#help-38

1 messages ยท Page 125 of 1

wraith hinge
#

A line

cyan nebula
#

Good job

wraith hinge
#

YAY

cyan nebula
#

When u get a like

#

Line

wraith hinge
#

Yeahhh?

cyan nebula
#

A line has a steepness

#

That we call

#

Gradient

wraith hinge
#

Yeah yeah

#

Okay okay

cyan nebula
#

Good

#

Can u show the original question

wraith hinge
#

Okay

cyan nebula
#

So to find a graduate

#

Gradient

wraith hinge
#

Yeah

cyan nebula
#

We have to count squares

wraith hinge
#

OKY okay

#

Do we ake that triangle thing?

cyan nebula
#

What

#

Whatโ€™s ake?

wraith hinge
#

Make

#

Typo

cyan nebula
#

Yes

#

So make the triangle

#

And show me

wraith hinge
#

Okay

cyan nebula
#

Count the squares

wraith hinge
cyan nebula
#

And show me

#

Count the squares

wraith hinge
strange fog
#

NO WAY

#

HE DID IT

wraith hinge
#

HUH?

strange fog
#

YOU GOT THE VALUES

wraith hinge
#

WHAT U MEAN?

cyan nebula
#

Good jov

#

Job

strange fog
#

nvm keep going perseus

rough frost
#

U got it

wraith hinge
#

Okay okay okayyy

#

Do I do 2/6?

#

Or something

#

And you get like

cyan nebula
#

Ok slow down

wraith hinge
#

Do I simplify it

#

What the gyatt

#

Okay nvm

#

Continue

cyan nebula
#

So to measure gradient

wraith hinge
#

Yeah

cyan nebula
#

We need rise/run

wraith hinge
#

Okay okay

cyan nebula
#

Rise is 2

#

Run is 6

wraith hinge
#

Yes yes

cyan nebula
#

Do the math

wraith hinge
#

Do I divide 2 by 6?

cyan nebula
#

Yes

#

Math

#

What is 2/6

wraith hinge
#

Erm

cyan nebula
#

If ur allowed a calculator use it

wraith hinge
#

0.33

cyan nebula
#

Take 3SF

#

3 significant figures

wraith hinge
#

Huh

cyan nebula
#

Ok nvm

wraith hinge
#

What is that

cyan nebula
#

Just take 0.333

wraith hinge
#

What

#

Okay

#

So 0.333?

cyan nebula
#

Yes

strange fog
cyan nebula
#

No

#

Iโ€™m not explaining that

strange fog
#

what is 3SF

#

please

#

now im curious

wraith hinge
#

Yeah what is that

#

Okay whatever

cyan nebula
#

Not teaching

#

That

wraith hinge
#

That not important

cyan nebula
#

Off topic

wraith hinge
#

Okay okay

strange fog
#

is it about orunding

#

the decimal places

#

thats all i wanna know

wraith hinge
#

So is the gradient 0.333

#

Evan use Google

cyan nebula
#

Yes

#

But since

#

The slope

wraith hinge
#

Yeah

cyan nebula
#

Is going downwards

wraith hinge
#

Yeahh

strange fog
cyan nebula
#

Right?

strange fog
#

sorry ill shut up

cyan nebula
#

So the gradient is negative

wraith hinge
wraith hinge
#

So -0.333?

cyan nebula
#

Yes

#

Thatโ€™s ur answer

wraith hinge
#

Okayokayyy

#

Now what is midpoint

strange fog
#

what the

cyan nebula
#

Midpoint

strange fog
#

wait

#

one second

#

nothing

cyan nebula
#

Shut up

wraith hinge
#

I agree

#

๐Ÿ˜

strange fog
#

(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

wraith hinge
#

๐Ÿ˜›

#

โœŒ๐Ÿฟ

wraith hinge
strange fog
#

its fucked

#

wait

#

thers no point in teaching midpoint

#

its just a formula

wraith hinge
#

What u mean?

strange fog
#

just put in the axis

solid kilnBOT
#

faiyrose

wraith hinge
#

Okay so u want me to skip the whole part of midpoint on my exam?

