help-38

[strange kelp]

need help with this problem

[still rose]

open a new channel

[strange kelp]

alright

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[somber ginkgo]

is this current homework?

[violet elbow]

yes!

there are a few provlems im havign issues with

[somber ginkgo]

sorry i meant does this contribute towards ur grade?

[violet elbow]

no, it’s for learnings sake

[somber ginkgo]

kk cool cool

[violet elbow]

extra work we can do to understand the stuffs

why do you ask?

[somber ginkgo]

i saw submit and was worried this was an online test

but then i realised it's hw so i think it's fine

[violet elbow]

HAHA no this isn't a test 😭

we do all our tests on paper

[somber ginkgo]

this server doesn't allow ppl to cheat on tests that's why

[violet elbow]

fuck yeah!

love a morally sound community 🗣️

[somber ginkgo]

how did u get those numbers?

[violet elbow]

by swapping x and y

ooho sorry

wrong problem

all of them are correct except answer G

i attained the others by using the information given

i can ping helpers if no one responds in 15 right?

yea

okii

<@&286206848099549185>

im confused! :)

[limber notch]

Hello

[violet elbow]

HELLOO

[limber notch]

I’ll try to help

[violet elbow]

awesome sauce

[limber notch]

So what do u understand by inverse of a function

[violet elbow]

uhh

[limber notch]

Are u there?

[violet elbow]

i mean all i tried to do was input y as x

with this problem i do not know where to begin!

since my answer that i inputted was incorrect

[limber notch]

Ok so have u seen this kind of diagram before

[violet elbow]

yes! i have

[limber notch]

Ok cool

So a function basically is a list telling u where each arrow will end up from the oval on the left to the oval on the right

Lemme know if u get that

[violet elbow]

i understand

[limber notch]

Cool

So what an inverse basically is when u have to make arrows from the right to the left. And since it is inverse all u have to do is take the same list for g(x) that is given in the question and flip it

[violet elbow]

may i have an example in comparison to the given graph?

like for the first column

is it read

g(2)=-6

or g(-6)=2

[limber notch]

According to ur question g(-6)=2

See just replace x in the g(x) row with the x right above it

[violet elbow]

so g(6)=-4

g(-2)=-2

and so on

oooh other way around

[limber notch]

The way to read it will be (for 1st column)
The first row says:
x=-6

The second row says:
when x=-6 then
g(x)=2,
which can be written as g(-6)=2
(Just substitute x=-6)

[limber notch]

Can u do this for each column

Like write g(x)=?

Just lemme know if u r here

[violet elbow]

g(-6)=2, g(-4)=6, g(-2)=-2, g(0)=-4, g(2)=4,g(4)=0, and g(6)=-6?

did i input those all right?

[limber notch]

Yes my friend

[violet elbow]

WOOOOOOOOOO

and for inverses then

what would g^1(-6)=2 be?

[limber notch]

So for example
g(-6)=2
Then
To get g inverse just flip -6 and 2

The arrow is now pointing in the opposite direction

[violet elbow]

i see

so it would usjt be -6

although, i am mainly confused becuase the system states i am incorrect

what am i doign wrong with my inputs?

[limber notch]

Trust me
Write down all the “inverse g” first

[violet elbow]

g^1(2)=-6, g^1(6)=-4, g^1(-2)=-2, g^1(-4)=0, g^1(4)=2, g^1(0)=4, and g^1(-6)=6

now wyhat

[limber notch]

Now what is “inverse g” of -6

Put that in

[violet elbow]

6?

[limber notch]

Cool put that under -6
Because see now u r filling “inverse g”

Fill it all and let me know

I think it will be solved

But wait I have to tell u where u made the mistake(I believe)

[violet elbow]

6, 0, -2, 4, -6, 2, -4

was correct

where was my mistake?

[limber notch]

I believe u were calculating each column from x and directly filling those values

[violet elbow]

i was

[limber notch]

Look at the question without the answer after a while
U will be able to understand why u had to write down all “inverse g” first

And u did a good job

U were the first person I helped

[violet elbow]

i was not taking into account what functions were and how to actually solve for inverse

[limber notch]

😁

[violet elbow]

you did a great jojb teaching step by step and finding out what level of mathematics i was standing at :D

[limber notch]

Good luck my friend
Try not to hate math when it’s difficult and always give urself time

[violet elbow]

haha i dont hate math

never will

math gives us everything we have

[limber notch]

Ciao

[violet elbow]

ciao bro

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[regal wing]

How do you get help?

[rapid mulch]

u ask a q here

[wraith hinge]

here

[rapid mulch]

and then someone helps u

[regal wing]

Alright

[prime lynx]

[wraith hinge]

so basically how does this thing work again?

