#help-38
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May someone help me with probability? It’s outing something that’s in a superposition through a measure gate. I’m just a bit lost because I don’t know where to go
@ripe plank Has your question been resolved?
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if a1>0 prove find monotone of an (by induction probably), how??
you need to prove this right?
Any value given ?
no, only that a1>0
we consider a1 as the first term btw
a1 > 0
So a2 = a1/(1+a1)
Numerator is greater than denominator
Therefore the statement holds true for the a2
let be true for a_m , therefore a_m <a_(m-1)
cook
Thefore a_m+1 = (a_m)/(1+a_m)
now since a_m < a_(m-1) evidently , a_m+1 < a_(m-1)
ai think this doesn't requires this sort of induction based proof
You can generally write the logic and proof it
I don't understand how this proves that a_n is decreasing
can anybody help?????????????
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Hello, quick question, why is the conditional probability P(A given B) = P(A by applying B), I'm referring to this
by doing $\operatorname{nCr}\left(3,1\right)\cdot\left(0.6\right)\cdot\left(0.4\right)^{2}$ one can get the same probability but i dont know why
Edsel Di Meo
I followed my intuition but i dont know why it holds true
I ask this because I know P(A given B) = P(A and B) / P(B)
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hello
I need someone to explain me what differentiation is
In this section we define the derivative, give various notations for the derivative and work a few problems illustrating how to use the definition of the derivative to actually compute the derivative of a function.
Okay. Is differentitation related to limits/continuity?
read the article
Thanks
it is
Okay
that is a pretty nice article, well written
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Hellooo, i'm not sure how to solve this, the person that gave me his problem, told me that its supose to get a number whit out calculator or aproximation
!15m
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@pale valve Has your question been resolved?
No😓
I still waiting for help
Sorry for taggim You but i been waiting for 35 minuts😓
<@&286206848099549185>
Do u want to solve for x?
Yep😓
does your teacher teach you by doing graphing
oh
😓
Don’t you just bring it to the other side to make it x=-2^x+5?
Or is there more to it?
Isn’t it straightfoward?
The person that gave me this problem, asked for an entire number
Because if you try whit log
You get this
And its kind the same situation
Yeah, thats literally the answer
What’s the person learning for them to get a whole number out of it?
The teacher came to the class and just said "resolve it" without context, he just said that there is a way to get an entire number without calculator
😓😓
Can i tagg helpers again?
<@&268886789983436800> can i tagg helpers again?
I think the rules are kinda vague as far as whether you can ping only once after the first 15 mins from posting your q or once every 15 mins. I think once every 15 min might annoy ppl though.
Might as well just ping now and give it like 30 min to an hr before pinging again.
But for your actual question, I don't see an easy way to solve this
There is a function called the W-lambert function that is supposed to be usable to solve this kind of equation I think.
But that seems unreasonable here to expect you to know.
Sometimes you can check this kind of thing via inspection, brute force, looking closely at the graph
For finding particular nice values.
I don't think that kind of thing works in general though.
I whant to know, been honest, i been 5 days tring to resolve it
,w solve 2^x = 5 - x
Wolfram alpha thinks this also requires the lambert w function
I don't think there is going to be an easy solution that doesn't use that.
Sometimes you get lucky.
For ex, try and solve 3^x=1-x
Do you see the solution?
Try x=0
Do you see it now?
Yes i get it
But this only works because we got lucky and I happened to pick a nice set of values for our equation.
Same idea applies for something like solving 2^x=3
You might say, aha! Just take the log!
But we had to invent a function, the logarithm, for this to be solvable in the first place.
Thats crazy, i mean at the begining the problem didnt look that hard
Yah sometimes things look a lot easier than they are lol.
😓 its crazy
It happens
Fwiw you can't just define a function that gives you a solution to every equation.
The function has to actually exist.
For ex x^2 + 1 = 0 doesn't have a real valued solution
Because squares of real numbers are always positive or zero.
It's hard to tell what the person asking you this question had in mind.
Dont know lmao
Your best bet is probably to ask them directly.
Maybe they know some trick neither of us know.
You too
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is this the correct answer?
This strikes me as a power rule derivative problem, but are you there yet in your course?
yes
is 15 the correct answer?
it is
SU TAOOOOOOOO
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i’m confused
Which part of that is confusing you first
how is it R?
