#help-38

1 messages · Page 159 of 1

wind estuary
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AAAAA HOW

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😭😭

prime lynx
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For the first one x is all numbers greater or equal to -3 and less or equal to 2

wind estuary
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hmmn

sacred gale
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what can I help you?

wind estuary
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table of values for no.1

sacred gale
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what table?

wind estuary
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uhmm

sacred gale
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oh, I see

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that is 3 right?

wind estuary
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@sacred gale

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-3

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Its negative

exotic pine
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just sub x

wind estuary
sacred gale
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no 3^2=9

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right?

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2*-3= -6 so 9-6=3 right?

prime lynx
# wind estuary

To get the values of f(x) when x is a certain number replace x with its value in x²+2x

wind estuary
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Who should I believe I need to finish this hahah

sacred gale
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trust me. You just know it's ture

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3 0 -1 0 3 this is answer

prime lynx
sacred gale
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okay/

wind estuary
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@prime lynx

prime lynx
sacred gale
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next problem/

wind estuary
sacred gale
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of course

trim joltBOT
wind estuary
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@prime lynx

prime lynx
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Yes

wind estuary
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Is the ans right?

sacred gale
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ah, I know

wind estuary
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??

sacred gale
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of course

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hi @wind estuary may I have your age?

prime lynx
wind estuary
wind estuary
sacred gale
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bro?

wind estuary
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is this even right!?

sacred gale
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of course

wind estuary
exotic pine
sacred gale
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ah, yes last answer is 8

wind estuary
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why??

exotic pine
wind estuary
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its 8?

prime lynx
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Let her try to solve it

sacred gale
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I mean x=2 f(2)=8, okay?

wind estuary
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I wanna know how..

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tell me how

prime lynx
sacred gale
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not interested

wind estuary
prime lynx
wind estuary
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Ohhh is this notation right?

prime lynx
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Since x²+2x = f(x)

wind estuary
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whats the value of x

prime lynx
prime lynx
prime lynx
wind estuary
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8

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Right??

exotic pine
prime lynx
exotic pine
prime lynx
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But I prefer dogs 🐶

exotic pine
# prime lynx Both

me too but i shifted my opinion abit once i saw mt friends dog and i stepped on catshit

wind estuary
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huh

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how is dog related to this

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😭😭

wind estuary
exotic pine
exotic pine
wind estuary
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oh okayy

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Btw what grade are yall

exotic pine
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9

prime lynx
exotic pine
prime lynx
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@wind estuary Has your question been resolved?

wind estuary
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how do I graph it

trim joltBOT
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@wind estuary Has your question been resolved?

wind estuary
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@helper

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<@&286206848099549185>

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How do I graph it

trim joltBOT
#

@wind estuary Has your question been resolved?

zinc ginkgo
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crude scaffold
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Could any1 help?

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My answer was 25.6 cm^2, but it's apparently wrong

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balmy granite
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balmy granite
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so for this one in the first step they multiplied both top and bottom with x in order to get rid of of the x in the numerator?

balmy granite
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why ?

prime lynx
tulip violet
# balmy granite why ?

When you have problems with limits to infinity you can divide all the terms by the highest power

balmy granite
balmy granite
balmy granite
tulip violet
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Because that's technically not the highest power

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The highest power is sqrt(x^2) or just basically x

balmy granite
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ohh wait yeaa

balmy granite
humble sun
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It works because constant/infinity is taken as 0

balmy granite
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that reminded me of something that i wrote in my noted but in here it seems like my teacher said to divide both top and bottom by the lowest of the powers 😭 is this something different or are they wrong?

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pearl lotus
#

Consider josephus problem
Here is my claim that if there are n ppl then when 1 kills 2
We have n-1 ppl with 3 holding the sword so the person who is going to be alive is the one who is alive among n-1 ppl
so if in n-1 let's say k is alive then for n k+2 should be alive (exept for the case where 1 is alive)

pearl lotus
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<@&286206848099549185>

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catscream can someone tell if my claim is wrong or right?

sacred gale
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hi

pearl lotus
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Hi

sacred gale
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can you tell me in detail?

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that's interesting

pearl lotus
# sacred gale can you tell me in detail?

Let's say u have 1 2 3 sitting in a circle
So we have that 1 has the sword and will kill the person left to him so he kills 2 now 3 has the sword and he kills 1 meaning 3 is now the winner

sacred gale
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interesting if case n?

pearl lotus
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Well then consider 1234 sitting in a circle when 1 kills 2
We have 134 sitting in a circle with 3 having the sword which is similar to our old arrangement we know that in case of 123 3 won so here also
The 3rd person will win which is 1

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Let's say in n-1 ppl kth person wins so
If n ppl we're sitting in a circle and 1 kills 2 we have arrangement for n-1 ppl and so k+2 is going to win
This is my argument

pearl lotus
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wut then 1 would win

sacred gale
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great. I think you are right

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then can you show me the problem?

pearl lotus
pearl lotus
pearl lotus
sacred gale
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I dont know Josephus.

