#help-38

1 messages · Page 168 of 1

maiden hare
#

Why half?

hard crane
#

it cuts it into two

#

so

#

two more faces

maiden hare
#

Right

hard crane
#

S_z is added

#

I got that

maiden hare
#

So now, one more cut

hard crane
#

it becomes 3S_z

maiden hare
#

Then do the same for the other directions (S_x, S_y)

#

And of course S = S_x + S_y + S_z

hard crane
#

so its just

#

3S

maiden hare
#

Yes

hard crane
#

Thank youu

#

.close

trim joltBOT
#
Channel closed

Closed by @hard crane

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

alpine mortar
#

help

trim joltBOT
alpine mortar
#

What is the probability of a pigeon making a noise which deflects it's poo at an angle of 45 degrees to the back right while making sure the bird flies above me(Conditional probability sum)

#

I move at 90km/hr

#

North direction

warm nymph
#

Close the channel

alpine mortar
#

Why

knotty oriole
#

This is not a serious question.

radiant quartz
#

youve jsut been spamming this nonsense quiestion so may times. what the heck does this mean

alpine mortar
#

IT'S THE SUM AT MY EXAM

alpine mortar
#

PLUS IM NOT SPAMMING

knotty oriole
#

Don't troll

alpine mortar
knotty oriole
radiant quartz
#

making a noise which deflects its poo
this is certified nonsense

alpine mortar
#

WHY CAN'T I NOT ASK

#

THIS ISN'T SHITPOST

#

A QUESTION AT MY EXAM

faint field
#

i'm sorry are you 11?

knotty oriole
alpine mortar
#

.close

trim joltBOT
#
Channel closed

Closed by @alpine mortar

Use .reopen if this was a mistake.

radiant quartz
#

if its so real u need to chill the hell out

warm nymph
#

You have too much free time

alpine mortar
#

IM NOT HAVING THESE IDIOTS CALLING MY EXAM FAKE

alpine mortar
knotty oriole
paper willow
#

Why are they bullying him

knotty oriole
#

@paper willow it's definitely not

paper willow
#

For a doubt

paper willow
knotty oriole
#

You should also stop.

paper willow
#

Why stop?

#

What did I even do

knotty oriole
#

Why are we prolonging this?

#

Go do something else.

paper willow
#

Technically why should they bully him for asking a doubt

#

You know what

#

I'm asking it

knotty oriole
#

Nobody is bullying anybody.

knotty oriole
paper willow
#

They reacted with laughing emoji and said "you have too much free time"

paper willow
#

IT'S AN ACTUAL QUESTION

paper willow
knotty oriole
#

Even if it's not, asking for help on exam questions is against the rules.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wraith hinge
trim joltBOT
wraith hinge
#

how does he get that?

limpid belfry
#

moving ax to the other side and simplifying

wind cloak
#

can you give more context

prime crystal
#

wait

#

if u move ax to left side

#

wouldnt it be 5x-ax = 0

wind cloak
still rose
#

x(5-a)

prime crystal
#

= 0

still rose
#

yep

prime crystal
#

u dont get 1/5-a

still rose
#

yes

limpid belfry
#

oh mb

wraith hinge
#

and its s not 5

#

lmao

limpid belfry
#

oh

prime crystal
#

well

#

you should post the question with proper context

wraith hinge
#

doesnt change anything ig

#

if its w s or 5

#

i think its because of f(0)

#

magbe

#

.close

trim joltBOT
#
Channel closed

Closed by @celest bramble

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

celest umbra
#

I don't know how I should approach this question, It starts by talking about number of potatoes (10) and then it switches to talking about bout whole bag of potatoes (1 bag and 100 bags).

trim joltBOT
#

@celest umbra Has your question been resolved?

trim joltBOT
#

@celest umbra Has your question been resolved?

trim joltBOT
#

@celest umbra Has your question been resolved?

trim joltBOT
#

@celest umbra Has your question been resolved?

lime sphinx
celest umbra
celest umbra
#

<@&286206848099549185>

tight sphinx
#

Hey gun master

#

How did you do the gun at the end of ur name

trim joltBOT
#

@celest umbra Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

marsh forum
trim joltBOT
marsh forum
#

so I first got $\delta. = 2 \varepsilon$

solid kilnBOT
#

Veni, vidi, perii

marsh forum
#

so Then $|x-2|< 2 \varepsilon$

solid kilnBOT
#

Veni, vidi, perii

marsh forum
#

|x|< 2( \varepsilon +1)

#

Now I'm lost

#

<@&286206848099549185>

thorn void
#

So you want to show that |1/x - 1/2| < epsilon right?

