#help-38
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snow would solve this in 2 minutes using complex numbers
fr?
probably
but thats cheating fr
snow would take one look at this and decide its not worth anyones time
you can use complex numbers for this?
don't ping them...
idk I can't
use de moivre?
if there is trig there is probably complex numbers
havent yall studied complex numbers
why you putting a question mark like me asking that is bizarre af?
anyway
Isn’t the first bracket equal to 21
Yeah I remember that result
in this question
same
could be, then the second must simplify to 5 to make final answer 105
but proving it is hard
$\tan(x) = \f{e^{-ix}-e^{ix}}{e^{ix}+e^{-ix}}i$ or something
thewizardofOU
then write it down
oh fk
8 of my neurons died just by looking at this
i was trying something
no wait
woa
(cosx+isinx)^n= cos(nx)+ isin(nx)
,w $$\left(\tan^2 \frac{\pi}{7} + \tan^2 \frac{2\pi}{7} + \tan^2 \frac{3\pi}{7}\right) \cdot \left(\cot^2 \frac{\pi}{7} + \cot^2 \frac{2\pi}{7} + \cot^2 \frac{3\pi}{7}\right)$$
Ah yeah this works
nah wtf
yepp
,w explanation $$\left(\tan^2 \frac{\pi}{7} + \tan^2 \frac{2\pi}{7} + \tan^2 \frac{3\pi}{7}\right) \cdot \left(\cot^2 \frac{\pi}{7} + \cot^2 \frac{2\pi}{7} + \cot^2 \frac{3\pi}{7}\right)$$
fkin give the stepss
That’s not how wolframalpha works…
WHAT THE F
wow
IM TRAUMATIZED
but i dont wanna use some random ass identities i dont even know
even if i get the solution now, theres no point
because using this method wont click in my mind ever
bro you gotta learn the tan (nx)
it is useful for jee
what chapter is that
you can learn it in trig and prove it in complex numbers
both my trig functons and equations is done but i havent been taught that tan(nx) thing
was about to suggest using complex numbers
you can see the pattern
tan2x = 2tanx / 1- tan^2x
tan 3x = 3tanx - tan^3x/ 1 - 3tan^2 x
this question is from topics you learn before complex numbers
if you see the pattern
tan (2x) = S1/S0 - S2
where Sn is sum of tan(x) taken n at a time
whaaaaaa
(this was taught to us im not lying)
hold on
yes
lemme use normal identities
$$\left(\tan^2 \frac{\pi}{7} + \tan^2 \frac{2\pi}{7} + \tan^2 \frac{3\pi}{7}\right) \cdot \left(\cot^2 \frac{\pi}{7} + \cot^2 \frac{2\pi}{7} + \cot^2 \frac{3\pi}{7}\right)$$
Aryan07
tan(nx) is a neat pattern
yeah so
tan 3x = S1 - S3/ S0 - S2
IKR
taking pie/7 as theta
its soo good
no other way
you can try finding an equation which has roots tan(pi/7), ...
yeah that's what the solutions says
but bro wont listen
ah, I see
that seems to be the easiest way other than like
expanding everything out
yeah
@tulip vapor he is little broing you
mb gotta go
$4\theta=\pi-3\theta$ and take tan on both sides
im a lil bro fr tho
kheerii
should work
but wheres 4theta in the question 💀
let $\theta=\frac{\pi}{7}$ then $7\theta=\pi$
kheerii
yeah
let theta = pi/7
also, $\tan(4\theta)=\tan(\pi-3\theta)$ has roots $\frac{\pi}{7},\frac{2\pi}{7},\frac{3\pi}{7}$
kheerii
how on earth is this gonna come in my mind bruv
that's the point of practicing questions, to build up your thought processes while solving questions
😭
theta=pi/7 is an obvious step, from where you have 7theta=pi
it was really more of a slow build up
after this 4theta=pi-3theta should also not be too hard to think of
till there is fine, after it just blows me off
whenever you have this kind of form you need to split your theta into two parts
it's a similar method to how we find $\cos\left(\frac{\pi}{5}\right)$ and the other trig ratios
kheerii
$5\theta=\pi\implies 3\theta=\pi-2\theta$
kheerii
i have memorized pie/5 and other important ratios tho
you should still know how they are found
hmm
instead of this, 3A + 2A = pie would come into my mind
it's the same
and I would be doing tan(A+B) 💀
hold on let me write it down
but
why are we bothered with 4theta here
but out of so many different ways why only 4theta = pie-3theta
It’s the easiest
If you did it as 5theta=pi-2theta you would need to find tan(5theta)
Although this approach will work as well
but I would have to find 4theta too and i dont know that formula
You should learn I
The formula for tan(nx)
It’s pretty handy
real for that
If you refuse to learn any approach which will help you solve this question, nobody can help you.
