help-39

[primal breach]

okay okay

what do i do after

:3

[abstract locust]

.

x = 3y + 4

x^2 + 3y^2 = 16

[primal breach]

(3y+4)(3y+4)

do i do that

[abstract locust]

yeah

(3y+4)^2 + 3y^2 = 16

[primal breach]

9y^2+24y+16

am i correct

[abstract locust]

yep nice

but that's just x^2

you need

x^2 + 3y^2 = 16

[primal breach]

9y^2+24y+16+3y^2=16

do i add like terms now?

[abstract locust]

yes

[primal breach]

11y^2 +24y+16=16

what do i do afterwards

[abstract locust]

good

subtract 16 from both sides

[primal breach]

11y^2+24y=0

[abstract locust]

yess, now how can factor this

[primal breach]

Idk

11 on both sides ?

idk tbh

how could i factor it

[abstract locust]

both terms have y as a factor

so factor out a y

[primal breach]

11y^+24y

so y divide both sides?

[abstract locust]

no just factor out a y

[primal breach]

how

[abstract locust]

ab + ac = a(b + c)

[abstract locust]

apply the same thing with this

[primal breach]

y(11y+24)

[abstract locust]

yes good

so this = 0

if a * b = 0, what does that say about a or b

[primal breach]

Idk

it equals zero ?

[abstract locust]

one of them equals zero

[primal breach]

oh

[abstract locust]

so y = 0, or 11y + 24 = 0

do you understand how I got that?

[primal breach]

Yeas

[abstract locust]

ok so now you have the solution y = 0, and what's the other solutoin for y?

[primal breach]

3y-x=-4

y=0

or No

so is x = 4

[abstract locust]

yeah

[primal breach]

im doing this totally wrong

[abstract locust]

no

y = 0 and x = 4 is one solution

but there's another one

11y + 24 = 0

so what is y

[primal breach]

its zero

[abstract locust]

11(0) + 24 = 0??

[primal breach]

oh

11y+24=0

what do i do after

tho

-24 on both sides

so 11y=-24

[abstract locust]

yeah, isolate y

[bright delta]

That's common lol

[primal breach]

?

11y=-24

you mean 11y^2=-24?

[bright delta]

Y=-2.4

[primal breach]

?

no

lol

No wtf

[bright delta]

Oh sorry, y=2.1 smt

[abstract locust]

isolate y natures

[primal breach]

no it doesnt.

[abstract locust]

make y by itself

[primal breach]

okay

[abstract locust]

11y = -24

what can you do from there

[abstract locust]

it's not

[primal breach]

what do you do from there

are you sure its not 11y^2=-24

[abstract locust]

isolate y!!

[primal breach]

HOW

I cant

it will be a decimal if i tried/

[abstract locust]

you litearly did the same thing before

just div ide by 11

so what if it's a decimal

[primal breach]

its wrong if its a decimal

[abstract locust]

no? remember where I got 11y + 24 from

[bright delta]

What's the answer?

In decimal?

[primal breach]

teacher said there wont be any decimals

lol

[abstract locust]

then it's only the first solution

[primal breach]

.close

[pearl pond]

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[primal breach]

Sorry you don't understnad it

[abstract locust]

it's not wrong still

[primal breach]

probably got confuse in something

allg

[abstract locust]

bruh

no you don't know what you're talking about

have some respect

[bright delta]

Ik bruh

Dw

I just converted into decimals

[pearl pond]

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[pulsar lark]

What is your question @bright delta

[bright delta]

11y=-24

[pearl pond]

@bright delta Has your question been resolved?

[pearl pond]

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[midnight haven]

what does integrating over a contour mean

[midnight haven]

and how does it work

[pearl pond]

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@midnight haven Has your question been resolved?

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[rapid needle]

I’m not sure what the parallel lines are here and I tried using theorems like if two lines are cut by a transversal and Corresponding angles are congruent then the lines are parallel but I’m not sure if that’s right

[rapid needle]

<@&286206848099549185>

[rapid needle]

,rotate

[rapid needle]

.close

[pearl pond]

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[shell oxide]

When u replace x with 3, you replace all the x’s with 3’s as well. That’s what it means to plug in 3 as an input. So -x-5 becomes -3-5

[midnight haven]

so -3-5 is the what h(3) is

?

[shell oxide]

Yup!