marsh forum
#

Yea

thorn void
#

So my first hint would be to combine the fraction

marsh forum
#

What fraction

#

I've found delta in terms of epsilon

thorn void
marsh forum
#

$\frac{|x-2|}{2|x|}< \varepsilon$

cosmic meadow
thorn void
#

Missing a {

#

After frac

solid kilnBOT
#

Veni, vidi, perii

vernal mica
#

I would rewrite this as $\frac{|2 - x|}{2|x|}$ , but you do you.

solid kilnBOT
#

Bishop

marsh forum
#

My issue isn't here

thorn void
#

You have one way to simplify this immediately

marsh forum
#

I have found $\delta in terms of epsilon$

solid kilnBOT
#

Veni, vidi, perii

thorn void
#

Since |2 - x| < delta (if you have an epsilon that works then you can sub that in already but I’m not gonna worry about that yet)

#

Have you been through examples where you set delta < some number to be able to bound something that isn’t |x - 2|

#

For example having delta < 1

marsh forum
#

I don't get what you're getting at?

#

I know I have to find delta in terms of epsilon

vernal mica
solid kilnBOT
#

Bishop

thorn void
vernal mica
#

Because all terms are positive

marsh forum
#

that' s smart

thorn void
#

Well tbh if delta < 1, |x - 2| < 1 then -1 < x - 2 < 1, so 1 < x < 3, so |x| > 1

vernal mica
marsh forum
#

Okay, my question is this

#

to put it better

#

how do I get $|1/x-1/2| < \varepsilon$ form $|x-2|< 2 \varepsilon$

thorn void
#

You now just need to bound |x| from below

solid kilnBOT
#

Veni, vidi, perii

marsh forum
#

I did get something when I tried

thorn void
#

I think you are misunderstanding something

solid kilnBOT
#

Veni, vidi, perii

marsh forum
#

oops

thorn void
#

Yeah so you have |x - 2| < delta, now you want to say |x| > …..

#

And the way I suggested is how you get that

charred storm
#

delta = 2epsilon is not correct btw

marsh forum
#

$|x-2|< 2 \varepsilon \implies \frac{1}{x} > \frac{1}{2 -2 \varepsilon}$

solid kilnBOT
#

Veni, vidi, perii

marsh forum
charred storm
#

no its just missing something

#

how did you bound 1/|x| in your scratchwork of finding delta?

vernal mica
#

$|\frac{1}{x} - \frac{1}{2}| = |\frac{2}{2x} - \frac{x}{2x}| = \frac{|2 - x|}{|2x|} < |x - 2| < \epsilon$ , which completes the proof by choosing $\delta = \epsilon$ , since as $|x - 2| < \delta = \epsilon$ , then $|\frac{1}{x} - \frac{1}{2}| < \epsilon$

solid kilnBOT
#

Bishop

thorn void
#

If you set $\delta < 1$ you have $|x - 2| < 1 \implies -1 < x - 1 < 1 \implies 1 < x < 3 \implies |x| > 1$

solid kilnBOT
#

eugene_krabs_has_cake

marsh forum
#

$|x-2|< \delta$
\
$2 - \delta <x<2+ \delta$
\
$\frac{1}{2-\delta}>1/x$

solid kilnBOT
#

Veni, vidi, perii

vernal mica
thorn void
charred storm
vernal mica
thorn void
#

That wasn’t my issue

#

|x-2|/|2x| < |x-2|

vernal mica
#

Oh

thorn void
#

It works if you let delta < 1 though

charred storm
#

if delta < 1 then 1/2>1/x from what you just found which means 1>1/x also

thorn void
# marsh forum how?

I’m sure Ann’s gone through examples where she gave you her solution where she made delta be less than some known number to be able to bound things

charred storm
#

thats how in your scratchwork you go from |x-2|/2|x| < |x-2|/2 by letting delta<1

#

which in the actual proof means you need it to go the opposite way

marsh forum
#

I see

#

thanks

#

.close

trim joltBOT
#
Channel closed

Closed by @marsh forum

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stray lynx
#

I got #3 like
(2²-5x+3)(x-3)
(2²-6x+1x+5)(x+1)
2x(x-3)+1(x+3)
(x-3)(x+3)(2x+1)(x-3)
(x+3)(2x+1)(x-3)²

stray lynx
#

Am I right?

#

Ohh I see my error

#

Thanks

#

.close

trim joltBOT
#
Channel closed

Closed by @stray lynx

Use .reopen if this was a mistake.

stray lynx
#

.reopen

trim joltBOT
#

stray lynx
#

Is it
(2x²-5x+3)(x-3)
(2x²-3x-2x+3)(x-3)
(2x²-3x)(-2x+3)(x-3)
2x(x-1)-3(x-1)(x-3)
(x-1)(2x-3)(x-3)?

#

?

#

Wait

#

I noticed something

#

On the 3rd part

#

Its x(2x-3)(-2x+3)(x-3)

stray lynx
#

I'd get -3x+3

#

???

trim joltBOT
#

@stray lynx Has your question been resolved?