Oh

oh it's 12

damn

Oh yeah

tomorrow's my exam

same

I got english

which class
k

11th

[high heron]

!redir

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[wraith hinge]

technically today i have my exam

[regal wing]

I need help with this, I technically answered but I’m not sure if it’s right

1. Determine the effect size in the following research example and state whether it is a small, medium, or large effect size:

Population 1: Mean = 307, SD = 22

Population 2: Mean = 300, SD = 22

2. Conduct the appropriate type of t-test (one-sample or paired samples) for the following example: Florida Atlantic University feels that their medical school is significantly better than other programs throughout the country. The 20 medical students who graduated from FAU in 2019 were given a performance exam before their residency programs began. The average score in the class was a 95 percent with a sum of squares of 1500. The nationwide average on this exam is a 92 percent.

2A. What is the estimated standard deviation based on the sample?

2B. What is the t-statistic and cutoff score (.05 test, 2-tailed) in the t-distribution

2C. Is there evidence to support the hypothesis that FAU's program better prepares its students than other programs (is the test significant) ?

3. As a further measure for the effectiveness of the medical program, FAU decides to administer the same exam to five students in their first year, and then again when they graduate the program: Use the scores below to conduct a t-test and determine whether the scores significantly change over time.

First Year Graduation

85 88

88 93

82 86

92 95

91 96

3B. State the t-statistic and cutoff score (.05-test, 2-tailed) in the t-distribution

3C. Was the test significant

I know it’s a lot 😅

[wraith hinge]

damn lemme read that all

yeah it is

chatgpt didn't work?

[regal wing]

Sorry for that 😅

[wraith hinge]

tbh try convincing a teacher

[wraith hinge]

lol np

[regal wing]

Thank you and this is stats btw

[wraith hinge]

yeah which class?

i mean meh stats isn't even that 'worth' of studying tbh

in 11th we have stats but our school is pretty chill with it

they don't teach it

[regal wing]

It’s called psych and experimental design statistics

[regal wing]

I know but it’s a requirement for me smh

[wraith hinge]

damn that's a long complex name

alr im not chit chatting, srry for trouble

[regal wing]

I know I just call it psych stats😅

[regal wing]

It’s no

Problem

[wraith hinge]

yup! byeee

Guys her problem hasn't been solved, so yeah don't judge by the messages

[regal wing]

Umm

?????

[regal wing]

<@&286206848099549185>

[prime lynx]

This looks like an exam

[regal wing]

It’s not😅😭

Can I show my answers to see if it’s right

<@&286206848099549185>

You can help with just number one if it’s too much

[regal wing]

<@&286206848099549185>

<@&268886789983436800>

[knotty oriole]

Don't ping mods for help with math stuff

Oh wait

[regal wing]

Sorry , no one was here yet so I was wondering

[knotty oriole]

You can ping mods if somebody is breaking the rules, trolling or stuff like that but general math help is not really the purpose of the mod role.

[regal wing]

Oh okay

[knotty oriole]

Idk what your exact question is but it helps to ask really clear, answerable questions if you want help with stuff.

Just saw it

[regal wing]

Sorry if it’s a lot

[knotty oriole]

Did you post your work? All I see is the question?

[regal wing]

No not yet

I’ll post it now

1. Difference between means: 307 - 300 = 7.
   Standard deviation (SD) for both is 22.
   Effect size (Cohen's d): 7 / 22 ≈ 0.318.
   Interpretation: 0.318 is closer to 0.2, so it's a small effect size.
   So the effect size is about 0.318 which is small.

2A. Standard deviation ≈ 8.88
Variance: 1500 / 19 = 78.95
Standard deviation: sqrt(78.95) ≈ 8.88
2B. T-statistic ≈ 1.51, Cutoff score ≈ ±2.093
T-Statistic and Cutoff Score
t = (95 - 92) / (8.88 / sqrt(20)) ≈ 1.51
Critical t-value (0.05 significance, 2-tailed, 19 df) ≈ ±2.093
2C. 1.51 < 2.093, the test isn’t significant.

[regal wing]

Hey?

<@&286206848099549185>

3B.

• T-statistic: 8.944
• Cutoff score: ±2.776

3C.
Yes, the test was significant.

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[regal wing]

<@&286206848099549185>

!done

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[knotty saffron]

was solving a system of equations but when i inputed it on an online calculator it got a different answer

[median torrent]

You added 5 to both sides but wrote it as minus 5

[knotty saffron]

i changed that already

[median torrent]

Oh nvm

I see

[knotty saffron]

that’s why i got -x+3

[median torrent]

Yea i see

Without going through myself I don't see an obvious problem with your algebra

You may want to try plugging in your answers to the original equations to check

[median torrent]

Did you try simplifying the root?

