#help-38
1 messages · Page 168 of 1
Right
So now, one more cut
it becomes 3S_z
Then do the same for the other directions (S_x, S_y)
And of course S = S_x + S_y + S_z
Yes
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help
What is the probability of a pigeon making a noise which deflects it's poo at an angle of 45 degrees to the back right while making sure the bird flies above me(Conditional probability sum)
I move at 90km/hr
North direction
Close the channel
Why
This is not a serious question.
youve jsut been spamming this nonsense quiestion so may times. what the heck does this mean
THIS ISN'T NONSENSE
IT'S THE SUM AT MY EXAM
Don't spam
PLUS IM NOT SPAMMING
Don't troll
I CREATED A CHANNEL AND ASKED A QUESTION
making a noise which deflects its poo
this is certified nonsense
i'm sorry are you 11?
NO THIS IS EXAM
Last chance to stop :^)
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if its so real u need to chill the hell out
You have too much free time
IM NOT HAVING THESE IDIOTS CALLING MY EXAM FAKE
BOO GO CRY WITH UR IMAGINARY FRIEND
Muting you for the week. Please review #rules before you come back.
Why are they bullying him
@paper willow it's definitely not
For a doubt
I saw the question paper
You should also stop.
Technically why should they bully him for asking a doubt
You know what
I'm asking it
Nobody is bullying anybody.
Okay, last chance to stop trolling in the help channels. :^)
They reacted with laughing emoji and said "you have too much free time"
I'M NOT TROLLING
IT'S AN ACTUAL QUESTION
WHY CAN'T YOU UNDERSTAND IT
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how does he get that?
moving ax to the other side and simplifying
fr
x(5-a)
= 0
yep
u dont get 1/5-a
yes
oh mb
laplace transform x’ = ax
and its s not 5
lmao
oh
doesnt change anything ig
if its w s or 5
i think its because of f(0)
magbe
.close
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I don't know how I should approach this question, It starts by talking about number of potatoes (10) and then it switches to talking about bout whole bag of potatoes (1 bag and 100 bags).
@celest umbra Has your question been resolved?
@celest umbra Has your question been resolved?
@celest umbra Has your question been resolved?
@celest umbra Has your question been resolved?
the formula you propose for sigma is in fact for sigma square the variance, but i don’t think it’s useful (you would need E(X^2)). To get the variance of the normal representing individual potato weights, i think you need https://en.wikipedia.org/wiki/68–95–99.7_rule.
soo the variance is then 10 i think. now what? are we considering the potatoes or bags as a sample set? because if we are talking about potatoes then we should use the T-table, and if we are talking about bags then we should use the z-table
<@&286206848099549185>
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so I first got $\delta. = 2 \varepsilon$
Veni, vidi, perii
so Then $|x-2|< 2 \varepsilon$
Veni, vidi, perii
So you want to show that |1/x - 1/2| < epsilon right?
Yea
So my first hint would be to combine the fraction
This fraction
$\frac{|x-2|}{2|x|}< \varepsilon$

Veni, vidi, perii
I would rewrite this as $\frac{|2 - x|}{2|x|}$ , but you do you.
Bishop
My issue isn't here
You have one way to simplify this immediately
I have found $\delta in terms of epsilon$
Veni, vidi, perii
Since |2 - x| < delta (if you have an epsilon that works then you can sub that in already but I’m not gonna worry about that yet)
Have you been through examples where you set delta < some number to be able to bound something that isn’t |x - 2|
For example having delta < 1
Why tho, $\frac{|x - 2|}{2|x|} < |x - 2| < e$
Bishop
That was purely an example
Because all terms are positive
Well tbh if delta < 1, |x - 2| < 1 then -1 < x - 2 < 1, so 1 < x < 3, so |x| > 1
(Also ignore why i wrote 2 - x , here idk)
Okay, my question is this
to put it better
how do I get $|1/x-1/2| < \varepsilon$ form $|x-2|< 2 \varepsilon$
Well you already have this, which is close
You now just need to bound |x| from below
Veni, vidi, perii
I did get something when I tried
I think you are misunderstanding something
Veni, vidi, perii
oops
Yeah so you have |x - 2| < delta, now you want to say |x| > …..