I dont know basic concepts of complex numbers
Who says this involves complex numbers…?
the people earlier
so whats the formula for tan(nx)?
the general formula
@worldly wing
...
what am i supposed to look for in this'
whats k
index variable for the summation
tan(nx) is equal to a sum of things from 0 to n
divided by another such sum
that's just an identity of the tan function
yes?
[ \sum_{k = 1}^{10} k ]
Do you know what this means
nope
Bob l'éponge
oh boy
i dont know what this summation function upper and buttom thing means
It means you put the value that it starts from
in this case 1
up to the value on top
in this case 10
oh
so this sum is just 1 + 2 + 3 + 4 ... 10
ahh
=1+2+3+4+5+6+7+8+9+10=55
yeah whats the next step now
Do you know what [ \binom nk ] means
Bob l'éponge
no
thats from binomial theorem ig, that chapter we'll study in future
the binomial coefficient describes how many ways there are to choose k of n elements
Bob l'éponge
yeah
so in short im cooked
ask your teacher about the problem
i doubt you'll be assigned something you haven't been taught the tools for
after doing theory of my trig function and eqn chapters i decide to hit some cengage or other modules, but internet decides to hit me up with this question
i havent been assigned this from my teacher, apparently this topic is from trigo compound angles, but almost all methods require some other tools from later chapters
usually 11 out of 10 people in help section are indians prepping for jee
idk why they abandon me today
sure but the whole point of your exam is to get as much in as little time as possible
you're no superhero for doing something anyone else can't
exactly, thats why I refuse to learn those extra long methods
¯_(ツ)_/¯
you said you aren't to spend more than 5 minutes, this channel's been open for an hour
fr
lol
but
its like a challenge
first time is always a longer time period
@frozen ploverhow to find range of sqrt(9tan^2 A+ 4cot^2 A + 13)
AM > GM probably
so I did 9tan^2 + 4cot^2 >= 12
where all is it applicable?
is it only for reciprocal functions
for positive reals
I mean can you find range of ANY function with this?
not really
it's only useful in certain cases
like this sure
but the condition for it to be true is positive real
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im lost please
@earnest frigate Has your question been resolved?
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,w derivatives
,w integrals
,w limits
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ok so this is a question on a practice quiz i narrowed it down between 2x^2+5x+2 and 6x^2-x-2 but i can't figure out which one of them is right because both of them interset the quartic function twice at y=0
Just divide as u normally do?
what do you mean?
Did u ever divide quadratic or cubic with linear?
it's just polynomial divison right?
Yes
why would it be with linear?
No i mean like
isn't it quartic division by quadratic?
That process
U have 2 options
Try diving the thing with ur options
Remainder is zero then that is the answer
ok give me a min to do that for both factors
Ok
ok so this is the point where i was at with my first factir
Yes
wait nvm i realize my mistake
the first factor divides evenly
both divide evenly
(6x^4+23x^5+18x^2-12x-8)/(2x^2+5x+2) = 3x^2+4x-4
and the other factor gives (x^2+4x+4)
would i just pick the first factor bc x^2 + 4x + 4 can be factored further into (x+2)(x+2)
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I would start by taking the log of the whole thing
since log is continuous you can move it inside the limit
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since arctan(inf) --> +pi/2
and yea you are right
but ugh ^(1/n) makes me think about taking ln or doing e^(...)
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Are there ways to define functions that are piecewise functions kind of like this, but in non piecewise form, like an actual function
Sign just gives the sign of the number correct
yes
Could you explain the floor function, is it describing the periods of the function, and counting what "piece" it's on
plot the graph or individual components to see how it looks
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Hey friends. I've been struggling with something in writing Mathematics: how to start a list of biconditional statements. It's something I come up against quite a lot, but I can't figure out the right way to go about it. Please can someone look at the two images I've posted, and tell me if Version 1 or Version 2 is correct? 🙂
@tall prawn Has your question been resolved?
what is ‘the series’
Hey, thanks for the reply. Ah yeah sorry, I should have included that in the post. (Although, I don't think it really matters to my question. I'm interested in the writing, in the parts of the images I've highlighted) 🙂
would you be able to continue this on your own?
Hey Xene, thanks for the reply. My question is not about how to solve this specific problem. My issue is, I am trying to understand how to correctly write a situation like I've highlighted in the images I've posted: how to start a series of biconditional statements. I think my pictures explain it better than I can in words!
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@tall prawn Has your question been resolved?