#
Channel closed

Closed by @stray lynx

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

grim raft
trim joltBOT
grim raft
#

How to determine corner / cusp

nimble stone
#

check if the derivatives are continuous

grim raft
#

How do I find the derivative ?

nimble stone
#

the derivative of f(x) will equate to the derivative of all its expressions, bounds unchanged

#

if the function is continuous at the point and the derivative is not then its a corner/cusp

grim raft
#

So it’s like if it continues in a straight line then derives from it ?

nimble stone
#

im not sure what you mean

grim raft
#

Like I understand at -2 it doesn’t connect so it’s discontinuos , but what does that have to do with the derivative ?

nimble stone
#

it doesnt
im saying that if f is continuous at a point, but its derivatives are not, then its a corner

#

,w graph |x|

nimble stone
#

like here, at 0 f is continuous, but the derivative isnt

#

its a corner

#

from the left the f'=-1, from the right f'=1

grim raft
#

Im still confused on what the derivative is , is there an algebraic value ?

nimble stone
#

do you know what derivatives are?

grim raft
#

No not really

nimble stone
#

here you would only need the power rule if you want to do it algebraically

#

however, if you draw your graph reasonably accurately, you should be able to tell by looking at it

grim raft
nimble stone
#

the connecting point on the bounds would be jagged rather than smooth

grim raft
#

So for example in this

#

Would it be where it goes down rapidly

#

Here is better image*

nimble stone
#

yeah thats nicer

grim raft
#

So since it is disconnected at -2 it’s a discontinuity, since it’s smooth at 0 it’s a continuous, and since it goes sharply down and jagged at 1 it’s a corner ?

nimble stone
#

you got it

grim raft
#

👍 thank you

trim joltBOT
#

@grim raft Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

haughty heath
#

how do i dooooooooooo this not sure if i need to go elsewhere tho since its kinda physics

mild oxide
#

Use equilibrium equations

dry copper
#

(the direction here is important)

mild oxide
#

Hun

#

Huh*

#

As the beam has to be in equilibrium use summation Fx=0, Fy=0
And summation of moment of all the force about any point on the beam =0

mild oxide
#

See

#

I did the question

#

And you don't need that much

#

You know moment of force?

#

About a point?

haughty heath
#

No…

#

I’m revising for an aptitude test

mild oxide
#

Aah

haughty heath
#

I haven’t touched high school stuff in a while

mild oxide
#

Oof

#

Still see

haughty heath
#

I’m cooked

mild oxide
#

Moment of force about a point

#

Is the perpendicular distance of the line of action of that force from that point

#

Like let me give you an example

#

Look at this

#

I hope I have written clear and crisp

#

@haughty heath

#

Are you getting what I have written?

haughty heath
# mild oxide

But what’s that got to do with the question above?

mild oxide
#

See

haughty heath
mild oxide
#

We need to find the weight

#

Which is needed to balance

#

The beam

haughty heath
mild oxide
#

Oh

haughty heath
mild oxide
#

See I explained a concept there

#

Which is useful in this question

#

See if the beam is balanced

#

It will be in equilibrium

haughty heath
#

If ur free might be easier to hop on a call to explain it

#

In like 5-10 mins

mild oxide
#

I am outside

#

Here connectivity is less

#

Actually I am not in my own home

haughty heath
#

Oh never mind

mild oxide
#

Wait gotta go

haughty heath
#

Remember I haven’t touched this stuff in a while and those terms aren’t gonna mean anything to me

mild oxide
#

Na no-one is a dummy

#

Rusty Is the term I coin

#

You are just rusty my man

haughty heath
#

Think about explaining this to ur dad who hasn’t done math in uears

#

He won’t know what most of these terms mean I’d assume so anyway

mild oxide
#

💀☠️

#

And let me explain it

haughty heath
#

😭

mild oxide
#

Be a man

#

Don't cry

#

See beo

haughty heath
#

Haha

mild oxide
#

Bro*

#

In your case

haughty heath
#

Alright let’s do it

mild oxide
#

I would prefer what Emily told

haughty heath
#

Just keep it simple and explain how to do the problem

#

I don’t necessarily want to understand it

#

Just need to get to the answer so I can pass a test

mild oxide
#

💀☠️

#

Sure?

haughty heath
#

So let’s go step by step

mild oxide
#

!nosols

trim joltBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

mild oxide
#

Yes

#

10x10+6x4=Wx8

haughty heath
haughty heath
#

Idk what I’ve got tho

#

What is it 124 N or Kg or m

mild oxide
#

Oh

#

Got it

#

You got 124/8

#

Kg

#

15.5 kg

haughty heath
#

Ohhh then I do 124 divide 8

mild oxide
#

Now for !