And the way I suggested is how you get that
delta = 2epsilon is not correct btw
$|x-2|< 2 \varepsilon \implies \frac{1}{x} > \frac{1}{2 -2 \varepsilon}$
Veni, vidi, perii
is it 3
no its just missing something
how did you bound 1/|x| in your scratchwork of finding delta?
$|\frac{1}{x} - \frac{1}{2}| = |\frac{2}{2x} - \frac{x}{2x}| = \frac{|2 - x|}{|2x|} < |x - 2| < \epsilon$ , which completes the proof by choosing $\delta = \epsilon$ , since as $|x - 2| < \delta = \epsilon$ , then $|\frac{1}{x} - \frac{1}{2}| < \epsilon$
Bishop
If you set $\delta < 1$ you have $|x - 2| < 1 \implies -1 < x - 1 < 1 \implies 1 < x < 3 \implies |x| > 1$
eugene_krabs_has_cake
$|x-2|< \delta$
\
$2 - \delta <x<2+ \delta$
\
$\frac{1}{2-\delta}>1/x$
Veni, vidi, perii
But this is a good way of thinking to keep in mind for different proofs yea
There’s no justification with that first inequality
this is where letting delta <= 1 helps, since that means 1/x<1 which is how the |x| can just 'dissappear' when upper bounding. So your delta=min(2epsilon,1) and you use that when doing the actual proof
|2 - x| = |x - 2|
Oh
It works if you let delta < 1 though
how?
if delta < 1 then 1/2>1/x from what you just found which means 1>1/x also
I’m sure Ann’s gone through examples where she gave you her solution where she made delta be less than some known number to be able to bound things
thats how in your scratchwork you go from |x-2|/2|x| < |x-2|/2 by letting delta<1
which in the actual proof means you need it to go the opposite way
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I got #3 like
(2²-5x+3)(x-3)
(2²-6x+1x+5)(x+1)
2x(x-3)+1(x+3)
(x-3)(x+3)(2x+1)(x-3)
(x+3)(2x+1)(x-3)²
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.reopen
✅
Is it
(2x²-5x+3)(x-3)
(2x²-3x-2x+3)(x-3)
(2x²-3x)(-2x+3)(x-3)
2x(x-1)-3(x-1)(x-3)
(x-1)(2x-3)(x-3)?
?
Wait
I noticed something
On the 3rd part
Its x(2x-3)(-2x+3)(x-3)
Cuz if i follow the -3(x-1) here
I'd get -3x+3
???
@stray lynx Has your question been resolved?
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How to determine corner / cusp
check if the derivatives are continuous
How do I find the derivative ?
the derivative of f(x) will equate to the derivative of all its expressions, bounds unchanged
if the function is continuous at the point and the derivative is not then its a corner/cusp
So it’s like if it continues in a straight line then derives from it ?
im not sure what you mean
Like I understand at -2 it doesn’t connect so it’s discontinuos , but what does that have to do with the derivative ?
it doesnt
im saying that if f is continuous at a point, but its derivatives are not, then its a corner
,w graph |x|
like here, at 0 f is continuous, but the derivative isnt
its a corner
from the left the f'=-1, from the right f'=1
Im still confused on what the derivative is , is there an algebraic value ?
do you know what derivatives are?
No not really
here you would only need the power rule if you want to do it algebraically
however, if you draw your graph reasonably accurately, you should be able to tell by looking at it
Im decent at that, how could I tell a corner / cusp from a graph?
the connecting point on the bounds would be jagged rather than smooth
So for example in this
Would it be where it goes down rapidly
Here is better image*
yeah thats nicer
So since it is disconnected at -2 it’s a discontinuity, since it’s smooth at 0 it’s a continuous, and since it goes sharply down and jagged at 1 it’s a corner ?
you got it
👍 thank you
@grim raft Has your question been resolved?