#

Good job

cyan nebula
#

Brother

wraith hinge
strange fog
#

oh

#

thanks

#

i didint know you can do that

cyan nebula
#

@harsh surge Iโ€™m going mad

strange fog
#

TeXit

wraith hinge
#

Huh

cyan nebula
#

Teach them

strange fog
wraith hinge
#

Iโ€™m tweaking

strange fog
#

pull up the grapgh

#

with the line

wraith hinge
#

Okay

strange fog
#

its asking you to get the midpoint of

wraith hinge
#

This

strange fog
#

so

#

on p2

cyan nebula
#

How many years did you retain?

strange fog
#

whats the coordinates

cyan nebula
#

Just curious

wraith hinge
#

Like

#

4

#

I think

strange fog
#

shes in grade 9

wraith hinge
#

Nuh uh

strange fog
#

she lied about that shit

wraith hinge
#

Boy

cyan nebula
#

oh

wraith hinge
#

What did that say

cyan nebula
#

ic

wraith hinge
#

Okay whatever

#

Wait so how do I do idpount

#

Mid

cyan nebula
#

Ok

#

So

#

Midpoint

wraith hinge
#

Yeah

cyan nebula
#

Midpoint

#

Is the middle

#

Of the line

#

Easy to understand

#

?

wraith hinge
#

Yes

cyan nebula
#

Good

#

Now how would you go about finding that

#

Any idea?

wraith hinge
#

No

cyan nebula
#

Anything?

#

Do I need to explain this through call ๐Ÿ’€

ocean flame
#

what the fuck is this

#

$(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

solid kilnBOT
#

dinkus

ocean flame
#

so midpoint = p1/2,p2/2

#

wheres your question

#

@wraith hinge

ocean flame
wraith hinge
ocean flame
#

alright

#

so

wraith hinge
#

Yeah

ocean flame
#

tell me the coordinates of p2

#

with that brain of yours

wraith hinge
#

2,9

ocean flame
#

nice now P1

cyan nebula
#

hav fun

wraith hinge
#

8,7

ocean flame
#

so now you have the points sandra

wraith hinge
#

Okay okay

ocean flame
#

so out of those two coordinates you have

wraith hinge
#

Yeah

ocean flame
#

sub them into this formula

#

$(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

solid kilnBOT
#

dinkus

wraith hinge
#

Huh

cyan nebula
#

Watching

ocean flame
#

shit

#

alright sandra

cyan nebula
#

HAHAHHA

ocean flame
#

you see

#

so the points are

#

2,9 and 8,7

#

lets sub it into this formula

wraith hinge
#

Is it that

#

Or am I wrong

ocean flame
#

good job

#

now one sec

#

$(x_m, y_m) = (\frac{8+2}{2}, \frac7+9}{2})$

solid kilnBOT
#

dinkus
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

rough frost
#

SANDRA HOW IS IT GOING

wraith hinge
#

Huh

ocean flame
#

one sec

cyan nebula
#

LMAO

wraith hinge
rough frost
#

DO U UNDERSTAND

wraith hinge
#

I DUNNO

#

MAKING PROGRESS

ocean flame
#

$(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$

solid kilnBOT
#

dinkus

ocean flame
#

there yah go

#

weve subbed it in

#

do you have a calculator with you?

wraith hinge
#

Yes

ocean flame
#

do you know how to put this into your calculator

wraith hinge
#

No

cyan nebula
ocean flame
#

click brackets

#

get an open and closed bracket

#

do you know how to use the fraction button

ocean flame
wraith hinge
#

Huh

ocean flame
#

shush im tryna teach her

#

wait

#

can you tell me how to make texit solve it

cyan nebula
#

How old r u brother

ocean flame
#

me?

cyan nebula
#

Yea

wraith hinge
#

Is it 5

ocean flame
#

uhh its me the evan guy

#

one sec

#

oh good job

#

faiy tell me

#

how the bot works

#

$(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$

wraith hinge
solid kilnBOT
#

dinkus

ocean flame
#

how i solve this

#

get the bot to

cyan nebula
#

Lmao

ocean flame
#

$(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$=

cyan nebula
#

Ya Iโ€™m done

solid kilnBOT
#

dinkus

cyan nebula
#

Have fun tho

wraith hinge
#

Erm

ocean flame
#

thank you for trying

wraith hinge
#

8

ocean flame
#

it looks like you taught her rise/run ๐Ÿ’€

cyan nebula
#

Yep

solid kilnBOT
#

Result:

3
ocean flame
#

,calc $(x_m, y_m) = (\frac{8+2}{2}, \frac{7+9}{2})$

solid kilnBOT
#

The following error occured while calculating:
Error: Syntax error in part "\frac{8+2}{2}, \frac{7+9}{2})$" (char 16)

wraith hinge
#

What is that

solid kilnBOT
#

Result:

5
ocean flame
#

so we got to segment it

#

i see

#

ok

wraith hinge
#

Huh?

ocean flame
#

,calc (7+9)/2

solid kilnBOT
#

Result:

8
ocean flame
#

theres y

#

so midpoint is 5,9

#

@wraith hinge

wraith hinge
#

Huh

#

How did u get that

ocean flame
#

my calculaters far away

#

i dont want it

#

mb

#

5,8

wraith hinge
#

Oh

#

BEO

ocean flame
#

im half asleep rn

wraith hinge
#

Why?

#

Samesies

cyan nebula
wraith hinge
#

How did u get the 5,8

solid kilnBOT
#

faiyrose

wraith hinge
#

Oh okay okay

solid kilnBOT
#

faiyrose

wraith hinge
#

Ohhh

#

So is that everything?

solid kilnBOT
#

faiyrose

wraith hinge
#

Then how do I do distance?

#

Did everybody leave ๐Ÿ˜”

#

Oh

#

What grade u in

ocean flame
#

distance

#

whats the distance formula

#

i alr forgot

wraith hinge
#

I dunno

ocean flame
#

AYO

wraith hinge
#

Twinning

wraith hinge
ocean flame
#

stfu

#

dont

#

stop

wraith hinge
#

Boy what?

ocean flame
#

fai your so mature

#

you talk in a mature manner

#

for you age

wraith hinge
#

Who

#

Huh?

#

What u mean?

ocean flame
#

im actually done

wraith hinge
#

Wait what?

ocean flame
#

sandra you need to start listening in class

wraith hinge
#

Huh

#

Bro who r u?

ocean flame
#

whats the distance formula

#

ITS ME EVACIH

rough frost
#

distance trust guys

ocean flame
#

HOLYSHIT

wraith hinge
#

BEO WHAT

rough frost
#

HELO ME

#

NO WAY

cyan nebula
ocean flame
#

I GOT TIMED OUT FOT ACCIDENTLY SAYING THE N WORD

wraith hinge
#

OH MYGOSH

rough frost
#

EVACHI

wraith hinge
#

WHAT THE FLIP

rough frost
#

TWIN BROTJER

ocean flame
#

SHUT UP

rough frost
#

ITS U

wraith hinge
#

NO WAY

ocean flame
#

ITS NOT THAT DEEP

#

SHUSH

#

NOW WHATS THE DISTANCE FORMULA

rough frost
#

Distance formula is the one of the square root

#

WAIR

wraith hinge
#

BRO I THOUGHT U WERE SOME RANDO

ocean flame
#

:?