haughty heath
#

Yeahhh

mild oxide
#

Now for N

haughty heath
#

Wait

mild oxide
#

We multiply by 10

haughty heath
#

Hold up

#

15.5 isn’t the answer?

mild oxide
#

See

#

15.5 kg

#

Its not the option

haughty heath
#

So need to covert 15.5kg to N

#

Is there a formula for that?

mild oxide
#

Yes

#

15.5*10

haughty heath
#

Jesus I don’t get formulas on the dam

#

Exam

#

How tf haha

mild oxide
#

See

#

15.5 kg is mass

#

Weight is force

dry copper
#

thanks for explaining that @mild oxide i was away

haughty heath
#

M is distance?

mild oxide
#

Actually Emily thanks

dry copper
#

exactly my point, nice

mild oxide
#

To you too for explaining simply

haughty heath
#

Simple explanation is the way I like it

mild oxide
#

I told him bout moment of force but he has gotten rusty

haughty heath
#

Yeah don’t remember that

#

Don’t think I need to but if you can somehow explain it on dummy terms I’m all ears

mild oxide
#

Bro see

dry copper
#

yeah, torque and lever arm and cross product, no one remembers lol

mild oxide
#

For you to understand moment of force

#

First I need you to explain force

#

And for this question specifically

#

I need to explain you weight,force, moment of force, and equilibrium equations

haughty heath
#

The what

#

What is equilibrium

#

English please

#

Not math language

#

Or chemistry

#

Whatever it is

mild oxide
#

Equilibrium is a state in which a body

#

Has net force 0 on it

#

In any direction

#

Along any dimension in which it exists

#

May it be 3 d 2d or 1d

haughty heath
mild oxide
#

💀☠️

haughty heath
#

Gang

dry copper
#

YT required imo lol

mild oxide
#

Now we begin with Schrodinger's time dependent equation

#

💀☠️

haughty heath
#

Lil reminder

#

I haven’t done this

#

In a while

mild oxide
#

Yes?

#

Lol

haughty heath
#

INFACT I may never have done this

mild oxide
#

Relax

haughty heath
#

It doesent ring a bell

#

I don’t think I’ve done whatever u were talking about above

mild oxide
#

Ok so we begin with the next unit

haughty heath
#

I did maths and physics up until 15 then stopped

mild oxide
#

Friction

#

💀☠️

haughty heath
#

That’s how it is in UK

#

we finish high school at 15-16

mild oxide
#

Chill bro see now

haughty heath
#

That’s where my knowledge with this shenanigans goes

mild oxide
#

W=mg

#

Weight = mass x acceleration of gravity

haughty heath
#

Weight = mass gravity

#

Yes

#

I get that

mild oxide
#

Weight is the force with which the earth pulls us towards its centre

#

Fr

#

So now

haughty heath
#

Yeah 9.81

#

Or something

mild oxide
#

You had mass as 15.5kg

#

Now for weight

haughty heath
#

Yes

mild oxide
#

,w 15.5x9.81

mild oxide
#

Which is not in the options

#

This means

#

They too 10

#

Took*

#

So

haughty heath
#

Nah

mild oxide
#

,w 15.5*10

haughty heath
#

It’s right

#

Wait

#

It says assume gravity is 10

#

So it’s 155

mild oxide
#

Yes

haughty heath
#

Cus 15.5x10

mild oxide
#

Fr

haughty heath
#

Is 155

mild oxide
#

Yes

haughty heath
#

Thank u

mild oxide
#

Yes

#

Good

haughty heath
#

Gracias

mild oxide
#

You got the answer by yourself

haughty heath
#

Si

#

Much as Gracias

mild oxide
#

Welcome

#

Say thanks to Emily too

haughty heath
#

Right I’m gonna continue practising… onto cognitive skills next

#

Thx em

mild oxide
#

em?

haughty heath
#

Short for Emily

mild oxide
#

Okok no prob

#

Okok

haughty heath
#

.close

trim joltBOT
#
Channel closed

Closed by @haughty heath

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

calm rover
#

Can someone please show me a step by step solution to this? Do i need to use natural log to get the answer? I have simplfied it but idk what to do next.

simple haven
#

!show

trim joltBOT
#

Show your work, and if possible, explain where you are stuck.

simple haven
#

!noans

trim joltBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

simple haven
#

For the record, I would start by raising everything to the x power and then multiplying by (x+1) on both sides.

calm rover
#

I am actually not learning this topic atm but my friend asked me if i know the answer I just wanna know how to approach it.

simple haven
#

But after this you have 2 = u^(u^2)

#

Where u = x+1

#

And this isn't straightforward to solve still

#

The problem is I saw the solution at a glance because I'm familiar with a particular proof.

#

But actually solving it when you're not familiar with said proof is less obvious

#

One method that will work is to rewrite the base of the right hand side.

#

So that the base is 2 instead of u

#

If you're familiar with log and exponents then you might have done something similar for base e.

