#help-38
1 messages ยท Page 125 of 1
Good job
YAY
Yeahhh?
Yeah
We have to count squares
Okay
Count the squares
HUH?
YOU GOT THE VALUES
WHAT U MEAN?
nvm keep going perseus
U got it
Ok slow down
So to measure gradient
Yeah
We need rise/run
Okay okay
Yes yes
Do the math
Do I divide 2 by 6?
Erm
If ur allowed a calculator use it
0.33
Huh
Ok nvm
What is that
Just take 0.333
Yes
wait is 3SF the 3 decimal places
That not important
Off topic
Okay okay
Yeah
Is going downwards
Yeahh
no i pulled it out of my ass
Right?
sorry ill shut up
So the gradient is negative
What?
what the
Midpoint
Shut up
(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})
What the fuck
What u mean?
just put in the axis
faiyrose
Brother
Whatโs that
@harsh surge Iโm going mad
TeXit
Huh
Teach them
so to get the mid point coordinates
Iโm tweaking
Okay
its asking you to get the midpoint of
How many years did you retain?
whats the coordinates
Just curious
Nuh uh
she lied about that shit
Boy
oh
What did that say
ic
Yeah
Yes
No
What do u understand from this
Anything?
Do I need to explain this through call ๐
dinkus
this?
Nothing
Yeah
2,9
nice now P1
hav fun
8,7
Okay okay
so out of those two coordinates you have
Yeah
dinkus
Huh
HAHAHHA
dinkus
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
SANDRA HOW IS IT GOING
Huh
one sec
LMAO
IDK
DO U UNDERSTAND
$(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$
dinkus
Yes
do you know how to put this into your calculator
No

click brackets
get an open and closed bracket
do you know how to use the fraction button
๐
Huh
How old r u brother
me?
Yea
Is it 5
uhh its me the evan guy
one sec
oh good job
faiy tell me
how the bot works
$(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$
Huh?
dinkus
Lmao
$(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$=
Ya Iโm done
dinkus
Have fun tho
Erm
8
it looks like you taught her rise/run ๐
Yep
Result:
3
,calc $(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$
The following error occured while calculating:
Error: Syntax error in part "\frac{8+2}{2}, \frac{7+9}{2})$" (char 16)
What is that
Result:
5
Huh?
,calc (7+9)/2
Result:
8
im half asleep rn

How did u get the 5,8
faiyrose
Oh okay okay
faiyrose
faiyrose
I dunno
AYO
Twinning
Ayo?
Boy what?
im actually done
Wait what?
sandra you need to start listening in class
distance trust guys
HOLYSHIT
BEO WHAT

I GOT TIMED OUT FOT ACCIDENTLY SAYING THE N WORD
OH MYGOSH
EVACHI
WHAT THE FLIP
TWIN BROTJER
SHUT UP
ITS U
NO WAY
BRO I THOUGHT U WERE SOME RANDO
:?
I donโt know
$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$
dinkus
What the hellll
How do I do that
Wait what
Let me see
ill sub it in for you
is it the same
$d = \sqrt{(8- 2)^2 + (7-9)^2$
dinkus
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Idk
$d = \sqrt{(8- 2)^2 + (7-9)^2$
dinkus
$d = \sqrt{(8- 2)^2 + (7-9)^2$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.49 $d = \sqrt{(8- 2)^2 + (7-9)^2$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
I donโt know how to work that
oh
What happend
$d = \sqrt{(8- 2)^2 + (7-9)^2}$
dinkus
Why does urs and mine look wrong
we subbed in the values
Different
i used the values from the thing you gave me
Did I do it wrong
Girl
$d = \sqrt{(8- 2)^2 + (7-9)^2$
dinkus
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Wiat guys
$d = \sqrt{(8- 2)^2 + (7-9)^2}$
I read the thing wrong
dinkus
Thas my bad
NO I DID ITWRING
its asking for x2 first
I REDA IT WRING
Oopy poopy
there
dinkus
now solve
Okay
Wait how do I put that in my calculator?