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can you explain in detail about that?

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eg. sword only 3?

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otherwise each person has sword?

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and when 1 kill 2, the others do nothing?

pearl lotus
sacred gale
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no case n

pearl lotus
sacred gale
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okay? then sword is only 2?

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I mean there are only 2 swords?

pearl lotus
sacred gale
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oh I know, there is one sword, right?

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first 1 has the sword. right?

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what is the right answer of this problem?

pearl lotus
sacred gale
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thank you. I can solve this problem. see you after 2 min

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sorry I cant do this, you are right

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but I will continue this pro.

pearl lotus
pearl lotus
sacred gale
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thank you for your attention

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I know.

pearl lotus
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Anyway thanks for conforming
.close

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.solved

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pearl lotus
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pseudo shoal
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I need help finding what the k is, but i am having problems integrating.

pseudo shoal
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Here is the work i did but i got stuck in that section

burnt mulch
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Hint: Note that this is the same as $$(\sin kt)(-k^2+18)=0$$

solid kilnBOT
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Civil Service Pigeon

pseudo shoal
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ahh ok i see since they both have the same sin kt it can be simplified into that. From there would you have two separate the sin kt by using algebraic manipulation?

burnt mulch
pseudo shoal
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i wasn't sure if you had to remove the sin kt by algebraic manipulation or it just stayed there.

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Because of course i am trying to find values of k that satisfi the differential equation

burnt mulch
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Hint: Suppose that ab=0. What can you about a and b?

pseudo shoal
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i see can you use product property

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sin kt = 0 and -k^2+18=0

burnt mulch
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But yeah

pseudo shoal
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oh ok my bad, i am not sure how i forgot that. I guess i was not getting the practice i needed to remember.

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from that point i use algebraic manipulation and i found for the right-side k is = to the square root of 18 what whould the left side be.

burnt mulch
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Take that as you will

solid kilnBOT
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Civil Service Pigeon

pseudo shoal
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ok why would it be +- if you dont mind

burnt mulch
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$$k^2=18$$ $$\sqrt{k^2}=\sqrt{18}$$ $$|k|=\sqrt{18}$$ $$k=\pm \sqrt{18}$$

solid kilnBOT
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Civil Service Pigeon

burnt mulch
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In general, $x^2=a \implies x=\pm \sqrt{a}$

solid kilnBOT
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Civil Service Pigeon

burnt mulch
pseudo shoal
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ahh ok i can see where you got that from

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from there i imagine you would find the second derivative and plug in both the second derivative and the original function

burnt mulch
pseudo shoal
trim joltBOT
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pseudo shoal
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yeah when i plugged in 18 squared into the equation it matches the right hand of the equation

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thank you @burnt mulch , i am sorry if you probably got frustrated or something like that but i appreciate your time and effort to help me. Thank you

burnt mulch
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You’re engaged and are making an effort

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In contrast, someone tried to say thank you by making a sex joke

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Yeah ._.

pseudo shoal
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well i guess that some weirdos for you on the internet well i appreciate your help, and hopefully i see you again

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.close

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crisp spruce
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the question is asking to identify the common function and describe the transformation shown in the graph and to also write an equation for the function. how do i do this?

pliant wagon
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Ask yourself, what function does this graph's shape resemble?

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You should ideally already know what all the common functions' graphs look like in general

crisp spruce
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cubic function?

crisp spruce
pliant wagon
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yeah I mean once you do that it'll be pretty quick. As for the transformations part, that transformation will be obvious if you know the graph shapes

crisp spruce
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you could u help me thru this one for now

pliant wagon
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okay so you should notice the function ends at x = 0 right. If you sub -1 into x³, it's a real number so it's definitely not a cubic.

the function doesn't seem to be approaching x = 0, kinda just touching it. Hence f(-1) is not real and f(0) is real.

What function doesn't accept negatives but accepts zeros and positive reals?