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how do i dooooooooooo this not sure if i need to go elsewhere tho since its kinda physics
Use equilibrium equations
the sum of the 3 masses multiplied by their respective distances from the barycenter must be 0
(the direction here is important)
Hun
Huh*
As the beam has to be in equilibrium use summation Fx=0, Fy=0
And summation of moment of all the force about any point on the beam =0
wdym
so 10+6
16x10
?
i dont get it
See
I did the question
And you don't need that much
You know moment of force?
About a point?
Aah
I haven’t touched high school stuff in a while
I’m cooked
Moment of force about a point
Is the perpendicular distance of the line of action of that force from that point
Like let me give you an example
Look at this
I hope I have written clear and crisp
@haughty heath
Are you getting what I have written?
But what’s that got to do with the question above?
See
Not really
I mean you have written clear I’m just not clear in the head
Oh
Right I got that
See I explained a concept there
Which is useful in this question
See if the beam is balanced
It will be in equilibrium
Oh never mind
Wait gotta go
Yeah gonna have to speak to me on a dummy level
Remember I haven’t touched this stuff in a while and those terms aren’t gonna mean anything to me
Think about explaining this to ur dad who hasn’t done math in uears
He won’t know what most of these terms mean I’d assume so anyway
He's gonna smack me if I say you don't know anything
💀☠️
And let me explain it
😭
Haha
Alright let’s do it
I would prefer what Emily told
This
Just keep it simple and explain how to do the problem
I don’t necessarily want to understand it
Just need to get to the answer so I can pass a test
So let’s go step by step
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
So 10x10
6x4?
Holy fuck I’m not a student ahaha
Right so that’s 124
Idk what I’ve got tho
What is it 124 N or Kg or m
Ohhh then I do 124 divide 8
Now for !
Yeahhh
Now for N
Wait
We multiply by 10
thanks for explaining that @mild oxide i was away
M is distance?
Actually Emily thanks
exactly my point, nice
To you too for explaining simply
Simple explanation is the way I like it
I told him bout moment of force but he has gotten rusty
Yeah don’t remember that
Don’t think I need to but if you can somehow explain it on dummy terms I’m all ears
Bro see
yeah, torque and lever arm and cross product, no one remembers lol
For you to understand moment of force
First I need you to explain force
And for this question specifically
I need to explain you weight,force, moment of force, and equilibrium equations
The what
What is equilibrium
English please
Not math language
Or chemistry
Whatever it is
Equilibrium is a state in which a body
Has net force 0 on it
In any direction
Along any dimension in which it exists
May it be 3 d 2d or 1d

💀☠️
Gang
YT required imo lol
INFACT I may never have done this
Relax
It doesent ring a bell
I don’t think I’ve done whatever u were talking about above
Ok so we begin with the next unit
I did maths and physics up until 15 then stopped
Chill bro see now
That’s where my knowledge with this shenanigans goes
Yes
,w 15.5x9.81
Nah
,w 15.5*10
Yes
Cus 15.5x10
Fr
Is 155
Yes
Thank u
Gracias
em?
Short for Emily
.close
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Can someone please show me a step by step solution to this? Do i need to use natural log to get the answer? I have simplfied it but idk what to do next.
!show
Show your work, and if possible, explain where you are stuck.
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
For the record, I would start by raising everything to the x power and then multiplying by (x+1) on both sides.
I am actually not learning this topic atm but my friend asked me if i know the answer I just wanna know how to approach it.
oh thanks
I will try that
But after this you have 2 = u^(u^2)
Where u = x+1
And this isn't straightforward to solve still
The problem is I saw the solution at a glance because I'm familiar with a particular proof.
But actually solving it when you're not familiar with said proof is less obvious
One method that will work is to rewrite the base of the right hand side.
So that the base is 2 instead of u
If you're familiar with log and exponents then you might have done something similar for base e.