They explain it
still confused
Which part of their explanation is confusing
Absolute function always give you positive result that means whatever the value of x, the expression will always be greater than -11. So x belongs to all real numbers
what’s an absolute value @obsidian valley
absolute value is a fuction notated by the big bars | | where no matter what is inside it, it will return the positive version of it
so why is it R if it’s -11
so like |-7| = 7
that’s a negative
yeah this is saying all real numbers inside an abs value will be bigger than -11
ah
since an abs value will only return a positive number
and positive is always bigger than a negative
oh so it abs can only return positive number
so it’s automatically positive?
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is a loop in basic circuit analysis
just basically any closed contour that you can draw from a node
is that a complete way to put it or is there an exception
That's it!
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no additional context
i'm a bit stumped on whether it would be a trick question or not
Why is it not just 1/7
that's what i was thinking but it just seemed like a trick question to me
if you want to take the question seriously, answer 1/7
but keep in mind this is very poorly designed
got it, i was overthinking this question a lot lol
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what if someone not responding to my thing
Please don't occupy multiple help channels.
We come to 2(n+k), but wouldn't that be 2n + 2k, not 2n + k?
huh
a = 2n
b = k
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how does the bottom give -inf? if I plug in 0 in lnx, why does it give -inf?
note that if y = ln(x), then e^y = x. what happens when x is a really small positive real number? -- ||y (or lnx) must be a large negative number||
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not relaly sure why this is true?
as sqrt(i) is not a cycle of 4 for a complete i cycle
how would you define i?
e^(i*pi/4)^2 = e^(ipi/2)
whats the barebones definition of i that you might have learned early high school
yeah, i was looking for "i^2 = -1"
thus we define sqrt(-1) = i despite it not really making sense
we can apply a similar idea that since (e^(i pi/4))^2 = i, then it would follow that e^(i pi/4) = sqrt(i)
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I konw its a physics question but Can somebody help me w this
draw free body diagram first
then write the relations for each mass
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Need help with simplifying square roots
Alberto Z.
No 😅
oooh
wait
so you get 10√2
then multiply the 5 on the outside to get 50√2
how did you get to 10√2?
is there an easy method that isnt done using a calculator
like not using the √ function
we could only divide the numbers to simplify until we got decimals which is where it would end
but i was wrong with my initial method
can 200 be simplified down to 2?
oh because it comes down to 10√2
and 200 was the radicand so it would be where the 2 is
and i only could get down to 10√25 before it couldnt be simplified anymore
since 25 cannot be divided by 2 since it becomes a decimal number

i apologize for my negative braincells 😭😭
$\sqrt{200}$ -> $\sqrt{2\times100}$ -> $\sqrt{2\times(10\times10)}$ -> $\sqrt{2\times10^2}$ -> $10\sqrt{2}$
Astar777
you basically split 200 in such a way that you make a perfect square inside the sqrt (for example here u got 10^2), then u can take it out
\implies is a thing too
yeahhh
because it turns into 2 x 100
and 100 is 10 x 10
which is perfect square so it escapes the radical
so its on the outside
leaving 2 on the inside
uhh yeahh
(just an advice no offense)
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yeah i keep using -> for some reason
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what is commute
transferable
consider $(A+B)(A^{-1}+B^{-1})$ (assuming they exist). is it $=I$?
eigentaylor
if the A^-1 + B-2 commutable yes
idk how they got to I then
you can distribute
no i meant distribute on the other thing
unless this is true for all invertible A and B, you cannot say that in general
PEMDAS sorta thing. if you have (stuff)inverse, then you generally don't wanna mess with the stuff in parentheses.
matrix inverses are not that nice
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can someone give me full answer and explanation? It is pretty important 🙂
u can explain only one of them
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can someone explain why the outer function from the perspective of the axis of rotation is first in h for shell in this example
and is inner in this one for shell
i cant find a pattern with which equation goes first with regards to h
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@sour crescent Has your question been resolved?
Here 4x is vertically greater than x³
Here x³ is horizontally greater than 4x
blue denotes the greater distance, green smaller
then why is it y^1/3 before y/4
Because in terms of x it's greater
You can see horizontally that y = x³ aka x = y^(1/3) is greater
Otherwise draw it into the yx plane
so what should always go first in h
Vertically it's here 4x
Horzizontally it's y^(1/3)
from the axis of rotatin
perpendicular?
here x^3 is outer on the x axis, but 4x is outer on the yaxis
Thats what I am basically saying
the only thing i can justify it by
from what you are saying
is to look at the graph from the perpindicularly from the axis of rotation
so if we are rotating around yaxis
In the end it's all about finding h which should be a positive difference. So drawing what you need to subtract should clear your doubt.
