#help-39

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pearl pondBOT
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pearl pondBOT
copper kestrel
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there’s no definite point at x = 4.5, so I’d say [-5, 4.5)

fast zealot
copper kestrel
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the range goes to - infinity

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not the domain

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actually

fast zealot
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no

copper kestrel
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there is an arrow

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hmm

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I guess that is infinity

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it’s likely [-5, infinity) now that I think about it

fast zealot
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im pretty sure its [-5, infinity) as no endpoint of the function is specified

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soo what you want to look for in these

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is if a specific endpoint is defined on the graph your given

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like the little dot

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and if there as arrow

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this implies that it just continues like that forever unless another interval is given

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so look at x^2 as a good example

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no

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thats what the arrow implies

pearl pondBOT
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pearl pondBOT
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pearl pondBOT
patent flame
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Do you know log rules?

cinder flower
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<@&268886789983436800>

plush bramble
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<@&268886789983436800>

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Ty nami

patent flame
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@vital estuary you there?

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Oop

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@vast dune

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Ok

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Do you know general log rules?

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Ok so log(ab)= log(a) + log(b)

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Natural log is just log base e

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Keep the absolute value

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But yes

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Idk it's just there

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Well actually

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It's there cuz logs don't take negative numbers

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Unless you go complex

pearl pondBOT
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desert tusk
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complex number: z=1-i

pearl pondBOT
desert tusk
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what is the polar form?

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z=2^(1/2)(cos(7pi/8)+isin(7pi/8)) right ?

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answer says its -pi/4

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is there a mistake ?

shell oxide
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The polar form is made of a magnitude m and angle(in radians) a, and it’s written like (m,a)

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,w polar form

desert tusk
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So

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Is my angle right ?

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@shell oxide

shell oxide
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Oh uhh u r right that it’s -pi/4

desert tusk
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?

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my answer is 7pi/8

shell oxide
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Can you walk me through your logic so that I can point out possible errors? Or just like snap a pic for me?

desert tusk
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y is the imaginary part x is real

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So it makes a triangle

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then

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tan(1/1)=45

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so 7pi/8

shell oxide
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Woah woah woah

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Ok so

desert tusk
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._.

shell oxide
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Tan(1/1) is 45 degrees?

desert tusk
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i think

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omg

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Im a dumbass

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thanks

shell oxide
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Tan, like all trig functions, takes in angles for input and spits out ratio of sides for outputs

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Np

desert tusk
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pearl pondBOT
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noble sigil
pearl pondBOT
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Please don't occupy multiple help channels.

noble sigil
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pearl pondBOT
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faint void
pearl pondBOT
faint void
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the equation would be 0.6 = (1-0.045)^t

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where t represents thickness of ice in cm

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how would i solve this without a calculator

glossy parrot
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1-0.045 = .955

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so now you have

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$0.6 = 0.955^t$

jolly parrotBOT
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WhyWouldYouKap

glossy parrot
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now you rearrange with logs

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t = log base .955 of 0.6

faint void
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i would still need a calculator to solve that though no?

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im not rly familiar with solving logs

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/evaluating

glossy parrot
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u would need a calculator

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bc of the change of base

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t = log 0.6 / log 0.955

faint void
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it says to the nearest integer in the question would that still not be possible

upbeat mirage
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You can round it

faint void
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so like round .955^2, then multiply that by 0.95, until its around 0.6?

glossy parrot
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is the no calc thing a self imposed rule or a test rule

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its about 11

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11.094 (3dp)

glossy parrot
faint void
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its kinda self imposed but good 2 know that u kinda need a calculator

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pearl pondBOT
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pearl pondBOT
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tardy epoch
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how is d(df) proportional to $dx^2$?

pearl pondBOT
jolly parrotBOT
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LichBaw_GT

elfin shale
tardy epoch
tardy epoch
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pearl pondBOT
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coarse pike
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currently at (b), no idea how to start solving it 🙏 sorry if im too stupid to solve it myself

safe pendant
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you have the frequencies and the values, simply start multiplying them like 5 x 10 + 10.2 x 3 ... etc all the way to the end, and that sum divided by 40 must be 17.95

coarse pike
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so i have to try all possible value for a and b from (a)?