[knotty saffron]

looking at what i did, 6/10 is already 3/5 making mine incorrect

[median torrent]

Ahh yea good point

[knotty saffron]

idk where i went wrong xd

[median torrent]

I would start over maybe xD

Unfortunately

Here's a trick to make it shorter

After expanding the second equation

Add the x^2 + y^2

And call it 16

Instead of doing operations between the equations

Maybe less chance to pick up a mistake that way

[knotty saffron]

so it would be 16 - 2x - 4y + 4 + 1 = 16?

[median torrent]

Basically

Maybe the error was there

In the way you combined equations

Try it again that way and see what you get

[knotty saffron]

alrightt

got the same y value

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[knotty saffron]

<@&286206848099549185>

[knotty saffron]

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@vocal night Has your question been resolved?

[vocal night]

<@&286206848099549185> anyone has an idea ?

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[zinc ginkgo]

Insert an e^log

[lethal vigil]

how

[zinc ginkgo]

a^b = e^{b * log(a)}

[lethal vigil]

?

which law is this

[zinc ginkgo]

Have you not learned log properties before

[lethal vigil]

ik but i forgot

[zinc ginkgo]

,tex .log rules

[solid kiln]

riemann

[lethal vigil]

which rule is this one

?

[lethal vigil]

which rule are u using

[prime crystal]

$a^b = e^{b\cdot lna} = a^{b\cdot lne} = a^b$

[solid kiln]

Astar777

[zinc ginkgo]

Try using them to figure it out

[lethal vigil]

ok

[lethal vigil]

now what

where to insert log

[zinc ginkgo]

Identify your a and b

[lethal vigil]

b is 1/x and rest is a

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@lethal vigil Has your question been resolved?

[lethal vigil]

<@&286206848099549185>

[zinc ginkgo]

This is right

[lethal vigil]

What after that

[zinc ginkgo]

Use continuity of exp

[lethal vigil]

series expansion?

[zinc ginkgo]

Thats

Not related at all

[lethal vigil]

idk continuity of exponents

[zinc ginkgo]

lim e^stuff = e^lim(stuff)

[lethal vigil]

oh

lim x tends to 0 e^ 6 = e lim x tends to 0 6?

like that

@zinc ginkgo ur method is lengthy

and complicated

[lusty delta]

if ur looking for an algebraic solution to this problem it is fine

[zinc ginkgo]

Tell me your shorter method

[lethal vigil]

can we not use 1^infinity method

[lethal vigil]

using 1^infinity

[lusty delta]

can you describe it

[lethal vigil]

ok

f(x)-1 x g(x)

[lusty delta]

(but if u just want a fast solution to this problem then do something silly like finding a simple function that satifies the problem constraints (like f(x) = C))

[lethal vigil]

raised to e

[lethal vigil]

like multiplying by the power and subtracting 1 from the base

isnt that the traditional method

and whole base is e

[zinc ginkgo]

Sure try that

[lethal vigil]

but i don't understand how to use it here

[zinc ginkgo]

This is better than my suggestion as well

[lethal vigil]

what does f'(3) mean btw

First derivative of what

[zinc ginkgo]

The function f(x)

[lethal vigil]

wheres the function

[zinc ginkgo]

Could be f(x)= constant like Mq said above

[lethal vigil]

oh

[lethal vigil]

so answer should be 1?

[lusty delta]

ans is 1 yes

[lethal vigil]

wow

[lusty delta]

i do not think it is particularly 'traditional', what riemann described earlier is also fairly normal way of doing problems like these

(i.e.)

[lethal vigil]

it is taught to use whenever you see 1^infinity apply that formula

[lethal vigil]

thnx for this

anways thanks @zinc ginkgo and @lusty delta have a good day

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[lusty delta]

u2

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[sharp mantle]

I get that by the sequential characterisation of closure, since the accumulation points ±1 aren't in A, it cannot be closed

But how do they know that A is not open?