wraith hinge
rough frost
#

here

ocean flame
#

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

solid kilnBOT
#

dinkus

ocean flame
#

there

#

thats the distance formula

wraith hinge
#

What the hellll

ocean flame
#

so its just subbing in the values

#

like last time

wraith hinge
#

How do I do that

ocean flame
#

then solving it

#

wdym

wraith hinge
#

Wait what

ocean flame
#

tell me the coordinates

#

of the line

#

in the question

wraith hinge
#

Let me see

ocean flame
#

ill sub it in for you

wraith hinge
#

That was the old one

ocean flame
#

is it the same

wraith hinge
#

Wait ill put it in

#

Yah

#

Yeah

ocean flame
#

$d = \sqrt{(8- 2)^2 + (7-9)^2$

solid kilnBOT
#

dinkus
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

wraith hinge
#

Is it that

ocean flame
#

$d = \sqrt{(8-2)^2 + (7-9)^2$

#

whats the error

wraith hinge
#

Idk

ocean flame
#

$d = \sqrt{(8- 2)^2 + (7-9)^2$

solid kilnBOT
#

dinkus

$d = \sqrt{(8- 2)^2 + (7-9)^2$
```Compilation error:```! Missing } inserted.
<inserted text> 
                }
l.49 $d = \sqrt{(8- 2)^2 + (7-9)^2$
                                   
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
wraith hinge
#

I donโ€™t know how to work that

ocean flame
#

oh

wraith hinge
#

What happend

ocean flame
#

$d = \sqrt{(8- 2)^2 + (7-9)^2}$

solid kilnBOT
#

dinkus

ocean flame
#

curly brackey

#

bracket

#

anyways

wraith hinge
#

Why does urs and mine look wrong

ocean flame
#

we subbed in the values

wraith hinge
#

Different

ocean flame
#

now we solved it

#

huh

wraith hinge
#

Yours and mine look different

ocean flame
#

i used the values from the thing you gave me

wraith hinge
#

Did I do it wrong

rough frost
#

Girl

wraith hinge
#

What

ocean flame
#

$d = \sqrt{(8- 2)^2 + (7-9)^2$

solid kilnBOT
#

dinkus
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

wraith hinge
#

Wiat guys

ocean flame
#

$d = \sqrt{(8- 2)^2 + (7-9)^2}$

wraith hinge
#

I read the thing wrong

solid kilnBOT
#

dinkus

wraith hinge
#

Thas my bad

ocean flame
#

wait idk

#

WAIT

wraith hinge
#

NO I DID ITWRING

ocean flame
#

its asking for x2 first

wraith hinge
#

I REDA IT WRING

ocean flame
#

so switch them around

#

$d = \sqrt{(2-8)^2 + (9-7)^2}$

wraith hinge
#

Oopy poopy

ocean flame
#

there

solid kilnBOT
#

dinkus

ocean flame
#

now solve

wraith hinge
#

Okay

ocean flame
#

just learn how to use your calculator

#

and sub in

#

the exam is not hard

wraith hinge
#

Wait how do I put that in my calculator?

ocean flame
#

square root X? button

#

then open bracker

#

2-8

#

power of 2

#

plus

wraith hinge
#

Is it 6.324

ocean flame
#

calc, $d = \sqrt{(8- 2)^2 + (7-9)^2}$

solid kilnBOT
#

dinkus

ocean flame
#

what hte sigma

wraith hinge
#

Em what the flip

ocean flame
#

,calc $d = \sqrt{(8- 2)^2 + (7-9)^2}$

solid kilnBOT
#

The following error occured while calculating:
Error: Syntax error in part "\sqrt{(8- 2)^2 + (7-9)^2}$" (char 6)

cyan nebula
#

Still here is crazy

ocean flame
#

shush

#

i hate you

#

you left

wraith hinge
#

๐Ÿ˜”

cyan nebula
#

Ya cause itโ€™s impossible

ocean flame
#

ik

wraith hinge
#

NO IT NOT

#

Filp u then

#

Is it flipping 6.324

ocean flame
#

here

wraith hinge
#

What the shit

#

Do I have to do that

ocean flame
#

you got it right

#

wait

#

i cropped out

solid kilnBOT
#

Result:

6.3245553203368
ocean flame
#

the anser

ocean flame
wraith hinge
#

Yayyy

ocean flame
wraith hinge
#

Okay okay

ocean flame
#

so

#

is that it?

#

.close?

#

do we

wraith hinge
#

NO

#

IM NOT DONE

ocean flame
#

what

#

๐Ÿ˜ฆ

#

what now

wraith hinge
#

What is that

#

The linerial

ocean flame
#

fuck

#

this

#

can somone

#

teach her

wraith hinge
#

Please eda

#

๐Ÿ™๐Ÿฝ๐Ÿ™๐Ÿฝ๐Ÿ™๐Ÿฝ

ocean flame
#

@cyan nebula

#

please

#

take my place

#

i need sleep

wraith hinge
#

Frick u

ocean flame
#

fube

#

so linear

#

means like straight

#

in simple terms

#

so plot this

wraith hinge
#

Huh

ocean flame
#

uhh

wraith hinge
#

Tf is that

ocean flame
#

one sec

wraith hinge
#

What is starlight

cyan nebula
#

Sorry

