Available help channel!
proper harness
What would be the steps to do this
pearl pondBOT
What would be the steps to do this
lethal rock
(3-1)^2 + (-4-2)^2 = 40 (Radius Square)
proper harness
@lethal rock so if it passes through a point I just do a^2+b^2=c^2
olive rover
pearl pondBOT
midnight haven
!status
pearl pondBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
pearl pondBOT
@olive rover Has your question been resolved?
olive rover
<@&286206848099549185>
regal plume
i think maybe start by writing it down
then either turn the fractions into percentages or add the fractions together then simplify it then turn it into a percentage
and then turn it into a decimal or number
pearl pondBOT
@olive rover Has your question been resolved?
queen sorrel
Hi
queen sorrel
8 a
And B
Are the questions Iām stuck on
Mainly a rn
I have a test tomorrow
So unfortunately imma ping
<@&286206848099549185>
Cus im in deep crap rn
pearl pondBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
coarse dawn
So unfortunately imma ping
You don't get special privileges to ping early
queen sorrel
Ok then I wonāt do that again
queen sorrel
Yes
queen sorrel
I tried
But the coords it gave were incorrect
Because I think I made a mistake
Somewhere
Maybe itās not supposed to be negative?
crisp laurel
Why is it -8?
because $$ (-2 \cdot 1)^3 = (-2)^3 = -8 $$
jolly parrotBOT
rti
crisp laurel
And see what comes out
Yes, that will be y
and then you plot those points on the graph
queen sorrel
Oh I think the ()^3 messed me up
Because I did this
Earlier
And thereās no ()^3
You just plug in
And abide by the b value
Thanks
.close
pearl pondBOT
pearl pondBOT
Available help channel!
still fiber
pearl pondBOT
still fiber
This is law of cosines, yes?
What exactly does it want me to show
Like just make up numbers?
mental hinge
im guessing they want you to derive that second equation
still fiber
How in the fuck would you even do that
still fiber
Cos(theta) = adjacent/hypotenuse
mental hinge
Thatās not the *cosine rule*
(alternatively called the law of cosines)
still fiber
Oh yeah law of cosines is what is given in the picture but take the square root
So itās not c^2
still fiber
Ya
wet osprey
Have you ever proved the law of cosines from geometry?
still fiber
I havenāt
wet osprey
Then as an exercise Iād say itās a good thing to try first
If you donāt have many things in your vector toolbox then you may possibly know more in geometry land, if you can prove it in geometry land itās possible you can transfer each line of your proof into vector notation
pearl pondBOT
@still fiber Has your question been resolved?
split lodge
I'm just perpetually stuck
pearl pondBOT
I'm just perpetually stuck
split lodge
i tried to chegg it only to find out that i got the same exact answer as chegg and it's still wrong
why am i just wrong???
pearl pondBOT
@split lodge Has your question been resolved?
wispy comet
Ive tried everything on this, and cant get the last row to work, the first 2 are correct but i cant find a multiplier that satisfys the third row
unborn abyss
if you can get the first two to work but not the last, it's probably impossible
woven matrix
a(1, 9, 8)+b(2, 6, 5) = (9, 21, 18)
it is indirectly a system with 3 equations and two unknowns
if it works for the first two but not the third, it's just a case where the system cannot be solved, so impossible
slender sundial
can someone help me understand limits?
pearl pondBOT
can someone help me understand limits?
fleet sky
This limit in particular is a well known one that equals 1. The proof for it is most commonly taught as a proof by geometry and at your level that would be the most intuitive approach
I recommend watching this: https://www.khanacademy.org/math/ap-calculus-ab/ab-limits-new/ab-1-8/v/sinx-over-x-as-x-approaches-0
it might take a few times to grasp
slender sundial
ill check it out rn
slender sundial
i just dont understand how to get there rn
spice coyote
i just dont understand how to get there rn
the answer for that limit when x-0 always is 1 simply, but if u want to understand why is a big issue.
clear sedge
slender sundial
i didnt have much knowledge going into limits
slender sundial
i was told i had to factor the numerator for a removable discontinuity
clear sedge
i was told i had to factor the numerator for a removable discontinuity
there are multiple theorems by which we can solve this limit
squeeze theorem being the most used one
did u find it helpful?