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since there are 10 possible pairs of a and b i think

safe pendant
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yeah I guess you could try

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couldn't think of an easier way

coarse pike
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alright thank you

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pearl pondBOT
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pearl pondBOT
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waxen kayak
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hi

pearl pondBOT
waxen kayak
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i am doing this question

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on circle theorem

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i do have answer for x and y but idk if correct

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i came to conclude y = 32 because angle on same chord are equal

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and x = 90 because triangle which pass through diameter of circle is 90

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am i correct?

viscid oxide
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y will be 32 if the 32° angle and y both were subtended by the same arc

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which is not the case here

waxen kayak
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so y is not 32

viscid oxide
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we see that angle SOR is 88
because SOR will be twice of SPR

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from there we can find ORS
then we will have y

vestal cobalt
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SOR = 2 × SPR

waxen kayak
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where is O

viscid oxide
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O is the centre

waxen kayak
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ohhh yea

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so isoceles?

viscid oxide
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PQRS is cyclic quadrilateral

viscid oxide
vestal cobalt
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SOR + 44 + y + 32 = 360

waxen kayak
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180 - 88 = 92

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92 / 2 = 46

viscid oxide
waxen kayak
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ohhhh yes 100%

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so like 32 + 46 = ORS?

viscid oxide
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yes

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it should be

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so x is 102

waxen kayak
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and y is 78?

viscid oxide
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$y=180-(44+32+46+46)=180-168=12$

jolly parrotBOT
waxen kayak
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what?

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confused

viscid oxide
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we have ORS=OSR=46 right?

jolly parrotBOT
viscid oxide
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hope this clears

pearl pondBOT
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@waxen kayak Has your question been resolved?

pearl pondBOT
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grizzled lodge
pearl pondBOT
midnight haven
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consider the equation mod 6. The squares mod 6 are 0,1,4, so q1^2=1 mod6

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then maybe try and figure out what some of the other primes are

grizzled lodge
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Okay ill see

shrewd basin
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Probably easier to check mod 3

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Then 8

midnight haven
midnight haven
grizzled lodge
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I think I got 5 2 2 2 2 3

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The only possibility?

pearl pondBOT
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dark jay
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I dont understand how they got to the answer at all, like i dont understand the steps they took. How did they get pi/2 - theta = 4pi/9? Why did they need to show that 1/cos4pi/9 is equal to a?

dark jay
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pearl pondBOT
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dark jay
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.reopen

pearl pondBOT
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eternal verge
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in the second column

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u understand the substitution?

dark jay
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Yes

eternal verge
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u realize what theta represents?

dark jay
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Does it represent a?

eternal verge
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its a variable

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it could be anything

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thats why on both sides u can subtitute theta with pi/18

dark jay
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O ok

eternal verge
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its fine; pi/2 - theta = 4pi/9

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this just says pi/2+4pi/9 adds up to a certain something

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which i have no idea about

dark jay
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ok i think i understand the question now ty

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late sequoia
#

Hi

pearl pondBOT
late sequoia
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How to express number as a product of prime factors?

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616

old geyser
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Easiest way to do this is to keep dividing by 2 until you can't

tropic saddle
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then divide by 3 until you cant, then 5, 7, 11 etc and work your way up the list of primes

old geyser
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Well

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I mean

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The funny thing about 616 is that you only need to do one step

pearl pondBOT
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@late sequoia Has your question been resolved?

tropic saddle
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one step?

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308 is not prime. so you need to repeat

vestal tapir
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that's after one third of one step

tropic saddle
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well ok if you wanna call all of dividing by 2 until you can't one step, sure. but not like 77 is prime either

pearl pondBOT
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shell niche
#

Thsi is supposed to give x=+-1, what have I done wrong

midnight haven
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if x = -1 then y = -2, x^2-y^2 = -3

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so yeah x=1 is correct

shell niche
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Oh, yeah. I read it wrong, x=1 is the right answer, thanks

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strange delta
#

How do you do part d)??

pearl pondBOT
strange delta
#

<@&286206848099549185>

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there's also this idk

pearl pondBOT
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pearl pondBOT
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@strange delta Has your question been resolved?

pearl pondBOT
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@strange delta Has your question been resolved?