#

But it's a little more rare with base 2

#

u^(u^2) becomes 2^(u^2 log2(u))

#

And you can rewrite it into a form where you can eventually use the Lambert W function

#

Which will give you all the solutions, not just the two real ones.

#

But I don't see a clean way of getting the two real solutions without just making an educated guess

calm rover
simple haven
#

For any base b > 0 and ≠ 1, if you have x (in the proper domain), then x = b^(logb(x))

calm rover
#

thank you for helping me, You made this easy to understand but now I know I really need to get better at logs.

simple haven
#

It's a much harder problem than you'd typically see at the high school level

calm rover
#

oh I am actually at year 10 rn.

#

thank you

#

.close

trim joltBOT
#
Channel closed

Closed by @calm rover

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wraith hinge
#

answer

trim joltBOT
main sigil
wraith hinge
# main sigil question

if there are 3 gorillas wearing tuxedos, how many dogs are purple and how many cats are red?

sudden trout
#

Ragebait

main sigil
#

:bending_skull:

#

I really need nitro for moments like this one

wraith hinge
#

X are purple and y cats are red

#

it's not ragebait it's a genuine question

wraith hinge
fallow grotto
#

Trick question. No cats are red

wraith hinge
#

correct

#

but what about the dogs question

#

The answer is: banhammer

#

you're gonna ban me for asking a question?

main sigil
wraith hinge
#

thought this was math

#

not strict moderation

main sigil
fallow grotto
high cipher
wraith hinge
main sigil
rare token
#

is there a question here?

wraith hinge
#

uh huh

main sigil
#

a very stupid one, but yes

wraith hinge
#

if there are 3 gorillas wearing tuxedos, how many dogs are purple and how many cats are red?

rare token
fallow grotto
wraith hinge
#

there IS an answer

main sigil
#

yes, there is an answer

wraith hinge
#

it's not even trolling it's a question

#

if there are 3 gorillas wearing tuxedos, how many dogs are purple and how many cats are red?

main sigil
#

we just dont know the answer

high cipher
wraith hinge
#

someone already got half of it

rare token
main sigil
high cipher
#

the gorilla mafia

sudden trout
#

"How much days does frazzle get to be banned" can someone help me solve this

high cipher
#

0

wraith hinge
wraith hinge
#

it's my question, i think i'd know

main sigil
#

prove that there were as many of them

high cipher
rare token
wraith hinge
main sigil
wraith hinge
#

@wraith hinge can I ask you a question now?

#

what

#

?

wraith hinge
rare token
#

i knew we were getting a group question

wraith hinge
main sigil
#

5_subgroups

wraith hinge
#

am i correct???

wraith hinge
wraith hinge
rare token
#

I definitely don't miss abstract algebra. Done w/ the kernel and that bs

main sigil
wraith hinge
wraith hinge
main sigil
wraith hinge
#

you want me to give a small sum up

#

brain is not enough for solving AA

main sigil
rare token
main sigil
wraith hinge
#

According to Sylow theorems, the number of Sylow 5)subgroups, denoted as n 5, must satisfy two conditions: n 5 is congruent to 1 modulo 5. n 5 divides the group order divided by 5, meaning 240 / 5 - 24. from this, the only divisor of 24 that is also 1 mod 5 is 1. Therefore, there is exactly one sylow 5 subgroup in S 5

#

example btw

rare token
#

we didn't study Sylow in AA. And I'm glad

wraith hinge
wraith hinge
whole coral
#

1 + 1 = 3, example btw

wraith hinge
rare token
#

Does ChatGPT actually help you guys? Idk 'cause that wasn't around when I was in school.

trim joltBOT
wraith hinge
#

I enslave ChatGPT to write my latex documents tho

#

i just gave an example

main sigil
#

How many sylow 5-subgroups are in the dihedral group of order 11?

rare token
wraith hinge
#

or the GPT's

rare token
#

gpt

#

And it gave pretty much the same explanation that frazzle did but more organized

main sigil
wraith hinge
rare token
wraith hinge
main sigil
#

frazzle left us :(

#

.close

trim joltBOT
#
Channel closed

Closed by @main sigil

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

dim falcon
#

Imagine we have a convex pentagon named P and we put a dot in the middle of the each side , then we connect the dots , lets call the new pentagon P' , now imagine that we never had the P pentagon , please state a way to draw the P pentagon with only the P' being given

#

Pls let me know if you didn't understand the problem

zinc ginkgo
trim joltBOT
# trim jolt

The original post of this help channel has been deleted, and it will abruptly close and possibly lock. (This is irreversible.) Please claim a new channel, and don't delete the first message of any future channel you claim.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

drifting storm
#

Hi guys, i’m supposed to solve the equation for 0 greater than or equal to x greater than or equal to 180. Am i wrong?

drifting storm
#

The answer key shows 26.6 and 153.4, but the answer key might be wrong

true kestrel
#

,w arccos(0.6)

still rose
#

wtf

whole coral
#

I don't get this here, I get something different

true kestrel
#

its 53.13

#

deg

#

cos inverse (0.6) is 53.13 deg

true kestrel
drifting storm
drifting storm
drifting storm
drifting storm
drifting storm
true kestrel
#

XD

drifting storm
#

😁😁

#

thanks again guys, i’m going to close the channel!