Does this help narrow it down a little more?

crisp spruce
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what are the different functions i don't know if I'm thinking about it correctly

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i know that square roots does accept negatives

pliant wagon
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polynomials, trigonometric, roots, logs, a few others

crisp spruce
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could it be like -√x

pliant wagon
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Actually the diagram is a bit odd. While it does look like it's touching x = 0, it might not be. There's an extra dot

crisp spruce
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yeah i'm not sure it's out of my textbook

pliant wagon
crisp spruce
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how do i find the translation with the graph? its not that clear

pliant wagon
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I don't think it's possible to get an exact value, because it's just a graph

crisp spruce
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i feel like it could possibly be -√x+3/4

crisp spruce
pliant wagon
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That's rather specific. Also consider the possibility that x is an asymptote. Because if your answer is wrong, that might be the confusion

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It would be nicer if the graph had more resolution

crisp spruce
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yeah i agree i'll probably check my answer later

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eager lynx
#

Correct me if I am wrong but here's what I am thinking at
-4 on f there is -2
-2 there is -1
and etc
but why is it using the y values when it says x

eager lynx
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I know inverses are swapped y and x

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But I just dont understand why we are inputing the y values

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nvmI think I uderstand

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eager lynx
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.reopen

trim joltBOT
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eager lynx
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nvm I dont understnad, can someone explain

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or is that just the table for the inverrse

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inverse

tulip violet
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This table is for the inverse

eager lynx
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ah

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okay

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thank you

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.close

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eager lynx
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.reopen

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eager lynx
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Sorry one last question

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So when it says inverse -4

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does that mean I look at -4 y

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or what exactly are the steps

trim joltBOT
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@eager lynx Has your question been resolved?

split chasm
#

by definition of the inverse you're looking for
f(what) = -4

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eager lynx
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.reopen

trim joltBOT
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eager lynx
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oh

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so am I looking at only the left graph?

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cause I thought f^-1 is the inverse graph

split chasm
eager lynx
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I thought it meajt inverse though

split chasm
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the f^-1?

eager lynx
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Yeah

split chasm
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yeh it does

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but g is just irrelevant for this question

eager lynx
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ohhh'

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soo by using -4 i find an inverse of 4?

split chasm
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yes

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if you mean that f^-1(-4) = 4

eager lynx
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or is it just asking to find the x when y= -4

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I want to understand what it actually means but I am unsure

split chasm
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given that f has an inverse function
f(f^-1(x)) = x
f(f^-1(-4)) = -4

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so

by definition of the inverse you're looking for
f(what) = -4

eager lynx
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if F(x) means y
and y of -4 is 4 on the x axis right

split chasm
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lowercase f but yes

eager lynx
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oh so thats it?

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was I overthinking it or smt

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alright have a nice one

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.close

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rocky wasp
#

Hello

trim joltBOT
rocky wasp
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My probelm is

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its a combinations and permutations probelm where you have to find how many combinations there are if you can only move right or down on a grid, and you have to get from (0,0) to (3,3). I know how to solve this, however its a variation where you can also move diagonally once(counts as moving down and right in 1 move) and i dont know how to find how many combinations there are to this

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@rocky wasp Has your question been resolved?

rocky wasp
#

no

austere cedar
#

How many permutations of the letters "R R D D X"?

trim joltBOT
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@rocky wasp Has your question been resolved?

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reef sphinx
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reef sphinx
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how do i do these?

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for the first question, i arrived at x/(x-1)(x-2) - (x-2)/x(x-1)

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i dunno wat to do next

past comet
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1+1=24737489324348425824684586485182346341812384623721364736483411848684368623482464634475476276363482348346324654385834658314832641836281463846384665884847462636485495906083873733749695959273949130949473947231743479349214934194793749393942974379342794379432794379437943217934794372347432974397432704379342743273474377943974329732417942379432794329074397432972439743297423974374326832472317523152315231762438962349705489548548589432984397439704329743279042397439432979704397043279043279432907439083429843980743298423198024390724397042374379437432743743743079398899297382392729329729729032979723177939779832187784236752314452167894909065908982899804329803498439084329084329842390854787625378607869086253989089078978978785478997859787897897897809078780078940789549785978987657890978854778548745878876589546567546846634978789478784978747437843784784378437878347843784378478437847847847848747856747747743676754677647667677654676743676767643677654767647676547667546765476547654765476765467545445454546745546755467545677647743767667675677585767678439597845978354978598438778787898878

past comet
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awwwww

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okay

rough goblet
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it's alr lol

rough goblet
reef sphinx
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ohh

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i got (x'2 - (x-2)'2)/x(x-1)(x-2)

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now what..