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pearl pondBOT
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hollow wedge
#

i need help with power sums

pearl pondBOT
plush bramble
hollow wedge
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So ive simplified this far

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and i know the first one is just 20*25

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but im not sure how to solve the second and third one

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since my teacher only explained how to solve in cases where the function was just m^2 or m

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Like this

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but i dont know how to apply this to the 15m and (9m^2)/4

plush bramble
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Factor out 9/4 from the sum

fleet sky
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so you can factor out

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yeah that

hollow wedge
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how do i do that

fleet sky
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The logic is like this. Say if we had the following:
$\ \sum_{i=1}^{n}3 j = 3 + 3(2) + 3(3) + ... + 3(n)\$
We can see that they all have a factor of 3, so we can factor that out:
$\ \sum_{i=1}^{n}3 j = 3 + 3(2) + 3(3) + ... + 3(n) = 3\sum_{i=1}^{n} j$

jolly parrotBOT
#

MellowDramaLlama

hollow wedge
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ah i see

fleet sky
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aka we can pull out constants out of sums

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then we have our standard form 🙂

hollow wedge
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so solve regularly as if it was j^2 then just multiply by 9/4

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and same for 15m just multiply by 15

scenic finch
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helphelphelp pls pls

fleet sky
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yep! You'll multiply 9/4 by the sum formula: $\ \sum_{i=1}^{20} \frac{9}{4}m^2 = \frac{9}{4} \sum_{i=1}^{20} m^2$

scenic finch
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i need to solve x²+10x+21=0 and find x

fleet sky
#

this channel is occupied

jolly parrotBOT
#

MellowDramaLlama

fleet sky
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and we know how to solve that summation 🙂

hollow wedge
#

great thanks!!

fleet sky
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yep np!

hollow wedge
#

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pearl pondBOT
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obsidian nexus
pearl pondBOT
obsidian nexus
#

for some reason i cant get the correct answer for p

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i got it as 80gN the answer is meant to be 2160gN

pearl pondBOT
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@obsidian nexus Has your question been resolved?

obsidian nexus
#

<@&286206848099549185>

pearl pondBOT
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pearl pondBOT
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tiny lily
#

Would this be an arithmetic or geometric and how do I find out

fleet sky
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I don't think it's either... it's not arithmetic since there's not a common difference between the values, and it's not geometric because the values don't have a common ratio

tiny lily
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Thanks

fleet sky
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yeah that's weirdly worded... they don't say it can be neitherlol

tiny lily
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Also if it's not Arithmetic or Geometric I cant find the common term?

midnight haven
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hi

tiny lily
fleet sky
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yeah correct.

tiny lily
#

Alright thank you very much for your help

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midnight haven
#

anyone here read manga ?

fleet sky
pearl pondBOT
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outer hazel
#

Help

pearl pondBOT
outer hazel
#

I have this one math problem I’m struggling with can someone help me out?

edgy veldt
#

u can form two equations using angles on a straight line and vertically opposite angles

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then solve for x and y

outer hazel
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Alright

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I think I got it

pearl pondBOT
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high magnet
#

how would i go about solving this?

pearl pondBOT
high magnet
#

i believe this is discrete mathematics, but i absolutely have no idea what i am supposed to be doing here

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hasty dome
#

I use CTCMath for school and they usually tend to not give things proper names and also tend to fail in explaining the formulas.
What I'm working on atm is Product and Addition Rules and I was doing fine until it gave me this problem:

hasty dome
#

(this, btw is all the help it gave and all the explanation it gave as well)

wet night
#

The number of possible dice domcinatilns is 36

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I think

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And you find number of combinations that sum to 9

pearl pondBOT
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devout grove
#

I dont want answers, I want help understanding this

devout grove
#

i need help pls

pearl pondBOT
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@devout grove Has your question been resolved?

pearl pondBOT
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@devout grove Has your question been resolved?

devout grove
#

Not yet

pearl pondBOT
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@devout grove Has your question been resolved?

slow pecan
#

Hi

pearl pondBOT
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torn coral
pearl pondBOT
midnight haven
#

How can it have only one solution I'm confusionthonk

cinder flower
#

can confirm it can

midnight haven
#

ah I see now

light helm
#

there seem to be two valid options here

midnight haven
#

😵‍💫

cinder flower
#

yea lol

pearl pondBOT
#

@torn coral Has your question been resolved?

torn coral
#

wait can smn explian

plush bramble
#

By that I mean plot 2sin(x)+1 and see when there's only one intersection with horizontal lines y=b in your interval (0,2pi)

#

Try setting b equal to all your options on the graph

pearl pondBOT
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hard plank
#

What the hell?

pearl pondBOT
gusty hamlet
#

hi

#

can someone help

hard plank
#

yes

#

someone help

dull lion
hard plank
#

How do I convert to Lc

#

I'm confused

dull lion
#

Yeah. What subject is this? Chemistry?

hard plank
#

Math

#

Algebra

dull lion
# hard plank What the hell?