#

Ur not gonna get this in one night

cyan nebula
ocean flame
#

kms

wraith hinge
#

Bro I gotta get this

ocean flame
#

so sandra

#

linear function

wraith hinge
#

My exam Tommorow

ocean flame
#

is a set of plots

#

that make a straight line

wraith hinge
#

Yeahh

ocean flame
#

non linear is like a curve

wraith hinge
#

Hat is a starlight line?

ocean flame
#

in your exam use a ruler for linear but sketch the non linear by hand

#

if you want marks

wraith hinge
#

Wait nvm I read it wrong

ocean flame
#

wdym

wraith hinge
#

Mb guys

ocean flame
#

ok

wraith hinge
#

Okay wait

#

What this?

ocean flame
#

there

#

horrible

#

but just use this

ocean flame
wraith hinge
ocean flame
#

im

#

unn

#

@cyan nebula

ocean flame
wraith hinge
#

Huh

ocean flame
#

r1 r2 r3 r4?

#

i dont get the question

wraith hinge
#

Whatโ€™s that

ocean flame
#

im gonna get rest

#

ask somone else

#

sorry

#

i helped you a fair bit

wraith hinge
#

Oh okay

#

Gn

#

@cyan nebula

#

CAN U PLEASE HELP ๐Ÿฅบ

cyan nebula
wraith hinge
#

Okay then

#

Let me fail my maths exam

#

Can somebody help with this

#

<@&286206848099549185>

knotty quest
#

In probability if it is AND u multiply
If it is OR u add

#

For R,1

#

What is probability ull get R out of R and B?

cyan nebula
#

Good luck I spent half an hour explaining gradient bleakkekw

wraith hinge
#

What

#

I donโ€™t get how to get the r 1 and stuff

knotty quest
#

Did u understand the question?

wraith hinge
#

No

knotty quest
#

Ok so

#

Basically

lucid estuary
#

is anyone here a mathematican from college or institute

knotty quest
#

There are two things

royal mirage
#

Can somebody help with this, even with the correction i canโ€™t understand

cyan nebula
knotty quest
#

1st one is he either chooses red or blue

wraith hinge
#

Girl

#

Oh okay

knotty quest
#

R,1 means

#

He chose red in 1st case and 1 in second case

#

Do u know what probability means?

wraith hinge
#

What

wraith hinge
wraith hinge
knotty quest
#

Ok lemme ask u a simple question

wraith hinge
#

Okay

knotty quest
#

There are 6 numbers

#

1,2,3,4,5,6

wraith hinge
#

Yeah

knotty quest
#

What is the probability that ull get 4

wraith hinge
#

1/6?

knotty quest
#

Yea

#

Same thing here

#

R,1 means

wraith hinge
#

Yeah?

knotty quest
#

1st case he chooses red

#

And second case he chooses 1

wraith hinge
#

Oh okay

knotty quest
#

So what is the probability that he will choose red?

#

From red and blue

wraith hinge
#

1/2

#

?

knotty quest
#

Yes

#

And to choose 1 from 1,2,3,4?

#

Brb

wraith hinge
wraith hinge
knotty quest
#

Is it and or or?

wraith hinge
#

Huh

wraith hinge
#

And

knotty quest
#

Does the question say

#

Yes

#

What do u do?

wraith hinge
#

Multiply it

knotty quest
#

Yes

#

What will u get

wraith hinge
#

How do I do that?

knotty quest
#

What is the 1st one?

#

1/2

#

Second one?

wraith hinge
#

Do I multiply the 1/4 and 1/2?

knotty quest
#

Yes yes

wraith hinge
#

Okay oka

knotty quest
#

That is the probability of R,1

wraith hinge
#

Okay okay

#

One sec

#

How do I put that in a calculator

cyan nebula
#

Show pic of calculator

knotty quest
wraith hinge
knotty quest
#

Do it on ur own smh

wraith hinge
#

Itโ€™s that one

knotty quest
#

Y the hell u need a calculator

#

Which class are u in

wraith hinge
#

Boy cause I donโ€™t get what u mean

knotty quest
#

Wdym u don't get what I mean?

wraith hinge
#

How do I multiply it

knotty quest
#

How do u solve this

#

1/2 * 2

wraith hinge
#

Erm what

#

What is that

cyan nebula
knotty quest
#

What

#

U know probability

#

But u don't know basics of multiplication?

knotty quest
cyan nebula
#

Yeaaโ€ฆ

knotty quest
wraith hinge
#

Huh

#

I donโ€™t get it

knotty quest
#

What do u not understand?

wraith hinge
#

How to do it

#

1/2 x 1/4

knotty quest
wraith hinge
#

How do I do that

#

HELP ME

#

NO WAY

#

BRO

#

IM SO DUMB

#

THATS MB

#

I remember learning that oops

knotty quest
wraith hinge
#

So is it 1/8?

knotty quest
#

Yea

#

Thank god

wraith hinge
#

Oh okay okay

#

Then what do I do for the rest?

knotty quest