#

.close

trim joltBOT
#
Channel closed

Closed by @drifting storm

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jaunty wigeon
#

For euler angles and different order modes (e.g. ZXY) are the rotations actually applied from left to right, i.e. is it
Rotate about the z axis, then rotate about the x axis and finally rotate about the y axis
or is it
Rotate about the y axis, then the x axis and finally the z axis?
I remember someone mentioning they are actually in reverse so it would be the latter, altho it was so long ago that it may have been about a different thing..

trim joltBOT
#

@jaunty wigeon Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mild scroll
trim joltBOT
mild scroll
#

so

#

at II

#

we need to find the arithmetic average and the geometric ones

#

idk im bad at english mb in advance

#

we'll work them out first

#

a = 2 / (sqrt 3 + sqrt 5 ) + sqrt 3 - 1

#

we could multiply the first one by sqrt 3 - sqrt 5 to get that formula

#

and it'd be (2sqrt3 - 2 sqrt 5) / (3-5) + sqrt 3 - 1

#

wait i wrote 3+5 in my class note

#

wtf

#

yea can anyone hel

#

p

#

(2sqrt3 - 2 sqrt 5) / (3-5) + sqrt 3 - 1 = (2sqrt3 - 2 sqrt 5) / -2 + sqrt 3 - 1

#

2sqrt3 / -2 + (2 sqrt 5) / -2 + sqrt 3 - 1

#

-sqrt3 + sqrt 5 + sqrt 3 - 1

#

sqrt 5 + 1

#

ez

#

for b we could do the same thing i believe

#

(6sqrt 2 + 3 sqrt 5 )/( 8-5 ) - sqrt 8+ 1

#

2sqrt 2 + sqrt 5 - sqrt 8+ 1

#

sqrt 8 + sqrt 5 - sqrt 8+ 1

#

sqrt 5 + 1

#

yea finished it

#

now 3

#

find b1 and q if ..

#

yea

#

idfk

#

tf

#

nvm

#

solve it

#

solvedi

#

yea ioll close this

#

.close

trim joltBOT
#
Channel closed

Closed by @mild scroll

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steep tiger
trim joltBOT
steep tiger
#

I’m not sure I understand what I have to prove here

#

Is this sufficient?

trim joltBOT
#

@steep tiger Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wraith hinge
trim joltBOT
wraith hinge
#

If you get 0.1730 then how is it a root if it’s not zero

prime lynx
wraith hinge
#

LEAVE ME ALONE DAVID 😭

#

Wait oops you don’t get that

#

But you still don’t get zero

prime lynx
#

It says correct to '1 decimal place'

wraith hinge
#

But 0.17300 to one dp is 0.2 no?

#

Isn’t that like not a root

prime lynx
wraith hinge
#

you find the root by decimals search or bisecting right

prime lynx
#

,w plot 3^x + x-8

wraith hinge
lusty delta
wraith hinge
#

Oh

#

And then if we get the root and when rounding to 1dp you get 1.7 you prove it?

lusty delta
#

yes

wraith hinge
#

Ok thanks gang ☺️☺️

prime lynx
wraith hinge
#

.close

trim joltBOT
#
Channel closed

Closed by @vapid dagger

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ocean remnant
#

Hello! I am looking for a function to increase resolution within my storage. I need small values to be stored with more accuracy, and larger values with less accuracy. Basically, I need a function that looks like this (and its inverse), with a more exaggerated/controllable curve (graphed here: f(x) = 2-2/(1+x)):

ocean remnant
#

in other terms, I need a continuous function where f(0) = 0 and (1) = 1, and f(0.2) roughly equal f(0.8)

#

it needs to be pretty fast in term of computing as well

limpid dawn
ocean remnant
#

how so?

#

I only care about [0,1]

trim joltBOT
#

@ocean remnant Has your question been resolved?

limpid dawn
#

I have one

#

,w plot y=x^(1/(7.21257)

#

Try this @ocean remnant

ocean remnant
#

ty!

trim joltBOT
#

@ocean remnant Has your question been resolved?