But it's a little more rare with base 2
u^(u^2) becomes 2^(u^2 log2(u))
And you can rewrite it into a form where you can eventually use the Lambert W function
Which will give you all the solutions, not just the two real ones.
But I don't see a clean way of getting the two real solutions without just making an educated guess
is it the power rule?
For any base b > 0 and ≠ 1, if you have x (in the proper domain), then x = b^(logb(x))
thank you for helping me, You made this easy to understand but now I know I really need to get better at logs.
It's a much harder problem than you'd typically see at the high school level
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answer
question
if there are 3 gorillas wearing tuxedos, how many dogs are purple and how many cats are red?
Ragebait
Boy the spelling mistakes
Trick question. No cats are red
correct
but what about the dogs question
The answer is: 
you're gonna ban me for asking a question?
conjecture debunked
Clearly a fox
they do exist
mb mb
is there a question here?
uh huh
a very stupid one, but yes
if there are 3 gorillas wearing tuxedos, how many dogs are purple and how many cats are red?
where?
No. Just trolling
there IS an answer
yes, there is an answer
it's not even trolling it's a question
if there are 3 gorillas wearing tuxedos, how many dogs are purple and how many cats are red?
we just dont know the answer
0 0
0w0
someone already got half of it
0, all the cats and dogs are dead because the gorillas killed them.
the other half is 0
the gorilla mafia
"How much days does frazzle get to be banned" can someone help me solve this
0
almost, there were 17 dogs and 32 cats, which would beat the gorillas.
0 and 0
I doubt they would
what if there weren't?
prove that there were as many of them
then the gorillas wouldn't wear tuxedos duh
no, ur asking the question 'cause u don't know the answer
so you got your answer?
if you know, why are u asking?
How many Sylow-5 subgroups are in S_5
i knew we were getting a group question
6 sylow 5_subgroups
5_subgroups
am i correct???
how would you know that
wdym
I definitely don't miss abstract algebra. Done w/ the kernel and that bs
like how do you derive that
so because i actually have a brain you think i cheat?
do d/dx maybe
yes, i do
||gonna be chatgpt.com now||
thats not what he meant by derive lol
yeah, ik lol
According to Sylow theorems, the number of Sylow 5)subgroups, denoted as n 5, must satisfy two conditions: n 5 is congruent to 1 modulo 5. n 5 divides the group order divided by 5, meaning 240 / 5 - 24. from this, the only divisor of 24 that is also 1 mod 5 is 1. Therefore, there is exactly one sylow 5 subgroup in S 5
example btw
we didn't study Sylow in AA. And I'm glad
"Therefore, there is exactly one sylow 5 subgroup in S 5"
uh what?
if you had read what i said under, it said "example btw"
Not a cheat, huh?
1 + 1 = 3, example btw
example what, that's my question answer, what you wrote is my question's answer not an example
Does ChatGPT actually help you guys? Idk 'cause that wasn't around when I was in school.
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
is it your question's answer?
I enslave ChatGPT to write my latex documents tho
i just gave an example
okay, do this now:
How many sylow 5-subgroups are in the dihedral group of order 11?
But it did get the correct answer for your question.
my example?
or the GPT's
@glad fog can you do this?
do you not know my question nor its answer?
r u taking real soon?
real analysis?
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Imagine we have a convex pentagon named P and we put a dot in the middle of the each side , then we connect the dots , lets call the new pentagon P' , now imagine that we never had the P pentagon , please state a way to draw the P pentagon with only the P' being given
Pls let me know if you didn't understand the problem
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Hi guys, i’m supposed to solve the equation for 0 greater than or equal to x greater than or equal to 180. Am i wrong?
The answer key shows 26.6 and 153.4, but the answer key might be wrong
,w arccos(0.6)
wtf
I don't get this here, I get something different
as u can see here
ohhhh u’re rightt
yess i miscalculated 🤦🏻♀️
thank you so much 😭🙏🏻
thankyouuu
i haven’t learned this but thats cool 😭😭
XD
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For euler angles and different order modes (e.g. ZXY) are the rotations actually applied from left to right, i.e. is it
Rotate about the z axis, then rotate about the x axis and finally rotate about the y axis
or is it
Rotate about the y axis, then the x axis and finally the z axis?