[midnight haven]

uh so

[shell oxide]

Mhm?

[midnight haven]

is there any paranthesis

or borders

i gotta use

or do i put flat out -3-5

[shell oxide]

It’s just flat out -3-5

[shell oxide]

?????

Ok what’s your answer for h(3)?

[midnight haven]

aye man ion know either

yk how to do this?

[shell oxide]

f(x) is the same thing as 5x-3, we’re solving for x when 5x-3=7

U with me so far?

[midnight haven]

yeah

[shell oxide]

So do u know how to solve 5x-3=7?

[midnight haven]

hmm if f(x) is the same as 5x-3

the answer is 2

7x = 5x - 3

[shell oxide]

YUSSSS LESGOOO

[midnight haven]

5x - 3 is 2x

[shell oxide]

WAwawait 7x=5x-3?

[midnight haven]

ye

f(x)

is 7

7 = 5x-3

5x - 3 is 2x

7 = 2x

[shell oxide]

Explain?

Why 2x?

[midnight haven]

well, i just did

7 = 5x-3

5x - 3 is what?

2x

meaning 2x is equal to 7

.close

[pearl pond]

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[crystal oyster]

Need help with this.

I know I need to find out the area that will be covered by 185ml but i dont know how

Wait

5ml will cover 480cm2

10ml will cover 960cm2

so 1ml will cover 96cm2

96 x 185 will be 17760

So the largest area will be 17760cm2

Am i right in my thinking?

[open pollen]

No

[crystal oyster]

aite kd where'd i go wrong

[open pollen]

To be honest

I dont know

[crystal oyster]

fairs

[open pollen]

Oh

[crystal oyster]

what

[open pollen]

Yes

Very good

Divide 17760 by pi

[crystal oyster]

then root

to get r

[open pollen]

Yes

[crystal oyster]

come on man

[open pollen]

W math

[crystal oyster]

ITS TOO EASY

[open pollen]

Yessie😤

[crystal oyster]

https://tenor.com/view/thats-too-easy-easy-lebron-lebron-james-izi-gif-26596051

.close

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[plush bramble]

unit of what

[pearl pond]

@gentle briar Has your question been resolved?

[gentle briar]

.close

[pearl pond]

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[thin lance]

how do i find domain for this function

[shrewd basin]

We require x^2 -2x > 0 as the thing inside log has to be positive else it’s not defined.

[thin lance]

yes my problem is finding that inequality

[shrewd basin]

x^2 -2x > 0 => x(x-2)>0

From here we sketch the graph y=x(x-2)

And find the region where it is positive ie. above the x axis

[pearl pond]

@thin lance Has your question been resolved?

[pearl pond]

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[regal stirrup]

can someone please help me with this

[thin lance]

i solved it

thank you

[pearl pond]

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[violet jasper]

Hey can anyone help out. I've tried solving through modular arithmetic but to no avail.

[violet jasper]

that m1 = 14 is encrypted to m′
1 = 111 and that m2 = 73 is encrypted to m′
2 = 14. What is a
and b? What is the decryption formula?```

[pearl pond]

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[pearl pond]

@violet jasper Has your question been resolved?

[pearl pond]

@violet jasper Has your question been resolved?

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[coral pilot]

A rectangle has a perimeter of 36 cm and an area of 45 cm 2. What are the length and
the width of the rectangle?

[fleet sky]

so if you have a rectangle with length $\ell$ and width $w$, what are the formulas for area and perimeter?

[jolly parrot]

MellowDramaLlama

[coral pilot]

I’m confused

I need help on this please

[fleet sky]

do you know the formula for area of a square?

[coral pilot]

No

[fleet sky]

length times width

[coral pilot]

Oh

[fleet sky]

and the perimter is the measure of going around your object and ending up back where you started

so then the formula is as such

so basically what this question is saying is that, given a length of $\ell$ and a width of $w$, the area is $2\ell + 2w = 36$ and $\ell w = 45$.

[jolly parrot]

MellowDramaLlama

[fleet sky]

so now you have 2 equations to play with

so solve 2l + 2w = 36 for one of the variables, say w, and then plug that into lw = 45 to find the value of l.

[coral pilot]

Oh ok

Ty

[fleet sky]

yep np

[coral pilot]

.close

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[midnight haven]

How should I proceed doing this problem

[midnight haven]

[pearl pond]

@midnight haven Has your question been resolved?