slender sundial
squeeze theorem being the most used one
i havent heard of any of this
clear sedge
i havent heard of any of this
yea because generally we learn limits as it is without going into the derivation as i dont see the need of it at a pre uni level
slender sundial
im not good at this so this is very confusing, i was hoping that my instructor would thouroughly go over it but the lectures only went over limits with polynomials and then this was the homework and i dont think ive got a good enough grasp yet
in order to make the connections
clear sedge
the link that i have sent above has on the dot derivation about this particular limit
if you scroll down a bit , you can find the derivation using a circle.You will find this very easy and intuitive
pearl pondBOT
Available help channel!
hoary blade
pearl pondBOT
fleet sky
there's not a way to reduce it any further. You can rearrange it by separating the function like so
hoary blade
Then i think i did the question wrong
fleet sky
$\frac{A}{2\pi r} - \frac{2\pi r^2}{2\pi r} = \frac{A}{2\pi r} - r$
jolly parrotBOT
MellowDramaLlama
hoary blade
When doing algebra, do you always approch the equation with Bedmas in mind?
fleet sky
What was the original question?
fleet sky
When doing algebra, do you always approch the equation with Bedmas in mind?
yeah that's usually the first approach I take. that even extends to calculus and higher level math
oh alright bet
hoary blade
paper totem
simplyfy the fraction
hoary blade
@fleet sky is an amazing helper
hoary blade
simplyfy the fraction
Thas my question
hoary blade
K
paper totem
You have to know the property of fractions
like this
\
also
2/4=2*1/4
So you can drag that 4 out of the fraction
make it into a integer
I don't know if you get it
paper totem
is this type of fraction you are having concern with?
and you don't know why 4 has to be simplify
hoary blade
Yea
hoary blade
**MellowDramaLlama**
So for this
paper totem
2/4=1/2
so 1/2*x/y=x/2y
You could go over the multiplications of fractions
you will understand it
And how to simplify fractions
hoary blade
Can u explain how to simplify this
hoary blade
How come it turns into this?
hoary blade
Can u say it is reduced as well?
paper totem
you don't have to subtract it,Cause you can't find the actuall value with those algebra
No
basically you just have to lower the term
Make this look more simple rather than complicate
If you could simplify the fractions,We usally simplify first
hoary blade
Can u say it is reduced as well?
It is reduced? Or jus simplified
hoary blade
If you could simplify the fractions,We usally simplify first
Like before trying to solve?
paper totem
no
its not reduced
the amount of the numbers aren't changing
simplify won't change the actuall value it had
Just like 2/4 and 1/2
2/4=0.5
1/2=0.5
hoary blade
How come it turns into this?
I dont understand what is happening to the numerators
Like in this:
paper totem
you are simplifying it which makes the numerator and denominator into smaller numbers
yes
that is how the numerator looks
11r=r
my bad
1 times 1 times radius
equals to radius
hoary blade
So the answer is r?
paper totem
yea
hoary blade
I have one last question
paper totem
what
hoary blade
So the part where i circled why cant i minus the c? Is it cause i gtta follow bedmas?
I was solving for t
Btw
Wait i mean
hoary blade
So the part i circled, i was wondering y i cant jus minus the c from both sides
Cause then i wouldnt get correct answer
hoary blade
No so i my last step i came up with 2A=hb+c. And i was wondering why i couldnt minus the c next
For next step
paper totem
hmmm
you probably have to divide the whole process of the left side
Did you forget to do it
hoary blade
Wdym
hoary blade
Ye but thas not the answer
hoary blade
Ye
paper totem
you should have rotated the side that has the value you're going to solve with
paper totem
Cuz for most of the people,We usually read the answer from the left side
like x=12
not like 12=x
lol
paper totem
ok lemme see
quiet narwhal
B+c should be in brackets, thats why you cant take only -b
hoary blade
Why should it be?
paper totem
bro
i get it
you got wrong
this part
lol
i was super confuse while looking at the bottom
hoary blade
Which part
paper totem
2h*b+c/2
quiet narwhal
Im your second last step you have h*(b+c) which is hb+hc and not hb+c
hoary blade
The step before i circled?
hoary blade
Okay wait lemme do it again
One sec
Ion think i get it
I know where u are looking but i dont know why there should be a bracket there
Cause i distributed the 2 into the brackets
paper totem
there needs to be bracket
hoary blade
Srry last line should be 2A= ā¦
quiet narwhal
You need to keep the bracket or distribute the h aswell
paper totem
or the multiplication will be h*b/2+c/2
hoary blade
I dont understand why tho
quiet narwhal
Because h(b+c)ā hb+c. Its hb+hc. You need to follow the distributive rule with the h
hoary blade
So follow the rule with the h first maybe and then distribute the 2?