Check with your teacher to see if there is some mistake

because, even if you convert the wrongly written units of Lc -> corrected -> cL -> convert -> L

it would be L•L which is L^2

hard plank
dull lion
#

Yeah according to the labeled units of the wanted answer

hard plank
#

Alright I will ask her thanks!

limber ravine
hard plank
#

oh what

limber ravine
#

Well, it's probably not the wanted answer, and it's most likely a mistake in the question, but if you out "245L" as the answer, the equality holds

hard plank
#

So remove the 245L? But if I do that their will be 2 Lc's

limber ravine
#

What do you mean remove?

hard plank
#

Cause you said out 245 L

#

oh wait

#

I get it now

#

Thanks @limber ravine

#

I will still ask my teacher

#

Thanks guys I appreciate you help

#

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tired lake
#

please how can i do this

pearl pondBOT
#

@tired lake Has your question been resolved?

pearl pondBOT
#

@tired lake Has your question been resolved?

pearl pondBOT
#

@tired lake Has your question been resolved?

tired lake
#

<@&286206848099549185>

#

pls

pearl pondBOT
#

@tired lake Has your question been resolved?

midnight haven
midnight haven
#

I am not sure, what you can use. Is A⇒(A∨B) an axiom?

tired lake
#

i think first one is demorgan but not sure

midnight haven
#

hm

#

3 is de Morgan, can you identify 2, 4, 5?

tired lake
midnight haven
#

2 and 5 is definition of implication - you change implication to or and back

midnight haven
#

good

midnight haven
#

yes

tired lake
#

because it consists of 3 nots

#

it cant be de morgan so

tired lake
#

how is two implication? to or and back

#

there's no implication sign or notation

midnight haven
#

1 had implication, 2 has or

tired lake
#

to be clear which one are you referring to

#

top or bottom?

midnight haven
#

in 2 from implication to or

tired lake
#

for 5 would it be the opposite?

midnight haven
#

yes

tired lake
#

ah that makes sense

#

thank you!

midnight haven
#

do you see that the whole question is about explaining a derivation?

tired lake
#

derivation meaning

#

the one from before

midnight haven
#

I am sorry, I do not know English terminology

tired lake
#

the previous equation is derived by the next one

midnight haven
#

yes

tired lake
#

np

tired lake
midnight haven
#

nice that I could help

tired lake
#

.close

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proper merlin
pearl pondBOT
proper merlin
#

I don't know if I did it correctly with 1.1 and 1.2 and also need help to solve 1.3 and 1.4

pearl pondBOT
#

@proper merlin Has your question been resolved?

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@proper merlin Has your question been resolved?

proper merlin
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<@&286206848099549185>

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quartz yew
#

Find the equation of a line containing points A(2a+1,3b) and B(-5a,3-6b) parallel to y = 1/2 + 10

quartz yew
#

I straight up don't know how to solve these. I can only get to figuring out the variables A & B but idk were to go from there

#

<@&286206848099549185>

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vivid forge
pearl pondBOT
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drifting bone
#

.close

#

.reopen

#

oh nvm

#

please help I’m begging 😭😭

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mighty ginkgo
pearl pondBOT
mighty ginkgo
#

First time doing trigonometric ratios for functions

vapid grove
#

which quetion

mighty ginkgo
#

So can someone explain how to do 4 b please

vapid grove
#

my english sucks, i cant help

mighty ginkgo
#

Awww okay

#

It’s ok

#

Ty

#

What language do u speak

vapid grove
#

english but it sucks

#

i can only do maths

mighty ginkgo
#

Okay u don’t have to explain it

#

You can just show it to me

vapid grove
#

i think u just plug it into the calculator??

mighty ginkgo
#

There’s no sec on an calcuatkr

#

At least not mines

vapid grove
#

because it says to evaluate to the nearest hundrth which means there is a decimal

mighty ginkgo
#

Yes

vapid grove
mighty ginkgo
#

Okay

vapid grove
#

cot is 1/tan

mighty ginkgo
#

Okok thank you

#

I get it known

#

Now

#

.close

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hexed granite
#

1+1 is?