#

Did u understand?

#

This one

wraith hinge
#

Which one

knotty quest
#

The one I explained u rn

wraith hinge
#

Wait so that?

knotty quest
#

No

wraith hinge
#

What the flip

knotty quest
#

Girl u didn't understand which one I was explaining?

#

The hel

#

Hell

wraith hinge
#

What the flip

#

What u mean

knotty quest
#

I was explaining the

#

Outcomes one

#

R,1 thing

wraith hinge
#

Oh what?

knotty quest
#

How the hell u didn't know what I was explaining

wraith hinge
#

I thought u were explaining how to do the first thing

#

Wait then how do I do the first thing

knotty quest
#

-_-

#

Same way

wraith hinge
#

Huh

#

I donโ€™t get it

knotty quest
#

Can't help

#

I gtg

wraith hinge
#

Oh okay

#

.close

trim joltBOT
#
Channel closed

Closed by @spiral talon

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

livid inlet
#

How can you tell if a function such as this one has an oblique asymptote?

livid inlet
#

but i would like to know in general, when should i search for an oblique asymptote with f(x)/x and f(x)-ax

trim joltBOT
#

@livid inlet Has your question been resolved?

ionic pendant
#

if you just look at the highest power of x, then that is $\sqrt[3]{x^3} = x$ so we would expect an oblique asymptote

solid kilnBOT
livid inlet
#

so because you have x

#

that is basically like a cartesian definition

#

so to + infinity on the x-axis it also goes to + infinity on the y-axis for example?

ionic pendant
#

well no, because it has a negative sign in the actual equation

livid inlet
#

ah yes but in general

#

if it goes to +infinity and it has something like that x then it could go into + infinity on the y axis which is what y=x looks like

ionic pendant
#

but we would also shoot off to infinity with something like $\sqrt[3]{x^2}$ and that does not have an oblique asymptote, because the function does not behave like $x^1$

solid kilnBOT
livid inlet
#

that would tend to have more like a horizontal asymptote right?

ionic pendant
#

it would look somewhat "horizontal" but it would not have a horizontal asymptote

livid inlet
#

okay

#

Thank you for your help, cloud, I really appreciate it!

#

.close

trim joltBOT
#
Channel closed

Closed by @livid inlet

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

surreal totem
#

Hi everybody,

Is someone available to help me with factorization?

trim joltBOT
#

@surreal totem Has your question been resolved?

cedar anvil
#

Do you have a specific question you need help solving?

trim joltBOT
#

@surreal totem Has your question been resolved?

surreal totem
#

Hey man, thank you for your response. Yes, I need help. I use an iPad where I can share you my screen

#

Can we connect through zoom, skype or Google meet? also if I can share you my screen here I'd be happy to learn how. It would be great if we discussed the subject lively. (I am not very good at maths)

#

Please, take a look a this. I tried to make some advances on my own but the problem is that I don't quite understand how the logic of the formulas connect with what I have wrote or with the example.

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torn shale
#

F(x)=1+x , r(x)=x^2 , whats the domain of f(r(x))

torn shale
#

So the rule is

#

Mutual donain between the two functions (^ looking sign that idk the name of) the domain of f(r(x))

torn shale
#

F(x) has domain [-2,3]

#

r(x)โ€™s domain is [0,2]

#

ok so

#

Mutual domain is [0,2] and the domain od f(r(x)) is R (bc its x^2+1)

#

So the answer must be [0,2] ^ R

#

Which is [0,2]

#

But it is incorrect.

#

Why?

#

The original question wanted f(r(2)) but appearantly 2 is not a part of tge domain so the answer is undefined)

torn shale
trim joltBOT
#

@torn shale Has your question been resolved?

proper kernel
#

r(x) = x^2's domain is [0, 2]

#

then find the range of r(x)

#

the range of r(x) is not R

#

because the domain of r(x) is not R

#

the domain of r(x) is only [0, 2]

#

that limits what numbers you can use to only be from 0 to 2

#

so that limits what range r(x) can have

#

figure out the range of r(x) then ping me

torn shale
#

Which requires no range

proper kernel