[pearl pond]

@midnight haven Has your question been resolved?

[pearl pond]

@midnight haven Has your question been resolved?

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[midnight haven]

.reopen

[pearl pond]

✅

[broken stirrup]

Let’s try to get each fractions to have the same denominator

[midnight haven]

Something like this

[pearl pond]

@midnight haven Has your question been resolved?

[slate thicket]

hmm

well for p to be minimum q should also be minimum no?

[midnight haven]

Hmm

I think no

The answer is the 4017 which is sum of numerators

Idk how

Or y

[slate thicket]

idk why but i’m getting a feeling that this is (2008+2009)/(2009+2010)

yes

[midnight haven]

But the thing is why

[slate thicket]

idk how to prove but that seems to be minimum

i just tried all kmown means

like am,gm etc

all were higher than 4017

numerator

[midnight haven]

Hmm just looked in the group

He says

[slate thicket]

thats not rigor proof

[midnight haven]

I am confusion

[slate thicket]

me too

[midnight haven]

Now wt do we do

[slate thicket]

🤔

[midnight haven]

,w 2008÷2009 <p/q < 2009/2010

💀

Ok

[jolly parrot]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Twerkingbee#7740

[midnight haven]

Ok

[slate thicket]

very insightful

[midnight haven]

[slate thicket]

so we need to prove for any a,b,c,d a/b <p/q <c/d the minimum pf p will be a+c

[midnight haven]

Yes

[slate thicket]

is that correct?

hmm

[midnight haven]

Yes

But a+c could be just a coincidence

[slate thicket]

thats what i’m saying

we need to either prove it or disprove it

[midnight haven]

Yes

[slate thicket]

hmm

[midnight haven]

But couldn't p just be as small as we like?

[slate thicket]

no

p,q naturals

[midnight haven]

Wait is it written

There

They dont say that

[slate thicket]

oh yeah right

Q flawed

[midnight haven]

Hence proved

[slate thicket]

good luck finding minimum positive real

[midnight haven]

[jolly parrot]

deep.

[rustic gate]

[midnight haven]

👁️👄👁️

Do you know how to

Find

Minimum

Value

Of p

[midnight haven]

@slate thicket 💀

What is this

Make me understand

[rustic gate]

nice

thats very straightforward lol

[pearl pond]

@midnight haven Has your question been resolved?

[pearl pond]

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[charred carbon]

😄

.close

[pearl pond]

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[still forge]

How to measure how homophily is a network?

[pearl pond]

@still forge Has your question been resolved?

[pearl pond]

@still forge Has your question been resolved?

[fringe haven]

wdym ? :)) ?

[still forge]

well

some graphs are more homophily than others right?

how do you measure them?

[pearl pond]

@still forge Has your question been resolved?

[jagged sedge]

@fringe haven how you define homophily in a graph?

[pearl pond]

@still forge Has your question been resolved?

[still forge]

That's part of the problem. IDK what's the formal definition. What's in my head is this https://en.wikipedia.org/wiki/Network_homophily

[pearl pond]

@still forge Has your question been resolved?

[pearl pond]

@still forge Has your question been resolved?

[compact owl]

i am trying to write an algoritm for that but i couldnt underrstand how mathematicians find the x1 , x2 and x3 by this method

[still forge]

<@&286206848099549185>

[compact owl]

i understand the solving

thx much guys !

[pearl pond]

@still forge Has your question been resolved?

[golden bolt]

10 hours later.... not closed

[pearl pond]

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[gloomy rapids]

Can anyone help me with this? I’m lost on how to run a regression analysis, as well as how to use y as the response variable for it

[pearl pond]

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@gloomy rapids Has your question been resolved?

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@gloomy rapids Has your question been resolved?

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[grim patrol]

looking at proof for Liouville’s

how did we conclude that |f'(z)| = 0

[round temple]

It limit on RHS is 0, then by absolute sign and squeeze theorem, limit of LHS is also 0

[pearl pond]

@grim patrol Has your question been resolved?

[grim patrol]

yea but thats R->inf, so shouldnt it be something like, there exists an R>0 such that for all |z|>R, |f'(z)|=0?

[pearl pond]

@grim patrol Has your question been resolved?