paper totem
these are very important basics
let me give you a short example
The bottom with red highlighted is wrong
you just did the wrong thing
this is what brackets are for
hoary blade
Alr so now in my next step, i put everything here in brackets before multiplying by 2 to get rid of denominators because i wna multiply everything on the side
hoary blade
you probably will need to go over middle school math again
Its cause i havent done math in over a year and a half
In pic i meant hb+hc not hb+hb
quiet narwhal
Yea start of with multiplying both sides with 2. Make a new row and see where youre at
hoary blade
Okay so i did get the right answer i was jus wondering for my final answer, how do I know if i should keep the b+c in brackets?
paper totem
umm
ok
so listen
you don't touch those numbers if they can't be simplify
cuz it might affect the final answer
quiet narwhal
My tip is to always keep the brackets. Makes all the equations a lot easier just to see what you need to add, subtract, divide or multiply with
paper totem
ye
quiet narwhal
Or keep them until youve distributed the numbers properly
hoary blade
My tip is to always keep the brackets. Makes all the equations a lot easier just...
So if i was doing more steps i could leave the brackets around the b+c?
quiet narwhal
In the answer? Ye if you want to
hoary blade
But also if lets say there were more steps to be done
quiet narwhal
Like at that point theyre redundant because theres nothing else there, but say you have other variables next to (b+c) then i would keep the brackets
paper totem
For most of the questions they always gives you a very very conspicuous expression like this
that is when you moving numbers
hoary blade
Thx
Alr
I think that was great review cause havenāt done math in over year and half like i said
Thx so much both of u
silk trellis
help
silk trellis
Good Afternoon.
i have inquire about my math problem
the teacher is teaching me this
she says
if there is negative function u must do the negative resopical of the piece wise function
okay i understand
but then why its not changing to 4x over 1 then
if its opposite
why
toxic lichen
misspelled and still not quite right
you were better off saying "expression"
anyway
$x^{-1} = \frac{1}{x}$ so $\frac{1}{4} x^{-1} = \frac{1}{4} \cdot \frac{1}{x} = \frac{1}{4x}$
jolly parrotBOT
Ann
silk trellis
š¤
toxic lichen
is there something you don't understand?
silk trellis
basically lol
teacher said if its power negative u must do resopical
okay fine then but resopical of
1/4
is just 4
so why just 4x like my answer above?
in blue
rite?
old mountain
If you were raising 1/4 to the power of -1 you'd be right!
...But it's raising x to the power of -1.
silk trellis
OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOH
yeeee
ye that makes sense oh okay
thanks @old mountain
old mountain
Hey np. Ann did the heavy lifting, though.
silk trellis
so basically u are saying
first do coifficent fine u get 1/4
then the powre negative of 1 only for expression for X
so in this case u do the mulitply rite
yep
just like the picture
old mountain
Yeah. Just like the latex that Ann whipped up.
old mountain
. from 1st, close from 2nd, and you got it ;D
pearl pondBOT
pearl pondBOT
Available help channel!
still fiber
pearl pondBOT
still fiber
Hey all, Iām trying to learn latex and Iām having trouble figuring out how to use this
How do I space the lines like this? Also, Iām having trouble setting them equal to each other below the proof
sudden arch
\usepackage{amssymb}
\theoremstyle{plain}
\newtheorem{theorem}{Theorem}
\begin{theorem}
Car
\end{theorem}
jolly parrotBOT
tales
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
sudden arch
\begin{proof}
\end{proof}
jolly parrotBOT
tales
midnight haven
Theorem 1. if $x$ is an even integer and $y$ is an odd integer, then $x+y$ is odd.
Proof. Let $x$ be an even integer and let $y$ be an odd integer. So $x=2a$ for some integer $a$ and $y = 2b +1$ for some integer $b.$ Observe
$$x+ = 2a + 2b + 1 = 2(a+b) + 1$$
since $a+b$ is an integer, then $x+y$ is odd as desired.
jolly parrotBOT
Replaced by new brandon H
still fiber
Theorem 1. if $x$ is an even integer and $y$ is an odd integer, then $x+y$ is od...
Does let get auto replaced by if?
polar steppe
pearl pondBOT
spiral sierra
cosh^2 = 1 + sinh^2
polar steppe
cosh^2 = 1 + sinh^2
was this what you were expecting me to do or am i way off
spiral sierra
cosh^2 = 1 + sinh^2
use this on where you left
for the first image
replace cosh^2 with that
polar steppe
I did!
oh
hold on
yeah I did that
didn't I?