pearl pondBOT
mossy canopy
#

2 in most cases

#

depends on which structure we are in

#

but in most cases it is 2

#

for example

#

$\mathbb{F}_{2}$

jolly parrotBOT
#

~Martin

mossy canopy
#

this is a field

#

a field is a structure containing elements, numbers if you will

#

a field has properties

#

in algebra, a field for example has the properties:
a(b+c)=ab+ac
a+(b+c)=(a+b)+c
a+b=b+a
similar stuff for multiplication
also inverse and neutral elements

#

F2 now is a field with just 2 elements

#

0 and 1

#

so

#

0+0=0
0+1=1+0=1
1+1=0

#

that would be an exception to 1+1=2

#

but generally we can assume 1+1=2 because we mostly deal with natural/whole/real/complex numbers
for these 1+1=2 is always correct

pearl pondBOT
#

@hexed granite Has your question been resolved?

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vapid grove
pearl pondBOT
vapid grove
#

trig identities, how do i solve this

bold ledge
#

honestly I would just plug in a bunch of numbers and see which work

#

but

#

since it's mostly sin from answer choices

#

you probably want to write

#

cos(2x)=1-2sin^2(x)

#

actually maybe it's difference of squares

#

try both

cunning heart
#

difference of squares

cunning heart
pearl pondBOT
#

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uncut pine
#

,tex $f(x)=\floor{x}+\floor{2x}-\floor{3x}+2}$

jolly parrotBOT
#

j0sephTheA
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

uncut pine
#

Hey,
what is the highest value of this function?

eternal verge
#

2..?

uncut pine
#

.close

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dark thistle
#

{\displaystyle n=qm+r,\quad n,q,m,r\in \mathbb {Z} ,\quad m\not =0,\quad 0\leq r<m}
wtf is this

toxic lichen
#

some mildly shoddy LaTeX code

dark thistle
#

is it even math

#

i was told it was math

toxic lichen
#

it's something mathematical written in a markup language called LaTeX

dark thistle
#

oh

#

well thanks

tropic niche
#

You forgot the $

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#

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midnight haven
#

quick question how do you write for all real numbers

tropic saddle
#

"for all real numbers"

#

or $\forall x\in\bR$

jolly parrotBOT
#

Denascite

midnight haven
#

that’s what I was looking for

#

tyty

#

.close

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white coral
#

I don’t know how to do this, I don’t have to know the number of people in the room?

clear trench
#

Well to come to a numeric value yes. But here you want something in terms of n. So for example what's the probability when n=10.

white coral
#

Ooh okay okay

night urchin
#

for 18b, consider the probability all n people are born on different days

#

i.e. calculate the complement

white coral
#

Mmm so, the possible cases are n? and the total also n? for the 18a

night urchin
#

?

#

for 18a you just have two people lol

#

where is the n

white coral
#

Oh sorry sorry

#

So possibles cases are 2 and the total is n?

night urchin
#

no and no

#

as I said there is no n

clear trench
#

n is just the amount of people in 18b

night urchin
#

you have 2 people

#

you look at which day of week person 1 was born, and which day of week person 2 was born

white coral
#

So... I have two events, and that events are and intersection A intersect B? cause both have to be the same day? for 18a

night urchin
#

not really

white coral
#

why?

night urchin
#

this is not the intersection of two events, it is more like the union of seven events

white coral
#

seven events is the days of the week, right?

night urchin
#

yes

white coral
#

oooh that is the event when a person birth

#

but union is p(a)+p(b)-p(a intersect b), and that intersection will be when someone birth the same day?

night urchin
#

I...

#

what is a and b here

#

I dont even

white coral
#

mmm a day of the week?

#

it will be seven letters

#

but it can't be and intersection between all days

night urchin
#

you are confused, before talking about events you need to get your sample space correct

#

what is the sample space for this experiment

white coral
#

the seven days of the week

night urchin
#

no

white coral
#

:o

#

why?

#

all days of the year

night urchin
#

we pick 2 people, we ask which day of the week they were born in

#

we can get something like (Monday, Tuesday)

#

(Sunday, Friday)

#

(Thursday, Thursday)

#

where the first element is the answer first person gave, second element answer second person gave

white coral
#

pairs of two days of the week

night urchin
#

yes

white coral
#

C(7,2)

#

combinatorics?

night urchin
#

wait wait what

white coral
#

no :c

night urchin
#

what are you calculating

#

?

white coral
#

The number of pairs

night urchin
#

that is very wrong

white coral
#

:o

#

why? :c

night urchin
#

there are 7 options for the first, and 7 options for the second?