[potent hedge]

No because R does not depend on z

It's valid for whatever R>0

Hence the result

[grim patrol]

ok sry i meant

there exist a q such that |z| > q implies |f'(z)| is arbitrarily close to

R is a bad variable choice as its alr used oops

[potent hedge]

Close to what?

[grim patrol]

0

[potent hedge]

You don't even need that

[pearl pond]

@grim patrol Has your question been resolved?

[grim patrol]

yea but it only approaches 0 as R approaches inf

nvm ill ask it ltr

i wanna ask smt else first

thanks

.close

[pearl pond]

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[exotic flare]

is anyone here good with circuits?

[vestal cobalt]

show the problem and we'll see

[grim patrol]

they r dangerous

[vestal cobalt]

just in relaxed state or in latching as well?

[exotic flare]

just in relaxed state

[vestal cobalt]

ok

so open 12/(4+4)

[exotic flare]

okay..

that would be 1.5

[vestal cobalt]

in closed 12/(4+ 1/(1/4 + 1/4))

that would be 2amps

[exotic flare]

ohhh okayy

one more q ( its an mcq)

[vestal cobalt]

b

amperometer in series

voltmeter in parallel

[exotic flare]

okay

[exotic flare]

also i got 120 as the answer for this

[vestal cobalt]

your calcultor malfunctions

[exotic flare]

i tried with a different one its still 120

[vestal cobalt]

one moment

[exotic flare]

how is 1/6 = 2??

[vestal cobalt]

should be 12/6

I messed up

[exotic flare]

okayy

[exotic flare]

how did you get 12?

[vestal cobalt]

U = 12V

[exotic flare]

oh okay okay

thank you @vestal cobalt for your help

[pearl pond]

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[pearl pond]

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[pearl pond]

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[gritty citrus]

can someone please explain how to do the last two parts

[pearl pond]

@gritty citrus Has your question been resolved?

[vestal cobalt]

https://www.wolframalpha.com/input?i=(n-1)n(n%2B1)(n%2B2)+%3D+(n^2+%2Bn+-+1)^2+-1

[stiff pelican]

the second to last part is a very clever difference of squares

recall that a^2 - b^2 = (a-b)(a+b)

so, x^2 - 4 would be (x-2)(x+2)

another one, more relevant to this problem, would be x^2 - 1 = (x+1)(x-1)

in this problem, we will pretend x^2 = n^4 + 2n^3 - n^2 - 2n + 1

[pearl pond]

@gritty citrus Has your question been resolved?

[pearl pond]

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[lyric elbow]

is this a Vandermonde determinant after switching row 4 and row 2 and for the the 3rd collum would the "c" term in the Vandermonde determinant be I^2 is that possible?

[lyric elbow]

nvm

.close

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[tawdry widget]

Can someone help with this? I know distance is 50 but how do I find displacement

[grim patrol]

um

draw a triangle

to represent the direction moved

the straight line from start to end

that lines length represents displacement

[merry stirrup]

@tawdry widget do it by parallelogram law of vector addition or Just A²+B² cuz it's cos90°

[pearl pond]

@tawdry widget Has your question been resolved?

[pearl pond]

@tawdry widget Has your question been resolved?

[pearl pond]

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[old marsh]

is there an easier way to do this?

[old marsh]

heres my work:

Or do I just gotta do it like this

(I wrote x’ and y’ instead of x2 and y2)

[pearl pond]

@old marsh Has your question been resolved?

[old marsh]

breh for it all to come down to this

There’s gotta be a better way

Anyone?

https://tenor.com/view/whatever-shrug-idk-i-dont-know-elmo-gif-16565594

.close

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[gleaming walrus]

https://gyazo.com/55332977001360354c1bf4eb36dc55b0

[gleaming walrus]

am i tripping

this cant be 40 right

its 10

i got 0.1

how is it 40%

[old marsh]

How’d u get 0.1?

1.8 - 1.2 = 0.6 and then (1.8 + 1.2)/2 = 3/2 = 1.5

0.6 / 1.5 = 0.4

[gleaming walrus]

i pluged mnie into a calculator

[old marsh]

Could u send a photo

It’s probably something to do with order of ops

[gleaming walrus]

@old marsh

[coarse dawn]

It's (1.8 - 1.2)/((1.8+1.2)/2)

[gleaming walrus]

oh

[coarse dawn]

Meaning (1.8+1.2)/2 is in the denominator

[gleaming walrus]

ohhhhhhhhhhhhhh

[coarse dawn]

So 0.6/1.5

[gleaming walrus]

so my order of oepration was wrong

when i did it

[coarse dawn]

Yes

[gleaming walrus]

ok ty

[pearl pond]

@gleaming walrus Has your question been resolved?