I can rewrite it to make it cleaner
spiral sierra
keep the csch there
and replace cosh^2 with sinh^2 + 1
and multiply
there are multiple methods to do this prob, im just going with what you tried
polar steppe
and replace cosh^2 with sinh^2 + 1
wait how did you derive this one
oh
jk
nvm
nvm
spiral sierra
its here
woven matrix
and replace cosh^2 with sinh^2 + 1
cosh no ?
woven matrix
also, there is a one liner proof where you just put coshĀ²(x)/sinhĀ²(x) - 1 on the same denominator
polar steppe
ooo
after I finish this
can you show me that
or you can just do that and I'll look at it after
woven matrix
I can or you can try first if you want, it's very direct
polar steppe
also, there is a one liner proof where you just put coshĀ²(x)/sinhĀ²(x) - 1 on the...
wait can you explain a little
on the same denominator?
woven matrix
coshĀ²(x)/sinhĀ²(x) - 1 = (coshĀ²(x)-sinhĀ²(x))/sinhĀ²(x)
woven matrix
yeah
spiral sierra
oh you changing method now
polar steppe
yeah
spiral sierra
yeah good
polar steppe
the other method started getting long
hmmm
I could change 1 = sinh^2 (x) / sinh^2 (x) to get one fraction
wait was that it
No way
.close
scenic spoke
the symbols are confusing me again, ive been doing triangles but now i dont understand
scenic spoke
.close
pearl pondBOT
scenic spoke
noone helped
pearl pondBOT
Available help channel!
scenic spoke
can someone help im struggling understand
pearl pondBOT
can someone help im struggling understand
scenic spoke
.close bro
pearl pondBOT
pearl pondBOT
Available help channel!
errant coral
Hi
errant coral
I know it starts from
ln(Ā³āxĀ²)
I think so at least
But after this.. i just started learning these
errant coral
I think so
light helm
can you express that $\cbrt{x^2}$ with exponents only?
jolly parrotBOT
āam()n()v
errant coral
X at 2/3
light helm
x^(2/3), yes
errant coral
And i do -2/3 then?
light helm
you'll have
$$\int \frac{1}{x^{2/3}}\dd{x}$$
then its pretty much an application of (reverse) power rule
jolly parrotBOT
āam()n()v
light helm
you can first convert that to
$$\int x^{-2/3} \dd{x}$$
first if you want
errant coral
Oh ok thank you
jolly parrotBOT
āam()n()v
errant coral
I was thinking about derivates ( if this is the word for them in english ) thank you a lot
How do i close this? Thank you a lot
light helm
errant coral
.close
pearl pondBOT
pearl pondBOT
Available help channel!
sly folio
What approach do you take to find the limit for this problem I guess I was totally off
solid ivy
What did u try
sly folio
I tried factoring the equation and graphing the domain of the simplified function and giving the intercept of the two graphed as the limit
I thought they did something like that here for the homework example
pearl pondBOT
@sly folio Has your question been resolved?
sly folio
Oh wait Iām just stupid I just need to plug the x value into my simplified function I just wasnāt doing algebra right lmao
.close
orchid egret
pearl pondBOT
cursive wraith
Can you show your work?
orchid egret
I found x>14/3 by ignoring the absolute value signs and solving
there are 2 more x ranges on the markscheme
cursive wraith
So you solved it in the case that x>=0
orchid egret
yes
cursive wraith
And so naturally, if you want to solve it for x<0, |x| becomes...?
cursive wraith
or does |x| =-x
Yes this
cursive wraith
I found x>14/3 by ignoring the absolute value signs and solving
Also those aren't the only solutions for x > 0
orchid egret
Also those aren't the only solutions for x > 0
x can't be 3 or -3
cursive wraith
Yes, but does that mean x>14/3 is the only possibility when x>=0
orchid egret
Yes, but does that mean x>14/3 is the only possibility when x>=0
wdym
cursive wraith
wdym
You went from $\frac{x+2}{x-3}<4$ to $x+2<4(x-3)$, are you always allowed to do that?
jolly parrotBOT
rafilou2003
orchid egret
**rafilou2003**
no
orchid egret
because it ignores the x-3 in the denom (anything divided by 0 is bad), which means that x deq 3 and x deq -3
cursive wraith
"x deq 3 and x deq -3"
Not enough
Here's an example
$\frac{3}{-1} < 2$, does this mean that $3 < (-1)\cdot 2$?
jolly parrotBOT
rafilou2003
orchid egret
no
cursive wraith
**rafilou2003**
Exactly. So what other values are incorrect for this approach?
cursive wraith
any -ve value?