#

there are 7^2 pairs

#

you take combinations when there are no repeats and order doesnt matter

#

here there are repeats and order does matter

white coral
#

Aaa I get it :')

#

So 7^2 will be my sample space?

night urchin
#

that is a wrong way to think about it, 7^2 is the size of your sample space

#

your sample space is pairs of days of the week

#

but yes

#

and what are the events you want

white coral
#

when I have repetition

night urchin
#

yes

#

how many of those are there

#

pairs that repeat

white coral
#

7

night urchin
#

yes, so whats the probability

white coral
#

7/7^2?

night urchin
#

yes

white coral
night urchin
#

good job, but to be clear 18a is supposed to be much easier than the rest of those questions and uhh, I would suggest studying more before doing the rest

white coral
#

oki doki, thank you so much, sorry for being slow

night urchin
#

np

#

good luck

white coral
#

💗

#

.close

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#
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midnight haven
#

did I do this correct

pearl pondBOT
dim sage
#

15 is hypotenuse and 15 is one side ???

midnight haven
#

dude idk

#

Ik I did something wrong

#

I just kept going cause I didn't know how to do it

dim sage
midnight haven
#

Find the angle measure of W

dim sage
#

Did it include that triangle?

midnight haven
#

mhm

#

without the 15

#

I added

#

wait I think Ik what I did

#

1 sec

dim sage
#

...

#

Use Pythagoras to find base then proceed...

midnight haven
#

idk how

#

forgot

#

a^2 + b^2 = c^2?

dim sage
#

Yes

midnight haven
#

ye

#

I do nvm

#

@dim sage

#

think I did it wrong again

#

or a. is wrong

dim sage
#

@midnight haven learn Pythagoras please

#

C should be 15...

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#

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covert basalt
#

Hello

pearl pondBOT
covert basalt
#

Am I able to find help here

honest bough
#

Yes

covert basalt
#

Could I please have help with this page

#

Is this possible? This is my first time doing something like this

pearl pondBOT
#

@covert basalt Has your question been resolved?

covert basalt
#

Hello

pearl pondBOT
#

@covert basalt Has your question been resolved?

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orchid cobalt
#

when optimizing how do I find the other variable? For example, I want to maximize the area of a rectangle with certain restrictions, I solve for x and find it, now I know what value of x makes the area function to maximize, I need to know z for example, because xz is area, so how do I find z?

orchid cobalt
#

Do I have to do everything I did but instead solving for x I solve for z?

#

or is there like a shortcut or something?

buoyant panther
#

wait, do you know the area?

#

or something other

orchid cobalt
#

yeah

buoyant panther
#

so then plug x into formula for the area and solve for z

#

aka z = A/x

orchid cobalt
#

since I know x, then I know when what's the maximum area

orchid cobalt
#

I don't know if I'm tripping but it doesn't work

#

it gives another value

#

that doesn't match with the graph

buoyant panther
#

Can you post the original problem/question?

orchid cobalt
#

this is the function*

#

and the critical points

#

since it's a rectangle I get that x and y are the same

#

but it's obviously not, maybe i'm dumb

buoyant panther
#

,w critical points (600/y-4)(y-5)

orchid cobalt
#

bro

#

I'm so confused

orchid cobalt
buoyant panther
#

idk, was that your derivative?

orchid cobalt
buoyant panther
#

-5 *

#

not 4

orchid cobalt
#

ohhhh

#

bro

#

thank you so much

#

my mind is blown, such a stupid mistake

#

.close

pearl pondBOT
#
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placid bane
pearl pondBOT
placid bane
#

How would I simplify this and what identity would I use

honest bough
#

Factor it

placid bane
#

How

honest bough
#

Start with a simplification

#

Let u = cos²x

#

What's the equation in terms of u?

placid bane
#

1-2u+u^2

honest bough
#

Now you have a quadratic

#

Factor it

placid bane
#

(u-2)(u+1)?

honest bough
#

How'd you get that?

hollow grove
#

try again

placid bane
#

How would I split the the 2u

honest bough
#

u² - 2u + 1

#

What two numbers multiply to 1 and add to -2

placid bane
#

-1 and - 1

honest bough
#

So what's the factored expression?