In worst case the difference is negative, but good news is you will still get in terms of absolute value the same result, just in negative, so you can put a minus infront
find the outer function on the xaxis
Yea so here in terms of horizontal height (x-axis) y^(1/3) is outer and y/4 inner
Nothing more or less
What system
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what do they mean when they say in the w space?
plot the function you got versus the angular frequency w
cool. thankyouu
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its going to look like a cosine that decays in amplitude
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can someone please explain how they went from the first line to last line?
the question is to find fourier transformation of cos(t)
this right
their version is quite hard, ours is simpler
$\mathbb{F}[1] = \delta(\omega) \ \ \int_{- \infty}^{\infty} e^{-i \omega t} , dt = \delta(\omega)$
wait, no
their s is frequency
our w is angular frequency
the formula is
$\mathbb{F}[1] = 2\pi \delta(\omega)$
Emily
yeah, this is it
oh that makes sense
but
now i have trouble understanding why fourier of 1 is that
i will watch a video
ill tell you
$\mathbb{F}[1] = 2 \pi , \delta(\omega) \ \ \int_{- \infty}^{\infty} e^{-i \omega t} , dt = 2 \pi , \delta(\omega)$
Emily
yup
shall we move to why the first line is correct?
yeaaa
okay, so, when you try to go from time domain to frequency domain
you find trouble computing the integral and extracting delta
even i dont know how to do it
buuut, the good thing is
take in frequency domain delta(w)
and compute its inverse fourier transform
you will find 1/(2 pi)
what i want to say is... if you go forward from time to frequency, you cant show it
but backward, from frequency to time, you can easily show it
using inverse fourier transform
ohhhh so we try to find the inverse
yeah, go find inverse of delta(w)
okay one thing, here delta is the krnocker delta right?
dirac delta
$\int_{- \infty}^{\infty} \delta(t) , dt = 1$
Emily
okay so
delta(w)
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new helpful🎉
nah you just became a member of some cult thing
secret clubs
lol
no one actually knows besides mods
I think there's specific number of help one do
then they'll get this role
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New to maclaurins series and wanted to see if my approach to this question was right
@wraith hinge Has your question been resolved?
,w maclaurin log(1+x)
Yup you're right
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This is the question I need help in:
Find the set of values for 'k' for which the equation 3x^4 + 4x^3 - 2x^2 + k = 0 has four real roots.
@mossy dagger Has your question been resolved?
What you have done?
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Thanks so much
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It is known that pressure is IP to the volume that contains a certain amount of gas. To what pressure is a gas subjected, if by increasing this pressure by 10 atmospheres the volume varies 2/7 of its value?
A) 25 atmospheres B) 18 atmospheres
C) 14 atmospheres D) 32 atmospheres E) 35 atmospheres
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If I have 3 planes and i want to know if they intersect or not ,
Can i put z=0 and then check if the three lines intersect or not?
Do you have the equation for the 3 planes?
To answer your question, no because they may intersect somewhere where Z =/= 0
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literally nothing yet I dont know WHERE TO START
it's like
i feel like if i can find a quartic equation
i can just find the discriminant of it
and solve the inequality discriminant>0
but quartic equation ain't a part of my syllabus
You know what is derivative?
uh yes! d/dx?
You can solve it by it graphics
graphics?
by sketching the graph, if you know where the derivative is positive, negative and 0, you can create a quite good sketch of the function
You only need to sketch
Not the only way, but quite certainly the best way. You don't have to draw it if you can at least imagine it
okay if i sketch then what's next?
3x^4 + 4x^3 - 2x^2 = -k and then right and left side of equation are function and you can sketch it
f(x) = 3x^4 + 4x^3 - 2x^2
g(x) = -k
And intersection of graphs are solution
Lets first do g(x) what is it?
For example if k=1 what is grapth of g(x)
you don't have to
i'd probably do this question by first finding the maxima and minima of 3x^4 + 4x^3 - 2x^2
once you have hose you know k has to lie between the minima and maxima for 4 solutions
Yeah
i understand
Graph allow you to see how many solution it has for specific k
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How would you graph f'(1) does not exist ?