#
Channel closed

Closed by @ocean remnant

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

twilit viper
#

(1+2​)^2006=a+b√2​. calculate a^2-2b^2

lusty delta
#

should that say (1 + sqrt(2)) at the start

twilit viper
#

no

zinc ginkgo
trim joltBOT
# twilit viper no

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

twilit viper
#

a and b reel numbers :(1+2​)^2006=a+b√2​. calculate a^2-2b^2

umbral dragon
#

Just post a picture

twilit viper
#

can't 'm on pc no cam

lusty delta
thorn void
lusty delta
#

to do this, use difference of squares to force a^2 - 2 b^2 to factor

zinc ginkgo
twilit viper
#

ths is it ;(1+√2​)^2006=a+b√2​. calculate a^2-2b^2

thorn void
zinc ginkgo
twilit viper
#

ok

#

but i tried solving it but i can't wa have just started a lesson and

#

the teacher gave us this exercice

zinc ginkgo
twilit viper
#

no

zinc ginkgo
twilit viper
#

tried what he said but haven't got result

zinc ginkgo
#

Show what you tried

twilit viper
#

don't have a camera sorry

zinc ginkgo
#

Type it then

twilit viper
#

If we find the value of a^2-2b^2, then we have the value of a-b root 2, e5 so we can find the value of a and b which is impossible since they have an infinity of solutions

zinc ginkgo
twilit viper
#

but we can't t have nfnity solutons

zinc ginkgo
umbral dragon
twilit viper
#

yes

umbral dragon
#

Then it’s not infinite

twilit viper
zinc ginkgo
umbral dragon
#

@zinc ginkgo just asking for myself, would I have to find a and b to get the solution or is there a shortcut

twilit viper
#

wait

limpid dawn
twilit viper
zinc ginkgo
#

Compare the binomial expansion of (1+sqrt(2))^2006 with (1-sqrt(2))^2006 to find a-b*sqrt(2)

twilit viper
#

haven't done the lesson yet

trim joltBOT
#

@twilit viper Has your question been resolved?

trim joltBOT
#

@twilit viper Has your question been resolved?

trim joltBOT
#

@twilit viper Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lone mauve
trim joltBOT
lone mauve
#

can someone explain what is going on here?

#

i don't see it

#

how do we expand this from 3 to 4

#

() groupings or whatever we call them

#

it's like (~p V r) is being duplicated. how is that distribution tho?

tulip violet
#

It's like an equation, (x + y) * z then when you distribute that, you get (xz + yz)

#

Same idea

lone mauve
#

i read it as a or b or c

tulip violet
#

It says to distribute the third term over the first two

lone mauve
#

I get that we can use associative law to move third term first

#

if that helps

#

since each () is seperated by same V symbol
but I don't get how we can distribute it, for some reason i don't see it

lone mauve
# lone mauve

with these examples it's like "p V" is being distributed

#

oh

#

it still is, but it's bigger

#

dang that's tricky to see

lone mauve
# lone mauve

it's like we are replacing p with (~p V r) in this

trim joltBOT
#

@lone mauve Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wet apex
#

Hi

trim joltBOT
wet apex
#

How i do number 15

prisma stone
# wet apex

Find average of those 2 lengths first.

Max: tallest player
Min: shortest player
Avg: (Max + Min) / 2

And inequality is |Avg-x| <= (Max - Avg)

wet apex
#

Thank you

#

I’ll give it a try

wet apex
#

Oh wait

#

Like that right

#

What does the compound inequality and set notation mean

trim joltBOT
#

@wet apex Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

spring summit
trim joltBOT
spring summit
#

<@&286206848099549185>

dry copper
#

!show

trim joltBOT
#

Show your work, and if possible, explain where you are stuck.

spring summit
#

Not sure what to do with the root x in numerator

dry copper
#

according to the substitution, u = 1 + sqrt(x)

#

sqrt(x) = u - 1

spring summit
#

Yeah but du would be 1/2root x

dry copper
#

yeah, so what

#

dx = 2 sqrt(x) du

#

dx = 2 (u-1) du

spring summit
#

Oh

#

I see

dry copper
#

yeah you see 😛

#

always manipulate them

spring summit
#

Thank u so much

#

.close

trim joltBOT
#
Channel closed

Closed by @spring summit

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

echo jasper
trim joltBOT
echo jasper
#

sry

#

what happens to mg?

#

oh

#

i didnt plug in what was given im idiot

#

.close

trim joltBOT
#
Channel closed

Closed by @echo jasper

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wraith hinge
trim joltBOT
wraith hinge
#

${x\leq0}$

solid kilnBOT
#

icannotdoanymorecauchy

wraith hinge
#

note the domain

#

how

#

if it is less than zero

#

the inverse should be negative

#

so

#

${f^{-1}(x) = -\sqrt{x+4}}$

solid kilnBOT
#

icannotdoanymorecauchy

wraith hinge
#

tysm

#

one more problem

#

plss

#

bro

#

the $f(x)$ stops at ${x=0}$

solid kilnBOT
#

icannotdoanymorecauchy

wraith hinge
#

so doamin = $(-\infty, 0]$

solid kilnBOT
#

icannotdoanymorecauchy

trim joltBOT
#

@wraith hinge Has your question been resolved?