Is it 6.324
calc, $d = \sqrt{(8- 2)^2 + (7-9)^2}$
dinkus
what hte sigma
Em what the flip
,calc $d = \sqrt{(8- 2)^2 + (7-9)^2}$
The following error occured while calculating:
Error: Syntax error in part "\sqrt{(8- 2)^2 + (7-9)^2}$" (char 6)
๐
Ya cause itโs impossible
ik
Result:
6.3245553203368
the anser
here
Yayyy
Okay okay
Frick u
Huh
uhh
Tf is that
one sec
What is starlight
Not this
kms
Bro I gotta get this
My exam Tommorow
Yeahh
non linear is like a curve
Hat is a starlight line?
in your exam use a ruler for linear but sketch the non linear by hand
if you want marks
Wait nvm I read it wrong
wdym
Okay okay
ok
Okay okay
for this
Huh
Whatโs that

Okay then
Let me fail my maths exam
Can somebody help with this
<@&286206848099549185>
In probability if it is AND u multiply
If it is OR u add
For R,1
What is probability ull get R out of R and B?
Good luck I spent half an hour explaining gradient 
Did u understand the question?
No
is anyone here a mathematican from college or institute
There are two things
Can somebody help with this, even with the correction i canโt understand
1st one is he either chooses red or blue
Second one is he either chooses 1,2,3 or 4
R,1 means
He chose red in 1st case and 1 in second case
Do u know what probability means?
What
Wait I donโt get that
Yes yes Iโm pretty sure
Ok lemme ask u a simple question
Okay
Yeah
What is the probability that ull get 4
1/6?
Yeah?
Oh okay
1/4?
Okay okay
Huh
And
Multiply it
How do I do that?
Do I multiply the 1/4 and 1/2?
Yes yes
Okay oka
That is the probability of R,1
Whaaaaaaaaat
Do it on ur own smh
Itโs that one
Boy cause I donโt get what u mean
Wdym u don't get what I mean?
How do I multiply it

I get it lol
Yeaaโฆ
@wraith hinge
What do u not understand?
This math video tutorial explains how to multiply two fractions together.
Fractions - Basic Introduction: https://www.youtube.com/watch?v=3TklZi6MeJ4
Adding Fractions - Unlike Denominators:
https://www.youtube.com/watch?v=5fbzZEK77DQ
Subtracting Fractions:
https://www.yo...
How do I do that
HELP ME
NO WAY
BRO
IM SO DUMB
THATS MB
I remember learning that oops
Just watch the video ig
So is it 1/8?
Which one
The one I explained u rn
No
What the flip
Oh what?
How the hell u didn't know what I was explaining
I thought u were explaining how to do the first thing
Wait then how do I do the first thing
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How can you tell if a function such as this one has an oblique asymptote?
but i would like to know in general, when should i search for an oblique asymptote with f(x)/x and f(x)-ax
@livid inlet Has your question been resolved?
if you just look at the highest power of x, then that is $\sqrt[3]{x^3} = x$ so we would expect an oblique asymptote
cloud
so because you have x
that is basically like a cartesian definition
so to + infinity on the x-axis it also goes to + infinity on the y-axis for example?
well no, because it has a negative sign in the actual equation
ah yes but in general
if it goes to +infinity and it has something like that x then it could go into + infinity on the y axis which is what y=x looks like
but we would also shoot off to infinity with something like $\sqrt[3]{x^2}$ and that does not have an oblique asymptote, because the function does not behave like $x^1$
cloud
that would tend to have more like a horizontal asymptote right?
it would look somewhat "horizontal" but it would not have a horizontal asymptote
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Send your question here to claim the channel.
Remember:
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โข Show your work, and if possible, explain where you are stuck.
โข After 15 minutes, feel free to ping <@&286206848099549185>.
โข Type the command .close to free the channel when you're done.
โข Be polite and have a nice day!