[pearl pond]

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[vapid dust]

what happened to the 2 above the cos?

[vapid trench]

how ur handwriting so neat

[wind wigeon]

they factored out costheta

[fleet sky]

they factored out a cos(\theta)

[fleet sky]

lol beat me to it again

[wind wigeon]

its like 2x^2 -x = (2x - 1)x = 0

hahha yeah

i should sleep

[fleet sky]

sleep is for the weak

[wind wigeon]

lol

winter time is ccoming

so technically i have an hour extra of time

[vapid dust]

thanks

[vapid trench]

what grade r u in

just curious

[vapid dust]

Should i replace cosTheta as X or is that a bad habit to have?

[vapid trench]

wat grade\

[vapid dust]

hmmm i can give you my life story but, im not sure you wanna hear it

[vapid trench]

naj just tell me ur grade pls

im in 9th

[vapid dust]

im past HIghschool

[vapid trench]

ah

[wind wigeon]

bad habit yes

but if it helps you visualise it by all means do it

but do it on scratch paper

[vapid trench]

how r u guys so smart xd

[wind wigeon]

dont put it in your final answer

practice 🙂

[vapid trench]

wat grade

im 9th

[vapid trench]

grade?

[wind wigeon]

why would you write grade in your final answer

[vapid trench]

wdym

[vapid trench]

im just asking

[vapid dust]

If i could tell my 9th grade something it would be, Find your self first, Ignore bad influences , and ignore what people think about you🙂

[vapid trench]

Mk

[wind wigeon]

i didnt mean it like that my b

im a 2nd years in uni

[wind wigeon]

facts

[vapid trench]

wow

what math class did u guys take in 9th

im taking alg 2/trig

[vapid dust]

when i was in middle school i used to skip school to play video games, and "forget" to do hw, and my 18 year old self regrets it lol

[vapid dust]

During my time of reflection aka post Graduation i came to the realization that math is more then math, but its a language of the universe and somewhat of a skill, If you practice math every single day for at least 2h a day you can find patterns in everything and its honesty scary and amazing at the same time

[vapid trench]

ty for the advice i take it to heart

[vapid dust]

please do

[vapid trench]

cuz rn after school most of the time im playing video games xd

[wind wigeon]

good times

i remember

[vapid dust]

Delay satisfaction, thats the key

[wind wigeon]

tbh idk, we didnt really name the classes

[vapid trench]

what should i do

[vapid dust]

When i used to play video games i would do it just to escape the real world and now that im forced to face the real world the passion of playing video games just gives me PtSD back to the times where i used to play videos games to escape life

[vapid trench]

ironic

@wind wigeon wat shouldi do

[wind wigeon]

write roots in exponential form

$\sqrt(x) = x^{\frac{1}{2}}$

[jolly parrot]

Gijs

[wind wigeon]

$\sqrt3 = x^{\frac{1}{3}}$

[vapid trench]

ik im not dumb xd

[jolly parrot]

Gijs

[wind wigeon]

fair enough

[vapid trench]

but it’s a lot of work

to shift back and dorth

forth

plua theres no need

plus*

[wind wigeon]

yeah

sometimes life be like that

[vapid trench]

so wat shluld i do

im kinda stuck

@wind wigeon whered u go xe

xd

[vapid dust]

hint
Practice until methods become second nature

[vapid trench]

ik

but rn i dont know the methods

well i kinda do

but im kinda loat here

lost

.closed

[vapid dust]

When im lost, i either look for help here or look up videos on the subject and dont stop looking until i find something close to what im looking for, or just take a break

[vapid trench]

IM LOOKING FOR HELP HERE

And no ones he;pint

So ima open a help thingy

wai rlemme ask helpers

<@&286206848099549185>

[vapid dust]

Whats the name of the unit

[vapid trench]

wdym

[vapid dust]