[river willow]

how do u define open

[sharp mantle]

A set is open if every point in it is an interior point

contrapositively, if there exists a point in A that is not an interior point, then A cannot be open

[river willow]

how would u define an interior in the set

[sharp mantle]

not a boundary point

[river willow]

interior point

[river willow]

thats not how its defined i believe

[sharp mantle]

there's also the formal def which I don't see how that would help

[river willow]

its a limit point

[sharp mantle]

$x\in A$ is interior iff $\exists r>0 $ s.t. $B(x,r)\subseteq A$

[solid kiln]

Kakaka

[river willow]

the limit of a sequence of points in the set is a limit point

nvm interior point is another definition which should be equivalent let me learn it :(

point x in a set X is an interior point has an open ball we can find an open ball centred at x comtained in X

[sharp mantle]

yup

which is the formal def I have written above

but I don't see how that helps here

[river willow]

how is close defined? complement is open?

anyhow, for any point in the set we can find a point outside of the set arbitrarily close to it so its not open

we have a sequence approaching 1 or -1

lets just look at the sequence approaching 1, which would include all even terms

for simplicity lets just translate the sequence so its 1/2,1/4,1/6,..., 1/2n,...

and lets scale the sequence so we get

1,1/2,1/3,... 1/n,...

the distance between 1/n and the closest other point in the set would be from 1/(n+1)-1/n=1/[n(n+1)]

for any point in the set we choose, we can pick an epsilon ball of radius 1/[n(n+1)] which would contain no points in the set thus the set is closed as it has no interior points

wait nvm mb

just look at the point one thats enough

[river willow]

we use this argument instead for showing that in the complement, there exist a point which is not an interior point

aka the set is not closed

@sharp mantle

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[wraith geyser]

more combinatorics

[wraith geyser]

for this question asking for probability of exactly 2 pair of dice in 6 rolling dices

the probability i calculated is not correct and looks too high, is there a mistake i made

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[acoustic trout]

would something like "666612" be considered two pairs?

in that case, counting ways of making two pairs is not just this

[shrewd ridge]

@wraith geyseryou need to dvide by 4

[wraith geyser]

divide by 4?

[shrewd ridge]

2233xx is the same 3322xx

so you overcounted that part

the last two is the same thing

[wraith geyser]

o right ye

[shrewd ridge]

i would choose 4 numbers, then choose 2 that are singles

6c4 × 4c2

[wraith geyser]

i didnt consider this combination

ye i missed the combination

of 4 being exactly the same

[shrewd ridge]