@tall prawn Has your question been resolved?
@tall prawn please forgive me, other than the text at the top indicating the version number, and very minor differences in how the words are written (n.b. literally how, as they appear to be all the same words), I am unable to spot the difference between your original two images.
Can you highlight the difference for me? Because apparently I am bad at reading.
Actually I think I found a difference being the text "the following equations hold" being included in the second and omitted in the first.
If this is the only difference, I don't see a significant problem with either including or excluding that phrase.
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why is this not diagonalizable over R, the eigenvalue of 3 has equal algebraic multiplicity and geometric multiplicity, no?
char. poly.
I mean the diagonalization would mean that you get a diagonal 3x3 matrix of the eigenvalues, but 2 of them are complex
oh shit yeah that was stupid of me, I was going purely off the definition
So even if one of them fills its eigenspace, you`re still missing two
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Nw
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$\exists x\forall y(x<y)$
ƒ(Why am. I here)=I don't Know
Trying to figure out why this statement is false
We're dsiscussing over W btw
so this means there exists x for all y such that y>x
ooh
say y is 0
there's no smaller number belonging to W
right?
whats W
whole numbers?
TIL whole numbers are non negative
yes
there exists x, for all y, such that $y>x$
ƒ(Why am. I here)=I don't Know
try saying it without using exists or for all
how? $\forall$ means forall, right?
ƒ(Why am. I here)=I don't Know
yes
ok, there is a x for every y such that y>x
there is a whole number such that any other whole number is greater than it?
something like this yeah
oh, right.
thanks
i.e. there is a smallest element of W
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Is there something more to part a in question 13 other than just cancelling the xs?
Uh
So you have to show that it agrees with sin(x) in both cases
Wdym
What is sin(x) when x is 0?
0
And what is xf(x) when x is 0?
0
🔠
What
So I’m just proving continuity
No you’re proving that they’re equivalent functions
In part a there is no integration
Yeah
Part a helps with part b
Sure but how does that like
Solve it
I guess
because it’s only sinx when x is not 0
No, both are 0
Wha
Sure
Sure or yes?
So when x is 0, x*f(x) = ?
0
No
There’s no division going on
Anywhere
Its x multiplied by f(x)
f(x) is 1
And x is 0
So it’s just 0*1
No division
x * f(x)
Equals
x * 1 (When x=0, f(x)=1 is why we make this replacement)
So
0 * 1
=0
So ignoring the top half of the function, for other values of x
All we’ve shown is that
Okay
In the other case, x is always greater than 0, so you can cancel the xs
So I can revolve it without it being defined at that point
Yes
Okay
And so we can simplify the top case, since x is not 0, they cancel
and we can simplify the bottom case, its x, which is 0
so
Austin
So do you then also agree with this?
So if we want to show xf(x) = sin(x)
We have to show it for both cases
If 0<x<=pi
We’re already done, because it is sin(x)
Right?
Look here
you agreed with this
you said, this is xf(x)
right?
Okay yeah
and we want to show its equal to sin(x)
Yes
maybe it makes more sense to write this
$$xf(x)=\begin{cases} \sin(x) \quad 0<x\leq \pi \ 0 \quad x=0\end{cases} ?= \begin{cases} \sin(x) \quad 0<x\leq \pi \ \sin(x) \quad x=0 \end{cases}$$
Austin
because the thing on the right is just sin(x), yes?
just written case-wise, so you can compare them more directly
Okay
Does it make sense to write it like that or not?
Yeah I guess
If it doesn't make sense, what is confusing you
Okay, so now we want to show that they're actually equal not just "?="
we will go case by case
starting with the top case
Are they equal for 0<x<= pi?
The top and bottom to each other?
Oh
consider first when 0<x<=pi
yes
this means showing that the top lines of both sides
are equal
which of course they're
since they're both the same thing
Then consider when x=0
Uhm
yeah x times sin(0) is 0
xsin(x)
for x is 0
it’s just the 0?
yes its just the 0
Okay
We showed that earlier
well yes x*f(x) is 0 for x is 0
So it’s true for both upper and lower case
what is it when x=0?
which case
I said "when x=0"
It’s 0
because 0*1=0 and sin(0)=0
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i need help understanding how completing the square can be used to find the vertex of parabolic equation
u know the genral form of the parabola?
u have to compare the genral form with the final eq
Completing the square converts the parabola from standard form (ax^2 + bx + c) to vertex form (x-h)^2 + k. And in vertex form the coordinates can be found simply as (h, k)
@royal escarp Has your question been resolved?
<@&286206848099549185>
hey
you pinged helpers ?