I remember someone mentioning they are actually in reverse so it would be the latter, altho it was so long ago that it may have been about a different thing..
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so
at II
we need to find the arithmetic average and the geometric ones
idk im bad at english mb in advance
we'll work them out first
a = 2 / (sqrt 3 + sqrt 5 ) + sqrt 3 - 1
we could multiply the first one by sqrt 3 - sqrt 5 to get that formula
and it'd be (2sqrt3 - 2 sqrt 5) / (3-5) + sqrt 3 - 1
wait i wrote 3+5 in my class note
wtf
yea can anyone hel
p
(2sqrt3 - 2 sqrt 5) / (3-5) + sqrt 3 - 1 = (2sqrt3 - 2 sqrt 5) / -2 + sqrt 3 - 1
2sqrt3 / -2 + (2 sqrt 5) / -2 + sqrt 3 - 1
-sqrt3 + sqrt 5 + sqrt 3 - 1
sqrt 5 + 1
ez
for b we could do the same thing i believe
(6sqrt 2 + 3 sqrt 5 )/( 8-5 ) - sqrt 8+ 1
2sqrt 2 + sqrt 5 - sqrt 8+ 1
sqrt 8 + sqrt 5 - sqrt 8+ 1
sqrt 5 + 1
yea finished it
now 3
find b1 and q if ..
yea
idfk
tf
nvm
solve it
solvedi
yea ioll close this
.close
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If you get 0.1730 then how is it a root if it’s not zero

It says correct to '1 decimal place'
Find the root and approximate to 1 decimal place to prove it
you find the root by decimals search or bisecting right
,w plot 3^x + x-8
Idk if I can use this in my exam tho
yes you plug in numbers into 3^x + x - 8 as you get closer to 0
yes
Yes
Ok thanks gang ☺️☺️

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Hello! I am looking for a function to increase resolution within my storage. I need small values to be stored with more accuracy, and larger values with less accuracy. Basically, I need a function that looks like this (and its inverse), with a more exaggerated/controllable curve (graphed here: f(x) = 2-2/(1+x)):
in other terms, I need a continuous function where f(0) = 0 and (1) = 1, and f(0.2) roughly equal f(0.8)
it needs to be pretty fast in term of computing as well
Do you want exponential growth?
@ocean remnant Has your question been resolved?
ty!
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(1+2)^2006=a+b√2. calculate a^2-2b^2
should that say (1 + sqrt(2)) at the start
no
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
a and b reel numbers :(1+2)^2006=a+b√2. calculate a^2-2b^2
Just post a picture
can't 'm on pc no cam
ok so that is definitely not what the problem is asking for so here is revised problem
(1 + sqrt(2))^2006 = a + b sqrt(2) where a and b are integers
compute a^2 - 2 b^2
Well the left is rational and the right isn’t
to do this, use difference of squares to force a^2 - 2 b^2 to factor
yes
You just proved b=0
ths is it ;(1+√2)^2006=a+b√2. calculate a^2-2b^2
Oh yeah true, but that surely isn’t the problem, otherwise it’s trivial
ik that is it
read here
Next time read more carefully what helpers are telling you
.
ok
but i tried solving it but i can't wa have just started a lesson and
the teacher gave us this exercice
People are helping you and you're just ignoring
no
.
tried what he said but haven't got result
Show what you tried
don't have a camera sorry
Type it then
If we find the value of a^2-2b^2, then we have the value of a-b root 2, e5 so we can find the value of a and b which is impossible since they have an infinity of solutions
So you didn't factor a^2 - 2 * b^2 yet
but we can't t have nfnity solutons
As another hint to this,
(m-n)(m+n) = m^2 - n^2
Not if a and b are integers
yes
Then it’s not infinite
tried it wn't help
Show how you factored
Because that ain't it
@zinc ginkgo just asking for myself, would I have to find a and b to get the solution or is there a shortcut
wait
i think you would have to pay him money for an answer
(a+b√2)(a-b√2)
Compare the binomial expansion of (1+sqrt(2))^2006 with (1-sqrt(2))^2006 to find a-b*sqrt(2)
haven't done the lesson yet
@twilit viper Has your question been resolved?