wait i'm confused

yeah i would have to multiply by 720/4 too

i don't think 4 same is supposed to be counted

i think your solution is exactly right

maybe you just need to divide by 2

you overcount something like x3232x

like maybe you go

_3_3__
_3232_
432321
```or maybe you go

_2_2
3232
432321

but the remaining 2 don't do that

[wraith geyser]

ye

[shrewd ridge]

yeah 0.34722

[wraith geyser]

i think thats it

bcz

when u have smth like 333221

does it still count

as exactly 2 pair

[shrewd ridge]

no, i think it doesn't

[wraith geyser]

i looked at the sol here and it seems like

the first 2 multiplication is fine

but the last 1 "we need to choose 2 numbers out of 6"

kinda screwed me over

bcz the 6C2 he did is just my 6 x 5 / 2 i did

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[ancient field]

I solved it and got. Y not equal to 3/2. Am I right

[meager bloom]

2x-5 ≠0

X not equal to 5/2

[ancient field]

Wouldn’t it be domain, i want its range

[meager bloom]

Ohhhh mb

[wet dragon]

a shortcut you can do for these kinds of problems is to look at the coefficients of x

nice edit.

and divide the coefficients

3/2

this function cant equal 3/2

or if you want to be more rigorous

set it equal to y

and solve for x in terms of y

[meager bloom]

It will almost reach 3/2 but not actually reach it

[ancient field]

Thanks. Means I was correct.

[wet dragon]

yes

[ancient field]

Got it.

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[wraith hinge]

how can i get help pls

[wind cloak]

!help

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[ancient field]

.close

[exotic pine]

it will close automatically, give it some time

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[cerulean trail]

forgot all my trigo skills and graphing, so uh-

Let 𝐴 = (1, 2), and let a line passing through (5, −2) intersect the curve 𝑦^2 = 4𝑥 at
points 𝐵, 𝐶. Triangle ABC is
(A) Scalene (B) Right-angled (C) Isosceles
(D) Equilateral (E) Cannot be determined

[cerulean trail]

I tried making a line equation of y = m(x-5) - 2

no idea what to do with it rn, I forgot everything

[wet dragon]

why would that be the line equaton

equation

just write y = mx + b

solve for m and b

[cerulean trail]

I forfor

[wet dragon]

-2 = 5m + b

try this

what i mean is

keep this fact

at the back of your mind

[wet dragon]

now because it intersects y^2 = 4x

at two points

try setting y^2 = (mx + b)^2 equal to y^2 = 4x

im squaring y btw cuz y^2 = 4x here y is squared

[cerulean trail]

gonna try rn, thx

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[hollow sage]

Hey guys! I have worked through this problem a few times now and I keep coming to the same conclusion. Could someone help me figure out what I'm doing wrong?

[hollow sage]

Here is the question I was given;

I'm just not sure what I'm missing here :/

[hybrid vine]

Isn't it 6x?

[hollow sage]

So, I tried 6x first and it still said I was wrong

I figured since it wants the derivative and that would just be the slope of the function 6x, the derivative would be 6?

[hybrid vine]

It should be 6x + 1

[hollow sage]

Okay I can definitely give that a shot, but where did you get the +1? I just want to understand so I know what I can do better next time

Wooo, it said that was correct!

[hybrid vine]

Check the last green step again

[hollow sage]

the (6xh+3h^2+h)/h?

[hollow sage]

Wouldn't factoring an h out just remove it? Or does it replace it with 1?

[hybrid vine]

h/h = 1

[hollow sage]

OHHHH

Oh okay I see now!

Thank you so much for your help 🙂 I appreciate it a lot!

[hybrid vine]

No problem

[hollow sage]

.close

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[gentle wagon]

Whats an easy way to isolate a unit for example

[gentle wagon]

Whats would be the formula for n

i know the answer but i dont really understand how its done

[hybrid vine]

You multiply (1-n) with Yk and then you take n common and take everything else to the other side

[gentle wagon]

So for example i got Yk = 26,5 kN/m3, Yw = 10kN/m3, g = 10m/s2, Y = 17,8 kN and S = 0,68

1-n * 26,5?

i dont get it

[trim jolt]

@gentle wagon Has your question been resolved?

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@gentle wagon Has your question been resolved?

[zinc ginkgo]

What unit are you isolating

[gentle wagon]

n

[gentle wagon]

n

[gentle wagon]

<@&286206848099549185>

[dusty sleet]

$$\gamma = \gamma_k - \gamma_k \cdot n + S\cdot \gamma_w \cdot n$$

[solid kiln]

Alberto Z.

[dusty sleet]

Do you agree so far? @gentle wagon

[faint schooner]

\begin{align}
\gamma - \gamma_k = n(-\gamma_k+S \cdot \gamma_\omega)\\
\frac{\gamma - \gamma_k}{-\gamma_k+S \cdot \gamma_\omega} = n
\end{align}

[solid kiln]

mari

[trim jolt]

@gentle wagon Has your question been resolved?

[gentle wagon]

Why is y=yk -yk

[dusty sleet]

It's not 🤔

[gentle wagon]

And the entire formula behind it

[zinc ginkgo]

There's a dot on the second y_k

That's multiplication so you should use PEMDAS

[dusty sleet]

Like, do you know how to isolate N in the equation N= 18 - 5•N ?

@gentle wagon

[gentle wagon]

Got it

[gentle wagon]

N = 13?

[zinc ginkgo]

Plug it in and check

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[river willow]