Read #โhow-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hi everybody,
Is someone available to help me with factorization?
@surreal totem Has your question been resolved?
Nope
no
Do you have a specific question you need help solving?
do you still need hel
@surreal totem Has your question been resolved?
Hey man, thank you for your response. Yes, I need help. I use an iPad where I can share you my screen
Can we connect through zoom, skype or Google meet? also if I can share you my screen here I'd be happy to learn how. It would be great if we discussed the subject lively. (I am not very good at maths)
Please, take a look a this. I tried to make some advances on my own but the problem is that I don't quite understand how the logic of the formulas connect with what I have wrote or with the example.
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Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
โข Ask your math question in a clear, concise manner.
โข Show your work, and if possible, explain where you are stuck.
โข After 15 minutes, feel free to ping <@&286206848099549185>.
โข Type the command .close to free the channel when you're done.
โข Be polite and have a nice day!
Read #โhow-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
F(x)=1+x , r(x)=x^2 , whats the domain of f(r(x))
So the rule is
Mutual donain between the two functions (^ looking sign that idk the name of) the domain of f(r(x))
Oh right i forgot
F(x) has domain [-2,3]
r(x)โs domain is [0,2]
ok so
Mutual domain is [0,2] and the domain od f(r(x)) is R (bc its x^2+1)
So the answer must be [0,2] ^ R
Which is [0,2]
But it is incorrect.
Why?
The original question wanted f(r(2)) but appearantly 2 is not a part of tge domain so the answer is undefined)
But 2 is a part of the domain here
@torn shale Has your question been resolved?
this is not how domain works
r(x) = x^2's domain is [0, 2]
then find the range of r(x)
the range of r(x) is not R
because the domain of r(x) is not R
the domain of r(x) is only [0, 2]
that limits what numbers you can use to only be from 0 to 2
so that limits what range r(x) can have
figure out the range of r(x) then ping me
Why do we need the range? @proper kernel the way i was taught used this
Which requires no range
well you got it wrong
do you want to try out an answer to see if what Im saying about range works out
Ok i understand
I understand why range of r(x) is not R
before that though, you said you know [0, 2] is incorrect
are you able to check a different answer
you would need to be taught range to do it my way, so theres a disconnect here
But i dont understand whT it has to do with the question
we're not there yet
for now, lets see if the question would even accept using this method as the answer
Ok do you want me to find the range of r(x)
Kk
are you able to check a different answer
you would need to be taught range to do it my way, so theres a disconnect here
Listening
Wdym check a different answer
you said you know [0, 2] is incorrect
Yes
that means you can check answers
what does the answer sheet say then
The answer is [0,2[ i think
its on the shset, theres no need for "I think"
Ah- theres a little issue
Welll
The question is asking about
F(r(2)) actually
And the answer to that is โundefinedโ
And this 2 is not a part of the domain
hold on there
one step at a time
youre going too fast for yourself
first off, what's r(2)
And thus [0,2] cant be the answer
so F(r(2)) is F(4), right
Yes
now is 4 in the domain of F?
No
so what would F(4) be?
Undefined
now would you like to know more about this
What doed this have to do with the question ๐ญ
Yea
??????