@royal escarp i saw your ping i js was helping another guy with potential energy
took ages having to explain it
hey mate u there ?
yeah
ppl ask for chemistry
physics
and other stuff commonly
may i ask what your inquiry was ?
id love to help
btw sry for the wait
i need help understanding what k is algebraically in vector form
may i ask for what level
is this o levels or a levels
if so what type of vectors ? do you mean the vectors in triangles
in further mathamatics
i have some notes on this
just gotta ask
what level of studies are you attending
is this for 16-18
or 14-16
because vectors change drastically
sorry im not sure what that is exactly
vectors are in both pre calc and calc
pre calc
makes sence but what system do you attend
correct
may i ask for the question you wish to have help with ?
i want help with the general idea
pardon ?
but i can provide a question if that would help
nah its no problem
vertex
not vector
i thought i had to do vectors of a parabola
ight so u know how there are quadratic functions right
the general graph is something called a parabola
a parabola graph is a graph which is used when dealing with quadratic functions as it has 2 x values
so look
the parabola has the axis of symetry the vertex and the y intersept
its the highest or lowest point depending on which side the parabola is on
ax^2 + bx + c
hmmm could you provide an example question
ahh makes sence
yeah
(x-h)^2 + k
to find the vertex from the two points right ?
where h and k are the vertex
sorry what ?
k
$(x - h)^2 = x^2 - 2hx + h^2$ do you mean this ?
Exornion
mate
you got it all wrong
when they tell you to graph it
they mean to draw the parabola
I'm aware
there cant be 2 vertexes though
But you need certain information to graph it don't you?
you get that from the equation
ahh makes sence
Since that's what I'm having trouble grasping
but let me help you here
all the points of the graph can be found
i have quite a lot of notes from my gcses
on this self same subject
first off
the parabola opens upwards
because the coefficent is positive
How
$x = -\frac{b}{2a}$
Exornion
for the given formula
a is 2
and b is 4
so x is -1
the parabola starts at -1
it intersects the 2 points
what about the y value
wait let me find the other thingy
ill do it rn
so look
you Substitute x = -1 back into the function to find the y-coordinate of the vertex:
f(-1) = 2(-1)^2 + 4(-1) + 3 = 2(1) - 4 + 3 = 1
see this
i tried to write it well
but it isnt so neat
but its equal to 1
so the vertex is at (-1,1)
@royal escarp
is this good enough ?
i could clarrify more
if you need me to
its -2,1
;-;
sry mb
i miscalculated
i went a bit fast
havent done 2d quadratic functions in a while
look u want the steps to graph a quadratic function
i can send an image of my past notes
this is a gbig help
actually no
its suppossed to be -2,-1
oh mb i alr sent
but there are the steps
sry for the mistake
have a good one mate !
also use .close when you are done
.close
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Not only did my teacher tell me that this function (x^2+y^2=y) is not implicit
He also said that we cant simplify it and turn it to non-implicit using quadratic formula
I need clarifications 🤨
Y is a function of x btw
how are you defining implicit and explicit?
i believe explicit is when you can algebraically rearrange for y to equal only a function of x
and implicit is anything else
Explicit: you can seperate y from x without having y in the product
Implicit is everything else
Like y=2+3x is explicit
Y=2+3xy^4 is implicit
Idk if thats the same thing 😭
But here
It is the same thing
@torn shale Has your question been resolved?
That means my teacher was wrong yeah?
it is implicit
What abt it being simplifiable with quadratic
but it's defined a bit differently (more generally) than the way you defined it
and how exactly would you do that?
Ah
yeah, you can't
you'd need -2xy for this to be a perfect square
and you have -y
also the quadratic formula doesn't apply here
Idk how to perfect square studd
well it's not a quadratic is it?
Isnt it 😭
But like
Isnt c is the coefiicent of y^0
Whats wrong eith applying it there
in one variable, that is
Why cant we consider x^2 as c
I mean, you could technically factorize this but
I don't see why you would want to
you get a very very messy answer
also it'll only be defined for a specific domain
.?
Oh hmm
$\left( y - \frac{1 + \sqrt{1 - 4x^2}}{2} \right) \left( y - \frac{1 - \sqrt{1 - 4x^2}}{2} \right) = 0$
45
no this is the factorization of y^2 + x^2 - y as two binomials
But it follows the same steps as this and gives the same answer
you can consider x^2 as c yeah
as a constant
however
note that
for the solutions of this to be real
we need a non-negative discriminant
1-4x^2 is equal to or bigger than 0
so the factorization is only valid for $x \in \left[-\frac{1}{2}, \frac{1}{2}\right]$
45
yeah
Ok so the answers for my questions are: yes the function is implicit and it we can factorize but with a certain domian
Would it be explicit
After we factorized it
$y$ would be expressed directly as a function without having it set to zero, if it were explicit
45
so no, it's implicit
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Im not sure where i'm going wrong for part b
this is telling you "if you go up in the air then go back down, you end up back where you started"
if the ball is at its highest point, what would its velocity be
(its velocity wouldnt be -5)
omg im so stupid
0
yea
np
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Hi, is there any difference in way this is solved (i mean is my calculation correct?) second photo is another example solved by professor
@regal roost Has your question been resolved?