placid bane
#

(u-1)(u-1)

honest bough
#

Yes

#

Now replace u with cos²x

placid bane
#

(cos²x - 1) (cos²x - 1)

honest bough
#

Now use identities

placid bane
#

(sin²x) (sin²x)

#

Would that multiply to sin⁴x?

honest bough
#

Yes

placid bane
#

Thanks

#

.close

pearl pondBOT
#
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distant wadi
#

turn them into improper fractions, make the denominator the same, add together and then make it a mixed number

pearl pondBOT
#
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ionic thistle
#

Hello! Did I resolve it well?

pearl pondBOT
#

@ionic thistle Has your question been resolved?

ionic thistle
#

.close

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noble root
#

help

pearl pondBOT
noble root
#

pls

junior flower
#

With what?

#

You are supposed to just ask the question instead of saying help pls.

coarse dawn
noble root
#

i dont know if ur suppose to add it all up

noble root
pearl pondBOT
#

@noble root Has your question been resolved?

pearl pondBOT
#

@noble root Has your question been resolved?

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steady arch
#

How to do b

pearl pondBOT
short magnet
#

area of garden is length x width of the rectangle

#

and is 45

midnight haven
#

what is this for thonk

steady arch
#

revision booklet for exam tommorow

midnight haven
#

fair enough

short magnet
#

b*c is product of inner terms

midnight haven
#

for 45

steady arch
#

i have no idea what that means

midnight haven
#

okay

#

solve

#

$x^2+10x+21 = 45$

steady arch
#

yes?

midnight haven
#

oh wait, you messed up your FOIL

#

it needs to be 21

jolly parrotBOT
#

♡LexQa♡

midnight haven
#

solve for the x's

steady arch
#

x^2 + 10x = 18

midnight haven
steady arch
#

24

midnight haven
#

also, keep the constant term on the left side, you want to solve for it here

#

anyways

#

$x^2+10x-24=0$ is what you have

jolly parrotBOT
#

♡LexQa♡

midnight haven
#

what do u think is the best approach?

#

to solve this

steady arch
#

factorisng or quadratic fomrula

midnight haven
#

yes, lets do the former

steady arch
#

ok

midnight haven
#

so actually, we can rewrite 10x as 12x - 2x

#

$x^2+12x-2x-24=0$

jolly parrotBOT
#

♡LexQa♡

steady arch
#

ye

midnight haven
#

how should we proceed?

steady arch
#

take out x from the first bit and 2 from the second bit

midnight haven
#

yep!

#

so you have

#

$x(x+12)-2(x+12)=0$ right?

steady arch
#

ye

jolly parrotBOT
#

♡LexQa♡

midnight haven
#

what is the next step?

steady arch
#

(x+12)(x-2)

midnight haven
#

yes

#

so you have $(x+12)(x-2) = 0$

jolly parrotBOT
#

♡LexQa♡

midnight haven
#

what are our solutions

steady arch
#

-12 and 2

midnight haven
#

yep

#

now, if we use x = -12 we will get a negative area

steady arch
#

but i can't be minus twelve so has to be 2

midnight haven
#

which does not make much sense

#

yes\

steady arch
#

tysm bro

midnight haven
#

you are pretty good, good job

steady arch
#

will really help

#

thanks for the help

midnight haven
#

ofc

steady arch
#

How do I close this help thing

#

.close

pearl pondBOT
#
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pearl pondBOT
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midnight haven
#

Hello, Would this be correct? I think I need to make n a radical but Idk

hollow cobalt
#

It's correct

toxic lichen
#

wdym "make n a radical"?

#

yeah this is correct

midnight haven
#

Would this also be correct?

#

@toxic lichen

toxic lichen
#

appears so, yes.

midnight haven
#

ty

#

.close

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rotund lagoon
#

Help me how to do that

pearl pondBOT
vivid coyote
#

what is a, b, x and y in this context

#

i assume a and b are some constants

rotund lagoon
#

Some arbitrary values

hollow cobalt
#

You don't need to prove that though, generally all of the equations remain true after replacing i with -i

rotund lagoon
#

and I hope you know what 'i' is

rotund lagoon
hollow cobalt
#

I haven't referred to a function anyways

#

You can actually take any equation, replace i with -i in it, and it's still true

rotund lagoon
#

Then how would you going to replace it then?

toxic lichen
rotund lagoon
toxic lichen
#

right

#

in that case you can expand the LHS in both equations

#

you will get from the first equation that x = ac - bd and y = ad + bc

rotund lagoon
#

Ok, I did that

#

next?

toxic lichen
#

you should immediately see that expanding the LHS of the second equation gives you (ac - bd) + (-ad-bc)i

#

which is exactly what you want it to be

rotund lagoon
#

But then how tf I am going to bring it in that RHS form?