#

well you got it wrong

#

do you want to try out an answer to see if what Im saying about range works out

torn shale
#

I understand why range of r(x) is not R

proper kernel
#

before that though, you said you know [0, 2] is incorrect

#

are you able to check a different answer

#

you would need to be taught range to do it my way, so theres a disconnect here

torn shale
#

But i dont understand whT it has to do with the question

proper kernel
#

we're not there yet

#

for now, lets see if the question would even accept using this method as the answer

torn shale
#

Ok do you want me to find the range of r(x)

proper kernel
#

no no

#

listen

torn shale
#

Kk

proper kernel
#

are you able to check a different answer
you would need to be taught range to do it my way, so theres a disconnect here

torn shale
#

Listening

proper kernel
#

you said you know [0, 2] is incorrect

torn shale
proper kernel
#

that means you can check answers

torn shale
#

Yes i have the answer sheet

#

For tge question

proper kernel
#

what does the answer sheet say then

torn shale
#

The answer is [0,2[ i think

proper kernel
#

its on the shset, theres no need for "I think"

torn shale
#

Welll

#

The question is asking about

#

F(r(2)) actually

#

And the answer to that is โ€œundefinedโ€

#

And this 2 is not a part of the domain

proper kernel
#

hold on there

#

one step at a time

#

youre going too fast for yourself

#

first off, what's r(2)

torn shale
#

And thus [0,2] cant be the answer

torn shale
#

Ah wasnt it x^2

#

So 4

proper kernel
#

so F(r(2)) is F(4), right

torn shale
#

Yes

proper kernel
#

now is 4 in the domain of F?

torn shale
#

No

proper kernel
#

so what would F(4) be?

torn shale
#

Undefined

proper kernel
#

thats why its undefined

#

thats all

torn shale
#

Yes

#

Aha

proper kernel
#

now would you like to know more about this

torn shale
#

What doed this have to do with the question ๐Ÿ˜ญ

proper kernel
#

bro

#

the questions asks for F(r(2))

torn shale
#

Listen listen

#

Im slow

proper kernel
#

slow โ‰  confident

torn shale
proper kernel
#

I dont see you slowly rereading

#

I see you asking questions without bothering to try answering them yourself

torn shale
#

I understand why the answer is undefined

proper kernel
#

and thats literally it

torn shale
#

But i dont understand why my solving is incorrect

proper kernel
#

your solving has nothing to do with this

#

so your solving cant be on the right track

#

F(r(2)) would be a number or would be "Undefined"

#

you dont say F(r(2)) is "[0, 2]"

#

already thats weird to say

#

you mean something else

torn shale
proper kernel
#

I just showed you the formal way

#

the formal way is "F(r(2)) = F(4) = undefined" and that is the end of the formal way

#

you mean something else

#

nothing that you did had anything to do with the original question

torn shale
proper kernel
#

thats a better question

proper kernel
#

to figure that out, we now need to consider that r(x)'s range isnt R

#

now we have an example of that

#

you saw F(r(2)) didnt work

torn shale
proper kernel
#

shouldve said so

torn shale
proper kernel
#

even though 2 is inside [0, 2]

torn shale
#

Aha

proper kernel
#

the real reason you saw was that r(2) = 4 was not in [-2, 3]

#

so F(r(x)) has a different domain than just F(x) or r(x)

torn shale
#

Yes

proper kernel
#

its smaller than F(x)'s domain

torn shale
#

Wait

#

No

proper kernel
#

youre close

torn shale
#

4 is not

#

Codomain

proper kernel
#

youre messing up the words but thats expected

#

youre close to the idea

#

4 is in the range of r(x)

torn shale
#

Lemme read what u said

proper kernel
#

but 4 is not in the domain of F(x)

proper kernel
#

Ive already repeated the same info too many times so its not convenient

proper kernel
#

nah dw

torn shale
#

Aha

torn shale
#

I get this

#

And is why we have use the rule ๐Ÿคฉ

proper kernel
#

"The" rule?

proper kernel
#

the ^ looking sign is called "intersect"

#

so $\cap$

solid kilnBOT
proper kernel
#

youre trying to intersect two things

#

one of them is [-2, 3]