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can someone explain what is going on here?
i don't see it
how do we expand this from 3 to 4
() groupings or whatever we call them
it's like (~p V r) is being duplicated. how is that distribution tho?
It's like an equation, (x + y) * z then when you distribute that, you get (xz + yz)
Same idea
except i dont see the brackets
i read it as a or b or c
It says to distribute the third term over the first two
I get that we can use associative law to move third term first
if that helps
since each () is seperated by same V symbol
but I don't get how we can distribute it, for some reason i don't see it
with these examples it's like "p V" is being distributed
oh
it still is, but it's bigger
dang that's tricky to see
it's like we are replacing p with (~p V r) in this
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Hi
Find average of those 2 lengths first.
Max: tallest player
Min: shortest player
Avg: (Max + Min) / 2
And inequality is |Avg-x| <= (Max - Avg)
I don’t get the last part
Oh wait
Like that right
What does the compound inequality and set notation mean
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<@&286206848099549185>
!show
Show your work, and if possible, explain where you are stuck.
Not sure what to do with the root x in numerator
Yeah but du would be 1/2root x
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${x\leq0}$
icannotdoanymorecauchy
note the domain
how
if it is less than zero
the inverse should be negative
so
${f^{-1}(x) = -\sqrt{x+4}}$
icannotdoanymorecauchy
icannotdoanymorecauchy
so doamin = $(-\infty, 0]$
icannotdoanymorecauchy
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hello, i require help with this question. i do not have much experience with vectors 🙂
i've been asking this question on some different servers, but no one know how to do it 😦
you can show that with a diagram
represented in argand diagra
im not familliar with this
wait
hmm
yeah ive lost it
can you do that in vectors 😭
is rhere any way to do it using vector equations?
idk
addition and subtraction of complex numbers is really the same thing as addition and subtraction of vectors, which is why we're equating complex numbers and vectors in the first place
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what is f supposed to be?
what is that extra f for
uh
well the previous problem he did that i just dont understand why the f is gone this time
let me show
Like
he put that F there
the F is supposed to be the force of the rope
the free body diagram only represents forces acting on an object, not forces exerted by an object
also shouldnt it be Fn - mg = ma
ya i thought that becuz mg going dwn
F is a generic name for any force that doesnt have a specific name
oh
it's a vector equation
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Does arranging all terms first so that the LHS has all ys and RHS has all the xs leads to a wrong answer in implicit differentiation?
not by itself
in which case $g(y)=f(x)\implies g'(y)\frac{dy}{dx}=f'(x)$
Flip
So rearranging it won't give wrong answer?
not without help
Cuz it seems like I got different answer when I rearranged x^2 + xy^2 + y^2 = 1 first before differentiating
you'd have to do the separation incorrectly to cause trouble
the strength of implicit differentiation is not having to do any separation
This is basically what I did
Is there any errors in the separation process
Typo?
typo
if this is coming from some homework question, what if you miswrote the original question?
Not rlly
From the arranged terms, this is what I got
Comparing the results with values x = 2, y = 3
I got this
Why's that if rearranging it doesn't yield to a wrong answer
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are you here?
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Just a easy physic question
For question i the question key is 4.5/3
How does that work
And i just need to find the slope for question i right?
So that mean find two point from that line and the plug in the slope equation
Speed is the change in distance / change in time
So that's the slope
I know
Because the line is like straight
So I got a little bit confuse
Because i use tangent method for the line that’s not straight
But how does 4.5/3 work
I am curious
It's just this
Find two points where the change in time is 3
And includes your point in the question
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How
Almost, - 0
icannotdoanymorecauchy
whats the 0-0?
this?