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Goofing up a bit with that question 7
I think I'm supposed to use an inverse trig substitution but what exactly
Have you ever learned about separable equations?
hint:- if $\frac{dy}{dx}= f(x$, it's the same as $dy = f(x) dx$
dy/√9-y² = xe^x dx
ƒ(Why am. I here)=I don't Know
Yeah I got past that
for DEs
Bi parts integration
oh, x= 3 __ should work
And dy part one step
what do you think x should be ?
I'm struggling with the integral of dy/root(9-y^2)
1/√(a²-x²) = sin^-1 x/a
I think Im getting somewhere
This is formula
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
You can derive by assuming x = 3sinø
this isn't a formula everywhere
Hey thats a formula
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oh sec i see i did some minor errors in the 2nd line. THis is the correct one:
here the correct one
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Can anyone explain fifth euclid postulate?
Hello i need help with ona radicals
This is ciup's help channel, you need to open your own
Ok sorry
Which is the fifth one?
Ohh i understood
wikipedia seems to have a decent article with a picture: https://en.wikipedia.org/wiki/Parallel_postulate
So the fifth one says we extends lines on the side which those sum of interior is less than 180°
They will intersect each other after some time
The important bit is that they will intersect to the side where the angles add up to less than 180°
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I just for the life of me cannot wrap my head around this.
I know that the rref is 1s down the diagonal, but how do I pull scalars from a bunch of 1s???
Any prompt assistance greatly appreciated. Test in 10 minutes.
Right
So they can be linearly independent
I don't know how to get the scalars.
You know
I really don't. I wouldn't have asked the question if I did.
Doesn't that defeat the purpose of using matrices if I'm going to solve it algebraicly?
You need fast answer ?
Bro What :
I think its done that way
What's the point of rref'ing if I don't even use the matrix?
That's the entire point of this class.
you see we get trivial solution if we try solve using matrix method
Right.
But how can I use a matrix to get the scalars
Just seems insanely backwards if they're teaching us all these things specifically to find scalars, then you can't use those tools to find these specific scalars.
I did it this way and just got a bunch of 0s.
Cuz 3x1+2x2=0 and -x1-x2=0
So (3x1+2x2)+3(-x1-x2)=0, and -x2=0
Which then gives me x1=0, and x3=0
Test time. Rip me
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if you want to do it more matrix-y, you can rewrite the additions as multiplications of 2 matrices, and then used methods like row echelon form or finding its determinant to find out if they're linearly independent or not
but there's nothing wrong with writing a system of equations and simply solving them for the unknown variables
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what's the question?
ah
hindi 💀 , btw this is like a 4th grade ques
Did you read my explanation?
what explanation?
this shit ain't no explanation
bro what standard? your english broken asf
If you can't read
Good more than your average english
bro why you getting riled up? 💀, you can type in hindi, I understand
...
bro why yall Indians get all riled up & defensive? like yall straight up start hurling curses or some zesty ahh replies, this is a math server tho, so I wouldn't respond further, good luck
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Sketch the graph of a function on [-1, 2] that has a local maximum but no absolute maximum
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
you know what local and absolute maximums are yes?
kind of but not really,,, here's' what i think i know..
local max and min are beginning and endpoints if closed [], and if there is a point on the graph it can be a local min or max, also if there are dips or waves then that is also a local min/max
absolute im not certain
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
the question i wrote is the origina;
do you know of a function on some interval that has no absolute maximum?
no
then there is no such function
ah sorry you're right
here is an example of a function that has no absolute maximum: 1/x on the interval (0, 1]
Sketch the graph of a function on [-1, 2] that has a local maximum but no absolute maximum
this is my question.
Also, since it only asks you to sketch it, I'd assume it doesn't want you to give an algebraic expression for it.
So you can just "draw anything" that fits the description
yeahh
but idk how not to draw an absolute max
my TA said theres always an absolute max
he is obviously wrong
not when the function isn't continous
only if you assume continuous like belabutter said
ok what would that look like on a grapph then lol
here's a simple example