Any x such that x-3 < 0
orchid egret
**rafilou2003**
u didn't switch sides here tho
when u multiply or divide by a -ve value, the inequality switches sides?
cursive wraith
u didn't switch sides here tho
Exactly, I didn't switch sides
cursive wraith
when u multiply or divide by a -ve value, the inequality switches sides?
Yes!
cursive wraith
Ok. Let's redo it
Let's start with when $x\geq 0$, this means we have to solve $\frac{x+2}{x-3}<4$. $\$
When $x>3$, $x-3>0$ and so we're allowed to write $x+2<4(x-3)$ and so $x>\frac{14}{3}$
jolly parrotBOT
rafilou2003
cursive wraith
However, what happens when $x<3$?
jolly parrotBOT
rafilou2003
jolly parrotBOT
pearl pondBOT
@orchid egret Has your question been resolved?
weak surge
pearl pondBOT
weak surge
Somehow my answer is off by 3/8
Iām supposed to use geometry. Can anyone help to show me where I went wrong?
warm current
this?
weak surge
Thatās both sides together
warm current
Or the whole shaded region?
weak surge
35
warm current
what's the height here?
weak surge
The left side is 4
warm current
4 is the height?
weak surge
Yeah, because the Y intercept is 4
warm current
is it?
weak surge
Oh damn
You are right
Itās rate of change is 4
Rise over run
y-intercept = -1
But because itās absolute I think itās +1 instead?
Tyty
I will try again
Ty!
weak surge
what the height of this triangle?
Gonna be honest, for some reason this is much easier for me to solve with FTC rather than geometry
warm current
should just be area of two triangles
weak surge
Yeah
warm current
Your symmetry idea here I think hurts more than helps
weak surge
But the graphing is what throws me off
weak surge
Your symmetry idea here I think hurts more than helps
You would have solved using geometry a bit differently?
warm current
$\frac{1}{2}(1\cdot \frac{1}{4}+(9-\frac{1}{4})\cdot (4(9)-1))$
jolly parrotBOT
SWR
warm current
That's all I would have done
pearl pondBOT
@weak surge Has your question been resolved?
sweet radish
pearl pondBOT
sweet radish
Can someone explain why it's C?
toxic fractal
it isnt
sweet radish
š
dim tangle
finding the difference of the accepted lengths gives you the tolerance, which is 1/4 inch. when we have a hotdog h, we can subtract the target from it to get the error. this gives us
h - 6 1/2 = error
since we know the error tolerance is 1/4 inch, we know the error should never be more than that. following that logic we can write
h - 6 1/2 < 1/4
now there's a problem with our equation, because if we undershoot the target, the equality will still hold true even if the hotdog is more than 1/4 from the target. so to get rid of the possible negative value we can use absolute value to get the "distance from the target"
|h - 6 1/2| < 1/4
toxic fractal
A would allow hot dogs between 6 and 6.5; not valid.
B would allow hot dogs between 5.75 and 6.75, also not valid.
C would allow hot dogs between 6.25 and 6.75, not valid.
And D would allow hot dogs that are NOT between 6.25 and 6.75.
Tell your teacher to learn how to solve the problem before putting every single answer wrong
dim tangle
yeah. technically the target should be the center of the range
toxic fractal
the correct interval would be |h - (6+5/8)| <= 1/8
not surprising that your teacher is a moron considering the notation they use for the fractions tbh.
That notation is usually understood as 6 multiplying the fraction, not adding the fraction. And it has been for several decades.
sweet radish
I'm confused š
dim tangle
problem is wrong. in reality you would have an interval of accepted values, find the center of the interval, then use absolute value to check for error.
toxic fractal
I'm confused š
None of the answers are correct.
Your teacher is incompetent.
sweet radish
This is sat math problem š
dim tangle
the "correct" answer would be if accepted values were 6 1/2 +- 1/4 inch
sweet radish
The solution ^^
sweet radish
finding the difference of the accepted lengths gives you the tolerance, which is...
What exactly is the tolerance
dim tangle
the interval of values
toxic fractal
The solution ^^
Check the answer.