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<@&286206848099549185>

rough goblet
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!15m

trim joltBOT
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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

rough goblet
#

usually x' represents the derivative of x

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hello?

reef sphinx
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1+

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from the right

reef sphinx
reef sphinx
rough goblet
#

yeah no that's wrong

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try again

reef sphinx
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where did i make the mistake?

trim joltBOT
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@reef sphinx Has your question been resolved?

stray drum
#

I have a fluke that it might be partial fractions but I might just be on about nothing

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unique field
#

If I say that f(4) = 4, then is that enough evidence to conclude that f(x) = x??

unique field
#

f(x) could also be equal to 4 for all values of x

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f(x)=4

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So now it's 4 in all cases

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For all values of x

trail ingot
#

correct

unique field
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🙏

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Thanks

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round galleon
#

someone explain to me how to simplify : log_3(6)=x

round galleon
#

so using change of base formula it turns
log6/log3

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but how do i further simplify it

left gazelle
#

do you know what log(a*b) is?

round galleon
#

i tried using a calculator and assumed that we turn log6 into two separate logs

round galleon
#

log(a*b)=loga+logb

trim thicket
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and what are the factors of 6

round galleon
#

2•3 , 6•1

trim thicket
#

yea split them using that

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thats it ig

left gazelle
#

wait a min
what form do you need the ans to be?

round galleon
left gazelle
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coz log_3(6) is already a constant

round galleon
#

i just wanted some confirmation

left gazelle
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okok

round galleon
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log2+log3/log3

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do i do this then

left gazelle
#

log_3(2) *

simple haven
#

log_3(2) + 1

left gazelle
round galleon
#

Oh they still have the same base?

simple haven
#

Well, we don't have to change the base to make this transformation

left gazelle
round galleon
#

log_3(2) + log_3(3)/log_3(3)?

sacred sapphire
#

are you trying to make it so you can use a calculator on it?

simple haven
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No, not quite

sacred sapphire
#

and your calculator only has log base 10?

simple haven
#

log_3(6)
= log_3(2 * 3)
= log_3(2) + log_3(3)
= log_3(2) + 1

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No need for the change of base formula at all

simple haven
round galleon
#

nop i was just curious on what wouldve happened if we got say,
3^x=18

#

and from searching i found the logs method

sacred sapphire
#

then idk what to say log₃(6) is already at its simplest form

#

unless what you mean by simplest form is that the arguments of the log is the lowest number possible

#

which in that case you have 2 terms instead of 1

round galleon
#

Oh

#

Is there btw a way to get the exact value of this types of equations?

sacred sapphire
#

that is the exact value

round galleon
#

like the actual number, like the decimal

sacred sapphire
#

well then you have to use a calculator

round galleon
#

ight thx anyways

#

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lethal vigil
#

i am getting the answer as 1/log3 but the ans is 1/log9

wind cloak
#

can you show your work?

bright jacinth
#

even i'm getting answer as 1/log3

#

do we use taylor's series expansion?

lethal vigil
#

im getting this

main sigil
#

im getting 1/log9.

bright jacinth
#

how can u tell

lethal vigil
bright jacinth
#

wait yea even me

#

i'm gettin 1/log9

lethal vigil
bright jacinth
#

i'm sending pic

lethal vigil
#

alr

#

why do i always mess up in differentiation

wind cloak
lethal vigil
main sigil
lethal vigil
wind cloak
lethal vigil
wind cloak
left gazelle
lethal vigil
wind cloak
lethal vigil
#

ye sorey

#

i messed up

#

1/2log3 = 1/log9

#

thanks @wind cloak

#

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bright jacinth
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wraith hinge
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# bright jacinth
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
bright jacinth
#

1

meager bloom
bright jacinth
#

yea kinda

#

we did it at the start of the year and it's been 6 months

#

and my notes arnt that neat

meager bloom
#

[➡️][⬇️]

#

This is how matrix multiplication happens

#

2 2X2 matrix multiplication will give 1 2X2 matrix only

meager bloom
# bright jacinth 1
2nd matrix is of size cxd
Result multiply matrix will have a size of axd```
left gazelle
#

if the ans is needed its J

meager bloom
left gazelle
bright jacinth
#

i wanted to see if its correcto

#

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turbid bough
#

Define a function f(x) with the following properties:

1.    The function must be defined for all positive real numbers  x > 0 .
2.    The function must produce exactly one integer value in its range. The rest of the values in the range must be real numbers, but non-integers.
3.    The function must be expressed as a single, continuous expression (i.e., it cannot be a piecewise function).