a group of order p^n has non trivial center

[river willow]

i dont quite under this trivial center thing. could someone help me understand.. so lets take a group of order 2

Z2

it has a non trivial center by this statement?

wait nvm im dumb

of course it does

for all abelian groups the center is the entire group

.close

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[proper plover]

apparently i hvae to do to this
we did learn it with like proportions like 1 2 and root 3 thing idk

[main drift]

use the fact thats its isosclees

[wraith hinge]

como entendo isso em ingles?

[trim jolt]

@proper plover Has your question been resolved?

[proper plover]

?

[proper plover]

<@&286206848099549185>

[dusty sleet]

What does not convince you?

[analog summit]

You can use 45-45-90 formula. With this formula a^2 =b^3 and a^2 √2=√6. After that you can set up the equations and solve the question.

[proper plover]

sorry what?

[proper plover]

how is a^2=b^3 possible

[analog summit]

Because the angles of a and b are the same

like this

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[graceful zenith]

Need help with a and b

[trim jolt]

@graceful zenith Has your question been resolved?

[graceful zenith]

<@&286206848099549185>

[proper plover]

i was looking for the lenth of the side

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[echo jasper]

why are we using 100cm^3

?

shouldnt that be 1cm^3 there

or is the goal trying to get to 1 meter only

i dont get this part

[twilit meteor]

wait, do u mean in the 3rd denominator?

[echo jasper]

ya

i get confused sometimes

like why are we notusing 1cm^3 from the 2nd numerator

[twilit meteor]

that's not 100cm^3

[echo jasper]

oh

100^3cm^3

[twilit meteor]

it's 100*^3* cm^3

that's just a conversion from cm^3 to m^3

since they want the answer in nm^3

[echo jasper]

so the goal is to get to 1m^3?

like for example

let me show

[twilit meteor]

reread the qjestion

[echo jasper]

like when we go to the next conversion we always want numerator 1?

oh ok

[twilit meteor]

imean ye this is basically the same thing

[ionic pendant]

you can chose either the numerator or denominator to be 1 depending on which conversion factor you can remember

[twilit meteor]

it's conversion between units, first cm^3 -> m^3, and then m^3 -> nm^3

[echo jasper]

yeah

[twilit meteor]

(which is what fraction 4 is doing)

[echo jasper]

like my question is

how do i know what to write for the 3rd denominator

Like

[twilit meteor]

bc 1m = 100 cm

[echo jasper]

How do u know u should put /1^3m^3100cm^3

whoops

Oh

OH

OMg

[twilit meteor]

and so for volume shit gets cubed innit

[ionic pendant]

we could alternatively put 0.01^3 m^3 / 1^3 cm^3 and that would be equivalent

[twilit meteor]

also true

[echo jasper]

so just a question

[twilit meteor]

?

[echo jasper]

I can't just do 1cm^3? at that 3rd denom?

would be bad

[ionic pendant]

you can but it would need to be this fraction

[echo jasper]

yeah

Ok

which do u think is begtter

[twilit meteor]

whichever u find easier, really

[echo jasper]

i feel like 1cm^3 helps me follow better

Ok

[ionic pendant]

i think it's nicer to work with conversion factors where numerator and denominator are both larger than 1, but that's a style choice and doesn't change the answer

[echo jasper]

ok

i will try to do both ways until i find which i am the best comfortable with

Thnx so much

[trim jolt]

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[tardy hamlet]

i tried using chinese remainder theorem

but i get stuck on 105

it doesnt seem possible to multiply 105 and a number to get 7 mod 9

[trim jolt]

@tardy hamlet Has your question been resolved?

[tardy hamlet]

@pliant seal

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@tardy hamlet Has your question been resolved?

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@tardy hamlet Has your question been resolved?

[tardy hamlet]

.close

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[small root]

. reopen

.reopen

[small root]

Bro

I think I got it

Is it 313?

[tardy hamlet]

idk

no answer key

[small root]

I think it's 313

First change the 'remainder' to negative

we don't consider 3 because we have 9

Then the number N will be of the form
5a - 2
And
7b - 2
And
9c - 2

By comparison

N = 5 *7. *. 9 k - 2

Since we want the smallest N

K= 1

@tardy hamlet dev bhai samjhe kya?

[tardy hamlet]

yes

lmao

how did you do ill understand

unless you live in india

my name isnt common in foreign countries

[small root]

I do live in India

[tardy hamlet]

oh

i live in the united states

[small root]

[tardy hamlet]

family is from uttarakhand though

[small root]

I thought for sure you were Indian

[small root]

I knew it!!

[tardy hamlet]

ive been to india every summer, still havent met another person with my name

is it common?

[small root]

Not really but it's a classic name I've heard

It has variations

Dev

Deva

Devraj

Dev is like the.. uh.. Diety

[tardy hamlet]

reference to indra no?

[small root]

He's also a Dev so Ig?

Idk much about these

I only know calculus

[tardy hamlet]

you on pace to get into IIT?

[small root]

Unfortunately yeah

[trim jolt]