Most of the time teachers use work sheets with the name of the unit on it

[vapid trench]

simplifying radicals

[vapid dust]

look for some relevant work sheets and google em

[vapid trench]

ye but our teachsr posts stuff much harder then whats online

so

im not gonna find anyhtung

plus

[vapid dust]

dont challenge the internet lol

[vapid trench]

i wanna know what to do from here

[vapid dust]

and also theres some Math solver website that give you the solution and also some steps to get to the solution

[vapid trench]

ik

i can get that

but i wanna know how to do it my way

like from what ive dine so far

[vapid dust]

lol i do that to, k just find the Solution for one of your problems and look at what changed from beginning to end and find the patterns in-between

[vapid trench]

can you not help m3

do you not know this

[vapid dust]

i would help you but i got a exam next week and i got memorize the whole unit circle and some forumlas so i got my hands full right now

[sick bloom]

You could have helped them instead of wasting your time saying that

[sick bloom]

Where did The 3 is the denominator or the 3rd root go

@vapid trench the easiest way would be to convert all of them to 6th root

And then just cancel Stuff

Try that

[pearl pond]

@vapid dust Has your question been resolved?

[vapid trench]

ok

@sick bloom

new work

wait in last line should be 1000 instead of 10000

but still,

y is it taking so long

wat am i supposed to do differently

also their should be a 9 in the secon image too

but stilll

[pearl pond]

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[sick bloom]

Lemme try writing it

[vapid trench]

hmm now wat do i do

Plus im gettinga diff answer

[vapid trench]

,rotate

[vapid trench]

,rotate

[vapid trench]

,rotate

[vapid trench]

im alr confused from ur first to second step

[sick bloom]

Where

[vapid trench]

@sick bloom plus i wanna know wat im doing wrong

where do u get y^2 outside from

plus wt am i doing wrong

Cuz j have a test in 2 days

and this is how ill be doing it

[sick bloom]

With a 9 your answer should technically be correct

[vapid trench]

hmm how

[sick bloom]

y^3=y^4/y

[vapid trench]

ik

[sick bloom]

I multiplied the y in the numerator

[vapid trench]

but no y^4 on the top

im talking about my work

lets forget ablut urs

[sick bloom]

So they want the root to only be on the top, right?

[sick bloom]

That probably means that x and y are in the numerator

[vapid trench]

this is how they want it to be

this is what i have so far

[sick bloom]

@vapid trench how can you move the variables to the numerator

[vapid trench]

uhnm

well

since

they are in the same root im trying to subtract

but then

it would be negative

snd that wouldnt be allowed

so

wtf

[sick bloom]

Nono

So instead of writing 1/y^3

[vapid trench]

y^-3

[sick bloom]

You can write y^3/y^6

Right?

[vapid trench]

ye

[sick bloom]

Do that and then you can take y^6 outside

[vapid trench]

can you do it from my work to the answer and send me a pic pls

[sick bloom]

Sure

[vapid trench]

ty

Xs

[vapid trench]

xd i was just about messge it shouldb tbe taking this long

[sick bloom]

Too many fucking numbers

Why are they torturing you like this

[vapid trench]

IKR

wveryone complains about my teacher

wait search up

joe bob kim

hes our teacher

xdd

[sick bloom]

That doesn't sound like a real name

[vapid trench]

ik

exacrly

but thats his name

search it up

trust me

ull see him

writting on the whiteboard

u can see him smiling

he enjoys torturing us

[sick bloom]

It's blurry, ye

[vapid trench]

the class average is like a 51 percent

on rhe tests

he makes them up and just adds imaginary numbers ane stuff

U see what he did to a simple simplifying radicals right

this is from last years quiz

[sick bloom]

My maths prof is so awesome that he directly gives everyone 50%

If you got Below 50%

So that noone fails

[vapid trench]

usually he gives the class work super ez

and the tests a hundred times harder

like he would give a prob like this on the test but add like another section of multiplication and give a simple radical simplification for class

btw

i dont get

how u got that

how did the x^4 move up

[sick bloom]

x^4

=

x^6/x^2

Right?