Provide the function and demonstrate that it meets all the specified criteria.

turbid bough
#

I am not sure I understand very well the question

acoustic trout
#

which part of the question are you having trouble with?

turbid bough
#

the second point

#

how can i do that?

acoustic trout
#

well maybe think of some function that is bounded between [0, 1] first

#

though, I wonder would they accept the constant function as an answer

turbid bough
#

Like which function bounded, and why 0 and 1?

dusky gust
violet gust
#

you can try some function thats asymptotic to some value and then modify its range to satisfy your conditions

dusky gust
violet gust
#

something like an exponential decay

violet gust
naive otter
#

x = -2

#

x=1

turbid bough
final coyote
#

x> 0

dusky gust
#

yeah, that seems ok

naive otter
acoustic trout
#

well rational functions wouldn't work because of...rationals number

violet gust
acoustic trout
#

exponential functions would be the easiest to model

naive otter
dusky gust
acoustic trout
#

yes

dusky gust
#

what?

acoustic trout
#

take x=1 for example

dusky gust
acoustic trout
#

oh right, oops x+1 is only rational for negative x

turbid bough
#

i think that works

acoustic trout
#

yeah nvm, it works

dusky gust
dusky gust
turbid bough
#

i am watching bow the solution example and it says (x/5)^(1/x)

violet gust
#

theres infinitely many such possible functions

acoustic trout
turbid bough
#

the 2/(x+1) was easy idk why didnt think about that

#

thank u all

#

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toxic stream
#

can anyone tell me how this happenned

toxic stream
#

up one is delta but it became this how??

marble wharf
#

first they multiplied by a/a

#

then they added and subtracted ax+b in the bottom

toxic stream
wise dagger
#

the second part is

#

wait...

#

oh

#

I get it

#

they first multiply the fractions be a/a

#

to get a∆x at the bottom

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toxic stream
toxic stream
#

.clos

#

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tepid fractal
#

Instead Of Finding The Radius, I want to try and find a new formula without calculating the radius of the quarter circle

split chasm
#

why are you trying to do that?

digital gulch
#

ez is good

#

no making hard

tepid fractal
digital gulch
sleek canopy
digital gulch
#

tangents?

split chasm
#

radius would be involved in some way

tepid fractal
#

i was thinking of AEC To make a square and without using pi to calculate

#

pi/8 is the easy route

meager bloom
#

You need to calculate area of AEC , for that radius is necessary

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#

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queen dew
#

My maths teacher gave us a question to create a function inverter which takes a value and gives 1 if the value is 0 and other wise gives 0 always. We were not allowed to create our own functions for this.
This was my attempt, however I'm looking for a much shorter solution.
Please help.

split chasm
#

are you allowed to use the sign/sgn/signum function?

queen dew
#

Signum?

#

Ah yes

shrewd ridge
#

start with 1 −

queen dew
shrewd ridge
#

nvm

#

actually yeah

#

it's just not the first step

whole coral
#

If you can use the floor function too, maybe you may want a positive function that has a max of 1 at x = 0…

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bronze breach
#

Does anyone know how to do this and can explain it to me? I think I know the math, I just don't know what they mean by angular form

I changed the numbers so it isn't the same problem as my homework (so it isn't cheating)

bronze breach
#

This is a homework on vector's angular form

shrewd ridge
#

means direction and magnitude

#

like this is 5i+3j but also angle 0.54 length 5.83

#

i don't know what exactly it looks like though

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#

@bronze breach Has your question been resolved?

shrewd ridge
#

ok, it looks like (0.54,5.83) i didn't expect that
or the other way?

bronze breach
#

i think i do actually

#

I never actually understood what i and j meant in a vector completely

#

so it's just

shrewd ridge
#

it's just cartesian and polar coordinates

bronze breach
#

i represents x?

shrewd ridge
#

yeah

bronze breach
#

oh

#

ok so

#

if the components of my velocity are

#

vx = 5 m/ys

#

vy = 10 m/ys

#

i would write it as

#

v = 5i + 10j

shrewd ridge
#

sure

bronze breach
shrewd ridge
#

ok wait

bronze breach
#

ill try your problem i think i got the magnitude of mine

#

8.72

shrewd ridge
#

(5.83, 0.54) is polar coordinates, the vector wouldn't look like this

bronze breach
#

the magnitude is 5.3

#

for 5i + 3j

shrewd ridge
#

or would it

bronze breach
#

reading my notes again

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shrewd ridge
#

i'm confused

bronze breach
#

.reopen

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#

bronze breach
shrewd ridge
#

i'll assume it is just 2 numbers

prime lynx
#

Hello 👋
What is going on

shrewd ridge
#

8.72 is correct

prime lynx
#

Oh polar form of a vector?

shrewd ridge
#

yeah i'm confused because it says angular form, and maybe it's distinct thing that uses a different notation

prime lynx
#

I haven't heard of angular form before.

bronze breach
prime lynx
#

I googled it and they seem similar.

bronze breach
#

dw about the exact form right now

#

or notation

#

ill rewrite it when i get back

#

i just want ot know what im doing

prime lynx
#

There's an organic chemistry tutor video on it

bronze breach
bronze breach
prime lynx
#

Oh.