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[tidal elk]

(dropped limit sign to save time), anyways, why does this not work?

[limpid belfry]

your second step is wrong i think

it should be 1/xsin2x

[vagrant marsh]

(1/a)/b = 1/(ab)

[tidal elk]

oh

what a dumb mistake

[tidal elk]

can i still solve normally like how i did here

using 1/ab

[vagrant marsh]

the x and sin are on the same side now, so things are gonna work differently

[tidal elk]

yeah im stuck

i was thinking of multiplying by 1/x but i dont think that works

[prime crystal]

its not an indeterminate form anymore, see what the the whole expression approaches

when denominator approaches 0

[tidal elk]

uh

[prime crystal]

sorry, when x approaches 0*

[tidal elk]

0/infinity

?

wait

the top part is wrong

[prime crystal]

both are wrong

where did infinity come from

numerator is just 1, no x term in it

denominator is xsinx

if you approach 0 it approaches 0

so 1/0+

which is inifnity

[tidal elk]

hold on

[prime crystal]

so limit does not exist

[tidal elk]

i think i was looking at the wrong problem when you asked that

gimme a sec to think it out again

i remember that 1/sinx when approaching 0 acts like infinity

right?

let me look at your explanation

ah ok

1/xsinx 1/spn

okay i get it

[tidal elk]

would my own explanation solve it the same way

regardless, thanks for the help

.close

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[prime crystal]

so you will have infinity/0+

now what

is this infinity?

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[patent fulcrum]

can anyone help me

[patent fulcrum]

with physics

but it involves maths

[mild oxide]

Ok

What physics tell

[patent fulcrum]

they want me to find the acceleration

but idk how to

[mild oxide]

Oh nlm

See

Force causes acceleration of the body

[limpid belfry]

do you know how to change 250N to the up and left directions?

[patent fulcrum]

They used trig

[mild oxide]

Can you tell me in the figure along how many axis is the force acting

[limpid belfry]

yeah

wait ill let oppailol cook

[patent fulcrum]

there are two forces

[mild oxide]

Ok

[patent fulcrum]

ik how to find a its Fres / mass

but idk how to get the Fres

thats the hard part

[mild oxide]

Do you know resolution of forces into components?

[patent fulcrum]

nope

[mild oxide]

Ok

Resolution of forces means

Finding components of the forces along the direction we are asked

[patent fulcrum]

hmm

alr

[mild oxide]

So do you know how to find components?

[patent fulcrum]

Soh Cah Toa?

Idk

[mild oxide]

That's fine

But like how you apply

Ok lemme sh9w

[patent fulcrum]

yeah i think

[mild oxide]

Show*

[patent fulcrum]

But the problem is

idk what to find

idk how i can find a single force from these two forces thats the problem

[patent fulcrum]

Yeah

[mild oxide]

Can you find sin and cos 35 degree in this triangle

[patent fulcrum]

cos(35)

hmm

cos is a/h

[mild oxide]

Yes

[patent fulcrum]

so isnt it the o?

or smth

the top one

[mild oxide]

Imma show more clearly

[patent fulcrum]

i know how to find parts from it using Cos Sin and Tan

but when someone says Sin(35)

i dont really understand what that means

[mild oxide]

Can u find sin 35 and cos 35 in this triangle

[patent fulcrum]

hmm

sin(35) would be y

and cos (35) would be x?

[mild oxide]

No in this triangle

How do u find sin

And cos

[patent fulcrum]

do you want me to find out Fy=

?

and Fx

[mild oxide]

Yes

[patent fulcrum]

oh then u can do

wait

[mild oxide]

what?

[patent fulcrum]

Soh Cah Toa

[mild oxide]

Okok

[patent fulcrum]

so Fy is adj

and we have H

we can use 250 x Cos(35) = Fy

[mild oxide]

Good

[patent fulcrum]

and for the other

its opposite

and hyp

so 250 x Sin(35) = Fx

?

[mild oxide]

Good

[patent fulcrum]

what do i do with this now?

[mild oxide]

Now see

Resolving the force means we break the force into components along the direction which we want

[patent fulcrum]

It sounds tough

but ill try

so what do i do

firs

[mild oxide]

Wait first let me show you something

[patent fulcrum]

alright

[mild oxide]

Find the resultant of the two vectors

[patent fulcrum]

the resultant

[mild oxide]

Yes

[patent fulcrum]

its the hypotheneus

you can use pythagoras theorum of smth

[mild oxide]

Do you know addition of vectors

[patent fulcrum]

i only know

that if opposite you can minus

and in same direction u add

thats all

cuz im new to physics

i only started a month ago

[patent fulcrum]

i dont know how to do it for

one verticle and horizontal

[mild oxide]

I am explaining read the stuff ok

[patent fulcrum]

ok

i read it

[patent fulcrum]

but

what is the direction

of the vector

then

[patent fulcrum]

oh the middle

[mild oxide]

Not the middle

[patent fulcrum]

i remember this

[mild oxide]

It makes and angle alpha with vector b

[patent fulcrum]

you draw a parallelogram or smth

[patent fulcrum]

alright

[mild oxide]

Addition of vectors by law of parallelogram

Ok so you remember it now?

[patent fulcrum]

i think

a bit

[mild oxide]

Solve this

[patent fulcrum]

you can use the formula

wait

sqrt of 25cos35^2 + 25sin35^2 + 2 x 25cos35 x 25sin35 x cos(angle)

[mild oxide]

angle is 90 see there