It's giving an answer to a DIFFERENT problem that the one you have there.
toxic fractal
the solution is using the data i've written in red
so, as we've said, the solution is wrong because it's a solution to a problem that you dont have
sweet radish
Ahh question is wrong
dim tangle
could be software error.
toxic fractal
you should bring it up with them and tell them to not be morons
sweet radish
On a different website
I payed for this website and they literally have so many wrong questions and answers ššš
toxic fractal
welcome to 'murica paid "education"
random siren
Why is it
random siren
When I'm looking for local minima and maximum of a multivariable function, do I only look at the region
But when looking for absolute extreme, I also look at the boundary?
pearl pondBOT
Available help channel!
fleet oriole
pearl pondBOT
fleet oriole
Is this correct
I got (5/4,5/2,13/4)
First I found the direction vector for the line which is <1,-2,-3>
then I found positional vector that is AP and got -2-t,-2+2t,-1+3t
afterwards I did the dot product between AP and V to solve for t
I got t=1/4
after that I plugged it into the equation of the line to get (5/4,5/2,13/4)
pearl pondBOT
@fleet oriole Has your question been resolved?
fleet oriole
<@&286206848099549185>
pearl pondBOT
@fleet oriole Has your question been resolved?
fleet oriole
.reopen
Is this correct
I got (5/4,5/2,13/4)
First I found the direction vector for the line which is <1,-2,-3>
then I found positional vector that is AP and got -2-t,-2+2t,-1+3t
afterwards I did the dot product between AP and V to solve for t
I got t=1/4
after that I plugged it into the equation of the line to get (5/4,5/2,13/4)
<@&286206848099549185>
pearl pondBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
fleet oriole
Its been literally 1 hour
plush bramble
pearl pondBOT
@fleet oriole Has your question been resolved?
midnight haven
Its been literally 1 hour
lol
frank goblet
you result "looks" good
i tried doing it myself and i have no idea what went wrong on my side
its way to late haha
pearl pondBOT
pearl pondBOT
Available help channel!
midnight haven
What's the significance of $\sum_{n=1}^\infty \frac{(x!)^2}{(2x)!}$
jolly parrotBOT
What should I do
pearl pondBOT
@midnight haven Has your question been resolved?
pearl pondBOT
@midnight haven Has your question been resolved?
pearl pondBOT
@midnight haven Has your question been resolved?
pearl pondBOT
pearl pondBOT
Available help channel!
terse temple
hello!
terse temple
.close
midnight haven
pearl pondBOT
midnight haven
Can someone help me draw this
midnight haven
Can someone help me draw this
looks like you're leaving out a lot of context
.close
midnight haven
pearl pondBOT
midnight haven
I got an answer for sin^-1 (-2/3)
which was -41.8
the answers i got inthe textbook were for the range -180 to 180
i got -41.8 and -138 but the cast diagram shows that you cna only have 1 answer so what did i do wrong
mint scarab
Keep in mind arcsin doesn't have a big range
sudden arch
arcsin(sqrt(2)/2)
fleet sky
how does it return angles on the a quadrant
because in order to create an inverse sin function we have to limit the domain
sudden arch
,w arcsin(sqrt(2)/2)
jolly parrotBOT
mint scarab
,w graph arcsin(x)
jolly parrotBOT
midnight haven
im not sure how to read that but could i just assume the bottom of the cast diagram is the negative 180 part of the graph? would that work every time?
midnight haven
like the top is normal 0 - 180 and the bottom starting from the tan is -180 to 0
midnight haven
you show review bijections, inverse functions, and the arcsin function
i literaly have no idea what that means
sudden arch
it's the same graph, but scaled
sudden arch
i literaly have no idea what that means
that's exactly why you should review
You can't understand arcsin without understand inverse functions, and you can't understand inverse functions without understanding bijections
midnight haven
You can't understand arcsin without understand inverse functions, and you can't ...
i recognise arcsin and inverse fucntion but whats a bijection?
sudden arch
A function must be a bijection to have a inverse function
$\sin(x)$ from $\mathbb{R} \to \mathbb{R}$ is not a bijection
jolly parrotBOT
tales
sudden arch
neither $\sin(x)$ from $[-180^{\circ}, 180^{\circ}] \to \mathbb{R} $
jolly parrotBOT
tales
midnight haven
I havent gone through this in class
ill look over it but for the sake of simplicity, can i just assume the bottom of the graph as being the -180 portion of the graph
sudden arch
No