[vapid trench]

ye

[sick bloom]

Try substituting that

And you can just take y^6 outside the root

As y

[vapid trench]

im confused

this dosent make sence

the x^4

should go up as

-x^4

or x^-4

how does it go up as x^2

and the y just directly transfers over

thats like not possible

it shouldnt be the same in the numberator and denominator

should be opposite signs

I

o

i seeeee

u did something

on the left side

[sick bloom]

yes x goes outside

In the denominator

[vapid trench]

thats brilliant ngl

i dont get the last step doe

@sick bloom

<@&286206848099549185>

[sick bloom]

@vapid trench after doing that, the answer was technically in the correct form so just putting that in the calculator should give you an acceptable answer

Your answer had 5 in the denominator

[vapid trench]

wait

so

[sick bloom]

So I just multiplied by 5^6 to take that out

But I don't get the need to do that unless you absolutely hate decimals

[vapid trench]

ye but th4 thing is

see the question

it needs to be in that form

form of

[sick bloom]

Yes

If you simplify the stuff inside the root

[vapid trench]

btw for future math problems can i just dm u

[sick bloom]

You'll get (x^2(1597.2)^(1/6))/y^4

[vapid trench]

ye i got it now

[sick bloom]

That's technically in that form

[vapid trench]

i got that

but u cant have a radical

in the denomiator

So its not vorrect

at the same time

[sick bloom]

Simplify it

[vapid trench]

no i know

thats right

im saying before

the step before where u said its technically correct

[sick bloom]

Do you see a radical in the denominator here

[vapid trench]

Not here

[sick bloom]

o

[vapid trench]

bruh

i said before

the stel before

Step

[sick bloom]

I don't use discord very often I'm just here rn coz I'm not feeling well xd

[vapid trench]

oof

welp

is this good sruff for 9th grade btw?

or did u do more advanced then this in 9th grade

[sick bloom]

Don't remember

[vapid trench]

also y dk u help peole

people

[sick bloom]

Because it's kinda entertaining at the moment

[vapid trench]

eh?

[sick bloom]

idk why

It's kinda fun rn

But probably won't feel as fun if I do this regularly

[vapid trench]

wait

also

when theirs

like

x/y/z

@sick bloom

[sick bloom]

Wdym

[vapid trench]

what do i do

when its like that’

[sick bloom]

It either has to be (x/y)/z or x/(y/z/)

[vapid trench]

Welpe

ok]

ty

wait

what math r u doing

have u done like linear algebra and multi varibale calc

[sick bloom]

Yes I have done those

[vapid trench]

which college

uni

i mean

[sick bloom]

I'm not great at it tho, I'm a physics major

[vapid trench]

o k

[sick bloom]

Don't wanna disclose xd

[vapid trench]

o y

[sick bloom]

.close

[pearl pond]

Channel closed

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Use .reopen if this was a mistake.

[vapid trench]

xd

[pearl pond]

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[tall tangle]

is the 2^n a mistype?

like it should just be 2(1* 2 * 3....*n)

???

[real scarab]

no

[tall tangle]

i dont get it

[real scarab]

you get one 2 out of every even number

its not additions

2*4*6 = (2*1)(2*2)(2*3) =(2^3) *1*2*3

[tall tangle]

oh

ok

thats right

thx

.close

[pearl pond]

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[pearl pond]

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[midnight haven]

so this is the question, i got part a), but im confused about part b. i got this far, but the answer is just pi/24 and pi/8, not the other two. does anyone know why?

[pearl pond]

@midnight haven Has your question been resolved?

[midnight haven]

<@&286206848099549185>

help p[ls

[pearl pond]

@midnight haven Has your question been resolved?

[midnight haven]

please...

[blazing cave]

try plugging in 3pi/8 and 11pi/24 back into the equation

[pearl pond]

@midnight haven Has your question been resolved?

[lavish rampart]

ig the answer key might be wrong

Because all 4 should be right , they all satisfy the inequality

[midnight haven]

yeah

this is what it says

p is pi im guessing

teacher was lazy so didnt bother actually copying a coherent homework assignment over

[midnight haven]

afaik itr didnt work

[lavish rampart]

How would 9/24pi be in the third quadrant ? 💀

[lavish rampart]

Why is he considering 3theta after dividing by 6? Shouldn't he consider theta ?

[midnight haven]

i have no clue

[midnight haven]

yeah i have no clue what is going on

[lavish rampart]

Idk man i suck at math , but i think the key is wrong , he should consider theta not 3theta

[midnight haven]

these homework sheets are so bad lmao

yeah idk

thanks

[lavish rampart]

It would be in the third quadrant for 3theta sure because it's >pi and pi is 180° , but where tf did 3theta come from lmao

[midnight haven]

how do you do the quadrant stuff btw

i dont really understand that

[lavish rampart]

It's easy , look do u understand radian measurement?