[patent fulcrum]

yeah

forgot

[mild oxide]

Okok so now see

What will it become

[patent fulcrum]

is this high school physics_

?

[mild oxide]

You can say somewhat

[patent fulcrum]

ima need a calculator

for it

[patent fulcrum]

because

[mild oxide]

Na bruh

Look at it

You are in highschool

Ik

[patent fulcrum]

yeah but my teacher didnt teach me this so i was wondering

alr but

how do i solve

without calculator

[mild oxide]

Imma show

[patent fulcrum]

cuz i havent even done derevation in maths yet

im on polynomials

so idk if i can do it in my head

[patent fulcrum]

oh

250 is the answer?

[mild oxide]

Yes

[patent fulcrum]

it says this is the law of cosines

would it work for sin if u replace

[mild oxide]

No

[patent fulcrum]

with cos

[mild oxide]

What

[patent fulcrum]

idk i found this online

[mild oxide]

No it's (sint)^2+(cost)^2=1

[mild oxide]

Its not what you think

[patent fulcrum]

alr

[mild oxide]

So we got the answer as 250

[patent fulcrum]

alr

how can i solve the question with this

if i have two forces opposite

one would have been easy to do

but two of them idk

[mild oxide]

,rotate l

[mild oxide]

Do you see any similarity?

[patent fulcrum]

yeah i do

its the same thing

[mild oxide]

Can you guess

[patent fulcrum]

the angle is also 90

[mild oxide]

If 250 cos 35 and 250 sin 35 gives 250 as resultant

Two forces give one force

[patent fulcrum]

alright

[mild oxide]

Two vectors give one vector

So don't you think one force can be written as two forces?

[patent fulcrum]

i guess

[mild oxide]

This is what we do in resolution

[patent fulcrum]

alright

so you can turn 2 vectors into 1

but also the opposite?

[mild oxide]

Yes

[patent fulcrum]

alright

understand

[mild oxide]

Now try your question

[patent fulcrum]

i think i need to focus on the former

more for now

[mild oxide]

Okok

[patent fulcrum]

for this question

can i not just

[mild oxide]

Now try maybe you do

It

[patent fulcrum]

turn the vector into 1

and for the 400 part

also do the same

[mild oxide]

No

[patent fulcrum]

then add them?

hmm

[mild oxide]

See

You need force along x and y direction

This is because forces can be added or subtracted if they are in same or opposite direction

That's why we resolve 250 N along x and Y axis

[patent fulcrum]

alright

[mild oxide]

Ok

Now do

[patent fulcrum]

so

[patent fulcrum]

oh wait

if i resolve both into their x and y components

can i not substract

or add

them

if i find x and y for the 250 one

and x and y for 400 one

can i not like

do that

[mild oxide]

Yes

But see 400 is already along x

[patent fulcrum]

yeah i get it now

[mild oxide]

Ok so now tell me acceleration

[patent fulcrum]

wait

[mild oxide]

Along x and along y

[patent fulcrum]

first x = 400 - 250 sin 35?

[mild oxide]

Good

[patent fulcrum]

i forgot the horizontal

for the first one

verticle(

y

[mild oxide]

250cos35

[patent fulcrum]

dont they both just have the same?

or wait

y = 400cos35 - 250cos35

so like

150 cos 35?

idk

does that work

you there?

x is like 257 N

y is 205N

if i use pythagorous theorum

i get 328N

328/60

which is the mass

i get 5.4 apporximate A

[patent fulcrum]

@mild oxide

5.4 m/s^2?

[mild oxide]

Why 400cos35

[patent fulcrum]

because

the bottom one is x

its 400

and the top one is 250

so i subtracted them

[mild oxide]

So it's 400-250cos35

[patent fulcrum]

and did cos(35)

yeah

[mild oxide]

Waith what

250cos35 is vertical

400-250sin35

[patent fulcrum]

yeah sin mb

i have a question

is horizontal always hypotheneus x sin(angle)

and verticle hypotheneus x cos(angle)

?

[trim jolt]

@patent fulcrum Has your question been resolved?

[patent fulcrum]

i finally goti t

thank you

.close

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[plain cargo]

Q9 part 2

[prime crystal]

it says f(x) < 9

and f(x) is x^2 - 4x + 8

so x^2 - 4x + 8 < 9

u have to find values of x for which this inequality holds true

[plain cargo]

Cant middle term

After x^2-4x-1

[prime crystal]

then

[plain cargo]

Ye got it in completing square

[prime crystal]

[plain cargo]

Whats afterthis

[prime crystal]

after what

[prime crystal]

complete the square here

you should get (x-2)^2 -3

you will get 2 values of x when u solve this

then just check for which intervals the inequality will hold

[plain cargo]

Thanks

.close

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[waxen harbor]

Is this an example of a quadratic inequality? and why or why not?

1. x(squared)y + 3y > 0

I've been confused for some time about this problem.

[nimble stone]

there is a quadratic, and theres an inequality, i think youre good to go

[noble escarp]

kind of. y(3 + x^2) > 0

[willow urchin]

.close

[trim jolt]

Channel closed

Closed by @willow urchin

Use .reopen if this was a mistake.

[willow urchin]

theyre gone, they brainrotted too hard in discussion

[noble escarp]

🤯

[trim jolt]

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[hard crane]

Back with another one, I need hints towards the concept of solving this

[maiden hare]

Consider only the horizontal surface area, maybe call it S_z

How much more does one horizontal cut add to it?

[hard crane]

half of S_z?