,w plot abs(x)
|x| is famously not differentiable at 0
So do I just draw |x| on the graph?
no idea what you're trying to do
I just need to graph all the points in the first photo and I am stuck on f'(1) does not exist
the derivative isn't defined for a single point
How would I graph that though? I could have a hole at x=1 but one of the points I am supposed to graph is f(1) = -2
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help me solve for x
just subtract 1 and flip
that is the easiest way yea
knief
then i multiply both sides by x-7?
you could
so it’d be 8/x?
knief
i’m so confused 😭
is this supposed to be finding the inverse function or something?
no im just solving for x
why
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I tried to prove that an image of a sphere from far enough away results in essentially parallel rays at the image plane. However, I need help rewriting it for clarity.
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How do I use the (f(x) - f(a))/f(a) formula to solve this problem?
what formula?
you mean $\lim_{x \to a} \frac{f(x) - f(a)}{x-a}$
knief
did you copy it correctly?
apparently not
nope
nope for?
a. knief wasn't mentioning the formula that I'm looking for
b. My copy is flawless
no, I did not copy it correctly
alr, it is normally used for looking derivate of a function
which can also be used for finding tangent
Ye that's what I'm doing
would you be able to walk me through solving it? I keep getting stuck
ok can you ping someone else to
the helper up there may be able to resolve your problem
@bright quarry
As a hint, let a = x - h, and let h -> 0 instead.
These are equivalent, and this form is significantly more convenient to work with.
ok. what's the use for the other formula then?
It's equivalent
Might be useful in some situations
Depends on the function in question
Also, what's the difference between this one and then one that is f(x+h)?
The bottom two in my picture
Ok
tank_driver011
plug in x+h or the others, which depends on the definition of a derivative that is being used.
e.g.,
i made a mistake of not putting limit h app 0 next to the 1/sqrt(x)..
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yes it does
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can someone explin
i don't understand solution/or example to show it is false
if not explanation at least step/nudge to understand it
@wanton minnow Has your question been resolved?
the idea is if we set z=0 we can simplify slightly
so if z=0 it suffices to find vectors x,y such that
$x \cross y = 0$
LY
last part i don't understand
that just comes from the cross product
what do u know about the cross product so far?
well x X x = 0
cuz there's not really a unique solution to finding something orthogonal to X and itself
and the direction matters
x X y = - y X x
btw i kinda got this question, and i have another about the scalar equation of a plane
in the form n1x1 + n2x2 + n3x3 = d
where n = [n1, n2, n3] normal vector and x1, x2, x3 variable for any point in the plane
what does D represent?
it feels like a y-intercept when you're solving sometimes because once you find the normal vector you have to sub in a point and solve for D then you're done
yeah so it's basically that same idea
if instead we had 2 vectors that are parallel
then there's not really a unique vector that's perpendicular to x and say kx
hope that made sense
d = (shortest) distance from origin
no but how is that derived
cuz in the original definition, the scalar equation of a line is derived from the dot product of the normal against any line PQ where P is some point and Q is x1, x2, x3
which equals 0
so if P = (1,1,1)
so n*PQ = n1(x1-1) + n2(x2-1) + n3(x3-1)
= 0
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Solve w Limit Comparison Test
It is obviously done with Direct Comparison
But we are asked to do it with LCT
Is it possible?
@civic dune Has your question been resolved?
could u compare it with 1/n^3/2
then it would be lim cos^2(n)
then you only need to know the convergence of 1/(n^3/2) and whatever cos is
I think
its been a while since I touched anything comparison test @civic dune
yea
so i cannotu se it
for the LCT I need some real number A
as the result of the limit
unlike the nth term test which allows for DNE 🙄
then isnt the answer unsolvable with lim comparison test
I know some textbooks use that card
mine does
My teacher is trying to get us to focus on one test
So yeah its not likely to be possible
Just wondering though
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Could you explain how to get get this?
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is this true?
(to be honest when i first reacted to that, i had not read the statement 
i just saw the three yes reactions and based on that assumed it must have been true)
LOL i just did that
i still have not read the question
and i refuse to
Proof by popular vote 
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How do I start this? Usually a question like this gives only one equation but now there are two so I'm confused...
First what do you expect the dimension of the set to be?
Not sure, one?