bronze breach
#

53.41 degrees

#

Magnitude is 8.72 and degrees are 53.41

shrewd ridge
#

if you're sure that degrees is fine

prime lynx
bronze breach
bronze breach
#

oh u put it in radians

#

mb

#

yep same thing

#

nice

bronze breach
#

me and frog got the same answer so im sure it's fine

#

ill specify it in my hw

#

ill write 0.54 radians about the +x axis

prime lynx
#

Yes it's better to specify

#

What the angle is

bronze breach
#

kk

#

tysm

shrewd ridge
#

great

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#

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unborn grail
#

What is the symbol for set translation

unborn grail
#

${2\diamondsuit,2\clubsuit,\ldots,A\heartsuit,A\spadesuit}\implies{1,2,3\ldots,51,52}$

#

is implies correct?

solid kilnBOT
#

Splash

marble wharf
#

sets dont imply anything

#

you can say it in words

unborn grail
#

yeahhhh

marble wharf
#

if you want to be more formal you can do something like defining a function f:A->B where A is your first set and B the second

unborn grail
#

so just {} translates to {}

marble wharf
#

but words usually are enough

unborn grail
#

this is homework and they said it can be informal, so ill just use words

#

Thanks a lot!

marble wharf
#

(its not like words are informal just because they are words)

unborn grail
#

(i know dont worry)

#

i dont need rigor in my proofs, needing to define a function to say that ace of spades is 52

#

thank you 😄

#

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astral mortar
#

Guys I know that the conductance weighted laplacian is given by K = A^TCA but the note hints at a quick way to construct this without going through that shenanigan. Can anyone tell me what that is?

astral mortar
#

Like when you construct a laplacian you just look at K_ii is the number of edges connected to node i and K_ij is -1 if i and j are connected. That’s what I’m talking about

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#

@astral mortar Has your question been resolved?

astral mortar
#

@helper

#

<@&286206848099549185>

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wraith hinge
#

if u live in uk, what did u write for your mathmatics personal statement?

wraith hinge
#

oh its 2am

#

oopsie

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ancient edge
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ancient edge
#

Can someone check if my work for this problem is right

solid kilnBOT
vapid pawn
ancient edge
#

How should I write the integral

vapid pawn
#

Why are you squaring your functions?

#

*bounds

ancient edge
#

Squaring the bound?

vapid pawn
#

Yeah, r = 4 and r= 4-sinx or whatever

ancient edge
#

Oh those are polar equations

vapid pawn
#

Yah, they are bounds of your area of integration. Why u squaring them

ancient edge
#

What

#

I’m sorry I’m confused

#

My bounds are 0 to pi

vapid pawn
#

Okay, whatever, the area you are trying to find is defined by two polar equations. In your integral you've squared then and subtracted them

#

I'm just trying to figure out why

#

I'm just trying to figure out what you're method to solve this was

ancient edge
#

Wdym method

vapid pawn
#

Just walk me through what your thinking was

ancient edge
#

ok so

#

i needed to find the bounds

#

and i did that by finding the intersection of the 2

#

got 0 and pi as the bounds

vapid pawn
#

Yep, that checks out

ancient edge
#

then to find the area inside r = 4 and outside 4 - 2sin i did integral(0 -> pi)(4 ^2- (4 - 2 sinx)^2dx

#

using this formula

vapid pawn
#

Ah, okay. I see what you've done. Sorry, that formula is not intuitive. They've just mashed the jacobian into all of it without explanation. My bad.

vapid pawn
#

Seems to check out. Looks good to me

ancient edge
vapid pawn
#

No worries

ancient edge
#

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tidal elk
#

i get everything else until the part (x-13,000)

tidal elk
#

i know its talking about excess

#

but i cant wrap my head around why excess is subtraction

stray drum
#

X is income right

tidal elk
#

yes

stray drum
#

So, x-13000 is all of her income, other than the first 13000

tidal elk
#

so ur saying x - 13000 = income

stray drum
#

Remember that you arent getting rid of the 13000, you’re calculating that in another term

stray drum
#

We want to separate the first 13000 because it is calculated differently

tidal elk
#

is that why theres the subtraction

stray drum
#

Yes

tidal elk
#

ah ok i see

#

thanks

#

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tidal elk
#

.reopen

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#

tidal elk
#

struggle understanding the wording and how I would format this word problem into equation

#

im thinking A but it doesnt seem right

fleet bear
#

Why do you think it's A?

tidal elk
#

wait nevermind

#

A is wrong

fleet bear
#

Alright, have you figured it out now?

tidal elk
#

nope

fleet bear
#

Okay. What is acceleration?