#

the other one is the range of r(x), knowing the domain is just [0, 2]

proper kernel
#

so what's the range of r(x), knowing the domain is just [0, 2]

torn shale
#

We get the intersect between domain of f and the range of r

#

Ah idk how to get the range algebrically

#

Lemme graph

#

Zero to infinity?

proper kernel
#

remember the domain is [0, 2]

torn shale
#

Yes

#

It is

proper kernel
#

whats the biggest number in the domain

torn shale
#

Exactly 2

proper kernel
#

now think that r(x) squares numbers

#

then look at the domain again

#

that would mean 2^2 is the biggest number in the range, right

torn shale
#

Omg

#

Yes

proper kernel
#

yep

#

0^2 would then be the smallest

torn shale
#

Yes

#

Ok the range is 0 to 4 wow

proper kernel
#

you didnt need to graph that too

torn shale
#

Im dumb i didnt consider the domain

proper kernel
#

so you can get that the range of r(x) is [0, 4]

torn shale
#

Yes okay

#

Presume

proper kernel
#

go ask if you need a recap, but I think you have enough to find the domain of F(r(x)) now

torn shale
#

Ok intersect between [-2,3] and [0,4]

proper kernel
#

thats correct

torn shale
#

Holup then

#

Answer is [0,3]

#

I hope

#

What now

proper kernel
#

back

#

yep [0, 3] is the domain of F(r(x))

#

wait

#

nvm [0, 3] is not the domain of F(r(x))

torn shale
#

??????

#

Ok

proper kernel
#

what we got for [0, 3] is the middle step

proper kernel
#

now youre looking for the domain

#

you know [0, 3] is an acceptable range for r(x) and an acceptable domain for F(x)

torn shale
#

Of f(r(x)) yes

proper kernel
#

so have [0, 3] be the range of r(x)

#

then work backwards to find out what the domain of r(x) is

#

already you have [0, 3] to tell you the middle step of F(r(x))

#

so working backwards will tell you the beginning step of F(r(x)), otherwise known as the domain

#

this wont make much sense for now since you interrupted earlier, but for now stick with the steps

torn shale
proper kernel
#

no no

#

let me repeat

#

if [0, 3] is the range of r(x),

#

then 2 cant be in r(x)'s domain anymore

#

because 2^2 isnt in [0, 3] is it

torn shale
#

Oh

#

Wtf

#

Okay

#

Yes i understand

proper kernel
#

so what would the smaller domain of r(x) have to be

#

for the range to only be [0, 3]

torn shale
#

Ah

#

0 to sqrt3

#

๐Ÿ˜ญ

proper kernel
#

yep

#

so the domain of F(r(x)) is [0, โˆš3]

torn shale
#

Omg ez

proper kernel
#

you can think of it as

#

F(r([0, โˆš3]))

#

F([0, 3])

torn shale
proper kernel
#

no question mark

#

the domain of F(r(x)) is [0, โˆš3]

torn shale
#

Wait uhm

#

Isnt

#

0 to sqrt of 3 the domain for r(x)

proper kernel
#

yea its the smaller domain that makes it okay to put into F

#

the larger [0, 2] domain had a 2 which didnt fit

#

we made the domain of r(x) smaller

#

so that way the range of r(x) is [0, 3]

torn shale
#

Aha then how is f(r(x)) is also from 0 to sqrt3

proper kernel
#

I am

torn shale
#

Domain

proper kernel
#

in the middle

#

of that

torn shale
#

Oh i interrupted you

proper kernel
#

[0, โˆš3] is the domain we chose for r(x)

torn shale
#

Yes

proper kernel
#

so lets see what happens after r(x) happens

#

you can pretend r([0, โˆš3])

#

= [0, 3]

#

this is short for "r(a number inside [0, โˆš3]) = a number inside [0, 3]"

torn shale
#

Okaaaay

#

Sure

proper kernel
#

now we chose [0, 3] because its in the range of r and the domain of F

#

so we do F([0, 3])

#

you saw that [0, 3] only uses numbers inside F's domain of [-2, 3]

#

so that means we dont have any problems like with 4

#

so that means F([0, 3]) = [1, 4] with no exceptions

torn shale
proper kernel
#

I mean what I type

#

I dont think you do

#

are you done yet?

#

Im not

torn shale
proper kernel
#

youre rereading past stuff again

torn shale
#

Yes

#

Iam trying to comprehend what u just did

proper kernel
#

if youre doing that, you shouldnt be interrupting from the beginning

#

do you want the full explanation

torn shale
#

How is r[ 0 to sqrt3] is [0,3]

torn shale
proper kernel
proper kernel
proper kernel
#

have you changed your mind or should we continue with this

torn shale