#
Channel closed

Closed by @olive breach

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

floral garnet
#

hello, i require help with this question. i do not have much experience with vectors 🙂

floral garnet
#

i've been asking this question on some different servers, but no one know how to do it 😦

wraith hinge
#

triangle

#

you're welcome

ionic pendant
#

you can show that with a diagram

floral garnet
#

waht

#

wait

#

how would i do that

#

also z1 and z2 are complex numbers

wraith hinge
floral garnet
#

represented in argand diagra

floral garnet
#

wait

#

hmm

#

yeah ive lost it

#

can you do that in vectors 😭

#

is rhere any way to do it using vector equations?

wraith hinge
#

wait no

#

there was that parallelogram thing

floral garnet
#

ye i thought it was a parallelogram

#

but like how do i prove it

wraith hinge
#

idk

floral garnet
#

like see this

#

ignore the bottom part

#

this the diagram i drew

ionic pendant
#

addition and subtraction of complex numbers is really the same thing as addition and subtraction of vectors, which is why we're equating complex numbers and vectors in the first place

floral garnet
#

yeah

#

but like how do i actually answer the question??

#

.close

trim joltBOT
#
Channel closed

Closed by @floral garnet

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

echo jasper
trim joltBOT
echo jasper
#

why not f+fn+mg=ma

#

is it because X isnt involved?

ionic pendant
#

what is f supposed to be?

prime crystal
#

what is that extra f for

echo jasper
#

uh

#

well the previous problem he did that i just dont understand why the f is gone this time

#

let me show

#

Like

#

he put that F there

ionic pendant
#

the F is supposed to be the force of the rope

echo jasper
#

wouldnt F being the student force

#

since he is on the scale

ionic pendant
#

the free body diagram only represents forces acting on an object, not forces exerted by an object

echo jasper
#

ph

#

oh

#

so f represnets an external force normally?

prime crystal
#

also shouldnt it be Fn - mg = ma

echo jasper
#

ya i thought that becuz mg going dwn

ionic pendant
#

F is a generic name for any force that doesnt have a specific name

echo jasper
#

oh

ionic pendant
prime crystal
#

oh yeah

#

didnt see that

#

mb

trim joltBOT
#

@echo jasper Has your question been resolved?

#
Channel closed

Closed by @echo jasper

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pearl lark
#

Does arranging all terms first so that the LHS has all ys and RHS has all the xs leads to a wrong answer in implicit differentiation?

vivid glade
#

in which case $g(y)=f(x)\implies g'(y)\frac{dy}{dx}=f'(x)$

solid kilnBOT
vivid glade
#

you'd have something like that

#

it's innocent enough

pearl lark
#

So rearranging it won't give wrong answer?

vivid glade
#

not without help

pearl lark
#

Cuz it seems like I got different answer when I rearranged x^2 + xy^2 + y^2 = 1 first before differentiating

vivid glade
#

you'd have to do the separation incorrectly to cause trouble

pearl lark
#

So ig I must have done separation incorrectly

#

Wait

marble wharf
#

the strength of implicit differentiation is not having to do any separation

pearl lark
#

Is there any errors in the separation process

vivid glade
#

it looks fine

#

there could always be a typo from the very beginning

pearl lark
#

Typo?

vivid glade
#

typo

#

if this is coming from some homework question, what if you miswrote the original question?

pearl lark
#

Not rlly

pearl lark
solid kilnBOT
pearl lark
#

And without arranging I got this

#

,rccw

solid kilnBOT
pearl lark
#

Comparing the results with values x = 2, y = 3

#

I got this

#

Why's that if rearranging it doesn't yield to a wrong answer

trim joltBOT
#

@pearl lark Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

zenith bane
#

Just a easy physic question

trim joltBOT
zenith bane
#

For question i the question key is 4.5/3

#

How does that work

#

And i just need to find the slope for question i right?

#

So that mean find two point from that line and the plug in the slope equation

zinc ginkgo
#

So that's the slope

zenith bane
#

I know

#

Because the line is like straight

#

So I got a little bit confuse

#

Because i use tangent method for the line that’s not straight

#

But how does 4.5/3 work

#

I am curious

zinc ginkgo
#

Find two points where the change in time is 3

#

And includes your point in the question

zenith bane
#

Ok

#

Like that right?

#

Thank you

#

.close

trim joltBOT
#
Channel closed

Closed by @zenith bane

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stoic burrow
trim joltBOT
wraith hinge
#

$\lim_{x\to0^{-}} 2^{\frac{1}{x}}$

#

This?

stoic burrow
#

Almost, - 0

solid kilnBOT
#

icannotdoanymorecauchy

limpid belfry
#

whats the 0-0?

wraith hinge
#

this?