tidal elk
#

speeding up

fleet bear
#

sorta yeah. It's the rate of "speeding up" or rather change of speed(velocity)

tidal elk
#

ok i understand its 3888h but why would it equal 250

fleet bear
fleet bear
#

3888km/h right

tidal elk
#

yes

fleet bear
#

But initially, the train likely wasn't moving

#

So we assume its speed at h = 0 is 0

tidal elk
#

okay

fleet bear
#

1 hour passes, 3888km/h
2 hours pass, 2 x 3888km/h
3 hours pass, 3 x 3888km/h,
... so on

tidal elk
#

yes but why equal 250

#

if 3888 is greater than it

fleet bear
#

Okay, I see. It accelerates at a constant rate. h is the time it takes to reaches 250km/hr. h itself could be smaller than 1 (i.e. less than an hour)

#

so like if 30 mins passed from the start, the train would be going at 1944km/h

stray drum
#

It takes accelerating for h hours at 3880km/h to get to 250km/h. H can be less than 1

#

This means h*3800=250

tidal elk
#

also its 250 km / h which is not equal to 3880 km / h (also confused about that)

fleet bear
#

Notice the units are different

tidal elk
#

cancelling the km and hours?

stray drum
#

3800km/h per hour is acceleration

tidal elk
#

oh i see

#

but would cancelling the km and hours be viable

#

or is it a coincidence

fleet bear
#

Wdym by the km cancelling?

tidal elk
#

ignore the messiness

#

but would that work

fleet bear
#

why does your remaining "hr" leave the denominator?

tidal elk
#

oh right

fleet bear
#

Also, you're solving for h, no?

#

250 km/hr =/= 3888 km/hr^2

tidal elk
#

it just says pick the best one that describes it

fleet bear
#

That's fine. I just thought it was weird that you equated them

#

without h at least

tidal elk
#

i think i get it

#

its just the numbers tripped me

fleet bear
#

Alright!

tidal elk
#

thanks

#

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blazing geode
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blazing geode
#

Weird I got a wrong answer

#

My interpretation of the question is that it asks whether rotate 135 or 180 of the graph about the origin would result in the original graph.

#

I notice that if you rotate the graph 135 about the origin, it would as same as before the rotation.

#

So 135 should be correct

#

Do you guys agree

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marsh forum
#

Prove that $\lim_{x\to a} f(x)= \lim_{h\to 0) f(a+h)$

cold sphinx
#

hi, on an exercise with intermediate value theorem, for all x, a<x<b and a<f(x)<b so f(a)>a, i understand why it works but could you guys give examples

trim joltBOT
#

Please don't occupy multiple help channels.

knotty locust
#

How dare you

cold sphinx
#

loll

knotty locust
#

The statement is false

solid kilnBOT
#

Veni, vidi, perii
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knotty locust
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Still false

marsh forum
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wait

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i'll send a picture

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question 9

knotty locust
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your book has left out key details

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what r they

marsh forum
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this is spivak

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the god of calculus

knotty locust
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prove lim x->0 1/x = lim h->0 f(0+h)

marsh forum
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okay, the limit exists

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so $|x-a| < \delta \implies |f(x)-f(a)| < \varepsilon$

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right so far?

knotty locust
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for every epsilon >0 , there exists such a delta where that is true,

fresh pendant
marsh forum
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limits page 107, 3E

marsh forum
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now $|a+h-0| < \delta^ {'} \implies |f(h+a) -f(h+a)|< \varepsilon$

solid kilnBOT
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Veni, vidi, perii

marsh forum
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so $0< \varepsilon$

solid kilnBOT
#

Veni, vidi, perii

#

Veni, vidi, perii

marsh forum
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and $|x-a|< \delta^{'} \implies |f(a+h)-f(a)| < \varepsilon^{\circ}$

solid kilnBOT
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Veni, vidi, perii

marsh forum
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so uh

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now what

trim joltBOT
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flint matrix
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e

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flint matrix
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common ratio of 27,9,3...

clear cloud
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9/27 ?

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3/9 ?

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@flint matrix

flint matrix
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wouldnt that be simply 3

clear cloud
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It is following term/the term

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It would have been 3 if this was 3,9,27...

flint matrix
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its supposedly decreased

clear cloud
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So it is less than 1

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And greater than 0

clear cloud
trim joltBOT
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@flint matrix Has your question been resolved?

flint matrix
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<@&286206848099549185>

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im not even sure abt the ratio

unkempt oxide
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That will give you the hint you need

flint matrix
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what

unkempt oxide
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Powers of 3

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Make the given terms into power of 3

flint matrix
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27³?

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9³?

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3³?

unkempt oxide
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3 cube
3 square
3 power 1
Then what's next till 7th?

flint matrix
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3 power -6?