bro
the questions asks for F(r(2))
slow โ confident
Yes ok i understand
I dont see you slowly rereading
I see you asking questions without bothering to try answering them yourself
I understand why the answer is undefined
and thats literally it
But i dont understand why my solving is incorrect
your solving has nothing to do with this
so your solving cant be on the right track
F(r(2)) would be a number or would be "Undefined"
you dont say F(r(2)) is "[0, 2]"
already thats weird to say
you mean something else
No i just want to use the formal way yk i wanna use the rule
I just showed you the formal way
the formal way is "F(r(2)) = F(4) = undefined" and that is the end of the formal way
you mean something else
nothing that you did had anything to do with the original question
this does
please understand
Can you use this to find the domain of f(r(x)) (in interval form)
thats a better question
Yesss but i want the domain
to figure that out, we now need to consider that r(x)'s range isnt R
now we have an example of that
you saw F(r(2)) didnt work
That was my question from the start ๐ญ
shouldve said so
Yes
even though 2 is inside [0, 2]
Aha
the real reason you saw was that r(2) = 4 was not in [-2, 3]
so F(r(x)) has a different domain than just F(x) or r(x)
Yes
its smaller than F(x)'s domain
Bc the 4 is the codomain (range) so it doesnt have to be in the domain.. or does it idk
Wait
No
youre close
youre messing up the words but thats expected
youre close to the idea
4 is in the range of r(x)
Lemme read what u said
but 4 is not in the domain of F(x)
on second thought we could just repeat what weve said before so you dont have to bother reading all of it
Ive already repeated the same info too many times so its not convenient
Im sorry ๐ญ
nah dw
Yes
I get this
And is why we have use the rule ๐คฉ
"The" rule?
This
mtt
youre trying to intersect two things
one of them is [-2, 3]
the other one is the range of r(x), knowing the domain is just [0, 2]
Mhm?
so what's the range of r(x), knowing the domain is just [0, 2]
We get the intersect between domain of f and the range of r
Ah idk how to get the range algebrically
Lemme graph
Zero to infinity?
remember the domain is [0, 2]
whats the biggest number in the domain
Exactly 2
now think that r(x) squares numbers
then look at the domain again
that would mean 2^2 is the biggest number in the range, right
you didnt need to graph that too
Im dumb i didnt consider the domain
so you can get that the range of r(x) is [0, 4]
go ask if you need a recap, but I think you have enough to find the domain of F(r(x)) now
Ok intersect between [-2,3] and [0,4]
thats correct
Ok i did it
What now
back
yep [0, 3] is the domain of F(r(x))
wait
nvm [0, 3] is not the domain of F(r(x))
what we got for [0, 3] is the middle step
Yes
now youre looking for the domain
you know [0, 3] is an acceptable range for r(x) and an acceptable domain for F(x)
Of f(r(x)) yes
Yes
so have [0, 3] be the range of r(x)
then work backwards to find out what the domain of r(x) is
already you have [0, 3] to tell you the middle step of F(r(x))
so working backwards will tell you the beginning step of F(r(x)), otherwise known as the domain
this wont make much sense for now since you interrupted earlier, but for now stick with the steps
I mean- they gave it to us
no no
let me repeat
if [0, 3] is the range of r(x),
then 2 cant be in r(x)'s domain anymore
because 2^2 isnt in [0, 3] is it
so what would the smaller domain of r(x) have to be
for the range to only be [0, 3]
Omg ez
Question mark?
yea its the smaller domain that makes it okay to put into F
the larger [0, 2] domain had a 2 which didnt fit
we made the domain of r(x) smaller
so that way the range of r(x) is [0, 3]
Aha then how is f(r(x)) is also from 0 to sqrt3
I am
Domain
Oh i interrupted you
[0, โ3] is the domain we chose for r(x)
Yes
so lets see what happens after r(x) happens
you can pretend r([0, โ3])
= [0, 3]
this is short for "r(a number inside [0, โ3]) = a number inside [0, 3]"
now we chose [0, 3] because its in the range of r and the domain of F
so we do F([0, 3])
you saw that [0, 3] only uses numbers inside F's domain of [-2, 3]
so that means we dont have any problems like with 4
so that means F([0, 3]) = [1, 4] with no exceptions
Thats f(r(x)) right
Tbh- you lost me here
youre rereading past stuff again
if youre doing that, you shouldnt be interrupting from the beginning
do you want the full explanation
How is r[ 0 to sqrt3] is [0,3]
I interrupt when you say smth that i dont understand
you said you were OK with that earlier
the specific question you chose said you didnt want to understand
didnt figure it would play into anything
have you changed your mind or should we continue with this
I understand why [0 to sqrt3] is in [0 to 3]