It is reasonable to assume that indeed you are looking for one vector.
Then by substracting the second equation to the first you get y = 2z and the first to twice the second gives you 3x = 4z. This suggests you fix z to a random value (say 1)
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Do I set up both equations as a matrix first and solve?
You can
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I'm working on part (a). The parameterization of z=2x^2+y^2 is (1,t,2+t^2) because its in the x=1 plane, so we know that x is 1. For y it would be t. And for z we just plug in t and 1 right? am i missing something or is it just this simple?
it is just that simple yes
huh, ok. Normally when i think something is really simple its because im doing it wrong. So i just wanted clarification
thank you
and in part b, what does it mean by analogous?
or is it just asking me to find another parametrization where instead of it being x=1 its y=3?
this yeah, idk why it says analogous
just trying to say it's similar to how it's done in (a)
ok, so i should just be able to plug in 3 for y then
wait no
would i plug in sqrt(3) instead?
no its 3
ok, so i did b. now im working on c. how would i determine the equation of the tangent plane here?
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Hey guys, I need assistance.
Some directions more specifically.
sure, just ask
It's an statistics problem and I don't know where to start.
Basically is this:
The average value of land and buildings per acre of a sample of farms is R$ 2,500.00, with a standard deviation of R$ 350.00. The dataset has a bell-shaped distribution. Furthermore, it is known that the region considered for the study has 768 farms. Thus, the number of farms that have the value of land and buildings per acre in the interval between R$ 1800.00 and R$ 3200.00 is approximately:
730
760
Impossible to estimate the result
522
499
384
752
I've also included the answers for reference.
*Possible answers.
It is very tempting to pick the third option because I don't if you can estimate the result using any of the formulas.
Like standard deviation, mean, median, mode, etc.
so you have a random variable, say X, which is distributed normally, N(2500, 350^2), and you need to find P(1800<=X<=3200), and then multiply this by 768
have i understood the question correctly just to confirm?
You have the average value of real estate property among a sample of data, which is R$ (which is my local currency)2500.
Which I guess that's the mean, represented by x with a macron.
okay yes, so first, recall how we denote normal distributions, by N(mean, standard deviation^2)
here, X~N(2500, 350^2)
Ok, that tilde is supposed to be on of the X right?
the tilde reads as "X is distributed normally/X follows a normal distribution" with parameters (mean = 2500, sd^2 = 350^2)
Ok, sorry I've encountered this format before, lol. My professor never taught this.
no need to apologise haha
He just showed us the bell curve graph and how to find quartiles.
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@rare sapphire Has your question been resolved?
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can someone pls help
I'm trying to find the distance between A to B
i found the slope, it gave me 1,43x
because i did 0 = 1,75x + 2,5
-2,5 = 1,75x
-2,5/1,75 = 1,75/1,75
x = 1,43 am i wrong
...well that seems to be a correct calculation of where that line intersects the x axis, but i have no idea what you'd be planning on using that number for
because im trying to find the point B
B (?,?)
maybe you could try splitting into x and y components somehow
well B isn't at y = 0
it's the point where the two lines (y = 1.75x + 2.5 and y = -1.5x + 9) intersect
wdym
like in physics with vectors you split into components
turn each side into a right angle triangle sorta thing
yeah the 1,75x + 2,5 is the formula of the line
..
well it's the formula of one of the lines, there's also another line
yes but what would i be doing with that line cause im not sure
well with both lines you can find the coordinates of B
oh so wait how would the calculations look like
well, how do you find the point where two lines intersect?
i think i would like have to find both of their slopes
just equate them right
the equation of the line is satisfied by every point on the line, and B is a point on both lines, so it's the point that satisfies both equations
im sorry cause i dont speak english that good since the maths im in are french
y = 1.75x + 2.5 and y = -1.5x + 9, so 1.75x + 2.5 = -1.5x + 9
then solve that
ohhhh so like y1 = y2
exactly
thanks guys
find x then plug it in
by pluggint it in to any one of the equations
yeah once you have the x you can just put it into the equation of one of the lines
alright so like by doing it with the (-2,1)?