#

Oh holy sex

#

I get it

#

thanks @toxic lichen

#

.close

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#
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merry stirrup
pearl pondBOT
merry stirrup
#

How would I solve this

#

Show I use log?

#

But it will result in ln (x)

#

Which dosent work

#

Oh I got it I think I should take whole square

#

.close

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little bough
#

Hello i need help in factoring I was answering some examples i found online and i can't understand where they got 2(x+7)(x-4) from 2x^2 + 6x - 56

old marsh
#

First you can factor out a 2

#

2(x^2 + 3x -28)

#

Now we can factor the quadratic using ac method. a = 1, c = -28. We want factors of ac that add to b, which is 3. So ac = -28, factors of -28 that add to 3 are 7 and -4. Then we just put x’s and parentheses in front of them and remember the 2 from before and we end up with 2(x+7)(x-4)

little bough
#

this only works if all numerical coefficients are divisible by the same number right or if it has a gcf?

old marsh
#

the ac method?

little bough
#

no like the factoring out the 2

old marsh
#

Yes, all numerical coefficients must be divisible by the same number or a gcf in order to yield whole number coefficients after factoring out

little bough
#

alright thanks alot i understand now

old marsh
#

Np

little bough
#

.close

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#
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silk vine
#

!help

pearl pondBOT
silk vine
#

This is a question from the Canadian Senior Maths contest

#

I brought it home to try attempt it myslef but still have had no luck

#

This is a more detailed drawing with units filled in

#

This is what I've been looking at

#

and am confident that if I had one more piece of information I could solve it

#

any idea

pearl pondBOT
#

@silk vine Has your question been resolved?

silk vine
#

<@&286206848099549185>

pearl pondBOT
#

@silk vine Has your question been resolved?

silk vine
#

Nope

pearl pondBOT
#
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sour badger
#

How do you find the remainder of a very large number, eg 15^123 divided by 176. Using modulo arithmetic?

sour badger
#

<@&286206848099549185>

#

I'm trying to do this question

#

and this is my working out so far

#

.close

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#
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midnight haven
#

Yo

pearl pondBOT
midnight haven
#

I need help with this one

#

What is the weight of a boy with a mass of 50 kg on earth?

plush bramble
#

what's the formula for weight

midnight haven
#

"N"

plush bramble
#

that's N for Newtons

graceful tendon
#

Isn't it Fg = mg

midnight haven
#

i guess

graceful tendon
#

r u solving then for force of gravity

plush bramble
midnight haven
graceful tendon
#

so Fg = 50 kg * 9.8 (gravity)

#

490 N?

midnight haven
#

I got wrong once

graceful tendon
#

should just be 490 N

midnight haven
#

is not fr

graceful tendon
#

Wait

#

well

#

is there like an answer key or smth

#

how do u know that's wrong

midnight haven
plush bramble
#

,calc 50 * 9.8

jolly parrotBOT
#

Result:

490
graceful tendon
#

Try -490

#

Maybe it's -9.8 since it pulls down

random eagle
midnight haven
#

wait let me just

random eagle
#

kelp

plush bramble
random eagle
#

that’s not spam but okay 💀

midnight haven
#

lmao

graceful tendon
#

swift open up a channel I can help you

midnight haven
#

bro just spawned

plush bramble
midnight haven
#

for the answer?

graceful tendon
#

,calc 50 *9.81

jolly parrotBOT
#

Result:

490.5
graceful tendon
#

Try 490.5

midnight haven
#

ok

#

is like my last try

#

🙏 _ _

graceful tendon
#

if its not that try negative

midnight haven
#

omg thank you so much

#

it worked

graceful tendon
#

sick

#

pls for the love of god answer mine im so dead for tmr

#

how does the transformation work

midnight haven
#

i dunno how to explain

#

srry

graceful tendon
#

j tell me if its one or the other