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or -7?

unkempt oxide
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Then 3 to power 2
Then keep decreasing till 7th term

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3,2,1,0,-1,-2,-3,-4

flint matrix
unkempt oxide
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3 square is 9

flint matrix
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also wont this be divisible by 3

unkempt oxide
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Oh my... You didn't understand it still?

flint matrix
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i have been stuck in this one

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for the past 40 minutes

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i cant take it anymore

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please

unkempt oxide
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Okay how much is 27 in powers of 3

flint matrix
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i do not know anymore dude

unkempt oxide
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Take a deep breathe, one step at a time 27 in terms of 3

flint matrix
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i was still able to solve the number 4 of finding the 6th sum of 32, 64, 128 by my own

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and ive been stuck in number 5 for the past 40 minutes

unkempt oxide
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That's wrong bruh

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I can't show the solution here, you need to solve by urself

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Just below 27 write what is it in powers of 3

flint matrix
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oh my god man

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unkempt oxide
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Now 9

flint matrix
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unkempt oxide
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Now 3

flint matrix
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unkempt oxide
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Okay 3³, 3², 3¹, now look at the powers what's next

flint matrix
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do i have to keep doing this util i get to 7th

unkempt oxide
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Ur already at 3rd, 7th is not so far away

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4th is what

flint matrix
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holdon

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dont i need to use the formula given

unkempt oxide
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Nope

flint matrix
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what

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really

unkempt oxide
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Just say the 4th term bro

flint matrix
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0

unkempt oxide
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In powers

flint matrix
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3⁰

unkempt oxide
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5th

flint matrix
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3^-1

unkempt oxide
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Almost there, now sixth

flint matrix
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3^-2

unkempt oxide
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And 7th is!

flint matrix
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3^-3

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oh my god

unkempt oxide
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Okay much is that?

flint matrix
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omfg

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1/27

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oh my god

unkempt oxide
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👍

flint matrix
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thank you

unkempt oxide
flint matrix
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.close

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unreal lark
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how do u solve b

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livid thunder
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try turning the RHS of part a into the eqn in part b

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north mountain
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help pls

trim joltBOT
north mountain
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idk how to even start this question

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for ii

wise dagger
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neck pain, sorry

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,rccw

solid kilnBOT
wise dagger
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ah, i see

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first find the non-shaded region of PBO

north mountain
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how do u find that

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watesigma

wise dagger
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note that area of :
triangle ABO - sector APO
= the above mentioned part PBO

north mountain
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wait

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ohhh

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ok ty

wise dagger
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after that you can just use
Sector QBO - above mentioned PBO
to find the shaded region

north mountain
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is radius of the open one 6

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or 8

wise dagger
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ah, new question.

north mountain
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yes me dumb

wise dagger
wise dagger
north mountain
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is it the slant height

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of the cone

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or smthing

trim joltBOT
#

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hexed thunder
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I really just need to know the difference for when I reject the null or fail to reject the null for this question...

hexed thunder
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Since H1 is correct, does that mean that I reject H0? If so, how would I word that appropriately?

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"We reject H0"
"There is sufficient evidence to suggest that H1 is true"
Those are the two statements that I believe I would write for this question.

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.close

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young mauve
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Help meee

trim joltBOT
young mauve
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I assume that you wanna change the 3^x into e ^something

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but idk how to do that

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or am i on the wrong track?

limpid belfry
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you are on the right track

clear cloud
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3^x = (e^ln(3))^x = e^xln(3)

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Keep going from there

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Same 15 = e^ln(15)

young mauve
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Oh yeahhhhhhhhhhhhhhh

clear cloud
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And im sure youll achieve from there

young mauve
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oh thats smart

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so e^ln(3^x)+7x+2=15?

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ln(3^x)+7x+2=ln(15)

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?

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oh wait

clear cloud
clear cloud
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Nvm

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You can just simplify the ln further

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Ln(3^x) = xln3

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Go ahead

young mauve
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(7+ln(3))x=ln(15)?

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x=ln(15)/(7+ln(3))?

clear cloud
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Not quite

clear cloud
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Be careful

young mauve
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oh yeah

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x should be ln(15)-2/ln(3)+7

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then

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also im curious where this comes from

limpid dawn
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thats a log rule

meager bloom
solid kilnBOT
young mauve
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wtf

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oh

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still wtf

solid kilnBOT
limpid dawn
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Sometimes this scares people off so I use the emoji version

forest niche
young mauve
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bro the emoji version makes me think im reading wingdings or something 😭

young mauve
limpid belfry
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the emoji version is like some facebook math quiz

young mauve
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eh screw it

amber python
young mauve
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i dont need no proof to do math

solid kilnBOT
young mauve
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💀

young mauve
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though the sweat one is probably better cause the swear in the corner indicates that its an exponent

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Ok thank you

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.close

trim joltBOT
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wraith hinge
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