...no, you'd take the x value of B and put it into one of the equations to get the y value of B
and you'd find the x value of B by solving this
alright im solving it right now ill keep u guys updated
alright so i got x = 2 and y = 3,5
im assuming those are the points for B?
yep
wait how did you get 3.5
alright let me begin
1,75x + 2,5 = -1.5x + 9
+1,5x
both sides
3,25x + 2,5 = 9
-2.5 both sides
3.25x = 6.5
divide it
i got 2
so x = 2 now
y = 1,75x +2,5
wait ur right
i didnt so + 2,5
do
i just did 1,75(2)
whoops
my mistake
👍
alright so yeah B is (2,6)
alright alright
@unborn creek Has your question been resolved?
i have 1 more question
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For A) I got $100
But I can't find out how to solve B)
The topic is derivatives
<@&286206848099549185>
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Really struggling with these two problems down here:
The lecturer mentioned to use double set inclusion for both, but I don't exactly see how in this case
have you made venn diagrams yet?
Since the definition of what we're given (A delta B) doesn't give us enough to work with for the double set inclusion (at least, that's what I think)
what do they look like?
it might also help to think of what this means in english. x is in A \Delta B means x is in exactly one of A or B (not both, not neither)
yea those look fine
Right right
errr
yea, like this
God bless
Moving on to the latter part of the question, how would we use double set inclusion?
Like I'd get it if we had basic operators like AND and OR to manipulate around
proving something is the empty set by double inclusion seems weird 
i wouldn't do that for A \Delta A
But since this is a completely new operator (from what they've introduced) I wouldn't exactly know how to manipulate the left side to match the right side
Do you get what I mean
yea. but it is just AND and OR
But on the left side right
How would you prove the left side if a subset of the right
wait are you talking about b
Yeah
what does it mean for $x$ to be in $(A\setminus B) \cup (B\setminus A)$?
:bending_skull:
x exists in A without B and B without A
Right, sorry
A without B is
The set A disregarding all elements that exist in B
(right?)
Yes
looks a lot like this
See that's what I was thinking
But how would you write that
Also (and I don't mean to be difficult, appreciate all the help I can get) but the Piazza (our student help centre) mentioned 1b should prob use double set inclusion
there are different ways you can do it, but sure, you can use double inclusion
this is really all there is to it though
I totally get that but I don't exactly know how to write that in a way that's rigorous enough to hand in
Does that make sense
yes that makes sense. you are trying to prove 2 sets are equal. let x be an element of one of them, then show x is in the other one
so....
it should go like: let $x \in A \Delta B$. then... thus $x\in (A\setminus B) \cup (B\setminus A)$
Yep
:bending_skull:
Like use that definition above
To get to A \ B U whatever whatever
Ofc
Isn't that kinda weird shifting from words to math symbols
I'll try the proof out on my own but
not at all
Is there anything I should look out for/
Got it
So like
Let x be an element of A delta B
It follows that x is an element of A and x is not an element of B OR x is an element of B and x is not an element of A
the key to the proof is that $$x \in A \Delta B$$ is equivalent (by definition) to $$(x\in A \text{ and } x\not\in B) \text{ or } (x\in B \text{ and } x\not\in A)$$ and that's equivalent (by set minus definition) to $$x\in (A\setminus B) \cup (B\setminus A)$$
:bending_skull:
I'm not exactly sure what other steps to take bc after this is basically just the end stmtt
Yep
This is what I'm talking about right
Is that not too simple
no, the question is pretty simple really
God bless
like piazza says, you just need to use the definition of set minus
or set difference whatever you wanna call it
Holy shit you're cracked
Yeah
Got it Got it Got it
Ok I get the first part
I get the second part
Would the first part (a) be (b)?
Same thing we did?
But this time without the A \ B U whatever
We're just using the same first definition
for A \Delta A = \emptyset, i would just write there are no elements x with the property x is in A and x is not in A
so it is empty
yea that would be weird for showing something is the empty set
I guess like
You know the empty set is the subset for anything
So that's easy to prove
And then the other side
Is just this
i suppose. i would say this is enough but whatever you wanna say
I'm just gonna follow whatever the instructor wants rs
And then the one where its A delta empty
I suppose I could borrow what you said here for it
Thank you so much! That really helps

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an urn contains r red balls and g green balls. a ball is drawn at random and then it is returned to the urn with k additional balls of the same color. prove by mathematical induction that if n=2,3,… such experiments are made, the probability of a red ball at each draw will always be r/(r+g) and the probability of a green ball will always be g/(r+g)
i’m struggling with the induction step of the proof
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this isnt their channel mate
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