[midnight haven]

yes

[lavish rampart]

So uk that pi=180°

[midnight haven]

wait was this the reason for the 3 theta stuff

[midnight haven]

yes

[lavish rampart]

So if u have 27pi/24 it will be > pi

[midnight haven]

yes

[lavish rampart]

So it will be greater than 180° and 180-270° is in the third quadrant

[midnight haven]

but what do quadrants mean

like

how do i know what each of the graphical quadrants corresponds to

[lavish rampart]

Hmm , are u aware of the unit circle ?

Wait I'll just draw it out

[midnight haven]

ohhh

thank you

[cyan oracle]

0 degrees is on the end of the line between the A and C

[midnight haven]

A=q1 S=q2 etc.?

[lavish rampart]

Ohhh ok ok

That's where it comes from ok now it makes sense ig

[midnight haven]

so 0<x<pi/2 = quadrant 1, pi/2 <x< pi = quadrant 2, etc/?

[midnight haven]

i still dont really get it

[lavish rampart]

Ye

[midnight haven]

why would you plug it back into that

shouldnt it work if you also plug it into the cos equation too

[cyan oracle]

it's because at the beginning you square both sides, which means negative solutions also work when they wouldn't in the original question

if that makes sense

[lavish rampart]

Because u can't take positive sq root if both quantities (sin and cos are negetive)

[cyan oracle]

thats why there's answers which don't work

[lavish rampart]

Ud have to take negetive

[midnight haven]

ohhhh

so you qwould plug it back into the sin3x + cos3x

it being the 4 solutions

[cyan oracle]

Well what I think the mark scheme is saying is that you don't have to plug them back in to find which results are wrong

if you have your values for theta, then you know that in the original question you're looking at 3theta

[midnight haven]

that makes a lot of sense, thanks

[midnight haven]

ahh

[cyan oracle]

3theta would be pi/8, 3pi/8, 9pi/8 and 11pi/8

[midnight haven]

now im ckinda confused again

[cyan oracle]

if you know that between pi and 3pi/2 that both sin and cos are negative then you show that you're squaring a negative number

[midnight haven]

why wouldnt you also find what theta is for the next equation of sin

like sin6x

why wouldnt you divide the 4 sols by 6

nvm

[cyan oracle]

because the original question is with 3theta. The 6theta just comes from you showing that (sin 3 theta + cos 3 theta)^2 has the same value as 1 + sin 6 theta.

[midnight haven]

yea yeah

thanks

[cyan oracle]

i mean you can still prove the last 2 solutions don't work with sin(6theta)

[midnight haven]

one last q

[cyan oracle]

but sometimes you can't

[midnight haven]

how do yo uknow that 9pi/24 is in the third quadrant

wouldnt the second start at 12pi/24

the third at 24pi/24

[cyan oracle]

you have to multiply all solutions by 3

because of the 3 theta

[midnight haven]

omg

yes

ur right

mvb

thanks

[lavish rampart]

Ye

[midnight haven]

thank you guys so much

that make s alot of sense

[lavish rampart]

If ur confused about quadrants just google trigmetry unit circle

[midnight haven]

thank you

[lavish rampart]

It'll make more sense if uk what a unit circle is

[midnight haven]

thank you very much!

.close

[pearl pond]

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil loom]

formula for how to calculate rank of a word from dictionary

[pearl pond]

Please don't occupy multiple help channels.

[tranquil loom]

@buoyant panther

<@&268886789983436800>

<@&286206848099549185>

[flint field]

!15m

[pearl pond]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[flint field]

Read this

[old geyser]

Bro

I love how you break 3 rules in single minute

[tranquil loom]

lol

sry

#help-2 message

[old geyser]

And a another rule

Don't waste channels dude

.close

[pearl pond]

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sage patrol]

how do i solve by completing the square

[shrewd basin]

Well by completing the sqaure

https://youtu.be/C206SNAXDGE

$x^2 + 6x +9 -20=0$

[jolly parrot]

Pure

[sage patrol]

for this question they used The quadratic formula

for some reason

[rose creek]

You can use the 0 product principle and quadratic formula to solve this yes

[old marsh]

Either method works

[shrewd basin]

You said by completing the square so I suggested the video